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clc //given that theta = 30 // angle between a line joining centres of anion with their median in degree printf("Example 4.4\n") r_ratio = (1- cos(theta*%pi/180))/ cos(theta*%pi/180) printf("\n Minimum cation to anion radius ratio is %.3f",r_ratio)
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// Scilab Code Ex3.11: Page:138 (2011) clc;clear; r = 1.86e-10;....// Radius of Na, angstrom m = 9.1e-31;....// Mass of electron,in kg h = 6.62e-34;....// Planck's constant, J-s N = 2;....// Number of free electrons in a unit cell of Na a = 4*r/sqrt(3);....// Volume of Na, m V = a^3;....// Volume of the unit ce...
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// Example1_14_pg29.sce // To find regulation by percent method // Theory of Alternating Current Machinery by Alexander Langsdorf // First Edition 1999, Thirty Second reprint // Tata McGraw Hill Publishing Company // Example in Page 29 clear; clc; close; // Given data v1 = 1100; // Primary voltage, volts v2 = 110; /...
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// // 08.05.31 // 09.12.25 // 10.01.01 // 11.05.26 (for pdflatex) function Drwpt(varargin) global Wfile FID TenSize TenSizeInit MilliIn; Nargs=length(varargin); All=Nargs; Tmp=varargin(All); Iro=[0,0,0,1]; Iroflg=0; if type(Tmp)==10 then Iro=Ratiocmyk(Tmp); Iroflg=1; All=All-1; end Tmp=v...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat transfer, Seventh Edition, Frank Kreith, Raj M Manglik and Mark S Bohn, Chapter 9, Example 4") //Hemispherical emissivity of an aluminum paint at wavelengths below 3 microns epsilon_lamda_1=0.4; ...
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// Exa 2.26 clc; clear; close; // Given data x1= 1.570; x2= 1.597; x3= 1.591; x4= 1.562; x5= 1.577; x6= 1.580; x7= 1.564; x8= 1.586; x9= 1.550; x10=1.575; n=10; // (i) x_bar= (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10; disp(x_bar,"Arithmetic mean in gramme") d1= x1-x_bar; d2= x2-x_bar; d3= x3-x_bar; d4= ...
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clc; funcprot(0); // Initialization of Variable B=180.0;//height in m f=120.0;//focal length in mm pa=54.32//parallax in mm pb=46.35;//parallax in m //calculation delH=B*f/pa/pb*(pa-pb); disp(delH,"height difference in m") clear()
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//Find the inductance per phase of 30 km line clear; clc; //soltion //given r=(15)/2;//mm//radius of the conductor re=r*exp(-1/4); d=1.5*1000;//mm//spacing L=0.2*log(d/re); printf("Loop Inductance of line= %.2f mH/km\n",L); Ll=L*30/1000; printf("Inductance per phase of 30 km long line= %.4f H",Ll);
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a=5*6*10^(-4); d=0.5*10^(-3); disp("Part a"); k=1; e0=8.85*10^(-12); c=k*e0*a/d; disp("the capacitance (in pF) is"); disp(c*10^12); disp("Part b"); k1=5; c1=k1*c; disp("the capacitance (in pF) is"); disp(c1*10^12); disp("Part c"); k2=7500; c2=k2*c; disp("the capacitance (in μF) is"); disp(c2*10^6); disp(...
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function [stk,txt,top]=sci_plot() // Copyright INRIA txt=[] RHS=[] for k=1:rhs RHS=[stk(top)(1),RHS] top=top-1 end stk=list('mtlb_plot'+'('+makeargs(RHS)+')','0','?','?','?')
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//page no 43 //example no 2.4 //CALCULATING NO OF CHIPS. clc; //chip 1024*1 has 1024(1k) registers & each register can store one bit with one data line. We need 8 data lines for byte size memory. Therefore 8 chips are necessary for 1k byte memory.For 1k byte memory we will need 64 chips. We can arrive at the same a...
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//developed in windows 8 operating system 64bit //platform Scilab 5.4.1 //example 29_2w clc;clear; //Given Data q_a=8*10^-6; //Charge at A (Unit: C) q_b=-2*10^-6; //Charge at B (Unit: C) dis_ab=20*10^-2; //Distance between A and B(Unit: m) //Calculation distance=dis_ab/((q_a/(-q_b))^(...
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clc //initialisation of variables T= 298.2 //K T1= 1000 //K R= 1.987 //cal/mol K k= -2.52 G= 34500 //cal G3= 4.63 //kcal //CALCULATIONS G1= -R*T1*2.303*k G2= ((T*G1/T1)-(G*(T-T1)/T1)-1.5*R*T*2.303*log10(T/T1))/1000 G4= (G2+G3)/2 //RESULTS printf (' Standard free energy = %.2f kcal mole^-1 ',G4)
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// Pregunta 5 // Aproxima la funcion que pasa por los puntos // x con imagen y // por el metodo de los minimos cuadrados // a partir de los 2 polinomios: // x // x^2 // retorna los coeficientes correspondientes function a = minimosCuadrados(x, y) [_, n] = size(x) A = zeros(n, 2) for i = 1:n ...
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//Program 11.5 data //Data for Program 11.5 A=1; B=2; C=3; X1=4; X2=5; X3=6;
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// Density of metal powder lubricant mix clc m_fe = 1000 // mass of iron in gram m_l = 25 // mass in gram d_fe = 7.86 // density of iron in gram/cc d_l = 1.2 // density of lubricant in gram/cc d_ap = 2.75 // apparent density in gram/cc m_L = 30 // mass of lubricant in gram printf("\n Example 11.2") V = m_fe/d...
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clear;lines(0); deff('exampl(a,varargin)',['[lhs,rhs]=argn(0)' 'if rhs>=1 then disp(varargin),end']) exampl(1) exampl() exampl(1,2,3) l=list('a',%s,%t); exampl(1,l(2:3))
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//one-turn test clc; clear; rootpath = "/home/feng/zhangfeng3/Interface_scilab_mbdyn/"; mbd_outfile = "out/double_swing_test_singleton.mbd"; mov_outfile = "out/double_swing_test_singleton.mov"; exec("model/init_2s.sci", -1); [time_cfg, const_val, ref_mat, nodes, bodies, joints] = init_2s(); exec("model/double_swing.s...
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//for the cessna skylane(CP-1): b=10.912;//wingspan(meter) S=16.165;//wingarea(m^2) AR=b^2/S;//aspect ratio D=1.225;//density at sea level(Kg/m^3) W=13127.5;//normal gross weight(N) f=65;//fuel capacity P=230;//power provided by piston engine (unit-horsepower(hp)) Sf=2.0025;//specific fuel consumption(N/(hp.h))...
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//Exa 7.7 clc; clear; close; // given : D_a=6 // Diameter of paraboloid reflector in m c=3*10^8 // speed of light in m/s f=4 // frequency in GHz f=4*10^9 // frequency in Hz lambda=c/f // wavelength in m r=2*D_a^2/lambda // required minimum distance between two antennae in m disp(r,"required minimum distance ...
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//Example 9.17.7 // impedance of CRO clear; close; clc; K=10;// vin=1;//vpp vout=0.1;//in vpp c1=2;// in pF c2=c1*(K-1);//CAPACITANCE IN Pf disp(c2,"capacitance in pF")
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clear; clc; disp('Vector potential A=-p^2/4'); Q=%pi/2,p1=1,p2=2,z1=0,z2=5 Y=.5*integrate('p','p',p1,p2)*integrate('1','z',z1,z2); disp(Y,'Total magnetic flux= ')
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// // Plik wczytujacy dane z pliku LogiSciLabbDane // data zbierania logow: 18_59 11/07/2016 // // Opis zmiennych: // AccGyroRaw_ACCX - wektor zaiwrajacy parametru :ACCX z pliku: AccGyroRaw_log.txt // AccGyroRaw_ACCX_Size - stala zawierajaca rozmiar powyzszego wektora // AccGyroRaw_ACCY - wektor zaiwrajacy parametru...
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clear; clc; // Example: 5.3 // Page: 151 printf("Example: 5.3 - Page: 151\n\n"); // Solution //*****Data*****// Th = 650 + 273;// [K] Tl = 30 + 273;// [K] Qh = 585;// [kJ/cycle] //*************// // Solution (a) // From Eqn. (5.9) eta = (Th - Tl)/Th; printf("(a) The efficiency of the Carnot engi...
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clc disp('15.1','ЗАДАНИЕ №15') function w=f(x,y) w=(y+(3/(x+1)))/x endfunction //clc scf format('v',5) x0=3; y0=2 x=[3:1:10] z=ode(y0,x0,x,f) xname('15.1') plot(x,z,'-*'); xgrid() disp(x); disp(z) disp('15.2', '********************************') function w=f(x,y) w=(y+cos(x)*x^2)/2 endfunction //clc scf format...
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//ex11.2 R_S=10^3; V_BIAS=110; V_BE=0.7; V_CE_sat=0.1; V_A=V_BE+V_CE_sat; //VOLTAGE ACROSS ANODE V_R_s=V_BIAS-V_A; //VOLTAGE ACROSS R_S I_A=V_R_s/R_S; disp(I_A,'Anode current in amperes')
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//Page Number: 376 //Example 7.11 clc; //Given e=1.6D-19; //J B0=0.01; //Wb/m2 d=6D-2; //m V0=20D+3; //V ebym=1.759D+11; //(i) Hull cut off voltage Voc=(B0*B0*d*d*ebym)/2; disp('KV',Voc/1000,'Hull cut off voltage:'); //(ii) Hull magnetic field Boc=sqrt((2*V0)/ebym)/d; disp('mT',Boc*1000,'Hull magnetic...
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//check o/p when i/p is a matrix y=[2+1*%i; 2; 3; 4; 5; 6; 7; 8; 9; 0; -2; 3; 4; 5; 6]; arcoeffs = armcov(y,4) disp(arcoeffs); ////output // // column 1 to 2 // // 1. - 1.0786743 - 0.0073891i // // column 3 // // 0.5713563 + 0.0093133i // // column 4 // // - 0.4206988 - 0.01219...
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//CAPTION: Criterion_of_Mode_Operation //chapter_no.-7, page_no.-304 //Example_no.7-3-1 clc; // Calculate_the_criterion_for_classifying_the_modes_of_operation er=13.1; e=1.6*(10^-19); E=8.854*(10^-12)*er;//dielectric_constant vd=2.5*(10^5);//electron_drift_velocity un=.015;//negative_electron_mobility ...
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//Chapter 2,Ex2.42,Pg2.53 clc; disp("Refer to the diagram shown in the question") A=[14 -12;-12 16] //Apply KVL theorem to obtain the required result B=[2;-4] I=A\B Vth=3*I(2)+4 //Thevenin voltage printf("\n Vth=%.1f \n",Vth) R1=((2*12)/(2+12))+1 Rth=R1*3/(R1+3) Iload=Vth/(Rth+2) printf("\n Il=%.2f \n",Iload...
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clc; R=330; VS=5; VD=VS; disp('V',VD*1,"VD=VS="); VR=0; disp(VR,"VR="); I=0; disp(I,"I=");
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// Scilab Code Ex4.1 : Page-91 (2010) D = 50; // Distance between source and the screen, cm lambda = 6563e-008; // Wavelength of light of parallel rays, m d = 0.385e-01; // Width of the slit, cm n = 1; // Order of diffraction for first minimum // As sin(theta1) = n*lambda/d = x1/D, solving for x1 ...
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clear; clc; //Example - 4.6 //Page number - 154 printf("Example - 4.6 and Page number - 154\n\n"); //Given m = 1000;//[g] - Mass of fluid P_1 = 20;//[bar] - Initial pressure P_2 = 2;//[bar] - Final ressure T_1 = 250 + 273.15;//[K] - Initial tempearture R = 8.314;//[J/mol*K] - Universal gas constant // ...
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// To find elapsed time // Modern Electronic Instrumentation And Measurement Techniques // By Albert D. Helfrick, William D. Cooper // First Edition Second Impression, 2009 // Dorling Kindersly Pvt. Ltd. India // Example 14-4 in Page 401 clear; clc; close; // Given data n = 1.55; //index of refraction c...
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// Exa 6.1 clc; clear; close; format('v',8) // Given data Rs = 10;// in k ohm Rs = Rs * 10^3;// in ohm Rin = 10;// in ohm Rout = 10;// in k ohm Rout = Rout * 10^3;// in ohm R_L = 10;// in ohm Ai = 1000;// unit less VinBY_Iin= Rin;// in ohm VoutBY_Iin= Ai*Rout*R_L/(Rout+R_L);// in V Av= VoutBY_Iin/VinBY_I...
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//Exa 1.8 clc; clear; close; //Given data R=1;//in kOhm RL=5;//in kOhm VZ=10;//in volt Vo=10;//in volt P=250;//in mW IL=Vo/RL;//in mA IZmin=0;//in mA IZmax=P/VZ;//in mA Imin=IZmin+IL;//in mA Imax=IZmax+IL;//in mA Vin_min=VZ+Imin*10^-3*R*10^3;//in volt Vin_max=VZ+Imax*10^-3*R*10^3;//in volt disp("The in...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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function save_csuper(x,fpath) // given a super block definition x save_super creates a file which contains // this super block handling macro definition x1=x(1);nam=x1(2); nin=0;nout=0;clkin=0;clkout=0; bl=' ' com='/'+'/' for k=2:size(x) o=x(k) if o(1)=='Block' then select o(5) case 'IN_f' then ni...
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function strmatOutput = BuildLevelCutToolPath(plRemovalArea, fRapidClearance, fSafetyClearance, fDoC) //TODO: Add a function to handle discontiguous areas... i.e. multiple calls //to this function with additional code to handle tool path between spearate areas. //DEFINE CONSTANTS sCodeRapid = ...
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// Example 3.15 // Calculation of external efficiency // Page no 484 clc; clear; close; //Given data ne1=0.20; //Total efficiency V=3; // Voltage applied Eg=1.43; // Bandgap energy // External efficiency ne=(ne1*Eg/V)*100; //Display result on command window printf("\n Ext...
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// problem 5.6 L=36 v1=2 g=9.81 H=1.2 H1=(v1*v1)/(2*g) n=2*12 w=0.6 Nv=11 Lf=L-(Nv*w) Q=1.84*(Lf-(0.1*n*(H+H1)))*((H+H1)^1.5-(H1^1.5)) disp(Q,"dischsrge over the weir in m3/sec")
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@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005]...
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clc //Intitalisation of variables clear t= 0.3965 A0= 126.45 //ohm^-1 CM62 //CALCULATIONS l= (1-t)*A0 //RESULTS printf ('ion conductance of the Cl- ion = %.2f ohms^-1 cm^2',l)
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clear; clc; t=100*10^-6; R=10; //V_s*(1-2*exp(-t/(R*C)))=0 C=-t/(R*log(1/2)); printf("Value of comutating component C=%.3f uF",C*10^6); disp("max permissible current through SCR is 2.5 times load current"); L=(4/9)*C*R^2; printf("value of comutating component L=%.1f uH",L*10^6); disp("max permissible curr...
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//Fiber-optics communication technology, by Djafer K. Mynbaev and Lowell L. Scheiner //Example 11.3.4 //windows 7 //Scilab version-6.0.0 clc; clear; //given NEPnorm1=3.3E-12;//Bandwidth normalised NEP in W/sqrt(Hz) from 0-10MHz BW1=10E+6;//Bandwidth for case 1 in Hz x=NEPnorm1*sqrt(BW1); NEPnorm2=30E-1...
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// Updated(9-8-07) // 6.16 process_armax = armac([1 -0.5],[0 0 0.6 -0.2],[1 -0.3],1,1,0.05); u = prbs_a(5000,250); xi = rand(1,5000); y = arsimul(process_armax,[u xi]); z = [y(1:length(u))' u']; zd = detrend(z,'constant'); // Compute IR for time-delay estimation [ir,r,cl_s] = cra(detrend(z,'constant')); ...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-8,Example 2,Page 275 //Title: Enthalpy and entropy departure //================================================================================================================ clear clc //INPUT T=427.85;//te...
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//Chapter 5:Dc Motor Drives //Example 7 clc; //Variable Initialization //Ratings of the DC series motor which operated under dynamic braking Ra=0.5 //total resistance of armature and field windings in ohms Rf=10 //field resistance in ohms T=500 //overhauling load torque in N-m N=600 ...
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//Ex6_14 //Segmentation in HSI Space // Version : Scilab 5.4.1 // Operating System : Window-xp, Window-7 //Toolbox: Image Processing Design 8.3.1-1 //Toolbox: SIVP 0.5.3.1-2 //Reference book name : Digital Image Processing //book author: Rafael C. Gonzalez and Richard E. Woods clc; close; clear; xdel(winsi...
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x0=0.996 basis=100 //mol combined feed to the reactor inputxH2=0.7 single_pass=0.6 inputxCO2=0.28 molI=2 Ix=0.004 final=155 //kmol/h
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clear exec('C:\Users\Julien Guégan\Desktop\PFE\fonctions test.sce',-1) exec('C:\Users\Julien Guégan\Desktop\PFE\Algorithmes\Uzawa\recherche lineaire.sce',-1) exec('C:\Users\Julien Guégan\Desktop\PFE\Algorithmes\Gradient\Gradient.sce',-1) function alpha = backtracking(f,x,d,grad) alpha = 1 w = 10^-4 cpt = 0 ...
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//chapter9 //example9.3 //page327 fc=1000; C2=.005*10^-6;R1=33*10^3;//let assume C3=C2;C=C2; R3=1/(2*3.14*fc*C); disp(R3) R2=R3 Rf=.586*R1; disp(Rf)
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PL/SQL Developer Test script 3.0 27 declare xml_clob clob; begin select xmlagg( xmlelement("CLASS",xmlelement("CLASS_BODY",'&'|| cl.id ||'&:{&NAME&:&' || cl.name || '&,').extract('//CLASS_BODY/text()') ,xmlelement("CLASS_BODY_END",'},'...
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// Example 5.3 format('v',4) clc; clear; close; // given data V_BE= 0.7;//in V V_CC= 30;// in V R_B= 390;// in kΩ R_B= R_B*10^3;//in Ω R_C= 1.5*10^3;//in Ω bita= 80;// unit less I_B= (V_CC-V_BE)/R_B;//in A // The collector current, I_C= bita*I_B;//in A // The value of V_CE V_CE= V_CC-I_C*R_C;//in V I_C...
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// Ex. 10.2, cont'd 6.6 mode(0) P = 1000; L = 2000; t = 4.7;//mm b = 20*t h = 2*b I = h^4/96 Q = t*b*h/2+2*t*h^2/8 Fxs = 0.87//from carpet Fxys= 0.4010*10/100+0.0884 Fxt = Fxs*903 Fxc = Fxs*357 Fxy = Fxys*357 M = P*L V = P sx = M*h/(2*I) Rb = Fxc/sx tau = Q*V/(I*2*t) Rs = Fxy/tau
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clc //Initialization of variables sigma1 = 2.92 // angstroms sigma2 = 3.68 // angstroms sigma12 = (sigma1+sigma2)/2 // angstroms T = 294 // Kelvin M1 = 2.02 // Mol wt of hydrogen V1 = 7.07 V2 = 17.9 M2 = 28 // Mol wt of Nitrogen p = 2 //atm Omega = 0.842 Dexp = 0.38 // cm^2/sec //calculations D1 = ((1.8...
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//(Friction Clutches) Example 11.9 //Torque transmitted by oil-immersed multi-disk clutch Mt (N-m) Mt = 75 //Coefficient of friction between the asbestos lining and steel plate mu mu = 0.1 //Permissible intensity of pressure on the asbestos lining Pa (kPa) Pa = 500 //Outer diameter of the friction lining due t...
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// Exa 10.1 clc; clear; // Given data //9-bit DAC step = 10.3; // mV y=[1 0 1 1 0 1 1 1 1]; n = 9; // since 9 bit DAC // Solution i = n; add = 0; while(i>0) op = step*2^(i-1)*y((n+1)-i); i = i-1; add = add + op end printf('The output voltage for input 101101111 is %.2f V. \n',a...
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//Variable Declaration n = 3840 p = 1.0/1200 l = [] x = [0,1,2,3,4,5,6,7,8,9,10] //Calculation lamda = n*p for i = 1:11 l(i) = ((%e^-lamda)*(lamda^i))/factorial(i) end //Results printf ( "Lamda: %.1f",lamda) bar(x,l,width=1) xlabel("$No. of Failed generators$") ylabel("$Probability$")
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# Header Info ########################################## pulse_width = 5; write_codes = true; response_matching = simple_matching; active_buttons = 1; button_codes = 100; default_text_color = 255, 255, 255; default_background_color = 128, 128, 128; no_logfile = false; # Begin SDL portion of code ###############...
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//example-23.2 //page no-684 //given //coefficient of linear expansion of Cu and steel are alphaCu=18*10^-6 //cm/cm/degree C alphaSteel=14*10^-6 //cm/cm/degree C //young's modulus of elasticity ECu=106*10^9 //Pa ESteel=200*10^9 //Pa //part(a) //since alphaCu>alphaSteel //so steel will contract less. pr...
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 27 // read it as example 26 in the book on page 2.79 disp("CHAPTER 2"); disp("EXAMPLE 27"); //VARIABLE INITIALIZATION V=250; //Amplitude in Volts w=314; //angular spped pv=-10; ...
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clc //solution // initialization of variables m=2 // mass of water in kg P=220 // pressure in KPa x=0.8 // quality of steam // Table C.2 is used for values vg=(P-200)*(0.6058-0.8857)/(300-200)+0.8857 // specific volume of saturated vapour @ given pressure by interpolating vf=0.0011 // specific volume of satu...
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clear all; TS= [1.36 3.16; 1.60 4.27; 1.89 5.45; 2.16 6.13; 2.42 6.99; 3.07 8.97; 3.59 10.64; 4.03 12.31; 4.79 16.27; 5.37 20.05; 5.84 23.39; 6.17 27.36; 6.43 30.77; 6.69 34.42; 6.93 38.08; 7.06 42.04; 7.19 45.56; 7.34 49.23; 7.47 53.02; 7.58 56.73; 7.65 64.30]; TP= [1.06 0.80; 1.10 1.55; 1.16 2.17; 1.26 2.79; 1.40 4...
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function y=F(x) f1 = x(1) + x(2) - 3 f2 = x(1).^2 + x(2).^2 - 9 y = [f1;f2] endfunction function y=J(x) j11 = 1 j12 = 1 j21 = 2.*x(1) j22 = 2.*x(2) y = [j11, j12; j21, j22] endfunction R = naolinear(F, J, [1;5], 0.0001) disp(R) printf("Aproximação obtida:") w = R(:,$...
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//Caption:Scilab code performs inverse filtering //Degrade the image by means of a known blur //Apply inverse filter to the blurred image and see the restored image //Fig6.5 //page 330 clc; close; x =imread('E:\DIP_JAYARAMAN\Chapter6\flower2.jpg'); x=double(rgb2gray(x)); [M N]=size(x); h = zeros(M,N); for i...
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function X = polyinv(x,k) gammaa = 1/ endfunction
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clc; T1=288; T2s=T1*[3^0.286]; T2=420.5 T4=T2; p6=8.14; p6!p7=4.19; p7=p6/(p6!p7); p8=(p7-0.2) p1=1.01 p10=p1 p9=0.05+p10 y2=1.333; T8=923; T9s=T8/[(p8/p9)^({y2-1}/y2)]; T9=T8-[(T8-T9s)*0.85]; cps2=1.15; N=cps2*(T8-T9); T5=728.8; T6=T8; T7=686.5; Q=cps2*(T6-T5+T8-T7) disp("kJ/kg",Q,"Heat supplied ...
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//Optical Fiber communication by A selvarajan //example 11.1 //OS=Windows XP sp3 //Scilab version 5.5.1 clc; clear all; BW=7//bandwidth in MHz SNR=60//signal to noise ratio in dB Pin=0//Launched power in dBm Trise_source=20//risetime at source LED in ns delta_lambda=20//spectra width in nm lambda=850;//opera...
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//chapter15 //example15.11 //page333 T_Jmax=90 // degree celcius T_amb=30 // degree celcius //case 1 : without heat sink theta1=300 // degree celcius per watt P_total1=(T_Jmax-T_amb)/theta1 //case 2 : with heat sink theta2=60 // degree celcius per watt P_total2=(T_Jmax-T_amb)/theta2 printf("case 1 : ...
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function result = Echange(A, ln1, ln2) nbrCol = size(A, "c"); for i=1:size(A, "r") for j=1:nbrCol if(i == ln1) result(i,j) = A(ln2,j); elseif (i == ln2 ) result(i,j) = A(ln1,j); else result(i,j) = A(i,j); ...
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question(1, 'item 2-1', 'Als we de drie lampjes aanzetten schijnen ze recht op de lens. Waar komen de lichtstralen samen?', [ '4 centimeter achter de lens', '8 centimeter achter de lens', '16 centimeter achter de lens', 'weet niet' ], state(state, '', [ m1 = lens(label(''), radius(...
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// chapter 16 // example 16.1 // Determine kVA rating of invertor, Wattage of the rectifier and A-H rating of battery // page-996 clear; clc; // given Load=600; // in W PF=0.8; // (lagging power factor) efficiency=80; // in % Edc=24; // in V backup_time=30; // in min // calculate // since PF=Load/kVA_ratin...
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<?xml version="1.0" encoding="ISO-8859-1"?> <start> <!-- optional path to inputs directory default is src/StandAlone/inputs --> <inputs_path></inputs_path> <upsFile>ICE/advect.ups</upsFile> <AllTests> <replace_lines> <max_Timesteps>10 </max_Timesteps> <resolution> [100,100,100] </resol...
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clear clc disp('Exa-9.4'); hc=1240; //in eV.nm m=0.5*1.008*931.5*10^6; //mass of hydrogen atom Req=0.074; //equivalent radius a=((hc)^2)/(4*(%pi^2)*m*(Req^2)); //reduced mass of hydrogen atom for L=1:3, delE= L*a; printf('The value of energy is %f eV\n',del...
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clc //Initialization of variables cv=0.98 g=32.2 h=1320 //ft A=0.196 //ft^2 eta=0.85 ne=400 phi=0.45 //calculations V=cv*sqrt(2*g*h) Q=A*V/3 bhp=eta*62.4*Q*h/550 ne2=600 ns1=ne2*sqrt(bhp) /h^(5/4) D=2500/ne2 Dj=sqrt(Q*4/V/%pi) //results printf("Jet diameter = %.3f ft",Dj) printf("\n Specific speed = ...
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//Chapter-9, Example 9.5, Page 389 //============================================================================= clc clear //INPUT DATA Ts=(827+273);//Surface temperature in degree C E=(1.37*10^10);//Emmisive power in W/m^3 //CALCULATIONS Eblmax=(1.307*10^-5*Ts^5);//Maximum emissive power in W/m^3 e=(E/E...
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disp('--- (©) Alexei Dergunov, 2009 ---'); //---------------------------------------- disp('----------- Задание 3 -----------'); //---------------------------------------- funcprot(0); n = 400; disp(n, 'объем выборки'); ax = 2.75; disp(ax, 'мат. ожидание X'); dx = 6.5; disp(dx, 'дисперсия X'); ay = -5.3; disp(ay, 'ма...
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clear; //clc(); // Example 6.3 // Page: 109 printf("Example-6.3 Page no.-109\n\n"); //***Data***// // All the data are same as in the previous example // The equation 6.5 reported in the book is // delta_V_mixing = V_solution _final-V_(solution and material to be mixaed) = integrate(v_i-v_i_0)dn // Here...
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clc // Given that n = 2 // no. of order lambda1 = 5.89e-7 // wavelength of light in first case in meter lambda2 = 5.896e-7 // wavelength of light in second case in meter // Sample Problem 37 on page no. 2.52 printf("\n # PROBLEM 37 # \n") N = lambda1 / (n * (lambda2 - lambda1)) // calculation for minimum no. of lines ...
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//Eg-3.12 //pg-100 clear clc A=[6 15 55 ;15 55 225;55 225 979]; B=[74.5;262.3;1078.1]; n=3; matsol=zeros(3,3);//initialising matrix matsol Z=A; Y=B; I=[1 0 0;0 1 0;0 0 1];//creates an identity matrix of size n*n X=zeros(3,1); inverse=zeros(3,3); ABI=zeros(3,7); ABI(:,:)=[A(:,:) B(:,:) I(:,:...
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// Exa 2.1 clc; clear; close; // Given data R_L = 1000;// in ohm N2byN1= 4; Vi= '10*sin(omega*t)' // V2= N2byN1*V1 // V2= 40*sin(omega*t) Vm= N2byN1*10;// in V V_Lav= Vm/%pi;// in V disp(V_Lav,"The average load voltage in volts is : ") Im= Vm/R_L;// in A I_dc= Im/%pi;// in A I_av = I_dc;// in A I_av= I_...
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mode(7) // Mini Tutorial para MAP0125 // // Sintaxe da linguagem do Scilab // Um programa em scilab é uma sequencia: // <expressao>[;] // ou // <variavel>=<expressao>; // com o ponto e virgula a expressao e executada silenciosamente. 2+4.^2 // expressão numerica (2+sqrt(3-1))>2 // expressão booleana "Hello" + " Worl...
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//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc.,USA,pp 436. //Chapter-1 Ex1.4.a Pg No. 23 //Title: Activation energy from packed bed data - I Order Reaction //========================================================================================================= clear clc clf //INPUT ...
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clc clear //Page number 480 //Input data p=135.2;//The given increase in the pressure in atmospheres V=-0.091;//The given increase in the specific volume when 1g of water freezes into ice in cm^3 L=80;//Latent heat of fusion of ice in cal/gram T=273;//The temperature of ice in K //Calculations L1=L*4.1...
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//Chapter 05: Induction and Recursion clc; clear; //Function to merge & sort function [ a1 ]= mergesort (a ,p , r ) if (p < r ) q = int (( p + r ) /2) ; a = mergesort (a ,p , q ) ; a = mergesort (a , q +1 , r ) ; a = merge (a ,p ,q , r ) ; else a1 = a ; return ; end a1 = a ; endfunction //Function to merge function ...
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// Example 5.21 // Computation of Inductance and voltage rating of each series connected // inductor required to limit the starting current to approximately 2*Irated. // Page No. 236 clc; clear all; close; // Given data KVA=6.7; // Average locked rotor KVA/hp hp=7.5; // Motor ...
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//Ex 7.1 clc;clear;close; RA=6.8;//kohm RB=3.3;//kohm C=0.1;//micro F VCC=5;//V t_high=0.695*(RA+RB)*C;//ms disp(t_high,"(a) t_high(ms)"); t_low=0.695*RB*C;//ms disp(t_low,"(b) t_low(ms)"); f=1.44/(RA+2*RB)/(C);//kHz disp(f,"(c) Frequency of oscillation(kHz)");
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// Chapter 9 example 7 //------------------------------------------------------------------------------ clc; clear; // Given Data // Rmax = [1000000/(12.4*PRF)]NM // = [1000000*t/12.4]NM mprintf('The Numerator represents round trip propagation time in us\n'); mprintf(' Therefore, number 12.4 repres...
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clear; clc; V_s=200; R1=10; R2=100; I1=V_s*(1/R1+2/R2); printf("peak value of current through SCR1=%.0f A",I1); I2=V_s*(2/R1+1/R2); printf("\npeak value of current through SCR2=%.0f A",I2); t_c1=40*10^-6; fos=2; //factor of safety C1=t_c1*fos/(R1*log(2)); C2=t_c1*fos/(R2*log(2)); if(C1>C2) ...
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import React, { Component, useState } from 'react'; import { fade, makeStyles, Theme, createStyles } from '@material-ui/core/styles'; import AppBar from '@material-ui/core/AppBar'; import Toolbar from '@material-ui/core/Toolbar'; import IconButton from '@material-ui/core/IconButton'; import Typography from '@material-u...
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//Calculate percentage regulation //Chapter 3 //Example 3.15 //page 217 clear; clc; disp("Example 3.15") kVA=30; //rating of the transformer V1=6000; //primary voltage in volts V2=230; //secondary voltage in volts R1=10; //primary resistance in ohms...
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Example7_12.sce
//Chapter-7,Example7_12,pg 7-36 //for meter A Rs=25*10^3 Rm=1*10^3 V=100 S=(Rs+Rm)/V printf("senstivity of meter A\n") printf("S=%.2f ohm/volt\n",S) //for meter B Rs=150*10^3 Rm=1*10^3 V=1000 S=(Rs+Rm)/V printf("senstivity of meter B\n") printf("S=%.2f ohm/volt",S)
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// problem 6.17 a=90 H1=10 d=0.15 l=400 H2=7 g=9.81 f=0.008 z=3.142*d*d*((2*g)^0.5) z1=(1.5+(4*f*l/d))^0.5 T=(8*a*z1*(H1^0.5-H2^0.5))/z disp(T/3600,"time to lower the level from 10m to 7m in hr")
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errcatch(-1,"stop");mode(2);//Example 3.15.3: shunt resistance ; ; //given data : Im=1;// in mA P=100;// in kilo-watt I=100;// in mA Rm=(P)/(Im)^2; Rsh=((Im*10^-3*Rm*10^3)/((I-Im)*10^-3))*10^-3; disp(Rsh,"shunt resistance,Rsh(kilo-ohm) = ") exit();
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//clc() l = 10;//cm k1 = 0.49;//cal/(s.cm.C) x = 2;//cm dt = 0.1;//sec C = 0.2174;//cal/(g.C) rho = 2.7;//g/cm^3 k = k1/(C*rho); L = k * dt / x^2; disp(L,"L =") //now, at t = 0, 1.04175 *T'1 + 0.020875 *T'2 = 0 + 0.020875*100 //similarly getting other simultaneous eqautions,we get the following matrix A = [...
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clear clc A=[2 3 -1 -1;1 -1 -2 -4;3 1 3 -2;6 3 0 -7] [R P]=spec(A) disp("rank of A") rank(A)