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clc // Given that lambda = 6000 // wavelength of light in angstrom e = 0.14 // Width of slit in mm y = 1.6 // Separation between second dark bend and center in cm d = 2 // Linear distance in mm // Sample Problem 2 on page no. 137 printf("\n # PROBLEM 2 # \n") printf(" Standard formula used \n") printf(" lambd...
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//to find the velocity and acceleration of the piston along the cylinder, the angular velocity and angular acceleration of the connecting rod cp and the coriolis component of the acceleration of P clc //given OC=3//inches CP=9//inches N=1200 //rpm (clockwise) X=55 //degrees //from the figure 66 OP=10.35//inches...
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function respfreq = get_fourier_transform(som) //TRANSFORMADA DE FOURIER fs = 88200; f = (0:length(som)-1)*fs/length(som); //vetor das frequ�ncias dispon�veis no som freq = f(1:round(length(f)/2)); //vetor das frequ�ncias propriamente ditas SOM = abs(fft(som)); //transformada de fourier criando vetor respostas SOM = S...
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<?php require 'root.php'; include_once ROOT.'mesclasses/classeprincipale.php'; define("TITRE","Nouveau [[NOM_TABLE]]"); define("FOND_TITRE", ROOT.'images/icones/icon-48-user.png'); $sous_menu=array( 1=>array('type'=>'annuler', 'chemin'=>ROOT."appl/[[NOM_TABLE]]/index.php"), ); include_once ROOT.'appl/layouts/tete.p...
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// Example 2.12;Acceptance Angle clc; clear; close; NA=0.4;// Numerical Aperture r= 50;// Angle at which angle changes for skew rays in degreee m=cosd(r); Oas=asind(NA/m) disp(Oas," ACCEPTANCE ANGLE FOR SKEW RAYS IN DEGREE")
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function [x,cout]=linprog(A,b,C,d,c,x0) // Copyright INRIA // Generated by lmitool on Thu Feb 02 16:32:14 MET 1995 Mbound = 1e3; abstol = 1e-10; nu = 10; maxiters = 100; reltol = 1.e-10; options=[Mbound,abstol,nu,maxiters,reltol]; /////////////////DO NOT REMOVE THIS LINE x_init=x0; [nx,nx]=size(A); /////////...
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_________ | | | | | | | | | | | | |_________|
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n=1:100 x=2*cos(4*%pi*n/20) figure plot(x)
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clc; Cgd=0.000000000004; Gm=0.0025; rD=5600; CinM=Cgd*(Gm*rD+1); disp('Farad',CinM,"CinM=")//The answers vary due to round off error
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 21 disp("CHAPTER 8"); disp("EXAMPLE 21"); //VARIABLE INITIALIZATION p_o=10*1000; //in Watts P=6; //number of poles E_g=200; //in Volts N=1500; //in rpm A=P; //si...
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//Example 16.8 clc Energy=1.2*10^3//in J c=1.1*10^-4//in f delta_v=sqrt((2*Energy)/c) disp("solution a") disp(delta_v,"Energy stored in volt") disp("solution b") Energy_deliverd=600//in j delta_t=2.5*10^-3//in s p=(Energy_deliverd)/delta_t disp(p,"power in watt=")
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//the examples are continuously numbered in textbook. This is the second example in chapter 2 as first example cannot be codded in scilab. //Example 2_12 page no:146 clc; //given weight = 391000;//in kg no_of_motor = 12; no_of_motors_parallel = 6; tot_tractive_effort = 171000;//in N line_voltage = 600;//in V ...
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> print(layouts[1024]) rm4@8@11@14@15.tem ------------- | | | ----- ----- | | | - - ----- | | | | ------------- undefined const fs = require("fs") const clslmat = require("./lmat") const clsdesc = require("../desc/desc.js") const clscmmn = require("./cmmn") const clspt = require("./pt") ...
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//Example No. 11_05 //Differentiation of tabulated data //Pg No. 358 clear ;close ;clc ; T = 5:9 ; s = [10 14.5 19.5 25.5 32 ]; h = T(2)-T(1); n = length(T) function V = v(t) if find(T == t) == 1 then V = [ -3*s( find(T == t) ) + 4*s( find(T==(t+h)) ) - s( find( T == (t+2*h) ) ) ]/(2*h) //Th...
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clc,clear printf('Example 1.28\n\n') I_L=100 P=4 //Poles A=P //for lap wound armature W_b=1.4,W_m=0 //Brush width and width of mica insulation N=1400//armature speed in r.p.m segments=64 //no of commutator segments L=0.05*10^-3 //inductance of armature coil in henry n_s=N/60 //speed in r.p.s v=n_s*segments...
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//example 3.5(a)// //3 input to exor// clc //refreshes all variables// clear //clears the screen// disp('in the figure output of first gate is exor of A and B. output of second gate is exor output of earlier two gates where A B C are inputs to the system') //result//
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function []=sci2map(a,nom) //! [lhs,rhs]=argn(0) if rhs<>2 then error('sci2map: 2 input parameters!');end; t__=gen_map(nom,a), // on sauvegarde si ce n'est pas une macro if type(a) <> 11 then if type(a) <> 13 then // unit=file('open',b_2_m,'unknown') // file('last',unit) nt=size(t__);for i=1:nt, writ...
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// Example 2.16 A business firm receives on an average clc; clear; m=2.5; disp(m,"Average call ="); function value = poisson(m, x) value = (exp(-m)*(m^x))/(factorial(x)); endfunction X_0=poisson(m,0); X_4=poisson(m,4); disp(X_0,"Probability of no call is "); disp(X_4,"Probability of exactly 4 call is ");
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// Script to load the serial gateway dynamic library. // Author: Errico Guidieri, Evidence Srl. // -------- Modules to be imported ---------- // Link to import the selected modules of the library serial_gateway_link_num = link(get_absolute_file_path('loader.sce') + 'Release\lib_serial_gateway.dll', 'serial_gate...
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function []=systems() function [xdot]=bioreact(t,x) //[xdot]=bioreact(t,x) // modele de bioreacteur // x(1): concentration de biomasse // x(2): '' de sucre //! xdot(1)=mu_td(x(2))*x(1)- debit*x(1); xdot(2)=-k*mu_td(x(2))*x(1)-debit*x(2)+debit*x2in; function [y]=mu_td(x) //[y]=mu_td(x) // mu : taux sp...
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clear; clc; // Example 1.3 printf('Example 1.3\n\n'); //Page no. 17 // Solution //(a) // Converting all terms to same unit nm = 10^(-9);//[meters] m1 = 10;//[decimeters] dm = (1.8*nm*m1)/(1*1);//[decimeters] printf('(a) 1.8 nanometers is equal to %.2e dm.\n',dm); //(b) m2 = 39.37;//[inches] in = (1....
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//(Threaded Joints) Example 7.16 //Refer Fig.7.35 on page 256 //Yield tensile strength of 30C8 Syt (N/mm2) Syt = 380 //Young's modulus of 30C8 E1 (N/mm2) E1 = 207000 //Young's modulus of aluminium E2 (N/mm2) E2 = 71000 //Initial pre-load in the bolt Pi (kN) Pi = 5 //External force acting on the bolted joint...
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clear ; clc; // Example 3.13 printf('Example 3.13\n\n'); printf('Page No. 73\n\n'); // given Cash_out = 80000;// Present value of cash outflow for project F in Pound n = 5;// years Cash_in= [50000 40000 30000 20000 10000]// Cashn in \flow for project F in Pound NPV = 0;//At the end of 5 years //Let the un...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 9.13w //calculation of the final velocity of the shuttle //given data v1=4000//speed(in km/hr) of shuttle with respect to the earth v2=100//speed(in km/hr) of the module with respect to the shuttle //calculation M...
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// Scilab Code Ex2.40: Page-96 (2008) clc; clear; mu_0 = 4*%pi*1e-007; // Absolute magnetic permeability of free space, N/ampere-square I1 = 30; // Current through the first wire, A I2 = 40; // Current through the second wire, A x = 2; // Separation distance between two wires, m F = mu_0/(4*%pi)*2*I1*I2/x...
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//9b clf champ1(1:10, 1:10, rand(10,10), rand(10,10), 1.0)
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errcatch(-1,"stop");mode(2);//ex7.6 I_D=6.25*10^-3; V_GS=-5; R_G=abs((V_GS/I_D)) disp(R_G,'Gate resistance in Ohms') exit();
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//subtraction using 1's complement// //Example 21.b// //subtraction in one's complement using 8 bits// clc //clears the window// clear //clears all the existing variables// x='1011' y=bin2dec('1011') z=bin2dec('0101') c=(bitcmp(z,4));//finding 1's complement// a=y+c+1 a=a-bin2dec('10000'); a=dec2bin(a,4);/...
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//Exa 12.3 clc; clear; close; //given data : D=30000;//in units/year Cc=2;//in Rs./unit/year Co=100;//in Rs./orde Cs=12;//in units/year EOQ=sqrt(2*Co*D*(Cs+Cc)/(Cc*Cs));//in units Q=round(EOQ);//units disp(Q,"Ordering quantity in units : "); Q1=sqrt(2*Co*D*Cs/(Cc*(Cs+Cc)));//in units disp(round(Q1),"Maximu...
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clc; clear all; a=imread('color.jpg'); subplot(1,3,1); title('Original image'); imshow(a); b=rgb2gray(a); c=im2double(b); subplot(1,3,2); title('Grayscale image'); imshow(b); s=log1p(c); x=255/(max(max(s))); s1=x*s; u=uint8(s1); subplot(1,3,3); title('logarithm image'); imshow(u);
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//Example 5_8 page no:198 clc funcprot(0) function [r,th]=rect2pol(x,y) //rectangle to polar coordinate conversion r=sqrt(x^2+y^2); th=atan(y,x)*180/3.14; endfunction function[x,y]=pol2rect(r,theta) x=r*cosd(theta) y=r*sind(theta) endfunction [Rr,Ri]=pol2rect(50,0) R=Rr+(%i*Ri) [Xlr,Xli]=pol2rect(...
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// scilab Code Exa 9.1 Calculation on multi stage turbine d=1; // mean diameter of the impeller blade in m T1=500; // Initial Temperature in degree C t1=T1+273; // in Kelvin p1=100; // Initial Pressure in bar N=3e3; // Speed in RPM m=100; // in kg/s alpha2=70; // exit angle of the first stage nozzle blades ...
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clc clear //input r=20;//pure resistance connected in parallel with a pure inductance in ohms l=0.08;//pure inductance in henry v=240;//supply voltage in volts f=50;//supply frequency in hertz //calculations i1=v/r;//current in resistive branch in amperes i2=v/(2*%pi*f*l);//current inductive branch in ampe...
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function full_path=get_subobj_path(path) // path : vector of integer gives the path of the required block from // top level (main diagram) to bottom level (required block). // Each vector entry is a block index in the current level structure. // full_path : is the path relative to scs_m ...
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s=%s T1=1*3*6*1 T3=1*2*5*1 T2=1*4*7*1 T4=1*2*(1/(s+1))*1*6 T5=1*2*(1/(s+1))*(1/(s+1))*7*1 T6=1*3*(1/(s+1))*7*1 delta=1 del1=1 del2=1 del3=1 del4=1 del5=1 del6=1 TF=(T1*del1 + T2*del2 + T3*del3 + T4*del4 + T5*del5 + T6*del6)/delta disp(TF,"Y/R = ")
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clear; clc; printf("\nEx7.3\n"); //page no.-218 //given V=29.7*10^-6;........//potential difference in volt d=4*10^-2;...........//width of copper strip in m I=100;...............//current in A B=2;.................//magnetic field of induction in weber/m^2 e=1.6*10^-19;........//charge in coulumb A=2*10^-5;....
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//Problem 41.01: The ratio of output power to input power in a system is //(a)2 (b) 25 (c) 1000 and (d) 0.01 //Determine the power ratio in each case (i) in decibels and (ii) in nepers. //initializing the variables: //ratio of output power to input power rp1 = 2; rp2 = 25; rp3 = 1000; rp4 = 0.01; //calcul...
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@relation vehicle @attribute COMPACTNESS integer[73,119] @attribute CIRCULARITY integer[33,59] @attribute DISTANCECIRCULARITY integer[40,112] @attribute RADIUSRATIO integer[104,333] @attribute PRAXISASPECTRATIO integer[47,138] @attribute MAXLENGTHASPECTRATIO integer[2,55] @attribute SCATTERRATIO integer[112,265] @attri...
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@relation .a/actual_final/actual_final @attribute Identification{'7f_45_4c_46_01_01_01_00_00_00_00_00_00_00_00_00','7f_45_4c_46_02_01_01_00_00_00_00_00_00_00_00_00','7f_45_4c_46_01_01_01_03_00_00_00_00_00_00_00_00','7f_45_4c_46_01_02_01_00_00_00_00_00_00_00_00_00','7f_45_4c_46_02_01_01_03_00_00_00_00_00_00_00_00','7f_...
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// generated by [dll_builder]: Please do not edit this file // ------------------------------------------------------ flexsim_path=get_absolute_file_path('loader.sce'); link(flexsim_path+'libflexsim.dll',['rt_sinus','rt_square','rt_step','rt_randm','rt_adcin','rt_buzzer','rt_gpin','rt_gpout','rt_lcd','rt_led','rt_p...
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clc clear //Initialization of variables Q=350 //gal/min D=6 //in rho=0.84 gam=62.4 g=32.2 //ft/s^2 mu=9.2e-5 //lb-sec/ft^2 L=5280 //ft //calculations V=Q/(7.48*60*%pi/4 *(D/12)^2) Nr=V*D/12 *rho*gam/g /mu f=0.3164/(Nr)^0.25 hl=f*L*12/D *V^2 /(2*g) hp=hl*gam*Q*rho/(550*7.48*60) //resu;ts printf("Horsepo...
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// find gate-source cutoff voltage and transconductance // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 13-12, page 447 clear; clc; close; // Given data Idss=5*10^-3;// maximum drain current in amperes gmo=5000*10^-6;// maximum transcon...
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function [img_ret]=cv_equalizeHist_path(path) pyImport equalizeHist_file img_ret=equalizeHist_file.equalizeHist_path(path) endfunction
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//Example 11.3.2 Page 407 //Non-Linear Dynamics and Chaos, First Indian Edition Print 2007 //Steven H. Strogatz clear; clear; clc; close; // m = number of copies. // r = scale factor. m=4; r=3; d=log(m)/log(r) //End of Example.
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clear;lines(0); mulf('1','a') mulf('0','a') 'a'+'b' //Caution...
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function [x,y]=polar_to_cart(r,theta) theta=theta/180*%pi x=r*cos(theta) y=r*sin(theta) endfunction I=4 w=500 [Ir,Ic]=polar_to_cart(3,40) Ix=complex(Ir,Ic) C=1E-3 L=10E-3 Xl=w*L*%i Xc=1/(w*C*%i) Il=I-Ix Ic=Ix Vc=Ic*Xc Vl=Il*Xl Vx=Vl-Vc disp(Vx) //answer wrong in the book
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function [tree] = sci_str2mat(tree) // Copyright INRIA (Generated by M2SCI) // Conversion function for Matlab str2mat() // Input: tree = Matlab funcall tree // Ouput: tree = Scilab equivalent for tree tree.lhs(1).dims=list(-1,-1) tree.lhs(1).type=Type(String,Real) endfunction
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clear; clc; V=66; V=V/sqrt(3); T=60; d=2; r=d/2; D=5.3; R=D/2; V=fix(V*sqrt(2) *10)/10; a=(R/r)^(1/3); a=round(a*1e3)/1e3; r1=a*r; r2=round(a*r1*1000)/1000; V1= V *((1/r)-(1/r2)) *r ; V2= (V-( V1* ((1/r)-(1/r1))) )*r1; //An error exists in the text book while calculating V1 and V2 and hence Emax a...
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clc; V1=1;//m^3 VA=1;//m^3 VB=1;//m^3 V2=VA+VB; p1=20;//BAR p2=p1*(V1/V2); disp("final pressure is:"); disp("bar",p2);
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########################################################################### # Header # ########################################################################### response_matching = simple_matching; default_font_size = 48; active_buttons = 3; button_codes = 1,2,3; #left, r...
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defects= 0.01; disks = 10; package = 3; probdefect0 = ((1-defects)^10); probdefect1 = factorial(disks)*defects*((1-defects)^9)/factorial(disks-1); prob = 1 - probdefect0 -probdefect1; disp(prob, "Probability that a package will be returned is") newprob = factorial(package)*prob*((1-prob)^2)/factorial(package-1);...
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//Chapter 8 //Example 8_15 //Page 185 clear;clc; v=220; r=1.5; d=200; t=40; b=76; mo=0.85; f=50; delta=3.92*b/(273+t); go=30/sqrt(2); vc=mo*go*delta*r*log(d/r); v_phase=v/sqrt(3); pc=242.2/delta*(f+25)*sqrt(r/d)*(v_phase-vc)^2*1e-5; printf("Delta = %.3f \n\n", delta); printf("Disruptive critical voltage per phase...
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ModuleName="MovingAverage"; Version="0.01"; DateModified="07-May-2015"; DateOfCreation="07-May-2015"; Author="Rob Eccleston"; Description="Takes a moving average for the data provided in a matrix"; function [ averaged_data ]= moving_average_matrix(data,window_size,direction) //change the data direction i...
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clc z=5 To=0.275 Cn=2/(1+To) N60=8 N160=Cn*N60 printf('(N1)60 = %f',N160)
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//Example No.2.6. // Page No.61. clc;clear; T = 300;//Temperature -[K] K = 1.38*10^(-23);//Boltzman's constant. w = 500*10^(-9);//wavelength -[m]. h = 6.626*10^(-34);//Planck's constant. c = (3*10^(8));//velocity of light. //By Maxwell's and Boltzman's law. N = exp((h*c)/(w*K*T)); //Relative population. pri...
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what is bioenergy bioenergy is not ethanol bioenergy is n t global warming bioenergy is something which seems counterintuitive bioenergy is oil it s gas it s coal and part of building that bridge to the future to the point where we can actually see the oceans in a rational way or put up these geo spatial orbits that wi...
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//Caption:Find efficiency of motor //Exa:8.12 clc; clear; close; V=500//Voltage of shunt motor(in volts) I=10//Current taken by motor on no load(inA) I_f=3//Field Current(inA) r_a=0.1//Armature resistance(in ohms) P_i=100000//Input power to motor(in watt) P_nl=V*I I_ao=I-I_f P_acn=(I_ao^2)*r_a P_fcn=I_f*V ...
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//binary to gray code// //Example 24.a// //binary to gray code// clc //clears the console// clear //clears all existing variables// a=110100 for i=1:6 x(i)=modulo(a,10) a=a/10 a=floor(a) end y(6)=x(6) k=5 while(k>0) if (bitand(x(k+1),x(k))==1) then a=bitand(x(k+1),x(k)) y(k)=bi...
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//NPSHA and NPSHR// pathname=get_absolute_file_path('10.08.sce') filename=pathname+filesep()+'10.08-data.sci' exec(filename) //Diameter of pipe (in feet): Df= Di/12 //Area of crossection of pipe(in ft^2): A=%pi/4*Df^2 //Velocity of flow(in ft/sec): V=Q/7.48/A/60 //For water at T=80F,viscosity=0.927e-5 ft^2/s...
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// Copyright INRIA if ~c_link('cfunc') then files=G_make(['/tmp/ex5cI.o','/tmp/ex5c.o'],'ex5c.dll'); addinter(strcat(files,' '),'cfunc','FuncEx'); end deff('[z]=f(x,y)','z=x+y'); res=FuncEx(1:3,4:6,f); if norm(res -feval(1:3,4:6,f)) > %eps then pause,end res1=FuncEx(1:3,4:6,'fp1'); if norm(res - res1 ) > %eps...
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//page 75 clc;funcprot(0);//EXAMPLE 3.13 // Initialisation of Variables r=1;............//Radius of each atom in units n=8;.........//No. of atoms present in Diamond cubic Silicon per cell //CALCULATIONS v=(4/3)*%pi*r^3;..........// Volume of each atom in Diamond cubic Silicon a0=(8*r)/sqrt(3);..........//Vol...
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/* Demonstrates nesting of auton transactions. */ DROP table emp2; CREATE TABLE emp2 as select * from emp; CREATE OR REPLACE PROCEDURE test_auton IS PROCEDURE auton IS PRAGMA AUTONOMOUS_TRANSACTION; BEGIN DELETE FROM emp2; DBMS_OUTPUT.PUT_LINE ('emp2 ' || tabcount ('emp2')); l...
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//Chapter 4 //Example 4-5 //designInvertingVoltageDetector //Page 97 clear;clc; //Given Vsatp = 15 ; Vsatm = -15 ;// Saturation Voltages Vh = 4 ; //Hysteresis Voltage Vctr = 10 ; //Center voltage n = ((Vsatp - Vsatm)/Vh)-1 ; R = 10*10^3 ;//Input Resistance Vref = ((n + 1)*(Vctr))/n ; // Reference Voltage R...
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 27 disp("CHAPTER 8"); disp("EXAMPLE 27"); //VARIABLE INITIALIZATION v_t=200; //in volts r_a=0.06; //in Ohms r_se=0.04; //in Ohms p_i=20*1000; //in Watts //SOLUTION //solution (a) I_a=p_i/v_t; E_b=v...
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//computation of equilibrium concentration clear; clc; printf("\t Example 14.10\n"); Kc=54.3; HIo=0.0224; H2o=0.00623; I2o=0.00414; //let us assume that x moles have reacted, so, HI=HIo+2x, H2=0.00623-x, I2=0.00414-x, when we substitute in Kc=(HI)^2/(H2)*(I2) we get 54.3=(2x+0.0224)^2/((0.00623-x)*(0.0041...
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// Ex5_20 clc; // Given: E1=1.4;// MeV mBi=208.980417; mn=1.008665; mBI=209.984110; // Solution:part(a) KE1=0;// in MeV BE1=(mBi+mn-mBI)*931;// in MeV Ex1=KE1+BE1; printf("\n The excitation energy of compound nucleus is = %f MeV",Ex1) // Solution:part(b) KE2=E1*(209/210);// in MeV BE2=(mBi+mn-mBI)...
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Pu=3000//in kN fck=20//in MPa fy=415//in MPa l=3//unsupported length, in m //assume 1% steel Ag=Pu*10^3/(0.4*fck*0.99+0.67*fy*0.01)//in sq mm L=sqrt(Ag)//assuming a square column L=530//in mm Asc=0.01*L^2//in sq mm emin=l*10^3/500+L/30//in mm ep=0.05*L//>emin, hence OK mprintf("Column size - %d x %d mm",L,L)...
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// sum 11-5 clc; clear; a=50; b=75; P=36*10^3; d=24; Ta=60; n=9; A=%pi*d^2/4; Td=P/(n*A); theta=atan(b/a); Ts=54.64; r2=90.184; e=A*29575.7/P; // printing data in scilab o/p window printf(" e is %0.1f mm ",e);
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//Example 6.5 //Program to f i n d the DFT o f a Sequenc e x [ n]=[ 1 , 2 , 3 , 4 , 4 , 3 , 2 , 1 ] // u s i n g DIF Algor i thm . clc ; x = [1 ,2 ,3 ,4 ,4 ,3 ,2 ,1]; //FFT Computation X = fft (x , -1); disp (X, 'X( z ) = ' );
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// Example 5.3 //threshold density and threshold current clc; clear; close; B=21*10^-3;//Gain factor in ampere per centimeter cube alpha=10;// in per cm L=250*10^-4;//length in meter w=100;//in micro meter r=0.32; Jth=(1/B)*(alpha+(1/L)*log(1/r));//Threshold current in ampere per centimeter cube ith=Jth*L*w...
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K m=1; Cp=1.005; P1=100; T1=17+273; T2=T1; P2=2500; printf('Final Temperature...
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//Example 5.17 clc disp(" D0 D1 D2 D3") disp("w''x'' 0 1 2 3") disp("w''x 4 5 6 7") disp("wx'' 8 9 10 11") disp("wx 12 13 14 15") disp("") disp("D0 = w''x + wx'' = w XOR x") disp("D1 = w''x'' + wx'' = x''") disp("D2 = w''x + wx'' = w XOR x") disp("D3 = w''x + wx'...
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clear all; clc; disp("Scilab Code Ex 5.4 : ") //Given: di = 80; //mm ri = 40/1000; //m d0 = 100; //mm ro = d0/2000; //m F = 80; //N l1 = 0.2; //m l2 = 0.3; //m //Internal Torque: T = F*(l1+l2); //Section Property: J = (%pi/2)*((ro^4)-(ri^4)); //Shear Stress: c_o = 0.05;//m tou_o = (T*c_o)/(J*1...
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function [aantal_muntstukken] = solve(te_betalen,betaald) // Reken uit hoeveel munten je minimaal moet teruggeven. // Dummy toekenningen aan outputvariabelen aantal_muntstukken = 0 terugbetalen = betaald - te_betalen if te_betalen > betaald then error("You didn`t pay enough.") end...
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//Example 4.17: clc; clear; close; //given data : format('v',5) A=200;//gain without feedback Beta=0.05;//feed back ratio Af=(A/(1+(Beta*A)));//gain with feedback disp(Af," gain with negative feedback is ,=") Dn=10;//percentage distortion format('v',6) Dn1=(Dn/(1+A*Beta));//percentage Distortion with negative feedback...
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clc NE=5*10^17 disp("NE = "+string(NE)+" /cm^3") //initializiation of doping concentration in the emitter. NB=10^16 disp("NB = "+string(NB)+" /cm^3") //initializiation of doping concentration in the base. NC=10^15 disp("NC = "+string(NC)+" /cm^3") //initializiation of doping concentration in the collector. WB...
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//Calculations on unsupercharged SI engine clc,clear //Given: Py=640 //Brake power at test in kW py=98 //Test ambient pressure in kPa Ty=303 //Test ambient temperature in K phiy=0.8 //Relative humidity at test //Solution: //Refer table 27.1, 27.3 psy=4.2 //Saturation vapour pressure at test in kPa psr=3.2 //Standard sa...
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clear; clc; disp('Example 4.4'); // aim : To determine // the specific enthalpy of steam // Given values P = 2.5;// pressure, [MN/m^2] t = 320; // temperature, [C] // solution // from steam table at given condition the saturation temperature of steam is 223.9 C, therefore steam is superheated tf ...
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clc; clear; m1=40;//kg m2=40;//kg k=200;//N/m sqw=poly(0,"s"); p=sqw^2-20*sqw+75; r=roots(p); f1=(r(1))^0.5; f2=(r(2))^0.5; Tp1=(2*%pi)/f1; Tp2=(2*%pi)/f2; //for first mode disp("For first mode:") disp(Tp1,"Period of oscillation:") disp("A1=-A2") disp("--------------------------------------------------"...
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disp("Exercício 1 - Item A") A = [10 -1 0;-1 10 -2;0 -2 10] b = [9;7;6] x0 = [0;0;0] L=tril(A,-1);D=diag(diag(A));U=triu(A,1); invD = diag(1./diag(D)) MJ = -invD*(L+U) cj = invD*b disp("||MJ||_inf = ",norm(MJ,%inf)) x1 = MJ*x0+cj x2 = MJ*x1+cj disp("x2=",x2) d...
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//Example 3.15.3: shunt resistance clc; clear; close; //given data : Im=1;// in mA P=100;// in kilo-watt I=100;// in mA Rm=(P)/(Im)^2; Rsh=((Im*10^-3*Rm*10^3)/((I-Im)*10^-3))*10^-3; disp(Rsh,"shunt resistance,Rsh(kilo-ohm) = ")
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// Test # 1 : No Input Arguments exec('./zpkbpc2bpc.sci',-1); [z,p,k,n,d]=zpkbpc2bpc(); //!--error 10000 //Number of input arguments should be 5 //at line 37 of function zpkbpc2bpc called by : //[z,p,k,n,d]=zpkbpc2bpc();
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//Solutions to Problems In applied mechanics //A N Gobby clear; clc //initialisation of variables v=4//in w=20//tonf d=10//ft m=13400//tonf/in^2 q=2//in l=120//in //CALCULATIONS Fmax=q*(w)/(%pi/v*v^2)//tonf/in^2 M=Fmax*l/m//in P=w*M//in tonf //RESULTS printf('The maximum instantneous stress=% f tonf/in^2',Fmax) printf...
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//Example 5.3 clear; clc; //Given n=2;//number of electrons transferred E=1.01463;//cell potential in V F=96500;//Farady charge in C T=298;//temperature in K p=-5*(10^(-5));//p=(delE/delT)p in V K^-1 //To determine the free energy change delG delG=-n*F*E;//the free energy change in J mprintf('delG for We...
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clear;lines(0); deff('[alpha,beta]=alpha_beta(n,m,m1)',... 'if 2*int(n/2)=n then, beta=K1; else, beta=0;end;... alpha=%k(1-m1)/%k(1-m);') epsilon=0.1;A=10; //ripple parameters m1=(epsilon*epsilon)/(A*A-1);n=5;omegac=6; m=find_freq(epsilon,A,n);omegar = omegac/sqrt(m) %k(1-m1)*%k(m)/(%k(m1)*%k(1-m))-n //Check... [alp...
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//Determine mean path loss by two models Lr = 31.7; gamma1 = 5.22; gamma2 = 3.27; R = 30; R0 = 1; FAF = 24.4; Ls1 = Lr + 10*gamma1*log10(R/R0) ; Ls2 = Lr + 10*gamma1*log10(R/R0) + FAF ; disp(Ls1, 'Mean path loss by 1st model (in dB)') disp(Ls2, 'Mean path loss by 2nd model (in dB)')
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clc; //Example 7.5 //Page No 260 //Solution df=75; fm=15; //(a) disp("(a)The deviation ratio is found by substituting into equation 7-35(refer pgno), "); DR=df/fm; disp(DR,"DR = "); disp("From Table 7.3"); B=2*(8*fm); disp('kHz',B,"B = "); //(b) disp("(b)For an 37.5kHz frequency deviation and modulating ...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>StdProject_Diff2D Triangle Modified basis P=6 Q=7</description> <executable>StdProject_Diff2D</executable> <parameters>3 4 5 6 6 7 7</parameters> <metrics> <metric type="L2" id="1"> <value tolerance="1e-12">2.0808e-13</value>...
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//Caption: 2D DFT of 4x4 grayscale image //Example4.5 //page 171 clc; F = [16,0,0,0;0,0,0,0;0,0,0,0;0,0,0,0]; N =4; //4-point DFT kernel = dft_mtx(N); f = (kernel*(F*kernel'))/(N^2); f = real(f); disp(f,'Inverse 2D DFT of the transformed image f =') //Result //Inverse 2D DFT of the transformed image f = ...
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// Example 10.2 clc; clear; close; // Given data format('v',6); VR= 12;// in V IL= 0.5;// in A RL= 25;// in Ω // Resistanc required, R= VR/IL;// in Ω VL= IL*RL;// in V Vout= VR+VL;//output voltage in V Vin= Vout+2;// input voltage in V disp(Vin,"The input voltage in volts is : ")
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//chapter10,Example10_11,pg 275 e=1.6*10^-19 v=5*10^5 B=0.3 N=6.025*10^26 M72=72/N R72=(M72*v)/(B*e) M74=74 R74=(R72/72)*M74 S=2*(R74-R72)//linear separation of two line printf("linear separation of two line\n") printf("S=%.2f m",S)
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// Exa 8.7 clc; clear; close; // Given data V1 = 745;// in µV V1 = V1 * 10^-6;// in V V2 = 740;// in µV V2 = V2 * 10^-6;// in V Av = 5*10^5; CMRR = 80;// in dB // Formula CMRR in dB= 20*log(Av/Ac) Ac= Av/(10^(CMRR/20)); disp(Ac,"The common mode gain is"); V_o = Av*(V1-V2)+Ac*((V1+V2)/2);// in V disp(V_o,...
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//clear// //Example3.3:Continuous Time Fourier Series Coefficients of //a periodic signal x(t) = sin(Wot) clear; close; clc; t = 0:0.01:1; T = 1; Wo = 2*%pi/T; xt = sin(Wo*t); for k =0:5 C(k+1,:) = exp(-sqrt(-1)*Wo*t.*k); a(k+1) = xt*C(k+1,:)'/length(t); if(abs(a(k+1))<=0.01) a(k+1)=0; end ...
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// Initilization of variables P=1000 // N // Force acting at the hinge of the 1st square Q=1000 // N // Force acting at the hinge of the 2nd square // Calculations // Chosing the co-ordinate system with originat A, we can write, theta=45 // degree // Forces that do work are P,Q & X_B. Applying the principle of vi...
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// Scilab Code Ex9.2.19: Page-421(2008) clc; clear; d = 1; // For simplicity assume interplanar spacing to be unity, m theta = 15; // Glancing angle for first order, degree n = 1; // Order of reflection // From Bragg's law, 2*d*sind(theta) = n*lambda, solving for lambda lambda = 2*d*sind(theta)/n; // Wavele...
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clear; clc; l=60; v=66; load1=25; pf=.8; r=.08; l=1.25; f=50; Z=complex(.08,(2*%pi*f*1.25*(10^-3)))*60; Vr=(v/sqrt(3)); I=((25*1000)/(sqrt(3)*66*0.8))*complex(.8,-.6); A=1; D=1; C=0; B=Z; M=[A Z;C D]*[Vr*1000;I]; Vs=M(1,:)*(10^-3); Vs1=Vs*sqrt(3); mprintf("Vs=%f+j%f Kv\n",real(Vs1),imag(Vs1)); Is=M(...
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void main() { bool a = false, b = true, c = a; c = d; }
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clc //Initialization of variables P1=50 //psia T1=540 //K g=32.2 R=1715 k=1.4 P3=13.5 //psia A2=0.0218 //ft^2 cp=6000 //calculations Pc=0.528*P1 V32=R*T1/g *k/(k-1) *(1- (P3/P1)^((k-1)/k)) V3=sqrt(V32*2*g) G3=g*A2*P1*144/sqrt(T1) *sqrt(k/R *(2/(k+1))^((k+1)/(k-1))) T3= T1 - V3^2 /(2*cp) gam3= g*P3*144/...