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// Scilab code Exa18.16 : : Page-768 (2011) clc; clear; phi = 45*%pi/180; // Phase difference Cross_sec_ratio = 1/4*(5+4*cos(phi))/(1-cos(phi)); // Cross section ratio printf("\nThe cross section ratio : %4.2f", Cross_sec_ratio); // Result
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function y = qfunc(x) y = 0.5*erfc(x/sqrt(2)); endfunction
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clc T=300//K a=5.43*10**-8//meter w=28.09//g/mol..atomic weight A=6.02*10^23 //atoms/mol....Avogadro's no. s=8/a^3 disp(s,"atoms per unit cell in atoms/cm^3 is") d=s*w/A disp(d,"density in g/cm^3 is")
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exec("swigtest.start", -1); foo_ptr = Foo_ptr_getPtr(); foo = Foo_ptr___deref__(foo_ptr); checkequal(Foo_getVal(foo), 17, "Foo_getVal(p)"); foo_ptr = Foo_ptr_getConstPtr(); foo = Foo_ptr___deref__(foo_ptr); checkequal(Foo_getVal(foo), 17, "Foo_getVal(p)"); exec("swigtest.quit", -1);
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clear ; clc; printf("\t Example 11.14\n"); T1=325; //temp. of helium-water tube,K l=0.2; //length of tube,m x=0.01; // mole fraction of water //the vapor pressure of the liquid water is approximately the saturation pressure at the water temp. p=1.341*10000 ; //vapor pressure using ste...
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clc //initialisation of variables w= 62.4 //lbsec/ft^3 l= 2 //miles v= 4 //ft/sec g= 32.2 //ft/sec^2 t= 20 //sec t1= 1 //sec //CALCULATIONS P= w*l*5280*v/(g*t) P1= w*l*5280*v/(g*t1) //RESULTS printf (' Rise in pressure behind the valve = %.f Lb/ft^2',P) printf (' \n Rise in pressure behind the valve = %....
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/* Questionaire created by optica toolkit Date: Fri Feb 28 10:22:06 1997 */ question(1, 'pre 1', 'Waar raakt de lichtstraal de hoofdas als we de lens vervangen door een platbolle?', [ 'dichterbij de lens', 'verder van de lens vandaan', 'plaats blijft hetzelfde' ], state(state, '', [ m1 = l...
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Name=Snake Tiles Mini PlayerCharacters=STM Challenger BotCharacters=STM Target 01.bot;STM Target 02.bot;STM Target 03.bot;STM Target 04.bot;STM Target 05.bot;STM Target 06.bot;STM Target 07.bot;STM Target 08.bot;STM Target 09.bot;STM Target 10.bot;STM Target 11.bot;STM Target 12.bot;STM Target 13.bot;STM Target 14.bo...
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//Example 27_5 clc(); clear; //To find how much of the orignal I will still present d1=20 //Units in mg d2=d1/2 //Units in mg d3=d2/2 //Units in mg d4=d3/2 //Units in mg d5=d4/2 //Units in mg d6=d5/2 //Units in mg d7=d6/2 //Units in mg printf("After 48 days onl...
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2 3 100 a a 3 100 a b ~~~~~~~~~~~~~~~~~~~~~~~~~~ 26 52
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//Initilization of variables m=200 //kg g=9.8 //m/s^2 r=1.2 //m F1=1000 //N F2=1400 //N //Calculations N=m*g //N I=(2/5)*(m)*r^2 //kg-m^2 //Using equations of motion //Solving for F and alpha using matrix method //Applying equations of motion A=[1,-m;-r,-I/r] B=[F1-F2;F1*r] C=inv(A)*B //Storing values ...
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// To find the resistance,capacitance and dissipation factors // example 8-4 in page 204 clc; //Given Data f=100;// frequency in Hz C1=0.1e-6;// satndard capacitance in farad R=[375e+3 0 10e+3 14.7e+3];// resistances R1,R3 and R4 values in ohms as R2 is not used it is take as 0 for convinence //calculation Cp=C...
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//Initilization of variables mb=0.06 //kg vb=500 //m/s mblock=5 //kg vblock=30 //m/s //Calculations //Applying conservation of momentum v=(mb*vb+mblock*vblock)/(mb+mblock) //m/s //Result clc printf('The speed of the system is %f m/s',v)
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clc; Hfe=200; re=22.7; R1=10000; R2=2200; Req=(R1*R2)/(R1+R2); X1=Hfe*re; ZinBJT=(Req*X1)/(Req+X1); ZinJFET=(R1*R2)/(R1+R2); disp('kOhm',ZinBJT/1000,"ZinBJT=")//The answers vary due to round off error disp('kOhm',ZinJFET/1000,"ZinJFET=")//The answers vary due to round off error
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// FUNDAMENTALS OF ELECTICAL MACHINES // M.A.SALAM // NAROSA PUBLISHING HOUSE // SECOND EDITION // Chapter 2 : BESICS OF MAGNETIC CIRCUITS // Example : 2.4 clc;clear; // clears the console and command history // Given data N = 6 // number of turns I =3 // current in A flux = 0.056 ...
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/////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Date: June 2010 // Description: find all the combinations of given number of indices // // Copyright (C) 2009-2010 OpenPR // All rights reserved. // // Redistribution and use in source and binary forms, with or ...
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clc clear printf("Example 9.10 | Page number 280 \n\n"); //Part(a) Find molar mass and gas constant //Part(b) Find mole fractions, partial fractions and partial volumes //Given m = 1.9 //kg T = 273+20 //K p = 150e3 //Pa yO2 = 0.1 //mass fraction of O2 yN2 = 0.75 //mass fraction of N2 yCO2 = 0.12 //mass fract...
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errcatch(-1,"stop");mode(2);//Ex2_17 L1 = 10*10^-3 L2 = 15*10^-3 LT = L1 + L2 disp("L1 = "+string(L1)+"H")//inductance of coil 1 disp("L2 = "+string(L2)+"H")//inductance of coil 2 disp("LT = L1+L2 = "+string(LT)+"H")//series inductance exit();
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clear; clc; printf("\t Example 3.3\n"); // a is CO2 and b is water p=2; //total pressure at 1 in atm pa1=0.2*10^5; //pressure of CO2 at pt 1 in atm pa2=0; //pressure of CO2 at pt 2 is 0 since air is pure ya1=0.1; //mole fraction of CO2 at 1 is 0.2/2 ya2=0; ...
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// vim: set tw=90 sw=2 ts=2 sts=2: // -*- fill-column: 90 -*- // // Make sure v is a column vector // function r = vect_to_col(v) [m,n] = size(v); r = v if m==1 && n>1 then r = v'; end endfunction // // Make sure v is a row vector // function r = vect_to_row(v) [m,n] = size(v); r = v if n==1 && m>1 then...
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//consider the combustion chamber condition as reservoir Po=20*1.01*10^5;//combustion chamber pressure in N/m^2 To=3144;//combustion chamber temperature in Kelvin R=378;//gas constant for mixture of kerosene and oxygen y=1.26;//specific heat ratio Pe=1*1.01*10^5//pressure at exit of rocket Nozzle in N/m^2 At=0.1;...
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//poles and zeroes s=%s sys=syslin('c',1/((2*s+1)*(1+5*s)*(s))) plzr(sys)
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// **** Purpose **** // gnerate a quantum mechanical rotation matrix // **** Variables **** // [J]: 1x1, integer or half-integer // <= the total angular momentum // [Euler_angles]: 1x3, real // <= Euler angles // [basis]: 1x1, char, 's'(shperical)or 'c'(cubic), default='s' // <= the output basis // [out_format]: 1x1, '...
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// This GUI file is generated by guibuilder version 4.2.1 ////////// f=figure('figure_position',[-8,32],'figure_size',[1382,744],'auto_resize','on','background',[33],'figure_name','Figure n°%d','dockable','off','infobar_visible','off','toolbar_visible','off','menubar_visible','off','default_axes','on','visible','off');...
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// Scilab code Ex4.33: : Pg:182 (2008) clc;clear; Lambda = 5.46e-05; // Wavelength of light, cm n = 12; // Number of fringes d = 0.40; // Spacing between 12 fringes, cm omega = d/n; // Fringe width, cm // Since fringe width in air wedge for normal incidence is given by omega = Lambda/2*theta. On solvi...
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//Exa 4.1 clc; clear; close; //Given data : f=50;//Hz d=1*100;//cm r=1.25/2;//cm r_dash=r*0.7788;//cm L=0.4*log(d/r_dash);//mH disp(L,"Loop inductance per km(mH)"); XL=2*%pi*f*L*10^-3;//ohm/Km disp(XL,"Reactance of transmission line(ohm/km)");
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clear clc //Example 8.4 REYNOLDS-NUMBER SIMILITUDE //p-prototype, m-model Vp=10; //speed[m/s] //Reynolds-number similitude, Rem=Rep //Vm*Lm/vm=Vp*Lp/vp //vm=vp vmp=1; //vmp=vm/vp Lmp=1/10; //Lmp=Lm/Lp Vm=Vp*vmp/Lmp //speed[m/s] printf("\n The air speed in the wind tunnel for scaled model and dynamically sim...
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//Example 7.17 clear; clc; //Given R=8.314;//gas constant in J K^-1 mol^-1 delTf=0.52;//Freezing temperature depression in K Kf=12;//molal freezing point depression constant of the solvent K mol^-1 kg w2=0.9;//mass of solute in g w1=180;//mass of solvent in g To=282;//freezing point of the solvent in K //...
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//Chapter-2, Example 2.1, Page 2.4 //============================================================================= clc clear //INPUT DATA V1=1000;//Voltage in primary circuit in V V2=100;//Voltage in secondary ciricut in V N2=60;//Number of turns in secondary R=10000;//Rating of transformer in VA //CALCUL...
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function A=row_swap(A,r,s) // Effetta lo swap della riga r con la riga s // nella matrice A // TODO Aggiungere controllo su validita' indici di riga e colonna tmp=A(r,:) A(r,:)=A(s,:) A(s,:)=tmp endfunction
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clc //initialisation of variables a=5//cm b=25//cm s=8.5//bars r=40//cpm T=460//F p2=77//ft p1=68//ft T1=273//F T2=273//F t=20//c d=1.01*10^5//N/m^2 q2=61024//in^3/m^3 q3=1/1728//ft^3/in^3 p=14.7//psi //CALCULATIONS Q=%pi*((a*10^-2)^2/4)*(b*10^-2)*(r)*1000//m^3/min Q2=((s*10^5+d)*Q)/d*0.001//m^3/min ...
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blade petiole pith female fruit male fruit ring 0.16689 0.05345 0.08310 0.11970 0.16835 0.23342 0.05259 0.01685 0.02619 0.03772 0.05306 0.07356 0.56880 0.02230 0.01416 0.01250 0.01339 0.01616 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00000 0.00850 0.008...
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// Cette fonction renvoie 1 si angle(Ox,OM)<angle(Ox,OP) ou angle(Ox,OM) = angle(Ox,OP) et norme(OM) <= norme(OP) test // renvoie 0 sinon. function [X]=ordre_pol(O,M,P) // Construction de la matrice qui nous permet de déterminer l'ordre polaire mat=zeros(3,3); mat(1,1)=1 mat(1,2)=1 mat(1,3)=1 mat(2,1)=O(1); ...
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format(12) function dy = f(t,y) dy = y - t^2 + 1 return dy endfunction function yt = y(t) yt = (t+1)^2 -0.5*%e^t return yt endfunction clc disp("> Una aproximación a la solución de la ecuación diferencial") disp(" dy = y - t^2 + 1 usando el método de Euler es: ") E = UN_ecua_dif_...
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//Example 11.6 clc; clear; close; format('v',6); //Given data : Cd=0.62;//constant H=200/1000;//meter theta=90;//degree g=9.81;//constant Q=8/15*Cd*sqrt(2*g)*tand(theta/2)*H^(5/2);//m^3/s Q=Q*1000*60;//litres/minute disp(Q,"Discharge in litres/minute : ");
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@relation yeast-5 @attribute Mcg real [0.11, 1.0] @attribute Gvh real [0.13, 1.0] @attribute Alm real [0.21, 1.0] @attribute Mit real [0.0, 1.0] @attribute Erl real [0.5, 1.0] @attribute Pox real [0.0, 0.83] @attribute Vac real [0.0, 0.73] @attribute Nuc real [0.0, 1.0] @attribute Class {MIT, NUC, CYT, ME1, ME2, ME3, E...
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//Example 1.29 // output clc; clear; close; //given data : Iin=0.35; // sinusoidl input relation t=0.3; // sec w=25; // rad/sec a=1/sqrt(1+(w*t)^2); Io=Iin*a; pi=atand(w*t); disp(pi,"the phase shift,pi(celcius)") disp("the output expression,Io = 0.0462sin(25t-82.4)")
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// Exa 1.18 clc; clear; close; // Given data miu= 35.2*10^-4;// in m^2/vs n=7.87*10^28; e= 1.6*10^-19;// in C sigma= n*e*miu;// in s/m disp(sigma,"Conductivity in s/m is : ")
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clc //initialisation of variables pN2O4= 1 //atm pNO2= 0.141 //atm R= 1.987 //cal mole^-1 deg^-1 T= 25 //C //CALCULATIONS dG= -R*2.303*(273.1+T)*log10(pN2O4/pNO2) //RESULTS printf ('dG= %.f cal ',dG)
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clc clear //INPUT L=1.2;//Length of the satillite in m v=0.98*3*10^8;//Speed of the satillite in m/s c=3*10^8;//Speed of light in m s^-1 //CALCULATIONS l=L*sqrt(1-(v^2/c^2))//The contracted length in m //OUTPUT mprintf('The contracted length is %3.4f m',l)
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//Exa 11.16 clc; clear; close; //Given data : Vs=11;//kV f=50;//Hz l=2.5*1000;//m C_all3=1.8;//micro F Cdash=1.5;//micro F(2*Cc+Cs) Cs=C_all3/3;//micro F Cc=(Cdash-Cs)/2;//micro F C_N=3*Cc+Cs;//micro F disp(C_N,"Capacitance of core to neutral(micro F)"); C_2=C_N/2;//micro F disp(C_2,"Capacitance between ...
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Expanding for base=2, level=4, reasons+features=same Refined variables=a,b,c,d,w,x,y,z ReasonFactory: same, code="same" SameReason.consider( "a²+b²-c²-d²; -a+w²; -b+x²; -c+y²; -d+z²", "a²+b²-c²-d²; -a+4w²; -b+4x²; -c+4y²; -d+4z²") = same a²+b²-c²-d²; -a+4w²; -b+4x²; -c+4y²; -d+4z² map {w=>w/2,x=>x/2,y=>y/2,z=>z/2}...
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// Example 6.2 // Determine (a) Capacitance required in series with the auxillary winding // in order to obtain a 90 degree phase displacement between the current in // the main winding and the current in the auxillary winding at locked rotor // (b) Locked rotor torque in terms of the machine constant // Page...
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//Chapter-11,Example 1,Page 275 clc(); close(); M =1000 //mass of alloy m_Cd= 0.25*M //25% of Cd in alloy //since in the eutectic system, 40% is Cd and 60% is Bi //corresponding to m_Cd Cd the content of Bi in eutectic is m_Bi = m_Cd*60/40 m= m_Cd+m_Bi printf('the mass of eutectic in 1 kg ...
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// cov. factor calculation example for multivariate normal distribution // N = 1500 clear; clc; stacksize('max'); rand("seed", 1234512345); RDATA = fscanfMat("D:\other\exp_rel\ACFDATA.txt"); i0 = 11; // alpha = 1. //i0 = 2; // alpha = 0.5 R = RDATA(i0, :); //kS = KDATA(i0, 2); alpha = R(1); R = R(2 : length(R)...
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clc clear //Input data r=20//Compression ratio c=5//Cut off at 5% dc=1//Specific heat at constant volume increases by 1% Cv=0.171//pecific heat at constant volume in kJ/kg.K R=29.3//Characteristic gas constant in mkg/kg/degree C k=1.95//k can be obtained from relation de/e=-dcv/cv*(1-e/e)*(g-1)*((1/g)+ln(r)-(k^...
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//Variable declaration: //From example 16.22: t2 = 75.0 //Temperature of water leaving the shell ( F) t1 = 35.0 //Temperature of water entering the shell ( F) T2 = 75.0 //Temperature of oil leaving the tube ( F) T1 = 110.0 //Temperat...
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//Programming Example 8.7 //Program to calculate successive fibonacci numbers funcprot(0); function[]= main() printf("How many fibonacci numbers?"); n=scanf("%d"); first_call="true"; for count=1:n printf("\ni = %2d F = %1d", count, fibonacci(count)); first_call="false"; ...
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## Test tag comment handling read <<EOF blob mark :1 data 23 This is a sample file. reset refs/heads/master commit refs/heads/master mark :2 committer esr <esr> 1322671432 +0000 data 16 First revision. M 100644 :1 README blob mark :3 data 68 This is a sample file. This is our first line of modified content. commit ...
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//Computation of Mutual and self inducatances clc; clear; n1=600; i1=2.5; flux1=0.4*(10^-3); flux2=0.8*(10^-3); n2=2000; tflux=flux1+flux2; L1=n1*tflux/i1; K=flux2/tflux; M=n2*flux2/i1; L2=((M/K)^2)/L1; disp('H',L1,'The self inductance of coil 1= ') disp('H',L2,'The self inductance of coil 2...
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// Copyright (C) 2012 - Prateek Papriwal // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCI...
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//Adapted from Stack Exchange // Signal Model DeltaT = 0.1; F = [1 DeltaT; 0 1]; G = [DeltaT^2; DeltaT]; H = [1 0]; x0 = [0;0]; sigma_a = 75; Q = sigma_a^2; R = 75; N = 1000; a = rand(1,N,"normal")*sigma_a; // Kalman Filter p0 = 100*eye(2,2); xx(:,1) = x0; pp = p0; pp_norm(1) = norm(pp); ...
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mode(2);errcatch(-1,"stop");driver("GIF");//Chapter 10, Problem 2, figure 10.6 clc; I=0.008; //total circuit current ra=10; //resistance of instrument V=100; //total p.d Va=I*ra; //calculating voltage across moving coil instrument ...
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//============================================================================== // chapter 5 example 25 clc; clear; //input data M1 = 202; //mass number M2 = 200; // mass number Tc1 = 4.153; // temperature in K alpha = 0.5; //formula //m^alpha*(Tc)...
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// Exa 1.2 clc; clear; close; // Given data T1 = 25;// in degree C T2 = 100;// in degree C del_T = T2-T1;// in degree C I_S = (2)^7 *5;// in nA I_S = (1.07)^5*I_S;// in nA disp(round(I_S),"The saturation current at 100 degree C in nA is");
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// Example 4.9;parameter of primary side ,regulation and efficiency clc; close; clear; //given format('v',6) po=100;//watts v1=200;//volts io=1;//amperes ocpf=po/(v1*io);//open circuit power factor sinpf=sqrt(1-ocpf^2);// im=io*sinpf;//in amperes iw=io*ocpf;//current in amperes rm=v1/iw;//ohms xm=v1/im;//in ohms vs=15;...
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function result= hyper(N, M, n, i) result = factorial(N)*factorial(M)*factorial(n)*factorial(N+M-n)/(factorial(i)*factorial(N-i)*factorial(n-i)*factorial(M-n+i)*factorial(N+M)); endfunction r= 50; n=100; X=25; disp(r*n/X , "Estimate of the number of animals in the region is")
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 26 // read it as example 25 in the book on page 2.79 disp("CHAPTER 2"); disp("EXAMPLE 26"); //VARIABLE INITIALIZATION A=100 //Amplitude in Amps f=25 //frquency in Hz a1=20 ...
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//Example 2.29,Convolution using Tabular method. clear; clc; x=[-2 0 1 -1 3]; h=[1 2 0 -1]; q=length(x); w=length(h); z=q+w-1; y0=0; for i=1:z; y(i)=0; for k=1:i; if k>q x(k)=0; else if (i-k+1)>w h(i-k+1)=0; else y(i)= y(i) + x(k)*...
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p1=60; t=8; p2=9; amt=20; cost=0.08; disp("Part a"); total=365*t*p1*cost/1000; disp("Cost (in $) to operate the incandescent lamp for a year is"); disp(total); disp("Part b"); total2=365*t*p2*cost/1000; disp("Cost (in $ )to operate the fluorescent lamp for a year is"); disp(total2); disp("Part c"); sav=tota...
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// example 4.9 // caption :obtain the polinomial of degree 2 x=[0 1 3]; f=[1 3 55]; n=2; // 1) iterated interpolation; [L012,L02,L01]=iteratedinterpol (x,f,n) // 2) newton divided diffrences interpolation; P2=NDDinterpol2 (x,f)
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//Example sec 5.2.2 c //Routh array in scilab clear;clc; xdel(winsid()); s=poly(0,'s') p=poly(0,'p') C=s^5+s^4+2*s^3+2*s^2+3*s+5 //substituting "s=(1/p)" in B //The resulting characteristic equation is C1=5*p^5+3*p^4+2*p^3+2*p^2+p+1 routh_t(C1)
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//Chapter-3,Example3_17_17,pg 3-41 n=50 //frequency V=10^-3 //volume of the specimen //Area of B-H loop A=0.5*10^3*1 P=n*V*A printf("Hysteresis power loss =") disp(P) printf("Watt")
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load ALU.hdl, output-file ALU.out, output-list X%B1.8.1 Y%B1.8.1 opcode%B3.3.3 US Z%B1.8.1 OF%B3.1.3 EQ%B3.1.3; set X %B00000100, set Y %B00000100, set US 0, set opcode %B000, eval, output; set X %B11110000, set Y %B00111100, set US 0, set opcode %B000, eval, output; set X %B00000100, set Y ...
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// Regelungstechnik Versuch 3 // Boris: cd "/Users/borishenckell/Documents/eclipse workspace/PR_Regelungsrtechnik_-_Versuch_3/PR Regelungsrechnik - Versuch 3" // Dirk: //cd "/media/daten/workspace/PR_Regelungsrechnik_-_Versuch_3/PR Regelungsrechnik - Versuch 3/Scilab/" s = poly(0, 's'); Kpid = 1.355; // ...
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exec("simulation_a.sci", 0); for i=1:n y(i) = stdev(vectorx(:,i)).^2 + stdev(vectory(:,i).^2).^(1/2); x(i) = i; end plot2d(x, y) xgrid(16) xtitle('Aleksander Skup, N = 1000','i-ty krok', 'σr położenia cząstek');
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clc //Initialization of variables m1=5 m2=2 cp1=0.248 cp2=0.203 T11=300 //F T12=100 //F P=10 //psia Pi=20 //psia Pf=15 //psia //calculations T2=(m1*cp1*T11 + m2*cp2*T12)/(m1*cp1+m2*cp2) n1=m1/28 n2=m2/44 n=n1+n2 P1=P*n1/n P2=P*n2/n dS=m2*(cp2*log((T2+460)/(T12+460)) - 35.1/778 *log(P2/Pi)) +m2*(cp2*lo...
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// ============================================================================= // gfx4scilab - drawing // dgerod@xyz-lab.org.es // ============================================================================= function [FrustCone] = dw_FrustCone_create(h, rb, rt, T) FrustCone = 0; if rt_ishomog( T ...
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; Directed test cases for log2 ; ; Copyright (c) 2018, Arm Limited. ; SPDX-License-Identifier: Apache-2.0 ; ; Licensed under the Apache License, Version 2.0 (the "License"); ; you may not use this file except in compliance with the License. ; You may obtain a copy of the License at ; ; http://www.apache.org/license...
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function y=f(x) y = log(x-1) + cos(x-1) endfunction // secante(f, 1.1, 5, 0.0001) x = 1.02:0.05:5 plot(x, f(x)) // [1, 1.5] secante(f, 1.1, 2, 0.0001)
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Name=Aimbotz_R6 PlayerCharacters=csplayer BotCharacters=csbotz harmless.bot IsChallenge=true Timelimit=60.0 PlayerProfile=csplayer AddedBots=csbotz harmless.bot;csbotz harmless.bot;csbotz harmless.bot;csbotz harmless.bot;csbotz harmless.bot;csbotz harmless.bot;csbotz harmless.bot;csbotz harmless.bot;csbotz harmless.bot...
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# PowerTests test file # (c) VMA soft # Automatically generated file. Do not edit ! .path "MEE1" .testname "Examen M.E.E. 1" .domain "M.E.E." "Masurari electrice si electronice" .time 60 .random 10 .category configuratii_ao 1 .category osciloscop_esantionare 1 .category probleme_opturi 1 .category probleme_usoare 1 .c...
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//Example 6.13// a=514;//K //Kelvin //Temperature b=273;//K //Kelvin //Temperature apt=a+b mprintf("apt = %i K for eta = 10^13.4P",apt) c=696;//K //Kelvin //Temperature spt=c+b//for eta=10^7.6P mprintf("\n spt = %i K",spt) i=(10^13.4); //P //Pascal //preexponential constant j=(10^7.6);//P // Pascal //preexpone...
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function [x,h] = biseccion(f,xmin,xmax,kmax,tol) if(xmax==xmin) then disp("No se puede aplicar el metodo, intervalo=0."); return; end a=xmin; b=xmax; h=zeros(1,kmax); i=1; while(i<kmax) x=a+(b-a)/2; h(1,i)=abs(f(x)); i=i+1; if (f(x...
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[default] aws_access_key_id = accessKey2 aws_secret_access_key = secretAccessKey2
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N_ACOMPANHAMENTO = 10; //Condicao para acompanhar o erro da epoca N_QUEBRA_DE_LINHA = 50; //Condicao para inserir quebra de linha TAXA_APRENDIZAGEM = 0.2; RNA_AJUSTE_DE_PESO = 0.1; NUMERO_DE_EPOCAS = 600; MAXIMO_LINHA_ARQUIVO = 99999; // Método que retorna os coeficientes da regressao linear // // As coordenadas de en...
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//Example 2.17: Reduce expression using Boolean laws clc // Clears the console disp('(x + y)(x + y +z'') + y''') disp('=(x + y) + y''') disp('= x + (y + y'')') disp('= x + 1') disp('= 1') //the reduced expression is displayed.
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//Created by: Kartik Patel // Indian Institute of Technology, Roorkee //Date : 28 Jan, 2016 //License : Creative Commons Attribution-ShareAlike 4.0 International License function[y]=ssbmod(x, Fc, Fs, varargin) // y = ssbmod(x, Fc, Fs, init_phase, 'upper') // This function will generate the sing...
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//Example 8.3, Page Number 370 //Single mode guide dimensions clc; n1=1.48//refractive index n2=1.46//refractive index l=1*(10**-6) //Wavelength in meter //from equation 8.16 d=l*(1/(2*sqrt((n1**2)-(n2**2)))) disp("meters",d,"The Waveguide core thickness must be less than")
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clc // Given that theta = 10 // Angle in second mu = 1.4 // Refractive index of soap film Beta = 0.5 // Fringe width in cm // Sample Problem 26 on page no. 100 printf("\n # PROBLEM 26 # \n") printf("\n Standard formula used \n Beta = lambda/(2*mu*theta)\n") lambda = (2*mu*Beta*1e-2*theta*(%pi/(60*60*180))) // ...
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clc;funcprot(0);//EXAMPLE 17.3 // Initialisation of Variables Db=0.6;.....................//Diameter of the brake wheel in m d=0.026;......................//Diameter of the rope in m W=200;.......................//Dead load on the brake in N S=30;......................//Spring balance reading in N N=450;............
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function [x, sflag] = gflineq(a, b, p) // GFLINEQ finds a solution for linear equation Ax = b over a prime Galois field. // [X, SFLAG] = GFLINEQ(A, B) returns a particular solution (X) of AX=B in GF(2). // If the equation has no solution, then X is empty and SFLAG = 0 else SFLAG = 1. // // [X, SFLAG]= GFLINEQ...
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//example 11.1// clc //clears the screen// clear //clears already existing variables// for (i=0:15) disp('word number to binary address is as follows:') disp(i) //displays the word number// t=dec2bin(i); //converts it into memory address// disp(t) //displays binary address// i=i+1 end
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clear; clc; //i1=p/v //line loss=2i^2*r //vol of conductor required v1=2*l*a1 a=1/6; //a=r1/r2 b=1/a //b=a2/a2 //v2=3*l*a2+ 0.5*l*a2 //v2/v1=3.5*l*a2/2*l*a1 c=3.5/(2*b); //c=v2/v1 printf("the ratio of the volumes of the conductors is:%.2f",c);
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function [lambda,v] = Metodo_potencia_inverso(A,x0,epsilon) A = inv(A) //usamos a matriz inversa [lambda,v] = Metodo_potencia(A,x0,epsilon) //lambda é autovalor de inv(A), então 1/lambda é autovalor de A lambda = 1/lambda endfunction
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clc clear x = [1 2 3 4 5 6 7 8 9 10] y = x for i=1:length(x)-1 y(i+1) = x(length(x)-i+1) end disp("before Circular-Shift") disp(x) disp("After Circular-Shift") disp(y) z1 = fft(y) z2 = fft(x) z1_r = real(z1) z1_i = imag(z1) z2_r = real(z2) z2_i = imag(z2) subplot(221) plot2d3(z1_r) title("Z1 Real") xlabel("in...
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// Exa 4.7 clc; clear; close; format('v',8) // Given data I_E = 3;// in mA I_CO = 10;// in µA I_CO = I_CO * 10^-3;// in mA Alpha = 0.98;// unit less I_C = (Alpha*I_E) + I_CO;// in mA disp(I_C,"The collector current in mA is"); I_B = I_E - I_C;// in mA disp(I_B,"The base current in mA is");
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3_7.sci
//3.7 clc; V=20; A=20*10^-3; Rv=10*10^3*20; Rx=(V/(A-(V/Rv)))/1000; printf("The resistance=%.2f Kohm",Rx) E_total=2.5+2.5; printf("Maximum possible error=%.0f percent",E_total)
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//Example 9.3: clc; clear; close; //given data : Ih=0;//in A Vi=100;// in V Vm=200;//in V Rl=100;//in ohm theta1=asind(Vi/Vm);//firing angle in degree ca=180-theta1;//conducting angle in dehree format('v',4) disp(theta1,"(i) firing angle is ,(degree)=") format('v',5) disp(ca,"(ii) conducting angle is ,(degree)=") av=(...
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6_9.sce
clc //initialisation of variables Q= 450 //gal/min w= 6.24 //lb/ft^3 f= 0.005 l1= 1000 //ft l2= 2000 //ft r1= 1.6 r2= 4.4 r3= 0.8 r4 = 12.85 h1= 59.1 //ft h2= 40.19 //ft v= 1.2 //ft/sec f= 0.0056 l= 10 //ft //CALCULATIONS Q1= Q/(w*60) Q2= (r1+sqrt(r1^2+4*r2))/2 Q3= Q2-Q1 Q4= (-r3+sqrt(r3^2+4*r4))...
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colorRange.sci
//Fonction to isolate a specific color range //imgsrc : The source image to analyse //rmin : the minimum color //rmax : the maximum color function render=colorRange(imgsrc,rmin,rmax) //The size of the image [wd,he]=size(imgsrc); //Create an empty image render = zeros(wd,he); //For each lines for...
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exa_2_35.sce
// Exa 2.35 clc; clear; close; // Given data N_A= 4.4*10^22/10^8;// in /m^3 N_D= 10^3*N_A;// in /m^3 ni= 2.5*10^13;// /cm^3 Vt= 26;// in mV Vt= Vt*10^-3;// in V Vj= Vt*log(N_A*N_D/ni^2);// in V disp(Vj,"The junction potential in volts is : ")
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// Examle 15.6 po=5*746; // O/p power n=0.875; // Efficiency of motor at no load pin=round(po/n); // I/p power p1=pin-po; // Total losses pm=0.05*p1; // Mechanical losses pe=p1-pm; // Electrical losses pd=po+pm; //...
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3_6.sce
clc; disp("Example 3.6") pgrad= 12500; // pressure gardient in dynes/cm^3 d=0.445; // diameter in metres mew=8; // viscosity in poise Q= %pi*pgrad*d*d*d*d/(128*mew); disp(" Volumetric flow rate is "); disp(Q); disp(" cc/s");
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//Exa 6.9 clc; clear; close; //given data K=0.0278;// in W/mK rho=1.092;// in kg/m^3 miu=19.57*10^-6;// in kg/ms Cp=1007;// in kg/kg degree C epsilon=0.9; sigma=5.67*10^-8; d=75+2*25;// in mm d=d*10^-3;// in meter T_s=80;// in degree C T_infinite=20;// in degree C T_f=(T_s+T_infinite)/2;// in degree C T...
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/************************* Animations des algorithmes *************************/ N = 20; //taille du réseau T = 2; //température sur-critique pour que les algorithmes de couplage terminent J = ones(N,N,2)/T; h = zeros(N,N)/T; n1 = 10; n2 = n1 * N^2; n3 = n2; printf("Temps d''exécution :\n"); //Échantillonneur de Gib...
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//page 238 clear; close; clc; A=[1 0 1 6 2;0 1 1 0 3]; b=[8 9]'; c=[0 0 7 -1 -3]'; lb=[0 0 0 0 0]' ub=[]; [x,lagr,f]=linpro(c,A,b,lb,ub); disp(x,'New corner:'); disp(f,'Minimum cost:'); //end
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clc //Simple cycle p2=4; //bar p1=1; //bar T1=293; n_compressor=0.8; n_turbine=0.85; ratio=90; //Air Fuel ratio C=41800; //kJ/kg cp=1.024; p4=1.01; //bar p3=3.9; //bar y=1.4; e=0.72; //thermal ratio T2=T1*(p2/p1)^((y-1)/y); T2a=(T2-T1)/n_compressor + T1; T3=C/cp/(ratio+1)+471; T4=T3*(p4/p3)^((y-1)/...