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//Kunii D., Levenspiel O., 1991. Fluidization Engineering(II Edition). Butterworth-Heinemann, MA, pp 491 //Chapter-14, Example 5, Page 353 //Title: Elutriation and Attrition of Catalyst //========================================================================================================== clear clc //I...
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clc clear //Initalization of variables v1=1234 //ft/s v2=532 //ft/s kb=0.92 alp=20 //degrees ve=900 //ft/s r=2200 //ft/s g=32.17 //ft/s^2 //calculations vr=sqrt(v1^2 +v2^2) vr2=vr*kb vrc=vr2*cosd(alp) W=(v1+vrc)*ve/g eta=W/(r^2 /(2*g)) *100 //results printf("Blade work = %d ft-lb/lb",W) printf("\n Ef...
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//Ex:2.16 clc; clear; close; temp_coeff=0.0005;//in per degree centigrade r_t1=680;//in ohm t1=20;//temperature diff. t2=90; r_o=r_t1/(1+(temp_coeff)*t1); r_t2=r_o*(1+(temp_coeff)*t2); printf("Resistance at %d degree = %f ohms",t2,r_t2);
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//Exa 4.10 clc; clear; close; //given data L=40*10^-2;// in m k=1.5;// in W/mK A=4;// in square meter alpha=1.65*10^-3;// in m^2/h //T = 50-40*x+10*x^2+20*x^3-15*x^4 , so // dtBYdx= -40+20*x+60*x^2-60*x^3 // d2tBYdx2 = 20+120*x-180*x^2 // Part (a) Heat entering the slab //q1= -k*A*dtBYdx , at x=0; qi= ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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// Calculate the guaranteed values of the resistance clc; R1=100; R1_le_perunit=0.5; // R1_le_perunit indicates dR1/R1 = 0.5% R2=1000; R2_le_perunit=0.5; R3=842; R3_le_perunit=0.5; Rx=R2*R3/R1; disp(Rx,'Value of resistance (ohm)=') Rx_le_perunit=R1_le_perunit+R2_le_perunit+R3_le_perunit; disp(Rx_le_perunit...
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function r=%bgspb(a,b) // perform logical elementwise a|b where a is a boolean sparse matrix // and b a boolean matrix r=sparse(a)|b
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clear; clc; x=.05; vs=1; vr=1; p=10; d=asin(p*x); qs=(vs^2/x)-(vs*vr*cos(d)/x); qs=round(qs*100)/100; qR=(vs^2/x)-(vs*vr*cos(d)/x); qR=round(qR*100)/100; q=(qs+qR); mprintf("%f+j%fpu",p,q);
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clear //Given m=1.67*10**-27 v=4*10**5 a=60 q=1.6*10**-19 B=0.3 //Calculation // r=(m*v*sin(a*3.14/180.0))/q*B P=v*cos(a*3.14/180.0)*((2*%pi*m)/(q*B)) //Result printf("\n (i) Radius of the helical path is %0.1f cm",r*10**3) printf("\n (ii) Pitch of helix is %0.2f cm",P*10**2)
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// Exa 5.35 format('v',6) clc; clear; close; // Given data V_DD= 10;// in V I_D= 0.4*10^3;// in A W= 100;// in µm L= 10;// in µm uACox= 20;// in A/V^2 Vt= 2;// in V R= poly(0,'R') V_GS= V_DD-I_D*R;// in V // Evaluation the value of R by using polynomial method, R= I_D-1/2*uACox*W/L*(V_GS-Vt)^2; R= roots...
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kolor = 5 importXcosDiagram("/home/evgeniy/Рабочий стол/СКБ/Введение в специальность/Новое/Segway/cart_3_clss.zcos"); xcos_simulate(scs_m, 4); subplot(3,2,1); xtitle("Угол Segway"); plot2d(outp.time, 180/%pi*outp.values(:,1),[kolor]); //subplot(3,2,3); //xtitle("Угол колес"); //plot2d(dtheta.time, 180/%pi*theta.values...
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// Example 9.7.a;//responsivity clc; clear; close; C=3*10^8;//SPEED of light in meter per second n=0.50;//quantum efficiency h=900;//wavelength in nano meter ht=6.62*10^-34;//plank constt. R=((n*h)/1248);//responsivity disp(R,"Responsivity is in ampere per watt")
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clc; clear; close; //pagec no 100 Rf=14*10^3;//in ohm Ri=2*10^3;//in ohm Av1=1+(Rf/Ri); disp(Av1,"Av1 is"); Av3=20*log10(Av1); disp(Av3,"Av1 in dB is"); Rf=18*10^3;//in ohm Ri=2*10^3;//in ohm Av2=1+(Rf/Ri); disp(Av2,"Av2 is"); Av4=20*log10(Av2); disp(Av4,"Av2 dB is "); Avt=Av3+Av4; disp(Avt,"Total Ga...
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clc //initialisation of variables w= 62.4 //lb/ft^3 d= 4 //in D= 0.0765 //lb/ft^3 Da= 8 //in vw= 1/13 nw= 20 va= 13 //ft/sec //CALCULATIONS na= nw*va*d^2/Da^2 //RESULTS printf ('power = %.f r.p.m ',na)
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// Exa 3.8 // TO find coverage radius of an access point. clc; clear all; SNRmin=12;//in dB n=3; //No of floors Backgroundnoise=-115; //dBm pt=100 //in dBm //solution pt_db=10*log10(pt); Sr=Backgroundnoise+SNRmin; //receiver sensitivity Lpmax=pt_db-Sr; //Refering table 3.4 Lp_d0=38; //ref path loss...
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p0:= PermList([2, 1, 11, 5, 4, 24, 12, 13, 14, 15, 3, 7, 8, 9, 10, 26, 18, 17, 25, 21, 20, 27, 28, 6, 19, 16, 22, 23, 30, 29, 32, 31]); p1:= PermList([6, 19, 1, 22, 23, 8, 2, 3, 4, 5, 20, 21, 7, 17, 18, 9, 27, 28, 13, 24, 25, 16, 26, 31, 32, 10, 29, 30, 14, 15, 11, 12]); p2:= PermList([3, 7, 4, 9, 10, 16, 5, 6, 1, 2, 1...
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clc; clear; s = poly(0, 's'); //--------------------- // Part a p1 = -1; p2 = %i; p3 = -%i; p4 = 2*%i; p5 = -2*%i; g = 1 / ((s-p1)*(s-p2)*(s-p3)*(s-p4)*(s-p5)); G = syslin('c', g); scf(); evans(G, 1000); xgrid(); //---------------------- // Part b shift = 5; g_shifted = 1 / ((s-p1 +shift)*(s-p2 +shift)*(s-p3 +shift)*(s...
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//exapple 9.7 clc; funcprot(0); // Initialization of Variable rhog=1200;//density of glycerol mu=1.45;//viscosity of glycerol pi=3.1428; g=9.81; rhos=2280;//density of sphere d=8/1000; s=0; uf=0.8*0.026; //calculation function[a]=intre() u=linspace(0,uf,1000); for i=1:1000 y=((pi/6*d...
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function y = f1(t,u1,u2) y = -4*u1-2*u2+cos(t)+4*sin(t); endfunction function y = f2(t,u1,u2) y = 3*u1+u2-3*sin(t); endfunction function [u1,u2] = rk4sist(a,b,h,u10,u20) [t] = a:h:b; u1 = zeros(length(t)) u2 = zeros(length(t)) u1(1) = u10; u2(1) = u20; for i=1:(length(t...
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//[f1,f2]=test_d(ue) //[f1,f2]=test_d(ue) // f1 est la dynamique linearisee //autour du point d'equilibre donne par equilcom(ue) //du systeme precedent observateur-controleur (voir simulcomp) // f2 est la valeur theorique de f1 (voir cours) //! deff('[yy,zdot]=fff(z,vv)',... ['u=1-k*z(3:4)'; 'yy=0'; 'xdot...
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# Adding to case 2 everything is stable and global information is correct # Drop the all nodes except fist and last nodes, now no explicit stab or fix_finger_table # predecessor and successor are correct but finger table stale, so call fix table on all to update # After fix everything is consistent add 0 add 1 add 2 ad...
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function [lambda,v] = Metodo_potencia_desl_inv(A,x0,alfa,epsilon) A = inv(A -alfa*eye(size(A,1), size(A,2))) //deslocamento e inversão da matriz [lambda,v] = Metodo_potencia(A,x0,epsilon) //lambda é autovalor de inv(A - alfa*I), então (alfa + 1/lambda) é autovalor de A lambda = alfa + 1/lambda end...
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// chapter 8 // example 8.23 // fig 8.43 // Find duty cycle, filter inductance and filter capacitance // page-514-515 clear; clc; // given Edc=14; // in V (dc source) E0=6; // in V (average output voltage) del_Vc=15; // mV (peak to peak ripple voltage) del_I=0.6; // in A (peak to peak ripple current) f=30; // in KHz (s...
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clear clc //to find speed of partical at r = 0 // GIVEN: //mass of Earth ME = 5.98e24//in Kg //radius of Earth RE = 6.37e6//in m //Gravitational constant G = 6.67e-11//in N.m^2/Kg^2 // SOLUTION: //applying newton's law of universal gravitation and law of conservation of energy //speed of partical at ...
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// Scilab code Ex1.1 : Pg:18 (2008) clc;clear; e = 1.6e-019; // Energy equivalent of 1 eV, J m = 0.05; // Mass of the golf ball, kg v = 20; // Velocity of golf ball, m/s h = 6.625e-034; // Planck's constant, joule-sec Lambda1 = h/(m*v); // de Broglie wavelength of a golf ball, m m = 1.67e-027; ...
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//Chapter 13, Problem 23, figure 13.83 clc; E=30; //e.m.f source r=1.5; //resistance in ohm Rl=r; I=E/(r+Rl); //current in ampere P=I^2*Rl; //power in watt printf("The circuit diagram is shown in Fig. 13.84.\n\n"); prin...
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clc disp("Example 3.54") printf("\n") disp(" Draw a DC load line for the base bias circuit neglecting Vbe") printf("Given\n") //given betadc=100 Rc=5*10^3 Rb=1.5*10^6 Vc=30 //to find Ib Ib=Vc/Rb //from ciruit //Ic value Icq=betadc*Ib //Vce value Vceq=Vc-(Icq*Rc) //to draw DC load line Ic1=Vc/Rc Vce1=...
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/////////////////////////////////////////////////////////////////////////////// // // // MONITEUR D'ENCHAINEMENT POUR LE CALCUL DE L'EQUILIBRE D'UN RESEAU D'EAU // // // ...
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clear;lines(0); // multiple plot without giving x x=[0:0.1:2*%pi]'; plot2d1("enn",1,[sin(x) sin(2*x) sin(3*x)]) // multiple plot using only one x xbasc() plot2d1("onn",x,[sin(x) sin(2*x) sin(3*x)]) // logarithmic plot x=[0.1:0.1:3]'; xbasc() plot2d1("oll",x,[exp(x) exp(x^2) exp(x^3)])
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global file_name; //get filename, path and extension [path,fname,extension] = fileparts(file_name); hid_dir = path + '.' + fname; select board_num case 2 then brdtype = ''; case 3 then brdtype = '_30a'; case 4 then brdtype = '_30n'; case 5 brdtype = '_30h'; else messagebox('Please select the FPA...
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vp=8; vm=vp/2; r=2.2*10^3; t=2*10^(-3); disp("Part a"); i=vm/r; disp("the peak value of the current (in mA) is"); disp(i*10^3); disp("Part b"); f=1/t; disp("the frequency (in Hz) is"); disp(f); disp("Part c"); w=2*%pi*f; disp("equation representing the current is i=1.82*sin(1000*π*t) mA.");
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function gui_callback() OutFormatVal = get(findobj("tag", "list_demo"), "string"); Out = get(findobj("tag", "list_demo"), "value"); disp(OutFormatVal(Out),"OutFormatVal is : " ); endfunction
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//example 5.1 clc; funcprot(0); clf() //initialization of variable Vth=3.6; Vgs=4;//voltage //volt change beyond 3.6 causes a major increase in Id as it is cut off voltage printf('Id=0 from 0 to 2 so not shown in the graph') x=linspace(2,3.6,300); y=(-2.5*(x-3.6))^.5; plot(x,y) xtitle('Vgs vs Id','Vgs','Id')...
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function [stk,txt,top]=sci_balance() // Copyright INRIA txt=[] if lhs==1 then t1=gettempvar(1) t2=gettempvar(2) txt=lhsargs([t1,t2])+' = balanc('+stk(top)(1)+')' stk=list(t1,'0',stk(top)(3),stk(top)(4),'1') else [t,b]=lhsvarsnames() txt='['+b+','+t+'] = balanc('+stk(top)(1)+')' stk=list(list('?','-2',stk(...
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function Y=Ymax() global YMAX Y=YMAX; endfunction
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//Chapter 13, Problem 17, Figure 13.62 clc; I1=15 //current source in ampere R1=6; //resistance in ohm R2=4; //resistance in ohm R3=2; //resistance in ohm R4=8; //resistance i...
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//Chapter-6,Example6_3,pg 6-63 //from plot 1 subdivision=0.2 units pp=2+3*0.2//positive peak np=2+3*0.2//negative peak Nd=pp+np//no. of divisions Vd=2*10^-3//volts per division Vpp=Nd*Vd Vm=Vpp/2 Vrms=Vm/sqrt(2) printf("peak value of voltage\n") printf("Vm=%.4f V\n",Vm) printf("RMS value of voltage\n") prin...
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// 22-3 clc; clear; //Power P P=40*10^3 //Watt n1=100; //rpm n2=400; //rpm //Speed factor Ks Ks=0.9+0.001*n2; //Clutch power Pc Pc=P*n2/(n1*Ks)*10^-3; // printing data in scilab o/p window printf("\nThe Speed factor is %0.1f ",Ks); printf("\nThe clutch poweris %0.0f KW",Pc);
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clc clear printf("Example 10.7 | Page number 354 \n\n"); //Find all thermodynamic properties //Given data p = 15 //bar u = 2594.5 //kJ/kg //Solution //From saturated steam table based on pressure at p = 15 bar hf = 844.87 //kJ/kg hg = 2792.1 //kJ/kg vf = 0.001154 //m^3/kg vg = 0.13177 //m^3/kg uf = hf-100*...
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// Function Name: repMat // Generate a matrix by replicating matrix A in a block-like fashion // The generated matrix has the following size: // n_rows = num_copies_per_row * A.n_rows // n_cols = num_copies_per_col * A.n_cols // 3rd parameter = num_copies_per_row // 4th parameter = num_copies_per...
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clc; //page no 114 //prob no 3.6 B=10*10^3; // maximum modulation freq is given as fm=B/2; disp('Hz',fm,'The maximum modulation freq is');
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//This problem solves sustem of nonlinear equations using fsolve //Reference: A. Golbabai, M. Javidi,Newton-like iterative methods for solving system of non-linear equations,Applied Mathematics and Computation,Volume 192, Issue 2,2007,Pages 546-551,ISSN 0096-3003,https://doi.org/10.1016/j.amc.2007.03.035.(http://www.sc...
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clc clear //input data c =2.25//Chord length of an aerofoil in m l=13.5//Span of the aerofoil in m C=125//Velocity of the aerofoil in m/s Cl=0.465//Lift coefficient Cd=0.022//Drag coefficient d=1.25//Density of the air in kg/m^3 //calculations A=c*l//Area of cross section of the aerofoil in m^2 W=Cl*d*((C^...
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// Example 4.10 : Small signal analysis V_t=1.5; // (V) K=0.00025;//K= k_nW/L (A/V^2) V_A=50; // (V) I_D=1.06*10^-3; // (A) V_D=4.4; // (V) R_D=10000; // (ohm) R_L=10000; // (ohm) V_GS=V_D; g_m=K*(V_GS-V_t); r_o=V_A/I_D; A_v=-g_m*(R_L*R_D*r_o)/(R_D*R_L+R_D*r_o+R_L*r_o); disp(A_v,"Voltage gain (V/V)") R_G=1...
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errcatch(-1,"stop");mode(2);// Aim:To find absolute pressure on skin diver of Example 2-5 // Given: // Gage Pressure: Pg=26; //psi exit();
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// chapter 14 // example 14.12 // Determine the range of frequencies of the chopper // page-893 clear; clc; // given I=80; // in A E=480; // in V N=960; // in rpm Ra=0.25; // in ohm (armature resistance) Rf=120; // in ohm (field resistance) N1=400, N2=750; // in rpm (range of speed) Ton=3; // in ms Ef=480; // in V // c...
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x=0.1 y=0.2 MAcid=98.1 MS=32 MSalt=142 MBase=40 MWater=18 MNa=46 basis=1000 //g T2=35 T1=25 T3=40
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exec macros/show.sci exec macros/imshow.sci exec macros/modified_if.sci exec macros/cmp.sci exec loader.sce //exec Octave/loader.sce exec macros/il2mat.sci exec macros/mat2il.sci exec macros/phantom.sci exec macros/para2fan.sci S = dir('macros/m/') for x=1:size(S(2), 1) exec('macros/m/'+S(2)(x)) end clear S clear x
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clear clc Z=[.2 .2 .05]' * %i S=30 V=11 I=S*1e6/(sqrt(3)*V*1e3) E=1 Ia1=E/(Z(1)+Z(2)+Z(3)) If= 3*abs(Ia1) * S*1e6/(sqrt(3)* V*1e3) Ia2=Ia1 Ia0=Ia1 a=exp(%i * 2 * %pi/3) A=[1 1 1 1 a^2 a 1 a a^2 ] Va1=E-Ia1*Z(1) Va2=0-Ia2*Z(2) Va0=0-Ia0*Z(3) Vp=[ Va0 Va1 Va2]' v=A*Vp vab=v(1)-v(2) vbc=...
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//EXAMPLE 2-23 PG NO-71 A=%pi/2; //[integrate('0',wt,'%pi/3')]^2=%pi/9 //integrate('%pi/3',wt,'%pi/2')=%pi/6; E=1/A*[(%pi/9)+(%pi/6)]; disp('i) Energy (E) is = '+string (E) +' '); disp('ii) Square Energy (E) is = '+string (sqrt(E)) +' '); ...
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function [X,dim]=range(A,k) // Computation of Range A^k ; the first dim columns of X span the // range of A^k. //F.D. //! if k==0 [n,n]=size(A); dim=n;X=eye(A);return; end [U,dim]=rowcomp(A);X=U; if k==1 return; end for l=2:k A=A*U'; [U,dim]=rowcomp(A(:,1:dim)); X=U*X; end;
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//To find gyroscopic couple and reaction clc //Given: I=180 //kg-m^2 D=1.8, R=D/2, x=1.5 //m v=95*1000/3600 //m/s t=0.1 //s //Solution: //Gyroscopic couple set up: //Calculating the angular velocity of the locomotive omega=v/R //rad/s //Calculating the amplitude A=1/2*6 //mm //Calculating the maximum veloc...
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// Chapter6 // Page.No-193, Figure.No-6.4(c) // Example_6_2_b // Max output voltage swing // Given clear;clc; R1=100*10^3;R2=100*10^3;R3=100*10^3;Rf=1*10^6;Rin=50; Ci=0.1*10^-6; // Capacitance b/w 2 stages being coupled Ro=Rin; // ac output resistance of the 1st stage UGB=10^6; // Unity gain bandwidth Vcc=15;...
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// MCP2200: Communication block to configure Serial Communication // and intereact with GPIO pins function [x,y,typ] = MCP2200(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then exprs=arg1.graphics.exprs; baudrate = exprs(1); pin_in = exprs(2); ...
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function x = my_laguerre(a,tol) // start from random number x = rand() n = length(a) - 1 MaxIter = 30 for i = 1:MaxIter [p, dp, d_dp] = evalpoly(a, x) if abs(p) < tol return end g = dp/p h = g*g - d_dp/p f = sqrt( (n-1)*(n*h - g*g) ) if abs(g + f) >= abs(g - f) dx = ...
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au2km=149598000; zoomf=2000; planetorbitcolor=color(0.0,0.3,0.6,1); function createstarback() { starbackframe=root.SC.Universe.addsubframe("StarBackFrame"); starbackframe.nearclipplane=5000*au2km; starbackframe.farclipplane=100000*au2km; tx=starbackframe.createtexture("star",DataDir+"\textures\star2.bmp");...
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c=eye(5,5) s=[1 2 3] e=c(2,:) if(e(1,:)==c(1,:)) printf("no") else printf("yes") end if(sum(s)~= 0) printf("great") end
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clc //initialisation of variables D= 64 //lb/ft^3 d= 6 //ft l= 10 //ft W= 2 //tons //CALCULATIONS V= W*2240/D h= V/(%pi*d^2/4) BM= d^2/(16*h) P= -(sqrt(64*BM*2*10*%pi*(22400-%pi*d^4))-W*22400)/10 //RESULTS printf ('Minimum pull required= %.f lbs ',P+3)
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PL/SQL Developer Test script 3.0 8 -- Created on 13.05.2020 by ÀÍÄÐÅÉ declare test_period date; test_return cashback_analyzer.cashback_list; begin test_period := to_date('13052020','ddmmyyyy'); test_return := cashback_analyzer.getReportForMonth(test_period); end; 0 0
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//Ex no.17.4,Page no.381 clc;clear;close; //Initilization of Variables sigma_t=100 //MPa //tensile stress P=170 //KN //Load //Calculations //For equal stress in the welds A and B, the load shared by the fillet welds will be proportional to size of weld //t_a=0.7*s //Effective throat thickness of weld A in upper pl...
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clc //initialization of varaibles P1=100 //psia T1=2000+460 //R P2=15 //psia g=1.4 cp=0.276 cv=0.207 T2=1520 //R //calculations h1=634.4 pr1=407.3 pr2=pr1*P2/P1 disp("From table 1,") T2=1535 //R h2=378.44 dh=h2-h1 v2=53.34*T2/(P2*144) dv=v2-v1 //results printf("Enthalpy change = %.2f B/lb",dh) prin...
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function y=f(x) y = x^2 -1 endfunction
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clc; v=2000; // rated voltage of motor xsm=2; // synchronous reactance of motor xsg=3; // synchronous reactance of generator xt=1.5; // transmission line reactance ia=100; // current drawn by motor pf=1; // power factor disp('case a'); vt=v/sqrt(3); // rated per phase voltage Efm=floor(sqrt(vt^2+(ia*xsm)^2)); ...
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# Header Info ########################################## pulse_width = 5; write_codes = false; response_matching = simple_matching; active_buttons = 2; button_codes = 100,255; default_text_color = 255, 255, 255; default_background_color = 128, 128, 128; no_logfile = true; # Begin SDL portion of code ###########...
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clc pathname=get_absolute_file_path('6_6_2.sce') filename=pathname+filesep()+'662.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") disp("Mass balance") printf("ms + %d = mE + mR",basis) disp("acetone balance") printf("%f *...
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ex_7_4.sce
//Example 7.4 // solar energy clc; clear; //given data : r=1.5D11;//distance from sun to earth P=3.8D26;//power radiated by sun N=P/(4*%pi*(r^2));// poyting vector (average energy) N=N*60/4.2D4 ;//to convert watt/m2 into cal/cm2.min N=ceil(N); disp(N," average solar energy in cal/cm2.min")
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function sal=info_mutua(pc,pe) px0=0.5; px1=0.5; pyx00=pc; pyx11=pc; pyx10=pe; pyx01=pe; pyxb0=1-pc-pe; pyxb1=1-pc-pe; py0=px1*pyx01+px0*pyx00; py1=px0*pyx10+px1*pyx11; pyb=px0*pyxb0+px1*pyxb1; pxy01=px0*pyx10*log2(py1/(px0*pyx10)); pxy10=px1*pyx01*log2(p...
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example4_5.sce
clear; clc; // Stoichiometry // Chapter 4 // Material Balances involving Chemical Reaction // Example 4.5 // Page 121 printf("Example 4.5, Page 121 \n \n"); // solution v = 1 //[l] water (basis) // 1 mol (100mg) CaCO3 gives 1 mol (56) Cao // use table 3.3 and eg 3.9 x = 56*390.6/100 //[mg/l] lime ...
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errcatch(-1,"stop");mode(2);// Example 3.10 page no-170 Vdc=(100/(2*%pi))*(-cos(5*%pi/6)+cos(%pi/6)) printf("\nVdc=%.1f V",Vdc) Vrms=sqrt(3.1)*Vdc printf("\nVrms=%.1fV",Vrms) exit();
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//Exa 11.7 clc; clear; close; //Given Data : format('v',9); MaxDemand=500;//in KW LoadFactor=70;//in %/year LoadFactor=70/100;//in fraction cosfi=0.8;//unitless //(i) Rs. 80/KVA of max demand //(ii) Running chargeare 5 paise/kwh C1=80;//in Rs./KVA C2=5;//in paisa/kwh AvgLoad=MaxDemand*LoadFactor;//in KW ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 4, Example 13") disp("Let: rh = hub radius") disp(" rt = tip radius") disp("The flow area of the impeller inlet annulus is:") rh ...
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Chapter4_Example4.sce
//Chapter-4, Illustration 4, Page 165 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA P1=2.2;//Pressure at entry in MN/(m^2) T1=533;//Temperature at entry in K P2=0.4;//Pressure at exit in MN/(m^2) m=11;//mass fl...
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//Chapter 12: Polymers and Polymerization //Problem: 1 clc; //Declaration of Variable Mwt = 21150 // in g per mol // Solution m = 2 * 12 + 3 * 1.008 + 1 * 35.45 // g per mer n = Mwt / m mprintf("The degree of polymerization is %d",n)
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subplot(211); w=logspace(-1,2,100); // de 10^-1 ate 10^2 com 100 pontos w = w/w0 H = 1 ./ (1+%i*w); plot2d(w,abs(H),logflag="ln"); xlabel("rad/s"); ylabel("modulo de H"); xgrid; subplot(212); plot2d(w,(atan(imag(H),real(H)))*180/%pi,logflag="ln"); xlabel("rad/s"); ylabel("fase de H"); xgrid
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 11 Example 10") Q=2.86*3.5;//refrigeration effect in KJ/s N=1200;//compressor rpm n=1.13;//compression index disp("properties of Freon-12,") disp("at -20 degre...
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function d=projaff(x,y,pt) // projaff - projection d'un point sur une droite //%Syntaxe // d=projaff(x,y,pt) //%Parametres // x: vecteur des abscisses des 2 points definissant la droite // y: vecteur des ordonnes des 2 points definissant la droite // pt: coordonnes du point a projeter [abscisses ordonnees] //%Methode /...
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clear //Given // d_pins = 0.375 //inch load1 = 3 //kips AB_x = 6 //inch,X-component AB_y = 3 //inch,Y-component BC_y = 6 //inch,Y-component BC_x = 6 //inch,X-component area_AB = 0.25*0.5 //inch*2 area_net = 0.20*2*(0.875-0.375) //inch*2 area_BC = 0.875*0.25 //inch*2 ...
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//chapter 18 //example 18.6 //page 578 clear all; clc ; //given VB1B2=15; eta=0.7;//intrinsic standoff ratio ec=0.7+(eta*VB1B2);//capacitor voltage VEB1sat=2.5;//saturation voltage when capacitor is discharged Eo=2.5;//capacitor voltage at start of each charging cycle t=0.1*10*log((15-2.5)/(15-11.2)); f=100...
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-- VectorCAST 19.sp1 (06/26/19) -- Test Case Script -- -- Environment : SIMPLE_TEST -- Unit(s) Under Test: manager -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCRIP...
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//Chapter 10 : The Minimum Polynomial //Example 10.2 //Scilab 6.0.1 //Windows 10 clear; clc; A=[5 -6 -6;-1 4 2;3 -6 -4] disp(A,'A=') A1=A-eye(3,3) A2=A-2*eye(3,3) Af=A1*A2 disp(Af,'(A-I3)(A-2I3)=') mprintf('\n =0') mprintf('\n it follows that ma(X)=(X-1)(X-2)')
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// Theory and Problems of Thermodynamics // Chapter 4 // Energy Analysis of Process // Example 2 clear ;clc; //Given data V = 0.3 // Volume of container in m^3 P1 = 0.2 // Initial Pressure in MPa power = 200 // Power of electric motor in watts t = 15 // electri...
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//calculating solubility //Example 6.5 clc clear Ecell=0.169 AgC=0.01 C1=AgC/(10^(Ecell/0.0591)) S=C1*143.5//solubility of AgCl in g/L Ksp=C1^2//solubility product of AgCl in Mol^2/L^2 printf('Thus solubility of AgCl = %e g/L',S) printf('\n and Ksp = %e Mol^2/L^2',Ksp)
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load('C:\Users\tangu\OneDrive\Documents\GitHub\Modelisation\TD4\NetworkData.sod') // Extraction des temps de service index_bool = ( data(:, 3) == 1 ) tabS1 = data(index_bool, :) t_s1 = tabS1(1:$,4); function q = quantile(l,p) q = -log(1-p)/l endfunction lambda=1/mean(t_s1); n = 10; C = zeros(1, n + 1) C(1) = 0;...
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//7.20 clc; r2s=0.32; r1=0.64; x2s=0.48; x1=1.1; s=r2s/(r1^2+(x1+x2s)^2)^0.5; printf("\nSlip=%.4f ",s) V1=400/3^0.5; Tmax=1.5*V1^2/(2*%pi*25)*(1/(r1+(r1^2+(x1+x2s)^2)^0.5)) printf("\nMaximum Torque=%.2f Nm",Tmax) n=25*(1-s); N=n*60; printf("\nSpeed=%.2f rpm",N) disp('at 25 Hz') x1=0.55; x2s=0.24; s=r2s...
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style.displayedLabel="wta_new" pal2=xcosPalAddBlock(pal2,"wta_new",[],style);
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#************************************************************ # Scenario of Test # # date : Fri Jun 5 10:45:20 2009 #************************************************************ p3d_sel_desc_name P3D_ENV Test p3d_sel_desc_name P3D_ROBOT barre p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0....
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// load the data load("edsonjLTImodif.sod","X","U","sys") // load the data load("edsonjLTIanalitmodif.sod","sysa") // obtaingin the matrices A,B,C,D A=sys.A B=sys.B C=sys.C D=sys.D //matrices Aa,Ba,Ca,Da de forma linealizada Aa=sysa.A Ba=sysa.B Ca=sysa.C Da=sysa.D // pregunta 7 Controllability and O...
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geraFourier.sci
function geraFourier(T, A, coef) // Intervalo (vetor com 2/passo posições) passo = 0.001; t = -1:passo:1; // Frequência Angular 2*%pi*(1/T) w = 2*%pi; // Número de bits 1 no período Ts = 1; // Definir o tamanho do f (cria um vetor com o mesmo tamanho de t) f = ...
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clc clear printf("example 2.6 page number 73\n\n") //to find the volume of air volume_H2=0.5 //in m3 volume_CH4=0.35 //in m3 volume_CO=0.08 //in m3 volume_C2H4=0.02 //in m3 volume_oxygen=0.21 //in m3 in air //required oxygen for various gases H2=0.5*volume_H2; CH4=2*volume_CH4; CO=0.5*volume_CO;...
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clc //initialisation of variables m= 4 //kg/s R= 8.314 //J/mol K M= 29 //gms k= 1.4 T1= 27 //C p2= 1800 //kPa p1= 105 //kPa n= 1.22 cp= 1.4 //Jmol K //CALCULATIONS T2= (273.15+T1)*(p2/p1)^((n-1)/n) W= m*k*(R/M)*((273.15+T1)/(k-1))*(1-(p2/p1))^((k-1)/k) Q= -m*R*(273.15+T1)*log(p2/p1)/M W1= m*(R/M)*n*((273...
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pathname=get_absolute_file_path('5_7.sce') filename=pathname+filesep()+'5_7data.sci' exec(filename) clear delY=(W*L^4)*((11/(24*EI))+ 1/(2*GJ)); delZ=(W*L^4)*((1/(6*EI))+ 1/(2*GJ)); printf("\ndel Y %f mm",delY); printf("\ndel Z %f mm",delZ);
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clc clear //Input data p1=20//pressure in bar T1=300+273//Tempereture in K p2=3//pressure in bar m=0.3//Flow rate in kg/s n=1.3//Adiabatic constant Cd=0.98//Coefficient of discharge Cv=0.92//Coefficient of velocity //Calculations vo=0.1255//Specific volume in m^3/kg px=(0.546*p1)//Critical pressure in ba...
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clc;funcprot(0);//EXAMPLE 20.12 // Initialisation of Variables n=2;........//No of cylinders ma=16;........//Mass of air supplied per min in kg p1=1;........//Suction pressure in bar t1=288;.......//Suction temperature in K k=0.04;.......//Clearance ratio ni=1.3;........//Compression index R=0.287;........//Ga...
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv //Mandel, Denis, Ali Abdollahzadeh, Didier Maquin, and Jos� Ragot. 1998. //Data reconciliation by inequality balance equilibration: a LMI approach. //...
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8_9.sce
clear; clc; funcprot(0); //Example - 8.9 //Page number - 304 printf("Example - 8.9 and Page number - 304\n\n"); //Given //At 1 bar, 310 K H_1 = 310.38;//[kJ/kg] //At 200 bar, 310 K H_2 = 277.7;//[kJ/kg] //At 1 bar, Saturated liquid H_7 = -122.6;//[kJ/kg] //At 1 bar, Saturated vapour H_8 = 77.8;//[kJ/...
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funcionSeno.sci
// format(10) function [y, t] = funcionSeno(tinicio, intervalo, tfin) t = tinicio:intervalo:tfin; y = sin(t); // plot(t,y,'color','red','marker','>'); // xlabel("t, seg"); // ylabel("y, amplitud"); // set(gca(),"grid",[1 1]); endfunction
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// Scilab Code Ex3.10: Page-91 (2006) clc; clear; N = 6.023e+023; // Avogadro's number, per kmol e = 1.602e-019; // Energy equivalent of 1 eV, J/eV k = 1.38e-023; // Boltzmann constant, J/K R = N*k; // Molar gas constant, J/kmol/K E_F = 7; // Fermi energy of Hf, eV theta_D = 343; // Debye temperature o...
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//In this program, new parameters are introduced to account for the physical characteristics //of the system: we imagine a small particule imersed in a fluid that suffers a large number of //independent identically distributed collisions modulated by a small time step, as well as a //dampening factor introduced by the...
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P1 = 1.013; P2 = 1.5*P1; Vs = 0.03; Va = Vs; WD = (P2-P1)*Vs*100; Pi = (P1+P2)/2; g = 1.4; Aa = ((g*P1*100*Vs)/(g-1))*((Pi/P1)^((g-1)/g)-1); Vb = Va *(P1/Pi)^(1/g); Ab = Vb*(P2-Pi)*100; WR = Aa+Ab; disp("kJ/rev",WR,"Work required is")