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function [x,y,typ]=MFCLCK_f(job,arg1,arg2) // Copyright INRIA x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1...
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clc; clear; lambda=0.154 //wavelength in nm theta1=20 //angle in degree theta2=29 //angle in degree h=1 //x intercept of parallel plane k=1 //y intercept of parallel plane l=0 //z intercept of parallel plane //calculation ratio=sind(theta1)^2/sind(theta2)^2 //ratio of sin^2 theta values of first and second a...
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clear clc //Example 21.5 disp('Example 21.5') //data x=[ 17.7 1380. 23.6 1458. 13.2 1322. 25.2 1448. 13.1 1334. 27.8 1485. 29.8 1503. 9. 1540. 14.3 1341. 26. 1448. 23.2 1426. 22.8 1417. 20.4 1384. 1...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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//chapter 4 //example 4.2 //page 193,figure 4.21 Vsat=12;Vh=6; // Vh=(R1/R1+R2)(Vsat-(-Vsat)) R1=10000;// let assume x=(Vh/(Vsat-(-Vsat))); disp(x) R2=((1-.25)*R1)/.25 disp(R2,R1)
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function Zeq=parallel(Z1,Z2) Zeq=Z1*Z2/(Z1+Z2) endfunction I=10 w=2000 R=200 L=0.125 Xl=w*L*%i Zeq=parallel(R,Xl) V=I*Zeq Il=V/Xl Ir=V/R t=1/1000 I1=sqrt(2)*real(I*exp(%i*w*t)) Il1=sqrt(2)*real(Il*exp(%i*w*t)) Ir1=sqrt(2)*real(Ir*exp(%i*w*t)) V1=sqrt(2)*real(V*exp(%i*w*t)) Ps=-V1*I1 Pr=-...
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clear clc //Example 9.4 RESISTANCE CALCULATION FOR LAMINAR BOUNDARY LAYER ON A FLAT PLATE //To find Approx Value function [A]= approx (V,n) A= round(V*10^n)/10^n; //V-Value, n-to what place funcprot (0) endfunction L=6; //[ft] v=10^-4; //viscosity [ft^2/s] Uo=1; //[ft/s] Re=Uo*L/v //Reynolds number ...
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clear clc RT_F=0.05913;//in V m_LHC=0.01;// gamma_LHC=0.708;// m_RHC=0.10;// gamma_RHC=0.502;// Ecell=((-3/2)*(RT_F*log10((m_LHC*gamma_LHC)/(m_RHC*gamma_RHC))));// printf('Ecell=%.4f V',Ecell) //page 527
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clc //initialisation of variables sp=200 //mean speed m/s //CALCULATIONS d=(21/(0.7773*1.18*200))^0.5 l=1.5*d s=200/(3*d) //RESULTS disp('volumetric efficiency is 0.7773') printf('\ndiameter is %2fm',d) printf('\nstroke is %2fm',l) printf('\nspeed of compressor is %2frev/min',s)
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function f=bode2freq(sys,val,fmin,fmax,typ) // Interpolation for bode values f=sqrt(fmin*fmax); repf=repfreq(sys,[fmin,f,fmax]); [db,phi]=dbphi(repf); if typ=='db' then valf=db; else valf=phi; end while(abs(val-valf(2))>1000*%eps) delta=val-valf; if delta(1)*delta(2) >=0 then fmin=f; else fmax=f; ...
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function y=roundn(x,n) y=round(x*10^n)/10^n; endfunction
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numero=input("Digite o numero:") soma = 1 for n=2:1:numero soma = soma*n end disp(soma)
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////Caption Nquist Rate //Example 3.3 //page no 104 //Find Nquist Rate //given clc; clear; f=100; fs=2*f;//Nyquist rate disp(" Hz",fs,"(i)To avoid aliasing Nquist Rate is ");
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//clear// //Example 4.9:Continuous Time Fourier Transform Properties: //Linearity and Time Shift Property clear; clc; close; // CTFT t1 = -1/2:0.1:1/2; t2 = -3/2:0.1:3/2; x1 = ones(1,length(t1)); x2 = ones(1,length(t2)); t3 = t1+2.5; t4 = t2+2.5; x1 = (1/2)*x1; x = [x2(1:floor(length(x2)/3)),x1+x2(ceil(l...
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// Exa 9.3 clc; clear; close; // Given data H2 = 3055;// in kj per kg H3 = 2550;// in kj per kg fie_1 = 7.15;// kj per kg k fie_2 = 7.57;// kj per kg k d_fie= fie_2 - fie_1;// in kj per kg k disp(d_fie,"Change in entropy during throttling process in kJ/kg-K is :"); dH = H2 - H3;// in kj per kg disp(dH,"Chan...
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// chapter 13 // example 13.17 // Determine the thermal resistance of the heat sink // page-842-843 clear; clc; // given I_D=20; // in A t_on=10; // in us del=0.1; // in % (duty cycle) T_A=40; // in degree C T_J_max=150; // in degree C theta_JC=1.5; // in degree C/W R_ds_on=5; // in ohm T_pr=0.03; // assu...
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//Problem 44.16: A transmission line has a characteristic impedance of 600/_0° and negligible loss. If the terminating impedance of the line is 400 + j250 ohm, determine (a) the reflection coefficient and (b) the standing-wave ratio. //initializing the variables: rzo = 600; // in ohm thetazo = 0; // in degrees ZR = 40...
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// Exa 5.3 clc; clear; close; // Given expression Vout= -2*V1+3*V2+4*V3 // For an operational amplifier // Vout= -Rf*[V1/R1+V2/R2+V3/R3] // Compare the above expression with the given expression for the output r_1=2;// value of Rf/R1 r_2=3;// value of Rf/R2 r_3=4;// value of Rf/R3 // Resistance R3 will be mi...
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// Part (a) vg1_ = 0.8919; T1_ = 120; vg2_ = 0.77076; T2_ = 125; vg_ = [vg1_ vg2_]; T_ = [T1 T2]; v1 = 0.7964; h1 = 2967.6; P1 = 0.3e03; // in Kpa T1 = interpln([vg_;T_],v1); disp("degree",T3,"The steam become saturated at ") // Part (b) vf = 0.001029; vg = 3.407; hf = 334.91; hfg = 2308.8; Psat = 47.39; //...
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function P=pto_fijo_sistemas(F,x0,maxit,tol) //ARGUMENTOS: // F vector de funciones // x0 aproximación inicial al vector solucion P=F(x0) for i=2:maxit P=F(P); end endfunction function Y=F(X) Y(1)=cos(X(1)); Y(2)=sin(X(2)); endfunction
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 2 - Pressure and its measurements // Problem 2.25 //Given Data Set in the Problem dens=1000 g=9.81 Z=4000 p0=10.143*10^4 t0=15 T0=t0+273.15 L=-0.0065 dens0=1.285
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clear clc disp("example 10.1") mp=250 //maximum power function [ic]=unit1(p1) //ic equation of unit 1 ic=0.2*p1+30 endfunction function [ic]=unit2(p2)//ic equation of unit 2 ic=0.15*p2+40 endfunction mil=20//minimum load disp("minimum load ic is") ic=[unit1(mil),unit2(mil)] [m,n]=max(ic) if m==uni...
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function x = resoltrsup(A, b) n = size(A,1) x(n)= b(n)/A(n,n) for i=n-1:-1:1 x(i) = (b(i)-A(i, i+1:n)*x(i+1:n))/A(i, i) end endfunction function x = resoltrinf(A, b) n = size(A,1) x(1)= b(1)/A(1, 1) for i=2:1:n x(i) = (b(i)-A(i, 1:i-1)*x(1:i-1))/A(i, i) end endfunction
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//example-19.14 //page no-583 //given //electron mobility mue=1.065*10^-3 //m^2/Vs //relaxation time tau=6*10^-15 //sec //charge on an electron e=1.6*10^-19 //C //mass of electron me=9.1*10^-31 //Kg n=1 //as we know that //mue=sigma*Hc and sigma=n*e^2*tau/me //so //mue=n*e^2*tau*Hc/me //upon rearr...
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// Example 11.17: (a) T, AoL, AF // (b) RoF clc, clear gm=1e-3; // in mho rd=20e3; // in ohms function[c]=parallel(a,b) c=a*b/(a+b); endfunction disp("Part (a)"); // From the ac equivalent circuit in Fig. 11.52 RF=10e3; // in ohms RD1=10e3; // in ohms RL=10e3; // in ohms ro=20e3; // ...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 5 //Some Applications of the Laws of Thermodynamics //Example 13 clear; clc; //Given: m1 = 10; //machine rating (ton) //Since 5 K approach is necessary T1 = 293+5; //temperature of cooling water (K) T2 = 261-5; //temperature of cold storage...
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clc; clear; disp("A partition pi0 on the states of a machine M is said to be output consistent if for every block pi0 and every input,all the states contained in the block have the same outputs"); disp("Considering the above definition It can be understood that"); disp("pi0={(AD),(BC)} is an output consistent partition...
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 23 disp("CHAPTER 8"); disp("EXAMPLE 23"); //230 V DC shunt motor //VARIABLE INITIALIZATION v=230; //in Volts r_a=0.4; //in Ohms r_f1=115; //in Ohms I_a=20; //in Amperes N1=800; ...
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//Problem 2 //Calculate the hysteresis loss clear clc f=50// Frequency in Hz v=0.01// Volume of the transformer core in m^3 A= M=1750*1000// Saturation magnetization of BCC irons in A/m m=(M*v)/n// Net magnetic moment per atom in Am^2 printf('Net magnetic moment = %.27f ',m)
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clc; clear all; ue = 1.553; // Refractive index of extraordinary ray uo = 1.544; // Refractive index of the ordinary ray lambda = 6e-7; // Wavelength of light in meters t = lambda/(2*(ue-uo)); disp('m',t,'The thickness of the half wave plate is')
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 7.4\n\n\n"); // Chapter 7 : Mixtures Of Ideal Gases // Problem 7.4 (page no. 325) // Solution //five moles of oxygen and 10 moles of hydrogen are mixed //The total number of moles is 10+5=15.Therefore,mole fraction of each constituent is xO2=5/15; //T...
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main { int i; i := true; return i; }
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clc // initialization of variables clear tau=[200 100 0 100 0 0 0 0 500] // some units theta=60 // degrees //calculations theta=theta*%pi/180 a=[cos(theta) sin(theta) 0 -sin(theta) cos(theta) 0 0 0 1] b=a.' tau_new=a*tau*b // stress invariants :old I1=tau(1,1)+tau(2,2)+tau(3,3) I2=tau(...
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clear; clc; l=100;R=10;G=10^-5;Vs=40;Zr=0; Zo=sqrt(R/G); P=sqrt(R*G); Zin=Zo*(Zr+(Zo*tanh(P*l)))/(Zo+(Zr*tanh(P*l))); Is=Vs/Zin; V=(Vs*(cosh(P*l)))-(Is*Zo*(sinh(P*l))); Vm=2*V; printf("Potential at mid point = %f volts",Vm); //the difference in result is due to erroneous value in textbook. disp("The differe...
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//Ex_2_14 clc; clear; close; format('v',10); //given data : N1=100;//turns N2=80;//turns I1=10;//A I2=1.5;//A li=40/100;//m lg=1/1000;//m(airgap) A=10/10000;//m^2 mur=2000;//relative permeability mu0=4*%pi*10^-7;//permeability mmf=N1*I1-N2*I2;//AT S=1/(mu0*A)*[li/mur+lg];//AT/Wb fi=mmf/S;//Wb disp(fi...
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path=sci+'/demos/bike/' // compile if necessary xhost("cd "+path+"; make control"); // link if necessary deff('[]=linkif(fname)','if ~c_link(fname),link(''/tmp/''+fname+''.o'', fname)'); linkif('vecfin'); linkif('hamu'); linkif('emat'); linkif('fvec'); linkif('c'); linkif('psi'); linkif('ii'); linkif('h'); //...
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//Example 17.5 clc R=76.8 Ro=50 alpha=3.92*10^-3 t=(R-Ro)/(alpha*Ro) T=t+20 disp(T,"Temperature in C=")
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//Find Power loss due to Hysteresis //Ex:14.3 clc; clear; close; a=600;//loop area in J/sqm f=50;//in Hz v=0.01//volume in cu. m w=a*f*v;//in W disp(w,"Power loss due to Hysteresis (in W) = ");
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function [nk,W]=hankell(g,tol) [lhs,rhs]=argn(0), if rhs <1 then error(msprintf(gettext("%s: Wrong number of input arguments: At least %d expected.\n"),"hankel",1)) end, if (typeof(g)=='rational') then if(degree(g.num)>degree(g.den)) error(msprintf(gettext("The %...
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V1 = 550; //velocity of Boeing 747 in mi/h h1 = 38000; //altitude of Boeing 747 in ft P1 = 432.6; //Freestream pressure in lb/sq.ft T1 = 390; //ambient temperature in R T2 = 430; //ambient temperature in the wind tunnel in R c = 50; //scaling factor //Calculations //By equating the Mach numbers we get V2 = V1...
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//Chapter 9, Problem 7 clc; N=200; //no of turns dphi=25*10^-3; //change in flux dt=50*10^-3; //change in time E=-N*(dphi/dt); //calculating induced emf printf("Induced emf E = %d V",E);
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clc; lamda=5893*1e-10;//wavelength of monocromatic light n=4000; x=n*lamda/2;//distance moved by mirror M1 disp(+'meter',x,'distance moved by mirror M1 =')
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// Modélisation du sujet // Création d'une matrice carrée aléatoire de taille n et de coefficient 0 ou 1 function X = matriceX(n) X = rand(n,n); X = round(X); X = - X .* (eye(n,n)-ones(n,n)) ; endfunction // Création d'un vecteur qui somme les valeurs de chaque colonne d'une matrice function N = sommecolo...
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// Scilab Code Ex 1.22 Miller indices of lattice plane: Page-26 (2010) a = 4; // Lattice parameter of the unit cell b = 3; // Lattice parameter of the unit cell c = 2; // Lattice parameter of the unit cell l1 = 2; // Length of the intercept along x-axis, m l2 = 3; // Length of the intercept alon...
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[Read-the-docs-example-9] # Read the docs - example 9 user_indice: {'indice_name': 'my_indice', 'calc_operation': 'nb_events', 'logical_operation': 'gt', 'thresh': 'p80', 'var_type': 't', 'date_event': True} in_files: ['tasmax_day_IPSL-CM5A-MR_historical_r1i1p1_20000101-20051231.nc'] base_dt1: 2000-01-01 base_dt2: 2003...
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clear clc //initialisation of variables e= 0.88 w= 1.25 //in d= 10 //in q= 630 //gal/min a= 40 //degrees g= 32.2 //ft/sec^2 e1= 0.83 //CALCULATIONS Q= q/(6.24*60) f1= Q/(e*%pi*(d/12)*(w/12)) u1= 1000*(w*4/12)*2*%pi/60 w1= u1-f1*cotd(a) W= u1*w1/g lr= (f1^2+u1^2-f1^2/(sind(a))^2)/(2*g) mh= e1*W p= mh-l...
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//Example 21 // frequency ,energy and maximum velocity clc; clear; close; c=1;//N-m m1=6;//gm m2=2;//gm mu=((m1*m2)/(m1+m2))*10^-3;//kg fr=((1/(2*%pi))*sqrt(c/mu));//vibrations/sec disp(fr,"frequency of oscillations is ,(vibrations/s)=") td= 1+(1/3);//cm e=((1/2)*c*(td*10^-2)^2);//joule disp(e,"energy is,(joule)=") y=...
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//======================================================================= // chapter 3 example 13 clc; clear; //input data //diamagnetic susceptability of He R = 0.6*10^-10; //mean radius of atom in m N = 28*10^26; //avagadro number in per m^3 e = 1.6*10...
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//Example 10//frequency clc; clear; close; sa=1.5;//km oa=1;//km so=sqrt(oa^2+sa^2);//km csd=sa/so;// v=0.33;//km/s n=400;//Hz vlov=120*(1000/3600);//m/s vs1=(1/30)*csd;//km/s nd=((v)/(v-vs1))*n;//vibrations/sec disp(round(nd),"apparent frequency is,(vibrations/second)=")
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// x=[4]; b=blackman(x); disp(b); //output //- 1.388D-17 // 0.63 // 0.63 // - 1.388D-17 //
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//Variable declaration: Q = 56760 //Heat transfer rate (Btu/h) U = 35.35 //Overall heat coefficient (Btu/ft.h..) A = 32.1 //Area of exachanger (ft^2) t1 = 63.0 //Outlet cold water temperature (.) T1 = 164 ...
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clear; clc; disp("--------------Example 10.23---------------") // sender text="Forouzan"; // computing the checksum a=ascii(text); h1=dec2hex(a(1)); h2=dec2hex(a(2)); h3=dec2hex(a(3)); h4=dec2hex(a(4)); h5=dec2hex(a(5)); h6=dec2hex(a(6)); h7=dec2hex(a(7)); h8=dec2hex(a(8)); // form the hexadecimal words ...
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I1 = 3; //peak value of i1 I2 = 5; //peak value of i2 I3 = 6; //peak value of i3 theta1 = %pi/6; //phase difference between i2 and i1 theta2 = -2*%pi/3; //phase difference between i3 and i1 // complex representation of the currents i1 = complex(3); i2 = complex(5*cos(%pi/6),5*sin(%pi/6)); i3 = complex(6*cos(-2...
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//This script demonstrate exporting plots to svg/pdf files clear clc //Import data from file Data = csvRead('../Data/Tut2_data1.csv'); //Segregate the data into variables t = Data(:,1); x = Data(:,2) //Ploting the figure. Name of the figure is fig1; //Use the field Linewidth to specify thickness of the plot fig1 = ...
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pathname=get_absolute_file_path('1_2.sce') filename=pathname+filesep()+'1_2_data.sci' exec(filename) //solving simultaneously for indicated power using fp/bp=nm and fp+bp=ip: ip=fp/(1-nm) //brake power(in kw): bp=ip-fp printf("\n\nRESULTS\n\n") printf("\nindicated power:%f\n",ip) printf("\nbrake power:%f\n",bp...
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//Problem 10.06: (a) A current of 20 A flows through a load having a resistance of 2 ohms. Determine the power dissipated in the load. (b) A wattmeter, whose current coil has a resistance of 0.01 ohm is connected as shown in Figure 10.13. Determine the wattmeter reading. //initializing the variables: I = 20; // i...
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clc //initialisation of variables P= 1//atm n= 70 T= 75 //F T1= 70 //F r1= 0.0131 //lb water/lb dry air r2= 0.0093 //lb water/lb dry air h1= 32.36 //Btu/lb dry air h2= 27.03 //Btu/lb dry air hd2= 23.40 //Btu/lb dry air hf= 23.4 //Btu/lb dry liquid hg= 1094.5 //Btu/lb dry liquid //CALCULATIONS R1= r1-r2 Q...
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//variable initialization n=3/2; dlembda=26*10^-2; //shifting in short wave limit of X-ray spectrum (Å) ch=12400 //product of speed of light and Plank's constant (eV*Å) e=1.6*10^-19; ...
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function [stk,nwrk,txt,top]=%m2for(nwrk) // multiplications //! // Copyright INRIA s2=stk(top);s1=stk(top-1); txt1=[] if s1(3)<>s2(3) then if s1(3)=='0' then [s1,nwrk,txt1]=typconv(s1,nwrk,'1'), else [s2,nwrk,txt1]=typconv(s2,nwrk,'1'), end end [s1,te1,t1,m1,n1]=s1(1:5); [s2,te2,t2,m2,n2]=s2(1:5); it1=...
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//Example 2.5 //MAXIMA SCILAB TOOLBOX REQUIRED FOR THIS PROGRAM //Z- transform of -b^n u(-n-1) clear; clc ; close ; syms b n z; x =b^n X= symsum (x*(z^(-n)),n ,0, %inf ); //Display the result in command window disp (X,"Z-transform of b^n u(n) with is:"); disp('ROC is the Region mod(z) < b')
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// load the program and setup load Computer.hdl, output-file Prog2.out, output-list RAM64[16]%D2.6.2 RAM64[17]%D2.6.2 RAM64[18]%D2.6.2; ROM32K load Prog2.hack, // TESTCASE 1 :: c = |8-16| set RAM64[16] 8, set RAM64[17] 16; repeat 12{ tick,tock; } output; set reset 1, // Reset the ...
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exec eval_spline.sci; //Puntos x=[8.3 8.6]'; //Coeficientes [a b c d] coef=[17.56492 1.116256 20.06827667 -44.46466667]'; //Llamada al polinomio cubico S=eval_spline(x,coef); //Muestra el resultado disp(S)
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// chapter 8 // example 8.3 // Determine average and rms output voltage, chopper efficiency and effective input resistance // page-440-441 clear; clc; // given Edc=200; // in V (input voltage) R=15; // in ohm Ed=2.5; // in V (voltage drop when the chopper is ON) f=1; // in KHz (chopper frequency) alpha=50; // in percen...
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clear; clc; //Example - 15.21 //Page number - 544 printf("Example - 15.21 and Page number - 544\n\n"); //Given T = 50;//[C] // At 50 C P_1_sat = 0.67;//[atm] P_2_sat = 0.18;//[atm] Y1_infinity = 2.5; Y2_infinity = 7.2; //(1) // alpha_12 = (y_1/x_1)/(y_2/x_2) = (Y1*P_1_sat)/((Y2*P_2_sat)) // At x_1 ...
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//Example 9.36 clc disp("For 12-bit DAC, step size is 8 mV") v=(8*10^-3)*((2^12)-1) format(6) disp(v," V_0FS = 8 mV * 2^12 - 1 =") r=((8*10^-3)/32.76)*100 format(8) disp(r,"% Resolution = 8mV/32.76V * 100 =") q=(8*10^-3)*1389 format(7) disp(q,"The output voltage for the input 010101101101 is = 8mV * 1389 ="...
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Name=RoE PlayerCharacters=RoE Player BotCharacters=RoE Opp.bot IsChallenge=false Timelimit=90.0 PlayerProfile=Ascended Tracking AddedBots=Long Strafe Bot.bot;Long Strafe Bot.bot;Long Strafe Bot.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=AscendedStrafesv2.map MapScale=3.8125 ...
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// Scilab code Ex18.3 : : Page-763 (2011) clc; clear; p = rand(1,2); // proton pi_minus = rand(1,2); //pi minus meson pi_plus = rand(1,2); // pi plus meson n = rand(1,2); // neutron lamda_0 = rand(1,2); // lamda hyperon K_0 = rand(1,2); // K zero (Kaons) K_plus = rand(...
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function [X,rk,Ac]=rowcompr(A) //[X,rk,Ac]=rowcompr(A) //row compression of polynomial matrix A (toward the bottom) //X left polynomial unimodular base //rk=normal rank of A //Ac = X*A //Warning: elimination of neglected terms //! [n,m]=size(A); [Ac,U,rk]=htrianr(A'); Ac=Ac'; X=U'; X=X(n:-1:1,:) Ac=Ac(n:-1:1,:)
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clc //initialisation of variables directstress= 80 //N.mm^2 shearstress= 45 //N/mm^2 //CALCULATIONS Sx= directstress Sy= 0 Txy= shearstress sigma1= ((Sx+Sy)/2)+(sqrt((Sx-Sy)^2+4*Txy^2))/2 sigma2= ((Sx+Sy)/2)-(sqrt((Sx-Sy)^2+4*Txy^2))/2 theta= (atand(-((2*Txy)/(Sx-Sy))))/2 direction1= theta direction2= thet...
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//Example No. 6_13 //Solving System of non-linear equations using FIXED POINT METHOD //Pg No. 169 clear ; close ; clc ; printf(' x^2 - y^2 = 3 \n x^2 + x*y \n'); deff('x = f(x,y)','x = y + 3/(x+y)') ; deff('y = g(x)','y = (6-x^2)/x') ; x(1) = 1 ; y(1) = 1 ; printf('\n x0 = %f \n y0 = %f \n',x(1),y(1)); for ...
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//determine the length of weld clc //solution //given //refer fig 10.16 b=120//mm//width t=15//mm//thickness l1=b-12.5//mm s=15//mm ft1=70//N/mm^2//tensile stress ft2=56//N/mm^2//shear stress //let l2 be length of weld //P=A*ft P=120*15*ft1//N ft11=ft1/1.5//N/mm^2 ft22=ft2/2.7//N/mm^2 P1=0.707*s*l1*ft11...
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function inv_ceps = icceps(input, remv_samp) // ICCEPS computes the inverse cepstrum of a real-valued input. This spectrum // will be complex in nature // Inputs: // input: Real-valued input // remv_samps: Number of samples of delay to be removed // Outputs: // inv_ceps: Inverse cepstrum output // Ch...
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function demo_united_nations() // header: header of the variable to deploy // data: core of the data to deploy // herokuapp: name of heroku app to deploy (contained in the URL) function [header, data] = importdata(filename) header = mgetl(filename, 1); header = csvTextScan(header, ",", ...
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//To compare the density of lattice points //area of (110) plane is a*sqrt(2)*a = sqrt(2)*a^2 n = (1/4)*4; //number of atoms theta = 30; //glancing angle x = cosd(theta); //area of (111) plane is (a/sqrt(2))*x*a*sqrt(2) //hence area is (sqrt(3)/2)*a^2 n1 = 3*(1/6); //number of atoms printf("area of ...
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clc; s = %s; syms t; num = 32; den = s*(s^2+12*s+32); y = syslin('c',num/den); disp(y); [A] = pfss(y);G = 0;disp(A); for k = 1:size(A) f(k) = ilaplace(A(k),s,t); G = G + f(k); end disp(G)
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clc; //e.g 22.16 gm=8000*10**-6; RS=10*10**3; RG=100*10**6; (1/gm); AV=RS/(RS+(1/gm)); disp(AV); Ri=RG; Ro=1/gm; disp('ohm',Ro*1,"Ro=");
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//pagenumber 114 example 20 clear i1=2*10^-7;//ampere voltag=0.026;//volt i=i1*((exp(0.1/voltag)-1)); disp("current = "+string((i))+"ampere");
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// Let x1, y1 be the transformed direction inclined at 15 deegree to the original sx = -46e06; // Direct stress in x-direction in Pa sy = 12e06; // Direct stress in y-direction "" txy = -19e06; // Shear stress in y-direction "" t = -15 ; // Inclination of plane in degree sx1 = (sx+sy)/2 + ((sx-sy)*(cosd(2*t))/2) ...
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function y=imBlur(foo) [x,y]=meshgrid([4:-4],[4:-4]) z=sqrt(x.*x+y.*y) h=((2*0.25)*sinc(2*z*0.25)) h=h/(sum(sum(h))) y=imfilter(foo,h) endfunction function y=imSharp(foo) [x,y]=meshgrid([4:-4],[4:-4]) z=sqrt(x.*x+y.*y) imp=double(~x)*double(~y) h=imp-((2*0.25)*sinc(2*z*0.25)) h=h...
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//Engineering and Chemical Thermodynamics //Example 8.9 //Page No:388 clear ; clc ; //Given R = 8.314 ; T = 10 + 273 ; //[K] A_B = 9.2806 ; // From Appendix A , Table A1.1 B_B = 2788.5 ; // From Appendix A , Table A1.1 C_B = -52.36 ; // From Appendix A , Table A1.1 A_C = 9.1325 ; // From Appendix A , Table...
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//check o/p when no i/p args are passed to the function y=arcov(); ////output // !--error 10000 //Not enough input arguments //at line 3 of function checkNArgin called by : //at line 3 of function arcov called by : //y=arcov();
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// Element-wise addition of two vectors function vadd2(V1, V2) R = V1 + V2; endfunction
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clear// //Variables R2 = 100.0 * 10**3 //Resistance (in ohm) R1 = 10.0 * 10**3 //Resistance (in ohm) ACM = 0.001 //Common-mode gain Slew_rate = 0.5 * 10**6 //Slew rate (in volt per second) Vpk = 5.0 //Peak voltag...
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//EX3_1 pg-3.14 clc disp("Refer to the circuit diagram shown in figure-3.7") Rf=75;//diode forward resistance Rl=10e3;//load resistance Rs=10;//transformer secondary resistance Ep=230;//rms value of primary voltage N2byN1=1/3;//turns ratio Es=Ep*N2byN1;//rms value of secondary voltage Esm=sqrt(2)*Es;//peak val...
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//1.6 clc; V=90; R=25; t=40*10^-6; L=0.5; i=(V/R)*(1-exp(-R*t/L)) iL=40*10^-3; printf("The circuit current is= %.4f A", i) disp('Since the circuit current is less than latching current of 40mA so thyristor will not turn ON') R=V/(iL-i); printf("R= %.0f Ohm", R) disp('R should be less than 2743 ohm')
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clc;clear; //Example 15.4 //given data EPF=180;//Energy consumed per disintegration in MeV E=1200;//average power in kW t=10;//time in hours Na=6.02*10^26;//Avgraodo no. in 1/kg mole e=1.6*10^-19;//the charge on electron in C //calculation TE=E*t;//energy consumed in kWh TE=TE*36*10^5;//conversion in J E...
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//example-26.7 //page no-784 //given //frequency of light f=1.5*10^9*10^6 //Hz //pank's constant h=6.626*10^-34 //J s //threshold frequency is f0=1.2*10^9*10^6 //Hz //maximum energy of emitted photoelectron is Emax=h*(f-f0)/(1.6*10^-19) //eV printf ("the maximum enery of the emitted photoe;lectron is %f ...
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//Ex:5.22 clc; clear; close; f=150;// frequency in MHz y=300/f;// wavelength in m ht=20;// transmeter height in km hr=2;// receiver height in km d=40*10^3;// distance in m p=100;// power in watt Er=(88*sqrt(p)*ht*hr)/(y*d^2);// field strength in uV/m printf("The field strength = %d uV/m", Er*10^6);
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function [j]=jmat(n,m) //j=jmat(n,m) //This macro permutes block rows or block columns of a matrix // // n : number of block rows or block columns of the matrix // m : size of the (square) blocks //! // Copyright INRIA j=[]; for k=1:n,j(k,n-k+1)=1;end; j=j.*.eye(m,m);
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// Exa 7.1 clc; clear; close; // Given data Vout = 5;// in V V = 1.5;//ON state voltage drop across LED in V I = 5;// in mA I = I*10^-3;// in A R = (Vout-V)/I;// in ohm disp(R,"Resistance in ohm is");
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clc //Initialization of variables wA=53.5 //lb/ft^3 wA2=8.4 //kN/m^3 wB=78.8 //lb/ft^3 wB2=12.3 //kN/m^3 PB=30 //psi PB2=200 //kN/m^2 AB=1.3 //ft AB2=40/100 //m BC=6.5 //ft BC2=2 //m CD=10 //ft CD2=3 //m //Calculations PAbyGB=PB*144/wB - AB*13.55*62.4/wB - (BC+CD) + (AB+BC)*wA/wB PA=PAbyGB*wB/144. PAby...
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clc //Given that h = 600 // distance of satellite from surface of Earth in km R_e = 6400 // radius of Earth in km m_s = 100 // mass of satellite in kg g = 10 // gravitational acceleration in m/s2 v_y = 2500 // upward velocity of launched satellite // sample problem 14 page No. 306 printf("\n\n\n # Problem 14 ...
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exec('degree_rad.sci', -1) //Given that i1 = 15 //in A i2 = 32 //in A d = 5.3*10^-2 //in m uo = 4*%pi*10^-7 //in SI unit //Sample Problem 30-2 printf("**Sample Problem 30-2**\n") R = d/sqrt(2) B1 = uo*i1/(2*%pi*R) B2 = uo*i2/(2*%pi*R) theta = atan(B1/B2) B = sqrt(B1^2 + B2^2) printf("The magnitude ...
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clc Q1=[],Q2=[],Q3=[]; n=input("Enter no of processes in HIGHEST PRIORITY queue"); for i=1:n Q1(i)=struct('pid',0,'AT',0,'BT',0,'TAT',0,'WT',0,'RT',0,'CT',0); /*SOME NOTATIONS FOR EACH PROCESS IN THE QUEUES*/ // 'pid'- Process Number/ID, 'BT'- burst time, 'WT'- waiting time // 'TAT'- turnaround time, 'RT'- remaining ti...
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// Example 2.2 // Parallel Resistance Calculations // From Figure 2.6(a) i_x=2; // Current through unknown resistance R_x G_par= 1/12+ 1/24+1/8 ; // Equivalent conductance for three resistors of value 12ohms, // 24ohms & 8ohms. R_par=1/G_par; // Equivalent Resistance of those three resistors....
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//Example 3.8 // voltage clc; clear; close; //given data : I=5; // current in A n=2; // number of resistance in parallel of section BC r1=15; // resistance in ohm r2=20; // resistance in ohm r3=60; // resistance in ohm r4=64; // resistance in ohm r5=64; // resistance in ohm r6=2.5; // resistance in ohm R1=r4/n; /...