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// Scilab Code Ex8.5: Page-8.35 (2004) clc;clear; mu = 9.4e-24; // Magnetic moment, ampere metre square H = 2; // Magnetic field , weber per squaremetre k = 1.38e-23; // Boltzmann Constant, joule per kelvin T = (2*mu*H)/(log(2)*k); //Temperature using classical statistics, K printf("\nTemperature using...
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//initial condition. set alpha exec("init.sce"); st = 7.45; exec("computeHandG.sce"); exec("buildMLCP.sce"); // the solution of this first MLCP is : nextL = [2.999496e-02; -1.999997e-02; 1.999997e+01; 9.994988e-03; 7.450000e+00; 0.000000e+00; 0.000000e+00; 1.999997e+01; 9.999990e+02]; ...
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clc clear //Initialization of variables tl=125 //F t0=80 //F t1=1000 //F d=1 //in k=25 //Btu/hr ft F k2=0.0208 Nu=18 //calculations byal=(tl-t0)/(t1-t0) al=acosh(1/byal) b=%pi*d/12 A=%pi*d^2 /(4*144) tm=(tl+t1)/2 +460 hr=0.79*0.1714*((tm/100)^4 - ((t0+460)/100)^4)/(tm-460-t0) hc=Nu*k2*12/d a=((hc+hr)*...
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:************************************************************************ : Patchname: RCVERR.TST product version: SDLC 1.12 : author: James Wang organization: sts : Customer: date written: fEB 22, 1991 : problem: When circuit is built, tif w...
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//Ex:8.11 clc; clear; close; h=0.35*10^-3;// irradiance W/cm^2 po=0.45*10^-3;// power output in watt d=1.5;// separation distance in cm x=sqrt((4*po)/(3.14*d^2*h));// divergence angle in radians X=(x*180)/3.14;// divergence angle in degree printf("The divergence angle =%f degree ", X);
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// Example 7.8;//overall power conversion efficiency clc; clear; close; Pc=150*10^-6;//Optical power in watt If=25;//forward current in milli ampere Vf=2.5;//forward voltage in volts P=If*10^-3*If;//power in watt npc=((Pc/P)*10^3);//overall power conversion efficiency disp(npc,"overall power conversion effici...
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clc; V=2; //in volts R1=30; //resisitance in Ohm R2=60; //resistance in Ohm Rp=(30*60)/(30+60); //calculating parallel resistance disp(Rp,"Resisitance in Ohm = "); //displaying result I=V/Rp; //Ohm's law disp(I,"Current in Ampere = "); //displaying result
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clc clear; x=[4, 5, 6] z=[1 2 3] y=[2 ; 2 ; 2] disp(x,'values of array x:') disp(z,'values of array z:') disp('array operations') disp(x+z,'addition');//add disp(x-z,'subtraction');//subtract disp(x.*z,'multiply');//multiply disp(x./z,'divide');//divide disp(y,'values of array y:') disp('matr...
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clear // //case a l=0.25 f=50 v=230 r=2 c=1/(((2*3.14*f)**2)*l) printf("\n c= %e ",c) //case b i=v/r printf("\n i= %0.1f A",i) //case c vl=2*3.14*f*l*i vc=i/(c*2*3.14*f) q=(2*3.14*f*l)/(r) printf("\n q")
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//Exa 5.12 clc; clear; close; //Given Data : format('v',8); R=2;//in ohm X=3;//in ohm VR=10*1000;//in volt P=1000*10^3;//in watt(power delivered) cos_fir=0.8;//unitless I=P/(VR*cos_fir);//in Ampere Vs=sqrt((VR*cos_fir+I*R)^2+(VR*sqrt(1-cos_fir^2)+I*X)^2);//in volt Reg=(Vs-VR)*100/VR;//in % disp(Reg,"% Reg...
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// Exa 2.5 clc; clear; close; // Given data v= 0.9/3;// in m^3/kg v= 2*v;// in m^3/kg mole (as M_hydrogen = 2) T=120+273;// in K R=8314;// in J/kg mole K a=2.51*10^4;// in Nm^4/(kg mole)^2 b= 0.0262; // Part (a) p= R*T/v;// in N/m^2 p= p*10^-5;// in bar disp(p,"Using perfect gas law the pressure for unit ...
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//Example 8.8 clc;clear;close; s=poly(0,'s'); z=poly(0,'z'); T=0.1; Hs=2/(s+1)/(s+2); Hz=ss2tf(cls2dls(tf2ss(Hs),T)); disp(Hs,'H(s)='); disp(Hz,'H(z)=');
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///Chapter No 7 Fluid Mechanics ///Example 7.9 Page No 118 ///Find Tangential speed of shaft //Input data clc; clear; mu=0.1; //Oil of viscosity used for lubricant in poise or Ns/m**2 D=0.15; //Clearance between the shaft of diameter in m dy=3*10^-4; //Clearance in m ...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 46 clc; disp("CHAPTER 1"); disp("EXAMPLE 46"); //VARIABLE INITIALIZATION v=240; //in Volts //SOLUTION //case1: p=60W p1=60; //in Watts r1=(v^2)/p1; disp(sprintf("Resistance of the metal filament lamp...
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clc disp("Example 5.43") printf("\n") disp("calculate the frequency of oscillation of RC phase shift oscillator") printf("Given\n") R=500 C=0.1*10^-6 //frequency of oscillation f=1/(2*%pi*R*C*sqrt(6)) printf("frequency of oscillation \n%f hz\n",f)
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example26_sce.sce
//chapter 19 //example 19.26 //page 882 printf("\n") printf("given") f=1*10^6;Xc=120;Vce=.5;Vcc=30;Rl=1.2*10^3;O=100; Cp=1/(2*3.14*f*Xc) Cp=1300*10^-12;//use standard value Lp=1/(((2*3.14*f)^2)*Cp) Vp=Vcc-Vce Po=((Vp)^2) /(2*Rl) Idc=Po/Vp T=1/f t=(O*T)/360 Ip=(Idc*T)/t
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//ques-1.11 //Calculating hardness of given water sample clc V=100;//volume of water sample (in mL) v=12.5;//volume of Magnesium sulphate (in mL) N=0.08;//normality of Magnesium sulphate h=(v*N)*50;//hardness in 100mL h=h*(1000/V);//hardness in 1L printf("Hardness of given water sample is %d ppm.",h);
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// Example 3.13 page no-176 clear clc veb=0.2 //V hfe=49 vz=6.3 //V i=5*10^-3 vi=8 //(1) y=veb+vz printf("\n1. The nominal output voltage is the sum of the transistor V_EB and zener voltage.\nV0=%.1f V\n",y) //(2) r1=(vi-vz)/i printf("\n2. R1 must supply 5mA to the zener diode\nR1=%.0f Ohm",r1) //(3) k...
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// Scilab Code Ex10.6: Page-512 (2011) clc;clear; V = 60;....// Electric potential of smaller drop, volt r = 1;....// For simplcity assume radius of each small drop to be unity, unit q = 1;....// For simplicity assume charge on smaller drop to be unity, C k = 1;....// For simplicity assume Coulomb's constant to be...
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userInput = input("Enter a positive whole number ") oldAnswer = 1 answer = 1 answerCount=0 Ea = 100 allowedError = 0 printf(" square root of %i Ea\n",userInput) while (Ea > allowedError) printf("n=%d ",answerCount) printf("%22.15f",answer) answer = (1/2)*(oldAnswer+(userInput/oldAnswer)) Ea = a...
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clc;clear; //Example 3.13 //Answer of part c-d are having slight difference due to approximation in molar volumne in the textbook which here is caluculated to the approximation of 7 decimal digits //given values T=175; v=0.00375; Pex=10000;//experimentaion determination //from Table A-1 R=0.2968// in kPa m^...
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//input impedance //given clc Zl=0//ohm Zo=50//ohm Bl=2*%pi*0.1//((2*pi/lem)*lem) Zi=Zo*(Zl+%i*Zo*tan(Bl))/(Zo+%i*Zl*tan(Bl))//the input impedence in ohm Zi=round(Zi*100)/100///rounding off decimals disp(Zi,'the input impedance of 50ohm loss less transmission line')
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function [vDiv, tDiv, offs, sCount, sRate] = determineAcquisitionSettings(connStr, channel) //Returns the acquisition settings of the Siglent SDS1202X-E oscilloscope. // //[vDiv, tDiv, offs, sCount, sRate] = determineAcquisitionSettings(connStr, channel) //connStr : enter VISA USB resourcename // (e.g. 'U...
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// Example 1.16 clc; clear; close; // Given data format('v',6); Vz= 1.8;// in V VBE= 0.7;// in V RE= 1;// in kΩ Beta= 180; VB= Vz-VBE;// in V IE= VB/RE;//emitter current in mA // Formula : I= IC= IE*(Beta/(Beta+1)) IC= IE*Beta/(Beta+1);// in mA disp(IC,"The value of current in mA is : ")
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//Example 3.4 //Program to estimate critical radius of curvature at which large //bending loss occur clear; clc ; close ; //Given data for part (a) n1=1.500; //metre - LENGTH delta=0.03; //*100 percent - RELATIVE REFRACTIVE INDEX DIFFERENCE lambda=0.82*10^(-6); //metre - OPERATING WAVELENGTH ...
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//calculating speed of machine //Chapter 2 //Example 2.13 //page 101 clear; clc; disp("Example 2.13") disp("At generator condition") P=50000; //power delivered in watts V=250; //voltage in volts Ra=0.02; //armature resistance in ohms Rf=50; //field resistance i...
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// ==================================================================== // Copyright DIGITEO 2010 // Allan CORNET // ==================================================================== // Call a new instance of Excel r = xls_NewExcel(); // Create a Workbook xls_AddWorkbook(); // Set Worksheet 1 xls_SetWorksheet(1)...
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clear // //variable declaration //summation of all horizontal forces is zero & vertical forces is zero. P1=(10) //Vertical down Load at 4m from A,KN P2=(15) //Inclined down Load at angle 30° at 6m from A,KN P3=(20) ...
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// Theory and Problems of Thermodynamics // Chapter 9 // Air_water Vapor Mixtures // Example 1 clear ;clc; //Given data X1 = 0.3 // volume fraction of N2 X2 = 0.5 // volume fraction of He X3 = 0.2 // volume fraction of CO2 m = 3000 // mass fl...
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clc; //Drawing of shear and bending moment diagram printf("Given problem is for drawing diagram, this diagram is drawn by step by step manner.\n "); F_AC=7200;//N/m, distributed load applied at A to C F_E=1800;//N, force applied at E AC=0.3;//m, perpendicular distance between A and B CD=0.15;//m, perpendicular di...
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clc; // page no 922 // prob no 25_3 L=45; T_Rtx=50; T_Rrx=75; T_Rf=100; T_RT=sqrt(T_Rtx^2 + T_Rrx^2 + T_Rf^2); // a) for NRZ fb=1/T_RT; disp('GHz',fb,'a) The maximum bit rate for NRZ'); // b) for RZ fb=1/(2*T_RT); disp('GHz',fb,'b) The maximum bit rate for NRZ');
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Teradata -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 4: OVERHEAD LINE INSULATORS // EXAMPLE : 4.2 : // Page number 183-184 clear ; clc ; close ; // Clear the work space and ...
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#Initialisation of some internal variables createvar(opticframe); ListOpticalObjects=list; ListRays=list; #Call this function to define the frame wherein the optics are defined and calculated function SetOpticFrame(iframe) { opticframe=iframe; } #Converts Hue-Saturation-Intensity to a color variable function HSI2...
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//Example No.3.2. // Page No.98. //To calculate numerical aperture and acceptance angle. clc;clear; n1 = 1.54;//Refractive index of core. n2 = 1.5;// Refractive index of cladding. no = 1; NA = sqroot((n1^(2))-(n2^(2)));//Numerical Aperture. printf("\nThe numerical aperture of the fibre is %.4f",NA); t = asin...
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//find the equation of voltage and current C=10e-6;//farad.. R=300;//ohms //i=2 sin 314t V=100;//volts f=50;//hertz Xc=1/(2*%pi*f*C); Z=sqrt(R^2+(Xc^2)); Im=2 Vm=2*Z coso=R/Z; o=acosd(coso); disp('The time equation of voltage Vr = 600sin(314t)' , 'The time equation of voltage Vc = 636sin(wt-90)')
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// Exa 3.25 clc; clear; close; // Given data R1= 10;// in kΩ R1=R1*10^3;// in Ω R2= 10;// in kΩ R2=R2*10^3;// in Ω I_C=.5;// mA V_T= 0.025;//in V I_C= I_C*10^-3;// in A V= 10;// in V Vth= V*R1/(R1+R2);// in V Rth= R1*R2/(R1+R2);//in Ω vo= I_C*Rth;// in V vi=V_T;// in V vo_by_vi= vo/vi;//in V/V disp(...
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clear, close exec ode1.sci; clc // parametry EI = 250e9; // sztywność na zginanie P = 5000; // wartość siły skupionej L = 2000; // długość belki // warunki początkowe h = 100; // krok x = 0:h:L; // x <0,L> function dydx = pochodna(x,y,P,EI,L) // równanie m...
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DS1[0]: Vehicle name : Airplane Sensor locations : Exterior (static) Intake Intake manifold Exhaust manifold DS1[1]: Vehicle name : Automobile Sensor locations : Roof
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//Circle n = 128; x = linspace(-1,1,n); y = linspace(-1,1,n); [X,Y] = ndgrid(x,y); r = sqrt(X.^2 + Y.^2); circle = zeros(n,n); circle(find(r<0.3)) = 1; imwrite(circle,'C:\Users\Marc Castro\Desktop\p166\Part1\Outputs\circle.png'); //Circle FFT circle_load = imread('C:\Users\Marc Castro\Desktop\p166\Part1...
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array <int> finalSeq[432] = {13,50,69,29,42,45,47,47,64,6,6,57,25,41,43,66,23,14,2,46,31,67,46,46,32,43,18,18,5,5,19,37,59,68,54,26,28,28,50,50,11,53,70,14,71,15,40,3,34,42,42,43,19,43,3,61,12,30,29,41,21,17,17,26,7,7,46,72,70,70,55,55,31,11,27,27,34,47,1,12,39,32,32,54,11,7,7,9,27,19,33,57,41,41,25,65,38,49,57,7,30,30...
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//A four point decimation-in-time FFT algorithm x=[1 2 1 0]; w=-%i; xdft=[0 0 0 0]; for i=1:4 for j=1:4 xdft(i)=xdft(i)+x(j)*w^((i-1)*(j-1)); end end XDFT=dft(x,-1); xdft,XDFT
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clear; clc; n=4; v2=14.2; v3=20; a=14.2;..//coeffiecients of the quadratic equation 14.2*k*k+22.6*k-5.8 b=22.6; c=-5.8; k=(-b+sqrt(b*b-4*a*c))/(2*a); v1=v2/(1+k); v4=(1+6*k+5*k*k+k*k*k)*v1; V=v1+v2+v3+v4; vl=sqrt(3)*V; eff=V/(n*v4); printf("\n the string efficiency is: %.2f percent",eff*100);
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////Given Rh=1.09678*10**7 //m-1 Rhe=1.09722*10**7 //m-1 //Calculation Mr=(Rhe-Rh)/(Rh-(Rhe/4.0)) //ratio of electron mass //Result printf("\n Ratio of the electron mas to the proton mass %0.2f *10**-4",Mr*10**4)
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function [x,y] =polar2rect (r,theta) x = r*cos(theta*%pi/180) y = r*sin(theta*%pi/180) endfunction function [degrees] = radian2degrees (radians) degress = radians *(180/%pi) endfunction
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//All the quantities are expressed in SI units T_inf = 288; //freestream temperature p_inf = 1; //freestream pressure p1 = 0.7545; //pressure at point 1 M = 0.9; ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART III : SWITCHGEAR AND PROTECTION // CHAPTER 4: UNSYMMETRICAL FAULTS IN POWER SYSTEMS // EXAMPLE : 4.9 : // Page number 519 clear ; clc ; close ; // Clear the work spac...
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//Example 2.8 clc clear function [f,df] = fun8(x) f = x.^3 - x - 1; df = 3*x.^2 - 1; endfunction xold = 1; maxit = 5; iter = 1; while (1) [fx,dfx] = fun8(xold); xnew = xold - fx/dfx; if iter == maxit then break end xold = xnew; iter = iter + 1; end root ...
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//Ex6_2 Pg-335 clc printf("Draw a vertical line from temperature axis at 50 degree \n celcius to cut the 71 degree celcius line. Join the point of \n intersection P through a horizontal line at Y-axis. The point \n where it intersects Y-axis gives the value of permissible \n dissipation equal to 45%% of maximum ra...
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//Chapter 12 //Example 12.11 //page 488 //To plot swing curves for fault cleared at 0.275s and 0.08s of a multimachine system clear;clc; xd1=%i*0.067;xd2=%i*0.1; //primitive admittances of the lines y45=1/(0.018+%i*0.11); B45=%i*0.113; y51=1/(0.004+%i*0.0235); B51=%i*0.098; y41=1/(0.007+%i*0.04); B41=%i*0.041...
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fortnitge .sce
Name=fortnitge PlayerCharacters=Cuboid - 100 BotCharacters=Cuboid - 100.bot;Cuboid - 100.bot;Cuboid - 100.bot;Cuboid - 100.bot;Cuboid - 100.bot IsChallenge=false Timelimit=30.0 PlayerProfile=A_air_pistol_frozen AddedBots=target.bot;target.bot;target.bot;target.bot PlayerMaxLives=0 BotMaxLives=0;0;0;0 PlayerTe...
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errcatch(-1,"stop");mode(2); //Example 1.43://limitting values and limiting error ; ; R1=25;//in ohms ER1=4;//percentage error R2=65;//in ohms ER2=4;//percentage error R3=45;//in ohms ER3=4;//percentage error er= (ER1/100)*(R1+R2+R3);//magnitude of resultant resistance limiting error r= (R1+R2+R3);//magnitude of result...
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drums = loadwave('DSP_2020_A3_DATA/drums.wav'); speech = loadwave('DSP_2020_A3_DATA/speech.wav'); violin = loadwave('DSP_2020_A3_DATA/violin.wav'); voice = loadwave('DSP_2020_A3_DATA/voice.wav'); all = loadwave('DSP_2020_A3_DATA/Violin_Viola_Cello_Bass.wav'); fir = loadwave('fir.wav'); function y=my_conv(f, g, filena...
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//example 7.9 clc; funcprot(0); // Initialization of Variable h1=3105.6; h2s=2743.0; nt=0.75;//effeiciency k=nt*(h1-h2s); disp(k,"Wcvdot/mdot in kJ/kg"); clear()
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-- VectorCAST 6.4d (02/29/16) -- Test Case Script -- -- Environment : SHAPE_2_W -- Unit(s) Under Test: combo -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCRIPT_FEAT...
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test9.sce~
src=imread("../images/image_0197.jpg.jpeg"); mask = roiFreeHand(src); c=illuminationChange(src,mask,1.9,0.8); imshow(c);
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n=6;m=5; L=([1:n]')*ones(1,m); // row number C=ones(n,1)*[1:m]; // column number D=1+abs(L-C) // diagonal index
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clc clear //Input data W=2.4//Work function in eV l=6000*10^-10//Wavelength of the light in m h=6.625*10^-34//Plancks constant in J.s c=3*10^8//Velocity of light in m/s e=1.6*10^-19//Charge of electron in Columbs //Calculations vo=((W*e)/h)/10^14//Threshold frequency in Hz*10^14 v=(c/l)/10^14//Frequency of ...
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y=[0.107533427909220; 0.663644537348001; 0.970587221665023; 0.608390883863076; -0.293540506673764; -1.42787086899790; -2.19233932281606; -1.88376277475872; 0.351621088370924; 4.20456888982602; 7.02440717036035; 6.65058196622351; 2.57013250348360; -3.50487012663216; -8.16852139220758; -8.56013313698647; -4.2042820915121...
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clear clc; dia=1.213; dist=1.25*100; f=50; rad=dia/2; effrad=.7788*rad; L=4d-7 * log (dist/effrad)*1d3; X=2*%pi*f*L; mprintf("L=%.2f *1e-4 H/km, X=%.1f ohm/km",L*1e4, X);
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//Chapter-11 example 48 //============================================================================= clc; clear; //Given data Vo = 3*10^8; // vel of EM wave m/s; PRF = 1000; // pulse repetitive freq. in Hz PW = 4*10^-6; // Pulse width in sec //Calculations Runamb = Vo/(2...
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ex1_39.sce
// Exa 1.39 clc; clear; close; format('v',6) // Given data V = 10;// in V R = 10;// in ohm // Current through resistance, I = V/R;// in A disp(I,"Part (a): The current through resistance in A is : ") disp("Part (b) : Current through 10 ohm resistance will be Zero") disp("Part (c): Current will be zero") di...
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// Caption: Finding maximum inductance for phase clear; close; clc; N=100; U_o=4*%pi*10^-7; alpha=%pi/3; R=3.8*10^-2; D=0.13; g=2.54*10^-4; L_max=N^2*U_o*alpha*R*D/(2*g); disp(L_max,'maximum inductance for phase 1=')
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//Test Stimulus File for Palindrome Chip load Palindrome.hdl, compare-to Palindrome.cmp, output-file Palindrome.out, output-list p%B3.1.3 q%B3.1.3 r%B3.1.3 s%B3.1.3 t%B3.1.3 out%B3.1.3; set p %B1, set q %B1, set r %B0, set s %B1, set t %B1, eval, output; set p %B1, set q %B0, set r %B0, set s %B0, set t %B1, eval, o...
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clc; clear; printf("\t\t\tChapter7_example9\n\n\n"); // determination of required current // properties of air at film temperature (300 + 500)/2 = 400 K from appendix table D1 rou= 0.883; // density in kg/cu.m cp= 1014; // specific heat in J/(kg*K) v= 25.90e-6; // viscosity in sq.m/s Pr = 0.689; // Prandtl Number k...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 7 Field Effect Transistors Pg no. 224 and 225 clear; clc; //Given Data IDSS=10D-3;//drain saturation current in amperes VP=6;//pinch-off voltage in volts VGS=-3;//gate to source voltage in volts //Solution disp("(i)"); ID=IDSS*(1-VGS/(-VP))^2;//drain cur...
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6_4.sce
//Example 6.4 //Gaussian Elimination Method without Pivoting //Page no. 227 clc;clear;close; A=[0.3*10^-11,1,0.7;1,1,0.9]; //augmented matrix //triangularization for i=1:3 B(1,i)=A(1,i) B(2,i)=A(2,i)-(A(2,1)/A(1,1))*A(1,i) end disp(A,'Augmented Matrix=') disp(B,'Triangulated Matrix=') ...
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clc m_O2=1; //kg m_H2=1; //kg p=1*10^5; //Pa T_O2=450; //K T_H2=450; //K T0=290; //K R0=8.314; M_O2=32; M_H2=2; R_O2=R0/M_O2; v_O2=m_O2*R_O2*T_O2/p; R_H2=R0/M_H2; v_H2=m_H2*R_H2*T_H2/p; v_f=v_O2 + v_H2; //total volume after mixing dS_O2=R_O2*log(v_f/v_O2); dS_H2=R_H2*log(v_f/v_H2); dS_net=dS_...
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ex1_1.sce
// Example 1.1, page no-8 clear clc r=0.45*10^-3 //m L=0.3 //m rho=17*10^-9 //ohm-m //Calculations R=rho*(L/(%pi*r^2)) printf("The Resistance of the wire is %.3f ohm",R)
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Ex12_1.sce
//===================================================================================== //Chapter 12 example 1 clc;clear all; //variable declaration Z1 = 100; //resistance of arm in Ω Z2 = 50; //resistance of arm in Ω Z3 = 200; //resistance of arm in Ω Z4 = 1...
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Ex16_5.sce
//Example 16-5,Page No - 661 clear clc T = 9.2 theta = 20 sin20 = 0.342 D_nautical = T/12.36 D_statute =D_nautical*0.87 A = D_statute*0.342 printf('\nThe line of distance to the aircraft in \nthe statute miles %.3f ',D_statute) printf('\n\nThe altitude of the aircraft is %.2f mi and in feet it is 11...
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// Ex6_6 Page:104 (2014) clc;clear; e = 1.6e-019; // Energy conversion factor, J/eV h_cross = 1.054e-034; // reduced Planck's constant, Js r = 1.131e-010; // Intermolecular separation of CO molecule, m m_Carbon = 19.9217e-027; // Mass of carbon atom, kg m_Oxygen = 26.5614e-027; // Mass of oxygen at...
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clc clear //Initalization of variables h3=85.282 //Btu/lb s2=0.16392 sf=0.16798 //calculations sfg=sf-0.023954 x3=-(s2-sf)/sfg h2=78.335 - x3*67.651 h4=26.365 //Btu/lb h1=h4 ref=h2-h1 work=h3-h2 cp1=ref/work h2d=78.355 h1d=26.365 //Btu/lb h3d=87.495 //Btu/lb ref2=h2d-h1d work2=h3d-h2d cp2=ref2/work2...
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clear; clc; //Example 4.4 b=100; Vbe=0.7; Va=100; V_T=0.026;//(V) //from dc analysis Icq=0.95; Vceq=6.31; //ac analysis r_pi=b*V_T/Icq; printf('\nsmall signal resistance=%.2f KOhm\n',r_pi) g_m=Icq/V_T; printf('\ntransconductance=%.3f mA/V\n',g_m) Rs=0.5; Rc=6; ro=Va/Icq; printf('\nro=%.2f KOhm\n',ro) ...
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// Grob's Basic Electronics 11e // Chapter No. 29 // Example No. 29_10 clc; clear; // Calculate the ac output voltage, vout. // Given data Rc = 1.2*10^3; // Collector resistance=1.2 kOhms Re = 2.2*10^3; // Emitter resistance=2.2 kOhms Rl = 3.3*10^3; // Load resistance=3.3 kOhms Rg = 600; ...
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exa_5_13.sce
//Exa 5.13 clc; clear; close; //given data Cp=0.138;// in KJ/kg-K m=8.33;// in kg/sec Pr=0.0238; k=8.7;// in W/mk d=1.5*10^-2;// in m miu=1.5*10^-3;// in kg/ms Re=4*m/(%pi*miu*d); Pe=Re*Pr; // Nu = h*d/k = 7+0.025*Pe^0.8 h= (7+0.025*Pe^0.8)*k/d;// in W/m^2 degree C disp(h,"Heat transfer coefficient in ...
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; assert with wrong sort (set-logic QF_LIA) (assert 1)
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@relation unknow @attribute mcg real[0.11,1.0] @attribute gvh real[0.13,1.0] @attribute alm real[0.21,1.0] @attribute mit real[0.0,1.0] @attribute erl real[0.5,1.0] @attribute pox real[0.0,0.83] @attribute vac real[0.0,0.73] @attribute nuc real[0.0,1.0] @attribute class{MIT,NUC,CYT,ME1,ME2,ME3,EXC,VAC,POX,ERL} @inputs...
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// Exa 2.3 clc; clear; close; // Given data rho= 0.60;// in Ωm q=1.6*10^-19;// in C miu_n= 0.38;// in m^2/vs miu_p= 0.18;// in m^2/vs sigma= 1/rho;// in (Ωm)^-1 ni= sigma/(q*(miu_n+miu_p));// in /m^3 disp(ni,"The intrinsic carrier concentration per meter cube is :")
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clc;funcprot(0);//Example 8.1 //Initilisation of Variables Tci=20;......//Inlet temparature of cooling water in degrees celcius Tco=40;......//Outlet temparature of cooling water in degrees celcius Thi=180;......//Inlet temparature of fluid on hot oil in degrees celcius Tho=140;......//Outlet temparature of fluid ...
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//error no output //ques11 disp('To find the inverse laplace transform of the function'); syms s t a f=s/(s^4+4*a^4); il=ilaplace(f,s,t); disp(il);
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# HEADER scenario = "Stop-signal anticipation task"; response_matching = simple_matching; active_buttons = 2; button_codes = 1, 2; default_background_color = 100, 100, 100; default_font = "Arial"; default_font_size = 40; # SDL begin; picture{ text{caption = "Stop-Signal Anticipation Task (SSAT) \nCopyright (c) 2017 B...
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clc r1=15.3; //V1/V2 r2=7.5; //V4/V3 p1=1; //bar T1=300; //K n_mech=0.8; C=42000; //kJ/kg y=1.4; R=287; cp=1.005; cv=0.718; V2=1; ////Assuming V2=1 m^3 T2=T1*r1^(y-1); p2=p1*r1^y; T3=r1/r2*T2; m=p2*10^5*V2/R/T2; T4=T3/r2^(y-1); Q_added=m*cp*(T3-T2); Q_rejected=m*cv*(T4-T1); W=Q_added-Q_rejected;...
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//Chapter 25 Ex 2 clc; close; clear; long=12; breadth=8; height=9; //all in meters ldia=sqrt(long^2+breadth^2+height^2); mprintf("The length of longest pole is %d meters",ldia);
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errcatch(-1,"stop");mode(2);// Exa 1.18 ; ; format('v',7) // Given data E_CminusE_F = 0.24;// in eV T = 300;// in K T1 = 350;// in K // E_CminusE_F = K*T*log(n_c/N_D) (i) // E_CminusE_F1 =K*T1*log(n_C/N_D) (ii) // From eq(i) and (ii) E_CminusE_F1 = E_CminusE_F*(T1/T);// in eV disp("The new position of the...
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clear; clc; close; Vi = 25*10^(-3); Acl = 30; SR = 0.5*10^6;//convertin from us to s K = Acl*Vi; fmax = SR/(2*%pi*K); disp(fmax,'Maximum frequency(Hertz) = ');
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clc Q=0.05; // m^3/s d=0.15; // m^2 h=8; // m g=9.81; // m/s^2 l=90; // m f=0.007; u1=Q/(%pi/4*d^2); t=-integrate('1/((h*g/l)+(2*f/d)*u^2)', 'u', u1, 0); disp("Time for which flow into the tank continues after the power failure = ") disp(t) disp("s")
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deff('y=f(x)','y=cos(x)') i=0:9; x=%pi/10*i; y=f(x); z=[%pi/7]; d=splin(x,y); [s,s1,s2,s3]=interp(z,x,y,d)
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clc; hw=7.5; //half wavelength in metre f=20*10^6; //frequency in Hz a=0.03; //area in metre square v=hw*a; //calculating voltage disp(v,"Voltage in volt = "); //displaying result
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$thermo = VirtualMaterials.Peng-Robinson / -> $thermo thermo + methane water 'Carbon dioxide' thermo.hypo1 = HypoCompound ''' NormalBoilingPoint = 100 C MolecularWeight = 108.0 LiquidDensity@298 = 880.0 kg/m3 ''' thermo.hypo2 = HypoCompound ''' NormalBoilingPoint = 373.15 MolecularWeight = 18 LiquidDensity@298 = 980...
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clear; clc; printf("\t\t\tProblem Number 6.22\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.22 (page no. 264) // Solution //data deltas=0.0743; //change in entropy //Unit:Btu/lbm*R T1=460+100; //Fahrenheit temperature converted to absolute initial temperature cv=0.219; //specific heat at constant volume...
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mode(7); // Primeira sessao no Scilab (parte 1) // define variável a = 1; // define outra variável (case sensitive) A = 2; // soma a + A // dois comandos na mesma linha c = [1 2]; b=1.5 // um comando em diversas linhas u = 1000000*(a*sin(A))^2+... 2000000*a*b*sin(A)*cos(A)+... 1000000*(b*cos(A))^2 // list...
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getd lib clf x=0:.1:12; for i=1:size(x,2) y(i) = 1/(1+exp(5-x(i)))+0.05*x(i); y2(i) = (1/(1+exp(5-10))+0.05*10)/10*x(i); end plot(x,y) cthick(2) plot(x,y2) ccolor("dark blue") cthick(2) pensize = 2 myfontSize=5 ylabs("Wealth at time t+1") xlabs("Wealth at time t") a=gca(); a.sub_t...
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-5, Illustration 8, Page 123 //Title: Estimation of humidity and saturation //======================================================...
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clear all; clc; disp("Ex 11_5") //Using the equation for equilibrium position, theta=asin(0) printf('\n\n Theta = %0.0f degrees',theta) m=10//mass in kg W=10*9.81//weight of the mass in N k=200//spring constant in N/m l=0.6//m theta1=acos(1-(W/(2*k*l)))//in radian theta2=theta1*180/%pi printf('\n\n Theta = %0.1f degree...
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function i2c_write(addr,data) rw(reg.I2C_ADDR,addr); rw(reg.I2C_DATA_W,data); rw(reg.I2C_WEN,1); while rw(reg.I2C_BUSY) sleep(1); end if rw(reg.I2C_NACK) error('No acknowledge from I2C'); end rw(reg.I2C_WEN,0); endfunction
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// Fourier Series Personal Project // Code by mtxslv // In the book "Numerical Analysis", by Burden&Faires, chapter 8, // The Fourier Series are introduced using the Least Squares approach. // This is another example, a classical one. The aim is to approximate the function // f(x) = {0, -%pi < x < 0 ; 1, 0 < x...
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errcatch(-1,"stop");mode(2);//Caption:Calculate the speed and BHP of the motor //Exam:2.51 ; ; V=250;//applied emf(in V) R_sh=0.05;//field resistance (in Ohm) R_a=0.1;//armature resistance(in Ohm) I=80;//motor current(in Amp) A_s=240;//armature slots C_s=4;//number of conductor per slot Z=A_s*C_s;//total n...