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clc //to calculate wavelength and energy //formula is lambda'-lambda=h*(1-cos phi)/(m0*c),where phi=90 degree, lambda'=2lambda ---------------eq(1) //dellambda=2lambda-lambda=lambda ----------------------------eq(2) h=6.62*10^-34 //planck's constant c=3*10^8 //light speed in m.s m0=9*10^-31 //mass of electron in ...
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clear clc // load the data A=[0 1 0 0;0 -0.0014 0.1271 0;0 0 0 1;0 -0.0025 19.1713 0]; B=[0;1.777;0;3.4296]; C=[1 0 0 0;0 0 1 0 ]; D=[0;0]; //trick to tackle when "D12 is not full rank" //inputs u and e; outputs dy1 and dy2 sys = syslin("c",A, B, C); Ap=sys.A; Bp=sys.B; Cp=sys.C; Dp=sys.D; ////Evluam...
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//Chapter 4 Ex 4 clc; clear; close; // from given statement we the equation as (4/21)x-(8/45)x=8 for x=1:700 if ((4/21)*x-(8/45)*x)==8 break; end end half=x/2; mprintf("The required number is %d",half);
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//Example 6. 3 //Program to c a l c u l a t e s h o r t e s t s e quenc e N such tha t a l g o r i t hm B runs // f a s t e r than A clc ; i =0; N =32; //Given // Ca l c u l a t i o n o f Twiddle f a c t o r exponent s f o r each s t a g e while 1==1 i=i+1; N =2^ i; A=N^2; B =5* N* log2 (N); if A>B then brea...
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x=[-100:100]; y=1./(1+exp(-x)); // Evaluating function disp(string(x)+" "+string(y)); plot(x,y); // Plotting x vs y
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s=0.0005; ms=s*10^3; disp("the value (in ms) is"); disp(ms); mus=s*10^6; disp("the value (in μs) is"); disp(mus);
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Python provids a complete set of control flow elements, including while and for loops, and conditionals Python uses the level of indentation to group blocks of code with control elements.
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clc //Chapter3: Modulation //Example3.29, page no 177 //Given Pc=100e3//Carrier power ma=0.5//Depth of modulation Pt=Pc*(1+((ma^2)/2))//total RF power mprintf('Total RF power delivered is:Pt= %f kW',Pt/1e3)
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= Tests for Custom Features 1 cd_test.py 2 history_test.py
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clc //Given that lambda1 = 4700 // wavelength in Angstrom lambda2 = 1.4e-5//wavelength in cm temp1 = 6174 // temperature of a black of in kelvin //Sample Problem 17 page No. 143 printf("\n\n\n # Problem 17 # \n") printf("\n Standard formula Used \n lambda * T = constant") temp2 = lambda1 * temp1 / (lambda2 * 1...
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a b b e 아 베 a b e l l 아 벨 a b i d j a n 아 비 장 a b u j a 아 부 자 a c c r a 아 크 라 a d o n i s 아 도 니 스 a d r i a n 에 이 드 리 언 a d r i e n n e 에 이 드 리 엔 a f a n a s i e v 아 파 나 시 예 프 a g o s t i n o 아 고 스 티 노 a g r i p p a 아 그 리 파 a l a m e d a 알 러 미 다 a l b a n o 알 바 노 a l b a n o 알 바 노 호 a l e k s a n d r 알 렉 산 드 르 a l e n ...
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clc; A=[0 1;-1/3 4/3]; B=[0;1/3]; C=[-1/3 4/3]; D=[1/3]; Hz=ss2tf(syslin('d',A,B,C,D)); disp(Hz,"H(z)="); z = %z; syms n z1; X =z ^2 /(1-4*z+3*z^2) X1 = denom (X); zp = roots (X1); X1 = z1 ^2 /((z1-1)*(z1-1/3)) F1 = X1 *( z1 ^(n -1) )*(z1 -1/3 ); F2 = X1 *( z1 ^(n -1) )*(z1 -1 ); h1 = limit (F1 ,z1 ,zp ...
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//Example 6.5.2 page 6.12 clc; clear; Ps_out= 30; //in uW... Ps_in=1; Noise_power = 0.5; G= Ps_out/Ps_in; G= 10*log10(G); printf("\nThe Gain EDFA is %.2f dB",G);
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//Exam:4.3 clc; clear; close; F_1=3.02*10^(-9);//force of attraction b/w ions of Na+ and Cl- Z_1=+1; Z_2=-1; e=1.6*10^(-19); E_o=8.854*10^-12; pi=22/7; r_Na=0.95;//ionic radius of Na+ ion r=(-Z_1*Z_2*e^2/(4*pi*E_o*F_1))^(1/2);//Radius of ion in meter R=r/10^(-10);//Radius of ion in Angstrom r_Cl=(R-r_Na);/...
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// Example 4.14 //birefringence clc; clear; close; Lbc1=0.7;//beat length micro meter h=1.3;//wavelength in micro meter Bf1=((h*10^-6)/(Lbc1*10^-3));// birefringence when beat length = 0.5mm Lbc2=80;//beat length meter Bf2=((h*10^-6)/(Lbc2));// birefringence when beat length = 60 meter disp(Bf1,"birefringence ...
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clc clear close //Dados experimentais: x = [1:8]; y = [3.9 2.7 1.8 2.5 3.8 6.5 10.0 14.1]; grau = 2; //grau do polinômio alfa = 0.0001;//parâmetro v = zeros(1,grau+1); //aproximação inicial dos coeficientes do polinômio function y=f(x,a)//criação do polinomio f y = 0 for i=1:length(a) y = y + a(i)*...
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//fminunc function y=fun(x) y=-((x(1)-1)^2+(x(2)-1)^2); endfunction //FAILURE CASES //Fails sometimes if starting point is a stationary point i.e. f'=0. (works for x1^2+x2^2 and (0,0) but fails for (x1-1)^2+(x2-1)^2 and (1,1)) //Fails when it converges to point of inflecion. So if function has a point of inflection ...
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clc //Intitalisation of variables clear m1= 1.947 //gms V= 10 //lit T= 22 //C p= 752 //mm of Hg T1= 28 //C W= 46 //gms R= 0.082 //lit-atm mole^-1 K^-1 //CALCULATIONS P= (m1*p/W)/((m1/W)+((p/760)*V/(R*(273+T)))) P1= (m1*p/W)/(((p/760)*V/(R*(273+T)))) P2= (m1/W)*R*(273+T)*760/V //RESULTS printf ('Vapour pr...
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clc; clear all; k = 1.38e-23; //Boltzmann constant h = 6.62e-34; // Planck's constant m = 9.1e-31; // Mass of an electron in Kg L = 0.1e-9 ; // Length of potential wall in meters nx = 1; // For the lowest energy level ny = 1; // nz = 2; // The higher energy level E = (h^2*(nx^2+ny^2+nz^2))/(8*m*L^2);//Energy o...
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// Problema 1 z=[0,4,8,12,16] a=[9.8175, 5.1051, 1.9635, 0.3927, 0] c=[10.2, 8.5, 7.4, 5.2, 4.1] //numero de ponto = 5 //numero de intervalos = 4 (par) //podemos usar simpson1/3 cMedia = simpson13tab(z,a.*c) / simpson13tab(z,a) disp(cMedia,"PROBLEMA 1 - Concentração média: ") // Problema 2 t=[0,10,20,30,35,40,45...
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//clc() //clc() x0 = 0; x1 = 1; x2 = 2; y1 = 6.194631; y2 = 14.84392; y10 = 5.607005; y11 = 6.360865; y1m = y11 - (y11 - y10)/5; e = (y1 - y1m)*100/y1; disp(y1m,"ym") disp("%",e,"error = ") y20 =2+(4*exp(0.8*x1) - 0.5*y1m)*2; e2 = (y2 - y20)*100/y2; disp(y20,"y20 = ") disp("%",e2,"error = ") y2o = y20 ...
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// Example 18.3, page no-461 clear clc n=2.69 er=4.94 alfi_by_alfe=(((n+2)*(er-1))/((er+2)*(n-1)))-1 printf("The ratio of the electronic to ionic polariability is %.4f",1/alfi_by_alfe)
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clc; P=2000; //power in Watt V=120; //potential diff in volt I=P/V; //current in Ampere s=2*10^-3; //distance in m K=2*10^-7; //constant in N/A square F=(I*I*K)/s; //calculating force per metre disp(F,"Force in Newton per metre in opposite direction = "); //displaying result
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clear// //Variables T1 = 800 //Temperature (in celsius degeree) T2 = 2250 //Temperature (in celsius degeree) R20 = 3.49 //Resistance at 20 degree celsius (in ohm) alpha20 = 4.5 * 10**-3 //Temperature ...
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//Example No. 3_09 //Binary representation //Pg No. 51 clear ;close ;clc ; n = -32768 compl_32767 = dec2bin(bitcmp(abs(n)-1,16) + 1) disp(compl_32767,'binary equivalent of -32767 is ') n_1 = -1 dcomp = bitcmp(1,16) compl_1 = dec2bin(dcomp+1) disp(compl_1,'binary equivalent of -1 is ') compl_32767_code = ...
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//Example 15.14 //position servomoter clear;clc; xdel(winsid()); //Mil= motor inertia referred tothe load side Mil=20^2*0.45*10^-6 //unit= kg.m^2 //Tr= Transformation ratio of gear train between the loadshaft and the tachogenerator Tr=20*2 //til= tachogenerator inertia referred to the load side til=40^2*0.35*10^-...
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clc // Given that N = 2620 // no. of lines in plane transmission grating per inch lambda = 5e-7 // wavelength of incident radiation in meter // Sample Problem 33 on page no. 2.51 printf("\n # PROBLEM 33 # \n") k = 2.54 / N * 1 / 100 // calculation for b+d in meter n = k / lambda // calculation for order of spectrum pr...
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clear all; clc; disp("Scilab Code Ex 13.10 : ") //Given: L = 750; //mm P = 60; //kN sigma = 195; //N/mm^2 K = 1; //Calculations: b2 = (P*1000)/(2*sigma); b = sqrt(b2); A = 2*b*b; Iy = (1/12)*(2*b*b^3); ry = sqrt(Iy/A); sl_ratio = (K*L)/(ry); if(sl_ratio>12) b4 = (P*1000*2598.1^2)/(2*3...
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s=%s; G=1/(1+2*s); sys=syslin("c",G); clf();bode(sys,1e-2,1e1,0.01)
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//to find velocity and acceleration of ram R clc printf("\n") //GIVEN OC=8//inches CP=4//inches N=60//inches ON=15//inches RN=6//inches X=120//degrees OP=10.6 OQ=OP //from fig 65(a) Vq=1.56//ft/s Vrn=0.74//ft/s //from fig 65(b) ftq=3.74//ft/s^2 ftrn=2.03//ft/s^2 w1=(%pi*N)/30 w=Vq/(OQ/12) wrn=Vrn/(...
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//clear// //Caption:Reed-Solomon Codes //Example8.6: Reed-Solomon Codes //Single-error-correcting RS code with a 2-bit byte clc; m =2; //m-bit symbol k = 1^2; //number of message bits t =1; //single bit error correction n = 2^m-1; //code word length in 2-bit byte p = n-k; //parity bits length in 2-bit byte r...
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s=%s; syms t s; F=(1- (3*%e^(-2*t)) + (2*%e^(-3*t)) ); y=laplace(F,t,s); G=1 x=laplace(G,t,s); disp((y/x),"closed loop transfer function is") T=y/x; disp((T/(1-T)) , "openloop transfer function is")
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// Exa 1.1 clc; clear; close; format('v',6) // Given data miu = 0.2;// in m^2/V-s V = 100;// in mV V = V * 10^-3;// in V d = 0.5;// in mm d = d * 10^-3;// in m // mobility, miu = Vd/E and E = V/d; // Drift velocity, Vd = miu*E;// in m/s disp(Vd,"The electron drift velocity in m/s is"); // Time required,...
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// This GUI file is generated by guibuilder version 4.2.1 ////////// f=figure('figure_position',[347,147],'figure_size',[640,501],'auto_resize','on','background',[33],'figure_name','图像窗口%d','dockable','off','infobar_visible','off','toolbar_visible','off','menubar_visible','off','default_axes','on','visible','off'); ///...
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function [res]=sendViaJava(x, t) sciBuffer = t; sciBuffer.write(x); res=sciBuffer.read(); endfunction
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## test the dedup function read <<EOF blob mark :1 data 75 This is a toy repo intended as a correctness test for the dedup operation. blob mark :2 data 50 This is a file with content in a duplicate blob. blob mark :3 data 50 This is a file with content in a duplicate blob. reset refs/heads/master commit refs/heads...
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clc //Initialization of variables pKa2=10.25 //calculations C=10^(-pKa2) //results printf("Concentration of Carbonate ions = %.1e mol/l",C)
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plot2d(D.time, D.values(:,2)); plot2d(D.time, D.values(:,3)); plot2d(D.time, D.values(:,4)); plot2d(D.time, D.values(:,5)); scf(0); plot(D.time, D.values(:,1), 1); plot(D.time, D.values(:,2), 2); plot(D.time, D.values(:,3), 3); plot(D.time, D.values(:,4), 4); plot(D.time, D.values(:,5), 4); plot(D.time, D.values(:,...
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disp('the augmented matrix is:') a=[2 -5 8 0;-2 -7 1 0;4 2 7 0] disp(a) disp('R2=R2+2*R1 and R3=R3-2*R1') a(2,:)=a(2,:)+a(1,:) a(3,:)=a(3,:)-2*a(1,:) disp(a) disp('R3=R3+R2') a(3,:)=a(3,:)+a(2,:) disp(a) disp('only two columns have non zero pivots') disp('hence, one column is a free column and therefore ther...
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// chapter 8 // example 8.20 // Compute the value of commutating capacitance and transformer inductances // page-499 clear; clc; // given Edc=60; // in V (dc source) I0_m=140; // in A (load current) t_q=20; // in us g=4; // calculate t_q=t_q*1E-6; // changing unit from us to s Rm=Edc/I0_m; // since g=(1/Rm)*sqrt(L1/C) ...
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nx = 100; ny = 100; x = linspace(-1,1,nx); y = linspace(-1,1,ny); [X,Y] = ndgrid(x,y); r = sqrt((X.^2) + (Y.^2)); A = zeros(nx,ny); A (find(r<0.7) ) = 1; f = scf(); grayplot(x,y,A); f.color_map = graycolormap(32); A = double(A); fftA = fft2(A); fftA = uint8(imnorm(fftshift(abs(fftA)))*255); f=scf(); imshow(fftA); //...
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//f(x):x->3x;g(x):x->x-2;fg(5) clear; clc; close; x=poly(0,'x'); f=3*x; g=x-2; // fg= f(g(x))=f(x-2)=3*(x-2) x=5; fg=3*(x-2)
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clc // Given that t = 2.5e-14 // life time of hydrogen atom in exited state in sec h = 6.62e-34 // Planck constant in J-sec // Sample Problem 11 on page no. 15.28 printf("\n # PROBLEM 11 # \n") printf("Standard formula used \n") printf(" del_E*del_t = h/(4*pi) \n") delta_E = h / (4 * %pi * t) printf("\n Minimum error ...
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errcatch(-1,"stop");mode(2);//Example 3.30 //Program to Calculate N from given data //fm=5000Hz //df=50Hz //t=0.5sec ; ; ; fm=5000 //Hz df=50 //Hz t=0.5 //sec N1=2*fm/df; N=2; while N<=N1, N=N*2,end //Displaying the value of N in command window disp(N,"N="); exit();
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4 2 ~~~~~~~~~~~~~~~~~~~~~ 5
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//page 214 clear; close; clc; A=[2 -1 0 0;-1 2 -1 0;0 -1 2 -1;0 0 -1 2]; disp(A,'A='); [m,n]=size(A) a=A(1,:); c=[]; for l=1:4 B=A([1:0,2:4],[1:l-1,l+1:4]); c1l=(-1)^(1+l)*det(B); c=[c;c1l]; end d=a*c; disp(d)
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// Example 2.1 // Compuatation of mode parameter // Page no. 479 clc; clear; close; //Given data n1=1.503; // refractive index of core n2=1.50; // refractive index of cladding a=4*10^-6; // core radius lambda=1*10^-6; // light wavelength // Mode parameter computation V=(2*%pi*a*sqrt(n1^2-n2^2))/(lamb...
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//Example 14.3 m_Al=0.5;//Mass of aluminum pan (kg) c_Al=900;//Specific heat of aluminum (J/kg.C) T_Al=150;//Initial temperature of pan (C) m_W=0.25;//Mass of water (kg) c_W=4186;//Specific heat of water (J/kg.C) T_W=20;//Initial temperature of water (C) T_f=[(m_Al*c_Al*T_Al)+(m_W*c_W*T_W)]/(m_Al*c_Al+m_W*c_W);/...
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//Chapter 9, Problem 3 clc; v=15; //velocity of conductor l=0.02; //length of conductor A=2*2*10^-4; //area of conductor phi=5*10^-6; //flux Q1=%pi/2; //converting 90 degree into radian Q2=%pi/3; //convert...
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clc //initialisation of variables n=180//rpm a=420//mm h=a/8//mm w=60*n*12//sec b=5//mm p=20//m v=30//m r=50//mm/sec d=28.5//mm //CALCULATIONS D=b*p/v//mm D1=d*r//mm/sec //RESULTS printf('the legth of crank =% f mm/sec',D1)
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errcatch(-1,"stop");mode(2);//Example 1.7://limiting error ; ; fse=1;//full scale deflection vr=150;//range in volts ev=(fse/100)*vr;//voltas v1=100;//volts le100=((ev)/v1)*100;//in percentage ve=100;//range in mA ee=(fse/100)*ve;//mA e1=55;//mA le50=((ee/e1)*100);//in percentage ler=le100+le50;// disp(ler,"limiting e...
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errcatch(-1,"stop");mode(2);//ques15(ii) syms n z y=z^(-n); f=symsum(y,n,0,%inf); disp(f); exit();
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clc clear //Initialization of variables T=32 //F m=1 //lbm J=778.16 //calculations disp("From steam tables,") hf=0 p=0.08854 //psia vf=0.01602 //ft^3/lbm u=hf-p*144*vf/J //results printf("Internal energy = %.7f Btu/lbm",u)
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clear; clc; disp("Example 6.2"); ////BFS Traversal funcprot(0) function[q2]=push(ele,q1) if(q1.rear==q1.front) q1.a=ele; q1.rear=q1.rear+1; else q1.a=[q1.a(:,:) ele]; q1.rear=q1.rear+1; end q2=q1; endfunction function[ele,q2]=pop(q1) ele=-1; q2=0; if(q1.rear==q1.front) ...
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// Exa 4.30 clc; clear; close; // Given data I_C = 10;// in mA I_B = 0.1;// in mA bita = I_C/I_B; disp(bita,"The current gain is");
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function [r]=%lss_o_r(s1,s2) //%lss_o_r(s1,s2) <=> s1==s2 // Copyright INRIA r=%f
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clc clear //Initialization of variables per=0.071 //mass fraction of nitrogen //calculations O2=8.74 N2=per/2 + 3.76*O2 Nin=32.85 CO2=7.333 H2o=3 So2=0.0312 //results printf("Oxygen = %.2f and Nitrogen = %.2f",O2,N2) printf("\n Equation is C %.3f H %d + %.2f O2 + %.2f N2 = %.3f CO2 + %d H2O + %.5f SO2 + %....
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//example9.2 clc disp("Initially electron is at rest and V=200 V") disp("Therefore, v(in m/sec)=sqrt(2*q*V/m)=(5.94*10^5)*sqrt(V)") v=(5.94*10^5)*sqrt(200) format(8) disp(v,"= (5.94*10^5)*sqrt(200) = ")
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//Chapter-4,Example 17,Page 97 clc(); close(); q= 300 //heat energy P= 2 // pressure in atm V1= 10 // volume in litre V2= 20 //volume in litre //since 1 lit.atm = 24.25 cal W=P*(V2-V1)*24.25 //work done delta_E= q-W //from the 1st law of thermodynamics printf('the change in inte...
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clc //Chapter 9:Phase locked loop Analysis //Example 9.7 page no 376 a=28//taking alpha as a Ka=0.21*10^6 GF=20*log10(a)^1/2 disp(GF,'The value of gain is ') disp('so we must determine where the uncompensated frequency response is -14.5dB ') Wc=a^(1/4)*Ka^(1/2) disp('The 28:1 lead ratio will increase the cros...
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// Exa 6.12 format('v',7);clc;clear;close; // Given data f1 = 2;//frequency in MHz f1 = f1 * 10^6;// in Hz C1 = 500;// in pF C2 = 60;// in pF // f1 = 1/(2*%pi*sqrrt(L*(C1+Cd))) (i) // f2 = 1/(2*%pi*sqrrt(L*(C2+Cd))) (ii) // and f2 = 2.5*f1 (iii) //From eq(i),(ii) and (iii) Cd = (C1 - (6.25*C2))/5.25;/...
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example_11.sce
clc clear printf("example 8.11 page number 372\n\n") //to find the maximum capacity of keroscene flow_rate_steel=1.2; //l/s density_steel=7.92; density_kerosene=0.82; density_water=1; flow_rate_kerosene =(((density_steel-density_kerosene)/density_kerosene)/((density_steel-density_water)/density_water))^0...
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//fiber optic communications by joseph c. palais //example 6.3 //OS=Windows XP sp3 //Scilab version 5.4.1 clc; clear all; //given NFdb=3.2//noise figure in dB SNRidb=50//input snr in dB //to find NF=10^(NFdb/10)//converting from decibels to ratios SNRi=10^(SNRidb/10)//converting from decibels to ratios SNRo...
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// Scilab Code Ex1.23 Energy released in fission: Pg: 30 (2008) c = 3e+08; // Speed of light, m/s e = 1.6e-019; // Charge on an electron, coulomb r0 = 1.2e-015; // Equilibrium nuclear radius, m A = 238; // Twice the mass of each fragment q1 = 46*e; // Charge on first fragment, coulomb q2 = 46*e; ...
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clear, clc function F = f(x) F = sin(x)/x endfunction a=0.01; b=1; N=1; n=2*N; h = (b-a)/n; x=a:h:b; soma=4*f(x(2)); printf("Para x%d -> f(x%d) = %c\n", 0,0, string(f(a))); printf("Para x%d -> f(x%d) = %c\n", 1,1, string(f(x(2)))); for i=3:n if(pmodulo(i,2)==0) soma = soma + 4*f(x(i)); ...
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clc //variable initialisation Pout=7.5 // Output Of Motor In KW Vm=230 //Supply Voltage in volt F=50 //supply frequency in hrtz R1=0.36 //resistance of stator in ohm R2=0.222 //resistance of rotor in ohm X1=0.47 //reactance of Motor in ohm X2=0.47 //reactance of Motor in Xm=15.5 //reactance of Motor in ohm S...
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//EXAMPLE 3-37 PG NO-196-197 Vry=450+%i*0; Vyb=-225-%i*389.711; Vbr=-225+%i*389.711; Vrn=225-%i*130; Vyn=-225-%i*130; Vbn=0+%i*259.8; Z1=10.60+%i*10.60; Z2=5+%i*8.66; Z3=2.6+%i*1.5; Z4=12.21+%i*4.44; Iry=Vry/Z1; disp('i) CURRENT (Iry) is in rectangular form = '+string...
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//example 2 //Total Differential versus Partial Differential clear clc R=0.287 //Universal gas constant kPa-m3/kg-K v=(0.86+0.87)/2 //average value m^3/kg T=(300+302)/2 //average temp. in kelvins dT=302-300 //change in tep. in K dv=0.87-0.86 //change in volume in m^3/kg dP=R*dT/v-R*T*dv/v^2 //Change in the pre...
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//Chemical Engineering Thermodynamics //Chapter 14 //Thermodynamics of Chemical Reactions //Example 14.1 clear; clc; //Given H_f_C2H4 = 12500;//Standard heat of formation of ethylene at 25 deg cel in Kcal/Kgmole H_f_C2H4O = -11667;//Standard heat of formation of ethylene oxide at 25 deg cel in Kcal/Kgmole ...
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clc clear all i=imread("C:\Users\VIshal\Desktop\lena.png") im=rgb2gray(i) figure,imshow(im); s1=255*bitget(im,1); s2=255*bitget(im,2); s3=255*bitget(im,3); s4=255*bitget(im,4); s5=255*bitget(im,5); s6=255*bitget(im,6); s7=255*bitget(im,7); s8=255*bitget(im,8); figure, subplot(2,4,1),imshow(uint8(s8)); subplot(2,4,2),im...
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TABLE_SIZE=256 ANNOTATIONS=1 QIF=$(cat<<'EOQ' dude nude dude nude dude where is my car? ## t 0 one fish two fish red fish blue fish EOQ )
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clc clear //DATA GIVEN N1=240; //speed of the engine shaft in R.P.M. d1=1.5; //diameter of pulley on engine shaft in m d2=0.75; //diameter of pulley on machine shaft in m t=0.005; //thickness of the belt in m //with no slip //(N2/N1...
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//Book - Power system: Analysisi & Design 5th Edition //Authors - J. Duncan Glover, Mulukutla S. Sarma, and Thomas J.Overbye //Chapter-9 ;Example 9.3 //Scilab Version - 6.0.0; OS - Windows clc; clear; Xn=0.05 //motor neutral is grounded through reactance in per unit Sb=100 ...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.6\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.6 (page no. 559) // Solution //For Brick, deltaX=0.150; //Unit:m //150 mm = 0.150 m //deltaX=length //unit:meter A=1; //area //unit:m^2 k=0.692; //Unit:W/(m*C) //k=proportionality constant //...
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clc; clear all; n = 25.33e27; // Number of electrons per unit volume tr = 3.1e14; // Mean free time of electron m = 9.11e-31; // Mass of electron in Kg e = 1.6e-19; // Charge of an electron rho = m/(n*e^2*tr); //Electrical resistivity of sodium metal disp('Ohm.meter',rho,'Electrical resistivity of sodium metal a...
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//Example_a_9_19 page no:418 clc; V=340; fund_comp=340/sqrt(3); harmonic_comp=sqrt(220^2-(fund_comp)^2); disp(harmonic_comp,"the third harmonic component is (in V)");
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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clc,clear printf('Example 4.6\n\n') P=400 //power absorbed in watts phi=acos(0.05) //power factor angle f=30*10^6 //frequency in hertz k_0=8.854*10^-12 //permittivity of free space k=5 //relative permittivity of wood A=150*10^-4 //area of cross section of plate in m^2 t=0.01 //thickness in m C=k_0*k*A/t //...
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// Scilab Code Ex2.11:: Page-2.13 (2009) clc; clear; alpha = %pi/180; // Acute angle of biprism, radian mu = 1.5; // Refractive index of biprism lambda = 5900e-008; // Wavelength of light used, cm y1 = 10; // Distance of biprism from the source, cm y2 = 100; // Distance of biprism from the screen, cm D = ...
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//**************************** nfet i2v *********************************** if (blk_name.entries(bl) =='nfet_i2v') then mputl("# nfet_i2v",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) nfet_i2v_str=".subckt nfet_i2v in[0]=net"+string(blk(blk_objs(bl),2))+'_'+ string(ss)+" out=net"+ string(blk(blk_objs(bl...
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clc //Initialization of variables D = 1.94 // slugs/ft^3 A1 = 0.06 //ft^2 V1 = 10 // ft/s // Calculations Fax = -D*A1*(V1)^2 Faz = D*A1*(V1)^2 // Results printf (" the force required in x direction is %.2f(1-cosT) lb",Fax) printf ("\n the force required in z direction is %.2f(sinT) lb",Faz)
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//chapter 6 //example 6.10 //Calculate mobility of electrons //page 149-150 clear; clc; //given n=9E28; // in 1/m^3 (density of valence electrons) sigma=6E7; // in mho/m (conductivity of copper) e=1.6E-19; // in C (charge of electron) //calculate // Since sigma=n*e*mu therefore mu=sigma/(n*e); // calculati...
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//Find avg of given no function[]=avg(n) x=1:n a=sum(x) disp('Average is') y=a/n disp(y) endfunction
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clc clear //input data M1=2 //Mach number at entry P1=1.4 //Static Pressure at entry in bar T1=323 //Static Temperature at entry in K Cp=1.005 //Specific heat of dry air in kJ/kg-K k=1.4 //Adiabatic constant R=287 //Gas constant in J/kg-K //calculation t1=0.555 //Temperature ratio at entry from gas tables...
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clc; // page no 144 // prob no 4_18_1 //A receiver with noise fig. 12dB fed by low noise amplr with gain 50 dB with noise temp of 90 k f=12; Tm=290;//Room temp value T=90; g=50; //calculating power ratio F=10^(f/10); G=10^(g/10); //Determination of equivalent noise at room temp Tem=(F-1)*Tm; disp('K',Tem...
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// Scilab Code Ex10.2: Page-10.5 (2004) clc;clear; Tc = 7.18; // Critical temperature, K r = 1e-003; // diameter of wire, m Ho = 6.5e+004; // Critical field at zero kelvin, A/m T = 4.2; // temperature at which filed being calculated, K Hc = Ho*[1-(T/Tc)^2]; ic = %pi*r*Hc; // critical current , A prin...
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// Example 1_3 clc;clear;funcprot(0); // Given values rho=850; // Density of oil in kg/m^3 V=2; // Volume of the tank in m^3 // Calculation m=rho*V;// kg printf('The amount of mass in the tank,m=%0.0fkg\n',m);
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clear; clc; // Illustration2.3 // Page: 32 printf('Illustration 2.3 - Page: 32\n\n'); // solution //***Data***// // a = C2H5OH b = air Pt = 101.3*10^(3);//[N/square m] T = 273;//[K] //********// Ma = 46.07;// [kg/kmol] Mb = 29;// [kg/kmol] //For air from Table 2.2 (Pg 33) Eb_by_k = 78.6;// [K] ...
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clear;lines(0); gammaln(0.5)
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex2_12.sce clc; clear; R=50; //Resistance in ohm Is=1/30; //Source current in Ampere Rs=40.92; //Parallel resistance in ohm Gs=1/Rs; //Parallel conductance in...
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//chapter 4 Ex 27 clc; clear; close; firstStation=280; secondStation=12; thirdStationTotal=248; totalBeginning=(((thirdStationTotal-secondStation)/(1/2))-280)/(2/3); mprintf("The total number of passengers in the beginning were %0.0f",totalBeginning);
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//Example 9.14 //Particular Solution //Page no. 296 clc;clear;close; x=poly(0,'x') n=2; f=x^(n)+5*x^(n-1)+4*x^(n-2); z=roots(f) disp(z,f) printf('\n\n') printf(' n n\nC.F. = ') for i=1:n printf('c%i(%g)',i,z(i)) if i~=n then printf(' + ') end end C=18; printf('...
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yjoq⁴ V;PROG;PL;3 yjoq⁴ V;PROSP;SG;3 yjoq⁴ V;PROG;SG;2 yjoq⁴ V;HAB;PL;1+INCL yjoq⁴ V;PROG;SG;3 yjoq⁴ V;PROG;SG;1 yjoq⁴ V;PROSP;PL;1+INCL yjoq⁴ V;PFV;PL;1+EXCL yjoq⁴ V;HAB;PL;2 yjoq⁴ V;PROSP;SG;2 yjoq⁴ V;PROG;PL;1+INCL yjoq⁴ V;HAB;SG;1 yjoq⁴ V;PROG;PL;2 yjoq⁴ V;PFV;PL;1+INCL yjoq⁴ V;HAB;SG;3 yjoq⁴ V;HAB;PL;1+EXCL yjoq⁴ ...
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function [fx,term]=series(fun, x, n_sig) // Cálculo de funções com serie de potências // function [fx,term]=series(funcao, x, n_sig) // onde fx é o valor da função em x // term é o número de termos usados para o erro especificado // fun é a função de entrada literal em x e n // onde n é o numero do termo ...
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exec('plates.sci') //funcion intercambia filas function sol = intercambiarFilas(A, i, j) temp = A(i,:) A(i,:) = A(j,:) A(j,:) = temp sol = A endfunction function sol = gausspivot(A, b) [m,n] = size(A) // Dimesiones de la matriz de entrada if (m <> n) then // Comprueba si la matriz es ...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Teradata -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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disp('chapter 4 ex4.4') disp('given') disp('capacitor coupled non inverting amplifier design') disp("lower cut off frequency for the circuit =120Hz") disp('Rl=2.2kohms') disp("R1max=0.1Vbe/Ibmax") disp("Vbe=0.7volts") disp("Ibmax=500nA") Vbe=0.7 Ibmax=500*10^(-9) R1max=0.1* Vbe/ Ibmax disp("R1max= ",R1max) ...
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//simplification of boolean expression// //example 8.a// clc //clears the command window// clear //clears// disp('given Y=AB+AB''C(B''C''+C)+A''C''') disp('Y=AB+AB''B''CC''+AB''CC+A''C''');//ON MULTIPLICATION// disp('Y=AB+AB''C+A''+C''');//CC''=0// disp('Y=C''+AB+(A+A'')(A''+B''C)') disp('Y=C''+AB+1.(A''+B''C...