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TranspositionSet={[0,2,1,3],[1,0,2,3],[1,2,0,3],[2,1,0,3],[2,0,1,3]} considerNonPrimitive Expanding for base=5, level=1, reasons+features=base,transpose,primitive,same,similiar Refined variables=a,b,c,d [0+1a,0+1b,0+1c,0+1d]: unknown -> [1] [0,0,0,0] a³+b³+c³-d³ -> solution [0,0,0,0],trivial(3) [1,0,0,1],trivial(...
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//Wave Propagation : example 13-3 : (pg 646) x=(32+(44/60)+(36/3600));// N latitude y=(106+(16/60)+(37/3600));//W longitude D=42.1642*10^6;//distance from the satellite to the center of the earth R=6.378*10^6;//earth's radius a=32.74333; B=-7.27694; m=D^2; n=R^2; e=2*D*R; q=cosd(a)*cosd(B); d=sqrt(m+n-(e*q))...
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//Ex9_4 Pg-475 clc funi=1*10^(6) //unity frequency in Hz Sr=0.5/10^(-6) //slew rate in V/sec Acl=10 //close loop gain fcl=funi/Acl //close loop frequency in Hz printf("(1) Close loop Bandwidth = %.0f kHz \n",fcl*10^-3) Vp_max=Sr/(2*%pi*fcl) //output peak value printf(" (2) Peak value of output = %.3f V \n...
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clc //initialisation of variables g= 10 //gm d= 1.038 //gm/mol M= 100 //gm x= 66.412 y= 0.127 z= 0.038 l= 20 //cm //CALCULATIONS p= g/(M/d) X= x+y-z ar= X*l*p/10 //RESULTS printf (' angle ofrotation= %.2f degrees ',ar)
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// Chapter 4 Example 10 //============================================================================== clc; clear; // input data l = 0.1*10^-9; // side of cubical box h = 6.625*10^-34 // plancks constant in Jsec m = 9.11*10^-31 // mass of electron in Kg Kb = 1.38*1...
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% READ_MESH_FROM_XML Read a mesh from an xml file written using % igl::serialize_xml V from the <vertices> tag and F from the <faces> tag. V % may be written using CGAL::Epeck but will be converted summarily to % double upon reading. % % [V,F] = read_mesh_from_xml(filename) % % Inputs: % filename path to .xml file %...
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clc; clear all; x=input("What is binary counter output?")//to take input of binary counter o/p if x==0 then disp(10,'output frequency in khz is=');//for binary counter o/p=0 else disp(x*10,'output frequency in khz is=');//for binary counter o/p!=0 end
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// Problem no 4.4.5,Page No.93 clc;clear; close; w1=30 //KN/m //u.d.l on L_CB F_C=120 //KN //Pt Load at C w2=50 //KN/m //u.d.l on L_AD L_DC=2;L_CB=2 //m //Length of DC and CB respectively L_AD=4 //m //Length of AD L_AB=8;L=8 //m //Length of beam //Calculations //Let R_A & R_B be the reactions at A & B //R_A+R_B=38...
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// Example 35_6 clc;funcprot(0); //Given data MD=50;// MW md=10;// MW n_o=60/100;// Over all efficiency of the plant L_h=60;// MWh // Calculation // From Fig.Prob.35.6 // Area DEGHD=0.6*Area EFBE; // xy-120*10^3=(24-x)*(40*10^3-y)0.6;.....(a) // y/40000=x/24;.....(b) // Solving (a) and (b),we get // x^...
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clc //initialization of varaibles disp("From steam tables,") T2=213 //F v2=23.9 //cu ft/lb W=133.7 //B/lb //results printf("Final specific volume = %.1f cu ft/lb",v2) printf("\n Final temperature = %d ",T2) printf("\n Work done = %.1f B/lb",W)
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//Example 4.4 clear; clc; fc=100; f01=fc/1.300; Q1=1.341; f02=fc/0.969; H0dB=20; H0=10^(H0dB/20); C=100*10^(-9); C1=C; C2=C; n=C1/C2; m=n/(((n+1)*Q1)^2); R=1/(2*%pi*f01*((m*n)^(1/2))*C); R21=R; R11=m*R; //The second op amp is first order high pass filter with high freq...
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clear; xdel(winsid()); mn = 100; //количество измерений b_size = mn+1; dt = 1; //период измерения data = read('goo1.txt', 3*b_size, 1); //показания 1 датчика высоты x(1,:) = data(1:b_size); //показания 2 датчика скорости x(2,:) = data(b_size+1:2*b_size); //вектор измерений z = data(2*b_size+1:$); //начальный векто...
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//example-5.1 //page no-136 //given //wavelength of X-rays beams of light lambda=0.824*10^-10 //m //glancing angle of the incident light theta1=(8+35/60)*(%pi)/180 //radians n1=1 //to find theta3 i.e at n3=3 //as we know that //2*d*sin(theta)=n*lambda //so for n1 and n3 we get in the same way and solving ...
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map1301" Width="13" Height="11" CellSize="40" BackgroundSize="1" Background="11plus.png"> <Cell Name="木箱" X="3" Y="1" /> <Cell Name="冰块" X="5" Y="1" /> <Cell Name="冰块" X="6" Y="1" /> <Cell Name="木箱" X="7" Y="1" /> <Cell Name="房子" X="8" Y="1" /> <Cell Na...
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//pathname=get_absolute_file_path('11.19.sce') //filename=pathname+filesep()+'11.19-data.sci' //exec(filename) //Ambient temperature(in K): Ta=20+273 //Velocity(in m/s): V=20 //Draught lost through grate(in mm of water column): hw1=30 //Mechanical efficiency: nm=0.80 //Rate at which coal is burnt(in kg/hr): ...
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PL/SQL Developer Test script 3.0 30 -- Created on 22/04/2016 by libertadAdmin DECLARE vID CURSO.ID%TYPE; vNombre CURSO.NOMBRE%TYPE; vCosto CURSO.COSTO%TYPE; vActivo CURSO.ISACTIVO%TYPE; vEdadMin RANGOEDAD.VALORMIN%TYPE; vLunes HORARIOSEMANAL.LUNES%TYPE; vMartes HORARIOSEMANAL.MARTES%TYPE; v...
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clc; clear; close; mprintf('T1=(R1*C1)+(R1*C2)+(R1*C3)\n\n');//for node 1 mprintf(' T2=(R1*C1)+(R1*C3)+(R1+R2)*C2\n\n');//for node 2 mprintf(' T3=(R1*C1)+(R1*C2)+(R1+R3)*C3\n\n');//for node 3
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errcatch(-1,"stop");mode(2);//3.8 ; Sp_constant=10.5*10^-6*%pi/180; deflection=83; Td=Sp_constant*deflection; I1=10; K=0.078; I2=(Td/(K*I1))*10^6; printf("Current in the voltage coil=%.2f uA",I2) exit();
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int x; int y; int z; void main(void) { }
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clc; T_AB=4200;//N , Tension in cable AB T_AC=6000;//N , Tension in cable AC // Vector AB=-(5m)i+(3m)j+(4m)k //Vector Ac= -(5m)i+(3m)j+(5m)k ABx=-5;//m ABy=3;//m ABz=4;//m ACx=-5;//m ACy=3;//m ACz=-5;//m AB=sqrt((-5)^2+3^2+4^2);//m, Magnitude of vector AB AC=sqrt((-5)^2+3^2+5^2);//m, Magnitude of vector A...
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//signals and systems //Unilateral Laplace Transform: transfer function //example 4.16 s = %s; syms t s; y1 =laplace('24*%e^(-3*t)+48*%e^(-4*t)',t,s); disp(y1) y2 =laplace('16*%e^(-3*t)-12*%e^(-4*t)',t,s); disp(y2)
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// Example 3.14 clear all; clc; // Fission of 1 g of Uranium-235 releases approximately 1 MW/day of energy. // 1 MW/day = 8.64*10^(10) J energy_uranium = 8.64*10^10; // 1. Coal h_coal = 3*10^7; // Heat contenet of coal in J/kg // Calculation amt_coal = energy_uranium/h_coal; // Result printf('\n Am...
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// Scilab code Ex4.25 : Pg:167 (2008) clc;clear; lambda = 5880e-008; // Wavelength of light, cm mu = 1.5; // Refractive index of mica r = 60; // Angle of reflection in the plate, degree n = 1; // Order of fringes for the smallest thickness t = n*lambda/(2*mu*cosd(r)); // The smallest thickness of t...
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//Exa 1.26 clc; clear; close; //given data BETAac=100;//unitless BETAdc=100;//unitless VT=25;//in mvolts VEE=10;//in volts VCC=10;//in volts VBE=0.7;//in volts VEB=-0.7;//in volts RC2=2.7;//in kohm RC1=2.7;//in kohm RC3=1.5;//in kohm RC4=1.5;//in kohm RE1=5;//in kohm RE2=10;//in kohm RE3=10;//in kohm ...
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//Two-Port Networks : example 11.29 :(pg11.59 & 11.60) printf("\nApplying KCL to Node 1 \nI1 = 3V1 - 2V2- - -(i)"); printf("\nApplying KCL to Node 2 \nI2 = 3V2 - V3 - - - -(ii)"); printf("\nApplying KCL to Node 3 \nV3 = (1/3)V2 - - - -(ii)"); //substituting (iii) in (i) & (ii),we get printf("\nI1 = 3V1 - (2/3)V2 \...
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clc clear D=0.25; L=0.4; Pm=6.5; N=250; W=1080; Ddrum=1.5; Mf=10; CV=44300; A=(22/7)*(1/4)*D*D; IP=(Pm*100*A*L*N)/(60*2); printf('Indicated Power= %3.2f kW',IP); printf('\n'); Reff=Ddrum/2; W=1.08; BP=[2*(22/7)*N*W*Reff]/60; printf('Brake Power= %3.2f kW',BP); printf('\n'); Em=BP/IP; Eith=...
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clc //solution //given //refer fig 9.29 and 9.30 T=100//N/mm^2 n=4 d=20//mm //Ps=P/4=0.25*P//N e=100//mm //T1=P*e//turning moment //la=ld=200=100//mm //lb=lc=100//mm //eqauting the moments equal to each other //P*e=(Fa/la)*[la^2+lb^2+lc^2+ld^2] //P*e=(Fa/la)*[2*300^2+2*100^2] //Fa=P*100*3/2000//N //Fa=0.15*P//N //Fb=...
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function [z]=%pap(x,y) //z = x + y one of which is a polynomial // and other matrix polynomial [m,n]=size(x) if m*n==1 then z=x*ones(y)+y else z=x+y*ones(x) end
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clc // Given that alpha = %pi / 180 // angle of bi prism in radian mu = 1.5 // refractive index of biprism a = 0.4 // distance of bi prism from slit in meter b = 0.6 // distance of bi prism from screen in meter lambda = 5.893e-7 // wavelength of light in meter // Sample Problem 11 on page no. 1.43 printf("\n ...
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clc //initialisation of variables d= 0.275 //in p= 15 p1= 20 p3= 8 //CALCULATIONS Fs= (d*p/100)+(d*p1/100)-(d*p3/100) Fs1= Fs*100/d //RESULTS printf ('final available squeeze = %.2f percent',Fs1)
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//fiber optic communications by joseph c. palais //example 2.6 //OS=Windows XP sp3 //Scilab version 5.4.1 //given spotsize=1e-3//spot size lambda=0.82e-6//wave length d1=10//distance in m d2=1e3//distance in m d3=10e3//distance in m //to find div1=2*lambda/(%pi*spotsize) wo1=lambda*d1/(%pi*spotsize) wo2=la...
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clc clear //DATA GIVEN p=20; //pressure in the boilers and main is 20 bar Tbs=350; //temperature of steam in boiler with superheater in deg. celsius Tm=250; //temperature of steam in the main in deg. celsius Cps=2.25; //specific he...
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//Example 2.25 clc; x1=[1,1,1,1] x2=[2,2,2,2] a=1 b=1 for n=1:length(x1) x3(n)=a*x1(n)+b*x2(n) end for n=1:length(x1) y1(n)=x1(n)^2 y2(n)=x2(n)^2 y3(n)=x3(n)^2 end for n=1:length(y1) z(n)=a*y1(n)+b*y2(n) end count=0 for n=1:length(y1) if(y3(n)==z(n)) count...
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//cd "U b Doc "// ############################################################################ // Scilab Script zum 2 Praktikum // // Reglerentwurf eines invertierten Pendels, // Frequenzkennlinienverfahren und Simulation // ############################################################################ // Boris...
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clear// //Variables VCC = 5.0 //Source voltage (in volts) RE = 100.0 //Emitter resistance (in kilo-ohm) VBE = 0.7 //Emitter-base Voltage (in volts) //Calculation //Case 1 : when VBB = 0.2 V ->OFF //Case 2: when VBB = 3 V ->ON //Result...
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// Scilab Code Ex2.11 Energy of photon : Pg:49 (2008) h = 6.624e-034; // Planck's constant, Js c = 3e+08; // Speed of light, m/s e = 1.6e-019; // Energy equivalent of 1 eV, joule/eV L = 1800e-010; // Wavelength of incident light, m L0 = 2300e-010; // Threshold wavelength of tungsten, m E = h*c*(1/L...
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//Chapter-1,Example 1_2,Page 1-16 clc() //Given Data: theta=40/3600*%pi/180 //angle of wedge in radians B=0.12*10^-2 //fringe spacing //Calculations: //We know, B=lam/(2*u*theta). Here u=1 lam=2*B*theta //wavelength of light used printf('Wavelength of light used is =%.10f m',lam...
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//Variable declaration: NPS = 3 //Nominal pipe size (inch) SN = 40 //Schedule number //Calculation: //From Table 6.2, we obtain that the inside diameter of steel pipe is ID = 3.068 in, outside diameter OD = 3.5 in, wal thickness WT = 0.216 in, and pipe weight PW = 7.58 lb/ft. ID...
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//Example 3.5 //Find the impulse responce and output of the system clc; syms jw t; H=(jw+1)/((jw+2)*(jw+3)); h=ilaplace(H,jw,t); disp(h,'IMPULSE RESPONCE='); x=%e^(-2*t); X=laplace(x,t,jw); Y=H*X; y=ilaplace(Y,jw,t); disp(y,'OUTPTU OF THE SYSTEM IS=');
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// Grob's Basic Electronics 11e // Chapter No. 16 // Example No. 16_2 clc; clear; // How much charge is stored in a 40 uF capacitor connected across a 50-V supply? // Given data V = 50; // Voltage=50 Volts C = 40*10^-6; // Capacitor=2 uFarad Q = C*V; disp (Q,'The Charge Stored in Columb') disp...
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//Function migration (image list to matrix) for: convexhull //Generated by migrate.cpp //Author: Anirudh Katoch function res = convexhull(varargin) select length(varargin) case 03 then res = raw_convexhull(varargin(01), varargin(02), varargin(03)) else error(39) end endfunction
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//Exa 2.3 clc; clear; close; //Given data alfa=0.98;//unitless deltaIB=0.2;//in mA Beta=alfa/(1-alfa);//unitless deltaIC=Beta*deltaIB;//in mA disp("Change in collector curent : "+string(deltaIC)+" milli Ampere.");
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clear; clc; b = 6;// inches d = 12;// inches t1 = 7/8;// inch t2 = 1/2;// inch I_xx = (1/12)*(b*d^3 - (b-t2)*(d-2*t1)^3);// in^4 Z1 = I_xx/b;// in ^3 A = 2*b*t1 + 0.5*(d-2*t1);// in^2 b = sqrt(A/2);// inches d = 2*b;// inches Z2 = (1/6)*b*d^2;// in^3 k = Z1/Z2 ; printf('The ratio of strengths Z1/Z2 = %.2f ...
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6 9:0.25 14:1.5 16:0.1 18:0.07142857142857142 27:1.0 29:1.0 43:0.25 44:0.3333333333333333 56:0.16666666666666666 60:0.07142857142857142 64:0.6666666666666666 70:0.06666666666666667 78:0.3333333333333333 127:1.0 129:1.0 160:0.3333333333333333 183:0.25 199:1.0 200:1.0 230:0.3333333333333333 289:1.0 301:1.0 387:0.2 398:0....
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clc clear //input R=68 //resistence i=4.5 //current e=17 //emf //calculation v=(i*R)+e//supply pd //output printf("the supply of pd across motor is %3.0f V",v)
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//Chapter-10,Example10_12,pg10_43 P=4 f=50 Pi=50*10^3 N=1440 Sl=1000 Fl=650 Ns=120*f/P s=(Ns-N)/Ns P2=Pi-Sl Pc=s*P2 Pm=P2-Pc Po=Pm-Fl n=Po*100/Pi printf("full load efficiency\n") printf("n=%.2f",n)
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// Scilab code Ex11.16: Pg.520-521 (2008) clc; clear; m_p = 1.007825; // Mass of proton, u m_L = 7.016003; // Mass of Lithium, u m_i = m_p + m_L; // Total mass of initial particles, u m_He = 4.002602; // Mass of Helium, u m_f = 2*m_He; // Total mass of final particles, u delta_m = m_i - m_f; //...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Steady ADR 2D problem with CG P=7</description> <executable>SteadyAdvectionDiffusionReaction2D</executable> <parameters>LinearAdvDiffReact2D_P7_Modes_GMRES.xml</parameters> <files> <file description="Session File">LinearAdvDiffReact2D_P7...
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//----------Histogramme---------- function hist(imgsrc) intensite=[]; nbpixel=[]; counter=1; [m,n]=size(imgsrc) for i=0:1:255 [x,y]=find(imgsrc==i); //finds where imgsrc==i nbpixel(counter)=i; intensite(counter)=length(x); //find how many pixels of im have v...
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printf("\t example 13.5 \n"); // for a Basis of one Hour printf("\t approximate values are mentioned in the book \n"); c(1)=1544; // Flow rate of CO2, Lb/hr h(1)=4500; // Flow rate of H20, Lb/hr c(2)=35; //Flow rate of CO2, Mol/hr h(2)=250;//Flow rate of H20, Mol/hr t(1)=c(1)+h(1); //Total flow rate , Lb/hr ...
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// Scilab code Exa10.4 : : Page-456 (2011) clc; clear; r_min = 4e-015; // Distance between two deutrons, metre k = 1.3806504e-023; // Boltzmann's constant, Joule per kelvin alpha = 1/137; // Fine structure constant h_red = 1.05457168e-034; // Reduced planck's constant, Joule sec C...
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clear // //Variable declaration //Free Body. Entire Crankshaft Vx=-30 // Force(kN) P=50 // Force(kN) Vz=-75 ...
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function [Chi]= Chi_test(Alpha,Test) if Alpha ==0.05 then if (Test==1 |Test==2) then Chi = 19.675 else Chi = [4.575,19.675] end elseif Alpha ==0.01 Chi = 1.239; end endfunction
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//chapter 38 //Example 6 clc //given m_0=(4*%pi*10^-7)//in weber e_0=(8.9*10^-12) R=5*10^-2//meters dEbydT=10^12 i_d=(e_0*%pi*R*R*dEbydT) disp(" current in amp=") disp(i_d)
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 4 : Circuit Theorems // Example 4 - 18 clear; clc; close; // // Given data Vs = 220.0000; R1 = 1000.0000; R3 = 3000.00...
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example_3.sce
clc clear printf("example 3.3 page number 91\n\n") //to find the consumption of NaCl and H2SO4 in HCl consumption HCl_production = 500 //required to be produced in kg NaCl_required = (117/73)*HCl_production; yield = 0.92; purity_NaCl= 0.96; actual_NaCl = NaCl_required/(purity_NaCl*yield); printf("amou...
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9_12.sce
clear clc ey=1/(.05 + %i*.15) y=[ 1 2 ey 1 5 ey 2 5 ey 2 3 ey 3 4 ey 4 5 ey ] n=5 e=6 Y=zeros(n,n) for i=1:e n1=real(y(i,1)) n2=real(y(i,2)) ynew=y(i,3) if(n1==0) Y(n2,n2)=Y(n2,n2)+ynew else Y(n1,n1)= Y(n1,n1)+ynew Y(n1,n2)= Y(n1,n2)-ynew ...
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//Exa 7.2 clc; clear; close; // given : D=2 // mouth diameter of paraboloid reflector in m c=3*10^8 // speed of light in m/s f=5 // frequency in GHz f=5*10^9 // frequency in Hz lambda=c/f // wavelength in m G=6.4*(D/lambda)^2 // power gain of paraboloid G_p=10*log10(G) //power gain in dB disp(G_p,"power gai...
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clc; clear all; hb=input("Enter the height of base station antenna:") hm=input("Enter the height of mobile station antenna:") Gt=input("Gain of the transmitting antenna:") Gr=input("Gain of the receiving antenna:") dist=input("Enter the distance between transmitting and receiving antenna:") Amu=24 f1=input("Enter the ...
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// scilab Code Exa 3.2 Gas Turbine Plant with an exhaust HE T1=300; // Minimum cycle Temperature in Kelvin funcprot(0); pr=10; // pressure ratio of the turbine and compressor T3=1500; // Maximum cycle Temperature in Kelvin m=10; // mass flow rate through the turbine and compressor in kg/s e(1)=0.8; // thermal ...
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function acquireAndDisplay(connStr, channel) //Acquires data from the Siglent SDS1202X-E oscilloscope and plots it. // //Dependencies : - "acquireOscilloscopeData.m" // - "determineAcquisitionSettings.m" // //acquireAndDisplay(connStr, channel) //connStr : enter VISA USB resourcename // (e...
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clc; clear; //Example 3.31 v=18.97*10^-6 //m^2/s k=28.96*10^-3 //W/(m.K) Npr=0.696 D=100 //Outer diameter [mm] D=D/1000 //[m] Tf=333 //Film temperature in [K] Tw=373 //[K] T_inf=293 //[K] dT=Tw-T_inf //[K] Beta=1/Tf //[K^-1] g=9.81 //[m/s^2] L=3 //Length of pipe [m] Ngr=(g*Beta*dT*(L^3))/...
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//chapter 37 //example6 clc //given n=10*10^2 //turns/m i=2 //in amp B=1.0 //in wb/m u0=4*%pi*10^-7 //in wb/amp-m //(A) H=n*i disp(H,"(A) Magnetic field strength in amp/m is") //(B) M=(B-u0*H)/u0 disp("(B) Magnetisation is Zero when core is removed") disp(M," Magnetisation when th ecore is replaced in ...
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//Function:- DC gain/////////////////// //cont time transfer function SISO s=poly(0,'s'); q=syslin('c',(s+8)/(s^2+8*s+4)); z=dcgain(q); //MIMO// s=poly(0,'s'); sysa=syslin('c',(s+2)/(s^2+2*s+3)) sys1=syslin('c',(s+8)/(s^8+3*s+4)); sysm=[sysa sys1]; z1=dcgain(sysm); //SISO array// aa=pid(rand(2,3,3),3,4,5); ...
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clc //initialisation of variables F= -51180 //cal T= 25 //C R= 1.99 //cal/mole K //CALCULATIONS K= 10^(-F/(R*(273+T)*2.303)) //RESULTS printf (' equilibrium constant = %.e ',K)
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clc //initialisation of variables b= 0.0386 //l^2 atm mole^-1 a= 1.348 //l mole^-1 R= 0.08205 //cal /mole K T= 25 //C a1= 3.61 //l^2 atm mole^-1 b1= 0.0428 //l mole^-1 P= 50 //atm P1= 1 //atm //CALCULATIONS Bn= b-(a/(R*(273.2+T))) Bc= b1-(a1/(R*(273.2+T))) Fn= P1^(Bn*P1/(R*(273.2+T))) Fc= P1^(Bc*P1/(R*(2...
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clc clear //INPUT y=1.5;//coefficient of expansion dp=1/8;//ratio of inital pressure to final pressure t1=300;//inital tempreature in K //CALCULATIONS t2=t1*(dp)^((1-y)/y);//change in temperature in K t3=t2-t1;//rise in temperature in K //OUTPUT mprintf('the rise in temperature is %3.2f K',t3)
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scenario = "Behavioural_Nogo2_11/11/04"; default_font_size = 25; pcl_file = "Behavioural_Nogo2_Main.pcl"; default_font = "Arial"; default_all_responses = false; default_background_color = 0,0,0; active_buttons = 4; button_codes = 1,2,3,4; response_matching = simple_matching; write_codes = true; pulse_width = 20; begi...
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T1 = 873; T2 = 313; T3 = 253; Q1 = 2000e03; // In joule W = 360e03; // in joule // Part (a) e_max = 1-(T2/T1); W1 = e_max*Q1; COP = T3/(T2-T3); W2 = W1-W; Q4 = COP*W2; Q3 = Q4+W2; Q2 = Q1-W1; disp("J",Q2+Q3,"The heat rejection to the 40 degree reservior is") // Part (b) e_max_ = 0.4*e_max; W1_ = e_max_*...
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clear; clc; // Stoichiometry // Chapter 4 // Material Balances involving Chemical Reaction // Example 4.17 // Page 146 printf("Example 4.17, Page 146 \n \n"); // solution //M = mix feed rate, F = fresh feed rate , R = recycle stream // using fig 4.3 // N2 balance // a = 24.75M/(.25M+7.5M) (i) ...
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// CLEAR ALL ********************************************************************** xdel(winsid()); clear; // PARAMS ********************************************************************** remin = 300; //min eTape resistance [ohm] remax = 1500; //max eTape resistance [ohm] vcc = 5; //power voltage rd = [0:10:2000]; //r...
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clc; warning('off'); printf("\n\n example2.6 - pg36"); // given d=1.2*10^-2; //[m] - diameter of the hole Ca1=0.083; //[kmol/m^3] Ca2=0; //[kmol/m^3] L=0.04; //[m] - thickness of the iron piece Dab=1.56*10^-3; //[m^2/sec] - diffusion coefficient of CO2 A=(%pi*d^2)/4; //area // (a)using the formula (Na/...
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//Example 9.6.refer fig.9.16. clc hib=24 hfb=-0.98 hob=0.49*10^-6 hrb=2.9*10^-4 RS=600 RE=6*10^3 RC=12*10^3 RL=14*10^3 disp("Current gain, AI = -hfb / 1+hob*RL''") format(5) RLd=(RC*RL)/(RC+RL) x1=RLd*10^-3 disp(x1,"where, RL''(k-ohm) = RC || RL =") format(6) AI=-hfb / (1+hob*RLd) disp(AI," ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); //% MAT-fem // // Clear memory and variables. clear // The variables are readed as a MAT-fem subroutine // pstrs = 1 indicate Plane Stress; 0 indicate Plane Strain // young = Young Modulus // poiss = Poission Ratio...
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// Exa 1.7 clc; clear; close; // Given data // mass of 1 litr of water is 1 kg. so m = 5000;// in kg h = 10-1;// in m g= 9.81;// PE = m * g * h;// in N m PE = PE*10^-3;// in kj Eta = 0.85; // Eta = energy output/energy input E_input = PE/Eta;// in Kj E_input = E_input*10^3;// in J t = 45;// time in min ...
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//Caption:Calculate the gap transit angle //Exa:8.12 clc; clear; close; V_o=1000;//Anode voltage(in volts) gap=0.002;//in m f=5*10^9;//in Hz L=2.463*10^-3;//length of drift region (in m) u_o=5.93*10^5*sqrt(V_o);//in m/s Theeta_g=2*%pi*f*2*10^-3/u_o;//radians disp(Theeta_g,'Transit angle(in radians) =');
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disp('chapter 12 ex12.6') disp('given') disp("design feedback limit for 12.4 and max circuit o/p current=400mA when limited foldback to 200mA") Ilmax=0.4 Isc=0.2 disp("Vr6=0.5 at short circuit") disp("R6=0.5/Isc") R6=0.5/Isc disp('ohms',R6) disp("use 2.7 ohm std value") R6=2.7 disp("Vr6=Ilmax*R6") Vr6=Ilmax...
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close; clear; clc; disp("Hc(s)=s") disp(" bilinear transformation s=2*(1-z^-1)/Ts*(1+z^-1)"); disp("Hd(z)=2*(1-z^-1)/Ts*(1+z^-1)") //z=e^-j*w*Ts w=-1:0.01:1; Ts=2; Hdw=2*(1-%e^(-%i*w*Ts))./(1+%e^(-%i*w*Ts)); //HdwTs=2*tan(w*Ts/2)/Ts; plot(w*Ts,imag(Hdw)); xtitle('Hd(w)','w')
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//Chapter-8, Example 8.5, Page 345 //============================================================================= clc clear //INPUT DATA L=0.8;//Height of the plate in m W=0.08;//Width of the plate in m Ts=170;//Surafce temperature in degree C Tw=70;//Temperature of water in degree C Tf=130;//Final temperat...
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//scilab 5.4.1 //windows 7 operating system //chapter 5:Semiconductor Junction Diodes clc clear Vs1=15 Vs2=30//Vs=supply voltage varying from 15(Vs1) to 30(Vs2) Volt Vzo=9//Vzo=knee voltage rZ=5//rZ=dynamic resistance in ohms R=800//R=series resistance in ohms Izmin=(Vs1-Vzo)/(R+rZ)//Izmin=current through ze...
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clc clear //Input data m=(32*1.66*10^-27)//Molecular mass of a gas in kg d=(3.65*10^-10)//Diameter in m k=(1.38*10^-23)//Boltzmans constant in J/K P=1.01*10^5//Pressure at STP in N/m^2 T=273//Temperature at STP in K //Calculations n=((1/(3.14*d^2))*sqrt((8*k*T*m)/(9*3.14)))/10^-5//Viscosity of gas at STP in ...
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mode(-1) stacksize(5E7) GL_SYS_DIR=get_absolute_file_path('builder.sce') if isdef('GreenLablib')//if the lib was alerady been built predef(0); clear GreenLablib end getf(GL_SYS_DIR+'/macros/gl_main.sci'); getf(GL_SYS_DIR+'/macros/Gl_StateOccupy.sci'); getf(GL_SYS_DIR+'/macros/gl_organ_axis.sc...
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clf N=1000000; x=-2+(2+2)*rand(1,N); y=-2+(2+2)*rand(1,N); I=find(x^2+y^2<=1); pi_test=(length(I)/N)*16
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function pcd2vtk() // Converts a PCD(Point Cloud Data)file to VTK(The Visualization Toolkit) format. // // Syntax // PointCloud(InputPCDFilename,OutputVTKFilename,"pcd2vtk") // // Parameters // inputPCDFilename : PCD file of input pointcloud // outputVTKFilename : VTK file where the output of the function had...
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// exa 1.6 Pg 15 clc;clear;close; Pmax=75;// kW Pmin=7.5;// kW z=5;// no. of models //Rn=Pmax/Pmin=fi**(z-1) fi=(Pmax/Pmin)**(1/(z-1));// common ratio printf('The models are:') for i=0:z-1 P1=fi**(i)*Pmin;// kW printf('\n\t\t\tP%d = %.1f kW',i,P1) end;
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clear; file="one.csv"; // TTC placement // A1 A2 A3 A4 // B1 B2 B3 B4 // C1 C2 C3 C4 // D1 D2 D3 D4 // // One line of the file contains the the temperatures in the following order // A1 A2 A3 A4 B1 B2 B3 B4 C1 C2 C3 C4 D1 D2 D3 D4 function index=rc2index(r,c) index=c+4*(r-1); endfunction a=fscanfMat(file); v=a...
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function [n] = solve(ns) last = 0; n = 0; for i = 1:length(ns) if ns(i) < last then last = ns(i); else n = n + 1; last = ns(i); end end endfunction
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function s=tf(s) s=poly(0,'s'); s=syslin('c',s/((0*s)+1)); disp('Continuous-time transfer function'); endfunction
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//[stk,nwrk,txt,top]=f_sin(nwrk) //! nam='sin' txt=[] s2=stk(top) if s2(4)<>s2(5)|(s2(4)=='1'&s2(5)=='1') then v=s2(1) it2=prod(size(v))-1 if it2==0 then [stk,nwrk,txt,top]=f_gener(nam,nwrk) else error(nam+' d''un argument complexe non traduit') end else error(nam+'d''une matrice carre non traduit...
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clc clear disp("Example 8.19") printf("\n") disp("convert the following binary numbers to hexadecimal") disp("a)101110 b)11010 c)1011101") //this program, converts only integer part to decimal bin='101110' dec=bin2dec(bin) Hdec=dec2hex(dec) printf("decimal=%s",Hdec)
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function r=%sgb(a,b) // r=a|b r=(a<>0)|b
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//Variable Declaration U = (1.0/6)*(1+2+3+4+5+6) // Mean of probability distribution U1 = (1.0/6)*(1*1 + 2*2 + 3*3 + 4*4 + 5*5 + 6*6) // Second moment about the origin //Calculation // As we know, Variance = (U1)-U*U Variance = (U1) - U*U ...
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//Example 8.1 //total voltage gain clc; clear; g1=100;//FIRST STAGE GAIN g1db=20*(log10(g1));//first stage gain in db g2=200;//second stage gain g2db=20*(log10(g2));//second stage gain in db g3=400;//third stage gain g3db=20*(log10(g3));//third stage gain in db Tdb=g1db+g2db+g3db;// disp(Tdb,"total gain in dB")
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function ACORDETOC = extract_chord(S1) exec correlation.sci; //get the correlations notes for index_correlation = 1:12 correlation = cell2mat(S1(index_correlation)); s1(index_correlation) = correlation(1); notes_frequencies(index_correlation) = correlation(2); end //get correlations chords i ...
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clc //initialisation of variables clear H= -6.8 //B.Th.U U= 4.8 //B.Th.U Vs= 6.25 //ft^3/lb H1= -17 //B.Th.U U1= -12.1 //B.Th.U Vs1= 10.6 //ft^3/lb t= -38 //F //RESULTS printf ('H = %.1f B.Th.U',H) printf (' \n U = %.1f B.Th.U',U) printf (' \n Vs = %.2f ft^3/Lb',Vs) printf (' \n H = %.1f B.Th.U',H1) pr...
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// problem 12.5 D1=0.76 D2=0.5 x1=20 Vf1=4 Vf2=Vf1 B1=0.15 N=300/60 u1=3.142*D1*N u2=3.142*D2*N Vw1=Vf1/tand(x1) y1=atand(Vf1/(u1-Vw1)) y2=atand(Vf2/u2) Q=3.142*D1*B1*Vf1 w=9810 g=9.81 P=w*Q*Vw1*u1/(g*1000) disp(P,y2,y1,"blade angle at inlet and outlet,power developed in Kw")
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clc; funcprot(0); //Example 11.2 Critical Pressure // Initialisation of variables V0 = 1.689*500; //Velocity in ft/sec rho = 0.001267; //From table 4.1 P = (848.7/12)*13.75; // Pressure at 20,000 ft gma = 1.4; g = 32.174; R = 53.351; T = 459.4+25; //Temperature ...