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clc; clear; //example 25.10 //binary division format('v',8);//changing the default precision to 8 a=11001;//first number b=100;//second number A=bin21dec(a);//converting a in to decimal number B=bin21dec(b);//converting b in to decimal number S=A/B; //multiply the two decimal numbers temp=dec21bin...
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clc x=%inf disp("x intercept = "+string(x)) //initializing value of X intercept. y=1 disp("y intercept = "+string(y)) //initializing value of Y intercept. z=1 disp("z intercept = "+string(z)) //initializing value of Z intercept. h=[1/x] disp("miller indices,h=[1/x] = "+string(h))//calculation k=[1/y] disp("k=...
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clc; ue=1.553;//given ue u0=1.544;//given uo lamda=500*1e-9;//in meter t=lamda/(4*(ue-u0));//The thickness of quarter wave plate disp(+'meter',t,'The thickness of quarter wave plate =')
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//ex_23 product of discrete signal and unit step function clear; clc; close; t=-3:3; x=[3 2 1 0 1 2 3]; //u[1-n] for i=1:length(t); if t(i)<=1 then u1(i)=1; else u1(i)=0; end end y=x.*u1'; figure a=gca(); plot2d3(t,y) plot(t,y,'r.') xtitle('y[n]','n') a.y_location='origin...
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function strAnswer = hrtCommandAnswer(strFrame,strMensage,strDescri) iniFrame = hrtFrameIni(strFrame); if hrtFrameType(strFrame) == 1 then str = hrtFramePreamble(strFrame)+' 86 '+part(strFrame,iniFrame+3:iniFrame+20)+strMensage; else str = hrtFramePreamble(strFrame)+' 06 '+part(strFrame,iniF...
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//Page Number: 11.32 //Example 11.33 clc; //Given //(a)Efficiency of code Px=[0.2 0.2 0.2 0.2 0.2]; na=[2 2 2 3 3]; //As H(X)=-Sum of[P(ai)log2P(ai)] //Where i=0 to n; HofX=0; for i=1:5 HofX=HofX+(Px(i)*log2(Px(i))); end //Average Code length //L=Summation(P(xi)ni) La=0; for i=1:5 La=La+(P...
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clc,clear printf('Example 3.4\n\n') W1=9.1 //Tension on tight side W2=0.8 //Tension on slack side I=10 //Total_current V=110 //Supply voltage R=7.5/100 //Radius of p-ulley in metres N=1320 //speed in r.p.m T_sh=(W1-W2)*9.81*R //9.81 is the accelration due to gravity omega=(2*%pi*N/60) P_out=T...
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// Example 6.4.c //optical loss clc; clear; close; NA=0.2;//numerical aperture n=1.4;//refractive index nc=(NA)^2;//coupling efficiency pe=0.012;// pc1=pe*nc;// Loss=round(-(10*log10(pc1)));//optical loss in dB disp(Loss,"optical loss in dB is") //answer is wrong in the text book
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clear// //Variables ni = 1.41 * 10**16 //intrinsic concentration (in per cubic-metre) un = 0.145 //mobility of electrons in germanium (in metre-square/volt-second) up = 0.05 //mobility of holes in germanium (in metre-square/volt-second) ...
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clear; clc; printf("\t Example 2.20\n"); //this is the case of equimolar counter diffusion as the latent heat of vaporisation are very close to each other T=(360); //temperature in kelvin pt=372.4/760; //total pressure in atm R=82.06; ...
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//Ex 3.23 clc;clear;close; format('v',6); f0=100;//Hz(3-dB frequency) Ri_inf=100;//kohm(High frequency input resistance) Tinf=1;//high frequency gain R1=Ri_inf;//kohm R2=Tinf*R1;//kohm C=1/(2*%pi*f0*R2*1000)*10^9;//nF disp("Design values are :"); disp(R2,"Resistance R1=R2 in kohm : "); disp(C,"Capacitance C(...
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clear clc CAo=[2;5;6;6;11;14;16;24];//mmol/m3 CA=[0.5;3;1;2;6;10;8;4];//mmol/m3 t=[30;1;50;8;4;20;20;4];//min vo=0.1;//m3/min for i=1:8 inv_rA(i)=t(i)/(CAo(i)-CA(i)); end //Sorting CA and accordingly changing -1/rA for plotting graph between CA and -1/rA for i=1:8 for j=i:8 if CA(i)>CA(j) ...
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clc //ex11.11 A_d=1000; //differential gain V_d_peak=1*10^-3; //peak value of differential input signal V_o_peak=A_d*V_d_peak; //peak output signal V_cm=100; V_o_cm=0.01*V_o_peak; //common mode contribution is 1% or less A_cm=V_o_cm/V_cm; //common mode gain CMRR=20*log(A_d/A_cm)/2.30258...
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clc;funcprot(0);//EXAMPLE 7.8 // Initialisation of Variables m=9;.........//Weibull modulus of an ceramic sigma1=250;.......//The flexural strength in MPa F1=0.4;.......//probability of failure F2=0.1;.......//Expected the probability of failure //CALCULATIONS sigma2=exp(log(sigma1)-(log(log(1/(1-F1)))/m ));.....
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clc; //Example 32.8 //page no 514 printf("Example 32.8 page no 514\n\n"); //a filter press is in operation //we have to determine the appraisal value of the press i=0.03375//intrest on fund n=9//time,year SFDF=i/((1+i)^n -1)//sinking fund depreciation factor P=60000//cost of filter press,$ L=500//salvage valu...
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function[r,theta]=rect2pol(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) theta=atand(y/x) endfunction function[z]=pol2rect(r,theta) x=r*cos(theta*%pi/180) y=r*sin(theta*%pi/180) z=x+y*%i endfunction j=%i I=pol2rect(300,-acosd(.8))//total load to be shared by transformers A and B at ...
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// Scilab Code Ex4.8 : Page-93 (2010) lambda = 550e-09; // Wavelength of light, m D = 3.2e-02; // Diameter of circular lens, m f = 24e-02; // Focal length of the lens, m theta_min = 1.22*lambda/D; // Minimum angle of resolution provided by the lens, rad // As delta_x/f = theta_min, solving for delt...
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//The ac Motor Control// //Example 15.8// f1a=50;//intial input frequency in hertz// Ta=2000;//developing torque in induction motor in watts// Tb=1500;//new value of torque reduced to in watts// f1b=f1a*sqrt(Ta/Tb);//value of stator frequency increased to in hertz// printf('value of stator frequency increased to ...
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w0=1000 w2=1050 wb=2*(w2-w0) Q0=w0/wb disp(Q0)
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//chapter12,Example12_1,pg 357 n1=1.53//refractive index n2=1.5 lam=1*10^-6//wavelength a=50*10^-6 NA=sqrt((n1^2)-(n2^2)) V=((2*%pi*a)*NA)/lam printf("normalised frequency\n") printf("V=%.2f ",V) M=(V^2)/2 printf("\ntotal no. of guided mode\n") printf("M=%.2f",M)
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FLAGS='-X -c bbb' STDIN='aaa,bbb,ccc\n"a1","b1","c1"\n"a2","b2","c2"\n' STDOUT='<?xml version="1.0" encoding="UTF-8"?>\n<csv>\n <row>\n <bbb>b1</bbb>\n </row>\n <row>\n <bbb>b2</bbb>\n </row>\n</csv>\n' STDERR='' EXITVAL='0'
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//Page Number: 15 //Example 1.5 clc; //Given l=1.2;//mH r=8;//ohm c=200D-12;//F //(i) Resonant frequency f0=(1/(2*%pi))*sqrt(1/(l*c));//hz disp('hz',f0,'Resonant frequency:'); //(ii) Impedance of circuit disp('ohm',r,'Impedance of circuit:'); //(iii)Q factor of the circuit q=1/(2*%pi*f0*c*r); disp(q...
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codeblock readtextfile(ScriptDir+"\TOOLS.sci"); codeblock readtextfile(ScriptDir+"\SSYS.sci"); lattit=51/180*Pi; ssysframe=ssys_create; ssys_createearth(200); ssys_showstarback(false); #Create dialog controls dialogframe=T_createdialogframe; chk_showhorizon=dialogframe.add("CheckControl","Size":0.03,"Position":po...
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//chapter 16 //example 16.6 //page 485 clear; clc ; //given Zzr=7;//dynamic impedance of 1N753 Vs=15;//dc supply R1=150; Vo=6.2; Ilmax=55; deltaVs=10/100*Vs; deltaVo=1000*deltaVs*Zzr/(R1+Zzr); //line regulation lineR=(deltaVo*100/Vo)/1000; printf("\nline regulation=%d%% ",lineR) deltaIl=Ilmax; deltaV...
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//Example 32.4 m=235.04;//Mass of one mole of 235 U (g) mol=1000/m;//Number of moles in 1 kg (mol) atoms=mol*6.02*10^23;//Number of atoms in 1kg of 235 U E=atoms*200*1.6*10^-13;//Total energy released (J) printf('Total energy released = %0.2e J',E) //The answer varies due to round off error //Openstax - College ...
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// Scilab code Exa1.4.7 : Determination of radius of Pb-208 : Page 36 (2011) A = 208; // Mass number of Pb-208 r0 = 1.2e-015; // Distance of closest approach, m r = r0*((A)^(1/3)); // Radius of Pb-208, m printf("\nThe radius of Pb-208 : %4.2e m", r) // Result // The radius of Pb-208 : 7.11e-015 m
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//laplace// syms t s; y=laplace('2*t-3*%e^(-t)',t,s); disp(y,"ans=")
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function trouver_message(image2) im2=imread(image2); [ligne,colonne]=size(im2); count2=0; for o=1:ligne for p=1:colonne //récupérer la taille de la chaine if o==1 & p==1 then k4=uint8(floor(im2(o,p,2)*16));//msb de la taille k5=floor(im2(o,p,3)*16...
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//Chapter-8,Example 2,Page 195 clc(); close(); H=20*0.1/1000 //as 20 ml of 0.1M HCl pH=-log10(H) pOH=14-pH OH=10^(-pOH) printf(' the [H+] = %.4f mole/l',H) printf('\n the [OH-] =') disp(OH) printf(' mole/l') printf('\n the pH = %.f ',pH)
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clc Vnl=27.3 //no load voltage in volts Vfl1=24 //full load voltage at power factor 1 in volts mprintf("(Vnl-Vfl/Vfl)=%f\n",(Vnl-Vfl1)/Vfl1) //ans may vary due to roundoff error Vfl2=22.1 //full load voltage at power factor 0.7 in volts mprintf("Voltage Regulation=%f",(Vnl-Vfl2)/Vfl1)
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clear; clc; printf("\t\t\tProblem Number 3.18\n\n\n"); // Chapter 3 : The First Law Of Thermodynamics // Problem 3.18 (page no. 119) // Solution h1=1220 //Unit:Btu/LBm //Inlet enthalpy h2=1100 //Unit:Btu/LBm //Outlet enthalpy //Z1=Inlet position //Unit:m //V1=Inlet velocity //Unit:m/s //Z2=Outlet posi...
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//Example 5.4 clc disp("Let us consider D for Door, I for ignition, L for Light. Then conditions to activate the alarm are:") disp("1. The headlights are ON while the ignition is OFF.") disp(" i.e. L = 1, I = 0 and D may be anything.") disp("2. The ddor is open while the ignition is ON") disp(" i.e. D = 1, I ...
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errcatch(-1,"stop");mode(2);//Ex:12.4 ; ; prf=50; C=100*10^-9; R=0.72/(prf*C);//in ohms printf("R= %d kohm",R/1000); exit();
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clear; clc; //page no. 203 r1 = 5;//ft r2 = 3.5;//ft beta1 = 60;//degrees beta2 = 150;//degrees t = 1;//ft alpha1 = 15;//degree Q = 333;//cfs gam = 0.434; V_r1 = Q/(2*%pi*r1); V_r2 = Q/(2*%pi*r2); V_t1 = V_r1*(1/tan(alpha1*%pi/180)); u1 = V_t1 - V_r1*tan((90-beta1)*%pi/180); omega = u1/r1; u2 = om...
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Z = [ 1 2 3 4 5 4 6 7 2 8 9 10 11 12 13 11 7 ; 14 15 16 17 18 19 20 21 1 22 3 23 24 25 26 19 17 ; 27 28 19 29 6 30 8 31 26 32 33 34 35 19 36 37 38 ; 39 40 4 1 2 7 3 9 10 41 6 2 42 10 43 26 44 ; 8 29 45 27 5 28 46 47 48 12 20 22 15 14 17 31 19 ; 23 16 26 18 36 1 24 30 38 21 26 13 49 37 50 39 40 ; 10 34 33 30 19 44 43 9 ...
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clc; disp("Example 2.4") m=0.2 // thickness in cm mew=1 // viscosity in poise w= 10 // width of the plate in cm density=1 // density in gm/cc g=981 // acceleration due to gravity in cm/s^2 //Q is the liquid flow rate Q=(density*g*m*m*m*w)/(3*mew) disp(" The flow rate is ") disp(Q) disp(" gm/cc")
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clc; Rf=100000; Rin=10000; AcL=Rf/Rin; Zin=Rin; Acm=0.001; CMRR=AcL/Acm; Vin=1; Vout=AcL*Vin; slewrate=500000; Vpk=5; fmax=slewrate/(2*3.14*Vpk); disp(' ',AcL,"AcL=");//The answers vary due to round off error disp(' ',CMRR,"CMRR=");//The answers vary due to round off error disp('Vpp',Vout,"Vout=");//T...
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// Test #2 : Excess Input Arguments exec('./iirpowcomp.sci',-1); [b,p]=iirpowcomp(3.33,0.444,90,9); //!--error 10000 //2/3 input arguments allowed //at line 33 of function iirpowcomp called by : //[b,p]=iirpowcomp(3.33,0.444,90,9)
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// Chapter 11 Example 1// clc clear // number of units=n,voltage across topmost unit=v1,voltage across second unit=v2// n=4; m=10;// capacitance ratio is 10 (given)// v1=1;//let v1=1 for our conveniance// v2=v1*(1+1/m); //voltage across third and fourth units from top =v3,v4 respectively// v3=v1*(1+(3/m)+(1/m^...
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function [yobt,yob]=icsvisu(vue) //Visualisation de l'observation de l'etat //Syntaxe //[yobt,yob]=icsvisu(vue) //variables d'entree : //vue : vecteur des indices des composantes a visualiser //variables de sortie : //yobt : observation de l'etat a tous les instants //yob : idem, aux instants d'observation //! // // ...
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//given d^2/dt(y(t)) + 6*d/dt(y(t)) + 8*y(t) s=%s; F= 16/((s+1)*(s^2+6*s+8)); syms t s; y=ilaplace(F,s,t); disp(y,"f(t)=")
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// Exa 7.2 clc; clear; // Given l = 50; // length of potentiometer in mm R = 5000; // Total resistance of potentiometer in Ohms Rt = 1850; // Resistance of potentiometer in Ohms // Solution R_length = R/l ; // Resistance per unit length R_normal = R/(l*10^-3*0.5); printf(' Resistance of normal posit...
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clc; clear all; Eg=0.3;//fermi level in eV //Ni300=Nc*exp(Ec-Ef300/k*T) so.. //Ni300=Nc*exp(-Eg*1.6e-19/k*T) //and //Ni330=Nc*exp(-(Ec-Ef300)/k*T) so.. //exp(Ec-Ef300/k*T)=exp(-(Ec-Ef300)/k*T) so.. //let Ec-Ef300=x x=Eg*330/300;//fermi energy lies at disp('eV',x,'fermi energy lies at:')
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//Example 8.14 clear; clc; A0=1; brecmin=5; Rc=3*10^3; Rf=Rc*(brecmin-1); GBP=20*10^6; fx=(1/brecmin)*GBP; Cc=brecmin/(%pi*Rc*fx); printf("(a) Rc=%.f kohms",Rc*10^(-3)); printf("\n Rf=%.f kohms",Rf*10^(-3)); printf("\n Cc=%.f pF",Cc*10^12); printf("\n\n(b) A(jf)=1/[1+jf/(%.f...
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//binnenhalen van de WAV-file [testsign,Fs,bits]=wavread("F:\scilab-5.5.2\modules\sound\demos\BART4.wav"); samplespeed = Fs; delay = 500; // choose the echo time of the sound (ms) echotime = [delay/1000] * samplespeed; //for loop voor de lengte van het audio-signaal for n=1:length(testsign), if n + echotime < leng...
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//pagenumber 307 example 29 clear beta1=500; ib=20*10^-6;//ampere re=100;//ohm ic=beta1*ib; vc=ic*0.47*10^3;//voltage drop across collector resistance v1=(10-vc); vb=v1-0.6; rb=vc/ib; disp("base resistance = "+string((rb))+"ohm"); ve=re*ic; disp("base resistance with re"); b=0.6+0.1; rb=(v1-b)/ib; di...
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Z0=50; //define 50 Ohm characteristic impedance Z=[50 48.5 75+%i*25 10-%i*5]; //define impedances for this example Gamma=(Z-Z0)./(Z+Z0) //compute corresponding reflection coefficients SWR=(1+abs(Gamma))./(1-abs(Gamma)); //find the SWRs a=0:0.01:2*%pi; for n=1:length(Z) plot(abs(Gamma(n))*cos(a),abs(Gamma(n))*si...
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clear; n = 5; // # of cells in a row m = 200; // # of steps x = linspace(0,9,n);// initial values y = linspace(0,9,n);// initial values for i=1:n for j=1:n p(i,j)=n-i//abs(cos(j)); r(i,j)=1//abs(sin(i)*cos(j)); end end sp = sum(p); sr = sum(r); for i=1:n for j=1:n p0(i...
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clc mu_n=6000 disp("mu_n = "+string(mu_n)+"cm^2(Vs)^-1") //initializing value of channel mobility phi_b=0.8 disp("phi_b = "+string(phi_b)+"V") //initializing value of Schottky barrier height kBT=0.026 disp("kBT = "+string(kBT)+"eV") //initializing value of multiplication of boltzmann constant and 300K temperatur...
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errcatch(-1,"stop");mode(2);// Example 2.32, page no-49 theta=20//in degrees d=2*10^-10//m n=1 h=6.626*10^-34 m=1.67*10^-27//kg e=1.6*10^-19//C lam=2*d*sin(theta*%pi/180)/n E=(1/(2*m))*(h/lam)^(2) printf("\nThe deBroglie wavelength of the neutron is %.3f *10^-10\nthe energy of the neutron is %.4f eV",lam*1...
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clc P1=0.124*10^5; //N/m^2 T1=433; //K T2=323; //K h_f1=687; //kJ/kg h2=2760; //kJ/kg h3=2160; //kJ/kg h_f4=209; //kJ/kg Q1=h2-h_f1; Q2=h_f4-h3; disp("Let A=ΣdQ/T") A=Q1/T1+Q2/T2; disp(A) disp("A<0. Hence classius inequality is verified")
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clear; clc; printf("\nEx4.2\n"); //page no.-156 //given b=2.898*10^-3;.......//constant in m*K T=2000;...............//temperature in kelvin lambda=b/T.............//wavelength in m, relation by Wein's Law printf("\nwavelength is 1.449 micron\n"); printf("\nWe know visible region is 0.4 micron to 0.8 micro...
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//Chapter-2, Example 2.2, Page 2.5 //============================================================================= clc clear //INPUT DATA N1=400;//Number of turns in the primary N2=30;//Number of turns in the secondary Q=20000;//Rating of the transformer in VA V1=2000;//Primary voltage in V f=50;//Power supp...
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clc //initialization of variables clear // linked to 6_14 D=10 //cm d= 1 //cm n=20 P=60 //kg G=8*10^5 //kg/cm^2 // calculations m=D/d fs=8*P*D/(d^3*%pi) fs1=fs*(1+0.615/m+3/(4*m-4)) // results printf('The shear stress with and without correction facor are \n respectively %d, %d kg/cm^2',fs,fs1)
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//============================================================================== //= Desarrollo del algoritmo de encriptado DES en Scilab //= El programa se realiza para el curso de Seguridad en redes Inalambricas //= de la Escuela de Ingenieria en Telecomunicaciones de la UNSA //= Creditos: //= Editor: Chacon Cadi...
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P=10^6;//pressure of gas in dyn per cm^2// p=0.00333;//density of gas in gram per cm^3// C2=3*P/p;//mean square velocity of gas in (cm/sec)^2// Crms=sqrt(C2);//Root mean square velocity of Oxygen in cm/sec// printf('Root mean square velocity of Gas=Crms=%fcm/sec',Crms); Cm=Crms/1.085;//mean velocity of Gas in cm/s...
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वेणु वेणुभ्याम् N;DAT;DU वेणु वेणुभ्यः N;DAT;PL वेणु वेण्वोः N;LOC;DU वेणु वेणुभिः N;INS;PL वेणु वेण्वोः N;GEN;DU वेणु वेणुः N;NOM;SG वेणु वेणवः N;NOM;PL वेणु वेणुना N;INS;SG वेणु वेणवे N;DAT;SG वेणु वेणोः N;GEN;SG वेणु वेणूनाम् N;GEN;PL वेणु वेणू N;NOM;DU वेणु वेणू N;VOC;DU वेणु वेणुभ्याम् N;INS;DU वेणु वेणुषु N;LOC;P...
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clear; clc; //Example - 1.12 //Page number - 30 printf("Example - 1.12 and Page number - 30\n\n"); //Given Y = 1.4;//molar heat capacities ratio for air R = 8.314;// [J/mol*K] - Universal gas constant Cv_0 = R/(Y-1);// [J/mol*K] Cp_0 = Y*Cv_0;// [J/mol*K] printf(" The molar heat capacity at constant vol...
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<start> <upsFile>cavityFlow_dx.ups</upsFile> <gnuplot> <script>plotScript.gp</script>s <title>ICE:Cavity Flow Res</title> <ylabel>Error</ylabel> <xlabel>Resolution</xlabel> </gnuplot> <AllTests> <replace_lines> <maxTime> 20 </maxTime> </replace_lines> <replace_values> /Uintah_specifica...
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clc clear //Initialization of variables vis=2.5/10 //N s/m^2 D=15 //cm N=180 dy=0.0001 //m l=0.15 //m b=0.25 //m r=0.152 //m //calculations dv=%pi *D*N/60/100 Tau=vis*dv/dy Tor=Tau*%pi*l*b*r/2 P=Tor*2*%pi*N/60 //results printf("Power required = %d W",P) disp("The answer is a bit different due to round...
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Me=2; //mach no in test section at standard sea level condition //following are the standard sea level conditions desired at the exit of nozzle: Pe=1.01*10^5;//static pressure,N/m^2 Te=288.16; //static temperature in Kelvin y=1.4; //specific heat ratio for air A=1+(y-1)*Me^2/2
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clc clear a=[5 12 6.8 7.4 23 15 18 48 12 14 23 22 29 15 9.3 15 13 16 22 19 35 30 35 33 30 35; 13 20 14 16 15 8.1 11 50 5.1 5.5 16 15 22 5.6 5.3 11 18 19 23 20 36 31 36 34 22 39; 23 34 29 24 8.6 4.9 4.1 4.1 14 8.5 3.1 2.4 7.4 12 13 13 22 23 15 18 20 17 18 19 9.3 23; 16 27 23 14 23 13 14 14 17 11 7.4 8.1 13 6.3 9.8 4.2 ...
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V=300 Ea=V n1=1200 n2=1100 Kaphi=Ea/2/%pi/n1*60 T=350 Ia=T/Kaphi Ea=V*n2/n1 Ra=(V-Ea)/Ia Kaphi=Kaphi/2 n=Ea/Kaphi*60/2/%pi Pm=Ea*Ia T=Kaphi*Ia disp(T) disp(Pm) disp(n)
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//chapter 5 Ex 9 clc; clear; close; //let the value to be found out be x x=sqrt(.289/.00121); mprintf("x=%.2f",x);
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function trainCascadeObjectDetector(outputFolder,positiveInstances,negativeImages,varargin) // It creates trained cascade XML file // // Calling Sequence // trainCascadeObjectDetector(outputFolder,positiveInstances,"negativeImages") // // Parameters // outputFolder: Folder name to store trained cascade (cascade.xml) ...
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clc //the code below uses userdefined complexstring function function s=complexstring(a) if imag(a)>=0 then s=sprintf('%g+%gi',real(a),imag(a)) else s=sprintf('%g%gi',real(a),imag(a)) end funcprot(0) endfunction VLB=2400 //line to base voltage in volts ...
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k=1; noe = zeros(1,12); noc_r=zeros(1,12); noc_f=zeros(1,12); noc_a=zeros(1,5); noc_d=zeros(1,5); noc_s = zeros(1,5); nocs_r=zeros(1,12); nocs_f=zeros(1,5); nocs_a=zeros(1,5); nocs_d=zeros(1,5); nocs_s=zeros(1,5); nocb_r=zeros(1,12); nocb_f=zeros(1,50); nocb_a=zeros(1,50); nocb_d=zeros(1,50); nocb_s=zeros(1,50); noc...
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clc T=300 //K k=8.617*10**-5//eV/K e=1.6*10**-19 //C Jp=5 //A/cm^2 Jn=20 //A/cm^2 Va=0.65 //V ni=1.5*10**10 //cm^-3 Dn=25 //cm^2/s Dp=10 //cm^2/s taup0=5*10^-7 //s taun0=5*10^-7 //s //Jn=(e*Dn*np0/Ln)*[exp(e*Va/k*T)-1]==e*sqrt(Dn/taun0)*(ni^2/Na)*[exp(e*Va/k*T)-1] Na=e*sqrt(Dn/taun0)*(ni^2/Jn)*[(exp(...
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//Page Number: //Example 2.10 clc; //Given, c=3D+8; //m/s a=3; //cm a1=a/100; //m b=2; //cm b1=b/100; //m f=7.5D+9; //HZ p=5D+3; //W mu=%pi*4D-7; w=2*%pi*f; bet=sqrt(((w/c)^2)-((%pi/a1)^2)); //Charecteristic impedance z0=w*mu*2*b/(bet*a); disp('ohm',z0,'Charecteristic impedance:'); //Peak electr...
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// chapter 13 // example 13.12 // Determine the value of thermal resistance, heat sink and temperature at base // page-840 clear; clc; // given Pa=30; // in W (power loss) Tc=125; // in degree C (junction temperature) Ta=40; // in degree C (ambient temperature) theta_CJ=0.7; // in degree C/W (junction to heat...
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//Example 11.2: Sag clc; clear; close; //given data : format('v',5) l=30;// in meter w=0.72;// weight per meter in kg E=640;// in kg/cm^2 d=1;// diameter in cm T=E*(%pi/4)*d^2; del=((w*l^2)/(2*T))*100; disp(del,"sag(cm) = ")
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errcatch(-1,"stop");mode(2);//Ex:3.16 ; ; V_s=5;//in volts V_c=0.8647*V_s; printf("Inductor voltage = %f V",V_c); exit();
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// 2.4 clc; T=100; G=80*10^9; d=2*15*10^-3; th=16*T/(%pi*G*d^3) printf("Angle of twist= %.6f rad",th)
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// Scilab Code Ex2.22:: Page-2.19 (2009) clc; clear; t = 3.2e-04; // Thickness of the glass sheet, cm lambda = 5500e-008; // Wavelength of light used, cm n = 5; // Order of interference fringes // As path difference (mu - 1)*t = n*lambda mu = n*lambda/t + 1; // Refractive indexof the glass sheet ...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-12,Example 3,Page 430 //Title: P-x-y data using the Margules parameters //================================================================================================================ clear clc //INPUT //...
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function [stk,txt,top]=sci_nnz() // Copyright INRIA txt=[] stk=list('nnz('+stk(top)(1)+')','0','1','1','1')
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//Chapter-1, Example 1.44, Page 51 //============================================================================= clc; clear; //INPUT DATA V=200;//supply voltage in volts I=25;//total current in A P1=1500;//power dissipated in watts //CALCULATIONS R1=(V)^2/(P1);//Resistance R1 in Ohms Reff=(V)/(I);//total e...
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clc //initialisation of variables alf=30//degree v=500//m/sec g=9.8//sec a=60//degre //CALCULATIONS T=2*v*sind(alf)/g//sec L=((v^2)/(g))*sind(a)//km //RESULTS printf('the time of flight is=% f km',L)
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clc; clf; clear all; s = poly(0,"s"); num1=s+3; num2=1; den2=s+1; s1=syslin('c',num2,den2); s2=num1*s1; s6=.5; s3=s2/.s6; s7=1; s4=s3/.s7; disp(s4) t=0:0.001:100; s8=csim('impulse',t,s4); plot(t,s8); xlabel("amplitude") ylabel("time") title("response plot by Om")
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clc //Initialization of variables r1=920 //kg/m^3 r2=1030 //kg/m^3 //calculations VtbyV2=r2/r1 V1byV2=VtbyV2-1 V1byVt=1/(1+1/V1byV2) //results printf("fraction = %.3f ",V1byVt)
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//Example_a_3_15 page no:144 clc; I=10; R1=1; R2=2; R3=3; R=3; I3=10*(2/(2+3)); V=I3*R; disp(V,"the voltage in first method is (in V)"); R=2; I2=10*(3/5); V=I2*R; disp(V,"the voltage in second method is (in V)"); disp("In both cases, the ratio of current to voltage is the same") ratio=0.833; disp(ratio,...
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clear clc //to find work done by three different paths //Given: //refer to figure 23-17 from page no. 529 //final volume vf = 1.0//in m^3 //initial volume vi = 4.0//in m^3 //final pressure pf = 40//in Pa //initialvolume pi = 10//in Pa //Solution: //applying laws of thermodynamics //work done by const...
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// example:-2.7.page no.-50. // program to plot the reflection coefficients for parallel and perpendicular polarized plane waves incident from free space on to a dielectric region with Er=2.55,versus incidence angle. Er=2.55; // relaitve permittivity of dielectric medium. N1=377; // intrinsic impedence N2=N1/sqrt...
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// Problem no 2.5,Page no.33 clc;clear; close; //Notifications has been changed as per requirement h=8 //cm //height of triangle b=8 //cm //breadth of triangle or diameter semicircle d=4 //cm //diameter of circle enclosed //Calculations I_1=b*h**3*12**-1 //cm //moment of inertia of the triangle ABC about the ax...
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clear; // *** データの作成 *** X = linspace(-180,180,360); //Y = log(X); // *** 解くべき関数の定義 *** function y = func(x) y = log(x) - yp; endfunction // *** 非線形方程式ソルバ *** yp = 1; // yp = f(x) x0 = 1; // ソルバ―の初期値 // 非線形方程式を解く xp = fsolve(x0, func) // 誤差 err = abs(xp - exp(yp)) // *** グラフのプロット *** plot(X, Y, '-b'); plot(...
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clc //initialisation of variables Pb= 1800//h.p d1= 0.002378 //slug/ft^3 d= 10 //ft U= 352 //ft/km hr //CALCULATIONS r= Pb*550/(2*d1*%pi*(d/2)^2*U^3) p= (1-r)*100 //CALCULATIONS printf (' ideal efficiency = %.f ',p+1.1)
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S wave equation 1.sce
//TO SOLVE SPHERICAL WAVE SCHRODINGER EQUATION USING VECTOR SPACES AND FINITE DIFFERENCE METHOD //BY VISHU SAINI //7 OCT. 2020 //GIVEN WAVE EQUATION IS OF THE FORM /* y''= A(r)y(r) y(0)=0 y(n)=0 lim n-->inf */ /* We write the above equation in form: H|y> = E|y> ...
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clc //to calculate orders eplusd=1/4000 lambda1=5*10^-5 //wavelengh in cm lambda2=7.5*10^-5 nmax1=eplusd/lambda1 nmax2=eplusd/lambda2 disp("orders will be observed by a grating ,if it is illuminated by light of wavelength of 5000 angstrom is nmax1="+string(nmax1)+"unitless ") disp("or...
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//Initilization of variables mb=0.06 //kg ms=50 //kg h=0.03 //m g=9.8 //m/s^2 //Calculations //Speed of bag+bullet v2=sqrt(2*g*h) //m/s //Applying conservation of momentum v1=((mb+ms)*v2)/mb //m/s //Result clc printf('The speed of bullet as it entered the bag was %f m/s',v1)
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// Solving Using Shooting Method // u''-(1-x/5)uu'=x, u(1)=2, u(3)=-1) function ydot=f(t, y), ydot=[y(2); t+y(1)*y(2)*(1-t/5);] endfunction y0=[2,-1.5]';t0=1;t=1:0.2:3; y=ode(['rkf'],y0,t0,t,f) y1=[2,-3]' U=ode(['rkf'],y1,t0,t,f) y2=[2,-2.2137]' V=ode(['rkf'],y2,t0,t,f) y11=[2,-1.9460]' U1...
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//Find (a) VGSQ; ðbÞ IDQ, and (c) VDSQ. //Solved Example Ex4.11 page no 121 clear clc Vt=4//V R1=50//k ohm R2=0.4//M ohm Rs=0 Rd=2 //k ohm Vdd=15//V Vgsq=(R1/(R1+R2*10^3))*Vdd printf("\n Vgsq = %0.2f V",Vgsq) Idon=10//*10^-3 Idq=Idon*((1-(Vgsq/Vt))^2) printf("\n Idq = %0.2f mA",Idq) Vdsq=Vdd-(Idq*R...
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// Copyright (C) 2012 - Prateek Papriwal // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_V2-...
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clc disp("Example 5.23") printf("\n") disp("calculate closed-loop gain for the negative feedback amplifier") printf("Given\n") //voltage gain without feedback Av=100000 //feedback factor B=1/100 //voltage gain with feedback Acl=Av/(1+(B*Av)) //when Av is changed by 50% Av1=50*100000/100 Av2=Av+Av1 //volta...
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//EXAMPLE 6.1 //Z-Transform of causal sequence clc; clear; syms n a z; x = a^n; X = nusum(x*(1/z)^n,n,0,%inf); limit(X); disp(' X = ',X); disp(' ROC = |z|>|a| ')
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PS_3.sce
// sum 16-3 clc; clear; d=30; W=5*10^3; p=5; rm=45/2; u1=0.15/cosd(14.5); u2=0.15; dm=d-(p/2); alpha=atan(p/(%pi*dm)); phi=atan(u1); Tr1=W*((dm*tan(alpha+phi)/2)+(u2*rm)); Tr1=Tr1*10^-3; n1=dm/2*tan(alpha)/(dm*tan(alpha+phi)/2+(u2*rm)); T1=W*((dm*tan(phi-alpha)/2)+(u2*rm)); T1=T1*10^-3; n2=dm/2*tan(alp...