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Ex14_3.sce
//Example 14.3, Page 514 clc u=9.3*10^-24//in Tesla B=1//in Tesla Eb=u*B*6.24150934*10^18 T=300//in K k=8.6*10^-5//ev/k x=k*T s=(Eb/x)*100 disp('Part a') printf("\n The percentage is %f",s) disp('Part b') n=2.0*10^28///m3 k=1.38*10^-23//in J/k uo=4*%pi*10^-7//T-m/amp con=(uo*n*u*u)/(k*T) printf("\n The number of unpa...
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Ex5_1.sce
clc //Variable Initilisation Ns=1500 //Speed of Squirrel Cage Induction Motor in RPM N1=1460 //Speed of Squirrel Cage Induction Motor in RPM N2=1350 //Speed of Squirrel Cage Induction Motor in RPM // At 1460 rpm the speed slip is given by S1=(Ns-N1)/Ns //Slip I=(sqrt(1/3)*(2/3))/(sqrt(S1)*(1-S1)) // At 1350...
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Ex3_34.sce
//Example 3_34 clc; clear; close; format('v',6); //given data : R=4;///ohm L=0.5;//H V=100;///V f=50;//Hz C=(1/2/%pi/f)^2/L*10^6;//micro F disp(C,"(a) Capacitance at resonant Frequency(micro F)"); I0=V/R;//A VC=I0/2/%pi/f/(C*10^-6);//V disp(VC,"(b) Voltage across the capacitor at resonant(V)"); Q=VC/V;//...
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Example_13_6.sce
syms s X1 X2 X3 U; T=(s^2+4)/((s+1)*(s+2)*(s+3)) disp("state modle is") A=[-1 0 0; -0 -2 0; 0 0 -3] B=[1;1;1]*U X=[X1;X2;X3] C=[2.5 -8 6.5]; D=0; disp(A*X+B,"[diff(X1);diff(X2);diff(X3)]=") disp(C*X+D,"and Y = ")
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// Exa 7.5 clc; clear; close; // Given data f=1000;//in Hz R1=1000;//in ohm R2=1000;// in ohm R3=2000;//in ohm R4=2000;//in ohm C1=1*10^-6;//in F r1= 10;// in ohm omega=2*%pi*f; C2=C1*R1/R2;//in F disp(C2*10^6,"Unknown capacitance in micro F "); r2=(R2*(R3+r1)-R1*R4)/R1;//in ohm del_1=omega*r1*C1;//i...
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Example_9_18.sce
clc; clear; printf("\n Example 9.18\n"); d=1; //Diameter of plate r1=0.5; r4=r1; //Radius of the imaginary disc sealing the hemisphere L=r1; //The distance between the plate and the bottom of the dome A1=%pi*d^2/4; //Area of the plate A2=2*%pi*d^2/4; //Area of the underside of the Hemisphere A4=%pi*r4^2/...
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8_4b.sce
clc clear //Initialization of variables T1=584.6 //R g=32.2 //ft/s^2 k=1.4 R=53.3 //ft-lb/lb R V1=600 //ft/s T2=519.6 //R pa=14.7 //psi p1=50 //psia //calculations Nm1=V1/(sqrt(k*g*R*T1)) Nm22= ((1+ (k-1)/2 *Nm1^2)/(T2/T1) -1)*(2/(k-1)) Nm2=sqrt(Nm22) pr=((1+ (k-1)/2 *Nm1^2)/(1+ (k-1)/2 *Nm2^2))^(k/(k-1)...
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ex6_10.sce
// Exa 6.10 clc; clear; close; format('v',7) // Given data Af = -100;// unit less Vin = 0.06;// in V Vout = Af*Vin;// in V Vin = 50;// in mV Vin = Vin * 10^-3;// in V A = Vout/Vin;// unit less //Af = A/(1+(A*Beta)); Beta = (abs(A)-abs(Af))/(Af*A);// unit less disp(Beta,"The value of ß is"); Amount = 20*l...
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Ex2_4.sce
//Chapter 2 Gases clc; clear; //Initialisation of Variables P= 752 //mm V= 0.2 //lit T= 21 //C R= 0.0821 //lit atm mole^-1 m= 0.980 //gms //CALCULATIONS M= m*R*(T+273)*760/(V*P) //RESULTS mprintf("Molecular Weight of Chloroform = %.1f gms per mole",M)
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// 4.4 clc; delta=4.8; Es=2.4; K=delta/Es; Es1=7.2; delta1=K*Es1; Es2=10; delta2=K*Es2; fs1=500*10^-3; mf1=delta/fs1; printf("\nmodulation index for Es (2.4) =%.1f",mf1) mf2=delta1/fs1; printf("\nmodulation index for Es(7.2)=%.1f",mf2) mf3=delta2/fs1; printf("\nmodulation indexfor Es(10) =%.1f",mf3)
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load Computer.hdl, output-file ComputerAdd.out, compare-to ComputerAdd.cmp, output-list time%S1.4.1 ARegister[0]%D1.7.1 DRegister[0]%D1.7.1 PC[]%D0.4.0 RAM16K[16]%D1.7.1 RAM16K[17]%D1.7.1 RAM16K[18]%D1.7.1 RAM16K[19]%D1.7.1; // Load a program written in the Hack machine language. ROM32K load add.hack, output; //sett...
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// File name: projects/01/Not16.tst load Not16.hdl, output-file Not16.out, compare-to Not16.cmp, output-list in%B1.16.1 out%B1.16.1; set in %B0000000000000000, eval, output; set in %B1111111111111111, eval, output; set in %B1010101010101010, eval, output; set in %B0011110011000011, eval, outpu...
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// Problem no 15.12,Page no.359 clc;clear; close; D=0.038 //m //External Diameter d=0.035 //m //Internal Diameter d_1=0.0008 //m //Steel wire diameter p=2*10**6 //pa //Pa //Internal Pressure sigma_t_1=7*10**6 //Pa //Circumferential stress //E_s=1.6*E_s m=0.3 //Calculation t=(D-d)*2**-1 //m Thickness //sigma_t*2*t...
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<session design_hash="00000000000000000000" m_completed_compilation="false"> <stp_instance is_hdl_type="false" m4k_usage="0" m512_usage="0" mram_usage="0"> <sci_design_instance entity_name="" instance_hpath="" instance_name="auto_signaltap_0" ir_bits="0" is_auto_index="false" is_imported_from_partition="false" is...
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//clear// //Caption:Illustrating the generation of DPSK signal //Table7.3 Generation of Differential Phase shift keying signal clc; bk = [1,0,0,1,0,0,1,1];//input digital sequence for i = 1:length(bk) if(bk(i)==1) bk_not(i) =~1; else bk_not(i)= 1; end end dk_1(1) =bool2s( 1 & bk(1)); //initial value of d...
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//example 4.2 //least square curve fitting procedure //page 129 clc;clear;close; x=[0 2 5 7]; y=[-1 5 12 20]; for i=1:4 x_2(i)=x(i)^2; xy(i)=x(i)*y(i); end printf('x\t y\t x^2\t xy\t \n\n'); S_x=0,S_y=0,S_x2=0,S_xy=0; for i=1:4 printf('%d\t %d\t %d\t %d\t\n',x(i),y(i),x_2(i...
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 23 disp("CHAPTER 8"); disp("EXAMPLE 23"); //VARIABLE INITIALIZATION v=230; //in Volts r_a=0.4; //in Ohms r_f1=115; //in Ohms I_a=20; //in Amperes N1=800; //in...
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Ex17_3.sce
P=6//no. of poles A=P//no. of parallel paths phi=.018//flux per pole N=600//speed of rotation in rpm Z=840//total no. of conductors Eg=P*phi*N*Z/(60*A) mprintf("Emf generated=%f V\n",Eg)
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clc;funcprot(0);//EXAMPLE 17.44 // Initialisation of Variables D=0.34;..............//Engine bore in m k=0.5;...............//Four stroke engine n=1;..................//No of cylinders L=0.44;................//Engine stroke in m Ne=400;................//Engine rpm aic=465;..............//Area of indicator diagra...
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/* ex. Sejam os nós x=[0, 0.6, 1]. Encontre os pesos A_i da quadratura I=A_1f(x_1)+A_2f(x_2)+A_3f(x_3) tal que o erro seja o menor possível para aproximar a integral de f no intervalo 0 a 1. R: [8/36, 25/36, 3/36] */ clear vetor_nodes = [-0.72, 0.12, 0.82] lim_inicial = -1 lim_final = 1 len_nodes = length(vet...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 11, Example 8") //Two concentric spheres of diameters D1=0.5m and D2=1m are separated by an air space. //The surface tempratures are T1=400K and T2=300K T1=400; ...
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clc;clear; //Example 7.12 //given data P2=1000; P1=100; //from Table A-5 //At P2 v1=0.001043; //calculations Wrev=v1*(P2-P1); disp(Wrev,'compressor work as saturated liquid at inlet in kJ/kg') //from Table A-5 //at P1 as sat. vapour h1=2675.0; s1=7.3589; s2=s1 //from Table A-6 //at P2 and s2 h2=...
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clc h=1.05*10^-34 disp("h = "+string(h)+"Js") //initializing value of reduced plancks constant or dirac constant or h-bar mo = 9.1*10^-31 disp("mo = "+string(mo)+"kg") //initializing value of mass of electron E = 0.1*1.6*10^(-19) disp("E= "+string(E)+"J")//initializing value of Energy of electron in conduction ba...
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//Example 11.5 //Inverse Power Method //Page no. 347 clc;close;clear; A=[7,6,-3;-12,-20,24;-6,-12,16]; e=10^-6; X=[1;1;1]; B=0; Y=[0;0;0] a=0;l=0; for i=1:2 printf('When a=%i\n',a); C=A-a*eye(); disp(C,"C=") C_1=inv(C); disp(C_1,"Inverse of C="); printf('\n\nItr lambda ...
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errcatch(-1,"stop");mode(2);//Example 2_14 ; ; //To find the angular separation between two wave lengths N=6*10^5 //units in lines per meter m=3 lemda1=500*10^-9 //units in meters lemda2=510*10^-9 //units in meters theta1=asin(m*N*lemda1)*180/%pi theta2=asin(m*...
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function [stk,txt,top]=sci_gray() // Copyright INRIA txt=[] if rhs<1 then stk=list('graycolormap(32)','0','32','3','1') else stk=list('graycolormap('+stk(top)(1)+')','0',stk(top)(1),'3','1') end
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scenario = "False memory - encoding session"; # name of this scenario file pcl_file = "3013065.02.MRI.Encoding.v1.pcl"; # direct to the correct pcl file #default_font = "Comic Sans MS"; # can choose all types of fonts you want default_font = "Calibri"; default_font_size = 30; default_text_color = 235,235,235; # near...
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//Calculations on diesel engine clc,clear //Given: bp=5 //Brake power in kW eta_it=30 //Indicated thermal efficiency in percent eta_m=75 //Mechanical efficiency in percent (printing error) //Solution: ip=bp*100/eta_m //Indicated power in kW CV=42000 //Calorific value of diesel(fuel) in kJ/kg m_f=ip*3600/(eta_i...
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// funcprot(0) //eaux chaude sur la carte : mission A3 //load getd('../scripts/') //save imgPos='../images/' renderPos = "render/" //The folder where the render images will be saved img=readpbm(imgPos + 'Europa_surface.pbm'); resultat = seuillage(img,250) writepbm(resultat,renderPos+"MissionA3.pbm");
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@Title displaced_Ag__a_1 @Columns AsymmetricAtom AtomicNumber int 0 Connections string {{}} Fractional double {{0.0 0.0 0.0}} Name string {{}} Site int 1 WyckoffPosition int -1 @end @data 47 {} {0.75 0.75 0.5} Ag 1 -1 47 {} {0.75 0.75 0} Ag 1 -1 47 {} {0.75 0 0.25} Ag 1 -1 47 {} {0.75 0.25 0.5} Ag ...
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//Initilization of variables F1=1000 //lb F2=1200 //lb F3=2000 //lb x1=1 //ft x2=7 //ft x4=2 //ft x3=6 //ft //Calculation //Equilibrium equations Rn=(F3*(x1+x2+x3)+F2*(x1+x2)+F1*x1)/(x1+x3+x2+x4)//Moment about point M Rm=(F1*(x2+x3+x4)+F2*(x3+x4)+F3*x4)/(x1+x2+x3+x4)//Moment about point N //Result clc pri...
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clc clear //Initialization of variables T1=673 //K T2=293 //K //calculations eta=(T1-T2)/T1 //results if eta>=0.5 then printf("Max efficiency = %.3f and an efficiency of 0.5 is possible",eta) else printf("Max efficiency = %.3f and an efficiency of 0.5 is not possible",eta) end
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clc; a=0.909; b=0.091; nR=1+0.5; nP=1; H0=-282990; R=8.3145; T0=298; U0=H0-(nP-nR)*R*T0; UR0=-7844; UR1=9487; UP0=-6716; UP2=(a*281751)-(UR0-UR1)+UP0 UP2_=(a*138720)+(b*74391)+(1.709*73555); disp("which compares with the actual,hence actual temperature of the products is slightly greater than 3200",UP2_,"and UP2 at...
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//Chapter-2, Example 2.28, Page 2.51 //============================================================================= clc clear //INPUT DATA Rp=1;//Percentage resistance drop in percentage Xp=4;//Percentage reactance drop in percentage cosQ1=0.8;//Lagging power factor sinQ1=0.6;//Sine of Q1 cosQ2=1;//Power fa...
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clc disp("the soln of eg 9.1-->Transient heat conduction in a Rectangular slab") disp("the values of Temp measured from centre at the gap of .2 cm are") alpha=10^-5, delta_t=.1, delta_x=10^-3 //given data m=alpha*delta_t/(delta_x^2) for i=2:4, a(i)=m //sub-diagonal end b(1...
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// Example 1.7 clc; clear; close; // Given data format('v',6); VEE= 5;// supply voltage in V RC= 2*10^3;// collector resistance in Ω RE= 4.3;// emitter resistance in kΩ VBE= 0.7;// in V VT= 26;// in mV IE= (VEE-VBE)/(2*RE);//emitter current in mA re_desh= VT/IE;//dynamic emitter resistance in Ω Ad= RC/(2*r...
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function [yp, betap, exitcode, active] = ir_predict(Xp, X, y, epsilon) // Computes interval prediction for response y at the point x // using the interval regression constructed for dataset (X,y,epsilon) // // TODO: Fix bugs in algorithm of active constraints detection. // // Inputs: // Xtest (k x m)-matr...
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;improperly masked indirect jump %2 <- %2 and 0xffffffe0 ijmp %3 ; wrong register
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clc clear //Input data P1=1;//pressure at the beginning of compression stroke in bar T1=298;//Temperature at the beginning of compression stroke in K P3=38;//Pressure at the end of constant volume heat addition in bar T4=1573;//Temperature at the end of constant volume heat addition in K r=9.5;//Compression rati...
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// Chapter 10_Fundamentals of the Metal Oxide Semiconductor Field Effect Transistor //Caption_Cut off frequency //Ex_11//page 484 mun=400 //mobility L=4*10^-4 VT=1 VGS=3 fT=mun*(VGS-VT)/(2*%pi*L^2)*10^-6 printf('The cut off frequency of this MOSFET with constant mobility is %1.0f MHz',fT)
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//Use of the x_choose function. n=x_choose(['Red'; 'Green'; 'Blue'],['Choose a color by double clicking'],'Return without selection')
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clc;clear; //Example 11.2 //given data hf=30;//half life in days //M is intial conc. //calcualtions k=0.693/hf; disp(k,'radioactive disintegration constant in 1/day'); //M/4 is left t=-log(1/4)/k; disp(t,'time taken for (ii) in days'); //M/8 is left t=-log(1/8)/k; disp(t,'time taken for (iii) in days')
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clc; clear; P=10^-3 //power in watt h=6.62*10^-34 //Plancks constant in J-s v=3*10^8 //frequncy of light in Hz lambda=4560*10^-10 //wavelength in m eff=0.005 //quantum efficiency e=1.6*10^-19 //charge in C //calculation E=(h*v)/lambda //energy of each photon in joules N=P/E //no of photons incident on the m...
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errcatch(-1,"stop");mode(2);//Initilization of variables v=4 //m/s m=9 //kg s=1.5 //m //Calculations Io=(2/3)*(m*s^2) //kg.m w=(m*v*s*0.5)/Io //rad/s //Result printf('The angular velocity of the box is %i rad/s',w) exit();
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# Per GAWK manual: # Inside a BEGIN rule, the value of FILENAME is "", because there are no input # files being processed yet. # https://www.gnu.org/software/gawk/manual/gawk.html#Auto_002dset BEGIN { print FILENAME } END { print NR } ##Input 1 2 3 ##Output 3 ##END
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# @Harness: probes # @Result: # @Program: array.asm # @Purpose: tests read watches watch A { | | | } main { insert A 0x100; } result { 4 A.beforeRead; 4 A.afterRead; }
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//Ex:5.13 clc; clear; close; Lc=100000;// coherence length in m y=1.32*10^-6;// operating wavelength in m dy=1.5*10^-9;// spectral width in m BF=y^2/(Lc*dy);//model birefrigence in um L=y/BF;// beat length in m printf("The beat length=%f m", L);
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clc(); clear; //To determine the uncertainity in determining the position of this electron m=9.1*10^-31; //mass of electron v=6*10^3; //speed of electron p=m*v; //uncertainity in momentum in kg.m/s h=6.626*10^-34; ...
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clear; clc; // Descomposición de Cholesky // // // // A: Matriz hermitiana y definida positiva // // L: Matriz triangular inferior tal que LL* = A (L* es la conjugada...
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Display Options Screen.tst
ScreenName String 'Display Options Screen' ImplName String 'NULL SCREEN' ElementChunkArray Int 26 ScreenElementType Int 0 ImplName String 'Front End Screen Backdrop' TabIndex Int 1 Selectable Bool False Enabled Bool True ReferenceArea Rect( 0, 113, 800, 507 ) # left,top,right,bottom ScreenElementType Int 1 ImplName St...
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// Scilab Code Ex1.13: Page:32 (2011) clc;clear; c = 3e+008; // Speed of light in vacuum, m/s E0 = 0.5; // Rest energy of the electron, MeV v1 = 0.6*c; // Initial velocity of the electron, m/s v2 = 0.8*c; // Final velocity of the electron, m/s W = (1/sqrt(1-v2^2/c^2)-1/sqrt(1-v1^2/c^2))*E0; // The...
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clc; clear all; disp("increase in heat dissipation") k=0.174;// W/(m*C) r1=6.5/2;//mm ho=8.722;// W/(m^2*K) rc=1000*k/ho;//mm L=1;//m t1=60;// degree C tair=20;// degree C disp("mm",rc,"critical radius of insulation =") t=rc-r1; disp("mm",t,"minimum insulation of thickness t = ") disp("i) without insula...
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clc //initialization of new variables clear n = 0.012; S = 1; alpha = 1;//degrees Z = 0.00005:0.05:5; k = (5-0.00005)/0.05 +1; for i = 1:k R_h(i) = S/((1/Z(i))+2*Z(i)); U_av(i) = (1/n)*(R_h(i)^(2/3))*sqrt(tan(alpha*%pi/180)); Q(i) = U_av(i)*S; b(i) = S/Z(i); AR(i) = Z(i)/b(i); end p...
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//Transport Processes and Seperation Process Principles //Chapter 5 //Example 5.5-1 //Principles of Unsteady State Heat Transfer //given data //english units h=39.7; k=0.498;//thermal conductivity Cp=3.48*1000;//specific heat rho=1073;//density alpha=k/(rho*Cp)//temp coefficient w=0.203; x1=w/2; x=0; n=x...
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a=[0 0 0 0]; b=[1 2 3 4]; z=tf2zpk(b,a); disp(z); //output // !--error 10000 //Dividing by zero not allowed //at line 46 of function eqtflength called by : //at line 7 of function tf2zpk called by : //z=tf2zpk(b,a); //at line 3 of exec file called by : //x Test/tf2zpk/tf2zpk9.sce', -1
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34_19.sce
//ques-34.19 //Calculating energy of light required to decompose 1g of ammonia clc w=200;//wavelength (in nm) QE=0.14;//quantum efficiency (in molecule/photon) m=1;//mass of ammonia given n=m/17;//moles of ammonia given q=(n/QE)*(2.859/w)*10^7; q1=q*4.184; printf("The energy of light required is %d cal or %d J...
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ppppStrafer6ShooterInvincible.sce
Name=ppppStrafer6ShooterInvincible PlayerCharacters=6Shooter BotCharacters=Quaker Bot Fast Strafes.bot IsChallenge=true Timelimit=60.0 PlayerProfile=6Shooter AddedBots=Quaker Bot Fast Strafes.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=2 BotTeams=1 MapName=cataIC.map MapScale=3.8125 BlockProjectilePredictors=true Blo...
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clc T=300 //K k=8.617*10**-5//eV/K e=1.6*10**-19 //C esp=11.7 esp0=8.85*10^-14 phibe=0.67 //V A=114 //A/K^2-cm^2 Na=10^18 //cm^-3 Nd=10^16 //cm^-3 taup0=10^-7 taun0=10^-7 Dp=10 //cm^2/s Dn=25 //cm^2/s Lp=1.0*10**-3 //cm Ln=1.58*10**-3 //cm pn0=2.25*10**4 //cm^-3 np0=2.25*10**2 //cm^-3 a=k*T Js...
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clc Vr=200; //Assiging values to parameters P=15.3; fr=10000; BW=1000; R=Vr^2/P; Q=fr/BW; L=Q*R/(2*%pi*fr); C=1/(4*%pi*%pi*fr*fr*L); disp("Ohms",R,"resistance"); disp("henry",L,"inductor"); disp("Farads",C,"Capacitor");
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//========================================================================== // Modified for RT purposes by Roberto Bucher - RTAI Team // roberto.bucher@supsi.ch function Makename=rt_gen_make(name,files,libs) Makename=rpat+'/Makefile'; T=mgetl(TARGETDIR+'/'+makfil); T=strsubst(T,'$$MODEL$$',name); T=strsubs...
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---------------------------------------------------------------------------------------- CREATE OR REPLACE VIEW tblLogRegr_vw AS ( SELECT ObsID, VarID, Num_Val as Value FROM tblLogRegrData); EXEC SP_LogRegr('tblLogRegr_vw', 0.10, 25, 'Test'); -------------------------------------------------------------------------...
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//Example 7.9. refer fig.7.17. clc format(6) KN=1*10^-3 lamda=0.01 Ri=100*10^3 IDt=4*10^-3 IDQ=1.5*10^-3 VTN=1.5 VDD=12 VDSQ=7 disp("To determine VDSi") disp("We have,") disp(" IDt = KN*(VGst - VTN)^2") disp("where the subscript t indicates transition point values.") VGSt=sqrt(IDt/KN)+VTN disp...
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//ques1(ii) disp('To find the laplace of given function in t '); syms t s f=exp(-3*t)*(2*cos(5*t)-3*sin(5*t)); disp(laplace(f,t,s));
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** **requires:LUA **requires:PGSQL **input <?xml version="1.0" encoding="UTF-8" standalone="no"?> <!DOCTYPE test SYSTEM 'test.simpleform'> <test> <pushCategoryHierarchy> <node name="Minicomputer"> <node name="Superminicomputer"/> <node name="Minicluster"/> <node name="Server (Minicomputer)"/> <node name="Works...
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//chapter-1,Example1_4_5,pg 1-34 Dn_1=0.218 //Diameter of nth ring Dn_2=0.451 //Diameter of (n+10)th ring wavelength=5893*10^-8 //wavelength of light R=90 //Radius of curvature p=10 u=(4*p*wave...
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//Calculate ENDURANCE STRESS FROM using various relations //Ex:8.5 clc; clear; close; p_min=20;//in kN p_max=50;//in kN l=500;//in mm d=60;//in mm a_u=650;//in MPa a_y=520;;//in MPa fos=1.8;//factor of safety m_max=p_max*l/4;//maximum bending moment in kN mm m_min=p_min*l/4;//minimum bending moment in kN m...
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//to calculate a).max demand on the station b).installed capacity c).energy supplied in a year clc; peak_l1=25; //load is in MW peak_l2=20; //load is in MW peak_l3=30; //load is in MW ann_lf=0.6; //load factor is dimentionless d_f=1.65; //diversity factor is dimention...
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clear;lines(0); rand('seed',0);sl=ssrand(2,2,5);[A,B,C,D]=abcd(sl);poles=spec(A) [Q,M]=pbig(A,0,'c'); //keeping unstable poles slred=projsl(sl,Q,M);spec(slred('A')) sl('D')=rand(2,2); //making proper system trzeros(sl) //zeros of sl wi=inv(sl); //wi=inverse in state-space [q,m]=psmall(wi('A'),2,'d'); //keeping sma...
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1793053674="2018/09/04" 106325153="UTC AD 2018/09/05 14:00:00" 942264642="1.0 min." 1345932452="UTC AD 2018/09/05 13:59:00" 1684156605="14:00"
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//chapter 2 //example 2.7 //page 49 clear; clc ; //given trr1=10;//in ns for 1N915 trr2=3;//in ns for 1N917 //finding maximum operating frequency for 1N915 fmax1=1/(10*trr1)*10^3;//in MHz //finding maximum operating frequency for 1N917 fmax2=1/(10*trr2)*10^3;//in MHz printf('maximum operating frequency...
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//chapter 19 //example 19.24 //page 875 printf("\n") printf("given") Rf=15*10^3;R1=5.6*10^3;vs=.5;Vp=2.7;Rl=8.0; Acl=(2*Rf)/R1 Vo=Acl*vs Po=(Vp)^2 /(2*Rl); printf("load power dissipation is %3.2fW\n",Po)
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clear; clc; //N=input("enter the no of elements in the set :"); //for i=1:1:N // s(1,i)=input("enter the elements in the set :"); //end; //n=input("enter the number of pairs in the relation :"); //for j=1:1:n // for k=1:1:2 // r(j,k)=input("enter the elements in the relation :"); // end //end...
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s=%s GH=syslin('c',k/(s*(s+2)*(s+10))) nyquist(GH)
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// sum 28-2 clc; clear; Z1=1; Z2=52; q=10; m=8; i=Z2/Z1; CD=((m*q)+(m*Z2))/2; lambda=atan(Z1/q); d=q*m; da=m*(q+2); df=m*(q+2-(4.4*cos(lambda))); pa=m*%pi; D=m*Z2; Da=m*(Z2+(4*cos(lambda))-2); Df=m*(Z2-2-(0.4*cos(lambda))); // printing data in scilab o/p window printf(" i is %0.0f ",i); pri...
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function sp=g_round(a) // Copyright INRIA [ij,v,mn]=spget(a) sp=sparse(ij,round(v),mn)
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clc //initialisation of variables T= 25 //C T1= 75 //C k= 6.45 //cal per mole per degree k1= 1.41*10^-3 //cal per mole per degree k^-1 k2= -8.1*10^-8 //cal per mole per degree k^-2 m= 14 //gms M= 28 //gms //CALCULATIONS Cp= k+k1*(273+T)+k2*(273+T)^2 Cp1= k+k1*(273+T1)+k2*(273+T1)^2 cp= (Cp+Cp1)/2 H= (m/M)*...
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01 072 495 633 !FORM 02 138 097 565 !FORM 01 456 280 934 !FORM 09 736 248 057 !FORM 04 389 217 055 !FORM 03 189 570 460 !FORM 48 954 371 207 ?NOK 55 492 670 836 ?NOK 12 345 678 903 ?NOK
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//Example_a_7_2 page no:270 clc; Rab=3+(4*%i); Rabmag=sqrt(real(Rab)^2+imag(Rab)^2); Rabang=atand(imag(Rab)/real(Rab)); Rbc=%i*4; Vmag=100; Vang=-45; Vreal=Vmag*cosd(Vang); Vimag=Vmag*sind(Vang); V=Vreal+(%i*Vimag); A=[(3+(%i*8)),(-%i*4) (-%i*4),(%i*2)]; B=[V, 0]; X=inv(A)*B; X1mag=sqrt(real(X(1...
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//Caption:Find (a)Efficiency of transformer at half load at 0.8 power factor lagging (b)At what load will the efficiency be maximum and maximum efficiency? //Exa:2.2 clc; clear; close; P_s=25000//Power supplied(in VA) V_1=3300//Voltage on primary side(in volts) V_2=230//Voltage on secondary side(in volts) f=50/...
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//EXAMPLE 5-25 PG NO-318-319 I1=4.4-%i*1.012; //Current I2=I1*[(%i*5)/(3+%i*9)]; Z1=1; I11=[I2/[10*%i*5]]*[%i*5/10+%i*5]; disp(' Current is in polar form = '+string(I1)+'A'); disp(' Current is in polar form = '+string(I2)+'A'); disp(' Current i...
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//(6.7) An inventor claims to have developed a device requiring no energy transfer by work or heat transfer, yet able to produce hot and cold streams of air from a single stream of air at an intermediate temperature. The inventor provides steady-state test data indicating that when air enters at a temperature of 21C...
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#1 - Black in check +---a---b---c---d---e---f---g---h---+ | | 8 -K . . . . . . . 8 | | 7 . . S . . . . . 7 | | 6 K . . . . . . . 6 | ...
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function [u,t] = heun(u0,t0,tn,h,f) //heun method solving ODE // du/dt = f(u,t), with initial //conditions u=u0 at t=t0. The //solution is obtained for t = [t0:h:tn] //and returned in u umaxAllowed = 1e+100; t = [t0:h:tn]; u = zeros(t); n = length(u); u(1) = u0; for j = 1:n-1 k1=h*f(t(j),u(j));...
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//Chapter 6, Problem 12 clc id=2e-3 //drain current in ampere vds=6 //drain to source voltage vcc=12 //supply voltage vs=0.1*vcc //source voltage vgs=1.8 //gate to source...
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// Cancellation of common factors and determination of covariance // 11.7 // function [N,dN,D,dD,yvar] = tfvar(N,dN,D,dD) // N and D polynomials in z^{-1} form; discrete case function [N,dN,D,dD,yvar] = tfvar(N,dN,D,dD) [N,dN,D,dD] = l2r(N,dN,D,dD); N = N/D(1); D = D/D(1); LN = length(N); LD = length(D); ...
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function mdaq_exec_profile_show() if isfile(TMPDIR + filesep() + "profiling_data") then load(TMPDIR + filesep() + "profiling_data"); if isdef("dsp_exec_profile") f=scf(4444); f.figure_name= "MicroDAQ execution profile"; plot2d2(dsp_exec_profile.step); ...
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// Case Study:-Chapter 2 Page no.-48 // 2.Solution of temprature in Farenheit and Celsius F_LOW=0; F_MAX=250; STEP=25; fahrenheit=F_LOW; //Initialization printf("Fahrenheit Celsius\n\n"); while(fahrenheit < = F_MAX) celsius=(fahrenheit-32.0)/1.8; //conversion from Farenheit to Celsiu...
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//Example 4.5, Page number 4.33 clc;clear;close // variable declaration W=1.55 // wavelength // Calculations E_g=(1.24)/W // Bandgap in eV // Result printf("Band gap = %0.1f eV",E_g)
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Fe=0.01;//concentration of Fe3+ ions in the solution// Ksp=3.8*10^-38;//Solubility product of Fe(OH)3// OH=(Ksp/Fe)^0.333;//Concentration of OH- ions in the solution// printf('Concentration of OH- ions in the solution=OH=%f=1.561*10^-12',OH); printf('\nAt this PH,Fe(OH)3 starts precipitating and precipitation is co...
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// Example 2.8, page no-120 clear clc dens_water=1000 h1=125 h2=250 d2=(h1/h2)*dens_water printf("(a)\nDensity of Liquid = %d kg/m^3",d2) printf("\nSpecific Density of the liquid = %.1f",(h1/h2)) //(b) printf("\n\n(b)\nIf Values of water and liquid interchanged:\n") d3=(h2/h1)*dens_water printf("\nDensi...
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clc // Given that n = 10^8 // no. of electron per discharge counted by GM counter r = 500 // counting rate in counts per minutes e = 1.6e-19 // charge on an electron in C // Sample Problem 35 on page no. 12.46 printf("\n # PROBLEM 35 # \n") N = r / 60 i = N * n * e printf("Standard formula used \n i = N * n * e . \n"...
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//Example 9.39 clc disp("From equation(3) we get") qe=(4.095/(4095*2))*10^3 format(4) disp(qe,"Q_E(in mV) = 4.095 / (4096-1)*2 =")
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clc; syms y y1 y2 x; t = %pi/2;j = 0:%pi; y = 5*cos(t);disp(y,"at x = pi/2, y ="); y1 = -5*sin(t);disp(y1,"at x = pi/2, dy/dt ="); printf("\n neglecting higher order terms"); k = y + y1*(x-%pi/2); disp(k,"linearized y =");
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clear flag=1 mode(-1) clc printf("Example 10 : Show the use of while loop and sleep \n") disp("****************************************************************") disp("Answer : ") disp("INSTRUCTIONS : ") printf("\n1. Here all instructions are preloaded in the form of a ...
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// chapter 13 // example 13.11 // Compute the values of RF filter components // page-833 clear; clc; // given R_L=120; // in ohm f0=50; // in KHz // calculate f0=f0*1E3; // changing unit from KHz to Hz L=R_L/(2*%pi*f0); // calculation of inductance C=1/(2*%pi*R_L*f0); // calculation of capacitance printf("...
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// Scilab code Ex17.2 : Pg:889 (2011) clc;clear; amu = 931.5; // Energy equivalent of 1 amu, MeV m_n = 1.008665; // Mass of the neutron, amu m_p = 1.007825; // Mass of the proton, amu M_He = 4.002870; // Mass of the heluim nucleus, amu c = 3e+08; // Speed of light, m/s BE = (2*m_n+2*m_p - M_He)*amu; /...
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function y = vco(x,frange,fs) //Voltage Controlled Oscillator //Calling Sequence //y=vco(x,fc,fs) //y=vco(x,[fmin fmax],fs) //Parameters //x //A vector or a matrix //fc //Carrier frequency //fs //fmin //Minimum frequency of the frequency range //fmax //Maximum frequency of the frequency range //Description //y=vco(x,fc...
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clc clear //input //AB,BC,CD,DA forms an unbalanced wheatstone's bridge r1=2;//resistance in arm AB in ohms r2=5;//resistance in arm BC in ohms r3=6;//resistance in arm CD in ohms r4=2;//resistance in arm DA in ohms r5=10;//resistance of detector placed between the points B and D v=4;//batterry supplying d.c...
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clc; p1=1;//bar p2=10;//bar n=1.1; v1=0.16;//m^3 v2=v1*(p1/p2)^(1/n); W=(p2*v2-p1*v1)*10^5/[10^3*(n-1)]; disp("work done by the refrigerant is:"); disp("kJ",W); hg1=174.2; u1=hg1-(p1*10^5*v1/10^3); hg2=203.8;//kJ/kg vg2=0.018;//m^3 v=0.02;//m^3 h=224;//kJ/kg h2=hg2+(v2-vg2)*(h-hg2)/(v-vg2); u2=h...