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// ----------------------------------------------------------------------- /// \brief Calcule un terme de contrainte a partir d'une homographie. /// /// \param H: matrice 3*3 définissant l'homographie. /// \param i: premiere colonne. /// \param j: deuxieme colonne. /// \return vecteur definissant le terme de contrainte...
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//Example 2.9 //Z transform of the signal x(n)=(a)^n*u(n)+(b)^n*u(-n-1). clear;clc; xdel(winsid()); //u(n)is unit step input //a=0.5 and b=0.6 n1=2; x1=(0.5)^n1; m1=1; w1=1; phi1=tand(0); a1=1; theta1=tand(45); [X1]=czt(x1,m1,w1,phi1,a1,theta1) n2=2; x2=(0.6)^n2; m2=1; w2=-1; phi2=tand(-45); a2=1;...
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//Finding of Head Discharge , Ratio of Power //Given Q1=0.035; H1=25; D1=0.5; N1=1200; D2=0.3; N2=2000; //To Find H=(D2*N2*sqrt(H1))/(D1*N1); H2=H^2; Q=(Q1*D2^3*N2)/(D1^3*N1); Pr=(D1/D2)^5*(N1/N2)^3; disp("Head ="+string(H2)+" meter"); disp("Discharge ="+string(Q)+" m^3/sec"); disp("Power Ratio ="+string...
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clc() //Metodo de secante f(x) = e^(-x)-x function result = f(x) result = exp(-x)-x endfunction function tabla=newtonRaphson(x0,fx,delta,n) [tabla] = (n+1) xr = x0 tabla(1,1) = 0 tabla(1,2) = x0 tabla(1,3) = fx(x0) tabla(1,4) = 0 for i = 1:1:n xa = xr ...
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#************************************************************ # Scenario of Ikea # # date : Sat Sep 15 18:50:48 2012 #************************************************************ p3d_sel_desc_name P3D_ENV Ikea p3d_sel_desc_name P3D_ROBOT BLUE_BOTTLE p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000...
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//Realiza la eliminacion de Gauss para una matriz A y un vector b // Devuelve: B matriz triangular superior resultado de aplicar eliminación // Gaussiana a A. Realiza pivoteo parcial. // Pivoteo Parcial: Busca el mejor candidato para pivote, que es el que // tenga mayor valor absoluto. function [B] = elimGaussPi...
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// Exa 1.25 clc; clear; close; format('v',5) // Given data R1 = 6;// in ohm R2 = 2;// in ohm R3 = 2;// in ohm R4 = 4;// in ohm R5 = 4;// in ohm R6 = 6;// in ohm R12= R1*R2/(R1+R2);// in ohm R34= R3*R4/(R3+R4);// in ohm R56= R5*R6/(R5+R6);// in ohm // Resistance between the point B and C R_BC= (R12+R34)*...
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clc clear //input data sc=0.8//Pitch-chord ratio of compressor blade b1=45//Relative air angle at inlet in degree b2=15//Relative air angle at oulet in degree a1=b1//Cascade air angle at inlet in degree a2=b2//Cascade air angle at outlet in degree //calculations en=a1-a2//Nominal deflection angle of the bla...
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// Ex5_10 clc; // Given: A1=3836;//in barns E1=1;// in eV E2=10^6// in eV // Solution: vr=sqrt(E2/E1); A2=A1/vr; printf("The cs area required will be = %f b", A2)
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load CS16B032add.asm, output-file CS16B032add.out, compare-to CS16B032add.cmp, output-list RAM[0]%D2.6.2 RAM[1]%D2.6.2 RAM[2]%D2.6.2; set RAM[0] 1, set RAM[1] 2, repeat 20 { ticktock; } output; set PC 0, set RAM[0] 5, set RAM[1] 7, repeat 20 { ticktock; } output;
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${ using Typewriter.Extensions.WebApi; Template(Settings settings) { settings .IncludeProject("CMS.Core"); settings.OutputExtension = ".cs"; settings.OutputFilenameFactory = file => { return $"outputAPIs/{file.Name.Replace(".cs", "") + "Con...
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errcatch(-1,"stop");mode(2);//caption:Find equivalant current source //Ex5.4 Vs=5//source voltage(in V) Rs=1//source resistance(in ohm) I=Vs/Rs disp(I,'equivalant current source(in A)=') exit();
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// Scilab code Ex5.12: Pg 158 (2008) clc; clear; d = 2; // Distance between two parallel conductors, m I_1 = 1000; // Electric current in first coil, A I_2 = 300; // Electric current in second coil, A mew_o = 4*(%pi)*1e-07; // Permeability...
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//Example 2_13 page no:97 clc; delta=[1.08,-0.75, -4.75,5.75]; delta1=[-6.25,-0.75, 21.25,5.75]; delta2=[1.08,-6.25, -4.75,21.25]; V1=det(delta1)/det(delta); V2=det(delta2)/det(delta); Vx=V1+5-V2; disp(V1,"the voltage V1 is"); disp(V2,"the voltage V2 is"); disp(Vx,"the voltage across 4 ohm resi...
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// **** Purpose **** // PiLab band structure calculator (level 3) //==== << PiLab inputs >> ==== //[ban.Format]: 1x1, string, 'red' / 'cart' //<= format of ban.Path points, reduced or cartisian k-points //[ban.Path]: nx3, n>=2, real //<= points to defined your paths, ban.Format defines their meaning //[ban...
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//Script file example //Note a=rand(1,8000,"normal"); L=length(a) b=sin(a); c=L+1 d=a+%i*%pi; //d¬O½Æ¼Æ j=2 d2=a+j*%pi; d1=a+%pi*%i; u1=sin(d1);u1(1:3) u2=sin(d2);u2(1:3),[max(u2),min(u2)]
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// Aim:To find final pressure in the cylinder in SI units // Given: // initial gas pressure: p1=70; //bar // initial volume of cylinder: V1=12900; //cm^3 // initial temperature of cylinder: T1=37.8; //deg C // final volume of cylinder: V2=9680; //cm^3 // final temperature of cylinder: T2=93.3; //deg C
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z=imread('C:\Users\prathima\Desktop\DIPproject\final.jpg');//z is the eroded image that we obtained H=imread('C:\Users\prathima\Desktop\DIPproject\finalA.jpg'); I=imread('C:\Users\prathima\Desktop\DIPproject\finalB.jpg'); J=imread('C:\Users\prathima\Desktop\DIPproject\finalD.jpg'); K=imread('C:\Users\prathima\Des...
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//Example 1_34 clc; clear; close; format('v',5); //given data : V1=48;//V R1=4;//ohm R2=20;//ohm R3=12;//ohm R4=12;//ohm V2=12;//V //Open circuit AB I1=V1/(R1+R2);//A I2=V1/(R3+R4);//A VR1=V1*R1/(R1+R2);//V//across 4 ohm resistance VR2=V1*R2/(R1+R2);//V//across 20 ohm resistance VR3=V1*R3/(R3+R4);//V//...
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//Example No.2.1. // Page No.59. clc;clear; p = 5*10^(-3);// output power -[W]. w = 632.8*10^(-9);//wavelength -[m]. h = 6.626*10^(-34);//Planck's constant. c = (3*10^(8));//Velocity of light. hv = ((h*c)/(w));// Energy of one photon printf("\nThe energy of one photon in joules is %3.3e J", hv); hv = hv/(1.6...
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1947 1 1 1 4 1 1041 'Neujahr' 1947 2 1 2 5 1 1025 '' 1947 3 1 3 6 1 1025 '' 1947 4 1 4 7 1 1028 '' 1947 5 1 5 1 2 1032 '2.So.n.Weihn.' 1947 6 1 6 2 2 1057 'Epiphanias' 1947 7 1 7 3 2 513 '' 1947 8 1 8 4 2 513 '' 1947 9 1 9 5 2 513 '' 1947 10 1 10 6 2 513 '' 1947 11 1 11 7 2 516 '' 1947 12 1 12 1 3 520 '1.So.n.Epiph.' 1...
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//Example 1.1 //Rounding off Numbers //Page no. 2 clc;clear;close; a=[81.9773;48.365;21.385;12.865;27.553] for i=1:5 printf('\n%g becomes %.4g\n',a(i),a(i)) end
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//-9=4.879704469003193e-316 //-8=4.879704469003193e-316
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//page 12 //Example 1.8 clear; close; clc; n = rand(); n = round(n*10); disp(eye(n,n)); printf('This is an Identity matrix of order %d * %d',n,n); disp('And It is a row reduced matrix.'); m = rand(); n = rand(); m = round(m*10); n = round(n*10); disp(zeros(m,n)); printf('This is an Zero matrix of order %...
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clc clear //Initialization of variables dL=1/6 //ft mf=0.430 //lbm/sec rho=62.4 gc=32.2 //ft/s^2 d=0.81/12 //ft //calculations V=mf*4/(rho*%pi) VD=V/dL^2 Vd=1.92 //ft/s dFf=0.031/(2*gc) *2.31 dFe=0.04*Vd^2 /(2*gc) dF=dFf+dFe dp=rho*(3.5/(2*gc) +dF) vd22=(2*gc)/rho *dp /(1-(d/dL)^4) vd2=sqrt(vd22) C=V...
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n = input("Enter value of n = "); for i = 1:n-1 for j = 1:n-1 a(i, j) = i^j; end end printf("Power of integers < n ") disp(a); for i = 1:n-1 for j = 1:n-1 a(i, j) = pmodulo(a(i, j), n); end end printf("\nPower of integers < n (mod n)") disp(a); for i = 1:n-1 for j...
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basis=150 //kg feed S100=0.905 //g AgNO3/g S20=0.689 //g AgNO3/g inputx=0.095 //kg water/kg outputx=0.311 //kg water/kg
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clc;clear; //Example 5.11 //given data W=6000;//wavelegth in Angstrom v=4*10^5;//velocity in m/sec m=9.12*10^-31;//mass of electron in kg e=1.6*10^-19;//the charge on electron in C //calculations KE=0.5*m*v^2/e; disp(KE,'The Kinetic energy in eV is'); WF=12400/W; Wo=12400/(WF-KE); disp(Wo,'The threshold...
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syms K s=%s; G=syslin('c',(K*(s+4/3))/(s^2*(s+12))) evans(G,60) d=derivat(G) p=numer(d) a=roots(p) // a=breakaway points disp(a,"Breakaway points=") printf("Equal roots are at s=-4") printf("/n Value of K at s=-4=") K=4*4*8/(4-(4/3)) disp(K)
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//In A low Speed subsonic wind tunnel,one side of a Mercury manometer is connected byto the reservior and the other side is connected to the test section. r=1/15; //contraction ratio of nozzle A2/A1 P1=1.1*1.01*10^5 //reservior pressure,N/m^2 T1=300 //reseroir temperature,k Dh=0.1 //height difference between the tw...
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errcatch(-1,"stop");mode(2);//Caption:Determine the (a)speed at full load (b)speed at double full load (c)stalling torque in terms of full load torque //Exa:2.30 ; ; V=250;//in volts R_a=0.2;//in ohms N_1=800;//in rpm R_f=250;//in ohms I_f=V/R_f;//in amperes I=41;//in ampers I_a1=I-I_f;//in amperes E_1=V-(...
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example8_13.sce
//Chapter 8 //Example 8_13 //Page 184 clear;clc; r=1; d=100; go=30/sqrt(2); mo=0.9; delta=0.952; vc=mo*go*delta*r*log(d/r); lv=vc*sqrt(3); printf("Disruptive critical voltage = %.2f kV/phase \n\n", vc); printf("Line voltage = %.2f kV \n\n", lv);
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clc; f=50*10**3; dutyc=0.60; C=0.0022*10**-6; T=1/f; t1=dutyc*T; t2=T-t1; R2=(t2)/(0.7*C); disp('Kohm',R2*10**-3,"R2="); R1=(t1)/(0.7*C)-R2; disp('Kohm',R1*10**-3,"R1=");
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// Example 12.1 // Write a program to read data from keyboard,write it to a file called INPUT, // again read the same data from the INPUT file and display it on the screen. warning('off'); disp("Data Input"); //Open the file INPUT f1=mopen('INPUT.txt','w'); // Get character from keyboard ...
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 1-Properties of Fluid // Problem 1.19 //Given Data Set in the Problem(SI Units) gap=2.2/100 visc=2 SG=0.9 g=9.81 W_dens=SG*1000*g Vol=1.2*1.2*0.2/100 Area=1.2*1.2 t=0.2/100 vel=0.15 W=40 //Calculations dis_from_plate...
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//Ex 9.15 clc; clear; close; format('v',6); fL=200;//Hz fH=1; //kHz Ap=4;//Pass band gain fc=sqrt(fH*1000*fL);//Hz(Cutoff frequency) BW=fH*1000-fL;//Hz Q=fc/BW;//Quality Factor disp(Q,"Quality factor is "); disp("As Q<12, it is a wide band filter."); Ap1=2;//Pass band gain for high pass section disp("Vari...
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//chapter-10 page 487 example 10.3 //============================================================================== clc; clear; //For a microwave LOS link f=2*10^9;//frequency of operation in Hz c=3*10^8;//Velocity of light in m/sec r=50000;//repeater spacing in m PrdBm=-20;//required carrier power at the rec...
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//Example 3.9 clear; clc; //Applying Thevenin's theorem //Anew=(R1B/(R1A+R1B))Aold and R1A || R1B =R1 AnewdB=0; Anew=10^AnewdB; C=10*10^(-9); Aold=2.8;//Obtained from Example 3.8 RA=10*10^3;//Assumed value of RA RB=17.8*10^3; R1=15915.494;//obtained from Example 3.8 R2=R1; R1A=R1*(A...
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clear; clc; close; Id_low = 2;//mA Id_high = 25;//mA Vd_reverse_bias = -10;//V Vd_low = 0.5;//V Vd_high = 0.85;//V Id_reverse_bias = -10*10^(-6);//A Rd_low = Vd_low/Id_low; Rd_high = Vd_high/Id_high; Rd_reverse_bias = Vd_reverse_bias/Id_reverse_bias; disp(Rd_low,'Low level dc resistance(in ohm):'); d...
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//Example 2.7.3.b: Average deviation clc; clear; close; //given data : n=10; X1=147.2;// in nF X2=147.4;// in nF X3=147.9;// in nF X4=148.1;// in nF X5=148.1;// in nF X6=147.5;// in nF X7=147.6;// in nF X8=147.4;// in nF X9=147.6;// in nF X10=147.5;// in nF AM=(X1+X2+X3+X4+X5+X6+X7+X8+X9+X10)/n; d1=X1-AM; d2=X2-AM; d3=...
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clc //initialisation of variables hf=-104036 //Btu/lb mole Cp0=4260//Btu/lb mole h1=4345//Btu/lb mole h3=3661 //Btu/lb mole P=500//lbf/in^2 T=600//F Pr=P/3206//lbf/in^2 Tr=1060/1165//F Tc=0.53//F //CALCULATIONS h=hf+Cp0//Btu/lb mole h2=hf+h1//Btu/lb mole h4=hf+h3//Btu/lb mole h5=Tc*1165//Btu/lb mole H...
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/////Chapter 10 Properties Of Steam ////Example 10.1 Page No:183 ///Find Dryness fuction of steam ///Input data clc; clear; mw=15; //Water steam ms=185; //Dry steam ///Calculation x=((ms)/(ms+mw))*100; //Dryness fuction of steam in % ///Output printf('Dryness fuction of steam= %f percent \n',x);...
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example26_18.sce
m_v=230; f=60; p_out=1.5*746; pf=0.8; eff=0.75; disp("Part a"); p_in=p_out/eff; m_i1=p_in/(m_v*pf); deg_i1=acos(pf); m_p1=m_v*m_i1; deg_v=0; deg_p1=deg_v+deg_i1*180/%pi; p1=m_p1*(cos(deg_p1*%pi/180)+%i*sin(deg_p1*%pi/180)); p=real(p1); p2=p-p1; qc=-imag(p2); x_c=m_v^2/qc; c=1/(2*%pi*f*x_c); disp("the ...
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clc //initialization of varaibles s=1.6315 //B/lb R //calculations disp("From table 1 ") h=1180.6 //B/lb t=302.92 //F p=70 //psia //results printf("Pressure = %d psia",p) printf("\n Temperature = %.2f F",t) printf("\n Enthalpy = %.1f B/lb",h)
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Example1_15_b.sce
//Example 1.15(b) clear; clc; Rp=100*10^3;//Potentiometer Resistance VCC=15; VEE=-15; //We have to choose the resistances in such a way that we get VA=10V and VB=-10V, so that if we want the source to be in the range -10V<=vW<=10V, we need to only turn the wiper. Let RA and RB be the resistances corre...
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// Variable declaration std_dev = 0.04 //standard deviation x = 4 // number of ounces p = 0.02 // probability of x <4 // Calculation // as we know p = (x-Mean)/std_dev // from Table-3 (page-514) we find closest value to 0.02 which is 0.0202 corresponding to Z = -2.05 Mean = 4 - (-2.05*0....
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 1 //Introduction and Basic Concepts //Example 4 clear; clc; //Given F = 600; //weight in N t = 120; //time in sec h = 0.18; //height of stairs in m //To determine the power developed in man S = 20*h; //total vertical displacement in m W =...
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f=50E6 w=2*%pi*f theta=5*%pi/180 C=1E-12 R=1/theta/w/C disp(R) C=10E-12 R=1/theta/w/C disp(R) C=100E-12 R=1/theta/w/C disp(R)
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clc; // page no 211 // prob no 6.6.1 //In given problem zero bias capacitance co is 20pF Co=20;// in pF Vd=-7;// reverse bias voltage in volt //constant pottential of junction is 0.5 a=0.5;// for abrupt junction Cd=Co/(1-(Vd/0.5))^a; disp('pF',Cd,+'The value of capacitor is ');
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 33 disp("CHAPTER 1"); disp("EXAMPLE 33"); //VARIABLE INITIALIZATION I=10; //current source in Amperes v=10; //voltage source in Volts r1=4; //top resistance in Ohms r1=4; ...
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//exa 1.13 clc;clear;close; format('v',7); LF=0.825;//Daily Load Factor ratio1=0.87;//daily peak load to monthly peak load ratio2=0.78;//monthly peak load to annually peak load LF_annual=LF*ratio1*ratio2;//Annual Load Factor disp(LF_annual,"Annual Load Factor : ");
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CH09Exa3.sce
// Scilab code Exa9.3 : : Page-390 (2011) clc; clear; h_cut = 1.0545e-34; // Reduced Planck's constant, joule sec G = 6.6e-11; // Gravitational constant, newton square metre per square Kg m = 10^30; // Mass of the star, Kg m_n = 1.67e-27; // Mass of the neutron, Kg R = (9*%pi/4)^(2/3)*h_cut^...
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Ex13_5.sce
// chapter 13 // example 13.5 // fig. 13.14 // Determine the snubber component values for critical damping, value of R and power loss // page-810-811 clear; clc; // given Edc=30; // in V fs=40; // in kHz i_L=30; // in A (load current) t_r=80; // in ns (rise time) t_f=30; // in ns (fall time) neta=10; // in...
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// Example 6.2//internal power level clc; clear; close; e=1.6*10^-19;//Electronic charge ht=6.62*10^-34;//Constt C=3*10^8;//speed light in m/s h=0.87*10^-6;//wavelength in meter tr=80;//radiative recombination time in nano second tnr=120;//non radiative recombination time in nano second t=(tr*tnr)/(tr+tnr);//...
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c2_4.sce
//(2.4) During steady-state operation, a gearbox receives 60 kW through the input shaft and delivers power through the output shaft.For the gearbox as the system, the rate of energy transfer by convection is Qdot = -hA(tb-tf) where h = 0.171 kW/m2.k is the heat transfer coefficient, A=  1.0 m2 is the outer surface a...
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//Example 3.14 clear; clc; C=100*10^(-9);//Assuming C=100 nF C1=C; C2=2*C; f0=60; BW=5; R=1/(2*%pi*f0*C); R1=R; R2=R/2; Q=f0/BW; K=(4-(1/Q))/2; RA=10*10^3; RB=(K-1)*RA; printf("Designed Second Order Notch Filter :") printf("\nR1=%.2f kohms",R1*10^(-3)); printf("\nR2=%....
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//Chapter 2 //Example 2_16 //PAge 30 clear;clc; p1=700; p2=500; n1=1; n2=2; fc=0.28; cv=10200; days=30; pcf=0.4; max_energy=(p1*n1+p2*n2)*24*days; printf("(i)\tMaximum energy that can be produced in a month = %.1f kWh \n\n", max_energy); act_energy=pcf*max_energy; printf("\t\t Actual energy produce...
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function [p] = prog6(A) n = 4; p = 1; for i = 1:n q = A(i, 1); for j = 2:n if q > A(i, j) then q = A(i,j); end end p = p * q; end endfunction
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// Grob's Basic Electronics 11e // Chapter No. I // Example No. I_1 clc; clear; // Express the following numbers in scientifi c notation:(a) 3900 (b) 0.0000056. disp ('To express 3900 in scientific notation, write the number as a number between 1 and 10, which is 3.9 in this case, times a power of 10.') disp ('...
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clear; clc; h1=75; h2=45; l=300; g=9.81; T=2500*g; m=.9; w=m*g; //(a) lc=l+ (2*T * (h1-h2)/(w*l)); dOC=(lc/2)-l; hCO=w * dOC *dOC / (2*T); dOP=dOC+(l/2); hPO=w * dOP *dOP / (2*T); hPC=hPO-hCO; mprintf("\nHeight of mid point P above C =%.2f m",hPC); hP=hPC+h2; mprintf("\nHeight of mid point P abo...
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// This is sketchy code - devise your own implementation for i=1:height for i=1:width // Ceck pixel value of I(i,j) against threshold // Act accordingly end end // Please also provide faster implementations than explicit for loops.
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//Example 2 . 1 1 //Program to Pl o t Magni tude and Phase Responce clc ; w=-%pi :0.01: %pi ; H =1/(1 -0.5*( cos (w)-%i* sin (w))); // c a l u c u l a t i o n o f Phase and Magni tude o f H [ phase_H ,m]= phasemag (H); Hm=abs(H); a= gca (); subplot (2 ,1 ,1); y_location =" o r i g i n "; plot2d (w/%pi ,Hm); ...
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// Exa 4.14 clc; clear; close; // Given data I_o = 2.4 * 10^-14; I = 1.5;// in mA I=I*10^-3;// in A Eta = 1; V_T = 26;// in mV V_T= V_T*10^-3;// in V v =log((I + I_o)/I_o) * V_T;// in V disp(v,"The forward biasing voltage across the junction in V is");
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//problem 1 pagenumber 4.38 //given z='0101';format(6); n=4; vof=15;//volt r=vof/(2^n-1); v0=r*base2dec(z,2); disp('Output voltage = '+string(v0)+' volt');
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//Example 2.6.1: magnitude and relative error clc; clear; close; //given data : format('v',5) R1=15;//ohm E1=R1*5/100;//±limiting error for R1 R2=33;//ohm E2=R2*2/100;//±limiting error for R2 R3=75;//ohm E3=R3*5/100;//±limiting error for R3 RT=R1+R2+R3;//ohm(in series) ET=E1+E2+E3;//±limiting error for RT disp("For ser...
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//Problem 15.05: Calculate the current taken by a 23 μF capacitor when connected to a 240 V, 50 Hz supply. //initializing the variables: C = 23E-6; // in Farads f = 50; // in Hz V = 240; // in volts //calculation: Xc = 1/(2*%pi*f*C) I = V/Xc printf("\n\n Result \n\n") printf("\n current I = %.2f A ",I)
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function result = dsp_upload( dsp_firmware ) // Load and upload DSP application if dsp_firmware <> "" then if isfile(dsp_firmware) <> %t then mprintf(" ERROR: Unable to load DSP firmware - file %s doesn''t exists!", dsp_firmware); result = -1; return end ...
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function plOutput = OffsetPolyline(plInput, mOffestRegimeBoundaries, mOffsetComponents) //plInput = FwdSelfIntSmoothing(plInput, 10, .05); iPointCount = size(plInput, 1); iSegmentCount = iPointCount - 1; iIntersectionCount = iSegmentCount - 1; lnOffsetSegmentBuffer = []; plOffsetP...
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//To Determine the Equivalent System Reliability of Each configuration //Page 612 clc; clear; Ri=0.85; deff('x=relp(y,z)','x=1-((1-(Ri^y))^z)')//Equal Parallel Combination deff('x=rels(y,z)','x=(1-((1-Ri)^y))^z') //Equal Series Combination //Case 1: 4 elements in series Req1= rels(1,4); //Case 2: T...
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//Exa:2.10 clc; clear; close; //Given: //Pb=(1+mt*mt/2)*Pc; printf("\n\n\t (a)when m=1 Pt=1.5Pc"); printf("\n and carrier and one sideband supressed Pt=1.25Pc"); r=1.25/1.5; printf("\n\n\t Percent power saving =%fpercent",r*100); printf("\n\n\t (b)when m=0.5 Pt=1.125Pc"); printf("\n and carrier and one sid...
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//Chapter-4, Illustration 19, Page 208 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA b1=30;//Blade angle at inlet in first stage in degrees b2=30;//Blade angle at exit in first stage in degrees b3=30;//Blade ang...
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//Example 20_1 clc(); clear; //To findout the time that it has to wait after turning off the set before it is safe to touch capacitor r=10^6 //Units in Ohms c=10^-5 //Units in F ti=r*c //Units in Sec printf("We have to wait for a time of t=%d sec",ti)
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//pagenumber 514 example 2 clear macapa=900*10^-12;//farad micapa=90*10^-12;//farad r=100*10^3;//ohm //(a) frequency range fremin=1/(2*3.14*r*macapa); disp("min frequency = "+string((fremin))+"hertz"); fremax=1/(2*3.14*r*micapa); disp("max frequency = "+string((fremax))+"hertz"); //(b) r3 r=10*10^3;/...
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[Read-the-docs-example-2-360-day] # Read the docs - example 2 indice_name: ETR in_files: [['tasmax_day_HadGEM2-ES_historical_r1i1p1_19891201-19991130.nc', 'tasmax_day_HadGEM2-ES_historical_r1i1p1_19991201-20051130.nc'], ['tasmin_day_HadGEM2-ES_historical_r1i1p1_19891201-19991130.nc', 'tasmin_day_HadGEM2-ES_historical_r...
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s=%s; // g i v e n Ka=10 sec^-1 K =10; g =K/(s *s*(1+0.25*s)) G= syslin ('c',g) fmin =0.01; fmax =100; bode (G,fmin , fmax ) show_margins (G) xtitle (" uncompensated system") [gm , freqGM ]= g_margin (G) [pm , freqPM ]= p_margin (G) disp (gm ," g a i n ma r g i n=") disp (( freqGM *2* %pi)," g a in margi...
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function [stk,txt,top]=sci_eval() // Copyright INRIA txt=[] write(logfile,'Warning: eval argument not translated to scilab syntax. Check') if lhs==1 then if rhs==1 then if and(lst(ilst+1)==['1' 'ans']) then stk=list('execstr('+stk(top)(1)+')','0','?','?','?') else stk=list('evstr('+stk(top)(1)+')'...
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//Problem 40.11:The charging current for an 800 m run of isolated twin line is not to exceed 15 mA. The voltage between the lines is 10 kV at 50 Hz. If the line is air-insulated, determine (a) the maximum value required for the capacitance per metre length, and (b) the maximum diameter of each conductor if their distan...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function [Out,G]=SSSoEDFAlimiter(In,P_dBm) // A simple optical limiter. // // Calling Sequence // [Out,G]=SSSoEDFAlimiter(In,P_dBm) // // Parameters // In : Optical Input // P_dBm : Output...
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Energy = -4.622E+05 Energy = -4.728E+05 Energy = -4.820E+05 Energy = -4.904E+05 Energy = -4.981E+05 Energy = -5.050E+05 Energy = -5.112E+05 Energy = -5.168E+05 Energy = -5.217E+05 Energy = -5.259E+05
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//EXAMPLE 8-9 PG NO-525 Ro=600; Fc=3000; L=Ro/(4*%pi*Fc); disp('i) INDUCTANCE (L) is = '+string ([L]) +' H ') C=1/(4*%pi*Fc*Ro); disp('ii) CAPACITOR (C) is = '+string ([C]) +' F ') Fo=2700; m=sqrt(1-(Fo/Fc)^2); disp('iii) (m) is = '+string ([m]) +' '); X=(2*C)/m; disp(...
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//To find the balance weight required and the residual unbalanced force clc //given W=180//lb R=150//lb c=.5 N=300//rpm r=7.5/12//ft Bb=(W+c*R)*r*12 b=6//in B=Bb/b w=(%pi*N)/30 Uf=(1/2)*(R/g)*w^2*r a=floor(Uf) printf("Balance weight required = %.1f lb\n The resultant unbalanced force = %.f lb\n",B,a)
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//Chapter-4, Illustration 23, Page 214 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA P0=800;//Steam pressure in kPa P2=100;//Pressure at point 2 in kPa T0=973;//Steam temperature in K a1=73;//Nozzle angle in de...
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//Example 5.8 //Program to determine the total loss incurred by the star coupler //and average insertion loss clear; clc ; close ; //Given data Pi=1*10^(-3); //Watts - INPUT POWER AT PORT 1 Po=14*10^(-6); //Watts - OUTPUT POWER AT OTHER PORTS N=32; //Ports //Calculation of Spli...
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function[x] = rich(a, b, c, u) //richtmayer's algorithm for solving tridiag matrices [one na] = size(a); if one <> 1 error('a not a vector'); end [one nb] = size(b); if one <> 1 | nb <> na + 1 error('b not the right dims'); end [one nc] = size(c); if one <> 1 | nc ...
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# -------------------------- Header Parameters -------------------------- scenario = "CPT-X"; write_codes = EXPARAM( "Send ERP Codes" ); default_font_size = EXPARAM( "Default Font Size" ); default_background_color = EXPARAM( "Default Background Color" ); default_text_color = EXPARAM( "Default Font Color" ); default_...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 11 Example 3") T1=(-27+273);//temperature of refrigerator in K W=3*.7457;//work input in KJ/s Q=1*3.5;//refrigeration effect in KJ/s disp("COP=T1/(T2-T1)=Q/W") ...
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clc; clear; // A = p2z(R,Theta) - Convert from polar to rectangular form. // R is a matrix containing the magnitudes // Theta is a matrix containing the phase angles (in degrees). function [A] = p2z(R,Theta) if argn(2) <> 2 then error("incorrect number of arguments."); end if ~and(size(R) == size(Theta)) t...
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// Estimating the limiting drawing ratio clc del_l = 0.23 // fractional change in length del_t = -0.1 // fractional change in thickness printf("\n Example 7.7") l_ratio = (1+del_l) t_ratio = (1+del_t) w_ratio = 1/(l_ratio*t_ratio) R = log(1/w_ratio)/log(1/t_ratio) printf("\n\n For planar isotropy and from ...
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/* callback.tst - Http tests using callbacks */ // MOB - re-enable if (false) { const HTTP = App.config.uris.http || "127.0.0.1:8080" let http: Http = new Http // Using a read callback http.setCallback(Http.Read, function (e) { if (e is HttpDataEvent) { if (e.eventMask == H...
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<?xml version="1.0" encoding="utf-8"?> <test> <description> 3D Helmholtz/Steady Diffusion Reaction P=7 Hex Deformed</description> <executable>ADRSolver</executable> <parameters>Helmholtz3D_nodal_HexDeformed.xml</parameters> <files> <file description="Session File">Helmholtz3D_nodal_HexDeformed.x...
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load Or8.hdl, output-file Or8.out, compare-to Or8.cmp, output-list ip1%B1.8.1 ip2%B1.8.1 out%B1.8.1; set ip1 %B00000000, set ip2 %B00000000, eval, output; set ip1 %B11111111, set ip2 %B00000000, eval, output; set ip1 %B11111111, set ip2 %B11111111, eval, output; set ip1 %B10101010, set ip2 %B01010101, eval, output;...
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@relation wine @attribute Alcohol real[11.0,14.9] @attribute MalicAcid real[0.7,5.8] @attribute Ash real[1.3,3.3] @attribute AlcalinityOfAsh real[10.6,30.0] @attribute Magnesium real[70.0,162.0] @attribute TotalPhenols real[0.9,3.9] @attribute flavanoids real[0.3,5.1] @attribute NonflavanoidsPhenols real[0.1,0.7] @att...
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// Example 4.3.1 page 4.4 clc; clear; L=10; //fiber length in km Pin=150d-6; //input power Pout=5d-6; //output power len=20; //length of optical link interval=1; //splices after interval of 1 km l=1.2; //loss due to 1 splice attenuation=10*log10(Pin/Pout); alpha=attenu...
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//Chapter 7,Ex7.4,Pg7.15 clc; B=100 Icbo=4 //current in microamperes Ib=40 //Current in microamperes Ic=B*Ib+(B+1)*Icbo printf("\n Ic=%.1f mA \n",Ic*10^-3)