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P=500//in kN Pu=1.5*P//in kN fck=15//in MPa fy=250//in MPa l=3//unsupported length, in m //assume 1% steel Ag=Pu*10^3/(0.4*fck*0.99+0.67*fy*0.01)//in sq mm L=sqrt(Ag)//assuming a square column L=315//in mm emin=l*10^3/500+L/30//<20 emin=20//in mm ep=0.05*L//<emin, hence the column is to be checked for bendin...
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// Exa 5.3 clc; clear all; // Given data // 3 1/2 digit display V1=1; // Volts V2=10;//Volts // Solution disp("Number of full digits is 3."); n=3;//Full digits Reso=1/10^n; printf(' Resolution = %.3f . Hence, meter cannot distinguish two values if their difference is less than %.3f \n ',Reso,Reso); ...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 12.5 //calculation of the total mechanical energy of the system //given data m=40*10^-3//mass(in kg) of the particle A=2*10^-2//amplitude(in cm) of motion T=0.2//time period(in s) of oscillation //calculation E=(...
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clc; disp((1.5*10^11)/(3*10^8),"Time in second = "); //using t=s/v
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function mdaqPWMInit(arg1, arg2, arg3, arg4, arg5, arg6) link_id = -1; if argn(2) == 5 then module = arg1; period = arg2; active_low = arg3; channel_a = arg4; channel_b = arg5; end if argn(2) == 6 then link_id = arg1; module = arg2; peri...
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// Exa 3.3 clc; clear; close; // Given data T=300;// in K V_T= T/11600;// in V v= 0.3;// forward bias voltage in volt I= 10;// leakage current in micro amp I=I*10^-6;// in amp id= I*(%e^(v/V_T));// in amp disp(id,"The diode current in amp")
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function [x]= gausssolve(A,b) n=size(A,1); mik=0; for k=1:n-1; for i=k+1:n; mik=(A(i,k)/A(k,k)); b(i)=b(i)-mik*b(k); A(i,(k+1):n)=A(i,(k+1):n)-mik*A(k,(k+1):n); end; end; x(n)=b(n)/A(n,n); for i=n-1:-1:1 x(i)=(b(i)-A(i,(i+1):n)*x((i+1):n))./A(i,i); end endfunction
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clear // // // //Variable declaration lamda=1.54*10**-10 //wavelength(m) n=1 //order theta=19.2*%pi/180 //glancing angle(radian) h=1 k=1 l=1 //Calculation d=n*lamda/(2*sin(theta)) a=d*sqrt(h**2+k**2+l**2) //cube edge of unit cell(m) //Result printf("\n cube edge of unit ce...
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clc w = 2 // width in mm t = 5 // thickness in mm theta=6 // shear in degrees tau = 382.5 // ultimate shear stress in MPa F = w*t*tau*1000 // cutting force in N l = t/sin(theta*%pi/180) // length to be cut in mm F_i = l*t*tau // cutting force in N printf("\n cutting force with parallel cutting edges = %0.3f MN\...
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clc; m=0.05; // mass flowrate of Freon 12 in kg/s p1=300; // Pressure of Freon 12 at inlet in kpa t1=5; // Temperature of Freon 12 at inlet in degree celcius p2=1.2; // Pressure of Freon 12 at outlet in MPa t2=80; // Temperature of Freon 12 at outlet in degree celcius W=-2.3; // Power consumption of compressor in...
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clear data7; exec('sec.007.txt'); getf('labelbode.sci'); T = data7(:,1); fan = data7(:,3); //T is time, fan is fan speed u = data7(:,2)-20; y = data7(:,4)-28; // u is current, y is temperature f=0.007; p=length(u);// u is current data_width=3; p2=(p/data_width); p1=round(p2); [q,k]=max(u((p-p1):p,1));//q is max...
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// 08.05.18 // 08.05.19 // 08.05.20 // 08.05.30 // 08.09.19 // 08.10.26 // 09.01.15 "e" // 09.05.18 // 09.12.05 // 16.11.03 Eps=10^(-5) // 16.12.05 Eps=10^(-7) function PLall=Kyoukai(varargin) global XMIN XMAX YMIN YMAX Nargs=length(varargin); Eps0=10^(-7); DataL=[]; for I=1:Nargs Tmp=varargin(I); i...
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qatel qtilt V;PRF;FIN;SG;1;PST indika jindika V;IPFV;FIN;MASC;SG;3;PST sama' semgħet V;PRF;FIN;SG;2;PST samat samtet V;PRF;FIN;FEM;SG;3;PST irrisponda irrisponda V;PRF;FIN;MASC;SG;3;PST gidem gidem V;PRF;FIN;MASC;SG;3;PST miet mmut V;IPFV;FIN;SG;1;PST ħolom ħolmu V;PRF;FIN;PL;3;PST jaf taf V;IPFV;FIN;SG;2;PST iddawnlow...
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clc clear //input data dH=0.14//Rise in static pressure of the air by fan in m of water N=650//The running speed of the fan in rpm P=85*0.735//Power consumed by the fan in kW H1=0.75//The static pressure of the air at the fan in m of Hg T1=298//The static pressure at the fan of air in K m=260//Mass flow rate of...
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// Example 6.22.2 page 6.69 clc; clear; n1=3.5; //refractive index n=1; //refractive index of air F=0.69; //transmission factor eta = 100*(n1*(n1+1)^2)^-1; //computing eta printf("\neta external is %.1f percent i.e. small fraction of intrnally generated opticalpower is emitted from the device.",...
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clc funcprot(0) format('v',10) mat1 = input("Enter a matrix[NxN]: ") function lu_decomposition(mat1) U = mat1; disp(mat1,"Matrix A = ") m = det(U(1,1)); n = det(U(2,1)); x=n/m; U(2,:) = U(2,:) - U(1,:)/(m/n); n= det(U(3,1)); y=n/m; U(3,:) = U(3,:)...
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clear clc disp("example 8.6") mh=205//mean height a=1000*10^6//in miters r=1.25//annual rain fall er=0.8//efficiency lf=0.75//load factor hl=5//head loss et=0.9//efficiency of turbine eg=0.95//efficiency of generator wu=a*r*er/(365*24*3600) printf("\nwater used is \t\t%fm^3/sec",wu) eh=mh-hl printf("\neff...
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clc clear deff('y=f(x)','y=x/(x*x+5)') a=input("enter lower limit") b=input("enter upper limit") n=input("enter number of sum intervals") h=(b-a)/n x(1)=a; sum=f(a); for i=2:n x(i)=x(i-1)+h end for j=2:2:n sum=sum+4*f(x(j)); end for k=3:2:n sum=sum+2*f(x(k)); end sum=sum+f(b); val=sum*h/3...
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//Ex_7_6 clc; clear; close; format('v',6); //given data : IE=10;//mA IB=5;///mA(Base Current) IC=IE-IB;//mA(Collector Current) BetaR=IC/IB;//unitless alfaR=IC/IE;//current gain disp(BetaR,"BetaR="); disp(alfaR,"alfaR="); //Answer is wrong in the book.
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// questao 2, lista 5 // Prof. Josenalde Oliveira - TADS MA II - Out/2015 x = 10:10:100; fx = [380.43 397.5 412.01 423.96 433.35 440.18 444.45 446.16 445.31 441.90]; for i = 1:length(x)-1 dx(i) = (fx(i+1) - fx(i)) / (x(i+1) - x(i)); end printf("Primeira Diferença:\n") disp(x') disp(dx) for i = 1:length(dx)-1 ...
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// Estimación de la descomposición de un contaminante en un reactor // function [c, t] = descomposicion(Cinicial, k, stepsize, tfinal) // Entrada: // Cinicial : Concentracion inicial del material radioactivo // k : constante de proporcionalidad // Salida: // t : vector de tiempo en minutos // c : vector concent...
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clc; clear all; disp("The Time lag") x=300/1000;//m rho=1600;// kg/m^3 k=0.65;//W/(m.C) c=440;// J/(kg.C) n=1/24;// h^-1 n a=k*3600/(rho*c); a deltau = (x/2)*(1/(3.1416*a*n)^(0.5)); disp("h",deltau,"time lag =")
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 2 : AC Circuits // Chapter 10 : Sinusoidal Steady State Analysis // Example 10 - 3 clear; clc; close; // Given data Z11 = complex(8.0000,8.000); Z12 = c...
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//example 3.4 clear; clc; //given: disp("C7H16(l) + 11O2(g) -> 7CO2(g) + 8H2O(l)"); n=-4;//change in no. of moles when reaction proceeds from reactants to products T=298;//temperature of the process [K] R=8.314;//universal gas constant [J/K/mol] Qv=-4800;//heat energy at constant volume [KJ] //to find ...
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//coefficient// p=poly([5],'s','coeff'); q=poly([5 3 1],'s','coeff'); G=p/q H=0.6 y=G*H //type 0 //refering the table 8.2 given in the book ,for type 1 Ka=0 & Kv=0 syms s Kp=limit(s*y/s,s,0) // Kp=positional error coefficient
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clc //initialisation s=1.5//cal cm^-2 min^-1 k=0.0027 //CALCULATIONS td=-(s/(k*60)) //results printf(' \n temperature gradient= % 1f c cm^-1',td)
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clc T_w1=323; //K T_w2=343; //K T_o1=513; //K T_o2=363; //K SG_oil=0.82; c_po=2.6; //kJ/kg K c_pw=4.18; //kJ/kg K T0=300; //K m_o=1; //kg //Heat lost by oil=Heat gained by water m_w=(m_o*c_po*(T_o1-T_o2))/(c_pw*(T_w2-T_w1)); dS_w=m_w*c_pw*log(T_w2/T_w1); dS_o=m_o*c_po*log(T_o2/T_o1); dAE_w=m_w*[c_pw...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 13.7 //Caption : Program to Find the Composition of Product Steam at Equillibrium T=1393.15;//K P=1;//[bar] x=10^4/T; //C2H2 --> 2C + H2 (I) //2C + 2H2 --> C2H4 (II) /...
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//determine the shaft power hydraulic efficiency //ex 6.5 pgno.151 clc N=1260 // runner speed Q=0.4 // flow rate H=92 // head g=9.8 //constant a1=20 // van angle R1=(2*600)/1000 // radius at inlet r1=600/1000 B1=30/1000 p=1000 // power hp=360e3 V1f=(Q/(%pi*R1*B1)) // velocity of flow mprintf(' V1f =...
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//Example 4.20: clc; clear; close; //given data : format('v',5) A=50;//gain without feedback Af=25;//gain with feedback Beta=(((A/Af)-1)/A);//feed back ratio Ad=40;//new gain after ageing Af1=(Ad/(1+(Beta*Ad)));//new gain with feedback df=Af-Af1;// reduction in gain pdf= (df/Af)*100;//percentage reduction in gain disp...
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//Chapter 22, Problem 13 clc; V=240; //supply voltage Ia=50; //armature current Ra=0.2; //armature resistance E=V-(Ia*Ra); //back e.m.f printf("Back emf = %d V",E);
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//Chapter-5,Example5_3_2,pg 5-6 h=6.63*10^-34 //Plancks constant m=9.1*10^-31 //mass of an electron wavelength=10^-10 //de Broglie wavelength of an electron v=h/(m*wavelength) //...
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; @Harness: disassembler ; @Result: PASS section .text size=0x00000080 vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x000000b4 ;2**0 start .text: label 0x00000000 ".text": 0x0: 0x00 0x1c adc r0, r0 0x2: 0x10 0x1c adc ...
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//Chapter 12 //page no 431 //given clc; clear all; Pt=10; //in microW Pr=1; //in microW PtdBm=10*log10(Pt*10^-6/10^-3) //in dBm printf("\n Transmitter Power = %0.0f dBm",PtdBm); PrdBm=10*log10(Pr*10^-6/10^-3) //in dBm printf("\n Receiver Power = %0.0...
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function lnkptr=lnkptrcomp(bllst,inpptr,outptr,inplnk,outlnk) // Copyright INRIA lnkbsz=[]; for blkout=1:length(bllst) for portout=1:outptr(blkout+1)-outptr(blkout) lnkbsz(outlnk(outptr(blkout)+portout-1))=bllst(blkout)(3)(portout) end end lnkptr=cumsum([1;lnkbsz])
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//Chapter-1, Example 1.20, Page 1.46 //============================================================================= clc clear //INPUT DATA IL=50;//Load current in A V=220;//Terminal voltage in V Ra=0.3;//Armature resistance in ohm Rsh=220;//Field resistance in ohm N=1200;//Speed of the motor in rpm //C...
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clc L=2.5*10^-6 disp("L = "+string(L)+" meter") //initializing value of length of channel. un=800 disp("un = "+string(un)+"cm^2/V-s") //initializing value of mobility of n-channel MOS transistor. VT=0.8 disp("VT = "+string(VT)+" V") //initializing value of threshold Voltage. Vgs=1 disp("Vgs = "+string(Vgs)+" V"...
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//Ex 7.8 clc; clear; close; format('v',7); //Given data : n1=6;//cylinders IP=150;//KW N=800;//rpm TwoLN=320;//m/s Lbyd=1.2;//stroke to bore ratio Pmi=650;//Kn/m^2 //Calculation //IP=n1*Pmi*(%pi/4*d^2)*L*n/60;//KW d=sqrt(IP/n1/Pmi/(%pi/4)*2/TwoLN*2*60);//meter(L*N replaced by TwoLN/2) L=Lbyd*d;//in m...
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//Initilization of variables W=2 //lb F=1.5 //lb g=32.2 //ft/s^2 //Angles are with respect to the plane theta1=10 //degrees theta2=30 //degrees //Calculations //Now here the forces are considered as parallel and perpendicular to the plane //Applying Newtond Principle ax=(g/2)*(F*cosd(theta1)-(W*sind(theta2))...
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---- j = 2 f = [[[1],[1,2],[1,5,4],[1,9,16,8],[1,14,41,44,16]], [[0],[0,0],[0,0,0],[0,0,0,0],[0,0,0,0,0],[1,20,85,146,112,32]]] q = [[[0]], [[0]]] s = [[[1]], [[0]]] f = [[[1],[1,2],[1,5,4],[1,9,16,8],[1,14,41,44,16]], [[0],[0,0],[0,0,0],[0,0,0,0],[0,0,0,0,0],[1,20,85,146,112,32]], [[1],[1,2],[1,5,4],[1,9,16,8],[1,14...
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function im=deleta_bit2(im,bit,lowdev,highdev,nbig) if(bit==1) [lab,n]=bwlabel(im,4); else [lab,n]=bwlabel(1-im,4); end lab=lab(:); for i=1:n tam(i)=length(find(lab==i)); end med=mean(tam); dev=sqrt(variance(tam)); if(nbig>0) big_i=ones(n,1); for i=1:nbig [m,j]=max(tam.*big_i); big_i(j)=0; end ruim=(t...
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function a = init(height, width, start) for i = 1:height, b = start; for j = 1:width, a(i, j) = b; if a(i, j) == 4 then a(i, j) = 5; end b = b - 1; if b < 1 then b = 4; end end sta...
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//chapter 6 Ex 2 clc; clear; close; n=40; Sum=n*(n+1)/2; //formula for sum of first n natural numbers avg=Sum/n; mprintf("The required average is %.1f",avg);
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// Example 5.6.2 clc; clear; N=16; //Number of ports Pin=1d-3; //input power Pout=12d-6; //output power split_loss=10*log10(N); //computing split loss excess_loss=10*log10(Pin/(Pout*N)); //computing excess loss total_loss=split_loss+excess_loss; //computing total loss insertion_loss= 10*...
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function grid_min() // Filters a point cloud using the pcl::GridMinimum filter. // // Syntax // PointCloud(InputPCDFilename,OutputPCDFilename,options,"grid_min") // // Parameters // inputPCDFilename : PCD file of input pointcloud // outputPCDFilename : PCD file where the output pointcloud had to be saved // ...
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errcatch(-1,"stop");mode(2);//Ex:3.15 ; ; L=6;//in henry r=24;//in ohms t=0.1;//in sec. V_s=12;//in volts i=(V_s/r)*(1-%e^(-t*r/L)); printf("current = %f A",i); exit();
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//(13.6) A mixture of 1 kmol of gaseous methane and 2 kmol of oxygen initially at 25C and 1 atm burns completely in a closed, rigid container. Heat transfer occurs until the products are cooled to 900 K. If the reactants and products each form ideal gas mixtures, determine (a) the amount of heat transfer, in kJ, and...
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clear; clc; disp("--------------Example 5.7---------------") d=0; r=2; // For QPSK, 2 bits is carried by one signal element N=12; // bit rate = 12 Mbps S=N*(1/r); // formula for signal rate B=S; // bandwidth , as d=0 printf("The bandwidth is %d MHz.",B); // display result
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function [solarAltitudeAngle,solarAzimuthAngle] = calcSunCoordinates(latitude, dayspassed, solarHourAngle) solarDec = 23.45*sind(360*(284+daysPassed)/365); solarAltitudeAngle = asind(sind(latitude)*sind(solarDec)+cosd(latitude)*cosd(solarDec)*cosd(solarHourAngle)); solarAzimuthAngle = asind(cosd(solarDec)*sind(solarH...
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clear; a = 4; b = 2; t(:,1) = 0:0.01:10; t(:,2) = a + sin(t(:,1) + b); deletefile("/media/data/evo/python_ev3/local/lctrs/lssn_2/data.txt"); write("/media/data/evo/python_ev3/local/lctrs/lssn_2/data.txt", t); data = read("/media/data/evo/python_ev3/local/lctrs/lssn_2/data.txt", -1, 2); plot(data(:,1), data(:,2));
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//Example 4.19 clc;clear;close; z=poly(0,'z'); h=[1 2 3];n1=0:length(h)-1; H=h*(z^-n1)'; y=[1 1 2 -1 3];n2=0:length(y)-1; Y=y*(z^-n2)'; X=Y/H; l=coeff(numer(X)); x=l(:,$:-1:1); disp(H,'h(n)={1,2,3} H(z)='); disp(Y,'y(n)={1,1,2,-1,3} Y(z)='); disp(X,'Z transform of input sequence X(z)='); disp(x,'Inpput S...
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//calculating parameters of each coil I=3//current through the circuit //for coil A Ra=12/3//resistance Va=15//voltage drop Za=Va/I Xa=sqrt(Za^2-Ra^2) //for coil B Rb=6/3//resistance Vb=9//voltage drop Zb=Vb/I Xb=sqrt(Zb^2-Rb^2) //for coil C Rc=9/3//resistance Vc=12//voltage drop Zc=Vc/I Xc=sqrt(Zc^2-...
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//Solutions to Problems In applied mechanics //A N Gobby clear all; clc //initialisation of variables clear w=450//lbf/in^2 m=3000//lbf/in^2 g=32.2//lbf/in^2 h=144//in //CALCULATIONS M=sqrt(g*m*h/w)//ft/f //RESULTS printf('the maximum rim speed of flywheel=% f ft/f',M)
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//// //Variable Declaration n = 1.0 //Number of moles of CO2 T = 300.0 //Temeperatures of Water bath, K vi = 25.0 //Initial and final state Volume of Ideal Gas, L vf = 10.0 R = 8.314 //Ideal Gas Constant, J/(mol.K) //Calcualtions pext = n*R*T/(vf/1e3) pi = n*R*T/...
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clc clear //INPUT l1=1.9;//length of the first bar in cm l2=5;//length of the second bar in cm k2=0.92;//thermal conductivity in cgs unit //CALCULATIONS k1=k2*(l1/l2)^2;//thermal conductivity if first bar in cgs unit //OUTPUT mprintf('thermal conductivity of first bar is %3.3f cgs unit',k1)
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//============================================================================== // chapter 5 example 20 clc; clear; //input data Ps = 10^7; V = 33*10^3; R = 2; //calculation I = Ps/V; Pd = (I^2*R)/1000; n = ((Ps-Pd)/Ps)*100; v = I*R; Vd = (v/V)*100; ...
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// Aim:To determine the system accuracy of in SI units // Given: // servo valve gain: G_SV=2.46; //(cm^3/s)/mA // cylinder gain: G_cyl=0.031; //cm/cm^3 // feedback transducer gain: H=4; //V/cm // mass of load: M=450; //kg // volume of oil: V=819; //cm^3 // system deadband: SD=4; //mA // bulk modulus of oil: beta1=1200;...
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////Variable Declaration n = 52 //Total cards //Calculations TotalM = n*(n-1)*(n-2)*(n-3)*(n-4) //Results printf("\n Total number of Five card arrangment from a deck of 52 cards is %d",TotalM)
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//clc() P = 101.3;//kPa T = [283 293 303 313]; for i=1:4 Ps(i) = exp(13.8858 - 2788.51/(T(i)-52.36)); end for j =1:4 Ys(j) = Ps(j) * 78.048 / ((P - Ps(j))*29); end disp(Ps) disp(Ys) plot(T,Ys,rect = [270,0,323,0.9]); //Tas = Tg - L *(Y1as - Y1) / Cs //Cs = Cb + Y1 *Ca = 1.005 + Y1 * 1.2, L = 43...
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clear; clc; format('v',6); w=10^6,B=1,a=8,Vg=10; Zo=60+40*%i,Zg=40,Zl=20+50*%i; a=(a/8.686);;//Since 1Np=8.686 dB Y=a+B*%i; Yl=2*Y; h=tanh(Yl); Zin=Zo*(Zl+Zo*tanh(Yl))/(Zo+Zl*tanh(Yl)); disp(Zin,'The input impdence ='); Io=Vg/(Zin+Zg);//at z=0 disp(Io*1000,'Sending end current in mA ='); Vo=Zin*Io; Vop =...
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clear; clc; Pr=90e6 pf=.9; S=Pr/(3*pf); P=Pr/3 Q=sqrt(S^2 - P^2); V1=220e3/sqrt(3); V2=220e3/sqrt(3); R=15 X=50; tr=sqrt(1-(((R*P)+(X*Q))/(V1^2))); mprintf("tap setting tr= %.4f, ts=%.3f",fix(1e4/tr)/1e4,tr)
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ex1_10.sce
// Exa 1.10 clc; clear; close; format('v',7) // Given data R1= 5;// in ohm R2= 5;// in ohm R3= 10;// in ohm R4= 10;// in ohm R5= 5;// in ohm V1= 50;// in V V2= 20;// in V //Applying KCL at node A: VA*(R1*R3+R3*R2+R2*R1)+VB*-R1*R3 = V1*R2*R3 (i) //Applying KCL at node B: VA*R4*R5+VB*-(R2*...
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function yprim=f(t,y) //declaring the ode as given in a function yprim(1)=y(2); yprim(2)=-4*y(1) ; endfunction t0=0; tmax=5; //defining initial conditions t=t0:0.05:tmax; //getting t from initial conditions with interval of 0.05 y0=3; yprim0=0; c10=1; c1prim0=1; //Case A c20=4; c2pr...
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7_3.sce
// example:-7.3,page no.-347. // program to find required length,d and Q for l=1 and l=2 resonator mode. a=0.04755;b=0.02215;eipsilar=2.25;tandelta=0.0004;f=5*10^9;c=3*10^8; k=(2*%pi*f*sqrt(eipsilar))/c // wave number. for l=1:1:2 d=(l*%pi)/sqrt((k^2)-((%pi/b)^2)); // m=1 & n=0 mode. disp(d,'d in meter = ') end ...
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//images = [ // "C:\Users\Sanjil\Desktop\OCR\Zero.png", // "C:\Users\Sanjil\Desktop\OCR\One.png", // "C:\Users\Sanjil\Desktop\OCR\Two.png", // "C:\Users\Sanjil\Desktop\OCR\Three.png", // "C:\Users\Sanjil\Desktop\OCR\Four.png", // "C:\Users\Sanjil\Desktop\OCR\Five.png", // "C:\Users\Sanjil\De...
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16Ex8.sce
//Chapter 9 Ex 8 clc; clear; close; //let B be closed after x min.Then part filled by(A+B) in x min +part filled by A in (18-x)=1 x=poly(0,'x'); for x=1:10 if ((x*(1/24+1/32))+((18-x)/24))==1 break; end end mprintf("The pipe B should be closed after %d min",x);
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get_contextura.tst
PL/SQL Developer Test script 3.0 4 begin -- Call the function :result := get_contextura(pcontextura_id => :pcontextura_id); end; 2 result 1 Gruesa 5 pcontextura_id 1 1 4 0
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AulaPratica1_Ficha_1.sce
//1º aula prática MD //1/numero_pontos-1 (numero_espacos) /*Exemplo linspace(1,2,5) --> Devolve valores dos intervalos */ clear clc /*a=4; b=5; c=a+b*/ a=4; b=5; //disp('O valor da soma entre a e b é igual a: '+string(a+b)) //disp(a+b,'O valor da soma entre a e b é igual a: ') //messagebox('O valo...
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2_11c.sce
clc clear //Initialization of variables mf=10000 //lb mr=700 //lb Cr=0.2 //calculations Q3=mr*Cr/mf *14600 //results printf("Heat loss = %d Btu per lb of fuel",Q3)
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//Example 12.5.1 // chart speed clc; clear; close; //given data : f=50;// frequency in Hz period=1/f; t=5;//in mm/cycle chart_speed=t/period;; disp(chart_speed,"chart speed(mm/s) = ")
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(unwatch all) ; globlerr.clp test (clear) (open "globlerr.rsl" globlerr "w") (load "compline.clp") (dribble-on "globlerr.out") (load "globlerr.clp") (show-defglobals) (dribble-off) (printout globlerr "globlerr.clp differences are as follows:" crlf) (compare-files globlerr.exp globlerr.out globlerr) ; close result file ...
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10_9.sce
clc //initialisation of variables f= 0.01 d= 3 //in l= 22 //ft l1= 20 //ft w= 20 //ft h= 5 //ft h1= 20 //ft t= 4 //min g= 32.2 //ft/sec^2 //CALCULATIONS h2= h+h1 h3= (h-(t*60*%pi*sqrt(2*g/h)/(l1*w*2*64)))^2-4 dh= h2-h3 Q= dh*l1*w //RESULTS printf ('Quantiy discharged= %.f cuses ',Q)
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bow.12_19.tst
12 7:1.0 18:0.2857142857142857 21:0.25 28:0.2222222222222222 43:0.3333333333333333 46:0.3333333333333333 190:2.0 246:0.5 493:2.0 508:1.0 553:0.25 757:1.0 1019:1.0 12 5:0.018867924528301886 18:0.14285714285714285 31:0.125 147:1.0 188:1.0 190:1.0 255:1.0 411:1.0 493:1.0 583:1.0 738:1.0 12 3:1.0 5:0.1320754716981132 12:0....
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clc clear close() exec importdata.sci; exec model2.sci; exec loss1.sci; exec loss2.sci; exec model.sci; [header, data] = importdata("time_series_covid19_confirmed_global.csv"); //----------Extrai os casos e nomes de todos os países---------------- confirmed = strtod(data(:,5:$)); country = data(:,2); state = data(:,1)...
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Ex10_2.sce
clear // // //Initilization of Variables M=40*10**6 //N-mm //Bending moment T=10*10**6 //N-mm //TOrque mu=0.25 //Poissons ratio P_e=200 //N/mm**2 //Stress at Elastic Limit FOS=2 //Calculations //Let d be the diameter of the shaft //Principal stresses are given by //P1=16*(%pi*d**3)**-1*(M+(M**2+T**2)**0.5) //Afte...
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clear // Variable declaration P=15// kW n_b=85// The effiency of the gas boiler in % SCOP=3// An average or seasonal COP (SCOP) of heat pump // Calcualtion // For the gas boiler R_pf=17.65// Rate of primary fuel use in kW m_co2=0.19// The mass of carbon in kg R_co2=R_pf*m_co2// Rate of CO_2 emission in kg/h // For exa...
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Ex8_1.sce
// Exa 8.1 // To calculate coverage gain in dB. clc; clear all; Pdiff=-3; //in dB AMR1=12.2; //in kbps AMR2=7.95; //in kbps AMR3=4.75; //in kbps //solution //CG(dB)=10log{(DPDCH(kbps)+DPCCH)/(DPDCH(AMR bit rate (kbps))+ DPCCH)} CG1=10*log10((AMR1+AMR1*10^(Pdiff/10))/(AMR2+AMR1*10^(Pdiff/10))); CG2=1...
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// sum 30-3 clc; clear; N1=1000; N2=500; P=2.03*10^3; //from table 30-8 K1=1.26; Ks=1; //let Pc be the power transmitting capacity of the chain Pc=P*K1/Ks; p=9.52; n1=21; n2=42; V=n1*p*N1/(60*10^3); //Let the chain tension be T T=Pc/V; //Let the breaking load be BL BL=10700; FOS=BL/T; C=50*p; Ln=(2*...
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clc clear close x=0:.05:5; y=sin(x.^2); plot2d3(x,y)
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// Scilab Code Ex9.1: De-broglie wavelength of an electron from accelerating potential : Page-202 (2010) V = 100; // Accelerating potential for electron, volt lambda = sqrt(150/V)*1e-010; // de-Broglie wavelength of electron, m printf("\nThe De-Broglie wavelength of electron = %4.2e m", lambda); // Result ...
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//Chapter 3 //Example 3_9 //PAge 52 clear; clc; houses=1e3; cl=1.5; dem_fac=0.4; div_fac=2.5; factories=10; md_f=90; tubewells=7; mdt=7; df=1.2; //Minimum capacity of power station sum_md=cl*dem_fac*houses; md_dl=sum_md/div_fac; md_t=mdt*tubewells; total_md=md_dl+md_t+md_f; md_station=total_md/df; printf("Minimum c...
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'successful test DECLARE SUB mouse.loadprog () DECLARE FUNCTION mouse.init% () DECLARE SUB mouse.show () DECLARE SUB mouse.hide () DECLARE SUB mouse.setrange (x1%, y1%, x2%, y2%) DECLARE SUB mouse.put (x%, y%) DECLARE SUB mouse.status () DECLARE SUB mouse.relativestatus () TYPE mouse left AS INTEGER r...
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//pagenumber 40 example 23 //figure is not given in the book clear nd=10^7;//per cubic centimetre na=10^17;//per cubic centimetre voltag=0.1*3800*10^-4*1500*3*10^-3; disp("hall voltage = "+string((voltag))+"volt"); disp("remains the same but there change in polarity");
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//Ex2.7.5 //calculation of voltage across diode connected in parallel. clc; clear; //given Io1=1*10^-12;//reverse saturation current for diode1 Io2=1*10^-10;//reverse saturation current for diode2 I=2*10^-3;//total current //room temperature T=27;//temp in celsius T=T+273;//temp in kelvin n=1//n is emission...
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clear; clc; printf("\t\t\tExample Number 10.14\n\n\n"); // ammonia condenser // Example 10.14 (page no.-552-553) // solution Ta = 50;// [degree celsius] temperature of entering ammonia vapour Tw1 = 20;// [degree celsius] temperature of entering water q = 200;// [kW] total heat transfer required U = 1;// [...
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//Fibonacci Series clc; clear; f(1)=1; f(2)=1; for i=3:30 f(i)=f(i-1)+f(i-2); end f
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clc //Given that lambda = 1 // wavelength in Angstrom theta = 90 // angle of scattered photon in degree m_e = 9.11e-31 // mass of electron in Kg c = 3e8 // speed of light in m/s h = 6.63e-34 // plank's constant //Sample Problem 19a page No. 144 printf("\n\n\n # Problem 19a # \n") printf("\n Standard formula Us...
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clear clc //initialisation of variables d= 8 //in w= 2 //in di= 12 //in wi= 3 //in a= 24 //degrees p= 88 //per cent a1= 85 //degrees a2= 30 //degrees p1= 94 //per cent h= 180 //ft d1= 18 //in Cd= 0.92 g=32.2 n1= 111 //rpm //RESULTS r1= 1/tand(a) r2= (1/tand(a1))+r1 r3= 2*r2/3 r4= (1/tand(a2))-r3 ...
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clc //Example 10.2 //Calculate the maximum elevation above the lowest water level in sump at which pump inlet can be placed P1=3.72//psia 0r lbf/in^2 P2=14.5//psia 0r lbf/in^2 dP=P2-P1//psia 0r lbf/in^2 rho=61.3//lbm/ft^3 g=32.2//ft/s^2 //1 ft = 12 in //1 lbf.s^2 = 32.2 lbm.ft h_loss=4//ft v=10//ft/s h_max=...
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clc //initialization of variables P= 5*746 // power of fan converted in watt t=1*60*60 // time converted to seconds // by first law of thermodynamics Q=delU + W // Q=0 hence -W=delU // first we find work input W=-P*t // work in J delU=-W // from 1st law printf("The internal energy increase is "+string(delU)+...
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//Example 5.4, Page number 5.29 clc;clear;close // variable declaration delta=0.05 //unitless n1=1.46//unitless // Calculation N_a=n1*(2*delta)**(1/2) // Numerical aperture // Result printf("Numerical aperture = %.2f",N_a)
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.6 //calculation of position of the image of an object placed at a distance from spherical convex surface //given data u=-15; //object distance(in cm) R=30; //radius of curvature of the spherical convex surface(in c...
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style.fontSize=14; style.displayedLabel="<b>GPIO In </b>(Loc. fix)</b><br>%1$s"; pal6 = xcosPalAddBlock(pal6,"gpio_in_fixloc",[],style); //arbitrary waveform generator
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//Example 5.7 clc;clear;close; format('v',5); G=100;//MVA f=50;//Hz n=3000;//rpm L=25;//MW//Load td=0.5;//sec H=4.5;//MW-sec/MVA //Calculation KE=H*G;//MW-sec////at no load KE_Loss=L*td;//MW-sec///due to increase in load f_new=sqrt((KE-KE_Loss)/KE)*f;//Hz delF=(f-f_new)/f*100;//%////frequency deviation di...
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//Problem 42.07: A low-pass T section filter having a cut-off frequency of 15 kHz is connected in series with a high-pass T section filter having a cut-off frequency of 10 kHz. The terminating impedance of the filter is 600 ohm.(a) Determine the values of the components comprising the composite filter. //initializi...