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//Page Number: 96 //Example 2.9 clc; //Given, c=3D+8; //m/s fc=3D+9; //Hz //Cutoff wavelength lamc=c/fc; a=lamc/2;//m a=a*100;//cm disp('Dimensions:'); disp('cm',a,'a:'); b=a/2; //cm disp('cm',b,'b:');
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// Examle 16.7 Il=100; // Series field current Rse=0.1; // Resistance series field Vse=Rse*Il; // Voltage drop across series field (Vse) disp('Voltage drop across series field (Vse) = '+string(Vse)+' Volt'); V=250; // Supply voltage Vsh=...
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X = [1, 2, 3, 4, 5]; Y = [10, 40, 50, 78, 83]; m = length(X); sum_ = 0; loss_i = 1; for a = 1:0.01:100 for i = 1:m H(i) = a * X(i); sum_ = sum_ + (H(i) - Y(i))**2; end loss(loss_i) = sum_ / (2*m); loss_i = loss_i + 1; sum_ = 0; end mprintf("Minimum value ...
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// 1 APPENDIX. Ex no 19. Page no 657 // Initilization of variables F=2 // kN W=1 // kN // Co-ordinates as matrices A=[0,0,0] C=[0,0,1.2] B=[0,0,2.5] D=[-1,1,0] E=[1,1,0] F=[0,0,1] G=[0,0,2] // Force vector f=[0,-2,0] // Weight vector w=[0,-1,0] // Calculations // we have 5 unknowns: A_x,A_y,A_z,T_FE & T_GD // we define...
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//Chapter 3, Example 3.1, page 61 clc //Initialisation h=2 //height in Km h1=5 //height in Km //Calculation t2=290-(6.5*h) //Proposed formula for height h=2Km p2=950-117*h e2=8-3*h t21=294.98-5.22*h-0.007*h**2 p21=1012.82-111.5...
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function[F, G, H, ind] = OraclePH(qc, ind) // Si ind = 2, on calcule seulement F if ind == 2 then F = 1/3*(q0+B*qc)'*(r .* (q0+B*qc) .* abs(q0+B*qc)) + pr'*Ar*(q0+B*qc) ; // Si ind = 3, on calcule seulement G elseif ind == 3 then G = B'*Ar'*pr + B'*(r.*(q0+B*qc).*abs(q0+B*qc)...
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clc clear //Initialization of variables T1=584.6 //R g=32.2 //ft/s^2 k=1.4 R=53.3 //ft-lb/lb R V1=600 //ft/s T2=519.6 //R //calculations Nm1=V1/(sqrt(k*g*R*T1)) Nm22= ((1+ (k-1)/2 *Nm1^2)/(T2/T1) -1)*(2/(k-1)) Nm2=sqrt(Nm22) Ar= Nm1/Nm2 *((1+ (k-1)/2 *Nm2^2)/(1+ (k-1)/2 *Nm1^2))^((k+1)/(2*(k-1))) //result...
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clear; clc; close; Pd_temp0 = 80; T1 = 100; T0 = 25; D = 0.5; Pd_temp1 = Pd_temp0-(T1-T0)*(D); disp(Pd_temp1,'Maximum power dissipation(Watts) = ');
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clc //Initialization of variables g=981 //cm/s^2 H=20 //cm err=3/100 //calculations dH=err/2.5 *H v0=sqrt(2*g*dH) //results printf("Required velocity = %.2f cm/s",v0) //The answer is a bit different due to rounding off error
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function V_0 = UpOutPut_BinMod (S_0, r, sigma, T, K, B, M) // Compute values of u, d and q according to Equations (2.4)--(2.7). delta_t = T/M; alpha = exp(r*delta_t); beta = 1/2 * ( 1/alpha + alpha*exp(sigma^2*delta_t) ); u = beta + sqrt(beta^2-1); d = 1/u; q = ( exp(r*delta_t)-d ) / ( ...
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Name=Ashe Sphere Frenzy Strafing PlayerCharacters=Clicker BotCharacters=TileFrenzyStrafing Sphere.bot;TileFrenzyStrafing Sphere.bot;TileFrenzyStrafing Sphere.bot IsChallenge=true Timelimit=61.0 PlayerProfile=Clicker AddedBots=TileFrenzyStrafing Sphere.bot;TileFrenzyStrafing Sphere.bot;TileFrenzyStrafing Sphere.bo...
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// Exa 7.17 clc; clear; close; // Given data r= 100;// in ohm R2= 1000;// in ohm R3= 500;//in ohm R4= 1000;//in ohm C= 3;// in micro F C= C*10^-6;// in F Rx= R2*R3/R4;// in ohm disp(Rx,"Value of Rx in ohm") Lx= C*R2/R4*(r*(R3+R4)+R3*R4);// in H disp(Lx,"Value of Lx in H")
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// HSpice automation supervisor script example // // (c)2008 L. Rayzman // Created : 10/17/2008 // Last Modified: 10/20/2008 // // TODO: // clear; getf("HSPiceUtilities.sci"); // Include HSpice utilities //////////////////////////////////////SPECIFY///////////////////////...
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function [stk,txt,top]=%l2sci() // \ //! // Copyright INRIA txt=[] s2=stk(top);s1=stk(top-1);top=top-1; if s2(2)=='2'|s2(2)=='1' then s2(1)='('+s2(1)+')',end if s1(2)=='2' then s1(1)='('+s1(1)+')',end if part(s1(1),1)=='-' then s1(1)='('+s1(1)+')',end if s1(3)=='1'&s1(4)=='1' then stk=list(s1(1)+'\'+s2(1),'1',s2(3),...
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// Scilab code Exa 4.8.5 : Identifying the nucleus and energy released in the given reaction : page no. 197 (2011) // Declare three cells (for three reactions) R = cell(4,3); // Enter data for first cell (Reaction) R(1,1).entries = 'H'; // Element R(1,2).entries = 1; // Atomic number R(1,3).entries = 2; // Mass nu...
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// 08.05.18 Koshikawa // 08.05.19 Changed // 08.06.03 // 09.11.12 // 09.11.14 debug function PL=Intersectcrvs(varargin) Nargs=length(varargin); Eps=10^(-4); Tmp=varargin(Nargs); if type(Tmp)==1 & length(Tmp)==1 Eps=Tmp; end G1=varargin(1); if Mixtype(G1)==1 G1=list(G1); end; G2=varargin(2);...
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//Example No. 7_04 //Gauss Jordan Elimination //Pg No. 228 clear ; close ; clc ; A = [ 2 4 -6 ; 1 3 1 ; 2 -4 -2 ]; B = [ -8 ; 10 ; -12 ]; [ar,ac] = size(A); Aug = [ 2 4 -6 -8 ; 1 3 1 10 ; 2 -4 -2 -12 ]; disp(Aug) for i = 1 : ar Aug(i,i:ar+1) = Aug(i,i:ar+1)/Aug(i,i) ; ...
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clc clear //Input data B=32;//Brake horse power in kW with all cylinders working B1=21.6;//BHP with number 1 cylinder cut out in kW B2=22.3;//BHP with number 2 cylinder cut out in kW B3=22.5;//BHP with number 3 cylinder cut out in kW B4=23;//BHP with number 4 cylinder cut out in kW //Calculations I1=B-B1;//I...
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//Example 5.1: E.C.E clc; clear; close; //given data : t=200; // time in sec M=111.83; // silver in mg I=0.5; // current in A Z=(M/(I*t*1000))*1000;// electro-chemical-equivalent disp(Z,"E.C.E,Z(mg/C) = ")
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clear //Given P1=100.0 //W P=1100.0 //W V=250 //Calculation P2=P-P1 R=V**2/P2 //Result printf("\n The value of unknown resistance is %0.3f ohm", R)
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function s=%spas(a,b) // %spas - adds a sparse matrix and a scalar s //! if size(b)==[-1 -1] then [m,n]=size(a) s=a+(b+0)*speye(m,n) else s=full(a)+b end
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//Exa3.5 clc; clear; close; // given data n_i=1.4*10^18;// in m^3 N_D=1.4*10^24;// in m^3 n=N_D;// (approx) p=n_i^2/n; // let Ratio of electron to hole concentration = r r=n/p; disp("Ratio of electron to hole concentration is : "+string(r));
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function [x,n] = myCubeRoot(a,tol) // Use iterative algorithm to compute cube root of a real number // Inputs // a Value for which cube-root is to be found // tol Tolerance up to which the result is to be found // Outputs // x Approximate value of cube root found // n ...
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//Problem 13.07: //initializing the variables: DG0fO2 = 0; // cal/gmol DG0fCO = -32781; // cal/gmol DG0fCO2 = -94258; // cal/gmol Tk = 298; // in K R = 1.987; // cal/gmol.K //calculation: DG0 = DG0fCO - 0.5*DG0fO2 - DG0fCO2 K = %e^(-1*DG0/(R*Tk)) printf("\n\nResult\n\n") printf("\n chemical reaction...
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clear clc //Example 4.3 PRESSURE IN A DECELERATING TANK OF LIQUID p1=0; Gamma=42; //[lbf/ft^3] g=32.2; //[ft/s^2] al=-10; //[ft/s^2] l=20; //[ft] //Euler's equation along the top of tank, dp/dl=-Gamma*l/g p2=p1-Gamma*al*l/g //[psfg] //1kPa=20.88psfg printf("\n(a)The pressure at the top front, p = %.f psfg (=...
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//example-2.113 pg no -149 Wo=9.798*10^3; Fo=1559.39; C=2; R=10*10^-6; L=10^-3; D.R=L/(C*R); //DYNAMIC RESISTANCE Q=(1/C)*((L/R)^0.5); B.W=Wo/Q; //BAND WIDTH disp('i) DYNAMIC RESISTANCE = '+string (D.R)+ ' ohm '); disp('ii) Q = '+string (Q)+' '); disp('iii) BAND WIDTH = '+string (B.W)+'rad/s...
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clear // //case 1 //2300 winding used as secondary //given and derived st=150 v1=13800 v2=2300 a=(v1-v2)/v2 b=a+1 sat=(6*150)/5 printf("\n sat= %0.1f Kva",sat) //case 2 v1=13.8 v2=11.5 a=(v1-v2)/v2 sat=((1+a)/a)*150 printf("\n sat= %0.1f kva",sat)
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//Example 5.7 // Shunt resistance clc; clear; close; //given data : N=800;// turns I=10;// in A reluctance=150000;// in AT per Wb fi=(N*I)/reluctance; K=.15*10^-3;// in Wb turns/ division rs=0.025;// in ohm Ns=1; theta=120;//divisions S=(K*rs*theta)/((fi*Ns)-(K*theta)); disp(S,"The shunt resistance,S(ohm) = ")
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//EX2_12 PG-2.43 clc Tf_min=1;//fall time in micro second Trr_max=Tf_min/10 printf("the maximum recovery time is %.1f micro sec",Trr_max)
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clc //initialisation of variables vi= 0.0009992 //m^3 T= 60 //C T1= 20 //C T2= 40 //C vi1= 0.0010042 //m^3 vi2= 0.0009886 //m^3 v= 0.000951 //m^3 v1= 0.0009992 //m^3 v2= 0.0009956 //m^3 //CALCULATIONS B= (vi1-vi2)/(vi*(T-T1)) Kt= (v1-v2)/(v*(T2-T1)) Et= 1/Kt //RESULTS printf (' volume exapansion coeffic...
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//Scilab Code for Example 1.1 of Signals and systems by //P.Ramakrishna Rao //Determine whether the given signal is periodic or not //x(t)=10*(cos(10*pi*t))^2 clc; clear; syms t; x=10*(cos(10*%pi*t))^2; disp(x,'x(t)'); t=0:0.01:1; x=10*(cos(10*%pi*t))^2; t=0:0.01:1; plot(t,x,'r') title('x(t)'); xlabel('Ti...
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function y=foo(x) y=1+x^2 endfunction foo(2) // returns 5
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function [r,k]=mtlb_min(a) // Copyright INRIA // Copyright INRIA if ~isreal(a,0) then if size(a,1)==1|size(a,2)==1 then [r,k]=min(abs(a)) r=a(k) else [r,k]=min(abs(a),'r') r=a(k,:) end else a=real(a) if size(a,1)==1|size(a,2)==1 then [r,k]=min(a) else [r,k]=min(a,'r') end end
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//chapter 18 //example 18.10 //page 785 printf("\n") printf("given") I1=1*10^-3;Vref=1.25;Vo=6;Vs=15;Il=200*10^-3; R1=Vref/I1 R2=(Vo-Vref)/I1 Pd=(Vs-Vo)*Il; printf("regulated power dissipation is %3.2fW\n",Pd)
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clear; // function that determines p_i function y=fun1(x) y=sin(4*x*%pi)+1; endfunction // function that determines r_i function y=fun2(x) y=cos(2*x*%pi)+1; endfunction // function that determines tau function y=fun3(x) y=1/(x+1); endfunction cp=intg(0,1,fun1); cr=intg(0,1,fun2); ct=intg(...
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errcatch(-1,"stop");mode(2);//Example 1.3 ; ; R1=10*10^3; R2=100*10^3; Ri=R1;//Input Resistance Ro=0;//Output Resistance A=-(R2/R1);// Ideal Overall Gain printf("Ri=%.2f kohms",(Ri/1000)); printf("\nRo=%.f ohms",Ro); printf("\nA=%.2f V/V",A); exit();
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//Chapter-5,Example5_15_2,pg 5-42 //En=(n^2*h^2)/(8*m*e*L^2) n=1,2,3,.... //as width 'L' gets double ,the ground state energy becomes one-fourth E=5.6*10^-3 //Ground state energy of an electron E_new=E/4 ...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-1,Example 3,Page 7 //Title:Pressure drop //================================================================================================================ clear clc //INPUT rho_water=1000;//density of water...
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mode(0) global Rc Sc Tc gamm s=%s; z=%z; //TFcont = syslin('c',-280.14/((s-31.32)*(s+100)*(s+31.32))); TFcont = syslin('c',0.593/((47.21*s+1)*(1.373*s+1)))//second order //TFcont = syslin('c',0.594/(49.19*s+1))//first order SScont = tf2ss(TFcont); //TFdisc=ss2tf(SScont); Ts = 1; [B,A,k] = myc2d(SScont,Ts); //polynomi...
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clc; clear; a=0.82 //cell parameter in nm b=0.94 //cell parameter in nm c=0.75 //cell parameter in nm h=1 //x intercept of parallel plane k=2 // intercept of parallel plane l=3 //z intercept of parallel plane //calculation d_123=((h/a)^2+(k/b)^2+(l/c)^2)^(-1/2) d_246=d_123/2 mprintf("The interplanar distan...
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clear; clc; printf("\t Example 7.2\n"); //part(i) a1=229.7; //solubility at 60 degree a2=174.7; //solubility at 60 degree t1=68; // percentage of sodium nitrate t2=30.34; x1=a1/329.7 *100; //percentage of saturated solution at 50 degree tw=(t1/32)/(x1/t2); ...
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//clc() //f(x) = x^3 - 5*x^2 + 7*x -3 //f'(x) = 3*x^2 - 10*x + 7 disp("standard Newton Raphson method") for i = 1:7 if i == 1 then x(i) = 0; else x(i) = x(i-1) - ((x(i-1))^3 - 5*(x(i-1))^2 + 7*x(i-1) -3)/(3*(x(i-1))^2 - 10*(x(i-1)) + 7); et(i) = (1 - x(i)) * 100 / 1; ...
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//Height from which stone fell //refer fig.12.7 //Let the stone be dropped from A at a height h above window //h=(g*t^2)/2 ...(1) //h+2.45=((g)*(t+0.5)^2)/2 ...(2) //from (1) and (2) t=0.2495 //sec g=9.81 //m/sec^2 h=(g*t^2)/2 //m printf("\nh=%.3f m",h)
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clc; Idc=0.2; Vdc=30; C1=100; C2=100; L=5; f=50; RL=Vdc/Idc; y=5700/(L*C1*C2*RL); disp('%',y*100,"y=");
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//Chapter 2 //Example 2.10 //Page 68 clear; clc; R1 = 1000; R2 = 2000; R3 = 1000; C1 = 1; printf("Because the bridge is at null , we have \n ") printf("Z2*Z3 = Z1*Zx \n") printf("R2(R3-j/wC)=R1(Rx-j/wCx) \n") printf("The real and imaginary parts must be indpendently equal,so that \n") printf("Rx-(R2*...
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//find the z transform of a simple sequence function [za]=ztransfer(seq, n) z=poly(0, 'z','r') za=seq*(1/z)^n' endfunction //my sequence starts from n=0 to n=8 x1=[2 -1 3 2 1 0 2 3 -1] n=0:8 zz=ztransfer(x1,n) ​ //find the z transform of a simple sequence function [za]=ztransfer(seq, n) z=poly(0...
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// Computation of solubility from Ksp clear; clc; printf("\t Example 16.9\n"); Ksp=2.2*10^-20;//solubility product //Let 's' be the equilibrium concentration of the [Cu2+] and hence conc of [OH-] ions will be'2s', M, so Ksp=s*(2s)^2=4s^3 s=(Ksp/4)^(1/3);//concentration, M M=97.57;//mol mass of Cu(OH)2, g...
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warning('off'); fp=mopen('lines.dat','rb'); count=0; ch=mfscanf(fp,"%c"); while(~meof(fp)) count=count+1; ch=mfscanf(fp,"%c"); end mclose(fp); printf("Count= %d\n",count);
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//variable initialization m=9.1*10^-31; //mass of electron (kg) h=6.6*10^-34; //planck's constant (joule-second) e=1.6*10^-19; ...
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function[ssim_val] = ssim(srcImg, reference) srcMat = mattolist(srcImg) ssim_val = opencv_ssim(srcMat, reference) endfunction
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//PRACTICAL-3(SAMPLING) clc; n=0:1:100; fs=50; T=1/fs; t=n*T; figure; x1=cos(2*%pi*5*t); plot2d3(n,x1); figure; x2=cos(2*%pi*45*t); plot2d3(n,x2); figure; x3=cos(2*%pi*55*t); plot2d3(n,x3); figure; n=0:1:100; fs=0.02; T=1/fs; t=n*T; x=cos(2*%pi*0.02*t); plot2d3(n,x); figure; n=0:1:100; ...
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output-file divide.out, compare-to divide.cmp, output-list RAM[13]%D2.6.2 RAM[14]%D2.6.2 RAM[15]%D2.6.2 ; // Set test arguments set RAM[13] 35, set RAM[14] 5, set RAM[15] 0, set RAM[16] 0, set RAM[17] 0, set RAM[18] 0, set RAM[19] 0, set RAM[20] 0, set RAM[21] 0, set RAM[22] 0, repeat 250 { ticktock; } output; ...
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; checks bit vector sorts (set-logic QF_BV) (declare-fun x () (_ BitVec 4)) (declare-fun y () (_ BitVec 1)) (declare-fun z () (_ BitVec 4)) (declare-fun k () (_ BitVec 0)) (declare-fun k () (_ BitVecx 0)) (declare-fun k () (_ BitVec -1)) (declare-fun k () (_ BitVec)) (declare-fun k () (_ BitVec 1 2)) (assert (= x #b010...
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//Chapter 9 Ionic Equilibria and Buffer Action clc; clear; //Initialisation of Variables c= 0.010 //M Ksp= 1.56*10**-10 M= 108 //gms C= 10**-3 //M //CALCULATIONS K= Ksp/C m= M*K m1= M*c //RESULTS mprintf("The atomic weight of silver being %d, the weight of silver remaining \n in solution is %.2e gram",M,m) mprintf...
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dsp = mdaqDSPTask(); dsp.init("mdaqsignalmem.out", 100, -1); dsp.start(); dsp.write(1, 3.14); disp(dsp.read(1, 1, 10, -1)); disp(dsp.read(2, 1, 10, -1)); dsp.write(1, 6.14); disp(dsp.read(1, 1, 10, -1)); disp(dsp.read(2, 1, 10, -1)); dsp.stop(); return;
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errcatch(-1,"stop");mode(2);// Example 2.4 ; ; // Given data V0= 1;// in m^3 t= 300;// in °C V= V0*(1+t/273);// in m^3 disp(V,"The volume occupied in m^3 is : ") exit();
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clc; clear; funcprot(0); function [S0, V0] = BS_EuPut_FiDi_Explicit (r, sigma, a, b, m, nu_max, T, K) q = 2*r/sigma^2; delta_t_tilde = T*sigma^2/(2*nu_max); delta_x_tilde = (b-a)/m; x_tilde = a + [0:m].*delta_x_tilde; lambda = delta_t_tilde/delta_x_tilde^2; w = max(exp(0.5.*x_tilde(1:(m...
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clear; clc; printf('Example 11.7'); //Example 11.7 // Find Number of theoretical plates needed and the position of entry for the feed F = 100; //Feed [kmol] function[f]=Feed(x) f(1)=x(1)+x(2)-100; //Overall mass Balance f(2)=0.9*x(1)+.1*x(2)-(100*.4); //A bala...
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//Example 3.11 //Triangularization Method //Page no. 63 clc;clear;close; A=[1,3,8;1,4,3;1,3,4]; B=[4;-2;1]; printf('A can be factorizaed as follows:\n') printf('\tL\t\t *\t\tU\t\t =\t\tA') U(2,1)=0;U(3,1)=0;U(3,2)=0; L(1,2)=0;L(1,3)=0;L(2,3)=0; for i=1:3 L(i,i)=1 end for i=1:3 U(1,i)=A(1,i) e...
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//Initilization of variables m1=14 //kg m2=7 //kg theta=45 //degrees u_1=1/4 //coefficient of friction between mass 1 and plane u_2=3/8 //coefficient of friction between mass 2 and plane g=9.8 //m/s^2 //Calculations //The equations of motion for m1 are N1=m1*g*cosd(theta) //N F1=u_1*N1 //N //The equations of...
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clc clear //Input data td=7.5//Throat diameter in cm Ca=0.85//Coefficient of air flow fd=0.5//Diameter of fuel orifice in cm Cd=0.7//Coefficient of discharge l=5//Nozzle lip in mm x=1//Approach factor dpa=0.15//Pressure drop in kg/cm^2 da=1.29//Density of air in kg/m^3 dp=720//Density of fuel in kg/m^3 //...
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//The notation has been changed for ease //Calculations x=(5*1*3.5+8*1*0.5)/(5*1+8*1) //in y=(5*1*0.5+8*1*4)/13 //in //Moment of inertia Ix=(1/12)*(5)*(1^3)+(5*2.15*2.15)+(1/12)*(1*8^3)+(8*1.35^2) //in^4 Iy=(1/12)*(1)*(5^3)+(5*1.85*1.85)+(1/12)*(8)*(1^3)+(8*1.15^2) //in^4 Ixy=(8*1*(-1.15)*1.35)+(5*1*1.85*(-2.15...
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//value theorem// p=poly([9 1],'s','coeff') q=poly([3 7 1],'s','coeff') f=p/q; disp(f,"F(s)=") x=s*f; y=limit(x,s,0); // final value theorem disp(y,"f(inf)=") z=limit(x,s,%inf); // initial value theorem disp(z,"f(0)=")
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// Example 10.6, page no-270 clear clc ni=2.1*10^19//m^-3 mue=0.4//m^2/V-s muh=0.2 e=1.6*10^-19//C p=4.5*10^23//m^-3 sig=ni*e*(mue+muh) r=p*e*muh printf("The conductivity of intrinsic Ge is %.3f *10^-2 /ohm-cm\nThe intrinsic resistivity is %.2f *10^4",sig,r*10^-4)
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//Example 2.6.b : frequency clc; clear; close; //given data : format('v',9) Z=1;//for hydrozen n1=3; n2=2; m=6.626*10^-34;// mass of electron in kg E3=-(13.6*Z^2)/n1^2; E2=-(13.6*Z^2)/n2^2; del_E=E3-E2; E=del_E*1.6*10^-19;// in joules v=(E/m); disp(v,"frequency of the photon emitted,v(Hz) = ")
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//Chemical Engineering Thermodynamics //Chapter 14 //Thermodynamics of Chemical Reactions //Example 14.10 clear; clc; //Given //SO2(A) + (1/2)O2 (B) - SO3(C) //Basis: 1 Kgmole SO2 n_A = 1;//Kgmole of SO2 fed n_B = n_A;//Kgmole of O2 fed T1 = 273+400;//Temperature in K at which reactants enter To = 298;/...
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// sum 8-6 clc; clear; // 18 SWG=1.219MM in dia d=1.219; E=198.6*10^3; G=80.7*10^3; m=0.19; A=1783; sig=A/(d^m); Tys=(0.4*sig); Do=12.5; D=Do-d; C=D/d; Ks=((2*C)+1)/(2*C); W=(Tys*%pi*(d^3))/(8*D*Ks); Nt=13.5; Na=Nt-2; del=(8*W*(D^3)*Na)/(G*(d^4)); Ls=(Nt-1)*d; Lo=Ls+del+(0.15*del); // printing ...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/ALU.tst load ALU.hdl, output-file ALU.out, compare-to ALU.cmp, output-list x%B1.16.1 y%B1.16.1 zx%B1.1.1 nx%B1.1.1 zy%B1.1.1 ny%B1.1.1 f%B1.1.1 no%...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 2 : AC Circuits // Chapter 12 : Three Phase Circuit // Example 12 - 13 clear; clc; close; // // Given data P1 = 1560.0000; P2 = 2100.0000; Vp ...
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// Exa 2.25 clc; clear; close; format('v',6) // Given data Vin = 15;// in V // Peak output voltage, Vout = Vin;// in V disp(Vout,"Peak output voltage in V is");
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function [rectCorners, rectAxis] = rectBbox2D(points) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku University //Description: //Computes the minimal rectangular planar bounding box of the set of points. //The bounding box is not axis-aligned, and the longest direction of the bo...
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clear; clc; // Example: 9.6 // Page: 341 printf("Example - 9.6 and Page number - 341\n\n"); //Given T = 25+273.15;// [K] P = 1;// [atm] // Component 1 = water // Component 2 = methanol a = -3.2;// [cubic cm/mol] A constant V2 = 40.7;// [cubic cm/mol] Molar volume of pure component 2 (methanol) // V1_b...
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//style.fontSize=12; //style.displayedLabel="<table> <tr> <td><b>In</b></td> <td>nfet_i2v</td> <td align=right><b>Out</b></td> </tr> </table>"; //pal5 = xcosPalAddBlock(pal5,"nfet_i2v",[],style);
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0: [414560,217519,95800,422481] is powerSum(4) 2⁵5¹2591w + 217519x + 2³5²479y + 3¹140827z 1: [2767624,1390400,673865,2813001] is powerSum(4) 2³345953w + 2⁶5²11¹79x + 5¹307¹439y + 3¹937667z 2: [8332208,5507880,1705575,8707481] is powerSum(4) 2⁴520763w + 2³3¹5¹7¹79¹83x + 3¹5²22741y + 223¹39047z 3: [11289040,8282543,58700...
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// example:-2.3,page no.-31. //program to find the resulting fields by assumibg plane waves on either side of the current sheet and enforcing the boundary conditions. syms E x E1 E2 H1 H2 z Jo A B c N n d ko y; sym('n*(E2-E1)=0'); //boundary condition to be satisfied at z=0 sym('z*(E2-E1)=0'); // " " ...
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clc; clear; //Example 6.4 Cpf=3.98 //Specific heat of feed in kJ/(kg.K) lambda_s=2202 //Latent heat of conds of heat at 0.2MPa in [kJ/kg] lambda=2383 //Latent heat of vaporisation of water aty 323 [kJ/kg ic=0.1 //Initial concentration of soilds in [%] fc=0.5 //Final concentratio...
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############################################################################### # @file Makefile.tst # # @brief Builds up test programs. # # @author Yury GEORGIEVSKIY, CERN. # # @date Created on 13/01/2009 ############################################################################### # Makefile from current directory...
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load SimpleSub.asm, output-file SimpleSub.out, compare-to SimpleSub.cmp, output-list RAM[0]%D2.6.2 RAM[256]%D2.6.2; set RAM[0] 256, // initializes the stack pointer repeat 60 { // enough cycles to complete the execution ticktock; } output; // the stack pointer and the stack base
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//Exa 4.4 clc; clear; close; //given data : n=10;//no. of elements //d=lambda/4 separation in meter disp("For broad side array : ") disp("D=2*n/(lambda/d)"); disp("Putting d=lambda/4 we get D=2*n/4") D=2*n/4;//directivity : unitless Ddb=10*log10(D);//in db disp(Ddb,"For broad side array D in db = "); disp(...
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//Example 11-5 Lift and Drag of commercial Airplane m = 70000 //mass of commercial airplane [kg] A = 150 //wing planeform area [m^2] V = 558 //crusing speed of the plane [km/hr] rho_altitude = 0.312 //density of air at altitude of 12000m [kg/m^3] rho_ground = 1.2 //density of air on ground [kg/m^3] C_Lmax_flap = 3.48 /...
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0:00 zwölf 0:15 viertel nach zwölf 0:20 zwanzig nach zwölf 0:45 viertel vor eins 1:00 eins 1:15 viertel nach eins 1:45 viertel vor zwei 2:15 viertel nach zwei 3:15 viertel nach drei 4:29 neunundzwanzig nach vier 5:30 halb sechs 6:31 neunundzwanzig vor sieben 7:45 viertel vor acht 8:50 zehn vor neun 9:00 neun 12:00 zwöl...
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clc // Given that N = 6000 // Grating lines per cm w = 10 // Width in cm n = 2 // Order m =3 // Order lambda = 6000 // wavelength of light in angstrom // Sample Problem 39 on page no. 177 printf("\n # PROBLEM 39 # \n") printf(" Standard formula used \n") printf(" lambda/d_lambda = n*N \n") n_tot = w*N // T...
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//Checking the output of the function when a matrix of negative values is given as an input y=[10 10; 10 10;10 0]; y1=pow2db(y); disp(y1); //Output // 10. 10. // 10. 10. // 10. - Inf
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ScaleChange 1 0.3 StartSlowEndFast Wait 0.1 SendEvent 5 Wait 0.2 SendEvent 0
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clear; clc; b1 = 10;// inches d1 = 7/2;// inches r = 9/2;// inches b2 = 12;// inches d2 = 1/2;// inches l = 20;// feet n = 4;// factor of safety A_s = 7.19;// in^2 I_xx1 = 109.42;// in^4 I_yy1 = 7.42;// in^4 d = 0.97;// inches f_c = 21;// lb/in^2 a = 1/7500; A = 2*A_s + 4*b2*d2;// in^2 I_xx = 2*I_xx1 + ...
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clear clc G=[50 11 0 .08 30 11 0 .07] T=[50 11 220 .1 30 220 11 .09] B=[50 11] T(1,5)= T(1,3)/T(1,2) T(2,5)= T(2,3)/T(2,2) B(3)=B(2)* T(1,5) B(4)=B(3)* T(2,5) B(5)= B(3)^2/B(1) Z=555.6 z=Z/B(5) zt2=T(2,4) * B(1)/T(2,1) zg2=G(2,4) * B(1)/G(2,1) Zn=3 zn=Zn *3 / ( B(4)^2/B(1)) mprintf("ze...
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//page 144 clear; close; clc; disp('Suppose V is a plane spanned by v1=(1,0,0,0) and v2=(1,1,0,0).If W is the line spanned by w=(0,0,4,5),then w is orthogonal to both v''s.The line W will be orthogonal to the whole plane V.')
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//charger les scripts des fonctions laplacien et slaplacien exec('exo6_laplacien.sci',-1) exec('exo7_slaplacien.sci',-1) //la fonction principal qui calcul la difference du temps entre L*b et Ls*b //l'hypothese est que cette différence >= 0 function[val]=calcul_temps(D,n) //Calcul du temps d'exécution pour différents...
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//cal stress at A and B clc //solution //given W=3000//N T=10^6//N-mm P=15000//N d=50//mm x=250//mm pi=3.14 A=(pi/4)*d^2//mm^2//area of shaft f1=P/A//tensile stress at A and B M=W*x//N-mm Z=(pi/32)*d^3//mm^3 f2=M/Z//N/mm^2 fa=f1+f2//N/mm^2 fb=f2-f1//N/mm^2//tensile stress at B fs=16*T/(pi*d^3)//N/mm^3 ...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 3 : TRANSFORMERS // EXAMPLE : 3.22 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA S = 10 * 10 ^ 3; // Rating of the Two-winding Transformer ...
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clc //initialisation of variables H2= 0.75 //ft v1= 1 //ft/sec v2= 6 //ft/sec k= 1.433 //CALCULATIONS H1= H2*(v1/v2)^(2/3) Q1= k*H1^2.47 Q2= Q1*(H2/H1)^2.5 //RESULTS printf ('Flow = %.3f cuses ',Q2 )
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//Variable declaration: P = 1.2 //Abslute pressure of gas (psia) MW = 29 //Molecular weight of gas (g/gmol) R = 82.06 //Universal gas constant (atm.cm^3/gmol.K) T = 20+273 //Temperature in Kelvin (K) //Calculation: p = P*MW/R/T ...
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function GetColor(name,opacity) { cl=color(1,1,1); if name=="Red" then cl=color(0.8,0.15,0.4); if name=="Clock" then cl=color(0.8,0.7,0.3); if isvardefined("opacity") then cl.a=opacity; return(cl); }
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clc // Given that lambda = 5.896e-7 // wavelength of first light in meter lambda_ = 2.83e-7 // wavelength of second light in meter V1 = 0.12 // stopping potential for emitted electrons for first light in V V2 = 2.2 // stopping potential for emitted electrons for second light in V c = 3e8 // speed of light in m/sec e =...