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clc //Initialization of variables aZn=0.1 aCu=0.01 e1=0.763 //volt e2=0.337 //volt //calculations e0=e1+e2 Q=aZn/aCu E=e0- 0.05915*log10(Q) /2 //results printf("Emf of the cell = %.3f volts",E)
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//Variable declaration rho=1.5*10**-8; //resistivity of metal(ohm m) n=6.5*10**28; //number of free electrons(per m**3) e=1.602*10**-19; //charge(c) m=9.11*10**-31; //mass(kg) //Calculation tow=m/(n*e**2*rho); //relaxation time(s) //Result printf('relaxation time is %0.3f *10**-14 ...
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//Chapter 6, Problem 13 clc funcprot(0) //using Y-parameters given in the case study Yin=(18.33+%i*11.59)*10^-3 //in complex form y21=(1.09-%i*17.51)*10^-3 //in complex form y22=(0.3+%i*1.57)*10^-3 //in complex form Yl=3.33e-3 //defining a funcion deff('[b]=imp1(d)...
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clear clc //to find speed of ball // GIVEN: //refer to figure 12-6 on page no. 263 //lift of car y = 25//in meters //acceleration due to gravity g = 9.8//in m/s^2 // SOLUTION: //applying conservation of energy principle //speed of car v = sqrt(2*g*y)//in m/s printf ("\n\n Speed of car v = \n\n %...
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#it does not match the risto "optimum MMN" paper scenario = "PS3_roving_MMNpractice_04072014"; #adapted from "nvMMNa5_napls06122009"; #attenuation updated for ER1 insert earphones and X-fi gamer card pcl_file = "nvMMNCommands.pcl"; scenario_type = trials ; write_codes = true ; response_matching = simple_matching ; ...
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function H = homomorphic(I) //, gL, gH, D0, c) // HOMOMORPHIC_ // I: imagem em tons de cinza // gL: parâmetro da curva do filtro homomórifico, gL < 1 // gC: parâmetro da curva do filtro homomórifico, gH > 1 // D0: frequência de corte do filtro // c: parâmetro de controle de "sharpness" // // Uso: // I = imrea...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 2: Basic Laws // Example 2 - 5 clear; clc; close; // // Given data v = 20.00; R1 = 2.00; R2 = 3.00; // // Cal...
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clear; clc; function [resultado] = verifica_matriz(matriz) [linhas, colunas] = size(matriz); //verificando se é nula ou cheia elementos_diferentes_de_zero = 0; elementos_iguais_a_zero = 0; for i=1:linhas for j=1:colunas if(matriz(i, j) == 0) elementos_igua...
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//Compound pendulum //refer fig. 21.8 //Length of uniform rod l=0.6 //m //Radius of uniform disc r=0.3 //m //Mass moment of inertia about centre of suspention Iz=((25*0.6^2)/(9.81*12))+((25*0.6^2)/(9.81*2*2))+((40*0.15^2)/(2*9.81))+((40*(0.6+0.15)^2)/(9.81)) //units M=((25)/(9.81))+((40)/(9.81)) //Kzz^2=0.3...
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//Exa 11.3 clc; clear; close; //Given Data : format('v',9); FixedLoad=200;//in kW PF=0.8;//unitless cosfi=PF;//unitless h=10;//in hours/day d=300;//in days Time=h*d;//in hours Energy=FixedLoad*Time;//in kwh/year // (i) tarrif=Rs. 100/KVA/Annum plus 20 paise per kwh C1=100;//in Rs.year/KVA C2=20;//in pais...
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clear; warning off; exec('../Classificacao_gaussiana/geragauss.sce',-1); exec('../adaline/adaline.sce',-1); exec('../adaline/treina_adaline.sce',-1); exec('../Plota_Dados_E_Reta/plotdata.sce',-1); W = [rand()]; b = rand(); X = []; Yd = []; for i = 0:2:100, X = [X i]; Yd = [Yd ((i + 2))]; end //Grafico de dados e da...
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clc; L=1; //length in m r=0.2*10^-3; //radius in m A=%pi*(r)^2; //calculating area disp(A) R=2; //resistance in Ohm P=(R*A)/L; //calculating resistivity disp(P,"Resistivity in Ohm. metre = "); //displaying result
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// Example 4.11 // Mesh Analysis of a Current Amplifier R=[37 -1 0;-1 41 -4;0 -4 19]; // Resistance matrix //v_a=6*i_1 , v_b=4*(i_3-i_2) // [v_s]=[30*i_s;0;0]+[0 0 0;-864 0 0 ; 0 96 -96]*[i_1;i_2;i_3] i_s=10^-3; // Assumption R_tilda=[0 0 0;-864 0 0;0 96 -96]; v_s_tilda=[30*i_s;0;0]; // Using Equation, [R-R_til...
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//Caption:Read an RGB image and segment it using the threshold method //Fig11.32 //Page605 close; clc; I = imread('E:\DIP_JAYARAMAN\Chapter11\ararauna.png'); //SIVP toolbox //Conversion of RGB to YCbCr b = rgb2ycbcr_1(I); //SIVP toolbox [m,n,p]=size(b); b = uint8(b); //Threshold is applied only to Cb compone...
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// Grob's Basic Electronics 11e // Chapter No. 22 // Example No. 22_2 clc; clear; // An applied dc voltage of 10 V will produce a steady-state current of 100 mA in the 100-Ohms coil. How much is the current after 0.2 s? After 1 s? // Given data L = 20; // Inductor=20 Henry R = 100; // Resistor...
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syms t s a T y= integ(exp(-a*t-s*t),t,0,T)
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clc // Given that r = 4 // ratio of mass of particle to the rest mass // Sample Problem 6 on page no. 11.20 printf("\n # PROBLEM 6 # \n") printf(" Standard formula used \n") printf(" m = m_0/((1-v^2/c^2)^1/2) \n ") v = 3e8 * sqrt(1 - (1 / r)^2) printf("\n Speed of particle is %e meter/sec.",v)
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clc // initialization of variables clear E=72 //GPa v=0.33 Di=200 //mm Do=800 //mm a=100 //mm r=a b=Do/2 //mm p1=150 //MPa E=E*10^3 S_rr=p1*(a^2*(r^2-b^2))/(r^2*(b^2-a^2)) S_th=p1*(a^2*(r^2+b^2))/(r^2*(b^2-a^2)) S_zz=p1*a^2/(b^2-a^2) tau_max=(S_th-S_rr)/2 u_a=p1*a/(E*(b^2-a^2))*((1-2*v)*a^2+(1+v)*b^2) ...
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//Bending moment// pathname=get_absolute_file_path('9.06.sce') filename=pathname+filesep()+'9.06-data.sci' exec(filename) //Velocity in m/sec: V=s*5/18 //Reynolds number: Re=d*V*D/u //Value of Cd is obtained as: Cd=0.35; //Area(in m^2): A=L^2; //Moment about the chimney base(in N-m): M0=Cd*A*D/4*d*V^2 pri...
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//ques-16.25 //Calculating relaxation time and equilibrium constant clc ka=1.5*10^4; kb=3*10^5;//rate constants (in /s) R_T=1/(ka+kb);//relaxation time K=ka/kb;//equilibrium constant printf("Relaxation time is %.10f s and equilibrium constant is %.2f.",R_T,K);
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function [z]=RndIntT(n) //------------------------------- OK [lhs,rhs]=argn(0) if rhs <= 0 ; n=10000;end imin=-10; imax=10; y=RndInt(1,n,-10,10); i=imin-2:imax+2; z=[]; for i1=i, z=[z,prod(size(find(y==i1)))],end plot2d3("onn",i',z'/n,[1,2],"151","Simulation ",[-12,0,12,0.1]); i1=(imin:imax)'; plot2d1("onn",i1,ones(i1...
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function dS=f(t,S) ds1=S(2); ds2=(g*sin(teta)-(Evs(i)**2)*(ro)*(Cd)*(A)*(0.5)/(m)); dS=[ds1;ds2]; endfunction //Método de Adams S=ode("adams",S0,t0,t,f); plot(t,S(1,:),'y'); //Método de Runge Kutta de quarta ordem S=ode("rk4",S0,t0,t,f); plot(t,S(1,:),'y'); //Método de Runge Kutta de Fehlberg de ordens 4 e ...
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// Grob's Basic Electronics 11e // Chapter No. 25 // Example No. 25_6 clc; clear; // What is the ac resistance of the coil in A series circuit resonant at 0.4 MHz develops 100 mV across a 250-uH L with a 2-mV input. // Given data Vo = 100*10^-3; // Output voltage=100 mVolts Vi = 2*10^-3; // Input ...
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// This file is part of www.nand2tetris.org // written by Oded Wertheimer // File name: projects/04/divide/Divide.tst load Divide.asm, output-file Divide.out, compare-to Divide.cmp, output-list RAM[13]%D2.6.2 RAM[14]%D2.6.2 RAM[15]%D2.6.2; set RAM[13] 100, // Set test arguments set RAM[14] 5, repeat 50...
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//Exa 7.5 clc; clear; close; //Given data : format('v',6); VA=400;//in volt r=0.03;//in ohm/km r=0.03/1000;//in ohm/m RAB=r*500*2;//in ohm RBC=r*300*2;//in ohm RAB=r*700*2;//in ohm RAB=r*500*2;//in ohm //VA-VB=VAC+VCD+VDE+VEF+VFB;//in volt IA=(17.4)/(0.09);//in Ampere VAB=(RAB)*IA;//in volt VB=VA-VAB;/...
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clear; clc; // Example: 6.1 // Page: 197 printf("Example: 6.1 - Page: 197\n\n"); // Mathematics is involved in proving but just that no numerical computations are involved. // For prove refer to this example 6.1 on page number 197 of the book. printf(" Mathematics is involved in proving but just that no ...
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funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=round(sd*100)/100 if sd==60 then m=m+1 sd=0 end dms=[d m sd] endfunction theta=42+50.0/60;//latitudde in degree...
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clc //Example 18.2 //Calculate the energy per unit mass and heat dissipation rate v=0.82//m/s energy_per_unit_mass=v^2/2//J/Kg printf("The energy per unit mass is %f J/Kg\n",energy_per_unit_mass); //Let dissipation rate be denoted by eta //Let D denote d/dL DP=0.0286//Pa/m rho=1.2//Kg/m^3 eta=DP*v/rho//m^2/s^...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.16w //calculation of height of the image of an object placed along axis ,at a distance from a horizontal cylindrical glass rod //given data u=-20; //object distance (in cm) R=5; //radius of curvature of the spheric...
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// Scilab code Exa1.11.1 : To find the speed, mass and mass number of the ion which is accelerated in a mass spectrograph : Page 40 (2011) V = 1000; // Potential difference, volts R = 0.122; // Radius of the circular path, m B = 1500e-04; // Magnetic field, tesla e = 1.602e-019; // Charge of the electron, C amu = ...
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exec sp2triplet.sci rmdir('gentests/dotproduct', 's') mkdir('gentests') mkdir('gentests', 'dotproduct') sz = stacksize() stacksize(50000000) ns = [10 100] for n=ns for d = 0.1:0.1:0.5 for count = 1:10 printf("n=%d d=%d c=%d\n", int(n), int(d*100), int(count)); A = sprand(n,1,d); if(abs(A(n,1)) < 1) A...
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clc clear //Initialization of variables p1=20 //psia p2=140 //psia J=778 t2=150 //F t1=30 //F //calculations disp("From Table A-3,") v1=2.0884 //cu ft/lb v2=0.33350 //cu ft/lb h2=95.709 h1=81.842 n=log(p2/p1) /log(v1/v2) W=(p2*v2-p1*v1)*144/(1-n) du=h2-h1 + (p1*v1-p2*v2)*144/J Q=du+W/J s2=0.17718 s1=...
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clc clear //Input data Mol=39.9 //Molar mass of a gas in kg/mol k=1.67 //Specific heat ratio Mx=2.5 //Mach number before the shock Px=40 //Pressure before the shock in kPa Tx=-20+273 //Temperature before the shock in K //Calculation My=0.554 //Mach number after the shock from gas tables @Mx p1=7.567 //...
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function [F]=deriva(f,ra) F=numderivative (f,x); F=F(ra); endfunction
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//EX10_17 PG-10.65 clc disp("Refer to the figure-10.59 shown") Rf=10e3;//feedback resistance R1=10e3; R2=20e3; R3=30e3; R4=40e3; V1=-1;//first input voltage at the inverting terminal V2=2;//second input voltage at the inverting terminal V3=3;//third input voltage at the inverting terminal V4=-2;//fourth inp...
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function r=%ip_m_s(ip,s) // ip*s if size(s,'*')<>1 then error(10),end r=(ip(1)*s):(ip(2)*s):(ip(3)*s)
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Project3D Prism Ortho basis P=6 Q=7</description> <executable>LocProject3D</executable> <parameters>7 1 1 2 6 6 6 7 7 6 0 0 0 1 0 0 1 1 0 0 1 0 0.5 0 1 0.5 1 1</parameters> <metrics> <metric type="L2" id="1"> <value tole...
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clear; clc; // Illustration 6.2 // Page: 157 printf('Illustration 6.2 - Page: 157\n\n'); // solution //****Data****// // a = N2 b = H2O L = 9.5*10^(-4);// [cubic m/s] G = 0.061;// [kg/s] Temp = 273+25;// [K] //*****// printf("Construction Arrangement\n"); printf("Use 4 vertical wall baffles, 100 ...
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//Exa 3.3 //To determine received power and allowable Path loss. clc; clear all; d=3*1000;//in metres Y=4;// path loss exponent Pt=4; //Transmitted power in watts f=1800*10^6;//in Hz Shadow=10.5; //in dB d0=100;//in metres P0=-32; //in dBm //solution disp("Using equation 3.11 and including shadow ...
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clear; clc; m = 15; t = 18000;// lb/in^2 c = 700;// lb/in^2 b = 12;;// inches M = 900000;//bending moment lb/inches k1 = 1/((t/(m*c))+1);//k = n/d k2 = 1-k1/3;//k2 = a/d p = 0.5*c*k1/(t); d = sqrt(M/(0.5*c*b*k1*k2));//inches A_t = p*b*d;// sq.inches A_t_previous = 0.25*%pi*(7/8)^2;//section area with diamet...
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clc clear //Input data c1=7;//Velocity of air at entrance in m/s c2=5;//Velocity of air at exit in m/s p1=100;//Pressure at the entrance in kPa p2=700;//Pressure at the exit in kPa v1=0.95;//Specific volume at entrance in m^3/kg v2=0.19;//Specific volume at exit in m^3/kg u=90;//Change in internal energy of th...
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n=4; function [y]=g(u1,u2,u3,u4) y=(u1+u2)/(1+u3-u4) endfunction function [y]=tn() U=grand(4,1,'def'); y=-log(prod(U)); endfunction function [y]=simG() vs=gsort(grand(n-1,1,'def'),'g','i'); vs($+1)=1; t=tn(); us(1)=exp(-t*vs(1)); for j=[2:n], us(j)=exp(-t*(vs(j)-vs(j-1))); end; y=g(us(1),us(2)...
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clc; N = input("Enter number of channels: "); cc = input("Enter number of control channels: "); vc = (N-cc); K = input("Enter size of the cluster: "); Matrix = zeros(K, ceil(N/K)); disp('Fixed Channel Allocation') vcpc = floor(vc./K); ccpc = floor(cc./K); disp(vcpc,"Number of Voice channels per cell are") disp(ccpc,"Nu...
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clc; clear; V=3.3; f=50; P=10; S=0.03; I=4;//Magnetizing current Lc=30;//core loss Zsl=0.18+(1.6*%i);//stator leakage impedance Zrl=0.4+(1.6*%i);//Rotor stan still leakage impedance W=27*10^2; Vph=1.9;//Rated phase voltage Ibsc=W/(3*Vph);//Bus bar short circuit current level Zs1=(Vph/Ibsc)*%i;//The effecti...
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disp('chapter 4 ex4.1') disp('given') disp('capacitor coupled voltage follower design') disp("lower cut off frequency for the circuit =50Hz") disp('Rl=3.9kohms') disp("R1max=0.1Vbe/Ibmax") disp("Vbe=0.7volts") disp("Ibmax=500nA") Vbe=0.7 Ibmax=500*10^(-9) R1max=0.1* Vbe/ Ibmax disp("R1max= ",R1max) disp("a...
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-5, Illustration 6, Page 118 //Title: Calculation of different concentrations in vaporization process //============================...
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clear; clc; // Definição da função f(x) function y = f(x) y = log(x) - 1 endfunction // Implementação Secante function [it, x, Er] = secante(x0, x1, p, itMax) it = 0; Er = 1; xOld1 = x0; x = x1; while (Er > 10^(-p) & it < itMax) xOld0 = xOld1; xOld1 = x; ...
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//Example 5.7, Page number 5.29 clc;clear;close // variable declaration a=5;//unitless n1=1.48;//unitless delta=0.01;//unitless V=25;// V number // Calculation lamda=(%pi*(a*10**-6)*n1*sqrt(2*delta))/V // Cutoff Wavelength // Result printf("Cutoff Wavellength = %.3f micro-m",(lamda*10**7))
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@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005] ...
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// Example 6.21.3 page 6.60 clc; clear; tr=50; //radiative recombination lifetime tnr=110; //non-radiative recombination lifetime h=6.624d-34; //plank's constant c=3d8; //speed of light q=1.6d-19; //charge of electron i=40d-3; //current lamda=0.87d-6; //wavelength t=tr*tnr/(tr+t...
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clc; //E=Ef+1% of Ef k=1.38*1e-23;//boltzman constant e=1.6*1e-19;//charge of electron E=0.0555; //0.1=1/[(exp((E*e)/(k*T)))+1] T=E*e/(k*log(9));//Temprature disp(+'kelvin',T,'Temprature = '); //there is slight variation than book's answer.. checked in calculator also.(book's mistake)
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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// Example 11.1 // Calculation of the minimum number of taps needed to compensate for the fiber dispersion // Page no 509 clc; clear; close; // Given data b=22*10^-27; // Power launched in port 1 l=800*10^3; // Power launched in port 2 T=50*10^-12; // Power l...
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clc //initialisation of variables g= 32.2 //ft/sec^2 //CALCULATIONS v= sqrt(32*g) //RESULTS printf ('speed that delivery commence= %.1f ft/sec',v)
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// Scilab code: Ex3.19 : Total energy of the three electron system:Pg: 87 (2008) m = 9.1e-031; // Mass of an electron, kg h = 6.624e-034; // Plancks constant, joule second a = 1e-010; // Length of the molecule, m E = 6*h^2/(8*m*a^2); // Energy of three electron system, joule printf("\nThe total energy ...
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R1 = 200e3; R2 = 8.06e6; C1 = 100e-9; C3 = 1e-9; s = poly(0, 's') z=poly(0,'z'); H = syslin('c', (1 + (C1*R2)*s), ( (C3+C1)*R1*s+R1*C1*C3*R2*s^2 ) ) // math model of regulator H_ss = tf2ss(H) // convert to ss H_z = cls2dls(H_ss,0.00001) // bilinear transform disp(H) disp(H_z) subplot(1,2,1) bode(H_ss) subplot(1,...
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53 39 data for surfaces useful for cost information Number, Name, Construction, class, area, grossarea 7,ZN_1_FLR_1_SEC_1_WALL_1,ASHRAE 30PERC GUIDE_ZONE 5_STEEL-FRAMED_EXT-WALL,Wall, 91.20038, 152.00000 8,ZN_1_FLR_1_SEC_1_WALL_1_WINDOW_1,ASHRAE 30PERC GUIDE_ZONE 5_0.3_0.4_FIXED_SO...
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//Copyright [2015] [FINESCE Consortium] // //Licensed under the Apache License, Version 2.0 (the "License"); //you may not use this file except in compliance with the License. //You may obtain a copy of the License at // // http://www.apache.org/licenses/LICENSE-2.0 // //Unless required by applicable law or agreed t...
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//******************************************* // This is the Scilab script for Exercise 17. // // Use the help facility for more information // on individual functions used. // // Author: J. Kaempf, 2015 (updated) //******************************************** clf; scf(0); a=gcf(); a.figure_size= [1000,500];...
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exa_8_10.sce
// Exa 8.10 clc; clear; close; //given data V_REF= -5;// in V V_B= 0;// in volt V_A= -5;// in volt V_C=V_A; V_D=V_C; Vout= -1*(V_A+V_B/2+V_C/4+V_D/8);// in volt disp(Vout,"Output voltage in volt")
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fq.sce
// quadrique associée à une matrice 2x2 //// points critiques non-dégénérés /////////// Q = eye(2,2) // minimum : x^2 + y^2 //Q = [0,1;1,0] // point selle : 2xy //Q = [1,0;0,-1] // point selle : x^2 - y^2 //Q = - eye(2,2) // maximum : - x^2 - y^2 //// points critiques dégénérés /////////// //Q = [1 0; 0 0] //...
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Alexis-Linke.sci
// ----------------------------------------------------------------------- /// \brief Calcule un terme de contrainte a partir d'une homographie. /// /// \param H: matrice 3*3 définissant l'homographie. /// \param i: premiere colonne. /// \param j: deuxieme colonne. /// \return vecteur definissant le terme de contra...
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10Ex20.sce
//chapter 10 Ex 20 clc; clear; close; spends=75/100; inc=20/100; expPercent=10/100; original=100; expAmt=original*spends; saving=original-expAmt; newIncome=original*(1+inc); newExp=(1+expPercent)*expAmt; newSaving=newIncome-newExp; incSaving=newSaving-saving; incPercent=(incSaving/(1-spends)); mprintf("T...
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9_5_2.sce
clc pathname=get_absolute_file_path('9_5_2.sce') filename=pathname+filesep()+'952.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") function[Cp]=fun1(T) Cp=34.31*10^(-3)+ T*5.469*10^(-5) + T^2 * 0.3661 *10^(-8) - T^3 * 11...
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Midair rockets.sce
Name=Midair rockets PlayerCharacters=QC no movement BotCharacters=target_decay_midair.bot IsChallenge=true Timelimit=100.0 PlayerProfile=QC no movement AddedBots=target_decay_midair.bot PlayerMaxLives=0 BotMaxLives=100 PlayerTeam=1 BotTeams=2 MapName=169_many_weird.map MapScale=1.0 BlockProjectilePredictor...
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ex14_6.sce
//Calculate the output voltage clear; clc; //soltion //given Ad=2000; //differential mode gain CMRR=10000; V1=10^-3;//V V2=0.9*10^-3;//V Vd=V1-V2; Vc=(V1+V2)/2; Vo=Ad*Vd*(1+Vc/(CMRR*Vd)); printf("The output voltage is %.2f mV",Vo*1000);
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ex5_1.sce
// Exa 5.1 clc; clear; close; format('v',6) // Given data R = 20;// in ohm X_L = 15;// in ohm V_L = 400;// in V f = 50;// in Hz V_Ph = V_L/sqrt(3);// in V Z_Ph = sqrt( (R^2) + (X_L^2) );// in ohm I_Ph = V_Ph/Z_Ph;// in A I_L = I_Ph;// in A disp(I_L,"The line current in A is"); //pf = cos(phi) = R_Ph/Z_Ph...
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example16_2.sce
clc // Given that t = 0 // temperature in K E = 7.9 // Fermi energy in eV e = 1.6e-19 // charge on an electron in C m = 9.1e-31 // mass of electron in kg // Sample Problem 2 on page no. 16.14 printf("\n # PROBLEM 2 # \n") printf("Standard formula used \n") printf("1/2 * m*v^2 = E_0 \n") E_ = E * 3 / 5 v = sqrt(2 * E_...
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ex_47.sce
I1=6; R1=1; R2=2; R3=5; V=10; I2=(2*I1-10)/7; IR2=(I1-I2); disp("Amperes",IR2,"Current in 2 Ohm resistor")
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zpkdata.sci
// ############################################################################ // Devuelve 3 vectores con los ceros, polos y ganancia (alta frec.) del sistema que se le pasa en el argumento function [z,p,k]=zpkdata(sys) if typeof(sys)=='state-space' sys=ss2tf(sys) end z=roots(numer(sys)) p=roots(denom(...
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portfoliobk.tst
<!DOCTYPE html> <html lang="pt"> <head> <meta charset="utf-8"> <title>Leandro Medeiros</title> <meta name="viewport" content="width=device-width, initial-scale=0.7"> <meta name="description" content="Clean responsive bootstrap website template"> <meta name="author" content=""> <!-- styles --> <link href=...
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ex_4.sce
// The equation cos(x)-x*%e^x==0 has real roots. // the graph of this function can be observed here. xset('window',3); x=0:.01:2; // defining the range of x. deff('[y...
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test_cases.tst
Random Round Result 66.34189842 0 66 38.15132711 0 38 -48.19796704 0 -48 -96.41723101 0 -96 -54.74978397 0 -55 45.20206872 0 45 66.67510482 0 67 -37.69107352 0 -38 86.39471088 0 86 64.07815336 0 64 0.237804701 0 0 -31.0271507 0 -31 94.6576568 0 95 -98.68337689 0 -99 -38.83397149 0 -39 -8.471977678 0 -8 84.04433293 0 84...
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EX10_4.sce
//Finding of Bottom slope, Conveyance //Given q=0.1; B=0.6; y=0.3; A=B*y; n=0.013; P=1.2; R=A/P; //To Find b=((q^2)*(P))/((A^3)*B^2) K=A*B*sqrt(R); disp("Bed of slope ="+string(b)+" no units"); disp("conveyance of channel ="+string(K)+" m^3/sec");
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My First Map.sce
Name=My First Map PlayerCharacters=Camera Man BotCharacters=crocbot.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Camera Man AddedBots=crocbot.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=0 MapName=test101.map MapScale=4.0 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=f...
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wpu-rencana-content.tst
RENCANA KONTEN WPU -Vidio tutorian EFI *dasar-dasar engine *kelitrikan body standart *wiring diagram -Membuat trobel code -ingine visual
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Example43_10.sce
//Given that e = 1.6*10^-19 //conversion from electron volt to Joule deltaE = 0.20*e h = 6.62*10^-34 //in J.s //Sample Problem 43-10 txt = mopen('Example43_10_result.txt','wt') mfprintf(txt, '**Sample Problem 43-9**\n') Tavg = h/(2*%pi)/deltaE mfprintf(txt, 'The average life of the compound is %esec', Tavg)...
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minus.tst
void main () { int i = 1 - 2 - 3 - 4 - 5; int j = 1 - 2 - 3 - 4 - 5; int k = 1 - 2 - 3 - 4 - 5; print ("i", i, "\n"); }
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Stratégie semi-circulaire deterministe.sci
clf; function newq = insere(q, ta, ts) // // Inscription de l'arrivée d'une requête //dans la file q, //au temps ta //avec un temps de service ts if q($, 1) < ta then // aucune requête dans le système q($+1,:) = [ta, 1, 1]; // ajout de la requête en fin de liste else // inscription ...
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Ex1_26.sce
clc //to calculate proton gain in mass c=3*10^8 //light speed(m/s) K=500*10^6*1.6*10^-19 //kinetic energy (J) deltam=K/c^2 disp("proton gain in mass is delm="+string(deltam)+"kg") //answer is given wrong in the book=8.89*10^28 kg
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sistemas lineares - jacobi.sce
clear; clc; // Implementação resolução pelo método de Jacobi function [x, Er]= jacobi(A,b,x0,n) [l,c]=size(A) erro = 1; cont = 1; x = x0; while (cont <= n) xa = x for i = 1:l soma=0; for j = 1:l if(j~=i) then ...
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//EXAMPLE 7-2 PG NO-437-438 Z11=99+%i*99; Z12=-%i*100; Z21=20-%i*102.26; Z22=90.06-%i*120; Z1=Z11-Z12; disp('i) Impedance (Z1) is in rectangular form = '+string (Z1) +'ohm '); Z2=Z22-Z12; disp('ii) Impedance (Z2) is in rectangular form = '+string (Z2) +'ohm '); Z3=...
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//fibo clc s=zeros(1,10) s(1)=1; s(2)=1; for i=3:10 s(i)=s(i-2)+s(i-1) end disp(s)
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// Exa 6.13 format('v',6) clc; clear; close; // Given data R_B= 200*10^3;// in Ω R_C= 20*10^3;// in Ω V_CC= 20;// in V V_BE= 0.7;// in V Beta= 100; // The value of collector current I_C= (V_CC-V_BE)/(R_C+R_B/Beta);// in A // The collector to emitter voltage V_CE= V_CC-I_C*R_C;// in V // The stability fac...
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week-2-q1.sce
clear; for i = 1:20 if ~modulo(i, 15) printf("Fizz-Buzz\n"); elseif ~modulo(i, 5) printf("Buzz\n"); elseif ~modulo(i, 3) printf("Fizz\n"); else printf("%d\n", i); end end // i
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Ex18_1.sce
// Example 18_1 clc;funcprot(0); // Given data T=20+273.15;// K m=1.00;// kg R=296;// J/kg.K M=28.0;// kg/kgmole N_o=6.022*10^26;// molecules/kgmole k=1.380*10^-23;// J/molecule.K // Calculation // (a) V_rms=sqrt(3*R*T);// The kinetic theory root mean square molecular velocity in m/s // (b) m_molecule=M/...
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clc; // after changing dc supply terminals from phase a to phase b disp('case a'); P=2; // number of poles te=(2/P)*120; printf('Number of mechanical degrees through which rotor moves is %d degrees\n',te); disp('case b'); P=4; // number of poles te=(2/P)*120; printf('Number of mechanical degrees through whi...
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Ch01Ex23.sce
// Scilab Code Ex 1.23 Page-34 (2006) clc; clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV h = 6.626e-034; // Planck's constant, Js c = 3.0e+08; // Speed of light, m/s E_K = 13.6*29^2; // Energy of electron in the K-shell E_L = 13.6*29^2/4; // Energy of electron in the L-shell // As E_K - E_L = h*c...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>NS, Couette flow, mixed bcs, WeakDG advection and LDG diffusion, MODIFIED</description> <executable>CompressibleFlowSolver</executable> <parameters>Couette_WeakDG_LDG_adiabatic.xml</parameters> <files> <file description="Session File">Co...
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Exa_2_39.sce
//Exa 2.39 clc; clear; close; format('v',8); //Given Data : mdot=0.4;//Kg/s C1=6;//m/s p1=1;//bar p1=p1*100;//KPa V1=0.16;//m^3/Kg u2subu1=88;//KJ/Kg Qdot=-59;//W Qdot=Qdot/1000;//KJ/s W=0.059;//KJ/ Gamma=1.4; Z2subZ1=0; h2subh1=Gamma*u2subu1;//KJ Wdot=Qdot-mdot*(h2subh1);//As C1=C2, C2^2-C1^2=0 & ...
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ex4_7.sce
clc; Va=-10; //voltage in volts W=100; //work in Joule q=2; //charge in Coulomb v=(Va)+(W/q); //calculating v disp(v,"Voltage in Volts = "); //displaying result
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Ex17_11.sce
//Initilization of variables d=0.6 //m T_t=800 //N T_s=180 //N w=200 //rpm //Calculations r=d/2 //m radius //Torque M=(T_t-T_s)*r //N.m //Power w_new=(2*%pi*w)/60 //rad/s Power=M*(w_new) //W //Result clc printf('The power transmitted is %f W',Power)
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Example11_5.sce
//Example 11.5 clc; clear; close; format('v',8); //Given data : Cd=0.66;//constant H=0.15;//meter L=0.40;//meter g=9.81;//constant Q=2/3*Cd*sqrt(2*g)*L*H^(3/2);//m^3/s disp(Q,"Discharge in m^3/sec : "); disp(Q*10^3,"Discharge in litres/sec : ");
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//Example_a_9_6 page no:406 clc; Vl=400; Vrnmag=400/sqrt(3); Vrnang=0; Vynmag=400/sqrt(3); Vrnang=-120; Vbnmag=400/sqrt(3); Vrnang=-240; R=10; omega=314; L=1; C=100*10^-6; Yph=(1/R)+(1/(%i*omega*L))+(%i*omega*C); Iph=Vrnmag*Yph;//multiplication of Vrnmag and Yph is rounded off in text book so output line ...
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sffs_set_sebit.tst
48 of 475 branches covered (10%) /* *------------------------------------------------------------ * Project: cagOS * Goal: * Copyright (c) 2013, 2014 CAG Systems, Inc. *-------------------------------------------------------...
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Ex7_9.sce
clear // // // //Variable declaration theta=30*%pi/180 //glancing angle(radian) h=1 k=1 l=1 lamda=1.5418 //wavelength(angstrom) n=1 //order //Calculation d=n*lamda/(2*sin(theta)) //interplanar spacing(angstrom) a=d*sqrt((h**2)+(k**2)+(l**2)) //interatomic spacing(angstrom...
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clc(); clear // To find the time required for the billet to remain in the oven A = 2; // Length of steel billet in ft B = 2; // Breadth of billet in ft C = 4; // Height of billet in ft To = 70; ...
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ex5_29.sce
// Exa 5.29 clc; clear; close; format('v',6) // Given data L = 0.01;// in H C = 10;// in pF C = C * 10^-12;// in F // The frequency of oscillation f = 1/(2*%pi*sqrt(L*C));// in Hz f = f * 10^-3;// in kHz disp(f,"The frequency of oscillation in kHz is"); // Note: In the book, the calculation is wrong.
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rlocus_ex1-old.sce
H = tf(1,[1 -1 0],-1); evans(H) H = tf(1,[1 -1 1 0],-1); evans(H) // Default xset('window',1) evans(H,5) // kmax = 5 k=-1/real(horner(H,[1,%i]*locate(1)))