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//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi //chapter 9 //example 9.6 //edition 1 //publisher and place:Nelson Engineering clc; clear; Ra=1;//armature resistance in ohm KQ=3;//field constant V=480;//Terminal voltage in volts Tl=120;//load torque in Nm alpha=30;//triggering angle...
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////Ex 11.2 clc; clear; close; format('v',7); R1=10;//kohm k=1.38*10^-23;//J/K T=298;//K q=1.6*10^-19;//C Kdash=k*T/q;//Kdash=k*T/q assumed for temporary calculation disp("Output Voltahe, Vout(V) is "+string(-Kdash)+"*log(Vin/10*10^3)");
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//Ex 2.6.4 clc;clear;close; format('v',6); //Given : rho_p=2;//ohm-cm rho_p=rho_p*10^-2;//ohm-m rho_n=1;//ohm-cm rho_n=rho_n*10^-2;//ohm-m mu_n=1500*10^-4;//m^2/V-s mu_p=2100*10^-4;//m^2/V-s ni=2.5*10^13;//per m^3 q=1.6*10^-19;//Coulomb sigma_p=1/rho_p;//(ohm-m)^-1 NA=sigma_p/q/mu_p;//m^3 sigma_n=1/rho...
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clear //Given u=-10.0 //cm f=-15.0 //Calculation v=1/((1/f)-(1/u)) m=-v/u //Result printf("\n (i) Image position is %0.3f cm", v)
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function getvaluesfromcolormap(filename,colormapstring) f_temp = mopen(filename, 'wt'); // Creating a text file string_to_pass = strcat(["cmp_value_from_script = [",colormapstring,"]"]); //forming string ok = execstr(string_to_pass,'errcatch'); if (ok~=0) then mfprintf(f_temp, '%s', lasterror()...
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function[icp,in,t]=iterative_binary(A,l,h,k,icp,itime) tic(); in=-1; while (l<=h) icp = icp+1; mid=round((l+h)/2); if ( A(mid) == k) in=mid; break; end if (A(mid) < k) l=mid+1; else h=mid-1; end ...
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a b b o u d เ อ ิ ป บ ู ด a b b y แ อ ็ บ บ ี ้ a b e เ อ บ a b e n d r o t h อ บ ิ น ด ร อ ท a b e r d a r e แ อ ็ บ เ บ อ ร ์ แ ด ร ์ a b e r d e e n แ อ เ บ อ ร ์ ด ี น a b e r d e e n แ อ ็ บ เ บ อ ร ์ ด ี น a b l e r เ อ เ บ อ เ ล อ ร ์ a b r a m s เ อ เ บ ร ิ ม ส ์ a b s o r b a n c e แ อ บ ซ อ ร ์ แ บ น ซ ์ a b ...
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//Example 8.6.2: Cx,Rx and D clc; clear; close; //given data : f=1000;//in Hz R1=1.1;// in kilo-ohm R2=2.2;// in kilo-ohm C1=0.47;// in micro-farad C3=0.5;// in micro-farad Rx=(R2*C1)/C3; disp(Rx,"unknown resistance,Rx(k-ohm) = ") Cx=(R1*C3)/R2; disp(Cx,"unknown capacitance,Cx(micro-farad) = ") w=2*f*%pi; D=w*Cx*10^-6*...
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[test,ilib] = c_link( "libpremiamodel_Interf"); if ~test then exec('../../loader.sce'); premia_init(); end load('test-premia-1.bin'); L=P.get_option_values[]; // Maturity if exists('Maturity') then L(2)(3)=Maturity;end if exists('Strike') then L(3)(3)=Strike;end P.set_option_values[L]; P.compute[]; L=P.get_metho...
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//5. Schaubild Höhenlinien //geht nicht!!! xy = linspace(-%pi, %pi, 40); [X, Y] = meshgrid(xy); F = sin(X.^2 + Y.^2)./(X.^2 + Y.^2); contour(xy, xy, F) //Achsenbeschriftung a = gca(); // a.font_size = 2; //Schriftgröße für x,y,z scala xlabel('x-Achse', 'fontsize', 5) ylabel('y-Achse', ...
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//variable initialization h=6.63*10^-34; //planck's constant (joule-second) m_n=1.67*10^-27; //mass of neutron (kg) T=300 ...
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//Chapter-4, Illustration 4, Page 135 //Title: Gears and Gear Drivers //============================================================================= clc clear //INPUT DATA x=3.5;//Ratio of teeth of wheels C=1.2;//Centre distance between axes in m DP=4.4;//Diametrical pitch in cm //CALCULATIONS D=2*C*100;...
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//To find initial tension and diameter clc //Given: PT=24 //kW d=400/1000 //m N=110 //rpm funcprot(0) beta=45/2 //degrees theta=160*%pi/180 //radians mu=0.28 n=10 //Solution: //Initial tension: //Calculating the power transmitted per rope P=PT/n*1000 //W //Calculating the velocity of the rope v=%pi*d*N/...
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clear; clc; // Illustration 7.5 // Page: 228 printf('Illustration 7.5 - Page: 228\n\n'); printf('Illustration 7.5 (a)\n\n'); // solution(a) //****Data****// // A = benzene vapour; B = Nitrogen Gas P = 1;// [atm] //*****// MA = 78.05;// [kg/kmol] MB = 28.02;// [kg/kmol] // Since gas is saturated, ...
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//Example number 1.7, Page number 1.37 clc;clear;close //Variable declaration Beta=0.00227 //distance between adjascent green lines D=2.5 // in m d=0.0006 //distance between narrow slits //Calculation lamda=(Beta*d)/D // in m //Result printf("Wavelength,lamda=%.4e m",(lamda)) //Answer varies...
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function [x] = lsolve ( L, b) n = size( L, "r"); x = zeros (n); x(1) = b(1)/L(1, 1); for i = 2:n x(i) = (b(i) - L( i, 1:(i-1))*x( 1:(i-1)))/L(i,i); end endfunction
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//---------------- first test filen = 'test.bin'; mopen(filen,'wb'); mput(1996,'l');mput(1996,'i');mput(1996,'s');mput(98,'c'); mput(1996,'ul');mput(1996,'ui');mput(1996,'us');mput(98,'uc'); mput(1996,'d');mput(1996,'f'); // force little-endian mput(1996,'ll');mput(1996,'il');mput(1996,'sl');mput(98,'cl')...
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clear; //clc(); max_dem=80; pf=0.45; tar_md=750; tar_en=1.1; ann_ener_cons=max_dem*pf*8760; ce=1.1*ann_ener_cons; cf=tar_md*max_dem; tot=ce+cf; cost_per_kwh=tot/ann_ener_cons; printf("the overall cost is:%.2f Rs",cost_per_kwh);
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// Scilab Code Ex2.7: Page-2.25 (2004) clc;clear; M = 63.5; // Atomic weight of Copper, g per mol N = 6.023e+23; // Avagadro number, per mol r = 1.278e-8; // Atomic radius of copper, cm m = M/N; // Mass of one Cu atom, kg a = (4*r)/sqrt(2); // Distance between two adjacent atom in Cu, angstrom n1 = 4*m; ...
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//Example 10.5// //(a) = For 0.5 wt % C steel indicates that complete bainite formation will have ocuurred 5degree C above Ms,by a=180;//s //second b=1;//m //minute c=60;//s//seconds d=a*(b/c) mprintf("d= %i min",d) //(b)= For 0.77 wt % C steel gives a time of a1=1.9*10^4;//s //seconds b1=3600;//s/h //seconds ...
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// Find the diode currents // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 3-2 in page 144 clear; clc; close; // Given data R=10*10^3; // Resistance in K-ohms // Calculation printf("(a) R = 10K.Assume both diodes are conducting.We have:\n");...
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function r=mtlb_exist(nam) // Copyright INRIA fptr=funptr(nam) if fptr<>0 then fptr=int(fptr/100) if fptr<=500 then r=5 else r=3 end elseif exists(nam)==1 then if type(nam)==11|type(nam)==13 then r=2 else r=1 end end
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اِسْتَصْدَرَ تَسْتَصْدِرْنَ V;2;PL;FEM;IPFV;IND;ACT كِيلُومِتْرٌ كِيلُومِتْرٌ N;SG;NDEF;NOM الْعَمِيق عُمُقًا ADJ;PL;MASC;NDEF;ACC اِسْتِقَامَةٌ الِاسْتِقَامَةَ N;SG;DEF;ACC فِكْرَةٌ الْفِكْرَة N;SG;DEF;INFM مِعًى أَمْعَاءً N;PL;NDEF;ACC رَمَادٌ الْأَرْمِدَةِ N;PL;DEF;GEN ضَاعَ يَضِيعُونَ V;3;PL;MASC;IPFV;IND;ACT السُّ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; //clf; clc; // Constants g = 9.81; u0 = 0; v0 = 0; b = 2; h0 = 5030; damp=0.0; force=0.1; forcefreq=0.1; k=2.5; // Define the x domain ni = 1001; xmax = 10.0; dx = xmax/(ni-1); x = 0:dx:xmax; // Define the y domain nj = 51;...
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// Example 4_7 clc;funcprot(0); // Given data D_1=0;// m D_2=0.0500;// m Sigma_s=0.0400;// N/m (constant) // Solution A_1=0;// m^2 R_2=D_2/2;// m A_2=2*(4*%pi*R_2^2);// m^2 W_12=-Sigma_s*(A_2-A_1);// J W_12=W_12/1055;// Btu printf('\nThe amount of surface tension work required to inflate the soap bubble,...
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//Ex8_9 clc alpha=1.414// Damping coefficient for Butterworth LP filter disp("alpha="+string(alpha)) AM=3-alpha disp("AM="+string(AM)) // Midband gain of filter fOH=1*10^(3) disp("fOH= "+string(fOH)+" Hz")//Cut off frequency R1=10*10^(3)// Choosing value of R1 same as in book disp("R1= "+string(R1)+ " ohm") ...
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//Chapter 10 //Example 10_12 //Page 245 clear;clc; f=50; ll=100; pd=20*1e6; pfr=0.9; v_r=110*1e3; r=0.2; xl=0.4; y=2.5*1e-6; tr=r*ll; txl=ll*xl; ty=ll*y; vr=v_r/sqrt(3); ir=pd/sqrt(3)/v_r/pfr; z=tr+%i*txl; ir_p=ir*(pfr-%i*sin(acos(pfr))); v1=vr+ir_p*z/2; ic=%i*ty*v1; is=ir_p+ic; vs=v1+is*z/2; lv=abs(vs)*sqrt(3); lo...
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clc; clear; //Takes input and check whether it is valid logic level or not. w=input("w = "); while(w~=0 & w~=1) disp("enter a valid logical level"); w=input("w = "); end x=input("x = "); while(x~=0 & x~=1) disp("enter a valid logical level"); x=input("x = "); end y=input("y = "); while(y~=...
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//OCF form s=%s A=[1 2 1;0 1 3;1 1 1] B=[1;0;1] [row,col]=size(A) c=s*eye(row,col)-A x=det(c) r=coeff(x) M=[r(1,2) r(1,3) 1;r(1,3) 1 0;1 0 0] S=[B A*B A^2*B] disp(S,"controllability matrix=") if (det(S)==0) then printf("system cannot be transformed into ccf form") else printf("system can be transf...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.378518D+00 ...
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// ----------------------------------------------------------------------- /// \brief Calcule un terme de contrainte a partir d'une homographie. /// /// \param H: matrice 3*3 définissant l'homographie. /// \param i: premiere colonne. /// \param j: deuxieme colonne. /// \return vecteur definissant le terme de contrainte...
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clear;lines(0); x=[1,%i,-1,-%i] tan(x) sin(x)./cos(x)
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Name=Air Dodge II PlayerCharacters=A BotCharacters=Air2 Rotation.rot IsChallenge=true Timelimit=240.0 PlayerProfile=A AddedBots=Air2 Rotation.rot PlayerMaxLives=0 BotMaxLives=8 PlayerTeam=2 BotTeams=1 MapName=boxerliprounded.map MapScale=6.0 BlockProjectilePredictors=false BlockCheats=true InvinciblePlayer=false Invinc...
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clc;clear;close; A=[] disp("-------------------------------------------------------------------------") printf("\n Enter 3 independent vectors to form of 3X3 matrix:\n") for j=1:3 printf("\n Enter vector v%d:\n",j); for i=1:3 A(i,j)=input(""); end end v1=A(:,1) v2=A(:,2) v3=A(:,3) printf("T...
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//calculate the reluctance and current A=5e-4 N=250 l=50e-2 F=700e-6 u=380 S=l/(4*%pi*10^-7*A*u) I=F*S/N disp('current='+string(I)+'amps' , 'reluctance ='+string(S)+'AT/Wb')
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//calculating the sum of resistances connected in series with uncertainity of one unit clc; R1=72.3; R2=2.73; R3=0.612; R=(R1+R2+R3); disp(R,'sum of resistances(ohm) ='); disp('the resultant resistance is 75.6 ohm with 6 as first doutful figure')
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//Chemical Engineering Thermodynamics //Chapter 9 //Fluid Flow in Pipes and Nozzles //Example 9.1 clear; clc; //Given R = 848;//gas constant in m Kgf/Kgmole K M = 29;//molecular weight of air g = 9.81; T1 = 90+273;//initial temperature in K y = 1.4;//gamma = Cp/Cv W = 800/3600;//Mass rate of air in Kg/sec...
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clear global SkedData SkedData = struct('SP_Tr',0,'alfa',0,'alfaBlock',0,... 'krr',0,'zrr',0,'kpi',0,'bmin',0,'bmax',0,... 'SP_Tp',0,... 'eTp',0,'eTr',0,'eTro',0,'bc',0,'bco',0,'b',0,'bo',0,... 'Tp',0,'Tr',0,'t',0,... 'dmod',0,'dm...
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//Eg-10.5 //pg-437 clear clc close() X = [0;5;10;15]; Y = [53;127;213;378]; T = zeros(4,4); T(:,1) = Y; for(j = 2:4) for(i = 1:4+1-j) T(i,j) = T(i+1,j-1) - T(i,j-1); end end //disp(T) // Using Gauss backward formula //p3 = f + d*A + d2*A(A+1)/2 + d3*A*(A-1)*(A+1)/6 /...
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// sum 6-3 clc; clear; P=((4*360)+(2*360))/900; Fv=4-2; Fh=P; Fr=sqrt(Fv^2+Fh^2); P1=4*0.36/0.9; Rf=sqrt(4^2+1.6^2); d=sqrt(Rf*10^3/(15*1.25)); d=16; l=1.25*d; T=Rf*10^3*4/(2*%pi*d^2); D=2*d; M1=Rf*10^3*(360-(D/2)); pa=15; h=80; b=h/4; Z=b*h^2/6; sigb=M1/Z; T=4310/(b*h); pmax=(sigb/2)+sqrt((sigb/2)...
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; cos.tst - Directed test cases for cosine ; ; Copyright (C) 1999-2015, ARM Limited, All Rights Reserved ; SPDX-License-Identifier: Apache-2.0 ; ; Licensed under the Apache License, Version 2.0 (the "License"); you may ; not use this file except in compliance with the License. ; You may obtain a copy of the License at ...
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//Section-5,Example-4,Page no.-D.124 //To calculate the energy required for dissociation of 1 bond clc; B_E=95*10^3 //Bond energy h=6.626*10^-34 c=3*10^8 lm=2450*10^-10 E=(h*c)/lm E_1=E*(1/4.184) //Energy in Calories disp(E_1) N_A=6.023*10^23 Ebar=B_E/N_A disp(Ebar,'Energy...
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Expanding for base=2, level=7, reasons+features=base,same,similiar invall,norm,showfail Refined variables=a,b [0+1a,0+1b]: unknown -> [1] [0,0] a²-3b²-8 ---------------- level 0 expanding queue[0]^-1,meter=[2,2]: a²-3b²-8 [0+2a,0+2b]: similiar [0], is mappable by: {a=>a,b=>b} [1+2a,0+2b]: failure constant=-7, vgcd=4...
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// Example 4.1 // Node Analysis with One Unknown // From figure 4.3 G_11=1/6+1/(5+7)+1/4; // Sum of all conductance connected at node 1 i_s1=18/6+(-60/4); // Net equivalent source current into node 1 // From node equation G_11*v_1=i_s1 v_1=i_s1/G_11; // Node voltage v_1 // Using Ohm's Law i_a=(18-v_1)/6; //...
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.idc.ac.il/tecs // File name: projects/01/IsNeg16.tst load IsNeg16.hdl, output-file IsNeg16.out, compare-to IsNeg16.cmp, output-list in%B1.16.1 out%B3.1.3; set in %B0...
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clc clear //At 10 bar Hg=2778.1; //in kJ/kg Cp=2.1; //in kJ/kg K T=50; CV=30000; //in kJ/kg H=Hg+(Cp*T); C=4.187; Tf=30; Hfw=C*Tf; Ms=800/100; Me=(Ms*(H-Hfw))/2257; printf('Equivalent Evaporation: %3.2f kg/kg of coal',Me); printf('\n'); Eff=(Ms*100*(H-Hfw)...
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15 1:0.06349206349206349 4:1.0 19:2.0 40:1.0 60:0.16666666666666666 75:1.0 195:1.0 243:1.0 317:2.0 372:0.5 15 4:1.0 17:0.05263157894736842 114:1.0 122:1.0 193:1.0 228:0.25 259:1.0 395:0.5 989:1.0 1094:1.0 1157:1.0 15 4:3.0 17:0.05263157894736842 19:2.0 36:0.2857142857142857 40:4.0 53:0.1111111111111111 55:1.0 72:1.0 85...
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clc; clear; close; x = [-1 -0.75 -0.6 -0.5 -0.3 0 0.2 0.4 0.5 0.7 1] y = [2.05 1.153 0.45 0.4 0.5 0 0.2 0.6 0.512 1.2 2.05] n = size(x,'c') sumX = sum(x,'c') sumX2 = sum(x^2,'c') sumX3 = sum(x^3,'c') sumX4 = sum(x^4,'c') sumY = sum(y,'c') sumYX = sum(y.*x,'c') sumYX2 = sum(y.*x^2,'c') A = [n sumX sumX2; sumX sumX2 ...
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clc; // page no 143 // prob no 4_17_1 //An attenuator is given with insertion loss of 6 dB //Noise fig is equivalent to insertion loss F=6;//Noise fig.=6 dB //Determination of noise factor Fn=10^(6/10); disp(Fn,'The value of noise factor is ');
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//Ex:59 clc; clear; close; G=6.67*10^(-11);//Gravitation const in N-m^2/kg^2 r_e=6360*10^3;//radius of earth in m h=640*10^3;// height in m m=5.98*10^24;//mass of earth in kg u=G*m; v=sqrt(u/(r_e+h));// velocity in km/s V=7.54;// km/s t=(2*3.14*(r_e+h)/1000)/V; printf("The orbital period=%d s",t); printf("...
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//Ex:9.3 clc; clear; close; e_c=1;// number of electron collected p=3;// number of photon incident n=e_c/p;// quantum efficiency e=1.602*10^-19;// charge h=6.626*10^-34;// plank constant c=3*10^8;// speed of light in m/s y=0.8*10^-6// wavelength in m Eg=(h*c)/y;// band gap energy in J R=(n*e*y)/(h*c);// res...
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//scilab 5.4.1 //windows 7 operating system //chapter 5:Semiconductor Junction Diodes clc clear //T1,T2=Temperature in kelvin //Is1=Reverse saturation current at temperature T1 in ampere //Is2=Reverse saturation current at temperature T2 in ampere //Is2=Is1*2^((T2-T1)/10) //((T2-T1)/10)*log(2)=log(Is2/Is1) /...
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clear; clc; xs=.22; xl=.15; Sb=1000; Vr=1; X=xl+xs; Pr=1; pf=.8; pfa=acos(pf); Qr=Pr*tan(pfa); Vs=complex(Vr + (X * Qr / Vr) , (X * Pr / Vr)); V=abs(Vs); mprintf("Vr = %.2f ang (%.1f) deg pu",V, fix(atand(imag(Vs)/real(Vs))*10)/10)
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//Ex:4.28 clc; clear; close; A=5;// area in m^2 w=25*10^-3;// power in watt f=15;// frequency in MHz y=300/f;// wavelength in m Rr=31171*(A/y^2)^2;// radiation resistance in ohm V=sqrt(w*4*Rr);// max emf in volts printf("The max emf = %f Volts", V);
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clc; funcprot(0); // Initialization of Variable theta=25+14.0/60;//latitude in degrees in North L1=29+15/60;//longitude in degrees in West L2=45+25/60;//longitude in degrees in West R=6370.0;//radius in km //calculation AB=cos(theta*%pi/180)*(L2-L1);//arc length in km dis=2*%pi*R*AB/360.0;//distance in km di...
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// Scilab Code Ex1.9 Ratio of rest mass and mass in motion: Pg:23 (2008) c = 1; // For convenience, speed of light is assumed to be unity, m/s v = 0.5*c; // Velocity of moving particle, m/s // As m0 = m*sqrt(1 - (v/c)^2), and m0/m = rel_mass, we have rel_mass = sqrt(1 - (v/c)^2); // Ratio of rest mass and ...
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// example:-7.3,page no.-347. // program to find required length,d and Q for l=1 and l=2 resonator mode. a=0.04755;b=0.02215;eipsilar=2.25;tandelta=0.0004;f=5*10^9;c=3*10^8; k=(2*%pi*f*sqrt(eipsilar))/c // wave number. for l=1:1:2 d=(l*%pi)/sqrt((k^2)-((%pi/b)^2)); // m=1 & n=0 mode. disp(d,'d in meter = ') end ...
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splitter P {} fIltEr Dg { } FIlTER c {NOt B or R oR noT eI Or nOt DvG w not vF Or u } K -> HRf -> G -> J -> Kr GRoupER qR {MoDuLe e{ } aGgrEgaTE Min(ch) as EP } UNgroUPER e { } GroUPFiLTeR KOr {} MerGer ql { MOduLE d { bRaNChES r, xgl, CGm nOt 8327 NoT in B::1D:3EC:eE:De:b/74 e ( aC:de:dE:e6:Ea:b0 ) } M...
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clc; //Example 33.9 //page no 531 printf("\n Example 33.9 page no 531\n\n"); //refer to example no 33.8 Y=74//age in year d=365//days h=24//hours m=60//minutes b=80//heart beats per minutes T=Y*d*h*m*b// no. of times heart beats v=70//volume of blood discharge with each blood,ml V=T*v//volume of blood that...
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//Exa:1.37 clc; clear; close; P_o=45*1000;//in watts R_a=0.2;//in ohms V=500;//in volts Eff=0.9;//Efficiency I_lf=P_o/(V*Eff);//Rated Line current (in amperes) R_sh=200;//in ohms I_sh=V/R_sh;//Shunt feild Current (in amperes) I_af=I_lf-I_sh;//Armature current on full load (in Amperes) E_f=V-I_af*R_a;//emf i...
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clear ; clc; // Example 3.7 printf('Example 3.7\n\n'); printf('Page No. 68\n\n'); // given Pc = 10000;// Capital cost for project C in Pound Pd = 10000;// Capital cost for project d in Pound nc = 3;// pay back period for C nd = 3;// pay back period for D Ca = [4500 3500 2000 2000 1000];// Annual Cash flow f...
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//Problem 12.02: //initializing the variables: xEtOH = 0.3; // mol% ethanol //calculation: xwater = 1 - xEtOH printf("\n\nResult\n\n") printf("\n the liquid mole fractions is %.2f ",xwater)
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clc //Initialization of variables dz=260 //ft ke=0.5 f=0.02 l=5000 //ft D=10 //in A2=0.545 //calculations V2by2g=dz/(1 + ke + f*l/(D/12)) V2=V2by2g*2*32.2 V=sqrt(V2) DV=D*V Q=%pi/4 *(D/12)^2 *V //results printf("Flow rate = %.2f cfs",Q)
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//Finding of Efficiency ,Slip //Given Nb=780; Na=800; //To Find E=Nb/Na; E1=E*100; S=100-E1; disp("Efficiency ="+string(E1)+" percentage"); disp("Slip ="+string(S)+" Percentage");
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clc; // From fig 1.45 N1=1000; // no of turns on primary N2=400; // no. of turns on secondary n2=300; // no. of turns across points A and B l1=600; // a load of 600 KW connected between points A and C l2=60+60*%i; // load connected between points A and B E=30000; // primary supply voltage vac=E*(N2/N1); // seco...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/Add16.tst load Add16.hdl, output-file AddSub.out, compare-to AddSub.cmp, output-list a%B1.16.1 b%B1.16.1 out%B1.16.1; set a %B0000000000000000, set b %B0000000...
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//Example 4.19 //reading and writing a line of text line=input("Enter a line of text (upto 80 characters):","string"); printf("%s", line);
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/*------------------------------------------------- Auteur : Manon Cassagne & Valentin Labat Vous trouverez ci-dessous les fonctions de reconstruction et les fonctions nécessaires à cette reconstruction ---------------------------------------------------*/ // Permet de pouvoir appeler les fonctions qui se trouven...
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ns=2*10^12; E1=(1.11*10^-19)*((ns)^(2/3)); E2=(1.95*10^-19)*((ns)^(2/3)); printf('\n The value of E1 is %feV',E1*10^10); printf('\n The value of E2 is %feV',E2*10^10); Ef=0.24418; nE=2.79*10^13; a=0.026; //say a=K*T/q ns1=nE*a*log(1+exp((Ef-(E1*10^10))/a)); ns2=nE*a*log(1+exp((Ef-(E2*10^10))/a)); printf('\n ...
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errcatch(-1,"stop");mode(2);//Ex:2.31 ; ; L1=60;//in mH L2=60;//in mH L_a=L1+L2; L3=120;//in mH L_b=L_a*L3/(L_a+L3); L4=50;//in mH L_eq=L4+L_b; printf("Equivalent Inductance = %d mH",L_eq); exit();
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clear; close; clc; //in standard units vsat=8*(10^4); tox=22*(10^(-10)); vgs=1.2; vt=0.4; cl=100*(10^(-9)); eo=8.85*(10^(-12)); cox=(4*eo)/tox; enln=6*(10^6)*cl; eplp=24*(10^6)*cl; ids1=(vsat*cox*((vgs-vt)^2))/(vgs-vt+enln); ids2=(vsat*cox*((vgs-vt)^2))/(vgs-vt+eplp); disp(ids1,'saturation current of NMOS(...
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function varargout = misdata(varargin) [lhs,rhs] = argn(0) //------------------------------------------------------------------------------ // checking the number of inputs if rhs <> 1 then error(msprintf(gettext("%s:Wrong number of input arguments.\n"),"misdata")) end //----------------------------...
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clc a = 1.50 //saving in labour b=55/100 // burden applied on labour T = 4/100 // allowance for taxes M = 5/100 // allowance for maintenance I = 8/100 // interest rate D = 50/100 // allowance for depreciation H = 2 // years to amortize the investment S = 50 // yearly cost for set up C = 3000 // first cost N1 ...
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//Example 9.7, page 355 clc Z=92 n=2 E=((Z/n)**2)*13.6//in ev printf("\n The ionization energy is %e ev",E) //Answer difference is because of round off
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funcprot(0) // évite l'avertissement réécrire fonction //function nouveau=suivant(actuel,nombreBoules) // alea = grand(1,1,"uin",1,nombreBoules) // if (alea<=actuel) // nouveau=actuel+1 // else // nouveau=actuel // end //endfunction function nouveau=suivant(actuel,nombreBoules) [Nech,_]=size(actuel) ale...
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//Harriot P., 2003, Chemical Reactor Design (I-Edition), Marcel Dekker, Inc., USA, pp 436. //Chapter-10 Ex10.2 Pg No. 414 //Title:Conversion as a function of No. of Gauzes //=========================================================================================================== clear clc // COMMON INPUT M_NH3...
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funcao_pendulo.sce
function pendulo = funcao_pendulo(r1,r2,r3,w0,x,n) pendulo = (r1 + r2*cosseno_taylor(w0*x,n) + r3*seno_taylor(w0*x,n)); endfunction
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SOS.sce
//**************************** SOS ********************************** if (blk_name.entries(bl) =='SOS') then mputl("# SOS",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) SOS_str= '.subckt speech in[0]=net' + string(blk(blk_objs(bl),2))+"_" + string(ss)+" out[0]=net'+ string(blk(blk_objs(bl),2+numofip))+"_...
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clc; warning("off"); printf("\n\n example7.12 - pg301"); // given Q=50/(7.48*60); //[ft/sec] - volumetric flow rate of water d1=1; //[inch] - diameter of pipe deltaz=-5; //[ft] - distance between end of pipe and tank g=32.1; //[ft/sec] - acceleration due to gravity Cp=1; //[Btu/lb*F] - heat capacity of wat...
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# - Header - # # - Disc Threshold One - # scenario = "17_March_2015"; # - Screen Parameters - # default_font_size = 26 ; default_font = "Arial"; default_text_color = 0, 0, 0; write_codes = true; screen_width = 1024; screen_height = 768; screen_bit_depth = 32; default_background_color = 200, 200, 200; ...
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// Theory and Problems of Thermodynamics // Chapter 9 // Air_water Vapor Mixtures // Example 2 clear ;clc; //Given data X1 = 0.5 // volume fraction of propane X2 = 0.5 // volume fraction of oxygen P1 = 0.1 // initial pressure of mixture in MPa T1 = 300 ...
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//Compute Loss of energy clc; clear; w=10; f=50;// 50 cycles in a second. ls_vol=250; density=7.5;// Density in gm/cm^3 d= density*(10^6)/(10^3); vol=w/d; ls_cycle= ls_vol*vol; ls_sec= ls_cycle*50; ls_hr= ls_sec*3600; disp('joules',ls_hr,'The Loss of energy per hour of an iron loop')
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//Exa 1.2 clc; clear all; //Refering to table 1.1- Set of 10 measurements that were recorded in the laboratory. X={98;101;102;97;101;100;103;98;106;99}; //From table 1.1 //solution X_n= mean(X); //Average value Prec=1-abs((X(6)-X_n)/X_n);//precision of 6th reading printf('The precision of 6th measuremen...
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clear; clc; close; Id_on = 4*10^(-3); Vgs_on = 6; Vgs_th = 3; Vgs = Vgs_on; Vdd = 2*Vgs; Vds = Vgs; Id = Id_on; Rd = (Vdd-Vds)/Id; disp(Rd,'Rd(Ohms) = ');
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function [stk,txt,top]=sci_tril() // Copyright INRIA txt=[] if rhs==2 then s1=stk(top-1) stk=list('tril('+s1(1)+','+stk(top)(1)+')','0',s1(3),s1(4),s1(5),'?') top=top-1 else s1=stk(top) stk=list('tril('+s1(1)+')','0',s1(3),s1(4),s1(5),'?') end
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function y=f(x) //y=1./(1+x^2) //y=x //y=(1-x^2)^(3/2) //y=log(3+x) y=1./(x-1) endfunction //Grafico f(x) x=-2:0.1:2; plot2d(x, f(x)); //muestra grilla xgrid(3,1,7); function I=inf(a,b,N,f) h=(b-a)/N printf("\nTamanio del paso h = %12.9f",h); x=a // Extremo inferior I=0 for i=0:...
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clear; clc; close; disp("Example 5.6") M9=1 // Mach no. p=1/8 //p=p0/pt7 gm=1.3 //gamma V9cd=(2*(1-p^((gm-1)/gm)))^(1/2) px=p*((gm+1)/2)^(gm/(gm-1)) V9c=(2*(gm-1)/(gm+1))^(1/2) FR=(V9cd/V9c)/(1+(1-px)/gm) pr=(FR-1)*100/1 disp(pr,"% increase in gross thrust:")
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errcatch(-1,"stop");mode(2);//Example 3.26 : density ; ; //given data : format('v',5) n=4; N=6.023*10^23; // avogadro's number r=1.278*10^-8;// in cm A=63.5; a=(r*4)/sqrt(2);// in cm b=(A*n)/(a^3*N); disp(b,"density of copper,b(g/cc) = ") exit();
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clc //initialisation of variables Ps= 200 //mm Pe= 390 //mm Pt= 300 //mm t= 500 //sec Pe1= 400 //mm //CALCULATIONS r= (Pe1-Pt)/(Pe1-Ps) //RESULTS printf ('fraction remained undecomposed= %.1f ',r)
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#-----------------------------------------------------------------------------------# # Incidental Learning Session for Statistical Learning/Rate Perception Study # Ava Kiai # # Log # 12/5/18 - v.0.0 # 2/4/19 - v.0.1 # 7/16/19 - v.2.0 #----------------------------------------------------------------...
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IK_target_RLeg_real = [0.069828271865844727, 0.23262149095535278, 0.35102164745330811]; //the foothold for the ith leg, in the leg attachment frame //disp(IK_target_RLeg); //HR Leg l1 = 0.1; l2 = 0.15; l3 = 0.3; xOff = [1 0 0]*0.15/2; yOff = [0 1 0]*0.3/2; offset_i = - xOff - yOff; orient = [-0.7022104 -0.4188790 ...
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*Testcase bfp-003-loadfpi.tst: CFEBR, CFEBRA, CFDBR, CFDBRA, CFXBR, CFXBRA #Testcase bfp-003-loadfpi.tst: IEEE Load FP Integer #..Includes LOAD FP INTEGER (6). Tests traps, exceptions, results #..from all rounding modes, and NaN propagation. sysclear archmode esame # # Following suppresses logging of program ch...
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//Derivacion Numerica clc x = [0 0.1 0.2 0.4 0.5 0.55]' y = [1.12 1.28 1.55 1.88 1.77 1.66]' M = [x^5 x^4 x^3 x^2 x ones(length(x),1)] v = M\y p = poly(v($:-1:1), 'x', 'c') disp(p) dp = derivat(p) disp(dp) xi = [0 0.25 0.5]//Evaluara p'(0), p'(0.25), p'(0.5) dpxi = horner(dp, xi) disp(dpxi)
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//using AmplNLReader //#nlp = AmplModel("../ampl/msqrtals") # loads the msqrtals.nl model [asl, x0, bl, bu, v, cl, cu] = ampl_init("msqrtals.nl"); //nlp = AmplModel("../ampl/curly10") # loads the msqrtals.nl model nvar = length(x0) //x0 = nlp.meta.x0 nbt=100000 mprintf("evaluating %i times the Hv product\n",nbt) go...
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function d = determinant(A) endfunction
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//Ex12.6.1.;calculate open circuit voltage and maximum power output B=2;//flux density;unit=Wb/m^2 u=10^3;//average gas velocity;unit=m/second d=0.50;//distance between plates;unit=m E0=B*u*d;//Open ccircuit voltage printf(" Open ccircuit voltage E0=%f Volts",E0); //Generator resistance; Rg=d/sigma*A sigma=10;//...
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-- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:REMOVED_CL_PREFIX TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCRIPT_FEATURE:STATIC_HEADER_FUNCS_IN_UUTS TEST.SCRIPT_FEATURE:VCAST_MAIN_NOT_RENAMED -- -...
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//Mission C2 //On récupère l'image pathname = "C:\Users\Jean-Guillaume P\Documents\Exia\A2\Projets\Imagerie\ExoLife\Images\Mission_Complementaire\Formes.pbm"; img_in = readpbm(pathname); //On crée l'élement structurant eStruct = [0, 0, 0;255, 255, 255;0, 0, 0]; //Erosion img_erosion = erosionBinaire(img_in, eStruct,...
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sci
Scilab_code_Results_validation.sci
// Optimal proteome allocation and the temperature dependence of microbial growth laws // Francis Mairet,Jean-Luc Gouzé, Hidde de Jong // npj Systems Biology and Applications // // SI: Scilab code for Figure 3 (validation) xdel(winsid()) clear ////////////////////// Parameters ////////////// R=8.314; Tref=31...