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R2=1.1//rotor resistance per phase //at 60 Hz supply f=60//frequency of supply P=6//no. of poles Ns1=120*f/P//synchronous speed Nr=1000//speed of rotor s_m1=(Ns1-Nr)/Ns1//slip at maximum torque X2=R2/s_m1 L2=X2/(2*%pi*60) //at 50 Hz supply X2=2*%pi*50*L2 s_m2=R2/X2//slip at maximum torque Ns2=120*50/6//sy...
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clc //initialisation of variables clear q= 26.45 //coloumbs e= 2.432 //volts //CALCULATIONS Q1= q*e Q2= Q1*1.0002*10^7 //RESULTS printf ('Energy expenditure in joules = %.2f int.joules',Q1) printf ('\n Energy expenditure in ergs = %.2e ergs',Q2)
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// Reading on ammeters when their shunts are interchanged clc; clear; I=10; Ra=1000; Rsa=0.02; Rb=1500; Rsb=0.01; deff('x=cur(y,z)','x=I*z/y') Ia1=cur(Ra,Rsa); // Initial Current in meter A Ia2=cur(Ra,Rsb); // Changed Current in meter A Ib1=cur(Rb,Rsb); // Initial Current in meter B Ib2=cur(Rb,R...
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Name=Lurkins aim trainer hard PlayerCharacters=A BotCharacters=fortnite w keyer.bot;fortnite w keyer.bot;Bot Profile.bot IsChallenge=true Timelimit=60.0 PlayerProfile=A AddedBots=fortnite w keyer.bot;fortnite w keyer.bot;Bot Profile.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=0 BotTeams=0;0;0 MapNa...
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scenario = "CC-Switch-Behavioral_Youcai_eyetracker"; $Version = "Youcai_1.0"; $eye_tracker = "true"; $gray_calibration_screen = "125, 125, 125"; # the default_background_color for calibration screen $TR = 3000; # scenario_type = fMRI_emulation; scan_period = $TR; $pulse_button = 1; active_buttons = 3; button_code...
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v=20; disp("Part a"); d=0.5*10^(-3); e=v/d; disp("the electric field intensity (in kV/m) is"); disp(e*10^(-3)); disp("Part b"); d1=0.25*10^(-3); e1=v/d1; disp("the electric field intensity (in kV/m) is"); disp(e1*10^(-3));
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function [S_r, f_r, t_r] = specgram(x,n,fs,window,overlap) funcprot(0); rhs = argn(2) if(rhs<1 | rhs>5) error("Wrong number of input arguments.") end select(rhs) case 1 then [S_r, f_r, t_r] = callOctave("specgram",x) case 2 then [S_r, f_r, t_r] = callOctave("specgram",x,n) case 3 then [S_r, f_r, t_r] = callOct...
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//To find addendum clc //Given: T=40, t=T phi=20 //degrees m=6 //mm //Solution: //Calculating the circular pitch pc=%pi*m //mm //Calculating the length of arc of contact Lac=1.75*pc //Length of arc of contact, mm //Calculating the length of path of contact Lpc=Lac*cosd(phi) //Length of path of contact, mm ...
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clc clear //Input data N=16000//Speed in rpm T1=17+273//Temperature in K rp=4//Pressure ratio in=82//Isentropic efficiency in percent s=0.85//Slip factor a=20//Angle in degrees d=200//Diameter in mm V=120//Velocity in m/s cp=1.005//Specific heat in kJ/kg.K g=1.4//Ratio of specific heats //Calculations ...
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//Find the value of Id clear; clc; //soltion //given Vt=1.5;//V //threshold voltage Id=2*10^-3;//A Vgs=3;//V //gate supply Vds=5;//V //saturation voltage Vdsm=Vgs-Vt; //minimum voltage required to pinch off // Vds > Vdsm therefore the device is in saturation region // Calculating K K...
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clc; disp("Example 2.8"); Y=1.41; //Young's Modulus. R=1.293*10^-3; //Density of air in g/centimetre cube. P=76*13.6*980; //atmospheric pressure in dyne/cm square. V=sqrt((Y*P)/R); //calculating speed using young's modulus. disp(V,"Speed of ultrasonic wave in air at n.t.p. in cm/sec = "); ...
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exec("swigtest.start", -1); // Functions checkequal(foo(int32([1, 2, 3])), "foo:int[SIZE]", "foo(int[SIZE])"); checkequal(foo([1, 2, 3]), "foo:double[SIZE]", "foo(double[SIZE])"); checkequal(foo(["1" "2" "3"]), "foo:char *[SIZE]", "foo(char *[SIZE])"); // Class methods s = new_Spam(); checkequal(Spam_foo(s, int32([...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_SSYS.sci"); codeblock readtextfile(ScriptFilePath+"\_SkyViewTools.sci"); mydata=map; mydata.longit=(3+43/60.0)/180*Pi; mydata.lattit=(51+3/60.0)/180*Pi; InitSkyView(ref(mydata)); SetViewPosition(0,deg2rad(51)); root.time=time(2011,6...
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function y1=formula(u1); y1=-5169*u1*u1+21240*u1+6135; disp(y1); endfunction
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// Example 6_11 clc;funcprot(0); // Given data // From example 6.10 P_1=140;// The steam pressure at turbine inlet in psia T_1=1000;// The temperature at turbine inlet in °F P_2=2;// The steam pressure at turbine exit in psia m=4;// lbm/sec W_s=1748;// Btu/sec n_t=0.80;// The isentropic efficiency of the turbi...
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//Chemical Engineering Thermodynamics //Chapter 13 //Thermodynamics in Phase Equilibria //Example 13.5 clear; clc; //Given //The given example is a theoretical problem and does not contain any numerical computation //end
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//pathname=get_absolute_file_path('11.18.sce') //filename=pathname+filesep()+'11.18-data.sci' //exec(filename) //Rate at which steam is generated(in kg/hr): r=5000 //Pressure of steam(in bar): p=20 //Dryness fraction: x=0.98 //Temperature of feed water(in C): T=60 //Rate at which coal is supplied(in kg/hr): ...
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clear // // // //Variable declaration H=6.5*10^-4; //magnetizing force(amp/m) M=1.4; //magnetic field(T) //Calculation chi=M/H; mewr=1+chi; //relative permeability //Result printf("\n relative permeability is %0.3f ",mewr) printf("\n answer in the book is wrong")
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naturalConvection_cavity_dx.tst
<?xml version="1.0" encoding="ISO-8859-1"?> <!--______________________________________________________________________ # # Parametric study to reproduce the results in the reference. # The domain length was computed using the script: # cavityFlowParameters.m # # Note you have to let the problems run for a long time...
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//Variable Declaration x1 = [1,2,3,4] // Domain of f(x) x2 = [0,1,2,3,4] // Domain of h(x) // calculations f = (x1-2)/2.0 // list of values of f(x) h = (x2^2)/25.0 // list of values of h(x) //Results if(sum(f) ~= 1 ) then printf ( "f(x) can not serve as p...
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// Exa 4.28 clc; clear; close; // Given data V_B = 4;// in V V_BE = 0.7;// in V R_E = 1.2;// in kohm R_E= R_E*10^3;// in ohm V_E = V_B-V_BE;// in V R_C = 2.2;// in kohm R_C= R_C*10^3;// in ohm R_B= 330;// in kohm R_B= R_B*10^3;// in ohm bita = 180; I_B = 7.11 * 10^-6;// in A V_CC = 18;// in V disp("Par...
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//Example 4.10 clc //i=integer type //x=float type //c=character type printf("Enter values for i , x and c in respective order"); printf("\n [Enter values in single line seperated by spaces]) "); [n,i, x,c]=mscanf("%3d %5f %c"); disp(i,"i = "); disp(x,"x = "); disp(c," c = "...
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clc; nH=0.5;//kmole m_O=32; VH!VO=2; x=m_O*nH/VH!VO; disp("mass of oxygen required is:"); disp("kg",x) nO=x/m_O; n=nH+nO; R_=8.3145; T=288;//K p=1;//bar V=n*R_*T*10^3/(p*10^5); disp("Volume of container is:"); disp("m^3",V);
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s=%s sys=syslin('c',(k)/(s*(s+2))) evans(sys) printf("there are 2 branches approaching infinity")
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//Example 3.2. format(6) me=1000*9.1*10^-31 disp(me,"Mass of the charged particle(kg) = 1000 times the mass of an electron =") disp("The charge of the partical = 1.6*10^-19 C") q=1.6*10^-19 //charge of the particle V=1000 //potential difference format(8) v=sqrt(2*q*V/me) disp(v,"Therefore, The velocity, v(m/s)...
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clear //Given I2=150 I1=75.0 E1=20 //Calculation E2=(I2*E1)/I1 //Result printf("\n Illumination is %0.3f lux", E2)
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// Chapter 4 Example 12 //============================================================================== clc; clear; // input data l = 0.1*10^-9; // length of one dimensional box h = 6.625*10^-34 // plancks constant in Jsec m = 9.11*10^-31 // mass of electron in Kg n ...
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//page 301 //Example 8.23 clc; clear; close; disp('Linear transformation from V into W i.e. T is:'); disp('T(x1,x2,x3) = '); disp('0 -x3 x2'); disp('x3 0 -x1'); disp('-x2 x1 0'); disp('Then, T maps V onto W'); disp('And, putting:'); disp('A = '); disp('0 -x3 x2'); disp('x3 0 -...
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clear // //given and derived v=450 r=0.25 i1=160 i2=125 r1=450/(160) eb1=v-i2*r1 //flux decreases by 12% hence eb2=1.12*eb1 eb2=110.60 r2=(v-eb2)/i1 eb3=v-i2*r2 eb4=1.12*eb3 r3=(v-eb4)/i1 //resistance of each section of the starter is determined as follows R1=r1-r2 printf("\n R1= %0.1f ohm",R1) R2=r2-r3 printf("\n R2...
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//EXAMPLE 2.46, Cross corelation Computation. // Given two finite length sequence.x[n],y[n]: clear; clc; x=[1 3 -2 1 2 -1 4 4 2]; disp(x,'x'); y=[2 -1 4 1 -2 3]; disp(y,'y'); //Cross corelation rxy[n]: rxy=convol(x,mtlb_fliplr(y)); disp(rxy,'The Cross-Corelation Operation of the Inputs is =')
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errcatch(-1,"stop");mode(2);//Ex10_8 h='48'; disp("Hexadecimal number="+string(h))// value in hexadecimal d=hex2dec(h)//hexadecimal to decimal disp("Eqivalent Decimal number="+string(d)) exit();
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Ex15_6.sce
clear // //Initialisation R=10**4 //Resistance in Ohm f=10**3 //Frequency in Hertz C=3*10**-8 //Capacitance in Farad V=10 //Voltage //Calculation Xc=1/(2*%pi*f*C) //Reactance a=((10**4)**2)+(5.3*10**3)**2 I=sqrt((V**2)/a) ...
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relu.sce
clear close() P = -4 :0.1: 4; T = P.^2 + 1*(rand(P)-0.5); //siec S1 = 100; W1 = rand(S1, 1)- 0.5; B1 = rand(S1, 1)- 0.5; W2 = rand(1, S1) -0,5; B2 = rand(1,1) -0.5; lr = 0.001 for epoka = 1 : 2000 //odpowiedz sieci X = W1*P + B1*ones(P) A1 = max(X,0); //ReLu A2 = W2*A1 + B2; //propagacja wsteczna E2 = T - A2; ...
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clc; clear all; d = 60e-6; // Diameter of core in fiber in meters lambda = 2.7e-6; // Operating Wavelength in meters NA = 0.25; // Numerical Aperture N = 4.9*((d*NA)/lambda)^2 // Number of modes propogating through fiber is disp('',N,'Number of modes propogating through fiber is')
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clear flag=1 mode(-1) clc printf("Example 12 : Show the use of shift arguments \n") disp("****************************************************************") disp("Answer : ") disp("INSTRUCTIONS : ") printf("\n1. Here all instructions are preloaded in the form of a demo\...
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a = [0.000 -23 -0.6149 -0.9899 -0.0000 -0.0031 -0.0082]; b=poly2lsf(a); disp(b); ////output //!--error 10000 //Input to ROOTS must not contain NaN or Inf //at line 19 of function poly2lsf called by : //b=poly2lsf(a); //at line 2 of exec file called by : //Test/poly2lsf/poly2lsf8.sce', -1
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// Exa 3.14 clc; clear; close; format('v',6) // Given data R_L = 200;// in ohm Vin = 20;// in V V_Z = 10;// in V P_Zmaz = 400;// in mW R_S = 220;// in ohm //The value of V_L with 200 ohm V_L =(R_L/(R_S+R_L))*Vin;// in V disp(V_L,"The value of V_L with 200 ohm in V is"); // The value of I_Z with 200 ohm ...
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//to calculate the generator current and its pf clc; j=sqrt(-1); X=.24; r=400; //rating in MVA rr=600; //rating in MVA Pe=r/rr; Vt=1; Vth=1; dl=asind(Pe*X/(Vt*Vth)); Ia=2*sind(dl/2)/X; V=24000; IaB=(rr/3)*10^6/(V/sqrt(3)); Iaa=Ia*IaB;disp(Iaa,'generating current(A)'); phi=dl/2; pf= cosd(phi);disp...
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//i1, i2, i3 be the currents in the branches CD, EF and GH respectively //i1+i2+i3=1.5 i2=(20-1.5*10)/15 i3=(20-1.5*10)/15 i1=1.5-i2-i3 r=(20-1.5*10)/i1 mprintf("r=%f ohm", r)
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exec('scilab-base-program-testtrycatch.sce')//to delete
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//Example 10.3.1 Page 357 //Non-Linear Dynamics and Chaos, First Indian Edition Print 2007 //Steven H. Strogatz clear; clear; clc; close; set(gca(),"auto_clear","off") //hold on //Taking r=2; r=2; x=poly(0,"x"); f = x-2*(x^2); //Defining Polynomial--> f(x*)-x* = 2*x(1-x)-x. Let th...
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//example 5.11 clear; clc; //Given: N=3;//Total no. of balls Nb=2;//Black balls Nw=1;//white ball //To find the total no. possible configuration w=prod(1:N)/prod(1:Nb)/prod(1:Nw); printf("The total no. of possible configurations are %f ",w);
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tol=[]; reroutes(1)=1.0485689505637468; reroutes(2)=0.8946877912395154; reroutes(3)=0.5102420856610801; reroutes(4)=0.622822299651568; reroutes(5)=0.28558052434456926; reroutes(6)=0.22595704948646125; reroutes(7)=0.20191470844212359; reroutes(8)=0.06273408239700375; reroutes(9)=0.06279287722586692; reroutes(10)=0.08355...
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errcatch(-1,"stop");mode(2);//Ex:13.4 ; ; f_rf=162.5;//in kHz f_af=1.25;//in kHz f_bfo_max=f_rf+f_af; f_bfo_min=f_rf-f_af; printf("The two possible BFO freq. =%f kHz and %f kHz",f_bfo_max,f_bfo_min); exit();
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clc; //page 222 //problem 5.3.a // refer fig from page no. 212 Fig.5.4a // The values of constsnts Kf and Kp are given as Kf= 2*pi*10^5 and Kp=5*pi . // Here we are assuming the Bandwidth B of m(t) as the frequency of the third harmonic, i.e. 3(10^4/2)Hz= 15kHz B=15;// in kHz // For FM: // Here peak amplitude ...
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/* Test the Eq3.htl program. The Eq3 chip sets out to 1 if it three inputs have the same values or 0 otherwise*/ load Eq3.hdl, output-file Eq3.out, compare-to Eq3.cmp, output-list a b c out; set a 0, set b 0, set c 0, eval, output; set a 1, set b 1, set c 1, eval, output; set a 1, set b 0, set c 0, eval, output; set ...
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//fonction corde driver("Rec"); SR = 44100; // taux d'échantillonage B = 0.001; // paramètre d'inharmonicité f = 110; // fréquence fondamentale TF = 4; // durée de la simulation x0 = 0.1; /...
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clc; s = %s; printf("S.S. error = 0.1"); Kv = 1/0.1 G = syslin('c',(s+5)/((s*(s+6)*(s+7)*(s+8)))); printf("\n For type-1 system and finite steady state error implies a ramp input. \n") syms k s; disp(s*G); l = limit(s*G,s,0); disp(l); k = Kv/l; disp(k,"Value of K:");
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//----------------------------------------------------------------------------- // Allan CORNET // INRIA 2005 //----------------------------------------------------------------------------- function MSCompiler=findmsvccompiler() MSCompiler='unknown'; // unknown if MSDOS then ierr=-1; ierr=execstr...
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<!DOCTYPE html> <title>My Example</title> <!-- Latest compiled and minified Bootstrap CSS --> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous"> <style> body { ...
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//Example 3.1: miller indices clc; clear; close; //given data x1=1;// x2=1;// x3=2;// h1=1/x1;// h2=1/x2;// h3=1/x3;// disp("Miller indices of the plane (112) are: "+string(h1)+","+string(h2)+","+string(h3)) x11=0;// x21=0;// x31=1;// h11=%inf;// h21=%inf;// h31=1/x31;// disp("Miller indices of the plane (001) are : "...
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112.sce
// problem 11.2 H=46 Q=1 u1=15 y=165 y2=180-y Cv=0.975 g=9.81 V1=((2*g*H)^0.5) Vw1=V1 Vr1=V1-u1 Vr2=Vr1 Vw2=(Vr2*(cosd(y2)))-u1 w=9810 P=(w*Q*(Vw1+Vw2)*u1)/(g*1000) n=P*1000/(w*Q*H) disp(n*100,P,"power developed in Kw and efficiency of the wheel")
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errcatch(-1,"stop");mode(2);//Ex:4.8 ; ; V=240; c=100*10^-9; f=50; X_c=1/(2*%pi*f*c); I_c=V/X_c; printf("Current flow = %f A",I_c); exit();
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//Example 9.1 : difference clc; clear; close; //given data : E=200*10^9; // in N/m^2 C=(4*10^-6)/2;// in m gama=1.48; // in J/m^2 sigma=sqrt((2*E*gama)/(%pi*C)); disp(sigma*10^-6,"fracture strength,sigma(MN/m^2) = ")
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// Discrete transfer function of the continuous state space system // 4.4 F = [0 0; 1 -0.1]; G = [0.1; 0]; C = [0 1]; dt = 0.2; sys = syslin('c',F,G,C); sysd = dscr(sys,dt); H = ss2tf(sysd);
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clc // Variable Initiallization Ea=400 // Voltage Of MOtor In Volt Ia1=70 //Line Current In Ampere Ia2=90 //Line Current In Ampere Ra=0.3 //Armature Resistance In Ohm N1=750 //Speed Of Motor In rpm N2=300 //Speed Of Motor In rpm //Solution Eb1=Ea-(Ia1*Ra) Eb2=(N2/N1)*Eb1 Rb=-((Eb2-Ea-Ia2*Ra)/Ia2)//Wrongly ...
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// Example 8.45 // Calculation of incident optical power. // Page no 499 clc; clear; close; //Given data lambda=1.3*10^-6; // Wavelength B=6*10^6; // Bandwidth S=10^5; // Total system margin n=1; ...
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//Initilization of variables P=5000 //N lAB=5 //m lOB=1.443 // m alpha=30 //degree //angle made by force P with the beam //Calculations theta=atand(lOB/lAB) // degree // eq'n 1 Xa=(P*cosd(alpha)) //N //using eq'n 4 Ya=Xa*tand(theta) //N // from eq'n 3 & 4 Rb=P*sind(alpha)-Ya // N from eq'n 5// substuting valu...
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clear; //clc(); z1=400; z2=600; zp=2000; ef1=100; ef2=(2/z1)*ef1/(1/z1 + 1/z2 + 1/zp); er1=ef2-ef1; printf("The voltage reflected in line1 is:%d kV\n",er1); ir1=round(er1)/z1; printf("The current reflected in line1 is:%.2f kV\n",ir1*1000); zp=1/(-(1/z1)-(1/z2)+(2/z1)); printf("The resistance at the junc...
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global file_name showprog; //get filename, path and extension [path,fname,extension] = fileparts(file_name); hid_dir = path + '.' + fname; //exec("~/rasp30/prog_assembly/libs/scilab_code/characterization/char_diodeADC.sce",-1); exec('~/rasp30/prog_assembly/libs/scilab_code/diodeADC_v2i.sce',-1); exec('~/rasp30/prog_as...
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//chapter 6 Ex 12 clc; clear; close; n=10; inc=1.8; weightreplaced=53; totalinc=n*inc; weightNew=weightreplaced+totalinc; mprintf("The weight of new man is %d kg.",weightNew);
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 4: DC Dynamo Torque Relations-DC Motors // Example 4-7 clear; clc; close; // Clear the work space and console. // Given data R_a = 0.25 ; // Armature resistance in ohm BD = 3 ; // Brush contact d...
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pathname=get_absolute_file_path('17_16.sce') filename=pathname+filesep()+'17_16_data.sci' exec(filename) //Swept Volume(in cc) Vs=0.25*%pi*D^2*L //Volume of gas in the cylinder(in cc/cycle) V1=(1/(1+AF))*(Vs+(Vs/(r-1))) //Volume of gas at NTP conditions(in cc) V=V1*(p2/p)*(T/T2) //Heat added(in kJ/cycle) H=V*...
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//scilab 5.4.1 //windows 7 operating system //chapter 3:Properties of Semiconductors clc clear //given ni=2.5*10^(19);//ni=intrinsic conductivity of intrinsic material in S/m Nd=5*(10^19)//Nd=donor concentration in /(m^3) n=(1/2)*(Nd+sqrt((Nd^2)+(4*(ni^2))))//n=electron concentration disp("/(m^3)",n,"n=") p=...
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//Example 3.1, page 69 clc; n1=1.5 r=1//in cm n=1//in cm a=4//in cm, air s=.5-(1/a) s1=n1/s printf("\n The image is formed at %d cm",s1)
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//Determine recieving end voltage and current clear; clc; //soltion //FUNCTIONS function [z]=rxr(A,B)//Function for the multiplication of rectangular z(1)=A(1)*B(1) z(2)=A(2)+B(2) endfunction function [a]=r2p(z)//Function for rectangular to polar a=z(1)*complex(cosd(z(2)),sind(z(2))) endf...
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//example 18.9 clc; funcprot(0); // Initialization of Variable sigma=5.67e-8; D1=0.02; D2=0.05; D3=0.035; pi=3.14; T1=77; T2=300; qwo=(sigma*pi*D1*(T1^4-T2^4))/(1/0.02+(1-0.05)/0.05*(D1/D2)); disp(qwo,"heat rate per unit length in W/m"); Rtot=(1-0.02)/(0.02*pi*D1)+1/pi/D1+2*(1-0.02/(0.02*pi*D3)+1/pi/0.035+(...
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//Calculate efficiency of transformer //Chapter 3 //Example 3.29 //page 236 clear; clc; disp("Example 3.29") kVA=50; //rating of the transformers I1=250; //primary current in amperes Re=0.006; //total resistance referred to the primary side ironloss=200; ...
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exec("alaqiltest.start", -1); try a = new_A_UF(); catch alaqiltesterror(); end try delete_A_UF(a); catch alaqiltesterror(); end exec("alaqiltest.quit", -1);
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// Theory and Problems of Thermodynamics // Chapter 9 // Air_water Vapor Mixtures // Example 5 clear ;clc; //Given data V = 1 // volume of tank in m^3 P1 = 0.1 // pressure of tank with He in MPa T1 = 300 // temperature of tank with He in K P2 = 0.4 ...
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clc disp("Example 9.7") printf("\n") printf("Given") disp("Resistance is 10ohm and Capacitance is 0.2F") disp("Applied voltage is 10*exp(-2*t)*cos(10*t+30)") s=%s; //For a RC circuit //Applying KVL equation //v=i*R+(1/C)*integrate(i*dt) (1) //As v=10(30 deg) (2) //Equating (1) and (2) // Let i=I*e...
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clc //initialisation of variables G= 2.6 LL= 20 P= 20 //calclations R= (4804574*G-195.55*(LL)^2+156971*(P)^0.5-9527830)^0.5 n= (1.195e-4)*((LL)^2)-1.964*G-(6.617e-5)*(P)+7.651 w= %e^n //results printf ('maximum dry density = % f kg/m^3 ',R) printf ('optimum moisture content = % 2f ',w)
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clc;clear; //Example 9.6 //from 9.5 Wsc=244.16;//compressor Wst=606.60;//turbine h1=300.19; h3=1395.17; //given data nC=0.8; nT=0.85; //calculations Win=Wsc/nC; Wout=nT*Wst; rbw=Win/Wout; disp(rbw,'back work ratio is'); h2a=h1+Win; qin=h3-h2a; Wnet=Wout-Win; nth=Wnet/qin; disp(nth,'thermal effi...
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PL/SQL Developer Test script 3.0 4 begin -- Call the function :result := get_ciudad(pciudad => :pciudad); end; 2 result 1 Síndey 5 pciudad 1 1 4 0
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//chapter 17 //example 17.4 //page 523 clear all; clc ; //given Rl=100;//load resistance Po=0.5;//output power //peak output voltage Vp=sqrt(2*Rl*Po); //peak output current Ip=1000*(2*Po)/Vp; Vr6=0.1*Vp; Vr7=Vr6; R6=1000*Vr6/Ip; R7=R6; //quiscent current Iq2=Ip/10; //dc voltage across R4 Vr4dc=0.7+10...
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clc(); clear; //To determine the wavelength lambda1=0.708; //wavelength of a certain line in an X-ray spectrum Z1=42; //atomic number Z2=24; a=1; //screening constant lambda2=(lambda1*(Z1-a)^2)/((Z2-a)^2) printf...
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clear // Variable declaration T_d=37// The dry bulb temperature of air in °C H=24// % saturation n_s=75// Saturation efficiency in % h=62.67// The entering enthalpy in kJ/kg // Calculation // By construction on the chart, or from tables, the ultimate saturation condition would be 21.5°C, and 75% of the drop from 37°C ...
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clear; clc; printf("\t\t\tProblem Number 3.17\n\n\n"); // Chapter 3 : The First Law Of Thermodynamics // Problem 3.17 (page no. 117) // Solution p1=1000; //Unit:psia //Initial pressure t1=100; //Unit:Fahrenheit //Temperature at pressure p1 p2=1000; //Unit:psia //Final pressure t2=1000; //Unit:Fahrenheit //...
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//MissionX2 function missionX2(imgX2) disp("Résultat de la mission X2 :") [y,x]=size(imgX2) //Les boucles for servent à parcourir tout les pixels de l'image for i=2:1:y-1 for j=2:1:x-1 //calcul de la moyenne entre les 4 pixels k=imgX2(i,j)+imgX2(i+1,j)+imgX2(i,j+1)+imgX2(i+1,j+1)+imgX2(i-1,j-1)...
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//pathname=get_absolute_file_path('6.18.sce') //filename=pathname+filesep()+'6.18-data.sci' //exec(filename) //Initial volume in part A(in m^3): Va=0.4 //Pressure(in bar): pa=10 //Initial volume in part B(in m^3): V=0.4 //Pressure in part B(in bar): p1=10 //Final pressure in part B(in bar): p2=15 //From st...
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errcatch(-1,"stop");mode(2);// sum 18-4 ; ; P=20*10^3; Co=22400; C=41000; Ln=(C/P)^3; Lh=Ln*10^6/(720*60); // printing data in scilab o/p window printf("Lh is %0.3f hrs ",Lh); exit();
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//Chemical Engineering Thermodynamics //Chapter 14 //Thermodynamics of Chemical Reactions //Example 14.7 clear; clc; //Given //SO2 + (1/2)O2 - SO3 //Basis: 1 Kgmole of SO2 n_SO2 = 1;// SO2 fed in Kgmole n_O2 = n_SO2;//O2 fed in kgmole //To Calculate the conversion of SO2 to SO3 at 1atm and at various t...
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//ques-35.19 //Calculating frequency shift from TMS required clc R=1;//resonance order f=500;//frequency (in MHz) shift=R*(f*10^6)*10^-6; printf("The frequency shift required is %d Hz.",shift);
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clc //Chapter3: Modulation, page no 142 //Example3.9 //Given t=0:0.001:10 //e=500*(1+(0.4*sin(3140*t)))*sin(6.28e7*t) //a wc=6.28e7//Carrier angular frequency fc=wc/(2*%pi)// Carrier freq //b wm=3140//Modulating angular freq fm=wm/(2*%pi)//Modulating freq //c Ec=500///peak carrier voltage Pc=(Ec^2)/(2*600...
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//Example 5.4, Page no 110 clc p=400*20*.88*sqrt(3)//input power in watt l=12193.6-10000//in watt, full load loss e=l*60//energy lost per minute ws=(2*%pi*1000)/60//angular frequency j=.5 R=1//resistance in ohm ir R1/R2 El=(0.5*j*ws**2)*(1+R) //disp(El) N=e/El //disp(N) printf("\n The number of starts that can be made ...
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V1 = 0.3; // Initial volume in m3 V2 = 0.15; // Final volume in m3 P = 0.105e06; // Pressure in Pa Q = -37.6e03; // Heat tranferred in J W = P*(V2-V1); // Work done U = Q-W; // Internal energy change disp("Joule",U,"Change in the internal energy of the system is")
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//Chapter2 //Page.No-45, Figure.No-2.9 //EXAMPLE_2_1_b //Output voltage for open-loop differential amplifier //Given: clear;clc; vin1=10*10^-3;vin2=20*10^-3; // Both input voltages are in volts A=200000; // Voltage gain vo=A*(vin1-vin2); // Output voltage in volts printf("\n Output voltage is vo = %.f V rms \...
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// Scilab Code Ex2.69:: Page-2.51(2009) clc; clear; R = 100; // Radius of curvature of plano-convex lens, cm D15 = 0.590; // Diameter of 15th dark ring, cm D5 = 0.336; // Diameter of 5th dark ring, cm p = 10; // Order of 10th Newton ring after 5th ring lambda = (D15^2-D5^2)/(4*p*R); // Wavele...
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//Network Theorem 1 //page no-2.34 //example2.30 disp("Applying KCL to node a:"); disp("0.5*Va-0.2*Vb = 34.2");....//equation 1 disp("Applying KCL to node b:"); disp("0.1*Va-0.4*Vb = -32.4");...//equation 2 disp("Solving equations 1 and 2");...//solving equations in matrix form A=[0.5 -0.2;0.1 -0.4]; B=[34.2 -...
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clc,clear printf('Example 6.36\n\n') V_L=11000 V_ph=V_L/sqrt(3) VA=2*10^6,phi=acos(0.8) I_FL=VA/(sqrt(3)*V_L) phi_1=acos(0.8) IX_s=(20/100)*V_ph //product of I and X_s X_s=IX_s/I_FL I_1=I_FL BC=I_1*cos(phi_1)*X_s AB=I_1*sin(phi_1)*X_s , OA=V_ph OC=sqrt( (OA+AB)^2+(BC)^2 ) ,E_1=OC E_2=1.25*E_1,OE=E_2 ...
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clf t = 0:.01:2*%pi; polarplot(t,sin(2*t)+cos(2*t)) filename='jitendra'; xs2pdf(1,filename); xs2pdf(gcf(),filename);
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EEC run k=3 [3,4,5,6] [1,6,8,9] [3,4,5,6] [1,6,8,9] [3,4,5,6] [3,10,18,19] [7,14,17,20] [3,4,5,6] [4,17,22,25] [1,6,8,9] [18,19,21,28] [11,15,27,29] [3,4,5,6] [1,6,8,9] [3,4,5,6] [3,10,18,19] [7,14,17,20] [2,17,40,41] [6,32,33,41] [3,4,5,6] [16,23,41,44] [1,6,8,9] [3,36,37,46] [27,30,37,46] [3,4,5,6] [4,17,22,25] [29,3...
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//Example 2.8 //To solve the triangle when 2 sides and opposite angle is given clc,clear a=18 //side oposite to vertex A A=25 //angle at vertex A b=30 //side opposite to vertex B //using law of cosines solving for c c_polynomial=[1 -54.38 576] root_c=roots(c_polynomial) //case 1 c=root_c(1) cos_B = (c^...
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 2 clc; disp("CHAPTER 7"); disp("EXAMPLE 2"); // //400/200V transformer //VARIABLE INITIALIZATION v1=400; //primary voltage in Volts v2=200; //secondary voltage in Volts I0=1; //in Amperes pf1=0.4; ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 3, Example 17") disp("Velocity in casing at inlet to turbine") Q = 7.8; disp("Cc = Discharge/(Cross - sectional area of casing)") Cc ...
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//chapter13 //example13.9 //page283 Rc=3 // kilo ohm Rl=6 // kilo ohm Rin=0.5 // kilo ohm Vin=1 // mV gain_beta=50 R_AC=Rc*Rl/(Rc+Rl) Av=gain_beta*R_AC/Rin // since Av=Vout/Vin we get Vout=Av*Vin printf("output voltage = %.3f mV \n",Vout)
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//Example 2.19 clear; clc; //Given T1=273; //initial temperature in K T2=1073; //final temperature in K w=1;//weight of aluminium taken in kg mp=931;//melting point of aluminium in K delHm=362.3;//enthalpy change during melting process in kJ kg^-1 // To determine delH delH1=(0.9121*(mp-T1))+(2.0083*0.0000...
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// clear the console window clc //Turn off the warning messages in the console previousprot = funcprot(1) //integer with possible values 0, 1, 2 returns previous value funcprot(0) //allows the user to specify what scilab will do when such variables are redefined. 0=nothing, 1=warning, 2=error // Import some useful X...
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//Example No.3.6. // Page No.100. //To find refractive idex. clc;clear; NA = 0.26;//Numerical aperture. del = 0.015;//Refractive index difference of the fibre. n1 = sqroot((((NA)^(2))/(2*del)));//Refractive index of the core printf("\nThe refractive index of the core is %.2f",n1); n2 = sqroot((n1^(2))-(NA^(...