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// Test #9 : Valid case #1 exec('./zpklp2xn.sci',-1); [z,p,k,n,d]=zpklp2xn([8 9],2,5,[0.1 0.5],[0.5,0.75],'pass'); disp(d); disp(n); disp(k); disp(p); disp(z); // //Scilab Output //d=1. -0.1783598 -0.1261194 //n=0.1261194 0.1783598 -1. //k=- 186.43631 //p= 0.1427731 + 0.6153536i // 0....
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//Example 2.2 On Bernoulli's Equation // Initialisation of variables D1 = 8; P1 = 20*144; //Gage Pressure in lb per square feet q = 1000; //Rate of flow in gallon per minute. D2 = 4; Patm = 2116.2; rho = 62.4; // Calculations q = q*231/(1728*60); //Rate of flow in ft^3/sec A1 = %pi*(D1/12/2)^2...
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//FIND THE DIRECTION OF POWER FLOW OF MICROWAVE //given clc function w=cross_prod(E,F)//function to determine the cross product of two vectors D=[E(:),F(:)] w(1)=det([[1;0;0],D]) w(2)=det([[0;1;0],D]) w(3)=det([[0;0;1],D]) endfunction E=[0 1 0] F=[1 0 0] q=cross_prod(E,F) disp(q','the cross product of the g...
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//example5.4 //constructing Routh array in scilab clear;clc xdel(winsid());//close all windows mode(0); s=%s; A=s^3+8*s^2+26*s+40; //consider p-plane is located to the left of the s-plane. //distance between p-plane and s-plane is 1. //if the origin is shifted from s-plane to the p-plane,then, s=p-1 z=%z...
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clc v1 = 25 // cutting speed in m/min t1 = 90 // tool life in min. v2 = 35 // cutting speed in m/min t2 = 20 // tool life in min n = log(v2/v1)/log(t1/t2) // exponent C = v1*(t1)^n // constant t = 60 // tool life in min. v = C/(t)^n // cutting speed in m/min. printf("\n n = %0.3f\n C = %0.1f\n Cutting speed = ...
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disp("Hello Pussy") a = 5; b = 2; c = 3; d = a + b + c; disp(d) disp("GoodBye Pussy")
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expression: -hypergeom(a,b,-c,d)^(1/2) + hypergeom(a,b,c)/(-1/2) postfix1: ;0;hypergeom(;a;b;,;0;c;-;,;d;,;hypergeom);1;2;/;^;-;hypergeom(;a;b;,;c;,;hypergeom);0;1;2;/;-;/;+ rebuilt1: -hypergeom(a,b,-c,d)^(1/2)+hypergeom(a,b,c)/(-1/2) postfix2: ;0;hypergeom(;a;b;,;0;c;-;,;d;,;hypergeom);1;2;/;^;-;hypergeom(;a;b;,;c;...
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clear //given // //find the brake horse power N=1150. Wt=151. l=4. Wo=22. //finding netforce //f=Wt-Wo F=Wt-Wo //then as R=4. //calculating Brake horse power Bhp=F*R*N/(5250.) printf("\n \n braking horse power %.2f bhp",Bhp)
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// Calculation of upsetting force clc d1 = 200 // diameter in mm h1 = 125 // height in mm h2 = 50 // height in mm K = 760 // in MPa n = 0.19 mu = 0.2 // coefficient of friction printf("\n Example 6.1") epsilon1 = log(h1/h2) Yf = K*epsilon1^n v = %pi/4*d1^2*h1 r2 = sqrt(v/(%pi*h2)) P_av= Yf*(1+(2*mu*r2/(...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Kovasznay Flow P=8</description> <executable>IncNavierStokesSolver</executable> <parameters>KovaFlow_m8_short_ConOBC.xml</parameters> <files> <file description="Session File">KovaFlow_m8_short_ConOBC.xml</file> </files> <metrics>...
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A=[1,2,1,3,4;2,1,5,9,8;5,0,6,4,3;2,5,8,9,8;7,3,4,2,7]; B=[11;25;18;32;23]; X=[]; M=eye(5,5); for j=1:5 M=eye(5,5); for i=1:5 if(i==j) M(i,j) = 1/A(i,j); elseif(i>j) M (i,j) = -A(i,j)/A(j,j); end end z=M*A; A=z; y=M*B; B=y; end disp("m:"); disp(M) disp("a:"); disp(A); X=zeros(...
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// Stage 4 // Saves files containing the max hold data exec('C:\Program Files\scilab-5.3.1\work\get_max_hold_data.sce', -1)
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var neggen = require("./neggen") neggen.showAllTems() neggen.srchTem("4tl3") neggen.printTem("4tl3tr2bl") neggen.config.template = "4tl3tr2bl" neggen.config neggen.getTemCfg() neggen.creat() tar -cvf 4tl3tr2bl.tar 4tl3tr2bl rm -r 4tl3tr2bl pscp root@192.168.152.128://opt/JS/APPS/4tl3tr2bl.tar 4tl3tr2bl.tar rm 4tl3tr2bl...
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//Ex11_9 clc VCC = 25//collector voltage Vi = 9//inout rms voltage RL = 10//load resistnce Vi_peak = 1.414*Vi//input peak voltage Vo = Vi_peak//output peak voltage Po_ac = (Vo^2)/(2*RL)//output power Io = Vo/RL//output current IC = (2/%pi)*Io//collector current Pi_dc = VCC*IC//input power eta = Po_ac/Pi_dc//...
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//Example 3.3: clc; clear; close; format('v',5) //given data : alfa=0.88; Ie=1;// in mA Ic=alfa*Ie;// in mA I_B=Ie-Ic; disp(I_B,"Base current,(mA) = ")
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//chapter 19 //example 19.22 //page 868 printf("\n") printf("given") Vcc=15;Rl=15;Rd=.3;R5=2.2*10^3;R6=33*10^3;C2=3.9*10^-6;C4=100*10^-12; disp(" power output") Vp=(Vcc*Rl)/(Rd+Rl) Ip=Vp/Rl Po=(Vp*Ip)/2 disp(" voltage gain") Av=(R5+R6)/R5 disp("cutoff frequency") f1=1/(2*3.14*C2*R5) f2=1/(2*3.14*C4*R6)
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clc ni = 1.5*10^10 disp("ni= "+string(ni)+"cm^-3")//initializing value of intrinsic carrier concentration Na = 10^18 disp("Na = "+string(Na)+"cm^-3") //initializing value of p+ doping Nd = 10^17 disp("Nd = "+string(Nd)+"cm^-3") //initializing value of n channel doping kBT=0.026 disp("kBT = "+string(kBT)+"eV") /...
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//example 4.4 clc;funcprot(0); //Initilization of variable Vload=[0.0 0.2 0.4 0.6 0.8 4.8 5.0 5.2 5.4 5.6 5.8 6.0 6.2 6.4 11.4 11.6 11.8 12.0]; Iload=[0.0 0.0 0.0 0.1 0.1 0.5 0.5 0.5 0.5 0.6 0.6 0.6 0.6 0.6 1.1 1.2 1.2 1.2]; Pload=[0.00 0.00 0.02 0.04 0.06 2.30 2.50 2.70 2.92 3.14 3.36 3.60 3.84 4.10 13.00 13.46 1...
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//Chapter 2, Problem 19 clc; P1=3000; //power in watts P2=150; //power in watts t1=20; //time in hours t2=30; //time in hours n1=2; //no of fires n2=6; //no of light m=14; //cost per unit E1=P...
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clc; clear; printf("\t\t\tChapter9_example3\n\n\n"); // Determination of the outlet temperature of the ethylene glycol for counterflow. // properties of air at (195 + 85)/2 = 140°F. from appendix table CII rou_1= 0.985*62.4; // density in lbm/ft^3 cp_1=0.9994; // specific heat BTU/(lbm-degree Rankine) v_1= 0.514e...
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//Example 16_2 clc(); clear; //To calculate the speed of the proton q=1.6*10^-19 //Units in C vab=45 //Units in V m=1.67*10^-27 //Units in Kg va=sqrt((2*q*vab)/m) //Units in meters/sec printf("The speed of the proton is Vab=%.2f meters/sec",va)
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x=[1 2 3 4 5 6 7 8 9 10]; y=[9 8 5 8 4 6 2 3 5 1]; n=10; z=[1.25, 5.63 ,9.8 ,4.24 ,7.31]; for i=0:4 for j=0:n if z(i)>x(j)& z(i)<x(j+1) k=j; end end for i=0:4 rez=rez[k]+(z(i)-x[k])/x[k+1]-x[k] end end disp(rez); plot(x,y,'...
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function [X] = solveGSM(A, B, X, n) [p, q] = size(A); while n>0 for k = 1:q X(k) = ((B-A*X)/A(k,k))(k) + X(k) end n=n-1 end endfunction A = [28 4 -1; 2 17 4; 1 3 10]; B = [32 35 24]'; X = [0 0 0]'; X = solveGSM(A, B, X,3); disp(X); A = [8 1 -1;1 -7 2; 2 1 9]; B = [8 -4 12]'; X = [0 0 0]'; X = solveGSM(...
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// Chapter 5 additional Example 6 //============================================================================== clc; clear; // input data a = 4.3*10^-10; // Lattice constant in Å p = 960; // Density of crystal in kg/m^3 A = 23; // Atomic wt N = 6.023*10^2...
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// Chargement de l'image img_input=readpbm("C:\Users\DimitriXPS\Documents\GitHub\Exolife\Exolife\Images\Mission 1\Encelade_surface.pbm"); // Affichage image display_gray(img_input); // Taille de l'entrée de l'image sizex = size(img_input, 1) sizey = size(img_input, 2) // Création image sortie img_output=zeros(s...
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// Example 9_4 clc;funcprot(0); // Given data r=10;// The compression ratio T_1=200+273;// K P_1=200;// kPa w_net=1000;// kJ/kg c_v=0.717;// kJ/kg.K R=0.287;// kJ/kg.K k=1.4;// The specific heat ratio // Calculation T_2=T_1*(r)^(k-1);// K function[X]=temperature(y) X(1)=w_net-((c_v*(T_1-T_2...
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clc // Given that l=500//in mm Length w=60//in mm width v=0.6//in m/min d=3//in mm depth of cut D=150//in mm diameter of cutter n=10//no. of inserts N=100//in rpm spindle rotation // Sample Problem on page no. 655 printf("\n # Material Removal Rate , Power Required and Cutting Time in Face Milling # \n...
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x=1;y=1;vs=5;vw=1; // Copyright INRIA getf('swim.sci'); [ts,ps,tps]=optim(swim,0) popt(ps);
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clc // Given that Mp = 1.67e-27 // mass of proton in kg v = 3e5 // speed of proton in meter/sec B = 5e-9 // magnetic field in tesla e = 1.6e-19 // charge on a proton in coulomb // Sample Problem 7 on page no. 6.23 printf("\n # PROBLEM 7 # \n") r = (Mp * v) / (e * B)//calculation for Larmour radius printf("\n Standard ...
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//Caption:Calculate the number of turns on both primary and secondary winding in a single phase transformer //Exam:3.1 clc; clear; close; E_1=500;//primary induced emf(in Volts) E_2=250;//secondary induced emf(in Volts) F=50;//supply frequency(in Hz) B_max=1.2;//maximum flux density(in T) a=0.009;//cross secti...
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//CHAPTER 6 _ PRESSURE AND SOUND MEASUREMENT //Caption : Elastic Transducers // Example 3 // Page 337 Sa=1000 disp("Sa=1000") //('Enter the sensitivity of LVDT =:') //Properties of diaphragm E=200*10^9 //('Enter the value of modulus of elasticity=:') disp("E=200*10^9 ") v=0.3 //('Enter the Poissons ratio=...
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//Chapter 1,Example 1.6,Pg 1.11 clc; R10=80 //Resistance at 10 degrees Celsius R60=96.6 //Resistance at 60 degrees Celsius disp("R10=R0(1 + 10a0)") disp("R60=R0(1 + 60a0)") disp("Divide both the equations") disp("96.6/80 = (1 +60a0)/(1+10a0)") a0=(96.6-80)/(4800-966) at=a0/(1+a0*60) printf("\n Temp coeff at 6...
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//Electric Drives:concepts and applications by V.subrahmanyam //Publisher:Tata McGraw-Hill //Edition:Second //Ex3_4 clc; clear; Vs=200;//Supply voltage in V Rd=12.5;//Resistance in ohm Xc=0.5;//Reactance in ohm pf=0.5;//Powerfactor Vdia=0.9*Vs*pf; Id=Vdia/(Rd+(Xc/%pi)); disp(Id,"The average value of dc cu...
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mode(-1) clf clear f = fscanfMat("./states.txt") f1 = f(:,1) f2 = f(:,2) f3 = f(:,3) state = f(:,4) //k = [1:length(f1)] //k = [1800:2000] k = [1000:1200] subplot(411) plot2d(k, f1(k)) subplot(412) plot2d(k,f2(k)) subplot(413) plot2d(k,f3(k)) subplot(414) plot2d(k,state(k))
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//associative property of convolution clc clear close x = input("sequence x(n): ") h1 = input("sequence h1(n): ") h2 = input("sequence h2(n): ") //lhs = [x(n)*h1(n)]*h2(n) lhs = conv(conv(x,h1),h2) //rhs = x(n)*[h1(n)*h2(n)] rhs = conv(x,conv(h1,h2)) disp("LHS: ",lhs) disp("RHS: ",rhs) //plotting n_lhs = 0:length(...
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clc //Initialization of variables g=1.4 r1=10 r2=12 r3=15 Tl=530 //R Th=1960 //R //calculations eta1=1- (r1)^(1-g) eta2=1- (r2)^(1-g) eta3=1- (r3)^(1-g) etac=1-Tl/Th //results printf("Efficiency in case 1 = %.1f percent",eta1*100) printf("\n Efficiency in case 2 = %.1f percent",eta2*100) printf("\n Effi...
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clear; clc; //Example 2.2 //full wave rectifier circuit with 60Hz input signal V_M=10;//(V)peak output voltage R=0.01;//(MOhm)output load resistance f=60;//Hz V_r=0.2;//(V)ripple voltage C=V_M/(2*f*R*V_r);//capacitance printf('\ncapacitance=%f microF\n',C)
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clc //initialisation of variables T1=(100+273)//Degree C T2=(300+273)//degree C T=(1-T1/T2)*100//F lam=0.41//in //CALCULATIONS R=log(T2)-log(T1)//lb/in^2 r=2.849//ratio of compression //RESULTS printf('The ideal efficiency and the compression ratio=% f ratio of compression',r)
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function y = f(x) y = x^2 endfunction function f1(a) c = a - (f(a)/numderivative(f,a)) if f(c) < 10^-5 then disp(c) break else f1(c) end endfunction
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//Example 1.2 clc disp("The transistor capacitance is given by,") disp(" CT = C(0) / [1+|VR/VJ|^n]") disp("Now C(0) = 80pF, n = 1/3 as diffused junction") disp(" VR = 4.2 V, VJ = 0.7 V") ct=((80*10^-12)/((1+(4.2/0.7))^(1/3)))*10^12 // in pF format(6) disp(ct,"Therefore, CT(pF) = ") disp("the transisto...
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//EX3_9: Show that //A'BC'D + (A' + BC)(A + C'D') + BC'D + A'BC' // = ABCD + A'C'D' + ABD + ABCD' + BC'D //clears the screen clc //clears already existing variables clear //First, we will reduce the left side disp('LHS = A''BC''D + (A'' + BC)(A + C''D'') + BC''D + A''BC''') //Eliminate ...
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# ATWM1 MRI Experiment scenario = "ATWM1_Working_Memory_MRI_nonsalient_uncued_run1"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds...
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//Chapter 8 //Example 8_11 //Page 179 clear;clc; n=3; shunt=0.2; line=0.1; lower=0.3; v2=15.4/15.5; v3=12-11*0.993; v=1+v2+v3; eff=v/n/v3; printf("V2 = %.3f*V1 \n", v2); printf("V3 = %.3f*V1 \n", v3); printf("Voltage between conductor and earth = %.2f*V1 \n", v); printf("String efficiency = %d %% \n\n", eff*100);
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clc h=1800; //m T=277; //K t=4; //s y=1.4; R=287; //J/kg K C=sqrt(y*R*T); //tan(a)=h/t*V //V=C/sin(a) //From above two equations we get a=(acos(C/h*t)); V=C/sin(a)*3600/1000; disp("Speed of the aircraft =") disp(V) disp("km/h")
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funcprot(0) function [polar] = rect2polar(x,y) //Function to convert rectangular coordinates to polar coordinates polar=ones(1,2) polar(1)=sqrt((x^2)+(y^2)) polar(2)=atan(y/x) polar(2)=(polar(2)*180)/%pi endfunction clc //Refer to the data given in the question Vl=208 //Line voltage P=1800 //A...
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result postfix=[1, 1, x, +, /, 1, 1, x, -, /, +] (2) / ( - x^2 + 1) vectors: [2],[1,0,-1] coefficients: [2,0,2,0,2,0,2,0,2,0,2,0,2,0,2,0]
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//Example 4.27//number and wattage clc; clear; close; format('v',6) h=5;// in meters el=100;//in lux ef=16;//efficiency in lumens/watt dp=0.2;//depreciation factor uf=0.4;//utiliazation factor l=60;// in meters b=15;// in meters a=l*b;//arean in m^2 glr=(a*el)/(uf*(1-dp));//gross illumination required n=12*3;//total ...
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//[s]=%palss(d1,s2) //s=%palss(d1,s2) calcule la mise en parallele d'une matrice de polynomes //d1 et d'un systeme lineaire decrit par sa representation d'etat s2. //Le systeme resultant admet pour sortie la somme des sorties de s1 et //d2. y= s1*u+d2*u //Cette macro correspond a l'operation s=d1+s2 //! // origine ...
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//Chapter 8 //Example 8-10 //ProbOnWheatstoneBridge //Page 232, Figure 8-12 clear;clc; E = 1 ; DR = 0.001 ; R = 120 ; //Resistance in Ohm Vout = (E*DR)/(4*R) ; printf ( "\n\n Output of the Bridge = %.9f V ", Vout )
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errcatch(-1,"stop");mode(2);//6.2 ; r=600; s=1000; El=500*30/50; l=450+El; x=r*l/s; printf("Position of the fault=%.1f m",x) exit();
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//Engineering and Chemical Thermodynamics //Example 9.2 //Page no :444 clear ; clc ; //Given del_gf_0_CO2 = -394.36 ; //[kJ/mol],From Appendix A.3 del_gf_0_H2 = 0 ; //[kJ/mol],From Appendix A.3 del_gf_0_H2O = -228.57 ; //[kJ/mol],From Appendix A.3 del_gf_0_CH3OH = -161.96 ; //[kJ/mol],From Appendix A.3 n_CO...
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// problem 6.10 d1=0.15 d2=0.1 Q=0.03 a1=3.142*d1*d1/4 a2=3.142*d2*d2/4 V1=Q/a1 V2=Q/a2 c=0.6 g=9.81 dz=(V2*V2/(2*g))-(V1*V1/(2*g))+(V2*V2/(2*g))*((1/c-1)^2) w=9810 dp=dz*w disp(dp,"pressure loss across the contraction in N/m2")
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//Problem 2.16: Electrical equipment in an office takes a current of 13 A from a 240 V supply. Estimate the cost per week of electricity if the equipment is used for 30 hours each week and 1 kWh of energy costs 7p? //initializing the variables: V = 240; // in Volts I = 13; // in ampere t = 30; // in hours p = 7;...
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function [bool,inter] = intersectSetIntervals(intrvSet) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku University //Description: // //INPUT //intrvSet : the cell containing the intervals for each leg //OUTPUT //inter: matrix of intervals //------------...
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clear clc disp('Ex-16.3'); k=8.62*10^-5; //various values and constants T= 1.5*10^10; delE=1.3*10^6; a= delE/(k*T); //exponent in boltzmann factor b=%e^-a; //ratio of neutron to protons r=(1/(1+b))*100; //relative number of protons printf('The percentage of protons is %.0f and neutrons is %....
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Expanding for base=27, level=3, reasons+features=base,same,similiar,evenexp norm Refined variables=x,y [0+1x,0+1y]: unknown -> [1] [0,0] x²-y³+2 ---------------- level 0 expanding queue[0]^-1,meter=[27,27]: x²-y³+2 [5+27x,0+27y]: unknown -> [1] [5,0] 10x+27x²-729y³+1 [22+27x,0+27y]: negative-1 [1] by {x=>-x-1} [5+27x,3...
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//determine the voltage gain. (c) Calculate the voltage gain using small-signalanalysis //Example 7.22 page no 220 clear clc Vpp=300 //V Vgq=4 //V Rl=11.6*10^3 //Ω Vpm=34 //V Vgm=2 Av=-(2*Vpm/2*Vgm) dvp=202-168 dip=(15-8)*10^-3 r...
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clc mo = 9.1*10^-31 disp("mo = "+string(mo)+"kg") //initializing value of mass of electron me = 0.067*mo disp("me* = "+string(me)+"kg") //initializing value of effective mass of GaAs kbT = 0.026 disp("kbT = "+string(kbT)+"eV/K") //initializing value of kbT at 300K ml = 0.98*mo disp("ml* = "+string(ml)+"kg") //i...
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//Exa 10.4 clc; clear; close; //given data format('v',9); d=3;// in mm d=d*10^-3;// in meter T=25;// in °C T=T+273;// in K D= 0.4*10^-4;// in m^2/s R= 8314; P_A1=1;// in atm P_A1=P_A1*10^5;// in w/m^2 P_A2=0; C_A2=0; x2= 15;// in meter x1= 0; A= %pi/4*d^2; M_A= D*A/(R*T)*(P_A1-P_A2)/(x2-x1);// in kg ...
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clear;lines(0); Plant=ssrand(1,3,5); [F,G,H,J]=abcd(Plant); nw=4;nuu=2;A=rand(nw,nw); st=maxi(real(spec(A)));A=A-st*eye(A); B=rand(nw,nuu);C=2*rand(1,nw);D=0*rand(C*B); Model=syslin('c',A,B,C,D); [L,M,T]=gfrancis(Plant,Model); norm(F*T+G*L-T*A,1) norm(H*T+J*L-C,1) norm(G*M-T*B,1) norm(J*M-D,1)
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//chapter 5 //example 5.22 //page 229 printf("\n") printf("given") Vcc=12;Ic=1.5*10^-3;Vs=5;hFE=10;Vbe=.7; Rc=Vcc/Ic Ib=Ic/hFE Rb=(Vs-Vbe)/Ib
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// HW 7 P 2---------------------- // Clear and Close Everything clear; clc; close; close; close; close; // Independent Parameters ------------------------------------------------ gamma_a = 1.4; gamma_e = 1.3; R = 287; // (j/(kg*K)) M = 1.8; P_a = 12112; // (Pa) T_a = 216.65...
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// Exa 6.9 format('v',6) clc; clear; close; // Given data h_ie = 1.5 * 10^3;// in ohm h_fe = 100; // R = R1||R2 = 20;// in k ohm R = 20 * 10^3;// in ohm R_E = 560;// in ohm R_S = 600;// in ohm Avf = (h_fe*R_E)/(h_ie+(h_fe*R_E)); VoByVs = Avf; disp(VoByVs,"The value of midband voltage gain (vo/vs) is :"); ...
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//Problem 31.02: For the a.c. network shown in Figure 31.3 determine, using mesh-current analysis, (a) the mesh currents I1 and I2 (b) the current flowing in the capacitor, and (c) the active power delivered by the 100/_0° V voltage source. //initializing the variables: rv = 100; // in volts thetav = 0; // in degr...
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clc //initialisation of variables f= 0.006 l= 2600 //ft Q= sqrt(5040) //ft^3 g= 32.2 //ft/sec^2 hf= 57.5 //ft //CALCULATIONS d= ((32*f*l*Q^2)/(%pi^2*g*hf))^(1/5)*12.11 //RESULTS printf ('diameter of the pipe= %.1f in',d)
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function [output, impdata ] = pid(varargin) [lhs,rhs] = argn(0) // disp(rhs) // disp(lhs) s = poly(0,'s') z = poly(0,'z') pid1 = []; integral_data = []; diff_data = []; pid_function = []; store_data = []; //__________________________________...
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//find clc //solution //given d=0.06//m l=0.09//m N=450//rpm Z=0.06//kg/m/s c=0.1 S=14.3*10^6 p=(Z*N)*(d*1000/c)^2/S//N/mm^2 printf("bearing pressure is,%f N/mm^2",p) W=p*l*d*10^6//N printf("safe load is ,%f N\n",W)
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//Introduction to Fiber Optics by A. Ghatak and K. Thyagarajan, Cambridge, New Delhi, 1999 //Example 12.1 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given lambda=0.8e-6;//wavelength of light in m n=3.5;//refractive index of Si e=1.6e-19;//electronic charge in C h=6.626e-34;//Planck's constant in...
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function [res,ver] = kiks_checkversion() // Ouput variables initialisation (not found in input variables) res=[]; ver=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // ...
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//[s]=%lssfr(s1,s2) [s1,s2]=sysconv(s1,s2);s=[s1;s2]; //end
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//check o/p when more than 2 i/p args are passed to the function k = [0.3090 0.9800 0.0031 0.0082 -0.0082]; r0 = 0.1; a = rc2ac(k,r0,0.2); disp(a); //output // !--error 58 //Wrong number of input arguments.at line 4 of exec file called by : //lbox Test/rc2ac/rc2ac10.sce', -1
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/* * By: Jatin Kumar Mandav * * Euler's Method: Is a first-order numerical procedure for solving * Ordinary Differential Equations with a given initial value. * It is the simplest Runge-Kutta Method * * Runge-Kutta 4th Order Method: is a nmerial technique used to * solve Ordinary...
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//----------------------------------------------- // Algorítimo FOCA responsável pela otimização na // corrente injetada na rede distribuição com con- // trole de tensão. // Projeto de Pesquisa FAPESP. // Projeto número: #2019/24128-2. // @date 01/07/2020. // @author Higor de Paula Kolecha. // @author Adolfo Blengini N...
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//Determine ABCD constant and sending end power factor clear; clc; //soltion //FUNCTIONS function [z]=rxr(A,B)//Function for the multiplication in rectangular form z(1)=A(1)*B(1) z(2)=A(2)+B(2) endfunction function [z]=rdr(A,B)//Function for the division in rectangular form z(1)=A(1)/B(1) ...
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function a=%r_r_s(a,b) // a/b a rational matrix, b scalar matrix //! // Copyright INRIA if size(b,'*')==0 then a=[],return,end [num,den]=a(2:3); [ma,na]=size(num); [mb,nb]=size(b); if mb*nb==1 then a(2)=a(2)/b, if ma==-1|mb==-1 then a(3)=a(3)*eye,end return, end na=abs(na);ma=abs(ma) mb=abs(mb);nb=abs(nb) if na=...
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clc; clear; close; Cin=1; a=8; b=64; LEinv=1; //solving without sideload 'a' SE=(LEinv*b/Cin)^(1/3); y=LEinv*b/SE; mprintf('WITHOUT SIDELOAD'); disp(y,'Y='); x=LEinv*y/SE; disp(x,'X='); w=LEinv*x/SE; disp(w,'W='); //adding sideload by removing gates beyond sideload sideload_c=y+a; SE1=(LEinv*sideload_...
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function [vp,vecp, kk]= puissiterSDP(A,x,N,tol) N=30 // N = input("Nombre maximale d itérations ?"); p = find(abs(x)==norm(x,%inf),1) //disp (p) //disp(x) x=x/x(p,1) //disp(x) for kk = 2:N y = A*x //disp (x) mu=y(p,1) Norm = norm(y,%inf) p = find(abs(y)==norm(y,%inf),1) if abs(mu) < tol then //disp ("0 es...
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// Given:- T1 = 480.0 // temperature of steam entering the turbine in degree celcius p1 = 8.0 // pressure of steam entering the turbine in MPa Pcond = 0.008 ...
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//pathname=get_absolute_file_path('8.19.sce') //filename=pathname+filesep()+'8.19-data.sci' //exec(filename) //Turbine efficiency: nt=0.85 //Generator efficiency: ng=0.90 //Mechanical efficiency: nm=0.95 //Specific heat of water: Cpw=4.18 //From steam tables: h1=3450.02 //kJ/kg s1=6.6923 //kJ/kg.K h3=3576...
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// to find the maximum and minimum output voltages in the fig 16-8(b) // example 16-2 in page 428 clc; //Data given Vz=6; R=1000*[0 5.6 5.6 3];// zener voltage and the resistance values A=['when the moving contact is at the bottom of R4' '0' '0' 'when the moving contact is at the top of R4']; //calculation for n...
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// 08.08.22 // 09.10.27 function Out=Phsrawparadata(Fdata) Out=Facesdata(Fdata,'rawpara') endfunction
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clear all; clc; disp("Scilab Code Ex 4.11 : ") //Given: area_sleeve = 600*10^-6; //m^2 area_bolt = 400*10^-6; //m^2 T1 = 15; //degree celcius T2 = 80; //degree celcius alpha_bolt = 12*10^-6; //per degree celcius alpha_sleeve = 23*10^-6; //per degree celcius l = 0.15; //m E_bolt = 200*10^9; //N/m^2 E_sle...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_SSYS.sci"); codeblock readtextfile(ScriptFilePath+"\_SUB\_PlanetariumTools.sci"); codeblock readtextfile(ScriptFilePath+"\_SUB\_Figure.sci"); ##########################################################################################...
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// Exa 3.5 clc; clear; close; // Given data P1 = 1.1;// in MN/m^2 P1 = P1 * 10^6;// in N/m^2 V1 = 1.5;// in m^3 V2 = 7.5;// in m^3 P2 = (P1*V1)/V2;// in kN/m^2 P2 = P2 * 10^-6;// in MN/m^2 P2 = P2 * 10^3;// in kN/m^2 disp(P2,"The final pressure in kN/m^2 is"); W = P1*V1*log(V2/V1);// in J W = W * 10^-3;//...
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// Example 9.3;//responsivity clc; clear; close; E=0.75;//energy gap in electron volt C=3*10^8;//SPEED of light in meter per second n=0.60;//quantum efficiency ht=6.62*10^-34;//plank constt. h=((ht*C)/(E*1.6*10^-19))*10^9;//wavelength in nano meter R=((n*h)/1248);//responsivity disp(R,"Responsivity is in ampe...
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Name=Skiing Aimer 50 Targets v2 PlayerCharacters=Player BotCharacters=target.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.bot;TileFrenzy Sphere.b...
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# camera: eye, center, up, fovy, width, height camera 2 2 -10 -0.3 0.5 0 0 1 0 45 1024 1024 # recursion depth depth 5 # background color background 0 0 0 # global ambient light ambience 0.0 0.0 0.0 # light: position and color light 10 10 -5 0.9 0.9 0.9 light -5 3 -5 0.4 0.4 0.4 # spheres: center, ...
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//Chapter-1,Example1_1,pg 1_17 Erms=10 Ep=sqrt(2)*Erms Eav=0.6*Ep E=Eav/2 Edc=0.45*Erms Idc=1*10^-3 Rm=200 Rs=(Edc/Idc)-Rm printf("required multiplier resistance") printf("Rs=%.2f ohm \n",Rs )
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clc //Chapter1 //Ex_1.3 //Given R=8.314 // in J/mol/K M_at=63.6 //in g/mol //Acc. to Dulong -Petit rule Cm=3R for NA atoms C_gram=3*R/M_at disp(C_gram,"Heat Capacity of copper per unit gram in J/g/K is")
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// Example 8.16, page no-220 clear clc d=10500//density avg=6.022*10^26 awt=107.9 n=d*avg/awt//per cubic m h=6.62*10^-34//Js m=9.1*10^-31//Kg e=1.6*10^-19//C ef=((3*n/(8*%pi))^(2/3))*((h^2)/(2*m)) ef=ef/e printf("The Fermi energy for given metal is %.2f eV ",ef)
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<scenario name="Test Scenario"> <objective type="Reach" string="Get to the point"> <checkpoint x="40" y="40" z="0"/> <enemyspawn type="CAamu" amount="69" x="0" y="0"/> </objective> <objective type="Survival" string="Remain alive for {0}"> <timer time="240"/> <enemyspawn type="CAamu" amount="69" x="0" y="0"/> ...
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clc // //Variable declaration P = 120 //Maximum allowable tension force s = 175 //Maximum allowable stress t = 100 //Maximum allowable stress Sb = 350 ...
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function x = invmulaw(y,mu) //Non-linear Quantization //invmulaw: inverse mulaw nonlinear quantization //x = output vector //y = input vector (using mulaw nonlinear comression) x = (((1+mu).^(abs(y))-1)./mu) endfunction
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clc;clear; //Example 12.2 //calculation of natural frequency //given values t=5.5*10^-3;//thickness in m d=2.65*10^3;//density in kg/m^3 Y=8*10^10;//Young's modulus in N/m^2 //calculation f=(sqrt(Y/d))/(2*t);//frequency in hertz disp(f*10^-3,'the natural frequency(in kHz) is');
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sce
EX19.sce
// Example 10.19: Approximate value of fH clc, clear btaf=150; VA=120; // in volts fT=400e6; // in hertz C_mu=0.5e-12; // in farads ICQ=100e-6; // in amperes RS=50e3; // in ohms RC=250e3; // in ohms VT=25e-3; // Voltage equivalent to temperatue at room temperature in volts gm=ICQ/VT; // in mho r_pi=btaf/gm; ...