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//Chemical Engineering Thermodynamics //Chapter 11 //Liquefaction of Gases //Example 11.3 clear; clc; //Given //From the figure 11.8 (page no 216) & from figure A.2.7 H3 = 0; H7 = -47;//in Kcal/Kg H6 = -93;//in Kcal/Kg H8 = 7;//in Kcal/Kg //To Calculate the fraction of air liquified at steady state an...
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//variable declaration a=100 N_a=0.3 //Numerical aperture lamda=850 //wavelength //Calculations V_n=(2*(%pi**2*a**2*10**-12*N_a**2)/lamda**2*10**-18) //Result printf('Number of modes =%0.3f modes\n',(V_n/10**-36)) printf('No.of modes is doubled to account for the two possible polaris...
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//Exa 7.13 clc; clear; close; format('v',6) //given data T1=800;// in K T3=200;// in K sigma=5.67*10^-8; d1=20*10^-2;// in m d2=30*10^-2;// in m d3=40*10^-2;// in m A1=4*%pi*(d1/2)^2;// in m^2 A2=4*%pi*(d2/2)^2;// in m^2 A3=4*%pi*(d3/2)^2;// in m^2 epsilon1=0.2; epsilon2=epsilon1 epsilon3=epsilon1 Fg1...
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SPLITter v {} fiLter L { NoT ::C:ad:5:b:f:F:eCb/4 < T BiToR (6.183.226.251, ) or NOT hb ( bf:aD:8A:3C:fc:af , G, ) or nOt 7:b1:f:CFEa:a:BC:ebe:f >> cD:Bd:De:FE:ab:eA nOT bitoR () } fILter g {QC Or cj or NOT zk or S Or Scvny } E -> jpD GROUpEr VTN {AGgrEGaTe u.dW } UNGRoUper VD { } gROupFilTEr R {nOt cB:...
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${ using Typewriter.Extensions.Types; Template(Settings settings) { settings.OutputFilenameFactory = file => { var filename = file.Name.Replace("Controller", string.Empty).Replace(".cs", ".ts"); return $"endpoints/{filename}"; }; } string Import(Cla...
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I = imread('C:\Users\csrc-lab03\Desktop\Activity5\A.jpg'); Igray0 = rgb2gray(I); //Change image to grayscale. Igray = mat2gray(Igray0); FIgray = fft2(Igray); //Apply 2D FFT. F1 = mat2gray(abs(FIgray)); //Get magnitude of complex values. FS1 = fftshift(F1); //Shift quadrants back to proper image. F2 = fft2(FIgray)...
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//Defining a function that will give the profit vector when the stock is n units for 500 days clc,clear exec('milk.sce',-1) function profit=f(n) to_be_sold=zeros(500,1) //to_be_sold be the column vector that will tell us the amount of milk Akbar will decide to sell //we want to know the expected profit of...
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function [q2] = %s_m_ZQuat(a,q1) q2 = q1 * a; endfunction
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//Example 4_1 clc(); clear; //To calculate the force required vf=12 //units in meters/sec v0=0 //units in meters/sec t=8 //units in sec a=(vf-v0)/t //units in meters/sec^2 m=900 //units in Kg F=m*a //units in Newtons printf("The force required is F=%d N",F)
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//example 15.9 clc ; clear; //part (a) //an=input('Enter the analog input in volts :'); format('v',12);// changing the precision of calculation an=2.5; k=an*1000/19.53; k= round(k); m=dec2bin(k); // converting from decmal to binary printf('The digital output is :%s\n',m); //part(b) //dg=input('Enter the...
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// // 09,12.05 // 09.12.06 // 09.12.07 // 09.12.20 function Texcom(Meirei) global Wfile FID; if Meirei=='\thinlines' Setpen(1); return end if Meirei=='\thicklines' Setpen(2); return end if Meirei=='\Thicklines' Setpen(3); return end; if Meirei=='' // 09.12.07 Tmp=[]; el...
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For input string: "-d" java.lang.NumberFormatException: For input string: "-d" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at org.teherba.ramath.linear.RationalTriangle.main(RationalTriangle.java:5...
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M = 15 ; // Bending moment in k-in t = 10 ; // Angle between line of action of moment and z-axis // Properties of cross section c = 0.634 ; // Location of centroid on the axis of symmetry Iy = 2.28; // Moment of inertia in y-direction in in4 Iz = 67.4; // Moment of inertia in z-direction in in4 ya = 5 ; za = -2.6...
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//Ex:5.28 clc; clear; close; y=900;// operating wavelength in nm yo=1343;// wavelength in nm so=0.095;// in ps/nm^2-km L=150;// in km dy=50;//in nm Dy=(so*y/4)*(1-(yo/y)^4);// inps/nm-km Dy1=Dy*(-1);// do not consider -ve sign dt=Dy1*L*dy;// pulse spreading in ps dt1=dt/1000;// pulse spreading in ns printf...
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//Part A Chapter 7 Example 3 clc; clear; close; m=5;//kg cp_super_heat=2.1;//kJ/kgK cp_water=4.18;//kJ/kgK Tsuper_heat=300+273.15;//K Tsat=212.42;//degreeC(at 2 MPa) Tsat=Tsat+273.15;//K hfg=1890.7;//kJ/kg(For 2 MPa & Tsat)\ S=cp_water*log(Tsat/273.15)+hfg/Tsat+cp_super_heat*log(Tsuper_heat/Tsat);//kJ/kgK S...
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function [left_out ,right_out]=rectifyStereoImages(input_image1,cameramatrix1,Distortion_coff1,input_image2,cameramatrix2,Distortioncoff2,Translationvector,Rotationvector) // Rectify the pair of image taken by stereo camera // // Calling Sequence // [left_image,right_image] = rectifyStereoImages (input_image1,camerama...
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clc; //page no 190 //prob no. 6.4 //All frequencies in kHz fi=250; //input freq LSB=[fi-1 fi-3 fi-5]; USB=[fi+1 fi+3 fi+5]; disp(LSB,'(a) For LSB transmission freq are' ); disp(USB,'(b) For USB transmission freq are' ); W=5; BT=W; disp(BT,'(c) The transmission bandwidth is ');
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// Example 5.3, page no-175 clear clc m=0.6 //60% modulation //for A3E pt1=(1+(m^2)/2) //for J3E pt2=(m^2)/4 //% power saving p=(pt1-pt2)*100/pt1 p=ceil(p*10)/10 printf("Percentage power saving is %.2f%%",p)
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//what inequality is represented on no. line clear; clc; close; x=string(0:10); n=string('<'+strcat(x,'---')+'>'); //0 to 10 no. line n1=string(strsubst(n,'---8---9---10','_______________')); mprintf("\n the number line \n %s represents n>7 ",n1) ...
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x=[2.30256624769934; 2.29071803023829; 2.26283604900314; 2.35145015316178; 2.27686291358213; 2.29805616201205; 2.32805830340568; 2.30878734371402; 2.29343801980763; 2.23019030245799]; fs=4e6; t=(1/fs); [F,LT]=falltime(x,t); disp(F); disp(LT); //output // // 3006202.5 // // 35585880. //
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//find clc //solution //given P=22000//W Np=1800//rpm Ng=600//rpm a=(%pi/180)*30 q=(%pi/180)*20 Tp=24 vr=3 fo=50//N/mm^2 //b=4*pc oh=150//mm..overhang t=50//N/mm^2 T=P*60*1000/(2*%pi*Np)//N-mm printf("torque acting is,%f N-mm\n",T) Te=T/(cos(a))^3//N yb=0.154-(0.912/Te) //Wt=T/(Dp/2)=(2T/m/Tp)....Dp=...
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//=========================================================================== //chapter 11 example 5 clc;clear all; //variable declaration R1 = 1; //standard resistance in Ω V3 = 0.952-0.340*%i; //voltage through the coil in A a = 10; //multiplying power of potential divider V2 = 1.35+1.28*%i; //voltage ...
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clear all; Fs = 16 // sampling frequency T = 4.2 // time duration t = (0:1/Fs:T) f0 = 2 // signal frequency leak1 = sin(2*%pi*f0*t) f0 = 3 // signal frequency leak2 = sin(2*%pi*f0*t) f0 = 4 // signal frequency no_leak = sin(2*%pi*f0*t) summ = leak1+ leak2 + no_leak summ = resize_matrix(summ, 1, 1024) figure(0)...
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c = [-1;-1.4;0;0;0] G = -eye(5,5); q = [-0.1;-0.2;0;0;0]; A = [1,1,1,0,0;1,2,0,1,0;1,0,0,0,1]; b = [4;5.8;3]; x = [0.2;1.45;2.35;2.7;2.8]; u = ones(5,1); v = zeros(3,1); function tmx = tmax_U(u,du) tmx = 1e10; n = length(u) for i = 1:n if du(i) < 0 tmx = min(tmx,-u(i)/du(i)) en...
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function [%pt,scs_m,needcompile]=do_delete(%pt,scs_m,needcompile) // do_delete - delete a scicos object // get first object to delete //! // Copyright INRIA while %t if %pt==[] then [btn,xc,yc,win,Cmenu]=cosclick() if Cmenu<>[] then %pt=[] [Cmenu]=resume(Cmenu) elseif btn>31 then Cmen...
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clear; clc; //Example10.7[Condensation of Steam on horizontal Tube Banks] //Given:- Tsat=40;//[degree Celcius] D=0.03;//[m] Ts=30;//Outer Surface temperature of tube[degree Celcius] Tf=(Ts+Tsat)/2;//Film Temperature[degree Celcius] g=9.81;//[m/s^2] N=3;//No of tubes in a vertical tier N_total=12;//Total num...
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clear;lines(0); plot2d([-100,500],[-100,600],[-1,-1],"022") x=0:100:200; xnumb(x,500*ones(x),[10,20,35],1)
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function [] = kiks_gui_vis2dtoggle() // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- global...
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//Page Number: 106 //Example 2.22 clc; //Given c=3D+8; //m/s a=2.286; //cm a1=a/100; //m b=1.016; //cm b1=b/100; //m sig=5.8D+7; //s/m f=9.6D+9; //Hz w=2*%pi*f; mu=%pi*4D-7; et=377; lam=c/f; lamc=2*a1; r=lam/lamc; Rs=sqrt((w*mu)/(2*sig)); ac=(Rs*(1+(2*(b1/a1)*r*r)))/(et*b1*sqrt(1-(r^2))); adb=-...
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P=100000 N1=400 N2=100 a=N1/N2 r1=0.3 r2=0.015 x1=1.1 x2=0.055 V1=2400 R=r1+a*a*r2 disp(R) X=x1+a*a*x2 disp(X) I1=P/V1 pf=0.8 theta=acos(pf) Vd=I1*(R*cos(theta)+X*sin(theta)) VR=Vd/V1*100 V2=(V1-Vd)/a disp(VR,V2) Vd=I1*(R*cos(theta)-X*sin(theta)) VR=Vd/V1*100 V2=(V1-Vd)/a disp(VR,V2) pf=co...
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clc(); clear; // To calculate the position of fermi level Eg=1.12; //band gap in eV K=1.38*10^-23; T=300; //temp in K //EF = (Eg/2)+(3*K*T/4)*log(mh/me) //given me=0.12m0 and mh=0.28m0. therefore mh/me = 0.28/0.12 //let mh/me be X. therefore X=0.28/0.12 X=0.28/0.12; EF=(Eg/2)+((3*K*T/4)*log(X)); printf...
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*Testcase Storage Keys: S/390 then z/Arch mainsize 3 numcpu 1 sysclear archlvl ESA/390 # # CPUVERID C8 FORCE # (NEW starting with version 4.4) # # loadcore "$(testpath)/skey390z.core" f- A000 f- B000 runtest 0.2 *Done *Testcase Storage Keys: Pure z/Arch only mainsize 3 n...
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load CLA164.hdl, output-file CLA164.out, //compare-to CLA164.cmp, output-list a%D1.6.1 b%D1.6.1 AS s%D1.6.1 of%B6.1.6; set a %D200, set b %D496, set AS 0, eval, output; set a %D20000, set b %D20000, set AS 0, eval, output; set a %D-3000, set b %D-356, set AS 0, eval, output; set a %D-20000, set b %D-20000, set AS...
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//Ch25 Ex 4 clc; clear; close; lb=24; bb=12; hb=8; //dimensions of brick lw=2400; bw=800; hw=60; //converting meter to centimeter mortar=10/100; remaining=1-mortar; volWall=lw*bw*hw; volBricks=remaining*(volWall); vol1brick=lb*bb*hb; //volume of 1 brick noBricks=volBricks/vol1brick; //number of bricks requ...
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//chapter 21 Ex 10 clc; clear; close; t=3; rateHigh=2/100; amtHigh=360; Sum=amtHigh/(t*(1+rateHigh)-t); mprintf("The sum is Rs.%.0f",Sum);
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// Example 5.8 page no-290 clear clc vcc =20 //V rc=2 //K-Ohm re= 0.1 //K-Ohm r1=100 //K-Ohm r2 =5 //k-Ohm b=50 //beta vbe=0.2 //V v=r2*vcc/(r1+r2) rb=r1*r2/(r1+r2) ib=(v-vbe)/(rb+re*(1+b)) ic=b*ib*1000 ie=ib*1000+ic vce=vcc-ic*rc/1000-ie*re/1000 s=(1+b)*((1+rb/re)/(1+b+rb/re)) printf("\nV = %.3f...
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////Given E=-3.4 //ev h=6.63*10**-34 //Js //Calculation // n=sqrt(-13.6/E) M=(n*h)/(2.0*%pi) //Result printf("\n Angular momentum of electron is given by %e Js" ,M)
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clc // solution //initialization of variables P2=2*1000 //higher pressure converted in kPa P1=10 // lower pressure in kPa h1=192 // enthalpy at 10 kPa in kJ/kg h3=3248 // enthalpy @ state 3 in kJ/kg from table C.3 s3=7.128 // entropy @ state 3 in kJ/kg.K from table C.3 s4=s3 // isentropic process h4=((s4...
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clear; clc; Fm=3; //frequency of message signal Fc=8; //frequency of carrier signal Ea=5; Eb=10; m=Ea/Eb; //modulation index disp(m,"m="); USf=Fc+Fm*10^(-3);//Upper Sideband frequency LSf=Fc-Fm*10^(-3);//Lower sideband frequency disp(USf,"USf(Mhz)="); disp(LSf,"LSf(Mhz)="); Amp=m*Eb/2;// amplitude of ...
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clc,clear function x=testrand(n) x=[] for i=1:n x=[x',[rand()]']' end endfunction clf subplot(2,2,1) histplot(5,testrand(10),xlabel('-----values---->'),ylabel('--Frequency density---->'),xtitle('histogram plot of testrand(10)')) subplot(2,2,2) histplot(5,testrand(1000),xlabel('-----values---->'),yl...
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// PG (476) A = [0.2 0.6 0;1.6 -0.2 0;-1.6 1.2 3.0] U = [0.6 0 -0.8;0.8 0 0.6;0 1.0 0] Ustar = inv(U) T = Ustar*A*U trace(A) lam =spec(A)' lam1 = lam(1,1) lam2 = lam(1,2) lam3 = lam(1,3) lam1 + lam2 + lam3 // trace(A) = lam1 + lam2 + lam3 det(A) lam1*lam2*lam3 // det(A) = lam1 * lam2 * lam3
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// Grob's Basic Electronics 11e // Chapter No. 01 // Example No. 1_9 clc; clear; //Calculate the conductance for the following resistance values: (a) 1 kOhms (b)5 kOhms // Given data R1 = 1*10^3; // R1=1k Ohms R2 = 5*10^3; // R2=5k Ohms G1 = 1/R1; disp (G1,'The Conductance for Resistance valu...
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//Variable declaration i=10**-2 A=0.01*0.001 RH=3.66*10**-4 Bz=0.5 //Calculations Jx=i/A Ey=RH*(Bz*Jx) Vy=Ey*0.01 //Result printf('Jx = %0.3f ampere/m**2 \n',Jx) printf('Ey = %0.3f V/m \n',(Ey)) printf('Vy = %0.3f mV \n',(Vy*10**3))
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//definição das funções // como fala de g derivado < 1, ja colocar aqui a derivada function y=f(x) y=5*x^4 - 1.4*x - 1 endfunction function y=fl(x) y=20*x^3 - 1.4 endfunction //metodo de newton para o primeiro corte em y=0 x=-1 for n=1:10 x=x-f(x)/fl(x) disp(x) end //metodo de newton para o segundo cor...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 3: STEADY STATE CHARACTERISTICS AND PERFORMANCE OF TRANSMISSION LINES // EXAMPLE : 3.9 : // Page number 134 clear ; clc ...
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clc //initialisation of variables T= 2000 //K R= 1.987 //cal /mol K G= 31160 //cal //CALULATIONS Kp= 10^(-G/(2.303*R*T)) //RESULTS printf ('Equilibrium constant = %.2e ',Kp )
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clc; heat_supplied=2800;//kJ/kg heat_rejected=2100;//kJ/kg sigma_dQ=heat_supplied-heat_rejected; work_done=1000; work_reqr=5; sigma_dW=work_reqr-work_done; m=-sigma_dW/sigma_dQ disp("steam mass flow rate required is:"); disp("kg/s",m)
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//clear// //Caption:Program to find Relative Intensity Noise (RIN) //Example9.1 //page 320 clear; clc; close; IB_Ith = [1.3,1.4,1.5,1.6];//ratio between bias current and threshold current f = 100e06; //frequency = 100MHz RIN = ((IB_Ith-1)^-3)/f; RIN_dB = 20*log10(RIN); disp(RIN_dB,'Relative Intensity Noise(R...
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r=10; ro=5.5*10^(-8); l=3*10^(-2); a=ro*l/r; d=sqrt(4*a/%pi); disp("the diameter (in mm) is"); disp(d*10^3);
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//example 11 //Determining the final temperature of steam clear clc u2=3040.4 //final internal energy in kJ/kg hi=u2 //in kJ/kg P2=1.4 //final Pressure in MPa disp('Since, the final pressure is given as 1.4 MPa,we know two properties at the final state and hence,final state can be determined.The temperature corr...
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clear ; clc ; Isc= 25e3; i=2.55*Isc; L=1; r=0.24; F=2.046*(i^2)*10^-5/r; mprintf("the force on busbar per meter length =%d kgfper meter",F/1e3);
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// Theory and Problems of Thermodynamics // Chapter 5 //Second Law of Thermodynamcis // Example 19 clear ;clc; //Given data T1 = 573.15 // entering temperature of superheated steam in K P1 = 3.0 // entering pressure of superheated steam in MPa P2 = 20 // leaving ...
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//Program to find the inductance per phase per metre for a 3 phase double circuit line clc; clear; format('v',20) r=input("Enter the radius of the conductors in cm: ") GMR=0.7788*r*10^-2 dab=input("Enter the spacing of A and B in ms: ") dbc=input("Enter the spacing of B and C in ms: ") dac1=input("Enter the spa...
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//НАЧАЛЬНЫЕ ДАННЫЕ rho_g = 1; //начальная плотность газа N = 2; //количество фракций пыли rho_i = [1, 1]; //массив начальной плотности пыли//все rho_i больше 0 и их сумма меньше rho_s t_i = [0.01, 0.001]; //массив времён релаксации rho_s = 4; //истинная плотность пыли Cs = 1.0; //скорость звука в газе k = 2*%pi;...
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//Example 12.5 clc; clear; ful_scale_voltage = 0 ; for i=1:5 op_v(1,i)= 10/2^i; ful_scale_voltage = ful_scale_voltage + op_v(1,i); // calculating the full scale voltage end disp("full scale output voltage in volts is ="); disp(ful_scale_voltage)
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Fourier Single Mode Basis, P=7</description> <executable>IncNavierStokesSolver</executable> <parameters>SM.xml</parameters> <files> <file description="Session File">SM.xml</file> </files> <metrics> <metric type="L2" id="1...
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clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 4 // Principles of Fluid Flow // Example 4.1 // Page 172 printf("Example 4.1, Page 172 \n\n"); L = 3 ; // Length, [m] D = 0.01 ; // ID, [m] V = 0.2 ; // Average Velocity, [m/s] // From Table A.1 at 10 degree C rho=999.7 ; // [kg/...
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//directivity of half wave dipole //given clc Pr=1//watts r=1//as value of "r" do not effect the expression n0=120*%pi for(r!=0) I=sqrt(Pr/73) Emax=60*I/r si=r^2*Emax^2/n0 gdmax=4*%pi*(si)/Pr gdmax=round(gdmax*1000)/1000///rounding off decimals end disp(gdmax,'the directivity expression for half wave dipol...
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// main programm //-----------------------------------------------// path=get_absolute_file_path("scilab-src"); disp('HOME:'+path), getd(path + "src/graphisme"); // pour charger un repertoire en entier getd(path + "src/transformation"); //-------------------------------------------------// // test de vecteur vitesse...
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clear clc //Example 12.6 ENTROPY INCREASE ACROSS SHOCK WAVE //To find Approx Value function [A]= approx (V,n) A= round(V*10^n)/10^n; //V-Value, n-to what place funcprot (0) endfunction k=1.4; M1=1.5; //Downstream Mach number M2=approx(sqrt(((k-1)*M1^2+2)/(2*k*M1^2-(k-1))),3) //Pressure ratio, (p21=p...
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clc; v=10; //voltage in volt t=2; //time in sec r=40; //resistance in ohm p=(v^2)/r; //power e=5/5; //energy in Watt disp(p,"Power in Watt = "); //displaying power disp("2 W resistor is adequate."); //displaying result
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//可制御正準形を求める L=[-3 1; 1 0]; Mc=cont_mat(A,b); Tc=inv(Mc*L); Ac=Tc*A*inv(Tc); bc=Tc*b; cc=c*inv(Tc);
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//determine the power dissipiated in resistance //v=200 sind 314t Vm=200; o=314; //@=omega //i=50 sind 314t Im=50 o=314 R=Vm/Im I=Im/1.414 P=(I*I*R) disp( 'power dissipiated in resistance='+string(P)+' watts')
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// FUNDAMENTALS OF ELECTICAL MACHINES // M.A.SALAM // NAROSA PUBLISHING HOUSE // SECOND EDITION // Chapter 5 : DIRECT CURRENT MOTORS // Example : 5.7 clc;clear; // clears the console and command history // Given data I_a1 = 65 // supply current to dc series motor in A V_t = 230 // supply volt...
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OK [13] (load "mbase/pl.m") Model of type atomic-models with name PL made. Processor of type simulators with name S:PL made. OK [14] (send pl inject 'in '(g1 (1 2 3 4 5 6 7 8 9 10 11 12 13 14 15))) state s = state s = (9 BUSY (G1 (1 2 3 4 ...
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int f(float x) { int x; /* ошибка */ }
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// Demo script for 1 hot encoding getd('../macros/') // Data preparation M = read_csv('Datasets/titanic.csv') x = M(:, 12); x = stripblanks(x) x(or(isnan(x),'c'),:) = [] l = size(x) y = [] for i = 1:l(1) if(strcmp(x(i), '') ~= 0) y = [y;x(i)]; end end x = y [categories, encode] = hotEncode(x); disp(categories); ...
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//Chapter-4, Example 4.21, Page 147 //============================================================================= clc clear function [polar] = r2p(x,y)//function to convert rectangular to polar polar = ones(1,2) polar(1) = sqrt ((x ^2) +(y^2)) polar(2) = atan (y/x) polar(2) =(polar (2)*180)/%pi endfunc...
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///Chapter No 7 Fluid Mechanics ///Example 7.16 Page No:127 ///Find continuity discharge equation ///input data clc; clear; ///refer figure 11 ZA=2; //water flows section A-A in m DA=0.3; //datum pipe diameter at section A-A in m PA=550*10^3; //pressure in kPa VA=6...
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// Exa 2.16.2 clc; clear; close; format('e',9) // Given data l = 0.1;// in m A = 1.7;// in mm^2 A = A * 10^-6;// in m^2 R = 0.1;// in ohm At = 63.5;// atomic weight N_A = 6.02*10^23; d = 8.96;// in gm/cc n = (N_A/At)*d;// in /cc n = n * 10^6;// in /m^3 //Formula R = Rho*(l/A); Rho = (R*A)/l;// in ohm m ...
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//Example 3.13 clc; clear; close; format('v',6); //Given data : a=8;//meter b=6;//meter h=3;//meter CD=2;//meter theta=30;//degree A=(a+b)/2*h;//meter^2 AB=(a+2*b)/(a+b)*h/3;//meter x1bar=AB;//meter BC=AB*sind(theta);//meter BD=BC+CD;//meter xbar=BD;//meter g=9.81;//gravity w=g*1000;//in N/m^3 p=w*A*...
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// Exa 8.4 clc; clear; close; // Given data R_f = 1;// in Mohm R_f = R_f * 10^6;// in ohm disp("Part (a)") V1 = 1;// in V V2 = 2;// in V V3 = 3;// in V R1 = 500;// in kohm R1 = R1 * 10^3;// in ohm R2 = 1;// in Mohm R2 = R2 * 10^6;// in ohm R3 = 1;// in Mohm R3 = R3 * 10^6;// in ohm V_o = -(R_f) * ( (V1...
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//example 5.5 clc; funcprot(0); B=5; L=10; Ef=2.3e6; Eo=1400; k=25; t=1.0; mus=0.3; Df=5; qo=5000; Ig=0.69; Be=sqrt(4*B*L/%pi); If=%pi/4+1/(4.6+10*(Ef/(Eo+2*Be/2*k))*(2*t/Be)^3); Ie=1-1/(3.5*exp(1.22*mus-0.4)*(Be/Df+1.6)); Se=qo*Be*Ig*If*Ie/Eo*(1-mus^2)/144; disp(Se*12,"settlement in inches");
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stacksize('max'); chdir('/home/anderson/VisaoComputacional/MaisLuz'); rotulo = ls('*.jpg'); QTDimagens = size(rotulo,1) M = [ ] for i = 1 : QTDimagens im = imread(rotulo(i)); M = [ M, im(:) ]; end [l,c,p] = size(im); ImMedia = mean(M,'c'); ImMedia = matrix(ImMedia,l,c,p); xset('window',1); imshow...
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// Scilab Code Ex5.13 : Page-5.25 (2004) clc;clear; V = 15000; // Accelerating potential, volts lam = 12.26/sqrt(V); // de Broglie wavelength, angstrom printf("\nde Broglie wavelength of electron wave = %5.1f angstrom", lam); // Result // de Broglie wavelength of electron wave = 0.1 angstrom
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//Stator Current and pf and efficiency of a motor operating at 0.03 slip clc; clear; V=400; Vph=V/sqrt(3); R1=0.2; R2=0.15; X1=%i*0.5; X2=%i*0.3; s=3/100; Ptl=2000; // Total Losses Z1=R1+X1; Z2=(R2/s)+X2; Zt=Z1+Z2; // Total Impedance of the circuit Is= Vph/Zt; // Stator Current Ctheta=atand...
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mode(-1); // Copyright (C) 2017 - IIT Bombay - FOSSEE // // This file must be used under the terms of the BSD. // This source file is licensed as described in the file LICENSE, which // you should have received as part of this distribution. The terms // are also available at // https://opensource.org/licenses/BSD-3-C...
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//MissionB3 function missionB3(imgB3) disp("Résultat de la mission B3 :") [y,x]=size(imgB3) display1=zeros(y,x) display2=zeros(y,x) display3=zeros(y,x) display4=zeros(y,x) for i=1:1:y for j=1:1:x if (imgB3(i,j)<= 64) then //disp("DEBUG 1") display1(i,j)=255 ...
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//Ex9_7 clc IIL=-1.6*10^(-3) disp("IIL= "+string(IIL)+" A") // Input sink Current of TTL driver IIH=40*10^(-6) disp("IIH= "+string(IIH)+" A") // source (supply) reverse Current of TTL driver IOL=16*10^(-3) disp("IOL= "+string(IOL)+" A") // Specified Maximum sink Current of TTL driver IOH=-400*10^(-6) disp("...
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example7_sce.sce
// chapter 3 // example 3.7 //page 135 A=10;//d.c gain R1=10000; F=10000;//input frequency CfRf=15915*10^-4; Fa=F/A; Rf=10*R1;// A=Rf/R1 //Fa=1/(2*3.14*Rf*Cf) Cf=15915*10^-4/Rf; disp(Cf) Rcomp=(R1*Rf)/(R1+Rf); disp(Rcomp)
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g_two_safe_groups_2_0.5.tst
#----------------------------------------------------------------------------- # Position evaluation tests involving two safe white groups on the 9x9 board. # All these positions are lost for Black so the uct_value should be low. #----------------------------------------------------------------------------- #----...
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metodoFalsaPosicion.sce
clear() clf() function xr = biseccion(xl,xu,n,fx) for i = 0:1:n xr = (xl+xu)/2 if(fx(xl)*fx(xr)<0) xu = xr else xl = xr end plot(xr ,fx(xr),"marker","p") xstring(xr, fx(xr),"B"+string(i+1)) end endfunction function xr ...
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exp_10_1.sce
clear; clc; v=[complex(100,0);complex(-75,129.90);complex(-105,-181.865)]; a=complex(-.5,.866); A=[1 1 1;1 a^2 a;1 a a^2]; vs=inv(A)*v; mprintf("symmetrical components of phase voltages are \n"); disp(vs);
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Example2_5_b.sce
//Example 2.5(b) clear; clc; R1=15*10^3;//From the result of Example 2.4 p=0.001;//For 1% tolerance p=t/100=1/100=0.01 emax=4*p;//imbalace factor Romin=R1/emax; printf("Ro can be anywhere in the range Ro>=%.2f Mohms",Romin*10^(-6));
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7_5.sce
//To find velocity and angular velocity clc //Given: NAO=120 //rpm OA=100/1000,CE=350/1000 //m //Solution: //Refer Fig. 7.13 //Calculating the angular speed of the crank OA omegaAO=2*%pi*NAO/60 //rad/s //Calculating the velocity of A with respect to O vAO=omegaAO*OA //m/s vA=vAO //By measurement from the ve...
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//system// s=%s; sys=syslin('c',1/(s*(s+2))) nyquist(sys) show_margins(sys,'nyquist') printf("Since P=0(no of poles in RHP)=Poles of G(s)H(s) \n here the number of zeros of 1+G(s)H(s) in the RHP is zero \n hence the system is stable")
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// 08.09.26 // 09.09.21 // 09.09.26 // 09.10.01 // 09.10.03 // 09.10.05 // 09.10.08 // 09.10.09 ( format=20) // 09.10.15 ( added Assign('') : reset // 09.10.17 ( Matrix added, ? -> number returned) // 09.10.21 ( list supported with Makeliststr ) // 14.10.04 format=12 // 14.12.11 only replaced when variable name /...
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//chapter 4 //example 4.1 //page 102 clear all; clc ; //given Rc=9;//collector resistance in kohm Ic1=0;//collector current Vcc=20;//supply voltage Vce1=Vcc;//point A(Vce,Ic)=(20,0) Vce2=0;//collector to emitter voltage V Ic2=Vcc/Rc;//mA //point F(Vce2,Ic2) plot([Vce1 Vce2],[Ic1 Ic2],'-.*'); xtitle('dc lo...
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//Ex 5.7 clc;clear;close; format('v',6); R1=10;//kohm R2=16;//kohm C=10;//nF R=62;//kohm Beta=R1/(R1+R2);//unitless T=2*R*1000*C*10^-9*log((1+Beta)/(1-Beta));//seconds f=1/T;//Hz disp(f,"Frequency of oscillations(Hz) : ");
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example13_17.sce
//Chapter 13 //Example 13_17 //Page 329 clear;clc; l=1000; i=1.25; r_km=0.05; r=2*r_km/1000; I=i*l; R=r*l; vd=I*R/8; //Part 1 is derivation of maximum voltage drop and is not included in the code. Only Part 2 is solved. printf("(i) Total current supplied by distributor = %d A \n\n", I); printf("Total resistance o...
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ex25_24.sce
clc;clear; //Example 25.24 //binary to hexadecimal conversion //given values X='1011101';//binary number //calculation x=bin2dec(X);//decimal equivalent z=dec2hex(x); disp(z,'hexadecimal number is ');
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//fiber optic communications by joseph c. palais //example 10.4 //OS=Windows XP sp3 //Scilab version 5.4.1 //given clc; clear all; deltaf=200//Frequency deviation in MHz/mA fm=300//modulation frequency in MHz pac_current1=1//peak ac current in mA pac_current2=5//peak ac current in mA //to find deltaf1=d...
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errcatch(-1,"stop");mode(2);//Exa 7.14 ; ; //Given data : format('v',7); //Applying KVL on +ve side V1=200-(600*0.015)-(100)*0.03;//in volt disp(V1,"Voltage at +ve side(in V): "); //Applying KVL on -ve side V2=200-(-100*0.03)-500*0.0015;//in volt disp(V2,"Voltage at -ve side(in V): "); //Note : answer of ...
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clc //initialisation of variables p= 4/3 //atm p1= 1 //atm R= 1.9872 //cal /mole K //CALCULATIONS S= 2*R*log(p/p1) //RESULTS printf (' increase in entropy= %.4f cal deg^-1',S)
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// Example 6-7-2 // Step and ramp response of lag compensated system clear; clc; xdel(winsid()); //close all windows // please edit the path // cd "/<your code directory>/"; // exec("plotresp.sci"); s = %s; G = 1.06 / (s * (s + 1) * (s + 2)); Kc = 0.9956; z = 0.05; p = 0.005; Gc = Kc * (s + z)/(s + p); GGc = G*G...
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${ using Typewriter.Extensions.Types; using System.Text.RegularExpressions; using System.Diagnostics; string ToKebabCase(string typeName){ return Regex.Replace(typeName, "(?<!^)([A-Z][a-z]|(?<=[a-z])[A-Z])","-$1", RegexOptions.Compiled) .Trim().ToLower(); } ...