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//Base 64 encoding example [u,t,n] = file() n = strcat(n) file_name = basename(n)+fileext(n) file_name = strcat(file_name) ind=strindex(n,file_name) path = part(n,1:ind-1) chdir(path) //Get function to create encoding table exec("Chapter_6.sci",-1) enc = encoding_table() inp = "00100011010111001001...
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//Optoelectronics - An Introduction, 2nd Edition by J. Wilson and J.F.B. Hawkes //Example 3.2 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given lambda=1.06e-6;//Wavelength at which half-wave voltage is to be calculated, in m r=10.6e-12;//Linear electro-optic coefficient of KDP crystal in m/V n0=...
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y=[79.2 ;64.0; 55.7; 56.3; 58.6; 84.3; 70.4; 61.3; 51.3; 49.8]; x1 = [0.02 0.03 0.03 0.04 0.10 0.15 0.15 0.09 0.13 0.09]; x2 = [1.05 1.20 1.25 1.30 1.30 1.00 1.10 1.20 1.40 1.40]; tvalue= 2.365; x = ones(10,3); for i=1:10 x(i,2)= x1(i); x(i,3)= x2(i); end pro1 = x'; //disp(pro1); pro2= pro1*x; /...
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//Chapter 16, Problem 10 clc; L=100e-3; //inductance in henry R=800; //resistance in ohm f=5000; //frequency V=12; //voltage w=2*%pi*f; C=(L*(w^2+(R^2/L^2)))^-1; //capacitance in farad Xl=2*%pi*f*L; /...
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clc //initialization of variables P1=100 //lb/in^2 T1=500+460 //R P2=15 //lb/in^2 eta=0.95 A=1 //in^2 gamma=1.4 //calculations Ve=2200 //ft/sec V2=eta*Ve T2=T1*(1-eta*(1-(P2/P1)^((gamma-1)/gamma))) vexit=53.3*T2/(144*P2) wdot=A*V2/(144*vexit) //results printf("Exit velocity = %.1f ft^3/lbm",vexit) print...
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<?xml version="1.0" encoding="utf-8"?> <test> <description> 2D MMF implicit diffusion </description> <executable>MMFDiffusion</executable> <parameters> TestMMFDiffPlane.xml</parameters> <files> <file description="Session File"> TestMMFDiffPlane.xml</file> </files> <metrics> <metr...
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clc // initialization of variables clear t=4 //mm // calculations l1=100 //mm See figure l2=50 //mm See figure ybar=125 //mm t=t*10^-3 ybar=ybar*10^-3 l1=l1*10^-3 l2=l2*10^-3 Ix=2*t*(2*(l1+l2))^3/12-t*(2*l1)^3/12 qAk=l1*t*ybar // qA=qAk*V qBk=qAk+l1*t*l1/2 qave=qAk+2/3*(qBk-qAk) F2k=200*qave*10^-3 //F2=...
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//exapple 5.4 clc; funcprot(0); // Initialization of Variable //part1 //maximizing eqution in theta & get a function function[y]=theta(x) y=(x-.5*sin(2*x))/2/x^2-(1-cos(2*x))/2/x; endfunction x=fsolve(2.2,theta); x=round(x*1000)/1000; a=(1-cos(x))/2; printf("velocity will be maximum when stream dept...
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clc; //Example 15.5 //Page No 651 //solution f=6; a=0.03; c=3*10^8; disp("(a)The cutoff frequency is determined by substituting into equation 15-41, "); fc=(c/(2*a)); fc=fc/10^9; disp('GHz',fc,"fc = "); disp("(b)The cutoff wavelength is determined by substituting into equation 15-42, "); lc=2*(a); disp('m',l...
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clear; stacksize('max'); //============================================================================== // Creates sparse matrix using the compressed row storage format //============================================================================== function [val, col_ind, row_ptr] = MakeCSRMat(M) [num_rows, num_co...
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clc,clear printf('Example 3.12\n\n') V=200 R_sh=240,R_a=0.1 //resistance of shunt field winding and armature rotational_loss=236 I_L_FL=9.8 //full load line current N=1450 I_sh=V/R_sh I_a_FL = I_L_FL - I_sh E_b= V- I_a_FL * R_a //part(i) gross_mech_P_dev= E_b*I_a_FL //gross mechanical power developed ...
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Qacb = 84e03; Wacb = 32e03; Uba = Qacb-Wacb; // Ub-Ua // Part (a) Wadb = 10.5e03; Qadb = Uba+Wadb; disp("J",Qadb,"The heat flow into the system along the path adb"); // Part (b) Wb_a = -21e03; Uab = - Uba; Qb_a = Uab+Wb_a; disp("J",Qb_a,"The heat liberated along the path b-a is") // Part (c) Wdb = 0; // ...
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clc; clear; printf("Example 10.8\n") L=825e-3; //length of the tube d=15e-3; //diameter of the tube P_i=7.5e3; //Partial pressure of ammonia at inlet P_o=2e3; //Partial pressure of ammonia at inlet A_r=2e-5; //Air rate P=101.3e3; //Atmospheric pressure D_F_m=(P_i-P_o)/log(P_i/P_o);//Mean driving force A...
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//control systems by Nagoor Kani A //Edition 3 //Year of publication 2015 //Scilab version 6.0.0 //operating systems windows 10 // Example 6.15 clc; clear; s=poly(0,'s') //dominent pole sd=-zeta*w=%i*w*sqrt(1-zeta^2) zeta=0.9//damping ratio w=2.5//natural frequency of osciilation in rad/sec sd=(-zeta*w)+...
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clc //page 82 printf("\t example 4.4 \n"); printf("\t approximate values are mentioned in the book \n"); T1=300+460; // R T2=75+460; //R A1=0.622; // area from table 11 in the appendix A,ft^2/lin ft A2=4*(1*1); // surface area of duct,ft^2/lin ft e1=0.79; // emissivity of oxidized steel from table 4.1 e2=0.276...
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//Scilab Code for Example 10.11 of Signals and systems by //P.Ramakrishna Rao //System Identification //Cross Correlation clear; clc; clear x n a y h z; x=[1,1,1,1,0,0]; y=[1,3,6,10,12,12,10,6,3,1]; h(1)=y(1)/x(1); for n=2:7 for k=1:n-1 z(k)=(h(k)*x(n-k)); h(n)=(y(n)-sum(z)); end end ...
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#test # TEST SUITE 10: Options ################################################ with(TestTools): kernelopts(opaquemodules=false): #libname := libname, "/home/mike/thesis/trunk/maple/pe/current/lib": libname := libname, "../lib": with(PEOptions); #########################################################...
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Name=Time attack Push out tiles PlayerCharacters=POT Challenger BotCharacters=POT Targets.rot IsChallenge=true Timelimit=30.0 PlayerProfile=POT Challenger AddedBots=POT Targets.rot;POT Targets.rot;POT Targets.rot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=push_out_tiles.map MapSc...
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@relation yeast-3 @attribute Mcg real [0.11, 1.0] @attribute Gvh real [0.13, 1.0] @attribute Alm real [0.21, 1.0] @attribute Mit real [0.0, 1.0] @attribute Erl real [0.5, 1.0] @attribute Pox real [0.0, 0.83] @attribute Vac real [0.0, 0.73] @attribute Nuc real [0.0, 1.0] @attribute Class {MIT, NUC, CYT, ME1, ME2, ME3, E...
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//Caption:transfer_function // example 3.2.3 //page 35 // we have defined parallel and series function which we are going to use here //exec parallel.sce; //exec series.sce; syms G1 G2 G3 G4 G5 G6 H1 H2; //shift the takeof point placed before G2 towards right side of block G2 a= G5/G2; b=parallel(G3,G4); c=se...
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clc // Given that d = 8.92e3 // density of copper in kg/m^3 i = 5 // current in amp w = 63.5 // atomic weight of copper r = 0.7e-3 // radius in meter N = 6.02e28 // Avogadro no. e = 1.6e-19 // charge on an electron in C // Sample Problem 8 on page no. 16.17 printf("\n # PROBLEM 8 # \n") printf("Standard formula used ...
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clc disp("Example 1.72") printf("\n") disp("Find the maximum current flow through Zener diode") Vz=7.5 //zener voltage Pd1=400*10^-3 //maximum power dissipation at 50c T1=50 T2=100 D=3.2*10^-3 //current at 50c Izm1=Pd1/Vz //current at 100 Pd2=Pd1-((T2-T1)*D) Izm2=Pd2/Vz printf("maximum current flow thr...
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// Exa 2.28 clc; clear; close; // given : epsilon_0=8.854*10^-12 // permittivity in free space in F/m mu_0=4*%pi*10^-7 // permeability in free space in H/m epsilon_r=4 // relative permittivity mu_r=1 // relative permeability epsilon=epsilon_r*epsilon_0 // permittivity mu=mu_0*mu_r // permeability H=5 // mag...
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clc // Given that mu = 0.08// Cofficient of friction between the job and the dies Y = 7 // Avg yield stress of the lead in N/mm^2 h = 6 // Height of die in mm L = 150 // Length of the strip in mm V1 = 24*24*150 // Volume of the strip in mm^3 V2 = 6*96*150 // Volume of the die in mm^3 w= 96 // Weidth of the die in mm ...
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//data f2=9 //MHz f1=11 //MHz R=50 //ohm W1=2*%pi*11*10^6 //rad/s W2=2*%pi*9*10^6 //rad/s //formula and result printf("\nresult:-") Wo=sqrt(W1*W2) fo=sqrt(f1*f2) printf("\nWo=sqrt(W1*W2)\nfo=sqrt(f1*f2)=%.6f MHz",fo) L=R/(W1-W2) printf("\nQ=Wo*L/R=Wo/(W1-W2)\nL=R/(W1-W2)=...
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// Exa 3.11 clc; clear; close; // Given data A_v = -8; V_in= -1;// in V I1 = 15;// in µA I1 = I1 * 10^-6;// in A R1 = -(V_in)/I1;// in ohm R1 = R1 * 10^-3;// in k ohm disp(R1,"Minimum value of R1 in kΩ is"); R_F = -(A_v)*R1;// in k ohm disp(R_F,"The minimum value of R_F in kΩ is"); // Note: There is ca...
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// Example 9.2 //Modify Example 9.1 to include arguments in function calls. funcprot(0); function []=printline(ch) //function with argument ch for i=1:52 printf("%c",ch); end printf("\n"); endfunction function []=value(p,r,n) //function with argument p,r,n ...
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clc //initialisation of variables r= 2 //ft p= 120 //lb/ft^2 //CALCULATIONS F= p*%pi*r^2 //RESULTS printf (' total force tending to lift the done= %.f Lb',F)
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//function myscijob() a=rand(20,20); b=rand(20,1); A=sparse(a); [h,rk]=lufact(A); x=lusolve(h,b); res=a*x-b fprintfMat('myscitest3.dat',x); exit(); //endfunction
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// chapter 7 example 6 //----------------------------------------------------------------------------- clc; clear; // given data D = 3; // diameter of the antenna in m n_l = 0.7; // length efficiency nr = 0.9; // radiation efficiency f = 10*10^9; // antenna operating freq....
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function[x] = MarkovChain(lambda, mu, p, n) Q = zeros(n,n); for i = 1:n for j = 1:n if (i - j == 1) then Q(i,j) = mu*(1-p); elseif (i - j == -1) then Q(i,j) = lambda; else Q(i,j) = 0; end end ...
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errcatch(-1,"stop");mode(2);//Chapter 6,Example 6.7 Page 201 //Refer Fig Ex. 6.7 Er = 3.8 v = 21 // KV/cm ind = v/Er // internal discharge in kV/cm V = (ind*0.9)+(v*0.1) printf (" Internal discharge = %f kV/cm\n ",ind) printf (" V = %f kV rms\n ",V) //Answer may vary due to round off error exit();
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//ques1(ii) disp('To find the laplace of given function in t '); syms t s disp(laplace((cos(t))^2,t,s));
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clear; clc; format('v',7); G=5; r=10*10^3; P=20*10^3; n=120*%pi; Gd=10^(G/10); E=sqrt(n*Gd*P/(2*%pi*r*r)); disp(E,'Electric field intensity at 10 km =');
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load Or16S1.hdl, output-file Or16S1.out, compare-to Or16S1.cmp, output-list a%B2.16.1 b%B2.1.2 out%B2.16.1; set a %B0000000000000000, set b 0, eval, output; set a %B0000000000000000, set b 1, eval, output; set a %B1111111111111111, set b 0, eval, output; set a %B1111111111111111, set b 1, eval, output;
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clc T = (3754-3063)/(23.03-19.49) // Temperature at triple point in K P = exp(23.03-(3754/195.2)) // Pressure at triple point R = 8.3143 // Gas constant Lsub = R*3754 // Latent heat of sublimation Lvap = 3063*R // Latent heat of vaporisation Lfu = Lsub-Lvap // Latent heat of fusion printf("\n Example 11.4") p...
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//Example_a_9_17 page no:417 clc; Il=35.35; n=6; Iph=Il/(2*sind(180/n)); disp(Iph,"the magnitude of phase current is (in A)");
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// Scilab code Ex1.7: Pg.32 (2008) clc; clear; Beta = 0.5; // Boost factor = v/c delta_ct_dash = 2; // Distance, m gama = 1.15; // Relativistic factor = 1/sqrt(1-(v/c)^2) delta_x = gama*Beta*delta_ct_dash; // Spatial separation of events, m printf("\nSpatial separation of events measured in S frame =...
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//chapter 5 example 5 //============================================================================= clc; clear; //Given Data F = 1*10^9;//two cavity klystron operating frequency Va = 2500;//Accelarating voltage in volts e = 1.6*10^-19;//charge of electron m = 9.1*10^-31;//mass of electron ...
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// Example 8.5 //Write a program using for loop to print the following output: // C // CP // .... // .... // CProgrammimg // CProgrammimg // .... // .... // CPr // CP // C string1='CProgramming'; printf(" -------------\n"); f=' '; for i=1:12 f=f+part(string1...
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//main program mask1=[-1 0 1;-2 0 2;-1 0 1]; mask2=[1 2 1;0 0 0;-1 -2 -1]; fd = mopen("image.asc",'r'); data = mfscanf(-1, fd, "%d"); dimension = sqrt(length(data)); //something wrong in the image rotation data = (matrix(data,dimension,dimension)); //matrices for both masks data_new1 = proc(data, mask1); data...
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// Exa 9.11 clc; clear; close; // given : n=0.92 // refrective index MUF=10 // maximum usable frequency in MHz MUF=10*10^6 // maximum usable frequency in Hz f=10*10^6 // in Hz ordinary frequency and maximum usable frequency are same h=400 // height of ray reflection point on the ionospheric layer in Km h=400*...
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2,1: 5 3 4 3,2: 13 5 12 4,1: 17 15 8 4,3: 25 7 24 5,2: 29 21 20 6,1: 37 35 12 5,4: 41 9 40 7,2: 53 45 28 8,1: 65 63 16 6,5: 61 11 60 7,4: 65 33 56 8,3: 73 55 48 9,2: 85 77 36 10,1: 101 99 20 7,6: 85 13 84 8,5: 89 39 80 9,4: 97 65 72 10,3: 109 91 60 11,2: 125 117 44 12,1: 145 143 24 8,7: 113 15 112 ...
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//Ex:96 clc; clear; close; t_o=300;// in K g_a=65;// antenna gain in db n_c=60;//in K l_w=0.5;//waveguide loss in db g_s=g_a-l_w;//system gain in db L=10^(.5/10); t_s=(n_c/L)+(L-1)*t_o/L; g_t=40;// in db/K t=10^((g_s-g_t)/10);//in k t_e=t-t_s;//in k printf("The equivalent noise temperature=%f K", t_e);
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// This code plots the fat band structure calculated by quantum espresso. // To run this code, you will need to download projwfc.dat, projwfc.out // and bands.dat clear; clc; xdel(winsid()); exec(PiLib); //stacksize('max'); // Parameters ====================================== work_dir=[]; project_name='KCu6B4' task='p...
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function L=luaspp(p,l) L = p*l; endfunction
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//Chapter 12 //Example 12.6 //page 457 //To find steady state power limit clear;clc; V=1.0; //infinite bus volatge Vt=1.2; //terminal volatge Xd=0.5*%i; //synchronous generator reactance X=%i; //series reactance //by solving the expressions given in the textbook theta=acosd(0.5/1.8); printf('\n\ntheta=%0.3f deg',theta...
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printf(" Given C(s)/R(s)=14/(s^2+1.4*s+14)") printf("characterstic equation of the given system is s^2+1.4*s+14=0"); printf("compare it with the standard second order characterstic equation s^2+2*d*w*s+w^2=0"); w=sqrt(14); d=1.4/(2*w); d1=.7; t=2*(d1-d)/w; pt1=%pi/(w*sqrt(1-d^2)); mo1=exp((-%pi*d)/sqrt(1-d^2))*...
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%Background scene-1.bg %Music NONE % OBJECT-NAME X-RELATIVE Y-RELATIVE X-SCALE Y-SCALE H-FLIP V-FLIP agua 0.0137 0.1045 1.0000 1.0000 0 0 agua 0.0403 0.1057 1.0000 1.0000 0 ...
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clear; xdel(winsid()); t=linspace (0,20,1E5); p=poly(0,'p'); K=1; H=syslin('c',K/(p*(p+1)*(p+2))); T=syslin('c',K/(p+0.1*p*p+p*p*p)); Tbf=T/(1+T); MGH=g_margin(H); MPH=p_margin(H); MGT=g_margin(T); MPT=p_margin(T); scf(1); bode(H,1E-3,100); a=gcf(); a.figure_name='bode H'; scf(2); black(H,1E-3,100...
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clear /////////////////////////////////////////////////////// // Integral.sce // // Este programa aproxima la integral con puntos de la // parábola con los valores de los limites y el número de // particiones // // Erick González A01039859 // Víctor Villarreal A01039863 // 04 / 11 / 2019 version 1.0 /...
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clc; fe=5; //focal length in cm D=25; //distance od distinct vision in cm mo=30/(1+(D/fe)); //calculating magnification of objective lens disp(mo,"Magnification produced by objective lens = "); //displaying result
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//Problem 26.06: A 300 kVA transformer is at full load with an overall power factor of 0.70 lagging. The power factor is improved by adding capacitors in parallel with the transformer until the overall power factor becomes 0.90 lagging. Determine the rating (in kilovars) of the capacitors required. //initializing th...
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//(Welded and Riveted Joints) Example 8.21 //Refer Fig.8.61 on page 310 //Width of the plate w (mm) w = 250 //Thickness of the plate t (mm) t = 20 //Permissible tensile stress in the plate and rivet sigmat (N/mm2) sigmat = 80 //Permissible compressive stress in the plate and rivet sigmac (N/mm2) sigmac = 120...
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// Chapter 1 //Rise time //page 29 //Example no 1-16 //Given clc; //f2=0.35/Tr; f2=100*10^3; //in kHz Tr=0.35/f2; printf("\n The rise time for 90 degree lag network is %.7f sec",Tr);// Result
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pathname=get_absolute_file_path('4_01.sce') filename=pathname+filesep()+'4_01data.sci' exec(filename) printf("\Answer:\n") printf("\n\area of the duct exit: %f m^2\n\n",A2)
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//Calculations on diesel cycle clc,clear //Given: r=14 //Compression ratio P1=1 //Pressure at 1 in bar T1=27+273,T3=2500+273 //Temperature at 1 and 3 in K //Solution: //Refer fig 2.26 g=1.4 //Specific heat ratio(gamma) T2=T1*(r)^(g-1) //Temperature at 2 in K P2=P1*(T2/T1)^(g/(g-1)) //Pressure at 2 in bar rho...
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function x=g_eye(a) // only to be called by function eye //! select type(a) case 1 then x=eye(a) case 2 then x=eye(a) case 5 then [m,n]=size(a) x=sparse([],[],[m,n]) case 15 then if a(1)=='r' then x=eye(a(2)); elseif a(1)='lss' then x=eye(a(5)) end case 10 then [m,n]=size(a) x=eye(m,n) else ...
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clc; r=18; // Compression ratio of an engine p1=100; // Pressure of air before compression in lPa T1=300; // Temperature air before compression in kelvin qH=1800; // Heat added to the air in kJ/kg k=1.4; // Index of reversible adiabatic process Cvo=0.7165; // Specific heat at constant volume in kJ/kg K Cpo=1.003...
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//Optoelectronics - An Introduction, 2nd Edition by J. Wilson and J.F.B. Hawkes //Example 7.1 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given D=1e9;//Specific detectivity of detector in m Hz^(1/2) W^(-1) Lambda=2e-6;//Wavelength in m A=25e-6//Detector area in m^2 Deltaf=10e3;//Detection band...
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clear, close exec ode1.sci; clc // | | // | q1 | | q2 | // --------------------------------------- // /\ L/4 L/2 L/4 /\ // parametry L = 4000; // długość belki E = 210000 //N/mm^2 - szytwnosc na zginanie I = ...
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// 2011.12.18 ( available for list ) function P=Framedata(varargin) global XMIN XMAX YMIN YMAX VaL=Flattenlist(varargin); N=length(VaL); if N<=1 H=1.0*10^(-4); PA=[XMIN+H,YMIN+H]; PB=[XMAX-H,YMIN+H]; PC=[XMAX-H,YMAX-H]; PD=[XMIN+H,YMAX-H]; else Tmp=VaL(N); if type(Tmp)==1 & leng...
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Name=QL Instagib Warmup #2 PlayerCharacters=ST Challenger BotCharacters=ST Target - Top.bot;ST Target - Middle.bot;ST Target - Bottom.bot IsChallenge=true Timelimit=30.0 PlayerProfile=ST Challenger AddedBots=ST Target - Top.bot;ST Target - Middle.bot;ST Target - Bottom.bot PlayerMaxLives=0 BotMaxLives=0;0;0 Pl...
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//============================================ // Exercise 20: Geostrophic adjustment in 3d //============================================ // Animation of surface density & flow field // Author: Jochen Kaempf, March 2015 (update) f = gcf(); f.color_map = jetcolormap(64); f.figure_size = [600,600]; scf(0); // ...
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//check o/p for 5*1 matrix x=[1.2;5;10; -20; 12] t=1:length(x) midcrossvalue=midcross(x, t); disp(midcrossvalue) //output //3.6426667 4.335
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clear clc //Example 6.4 WATER DEFLECTED BY A VANE r=0.0417; //[ft] A=%pi*r^2 //area[ft^2] v=100; //velocty[ft/s] rho=1.94; //[slugs/ft^3] m=rho*A*v; //mass flow rate[slugs/s] theta=60;//degrees //Momentum outflow vector, mo=[mo_x mo_y] mo=[m*v*cosd(theta) -m*v*sind(theta)] //Momentum inflow vector, mi=[mi_x ...
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// Scilab code Ex6.6: Pg 203 (2005) clc; clear; c = 1; // Assume speed of light to be unity, m/s h_cross = 197.3; // Reduced Planck's constant, eV.nm/c^2 m_e = 511e+03; // Mass of an electron, eV/c^2 L = 0.200; // Length of the box, nm E1 = %pi^2*(h_cross/c)^2/(2*m_e*L^2); // Ground state ener...
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//Kunii D., Levenspiel O., 1991. Fluidization Engineering(II Edition). Butterworth-Heinemann, MA, pp 491 //Chapter-17, Example 3, Page 444 //Title: Reactor-Regenerator with Circulating Catalyst: Catalytic Cracking //===================================================================================================...
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function dx=Gl(t,x) k=4.2; m=3; v=1; dx(1)=x(1)*(1-x(1)/k)-m*x(2)*x(1)/(1+x(1)) dx(2)=m*x(2)*x(1)/(1+x(1))-v*x(2) endfunction function dx=Gl(t,x) v=0.4; m=.2505; k=0.1770068; dx(1)=x(1)*(1-x(1)/k)-m*x(2)*x(1)/(1+x(1)) dx(2)=m*x(2)*x(1)/(1+x(1))-v*x(2) endfunction clf() v=0.2; m=...
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//===================================================================================== //Chapter 12 example 21 clc;clear all; //variable declaration M1 = 15.9; //mutual inductance in mH M2 = 0.1; //mutual inductance in mH r1 = 25.9; //resistance in Ω r2 = 12.63; //resistance in ...
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//To Calculate the Time Elapsed between Door Openings //Example 47.3 clear; clc; c=3*10^8;//Speed of Light in m/s v=0.8*c;//Speed of Train T1 in m/s y=1/sqrt(1-(v/c)^2);//Speed of Box in the frame of T1 in m/s rl=30*c;//Rest Length of the box in metres t=(rl*v*y)/(c^2);//Time elapsed between th...
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//Exa3_2 clc; clear; close; //given data is : F=100000;//in rupees n=10;//in years i=15;//% per annum P=F/(1+i/100)^n; disp("The person has to invest : "+string(P)+" Rupees."); //Note : Ans in the book is not correct.
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clc,clear printf('Example 7.9\n\n') SA_plate= 2.54^2 thickness= 0.05 //thickness of deposit density=9 //density of nickel W=SA_plate*thickness*density //masss of deposit CE_Ni=59; CE_Ag=108; //chemical equivalents ECE_Ag=0.001118 //electrochemical equivalents ECE_Ni = ECE_Ag*((CE_Ni/2)/CE_Ag) //valancy of N...
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// File name: projects/01/Or8Way.tst load Or8Way.hdl, output-file Or8Way.out, compare-to Or8Way.cmp, output-list in%B2.8.2 out%B2.1.2; set in %B00000000, eval, output; set in %B11111111, eval, output; set in %B00010000, eval, output; set in %B00000001, eval, output; set in %B00100110, eval...
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clc(); clear; // To calculate the velocity of an electron and proton Ee=10; //electron kinetic energy in eV EeeV=Ee*1.6*10^-19; //electron kinetic energy in J Ep=10; //proton kinetic energy in eV EpeV=Ep*1.6*10^-19; //proton kinetic energy in J me=9.1*10^-31; //mass of electron in kg mp=1.67*10^-27; ...
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errcatch(-1,"stop");mode(2);//Caption:In a single phase transformer Find Full load regulation at a power factor (a) 0.8 lagging (b) unity (c) 0.8 leading. //Exam:3.22 ; ; V_1=6600;//Primary voltage (in Volts) V_2=250;//Secondary voltage (in Volts) K=V_2/V_1;//Ratio of transformation R_1=10;//Primary resistance...
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8_7.sce
clear; clc; //Example - 8.7 //Page number - 292 printf("Example - 8.7 and Page number - 292\n\n"); //Given m = 0.6;//[kg/s] - mass flow rate T_low = -20+273.15;//[K] - Temperature at which vapour enters the compressor T_high = 30+273.15;//[K] - Temperature at which vapour leaves the condenser //From satu...
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function F=dft_fga(f) N=length(f) for m=0:N-1 F(m+1)=0; for n=0:N-1 F(m+1)=F(m+1)+f(n+1)*exp(-%i*2*%pi*n*m/N); end end F=clean(F) endfunction function F=dft_fga2(f) N=length(f) m=0:N-1; n=0:N-1; W=exp(-%i*2*%pi*n'*m/N); F=f*W; F=clean(F) e...
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//Problem 7.07: An iron ring of mean diameter 10 cm is uniformly wound with 2000 turns of wire. When a current of 0.25 A is passed through the coil a flux density of 0.4 T is set up in the iron. Find (a) the magnetizing force and (b) the relative permeability of the iron under these conditions. //initializing the va...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); sf=T_scene_create; sss=T_getscene; vp=T_getviewport; vp.CameraPos=point(0,0,1); vp.CameraDir=vector(0,0,-1); vp.FocalDistance=1; vp.NearClipPlane=0.1; vp.FarClipPlane=20; vp.enableusernavigation=false; vp.EnableUserStop=true; #Show list of videos filelist=GetFileLis...
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//Example 10.3 omega_0=0;//Initial angular velocity (rad/s) alpha=110;//Angular acceleration (rad/s^2) t=2;//Time (s) r=4.50*10^-2//Radius of reel (m) omega=omega_0+alpha*t;//Final angular velocity (rad/s) printf('a.Final angular velocity = %0.1f rad/s',omega) v=r*omega;//Speed of fishing line (m/s) printf('\nb...
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clc clear //Input data m=1;//Mass of water in g t1=20;//The temperature of water in degree centigrade t2=-10;//The temperature of ice in degree centigrade s1=4.2;//Heat capacity for one gram of water in J/g-K s2=2.1;//Heat capacity for ice in J/g-K li=335;//Latent heat of fusion of ice at 0 degree centigr...
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//To Calculate the Work Done in Rotating the Magnet //Example 36.2 clear; clc; M=1.0*10^4;//Magnetic Moment of the Bar Magnet in J/T B=4*10^-5;//Horizontal Magnetic Field in Tesla theta1=0;//Initial Angular position of the Magnet theta2=%pi/3;//Final Angular position of the Magnet W=-M*B*(cos(t...
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@relation vehicle @attribute COMPACTNESS integer[73,119] @attribute CIRCULARITY integer[33,59] @attribute DISTANCECIRCULARITY integer[40,112] @attribute RADIUSRATIO integer[104,333] @attribute PRAXISASPECTRATIO integer[47,138] @attribute MAXLENGTHASPECTRATIO integer[2,55] @attribute SCATTERRATIO integer[112,265] @attr...
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function Purb = funcion1(t) //mode(0) Purmax = 80000; Purmin = 110000; ku = 0.05; Purb = Purmax*exp(-ku*t)+Purmin; endfunction function Psub = funcion2(t) //mode(0) Psmax = 320000; P0 = 10000 ks = 0.09; Psub = Psmax./(1+(Psmax/P0-1)*exp(-ks*t)) endfunction function fx = tiempoP...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 10: POWER SYSTEM STABILITY // EXAMPLE : 10.19 : // Page number 305 clear ; clc ; close ; // Clear the work space and con...
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function [stk,txt,top]=sci_text() // Copyright INRIA txt=[] if rhs==3 then str=stk(top)(1) x=stk(top-2)(1) y=stk(top-1)(1) stk=list('xstring'+rhsargs([x,y,str]),'0','0','0','0') elseif rhs==0 then stk=list(' ','-2','0','0','0') else str=stk(top)(1) z1=stk(top-1)(1) y1=stk(top-2)(1) x1=stk(top-3)(1) ...
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clear; clc; printf("\nEx2.15\n"); //page no.-63 //given m=9.11*10^-31;.............//mass of e in kg E=1.6*10^-15;..............//energy in joule h=6.625*10^-34;.............//planck's constant d=5.5*10^-11;...............//interplanar spacing in m //we knoe , E=m*v^2/2 v=sqrt((2*E)/m);..........//velocity ...
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//<f>=%rdr(s1,s2) // %rdr(s1,s2) calcule la division element par element de la matrice de //fractions rationnelles s1 par la matrice de fractions rationnelles s2 // s1./s2 //! [s1,s2]=sysconv(s1,s2) [num,den]=simp(s1(2).*s2(3),s1(3).*s2(2)) f=tlist('r',num,den,s1(4)) //end
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//page no 229 //example no 7.7 // INCREMENT & DECREMENT. clc; disp('LXI H,2040H'); // loads HL register pair. disp('H=20H L=40H'); disp('MVI M,59H'); M=59; M=hex2dec(['59']); disp('2040H-->59H') disp('INR M'); M=M+1; // increments the value at the memory location by 1. m=dec2hex(M); printf('\n Content...
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// Scilab Code Ex 1.11 :Page-25 (2006) clc; clear; R = 1; // For simplicity we assume radius of atom to be unity, m // For bcc Structure, a = 4*R/sqrt(3); // Lattice parameter of bcc crystal, m // We have R+r = a/2, solving for r r = a/2-R // Relation between radius of the void and radius of the atom, m p...
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/////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Date: Feb. 2010 // Description: hierarchical dimensionality reduction (hdr) // // Copyright (C) 2009 OpenPR // All rights reserved. // // Redistribution and use in source and binary forms, with or without...
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function txt=do_newblk(o,nam) //create text of GUI function associated with a a block // o : block data structure // nam : name of the created GUI function //! for k=5:8,o(2)(k)=0*o(2)(k),end // disconnect links o(2)(1)=0*o(2)(1) // set origin to zero o(2)(2)=o(2)(2)/20 // set definition size ????? // form text...
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//clear// //Caption:Nonreturn-to-zero unipolar format //Figure 6.1(a): Discrete PAM Signals Generation //[1].Unipolar NRZ //page 235 clear; close; clc; x = [0 1 0 0 0 1 0 0 1 1]; binary_zero = [0 0 0 0 0 0 0 0 0 0]; binary_one = [1 1 1 1 1 1 1 1 1 1]; L = length(x); L1 = length(binary_zero); total_durati...
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// Exa 5.3 format('v',5); clc; clear; close; // Given data Bita= 5/100; f_H= 50;// in kHz f_H= f_H*10^3;// in Hz f_L= 50;// in kHz Amid= 1000; f_LF= f_L/(1+Bita*Amid);// in Hz f_HF= f_H*(1+Bita*Amid);// in Hz disp(f_LF,"Value of f_LF in Hz is : ") disp(f_HF*10^-6,"Value of f_LF in MHz is : ")
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//Example 4.6 // total cost of elecric charge clc; clear; close; nl=12;//no. of lamps wl=100;//wattage of lamps hl=6;//each lamps work 6 hours a days w12=wl*nl*hl;//wattage of 12 lamps in Wh nf=6;//no. of fans wf=60;//wattage of fans hf=5;//each fans work 5 hours a days w6=wf*nf*hf;//wattage of 12 fans in Wh nc=2;//no....
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//Example 20 //temperature clc; clear; close; rtd=16/14;//ratio of densities tk=15+273;//degree celsius x=(tk*rtd)-273;//degree celsius disp(x,"temperature is ,(degree-celsius)=")
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// Example 4.11 page no-211 clear clc alfa = 0.96 B=alfa/(1-alfa) x=80 Rl=75000 //ohm Av=B*Rl/x Ap=Av*B printf("power gain = %.0f",Ap)