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<?xml version="1.0" encoding="utf-8"?> <test> <description>StdProject2D Triangle Modified basis P=6 Q=7</description> <executable>StdProject2D</executable> <parameters>3 4 5 6 6 7 7</parameters> <metrics> <metric type="L2" id="1"> <value tolerance="1e-12">2.18252e-14</value> ...
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//Author: Parthasarathi Panda //parthasarathipanda314@gmail.com function [sos,g]=ss2sos(A,B,C,D) //not taking if, order and scale as input since they do not seem useful if (type(A)~=1 | type(B)~=1 | type(C)~=1 | type(D)~=1) then error('check input types'); end if (length(size(A))~=2 | length(size(B)...
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clc //initialisation of variables E= -0.126 //volt E1= -0.140 //volt n=2 R= 0.0591 //volt //CALCULATIONS E0= E-E1 K= 10^((E-E1)*n/R) //RESULTS printf ('equilibrium constant = %.2f ',K)
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//Example 9.9 //Particular Solution //Page no. 293 clc;clear;close; x=poly(0,'x') n=2; f=x^(n)-x^(n-1)-2*x^(n-2); z=roots(f) disp(z,f) printf('\n\n') printf(' n n\nC.F. = ') for i=1:n printf('c%i(%g)',i,z(i)) if i~=n then printf(' + ') end end A=[-2,0,0;10,-2,0;9,...
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Scene: Untitled Entities: - Entity: 12837192831273 TagComponent: Tag: Camera B TransformComponent: Translation: [0, 0, 0] Rotation: [0, 0, 0] Scale: [1, 1, 1] CameraComponent: Camera: ProjectionType: 1 PerspectiveFOV: 0.785398185 PerspectiveNear: 0.009...
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// Scilab code Ex7.2: Pg 236 (2005) clc; clear; e = 1.60e-19; // Electrc charge, C i = 1.00e-03; // Electron current, A N = i/e; // Electrons per second T = 0.657e-07; // Fraction of electrons transmitted T_e = N*T; // Number of electrons transmitted per second T_i = T_e*e; // Transmitted...
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//Design a TDMA frame for a cellular system Nca1 = 1' Nca2 = 2; Rbmin = 8; a1 = 0.1; nf = 0.75; Rc = 0.5; Nslot1 = 16/Nca1; Nslot2 = 16/Nca2; Rs1 = (Rbmin*(1+a1)*Nslot1)/(nf*Rc); Rs2 = (Rbmin*(1+a1)*Nslot2)/(nf*Rc); disp(Nslot1, 'Nslot for Nca=1') disp(Nslot2, 'Nslot for Nca=2') disp(Rs1, 'Rs for Nca...
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// Programa para executar o princípio da separação, realizando o controle do sistema a partir do lambda = [A-B*Kc,B*Kc;zeros(4,4),A-Ko*C] // Crianção da matriz lambda t0 = 0 // Definição do intervalo de tempo dt = 0.1 n = 50 tf = t0 + (n-1)*dt t = t0:dt:tf x0 = [1;1;1;1;0;0;0;0] // Condições inicias x1=[] x2=[] x3=[] ...
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clc clear //Input data d=180//Distance of satellite above the surface of earth in km t=90//Time taken to complete one revolution of the earth in minutes r=6400//Radius of the earth in kms //Calculations R=(r+d)*1000//Total distance in m T=t*60//Time in seconds v=(2*3.14*R)/T//Orbital speed in m/s a=(v^2/R)/...
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disp("Exercice 1.1:") M=[0,1,1;0,0,1;1,0,0] N=[0,0,1;1,1,1;1,0,1] disp(modulo(M+N,2),"M+N=") disp(modulo(M*N,2),"M.N=") disp("Exercice2.2") disp("f est injective si et seulement si pour chaque image sur (Z/2Z)7, il existe au plus un antécédent sur (Z/2Z)3 . Soit deux matrice M et M’ appartenant à (Z/2Z)3 ") disp("Or ...
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errcatch(-1,"stop");mode(2);//Engineering and Chemical Thermodynamics //Example 7.6 //Page no :324 ; ; // The problem does not contain any numerical part . The readers can refer the text book to get the answer . disp(" Example: 7.6 Page no : 324") ; disp(" Like interactions are stronger than unlike int...
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function [stk,txt,top]=sci_toeplitz() // Copyright INRIA txt=[] if rhs==1 then stk=list('toeplitz('+stk(top)(1)+')','0','?','?','1') else stk=list('toeplitz'+rhsargs([stk(top-1)(1),stk(top)(1)]),'0','?','?','1') top=top-1 end
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clc; //page 185 //problem 3.8 //Given ohmnic loss resistance is Ro = 12 Ohm, Ro = 12 //radiation resistance is Rr = 48 Ohm, Rr = 48 //directivity is D = 2 D = 2 //Input current = 0.1*cos[2*pi*(10^6)*t], Amplitude of input current is A = 0.1 Amp A = 0.1 //Equivalent resistance = Re = Ro+Rr Re = R...
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// Additional solved examples , Example 15 , pg 337 //plane has intercepts 2a,2b,3c along the 3 crystal axes //lattice points in 3-d lattice are given by r=p*a+q*b+s*c //as p,q,r are the basic vectors the proportion of intercepts 2:2:3 p=2 q=2 s=3 //therefore reciprocal r1=1/2 r2=1/2 r3=1/3 //taking LCM...
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//exec('Setup_Parameters_Finish.sce'); exec('Setup_Parameters.sce'); //stacksize('max') fZ_ClearPlane = 1; fZ_ChipBreakMove = .5; //mm Amount to retract tool fDOC = -.05; toolT1 = BuildTool('FULL_RADIUS', .051, 35 * (%pi / 180), (5 + 35/2) * (%pi / 180)); plFinalProfile = OffsetNormal(plPoints, .050); //Build the ...
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//Scilab Code for Example 4.6 of Signals and systems by //P.Ramakrishna Rao clear; clc; close; disp("X(w)=1/(a+jw)^2=1/(a+jw)*1/(a+jw) "); disp("exp(-a*t)*u(t) <--> 1/(a+jw) "); disp("therefore x(t)=convolution(2*sinc(2*t),(sinc t)^2"); a=2; n=1; for t=-10:0.1:10 y1(1,n)=(sinc(t))^2; y2(1,n)=2*sinc(2*t); n...
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//argument function for ode //call ext8c argument function with dynamic link host('make /tmp/ext8c.o'); link('/tmp/ext8c.o','ext8c','C'); ode([1;0;0],0,[0.4,4],'ext8c')
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clear; clc; disp("--------------Example 28.3---------------") tag="00000110"; // OBJECT IDENTIFIER tag Length="00000100"; // 4 bytes ObjectIdentifier="1.3.6.1"; // (iso.org.dod.internet) ot1=1; ot2=3; ot3=6; ot4=1; // convert the bytes to binary byte1=dec2bin(ot1,8); byte2=dec2bin(ot2,8); byte3=dec2bin(ot...
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//chapter 11 //example 11.9 //page 332 clear all; clc ; //given Vb2=8; Rl=100;//load resistance in kohm Vcc=20;//supply voltage V vp=100;//op voltage mV ip=vp/Rl; Ie2=2;//Ie2>ip Ve1=5;Vce1=3; Vc1=Ve1+Vce1; Vb1=Vc1; Ve2=Vb2-0.7; R5=Ve2/Ie2; printf("\nR5= %.2f kohm,use 3.3 standard value kohm ",R5);R5=3....
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.481270D+00 ...
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//Variable declaration mew0=4*%pi*10**-7; B=0.0044; //flux density(Wb/m**2) M=3300; //magnetic moment(A/m) //Calculation H=(B/mew0)-M; //magnetizing force(A/m) mewr=1+(M/H); //relative permeability //Result printf('magnetizing force is %0.3f A/m \n',int(H)) printf('relative permeabi...
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//Exa 10.7 clc; clear; close; //Given data : D=19.5;//mm wc=0.85;//kg/m L=275;//m Pw=39;//kg/m^2(Wind pressure) r=13;//mm U_stress=8000;//kg/cm^2 SF=2;//factor of safety rho_i=910;//kg/m^3(density of ice) T=U_stress/SF;//kg wi=rho_i*%pi*r*10^-3*(D+r)*10^-3;//kg w_w=Pw*(D+2*r)*10^-3;//kg wr=sqrt((wc+wi)^...
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clc //initialisation of variables Sc= 800 //psi Ss= 18000 //psi ratio= 15 d= 5/8 //in l= 20 //in b= 10 //in //CALCULATIONS x= Sc*ratio*l/(Ss+Sc*ratio) As= b*x*(x/2)/((l-x)*ratio) Ina= (b*x^3/3)+ratio*As*(l-x)^2 M= Sc*I/x N= As/(%pi*(d/2)^2) //RESULTS printf ('Number of steel bars required= %.2f',N) disp...
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//Example 1 6 clc ; clear; close; f=9; //assuming frequency to be a constant 9Hz. t =0:.1:10; x= t+sin(4*180*f*t)+cos(2*180*f*t); disp(x); disp('Since value of the signal at any time t is known, it is a DETERMINISTIC signal');
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clc; clear; //clears the console and all previously stored variables funcprot(0); //disables the warning messages, when function is redefined //calculating the greeks with approximation of partial differential function [Delta, vega, rho, Theta] = BS_Greeks_num(r, sigma, S0, T, g, eps) Delta = (BS_Price_Int(r, si...
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// Exa 1.28 clc; clear; close; format('v',6) // Given data T = 125;// in degree C T = T + 273;// in K V_T = T/11600; Io = 30;// in µA Io = Io * 10^-6;// in A V = 0.2;// in V // The dynamic resistance in forward direction, r_f = V_T/( Io * (%e^(V/V_T)) );// in ohm disp(r_f,"The dynamic resistance in forwar...
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clc //Example 2.12 //Stresses in a locomotive //------------------------------------------------------------------------------ //Given Data: //Speed V=96.6 //kmph //Crank length Cl=0.375 // m //Length of side rod L=2 // m //Radius of driver R=0.915 // m //Tractive effort per wheel Et=45000 // N...
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//chapter 5 example 2// clc clear //hole concentration=Pn,minority carrier life time=Tr// Br=7.21*(10^-10); Pn=10^18;//in per cm cube// Tr=((Br*Pn)^-1)*(10^9);//minority carrier life time// printf("\n minority carrier life time=%f *(10^-9) sec \n",Tr);
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// Scilab Code Ex 10.9 Electrical Conductivity of Cu: Page-345 (2010) e = 1.6D-19; // Electronic charge, C N = 6.023D+23; // Avogardro's number d = 8920; // Density of Copper, kg per metre cube A = 63.5; // Atomic weight of copper, g/mole I = 10; // Current through uniform copper wir, ...
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//signals and systems //Unilateral Laplace Transform:Solving Differential Equation //example 4.10 s = %s; syms t; [A] = pfss((2*s^2+20*s+45)/((s+2)*(s+3)*(s+4))); F1 = ilaplace(A(1),s,t) F2 = ilaplace(A(2),s,t) F3 = ilaplace(A(3),s,t) F = F1+F2+F3 disp(F)
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 3 : TRANSFORMERS // EXAMPLE : 3.21 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA // Refer figures 3.31(a), 3.31(b) and 3.31(c):- Page no. 121 VaH = 220; ...
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// Example 1.37 clear; clc; close; format('v',7); // Given data Nnl=1485;//in rpm Nfl=1350;//in rpm f=50;//in Hz //Calculations Ns=1500;//nearest syn speed to Nfl in rpm(Assumed) //Formula : Ns=120*f/P P=120*f/Ns;//no. of poles disp("Part (i)"); disp(P,"No. of poles : "); Snl=(Ns-Nnl)/Ns;//slip disp...
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clear; clc; //Example - 14.9 //Page number - 465 printf("Example - 14.9 and Page number - 465\n\n"); //This problem involves proving a relation in which no mathematics and no calculations are involved. //For prove refer to this example 14.9 on page number 465 of the book. printf(" This problem involves provi...
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function [s]=%lssas(s1,d2) //s=%lssas(s1,d2) iff s=s1+d2 //! // origine s. steer inria 1987 // [a1,b1,c1,d1,x1,dom1]=s1(2:7) s=tlist('lss',a1,b1,c1,d1+d2,x1,dom1)
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function y=f(x) y = x.*exp(x./2) endfunction xs = [2; 2.25; 2.5; 2.75; 3] fx = [2.71; 3.08; 3.49; 3.96; 4.48] axes = get("default_axes") axes.x_location = "origin" axes.y_location = "origin" x1 = xs(1) x2 = xs(2) x3 = xs(3) x4 = xs(4) x5 = xs(5) function y=p(x) L1 = ((x - x2).*(x - x3).*(x - x4).*(x - x5))./...
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clc w=0.1 //m d=0.115 //m l=4 //m p=175 //kN/m k=14*10^6 //Pa E=200*10^9 //Pa I=(0.1*(0.15)^3) //deltav=(p/2*k)*derivative(x)*beta*exp^(betax)*(cos beta(x)+sin beta(x)) //vA=(p/2k)*(2-exp^(betaa)*cos betaa - exp^(betab)*cos betab) beta=(k/(4*E*I/12))^(0.25) disp(beta,"in meter inverse is= ") vmax=(p...
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clear // // //Initilization of Variables q_b=80 //N/mm**2 //Shear stress in Brass q_s=100 //N/mm**2 //Shear stress in Steel G_b=40*10**3 //N/mm**2 G_s=80*10**3 L_b=1000 //mm //Length of brass shaft L_s=1200 //mm //Length of steel shaft d1=80 //mm //Diameter of brass shaft d2=60 //mm //Diameter of steel shaft //Cal...
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clc; clear all; h = 6.62e-34; // Planck's constant in J.s m = 9.1e-31 // Mass of electron in kg nk =1; nl = 1; nm = 1; a = 0.5e-10 // Width of cubical box in meter E = (h^2*(nk^2+nl^2+nm^2))/(8*m*a^2*1.6e-19);//The lowest energy level will have energy disp('eV',E,'The lowest energy level will have energy ');
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clc clear //Input data f=20//Focal length in cm fl=[0.015,0.019]//Dispersive powers of crown and flint glasses respectively r=[1.495,1.53]//Refractive indices respectively //Calculations fx=-(fl(1)/fl(2))//Ratio of focal lengths //Solving two equations //(1/f)=(1/f1)+(1/f2) //(f1/f2)=(-0.015/0.019) f2=((1/...
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function [s] = leastsq(A, b) s = lsq(A, b); endfunction A = [2 -1; 1 -2; 1 1]; b = [2 1 4]'; r = leastsq(A, b); disp(r); /* 2. 1. */
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// Scilab code Ex12.2: Pg:464 (2008) clc;clear; n2 = 1.59; // Cladding refractive index of an optical fibre n0 = 1; // Refractive index when the fiber is in air NA = 0.20; // Numerical aperture of fiber // Since NA = sqrt(n_1^2-n_2^2)/n0, solving for n1 n1 = sqrt(NA^2 + n2^2)/n0; // Core refractive in...
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function [alp,cux,cuy,cuz,rg,... uxx,uxy,uxz,uyy,uyz,uzz,... gxx,gxy,gxz,gyy,gyz,gzz,... qxx,qxy,qxz,qyy,qyz,qzz,... dxuxx,dxuxy,dxuxz,dxuyy,dxuyz,dxuzz,... dyuxx,dyuxy,dyuxz,dyuyy,dyuyz,dyuzz,... dzuxx,dzuxy,dzuxz,dzuyy,dzuyz,dzuzz... ...
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%*******************************************************************% % % % C R A C K . T S T % % ----------------- % % crack.tst contains test examples ...
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// Example 3.7.5;alpha clc; clear; close; format('v',4) disp("part (a)") vc=135;//in volts vs=220;//in vlts rl=0.5;//in ohms io=10;//in ampeeres vm=sqrt(2)*vs;// vldc=io*rl+vc;// alpha=acosd((vldc*%pi)/(2*vm));// disp("alpha is in degree "+string(alpha)+" ") disp("part (b)") vc=145;//in volts vs=220;//in vlts rl=0.5;//...
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// To calculate the number of turns per limb on the high and low voltage sides clc; clear; f=50; A=400*(10^-4); Bm=1; V1=3000; V2=220; l=2; // Number of limbs //Neglecting the series voltage drop // Induced EMF equation a=V1/(4.44*f*A*Bm); b=V2*a/V1; if(modulo(round(a),2)==0) // No. of turns ...
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6_11.sce
clear clc //initialisation of variables r1= 1/3 r2= 7/12 l= 5000 //ft l1= 10000 //ft d= 27 //in d1= 18 //in Q= 10 //cuses f= 0.006 //CALCULATIONS Q2= Q/(sqrt(r2/r1)+1) Q1= Q-Q2 H= (f*l*Q^2/(10*(d/12)^5))+(f*l1*Q1^2/(3*10^(d1/12)^5)) //RESULTS printf ('total difference in head = %.2f ft',H) //ANSWER...
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function P=possibility(i,j,S) // S= matrix with 9 rows and 9 columns = sudoku //(i,j)= cell of interest in sudoku S // P= list of possible values out of {1;2;...;9} // for element (i,j) S(i,j)=0//we set element (i,j) to 0 A=unique(S(i,:)) // values in row i A=A(find(A<>0)) // remove t...
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b=300//in mm Pu=1500//in kN Mux=100//in kN-m Muy=70//in kN-m fck=15//in MPa fy=250//in MPa p=1.5//assume 1.5% steel, placed on four sides Ag=Pu*10^3/(0.4*fck*(1-p/100)+0.67*fy*p/100)//in sq mm D=Ag/b//in mm D=600//assume, in mm m=p/fck c=60//cover (assume), in mm //to find Mux1 n=c/D//n=d'/D l=Pu*10^3/fck...
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taylor.sce
function y = f0(t, u) y = u*t endfunction function y = f0t(t, u) y = (u*t)*t + u endfunction function y = f0tt(t, u) y = ((u*t)*t + u)*t + (u*t) + (u*t) endfunction function [u] = taylor(N, uInicial, tInicial, tFinal, h) f = f0 ft = f0t ftt = f0tt cor = 'ro-' u(1) = uInicial...
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peig4.sce
x=[1 2 3 4 5 6 2 3 7]; p=3; nwin=7; noverlap=3; fs=4e6; nfft=6; [S,f] = peig(x,p,nfft,fs,nwin,noverlap); //output // !--error 21 //Invalid index. //at line 32 of function musicBase called by : //at line 86 of function peig called by : //[S,f] = peig(x,p,nfft,fs,nwin,noverlap);
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sergeant vs pigeon.sce
Name=sergeant vs pigeon PlayerCharacters=Sergeant 87 BotCharacters=Pigeon.bot;Pigeon.bot;Pigeon.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Sergeant 87 AddedBots=Pigeon.bot;Pigeon.bot;Pigeon.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=0 BotTeams=0;0;0 MapName=kovaim1.map MapScale=3.8125 BlockPr...
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vectors.sce
F = input("Введите номер формы: ") if F == 0 then disp("Неверный номер формы!") return end V = input("Введите номер вида: ") if F == 1 then disp("1."+string(V)+" = "+"0 + 1."+string(V - 1)) return end H = F if modulo(F,2) ~= 0 then G = F + 1 F = F - 1 else G = F end M = F n = 0 while modulo(M,2) == 0 M ...
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 1 clc; disp("CHAPTER 7"); disp("EXAMPLE 1"); //VARIABLE INITIALIZATION I_0=10; //no load current in Amperes pf=0.25; //power factor v1=400; //in Volts f=50; //in Hertz //SOLUTI...
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function y=foo(x) y=1+x^2 endfunction fun2string(foo,'foo1')
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fibonacciUsingForLoop2.sci
v0 = 20; g = 9.8; y = 0; t = 0; while (y>=0) disp('At time t = '+t+'location = '+string(y)); t = t + 0.1; y = v0 - 0.5*g*t*t; end
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example22.sce
//Chapter-11 example 22 //============================================================================= clc; clear; //input data Ra = 1000;//Range of target A in Kms //Calculations Rb =Ra*cos(45*%pi/180);//range of target B in kms //output mprintf('Range of target B is %g Kms\n',Rb); mprintf(' Note:value of...
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//Ex4_6 Pg-222 clc Vr=0.7 //voltage drop Vi=120 //input voltage disp("RMS value of secondary voltage") V_sec=Vi/5 //RMS value of secondary voltage printf(" = %.0f V\n ",V_sec) disp("Peak secondary voltage") Vm=V_sec*sqrt(2) //Peak secondary voltage printf(" = %.0f V\n ",Vm) disp("Peak inve...
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int main(void) { int i; for (i = 1; i <= 10; ++i) { do i++; while (++i); } }
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calibSimplexMeanSquares_05:33:45.739 PM 05-juin-2013.sci
ms=[];incomemean=[];bref=[];bnorm=[]; ms(1)=50000; incomemean(1)=10000; bref(1)=5000; bnorm(1)=5000; ms(2)=50000; incomemean(2)=10000; bref(2)=7000; bnorm(2)=5000; ms(3)=50000; incomemean(3)=10000; bref(3)=5000; bnorm(3)=7000; ms(4)=50000; incomemean(4)=12000; bref(4)=5000; bnorm(4)=5000; ms(5)=50000; incomemean(5)=113...
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thermocalc.sce
pa=99450 //Atmosphärischer Druck in Pascal kugelmasse=16.697*10^-3 //kilogramm kugelmassefehler=3*10^-7 //kilogramm quer=%pi*(8*(10^-3))^2 //rohrquerschnitt druck=pa+(kugelmasse*9.81)/quer Tschw=4.35/4 VolGef=10*10^-3 kappa=((2*%pi)/Tschw)^2*(kugelmasse*VolGef)/(quer^2*druck) disp(kappa)
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clear; clc; close; Vcc = 24; //part a Vl_p = 22; n = 78.54*(Vl_p/Vcc); disp(n,'Efficiency(Percentage) = '); //part b Vl_p = 12; n = 78.54*(Vl_p/Vcc); disp(n,'Efficiency(Percentage) = ');
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clear; clc; P1=67;P2=30; L=10*log10(P1/P2); printf("Insertion loss = %f db",fix(L*100)/100);
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// Example no 5.5 // To calculate mean excess delay, rms delay spread and maximum excess delay // Page no. 202 clc; clear all; // Given data t10dB=5*10^-6; // By definition of maximum excess delay (10dB) t1=0; ...
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// chapter 8 // example 8.17 // fig. 8.26 // Compute the value of commutating capacitor and inductor // page-483-484 clear; clc; // given Edc=80; // in V (dc source) Toff=20; // in us (turn off time of SCR) T=2000; // in us (chopping period) I0_m=80; // in A (starting current) // calculate Toff=Toff*1E-6; T=T*1E-6; dt=...
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clc //initialisation of variables v= 1.75*10^-3 //pa s l= 1 //m P= 1 //Mpa d= 0.5 //mm //CALCULATIONS Q= (%pi*P*10^6*((d/2)*10^-3)^4)/(l*8*v) //RESULTS printf ('Q= %.2e Ns/m^2',Q)
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//============================================================================ // nom : caracterisation d'assemblage en vissage discontinu.sce // auteur : ID TALEB ABDERRAHIM // date de création : 2017-05-15 // dates de modification : ... //---------------------------------------------------------------------------- /...
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clear L=1.0; imax=12;xi=linspace(0,1,imax-1); Beta=1.2; Beta_p1=Beta+1;Beta_m1=Beta-1;Beta_p1_div_m1=(Beta_p1/Beta_m1)^(2*xi-1); num=(Beta_p1*Beta_p1_div_m1)-Beta_m1;den=2*(1+Beta_p1_div_m1); x=L*num./den; y=x;//by symmetry of the situation xc(2:imax-1)=(x(2:imax-1)+x(1:imax-2))/2; xc(1)=x(1);xc(imax)=x(imax-1);yc=xc...
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// Copyright (C) 2012 - Prateek Papriwal // Copyright (C) 2012 - Michael Baudin // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http...
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clc(); clear; //Given : D = 5*10^28; // density of atoms in silicon per m^3 C = 2.0*10^8; //donor concentration ND = D/C; // donor atoms density per m^3 // ND = 4.82*10^21*T^(3/2) T = (ND/(4.82*10^21))^(2/3); printf("Temperature = %.2f K",T);
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//Calculations for comparison of SI and CI engine clc,clear //Given: //For SI engine s1=0.72 //Specific gravity of gasoline fuel CV1=44800 //Calorific value of gasoline fuel in kJ/kg eta_bt1=20 //Brake thermal efficiency in percent A_F1=14 //Air fuel ratio //For CI engine s2=0.87 //Specific gravity of diesel oil CV2=43...
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//Calculate sag from taller of the two supports clear; clc; //soltion //given Wc=1.925;//kg/m//Line conductor wieght L=600;//meter//span of the line h=15//m//T1-T2 Wi=1//kg//Wieght of the ice Wr=Wi+Wc;//resultant weight A=2.2//cm^2 U=8000*A;//kg//Breaking strength sf=5;//safety factor T=U/sf;//kg//max allo...
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s = poly(0,'s'); G = (s+1)/((s+5)*(s+10)*(s+100)); G = syslin('c',G); bode(G, 0.01, 100);
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black_body_radiation.sce
s = 0 //%spectral emittance h = 6.62607004e-34 //%planks constant k = 1.38064852e-23 //%boltzmanns constant wl = 600e-9 //%wavelength (nm) t = 293 //%absolute temperature (kelvin) c = 3e8 //%speed of light (m/s) e = exp(1) pi=%pi temps=300:5:400 //temps=[79 195 300 800 3000 6000] temps=temps($:-1:1) //te...
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//Example 3_8 clc(); clear; //To calculate the acceleration vf=30 //units in meters/sec v0=0 //units in meters/sec t=9 //units in sec a=(vf-v0)/t //units in meters/sec^2 a=a*(1/1000)*(3600/1)*(3600/1) //units in km/h^2 printf("Acceleration a=%d km/h^2",a)
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exec("lib/page_rank_matrice.sce"); exec("lib/methode_puissance.sce"); M = bool2s(rand(500, 500)<0.5); A = page_rank_matrice(M, 0.85); r = methode_puissance(A, 100)
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n= 8.48*(10^28); //free electron density, m^(-3) Vfermi= 1.57*(10^6); //Fermi Velocity, m/s rho= 1.72*(10^(-8)); //resistivity, ohm e= 1.6*(10^(-19)); //charge of an electron, C Me= 9.1*(10^(-31)); //mass of electron, kg lambda= Me*Vfermi/(n*(e^2)*rho); //m lambda= lambda*(10^9); //converting to nm disp(lambd...
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//calculation of heat of neutralization clear; clc; printf("\t Example 6.8\n"); //for water m=100+100;//mass, g s=4.184;//specific heat, J/g C deltaT=25.86-22.5;//change in temp., C qsoln=m*s*deltaT/1000;//heat gained by water, kJ qrxn=-qsoln; Hneut=qrxn/(0.5*0.1); printf("\t the heat of neutraliza...
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//Chapter 17 //Example 17_8 //Page 410 clear;clc; kva=5000; x=12; r=6; base=input("Input base kva: "); perx=base*x/kva; printf("With reactors: \n"); x1=(perx+r)/2+r; tx1=x1*x/(x1+x); sci1=base*100/tx1; printf("Total %% reactance from generator to fault = %.2f %% \n", tx1); printf("Short circuit input = %.3f MVA \...
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exec("swigtest.start", -1); // Test on NULL null = getNull(); checkequal(SWIG_this(null), 0, "SWIG_this(null)"); null = SWIG_ptr(0); checkequal(isNull(null), %T, "func(null)"); // Test on variable expected_foo_addr = getFooAddress(); foo_addr = SWIG_this(pfoo_get()); checkequal(foo_addr, expected_foo_addr, "SWIG_thi...
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function y = es_sdp(A) [m,n] = size(A); y=es_simetrica(A); if y then // controla si la matriz es definida positiva for i = 1 : n if det(A(1:i,1:i)) <= 0 then disp("La matriz no es simétrica definida positiva.") y = %F; ret...
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// Copyright (C) 2019 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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// Chapter 11 // Design a filter to remove subsonic tones // Page.No-406 // Example11_2 //Figure 11.29 // Given clear;clc; f3db=20; //In Hz W3db=2*%pi*f3db; printf("\n The desired break frequency, W3db is = %.1f radians per second\n",W3db); // Result disp("Stage 1"); kf=1.557; Wc=W3db/kf; printf...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.274797D+00 ...
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//Problem 19.11: A 415 V, 3-phase a.c. motor has a power output of 12.75 kW and operates at a power factor of 0.77 lagging and with an efficiency of 85%. If the motor is delta-connected, determine (a) the power input, (b) the line current and (c) the phase current. //initializing the variables: Po = 12750; // in Wa...
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we we wy x1 x2 #d -6,449 6,677 Klasa1 -5,973 6,435 Klasa1 -5,476 6,725 Klasa1 -4,731 7,16 Klasa1 -3,882 7,184 Klasa1 -2,847 7,16 Klasa1 -1,915 7,136 Klasa1 -0,756 7,184 Klasa1 0,155 7,063 Klasa1 1,439 6,967 Klasa1 1,832 6,604 Klasa1 2,598 6,701 Klasa1 3,095 6,122 Klasa1 4,813 2,958 Klasa1 4,896 1,195 Klasa1 5,041 -0,35...
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clc;funcprot(0);//EXAMPLE 3.33 // Initialisation of Variables p1=1;....................//Intake pressure in bar p2=5;....................//Supply pressure in bar t3=1000;..................//Supply temperature in Kelvin cp=1.0425;................//Specific heat at constant pressure in kJ/kgK cv=0.7662;...............
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clc clear clf() a=uigetfile('*.*','Select the Image:') a = imread(a); imshow(a);
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//clear// //Caption:Comparison of M-ary PCM with ideal system (Channel Capacity Theorem) //Example5.2:Comparison of M-ary PCM system //Channel Capacity theorem clear; close; clc; P_NoB_dB = [-20:30];//Input signal-to-noise ratio P/NoB, decibels P_NoB = 10^(P_NoB_dB/10); k =7; // for M-ary PCM system; Rb_B = l...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART I : GENERATION // CHAPTER 7: TARIFFS AND ECONOMIC ASPECTS IN POWER GENERATION // EXAMPLE : 7.16 : // Page number 78 clear ; clc ; close ; // Clear the work space and ...
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//find line current and starting torque with direct switching, stator resistance starting, autotransformer starting, star delta starting, autotransformer ratio give 1 pu clc; //I_s/I_fl=6; s_fl=0.05; disp('by direct switching'); Is=6;disp(Is,'line current(pu)'); T=Is^2*s_fl;disp(T,'torque(pu)'); disp('by sta...
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errcatch(-1,"stop");mode(2);//developed in windows XP operating system 32bit //platform Scilab 5.4.1 ;; //example 6.1w //calculation of the maximum angle to prevent slipping //given data mus=.3//coefficient of static friction //calculation thetamax=atand(mus) printf('the maximum angle to prevent slipping...
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//Example 6.3 clc disp("R_L = 8 ohm, R''_L = 648 ohm") disp("Now R''_L = R_L / n^2") n=8/648 format(8) disp(n,"Therefore, n^2 = R_L / R''_L =") disp("Therefore, n = 0.1111 = Turn ratio") disp("But, n = N2 / N1 = 0.1111") disp("Therefore, N1/N2 = 9") disp("Generally the turns ratio is specified as Ni/N2 :...
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style.fontSize=12; style.displayedLabel="<table> <tr> <td><b>In</b></td> <td align=center>CAP0 <b color=green>%1$s</b></td> <td align=left><b>Out</b></td> </tr> </table>"; pal11 = xcosPalAddBlock(pal11,"macrocab_cap0",[],style);
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//Exa 6.1 clc; clear; close; //given : f=30 // frequency in MHz f=30*10^6 // frequency in Hz c=3*10^8 // speed of light in m/s lambda=c/f // wavelength in meter Delta=30 // angle of elevation in Degrees H=lambda/(4*sind(Delta)) // Rhombic height in m phi=90-Delta // tilt angle in Degrees l=lambda/(2*(cosd(p...
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clc clear //Input data d=20//Bore in cm l=38//Stroke in cm Vc=900//Clearance volume in c.c p1=1//Pressure at the start of compression stroke in kg/cm^2 T1=90+273//Temperature at the start of compression stroke in K x=0.75//Piston travelled 0.75 of the compression stroke n=1.32//Compression curve index wa=0.01...
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clear; //clc(); // Example 15.3 // Page: 402 printf("Example-15.3 Page no.-402\n\n"); //***Data***// // This contains three species. printf(" The three species in this system are H2, N2 and NH3\n"); N = 3; printf(" There is only one balanced chemical reaction among these species\n"); Q = 1 // 2NH3 = N...
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Mx=100*10^6; B=[640;600;600;600;620;640;640;850;640];//matrix having the values of B D=[1200;1140;960;768;565;336;144;38;0];//matrix having the distence of all booms from boom 9
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function odedi() // Tests simples de ode et arsimul // Test de l'option discrete de ode // x_{n+1}=n*x_{n}, x_{1}=1; deff('[xnp1]=ttt(n,xn)','xnp1=(xn**2);'); // remarque sur la syntaxe a utiliser pour l'option discrete // utilizer y=ode('discret',y1,1,2:n,macro);y=<y1,y> // on a alors dans y=<y1,y2,....,y_n>; //! writ...
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exec('/home/amine/Documents/2A/Projet MOPSI/MOPSI-Project/code_ameliore.sci', -1) function [B] = brownien(N,couleur) B = M(1 :N+1)/sqrt(N) ; abscisse = 0 :1/N :1 ; plot2d(abscisse,B,style=couleur) endfunction function [Y]= S_t(x,r,t_init,t,sigma) W_t = grand(1,1,"nor",0,t_init); h = t-t_init; W = W_t...
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// Example 10.2.a;//threshold quantum limit clc; clear; close; n=1;//efficiency for idea case ht=6.62*10^-34;//plank constt. f=3*10^14;//frequency in hertz B=10^7;//NO. OF BITS h=10^-6;//wavelength in metr BER=10^-9;//bit error rate Zm=-(log(BER));//probality of error Po=((20.7*ht*f*B)/(2*n))*10^12;//pulse e...