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s = %s sysl = syslin('c',1,(s*s+0.3*2*s+1)); xtitle( 'Second order step response with damping factor 0.3', 'X axis', 'Y axis' ) ; t =0:0.1:10; y = csim('step',t,sysl) plot(t,y)
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////Given W=3 //ev h=6.63*10**-34 e=1.6*10**-19 lembda=3.0*10**-7 //m c=3*10**8 //m/s //Calculation v0=(W*e)/h v=c/lembda E=h*(v-v0) E1=(h*(v-v0))/(1.6*10**-19) V0=E/e //Result printf("\n (a) Threshold frequency %0.2f...
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function contourf(x,y,z,nv,style,strf,leg,rect,nax) [nout,nin]=argn(0); if nin==0, s_mat=['t=-%pi:0.1:%pi;m=sin(t)''*cos(t);contourf(t,t,m);']; write(%io(2),s_mat);execstr(s_mat); return; end; if nin <= 8 then nax=[1,10,1,10];end if nin <= 7 then rect=[0,0,1,1];end if nin <= 6 then leg=" ";end if nin <= 5 the...
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//Chapter 3 : Systems of Linear Equations //Example 3.6 //Scilab 6.0.1 //Windows 10 clear; clc; lambda=3 //assume lambda to be 3 P=[1 lambda 0;0 1 0;0 0 1]; A=[1 3;5 7;9 11]; //let A be any 4*2 matrix disp(P,'P:') disp(A,'A:') disp(lambda,'lambda:') PA=P*A; disp(PA,'PA') mprintf('the effect of mul...
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//Example number 7.7, Page number 148 clc;clear; close; //Variable declaration epsilonr=1.0000684; //dielectric constant Na=2.7*10**25; //number of atoms x=1/(9*10**9); E=10**6; //electric field(V/m) e=1.6*10**-19; //charge(c) Z=2; //atomic number //Calculation r0=((epsilonr-1)/(4*%pi*Na))**(1/3); ...
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clc; clear; y=5;//ft angle=40;//degree l=12;//ft rate=1.4;//ft per 1000 ft of length K=1.49; A=(l*y)+(y*y/tan(angle*%pi/180));//ft P=(l+(2*y/sin(angle*%pi/180)));//ft Rh=A/P; S0=rate/1000; x=K*(A)*(Rh^(2/3))*(S0^0.5);//where Rh=Q*n n=0.012; Q=x/n;//cfs disp("cfs",Q,"The flowrate=") V=Q/A;//ft/sec Fr=V/(...
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//Example 8.6 //current clc; clear; close; V=220;// in volts I=60;// in amperes rpm=728;//turns Ts=150;//shaft torque in N-m nc=80;//commercial efficiency in percentge I=((Ts*2*%pi*rpm*746)/(60*746*(nc/100)*V));// CURRENT TAKEN IN AMPERES disp(round(I),"current taken in amperes is")
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clc m=1; //kg p=8; //bar s1=6.55; //kJ/kg.K T=200; //0C s_f1=2.0457; //kJ/kg.K s_fg1=4.6139; //kJ/kg.K h_f1=720.9; //kJ/kg h_fg1=2046.5; //kJ/kg h2=2839.3; //kJ/kg x1=(s1-s_f1)/s_fg1; h1=h_f1+x1*h_fg1; Q=h2-h1; disp("Heat supplied=") disp(Q) disp("kJ/kg") // For T-s diagram s=0:0.01:10; T=(-(s-5...
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// Test avec la matrice suivante : K3 = [ 5 0 0 0 0 0 0 0 0 0 0 0 0 -1 0 -1 0 0 0 -1 0 0 0 -1 -1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ; 0 8 0 -1 0 0 0 0 0 0 0 0 0 -1 -1 0 0 0 0 0 -1 -1 0 0 0 -1 -1...
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//CAPTION: Linear_Magnetron //chapter_no.-10, page_no.-459 //Example_no.10-1-2a clc; //(a) Calculate_the_electron_velocity_at_the_hub_surface em=1.759*(10^11);//em=e/m Bo=.015;//Magnetic_flux_density d=5*(10^-2);//Distance_between_cathode_and_anode h=2.77*(10^-2);//hub_thickness V=em*Bo*h; disp(V,'the_...
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//23.3 p=30//in cm f=10//in cm x=(1/f)-(1/p) q=1/x M=-(q/p) disp("part a") disp(q,"The position of final image in cm=") disp(M,"The magnification=") p=5//in cm f=10//in cm x=(1/f)-(1/p) q=1/x M=-(q/p) disp("part b") disp(q,"The position of final image in cm=") disp(M,"The magnification=")
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clc clear //Input data n=1.66*10^-4;//The viscosity of the gas in dynes/cm^2 C=4.5*10^4;//The R.M.S velocity of the molecules in cm/s d=1.25*10^-3;//The density of the gas in g/cc N=6.023*10^23;//The Avogadro number V=22400;//The volume of a gas at N.T.P in cc pi=3.142;//The mathematical constant of pi ...
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//Euler's Method clc; clear; close(); format('v',8); funcprot(0); deff('[g]=f(x,y)','g= -y^2/(1+x)'); y = 1; x = 0; h = 0.05; while x<0.2 y = y - 0.05*y^2/(1+x); x = x + h; disp(y,x,'Value of y at x :'); end disp(y,'The calculated value of y(0.2):'); x = 0.2; act = 1/(1+log(1+x)); disp(act...
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//Exa 7.11 clc; clear; close; //Given data : format('v',7); l=600;//in meter VA=440;//in volt VB=400;//in volt R=0.01;//in ohm/100m RAC=(R/100)*300;//in ohm RCD=(R/100)*300;//in ohm RDE=(R/100)*100;//in ohm REF=(R/100)*200;//in ohm RFB=(R/100)*300;//in ohm //VA-VB=VAC+VCD+VDE+VEF+VFB;//in volt IA=(VA-V...
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clc // Given that lambda = 6.6e-7 // wavelength of light in meter L = 1.32e-5 // coherence length in meter // Sample Problem 1 on page no. 1.40 printf("\n # PROBLEM 1 # \n") printf("\n Standard formulae used \n delta_L = c * delta_t \n") coherence_time = L / (3 * 10 ^ 8)//calculation for coherence time printf("\n Cohe...
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//Chapter 9 : Eigenvalues and Eigenvectors //Example 9.11 //Scilab 6.0.1 //Windows 10 clear; clc; A=[2 1;1 0] disp(A,'A=') eig=spec(A) disp(eig,'eigen values are') P=[1 1;-eig(1) -eig(2)] disp(P,'P=') pap=inv(P)*A*P pap(1,2)=round(pap(1,2)) pap(2,1)=round(pap(2,1)) disp(pap,'P^-1AP=') invp=(1/(2*sqr...
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//Chapter-3,Example 5,Page 57 clc; close; //Part (a) t_half= 1620 //half life of radium lamda= 0.693/t_half //as radium lose one centigram mass N_0=100 // in centigram N_1=N_0-1 t_1=log10(N_0/N_1)/(lamda*log10(%e)) printf('Part (a)---total number of years required are %.2f years ',t_1) //...
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clc //Initialzation of variables T1=298//K T2=273//K //Calculations factor=sqrt(T2/T1) percentage=(1-factor)*100 //Results printf('Percentage loss of speed of air molecules = %.2f',percentage)
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clc clear //input data N=3600//Running speed of blower in rpm Dt=0.2//The rotor tip diameter in m Dh=0.125//The rotor hub diameter in m P1=1.013//The atmospheric pressure in bar T1=298//The atmospheric temperature in K m=0.5//Mass flow rate of air in kg/s db=20//The turning angle of the rotor in degree b1=55...
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//Example 6.19 //PID compensation design for spacecraft attitude control. xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ //System transfer function s=poly(0,'s'); G1=(0.9/s^2); G2=(2/(s+2)); G=G1*G2; Gs=syslin('c',G); // PID controller para...
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//EXAMPLE 8.1 //MAXIMA SCILAB TOOLBOX REQUIRED FOR THIS EXAMPLE //Digital filter structure clear; clc; syms W1 W2 W3 X Y a d B y E z; //Equations obtained are as follows: W1 = X - a*W3/z; W2 = W1 - d*W2/z; W3 = W2/z + E*W2; Y = B*W1 +y*W3/z; //Solving the above equations: Hz=(B + (B*d+y*E)/z + y/(z^2))/(1 + (d+a*E)/z ...
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errcatch(-1,"stop");mode(2);// Example 5.16: Io , bta=100; VBE=0.7; // in volts // From Fig. 5.30 // Writing KVL for the indicated loop I_ref=(10-VBE)/10; // in mili-amperes Io=bta*I_ref/(2*(1+bta)); // in mili-amperes disp(Io,"Io (mA) ="); exit();
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clc disp("the soln of eg 10.1-->2-D steady heat conduction-Gauss Seidel method "); for i=1:9,tnew(i)=101,e(i)=1 //assumed values end t=1e-6 //since all the nodes are interior nodes so discretized eqn used is eqn 10.10 while e(1)>t&e(2)>t&e(3)>t&e(4)>t&e(5)>t &e(6)>t& e(7)>t& e(8)>t & e(9)>t ...
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clc; v=230; // rated voltage of dc shunt motor n=1000; // rated speed of motor rf=115; // field resistance ra=0.5; // armature resistance ia=4; // no load armature current k=(v-ia*ra)/(2*%pi*n/60); // constant term in formula of back EMF disp('case a'); t=80; // load torque ia2=t/k; // armature load current E...
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// Example 6.21.3 page 6.60 clc; clear; tr=50; //radiative recombination lifetime tnr=110; //non-radiative recombination lifetime h=6.624d-34; //plank's constant c=3d8; //speed of light q=1.6d-19; //charge of electron i=40d-3; //current lamda=0.87d-6; //wavelength t=tr*tnr/(tr+t...
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clc; //page 185 //problem 3.7 //Given input inmedance of matching networkis R1 = 10 ohm & output impedance of matching networ is R2 = 50 ohm & carrier frequency is fc = 500 KHz R1 = 10 R2 = 50 fc = 500000 //Wc = 2*pi*fc Wc = 2*%pi*fc //AS R1 = R2*(X2^2)/[(R2^2)+(X2^2)], X2 = 25ohm X2 = 25 //AS X1 = (...
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// (Distortion in CT system) // Exercise 5 clear; clf; dt = 1/10000; t = -0.01:dt:0.01; x1 = sin(2*%pi*100*t) subplot(231) plot(t,x1,'y'); title("x1 vs time","fontsize",3) x2 = sin(2*%pi*200*t) subplot(232) plot(t,x2,'r'); title("x2 vs time","fontsize",3) x = x1 + x2; // input signal subplot(233) plot(t,x,'m') ti...
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//Example 12.2 //Program to determine the required electrical and optical SNR clear; clc ; close ; //Given data BER=10^(-9); //BIT ERROR RATE //Optical SNR SNR_op=(erfinv(1-2*BER))*2*sqrt(2); //erfc(x)=1-erf(x) //Electrical SNR SNR_el=((erfinv(1-2*BER))*2*sqrt(2))^2; //erfc(x)=1-erf(x) ...
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clc clear //At 7 bar pressure P1=7; //in bar P2=1; //in bar n=1.1; //Now according to law of expansion P(V)^1.1= Constant Vg1=0.273; //in m^3/kg V1=Vg1; V2=((P1/P2)^(1/n))*V1; W=((P1*100*V1)-(P2*100*V2))/(n-1); printf('Work Done: %3.1f kJ/kg',W); printf('\n'); H...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-4,Example 14,Page 113 //Title:Final state and mass of steam that entered the tank //================================================================================================================ clear clc /...
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## Test of tag deletion by regexp set echo read <snarl.svn tag /INITIAL_IMPORT/ delete write -
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clc; m = input('enter row'); n = input('enter col'); a = zeros(m,n); b = zeros(m,n); c = zeros(m,n); disp('enter elements'); for i = 1:m for j = 1:n a(i,j) = input(''); end end disp('enter elements'); for i = 1:m for j = 1:n b(i,j) = input(''); end end for i = 1:n for j = 1:m ...
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// To determine the short circuit capacity of each station clear clc; X=1200*100/800;// percent reactance of other generating station Xc=.5*1200/(11*11); Sc=1200*100/86.59;// short circuit MVA of the bus Xf=119.84;// equivalent fault impedence between F and neutral bus MVA=1200*100/Xf; mprintf("short circuit ...
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clear clc //to find kinetic energy // GIVEN:: //distance travelled by neutron d = 6.2//in meters //time for neutron travel t = 160//in micrometers //mass of neutron m = 1.67e-27//in kg // SOLUTION: //speed of neutron v = d/(t*10^-6)//in m/s //applying formula for kinetic energy //kinetic energy...
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// Scilab code Exa 4.5.5 : Checking whether the reaction is spontaneous or exoergic : page no. 185 (2011) // Cf-252 > Zr-98 +Ce-145 + 9*n-1 is the given reaction M_Cf = 252.081621; // Atomic mass of Cf, amu M_Zr = 97.912735; // Atomic mass of Zr, amu M_Ce = 144.917230; // Atomic mass of Ce, amu M_n = 3.0160294; ...
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// Exa 5.22 format('v',6) clc; clear; close; // Given data V_T = 1;// in V k = 160*10^-6;// in A/V^2 I_DQ = 160*10^-6;// in A V_GS = V_T + sqrt(I_DQ/k);// in V V_DD = 5;// in V V_DSQ = 3;// in V R_D = (V_DD - V_DSQ)/(I_DQ);// in ohm R_D = R_D * 10^-3;// in k ohm disp(R_D,"The value of R_D in k ohm is");
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l=30*10^(-3); r=200; v=10; f=1000; disp("Part a"); x_l=2*%pi*f*l; z=sqrt(r^2+x_l^2); disp("the impedance (in Ω) of the circuit is"); disp(z); disp("Part b"); i=v/z; disp("the current (in A) in the circuit is"); disp(i); disp("Part c"); deg=atan(x_l/r)*180/%pi; disp("the phase angle (in deg) between applied...
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// Exa 9.31 clc; clear; close; // Given data V_DD = 5;// in V V_T= 1;// in V k= 1;// in mA/V^2 R1 = 1;// in M ohm R2 = 1;// in M ohm R_S= 2;// in k ohm R_D= 2;// in k ohm I1 = V_DD/(R1+R2);// in A disp(I1,"The value of I1 in µA is : ") V_A = (R2/(R2+R1))*V_DD;// in V disp(V_A,"The value of V_A and V_G in...
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clear // //Given //Variable declaration sigma1=100 //Major principal stress in N/sq.mm sigma2=-40 //Minor principal stress in N/sq.mm theta=90-60 //Angle of inclination in degrees //Calculation sigman=((sigma1+sigma2)/2)+(((sigma1-sigma2)/2)*cos((%pi/180)*(2*theta))) sigmat=((sigma1-sigma2)/2*(sin...
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// Example 12_4 clc;funcprot(0); // Given data X_O_2=0.2095;// The mole fraction for oxygen p_m=0.1013;// MN/m^2 d=100;// m M_O_2=32.00;// The molecular mass of oxygen M_He=4.003;// The molecular mass of helium R=8.3143;// kJ/(kgmole.K) // Calculation // (a) p_O_2=X_O_2*p_m;// MN/m^2 p_m=1.08;// MN/m^2 X...
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//Example 7.2: Diffusion potential clc; clear; close; format('v',6) //given data : Na=5*10^23;// in m^-3 Nd=5*10^21;// in m^-3 T=300;// in K e=1.6*10^-19;// in J k=1.38*10^-23;// in JK^-1 V=(k*T)/e; ni=2.2*10^12;// in m^-3 Vd=V*log((Na*Nd)/ni^2); disp(Vd,"Diffusion potential,Vd(V) = ")
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// Calculate width of Gating pulse // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 8-3 in page 377 clear; clc; close; // Given Data Il=4*10^-3; // Latching current of SCR in A V=100; // DC voltage of the circuit in V L=0.1; // Inductance of th...
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Tint 0 0 0 0 TintAlphaChange 100 1 Linear Wait 1 TintAlphaChange 0 1 Linear Wait 1 Loop
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// Example 9.4.2 page 9.12 clc; clear; output=3; //laser output sensitivity=-54; //APD sensitivity coupling_loss=17.5; L=6; //length in km sl=1.1; //loss correspond to one splice in dB n=3; //number of splices fl=5; //fiber loss in dB/km connector_loss=0.8; allowed_loss=output-sensitiv...
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Iteration = 0 Energy = 0.000E+00 Iteration = 0 Energy = 0.000E+00 Iteration = 0 Energy = 0.000E+00 Iteration = 0 Energy = 0.000E+00 Iteration = 0 Energy = 0.000E+00 Itera...
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clc //initialisation of variables d= 10 //in h= 3.5 //in g= 32.2 //ft/sec^2 //CALCULATIONS A= (%pi/4)*(d^2/144) V= sqrt(2*g*(h/12)) vm= (2/3)*V Q= vm*A*60 //RESULTS printf (' Quantity flowing per minute = %.1f ft^3 ',Q)
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<ApMenu> <DocumentProperties> <Module>SIGAFIN</Module> <Version>7.10</Version> </DocumentProperties> <Menu Status="Enable"> <Title lang="pt">Atualizacoes</Title> <Title lang="es">Actualizaciones</Title> <Title lang="en">Updates</Title> <Menu Status="Enable"> <Title lang="pt">Cadastros</Tit...
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//pathname=get_absolute_file_path('12.03.sce') //filename=pathname+filesep()+'12.03-data.sci' //exec(filename) //Diameter of the bore(in m): d=0.3 //Length of the stroke(in m): L=0.6 //Occerance od cut-off: r1=0.4 //Pressure at which steam enters(in bar): p1=7.5 //Pressure at exhaust(in bar): p3=0.1 //Rpm ...
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//find clc //solution //given BP=5000//W N=1200//rpm n=N/2 pm=0.35//N/mm^2 effm=0.8 //let D bebore dia IP=BP/effm//W //IP=pm*l*A*n/60 //A=%pi*D^2/4,l=1.5D //IP=4.12*10^-3 *D^3 D=(IP*1000/4.12)^(1/3)//mm printf("dia of bore dis,%f mm\n",D) l=1.5*D L=1.15*l ft=42 printf("stroke length is,%f mm\n",L) p=9*pm C=0.1 th=D*sqr...
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//Example 9.39 clc disp("From equation(3) we get") qe=(4.095/(4095*2))*10^3 format(4) disp(qe,"Q_E(in mV) = 4.095 / (4096-1)*2 =")
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clc; clear; m=68.1;//kg v=40;//m/s t=10;//s g=9.8;//m/s^2 function y=f(c) y=g*m*(1-exp(-c*t/m))/c - v; endfunction x1=12; x2=16; xt=14.7802;//true value e=input("enter the tolerable true percent error=") xr=x1-(f(x1)*(x2-x1))/(f(x2)-f(x1)); etemp=abs(xr-xt)/xt*100;//error while etemp>e if f(x1)*...
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; checks bit vector sorts (set-logic QF_BV) (declare-fun x () (_ BitVec 4)) (declare-fun y () (_ BitVec 1)) (declare-fun z () (_ BitVec 4)) (declare-fun k () (_ BitVec 0)) (declare-fun k () (_ BitVecx 0)) (declare-fun k () (_ BitVec -1)) (declare-fun k () (_ BitVec)) (declare-fun k () (_ BitVec 1 2)) (assert (= x #b010...
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clc // C_aH_bO_cN_dS_e a=60/12; b=20; c=5/16; d=10/14; e=5/32; // C_5 H_20 O_0.3125 N_0.7143 S_0.1562 + x O2 + x*(79/21)N2 → p CO2 + q H2O + r SO2 + s N2 p=5; q=20/2; r=0.1562; x=(2*p+q+2*r-0.3125)/2; s=(0.7143+2*x*79/21)/2; air=(9.92*32+x*79/21*28)/100; disp("Stoichiometric air required =") disp(a...
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clc; clear; //clears the console and all previously stored variables function V0 = BS_EuCall_FFT (S0, r, sigma, T, K, R, N, M) //defining initial parameters delta=M/N; m=1:N; kappa_1=0; //f_tilde_0 for European Call for K=e^kappa function y = f_tilde(z) y = 1/ (z*(z-1)); ...
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//Ex8_9 clc Ai = -60 Ri = 2.0*10^3 RL = 15*10^3 disp("Ai = "+string(Ai))//current gain disp("Ri = "+string(Ri)+"ohm")//input resistance disp("RL = "+string(RL)+"ohm")//load resistance Av = Ai*RL/Ri disp("Av = Ai*RL/Ri = "+string(Av))//voltage gain //note : in textbook, // author notify LOAD RESISTANC...
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function [a,b]=foo(x,y) u=x+y // u is a local variable v=x*y // v is a local variable a=u+c // c is an external variable b=u*exp(v) // exp is an external functions endfunction L=macrovar(foo) // L=list(in,out,nolocal,called,local)
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Baptiste Distance FS Dodge.sce
Name=Baptiste Distance FS Dodge PlayerCharacters=Quaker BotCharacters=Quaker Bot Hard.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Quaker AddedBots=Quaker Bot Hard.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=2 BotTeams=1 MapName=Dodgingg.map MapScale=5.3 BlockProjectilePredictors=true BlockCheats=true Invincible...
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 20 // read it as example 19 in the book on page 2.72 disp("CHAPTER 2"); disp("EXAMPLE 20"); //VARIABLE INITIALIZATION L=0.5 //in Henry C=5 //in mf, multiply by 10^-6 to convert to f R=25 ...
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// Exa 2.15 clc; clear; close; // Given data miu_n= 1300;// in cm^2/Vs q=1.6*10^-19;// in C ni= 4.3*10^-6;// in /cm^3 V= 1;// in volt L=8;// in cm A=0.8*0.8;// in cm^2 I=4*10^-3;// in A // R= rho*L/A = V/I R= V/I;// in Ω sigma= L/(R*A);// in (Ωcm)^-1 // sigma= q*n*miu_n n= sigma/(q*miu_n); N_D= n; dis...
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load AND1250918.hdl; output-file AND1250918.out; output-list a b out; set a %B1011001011101001 , set b %B1011111010110010, eval , output; set a %B1101001101100101 , set b %B1011011001011010, eval , output; set a %B1011001101011010 , set b %B1011011010100010, eval , output; set a %B0101101100101110 , set b %B1011011101...
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//Example 19.3 // position of fermi level clc; clear; //given data : Eo=.3;// initial position in eV T=300;//initially temperature in kelvin T1=330;// final temperature in kelvin E=Eo*T1/T;// (formula to calculate) final position in eV disp(E,"new position of fermi level in eV")
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clear; clc; N = 2640;//rigidity modulus in tons/in^2 d = 3/8;//diameter of the rod in inches P = 1/2;//axial pull in tons del_d = 0.000078;//change in diameter in inches A = 0.25*%pi*d^2;//section area in in^2 p = P/A ;//stress tons/in^2 LS = del_d/d;//lateral strain m = p/(LS*2*N) - 1; E = 2*N*(1 + 1/m);//mo...
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// Chapter 5 additional Example 12 //============================================================================== clc; clear; //input data h = 1; // miller indice k = 1; // miller indice l = 0; // miller indice d = 2.86*10^-10 // interplanar dista...
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clc clear //Input data C=800*(5/18) //Velocity in m/s Po=105 //Stagnation pressure in kPa To=35+273 //Stagnation temperature in K Cp=1005 //Specific heat capacity at constant pressure in J/kg-K k=1.4 //Adiabatic Constant R=287 //Specific gas constant in J/kg-k //Calculation T=To-(C^2/(2*Cp)) //Static temp...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 3 Semiconductor Diodes and Miscellaneous Devices Pg no. 91 clear; clc; //Given Data Rl=200;//Load resistance in ohms esf=50;//Input signal frequncy in hertz RF=5/100;//Ripple Factor //Solution C=1/(esf*Rl*2*RF)*10^6;//Capacitance in micro faraday; prin...
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clc // Example 1.7.py // A flat plate with a chord length of 3 ft and an infinite span(perpendicular to // the page in fig 1.5) is immersed in a Mach 2 flow at standard sea level // conditions at an angle of attack of 10 degrees. The pressure distribution // over the plate is as follows: upper surface, p2=constant=1132...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 5 //Some Applications of the Laws of Thermodynamics //Example 21 clear; clc; //Given: P2 = 2800; //pressure of superheated steam (kPa) P1 = 275; //pressure of withdrawn steam (kPa) V = 1.070*10^-3; //specific volume of saturated liquid at 27...
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clear // // // //Variable declaration d=0.4086*10^-10; //lattice spacing(m) theta=65; //glancing angle(degree) h=6.6*10^-34; //plank's constant(Js) m=9.1*10^-31; //mass(kg) n=1; //Calculation theta=theta*%pi/180; //angle(radian) lamda=2*d*sin(theta)/n; //debroglie wavelength(m) v=h/(m*...
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float a[][]; /* ошибка */
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//=========================================================================== //chapter 3 example 13 clc;clear all; //variable declaration R1 = 1000; //resistance in Ω R2 = 500; //resistance in Ω eR1 = 1; //error resistance eR2 = 1; //error resistance //calcula...
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// Updated(18-7-07) // 4.1 a = 0.9; n = -10:20; y = zeros(1,size(n,'*')); for i = 1:length(n) if n(i)>=0, y(i) = a^n(i); end end stem(n,y) label('u1',4,'Time(n)','0.9^n1(n)',4)
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//trace asteroid clc; clear; x=[-5:0.01:5]; a=4; y1=(a^(2/3) - (x.^2).^(1/3)).^(3/2); //for some odd reason, x^(2/3) != (x^2)^(1/3) y2=-y1; plot2d(x,y1); plot2d(x,y2); xlabel("X-Axis") ylabel("Y-Axis") title("Asteroid")
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clc clear //INPUT DATA r1=0.1258*10^-9//atomic radii of the iron atom in BCC structure in m r2=0.1292*10^-9//atomic radii of the iron atom in FCC structure in m T=910//metallic iron changes from BCC to FCC in centigrade //CALCULATION a1=((4*r1)/sqrt(3))//lattice constant of BCC structure in m v1=((a1*a1*a1)/2...
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//Problem 9.03: A conductor moves with a velocity of 15 m/s at an angle of (a) 90°, (b) 60° and (c) 30° to a magnetic field produced between two square-faced poles of side length 2 cm. If the flux leaving a pole face is 5 μWb, find the magnitude of the induced e.m.f. in each case. //initializing the variables: l = ...
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// Scilab Code Ex4.3: Page-234 (2008) clc; clear; c = 3e+008; // Speed of light in vacuum, m/s v = [c c/sqrt(2) sqrt(3)/2*c c/2 0.8*c]; // Different speeds of metre rod, m/s L0 = 100; // Actual length of the rod, cm for i = 1:1:5 L = L0*sqrt(1-v(i)^2/c^2); // Apparent length of rod from Lorentz tr...
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res_log=read('../data/gps_kalman_log.m',-1,16); [r_n,c_n]=size(res_log); idx=[1:r_n]; // First plot KF state //xset('color',3); //xset('background', 1); xbasc(); xset('window',0); // plot pos_x result subplot(511); plot2d(res_log(:,2)); xtitle("ECEF_x",'100ms','m'); xset('background', 4); // plot pos_y result subplo...
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//Example 4.17. clc format(6) Io1=7.5*10^-6 T1=27 T2=127 disp("The saturation current at 400 K is,") disp("Io2 = Io1 * 2^((T2-T1)/10)") disp(" = 7.5*10^-6 * 2^(127-27/10)") Io2=Io1*(2^((T2-T1)/10)) I=Io2*10^3 disp(I,"Io2(mA) = ")
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#define your files scenario = "EP"; pcl_file = "EP.pcl"; #standard settings scenario_type = trials; active_buttons = 5; button_codes = 1,2,3,4,5; response_logging = log_active; #log only if response is expected response_matching = simple_matching; default_output_port = 1; #parallel port response_port_out...
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//Chapter 1, Example 1.7 clc //Initialisation v1=10 //voltage v2=0 //voltage r1=200 //resistance in ohm r2=300 //resistance in ohm //Calculation v=v1*(r2/(r1+r2)) ...
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//Caption: Entropy //Example 9.9 //page no 398 //Find Entropy,Amount of information clc; clear; px1=0.4; px2=0.3; px3=0.2; px4=0.1; HX=-px1*log2(px1)-px2*log2(px2)-px3*log2(px3)-px4*log2(px4); printf(" \n Entropy \n \n\t i) H(X) = %.2f bits/symbol,\n",HX); Px1x2x1x3=px1*px2*px1*px3; Ix1x2x1x3=-log2(Px1x2...
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//Example 3.7 // total resistance clc; clear; close; //given data : r1=6; // resistance in ohm r2=10; // resistance in ohm r3=15; // resistance in ohm r=(1/r1)+(1/r2)+(1/r3); R=1/r; disp(R,"equivalent resistance,R(ohm) = ")
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h1=2//m h2=0.5//m S=0.85//specific gravity of oil
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// Example 4.20.a;//delay clc; clear; close; d=0.02;// Change in refractive index n1=1.5;//Core refrctive index L=3*10^3;//Length in meter C=2.998*10^8;//Speed of light in m/s dts=round(((L*n1*d)/C)*10^9);//DELAY IN NS disp(dts,"DELAY IN NS")
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//Example 12.3;no. of subscribers clc; clear; close; pt=1;//mW pn=-40;//dBm pn1=10^(pn/10);// c=0.05;// d=0.11;// x=((pn1)/(pt*c));// y=((log10(x))/(log10((1-d)*(1-c))));// n=y+1;// disp(round(n),"no. of subscribers are")
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//8.7 clc; f_unity=10^6; Av=100000; open_loop_upper_cutoff_f=f_unity/Av; printf("open loop upper cutoff frequency=%.0f Hz", open_loop_upper_cutoff_f) disp('when beta=0.001') beta=0.001; Closed_loop_gain=Av/(1+Av*beta); printf("\nClosed loop gain=%.1f ",Closed_loop_gain) upper_cutoff_frequency=f_unity/Closed_l...
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//Motor boat crossing river //refer fig. 14.11 and 14.12 //let the motor boat start from A and reaches C vrx=15 //kmph //distance to be moved in x direction=1 km //time required t is t=4 //min //boat will move down the stream vy=5 //kmph //Distance moved in downstream direction (d) d=333.33 //m //Let the...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 5 //Some Applications of the Laws of Thermodynamics //Example 15 clear; clc; //Given: T1 = 300; //indoor temperatur (K) T2 = 290; //outside temperature (K) W_input = 1; //1 kW heat pump W_output = 30; //given output (kW) //To verify that...
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function y=f1( x ) y = 0.5^x - 3 + ( x + 1 ) ^ 2 endfunction function y=f2( x ) y = x .* log10( x + 1 ) - 1; endfunction function y=f3( x ) y = x + log10( x ) - 0.5; endfunction density = 0.0001;
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// Mission X1 // Chargement de l'image au format .dat dans la mémoire load("C:\Users\Jean-Guillaume P\Documents\Exia\A2\Projets\Imagerie\ExoLife\Images\Mission_X\Asellus Secundus.dat"); // Utilisation de l'inverse de la transformée de Fourrier img_out = ifft(imgT); // Affichage figure; display_gray(img_out); // Sa...
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// Chapter 9 example 3 //------------------------------------------------------------------------------ clc; clear; // Given Data f = 10*10^9; // radar Tx frequency PRF = 2000; // Pulse repetitive frequency in Hz Vr = 0.5; // radial vel in Mach c = 3*10^8; // vel...
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function zp = FallschirmspringerDGL(t, z) g = 9,81; m = 100; cw = 1,4; p = 1,2; r = 5; zp = [z(2); -g*m + 0,5*cw*p*%pi*r^2*z(2).^2/m]; endfunction
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load MantissaMUL.hdl, output-file MantissaMUL.out, output-list a%B1.8.1 a%D1.8.1 b%D1.8.1 b%B1.8.1 out%B1.16.1 out%D1.16.1; //170(10101010) * 187(10111011) = 31,790(01111100 00101110) set a %B10101010 , set b %B10111011 , eval, output; //139(10001011) * 138(10001010) = 19182(01001010 11101110) set a %B10001011 , set...
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s = poly(0,'s'); G = 10/(s*(s+2)*(s+4)); // PART A k = 4; // any arbitrary value chosen H = k*G/(1+k*G); disp(H); // PART B k_range = .1:.1:100.1; // excluding k =0 case // for each k we get 3 poles since denominator of H is cubic poles = zeros(3,length(k...
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//Find fracture strength and ratio //Ex:20.1 clc; clear; close; l=1.5*10^-6;//crack length in m e=70*10^9;//Young's modulous in N/m^2 y_e=1.05;//specific surface energy in j/m^2 a_f=sqrt((2*y_e*e)/(3.14*l)); a_f1=a_f*10^-6;//in MPa disp(a_f1,"Fracture strength (in MPa) = "); r=a_f/e;//ratio disp(r,"Ratio of...
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//Example sec 10.1.1 //mass, dashpot, spring arrangement. clear;clc; xdel(winsid()); M=1 K=2 F=2 A=[0 1;-2 -2] C=eye(A) s=%s D=s*C-A X=inv(D)*[1;1] //taking the laplace transform of X disp("X(t)=sqrt(5)*sin(t+inv(tan 0.5));sqrt(10)*sin(t+inv(tan -1/3))") disp("The system is asymptotically stable")