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//Example 12.4 //Page 529 disp('The Traffic intensity of system is,') A=1*2 disp('The raffic intensity carried by i active ckt is exactly i erlangs. Hence the traffic carried by 1st 5 ckt is,') P1=[(1*2^1)/(1)] P2=[(2*2^2)/(1*2)] P3=[(3*2^3)/(1*2*3)] P4=[(4*2^4)/(1*2*3*4)] P5=[(5*2^5)/(1*2*3*4*5)] A5={...
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// Example 2.11:diameter clc; clear; close; v1=1.2;// v2=2.4;// h=0.85;//in micro meter n1=1.5;//refrative index d1=0.015;// a1=((v1*h)/(2*%pi*n1*sqrt(2*d1)));//in micro meter d2=0.0015;// a2=((v2*h)/(2*%pi*n1*sqrt(2*d2)));//in micro meter disp(2*a1,"diameter (case 1) in micro meters is") disp(2*a2,"diameter (case 2) i...
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i = imread('test3.jpg'); corners = detectHarrisFeatures(i,'FilterSize',5,'MinQuality',0.5); disp(corners);
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//Chapter 19, Problem 3 clc; Av=120; //open-loop voltage gain Vi=3; //input voltage Vo=24*10^-3; //output voltage Ac=Vo/Vi; //common mode gain cmrr=20*log10(Av/Ac); //CMRR printf("CMRR = %.2f dB",cmrr);
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clc //calc pressuer at different heights considering on density change in air p_atm=14.7;//psia g=9.81;//m/s^2 //P2=P1*[1-(acc. due to gravity)*(mass of air)*(height)/(univ. gas const.)/(temp.)] T=289;//K R=8314//N.m^2/Kmol/K //for height of 1000ft=304.8m h=304.8//m p_1000=p_atm*[1-g*29*h/R/T]; disp("pressure...
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clc; clear; D=0.1;//mm sg=2.3; vis=1.12*(10^(-3));//N*s/(m^2) //by free body diagram and assuming CD=24/Re U=(sg-1)*999*9.81*((D/1000)^2)/(18*vis); disp("m/sec",U,"The velocity of the particle through still water =") dia=0:0.001:0.1; count=1; for i=0:0.001:0.1 u(count)=(sg-1)*999*9.81*((i/1000)^2)/(18*vi...
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//Example 12_15 clc;clear; //Properties k=1.4; C_p=1.005;// kJ/kg*K R=0.287;// kJ/kg*K // given values D=0.15;// m V_1=80;// m/s T_1=550;// K P_1=480;// kPa HV=42000;// kJ/kg AF=40; //Calculation rho_1=P_1/(R*T_1);// kg/m^3 A=%pi*D^2*V_1;// m^2 m_air=rho_1*A*V_1; // kg/s m_f=m_air/AF;// kg/s Q=m_f*H...
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clc //initialisation of variables R= 8.314 //J/mol K M= 29 //gms T= 400 //K p2= 1.6 //bar p1= 1 //bar Tenvir= 300 //K //CALCULATIONS q= R*T*log(p2/p1)/M S= -R*log(p2/p1)/M Senvir= q/Tenvir //RESULTS printf (' heat = %.1f kJ/kg',q) printf (' \n change in entropy of system= %.4f kJ/kg K',S) printf (' \n ch...
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clc; clear all; //chapter 3 //page no 89 //example 3.6 A=1 //arbitrary value provided Tau=10^-3 //in seconds fc=30*10^6; //centre frequency in Hz //plot for amplitude spectum f=-3/Tau:3/Tau; Vf=[] for i=1:length(f) if f(i)==0 then Vf=[Vf A*Tau]; //according to L'Hopitals rule sin(x)/x...
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//Example No. 5.37 clc; clear; close; format('v',9); //Given Data : V1=230;//V N1=870;//rpm Ia=100;//A Ra=0.05;//ohm T=400;//N-m Eb=V1-Ia*Ra;//V Vgen=V1+Ia*Ra;//V N2=N1*Vgen/Eb;//rpm disp(N2,"Speed in rpm : ");
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! Set active HYSCAN nodes active_nodes 12 ! Copy initialization batch file to the nodes send_to nodes ?:\OUT\SETUP\PLW\INITNDPL.BAT C:\BAT\INITNDPL.BAT ! Execute initialization batch file on the nodes exebat nodes C:\BAT\INITNDPL.BAT delay 150 ! Copy TUNNEL.CTL file to the nodes send_to nodes ?:\OUT\INPUTS\TUNNEL.C...
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clc clear //Input data CO=17//Percentage composition by volume H2=53.4//Percentage composition by volume CH2=28.8//Percentage composition by volume O2=0.8//Percentage composition by volume ea=30//Percentage of excess air v=1//Volume in m^3 //Calculations ta=((100/21)*((CO/100)/2+(H2/100)/2+(CH2/100)*2-(O2/1...
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// Example 24_20 clc;funcprot(0); //Given data P=5;// Power plant capacity in MW T_1=15+273;// K p_1=1;// bar T_4=750+273;// K p_r=6;// Pressure ratio p_3=2.24;// bar e=0.75;// The effectiveness of heat exchanger n_c=0.8;// Isentropic efficiency of compressor n_t=0.85;// Isentropic efficiency of both turbin...
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//Tarefa 2 - Flavius //Condições iniciais pi=%pi g=9.8 //Gravidade em m/s r=1e-3 //Raio da esfera ro=7850 //Densidade da esfera vol=(4/3)*pi*r^3 //Volume da esfera m=ro*vol //Massa da esfera R=1 //Raio do tubo (m) //Item a //Espaço de estados function [y_dot]=deriva(t,y0) k=y0(1,:) kdot=y0(2,:) dk_dt=kdot...
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// Exa 3.18 (Miss printed as example 3.15) clc; clear; close; format('v',5) // Given data P_Cmax = 125;// in mW P_D = P_Cmax;// in mW T_A = 25;// in degree C Tj = 150;// in degree C // Tj-T_A = theta*P_D; theta = (Tj-T_A)/P_D;// in degree C/mW disp(theta,"The thermal resistance for a transistor ...
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//Chapter-1,Example 1_14,Page 1-41 clc() //Given Data: n=4 //4th dark ring m=12 //m=n+p D4=0.4*10^-2 //Diameter of 4th ring D12=0.7*10^-2 //Diameter of 12th ring //Calculations: //(Dn+p)^2-Dn^2=4*p*lam*R //Solving, (D12^2-D4^2)/(D20^2-D4^2) //We get above value =1/2. Hence D...
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clear; clc; disp("--------------Example 2.5---------------") disp("753 - A 16-bit port address represented as one single decimal number.")
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//Example 8.10, Page Number 390 //Material dispersion for a laser and LED source clc; clf(); //Fig 8.26 Page No 390 X=[0.5,0.75,1,1.25,1.4,1.5,1.75,2,2.5]//Values as observed from graph V=[0.07,0.04,0.02,0.0,-0.01,-0.02,-0.03,-0.04,-0.06]//Values as observed from graph plot(X,V); xlabel("Wavelength (um)") ylab...
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sPlITtEr ggj {} FiltER NCL { NOT 9 = BITaNd ( Ca:bB:Ae:EA:fA:c5 , ) OR HtG ( ) } fIlteR a {d } g -> SyO GroUpeR wZV {mOdUlE C{ N = C L > sd RDelta 115 } AggrEgAtE biTanD(dL) As v } uNgrOupER Y { } gROUPfiltER Fq {Not ::a:d56:F:5.3.44.250 >> 253.201.134.4 oR nOt sMw ( ) not BitAnd ( ) Or bITAnd ( 177.2....
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bow.1_9.tst
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clear; clc; V_s=230; V_m=sqrt(2)*V_s; a=45; V_or=(V_m/2)*sqrt(1/%pi*((2*%pi-a*%pi/180)+sind(2*a)/2)); printf("rms value of o/p voltage=%.3f V",V_or); R=20; I_or=V_or/R; P_o=I_or^2*R; printf("\nload power=%.1f W",P_o); I_s=I_or; VA=V_s*I_s; pf=P_o/VA; printf("\ni/p pf=%.4f",pf); V_o=sqrt(2)*V_s/(2...
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ft=3.67; m=ft*0.3048; disp("the given length (in m) is"); disp(m);
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r1=3.3; r2=4.7; vp=36; disp("Part a"); vt=vp/(2*sqrt(2)); rt=r1+r2; i=vt/rt; disp("the reading of a series-connected ammeter (in mA) is"); disp(i); disp("Part b"); v=vt*r2/(r1+r2); disp("voltage (in V) across the 4.7 kΩ resistor is"); disp(v); disp("Part c"); p=i^2*r1; disp("power dissipated (in mW) in he ...
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//Example 2_9 clc;funcprot(0); // Given values A=250*10^6;// Catchment area in m^2 Ar=1.25;// Annual rainfall in m H=60;// Average head in m P_w=70;// Percentage of water in the dam n_t=0.9// Turbine efficiency n_g=0.95// Generator efficiency g=9.81;// The acceleration due to gravity in m/s^2 //Calculation ...
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pathname=get_absolute_file_path('3_3.sce') filename=pathname+filesep()+'3_3_data.sci' exec(filename) //For Process 1 and 2 //Compression Ratio r=(p2/p1)^(1/y) //Efficiency n=1-((1/r)^(y-1)) //Final Temperature (in kelvin) t2=(p2*t1)/(p1*r) //For Process 2 and 3 t3=(p3 /p2)*t2 //Heat Supplied qs=Cv*(t3 -...
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map1207" Width="13" Height="11" CellSize="40" BackgroundSize="1" Background="9plus.png"> <Cell Name="南瓜" X="5" Y="1" /> <Cell Name="十字架" X="6" Y="1" /> <Cell Name="南瓜" X="7" Y="1" /> <Cell Name="十字架" X="9" Y="1" /> <Cell Name="盔甲怪" X="10" Y="1" arg0="24" /> <C...
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//Exa2.18 clc; clear; close; disp("Let the temperature coefficient of resistance of platinum at 0 degree C be alpha0 and resistance of platinum coil at 0 degree C be R0,then"); disp("Resistance at 40 degree C, R1 = R0 * (1+40*alpha0) (i)"); disp("Resistance at 100 degree C, R2 = R0 * (1+100*alpha0)...
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//find dc current gain in common emitter configuration clear; clc; //soltion //given a=0.98;//dc current gain in common base configuration B=a/(1-a); printf("The dc current gain in common emitter configuration is %.0f",B);
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Chapter12_Example9.sce
clc clear //INPUT n=17000;//luminosity of star compared to sun t=6000;//temperature of the sun in K //CALCULATIONS t1=(n*t^4)^(1/4);//temperature of the star in K //OUTPUT mprintf('the temperature of the star is %3.2f K',t1)
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//developed in windows 8 operating system 64bit //platform Scilab 5.4.1 //example 26_4w clc;clear; //Given Data mole=1; //Number of moles of helium gas (Unit:mole) area=8.5*10^-4; //Area of the piston (Unit : m^2) temp_rise=2; //Temperature rise (Unit : degree centigrade) atm_press=100*10^3; ...
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Example12_4.sce
//chapter-12,Example12_4,pg 508 V=1.3//excitation voltage Vgrad=10^5//potential gradient //10^5 V/mm*thickness in mm=excitation voltage l=(V/Vgrad)//thickness of LCD printf("thickness of LCD\n") printf("l=%.8f m\n",l)
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15_2.sce
clc //initialisation of variables clear M= 0.1 //molal Tf= 0.345 //C k= -9.702*10^-3 k1= -5.2*10^-6 //CALCULATIONS a= %e^(k*Tf+k1*Tf^2) //RESULTS printf ('activity = %.4f ',a)
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// Example 8.9 clear all; clc; // Using the data from Example 8.8 s = 0.6; // Pitch of square lattice in inches d = 0.42; // Diameter of the fuel rod in inches b = 0.024; // Thickness of Zircaloy-4 clad in inches a ...
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// Example 2.5 // From the diagram 2.14 rp=(1/20)+(1/10)+(1/20); // Parallel resistance Rp=1/rp; // The resistance Rp Rs=15; // Series resistance Rab=Rs+Rp; // Effective resistance between A & B...
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ques48.sce
//ques48 disp('centre of curvature of given cycloid '); syms a t x=a*(t-sin(t)); y=a*(1-cos(t)); y1=diff(y,t,1); y2=diff(y,t,2); xx=x-y1*(1+y1)^2/y2; yy=y+(1+y1^2)/y2; disp('the coordinates x,y are resp :'); disp(xx); disp(yy); disp('which another parametric equation of cycloid ');
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Ex2_15.sce
clc n=1*10^5 disp("n = "+string(n)+" /cm^3") //initializing value of electrons and hole per cm^3. p=1*10^19 disp("p = "+string(p)+" /cm^3") //initializing value of number of hole per cm^3 no=sqrt(n*p) disp("Value of intrinsic concentration,no=sqrt(n*p))= "+string(no)+" /cm^3")//calculation //this is solved...
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example_3_25.sce
clear; clc; disp("--------------Example 3.25---------------") printf("Another example of broadband transmission is the digital cellular telephone. For better reception, digital cellular phones convert the analog\nvoice signal to a digital signal.Although the bandwidth allocated to a company providing digital cellula...
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ژېړ ADJ;NOM;FEM;SG ژېړ ADJ;non{NOM};MASC;PL ژېړ ADJ;non{NOM};FEM;PL ژېړ ADJ;NOM;MASC;PL ژېړ ADJ;VOC;FEM;PL ژېړ ADJ;VOC;MASC;SG ژېړ ADJ;VOC;FEM;SG ژېړ ADJ;NOM;MASC;SG ژېړ ADJ;NOM;FEM;PL ژېړ ADJ;non{NOM};MASC;SG ژېړ ADJ;non{NOM};FEM;SG ژېړ ADJ;VOC;MASC;PL کتاب N;NOM;PL کتاب N;VOC;PL کتاب N;non{NOM};SG کتاب N;VOC;SG کتاب ...
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ex_5_7.sce
// Example 5.7: mobility of electrons clc, clear // given : format('v',8) e=1.602*10^-19; // in C m=9.1*10^-31; // in kg t=10^-14; // time in sec mu=(e*t)/m; disp(mu,"mobility of electrons,mu(m^2/volts.sec) = ")
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clc lambda=0.708*10^-8// cm h=6.625*10^-34// J*s Plank's constant c=3*10^10// cm/s e=1.6*10^-19// eV E=h*c/lambda// E=hv=hc/lambda disp(E,"the value of E in J is") E=E/e disp(E,"the value of E in eV is")
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function [Er,Ar,Q,Z]=epsfin(E,A) // Returns the epsilon + finite part of the pencil sE-A // Z right subspace associated with epsilon and finite part // For a regular pencil Z spans the right finite eigenspace // FD & RN (see fineta macro) [LHS,RHS]=argn(0) if RHS==1 then [E,A]=pen2ea(E);end E=pertrans(E);A=pertrans(A);...
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//clc() N = 100;//mol gas mixture burned //CO(g) + 1/2 O2(g) = CO2 - Hr1 = - 282.91kJ/mol //H2(g) + 1/2 O2(g) = H2O - Hr2 = - 241.83kJ/mol Hr1 = - 282.91;//kJ/mol Hr2 = - 241.83;//kJ/mol Nco1 = 20; Nh21 = 30; Nn21 = 50; Htotal = Nco1*Hr1 + Nh21*Hr2; disp("kJ",-Htotal,"the...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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num=[1 0.5 50 5]; den=[0 0 0 0]; [b,a]=eqtflength(num,den); disp(b); disp(a); //output //!--error 10000 //Division by zero not allowed //at line 24 of function eqtflength called by : //[b,a]=eqtflength(num,den); //at line 3 of exec file called by : //length5.sce', -1
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// Example 10.9 format('v',5) clc; clear; close; // given data I_Csat= 109*10^-3;// in A bita_dc= 200; R_B= 1*10^3;// in Ω V_BE1= 0.7;// in V V_BE2= 1.6;// in V // The base current, I_Bsat= I_Csat/bita_dc;// in A // The input voltage Vin= I_Bsat*R_B+V_BE1+V_BE2;// in V disp(Vin,"The input voltage in volt...
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function [x,y] = TracerPolygone() clf() plot2d(0,0,rect=[0 0 3 3]) xgrid(1) ibutton = 0 while ibutton<>5 [ibutton, xcoord, ycoord] = xclick() x($+1)=xcoord y($+1)=ycoord plot(x,y,'-o') end endfunction
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// Examle 3.4 C1=0.05; // Capacitor 1 ( in Micro ) C2=0.1; // Capacitor 2 ( in Micro ) C3=0.2; // Capacitor 3 ( in Micro ) C4=0.05; // Capacitor 4 ( in Micro ) C=(1/C1...
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//ques9 clc disp('solution of the given linear differential equation is given by : '); m=poly(0,'m'); disp('y=1/(D(D+1))[x^2+2x+4] can be written as (1-D+D^2)/D[x^2+2x+4] which is combination of differentiation and integration '); g=x^2+2*x+4; f=g-diff(g,x)+diff(g,x,2); y=integ(f,x); disp('y='); disp(y);
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//Checking if error message pops up when width length is negativr a = [14 11.0; 217.0 83.4; 22.0 33.3; 211.0 321]; in1 = list(a) b = [1.0 21.0 15; 25.0 13.0 23; 223.0 26.0 2; 179.0 52.0 13]; in2 = list(b) width = -1280; [output1] = initCameraMatrix2D(1,in2,in1,width,1024,0); //output-> // ...
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@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005]...
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clear clc xd=.2 x1=.4 x2=.4 Pi=1.5 E=1.2 V=1 X=xd +((x1*x2)/(x1+x2)) pe=E*V/X d0 = asin(Pi/pe) X2=xd+x1 pe2=E*V/X2 d1 = asin(Pi/pe2) dm=%pi- d1 A1=((Pi * d1)+ ( pe2 * cos(d1)))- ((Pi * d0)+ ( pe2 * cos(d0))) A2=((Pi * dm)+ ( pe2 * cos(dm)))- ((Pi * d1)+ ( pe2 * cos(d1))) if abs(A1)<abs(A2)...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); sf=T_scene_create; sss=T_getscene; sss.ambientlightcolor=color(0.15,0.15,0.15); refframe=sss.addsubframe("refframe"); sf1=sss.addsubframe("sf1"); tf=Transformation.rotate(vector(0,0,1),Pi/5); s=Bar(point(0,-1,0),vector(2,1,1)); s.subsample(0.5); s2=Sphere(point(1,0,0....
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//All the quantities are expressed in Si units area_ratio = 2; //exit to throat area ratio p0 = 1; //reservoir pressure in atm T0 = 288; //reservoir temperature pe = 0.973; //exit pressure...
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h1 = 3230.9; s1 = 6.9212; s2 = s1; s3 = s1; h2 = 2796; sf = 0.6493; sfg = 7.5009; x3 = (s3-sf)/sfg; h3 = 191.83 + x3*2392.8; h4 = 191.83; h5 = h4; h6 = 640.23; h7 = h6; m = (h6-h5)/(h2-h5); Wt = (h1-h2)+(1-m)*(h2-h3); Q1 = h1-h6; n_cycle = 100*Wt/Q1; sr = 3600/Wt; s7 = 1.8607; s4 = 0.6493; Tm = (h1-h7)/(s1-...
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//edsig chain dirve clc //soltuion //given RP=15000//W//rated power N1=1000//rpm N2=350//rpm VR=N1/N2 //ref table 21.5,numbr of teeth on smaller sprocket is T1=25 T1=25 T2=T1*N1/N2 K1=1.5//load factor K2=1//lubricaiton factor K3=1.25//rating factor Ks=K1*K2*K3//service factor DP=Ks*RP//design power //fr...
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load Not16.hdl, output-file Not16.out, compare-to Not16.cmp, output-list in%B3.16.3 out%B3.16.3; // Used these four test cases because it there were over 256 possibilities set in %B0000000000000000, eval, output; set in %B1111111111111111, eval, output; set in %B1010101010101010, eval, output; set...
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clc; v=230; // rated voltage of dc shunt motor ra=0.4; // armature circuit resistance rf=115; // field resistance n1=800; // initial speed n2=1000; // final speed ia1=20; // armature current at n=800 rpm // torque at both speed is same therefore f1*ia1=f2*ia2 where f=field flux therefore Ea1=v-ia1*ra; // count...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 3.4 //calculation of average velocity of the tip of minute hand in a table clock //given data R=4; //length(in cm) of the minute hand = radius(in cm) of the circle representing the clock t1=1800; //time(in second) ela...
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// CAPTION: UP-Converter_parametric_Amplifier //chapter_no.-8, page_no.-346 //Example_no.8-5-1 clc; //(a)Calculate_the_power_gain R=25;//R=f0/fs ,ratio_of_output_frequency_over_signal_frequency rQ=10;//figure_of_merit x=((rQ)^2)/R; PG=(R*x)/((1+sqrt(1+x))^2); PG=10*log10(PG);//calculating_in_dB disp(PG,'Up...
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12 #rooms r1 0 0 Lr2 0 1 r3 0 2 ##start s 1 1 ##end e 2 2 #links e-s r1-s r1-e r1-Lr2 r1-r3 Lr2-r3 r3-e
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//Exam:1.2 clc; clear; close; a=1; b=1; c=-30; w_m=(-b+sqrt((b^2)-4*a*c))/(2*a);//speed of the drive t_l=0.5*(w_m^2);//motoring torqe disp(t_l,w_m,'stable operating point=');
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//ques1 clc disp('finding the fourier series of given function'); syms x ao=2/%pi*(integ(cos(x),x,0,%pi/2)+integ(-cos(x),x,%pi/2,%pi)); s=ao/2; n=input('enter the no of terms upto each of sin or cos terms in the expansion : '); for i=1:n ai=2/%pi*(integ(cos(x)*cos(i*x),x,0,%pi/2)+integ(-cos(x)*cos(i*x),x,%p...
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example12.sce
Syms t,s //on applying KVL we get the laplace transformed current as disp(' the laplace transformed current equation is i(s)=s^2+6s+5/(s*(s^2+4s+5))') //by partial fraction method [A]=pfss(s^2+6*s+5/((s)*(s^2+4*s+5))) b=ilt(A (1),s,t) c=ilt(A(2),s,t) d=b+c disp('the time domain expression is') disp(d)
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// Example 4.2, page no-209 clear clc //(a) Cc=1.0 C=0.7*Cc m=0.005 k=50 w=sqrt((k/m)-(C/(2*m))^2) printf("(a)\nw=%.1f rad/s",w) //(b) w1=250 theta=C*w1/(k-m*w1^2) printf("\ntheta=%f",theta) fi=atan(-theta) fi=fi*180/%pi printf("\nfi = %d°",fi)
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//Determine the first four terms in the Fourier series for a rectangular waveform f = 1e+3; T = 1/f; pw = 500e-6; A = 10; p = pw/T; ft1 = (A*p); ft2 = ( (2*A*p) * sin(%pi*p)/(%pi*p) * cos(2e+3*%pi*p) ); ft3 = ( (2*A*p) * sin(%pi)/(%pi) * cos(4e+3*%pi*p) ); ft4 = ( (2*A*p) * sin(1.5*%pi)/(1.5*%pi) * cos(6e+3*...
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clear clc disp('Exa-2.13'); E=10.51; mc2=0.511; //all the values are in MeV p=sqrt(E^2-mc2^2); //momentum of the electron printf('The momentum of electron is %.1f MeV/c\n',p); v=sqrt(1-(mc2/E)^2); //velocity in terms of c printf('The velocity of electron is %.4f c',v);
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//ques4 //Critical Temperature and Pressure in Gas Flow clear clc k=1.289; T0=473;//Temp at in K Tx=T0*2/(k+1);//Temp in K P0=1400//pressure in kPa Px=P0*(2/(k+1))^(k/(k-1));//Pressure in kPa printf('T* = %.0f K \n',Tx); printf(' P* = %.0f kPa \n',Px);
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// given 4 input-outputs of the boolean XOR function // determine the parameters of the best fitting function // i.e. f(x,y) = axy + bx + cy + d // via gradient descent // x y | x AND y // -----+------------ // 0 0 | 0 // 0 1 | 1 // 1 0 | 1 // 1 1 | 0 xx = [0,1,0,1]; yy = [0,0,1,1]; xxyy = xx.*yy; zz...
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clear; clc; printf("\nEx2.36\n"); //page no.-84 //given theta=45;................//angle in degrees _lambda=0.022*10^-10;.....//wavelength in m h=6.6*10^-34;..........//planck's constant in J-sec m=9.1*10^-31;.........//mass of electron c=3*10^8;..............//speed of light in m/s //acc. to compton exp.,_l...
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clc //initialisation of variables h=44.10//Btu/lbm hf=-51688 //Btu/lb mole Hr=-948087 //Btu/lb mole Hr1=-872347//Btu/lb mole Hr2=-955099 //Btu/lb mole Hr3=-879359//Btu/lb mole //CALCULATIONS hRp=Hr/h//Btu/lbm hRp1=Hr1/h//Btu/lbm hRp2=Hr2/h //btu/lbm hRp3=Hr3/h //Btu/lbm //RESULTS printf('Liquid propane ...
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function [tour, valor] = vecino_mas_cercano(A, v1) // Ejecuta el algoritmo del Vecino más cercano sobre la instancia TSP dada // Entrada: // A = matríz de distancias de la instancia TSP // v1 = vértice inicial // Salida: // tour = vector con los vértices a ser recoridos por el tour // valor = valor del tour generad...
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clc// // // //Variable declaration rho_s=10.5*10^3; //density(kg/m^3) NA=6.02*10^26; //avagadro number(per k mol) MA=107.9; //atomic mass sigma=6.8*10^7; //conductance(ohm-1 m-1) e=1.6*10^-19; //charge(coulomb) //Calculation n=rho_s*NA/MA; //density of electrons mew=sigma/(n*e)...
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clc //Chapter2 //Ex_2.11 //Given u=1.58*10^6 //in m/s N=8.5*10^28 //m^-3 e=1.6*10^-19 // in coulombs me=9.1*10^-31 //in Kg N_I=0.01*N l_I=N_I^(-1/3) t_I=l_I/u p=me/(e^2*N*t_I) disp(p," worst case resistivity in ohm*m") //slight change in answer due to computational method
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//Exa 4.3 clc; clear; close; //given data : disp("For a two elements arrayy the total field is given by : "); disp("E=2*Eo*cos(psi/2)"); disp("(i) It is a case of braod side array : so, delta = 0"); disp("psi = Beta*d*cos(theta)+delta") disp("d=3*lambda/2"); disp("Beta*d = (2*%pi/lambda)*(3*lambda/2) = 3*%pi"...
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function test() for i=5:-1:1 disp(i); end endfunction
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// Example 8.8 clear all; clc; // Given data d = 0.42; // Diameter of the fuel rod in inches b = 0.024; // Thickness of Zircaloy-4 clad in inches v = 15.6*3600; // Speed of fluid in feet/hour a = (d/2)+b; ...
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @output...
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//Exa 1.3 clc; clear; close // given data t_f=30;// in degree C t_s=400;// in degree C d=0.04;//in m h=20;// in W/m^2K l=1;//in meter A=%pi*d*l; q=h*A*(t_s-t_f);// in W disp(q,"Rate of heat loss in watt is : ")
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errcatch(-1,"stop");mode(2);//Example 1_2 ; ; //Given data dv_dt=190;//V/µs IC=8*10^-3;//A //Solution : C=IC/(dv_dt/10^-6);//F disp(C,"Capacitance of depletion layer in F : "); exit();
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//CHAPTER 7_ Flow Measurement //Caption : Gross volume flow rate(venturi) // Example 3// Page 438 dp=0.02 //('entering the diameter of the line in which water is flowing=:') dt=0.01 //('entering the diameter of venturi=:') B=0.5; // given // The discharge coefficients remains in the flat portion of the c...
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errcatch(-1,"stop");mode(2);//Ex:7.2 ; ; A_v_max=35; A_v_cutoff=0.707*A_v_max; printf(" Mid-band Volt gain = %f ",A_v_cutoff); printf("\n upper freq = 590Hz & lower freq = 57Hz"); exit();
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clc //Variable Initialisation V=440//Input Voltage of motor in volts Rf=100//Field resistance in ohm Il=50//Load Current in Ampere N1=900//Rated Speed of Motor in rpm N2=300//Rated Speed of Motor in rpm N3=400//Rated Speed of Motor in rpm N4=600//Rated Speed of Motor in rpm Ra=0.3//Armature resistance in ohm ...
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<<<<<<< HEAD // Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Li...
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//Obtain path of solution file path = get_absolute_file_path('solution8_11.sce') //Obtain path of data file datapath = path + filesep() + 'data8_11.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the x-coordinate of the C.G. of the three welds, origin being at G3 on weld3, xbar (mm) x...
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clc; clear all; disp("heat transfer rate") L=0.5;//m b=1;//m ts=30;// degree C rho=980.3;//kg/m^3 k=66.4*10^(-2);//W/m.C mu=434*10^(-6);// kg/ms hfg=2257*10^3;// J/kg g=9.81;// m/s tsat=100;// degree C ts=30;// degree C h=0.943*(rho^2*k^3*g*hfg/(mu*L*(tsat-ts)))^0.25; Q=h*L*b*(tsat-ts)*3600/1000; disp("k...
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clc //initialisation of variables T1=25//C T2=25//C g=0//ft^3/lbm v=0.00712//ft^3/lbm vd=0.00456//Btu/lb mole-R Bt=3.0*10^-6//atm^-1 Bd=0.16*10^-6//atm^-1 G=(1233/12)*(778/14.7*144)//Btu/lb mole-R //CALCULATIONS Gd=(v-vd)-(v*Bt-vd*Bd)//Btu/lb mole-R P=15500//atm //RESULTS printf('The pressure=% f atm',P...
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clc; clear all; close; // figure; t2=0:0.1:10 x2=exp(t2); plot(t2,x2); xlabel("Time"); ylabel("exponential"); figure; t3=-10:0.01:6; r=t3.*(t3>=0); plot(t3,r); xlabel("Time"); ylabel("Ramp"); figure; t4=0:4; x4=ones(1,5); plot(t4,x4); figure; t5=0:0.1:10; x5=sin(t5); plot(t5,x5);
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//Integration par la méthode de Romberg decroissante function y=f(x) y=exp(1+x.^2); endfunction; function I=IntTrap(f,a,b,h) I=(f(a)+f(b))/2; //h=(b-a)/n; x=a:h:b; n=length(x); if n>2 then I=I+sum(f(x(2:n-1))); end I=I*h; endfunction function r=g(X,Y,x) //A=s...
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deff('g=f(x,y)','g=2*y+x') xo=input("Enter initial value of xo: ") yo=input("Enter the value of yo: ") h=input("Enter value of h: ") xn=input("Enter Final value of xn: ") n=(xn-xo)/h for i=1:n k1=h*f(xo,yo) k2=h*f(xo+h,yo+k1) y1=yo+(1/2)*(k1+k2) xo=xo+h disp([xo y1]) yo=y1 end
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clc //initialisation of variables T2w= 100 //F T1w= 75 //F cw= 1 //Btu/lb F T2i= 100 //F T1i= 500 //F ci= 0.12 //Btu/lb F mi= 1 //CALCULATIONS Mw= -mi*ci*(T2i-T1i)/(cw*(T2w-T1w)) //RESULTS printf ('Pounds of water needed per pound of iron= %.2f lb water/lb iron',Mw)
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//Example 4.8 //Program to find the DFT of a Sequence x[n]=[1,2,3,4,4,3,2,1] //using DIF Algorithm. clear; clc ; close ; x = [1,2,3,4,4,3,2,1]; //FFT Computation X = fft (x , -1); disp(X,'X(z) = ');
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clc //initialisation of variables t=120//F p=0.2//percent p1=0.622//ft p2=0.6//percent h=0.0111//ft q=14.7//ft s=1.6924//ft w=0.3385//lb per h1=0.0185//lb per m=0.24//ft w1=1061.0//ft w2=0.445//ft //CALCULATIONS V=p2*h1//psia H=p1*(h/(q-h))//lb per lb dry air P1=p*s//psia H1=p1*(P1/(q-h1))//lb per ...
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//---------------- first test filen = 'test.bin'; mopen(filen,'wb'); mput(1996,'l');mput(1996,'i');mput(1996,'s');mput(98,'c'); mput(1996,'ul');mput(1996,'ui');mput(1996,'us');mput(98,'uc'); mput(1996,'d');mput(1996,'f'); // force little-endian mput(1996,'ll');mput(1996,'il');mput(1996,'sl');mput(98,'cl')...
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clc d1=0.1; //m rho_Hg=13600; //kg/m^3 rho=1000; //kg/m^3 g=9.81; //m/s^2 H=0.8; //m Cd=0.96; Q=0.025; //m^3/s a=%pi*d1^2/4; dp=(rho_Hg-rho)*g*H; B=((2*dp/(rho*((Q/Cd/a)^2)))+1)^(1/4); d2=d1/B; disp("Throat diameter =") disp(d2) disp("m") // The shortest possible overall length of venturi is ther...
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//clear// clear; clc; //Example 12.2 //Given Tb1 = 141; //[F] Tb2 = 79; //[F]/ Tw1 = 65; //[F] Tw2 = 75; //[F] Vb_bar = 5; //[ft/s] rho_b = 53.1; //[lb/ft^3] mu_b = 1.16; //[lb/ft-h], Form Appendix 9 k_b = 0.089; //[Btu/ft-h-F], From Appendix 13 Cp_b = 0.435; //[Btu/lb-F], From Appendix 16 //Using Appnd...
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//Ex 9.2 //Band Stop Filter Design //a clc; w1=1200; w2=2000; s=%s; w=poly(0,'w'); St=poly(0,'St'); wc=1; //For normalised Prototype wd1t=poly(0,'wd1t'); wt1=2500; wx1=(wt1*(w2-w1)*wd1t)/(-wt1^2+w2*w1); wt2=400; wx2=(wt2*(w2-w1)*wd1t)/(-wt2^2+w2*w1); disp(w); wx=wx1; // required attenuation to less ...
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function[u]=idinput(N,types,band,levels) //generates random binary input signal // //Calling Seqence //u=idinput(N); //u=idinput([n,nu]) //u=idinput([n,nu,m]) //u=idinput(__,type) //u=idinput(__,type,band) //u=idinput(__,type,band,levels) // //Parameters //N : no o...
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//------------------------------------ Método de Newton-Raphson ------------------------------- // code for SciLab // This find zeros of the function using approximit of derivate of function // Author : Daniel Marques //====================== Initial Definitions =========================== xn = 0 Er = 1 e = 0.01/10...
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Ex2_10.sce
clc; //ex2.10 Vss=10; //volt Vf=0.7; //volt R=100; //ohm //total current through the circuit by using kirchhoff's voltage law If=(Vss-Vf)/R; //Ampere //power dissipation form diode for Vf and If Pf=Vf*If; //Watt PDmax=(20/100)*Pf+Pf; //Watt//forward power dissipation that is 20% greater than value of Pf disp(...