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clc //initialisation of variables Xac= 2 //m Xcb= 4 //m Xbd= 2 //m Wa= 1 //N Wc= 1 //N Wd= 1 //N //CALCULATIONS Rb= Wa*Xac/(Xac+Xcb) Sc= Rb Ra= Wc*Xcb/(Xac+Xcb) Sc1= -Ra Ra1=-Wd*Xbd/(Xac+Xcb) Mc= Ra*Xac Mc1= Ra1*Xac //RESULTS printf ('Rb= %.2f KN',Rb) printf (' \n Ra= %.2f KN ',Ra) printf (' \n Ra...
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// Data Reconciliation Benchmark and GED Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv function [x_sol] = calc_results_DR(xfinal, jac, sigma, resGrossErrorNodalRandFi, opt_type) obj_function_type = opt_type; exec ../functions/setup...
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//Operation pressure of hydraulic system(in kPa): p1=20000; //Operation temperature of hydraulic system(in C): T=55; //Piston diameter(in mm): D=25; //Viscosity of SAE 10W at 55C(in kg/(m-s): u=0.018; //Mean radial clearance of a cylinder(in mm): a=0.005; //Gauge pressure on lower pressure side of piston(in k...
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//Example 15.25 //Hamming Predictor Corrector Method //Page no. 548 clc;clear;close; deff('y=f(x,y)','y=y-x^2') y(1)=1;h=0.25;x=0; printf('n\tXn\tYn\tfn\tY`n\tYc(n)\tY`n+1\tm(n+1)\tv(n+1)\tYc(n+1)\n-----------------------------------------------------------------------------------------\n') f1(1)=f(x,y(1)); f...
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//clc(); clear; //To determine permeability H=1800; //magnetizing field in amp/m phi=3*10^-5; //magnetic flux in wb A=0.2*10^-4; //cross-sectional area in m^2; B=phi/A; mew=B/H; printf("permeability is %f Henry/m",mew); //answer in book is wrong
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//chapter 14 //example 14.14 //page 630 printf("\n") printf("given") Vcc=15;Vsat=Vcc;R2=150*10^3;Vf=.7;R1=27*10^3;R3=120*10^3; I2=(Vsat-Vf)/R2 UTP=I2*R1 disp(" LTP calculation including Vf") I3=(Vsat-Vf)/R3 LTP=-I3*R1
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// Theory and Problems of Thermodynamics // Chapter 8 // Power and Refrigeration Cycles // Example 6 clear ;clc; //Given data P1 = 2.5 // entering pressure of superheated steam in MPa P2 = 10 // leaving pressure of steam in kPa T1 = 523.15 // steam is superheated...
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clc //initialisation of variables a= 43560 //ft^-2 t= 500 //min day^-1 E= 1000 //cal min^-1 ft^-2 m= 2 //tons acre^-1 E1= 4000 //cal gram^-1 M= 9.07*10^5 //gram ton^-1 //CALCULATIONS Sh= a*t*E*365.26 Hs= m*M*E1 r= Hs/Sh //RESULTS printf ('fraction of solar energy stored = %.3f ',r)
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clear //Given a=5 ///ohm/cm ue=3900 //cm**2/vs e=1.6*10**-19 //Calculation Nd=a/(ue*e) //Result printf("\n Number density of donor atom is %0.2f *10**15 /cm**3",Nd*10**-15)
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//Chapter 6 //Example 6.1 //page 195 //To Ybus using singular transformation clear;clc; printf('Let us solve this problem by giving values given in the table 6.1 instead of keeping it in variables'); y10=1;y20=1;y30=1;y40=1; y34=2-%i*6;y23=0.666-%i*2; y12=2-%i*6;y24=1-%i*3; y13=1-%i*3; Y=[y10 0 0 0 0 0 0 0 0; 0 y...
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<<<<<<< HEAD function [rmsx, w] = movingrms(x, width, risetime, varargin) // Find moving RMS value of signal in x // Calling Sequence //[rmsx,w]=movingrms(x,width,risetime) //[rmsx,w]=movingrms(x,width,risetime,Fs) // Parameters // x: (Real or complex valued vector or matrix) Input Signal // width: Real or complex ...
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clear; clf; dt = 1/1000; t = -1 : dt : 1; A = 1; f = 1; theta = 0; x = A*cos(2*%pi*f*t + theta); // %pi = PI plot(t, x); xgrid(1); // The argument defines the color of the grid xlabel("t", "fontsize", 4); ylabel("x", "fontsize", 4); title("Continuous time cosine wave", "fontsize", 4);
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//Example 3.9 // mass of aluminium clc; clear; close; //given data : ECE_silver=111*10^-8;//in kg/C Cew_silver=107.98;//chemical equivalent of silver Cew_al=27/3;//chemical equivalent of aluminium Z=(ECE_silver*Cew_al)/Cew_silver; C_efficiency=0.92; I=3000;//in A t=24*60*60;//in seconds m=Z*I*t*C_efficiency; disp(m,"ma...
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// 08.05.18 Koshikawa // 08.05.19 Changed // 08.00.04 // 09.11.07 for the same curve function KL=IntersectcrvsPp(varargin) // Modified Nargs=length(varargin); G1=varargin(1); G2=varargin(2); Eps=10.0^(-4); if Nargs>2 Eps=varargin(3) end SqEps=10.0^(-10); Eps2=0.1; if Nargs>3 Eps2=varargin(4) ...
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errcatch(-1,"stop");mode(2);//ex15.2 R2=10*10^3; R1=0.586*R2; //FOR BUTTERWORTH RESPONSE disp(R1,'R1 in ohms') disp('5.6kilo ohm will be ideally to maximally flat butterworth response') exit();
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z=poly(0,'z'); sys1=syslin('d',z/(z-0.3)); //example taken from http://in.mathworks.com/help/control/ref/zpkdata.html sys2=syslin('d',2*(z+0.5)/(z^2 -0.2*z+1.01)); a=[sys1,sys2]; [z1 p1 k1]=zpkdata(sys) aa=pid(rand(2,2,3),3,4,5) [z2 p2 k2]=zpkdata(aa) ss=syslin('c',[1...
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// Exa 10.7 // To determine the minimum delay difference to successfully resolve the multipath components and operate the Rake receiver clc; clear all; SR=3.84; //spreading rate in Mcps //solution disp("In order to resolve multipath components, the chip duration should be equalto or greater than T(tau), ...
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METHOD='GET' ARGS="${DATETIMES[0]} ${DATETIMES[1]}" OUT='Status code is 200: {"domains": ["test1.org"], "status": "ok"}'
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// Exa 14.2 clc; clear; // Given data Va=2;// Volts Vb=1;// Volts Vc=3; // Volts Ra=3;// k Ohms Rb=3;// k Ohms Rc=3;// k Ohms Rf=1;// k Ohms Rom=270;// Ohms Supply=15;// Volts // Solution disp(" Assuming that the opamp is initially nulled"); // Using equation 14.8 to determine the output voltage Vo=-(Rf/Ra *Va+Rf/...
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//ques 32 disp('Equation of tangent'); syms x a y; f=(a^(2/3)-x^(2/3))^(3/2); s=diff(f,x); Y1=s*(-x)+y; X1=-y/s*x; g=x-(Y1-s*(X1-x)); disp('Equation is g=0 where g is'); disp(g);
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function signal = genqamdemod(mod, constellation) // //Function Description //genqamdemod: This function demodulates a matrix of complex baseband signals //into a matrix of integers, according to a specified constellation. // //Calling sequence:- //genqamdemod(mod, constellation) // //Parameters: //m...
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Time = 0.001 Temperature = 30.02 Energy = 0.000E+00 Time = 0.001 Temperature = 107.10 Energy = -6.849E+02 Time = 0.002 Temperature = 196.30 Energy = -6.841E+02 Time = 0.002 Temperature = ...
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//Chapter-4,Example 4_3,Page 4-29 clc() //Given Data: lam=780*10^-9 //Wavelength of photon in meter P=20*10^-3 //Power of each pulse in watts t=10*10^-9 //Duration of each pulse h=6.63*10^-34 //Planck's Constant c=3*10^8 //Velocity of light //Calc...
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clc; clear; format('e',11); rho_v_tf=10^-18; rho_v_t0=1; tf=log(rho_v_tf)/(-6.6*10^18); //from rho_v_tf=rho_v_t0*exp(-sigma/epsilone0*t) and for copper,taking sigma/epsilone0=6.6*10^18. disp(tf,"The time taken by the charge to dissipate(in sec)=");
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clc; disp("Example A.19") n=100 // in rpm omega=2*%pi*n/60 r=0.05 // radius in m u=r*omega // velocity in m/s gap=0.001 // in m mew=0.5 // in kg/ms tau=mew*u/gap disp(tau,"Shear stress is ")
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clc disp("Example 7.5") printf("\n") printf("Given") disp("v(t)=cos5t+3sin(3t+45)") //Finding the periods of individual terms disp("Period of cos5t=2*%pi/5") disp("Period of 3*sin(3t+45)=2*%pi/3") //If T=2*%pi T=2*%pi; disp("Now T=5*T1=3*T2") //Now the relation for T is the smallest common integral multipl...
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// Scilab code Ex8.19 : Pg:346(2008) clc;clear; function [bini]= decimal_binary(ni) // Function to convert decimal to binary bini = 0; i = 1; while (ni <> 0) rem = ni-fix(ni./2).*2; ni = int(ni/2); bini = bini + rem*i; i = i * 10; end endfunction function octal ...
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clear ; clc; // Example 3.15 printf('Example 3.15\n\n'); printf('Page No. 77\n\n'); // given i_t = [20 40 60 80 100];// Insulation thickness in mm f_c = [2.2 3.5 4.8 6.1 7.4];// Fixed costs in (10^3 Pound / year) h_c = [10.2 6.5 5.2 4.6 4.2];// Heat costs in (10^3 Pound / year) t_c = [12.4 10 10 10.7 11.6];/...
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//(9.3) At the beginning of the compression process of an air-standard dual cycle with a compression ratio of 18, the temperature is 300 K and the pressure is 0.1 MPa. The pressure ratio for the constant volume part of the heating process is 1.5:1. The volume ratio for the constant pressure part of the heating proces...
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//Chapter 6: Electrochemistry //Problem: 13 clc; //Declaration of Variables EoSn = 0.15 // V EoCr = - 0.74 // V // Solution mprintf("3Sn+4 + 2Cr --> 3Sn+2 + 2Cr+3\n") Eo_cell = EoSn - EoCr n = 6 K = 10 ** (n * Eo_cell / 0.0591) mprintf(" The equillibrium constant for th reaction is %....
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e6_30.sce
//example6.30 disp("The circuit used for providing proper biasing is self bias, for which the various currents can be shown in the fig 6.52") disp("Applying KVL to base emiter loop,") disp("(-V_BE)-(I_E*R_E)+(I*R2)=0") disp("Theredfore (I*100)-(1+beta)*I_B*10=V_BE") disp("100I-210(I_B)=0.5 ..(1)") disp("Apply...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>StdInterp Triangle Orthonormal basis P=7n Q=8</description> <executable>StdInterp</executable> <parameters>-s triangle -b Ortho_A Ortho_B -o 7 7 -p 8 8 -P GaussGaussLegendre GaussGaussLegendre</parameters> <metrics> <metric type="L2" id=...
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clc //initialisation of variables clear To1= 540 //R po3= 12.6 //lbf/in^2 l3= 3 //ft po1= 14.7 //lbf/in^2 l1= 1 //ft vo1= 500 //ft/sec r= 0.83 P1= 1 //lbf/in^2 //CALCULATIONS To3= To1*(po3*l3/(po1*l1))^r Vo3= vo1*sqrt(To3/To1) P3= P1*po3*l3/(po1*l1) //RESULTS printf ('To3 = %.f R',To3) printf ('\n Vo3 ...
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//Variable Declaration BIF=36 //Bandwidth of channel over which carriers are spread(MHz) R=0.4 //Rolloff factor for filtering Rb=64 //Information bit rate(kb/s) BER=10**-5 //Bit error rate required EbN0R=9.6 //Eb/N0 ratio for BER given from Fig.10.18 //Calculation Rch=BIF*10**6/(1+R) //Rate of unspreaded sign...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clear // // // //Variable declaration lamda=1.66*10**-10 //wavelength(m) m=9.1*10**-31 //mass(kg) e=1.6*10**-19 //charge(c) h=6.63*10**-34 //plank constant //Calculation E=h**2/(2*m*e*lamda**2) //kinetic energy(eV) v=h/(m*lamda) //velocity(m/s) //Result
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//**************************** C4 ************************************** if (blk_name.entries(bl) =='c4_sp') then plcvpr=%t j=scs_m.objs(blk_objs(bl)).model.ipar(1) freq_c=scs_m.objs(blk_objs(bl)).model.rpar' // tau1=1 ./(2*%pi *freq_c(1:j))//high // tau2=1 ./(2*%pi*freq_c(3*j+1:3*j+j))//low // c2...
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clc //variable initialization Vm= 220 //armature voltage in volts N= 1000 //speed in rpm N1= 900 // speed in rpm Ia= 60 //armature current in ampere Ra= 0.6 //armature resistance in ohm a= 0 V= 165 //line voltage in volts //solution Eb1= Vm-Ia*Ra //back emf in volts Eb2= (N1/N)*Eb1 //back emf in volts Ea=...
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//Example 11.2 //Page no. 488 //Calculate the thermal boundary layer thickness & //local heat transfer coefficient 0.75 m from the leading edge. //Variable declaration Ts=200 // C,temp. of air Ta=30 //C, temp .of surface Va=8 //m/s, velocity of air d=0.75 //m, distant from l...
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//To calculate the concentration of intrinsic charge carriers T = 300; //temperature, K pi = 22/7; //value of pi e = 1.6*10^-19; m = 9.109*10^-31; //mass of electron, kg k = 1.38*10^-23; //boltzmann's constant h = 6.626*10^-34; //planck's constant Eg = 0.7; //band gap, eV Eg = Eg*e; ...
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// Problem no 7.12,Page no.192 clc;clear; close; P=3680 //KW //Power transmitted N=110 //r.p.m X=20000 //N*m //Energy stored G=85 //GPa //Calculations //U*V**-1=X //Strain Energy per unit volume //Notification has been changed //X=sigma_s**2*(4*G)**-1*((D**2+d**2)*(D**2)**-1) T=P*60000*(2*%pi*N)**-1 //N*m //Torq...
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function [V,Ivtg,P]=photovoltaicCell(Vi,Vf,N,T,G,Voc,Isc,k,q,Ns,Np,A,Ki,Eg) h=(Vf-Vi)/N; Tref=273+25; Tc=273+T; Irs=Isc/(exp(q*Voc/(Ns*k*A*Tc))-1); Is=Irs*(Tc/Tref)^3*exp(q*Eg*(1/Tref-1/Tc)/(k*A)); Iph=(Isc+Ki*(Tc-Tref))*G; for i = 1:N //Seccion Modificable para matriz V(i+1)=Vi+i*h; Iv...
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//Chapter 7,Example 7.3 Page 223 clc clear E = 100 Z1 = 1/600 // 1/Z1 Z2 = 1/800 // 1/Z2 Z3 = 1/200 // 1/Z3 E11 = (2*E*Z1)/((Z1+Z2+Z3)*10^-3) Iz2 = E11*1000*Z2 Iz3 = E11*1000*Z3 printf (" E'' = %f kV \n",E11*10^-3) printf (" Iz2′= %f amps \n",Iz2*10^-3) printf (" Iz3′= %f amps \n",Iz3*10^-3) //Answers may vary due to ...
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clear; clc; close; Rl = 4.7*(10^(3)); Rs = 0.3*(10^(3)); Ro = 4.7*(10^(3)); Zi = 846.1; Zo = 4.7*(10^(3)); AvNL = -555.55; //gain under no-load condition Av = {Rl/(Rl+Ro)}*AvNL; disp(Av,"Voltage gain(Av) with 4.7kohm load :"); Avs = (Zi/(Zi+Rs))*(Rl/(Rl+Ro))*AvNL; disp(Avs,"Voltage gain(Avs) from sou...
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clear // //Initialization l1=10 //Inductance in henry l2=20 //Inductance in henry //Calculation ls1=l1+l2 //Inductance in henry lp=((l1*l2)*(l1+l2)**-1) //Inductance in henry //Results printf("\n (a) Inductance in series,L = %d uH",ls1...
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// Ex17_6 Page:335 (2014) clc;clear; m_n = 1.008665; // Mass of a neutron, amu M_Na22 = 21.9944; // Mass of Na-22 atom, amu M_Na23 = 22.989767; // Mass of Na-23 atom, amu delta_m = M_Na22 + m_n - M_Na23; // Mass deficiency with Na-23, amu E_B = delta_m*931.5; // Energy equivalent of mass deficiency...
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// Calculate V_z // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 2-35 in page 112 clear; clc; close; // Given data // (a) Proof of V_z=51/sigma has been given sigmai=1/45; // Intrinsic conductivity in 1/ohm-cm sigmap=1/3.9; // Conductivity of ...
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clc //Example 3.11 //calculate flow rate of ventilation air supply q=5/8;//kg/hr mass evaporation rate of benzene c=1.3*10^(-6);//kg/m^3 concentration of benzene Q=q/c/3600//m^3/s printf("The flow rate of ventilation air supply is %f m^3/s",Q);
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clear; clc; printf("\n Example 6.6"); cp = 0.85; //specific heat capacity of the air h = [0 0.625 1.25 1.875 2.5 3.75]; //height in mm T=[339.5 337.7 335.0 333.6 333.3 333.2];//temperature in K deltaT = T - 333.2; //temperature difference in...
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//a function to choose randomly a number nb_config of observations //to remove in the range [1,l] (l being the total number of observations ; i.e., the number of line) //inputs : // - nb_config : number of observations to be removed // - l : total number of observations //outputs : // - idx_config : randomly chosen ...
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function prob=myfunc2lo(n,m,data,x) for i=[1:n] s(i)=mean(data([1:m],i)) end prob=0 for i=[1:n] prob=prob+(x(i)-s(i))^2 end prob=sqrt(prob) endfunction
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//Chapter 12 //page no 483 //given clc; clear all; E=0.115; fb=622; //in Mb/s dl=4; //in nm mt=0.1; //in dBm mr=-31.5; //in dBm mc=0.41; //in dB L=25; mco=0.12; //in dB Nco=2; ms=0.15; //in dB Ns=4; mD=1; mH=0; mCR=0; sc=0.0; /...
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avg = 4; prob = cdfpoi("PQ", 3, 2*avg) disp(prob)
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//Network Theorem 1 //page no-2.30 //example2.26 disp("Applying KCL to node 1:"); disp("5*V1-2*V2 = -24");....//equation 1 disp("Applying KCL to node 2:"); disp("10*V1-31*V2+6*V3 = 300");...//equation 2 disp("Applying KCL to node 3:"); disp("-4*V2 +9*V3 = 160");...//equation 3 disp("Solving equations 1,2 and 3...
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clc; clear all; disp("Time and Temperature") L=60/1000;// m a=1.22*10^(-5);//m^2/s ti=30;// degree C ta=110;// degree C tau=1.5*60;// seconds taumax=L^2/(4*a*0.25); disp("s",taumax,"maximum time that the slab be treated asa semi infinite body taumax=") x=L/2; M=x/(2*(a*tau)^0.5); //erfM=0.47=T1; T1=0.47;...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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errcatch(-1,"stop");mode(2);; ; disp("--------------Example 2.5---------------") disp("753 - A 16-bit port address represented as one single decimal number.") exit();
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getDepth.sci
function depth = getDepth(src) // Returns the depth of a matrix element // // Calling Sequence // src = imread("image-location-for-src"); // depth = getDepth(src) // //Parameters //src: Input 8-bit 3-channel image. //depth: a string which denoted the depth of the src.It identifies the following // //CV_...
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function [z] = lulu(qc) Membre1=q0+B*qc; Membre2=abs(q0+B*qc).*(q0+B*qc).*r; Membre3=pr; Membre4=Ar*(q0+B*qc); z = (Membre1'*Membre2)/3 + Membre3'*Membre4; endfunction function [y] = deriv(qc) Membre1=B'*(abs(q0+B*qc).*(q0+B*qc).*r); Membre2=(Ar*B)'*pr; y=Membre1+Membre2; endfunction ...
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function[dstImg] = watershed(srcImg) srcMat = mattolist(srcImg) out = opencv_watershed(srcMat) channels = size(out) for i = 1 : channels dstImg(:,:,i) = out(i) end endfunction
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clc(); clear; //To calculate the bandwidth lambda=600*10^-9; mew=2; teta=0.025; //wedge-angle x=(lambda/(2*mew*sind(teta)))*10^2 //bandwidth printf("The bandwidth is %f cm",x);
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//Chapter 3 //Example 3-18 //ProbOnEquilibriumTime //Page 73,Figure 3-17 clear;clc; //Given Ri=10^5;//in ohm C=10^-6;//in farad T=3*Ri*C;//Time constant ETime=5*T;//equilibrium time printf("\n\n Value of Equilibrium Time = %.4f s \n\n",ETime)
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clc clear printf("example 7.3 page number 305\n\n") //to find the change on rate of reaction //part 1 //rate equation r = kC_NO^2*C_O2 //if pressure increases 3 times r = 3^2*3; //according to the rate reaction printf("reaction reate will be increased by with 3 times increase in pressure = %f times",r) ...
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute...
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P=1; a=0.5;//dissociation constant// Kp=(a^2*P)/(1-a^2); printf('Total pressure required to bring 50 percent dissociation=P=3*Kp');
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//Exa 7.3 clc; clear; close; //Given data : format('v',6); l=250;//in meter VA=230;//in volt VB=232;//in volt r=0.5;//in ohm/km r=0.5/10^3;//in ohm/m RAC=r*50*2;//in ohm RCD=RAC;RDE=RAC;REF=RAC;RFB=RAC;//in ohm //VA-VB=VAC+VCD+VDE+VEF+VFB;//in volt Ia=(VA-VB+15)/(5*RAC);//in Ampere IAC=Ia;ICD=IAC-20;IDE...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function Out=SSSoModLin(In,V) // Linear Optical Modulator // // Calling Sequence // Out=SSSoModLin(In,V)) // // Parameters // In : Optical Input // V : Modulating Signal // Out : Opt...
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clc //Initialization of variables k1 = 3.0*10^-4 // m.t.c in benzene in cm/sec k2 = 2.4*10^-3 // m.t.c in water in cm/sec ratio = 150 // Solubility ratio in benzene to water //Calculations K1 = (1/((1/k1)+(ratio/k2)))*10^5 // Overall m.t.c through benzene phase in x*10^-5 cm/sec //Results printf("The overall M...
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function [stk,txt,top]=sci_menu() // Copyright INRIA txt=[] RHS=[] for k=2:rhs RHS=[RHS stk(top-rhs+k)(1)] end dlg=stk(top-rhs+1)(1) c=lhsargs(RHS) stk=list('max(x_choose('+c+','+dlg+'),1)','0','1','1','1')
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src = imread("../images/color2.jpeg"); mask = roiFreeHand(src); c=illuminationChange(src,mask,1.3,0.6,7) //wrong no of input arg imshow(c);
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// Test #6 : Input Argument #2 range test exec('./allpasslp2bs.sci',-1); [n,d]=allpasslp2bs(0.4,[-4,0.39]); //!--error 10000 //Wt must lie between 0 and 1 //at line 46 of function allpasslp2bs called by : //[n,d]=allpasslp2bs(0.4,[-4,0.39]);
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//Example 11_9 //Find state space representation of the system clc; clear; s=%s; tf=syslin('c',((3*s+7)/((s+1)*(s+2)*(s+5)))); ss=tf2ss(tf); disp(ss)
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clc; clear; x=1:8; printf("\nX values"); disp(x); y=[1,8,27,64,125,216,343,512]; printf("\ny values"); disp(y); X=7.5; n=length(x); h=x(2)-x(1); p=(X-x(n))/h; sum1=y(n); term=1; printf("\nDifference Table"); for i=1:n-1 for j=1:n-i y(j)=y(j+1)-y(j); printf("\t%d",y(j)); end term=term*(p+i-1)/i; sum1=sum1+term*y...
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clear //Given a=0.8 //Calculation H=a**2 H1=(1-H)*100 //Result printf("\n Decreased percentage is %0.3f percentage", H1)
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// Scilab Code Ex7.1: Page-7.23 (2004) clc;clear; C = 2e-6; // Capacitance, farad V = 1000; // Applied Voltage, volt W = C*V^2/2; // Energy stored in capacitor, joule er = 100; //Electric permittivity Co = C/er; // New Capacitance without dielectric, farad Wo = Co*V^2/2; // New Energy without die...
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function [stk,txt,top]=%p2sci() // ^ //! // Copyright INRIA txt=[] s2=stk(top);s1=stk(top-1); [s1,te1,t1,m1,n1]=s1(1:5); [s2,te2,t2,m2,n2]=s2(1:5); // if te2=='2' then s2='('+s2+')',end if te1=='2' then s1='('+s1+')',end if part(s2,1)=='-' then s2='('+s2+')',end stk=list(s1+'^'+s2,'2',m1,n1,'1') top=top-1
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//example 7.1// clc //clears the screen// clear //clears the command window// e=input('Enter the enable i/p level (1or0) :'); //accepting the input of enable// r=input('enter the R i/p level(1or0):'); //accepting the inputs from the user// s=input('enter the S i/p level(1or0):'); //accepting the input S from ...
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//Initilization of variables V_ao=29.3 //ft/s OA=50 //ft theta=45 //degrees OB=50*sqrt(2) //ft //Calculations w_ao=V_ao/OA //rad/s V_bo=V_ao*cosd(theta) //ft/s w_bo=V_bo/OB //rad/s //Result clc printf('The angular velocity with respect to the observer is %frad/s\n The angular velocity after moving 50ft is %f...
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// Scilab code Ex2.15: Pg 67 (2008) clc; clear; l1 = 600e-03; // Scale reading, metre l2 = 745e-03; // Scale reading, metre l_s = 509.3e-03; // Total scale length, metre E_s = 1.0186; // Source voltage, V E1 = ( l1/l_s )*E_s; // Voltage drop across length l1,...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 5 disp("CHAPTER 1"); disp("EXAMPLE 5"); //VARIABLE INITIALIZATION r1=2; //in Ohms r2=4; //in Ohms r3=8; //in Ohms r4=8; //in Ohms r5=2; ...
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clc;clear; //Example 9.10 //from 9.2 r=8; T0=290; T1=290; T2=652.4; T3=1575.1; P2=1.7997; P3=4.345; qin=800; qout=381.83; wnet=418.17; Tsource=1700; //constants used R=0.287;//in kPa-m^3/kg-K //calculations //s1=s2 ; s3=s4 s03=3.5045; s02=2.4975; s32=(s03-s02)-R*log(P3/P2);//s32 stands for s3-...
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//Ex2_2 Pg-87 clc disp("sigma = u*e*n") u=1200 //mobility e=1.6*10^(-19) //electron charge n=10^13 //phosphorous concentration sigma=u*e*n //conductivity printf("\n Conductivity of pure silicon crystal = %.5f ohm^(-1)/cm \n",sigma) rho=1/sigma //resistivity printf("\n Resistivity of pure phosphorous = %.0f oh...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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// INTERFACE GRÁFICA DO PROGRAMA DA DISSERTAÇÃO //@ Figura principal deff("Fechar(win,x,y,ibut)",["if ibut==-1000 then";"close(win)";"quit";"end"]) clear o; //o.figure_position = [0 0] o.figure_size = [1366 742]//get(0, "screensize_px")(3:4) - [0 40] o.layout = "border...
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clc //Example 17.8 //Spiral bevel gear //------------------------------------------------------------------------------ //Given data //Gear ratio G=4/3 //dimensions of pinion dp=0.15 //m rp=dp/2 b=0.05 //m //speed np=240 //rpm //module m=5*10e-3 //m //pressure angle phi_n=14.5 //degrees //spiral an...
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//maximum mechanical advantage and maximum efficiency //Effort P=150 //N W=7700 //N MA=W/P //mechanical advantage //If efficiency=60% eff=0.6 VR=(MA)/(eff) //When an effort of 250 N raised a load of 13200 N P1=250 //N W1=13200 //N MA1=(W1)/(P1) eff1=MA1*100/VR //percent //assume law of machine as P=...
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//Find the equivalent current source clear; clc; //soltion //given Vs=2;//Volts //dc voltage source Rs=1;//ohm //internal resistance Rl=1;//ohm //load resistance Ise=Vs/Rs;//ampere //equivalent current source // In accordance to figure 1.23a Il1=Ise*(Rs/(Rs+Rl))...
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clear; n = 10; // # of cells in a row m = 4; // # of steps function y=moduln(x) if x==n/2 then y=n else y=modulo(x+n/2,n) end endfunction cp = -1; cr = -1; con_coef = 1; pos_coef = 1; //sun energy = fire for i=1:n/2 for j=1:n sun(i,j)=sin((2*j-1)*%pi/(2*n))*sin((2*i-1)*%pi/...
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//Example 7.13 Energy=1000;//Energy (kJ) E_by_time=400;//Rate of energy consumption (W) Time=Energy*10^3/E_by_time;//Time (s) printf('Duration of bicycling required per day = %0.1f min',Time/60) //Discussion Fat_loss=Energy*1/39;//Fat loss if energy content of fat is assumed to be 39kJ/g (g) printf('\nDiscussion...
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%%-*- mode: erlang -*- %%-*- coding: utf-8 -*- % Test control options [{tests, []}]. %% ============================================================================= %% TESTS: CREATE INDEX & CREATE ROLE & CREATE TABLE & CREATE USER %% ----------------------------------------------------------------------------- % %%...
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s=poly(0,'s') dt=10;//delay time //h=syslin('c',((0.510/(65.49*s+1))))//transfer function using first order pade' approximation tf=((0.475/(36*s+1))*((-dt/2)*s+1/(dt/2)*s+1)); bode(h,0.001,10);
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clear; clc; A= 1.5e-4; Deff=39.8e-3; D= 8; rho1=1.73e-6 / 100; l=1e3; f=50; V=132e3; //(a) R= rho1 * l / A; r=.5 * Deff; L= .4605 * log10 (D/(.7788 *r)); mprintf("L = %.2f mH/km\n",L); C= .02412/(log10 (D/r)); mprintf("C = %.5f e-6 F/km\n",C); //(b) Ic = 2 * %pi * f * C *1e-6 * V / sqrt(3); mp...
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function map_func(i,v,x,y,z) { console.log(i) console.log(v) console.log(x) console.log(y) console.log(z) } mapfivo(arr,Array(3).fill(map_func),Array(3).fill(['a','b','c']))
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clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 3 // Thermal Radiation // Example 3.7 // Page 134 printf("Example 3.7, Page 134 \n\n") // This is a theoretical problem with no numerical data printf("This is a theoretical problem with no numerical data \n"); // Considering an el...
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//example-5.2 //page no-141 //given //bragg's angle of reflection theta1=17.03*(%pi)/180 //radians //wavelength of light lambda=0.71 //A //according to bragg's equation //n*lambda=2*d*sin(theta) //for n=1 d=lambda/2/sin(theta1) //A //given that h^2+k^2+l^2=8 //let (h^2+k^2+l^2)^1/2=H //we get H=sqrt(8...