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errcatch(-1,"stop");mode(2);//ill condiioned linear systems //example 7.10 //page 277 ;; A=[1/2 1/3 1/4;1/5 1/6 1/7;1/8 1/9 1/10]//hilbert's matrix de_A=det(A); if de_A<1 then printf(' A is ill-conditioned') end exit();
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function z = f(vector_x) z = vector_x(1)*vector_x(1) -sin(vector_x(2)) + 1; endfunction function grad = del_f(vector_x) grad(1) = 2*vector_x(1); grad(2) = -cos(vector_x(2)); endfunctions function H = hessian(vector_x) H = [2 0;0 sin(vector_x(2))]; endfunction function dot = inner(vector_x) dot = ...
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errcatch(-1,"stop");mode(2); all; ; disp("To calculate the thermal efficiency,the units have to be consisitent. With hp=0.707 Btu/s=2545Btu/h, we have ETAth=Ps+Qe/Qin") ETA_th=(2512*0.707+1259*7)/(7*1750) printf(" Thus ETA_h= %0.3f",ETA_th) ETA_th=2512*0.707/(7*1750) printf("\n For the simple shaft power syste...
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//Optical Fiber communication by A selvarajan //example 9.2 //OS=Windows XP sp3 //Scilab version 5.5.1 clc; clear all; PASE=1e-3;//amplified spontaneous emission power in W Gdb=20;//optical amplifier gain in dB G=10^(Gdb/10);//optical amplifier gain in normal scale delta_newbynew=5e-6;//fractional bandwidth h...
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clc // Given that E = 900 // total relativistic energy of proton in Mev m = 1.63-27 // rest mass of proton in kg c = 3e8 // velocity of photon in meter/sec // Sample Problem 37 on page no. 11.32 printf("\n # PROBLEM 37 # \n") printf(" Standard formula used \n") printf(" E = m*c^2 \n ") m_ = (E * 1.6e-13) / (c)^2 print...
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clear; clc; f=5000/(2*%pi);R=196;C=.09*(10^-6);L=.71*(10^-3);G=0; //value of C as taken in solution w=2*%pi*f; Z=R+(%i*w*L); Y=G+(%i*w*C); Zo=sqrt(Z/Y); printf('-Characteristic impedance is Zo = %f /_%f ohms\n',fix(abs(Zo)),round(((atan(imag(Zo),real(Zo))*180/%pi))*10)/10); P=sqrt(Z*Y);F=fix(abs(P)*100)/100; ...
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clc t=1.25 //mm y=15.87 //mm z=5.28 //mm Iy=4765.62 //mm^4 Iz=21054.69 //mm^4 Iyz=3984.37 //mm^4 thetap=13.05 //degree Iy1=3828.12 //mm^4 Iz1=21953.12//mm^4 s=12.5 //tau=(Vy/Iz1*t)*s*t(19.55+s*asind(13.05)/2)....equation 1 //F1=integrate((tau*t)ds) x=integrate('(0)','s',0,1) //F1=0.0912*Vy1 ...
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clc // Given that x1 = 3 // intercepts cut by the plane along vector a of crystallographic axes in first case y1 = 3 // intercepts cut by the plane along vector b of crystallographic axes in first case z1 = 2 // intercepts cut by the plane along vector c of crystallographic axes in first case x2 = 1 // intercepts cut...
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//EXAMPLE 1-27 PG NO27 L1=50*10^-3; // Inductar L2=100*10^-3; //Inductar X=(L1/L2); disp('i) (L1/L2) = '+string (X)+' ') Q1+Q2=600; Q11=200; //flux Q22=400 //flux disp('ii) Flux Q11 = '+string (Q11)+' mWb'); disp('iii) Flux ...
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time_scale=1e-5; // Time unit : 10us clear data_02; data_02=read_tar_pgm_result('data'+info_name+'2.hex',m_graph,time_scale); clear data_03; data_03=read_tar_pgm_result('data'+info_name+'3.hex',m_graph,time_scale); clear data_04; data_04=read_tar_pgm_result('data'+info_name+'4.hex',m_graph,time_scale); clear data_05; d...
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//Chapter 03: Algorithms clc; clear; //Linear Search is also known as Sequential Search function []= linearsearch (a ,n , ie ) i =1; j =0; for i =1: n if ( arr(i) == ie ) printf ( "\nElement:%d found at position %d\n " ,ie , i ) ; j =1; end end if ( j ==0) disp ( "Element Not Found!") ; end endfunction arr =[1 2 3 5...
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;scrnx.tst - in test for lighting up default key mod ;SCRNX.DBL ;isam ; 3-9-04 - RE_PRICE_ROUTINE in test ; 1/15/03 installed - note that material multiplier not activated!! SUBROUTINE SCRNX ; ; 16-MAY-1997 SSQ: ADD QTY BREAK PRICING. ; 01-JUN-1998 SSQ: CHANGE "INCH" CHAR FROM "," TO "+" ; 11-Nov-1998 SSQ: ...
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// 14.10.10 // 14.12.14 for 3d // 15.01.03 changed ("start","end") // 15.10.24 in case of list-length==1 function Out=ReadOutData(varargin) global Fnameout if length(varargin)==0 then Fname=Rnameout; else Fname=varargin(1); end Fid=mopen(Fname,"rb"); Gstr=[]; Str=""; Flg=1; Tmp=mgetstr(1,Fid...
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//chapter 4 //broadside array //part a printf("\n"); n=8; m1=1; d=0.5; lamda=1; ph1=acos((m1*lamda)/(n*d)); m2=2; ph2=acos((m2*lamda)/(n*d)); m3=3; ph3=acos((m3*lamda)/(n*d)); printf("the direction of nulls are"); printf("\n%g %g %g radians",ph1,ph2,ph3);
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// Exa 5.21 format('v',6) clc; clear; close; // Given data k= 75*10^-3;//in mA/V^2 Vth= -0.8;// in V R2 = 100;// in k ohm R1 = 100;// in k ohm R_S= 6;// in kΩ R_D= 3;// in kΩ V_SS = 10;// in V V_G = (R2/(R1+R2))*V_SS;// in V I_D= poly(0,'I_D'); V_S= V_SS-I_D*R_S;// in V V_GS= V_G-V_S;//in V I_D= I_D-k...
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clear data_00;clear data_01;clear data_02; data_00 = [ // case 00 // Vin(V) Iout(A) R(ohm) 0.2 0.419E-06; 0.4 1.098E-06; 0.6 2.036E-06; 0.8 3.199E-06; 1.0 4.556E-06; 1.2 6.091E-06; 1.4 7.759E-06; 1.6 9.434E-06; 1.8 11.099E-06; 2.0 13.214E-06; 2.2 15.387E-06; 2.4 17.502E-06; ]; data_01 = [ // case 01 (indirect) // Vin...
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inf = float('inf') plant_pvt_init_data = None T = 720.0 delta_t = 0.5 # HybridConfig initialConfig(initialSet, 2, 0, 0); # Initial Mode initial_discrete_state = [2] # Interval init_Gp = init_Gs; # init_Gp.mul_assign(1.9152); # States # idx 0 1 2 3 4 5 6 7 ...
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clear; clc; //Example - 7.34 //Page number - 269 printf("Example - 7.34 and Page number - 269\n\n"); //Given T_1 = 0.01 +273.15;//[K] T_2 = 1 + 273.15;//[K] P_sat_1 = 0.611;//[kPa] - P_sat at temperature T_1 P_sat_2 = 0.657;//[kPa] - P_sat at temperature T_2 Mol_wt = 18.015;//[g/mol] - Molecular weight of water R = 8...
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// Exa 8.17 clc; clear; close; //given data C=0.1;// in nF C=C*10^-9;//in F V=5;//in V t=1;// in micro S t=t*10^-6;// in sec // v= V*(1-%e^(-t/(R*C))) // Since hold value does not drop by more than 0.5% or by 0.005 V, hold value is 0.995 V, Thus // 0.995*V= V*(1-%e^(-t/(R*C))) // or %e^(-t/(R*C))= 1-0.995...
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function [sum] = solve(n) rest = 0; sum = 0; while n <> 0 rest = modulo(n,10); n = (n - rest)/10; sum = sum + rest; end endfunction
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clc; //e.g 18.11 Rb=100*10**3; Vcc=10; Rc=2*10**3; beta1=50; Vbe=0.7; Ib=(Vcc-Vbe)/(Rb+(beta1*Rc)); disp('mA',Ib*10**3,"Ib="); Ic=beta1*Ib; disp('mA',Ic*10**3,"Ic="); Ie=Ic; disp('mA',Ie*10**3,"Ie=");
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//Caption:Find the reading on the scale //Exa:6.8 clc; clear; close; P_o=5*746;//power output (in Watts) N_m=1200;//speed of motor (in rpm) L=0.4;//arm length (in meter) w_m=(2*%pi*N_m)/60; T_s=P_o/w_m; F=T_s/L;//force reading on the scale (in Newton) disp(F/9.81,'Reading on the scale (in Kg)=');
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ModuleName="findallpeaks"; Version="0.01"; DateModified="13-Feb-2015"; DateOfCreation="13-Feb-2015"; Author="Rob Eccleston"; Description="Find peaks in a vector of values, returns two arrays of peaks and troughs."; mprintf("Loading " + ModuleName + " V" + Version + ", Last Modified: " + DateModified + "\n") ...
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//Chapter 25 Ex 6 clc; clear; close; ExtVol=50*40*23; //given IntVol=44*34*20; //given Metal_vol=ExtVol-IntVol; Weight=(Metal_vol*0.5)/1000; printf("Weight of box is %2.2f kg",Weight);
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s=%s; F=(s^2+3)/((s^2+2*s+5)*(s+2)); syms t s; y=ilaplace(F,s,t); disp(y,"f(t)=")
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EX20_3.sce
clc;funcprot(0);//EXAMPLE 20.3 // Initialisation of Variables p1=1;......//Suction pressure in bar t1=293;.....//Suction temperature in K n=1.2;......//Compression index p2=10;......//Delivery pressure in bar R=0.287;....//Gas constant in kJ/kgK cv=0.718;...//Specific heat at constant volume in kJ/kgK //Calcula...
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clc T=300//K M=3.64//Armstrong Nx=(7.54*10^14)//cm^-2 P1=1//Pa t1=(Nx*sqrt(M*T))/(2.64*10^20*P1) disp(t1,"t1 at 1Pa in ms is= ") //textbook ans is wrong P2=10^-4//Pa t2=(Nx*sqrt(M*T))/(2.64*10^20*P2) disp(t2,"t2 at 10^-4Pa in s is= ") //textbook ans is wrong P3=10^-8//Pa t3=(Nx*sqrt(M*T))/(2.64*10^20...
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2_48.sci
// 2.48 clc; g=0.055; t=1.5*10^-3; Eo=100; P= Eo/(g*t); A=25*10^-6; F=P*A; printf("\n Force=%.0f N",F)
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Exa2_29.sce
//Exa2.29 clc; clear; close; //given data //Take iron as metal A and copper as metal B with respect to lead //For metal A: p_A=16.2; q_A=-0.02; //For metal B: p_B=2.78; q_B=+0.009; p_AB=p_A-p_B; q_AB=q_A-q_B; T2=210;//in degree C T1=10;// in degree C E=p_AB*(T2-T1)+q_AB/2*(T2^2-T1^2); disp("Thermo-elec...
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20_4.sce
clc; // page no 759 // prob no 20.4 //A satellite transmitter operates at 4GHz with 7W & antenna gain 40dBi //Receiver antenna gain 30dBi & path length is 4*10^7 Gt_dBi=40;Gr_dBi=30;Pt=7;d=40000;//in km f=4000;//in MHz Pr_Pt_dB=Gt_dBi+Gr_dBi-(32.44+(20*log10(d))+(20*log10(f))); //Signal strength at transmitter ...
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Example9_3.sce
close(); clear; clc; Vgsq = 6.9; //V //from drain characterstics of Fig 9.9(b), Vt = 4; //V Id_on = 5; //mA Vgs_on = 8; //V Idq = Id_on*(1-Vgsq/Vt)^2; //mA mprintf("Idq = %0.2f mA",Idq);
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clc p1=8*10^5; // N/m^2 p2=5*10^5; // N/m^2 f=0.006; l=145; // m m=0.32; // kg/s R=287; // J/kg.K T=288; // K y=1.4; d=(4*f*l*m^2*R*T/(%pi/4)^2/(p1^2-p2^2))^(1/5); disp("(a) Diameter of pipe =") disp(d) disp("m") rho=p1/R/T; A=%pi/4*d^2; u=m/rho/A; a=sqrt(y*R*T); M1=u/a; M2=p1/p2*M1; disp...
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dbt air rockets.sce
Name=dbt air rockets PlayerCharacters=QC no movement BotCharacters=target_decay_midair.bot IsChallenge=true Timelimit=60.0 PlayerProfile=QC no movement AddedBots=target_decay_midair.bot PlayerMaxLives=0 BotMaxLives=100 PlayerTeam=1 BotTeams=2 MapName=boxernobounds.map MapScale=3.5 BlockProjectilePredictors=false BlockC...
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//given //find the area of piston and displacement of that piston a=3. b=4. A=0.785*3**2 printf("\n area of piston %.2f ",A) D=A*b //by using above results printf("\n displacement of piston %.2f cu in",D)
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// Test #10 : For complex vector inputs exec('./zpklp2hp.sci',-1); [z,p,k,n,d]=zpklp2hp([2*%i,0.4*%i],[%i,3*%i],1,0.2,0.7); disp(d); disp(n); disp(k); disp(p); disp(z); // //Scilab Output //d=1. - 0.2212317 //n=0.2212317 - 1. //k=0.2830084 + 0.0950556i //p=0.4218182 + 0.9066804i // 0.2444835 + 0.3153042i ...
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sinus.sci
function [y]=sinus(f0,Fe,d) // f0 -> hauteur frequence d-> durée Te=1/Fe; // temps echantillonage x=[0:Te:d]; //axe temps y=[0:Te:d]; // amplitude constante au cours du temps n=length(y); for i=1:n y(i)= sin(2*3.14159*f0*x(i)); end endfunction
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clc clear D1=0.3; D2=0.2; C=3; L1=[(22/7)*(1/2)*(D1+D2)]+[((D1+D2)^2)/(4*C)]+(2*C); L2=[(22/7)*(1/2)*(D1+D2)]+[((D1-D2)^2)/(4*C)]+(2*C); L=L2-L1; printf('The belt length is to be reduced by %2.4f mm',(0-L)*1000); printf('\n');
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//Exa 6.2 clc; clear; close; //Part (a): Given data : disp("Part (a) : At the center frequency with a circumference of lambda, the directivity of an axial mode helix is, : D=12*n*Slambda"); n=20;//no. of turns Slambda=0.472;//in meter D=12*n*Slambda;//in meter disp("Ae=(lambda^2/(4*%pi))*D"); disp("Ae="+strin...
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function[dstMat] = imimposemin(maskImg, markerImg) out = opencv_imimposemin(maskImg, markerImg) channel = size(out) for i = 1: channel dstMat(:,:,i) = out(i) end endfunction
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// // r1=2.550 r2=2.500 s=r1-r2 d=0.002 D=100 n=5 r=(n*d*D/s) printf("\n R= %0.3f ",r) alp=(s/(n*D))*206265 printf("\n sensitiveness of bubble is %0.3f seconds',alp)
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// problem 10.13 Q=0.125 Hm=25 N=660/60 d2=0.6 d1=d2*0.5 a=0.06 y2=45 g=9.81 u2=3.142*d2*N u1=u2*0.5 Vf2=Q/a Vw2=u2-(Vf2/tand(y2)) n=g*Hm/(Vw2*u2) Vf1=Q/(a) y1=atand(Vf1/u1) disp(y1,n*100,"manometric efficiency,vane angle at inlet")
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function [MSim,VSim,MSSim,VSSim] = gl_stat_simu(S,N,maxp,Tr,b,bu,c,Nu_Ma,Nu_I,Nu_A,st_j,rt_a) // Ouput variables initialisation (not found in input variables) MSim=[]; VSim=[]; MSSim=[]; VSSim=[]; // Display mode mode(-1); // Display warning for floating point exception //ieee(1); //this function is to find mean a...
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clear// //Variables n = 5.8 * 10**28 //number of free electrons (in per cubic-meter) p = 1.54 * 10**-8 //resistivity (in ohm-meter) q = 1.6 * 10**-19 //charge (in Coulomb) m = 9.1 * 10**-31 //mass of electron (in kg) //Calculation sig = 1/p...
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r=100; c=1000*10^(-6); vm=9; vr=0.8; disp("Part a"); vrms=vr/(2*sqrt(3)); disp("the r.m.s. value of the ripple voltage (in V) is"); disp(vrms); disp("Part b"); vdc=vm-vr/2; disp("the dc output voltage (in V) is"); disp(vdc); disp("Part c"); rip=vrms/vdc; disp("the ripple factor is"); disp(rip);
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[Read-the-docs-example-10] # Read the docs - example 10 user_indice: {'indice_name': 'my_indice', 'calc_operation': 'nb_events', 'calc_operation': 'max_nb_consecutive_events', 'logical_operation': 'gt', 'thresh': 'p85', 'var_type': 'p'} in_files: ['pr_day_CNRM-CM5_historical_r1i1p1_19700101-19741231.nc','pr_day_CNRM-CM...
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//ques-25.21 //Calculating pressure using van der Waals equation clc n=2;//moles of ammonia T=300;//temperature (in K) V=5*10^-3;//volume (in kL) a=0.417;//(in N M^4/mol^2) b=0.037*10^-3;//(in m^3/mol) P=(n*8.314*T)/(V-n*b)-(a*n^2)/V^2; printf("The pressure required is %.1f N/m^2.",P);
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#************************************************************ # Scenario of lydia # # date : Tue Jul 28 11:26:38 2009 #************************************************************ p3d_sel_desc_name P3D_ENV lydia p3d_sel_desc_name P3D_ROBOT lydia2.robot p3d_set_robot_steering_method Linear p3d_set_robot_current 0....
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//Exa 5.4 clc; clear; close; //given data rho=985;// in kg/m^3 k=.654;// in W/mK Cp=4.18;// in kgJ/kgK Cp=Cp*10^3;// in J/kgK v= 0.517*10^-6;// in m^2/s Pr=3.26; V=1.2;// in m/s t_s=85;// in degree C t_i=40;// in degree C t_o=70;// in degree C Ax=15*35;// in mm P=15+35; de=4*Ax/(2*P);// in mm de=de*10...
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function [x,y,typ]=LOOKUP_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; graphics=arg1(2...
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clear all; clc; disp("Scilab Code Ex 5.15 : ") //Given: l_cd = 0.5; //m l_de = 1.5; //m h =60/1000; //m w = 40/1000; //m t_h = 3/1000; //m t_w = 5/1000; //m T_c = 60; //Nm T_d = 25; //Nm G = 38*10^9; //N/m^2 T1 = T_c - T_d; //Average Shear Stress: area = (w-t_w)*(h-t_h); shear_a = T1/(2*t_w*area*...
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////Ex 2.9 clc; clear; close; format('v',5); Beta=110;//unitless VBE=0.7;//V VT=26;//mV VCC=10;//V VEE=10;//V RC=1.8;//kohm R=3.9;//kohm IExt=(VCC-VBE-(-VEE))/R;//mA IT=IExt;;//mA ICQ=IT/2;//mA V1=0;V2=0;//V VE=-2*VBE;//V VC=VCC-ICQ*RC;//V VCEQ=VC-VE;//V Q=[ICQ VCEQ];//[mA V](Q point) disp(Q,"Q poin...
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//fiber optic communications by joseph c. palais //example 7.6 //OS=Windows XP sp3 //Scilab version 5.4.1 clc; clear all; //given Wg1=1.1//band gap energy of silicon pin diode in eV Wg2=0.67//band gap energy of germanium pin diode in eV //to find lambda_c1=1.24/Wg1//wavelength in um lambda_c2=1.24/Wg2//wavel...
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clc //initialisation of variables BeamL= 60 //mm BeamB= 100 //mm Load= 60000 //N Stress= 150 //N/mm^2 //CALCULATIONS sigmax= Load/(BeamL*BeamB) stressmax1= sqrt((Stress/2)^2-(sigmax^2/4)) Sy1= (2*stressmax1*BeamL*BeamB)/3 stressmax2= sqrt((Stress^2-(sigmax^2/4))/3-(sigmax^2/4)) Sy2= (2*stressmax2*BeamL*Beam...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Teradata -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. ...
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clc,clear printf('Example 2.11\n\n') V=220 I_1=50, I_a1=I_1 //Currents before adding extra resistance T_2_by_T_1 =0.5 R_t=0.15 //R_e + R_se =0.15 I_a2 =I_a1 * sqrt(T_2_by_T_1) //Because T (prop.) I_a^2 E_b1=V-I_a1*(R_t) //induced emf before adding extra resistance N_1=500,N_2=300 //speeds before and addin...
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//Example 7.5 //Inverse of Complex Matrices //Page no. 262 clc;clear;close; A=[1,-1,0;2,3,4;0,1,2]; B=[1,1,3;1,3,-3;-2,-4,-4]; P=A+%i*B; disp(P,'Matrix P=') disp(A,'Matrix A=');disp(B,'Matrix B='); A1=inv(A);B1=inv(B); disp(A1,'Inverse of Matrix A='); disp(B1,'Inverse of Matrix B='); B1A=B1*A;disp(B1A,'In...
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//// //Variable Declaration n = 1.0 //Number of moles of CO2 T = 300.0 //Temeperatures of Water bath, K vi = 25.0 //Initial and final state Volume of Ideal Gas, L vf = 10.0 R = 8.314 //Ideal Gas Constant, J/(mol.K) //Calcualtions qrev = n*R*T*log(vf/vi) w = -qrev...
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clear // // // //Variable declaration rho=10**10 //resistivity(ohm m) d=10**-3 //thickness(m) A=10**4*10**-6 //area(m**2) V=10**3 //voltage(V) f=50 //power frequency(Hz) epsilonr=8 epsilon0=8.84*10**-12 tan_delta=0.1 //Calculation Rv=rho*d/A dl_DC=V**2/Rv //DC dielectric loss(watt) C=A*epsilon0*e...
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clc(); clear; // To calculate the temperature of surface and centre plane t=2; // Thickness of wall in ft To=100; // Initial temperature of wall in degF Tg=1000; // Temperature of hot gases exposed in degF k=8; ...
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function [filtre, coef, nom] = creerFiltreConique() filtre = [0 0 1 0 0; 0 2 2 2 0; 1 2 5 2 1; 0 2 2 2 0; 0 0 1 0 0]; coef = 25; nom = 'Conique'; endfunction
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d=0:0.1:10; k=50; P_r=2000; P_t=100; m=0.01; x=log(d); y=(k-m*log(d)); plot(x,y); xlabel("Distance"); ylabel("Pathloss Constant"); title("Pathloss");
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pathname=get_absolute_file_path('12_1.sce') filename=pathname+filesep()+'12_1data.sci' exec(filename) clear Ar=(%pi*d^2)/4; b=((2*Ar*Ls)/(t*Lt))+d; printf("\nb: %f",b);
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clc; p=200; //power in Watt v=12; //voltage in volt i=p/v; //calculating current in Ampere I=p/6; //calculating disp(i,"Current in Ampere = "); //displaying disp(I,"Current in Ampere if voltage were 6V = "); //displaying result
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clc //initialisation of variables t=30//deg y=9802//N/m^3 sg=0.78 r=6*10^-2//m //CALCULATIONS P=(1/2)*y*sg*r//Pa //RESULTS printf('The pressure is=% f Pa',P)
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//Chapter-1, Example 1.32, Page 45 //============================================================================= clc; clear; //INPUT DATA V=24;//supply voltage of battery in volts Rab=13;//resistance between A and B points in ohms Rbc=11;//resistance between B and C points in ohms Rbe=18;//resistance between ...
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clc // initialization of variables clear Y=345 //MPa S_u=586 //MPa d=20 //mm R=800 //mm //part (a) SF=1.8 N=1e+07 S_am=290 //MPa // P_max not yet known. take it as unity until an equation to be solved is encountered P_max=1 c=d/2 M=SF/2*P_max*R //M=T I=%pi*c^4/4 Sigma=M*c/I J=%pi*c^4/2 tau=M*c/J S_ma...
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clear // // // //Variable declaration chi=-0.25*10**-5 //magnetic susceptibility H=1000 //magnetic field intensity(amp/m) mew0=4*%pi*10**-7 //Calculation M=chi*H //magnetisation(A/m) B=mew0*(H+M) //magnetic flux density(wb/m**2) //Result
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function ans = derivadadistancia(x) numerador = -3 - x + 2*x^3 denominador = sqrt(10 - 6*x - x*x + x*x*x*x) ans = numerador/denominador endfunction
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//Exa 2.31 clc; clear; close; format('v',8); //Given Data : p1=1;//bar T1=20+273;//K p2=6;//bar m=1;//Kg R=287;//Nm/Kg Gamma=1.4; Cp=1.005;//KJ/KgK Cv=0.7175;//KJ/KgK //T2=T1 : Isothermal compression T2subT1=0; deltaU=m*Cv*(T2subT1);//KJ disp("Isothermal :"); disp(deltaU,"Change in internal energy ...
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// 06 Nov / 2018 // Cyclohexane-Toluene *** Cinetica_2_Replica *** clear mclose('all') //<< El archivo fun_read.sce contiene las herramientas necesarias para extraer //los valores de spoffs0 como los respectivos espectros procesados a partir de //Topspin >> exec("/Users/christianpantoja/Documents/new_processing...
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clc;clear; //Example 5.12 //given data Wo=4.8;//work function in eV W=2220;//wavelength in angstrom //calculations E=12400/W; Emax=E-Wo; disp(Emax,'The maximum Kinetic energy in eV is')
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// Grob's Basic Electronics 11e // Chapter No. 27 // Example No. 27_10 clc; clear; // Calculate the maximum rated zener current for a 1 W, 10 V zener. // Given data Pzm = 1; // Power rating of zener= 1 Watts Vz = 10; // Voltage rating of zener= 10 Volts Izm = Pzm/Vz; disp (Izm,'The Maximum ...
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h1 = 3465; h2s = 3065; h3 = 3565; h4s = 2300; x4s = 0.88; h5 = 191.83; v = 0.001; P = 150; // in bar Wp = v*P*100; h6s = 206.83; Q1 = (h1-h6s)+(h3-h2s); Wt = (h1-h2s)+(h3-h4s); Wnet = Wt-Wp; n_cycle = 100*Wnet/Q1; sr = 3600/Wnet; disp(0.88,"Quality at turbine exhaust is") disp("%",n_cycle,"Cycle efficiency ...
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//EXAMPLE 2-11 PG NO-66 W=314.16; PV=14.14; //PEAK VALUE t=0.0025; //TIME i=PV*sin(W*t); //CURRENT T=0.0175; //TOTAL TIME I=PV*sin(W*T); disp('ii) CURRNT (i) is = '+string (i) +' '); disp('ii) CURRNT (I) is = '+string (I) +...
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//Example 4.11 clc; clear; close; format('v',9); //Given data : S1=1.9;//sp. gravity S2=1.2;//sp. gravity S3=0.79;//sp. gravity h2=545/1000;//m h1=750/1000;//m h3=h1-h2;//m w=1000*9.81;//N/m^3 pAB=(h1*S1-h2*S2-h3*S3)*w;//N/m^2 disp(pAB,"Pressure difference between the two vessel in N/m^2: ");
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//developed in windows XP operating system //platform Scilab 5.4.1 clc;clear all; //example 6.5 //calculation circuit inductance and dynamic resistance //given data C=8*10^-6//value of capacitor (in farad) Ip=10//output peak current(in kA) t1=8*10^-6//time to front(in second) t2=20*10^-6//time to first half ...
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function [result] = trim(str) // Ouput variables initialisation (not found in input variables) result=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); //Trim trailing blanks from str i = max(size(mtlb_double(str))); while mtlb_isspace(mtlb_e(str,i)) i = i-1; end; result = mtl...
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function [featureVector] = extractHOGFeatuers(I, varargin) img = mattolist(I); [lhs rhs] = argn(0); if rhs<1 then error(msprintf("Not enough input arguments")); end if rhs>9 then error(msprintf("Too many input arguments")); end l = rhs-1; if(l==0) then featureVector = opencv_extractHOGFeatures(img); els...
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//Optoelectronics and Fiber Optics Communication by C.R. Sarkar and D.C. Sarkar //Example 7.3 //OS = Windows 7 //Scilab version 5.5.2 clc; clear; //given Df=80*10^-6;// diameter of the fiber in m Ds=45*10^-6;// diameter of the source in m NA=0.15;// numerical aperture of the fiber Mmax=(Df/Ds);// maximum...
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function B=tridiaganal(n) B=zeros(n,n); for i=1:n, B(i,i)=3 end for i=2:n, B(i,i-1)=1 end for i=1:n-1, B(i,i+1)=1 end endfunction
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clear clc //initialisation of variables m= 60/26 i= 1/2000 h1= 3 //ft h2= 5 //ft m1= 10/3 C= 90 l= 500 //ft H= 20 //ft H1= 29.62 //ft g= 32.2 //ft/s^2 //CALCULATIONS v= 90*sqrt(m*i) v1= v*h1/h2 dh= (i-(v1^2/(C^2*m1)))*l/(1-v1^2/(g*h2)) h3= h2-dh V= h1*v/h3 //RESULTS printf ('Height of water 1000 ft ...
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// Ex 72 Page 411 clc;clear;close; // Given R=200;//ohm L=2;//H C=5*10**-6;//F if R<2*sqrt(L/C) then printf("Since R<2sqrt(L/C), the circuit is originally oscillatory.") end a=R/(2*L) omega = sqrt(1/L/C-R^2/4/L^2);//rad/s //i=Im*%e**(-a*t)*sin(omega*t+fi) //at t=0 sec i0=0;//A vc=10;//V fi=asin(i0);//degree //L*di...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 16.7 //calculation of the tunning frequency of fork B //given data nu1=384//tunning frequency(in Hz) of fork A n=6//number of beats t=2//time(in s) taken by the beats //calculation deltanu=n/t//frequency of beats...
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x1=input("informe a primeira nota: "); x2=input("informe a segunda nota: "); x3=input("informe a terceira nota: "); x3=(x1+x2+x3)/3; if x3>=7 then mprintf("ALUNO APROVADO"); else mprintf("ALUNO REPROVADO"); end
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//Obtain path of solution file path = get_absolute_file_path('solution4_8.sce') //Obtain path of data file datapath = path + filesep() + 'data4_8.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the permissible tensile stress for the link sigmat (N/mm2) sigmat = Sut/fs //Assume the va...
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//too many o/p args f = ['a' 'b' 'c']; a = [1 0]; dev = [0.01 0.1]; fs = 8000; [n,fo,ao,w,s] = firpmord(f,a,dev,fs,'d'); //output //!--error 59 //Wrong number of output arguments.
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test for add
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pam.sce
t=(0:0.01:5*%pi)'; - - tc=(2*%pi)/10; - - fc=1/tc; - - tl=t/20; - u=cos(2*%pi*fc*tl); - ta=8*t; - k=(squarewave(ta)+1)*(1/2); - y=k.*u; plot(t,y)
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//Caption:Find (a) Power factor on no load (b) active current (c) magnetising current (d) copper loss in the primary winding (e) core loss //Exa:1.2 clc; clear; close; V_1=3300//Primary voltage (in volt) V_2=240//Secondary voltage (in volt) I_0=2//No load current (in A) P=60//Power (in watt) R=0.8//Resistance ...
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P1 = 700e03; T1 = 273+260; T3 = T1; V1 = 0.028; V2 = 0.084; R = 0.287; m = (P1*V1)/(R*T1); P2 = P1; T2 = T1*((P2*V2)/(P1*V1)); n = 1.5; P3 = P2*((T3/T2)^(n/(n-1))); cp = 1.005; cv = 0.718; Q12 = m*cp*(T2-T1); Q23 = m*cv*(T3-T2) + (m*R*(T2-T3))/(n-1); Q31 = m*R*T1*log(P3/P1); Q1 = Q12; Q2 = -(Q23+Q31); e ...
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// File name: projects/00/Not16.tst load Not16.hdl, output-file Not16.out, compare-to Not16.cmp, output-list in%X1.6.1 out%X1.6.1; set in 0, eval, output; set in 1, eval, output; set in -1, eval, output; set in %Xff0f, eval, output;
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//example 2.10 //page 75 clc; funcprot(0); //initialisation of variable ybar=4; pi=3.14; A=4; Gamma=62.4; Ig=4^3/12; x1=2; x2=1.7; hbar=ybar+Ig/A/ybar; Fv1=2*A*Gamma; Fv2=pi*A*Gamma; Fv=Fv1+Fv2; disp(Fv,"vertical component of Hydrostatic force(lbs)="); xv=(Fv1*x1+Fv2*x2)/(Fv1+Fv2); disp(xv,"point of ap...
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//Fluid Systems- By Shiv Kumar //Chapter 5- Francis Turbine //Example 5.8 //Theoritical Problem .
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clc //initialisation of variables I= 1.5 //in^4 Da= 0.5 //in E= 30*10^6 l= 60 //in //CALCULATIONS F= 6*Da*E*I/(l^3) //RESULTS printf ('F= %.2f lb',F)
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clear //Given P=60 //W Ev=100.0 //V Ev1=220 //v f=50 //Hz //Calculation Iv=P/Ev Vr=Ev1-Ev R=Vr/Iv Vl=sqrt(Ev1**2-Ev**2) Xl=Vl/Iv L=Xl/(2*%pi*f) //Result printf("\n (i) The value of non inductive resistance is %0.3f ohm", R) print...
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// Example 8.2 // Determine (a) The minimum value of excitation that will maintain // synchronism (b) Repeat (a) using eq.(8.16) (c) Repeat (a) using eq.(8.21) // (d) Power angle if the field excitation voltage is increased to 175% of the // stability limit determined in (c) // Page No. 322 clc; clear; close...