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//Find Band gap energy //Ex:15.16 clc; clear; close; c=2.99*10^8;//speed of light in m/s h=6.62*10^-24;//planck's constant w=1.771*10^-6;//wavelength in J eg=h*c/w;//in J disp(eg,"Band gap energy (in J) = ");
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//resistance of a current wire varies as length varies also, varies inversly as the cross section of wire clear clc close //R=the resistance //l=the length //the cross section mprintf("\n R=k*l/A \n ")
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clc; clear; p1=1/2; p2=1/4; p3=1/8; p4=1/16; p5=1/16;// probabilities H=p1*log2(1/p1)+p2*log2(1/p2)+p3*log2(1/p3)+p4*log2(1/p4)+p5*log2(1/p5); Bw=4000; //Bandwidth in Hz R=2*H*Bw ; disp(R,"Rate of the source ( in bits/s) is");
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/////////Chapter 10 Properties Of Steam ///Example 10.6 Page No:186 ///Find Enthalpy of superheated steam ///Input data clc; clear; IT=25; //Initial temperature m=5; //Heat required to generate steam in kg pf=10; //Final pressure in bar tsup=250; //Water t...
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// Example 5.8 : Analyse the circuit to find node voltages and branch currents V_CC= 10; // (V) R_C=2000; // (ohm) V_BB=5; // (V) R_B=100*10^3; // (ohm) B=100; // beta value I_B=(V_BB-V_BE)/R_B; disp(I_B,"Base current (A)") I_C=B*I_B; disp(I_C,"Collector current (A)") V_C=V_CC-I_C*R_C; disp(V_C,"Collector vo...
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<gedcom><INDI id="@I1@"><NAME>Jamis Gordon /Buck/<SURN>Buck</SURN><GIVN>Jamis Gordon</GIVN></NAME><SEX>M</SEX></INDI><INDI id="@I1@"><NAME>Jamis Gordon /Buck/<SURN>Buck</SURN><GIVN>Jamis Gordon</GIVN></NAME><SEX>M</SEX></INDI></gedcom>
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//Exa 7.3 clc; clear; close; //given data epsilon=0.5; T1=1200;// in K T2=300;// in K //(a) Heat transfer rate between the two plates is // Formula Fg12=1/((1/epsilon1+(1/epsilon2-1)*A1/A2)) epsilon1=epsilon; epsilon2=epsilon; A1byA2=1; Fg12=1/(1/epsilon1+(1/epsilon2-1)*A1byA2); // Formula q12= sigma*A*F...
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// dokumentacja mówi żeby to wstawić w skryptach, gdzie używa się rand() rand('seed',getdate('s')); function z = manhattan_distance(a, b) z = sum(abs(a - b)); endfunction // funkcja wybierająca n losowych liczb z wektora a bez zwracania function z = choose_random_numbers(a, n) z = [] if n <= length(a)...
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function[a1]=selection(a,n) i=n; while(i>=1) large=a(1); indx=1; for j=1:i if(a(j)>large) large=a(j); indx=j; end end a(indx)=a(i); a(i)=large; i=i-1; end a1=a; disp(a1,"Sorted array is:"); endfunction //Calling Routine: a=[23 21 232 1...
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// Grob's Basic Electronics 11e // Chapter No. 30 // Example No. 30_10 clear; clc; // Calculate the value of Rd to provide an Id(on) of 10m Amps. // Given Data Vdd = 15; // Suppy Voltage(Drain)=15 Volts Vgson = 10; // Voltage Gate-Source(on)=10 Volts Idon = 10*10^-3; // Drain Current(on...
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// Exa 5.30 clc; clear; close; format('v',6) // Given data L = 150;// in µH L = L * 10^-6;// in H // f = 1/(2*%pi*sqrt(L*C)) or C = 1/(4*%pi^2*f^2*L) //For f= 500 kHz f1 = 500;// in kHz f1 = f1 * 10^3;// in Hz C1 = 1/(4*%pi^2*f1^2*L);// in F //For f= 1500 kHz f2 = 1500;// in kHz f2 = f2 * 10^3;// in Hz ...
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//Eg-11.2 //pg-472 // To find the work done pressure is to be integrated with respect to volume which is compressed from 20 to 5 litres at 300k // i.e integrating the function [RT/(V-b)-a/V^2] from 20 to 5. Here we take 500 intervals between the given limits 20 and 5. // b and a represent the upper and lower l...
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//chapter 6 example 5// clc clear //absorption coeffcient=a,refractive index=n1,reflection coeffcient=Rf,fraction of the incident power absorbed=K,distance=d// n1=3.5; d=3*(10^-6); a=10^5; W=3*(10^-6); Rf=((n1-1)^2)/((n1+1)^2); K=exp(-a*d)*(1-(exp(-a*W)))*(1-Rf); printf("\n fraction of incident power absorbed...
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//chapter 10 Ex 10 clc; clear; close; Diff=21; per=65/100 num=Diff/(4/5-per); printf("The number is %1.0f.",num);
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clc //initialisation of variables R= 8.31*10^7 //ergs mole^-1 T= 27 //C M= 28 //gram per mole //CALCULATIONS c= sqrt(3*R*(273+T)/M) //RESULTS printf (' root-mean-square velocity = %.2e cm per sec',c)
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clear clf r = 1 ; A = 0.8 ; I=0.05 ; // variables du modèles Kvect=1.5:0.1:2.5; // variable qui varie x = linspace(0, 2.2, 301); // vecteur contenant les valeurs de la vitesse d'accroissement function f = allee_imig(x) // fonction qui calcule la vitesse d'accroissement f = r * x .* (x / A - 1 ) .* (1 - x / K)+ I ...
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clear mode(-1) clc disp("Example 6 : Display all the files in the current directory and files beginning with ->Ex<-") printf("\n*******************************************************************\n") disp('Answer : ') halt('Press [Enter] to continue') disp('Files in the current directory ') mode(0) ls ...
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//Exercício1-Bruna de Sousa Silva //Exercícios 1º lauda mkdir("file") chdir("file") A=ones(2,2) disp(A) save('teste.dat','A') clear("A") load('teste.dat','A') removedir("file") //Lauda 2 //Exercícios 2º lauda i=sqrt(-1) Z1=3+5*i Z2=7+3*i disp(Z1+Z2) disp(Z1*Z2) disp(Z1+sqrt(-20)) Z1=sqrt((3^2)+(5^2)) Z2=sqrt((7^2)+(...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 19.3w //calculation of the position of the image ,linear magnification and the angular magnification //given data u=-3.6*10^-2//object distance(in m) f=4*10^-2//focal length(in m) D=25*10^-2//least distance for clea...
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java -ea make.Main -f make-tests/omega02.mk -D make-tests/preomega02 stew
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//Section-6,Example-1,Page no.-P.38 //To find the change in chemical potential of the substance in the given condition. clc; R=8.314 T=298 P=0.5 P_0=1 mu_1=R*T*log(P/P_0) //mu_1=mu-mu_0 disp(mu_1,'Change in chemical potential of the substance(J/mol)')
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clc clear disp('example14.9') c=4000 //capacity of system f=50 //frequency //operatingload=rated area capacity h=5 //time constent r=0.025 // dl=0.01 //change in load df=0.01 //change in frequency rr=r*f // d=(dl*c)/(df*f) dpu=d/c kp=1/dpu tp=(kp)*(2*h/f) tt=(rr+kp)/(rr*tp) sfe=(kp*rr*dpu)/(rr+kp) ...
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// Spectral factorization, as discussed in Example 13.3 on page 467. // 13.1 exec('spec1.sci',-1); exec('flip.sci',-1); exec('polmul.sci',-1); exec('polsize.sci',-1); exec('poladd.sci',-1); A = convol([-0.5 1],[-0.9 1]); dA = 2; B = 0.5*[-0.9 1]; dB = 1; rho = 1; [r,beta1,sigma] = spec1(A,dA,B,dB,rho)
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$thermo = VirtualMaterials.NRTL/Ideal/HC . -> $thermo /thermo + 1,2-PROPYLENE_OXIDE METHANOL WATER 1,2-PROPYLENE_GLYCOL SULFURIC_ACID mycstr = KineticReactor.CSTR() mycstr.NumberRxn = 1 /mycstr.Rxn0.Formula = theRxn:1.0*'1,2-PROPYLENE GLYCOL'-1.0*!'1,2-PROPYLENE OXIDE'-1.0*WATER /mycstr.CustomEquationUnitSet...
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load PriorityMUX2bit4to1.hdl, output-file PriorityMUX2bit4to1A.out, compare-to PriorityMUX2bit4to1A.cmp, output-list R0%B3.1.3 R1%B3.1.3 R2%B3.1.3 R3%B3.1.3 X0%B3.2.3 X1%B3.2.3 X2%B3.2.3 X3%B3.2.3 Y0%B3.2.3; set R0 0, set R1 0, set R2 0, set R3 1, set X0 %B00, set X1 %B00, set X2 %B00, set X3 %B00, eval, output; set...
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clc clear //DATA GIVEN L=0.25; //stroke of the engine in m D=0.15; //diameter of cylinder in m V2=0.0004; //clearance volume in m^3 Vs=(%pi/4)*D^2*L; //swept volume in m^3 Vt=Vs+V2; //total cyl...
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clc clear //input v=3*10^5//orbit speed r=4.6*10^20//distance g1=6.7*10^-11 //calculation of mass m=v*v*r/g1 //Newtons law //output printf("the mass is %2.3e kg",m)
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2016 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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//problem 1.12 l=4 b=2 h=3 w=9810 s=0.8 p1=w*l*b*h*s p2=w*s*l*h*1.5 p3=w*s*b*h*1.5 disp(p1,"total pressure on horizontal base") disp(p2, "total pressure on larger vertical base") disp(p3,"total pressure on smaller vertical walls")
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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errcatch(-1,"stop");mode(2);//Example 1.13 //Program to Compute convolution of given sequences //x(n)=[1 2 1 1], h(n)=[1 -1 1 -1]; ; ; ; x=[1 2 1 1]; h=[1 -1 1 -1]; y=convol(x,h); disp(round(y)); exit();
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clc // Given that E1 = 3*10^5 // electric intensity when space between plates evacuated in V/m E2 = 1*10^5 // electric intensity when space between plates is filled with dielectric in V/m e_ = 8.85e-12 // electric permittivity of air in C^2/Nm^2 // Sample Problem 2 on page no. 9.11 printf("\n # PROBLEM 2 # \n") printf...
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x=[1,2,3,4]; i=sqrt(-1); s=0; for k=1:length(x) v(k)=0; for n=1:length(x) v(k)=v(k)+(x(n)*exp(-i*((2*3.14)/length(x)*(k-1)*(n-1)))); end end disp(v); dft=round(v); v1=abs(dft) disp(dft); k=1:length(x); a=gca(); a.data_bounds=[0,0;4,10] plot2d3(k,v1)
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function infer_objects() // Attempt to infer better dtypes for object columns. // // Syntax //df.memory_usage(index = False) // // Parameters // // For additional information on parameters, See https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.DataFrame.infer_objects.ht...
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function imgSetList=imageSetToList(imageSet) if isstruct(imageSet)<> %T then error(msprintf("Error: The input argument is not of type imageSet.")); end fieldNamesActual=["Description";"ImageLocation";"Count"]; fieldNamesInput=fieldnames(imageSet); if fieldNamesActual <> ...
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clc clear A=[2 3 -1;4 4 -3;-2 3 -1]; //coefficient B=[5;3;1]; //constant n=length(B); Aug=[A,B]; //forward elimination for j=1:n-1 for i=j+1:n Aug(i,j:n+1)=Aug(i,j:n+1)-(Aug(i,j)/Aug(j,j)*Aug(j,j:n+1)); end end //backward substitution x=zeros(n,1); x(n)=Aug(n,n+1)/Aug(n,n); for i=n-1:-1:1...
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function [stk,txt,top]=%i2sci() // //! // Copyright INRIA txt=[] rhs=abs(evstr(op(3)))-2 sto=stk(top);top=top-1 sfrom=stk(top);top=top-1 top=top-rhs+1 s2=stk(top) if rhs==1 then if s2(1)<>':' then if sto(3)=='0'|sto(4)=='0' then txt=sto(1)+'(1,'+s2(1)+') = '+sfrom(1)+';' else txt=sto(1)+'('+s2(1)+...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 6, Example 7") disp("Blade speed U is given by: in m/s") D = 1050; N = 2800; U1 = %pi*D*N/(60*1000) disp("The velocity diagram is sh...
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// Frequency Response // Experiment Condition: Input (+- 100mV) Input_Amplitude= 207; // (mV) // Input cap: x18, Input cap: x6, Gain_OTA 500pA Feedback_OTA 35pA Freq_resp_x18_x6_500pA_35pA = [ // Freq(Hz) Amplitude (mV) 0.5 33.83; 1 63.83; 2 138.4; 5 349.1; 10 298.3; 20 167.4; 50 71.25; 100 46.33; 200 33.2; 500 27.81...
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clc clear //INPUT DATA r1=0.1258*10^-9//atomic radii of the iron atom in BCC structure in m r2=0.1292*10^-9//atomic radii of the iron atom in FCC structure in m T=910//metallic iron changes from BCC to FCC in centigrade //CALCULATION a1=((4*r1)/sqrt(3))//lattice constant of BCC structure in m v1=((a1*a1*a1)/2...
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//Example 15.5 (fig 15.4) //transfer function of the system clear;clc; xdel(winsid()); mode(0); s=poly(0,'s'); //G1 and G2 are connected in series G1=s^2/(s+4)^2 G2=(s+1)/(s^3*(s+3)) //H1 is feedback loop H1=(s^2+s+1)/(s*(s+3)) // Tf=transfer function Tf=(G1*G2*H1) A=type(s); disp(A,'Type of the syste...
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//Engineering and Chemical Thermodynamics //Example 2.13 //Page no :73 clear ; clc ; //Given data : del_h0_f_CO2 = -393.51 ; //[kJ/mol], From Appendix A.3 del_h0_f_CO = -110.53 ; //[kJ/mol], From Appendix A.3 del_h0_f_H2O = -241.82 ; //[kJ/mol], From Appendix A.3 del_h0_f_C3H8 = -103.85 ; //[kJ/mol], From Ap...
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.VECTORS 85 .PATTERNS 11101000110010111100010101101000101000000hhllhlhhhhlllhlhlhhlhlllhlhllllllhlhllhlhllhlhllhhllhhhllhhlhllhhllhlllllllhhhllhhhhlhllllhhhlllllhhllhhhllhllhhhhlllhlhhhlhlllllllhlhllhlhllllhhhllhhhhlhllllhhhhlhlllllllhhllhhhllhhlhllhhllhlllllllhhhhlhllllhhhhhllhhhllhlllllllhhhllhhhlllllhlhllhlhllll...
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//========================================================================== // Modified for RT purposes by Roberto Bucher - RTAI Team // roberto.bucher@supsi.ch function ok = compile_standalone() //compile rt standalone executable for standalone // 22.01.2004 //Author : Roberto Bucher (roberto.bucher@die.supsi.ch) ...
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void main() { print("sum: ","\n"); }
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//Chapter-11 example 32 //============================================================================= clc; clear; //input data F1 = 490;//freq shift lower limit in Mhz F2 = 510;//freq shift upper limit in Mhz //calculations SC = (F1+F2)/2;//Spectrum Centre in Mhz BW = F2-F1;//bandwidth in Mhz CPW = 1/...
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//Exa 1.1 clc; clear; close; //given data : E=4;//in V/m Eta=120*%pi;//constant //Formula : E/H=Eta H=E/Eta;//in A/m disp(H,"Strength of magnetic field in free space in A/m : ");
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H=5; ws=H*H+4*H+6; [fdg, err] = mopen("gen0.dat"); [fdp, err] = mopen("path0.dat"); gsize=strtod(mgetl(fdg,1)); grid=mgetl(fdg); expert=strtod(mgetl(fdp)); epls=zeros(size(expert,1)-1,1); for i=2:size(expert,1) epls(i-1)=expert(i)-expert(i-1); end //use part to search character //define feature vectors for a state ...
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//cubic spline method //example 6.5 //page 214 clc;clear;close; x=[0 %pi/2 %pi]; y=[0 1 0]; M0=0,M2=0; h=%pi/2; M1=(6*(y(1)-2*y(2)+y(3))/(h^2)-M0-M2)/4; deff('y=s1(x)','y=2*((-2*3*x^2)/(%pi^2)+3/2)/%pi'); S1=s1(%pi/4); disp(S1,'S1(pi/4)='); deff('y=s2(x)','y=(-24*x)/(%pi^3)'); S2=s2(%pi/4); disp(S2,'S2(pi...
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clc; clear all; close; //Convolution and Correlation x1=[1,3,7,-2,5]; x2=[2,-1,0,3]; y1=conv(x1,x2); z=xcorr(x1,x2); n=0:3; x3=mtlb_fliplr(x2) y2=conv(x1,x3); c=mtlb_fliplr(x2(2:4)) x=[c x2(1)]; y=mtlb_fliplr(-n); plot(y,x); figure; x4=mtlb_fliplr(z); c1=mtlb_fliplr(z(2:4)); k=[c1 z(1)]; l=mtlb_flipl...
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clc,clear printf('Example 1.1\n\n') Pole=4 Z=440 //number of conductors in armature phi=0.07 //flux produced by each pole in webers N=900 //Speed of armature in r.p.m //Part(i) lap wound A1=Pole //no of parallel paths for lap winding E1=phi*N*Z*Pole/(60*A1) printf('(i) e.m.f generated (lap-wound) ...
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//calculating pH //Example 6.3 clc clear //for hydrogen electrode Ecell=0.6734//Emf of cell in V pH=(Ecell-0.2422)/0.0591//pH of the solution printf('Thus the pH of the solution = %2.3f ',pH)
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//Exa:2.11 clc; clear; clc; close; //Given: //Vt=[50+205msin(5*10^3*pi*t)]cos(2*pi*10^7)V //comparing it with Vt=[Vc+Vesin(Wm*t)]cos(wc*t)V Vc=50; Ve=20; wc=2*%pi*10^7; wm=5*10^3; fm=500/2; fc=10^7; m=Ve/Vc; Pc=Vc*Vc; Ps=(m*m/4)*Pc*2; Pt=Pc+Ps; printf("\n\n\t carrier frequency =%f",fc); printf("\n\...
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// Maximum current and frequncy at which it occurs and respective voltages clc; clear; R=5; L=4*(10^-3); C=0.1*(10^-6); V=10; w0=1/(sqrt(L*C)); Ir=V/R; Vl=w0*L*Ir; Vc=Ir/(w0*C); mprintf('The Maximum Current at resonance = %f A \n',Ir) mprintf('The frequency for resonance = %f rad/sec \n',w0) ...
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# # This test takes some CSD Z'=2 structures and tests the \MATCH command # \set time slow \rele print CROUTPUT: \TITLE CSD_CIF_MIF_AFEBAO \LIST 1 REAL 9.5830 10.7400 15.2470 106.7900 90.6500 104.0900 END # The spacegroup symbol must have a space between each of the operators. \SPACEGROUP SYMBOL P -1 E...
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//Ex1_1 Pg-43 clc disp("Refer to the figure 1.52") disp("Hold the resistor as shown in the figure such that tolerance is on your extreme right.") disp("Now the value of the resistor is equal to") disp(" Red Black Blue Gold") disp(" 2 0 6 (+/-)5%") red=2 //red value ...
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//Electric machines and power systems by Syed A Nasar //Publisher:TataMcgraw Hill //Year: 2002 ; Edition - 7 //Example 2.7 //Scilab Version : 6.0.0 ; OS : Windows clc; clear; c=0.1; //circumference in m A=0.0016; //cross sectional area in m^2 N1=10; ...
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//Network Theorem 1 //page no-2.29 //example2.24 disp("Applying KCL to node 1:"); disp("2*V1-V2 = 2");....//equation 1 disp("Applying KCL to node 2:"); disp("3*V2-V1 = 4");...//equation 2 disp("Solving equations 1 and 2");...//solving equations in matrix form A=[2 -1;-1 3]; B=[2 4]' X=inv(A)*B; disp(X); dis...
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//To determine the class distribution factors //Page 50 //Refer diagram of the first example of this chapter clc; clear; Ps=100; //Peak load for street lighting in kW Pr=1000; //Peak load for Residential in kW Pc=1200; //Peak Commercial load in kW P=[Ps,Pr,Pc] //Peaks of various loads Ls5=0; //Street light...
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contador =10000; while contador>0 // executará um loop infinito num= input("Digite o valor "); //ler um dado digitado pelo usuário if isempty(num) then //se esse valor estiver vazio, ele para a execução printf("tchau");//emite mensagem de saída break;// para a execução else // caso não oco...
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function apply() // Apply a function along an axis of the DataFrame. // // Syntax // dfr.apply(input_string) // // Parameters // input_string : String containing the function to be passed. Scilab functions are not supported as of now. Additional parameters supported can be passed // // F...
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//Лабораторная работа 2 clc m=[1 2 3], v=poly(m, 'x', 'r'), disp(v, 'полином:', '*****ЗАДАНИЕ №1*****'), x=roots(v), disp(x, 'проверка:'), p=[5 0 -3 10 -20], x1=roots(p), disp(x1, 'корни уравнения:', '*****ЗАДАНИЕ №2*****'), x=poly(0, 'x'); k=3*x^3 + 2*x^2-10*x l=5*x^2-25*x-10 disp(k*l, 'умножение полиномов:', '*****ЗА...
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; @Harness: disassembler ; @Result: PASS section .text size=0x0000018c vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x000001c0 ;2**0 start .text: label 0x00000000 ".text": 0x0: 0x00 0x90 0x00 0x80 lds r0, 0x8000 0x4: 0...
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// Scilab Code Ex2.4 Compressibility and ionic energy of NaCl crystal: Page-68 (2010) e = 1.6D-19; // Electronic charge, C ep_0 = 8.854D-12; // Absolute electrical permittivity of free space, coulomb square per newton per metre square Re = 2.81D-10; // Equilibrium separation between Na+ and Cl- ions, m A = 1.7496; ...
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//Application of Le chatelier's Principle clear; clc; printf("\t Example 14.11\n"); //(b) Kc=2.37*10^-3;//equilibrium constant for the reaction N2=0.683;//conc of N2, M H2=8.8;//conc of H2, M NH3=3.65;//conc of NH3, M Qc=NH3^2/(N2*H2^3);//reaction quotient initial if(Qc==Kc) then d="the system is...
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//Rating of electric heating pad Vr,Pr //Rating of bulbs Vbr,Pr close(); clear; clc; Vr = 110;//V Pr = 55;//W V = 220; Vbr = 110; Pr1 = 25; Pr2 = 60; Pr3 = 75; Pr4 = 100; //Resistance of heating pad 'Rp' Rp = Vr^2/Pr; R1 = Vbr^2/Pr1; R2 = Vbr^2/Pr2; R3 = Vbr^2/Pr3; R4 = Vbr^2/Pr4; Rb = R4 + 1/2*R2; ...
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--> zeros(3,4) ans = 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.
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//Example 6.24 clc;clear; X=[20 -5.828-2.414*%i 0 -0.172-0.414*%i 0 -0.172+0.414*%i 0 -5.828+2.414*%i]; x=round(clean(ifft(X))); disp(X,'X(k)='); disp(x,'x(n)=');
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clear // l = 15 //in - The length of the crossection b = 33.9 //in - the width of the crossection L = 100 //in The length of the cantilever E = 29*(10**6) //psi The youngs modulus of the material used I_Z = 315 //in^4 - the moment of inertia wrt Z axis I_y = 8.13 //in^4 - the mom...
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//scilab 5.4.1 //Windows 7 operating system //chapter 9 Basic Voltage and Power Amplifiers clc clear AVm=120//AVm=mid-band gain of an RC-coupled amplifier fm=100//fm=frequency in Hz corresponding to the mid-band gain AVl=60//AVl=reduced gain AVh=AVl f=100*10^3//f=frequency in Hz corresponding to the reduced ga...
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clear clc disp("example 9.7") en=3*10^6 a=12 fen=0.1 Es=2/(12+2/3) re=exp(Es) printf("(a)\nratio of energies per collision is %f",re) rietf=en/fen ldie=log(rietf) nc=ldie/Es printf("(b)\npatio of iniial to final energies is %e \n logarithemic decrement in energy is %f \n number of collisions is %d",rietf,ld...
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clc //initialisation of variables w= 750 //R.P.M t= 0.02 //in r1=9 //in r2= 5 //in u= 0.003 //slug/ft sec //CALCULATIONS T= u*%pi*(2*%pi*w/60)*((r1/24)^4-(r2/24)^4)*2*%pi*w/(2*t/12*33000) //RESULTS printf ('horse power required to overcome= %.1f hp',T)
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clc syms n; v=1/((1/n)^2) u=(2/n-1)/(1/n*(1/n+1)*(1/n+2)) disp(limit(u/v,n,0)); disp('both u and v converge and diverge together,hence u is convergent')
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//to find the ratio of currents and torques at the starting,V2/V1 clc; f1=50; f2=60; f=f2/f1; V=1; //V=V2/V1 s_max_T=0.2; //Is=I_s2/I_s1 Is=V*sqrt((s_max_T^2+1)/(s_max_T^2+f^2)); disp(Is,'ratio of currents at starting'); //Ts=T_s2/T_s1 Ts=V^2*((s_max_T^2+1)/(s_max_T^2+f^2)); disp(Ts,'ratio of torques a...
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//All the quantities are expressed in SI units M1 = 3.5; theta1 = 10*%pi/180; gam = 1.4; p1 = 101300; T1 = 288; //for these values of M and theta, from fig. 9.9 b1 = 24*%pi/180; Mn_1 = M1*sin(b); //from Appendix B, for Mn,1 = 2.05, we have Mn_2 = 0.7157; p_ratio1 = 2.32; T_ratio1 = 1.294; M2 = Mn_2/s...
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//Optoelectronics and Fiber Optics Communication by C.R. Sarkar and D.C. Sarkar //Example 4.1 //OS = Windows 7 //Scilab version 5.5.2 clc; clear; //given h=6.62*10^-34;//Plank's constant in SI units c=3*10^8;//speed of the light in m/s e=1.9*10^-19;//electric charge in columb I=50*10^-3;//drive current i...
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clc; close(); clear(); //page no 412 //prob no. 12.11 Fdb=5; T0=290; //K F=10^(Fdb/10); mprintf('Noise figure, F=%.3f\n',F); Te=(F-1)*T0; mprintf(' Noise Temperature , Te=%i K ',Te);
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//Tested on Windows 7 Ultimate 32-bit //Chapter 9 Frequency Response of Amplifier Pg no. 307 and 308 clear; clc; //Given VCC=15;//collector supply voltage in volts RC=2.2D3;//collector resistance in ohms RE=470;//emitter resistance in ohms R1=33D3;//divider network resistance R1 in ohms R2=10D3;//divider n...
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clc //Initialization of variables capacity=50 //tons hp=10 //hp //calculations beta=778*3.33*capacity/(hp*550) //results printf("Coefficient of performance = %.2f",beta) //The answer given in textbook is wrong
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//Fluid system - By - Shiv Kumar //Chapter 2 - Impact of Jet //Example 2.26 clc clear //Given Data:- H=4; //Head of water in tank, m d=150; //Diameter of orfice, mm Cv=0.96; //Data Used:- rho=1000; //Density of water, kg/m^3 g=9.81; ...
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//Example 6.14 clc;clear;close; X=[3 2+%i 1 2-%i]; //Calculation of IDFT x=dft(X,1); x=clean(x); disp(X,'DFT of the Sequence is X(k): '); disp(x,'Sequence is x(n): ');
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clear; clc; // Illustration 10.2 // Page: 497 printf('Illustration 10.2 - Page: 497\n\n'); printf('Illustration 10.2 (a)\n\n'); // solution (a) //****Data****// // a:water b:kerosene c:Nicotine xF = 0.01;// [wt fraction nicotine] F = 100;// [kg] B = 150;// [kg] //******// // Equilibrium data: ...
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// Script to load the Flex-Sim dynamic library. // Author: Dario Di Stefano, Evidence Srl. flexsim_path = get_absolute_file_path('loader.sce'); // -------- Modules to be imported ---------- // Flex comp_fun = ['flex_adcin',.. 'flex_gpin',.. 'flex_gpout',.. 'flex_lcd',.....
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//Example (pg no.20) //the number %pi/4 is the value of infinite series //sum(((-1)^i)/(2*i+1))=1-sum(2/(16*(j)^2)-1) // The sequence alpha1,alpha2,........is monotone-decreasing // to its limit %pi/4 // 0< =(alpha)n - %pi/4 <= (1/(4*n+3)) n=1,2,..... // To calculate %pi/4 correct to within 10^(-6) usi...
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function h=%rvs(h1,h2) // %rvs(h1,h2) calcule (I+h1*h2)\h1. h1: matrice de fractions rationnelles // h2 matrice de scalaires //! [m1,n1]=size(h1(2)) [m2,n2]=size(h2) if abs(n1-m2)+abs(m1-n2)<>0 then error('inconsistent dimensions'),end if m1*n1==1 then h=h1;h(3)=h1(2)*h2+h1(3); else h=(eye(m1,m1)+h1*h2)\h1 end
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clc; v=230; // rated voltage of dc motor p=10000; // rated power of dc motor rf=115; // field resistance ra=0.348; // net armature resistance ifs=v/rf; // shunt field current ia=(p/v)-ifs; // rated armature current disp('case a'); rx1=(v/(2*ia))-ra; printf('External resistance required at the time of starting...
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clc // Given That n = 140 // no. of shift in fringe lambda = 5.46e-7 // wavelength of light in meter t = 0.2 // length of tube in meter // Sample Problem 54 on page no. 1.58 printf("\n # PROBLEM 54 # \n") mu = (n*lambda)/(2*t) + 1 // calculation for refractive index of gas printf("\n Standard formula used \n mu = (n*...
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 37 disp("CHAPTER 8"); disp("EXAMPLE 37"); //VARIABLE INITIALIZATION p_o=50*1000; //in Watts v_t=250; //in Volts loss1=5000; //total core loss in Watts loss2=2000; //total core loss in Watts (when speed is ...
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//EXAMPLE 2-27 PG NO 74 F=50 V=230; //voltage R=20; //resisance I=V/R; //current P=V*I; //power Im=I*1.414; //Maximum current W=2*%pi*F; disp(' current is = '+string(I)+' A'); disp(' POWER is = '+string(P)+' W'); disp(' MAXIMUM CURENT is = '+...
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//Example 5_17 clc(); clear; //To find the lattice parameter and atomic diameter lamda=0.171 //units in nm theta=30 //units in degrees d110=lamda/(2*sin(theta*%pi/180)) //units in nm h=1 k=1 l=0 a=d110*sqrt(h^2+k^2+l^2) //units in nm printf("The lattice parameter is a=%.3fnm...
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clc // given data G=39.0 // temperature gradient in K/km. h2=10.0 // depth in km rhow = 1000; rhor=2700.0 // kg/m^3 cr=820.0 // in J/kg-K cw=4200.0; // specific heat of water in J/kg-K QbyA=0.5; h1=120/G // T1-T0=120 K is given h21=h2-h1 // in km E0byA=(rhor*(1000**3)*G*cr*h21**2)/2 // in J/km^2 Heat content per squar...
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//Example 7.2 //Inverse in Place without Pivoting //Page no. 256 clc;clear;close; A=[3,-6,7;9,0,-5;5,-8,6]; //matrix B=[3,-6,7;9,0,-5;5,-8,6]; //copied matrix for i=1:3 printf('\n\nStage %i',i); for j=1:3 if(i==j) B(i,j)=1/B(i,j); else B(i,j)=A(i,j)/A(i,...
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//chapter-10,Example10_7,pg 309 a1=3.81*10^-3 a2=-6.17*10^-7 //R1=(R2/2),i.e R2/R1=2 R1=10*10^3 R2=20*10^3 R5=4*10^3 R6=20*10^3 B=(R5/(R5+R6)) //using relation 10.68(b) printf("(Vo/Vi)= (-3.05*10^-3)t/(1+0.76*10^-3)t\n") printf("thus for, t<=130 C, Vo is approx. linear. this however can...
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clc t1=20; //0C C1=40; //m/s t2=820; //0C C2=40; //m/s t3=620; //0C C3=55; //m/s t4=510; //0C m=2.5; //kg/s cp=1.005; //kJ/kg.0C disp("(i) Heat exchanger") Q_12=m*cp*(t2-t1); disp("rate of heat transfer=") disp(Q_12) disp("kJ/s") disp("(ii) Turbine") W_23=m*[(cp*(t2-t3))+(C2^2-C3^2)/2/1000]; di...
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function [data] = mdaqDSPSignalRead(arg1, arg2, arg3, arg4) // Check version compatibility [is_supp vers] = mdaq_is_working('mdaqDSPSignalRead'); if is_supp == %F then error('ERROR: ' + vers) return; end data = []; result = -1; if argn(2) <> 4 then mprintf(...
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clear // //given f=50 //frequency p=10 //number of poles //case a n=120*f/p printf("\n n= %0.0f rpm",n) //case b //the pitch factor kp=0.966 //m=2 and gama=180/slots per pole and it is obtained as 30 //kd=sin[(mgama)/2]/msin(gama/2)=0.966 z=6*2*10 ep=z*2.22*0.966*0.966*50*0.15 printf("\n phase emf= %0.5f v",ep) //cas...
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//Chapter 13, Problem 22, figure 13.82 clc; E=6; //in volt r=2.5; //in ohm //defining a function function a = myfunction ( c,d,e) b = c/(d+e); a=b^2*e; endfunction for Rl=0:0.5:5 P=myfunction(E,r,Rl) x=linspace(0,7,12); y=linspace(0,5,12); plot(Rl,P...
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function [s]=%lssmr(s1,s2) //s=%lssmr(s1,s2) <=> s= s2*s1 //! [s1,s2]=sysconv(s1,s2);s=s1*s2