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// Exa 9.6 clc; clear; close; format('v',7) // Given data V1 = 2200;// in V V2 = 440;// in V R1 = 0.3;// in ohm R2 = 0.01;// in ohm X1 = 1.1;// in ohm X2 = 0.035;// in ohm K = V2/V1; Rating = 100;// in KVA I1 = (Rating*10^3)/V1;// in A I2 = (Rating*10^3)/V2;// in A R1e = R1 + (R2/(K^2));// in ohm X1e =...
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//example-19.4 //page no-565 //given //resistivity rho=2*10^-3 //ohm m //conductivity sigma=1/rho //per ohm m //electrons and holes mobility mue=0.3 //m^2/V s muh=0.1 //m^2/V s //charge on holes and electrons are same so e=1.602*10^-19 //C //we know that //sigma=ne*e*mue+nh*e*muh //here ne=nh=n //so...
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//Ex2_10 clc C = 10*10^-6 V = 100 W = C*(V^2)/2 disp("C = "+string(C)+"F")//capacitance disp("V = "+string(V)+"V")//voltage disp("W = C*(V^2)/2 = "+string(W)+"Joules")//calculating for energy stored
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exec get_frequencies.sci; function results = create_dataset(filenames, outfiles) concat_row = 1; // concatenation accord to the rows concat_col = 2; // concatenation accord to the cols filenames_size = size(filenames) for i=1:filenames_size(1) // get number of chords results = []; for j...
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//Example 3.1 //This code utilises dependency file 'Compute_Angle.sci' exec Compute_Angle.sci;//Execute dependency file //To draw vector A x=0; y=0;//x and y are the starting point coordinates magnitude=25; theta=49; x_end=magnitude*cosd(theta); y_end=magnitude*sind(theta);//x_end and y_end are the ending...
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function [F,G] = OraclePG(qc,ind) q = q0+B*qc; if (ind == 2 | ind == 4) then F = (1/3) * (q)' * (r .* (q0 + B * qc) .* abs(q)) + pr' * (Ar*(q)); end if (ind == 3 | ind == 4) then G = B' * (r .* (q) .* abs((q)) + Ar' * pr); end endfunction
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function [y] = WalshCode(len,index,opsamples) y=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); //HadamardCode Generate hadamard code //Y = WalshCode(len,opsamples)) outputs a frame of the Walsh // code in column vector Y. It generates ...
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// Example 2.1 clc; clear; close; // Given data P1= 250;// in kN/m^2 V1= 6.2;// in m^3 V2= 1.82;// in m^3 // Formula P1*V1 = P2*V2 P2= P1*V1/V2;// in kN/m^2 disp(P2,"Pressure of air after compression in kN/m^2 is : ")
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function [M] = expMapDirectThetaU(v,dt) // compute the transformation from the pose t to the pose t+dt // input : the velocity (m/s,rad/s) and the time to apply it (s) // the velocity vector is a ThetaU // resulting motion in translation and theta U //disp("1.Create the vector v_dt"); v_dt = v * dt; u = v_dt(4:6); ...
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// Exa 2.3 clc; clear; // Given // A phase shift oscillator R = 800*10^3; // in Ohm's // R = R1 = R2 = R3 .. given C = 100*10^-12; // in Farad // C = C1 = C2 = C3 .. farad // Solution fo = 1/(2*%pi*R*C*sqrt(6)); printf(' The frequency of oscillations = %d Hz \n',fo);
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<?xml version="1.0" encoding="utf-8" ?> <test> <description>NS, Couette flow with periodic BCs, exact solution, parallel</description> <executable>CompressibleFlowSolver</executable> <parameters>-I parts=6,7:2,4,5:0,1,3 Couette_WeakDG_LDG_Exact_par.xml</parameters> <processes>4</processes> <files> ...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 3 : TRANSFORMERS // EXAMPLE : 3.11 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA S = 50; // kVA Rating of the Transformer f = 50; /...
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function x=%c_rand(a) // Copyright INRIA [m,n]=size(a) x=rand(m,n)
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// Example 19_2 clc;funcprot(0); // Given data T=100.0;// °C // Solution // (a) alpha_fecu=-(-13.4+(0.028*T)+(0.00039*T^2))*10^-6;// V/K // (b) pi_fecu=(T+273.16)*alpha_fecu;// V printf('\n(a)The relative Seebeck coefficient,alpha_fecu=%1.2e V/K \n(b)The relative Peltier coefficient,pi_fecu=%1.2e V',alpha_fe...
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// Example 4.4:core diameter clc; clear; close; format('v',4) d=0.02;//difference n1=1.5;//core refrative index m=1000;// number of modes h= 1.3;// Wavelenght in micrometers a=((h/(%pi*n1))*(m/d)^(1/2));//core diamter in micro meter disp(a,"core diameter in micro meter")
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deff('y=foo(x)','y=1+x^2') foo(3) // outputs 10
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// Example 2.5.1 page 2.17 clc; clear; NA = 0.45 //Numerical aperture betaB = 45 // Skew ray change direction by 90 degree at each reflection Meridional_theta = asind(NA); //computing acceptacne angle for meridoinal ray Skew_theta = asind(NA/cosd(betaB)); //computing acceptacne angle for ske...
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// // // steepest descent method with backtracking line search applied to the rastrigin function // // function y=rastrigin(x) // the function to optimize n=max(size(x)); y=n+sum(x.^2-cos(2*%pi*x)); endfunction //----------------------------------------------------- function y=rastrigingrad(x...
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//Homework Problem function evaluations function [f,g,h] = myfuncn(x,t,y) phi=x(1)*exp(x(2)*t) r=phi-y f=1/2*sum(phi.^2) g(1)=sum(exp(x(2)*t).*r) g(2)=sum(t.*phi.*r) h(1,1)=sum(exp(2*x(2)*t)) h(1,2)=sum(2*x(1)*t.*exp(2*x(2)*t)-y.*t.*exp(x(2)*t)) h(2,1)=h(1,2) h(2,2)=sum(2*(t.*phi).^2...
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//Obtain path of solution file path = get_absolute_file_path('solution11_7.sce') //Obtain path of data file datapath = path + filesep() + 'data11_7.sci' //Clear all clc //Execute the data file exec(datapath) //Evaluate total operating force P (N) P = ((%pi * Pa * d)*(D - d))/2 //Evaluate number of contactin...
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//Ex 3.1 clc;clear;close; R1=2.2;//kohm G=-100;//Voltage gain Rf=-G*R1;//kohm disp(Rf,"Value of Rf(kohm) : ");
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funcprot(0) function [F] = f(x) F=exp(-abs(x)); //mprintf("%f\n",F); endfunction function [R]=rom(p,f) F=0; tol=10^(-6) h=p*2; R(1,1)=f(h); //mprintf("rom: 1 1 %f\n",R(1,1)); h=h/2; R(1,2)=f(h); R(2,2)=(R(1,1) - (4*R(1,2)))/(-3); i=2; j=2; //mprintf("rom: %d %d %f\n"...
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// Scilab code Ex3.6: Pg.131-132 (2008) clc; clear; r = 1e-10; // Radius of Potassium atom, m i = 1e-02; // Intensity of light, W/m^2 phi = 2.22; // Work function of potassium, eV e = 1.60e-19; // Conversion factor t = phi*e/(i*%pi*r^2); // Time lag for the emmision of photoelectron, s printf("\n...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 3 : TRANSFORMERS // EXAMPLE : 3.20 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA V1 = 110; // Primary voltage of the Two Transformers the two p...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.528526D+00 ...
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//x^2+z^2=y^2,y>0 (CONE) x=-5:0.1:5; y=0:0.1:3; deff('z=f1(x,y)','z=sqrt(y^2-x^2)'); fplot3d(x,y,f1) deff('z=f2(x,y)','z=-sqrt(y^2-x^2)'); fplot3d(x,y,f2)
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// Example 15_17 clc;funcprot(0); // Given data T=5000;// K // Calculation // (a) K_e1=10^0.450;// The equilibrium constant for the reaction K_e2=1/K_e1;// The equilibrium constant for a second reaction printf("\n(a)The equilibrium constant for the first reaction,K_e1=%1.2f \n The equilibrium constant for a...
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//Example5.28,Pg5.28 clc; Wi=1 //Iron loss in kW op=50*0.8*10+25*0.6*10+0*4 Wcu=1.2 //Copper loss in kW Culoss=1*1.2*10+(25/50)*1.2*10+0 //Copper loss in the entire day considering the load cycle for a day as given in the question Iloss=1*24 nallday= (op/(op+Iloss+Culoss))*100 printf("\n All day efficiency=%.2f...
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clear; clc; // Stoichiometry // Chapter 6 // Stoichiometry and Unit Operations // Example 6.14 // Page 384 printf("Example 6.14, Page 383 \n \n"); // solution //Pa = v.p. at DP Pw = 2.0624 //kPa P = 100 //kPa Hm = Pw/(P-Pw) // kmol water vapour / kmol dry air H = .622*Hm // kg moisture/kg dry ...
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//Ex 2.2 clc;clear;close; format('v',5); IC10=20*10^-6;//A IREF=0.5*10^-3;//A IS=10^-14;//A VT=25*10^-3;//V(Thermal Voltage) R4=VT/IC10*log(IREF/IC10);//ohm disp(R4/1000,"For Widlar current source design, the value of R4(kohm) : ");
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//4.12 clc; Vs=7; Vn=1; fh=10^3; H=2*fh*log2(1+(Vs/Vn)); printf("\nMaximum possible data transmission rate =%.1f bits per second",H) Sampling_rate=2*fh; printf("\nminimum sampling rate per channel =%.1f samples per second",Sampling_rate) C_max=85714/2000; printf("\nmaximum number of channels =%.0f ",C_max)
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clc // Given that delta_lambda = 1e-6 // accuracy in wavelength of its one part lambda = 1e-10 // wavelength of x-ray in m h = 6.62e-34 // Planck constant in J-sec // Sample Problem 4 on page no. 15.25 printf("\n # PROBLEM 4 # \n") printf("Standard formula used \n") printf(" del_x*del_p = h/(4*pi) \n") delta_x = lamb...
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clc; //Example 18.3 //page no 227 printf("\n Example 18.3 page no 227\n\n"); // water is flowing at room temperature rho=62.4//density of water,lb/ft^3 meu=6.72e-4//viscosity of water,lb/ft.s D=0.03125//diameter of pipe v=10//velocity R_e=D*v*rho/meu//reynolds no. printf("\n reynolds no R_e=%f ",R_e); f=0....
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// Exa 9.7 // To determine modulation scheme to be used and Eb/No. clc; clear all; Rb=144; //data rate in kbps BW=36; //in MHz Pb=3*10^-5;//probability of bit error //solution Seff=Rb/BW; //spectral efficiency in bps/Hz M=2^(Rb/BW); //since the channel is band limited disp("16-QAM (refer Equation 9...
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// Scilab code Ex5.11: Pg:219 (2008) clc;clear; Lambda_1 = 5000e-08; // First wavelength of spectral line, cm Lambda_2 = 5200e-08; // Second wavelength of spectral line, cm aplusb = 1/10000; // Grating element where a is the width of slit and b is the width of opaque region in a grating, cm f = 150; //...
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module Dto {$Classes(*Model)[ export interface $Name$TypeParameters {$Properties[ $name: $Type;] }] } ${ Template(Settings settings) { settings.OutputFilenameFactory = file => { var fileName = file.Name.Replace(".cs", ""); fileName = fileName.Replace("Model", ""); fil...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Euler, pressure perturbation to test RiemannInvariant CBC, parallel</description> <executable>CompressibleFlowSolver</executable> <parameters>--use-scotch Perturbation_M05_square_CBC_par.xml</parameters> <processes>3</processes> <files> ...
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//Example 6_15 clc; clear; close; format('v',4); //given data : //v=50*sin(100*%pi*t) Vm=50;//V f=50;//Hz rf=20;//ohm RL=5000;//ohm Im=Vm/(rf+RL)*1000;//mA disp("(a) Current is "+string(Im)+"*sin(100*%pi*t) for %pi <100*%pi*t<2*%pi & it will be zero for 0 <100*%pi*t<%pi"); format('v',5); Vdc=Im/1000/%pi*...
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//Chapter 30 Ex5 clc; clear; close; S={'D','A','U','G','H','T','E','R'}; sizeS=size(S,"c"); n=6; //since there are 3 vowels, they are considered as 1 letter reqLetters=n; //since all the letters are required noLetters=factorial(n)/factorial(n-reqLetters); reqVowels=3; //since vowels are required to be toget...
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//Kunii D., Levenspiel O., 1991. Fluidization Engineering(II Edition). Butterworth-Heinemann, MA, pp 491 //Chapter-13, Example 3, Page 332 //Title: Effect of Particle Size on h //========================================================================================================== clear clc //INPUT rho...
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//example 1 //Calculating reversible work clear clc //Form the Steam Tables,the inlet and the exit state properties are hi=171.95 //initial specific heat of enthalpy in kJ/kg si=0.5705 //initial specific entropy in kJ/kg-K se=2.1341 //final specific entropy in kJ/kg-K he=765.34 //final specific heat of enthalp...
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clear// //Variables VS = 1.5 //Source Voltage (in volts) RS = 0.4 //Resistance (in ohm) RL = 2.0 //Load Resistance (in ohm) //Calculation RT = RS + RL //Total Resistance (in ohm) I = VS/ RT //Current (in Ampere) VT ...
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//Car and truck //refer fig.12.14 and 12.15 u=12.5 //m/sec //sT=10+12.5*t+(aT*t^2)/2 aT=-2 //m/sec^2 //t is the time at any instant after the brakes are applied //sT=10+12.5*t-t^2 //distance moved by car //sC=u*2+u*(t-2)+(aC*(t-2)^2)/2 //sT=sC //Apply equations of motion //we get quadratic equation whose ...
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clear; clc; printf("Example 10.5\n"); N_dot=50; //Initial maas transfer rate D=1.8e-9; //Diffusivity of gas in liquid phase C_bg=(1/22.4)*(273/293); //bulk gas concentration N_C=N_dot*C_bg; //Initial maas transfer rate in terms of cocentration h=N_C/0.04;// Effective Mass transfer coefficient R=1/h;//Equi...
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//design a clamp coupling clc //solution //given P=30000//W N=100//rpm t=40//N/mm^2 n=6 ft=70//N/mm^2 u=0.3 //let d be dia Tq=(P*60*1000)/(2*%pi*N)//N-mm //Tq=(%pi/16)*t*d^3=7.86*d^3 //d=(Tq/7.86)^(1/3)//mm printf("the dia of shaft is,%f mm\n ",(Tq/7.86)^(1/3)) printf("the dia of shaft is ,say 75mm\n") ...
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//Page Number: 4.20 //Example 4.22 clc; //Given B=0.2; f1=200D+3; //Hz fml=50; //Hz fmh=15D+3; //Hz delf=75D+3; //hz fc=108D+6; //Hz delf1=B*fml; n1n2=delf/delf1; //Let n2=150 n2=150; flo=((delf*f1)-fc)/n2; disp('Hz',flo,'fLO'); n1=n1n2/n2; disp(n1, "n1 with n2=150:")
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//clc(); clear; //To determine the visible number of orders N=10520; //grating lines in lines per centimetre theta=90; //angle in degrees lambda=5*10^(-5); //wavelength of light in centimetres e=1/N; n=(e*sind(theta))/lambda; printf("the number of orders visible in grating spectra i...
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clc //Initialization of variables P1=15 //lb/in^2 P2=20 //lb/in^2 T1=40+460 //R T2=540+460 //R //calculations disp("From table 6 at the two temperatures") phi1=0.58233 phi2=0.75042 ds=phi2-phi1-53.3*log(P2/P1) /778 //results printf("Entropy change = %.5f B/lbm R",ds)
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clear ; close; clc; T0=4; t=.01:0.01:2*T0; t_temp=0.01:0.01:T0/2; s=length(t)/length(t_temp); x=[]; for i=1:s if modulo(i,2)==0 then x=[x zeros(1,length(t_temp))]; else x=[x ones(1,length(t_temp))]; end end a=gca(); plot(t,x) poly1=a.children.children; poly1.thickness=3; p...
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//Chapter-4, Example 4.3, Page 132 //============================================================================= clc clear //CALCULATIONS v1=0;v2=5;v3=10;v4=20;v5=50;v6=60;v7=50;v8=20;v9=10;v10=5;v11=0;v12=-5;v13=-10; Vm=60; V=((v1^2)+(v2^2)+(v3^2)+(v4^2)+(v5^2)+(v6^2)+(v7^2)+(v8^2)+(v9^2)+(v10^2)) V=sqrt(V/1...
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// Exa 17.2 // To calculate voice and data traffic per cell. clc; clear all; usage=150; //subscriber usage per month in mins days=24;//Days in a month BHrs=6;//Busy hours per day BW=4.8; //in MHz RFch=200; //in kHz Psubscribers=50000;//present subscriber count growth=0.05;//subscriber growth per year ...
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Expanding for base=3, level=3, reasons+features=base,same,similiar,evenexp norm,showfail Refined variables=k,x,y [0+1k,0+1x,0+1y]: unknown -> [1] [0,0,0] 3k-x²-3y²-1 ---------------- level 0 expanding queue[0]^-1,meter=[1,3,1]: 3k-x²-3y²-1 [0+1k,0+3x,0+1y]: failure constant=-1, vgcd=3 [0,0,0] 3k-9x²-3y²-1 [0+1k,1+3x,0+...
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//chapter 10 //example 10.4 //page 350 figure 10.9 Vz=5; V_=5; R2=15;R3=15; //V_ across R3 Vout=((R2+R3)/R3)*(V_)//voltage across R3 disp(Vout)
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 7: UNDERGROUND CABLES // EXAMPLE : 7.12 : // Page number 219 clear ; clc ; close ; // Clear the work space and console ...
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// Interpolação de Newton ----------------------------------------------------- function tabelaDiffDiv = tDD(x, y) global tabela dimensao = length(x) tabela = zeros(dimensao, dimensao) tabela( : , 1) = y' diffDiv(x, 1, dimensao) tabelaDiffDiv = tabela endfunction function dd = diffDiv(x, linha, coluna) global ...
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// a =[1 2; 3 4; 5 6]; b = [1 2 3; 4 5 6]; for i=1:3 for j=1:3 c(i,j) =0; for k=1:2 c(i,j =c(i,j)+a(i,k)*b(k,j); end end end disp(c);
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clear clc //to find tension in string to get 4 loops // GIVEN: //refer to figure 18-23 from page no. 418 //freqyuency fn = 120//in Hz //length of string L = 1.2//in meters //linear mass density of string mew = 1.6//in g/m //no. of loops n = 4 // SOLUTION //using equation of wave motion //tension in s...
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//Example 2.15://load current clc; clear; close; rw=3550;//reading of wattmeter rp=806;//watts ph=atand((sqrt(3)*rp)/rw);//in degree pf=cosd(ph);//power factor v=440;//volts i=((rw)/(sqrt(3)*v*pf));//amperes disp(round(i),"load current in amperes is")
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//Transport Processes and Seperation Process Principles //Chapter 2 //Example 2.5-1 //Principles of Momentum Transfer and Overall Balances //given data f=10*(1/7.481)*(1/60);//flow rate(ft3/s)=10(gal/min)*(1ft3/7.481 gal)(1min/60s) D=2.067/12;//diameter in ft A=(3.14*D*D)/4;//cross sectional area in ft2 v=f/A;/...
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// Scilab Code Ex9.6: Page-466 (2011) clc;clear; mu1 = 1.466; // Refractive index of core mu2 = 1.460; // Refractive index of cladding v = 2.4;....// Cut-off parameter of the optical fibre lambda = 0.8e-006;....// Operating wavelength, m NA = sqrt(mu1^2-mu2^2); printf("\nThe NA of optical fibre = %4.2f", NA)...
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//Notations have been changed //Calculations x=-(25*125*0.5*125+25*100*0.5*25)/(25*125+25*100) //mm y=(25*125*0.5*25+25*100*75)/5625 //mm Iy=(1/12)*25*125^3+25*125*(62.5-40.3)^2+(1/12)*100*25^3+100*25*(40.3-12.5)^2 //mm^4 Ix=Iy //mm^4 for L-section //The second computation checks the first Ixy=(125*25*22.2*27.8...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 3 Example 22") p1=1.5*10^5;//initial pressure of air in pa T1=(77+273);//initial temperature of air in K p2=7.5*10^5;//final pressure of air in pa n=1.2;//expan...
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//Ex:3 clc; clear; close; a=6628.14;//Radius of space shuttle in km T=5370.30//Time period in sec v_s=2*%pi*a/T;//Velocity in km per sec printf("Velocity of the shuttle =%f km per sec", v_s);
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//example 6.5 clear; clc; //Given: b=0.0391;//Van der waals constant[dm3/mol] R=0.082;//Universal gas constant[dm3*atm/mol] P2=1000;//pressure [atm] P1=0;//pressure [atm] T=1273;//Temperature [K] //To find the fugacity and fugacity coefficient x=b*(P2-P1); y=R*T; fc=exp(x/y);//fugacity coefficient ...
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//Variable declaration beeta=100 //current gain factor Vbe=0.7 //base to emitter voltage(V) Rb=250 //base resistance(k ohms) Vee=10 //emitter voltage(V) Re=1 //emitter resistance(k ohms) //Calculations...
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// Example 7.9:oscillation frequency clc; clear; close; C=0.2;//capacitance of tunned circuit in MICRO farad L1=0.5;//INDUCTANCE of tunned circuit in milli henry L2=1;//INDUCTANCE of tunned circuit in milli henry fo=(1/(2*%pi*sqrt((L1+L2)*10^-3*C*10^-6)));//tunned frequency in killo hertz disp(fo,"tunned frequ...
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//example 12.10 //calculate critical exit gradient and factor of safety of system clc;funcprot(0); //given b=60; //length of floor H=6; //static head of weir d=6; //downstream depth of pile n=0.3; //porousity of soil particles G=2.7; //relative density of soil particles alph...
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clc clear; close; A=[0,0,0;0,0,0;0,0,0] A(1,1)=input("enter a11: ") A(1,2)=input("enter a12: ") A(1,3)=input("enter a13: ") A(2,1)=input("enter a21: ") A(2,2)=input("enter a22: ") A(2,3)=input("enter a23: ") A(3,1)=input("enter a31: ") A(3,2)=input("enter a32: ")...
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// Example 32_17 clc;funcprot(0); //Given data P=1000;// Plant capacity in MW P_1=1000;// MW t_1=2;// hours P_2=500;// MW t_2=6;// hours P_3=300;// MW t_3=8;// hours n=50;// Number of days plant should shut down completely // Calculation E_g=((P_1*t_1))+((P_2*t_2)+((P_3*t_3)));//Eenergy generated per work...
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clc //initialisation of variables Q= 400000 d= 4 //miles h= 50 //ft q= 40 //gallons of water t= 8 //hr f= 0.0075 w= 6.24 //lb/ft^3 g= 32.2 //ft/sec^2 //CALCULATIONS Q1=Q*q*0.5/(t*60*60*w) d= (4*f*(d*5280)*Q1^2*16/(%pi^2*h*2*g))^0.2*12 //RESULTS printf ('size of the supply = %.1f in ',d)
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//CHAPTER 10- THREE-PHASE INDUCTION MACHINES //Example 11 clc; disp("CHAPTER 10"); disp("EXAMPLE 11"); //VARIABLE INITIALIZATION P1=4; //number of poles s=5/100; //slip f=60; //frequency of synchronous generator in Hertz //SOLUTION //solution (a) ...
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//Example 3.1, Page Number 97 //Change in Refraction Index due to Pockels effect clc; //Variable Initialization l=10*(10**-3) //Width of Crystal in milli meter V=4000 //Applied Voltage in volts r=26.4*(10**-12)//linear electro optic coefficient in pm per volt no=1.51**3//Value for KD*P taken from table 3.1 //...
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clc //initialisation of variables mn= 0.0134 //gms mo= 0.0261 //gms mh= 0.0081 //gms T= 30 //C P= 3 //atm r= 4/5 //CALCULATIONS V= mn*(273+T)*1000/273 V1= V*r V2= V1*P V3= mo*(273+T)*(1-r)*P*1000/273 V4= mh*(273+T)*r*1000/273 V5= V4*P V6= V2-V1 V7= V5-V4 //RESULTS printf (' volume of oxygen= %.1f ml',...
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// A simple JSON parser function JSON2Struct = JSONParse(JSON) true = "%T" false = "%F" oldnull = null, null = "%Nan" // Backup the null() function and set variable JSON_text_cat = strcat(JSON); // The following section is required to convert multidimensional // arrays into...
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function [queue,status]=commStatus(h) TCL_EvalStr("set ttyq [fconfigure "+h+" -queue]") queue=evstr(TCL_GetVar("ttyq")); TCL_EvalStr("set ttys [fconfigure "+h+" -ttystatus]") status=TCL_GetVar("ttys"); endfunction
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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scenario = "run1_Audball_pronetSZAMP_09042021"; #======================================= # #Auditory Task: # #Standard 1 #Target 2 #Novel 4 #Response 5 # #======================================== #attenuation updated for ER1 insert earphones and X-fi gamer card pcl_file = "Commands.pcl"; scenario_type = trial...
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//Problem 13.15: Determine the current flowing in the 2ohm resistance in the network shown in Figure 13.37(a). //initializing the variables: I = 15; // in amperes R1 = 6; // in ohms R2 = 4; // in ohms R3 = 8; // in ohms R4 = 2; // in ohms R5 = 7; // in ohms //calculation: //The 2ohm resistance branch is sh...
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//EX13_15 PG-13.10 clc clear printf("conversion of binary no 1101.1 to its decimal equivalent =") N=(1*2^3)+(1*2^2)+(0*2^1)+(1*2^0)+(1*2^(-1)); printf(" %.1f",N)
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clc x=poly(0,'x') Lx=13/80*x^4-239/120*x^3+691/80*x^2-1429/120*x+88/5 Lx_=13/80*x_^4-239/120*x_^3+691/80*x_^2-1429/120*x_+88/5 dx1=derivat(Lx) dx2=derivat(dx1) disp(dx2) disp(dx1) dx1=-11.908333+17.275*x_-5.975*x_^2+0.65*x_^3 dx2=17.275-11.95*x_+1.95*x_^2 x=[1 2 3 4 5] y=[12.5 15 19 22.3 26.6] plot(x, y,'r*') x_=0:0.1:...
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//(Chain Drives) Example 14.7 //Speed of the electric motor n1 (rpm) n1 = 1400 //Speed of the line shaft n2 (rpm) n2 = 350 //Number of teeth on the driving sprocket z1 z1 = 19 //kW rating of 10B chain for n1 rpm from table 14.2 on page 550 kW kW = 11.67 //Pitch of the chain p (mm) p = 15.875 //Breaking loa...
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clear; clc; Za=%i*300;Zc=-%i*700; Zoc1=Za+Zc; Zsc1=Za; Zoc2=Zc; Zsc2=(Za*Zc)/(Za+Zc); Zi1=sqrt(Zoc1*Zsc1); printf("-Image impedance Zi1 = %f ohms\n",round(Zi1)); Zi2=sqrt(Zoc2*Zsc2); printf("-Image impedance Zi2(in ohms)= %f ohms\n",round(Zi2)); Zt1=(Za/2)+(sqrt((Za*Za/4)+(Za*Zc))); A=real(Zt1) B=imag(Zt1)...
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function node_num = kd_tree(points,depth,parent_number) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku University global cellIn; //cell array global lcell; //int //Description: //Computes a kd_tree from the dataset //INPUT: //points : the dataset //dept...
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//example 3.3 clear; clc; //given: H=29.2;//latent heat of vaporisation[KJ/mol] T=332;//temperature of the system[K] R=8.314;//universal gas constant [J/K/mol] //to find Q,W,U for 1 mole of bromine vaporizes //where Q is heat absorbed or evolved //W is the work done by system //U is the change in inte...
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//Example 3.5, page no 94 clc disp('part b') lambda=5890*10^-8//in cm c=3*10^10//in cm/s v=c/lambda del_v=8*10^6//per s x=del_v/v h=4.14*10^-15//in ev-sec printf("\n Fractional width of either line(del_v/v) %e ",x) //Calculate uncertainty disp('part c') del_t=10^-8 del_e=(h)/(4*%pi*del_t) printf("\n Uncertainty is %e ...
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function [ok,kevans]=rlsettings(); // This program is free software; you can redistribute it and/or modify // it under the terms of the GNU General Public License as published by // the Free Software Foundation; either version 2 of the License, or // (at your option) any later version. // // This program is ...
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//Variable declaration e=1.6*10**-19; //charge of electron(c) epsilon0=8.85*10**-12; //permittivity(C/Nm) r0=0.281*10**-9; //seperation(m) IE=5.14; //ionisation energy of Na(eV) Ea=-3.61; //electron affinity(eV) //Calculation V=-e**2/(4*e*%pi*epsilon0*r0); CE=IE+Ea+(V); //cohesiv...
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clc clear exec('objective.sce'); disp('RUNNING...') rand('seed',getdate('s')) POPSIZE = 50 DIM = 2 UPPER = 100 LOWER = -100 MAXITER = 50 SALP = rand(POPSIZE,DIM).*(UPPER-LOWER)+LOWER FIT = F1(SALP) [FIT SORTIND] = gsort(FIT,'lr','i') SALP = SALP(SORTIND,:) GBESTFIT = FIT(1) GBESTPOS = SALP(1,:) ...
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//page no 448 //prob 10.11 clc; Px0=.4 , Px1=.6 ,PE0=10^-6 , PE1=10^-4 ;// given PE=(Px0*PE0) + (Px1*PE1)// formula for probability of error disp(PE,"probability of error = ");
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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function mdaq_close(link_id) if link_id < 0 then disp("WARNING: You are trying to close non existing connection!"); return; end mdaq_disconnect(link_id); endfunction
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clc clear //Initialization of variables Fa=0.045 l=4 //m b=4 //m Fe=1 Ta=540+460 //R Tb=1540+460 //R //calculations A=l*b Q=0.173*A*Fa*Fe*((Tb/100)^4 -(Ta/100)^4) Q2=416000 //results printf("In case 1, Net energy exchange = %d Btu/hr",Q) printf("\n In case 2, Net energy exchange = %d Btu/hr",Q2) disp('T...
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//Example 7_11 clc(); clear; //To calculate the fractional index for an optical fiber n1=1.563 n2=1.498 delta=(n1-n2)/n1 printf("The fractioal index of an optical fiber is %.4f",delta)
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clc; //page 272 //problem 5.5 //Let Abe the maximum value of the discrete samples. //Error tolerated is 0.1% i.e. 0.001A //If D is step size then possible maximum error is D/2 //Thus D/2 = 0.001A or A/D = 500 = no of levels required(Levels) Levels = 500 //minimum no of binary digits required(B) = rounded va...
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clc clear printf("example 4.1 page number 125\n\n") //to find water compressibility delta_p=70; //in bar Et=20680 //in bar compressibility = delta_p/Et; printf("compressibilty of water = %f",compressibility)
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//Exa 9.5 clc; clear; close; //Given data : P=100000;//in Rs F=20000;//in Rs n=8;//in years Sum=n*(n+1)/2;//sum of the years disp("The rates for years 1-8, are respectively 8/36,7/36,6/36,5/36,4/36,3/36,2/36,1/36"); disp("The calculations of Dt and Bt for different values of t are summarized in table below u...
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//fonction d'addition d'image // chargment des images // for d'analyse de pixels addition function img_out=additionMoyenne(matriceA,matriceB) img_inA = matriceA; img_inB = matriceB; SizeXa = size(matriceA,"r"); SizeYa = size(matriceA,"c"); SizeXb = size(matriceB,"r"); SizeYb =...
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//calculating the reading of the multimeter and percentage error clc; Zl=20000; Zo=10000; Eo=6; El=Eo/(1+Zo/Zl); disp(El,'Reading of the multimeter (V)=') PE=((El-Eo)/Eo)*100; disp(PE,'Percentage error=')
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//Chapter 5, Problem 3 clc f1=260*10^6 //frequency in hertz f2=100*10^6 //frequency in hertz A=40 //minimum attenuation in dB //calculation fr=f1/f2 n=A/(20*log10(fr)) printf("Number of arms = %f\n i.e 5 arms",n)