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<?xml version="1.0" encoding="utf-8" ?> <test> <description>Nodal triangle integration, Fekete points, P = 6</description> <executable>NodalDemo</executable> <parameters>--order 6 --type 23 --integral</parameters> <metrics> <metric type="Linf" id="1"> <value tolerance="1e-12">7.28803...
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 2 disp("CHAPTER 8"); disp("EXAMPLE 2"); // 230 V DC shunt machine //VARIABLE INITIALZATION v_t=230; //terminal voltage in Volts r_a=0.5; //armature resistance in Ohms r_f=115; //shunt field resistance in Ohms I_l=40; //line c...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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clc // Given That lambda = 6e-7 // wavelength of light in meter Mu = 1 // refractive index of air film l = 3e-5 // diameter of wire in meter L = 0.15 // distance of wire from edge in meter i = 0 // incidence angle in radian r = 0 // refracted angle in radian // Sample Problem 31 on page no. 1.51 printf("\n # PROBLEM...
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.TH graycolormap 1 "November 1997" "Scilab Group" "Scilab Function" .so ../sci.an .SH NAME graycolormap - Linear gray colormap .SH CALLING SEQUENCE .nf cmap=graycolormap(n) .fi .SH PARAMETERS .TP 10 n : an integer greater or equal than 1, the "colormap" size .TP cmap : matrix with 3 column, \fV[R,G,B]\fR color definiti...
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clc clear //Input data Z1=0.17;//Level of liquid in m Z=0.76;//Barometer readings in m d=13596;//Density of Hg in kg/m^3 g=9.806;//Gravity in m/sec^2 s=0.8;//Specific gravity d1=1000;//Density of water in kg/m^3 //Calculations dl=s*d1;//Density of given liquid in kg/m^3 Pa=d*g*Z;//Atmospheric pressure in ...
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//------------------------------------------------------------------------------ // Simulation trajectoire exacte sans discrétisation en temps. //------------------------------------------------------------------------------ //------------------------------------------------------------------------------ // Renvoie ...
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clc; clear; //Example 5.16 mo_dot=6*10^-2 //[kg/s] Cpo=2*10^3 //Specific heat of oil in [J/kg.K] Cpw=4.18*10^3 //Specific heat of water in [J/kg.K] T1=420 //[K] T2=320 //[K] T=290 //[K] Water enterin...
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//Finding of Totoal Pressure , Depth of centre //given d=2.5; rho=1000; g=9.81; y1=2; //To Find Ig=(%pi*d^4)/64; Ay=(%pi/4)*d^2; P=Ay*rho*g*y1; a=4/6.25; Ycp=((Ig*a)/(Ay*y1))+y1; disp("P= "+string(P)+" Newtons"); disp("Ycp ="+string(Ycp)+" meter");
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R1=3; //Assigning values to parameters R2=2; R3=4; V1=35; V2=40; A=[5,2;3,-4] //Matrix of I1,I2 by KVL equations B=[35;-5] [I]=inv(A)*B // I matrix has I1 and I2 values disp("Amperes",I(1,1),"Current in 3 ohm resistor"); disp("Amperes",I(2,1),"Current in 4 ohm resistor"); ...
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t1 = input("Enter starting index of t = "); t2 = input("Enter ending index of t = "); c = input("Enter value of c = "); a = input("Enter value of a = "); t = [t1:1:t2+1]; y = [c*(a^t)]; plot2d3(t,y); energy_exp_signal = sum(t.*y); disp(energy_exp_signal,"Energy of signal = ");
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function new_image = getrectsubpix(image, alpha, beta, centerX, centerY, patchType) image_list = mattolist(image) out = opencv_getrectsubpix(image_list, alpha, beta, centerX, centerY, patchType) sz = size(out) for i = 1 : sz new_image(:, :, i) = out(i) end endfunction
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clc clear //Initialization of variables d1=0.5 //ft t1=200 //F t2=80 //F ta=400 //F rho=0.0662 //lbm/ft^3 mum=0.0483 //lbm/ft hr k=0.0167 //Btu/hr ft F cp=0.2408 //Btu/lbm F rho2=0.0567 //lbm/ft^3 mum2=0.0542 //lbm/ft hr k2=0.0190 //Btu/hr ft F cp2=0.2419 //Btu/lbm F g=32.17 //calculations ti=(t1+t2)/2...
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clc,clear clf function testrand2(k) exec('input1.sce',-1) //k is an integer y=[] for i=1:length(S) if modulo(i,k)==0 y=[y',S(i)']' end end histplot(10,y,xlabel('--S with kth elements-->'),ylabel('Frequency Density')) endfunction subplot(1,2,1) testrand2(2) title('Hi...
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//Matemática Discreta - Proposta de resolução da ficha prática 4 //Nota: As resoluções que se seguem apresentam apenas sugestões de resolução dos exercícios propostos. Na maior parte dos casos, existem muitas outras formas de resolver o exercício. //Exercício 1 //a) ceil(100/8) //b) function y=conversor(x) y=ce...
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style.fontSize=16; style.displayedLabel="<table> <tr> <td align=center><b>Vin</b></td> <td align=center>Common<br>Source</td> <td><b>Vout</b></td> </tr> </table>"; pal5 = xcosPalAddBlock(pal5,"common_source",[],style);
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// Distortion Matrix Examples Q1 = [0. 0. 1.1111 1.0784; 0. -1.5464 -1.7172 -0.1961]; Q2 = [0. 0.3191 1.3542 0.9804; 0. -2.1489 -2.2083 -0.098]; Q3 = [0. -0.5 0.9375 0.7692; 0. -2. -1. 0.1538]; [A1,Q1] = dist_mat(Q1,0.5); [A2,Q2] = dist_mat(Q2,0.7); [A3,Q3] = dist_mat(Q3,1.2);
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rand("seed", 9504); T = rand(10,10) + rand(10,10); A = floor((1.0-0.02-4*0.005-0.25)*T); disp(A); for i=1:10 for j=1:10 if(A(i,j)==1 && A(j,i)~=1) then A(j,i)=1; end end end disp(A); clf; plot2d([0,100], [0,100],0); function circle(x, y, r) xarc(x-r, y+r, 2*r, 2*r, ...
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clear; clc; printf("\t\t\tExample Number 10.16\n\n\n"); // heat-transfer coefficient in compact exchanger // Example 10.16 (page no.-556-557) // solution p = 101325;// [Pa] pressure of air T = 300;// [K] temperature of entering air u = 15;// [m/s] velocity of air // we obtain the air properties from tabl...
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// Example 11.5 clear all; clc; // Given data A = 1.23; // Amount of radioactivity release due to I-131 in curie in one year h = 30; // Location of radioactivity release through vent in meter v_bar = 1.2; // Win...
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//Chapter-2,Example 2_8,Page 2-34 clc() //Given Data: lam=5.893*10^-7 //Wavelength of light d=0.01*10^-2 //width of slit (a=d) f=1 //distance between screen and slit //Calculations: x=f*lam/d //separation between central maxima and first minima printf('Separa...
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Name=All-Rounder PlayerCharacters=TileFrenzy Challenger BotCharacters=AR.rot;AR22.rot IsChallenge=true Timelimit=90.0 PlayerProfile=TileFrenzy Challenger AddedBots=AR.rot;AR.rot;AR22.rot PlayerMaxLives=0 BotMaxLives=18;18;37 PlayerTeam=1 BotTeams=2;2;2 MapName=1A.map MapScale=4.3 BlockProjectilePredictors=...
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// Calculate the circuit parameters of a transformer using OC and SC tests clc; clear; E1=200; E2=400; n=E2/E1; // Transformation ratio // O.C Calculations V1=200; Ioc=0.7; Pi=70; R0=(V1^2)/Pi; Iw=V1/R0; Im=sqrt((Ioc^2)-(Iw^2)); X0=V1/Im; //S.C Calculations on HT side Pc=80; I=10; V...
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clc; N = input("Enter number of channels: "); CC = input("Enter number of control channels: "); VC = (N-CC); K = input("Enter size of the cluster: "); Matrix = zeros(K, ceil(N/K)); disp('Fixed Channel Allocation') VCPC = floor(VC./K); CCPC = floor(CC./K); disp(VCPC,"Number of Voice channels per cell are") disp(CCPC,...
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#************************************************************ # Scenario of humanTestEnv # # date : Wed Nov 19 16:37:21 2014 #************************************************************ p3d_sel_desc_name P3D_ENV humanTestEnv p3d_sel_desc_name P3D_ROBOT HERAKLES_HUMAN1 p3d_set_robot_steering_method Linear p3d_set...
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//Initilization of variables d_m=2 //in mean diameter of the screw p=1/4 //in mu=0.15 //coefficient of friction l=2 //ft L=4000 //lb //Calculations phi=atand(mu) //degrees beta=atand(p/(%pi*l)) //degrees //Force to raise the load P=(L*tand(phi+beta))/(d_m*12) //lb //Force to lower the load P2=(L*tand(phi-...
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//Example 1_3 clc; clear; //To compare the intensity at a point distance 1mm from the center to that at its center and to find minimum dist from center of point //Path difference=(Y*d)/D y=1 //units in mm y=y*10^-3 //units in mts D=1 //units in mts d=1 //units in mm d=d*10^-3 //units in mts path...
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load Or16Way.hdl, output-file Or16Way.out, compare-to Or16Way.cmp, output-list ip1%B2.16.2 out%B2.1.2; set ip1 %B0000000000000000, eval, output; set ip1 %B1111111111111111, eval, output; set ip1 %B0001000000000000, eval, output; set ip1 %B0000000100000000, eval,
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function x=msqrt(a) // msqrt - computes the matrix square root. //%CALLING SEQUENCE // x=msqrt(a) //%PARAMETERS // a : square hermitian or diagonalizable matrix // x : square hermitian matrix //%DESCRIPTION // This macro is called by the function sqrt to compute square matrix // square root. //! x=mpow...
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function mostrar = show(valor, X, y) printf('O valor otimo de z = %f',valor,'\n'); printf('Nova matriz de coeficientes = %f',X,'\n'); printf('Novo vetor de resultados = %f',y); mostrar = 0; endfunction
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//SS SCILAB EXPT 5 PART 1 t=-1:0.001:1 w=2*%pi; n_har=5 n=1:n_har b=2./(n*%pi); x=0.5+b*sin(w*n'*t) plot(t,x)
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//Example 5_1 clc(); clear; //To calculate the work done Fs=8 //units in meters W=Fs*round(cos(%pi/2)) //units in Joules printf("The work done is W=%d Joules",W)
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clc a = 21.89 // stochiometric coefficient y = 18.5 // stochiometric coefficient x = 8.9 // stochiometric coefficient PC = 100*(x*12)/((x*12)+(y)) // Carbon percentage PH = 100-PC // Hydrogen percentage AFR = ((32*a)+(3.76*a*28))/((12*x)+y) //Air fuel ratio EAU = (8.8*32)/((21.89*32)-(8.8*32)) // Excess air used...
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clc #defina a matriz A = [4 3 8 1; 12 10 30 8; 24 25 93 49; 20 19 85 90] [nl,nc]=size(A) for i= 1:nl pivo=A(i,i) for j= i+1:nc A(j,:)=A(j,:)-(A(j,i)/pivo).*A(i,:) end end
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//Ex 2.7.2 clc;clear;close; format('v',7); //Given : Vgamma=0.6;//volt Rf=10;//ohm Eta=2; Vm=0.2;//volts Vdc=10;//volts RL=1;//kohm IDQ=(Vdc-Vgamma)/(RL*1000+Rf);//A VT=25*10^-3;//volts rd=Eta*VT/IDQ;//ohm disp("Alternating component of voltage across RL, Vo(ac) = "+string(RL*1000/(RL*1000+rd)*Vm)+"*sin...
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2//Authors: //Sachin Gopal (15BCE1188) //Aashay Gondalia (15BCE1284) //Dhruv Dixit (15BCE1324) //VIT Chennai //Code to compute the CPU time taken by each routing algorithm to return the //Vector of the total distance between each network node and the source node and //Vector composed by the predecessor of eac...
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//calculating volume //Example 1.10 clc clear v=100//Amount of NaCl solution in litres m=120*v//Amount of NaCl in g wt=58.5*2//molecular mass of NaCl Eq=m*100/wt//Equivalents of CaCO3 in g h=500//hardness in ppm V=Eq*1000/h//water required to soften the zeolite softner in litres printf('Thus the zeolite softn...
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@@wildside.sql @@anynums.pkg DECLARE mynums anynums_pkg.numbers_t; BEGIN mynums := anynums_pkg.getvals; DBMS_OUTPUT.PUT_LINE (mynums.count); mynums := anynums_pkg.getvals ('> 100'); DBMS_OUTPUT.PUT_LINE (mynums.count); END; / /*====================================================================== |...
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// Initilization of variables m_a=2 // kg // mass of ball A m_b=6 // kg // mass of ball B m_c=12 // kg // mass of ball C v_a=12 // m/s // velocity of ball A v_b=4 // m/s // velocity of ball B v_c=2 // m/s // velocity of ball C e=1 // coefficient of restitution for perfectly elastic body // Calculations // (A) ...
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//3/8th clc; funcprot(); function y=f(x) y=1/(1+x^2) endfunction x0=input("lower limit of the interval:"); xn=input("upper limit of the interval:"); n=input("no of the subintervals(multiples of 3):"); h=(xn-x0)/n; sum1 = f(x0)+f(xn); for i=1:n-1 if modulo(i,3)==0 then sum1=sum1+2*f(x0+i*h)...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 3.11w //calculation of time of flight,horizontal range and vertical range //given data u=20//initial velocity(in m/s) of the football theta=45//angle(in degree) made by the football with ground g=10//gravitational ac...
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function [stk,txt,top]=sci_findstr(nam) txt=[] stk=list('mtlb_findstr'+rhsargs([stk(top-1)(1),stk(top)(1)]),'0','1','1','10')
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//Example number 9.15, Page number 209 clc;clear; close; //Variable declaration I=3*10**-3; //current(A) RH=3.66*10**-4; //hall coefficient(m**3/C) e=1.6*10**-19; //charge(c) d=2*10**-2; z=1*10**-3; B=1; //magnetic field(wb/m**2) //Calculation w=d*z; //width(m**2) A=w; //area(m**2) EH=RH*I*B/...
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clc; //Example 12.3 //Page No 506 disp("Given: An RG-59A coaxial cable, with L=0.118uH/ft and C=21pF/ft"); //Solution L=0.118*10^-6; C=21*10^-12; disp("Substituting into Equation 12-15(refer pgno506) give us,"); Z0=sqrt((L/C)); disp('ohm',round(Z0),"Z0 = ");
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//Scilab Code for Example 9.1 of Signals and systems by //P.Ramakrishna Rao //Convolution of two signals clc; n=1; for t=-10:0.1:10 x(n)=5*cos(t); y(n)=2*exp(-abs(t)); n=n+1; end z=conv(x,y); t2=-20:0.1:20; plot2d(t2,z); title('Output signal'); xlabel('Time t-->');
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 2.1w //calculation of magnitude and direction of vector //given data xcomp=25; //value of component along X axis ycomp=60; //value of component along Y axis theta=90; //angle between X and Y axis //calculation A=...
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//Ex10_10 clc x='1001000'; disp("Binary number="+string(x))//binary value d=bin2dec(x)//binary to decimal h=dec2hex(d)//decimal to hexa decimal disp("Eqivalent hexadecimal number="+string(h))
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syms G1 G2 G3 H1 H2 a=G2/(1+G2) b=1+G3 c= b*a //shifting the take off point d= (1/(1+G3))+(H2) e= d*H1 Y= a*b/e disp(Y,"R/C = ")
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clear clc sigma1=14;sigma2=10.5; L1=119; //spread of curve is directly proportional to sqrt of distance from origin L=sigma1^2*L1/(sigma1^2-sigma2^2); printf("\n The dumping of toxic phenol must have occured within %f",L) printf("miles upstream of cincinnati")
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clc clear //input data D1=0.9//External diameter of the turbine in m D2=0.45//Internal diameter of the turbine in m N=200//Speed of turbine running in rpm b1=0.2//Width of turbine at inlet in m Cr1=1.8//Velocity of flow through runner at inlet in m/s Cr2=Cr1//Velocity of flow through runner at outlet in m/s a1...
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clc clear //Input data d=0.1;//The diameter of the bore in m L=0.12;//The length of the stroke in m N=3000;//The speed of the engine in rpm n=4;//Number of cylinders pi=3.141;//Mathematical constant of pi R=287;//Real gas constant in J/kgK t=120;//Output Torque in Nm nm=85;//The mechanical efficiency of the e...
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//example 9 //Cooling of a Power Plant by a Cooling Tower clear clc h1=42.2 // Specific enthalpy of dry air in kJ/kg w1=0.0087 //kg water/kg dry air v1=0.842 //specific volume of dry air in m3/kg h2=100.0 //Specific enthalpy of leaving air in kJ/kg w2=0.0273 //kg water/kg dry air h3=146.64 //Specific enthalp...
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clc // Given that t = 1600 // the half life of radium(226) in year t1 = 3.8 // the half life of radon(222) in days m = 1 // mass of Ra(226) in gm // Sample Problem 20 on page no. 12.38 printf("\n # PROBLEM 20 # \n") printf(" Standard formula used \n") printf(" N_1*lambda_1 = N_2*lambda_2 \n") m_ = (222 * t1 * m) / (22...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 1 Example # 1.9 ") //Cross sectional area in m2 A = 1; //Heat transfer coefficient on hot side in W/m2-K hchot = 10; //Heat transfer coeffic...
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//Example 3.24 //Program to Compute the DFT of the Sequence x[n]=(-1)^n, for N=4 clear; clc ; close ; N=4; n=0:1:N-1; x=(-1)^n; //DFT Computation X = fft (x,-1); //Display Sequence X[k] in command window disp(X,"X[k]=");
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// Scilab Code Ex4.6a: Page-139 (2006) clc; clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV E_F = 7.0; // Fermi energy of Cu, eV f_E = 0.9; // Occupation probability of Cu k = 1.38e-023; // Boltzmann constant, J/mol/K T = 1000; // Given temperature, K // We have, f_E = 1/(exp((E-E_F)*e/(k*T))+1), ...
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//Example 22.3 // critical current density clc; clear; //given data : d=1D-3;//diameter of wire in m Ho=6.5D4;//critical field at temperature at 0k Tc=7.18;// critical temperature in kelvin T=4.2;//temperature in kelvin Hc=Ho*(1-(T/Tc)^2);//critical field at T kelvin Jc=4*Hc/d;//formula disp(Jc,"critical curr...
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clc() clear all function result=f(x) result = 0.2+25*x-200*x^2+675*x^3-900*x^4+400*x^5 endfunction function result=reglaSimpson13(a,b,funcion) paso = (b-a)/2 x0 = a x1 = a+paso x2 = b result = (x2-x0)*(funcion(x0)+4*funcion(x1)+funcion(x2))/6 endfunction a = 0 b = 0.8 disp("integral") i...
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PL/SQL Developer Test script 3.0 28 DECLARE --variables -- cursor CURSOR c_CLIENT IS SELECT * FROM CLIENT; -- record r_CLIENT c_CLIENT%ROWTYPE; BEGIN OPEN c_CLIENT; LOOP FETCH c_CLIENT INTO r_CLIENT; EXIT WHEN c_CLIENT%NOTFOUND; updatecityforclient(2190855, ...
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// Example 18.21, page no-473 clear clc A=7.54*10^-4 //m^2 d=2.45*10^-3 //m epsr=6 v=10 //V eps=8.854*10^-12//F/m c=eps*epsr*A/d printf("\nThe capacitance of the capacitor is %.3f pF",c*10^12) Q=c*v E=v/d p=eps*(epsr-1)*E D=eps*epsr*E printf("\nCharge stored on capacitor = %.3f *10^-11 C\nE=%.2f*10^3 V/m\...
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ut͡ʃeniki ut͡ʃenikilwiː N;NOM;PL;PSS1S dariː dariːliː N;PROL;SG dariː dariːləː N;TERM;SG pastuk pastuk N;NOM;SG kiŋgit kiŋgitŋiː N;NOM;SG kiŋgit kiŋgittuː N;DAT;SG kiŋgit kiŋgit N;NOM;SG haŋuːkt͡ʃa haŋuːkt͡ʃaďaran V;IPFV;FIN;IND;SG;3;PRS;ACT huktimət huktimət ADJ trofimi trofimi N;NOM;SG ďapkutal ďapkutalwaːγint͡ʃə N;A...
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//Variable Declaration: Q1 = 20.0 //Mass (lb) (part 1) MH = 1.008 //Molecular weight of H (lb/lbmol) MO = 15.999 //Molecular weight of O (lb/lbmol) Q2 = 454 //Gram in pound (part 2) Q3 = 6.023*10**23 //Avogadro nuber (part 3) //Calculatio...
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+---a---b---c---d---e---f---g---h---+ | | 8 . . . . . . . . 8 | | 7 -Q . . . . . -P . 7 | | 6 . . -P . . -R . . 6 | | 5 . . . ...
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clc clear //INPUT p1=8;//intial pressure in cm of hg p2=6;//final pressure in cm of hg v1=1000;//intial volume in cc v2=1190;//final volume in cc //CALCULATIONS y=log(p1/p2)/log(v2/v1);//coefficient of expansion //OUTPUT mprintf('the coefficent of expansion is %3.2f',y)
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clc; clear; //Example 5.15 //CASE I: Cp=4*10^3; //[J/kg.K] t1=295; //[K] t2=375; //[K] sp=1.1; //Specific gravity of liquid v1=1.75*10^-4; //Flow of liquid in [m^3/s] rho=sp*1000 //[kg/m^3] m_dot=v1*rho //[kg/s] Q=m_dot*Cp*(t2-t1) //...
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// Scilab Code Ex8.1: Page-171 (2010) L_0 = 1; // For simplicity, we assume classical length to be unity, m c = 1; // For simplicity assume speed of light to be unity, m/s L = (1-1/100)*L_0; // Relativistic length, m // Relativistic length contraction gives // L = L_0*sqrt(1-v^2/c^2), solving for v v = s...
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stacksize('max'); echo = read("echo", -1,3); echot = echo(:,1); echov = echo(:,2)+%i*echo(:,3); model = read("model", -1,3); modelt = model(:,1); modelv = model(:,2)+%i*model(:,3); clf; plot(abs(echov)); plot(abs(modelv),'r');
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//Ex6_13 clc ic = 4*10^-3 ib = 80*10^-6 disp("ib = "+string(ib)+"A")//base current disp("ic = "+string(ic)+"A")//collector current Ai = ic/ib disp("Ai = ic/ib = "+string(Ai))//current gain in CE amplifier
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//Variable Declaration R=6371 //Mean Earth's radius(km) e=0.0011501 //Eccentricity a=7192.3 //Semimajor axis(km) //Calculation ra=a*(1+e) //Radius Vector at apogee(km) rp=a*(1-e) //Radius Vector at perigee(km) ha=ra-R //Apogee height(km) hp=rp-R //Perigee height(km) //Result printf("The Apoge...
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## Copyright (C) 2008-2017 Jaroslav Hajek ## ## This file is part of Octave. ## ## Octave is free software; you can redistribute it and/or modify it ## under the terms of the GNU General Public License as published by ## the Free Software Foundation; either version 3 of the License, or (at ## your option) any later ver...
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//clc() //lnPas = 14.5463 - 2940.46/(T - 35.93) //lnPbs = 14.2724 - 2945.47 / (T - 49.15) //xa = (P - Pbs)/(Pas - Pbs) //Ya = Pas * (P - Pbs)/(P * (Pas - Pbs)) Ya = 0.4; P = 65;//kPa //various temperature value are assumed and tried till LHS = RHS, we get T = 334.15;//K Pas = exp(14.5463 - 2940.46/(T - 35.93))...
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//Chapter 30 Ex6 clc; clear; close; S={'E','X','T','R','A'}; sizeS=size(S,"c"); n=4; //since there are 3 vowels, they are considered as 1 letter reqLetters=n; //since all the letters are required noLetters=factorial(n)/factorial(n-reqLetters); reqVowels=2; //since vowels are required to be together noWays=...
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function [hdl]=visu(vecx,vecy,matz,xmin,xmax,ymin,ymax,zmin,zmax,option,coul,langage) hdl=[]; // // MATHFI Project, Inria Rocquencourt. // Jean-Marc Cognet, November 2002. // // -------------------------------------------------------------------- // Auteur : Jean-Marc Cognet // Date de derniere modification : 12/07/0...
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clear clc //Example 15.4 CALCULATING DISCHARGE AND MANNING’S n USING CHEZY EQUATION //To find Approx Value function [A]= approx (V,n) A= round(V*10^n)/10^n; //V-Value, n-to what place funcprot (0) endfunction g=32.2; //[ft/s^2] l=100; //width[ft] y=4.3; //depth[ft] A=l*y //area[ft^2] //Estimate Rh t...
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clc //initialisation of variables H= 2.5 //ft L= 10 //ft A= 10 //miles p= 30 //per cent a= 2 //in/hr w= 2 //ft //CALCULATIONS Q= L*1760^2*3^2*a*p/(60*60*12*100) n= ((Q/(3.33*H^1.5))-(L-0.1*w*H))/(L-0.1*w*H) //RESULTS printf ('n = %.f ',n)
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//chapter 36 //example3 clc //given L=5 //inductance in henry V=100 //emf in volts R=20 //resistance in ohms i=V/R disp(i,"Maximum current in amp is") U=(L*i^2)/2 disp(U,"Energy stored in the magnetic field in joules is")
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// Example 2.4 :current clc; close; clear; format('v',7) // given : vs1=72;//voltage in volts vs2=40;//voltage in volts R1=36;//resistance in ohms R2=10;//resistance in ohms ig=2;//current in amperes Rx=8;//resistance in ohms disp("Applying Thevenins Theorem ") //(vs1-voc)/R1+(v40-voc)/R2 +2 =0 node equation at 1 voc=(...
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liban lilibanan V;PFOC;LGSPEC1 isip inisip V;PFV;PFOC bagsak bagsak V;NFIN alaga' alaga' V;NFIN nakaw ninanakaw V;IPFV;PFOC maneho minamaneho V;IPFV;PFOC másid minamásdan V;IPFV;PFOC taguyod itataguyod V;PFOC;LGSPEC1 kuha' kukuhanin V;PFOC;LGSPEC1 basag nagbasag V;PFV;AGFOC hirap hirap V;NFIN babá' babá' V;NFIN panalo ...
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clc //initialisation of variables Lab= 2 //m Lbc= 0.5 //m Dab= 200 //mm Dbc= 100 //mm T= 50 //KNm G= 80000 //N/mm^2 //CALCULATIONS Jab= %pi*Dab^4/32 Jbc= %pi*Dbc^4/32 Tc= T/((Lbc*Jab)/(Lab*Jbc)+1) Ta= T-Tc if(Dab<Dbc) Dbc=Dab;Tc=Ta; else Dab=Dab;Tc=Tc end Stressmax= (Tc*10^6*Dbc*32)/(2*%pi*Dbc...
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clear // // // //Variable declaration a1=5.43*10^-8; //lattice constant(cm) M1=28.1; //atomic weight N=6.023*10^23; //avagadro number n1=8; //number of atoms a2=5.65*10^-8; //lattice constant(cm) M2=144.6; //atomic weight n2=4; //number of atoms //Calculations rho...
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// Lecture de l'image img = readpbm('A1.pbm'); //Attribution de la taille de l'image [colonne, ligne]=size(img) // Déclaration & initialisation d'une compteur pour déterminer // le nombre de coordonnées de zones d'atterrissage possibles. coordonnées=0 // Déclaration & initialisation d'un variable pour dét...
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clc; clear; D=0.82 //distance between the source and the screen in m B=0.02 //distance between the source and the biprism in m lambda=6900*10^-10 //wavelength in m myu=1.5 //refractive index alpha=%pi/180 //refracting angle in radian //calculation d=2*(myu-1)*alpha*B //distance between sources in m Beta=(lam...
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//To determine the current in each loop of the circuit. clc; M=[5.11 -0.71 0 -3.25;-0.71 1.86 -0.92 -0.23;0 -0.92 2.86 -1.12;-3.25 -0.23 -1.12 5.55] D=det(M) M_1=[1.5 -0.71 0 -3.25;-1.3 1.86 -0.92 -0.23;-7.1 -0.92 2.86 -1.12;-2.1 -0.23 -1.12 5.55] D_1=det(M_1) M_2=[5.11 1.5 0 -3.25;-0.71 -1.3 -0.92 -0.23;0 -7.1 2.86 -1...
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clc clear T=50; Vst=870; N=300; Pm=10; n=N/2; BP=(2*(22/7)*N*T)/(60*1000); IP=(Pm*100*Vst*(10^-6)*N)/(60*2); Em=BP/IP; printf('Mechanical Efficiency= %3.2f Percent',Em*100); printf('\n');
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1.000000 1.000000 0.0000000E+00 0.0000000E+00 0.0000000E+00 1.000000 0.0000000E+00 1.000000 16.00000 0.0000000E+00 1.032258 0.0000000E+00 2.615385 0.9135135 1.177778 0.8936170 1 1.000000 1.000000 1.000000 1.000000 ...
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clear; clc; funcprot(0); //given data H_eps = 150;//in m z = 2;//in m U2 = 35;//runner tip speed in m/s c3 = 10.5;//meridonal velocity of water in m/s c4 = 3.5;//velocity at exit in m/s delHN = 6.0;//in m delHR = 10.0;//in m delHDT = 1.0;//in m g = 9.81;//in m/s^2 Q = 20;//in m^3/s omega_sp = 0.8;//spec...
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//Graphical// //Example 7.7.01 //Determination of Variance of round-off noise //at the output of cascade realization //H1(Z) = 1/(1-(1/2)z-1) //H2(Z) = 1/(1-(1/4)z-1) //H(Z) = (2/(1-(1/2)z-1))-(1/(1-(1/4)z-1)) clear; clc; close; a1 = (1/2); //pole of first system in cascade connection a2 = (1/4); //ploe of s...
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//Section-1,Example-1,Page no.-AC.483 //To find the no. of diffusion stages required for enrichment clc; //separation factor ,s=(1.0014)^n //separation factor, s=(% of U^235 after treatment/% of U^235 before treatment) s=3.0/0.7 //2.3=(1.0014)^n n=1040 disp(n,'No. of diffusion stages required for enrichment') ...
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wta_result_chip21=csvRead('/home/ubuntu/RASP_Workspace/test_20161031_draper_lab_demo/data_calibration_iscas2016/MITE_ADC_Output_voltage_chip21.csv'); wta_result_chip11_30a=csvRead('/home/ubuntu/RASP_Workspace/test_20161031_draper_lab_demo/data_calibration_iscas2016/MITE_ADC_Output_voltage_chip11_30a.csv'); wta_result_c...
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clear; clc; close; disp("When the eigen values are complex, then the fixed point is either :") disp("1. Center, or") disp("2. Spiral.") function xd=linear524(t,x) xd(1)=0*x(1)+x(2); //x(dot); x(2) means y. xd(2)=-4*x(1)+0*x(2); //y(dot); x(1) means x.; endfunction bound=...
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//Initilization of variables w=10/16 //lb/ft a=80 //ft P=500 //lb //Calculations lhs=(P*2)/(w*a) d=sqrt(1/((((lhs^2)-1)*16)/(80^2))) //ft //Result clc printf('The sag in the cable is %fft',d)
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clc //variable initialization Php=100 //power in hp P=Php*735.5 //power in Watts Va1=440 //voltage in volts N1=1000 //speed in rpm N2=500 //speed in rpm Eb1=430//Given back EMF in volts Vrms=415 //RMS voltage in volts //solution Eb2=Eb1*(N2/N1) Ia1=P/Va1 Ra=10/Ia1 Ia2=0.85*Ia1 Va2=Eb2+Ia2*Ra//At 85% lo...
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clc; v=11000; // rated voltage of motor zs=1+10*%i; // per phase synchronous impedance ia=100; // armature current at unity power factor vt=v/sqrt(3); // per phase voltage Ef=sqrt((vt+ia*real(zs))^2+(ia*imag(zs))^2); // excitation EMF from phasor diagram al=atand(real(zs),imag(zs)); de=atand((ia*imag(zs))/(vt+ia...
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//Solved Example Ex2.30 page no 65 clear clc Vz=8.2 //V Rl=9 //kΩ iL=Vz/Rl //mA printf("iL = %0.3f A",iL) iZ=1 Vb=13.2 Rs=((Vb-Vz)/(iZ+iL)) printf("\n Rs = %0.3f ohm",Rs) Vb=11.7 iZ=((Vb-Vz)/Rs)-iL printf("\n iZ = %0.3f",iZ)
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[[5,5,0,-3],[3,0,5,5],[0,-3,5,5],[5,5,3,0]] * [a,b,c,d] = 277*a^3+750*a^2*b+750*a*b^2+223*b^3+360*a^2*c+450*a*b*c+360*b^2*c+360*a*c^2-90*b*c^2+277*c^3-90*a^2*d-450*a*b*d-90*b^2*d+450*a*c*d-450*b*c*d+750*c^2*d+360*a*d^2-90*b*d^2+750*c*d^2+223*d^3
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function [a,g] = lpc(x,varargin) // Linear prediction filter coefficients // // // Calling Sequence // [a,g] = lpc(x) // [a,g] = lpc(x,p) // // // Description // [a,g] = lpc(x,p) // Determines the coefficients of a pth order forward linear predictor // filter b...
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//Example 19.13 //Hyperbolic Differential Equations in 2D or 3D //Page no. 675 clc;clear;close; deff('y=f(x,y)','y=x*(2-x)*y*(2-y)') c2=3;k=0.4;h=0.4;c2=3;s2=0.5 for l=0:11 if l==0 then printf('\n t = %i\n\n i\t x\t|\tj -->\t',l) for i=0:5 printf(' %i\t',i) end printf('\n...