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clear; clc; close; disp("Example 9.1") Tt1=1800 M1=0.55 alfa1=0 gm=1.33 Cp=1157 alfa2=60 T1=Tt1/(1+(gm-1)*M1^2/2) a1=((gm-1)*Cp*T1)^(1/2) C1=a1*M1 C2=C1/cosd(alfa2) Tt2=Tt1 T2=Tt2-C2^2/(2*Cp) a2=((gm-1)*Cp*T2)^(1/2) M2=C2/a2 Ct2=C1*tand(alfa2) r=0.35 t=0-r*Ct2 disp(C1,"(a)Inlet ve...
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//example 6.12 clear; clc; //Given: x1=0.5;//mole fraction of chloroform x2=0.5;//mole fraction of p-xylene T=298;//Temperature[K] //to find the excess volume Ve=x1*x2*[0.585+0.085*(x1-x2)-0.165*(x1-x2)^2];//Excess volume measured by using a dilatometer printf("Ve/(cm3.mol^-1) = %f ",Ve);
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clear //Given R1=15.0 // ohm R2=15.0 E=2 V=1.6 //Calculation R=R1*R2/(R1+R2) r=((E/V)-1)*R*4 //Result printf("\n Internal resisatnce of each cell is %0.3f ohm", r)
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clc; clf; clear all; s=poly(0,"s"); num1=(s^2+4*s+4); den1=(s^2+10*s+25); s1=syslin('c',num1,den1); [z,p,k]=tf2zp(s1); disp(z); disp(p); disp(k); s4=zp2tf(z,p,k,"c"); disp(s4); s5=tf2ss(s4); disp(s5);
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clc(); clear; //Given : Eg1 = 0.72; // Energy gap for Ge in eV Eg2 = 1.1; // Energy gap for Si in eV Eg3 = 1.32; // Energy gap for GaAs in eV // lambda = c/v = (c*h)/Eg or lambda(A) = 12422/Eg (eV) lambda1 = 12422/Eg1; // wavelength in A (Ge) lambda2 = 12422/Eg2; // wavelength in A (Si) lambda3 = 12422/Eg3...
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clc clear //input f=55//frequency amp=7*10^-3//amplitude m=1.2//mass //calculation e=0.5*m*4*%pi^2*f^2*amp^2//maximum pe occurs at zero position //output printf("the maximum pe is %3.3f J",e)
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clear; clc; // Stoichiometry // Chapter 4 // Material Balances involving Chemical Reaction // Example 4.14 // Page 140 printf("Example 4.14, Page 140 \n \n"); // solution // using equations of example 4.10 // soving 4.10 by linear model method M = [1 0 0 0 0 0 0 0 0 0 0 0 0 0 0;0 1 0 0 0 0 0 0 0 ...
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clc D=0.2; //m L=0.3; //m p1=1; //bar T1=300; //K R=287; r=15; y=1.4; disp("(i) Pressures and temperatures at salient points") Vs=%pi/4*D^2*L; V1=r/(r-1)*Vs; disp("V1=") disp(V1) disp("m^3") m=p1*10^5*V1/R/T1; p2=p1*r^y; disp("p2=") disp(p2) disp("bar") T2=T1*r^(y-1); disp("T2=") disp(T2)...
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clear; clc; d = 3/8;// inches n = 12;//no. of complete turns D = 4;// inches W = 50;// lb-wt N = 12*10^6;// lb/in^2 T = W*0.5*D;// lb-inches f_s = T*16/(%pi*d^3);//lb/in^2 delta = 64*W*(D^3 /8)*n/(N*d^4);// inches E = 0.5*W*delta;// inch-lbs printf('Shear stress induced is f_s = %d lb/in^2',f_s); printf('\n...
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// Demo script data = input('Name of processed dataset : ',"string") algorithm = input('Algorithm to run : ',"string") toolbox_basedir = input('Base directory for toolbox : ', "string") getd(toolbox_basedir + '/macros') machineLearn(algorithm, data, toolbox_basedir);
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// Example 3.9 // To analyze trunking efficiency capacity of sectoring and unsectoring // Page 92 clc; clear all; // Given data H=2/60; // Average call duration in hour GOS=0.01; // Probability of blocki...
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//3次系の安定余裕計算 s=%s; G=1/(s*(s^2+2*s+4)); H=20; croots=roots(denom(G*H)+numer(G*H)) sys=syslin('c',G*H); gm=g_margin(sys) pm0=p_margin(sys); if pm0 < 0 then pm = pm0+180 else pm = pm0-180 end xset("window",0);clf();bode(sys,0.1,1);
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//check o/p when 2 i/p args are passed to the function g = [0.6389 4.5989 ;0.0063 0.0163; -0.0163 0.99934]; a=0.2; k = lar2rc(g,a); disp(k); //output // !--error 58 //Wrong number of input arguments.at line 4 of exec file called by : //box Test/lar2rc/lar2rc7.sce', -1 //
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// Commande Manuelle // Maxime Touroute // Nicolas Sintes // Vincent Montalieu // Avril 2015 masse = 0.8; //kg gterre = 9.81; Te = 0.03 // 40ms // Conditions initiales theta = 60; // angle d'attaque. pi = 3.14 theta = pi * (theta) / 180 hauteur = 2; // hauteur initiale de la boule (m) v0 = 5; // m/s² epsilon = 1; /...
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// Example 4.5.a:Maximum possible optical bandwidth clc; clear; close; t=0.1*10^-6;//Time in second L=15;//Distance in km Bt=(1/(2*t))*10^-6;//Maximum possible optical bandwidth in Mega Hertz disp(Bt,"Maximum possible optical bandwidth in Mega Hertz")
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clear // // // //Variable declaration lamda=5000*10**-8 //wavelength(cm) e=1/6000 //number of lines(cm) //Calculation theta1=asin(lamda/e)*180/%pi //angle for 1st order(degrees) theta2=asin(3*lamda/e)*180/%pi //angle for 3rd order(degrees) theta=(theta2)-(theta1) ...
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//EMF and copper losses of a Shunt Motor clc; clear; V=250; I=200; Ra=0.02; // Armature Resistance Rf=50; // Field Resistance Pil=950; // Iron and frictional losses Ish=V/Rf; // Field Current Ia=Ish+I; // Armature Current Pac=(Ia^2)*Ra; // Armature copper loss Pfc=(Ish^2)*Rf;// Field copper loss P...
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function [n]=np() // Return the size of the Fortran pendulum n=1; n=fort('np',n,1,'i','sort',1); function [ydot]=npend ( t, th) // Fortran version // data r / 1.0, 1.0, 1.0, 1.0 / // data m / 1.0, 1.0, 1.0, 1.0 / // data j / 0.3, 0.3, 0.3, 0.3 / ydot=ones(6,1) ydot=fort('npend',3,1,'i',t,2,'d',th,...
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clear; clc; funcprot(0); //given data k = 1/5;//scale ratio Pm = 3;//in kW Hm = 1.8;//in m Nm = 360;//in rev/min Qm = 0.215;//in m^3/s Hp = 60;//in m n = 0.25; rho = 1000;//in kg/m^3 g = 9.81;//in m/s^2 //Calculations Np = Nm*k*(Hp/Hm)^0.5; Qp = Qm*(Nm/Np)*(1/k)^3; Pp = Pm*((Np/Nm)^3)*(1/k)^5; eff_...
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//Network Theorem 1 //page no-3.56 //example3.49 //calculation of Vth disp("Removing the variable resistor RL from the network:"); x=100; a=10; b=20; c=30; d=40; i1=x/(a+c); i2=x/(b+d); printf("\nI1 = %.1f A",i1); printf("\ni2 = %.2f A",i2); disp("Writing Vth equation,"); x=2.5; y=1.66; v=(20*y)-(10*x)...
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//Perform 4 point DFT of x(n)=(1 1 0 0) and sketch magnitude and phase spectrum clc; clear; N=4; xn=[1 1 0 0]; for k=0:1:N-1 Xk(k+1)=0; for n=0:1:N-1 Xk(k+1)=Xk(k+1)+xn(n+1)*exp(-%i*2*%pi*k*n/N); end end wk=0:1:N-1; disp(Xk,'4 point DFT of x(n)=>'); disp(abs(Xk),'magnitude of 4 point DF...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>StdProject_Diff2D Triangle Orthonormal basis P=6 Q=7</description> <executable>StdProject</executable> <parameters>-s triangle -b Ortho_A Ortho_B -o 6 6 -p 7 7 -d</parameters> <metrics> <metric type="L2" id="1"> <value tolera...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 14.2w //calculation of the elongation of the rope and corresponding change in the diameter //given data L=4.5//length(in m) of the nylon rope d=6*10^-3//diameter(in m) of the nylon rope T=100//weight(in N) of the mon...
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function [x,y,typ]=BIGSOM_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; [graphics,model...
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//example 12.2 clc; funcprot(0); Ap=%pi/4*1.75^2; q=135.6; w=0.83; FS=4; phi=36; Nq=0.21*exp(0.17*phi); Qp=Ap*q*(w*Nq-1); Qpall=Qp/FS; disp(Qpall,"allowed load in kN");
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clear; clc; printf("\nEx2.45\n"); //page no.-90 //given E=1.56;...............//energy of e ejected in eV lambda_o=2500*10^-8;..........//threshold wavelength in cm c=3*10^10;...........//speed of light in cm/sec e=1.6*10^-12;.........//charge in ergs h=6.62*10^-27;........//planck's constant in ergs-sec vo...
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// Example 1.67 There are 3 children in a family clc; clear; disp(8,"No.of sample points and sample space of 3 children in a family "); disp(4/8,"Probab. that there is not more than one girl (BBB,BBG,BGB,GBB)",3/8,"Probab. that there are exactly 2 girls (BGG,GBG,GGB)");
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//Example 5_10 clc; clear; close; format('v',6); //given data : sigma_p=3;//(ohm-cm)^-1 sigma_n=0.1;//(ohm-cm)^-1 Ln=0.15;//cm Lp=0.15;//cm e=1.6*10^-19;//C/electron mu_p=1800;//cm^2/V-s//For Ge mu_n=3800;//cm^2/V-s//For Si VT=0.026;///eV//at T=27 degree C A=1.5;//mm^2 A=A*10^-6;//m^2 b=mu_n/mu_p;//uni...
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clear; clc; // Stoichiometry // Chapter 6 // Stoichiometry and Unit Operations // Example 6.20 // Page 393 printf("Example 6.20, Page 393 \n \n"); // solution // basis 100 kmol of feed gas // using table 5.1 Sniai = 20.6*29.5909+62*28.6105+4.1*20.7723+11.1*19.2494+2.2*25.6503 Snibi = [20.6*(-5.141...
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sunoco sariful fertliser calf sahil indurani somarani nandita jababibi abdul dalasi ruocheng chinnamalai maheshprasad sahani yala najmeddin mchenry punjokhara sureshkumar jump manuel kamaldeo fram kutai snowboarding chenari psivida muchiram ratish shrikrushna sigourney mehandi wight uruguay manyara tanzania dhamendra t...
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//Example 4.11: clc; clear; close; //given data : del_ic=1;// in mA del_ib=10;// in micro-A del_Vbe=0.02;// in V del_ib=10*10^-6;// in A Rc=2;// in k-ohm Rl=10;// in k-ohm Beta=del_ic/(del_ib*10^3);// format('v',5) disp(Beta,"Current gain,Beta = ") Ri=(del_Vbe/del_ib)*10^-3; format('v',4) disp(Ri,"Input impedence,Ri(k...
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clc; //page 85 //problem 2.1 //A & B are two events occured in sample space S, where P(A) & P(B) are their corresponding probability P_S=1 //Given A&B are not mutually exclusive events, //Probability of A is 0.2 = P_A //Probability of B is 0.4 = P_B //Probability of either A or B is 0.5 = P_AUB P_A = 0.2 ...
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// Ex 55 Page 400 clc;clear;close; // Given Edc=250;//V fim=.065;//Wb f=50;//Hz E1=6000;//V P=1500;//kW p=8;//pole pf=0.9 V=400;//V J=3;//A/mm^2 E2=Edc/sqrt(2)//V N2=E2/4.44/f/fim;//no. of turns N1=E1/E2*N2;//no. of turns printf("no. of turns in primary = %d",N1) printf("\n no. of turns in secondary = %d",N2) Idc=P*1...
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// Define your variable t = linspace(0, 2*%pi, 100); // Define your polar function r = sqrt(abs(2 * cos(5*t))); disp(r); driver('PNG'); xinit('plot.png'); // Plot in polar coordinates polarplot(t, r); legend('r = Satellite passes'); xend(); exit();
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style.fontSize=12; style.displayedLabel="<table> <tr> <td align=left><b>Vfg0<br>Vfg1<br>Vsource</b></td> <td>mite_FG</td> <td><b>Vdrain</b></td> </tr> </table>"; pal2=xcosPalAddBlock(pal2,"mite_FG",[],style);
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function xyp=f1(t,Z); //Earth //Venus //M = [(5.9737 * 10^24) (4.8685 * 10^24)]; //SUN = 1.991 * 10^30; //G = 6.67259 * 10^(-11); M = [1 1]; G = 1; SUN = 1; x(1) = Z(1); x(2) = Z(2); y(1) = Z(3); y(2) = Z(4); x2(1) = Z(5); x2(2) = Z(6); y2(1) = Z(7); y2(2) =...
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function y = f(x) y = sin(x * 10 / (2 * %pi)); // y = x; // y = 2; endfunction function A = addto(A, x) A = [A x]; endfunction function A = naive_polling(freq, samples) A = [] for i = 0:(samples-1) A = addto(A, [i*freq; f(i*freq)]); end; endfunction function A = adaptive_polling_single(wait, samples,...
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; Mixed Tests for Cthulhu Scheme ; Scot W. Stevenson <scot.stevenson@gmail.com> ; First version: 10. Mai 2020 ; This version: 10. Mai 2020 ; Formats: ; - empty lines are ignored ; - lines that start with a semicolon ';' like this one are ignored ; - lines that start with a SECTION are printed to the output ; - All ot...
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clc clear //Initalization of variables disp("From table 5-4,") a=1 //moles of C6H6 b=7.5 //moles of O2 in reactant c=1.875 //moles of excess O2 d=35.27 //moles of N2 e=3 //moles of H2O flow=40 //lb/min w=1360850 //Btu/mol //calculations U11=a*337 U12=(b+c)*85 U13=d*82 U14=(a+b+c+d)*1066 Ua1=U11+U12+U13+...
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clc //initialisation of variables T= 20 //C R= 0.082 //li-atm per mole per degree V= 2 //lit m= 6 //gms M= 60 //gms //CALCULATIONS P= m*R*(273+T)/(M*V) //RESULTS printf (' osmotic pressure= %.1f atm',P)
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function hasil=tes2(g,tol) while g>tol g=g-1 disp(g); end hasil=[g]; endfunction
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 3: STEADY STATE CHARACTERISTICS AND PERFORMANCE OF TRANSMISSION LINES // EXAMPLE : 3.12 : // Page number 143 clear ; clc...
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//Part A Chapter 7 Example 8 clc; clear; close; P1=1;//MPa V1=0.05;//m^3 x1=80/100;//dryness fraction P2=1;//MPa V2=0.2;//m^3 W=P1*1000*(V2-V1);//kJ vf=0.001127;//m^3/kg//at 1 MPa vg=0.19444;//m^3/kg//at 1 MPa uf=761.68;//kJ/kg//at 1 MPa ufg=1822;//kJ/kg//at 1 MPa vfg=vg-vf;//m^3/kg v1=vf+x1*vfg;//m^3/kg...
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// Scilab Code Ex9.16: Page-9.47 ; (2004) clc;clear; e = 1.6e-19; // Electronic charge, C B = 1.5; // Magnetic field, tesla I = 50; // Current, ampere n = 8.4e+28; // Electron density, per metre cube t = 0.5e-2; // thickness of slab, metre RH = 1/(n*e); // Hall coefficent V_H = RH*I*B/t; // Hall...
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clc //initialisation of variables kw= 10^-14 ka= 2.69*10^-5 c= 0.1 //N //CALCULATIONS pH= -log10(sqrt(kw*ka/c)) //RESULTS printf ('pH = %.2f ',pH)
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//Problem 3.10: //initializing the variables: B = -0.159; // in m3/kgmol C = 0.009; // in (m3/kgmol)2 T = 400; // in K P = 40; // in atm //calculation: //Virial equation. //Z = PV/RT = 1 + B/V + C/V^2 //Insert the appropriate values of the terms and coefficients. Use R = 0.082 Latm/gmolK = 82.06 cm3.atm/gm...
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errcatch(-1,"stop");mode(2);//Example 5.17 // fluxmeter ; ; //given data : N1=800;// turns I=5;// in A l=1;// in m A=5*10^-4;// in m^2 N=500;// turns theta=25;// divisions H=(N1*I)/l; B=(4*%pi*10^-7*H); fi=B*A*10^8; K=((2*N*fi*10^-8)/(theta)); disp(K*10^-3,"Constant is,(Wb-turn/scale-div)=") exit();
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//example 14.20 PG-14.41 clc clear printf(" Refer to the Figure-14.52 shown\n\n") printf(" From the Figure we can see that\n\n") printf(" Y = ((A+B)''.(B+C'')'')''\n\n") printf(" Y = (A+B)''''+(B+C'')'''' .....Since (A.B)''=A''+B''\n") printf(" DeMorgan''s Therem \n") print...
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type t1 = array 10 of int; short proc(short a) { return a; } main() { var a : t1; const c = 11; get(a[1]); }
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// Removing whitespaces from binary image, returns co-ordinates image without white-space function [clean_img] = rm_ws(given_img, input_string); dirty_img = given_img; // given_img is binary image dirty_img_dim = size(dirty_img); select input_string // Remove top and bottom whitespace case "cols" then col...
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clc // Given that p = 1.013e5 // Pressure in Pa t = 300 // Temperature in K d = 3.5 // Effective diameter of oxygen molecule in Angstrom r = 2 // Ratio of free path of molecules with the lambda printf("\n Example 22.1 \n") sigma = %pi*(d*(10^-10))^2 n = p/(t*1.38*(10^-23)) lambda = 0.707/(sigma*n) R = exp(-r...
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clc clear //DATA GIVEN b=0.2; //width of the belt in m t=0.01; //thickness of the belt in m Tp=2; //permissible tension of the belt in MN/m^2 ratio=1.8; //ratio of T1/T2=1.8 rho=1100; //density of the material in kg...
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//Chapter-4, Illustration 22, Page 212 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA N=300;//Speed in rpm m=4.28;//Mass of steam in kg/s P=1.9;//Pressure of steam in bar x=0.93;//Dryness fraction W=3.5;//Stage...
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clc //Initialization of variables T1=25+273 //K T2=25+273 //K //calculations disp("Since, T2=T1, dE=0") dE=0 w=0 q=dE+w //results printf("\n Work done = %d ",w) printf("\n Heat transferred = %d ",q) printf("\n Change in energy = %d",dE)
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l=2.7+1//span, in m R=0.15//rise, in m t=0.27//tread, in m sigma_cbc=5//in MPa sigma_st=230//in MPa //assuming 50 mm per 1 m of span D=50*l//in mm D=200//assume, in mm W1=D/10^3*25*sqrt(R^2+t^2)/t//slab load on plan, in kN/m W2=1/2*R*t*25/t//load of step per metre, in kN/m W3=3//live load, in kN/m W=W1+W2+W3...
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//example:-3.6,page no.-93. // program to find out characteristic impedence and plot the magnitude of reflection coefficient versus normalized frequency. Zl=100;// load impedence Zi=50;//impedence of line which is to be matched //as it is a quarter wave transformer so,Zi=(Zo)^2/zl; Zo=sqrt(Zi*Zl); disp(Zo,'charac...
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clear clc dp=2.4*(10^-3);L=dp/6; //Effective mass conductivity(m3/hr.mcat) De=5*10^-5; //Effective thermal conductivity(KJ/hr.mcat.K) Keff=1.6; //For the gas film surrounding the pellet h=160;//heat transfer coefficient(KJ/hr.m2cat.K) kg=300;//mass transfer coefficient(m3/hr.m2cat) //For the reaction Hr=-160...
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// Exa 6.20 clc; clear; close; // Given data del_VDS = 1.5;// in V del_ID = 120 * 10^-6;// in A r_d = del_VDS/del_ID;// in ohm r_d = r_d * 10^-3;// in kohm disp(r_d,"The drain resistance of the JFET in K ohm is");
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echo "### Test Ex3-1" ../bin/carat/Bravais_catalog << EOF 1,1,1,1,1 y stdout a EOF echo "### Ex3-1 return code $?" echo "### Test Ex3-2" ../bin/carat/Bravais_inclusions Ex3_11111 -S echo "### Ex3-2 return code $?" echo "### Test Ex3-3" ../bin/carat/Bravais_catalog << EOF 5-1 y stdout a EOF echo "### Ex3-3 return cod...
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clc(); clear; // To calculate the range in temperatures at different depths T1=-15; // Min temperature at surface in degF T2=25; // Max temperature at surface in degF t=24; // time gap in hrs k=1.3; ...
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clear; clc; r0=.1; v=1; r1=.05; r2=.05; r3=.2; r4=.2; r34=inv(inv(r3)+inv(r4)); r234=r2+r34; r10=r1+r0; r=inv(inv(r234)+inv(r10)); ip=v/r; mprintf("the positive sequence current=%fpu",ip);
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function xdec=bizdec(x) k = 1:2:length(x); xdec = x(k); xdec = xdec(:); endfunction
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/05/CPU.tst load CPU.hdl, output-file CPU.out, compare-to CPU-decoding.cmp, output-list time%S0.4.0 inM%D0.6.0 instruction%B0.16.0 reset%B2.1.2 outM%D1.6.0 writeM%B...
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shapering.tst
\release printer CROUTPUT: \set time slow # # # # \USE shapering.in # NOFSQ, NOANOM \LIST 23 MODIFY EXTINCTION=YES ANOM=NO MINIMISE F-SQ=NO END #list 4 end #SFLS R R R R END \USE shapering1.in \USE shapering.ref # NOFSQ, ANOM \use shapering...
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Ex1_3.sce
clc // Example 1.3.py // Calculate the isothermal compressibility for air at a pressure of 0.5 atm. // Variable declaration p = 0.5 // pressure (atm) p_si = 0.5*101325 // pressure (N/m^2) p_eng = 0.5*2116 // pressure (lb/ft^2) // Calculations tau_atm = 1/p // isothermal compressibility in atm^-1 tau...
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Example9_2.sce
//Exa 9.2 clc; clear; close; //Given data : C1=1;// C=10; K=C1/C; V2byV1=(1+K); V3byV1=(1+3*K+K^2); V4byV1=(1+6*K+5*K^2+K^3); V5byV1=1+10*K+15*K^2+7*K^3+K^4 //I6=I5+i5; //omega*C*V6=omega*C*V5+omega*C1*(V1+V2+V3+V4+V5) V6byV1=V5byV1+K*(1+V2byV1+V3byV1+V4byV1+V5byV1); VbyV1=1+V2byV1+V3byV1+V4byV1+V5byV1+V...
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example21_5.sce
c1=5; v1=25; c2=10; v2=20; c3=1; v3=50; disp("Part a"); c=c1+c2+c3; disp("the total capacitance (in μF) is"); disp(c); disp("Part b"); disp("the maximum working voltage (in V) s"); disp(v2); disp("Part c"); q=v2*c; disp("the maximim charge (in μC) that can be stored is");disp(q);
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printf("\texample 14.4 \n"); printf("\tapproximate values are mentioned in the book \n"); //Assumed that 37500 lb/hr of 15 psig vapor is bled from the first effect for use in thevaccum pans printf("\n\tAVERAGE EVAPORATION PER SQUARE FOOT HEATING SURFACE FOR SUGAR EVAPORATORS\n"); printf("\tEffects\t\tWater evaporat...
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ex8_12.sce
//Page Number: 435 //Example 8.12 clc; //Given Qmax=0.06D-12; //C f=20D+6; //Hz V=10; //V n=3; //Power disspated per bit P=n*f*V*Qmax; disp('muW',P*10^6,'Power disspated per bit:');
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// Chapter 1 //Amplifier Gain //page 17 //Example no 1-6 //Given clc; G1=26; //in dB Vin=0.01; //in volt G=10^(G1/20); printf("\n The ordinary power gain %.2f \n",G); // Result Vout=Vin*G; printf("\n The output voltage is %.4f V\n",Vout); // Result
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example3_5.sce
errcatch(-1,"stop");mode(2); //example 3.5 //page 127 ; funcprot(0); // Initialization of Variable x=2; y=4; pi=3.14; u=4*x;//velocity x v=-4*y;//velocity y V=sqroot(u^2+v^2); theta=180/pi*atan(v/u); disp(V,"velocity at (2,4)is (m/s)="); disp(theta,"angle of the velocity with X axis(degrees)="); exit()...
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//chapter 12 //page no 540 //exa 12_46 //given clear; clc; Tb=100; //bit period in ps dZ=0.4; //in ps/nm/km Zr=150; //Modulator spacing in km Ta=Tb/(dZ*Zr); //channel spacing in nm printf("\n Channel spacing %0.1f nm",Ta); //result
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clc //initialisation of variables W= 0.0020 //M W1= 0.0010 //M W2= 0.0040 //M T= 1.86 //C n= 1 //moles n1= 1 //moles n2= 2 //moles a= 1.122 //CALCULATIONS dT= T*(W+W1+W2) I= 0.5*(n^2*W+n1^2*W2+n2^2*W1) g= 1-(2*a*I^1.5/(3*(W+W1+W2))) dT1= g*dT //RESULTS printf (' lowering the freezing point = %.4f C ',dT...
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// scilab Code Exa 11.5 Forced Vortex axial compressor stage dm=50/100; // Mean Blade ring diameter in m rm=dm/2; dh=0.3098354; // from results of exa 11.2 dt=0.6901646; um=100; // peripheral speed in m/s beta_1m=51; beta_2m=9; alpha_1m=7; // air angle at rotor and stator exit alpha_2m=50.177922; omega=u...
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C2P10.sce
clear clc //to find time required to reach highest point //to find distance travelled by the ball till the highest position is reached //to find time at which ball will be 27m above the groung // GIVEN:: //initial speed of the ball v0y = 25.2//in m/s //final speed of the ball vy = 0//in m/s //accel...
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// // //given FB_AB=80+(30/60) FB_BC=FB_AB+180-60 FB_CA=FB_BC-180+300 //convert into mins and degrees deg1=int(FB_AB) mins1=(FB_AB-deg1)*60 deg2=int(FB_BC) mins2=(FB_BC-deg2)*60 deg3=int(FB_CA) mins3=(FB_CA-deg3)*60 printf("\nFB_AB is %0.3f degrees %0.3f minutes W",deg1,mins1) printf("\nFB_BC is %0.3f degrees %0...
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pyAddToPath("N:\project\Python_Files\") pyImport imp //imp.reload("N:\project\Python_Files\") //image burring is left..no documentation //open closse function->kya hain pata nai...give proper function name function [image] = cv_rgb2gray_path(path) pyImport rgb2gray_file image=rgb2gray_file.rgb2gray(...
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function [x,y,typ] = mdaq_adc(job,arg1,arg2) global %microdaq; adc_desc = ["This block reads MicroDAQ analog inputs (AI). Block detects"; "MicroDAQ analog inputs type and allows channel, range"; "and measurement type selection."; "In order to select analog input channels scalar or vector"; "con...
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close t = 0:0.000001:0.001; function y = step(t) y = round((sign(t) + 1) / 2) endfunction function y = Pi(t) y = step(t + 0.5) - step(t - 0.5) endfunction function y = delta(t) y = 20000 * Pi(20000 * t); endfunction t0 = t(1); y0 = [0;0]; L = 0.001; R = 10; C = 1e-6; function zdot = RLCa(t...
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//Example 7.1 // Energy of plane wave clc; clear; //given data : u=(4D-7*%pi);// permeability(free space) in H/m e=8.85D-12;// permitivity(free space) in Farad/m H=1;// magnetic field in amp/m E=H*sqrt(u/e);// formula to calculate disp(E,"magnitude of Energy of plane wave in V/m")
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getf('functions.sci'); // bcms pgm = pgm_read('tri_thres.pgm'); pgm(1) = pgm(2) - pgm(1); disp(bcms_bi_get(pgm(1))); // bi threshold truck pgm = pgm_read('1.pic.pgm'); thres = thres_cr_get(pgm(1)); pgm(1) = thres_gray_apply(pgm(1), [thres], pgm(2)); pgm_write('test.pgm', pgm(1), pgm(2)); exit; // bi th...
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// José Augusto Câmara Filho - Matemática Industrial function A=Oitava(v,k) //Essa função insere os elementos de um vetor que o usuário cadastra previamente para serem os elementos que farão parte da matriz de Vandermonde e um inteiro "k" será o termo da ultima potência. b= length(v) // A variável "b" rec...
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//chapter 1 Ex 4 clc; clear; close; //let value to be found is x x=976*237+976*763; mprintf("x=%.0f",x);
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//scilab 5.4.1 //Windows 7 operating system //chapter 9 Basic Voltage and Power Amplifiers clc clear //In a single tuned amplifier L=120*10^-6//L=inductance in henry C=100*10^-12//C=capacitance in farad R=10//R=resistance in ohms hoe=50*10^-6//hoe=output impedance in mho(or S) hfe=100//hfe=current gain hie=2...
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clc; //page 675 //problem 13.8 //With single parity bit added, the code size = 4. An error evades parity check if any 2 or all symbols ofthe code arrives are erroneous. //Probability of any symbol from n are erroneous = nCm*(p^m)*(1-p)^(n-m) //Thus, the probability of error undetected, P_undeterr = (4C2*(p^2)*...
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// Exa 5.25 clc; clear; close; format('v',6) // Given data A = 54.8; A = 20 * log(A); Beta = 1/50;// feedback factor // gain with feedback Af = A/(1+(A*Beta)); //Distortion with feedback, Df = D/(1+(A*Beta)) Df = 1; D = 12; Pd = (Df/D)*100;// percenatge change in distortion in % disp(Pd,"The percentage r...
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/** * Calculates point positions. Provides numerical solution for second exercise. * * @param amount - number of positions * @param A, B, C - triangle vertices * @returns x, y - vectors of calculated points coordinates * @author Jakub Szota */ function [x, y] = generateTriangledPositions(amount, A, B, C) ...
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// // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2011-2011 - DIGITEO - Bruno JOFRET // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The ter...
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//Chapter-1, Example 1.2, Page 1.15 //============================================================================= clc clear //INPUT DATA Il=40;//Load current in A V=400;//Terminal voltage in V Ra=0.04;//Armature resistance in ohm Rse=0.02;//Series field resistance in ohm Rsh=300;//Shunt field resistance in...
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//Example 6_3 clc(); clear; //To find out how fast and the direction car moving m1=30000 //units in Kg m2=1200 //units in Kg v10=10 //units in meters/sec v20=-25 //units in meters/sec vf=((m1*v10)+(m2*v20))/(m1+m2) //unis in meters/sec printf("The car is moving at vf=%.2f Meters/sec\n",vf) printf("T...
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// Example 25_3 clc;funcprot(0); //Given data T_1=15+273;// K T_3=800+273;// K p_r=8;// Pressure ratio T_6=200+273;// K p_9=0.05;// bar W_t=190;// MW C_pa=1;// kJ/kg.K C_pg=1.1;// kJ/kg.K r=1.33;// Specific heat ratio CV=40*10^3;// kJ/kg // Calculation T_2=T_1*(p_r)^((r-1)/r);// K T_4=T_3/(p_r)^((r-1...
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function [Ab, P, sub] = gauss(A, b) [linhas colunas] = size(A); sub = zeros(linhas,colunas+1); P = eye(linhas,colunas); //---------------------------------------------------------- //---------------------------------------------------------- //-----------------------------------------------------...
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// scilab Code Exa 8.1 Calculation on a compressor cascade V1=75; // Absolute Velocity of air at entry in m/s alpha1=48; // air angle at entry alpha2=25; // air angle at exit p=1.1; // pitch-chord ratio delps=11; // stagnation pressure loss in mm W.G. ro=1.25; // density of air in kg/m3 g=9.81; a=0.5*(tand(al...
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function [y] = peak2rms(x,dim) funcprot(0); if(~exists('dim','local')) [r,c]=size(x); big=abs(x(1)); for i=2:r:1 big<abs(x(i)); big=abs(x(i)); end x=x.^2; for i=1:r:1 ys(i)=sum(x(i,:)) ys=ys./c ys=ys.^0.5 //disp(ys) end y=big./ys else if(dim==1) [r,c]=size(x); big=abs(x(1)); for i=...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 10: POWER SYSTEM STABILITY // EXAMPLE : 10.3 : // Page number 270-271 clear ; clc ; close ; // Clear the work space and ...
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// Exa 4.4 clc; clear; close; format('v',7) // Given data I_B = 45;// in µA I_B = I_B * 10^-6;// in A I_C = 5.45;// in mA I_C = I_C * 10^-3;// in A I_E = I_B+I_C;// in A I_E= I_E*10^3;// in mA disp(I_E,"The value of I_E in mA is"); I_E= I_E*10^-3;// in A Alpha = I_C/I_E;// unit less disp(Alpha,"The value...