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<?xml version="1.0" encoding="utf-8"?> <test> <description> Process 2D tecplot output </description> <executable>FieldConvert</executable> <parameters> -f -e bfs_tg.xml bfs_tg.fld bfs_tg.dat</parameters> <files> <file description="Session File">bfs_tg.xml</file> <file description="Session File"...
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// Author: Michelle Sagnelli D'urzo // Create an augmented matrix using two given matrices. AUGM = [A B] X = AUGM VARIABLES = [] ERRORS = [] // Display the complete matrix disp("Augmented Matrix") disp(X) // Applying Gauss-Jordan X = rref(X); // Display Gauss-Jordan matrix disp(X) // Adding varia...
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//EXAMPLE 2.21.C clc; x1=10; x=integrate('1','t',-2,x1); disp(x) disp('valid for t<=2')
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//Problem to test fminbnd //Problem taken from Engineering Optimization b Singiresu S.Rao //A manufacturing firm producing small refrigerators has entered into a contract to supply 50 refrigerators at the end of the first month, 50 at the end of the second month, and 50 at the end of the third. The cost of producing x...
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function [s]=%pmlss(d2,s1) // [s]=%lssmp(d2,s1) // d2*s1 // // s1 : state-space // d2 : polynomial matrix //! // origine s. steer inria 1992 // s=tlist(['lss','A','B','C','D','X0','dt'],[],[],[],d2,[],[])*s1
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function out = typecheck(A,B,C,D,F1) if(A==1) if(C==1 | F1==1) out = "oe" else out = "bj" end elseif(D==1 & F1==1) if(C==1)' out = "arx" else out = "armax" end else out = "idpoly" end ...
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Name=closefast PlayerCharacters=ow-heavysurgerifle BotCharacters=ow-rotation.rot IsChallenge=true Timelimit=60.0 PlayerProfile=ow-heavysurgerifle AddedBots=ow-rotation.rot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=2 BotTeams=1 MapName=boxernobounds.map MapScale=2.0 BlockProjectilePredictors=true BlockCheats=true Invinc...
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//Transport Processes and Seperation Process Principles //Chapter 2 //Example 2.7-1 //Principles of Momentum Transfer and Overall Balances //given data //Q=(z2-z1)*g+(v2^2-v1^2)/2 + (H2-H1) //for KE terms v1=1.52;//velociy of inlet stream v2=9.14;//velocity of exit stream KE=((v1^2)-(v2^2))/2; //for PE terms ...
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clear; clc; printf("\n Example 8.2"); //From the gel polarisation model: //J = (1/A)(dV/dt) = hD ln(Cg/Cf) //Cf = Co(Vo/V) //where Co and Vo are the initial concentration and volume,respectively and Cf and V are the values at subsequent times //Combining these eq gives //dV/dt =...
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//chapter 6 Ex 8 clc; clear; close; total=25; avg25=18; avg12first=14; avg12last=17; num13=(avg25*total)-((avg12first*12)+(avg12last*12)); mprintf("The 13th number is %d",num13);
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//Ex19_3 Pg-958 clc a=1 b=0 c=1 dec=a*2^(-1)+b*2^(-2)+c*2^(-3) //decimal output disp("The decimal equivqlent of 0.101 is") disp(dec)
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clc clf // --------- PLOT SIGNAL -------- function plot_signal(x, n, pos, name, dotColor) subplot(2,4, pos) indice = linspace(0, length(x) - 1, length(x)) indice = indice - n + 1; plot2d3(indice, x) config = gca() config.x_location = "origin"; config.data_bounds = [ -10 -10; 10 10]; ...
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clear; xdel(winsid()); /* 1 вар если уже в открытом списке, проверяем текущую Ф бол */ function s=f(h,g) s = (h(1)) endfunction size_ = 32; map = zeros(size_,size_); map(1,:) = 1; map(size_,:) = 1; map(:,1) = 1; map(:,size_) = 1; // отображение figure(1); clf; hist3d(map);
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function M=Pk(n,k,v) u = householder(v); M = eye() - 2*u*u'; endfunction function M = P(n,k,a) M = eye(n,n); M(k:n,k:n)=Pk(n,k,A(k:n,k)) endfunction function A= p2z(R,theta) A = R*exp(%i*%pi*theta/180.0); endfunction A = eye(8,8) for i=1:8 for j=1:8 A(i,j)=cos((i-1)*(j-1)*%...
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clc; //page no 258 //prob no. 6.9 //An IF transformer at 455kHz & primary ckt has Qp=40 & secondary Q=30 fo=455*10^3;Qp=40;Qs=30; //a)Determination of critical coupling factor kc=1/sqrt(Qp*Qs); disp(kc,'a)The critical coupling factor is'); //b)Determination of optimum coupling factor Kopt=1.5*kc; disp(Kopt,'b...
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Vdata First Vdata: - contains 5 records Interlace mode: FULL Fields: Single-component Field - 1 bytes Vdata Second Vdata: - contains 6 records Interlace mode: FULL Fields: Multi-component Field - 16 bytes
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clc // Given that W=250//in ton Weight of injection moulding machine d=4.5//in inch diameter of spur gear t=0.5//in inch thickness of spur gear //Gears have a fine tooth profile // Sample Problem on page no. 488 printf("\n # Injection Molding of Parts # \n") //because of fine tooth profile pressure requi...
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clear;lines(0); A=[1,2;3,4]; cothm(A)
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// // 08.05.31 // 09.12.25 // 10.01.01 function Drwpt(varargin) global Wfile FID TenSize TenSizeInit MilliIn; Nargs=length(varargin); if TenSize>TenSizeInit N=round(6*sqrt(TenSize/TenSizeInit)); else N=4 end Tmp=varargin(Nargs); if type(Tmp)==1 if length(Tmp)>1 Kosa=1; All=Nargs; el...
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in = [ -75 -90 30 ; -120 11 12; 122 11 14]; //Checking if error message pops up when input is 3D instead of 2D point set output = convertPointsToHomogeneous(in); //output-> // !--error 999 //Please enter 2D points matrix of size Nx2.
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Ex6_5.sce
clc(); clear; //Given : ME = 35*10^3 ; //Maximum energy in eV theta = %pi; // photon is backscattered h = 6.625*10^-34; //planck's constant in Js m0 = 9.1*10^-31; //electron mass in Kg c = 3*10^8; //Speed of light in m/s deltalambda = (h*(1-cos(theta)))/(m0*c); // in A // (h*c/lambda) - (h*c/lambda') = 35 KeV ...
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Example4_6.sce
//chapter-4,Example4_6,pg 490 add="0011"//binary-3 to be added x="0010"//binary-2 x=bin2dec(x) add=bin2dec(add) XS31=x+add XS31=dec2bin(XS31) y="0100"//binary-4 y=bin2dec(y) XS32=y+add XS32=dec2bin(XS32) z="0111"//binary-7 z=bin2dec(z) XS33=z+add XS33=dec2bin(XS33) printf("X...
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//find dft of a rectangular pulse --> sinc function clear clc close n = -10:0.1:10 a = 1 for i = 1:length(n) if(n(i)>=-a & n(i)<=a) x(i) = 1 else x(i) = 0 end end figure(0) subplot(211) plot2d3(n,x) title("Rectangular pulse") xlabel("---->n") ylabel("x(n)") a1 = gca() a1.x_location = 'ori...
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ex10_15.sce
// Exa 10.15 clc; clear; close; format('v',6) // Given data P = 8; phi = 0.1;// in Wb Z = 400; N =300;// in rpm Eg = (N*phi*Z)/(60);// in V (A = p) disp(Eg,"The emf when lap is connected in V is"); // For A=2, connected armature A = 2; Eg = (N*phi*P*Z)/(60*A);// in V disp(Eg,"The emf when wave is connect...
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clc clear //Input data p1=5.62//Pressure of gas entering the turbine in kg/cm^2 T1=1000+273//Temperature of gas entering the turbine in K p2=1.124//Pressure of gas leaving the turbine in kg/cm^2. In textbook it is given as 1.24 instead of 1.124 n1=0.8//Isotropic efficiency of the turbine in ratio n=1.36//Adiabat...
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clc //initialisation of variables v= 1155 //ft/sec V= 600 //m.p.h r= 880 //CALCULATIONS V1= ((sqrt(v/1000))-1)*100 //RESULTS printf ('percentage error = %.1f per cent',V1)
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.21\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.21 (page no. 589) // Solution //Because the conditions of illustrative problem 11.15 are the same as for problem 11.19 and 11.20,we can solve this problem in two ways to obtain a check. //Thus,...
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ex1_8_a.sce
//Example 1.8(a) clc; Fs=500*10^-3; //Full Scale e=0.02; //error permissable +-2% I=300*10^-3; //Current measured lim_err=Fs*e; //magnitude of limiting error //limiting error at a given current I lim_err_I=100*lim_err/I; printf('\nLimiting error at 300 mA = %.2f percen...
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//Example 6_13 clc; clear; close; format('v',6); //given data : Vdc=30;//V rf=25;//ohm RL=500;//ohm Idc=Vdc/RL;//A Im=%pi*Idc;//A Vi_max=Im^2*(rf+RL);//V disp(Vi_max,"Voltage required at input(V) : "); //Answer in the textbook is not accurate.
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clc; //ex3.12 d=0.001; q=1.6*10**-19; ND=10**20; R=1000; mun=0.1; n=ND;//number of free electrons sigma=q*n*mun;//conductivity disp('S/m',sigma*1,"sigma="); a=(1/sigma)*(1/(%pi*(0.001^2)/4)); l=R/a; disp('mm',l*10**3,"l=");
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clc //initialistions t1=80//c t2=50//c t3=60//c t4=30//c t=20 e=5 //CALCULATIONS k=2.3026*log((t1-t)/(t2-t))/e T=2.3026*log((t3-t)/(t4-t))/k //results printf(' time it will take = % 1f min',T)
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5_15.sce
clear all; clc; disp("Ex 5_15") disp("Free body diagram is as shown in fig 5-30b") //Initilization of variables F=[0,-1000,0] //matrix notation T_C=[0.707,0,-0.707] //matrix notation T_D=[-3/9,6/9,-6/9] //matrix notation //Calculations //Applying summation of forces along each axes and equating them to zero //Apply...
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islinphase11.sce
//i/p args are matrices b=[1 2 3 4;2 3 4 5]; a=[2 3 4 5;3 4 5 6]; flag2=islinphase(b,a); disp(flag2); ////output //!--error 10000 //check input dimension //at line 23 of function islinphase called by : //flag2=islinphase(b,a);
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8_5.sce
//All the quantities are expressed in SI units M = 3.5; //Mach number T = 180; //static temperature from ex. 7.3 p = 0.3; //static pressure in atm gam = 1.4; R = 287; //from eq. (8.40) T0 = T*(1+((gam-1)/2*M*M)); //from eq. (8.42) p0 = p*((1+((gam-1)/2*M*M))^(gam/(gam-1))); a ...
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s=2;// начальное расстояние от лодки до катера fi=3*%pi/4; //функция, описывающая движение катера береговой охраны function dr=f(tetha, r) dr=r/sqrt(3); endfunction; //начальные условия в случае 2 r0=s; tetha0=-%pi; tetha=0:0.01:2*%pi; r=ode(r0,tetha0,tetha,f); //функция, описывающая движение лодки браконьер...
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testPredictionICRA2013.sce
// Exp1 : erreur en translation et mouvement de translation pathSave = "results/Exp1"; Delta = [-0.04 0.07 0.0 0.00*%pi/180 0.0*%pi/180 0.00*%pi/180]; Uc_m = [0.1; 0; 0.0; 0; 0; 0]; // init velocity FlagNoise = 0; // Exp2 : erreur en translation et trans rot pathSave = "results...
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Example11_7.sce
//Example 11.7 clc; clear; close; format('v',6); //Given data : Cd=0.62;//constant Q=250;//litres/sec Q=Q*10^-3;//m^3/s theta=90;//degree g=9.81;//constant d=1.3;//meter H=(Q/8*15/Cd/sqrt(2*g)/tand(theta/2))^(2/5);//m h=d-H;//meter disp(h,"Position above the bed in meter : ");
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clc //solution //given P=40000//W N=350//rpm ts=40//N/mm^2 fcs=80//N/mm^2 tc=15//N/mm^2 //let d be dia Tq=(P*60*1000)/(2*%pi*N)//N-mm //Tq=(%pi/16)*ts*d^3=7.86*d^3 //d=(Tq/7.86)^(1/3)//mm printf("the dia of shaft is,%f mm\n ",(Tq/7.86)^(1/3)) printf("the dia of shaft is ,say 55mm\n") d=55//mm D=2*d + 13//mm printf("th...
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// Chapter 3 example 8 //------------------------------------------------------------------------------ clc; clear; // Given data f = 100*10^6; // operating frequency in Hz v = 2*10^8 ; // propagation velocity in m/s Zo = 300; // charecteristic impedance...
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Example_7_4.sce
//Scilab Code for Example 7.4 of Signals and systems by //P.Ramakrishna Rao clc; clear x y1 y y2 q t n; clear; //y(t)=x(2*t) disp('y(t) depends upon past inputs for t<0'); disp('y(t) depends upon future inputs for t>0'); disp('Hence the system is Dynamic'); x1=[1,3,5,7,2,5,3,9];//Random Variable x2=[2,4,6,8,2...
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zerocrossings.sci
function r = zerocrossing (x,y) //This function estimates the points at which a given waveform crosses the x-axis. //Estimates the points at which a given waveform y=y(x) crosses the //x-axis using linear interpolation. //Calling Sequence //r = zerocrossing (w, y) //Parameters //r: zero crossing points //y:function...
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// Example 10.1 // From Diagram 10.2a Vm=141+%i*0; // Peak value of Voltage V=Vm/1.414; // Rms value of Voltage v=100+%i*0; // Here will have V=99.70, but we took v=100 R=3; // Resistance wL=0.0127*100*%pi; // Reactan...
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ch9_10.sci
//to calculate max torque and slip, starting torque clc; k=5; //k=I_s/I_fl s_fl=0.04; s_max_T=sqrt((s_fl^2*(1-k^2))/((k*s_fl)^2-1));disp(s_max_T,'slip'); T_max=.5*(s_max_T^2+s_fl^2)/(s_fl*s_max_T);disp(T_max,'max torque(pu)'); T_s=k^2*s_fl;disp(T_s,'starting torque(pu)');
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clc; //Example 1.15 //Page no 28 //solution v1=4; v2=0.005; sn=20*log10(v1/v2); disp('dB',sn,"S/N = ");
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clear all; clc; disp("From figure 5.3a, we have Cl=0.36, Cd=0.017 and alpha=1.8 degrees at maximum L/D") N=3500 C_l=0.36 alpha=1.8 C_d=0.017 r_t=13.25 r_h=3.25 Zb=7 Q=11560//cfm gamma_1=70 alpha=1.8 A=%pi*(r_t^2-r_h^2) printf("\n A is equal to %0.1f in^2",A) disp("On converting it in terms of feet ...
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FA.tst
load FA.hdl, output-file FA.out, output-list a b c0 c1 s; set a 0, set b 0, set c0 0, eval, output; set a 0, set b 0, set c0 1, eval, output; set a 0, set b 1, set c0 0, eval, output; set a 1, set b 0, set c0 0, eval, output; set a 0, set b 1, set c0 1, eval, output; set a 1, set b 0, set c0 1, eval, output; set a 1, ...
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Example3_15.sce
//Example 3.15 clc disp("Step 1: Identify topology") disp(" By shorting output(Vo = 0), feedback voltage does not become zero. By opening the output loop feedback becomes zero and hence it is current sampling. The feedback is applied in series with the input signal, hence topology used is current series feedback.")...
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clc // solution //initialization of variables // refer to fig 6.10c QdotC=300 //heating Load in KWh or heat rejected by condensor T1=-12 // evaporator temperature in degree celsius P2=800 // condensor pressure in kPa h1=240 // specific enthalpy of saturated R-134a vapour @ -12 degree celsius from table D.1 s...
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8_3_soln.sce
clc; pathname=get_absolute_file_path('8_3_soln.sce') filename=pathname+filesep()+'8_3_data.sci' exec(filename) // Solution: // Horsepower across the valve, HP=((p*Q)/1714); //HP // Results: printf("\n Results: ") printf("\n The Horsepower across the unloading valve is %.2f HP.",HP)
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Ch09Ex05.sce
// Scilab code Ex9.5: Pg.381-382 (2008) clc; clear; delta_E = 4.77e-04*1.6e-19; // Energy difference, J l = 0; // Rotational level h_cross = 1.055e-34; // Reduced plank's constant, J-s I = h_cross^2/delta_E; // Moment of inertia, ev-s^2 m_1 = 12; // Mass of C, u m_2 = 16; // Mass of O, u mu = ...
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Ex8_3.sce
clear all; clc; disp("Scilab Code Ex 8.3 : ") //Given: ri = 600/1000; //m t = 12/1000; //m ro = ri+t; sp_wt_water = 10; //kN/m^3 sp_wt_steel = 78; //kN/m^3 l_a = 1; //m depth of point A from the top //Internal Loadings: v = (%pi*l_a)*(ro^2 - ri^2); W_st = sp_wt_steel*v; p = sp_wt_water*l_a; //Pascal...
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clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.45 // Page 297 printf("Example 5.45, Page 297 \n \n"); // solution // (a) Hf = -982.8 Hfcryst = -1053.904 Hdis = Hfcryst-Hf // (b) Hfcr = -3077.75 Hsol = Hfcryst+7*(-285.83)-(-3077.75) printf(" (a) \n \n Hdissolulition =...
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//Chapter-5, Example 5.10, Page 178 //============================================================================= clc clear //INPUT DATA q=(0.3*10^6);//Heat flux in W/m^2 t=(10/60);//Time taken for heat transfer in s Ti=30;//Initial temperature of the slab in degree C x=0.2;//Distance of the plane from th...
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mu_not=4D-7*%pi //calculating exciting current B=1.2//flux density mu_r=500//rel permeability for iron H=B/(mu_not*mu_r) D=10D-2//mean diameter l=%pi*D//length of flux path in the ring AT=H*l N=300//number of turns on the ring I=AT/N mprintf("Exciting current=%d A\n",round(I)) //calculating inductance As=...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 7.6 //calculation of the speed of vehicle on the turn //given data r=10//radius(in m) of the turn theta=10//angle(in degree) of the bank g=9.8//gravitational acceleration(in m/s^2) of the earth //calculation v=sq...
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// To determine whether corona will be present in the air space round the conductor clear clc; d=2.5; di=3;// internal diameter do=9;// external diameter ri=di/2;// internal radius ro=do/2;// external diameter g1max=20/(1.25*log(ri/(d/2))+ .208*1.5*log(ro/ri)); mprintf("g1max=%.0f kV/cm \n",g1max); mprintf("S...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/07/StackArithmetic/StackTest/StackTest.tst load StackTest.asm, output-file StackTest.out, compare-to StackTest.cmp, output-list RAM[0]%D2.6.2 RAM[256]%D2....
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//Задаем исходные данные R=2.1;L=0.1;C=0.02;U=220;f=50; // Выполняем расчет I=U/((R^2+(2*3.1415926*f*L-1/(2*3.1415926*f*C))^2)^0.5) // Выводим в командное окно mprintf('\n') mprintf(' ИСХОДНЫЕ ДАННЫЕ:\n') mprintf('\n') mprintf(' R=%.2f Ом L=%.3f Гн C=%.3f Ф\n',R,L,C) mprintf(' U=%.2f В f=%.3f Гц\n',U,f) mprintf(' ОТВЕ...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 11 Oscillators and Multivibrators Pg no. 355 and 356 clear; clc; //Given //Figure E 11.1 L=20D-3;//colpitts inductance in henry C1=0.2D-6;//colpitts capacitor C1 in farads C2=0.02D-6;//colpitts capacitor C2 in farads //Solution Ce=C1*C2/(C1+C2);//equival...
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//======================================================================= // chapter 3 example 11 clc; clear; //input data sighem = 0.084; //magnetic susceptability u0 = 4*%pi*10^-7; //calculation ur = 1+(sighem); u = u0*ur; //result mpr...
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clear;lines(0); A=[1,2;3,4] pertrans(A)
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//Chapter 15: Antennas for Special Applications //Example 15-20.2 clc; //Variable Initialization f = 1.6e9 //Frequency (Hz) r = 1400e3 //Height (m) r_sep = 3500e3 //Height for 10 degree seperation (m) c = 3e8 //Speed of light(m/s) Ta = 300 //Satellite antenna temperature (K) Tr = 45 ...
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clc //Initialization of variables T1=150+460 //R T1=40+460 //R //calculations disp("from freon tables,") h2=43.850 //B/lbm hf2=17.273 hfg2=64.163 x2=(h2-hf2)/hfg2 //results printf("Quality of freon vapor = %.3f",x2)
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clc; close(); clear(); //page no 484 //prob no. 14.10 ZL=100; //ohm RL=ZL; R0=300; //ohm TauL=(RL-R0)/(RL+R0); mprintf('(a)The reflection coefficient at load is= %0.2f,',TauL); S=R0/RL; mprintf('\n (b) The standing wave ratio is, S = %.0f \n',S);
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t = [0:0.1:2]; y = sin(t); //plot(t,y) nx = 100; ny = 100; x = linspace(-1,1,nx); y = linspace(-1,1,ny); [X,Y] = ndgrid(x,y); r = sqrt(X.^2 + Y.^2); A = zeros(nx,ny); A (find(r<0.7) ) = 1; f = scf(); grayplot(x,y,A); f.color_map = graycolormap(32);
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//Example 1_17 page no:20 clc I=12;//total current in circuit(in ampere) R1=4;//Resistance in ohm R2=4;//Resistance in ohm R3=4;//Resistance in ohm R=R2*R3/(R2+R3) I1=I*R/(R+R1) disp(I1,"Current in resistor R1(in ampere)") I2=I*R/(R+R2) disp(I1,"Current in resistor R1(in ampere)") I3=I*R/(R+R3) disp(I1,"Cur...
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//exapple 2.15 clc; funcprot(0); // Initialization of Variable Pl=0.6;//longitudinal lap Pw=0.3;//side lap L1=12500; s=100*20; L2=8000; N1=L1/((1-Pl)*s)+1; A1=round(N1); if N1-A1<0 then N1=A1 else N1=A1+1; end N2=L2/((1-Pw)*s)+1; A2=round(N2); if N2-A2<0 then N2=A2 else N2=A2+1; ...
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xlyu V;HAB;1 xlyu V;PFV;1 xlyu V;PFV;3 xlyu V;HAB;3 xlyu V;PROSP;2 xlyu V;PROSP;1 xlyu V;HAB;2 xlyu V;PROG;3 xlyu V;PROSP;3 xlyu V;PROG;2 xlyu V;PROG;1 xlyu V;PFV;2 lya V;PROG;2 lya V;PROSP;1 lya V;PROG;1 lya V;PFV;3 lya V;HAB;3 lya V;HAB;1 lya V;PROSP;2 lya V;PROSP;3 lya V;HAB;2 lya V;PFV;2 lya V;PROG;3 lya V;PFV;1 jl...
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clc //initialisation of variables P= 5 //kips xab= 3 //in xbc= 6 //in xbp= 1 //in y= 6 //in n= 3 //CALCULATIONS Dl= P/3 Pct= (6*P)/(((xab+xbp)*(xab+xbp)/(xbc-xbp))+(xbp/(xbc-xbp))+(xbc-xbp)) R= sqrt(Pct^2+Dl^2) //RESULTS printf ('Greatest Load= %.2f kips',R)
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example8_14.sce
//clc() P = 101.3;//kPa MW = 58; T1 = 280.8;//K Ps = 5;//kPa pr = 2;//kJ/kgK ( Psychometric ratio ) Hvap = 360;//kJ/kg Tw = T1; Yw1 = Ps * MW / (( P - Ps) * 29); // Tw = Tg - Hvap * ( Yw1 - Y1) / (hG / kY), where hG/kY is the psychmetric ratio pr Y1 = 0; Tg = Tw + Hvap * ( Yw1 - Y1) / pr; disp("K",Tg,"The a...
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ok_sat.tst
(set-logic QF_UF) (declare-fun p () Bool) (declare-fun q () Bool) (assert (or p q)) (assert (not p)) (check-sat)
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errcatch(-1,"stop");mode(2);//gauss' formula //example 6.19 //page 242 ;; u=[-0.86113 -0.33998 0.33998 0.86113]; W=[0.34785 0.65214 0.65214 0.34785]; I=0; for i=1:4 I=I+(u(i)+1)*W(i); end I=I/4; printf(' the value of integrand is : %0.5f',I); exit();
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Hamster Wheel Switching.sce
Name=Hamster Wheel Switching PlayerCharacters=HWS Player BotCharacters=HWS Bot Rotation.rot;HWS Bot Rotation Even.rot;HWS Bot Rotation Odd.rot IsChallenge=true Timelimit=300.0 PlayerProfile=HWS Player AddedBots=HWS Bot Rotation Even.rot;HWS Bot Rotation Odd.rot PlayerMaxLives=0 BotMaxLives=22;23 PlayerTeam=1 BotTeams=2...
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clc clear printf("Example 5.11 | Page number 133 \n\n"); //This is a theoritical question. Refer textbook for solution. printf("This is a theoritical question. Refer textbook for solution.")
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11_04.sce
clear clc k=0.307; //Given mean residence time(min) t=15; //For plug flow with negligible density fr_unconverted=exp(-k*t); printf("\n The fraction of reactant unconverted in a plug flow reactor is %f",fr_unconverted) //For the real reactor T=[5;10;15;20;25;30];//given time E=[0.03;0.05;0.05;0.04;0.02;0.01];/...
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6 9:0.25 14:1.5 16:0.05 18:0.07142857142857142 27:1.0 29:0.5 43:0.3333333333333333 44:0.25 56:0.3333333333333333 60:0.07692307692307693 64:0.5 70:0.125 78:0.3333333333333333 127:1.0 129:0.5 160:0.3333333333333333 183:0.25 199:1.0 200:1.0 230:0.3333333333333333 289:0.5 301:1.0 387:0.25 398:0.3333333333333333 442:0.2 578...
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clear; //clc(); d=6; s=0.3; r=12.5/1000; dab=6; dbc=6; dca=12; dsl=sqrt(0.7788*r*s); dm=(dab*dbc*dca)^(1/3); lb=2*log([dm/dsl])/10; xl=2*(%pi)*50*lb; ds1=0.7788*r*sqrt(2); l1=2*log([dm/ds1])/10; xl1=2*(%pi)*50*l1; printf("\n the line inductance is: %.3f Ohm/km\n",xl1/1000); pu_red=(xl1-...
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//Example 1.15<a> // Find wheather the following signal is periodic or not x3(n)=2*e^(%i*(t+%pi/4)) clc; t=-21:21; x=2*exp(%i*(t+%pi/4)); f=1/(2*%pi); N=1/f; disp('samples',N,'(b)the given signal is not periodic');
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// Example 4.9 clc; clear; close; // Given data V_BB= 1.8;// in V V_BE= 0.7;// in V R1= 10;// in kΩ R2= 2.2;// in kΩ R_E= 1;// in kΩ bita= 200; R= R1*R2/(R1+R2);// in kΩ R=R*10^3;// in Ω R_E= R_E*10^3;// in Ω I_E= (V_BB-V_BE)/(R_E+R/bita);// in mA disp(I_E*10^3,"The emitter current in mA is : ") disp("T...
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//chapter 33 //example5 clc //given i=200 //current in the strip in amp B=1.5 //magnetic field in wb/m2 n=8.4*10^28 //in m-3 e=1.6*10^-19 //in coul h=1.0*10^-3 //thickness of copper strip in metre w=2*10^-2 //width of copper strip in meter //calculation Vxy=i*B/(n*e*h) disp(Vxy,"Hall potential difference ar...
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//Chapter 10, Problem 16 clc; g1=12; //gain of stage 1 g2=15; //gain of stage 2 g3=-8; //gain of stage 3 P=g1+g2+g3; //Power ratio P1=10^(P/10); //calculating overall power gain printf("Overall power gain (P2/P1) = %f ",P1);
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clear clc //Example 10.12 disp('Example 10.12') w=poly(0,"w") s=%i*w; //j or iota is i G=10*s^3+17*s^2+8*s+1;//Kc has been removed here because in a single expression //two polynomials are not allowed w=roots(imag(G)); p=-real(G)//Real part of G Kc=horner(p,w) mprintf("The values outside which system is unstable \n...
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(unwatch all) (clear) (set-strategy depth) (open "Results//fuzzy.rsl" fuzzy "w") (dribble-on "Actual//fuzzy.out") (batch "fuzzy.bat") (dribble-off) (load "compline.clp") (printout fuzzy "fuzzy.bat differences are as follows:" crlf) (compare-files "Expected//fuzzy.out" "Actual//fuzzy.out" fuzzy) ; close result file (clo...
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clc //Example 18.3 //Strength of gear pair P=12e3 N=1000 phi=14.5 m=6 b=60 Np=30 Ng=75 yp=0.101 S_bend_perm=100e6 surface_endurance=600e6 E=100e9 printf('Beam Strength:\n\tBoth gears are made of same material, hence the pinion is weaker\n') Mt = (P*60)/(2*%pi*N) Rp=(m*Np)/2 F=Mt/Rp printf('...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Moving Frame of Reference test </description> <executable>IncNavierStokesSolver</executable> <parameters>Moving_reference_frame.xml</parameters> <files> <file description="Session File">Moving_reference_frame.xml</file> <file descri...
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clc; clear all; disp("Net heat flux") t1=100;// degree C temperature of one surface of the slab t2=0;// degree C temperature of another surface of the slab L=0.25;// m thickness of the wall k=387.6;// W/(m*K) thermal conductivity of the brick q = k*(t1-t2)/L ;// = Q/A W/m^2 rate of heat transfer disp ("W/m^2",q...
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//Determine the spectral efficiency using the given parameters Bw = 12.5e+3; Cd = 200; A = 8; At = 4000; N = 4; F = 4; C = Bw/Cd; Tc = C*A; Ts = 3; Tc1 = ((Tc/F) - Ts); N1 = At/A; T1 = 108.4 N = (T1*N1*1e+3)/(At*Bw); disp(C, 'No. of 200 Khz channels') disp(Tc, 'No. of traffic channels') disp(T...
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folder_add 111 cd 111 folder_add 222 cd 222 folder_add 333 cd / file_move aaa 111 file_move bbb 111 file_move ccc 111 file_move ddd 111/222 file_move eee 111/222 file_move fff 111/222 file_move ggg 111/222/333 file_move hhh 111/222/333 file_move iii 111/222/333 branch objects 111/ 111/222/ 111/222/333/ 111/222/333/ggg*...
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// Exa 3.17 clc; clear; close; // Gievn data D_n = 35;// in cm^2/sec q = 1.6*10^-19;// in C y2 = 6*10^16;// in /cm^3 y1 = 10^17;// in /cm^3 x2 = 2*10^-4; x1 = 0; dnBYdx = (y2-y1)/(x2-x1); J_n = q*D_n*dnBYdx;// in A/cm^2 disp(J_n,"The current density in A/cm^2 is");
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/* Generated at yyyy-mm-dd hh:mm by java -cp dist/ramath.jar org.teherba.ramath.ProgramGenerator -l 2 -f test/PG21.data.tmp pident Do N O T edit this file, but ProgramGenerator.java instead! */ #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int reslines = 0; printf("#---> start ...
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//Area of indicator diagram(in mm^2) Area=2000; //Length of indicaor diagram(in mm) l=100; //Deflection of pointer(in bar/mm) d=2/10; //Stroke of the engine(in m) L=0.1; //Bore of the engine(in m) D=0.1; //Speed of the engine(in rpm) N=1000; //Mechanical effciency nm=0.75;
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clc clear //Initialization of variables pi=14.7 //psia pf=50 //psia cp=0.240 //Btu/lb R cv=0.170 //Btu/lb R J=778 T=60+459.6 //R //calculations R=J*(cp-cv) k=cp/cv gam=pi*144/(R*T) V=1/gam Vf=V*(pi/pf)^(1/k) Tf=T*(pf*Vf/(pi*V)) //results printf("Initial volume = %.2f ft^3",V) printf("\n Final volume =...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AutoTestC version="2.0.0"> <Pulse>CUSTOM WAVE</Pulse> <Title>9V Vmin</Title> <Organization>Daimler Chrysler</Organization> <Standard>DC-10615-E 2007</Standard> <Item>7.7 Supply Voltage Ramp Down</Item> <voltage>13.5</voltage> <count>5<...
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//clc() NA = 100;//mol ( basi - 100 mol A in the fresh feed ) Pconv = 95;//% NApro = NA * (100 - Pconv)/100; //A = 2B + C NB = NA * Pconv * 2 / 100; NC = NA * Pconv/100; PAent = 0.5;//% NAent = NApro * 100 / PAent; PBrec = 1;//% NBent = NB * 100 / (100 - PBrec); m = (NAent - NApro + NA); conv = ((NAent - N...
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//Example 5.4 //Root locus for satellite attitude control with modified //PD control or Lead compensator. xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ //System transfer function and its root locus s=poly(0,'s'); sysL=(s+1)/(...
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clear /* Os algoritmos do Arquivo EDO_MMQ.sce São implementações dos métodos de EULER de primeiro grau e segundo grau, e Runge-Kutta de primeiro, segundo grau, Runge-Kutta de ordem 4 segundo grau , Algoritmo Ajuste Linear Polinomial,respectivamente. */ exec("EDO_MMQ.sce") function plotEDOResult(x,y,icon,description) ...
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//========================================================================================= // chapter 4 example 11 clc; clear; //input data E = 1.46*10^-10; //permitivity in c^2*N^-1*m^-2 E0 = 8.885*10^-12; // permitivity in c^2*N^-1*m^-2 //calculation Er ...
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//CHAPTER 2,ILLUSTRATION 8 PAGE 62 //TITLE:TRANSMISSION OF MOTION AND POWER BY BELTS AND PULLEYS clc clear //INPUT t=9//THICKNESS IN mm b=250//WIDTH IN mm D=90//DIAMETER OF PULLEY IN cm N=336//SPEED IN rpm PI=3.141 U=.35//COEFFICIENT FRICTION e=2.71 THETA=120*PI/180 Fb=2//STRESS IN MPa d=1000//DENSITY IN ...