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clc; clear; a=input('enter a value: '); f=1; for i=1:1:a f=f*i; end printf('\nfactorial of %d is %d\n',a,f)
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//Example 10.7 //to demonstrate the use of predefined string reated function function[] = main() printf("Enter one string:"); str1 = read(%io(1), 1, 1, '(a)'); //read is used instead of using gets len1= length(str1); printf("The length of string is %d \n", len1); str2 = str1;...
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function[img_ret]=cv_tophat(image) pyImport morphological_file img_ret=morphological_file.dilate(image) endfunction
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clc //initialisation of variables P= 10 //psia P1= 100 //psia T= 140 //F k= 1.4 R= 55.16 //ft lb/lb R //CALCULATIONS dh= (k*R*(T+460)/(k-1))*((P/P1)^((k-1)/k)-1)*(72/56000) //RESULTS printf ('Enthalpy change= %.1f Btu/lb',dh)
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clc clear //Initialization of variables d1=12 //in d2=8 //in v1=15 //ft/s p1=12 //psig p2=5.85 //psig rho=1.94 //ft^3/slug angle=60 //degrees //calculations Q=%pi/4 *(d1/12)^2 *v1 v2=Q/(%pi/4 *(d2/12)^2) pa1=p1*%pi/4 *(d1)^2 pa2=p2*%pi/4 *(d2)^2 qv1=rho*Q*v1 qv2=rho*Q*v2 Fx=pa1+qv1+ cosd(angle)*(pa2+qv...
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clc // Given that lambda = 5.89e-7 // wavelength of light in meter d1 = 1 // distance of wavefront recieved on the screen from the opening in first side in meter d2 = 2 // distance of wavefront recieved on the screen from the opening in other side in meter // Sample Problem 8 on page no. 2.40 printf("\n # PROBLEM 8 # ...
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//Exa 3.2 clc; clear; close; //Given data RL=10;//in kohm RS=1;//in kohm hie=1.1;//in kOhm hre=2.5*10^-4;//unitless hfe=50;//unitless hoe=25;//in u mho Aie=-hfe/(1+hoe*10^-6*RL*10^3);//unitless Zie=hie+hre*Aie*RL;//in kOhm Zie=round(Zie); Ave=Aie*RL/Zie;//unitless Avs_e=Ave*Zie/(Zie+RS);// deltah=hoe*10...
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clc;funcprot(0);//EXAMPLE 11.4 // Initialisation of Variables pc=5.45;......................//Petrol consumption in kg/h afr=15;......................//Air fuel ratio af=2*10^(-6);................//Fuel jet orifice area in m^2 z=0.00635;...................//Distance between tip of fuel jet and level of petrol in t...
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clear clc Pp=3e3; Et=1e7 Plp=220 C=2.1 lf=(Et/8760)/Pp lf=round(lf*100)/100 mprintf("\nLoad Factor = %.2f ", lf) L=(.3*lf) + (.7*lf*lf) L=round(L*1000)/1000 mprintf("\nLoss Factor = %.3f ", L) Loss=L*Plp mprintf("\nLoss = %.1f kW", Loss) CLY=Loss*8760*C mprintf("\nCost of Energy Loss = Rs %.1f ...
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clc //initialisation of variables P1=14.7 //lbf/in^2 T1=520//R T3=2060//R P2=70//lbf/in^2 T=1.563 //lbf/in^2 Cp=0.24 s=0.286 //CALCULATIONS T2=T*T1//R Wc=Cp*(T2-T1)//Btu/lbm T4=T3/T//R Wt=Cp*(T3-T4)//Btu/lbm Wnet=Wt-Wc//Btu/lbm qH=Cp*(T3-T2)//Btu/lbm qL=Cp*(T4-T1)//Btu/lbm Nth=(Wnet/qH)*100//per cent...
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clc //Example 14.5 //Install Symbolic toolbox //Find the Inverse Laplace transform syms s s=%s; P =(7*s+5)/(s^2+s); Pp=pfss (P) p1=ilaplace (Pp(1)) p2=ilaplace (Pp(2)) p=p1+p2 disp(p,'p(t)=');
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clear; clc; disp("--------------Example 19.9---------------") //address :- 205.16.37.39/28 n=28; by=8; //number of bits i.e 1 byte a3=dec2bin(205,by); // convert decimal numbers to binary numbers a2=dec2bin(16,by); a1=dec2bin(37,by); a0=dec2bin(39,by); disp("Binary notation of the address is "+a3+"...
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//Variable declaration Idson=0.2 Vgs=5 //gate to source voltage(V) Vdd=12 //drain voltage(V) Vt=2 //thevinine voltage(V) R1=100. //resistance(k ohms) R2=100. //resistance(k ohms) Rd=3...
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//Example 12.9 //Program to determine the viability of optical power budget clear; clc ; close ; //Given data L=7; //km - OPTICAL FIBER LINK LENGTH alpha_fc=2.6; //dB/km - CABLE FIBER LOSS alpha_j=0.5; //dB/km - SPLICE LOSS alpha_cr=1.5; //dB - TOT...
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//Example 4.13. clc format(7) VF=0.6 T=298 Io=10^-5 eta=2 VT=T/11600 disp("The volt-equivalent of the temperature(T) is,") disp(VT,"VT(V) = T / 11600 = ") format(6) I=Io*((%e^((VF/(eta*VT))))-1) disp(I,"Therefore, the diode current, I(A) = Io*e^((VF/eta*VT)-1) =")
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clc; clear; sin_theta1=0.2 //angle in radian sin_theta2=0.3 // angle in radian lambda = 5000*10^-9 //wavelength in cm d=2.5 //width of the grating surface in cm //calculations e=lambda/(sin_theta2-sin_theta1) //in cm N=d/e //number or rulings Rp=2*N printf("Resolving power = %d",ceil(Rp))
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// Creates two plots: // The first contains a function f(x) = exp(-x^2/2), the analytic derivative -x*exp(-x^2/2) // and numerical derivatives based on the difference quotient for three different amount of nodes // The second contains the numerical derivative where the function value contains an error by adding // a no...
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//Chapter 1 : Wave Optics clear; //Variable declaration D1=1.50 D2=1.30 //Calculation myu=(D1/D2)**2 //Result mprintf("Refractive index of liquid= %.3f",myu)
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K m=1; P2=25; P1=1; pV=260; T1=17+273; T2=T1; V1=(pV*T1)/(P1*100000); printf...
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// Exa 7.5 clc; clear; close; // Given data I_D = 5;// in mA V_GS1 = 8;// in V V_GS2 = 4;// in V V_GS = 6;// in V K = I_D/(V_GS1-V_GS2)^2;// in mA/V^2 I_D = K*(V_GS-V_GS2)^2;// in mA disp(I_D,"The drain current in mA is");
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//ex14.3 disp("cannot be shown in scilab")
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clc T1 = 90 // Operating temperature of power plant in degree Celsius T2 = 20 // Atmospheric temperature in degree Celsius W = 1 // Power production from power plant in kW E = 1880 // Capability of energy collection in kJ/m^2 h printf("\n Example 6.6") e_max = 1-((T2+273)/(T1+273)) // maximum efficiency Qm...
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errcatch(-1,"stop");mode(2);//entropy changes in the system for phase transitions ; ; printf("\t Example 18.5\n"); //for fusion T=5.5+273;//temperature of fusion, K deltaH=10.9*1000;//change in enthalpy, J/mol deltaSf=deltaH/T;//since in fusion deltaG=0, J/ K mol //for vaporisation T=80.1+273;//tempera...
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function [x,y,typ] = flex_maxon_mot(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then exprs=arg1.graphics.exprs; maxon_id=exprs(1) standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin'...
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//Example 3_13 //Continuous Time Fourier Series Coefficients of a periodic signal x(t)=2+4*sin((5*%pi)/3*t)+cos((2*%pi/3)*t) clear; clc; t=0:0.01:1; xt=2+4*sin((5*%pi)/3*t)+cos((2*%pi/3)*t); x_t=2+4*sin((5*%pi)/3*-t)+cos((2*%pi/3)*-t); x=2+(1/2)*exp(%i*(2*%pi/3)*t)+(1/2)*exp(-%i*(2*%pi/3)*t)+(4/(2*%i))*exp(%i*(5...
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clc; absorp1=92.90; //in m^^2 absorp2=92.90;//in m^2 V=2265.6;//in m^3 T1=0.16*V/(absorp1); T2=0.16*V/(absorp1+absorp2); ans=T2/T1;//effect on Reverberation time disp(+"of its original value",ans,"Reverberation time will reduced to ")
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//example 5.21 clear; clc; disp("CH4(g)+2O2(g)-->CO2(g)+2H2O(l)"); //Given: S=-242.98;//standard entropy change for reaction [J/K] T=298;//temperature[K] Gf1=-50.72;//standard Gibbs free energy of formation for CH4(g)[KJ/mol] Gf2=-394.36;//standard Gibbs free energy of formation for CO2(g)[KJ/mol] Gf3=-237...
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//Caption:Design a interface circuit for CMOS //Ex12.4 clc; clear; close; Vdd=15//Drain voltage(in volts) Rd=1//Drain resistance(in kilo ohm) Vcc=5//Supply voltage(in volts) Ih=40//Current(in micro ampere) hfe=20 Vce=0.2//Saturated collector emitter voltage(in volts) vih=2//High input voltage(in volts) il=...
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pathname=get_absolute_file_path('8_7.sce') filename=pathname+filesep()+'8_7_data.sci' exec(filename) //Volume flow rate of mixture per second(in m^3/s) V=0.25*%pi*D^2*L*10^-6*(N/(2*60))*k*nv //Air required for the stoichiometric mixture with 1kg fuel(kg/kg of fuel) ma=Ca*((PC/AtC)*32+(PH/AtH)*16)*(100/23.3) //vo...
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// chapter 12 // example 12.8 // calculate numerical aperture and acceptance angle of an optical fibre // page 361-362 clear; clc; // given u1=1.48; // refractive index of core u2=1.45; // refractive index of cladding //calculate NA=sqrt(u1^2-u2^2); // calculation of numerical aperture printf('\nThe numeric...
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function show_info(info) //This function may be redefined by the user to handle display //of the informations associated with the current diagram // Copyright INRIA
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# Monetary incentive delay task # By Gustav Nilsonne and Daniel Samsami 2016 # Free to use with attribution # MID demo test scenario_type = fMRI; pulses_per_scan = 1; pulse_code = 115; active_buttons = 1; response_matching = simple_matching; default_clear_active_stimuli = false; default_background_color = 100, 100, 1...
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errcatch(-1,"stop");mode(2);//Example 6.6.7;inductance ; ; v=220;//in volts r=0.2;//in ohms ia=200;//in amperes f=200;//in hz di=0.05*ia;//in amperes e=0;//in volts d=0.5;// l=((1-d)*v*d*(1/f))/di;// disp(l*10^3,"inductance in mH is") exit();
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; @Harness: simulator ; @Format: atmel ; @Arch: avr ; @Purpose: "Test the TST (test for zero or minus) instruction" ; @Result: "flags.s=0, flags.v=0, flags.n=0, flags.z=1, r16 = 0" start: ldi r16, 0b00000000 tst r16 end: break
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clc; G=3.44*10^-8; //universal gravitational constant in lb.ft square/slug square r=10 //radius in ft w=2000; //weight in lb g=32; //gravitational constant in ft/sec square m=w/g; //calculating mass in slugs F=(G*m*m)/(r*r); //calculating gravitational force in lb disp(F,"Gravitational force in lb = "...
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clc //Initialization of variables dn1=4 //cm v1=300 //cm/s dn2=2.5 //cm //calculations v2=v1*dn1/dn2 //results printf("Velocity = %.1f m/s",v2/100)
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//Chemical Engineering Thermodynamics //Chapter 3 //First Law of Thermodynamics //Example 3.10 clear; clc; //Given V = 0.3;//Volume of the tank in m^3 P1 = 1;//Initial pressure of the tank in atm P2 = 0;//Final pressure of the tank in atm T = 298;//Temperature of the tank in K t = 10;//evacuation time in...
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Irad=20;Orad=25;Dia=22.5 N=250;i=2.5; l=2*%pi*Dia*10^-2; B=1.225; radius=1/2*(Irad+Orad) H=(N*i)/l A=%pi*((Orad-Irad)/2)^2*10^-4 z=(1.225)*(%pi*6.25*10^-4) y=(N*z) L=(y/i) core=(B/H) l=(2*%pi*22.5*10^-2) Rcore=(l)/(core*A) L=(N^2)/(Rcore)
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function [x] = usolve(A,b) // Solve Ax = b by upper solution method // We assume A upper triangular : only the upper triangular // part of A is considered // n = size(A,1); x = zeros(size(b,1),1); x(n)=b(n)/A(n,n); for i=n-1 : -1 : 1 x(i,1) = (b(i,1)-A(i,i+1:n)*x((i+1):n,1))/A(i,i); end endfunction
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//Example 1.21 clc; x1=[1,1,1,1] x2=[2,2,2,2] a1=1; b1=1; a=7; b=5; for t=1:length(x1) x3(t)=a1*x1(t)+b1*x2(t) end for t=1:length(x1) y1(t)=a*x1(t)+b y2(t)=a*x2(t)+b y3(t)=a*x3(t)+b end for t=1:length(y1) z(t)=a1*y1(t)+b1*y2(t) end count=0 for n=1:length(y1) if(y3(t)==z(t)) ...
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x = -10:10; alpha = [0.1 0.33 0.5] sigmoid = 1./(1+exp(-x)) figure(1) subplot(4,1,1) plot(x,sigmoid) sigmoid = 1./(1+0.1*exp(-x)) subplot(4,1,2) plot(x,sigmoid) sigmoid = 1./(1+0.33*exp(-x)) subplot(4,1,3) plot(x,sigmoid) sigmoid = 1./(1+0.5*exp(-x)) subplot(4,1,4) plot(x,sigmoid)
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//Effect of air cleaner clc,clear //Given: A_F=14 //Air fuel ratio at sea level P2=0.834 //Pressure at venturi throat without an air cleaner in bar P1=1.013 //Pressure of air in bar at sea level deltaP_ac=30 //Pressure drop to air cleaner in mm of mercury m_a=250 //Air flow in kg/hr //Solution: //No air cleane...
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#************************************************************ # Scenario of humanTestEnv # # date : Thu Feb 26 16:39:55 2015 #************************************************************ p3d_sel_desc_name P3D_ENV humanTestEnv p3d_sel_desc_name P3D_ROBOT HERAKLES_HUMAN1 p3d_set_robot_steering_method Linear p3d_set...
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//Example 2_4 clc(); clear; //To calculate the total number of lines for the first order lemda=5890 //units in angstrom lemda=5890*10^-8 //units in centimeters dlemda=6*10^-8 //units in centimeters k=1 N=lemda/(k*dlemda) printf("Total no. of l...
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// Scilab Code Ex5.19: Page:306 (2011) clc;clear; D = 1.7;....// Distance between the slit and the screen, m W = 2.5e-003;....// Given fringe width, m a = 8e-005;....// Width of the first slit, m b = 4e-004;....// Width of the second slit, m n = b; // p = [1 2 3 4 5 6]; // In a double slit experiment ...
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## Copyright (C) 2007-2017 John W. Eaton ## ## This file is part of Octave. ## ## Octave is free software; you can redistribute it and/or modify it ## under the terms of the GNU General Public License as published by ## the Free Software Foundation; either version 3 of the License, or (at ## your option) any later vers...
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//===================================================================================== //Chapter 14 example 7 clc; clear all; //variable declaration n =4; //number of full digits v1 = 1; //voltage in V v2 = 10; //voltage in V //calculations R = 1/(10^n); //resolutio...
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//clear// //Example 1.13:Determination of stablility of a given system //Page 49 //given system y(t) = t.x(t) clear; clc; x = [1,2,3,4,0,2,1,3,5,8]; //Assign some input Maximum_Limit = 10; S = 0; for t = 0:Maximum_Limit-1 S = S+t*x(t+1); end if (S >Maximum_Limit) disp('Eventhough input is bounded out...
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clear all; clc; disp("Ex 2_5") //Refer figure 2-17b, we determine the magnitude of each component using trignometry f=200//Magnitude of force F1 in N p1=30//given angle theta in degrees p=p1*%pi/180//angle in radian x1=-1*f*sin(p) x=x1*(-1) y=f*cos(p) printf('\n\nF_1x = %g N = %g N leftwards',x1,x) printf('\n\nF_1y = %...
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//Example 2_19 <a> //compute the Convolution of x[n] and Unit Impulse response h[n] clear; close; clc; Max_Limit=10; for n=1:Max_Limit Alpha=0.5; h=ones(1,Max_Limit); N1=0:Max_Limit-1; x(n)=1; end N2=0:Max_Limit-1; y=convol(x,h); N=0:2*Max_Limit-2; figure a=gca(); plot2d3('gnn',N2,x) xtitle('Input Re...
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function competitive_learning() endfunction
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// Amplitude Modulation-Reception : example 3-3 : (pg 150 & 151) V=8*10^-6; R=50; P=(V^2)/R; dBm=10*log10(P/0.001); dBW=10*log10(P/1); a=(-89+8+3+24+26+26-2+34); x=(a/10); y=10^x; z=y*0.001; printf("\nP = V^2/R = %.15f W",P);//input power in Watts printf("\ndBm = 10log(P/1mW) = %.f dBm",dBm);//input power in...
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//Example 1 // Pressure amplitude, Energy density and Energy flux clc; clear; close; //given data : A=1*10^-5;// in m n=500;// in per sec v=340;// in m/s p=1.29;// in kg/m^3 Pa=2*%pi*n*v*p*A; disp(Pa,"Pressure amplitude,Pa(N/m^2) = ") Ed=2*%pi^2*n^2*p*A^2; disp(Ed,"Energy density,Ed(J/m^3) = ") Ev=Ed*v; disp(Ev,"Energy...
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//To calculate the relative permeability M = 1.4; //field, T H = 6.5*10^-4; //magnetic field, T chi = M/H; //susceptibility mew_r = 1+chi; //relative permeability printf("relative permeability of iron is %d",mew_r); //answer given in the book is wrong
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clc T=1.25; //N.m N=9500; W1=2*%pi*N*T/1000; //kJ p=101.3; //kPa d=0.65; //m A=%pi/4*d^2; //m^2 L=0.6; //m W2=p*A*L; //kJ Wnet=(-W1)+W2; disp("The net work transfer for the system=") disp(Wnet) disp("kJ")
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errcatch(-1,"stop");mode(2);//Ex 7.2 ;; RA=10;//kohm C=0.1;//micro F t=1.1*RA*C;//ms disp(t,"Timing interval(ms)"); exit();
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//(Threaded Joints) Example 7.17 //Refer Fig. 7.36 on page 257 //Pre-load in the bolt Pi (kN) Pi = 2.5 //External force acting on the bolt P (kN) P = 5 //Yield tensile strength of 30C8 Syt (N/mm2) Syt = 400 //Factor of safety fs fs = 2.5 //Assume stiffness of bolts to be 1N/mm kb kb = 1 //Stiffness of par...
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//EX5_2 PG-5.6 clc Vbe=0.7;//base emitter voltage for silicon Vcc=12;//supply voltage Rb=150e3; Rc=2e3 hFE_min=50;//minimum voltage gain hFE_max=60;//maximum voltage gain Ib=(Vcc-Vbe)/Rb;//since Vcc=Ib*Rb+Vbe printf("\n base current is %.8f A \n",Ib) printf("\n for hFE_min=50") Ic=hFE_min*Ib printf("\n Ic=%...
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//Chapter 7, Problem 10 clc; l=150*10^-3; //length u0=4*%pi*10^-7; //permeability of free space ur=4000; //relative permeability A=1800*10^-6; //cross-sectional area S=l/(u0*ur*A); ...
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function lst=mmodlst(lst) // mmodlst is used to reduce mutiple concatenations, obtained by the // interpretor, such as // [[a,b],c] // [[a;b];c] // to a single one whenever possible //! // Copyright INRIA void=['0','0','0','0'] nlst=size(lst);top=0 ilst=0 pos=[] to_kill=[] while ilst<nlst ilst=ilst+1 if type(ls...
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clc; P=200000; //rated power of transformer E1=4000; // primary side rated voltage E2=1000; // secondary side rated voltage n=0.97; // efficiency pfn=0.25; // power factor at no load pff=0.8; // power factor at full load vr=5; // percentage voltage regulation Pl=((1/n)-1)*200000; // total losses at full load ...
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clc; //Exmple 24.4 //page no 354 printf("Example 24.4 page no 354\n\n"); //a particle is spining in a 3 inch ID centrifuge r=3/12//radius of centrifuge,ft omega=30//rotational speed,rad/s g=32.2 G=round(r*omega^2/g) printf("\n G=%f ",G);
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// Exa 1.35 clc; clear; // Given f = 450; // Resonating frequency in kHz C = 250; // Capacitor value at resonating frequency (pf) Q = 105; // Q-meter reading at resonance Rsh = 0.75; // Value of shunt resistance in ohms // Solution L = 1/((2*%pi*f*10^3)^2*C*10^-12); // in H w=2*%pi*f*10^3; R = (w*...
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// calculate the percentage change in value of the gauge resistance clc; s=100*10^6; E=200*10^9; strain=s/E; Gf=2; r_perunit=Gf*strain*100; disp(r_perunit,'Percentage change in resistance=')
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//scilab 5.4.1 //Windows 7 operating system //chapter 17 Number Systems,Boolean Algebra,and Digital Circuits clc clear p=1; //initialising variables q=1; z=0; b=0; w=0; f=0; format('v',18);//increasing the precision to 18 . bin=11.1101; d=modulo(bin,1);//separating the decimal part and the integer part d...
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// Example 4.11 clc; clear; close; // Given data V_CC= 6;// in V V_BE= 0.7;// in V bita= 100; R_C= 2;// in kΩ R_C= R_C*10^3;// in Ω R_B= 530;// in kΩ R_B= R_B*10^3;// in Ω R1= 10;// in kΩ R1= R1*10^3;// in Ω R2= 5;// in kΩ R2= R2*10^3;// in Ω V_CE= 0:0.1:V_CC;// in V I_C= (V_CC-V_CE)/(R_C)*10^3;// in m...
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clc Qa=0.003/60; // m^3/s Ca=20; // g/l Co=0.126; // g/l dp=3700; // N/m^2 p=1000; // N/m^2 d=0.1; // m a=%pi*d^2/4; Qi=Qa*((Ca-Co)/Co); Q=Qi+Qa; B=10/6; Cd=Q/a/sqrt(2*dp/p/(B^4-1)); disp("Coefficient of discharge =") disp(Cd)
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Ex13_12.sce
clc(); clear; //Given : M1 = 20; // neon isotope mass in amu M2 = 22;//neon isotope mass in amu E = 7*10^4; // Electric field in V/m e = 1.6*10^-19;// electron charge in C B = 0.5;// Magnetic field in Wb/m^2 B1 = 0.75; // Magnetic field in Wb/m^2 // Linear seperation = S2 - S1 = (2*E*(M2-M1))/(B*B1*e) // 1 ...
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Chapter14_Example2.sce
//Chapter-14, Example 14.2, Page 576 //============================================================================= clc clear //INPUT DATA pA=-0.9;//Partial pressure of water vapour in atm t=0.0025;//Boundary layer thickness in m //CALCULATIONS //pA=(exp(-33.35y)-0.9) y=0; pAs1=exp(-33.35*y)-0.9;//Partia...
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example2_31.sce
clc // Given that lambda1 = 5.4e-7 // wavelength of light for nth order in meter lambda2 = 4.05e-7 // wavelength of light for (n+1)th order in meter theta = %pi / 6 // angle of diffraction in radian // Sample Problem 31 on page no. 2.50 printf("\n # PROBLEM 31 # \n") k = (lambda1 * lambda2) / ((lambda1 - lambda2) * ...
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hellow world.sce
d="hellow world"; disp(d)
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//Function to round-up a value such that it is divisible by 5 function[v] = round_five(w) v = ceil(w) rem = pmodulo(v,5) if (rem ~= 0) then v = v + (5 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution10_6.sce') //Obtain path of data file dat...
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clc clear //DATA GIVEN //CASE-1 //(T1-T2)/T1=1/6 //SO, T1=1.2(T2)......... Eqn(1) //CASE-2 //T2 REDUCED BY 70 DEG. CELSIUS //{T1-[T2-(70+273)]}/T1=1/3..............Eqn(2) //2T1=3T2-1029 //By Eqn (1) and (2) T2=(70+273)*3/(3-2*1.2); T1=1.2*T2; printf('(i) The Temperature of the Source, ...
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//example 10.1 clc; funcprot(0); Gamma=18; H=7; sigmaa=0.3*Gamma*H; disp(sigmaa,"maximum pressure intensity in kN/m^2"); //partb A=54.02; B1=1/2*1.75*37.8+37.8*1.75-A; B2=45.2; C=54.02; s=3; //spacing Pa=C*s; disp(Pa,"strut loads in kN"); Pb=(B1+B2)*s; disp(Pb,"strut loads in kN") Pc=C*s; disp(Pc,"stru...
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Resposta_Frequencia_Hs.sci
function [H,f]=Resposta_Frequencia_Hs(Hs,fs,N) b=coeff(Hs(2)) a=coeff(Hs(3)) npolos=length(a)-1 nzeros=length(b)-1 f=linspace(0,2*fs,N); w=2*%pi*f; s=%i*w; num=zeros(1:N); den=zeros(1:N)+0.0001;; for p=0:npolos den=den+a(p+1)*s.^p; end for p=0:nzeros num=num+b(p+1)*s.^p; end H= num./den; ...
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clear; clc; printf("\nEx2.1\n"); //page no.-55 //given h=6.60*10^-34;...........//planck's constant in J-s m=1.674*10^-27;.........//mass of neutron in Kg lambda=10^-10;...........//wavelength in m e=1.6*10^-19;.............//charge //We know lambda=h/sqrt(2*m*E) E=(h^2)/(2*m*lambda^2*e)............//energy...
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load Mux2Way7Bit.hdl, output-file Mux2Way7Bit.out, output-list x0%B1.7.1 x1%B1.7.1 s0%B1.1.1 y%B1.7.1; set x0 %B1010101, set x1 %B0000000, set s0 0, eval, output; set x0 %B0000000, set x1 %B0000011, set s0 1, eval, output;
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//Finding of C and f //Given n=0.012; d=0.5; w=2; g=9.81; //To Find A=w*d; P=2+(w*d); R=P/A; C=(1/n)*(R)^(1/6); f=sqrt((8*g)/(C^2)); disp(" C="+string(C)+" m/sec"); disp("f ="+string(f)+" no units");
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//control systems by Nagoor Kani A //Edition 3 //Year of publication 2015 //Scilab version 6.0.0 //operating systems windows 10 // Example 5.7 clc; clear; s=poly(0,'s') a=(s^5)+(4*s^4)+(8*s^3)+(8*s^2)+(7*s)+4 b=coeff(a) n=length(b) R=routh_t(a) disp(R,'the routh array is;') ap=s^2+1 r=roots(ap) disp(...
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//Chapter-6,Example 6_18_2,Page 6-38 clc() //Given Values: u0=4*%pi*10^-7 //Permeability in vacuum ur=380 //Relative permeability d=20*10^-2 //diameter of solenoid in m r=d/2 //radius of ring in m A=5*10^-4 //Crosss sectional area of ring in m^2 phi=2*10^-3 ...
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liban V;PFOC;LGSPEC1 isip V;PFV;PFOC bagsak V;NFIN alaga' V;NFIN nakaw V;IPFV;PFOC maneho V;IPFV;PFOC másid V;IPFV;PFOC taguyod V;PFOC;LGSPEC1 kuha' V;PFOC;LGSPEC1 basag V;PFV;AGFOC hirap V;NFIN babá' V;NFIN panalo V;IPFV;AGFOC hagod V;PFOC;LGSPEC1 sundó' V;PFV;PFOC kusot V;PFOC;LGSPEC1 gayat V;IPFV;PFOC bagsak V;IPFV;...
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clc // Given that lambda = 5000 // wavelength of light in angstrom theta = 30 // angle in degree d_theta = 0.01 // angular separation in radian // Sample Problem 22 on page no. 165 printf("\n # PROBLEM 22 # \n") printf(" Standard formula used \n") printf(" d_theta /d_lambda = n/(e+d)*cos(theta) \n") d_lambda...
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clc clear mode(-1) //CPII UFU 2017 //define macro which traces an ellipse function []=ellipse(m1,m2,s1,s2,s12) t=0:.1:.1+%pi*2; c=2*cos(t);... s=2*sin(t);... rho=s12/sqrt(s1*s2);... cr=sqrt(s1)*c+m1*ones(c);... sr=sqrt(s2)*(rho*c+sqrt(1-rho*rho)*s)+m2*ones(s);... plot(cr',sr') endfunction //gener...
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//ques-18.23 //Calculating standard free energy change for the reaction clc //G = free energy (in kJ/mol) G1=-16.8;//ammonia G2=-86.7;//NO G3=-237.2;//water G=G2+G3*(1.5)-G1;//free energy change printf("The free energy change required is %.1f kJ/mol.",G);
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// Scilab Code Ex2.21 Ionization potential of hydrogen atom: Pg:59 (2008) m = 9.1e-031; // Mass of the electron, C e = 1.6e-019; // Charge on an electron, coulomb h = 6.626e-034; // Planck's Constant, Js epsilon_0 = 8.85e-012; // Absolute electrical permittivity of free space, coulomb square per newton ...
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//To find torque exerted clc //Given: TA=15, TB=20, TC=15 NA=1000 //rpm Tm=100 //Torque developed by motor, N-m //Solution: //Refer Fig. 13.26 and Table 13.21 //Calculating the number of teeth on gears E and D TE=TA+2*TB TD=TE-(TB-TC) //Speed of the machine shaft: //From the fourth row of the table, x+y = 1...
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clear; clc; //Example2.16[Heat Conduction through a Spherical Shell] //Given:- r1=0.08;//Inner Radius[m] r2=0.1;//Outer radius[m] k=45;//Thermal conductivity[W/m.degree Celcius] T1=200;//Temperature of inner surface[degree Celcius] T2=80;//Temperarure of outer surface[degree Celcius] //Solution:- //Integrat...
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// Etude numˇrique du rayonnement d'un corps noir clear h = 6.6256e-34; c0 = 2.9979e8; nlambda = 1; clambda = c0/nlambda kB = 1.3807e-23; function Llambda = corpsnoir(lambda,T) // dˇfinit la distribution de luminance ˇnergˇtique monochromatique // du rayonnement thermique du corps noir en fonction // de la...
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clear ; clc; // Example 4.1 printf('Example 4.1\n\n'); //Page no. 92 // Solution //(a) Temp_c=100 ;//[degree Celsius] Temp_k=Temp_c+273 ;//[K] printf('(a) Temperature in kelvin is %.2f K\n',Temp_k); //(b) Temp_f=(100*(1.8/1)) +32 ;//[degree Fahrenheit] printf(' (b) Temperature in degree Fahrenheit is ...
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clear; clc; V_s=11000; V_ml=sqrt(2)*V_s; f=50; w=2*%pi*f; I_d=300; R_d=1; g=20;//g=gamma a=acosd(cosd(g)+%pi/(3*V_ml)*I_d*R_d); printf("firing angle=%.3f deg",a); L_s=.01; V_d=(3/%pi)*((V_ml*cosd(a))-w*L_s*I_d); printf("\nrectifier o/p voltage=%.1f V",V_d); printf("\ndc link voltage=%.3f V",2*V_d/1000...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 12: POWER,ENERGY,AND EFFICIENCY RELATIONS OF DC AND AC DYNAMOS // Example 12-17 clear; clc; close; // Clear the work space and console. // Given data // code letter = J of SCIM (Ex.12-16) // Ca...
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//Ex 1.12 clc;clear;close; format('v',6); R1=30;//ohm R2=60;//ohm R3=30;//ohm I3=1;//A I1=I3*(R2+R3)/R2;//A I2=I1-I3;//A disp(I1,"Current I1(A)"); disp(I2,"Current I2(A)");
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clc ;funcprot(0); //Example 2.3 //Initializing the variables p1 = 101*10^3;//Initial Pressure z1 = 0;//Initial Height z2 = 1200;//Final Height T1 = 15+273;//Initial Temperature g = 9.81;//Acceleration due to gravity gamma = 1.4;//Heat capacity ratio R = 287;//Gas Constant //Calculations p2 = p1*(1-g*(z...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh,Chapter 1,Example 1") h=30*10^-2;//manometer deflection of mercury in m g=9.78;//acceleration due to gravity in m/s^2 rho=13550;//density of mercury at room temperature ...
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//example 4.3 clear; clc; //Given: M=2.5;//mass of a substance[Kg] x=0.6;//fraction of vapour phase Ug=1105;//specific internal energy of saturated vapour[J/Kg] Ul=298;//specific internal energy of saturated liquid[J/Kg] //to find the total internal energy of the mixture U=M*[(1-x)*Ul+x*Ug]; printf(...