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clc; pathname=get_absolute_file_path('13_11_soln.sce') filename=pathname+filesep()+'13_11_data.sci' exec(filename) // Solution: // upstream temperature in Rankine, T1=T1+460; //deg R // absolute downstream pressure, p2=p2+14.7; //psia // flow capacity constant, Cv=(Q/22.7)*sqrt(T1/(p2*del_p)); // Results: printf("\n ...
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clear; clc; //Atomic weigths Si=28.1 Ga=69.7 As=74.9 Na=6.02*10^23 // Avagadro Number in mol^-1 //(a)Si a=5.43*10^-8 //in cm n=8 //no. of atoms/cell //(b)GaAs a1=5.65*10^-8 //in cm //Calculation N=8/a^3 //Atomic Concentration in atoms/cc N1=4/a1^3 //Atomic Concentration in atoms/cc Density=(N*Si)/(...
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//Scilab Code for Example 7.11 of Signals and systems by //P.Ramakrishna Rao clear; clc; clear x y n; x=[0,0,2,0,0]; y=[0,0,1,1,0]; n=-2:2; c = gca(); c.y_location = "origin"; c.x_location = "origin"; plot2d2(n,x,2); title('x(t)') xlabel('t') figure(1); n=-2:2; c = gca(); c.y_location = "origin"; c.x_...
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//Exa 4.5 clc;clear;close; format('v',6); I=100;//A///Current V=11;//kV Xs=4;//ohm/phase f=50;//Hz pf=0.8;//Power factor Lagging //Calculation theta=acosd(pf);//degree disp("Part(a)"); E=V*1000/sqrt(3)+I*(cosd(theta)-%i*sind(theta))*%i*Xs;//V del=atand(imag(E)/real(E));//degree E=abs(E);//V/phase disp(E,"...
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// Updated(19-7-07) // 12.4 A=[1 -0.8]; dA=1; B=[0.4 0.6]; dB=1; rho = 0.8; k = 1; N1 = 0; N2 = 3; Nu = 2; getf gpc_N.sci; [K,KH1,KH2,Tc,dTc,Sc,dSc,R1,dR1] = ... gpc_N(A,dA,B,dB,k,N1,N2,Nu,rho)
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//example 8.1 clc; funcprot(0); // Initialization of Variable h1=2758.0; h2=1794.8; h3=173.88; h4=h3+1.0084/1000*(8-0.008)*1000; neta=(h1-h2-h4+h3)/(h1-h4); disp(neta*100,"thermal efficiency in %"); bwr=(h4-h3)/(h1-h2); disp(bwr*100,"back work ratio in %"); mdot=100*1000*3600/(h1-h2-h4+h3); disp(mdot,"mass ...
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//Problem 40.09: Two parallel wires, each of diameter 5 mm, are uniformly spaced in air at a distance of 50 mm between centres. Determine the capacitance of the line if the total length is 200 m. //initializing the variables: e0 = 8.85E-12; er = 1; D = 0.05; // in m d = 0.005; // in m l = 200; // in m //cal...
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-- VectorCAST 18.sp2 (07/02/18) -- Test Case Script -- -- Environment : AIRPORT -- Unit(s) Under Test: airport -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXED_CASE_NAMES TEST.SCRIPT_FE...
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clc clear printf("Example 12.7 | Page number 422 \n\n"); //Find //(a) Actual air //(b) Excess air //(c) Percentage theoritical air //(d) Mass fractions //(e) Dew point //Part(a) printf("Part(a)\n") mC = 0.65 //kg //mass of C per kg coal mA = 0.15 //kg //mass of Ash per kg coal CR = 0.05 //kg //mass of ...
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exec("swigtest.start", -1); if endif_get() <> 1 then swigtesterror(); end if define_get() <> 1 then swigtesterror(); end if defined_get() <> 1 then swigtesterror(); end if 2 * one_get() <> two_get() then swigtesterror(); end exec("swigtest.quit", -1);
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//Chapter-11, Example 11.9, Page 494 //============================================================================= clc clear //INPUT DATA T=100;//Temperature of dry steam in degree C Do=0.025;//Outer diameter of the pipe in m Ts=84;//Surface temmperature of pipe in degree C Tf=(T+Ts)/2;//Film temperature in...
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function [x,y,typ]=standard_outputs(o) //get position of inputs ports and clock inputs port for a standard block // the output ports are located on the right (or left if tilded) vertical // side of the block, regularly located from bottom to top // the clock output ports are located on the bottom horizontal side /...
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function [ECmInv,EeV] = HCl(var,J) //Written by Aditi and O.S.K.S. Sastri //var is vector consisting of De, b and Re values. //Typical input for var for HCl is [5,1,1.27455] //J is rotational quantum number. //J = 0 gives pure vibrational levels //J = 1 gives energy eigen values corresponding to //first excit...
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P=10000 V=1000 W1=4*%pi*10^6 Wc=2*%pi*10^8 a=P/V^2 printf("\na=%.2f",a) //(b)= A=1000+2*225+2*150+2*75 peak_power=a*A^2 printf("\nA=%.0f V\npeak_power=%.0f W",A,peak_power)
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//Exa 2.3 clc; clear; close; //given data n=10^24;//electrons/m^3 e=1.6*10^-19;//constant v=1.5*10^-2;//in m/s A=1;//in cm^2 A=1*10^-4;//in m^2 I=e*n*v*A;//in Ampere disp(I,"Magnitude of current in Ampere : ");
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//Problem 16.12: A motor has an output of 4.8 kW, an efficiency of 80% and a power factor of 0.625 lagging when operated from a 240 V, 50 Hz supply. It is required to improve the power factor to 0.95 lagging by connecting a capacitor in parallel with the motor. Determine (a) the current taken by the motor, (b) the supp...
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clc //initialisation of variables clear W= 38 //rev/sec w= 62.4 //lbf/ft^3 m= 2000 //lbm/sec g= 32.2 //ft/sec^2 ps= 5000 //lbf/ft^2 S3= 4.6 e= 0.91 //CALCULATIONS S1= W*(w*m^2/(g*ps)^3)^0.25 D= S3*(m^2/(w*g*ps))^0.25 //RESULTS printf ('S1 = %.3f',S1) printf ('\n Diameter = %.2f ft',D) printf ('\n ef...
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//no i/p args are passed to the function X=corrmtx(); //output //!--error 4 //Undefined variable: varargin //at line 88 of function corrmtx called by : //X=corrmtx();
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clc; clear; h=6.63*10^-34 //Plancks constant in J-s c=3*10^8 //velocity of light in m/s m=9.1*10^-31 //mass in kg lambda_1=100*10^-12 //wavelength in m e=1.6*10^-19 //charge in C //calculation delta_lambda=(h/(m*c)) //wavelength in m mprintf("The compton shift is = %1.2e m\n",delta_lambda) lambda_0=lamb...
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function z=zeros(n,m) // Copyright INRIA [lhs,rhs]=argn(0) if rhs==1 then z=0*ones(n);return;end if rhs==2 then z=0*ones(n,m);return;end
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//Problem 7.09: //initializing the variables: F1 = 50000; // in lb/h F2 = 60000; // in lb/h F3 = 80000; // in lb/h F4 = 60000; // in lb/h F5 = 40000; // in lb/h F6 = 35000; // in lb/h Cp1 = 0.65; // in Btu/lb.degF Cp2 = 0.58; // in Btu/lb.degF Cp3 = 0.78; // in Btu/lb.degF Cp4 = 0.70; // in Btu/lb.degF Cp...
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//This Source file is written by Nikita Rath (18BLC1131), VIT Chennai //Function for C-SCAN function [] = cscan(a,head,n) printf("Order of Track "); seek_count = 0; ihead = head; maximum = 4999; temp1 = 1; temp2 = 1; //Traversing through requests for i = 1:n //Reque...
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// Example 14.9 // Calculating a Transfer Function // From figure 14.21 and ABCD parameters that we found in example 14.7 we have, // since V_1=V_s // Z_s=0; s=%s; disp("H(s)=I_2/V_1") disp("=> H(s)=-1/A*Z_L+B") A=1-2/s; B=-20/s; Z_L=2.5*s// Assume H_s=-1/(A*Z_L+B); P_s=(s^2-2*s-8); // denominator of H_s ...
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//Determine the maximum value of transmitted wave clear clc; Z=350;//surge impedencr (ohms) C=3000*(10^-12);// earth capacitance(F) t=2*(10^-6); E=500; E1=2*E*(1-exp((-1*t/(Z*C)))); mprintf("the maximum value of transmitted voltage=%.0f kV \n",E1);
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//Example 8_2 <a> //determine the nyquist rate of x(t)=sinc(200*pi*t) //sinc(t)=cos(t)/t //cos3(t)=3/4[cos(200)+1/4cos(600)] clc; clear all; wp=200; F1=wp/2; Fs=2*F1; disp('Nyquist Rate='); disp(Fs);
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// Scilab Code Ex2.39:: Page-2.29 (2009) clc; clear; t = 0.75e-06; // Thickness of the glass plate, m mu = 1.5; // Refractive index of the glass plate lambda1 = 4000e-010; // First wavelength of visible range, cm lambda2 = 7000e-010; // Last wavelength of visible range, cm r = 0; // Angle of refraction...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/08/FunctionCalls/FibonacciElement/FibonacciElement.tst // FibonacciElement.asm is the result of translating both Main.vm and Sys.vm. load FibonacciElement.asm, ou...
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clear all; clc; disp("Since the pressure changes are small compared with the barometric pressure,constant densities are assumed that is rho3 =rho2=rhoa where rhoa=pa/(RTa)") p_a=14.6 T_a=535 R=53.3 rho_a=(p_a*144)/(R*T_a)//144 is the conversion factor printf("rhoa= %0.4f lbm/ft^3",rho_a) A2=5*6.5 printf("\n...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AutoTestC version="2.0.0"> <Pulse>CUSTOM WAVE</Pulse> <Title>Waveform 3</Title> <Organization>GM</Organization> <Standard>GMW3172 2010</Standard> <Item>9.2.17 Crank Pulse Capability and Durability</Item> <voltage>14</voltage> <count>49...
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clc;clear; printf("\nBalanço de Massa\nMétodos Decomposição LU e Jacobi\n\n") /*ordem = input("Qual a ordem da matriz? ") printf("Preencha os valores da matriz dos coeficientes:\n") for i = 1:ordem printf("Linha %d\n", i) for j = 1:ordem printf("Coluna %d", j) A(i, j) = input("Valor: ") end...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.409234D+00 ...
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x=[2.30256624769934; 2.29071803023829; 2.26283604900314; 2.35145015316178; 2.27686291358213; 2.29805616201205; 2.32805830340568; 2.30878734371402; 2.29343801980763; 2.23019030245799]; fs=4e6; t=(1/fs); [F,LT,UT]=falltime(x,fs); disp(F); disp(LT); disp(UT); //output // 0.0000002 // // 0.0000022 // // 0.0000...
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// Problem 5.1,Page no.121 clc;clear; close; b=100 //mm //width of timber joist d=200 //mm //depth of joist L=3 //m //Length of beam sigma=7 //KN/mm**2 //bending stress w_1=5 //KN/mm**2 //unit weight of timber //Calculations w=0.1*0.2*1*5*100 //N/m //self weight of the joist I_xx=1*12**-1*100*200**3 //mm**4 //M.I of...
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E = 29000; // Modulus of elasticity in ksi spl = 42 ; // Proportional limit in ksi L = 25 ; // Total length of coloum in ft n = 2.5 ; // factor of safety I1 = 98 ; // Moment of inertia on horizontal axis I2 = 21.7 ; // Moment of inertia on vertical axis A = 8.25 ; // Area of the cross section Pcr2 = (4*%pi^2*E*I...
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clear;lines(0); a=rand(3,3);p=poly([1,2,3],'s');l=list(1,'asdf',[1 2 3]); print(%io(2),a,p,l) write(%io(2),a)
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function [out]=erode(input_image ,kernel,actualkernel,anchorX,anchorY) input_image1=mattolist(input_image); a=opencv_erode(input_image1 ,kernel,actualkernel,anchorX,anchorY); dimension=size(a) for i = 1:dimension out(:,:,i)=a(i); end endfunction;
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function [x,y,typ] = mdaq_dio_get(job,arg1,arg2) dio_get_desc = ["This block reads MicroDAQ DIO input state."; ""; "DIO pin: 1...32"; ""; "Set block parameters:"]; x=[];y=[];typ=[]; select job case 'set' then x=arg1 model=arg1.model; graphics=arg1.graphics; ...
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function [out]=convexhull(pstData,clkwise,returnpoints) out=opencv_convexhull(pstData,clkwise,returnpoints); endfunction;
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clear; clc; printf("\nEx1.7\n"); //page no.-9 //given rho=2700;.......//density of potassium bromide in kg/m^3 m=119;.........//molecular wt. n=4;...........//molecules per unit cell for F.C.C. N=6.02*10^26;...//avagadro no. M=(n*m)/N;..........//mass in each unit cell //as density=mass/volume, so volume i...
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;Create new list /*declare json = vc go set json = '{"LISTREQUEST":{"patient_list_id":0.0,"name":"Test List 1","description":"","patient_list_type_cd":2177315703.0,"\ owner_prsnl_id":18811197.0,"arguments":[{"argument_name":"ACMPRSNLGROUPS","argument_value":"","parent_entity_id":20705740.0,"\ parent_entity_name":"PRSNL...
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load HackComputer.hdl; output-file TestCaseIntegerArithmetic.out; //Loading program to instruction memory ROM32K load TestCaseIntegerArithmetic.hack; //Expression being evaluated is d=a+b-c with - //a=100 //b=50 //c=10 //Value of d is stored at address 19 output-list RAM64[19]%D1.3.1; set reset 1; tick,tock; set r...
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//------------------------------------------------------------------------------ // FEDERAL UNIVERSITY OF UBERLANDIA // Faculty of Electrical Engineering // Biomedical Engineering Lab // Uberlandia, Brazil //------------------------------------------------------------------------------ // Author: Andrei Nakagawa, MSc /...
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clear clc disp("2*x1*x2+2*x1*x3-2*x2*x3 ") disp("The matrix of the given quadratic form is ") A=[0 1 1;1 0 -1;1 -1 0] disp("let R represents the matrix of transformation and P represents a diagonal matrix whose values are the eigen values of A.then ") [R P]=spec(A) disp("so,canonical form is -2*x^2+y^2+z^2")
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clear;lines(0); genlib('auto1','SCI/macros/auto') disp(auto1)
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10_1.sce
clc //Initialization of variables m=2 M=28 M2=32 PN=300 //psia Pt=400 //psia //calculations nN=m/M PO=Pt-PN nO=nN*PO/PN mO=M2*nO //results printf("Mass of oxygen added = %.3f lbm",mO)
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0 0.651579 0.0119643 0.5 0.153846 0.5 0.0350877 1 0 0 1 0.5 0.126 0.02197 class0 1 0.037594 0.0298214 0.5 0.461538 0.375 0.00298246 1 0 0 0 0 0.1 0 class0 1 0.286917 0.0892857 0.5 0.923077 0.875 0.0964912 1 1 0.0895522 0 0.5 0.08 0.02072 class1 1 0.518797 0.895893 0.5 0.615385 0.375 0.0614035 1 1 0.0447761 0 0.5 0.06 0...
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// To convert flux density to different units // Modern Electronic Instrumentation And Measurement Techniques // By Albert D. Helfrick, William D. Cooper // First Edition Second Impression, 2009 // Dorling Kindersly Pvt. Ltd. India // Example 2-2 in Page 29 clear; clc; close; // Given data B_cm = 20; // flu...
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%lsslp.sci
function [sr]=%lsslp(s,p) //sr=%lsslp(s,p) <=> sr=s\p // p polynomial matrix // s syslin list //! //origine S Steer INRIA 1992 sr=s\tlist(['lss','A','B','C','D','X0','dt'],[],[],[],p,[],[])
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//Example 8.32 clc disp("Cascading four 74161 (each 4-bit) counters we get 16 (4 x 4) bit counter as shown in fig 8.63.") disp("Therefore, we get 2^16 = 65,536 modulus counter") disp("However, we require divide-by-40,000 counter. The difference between 65,536 and 40,000 is 25,536, which is the number of states thos...
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clf; clear; clc; load('C:\Users\tangu\OneDrive\Documents\GitHub\Modelisation\TD4\NetworkData.sod') // Extraction des temps de service index_bool = ( data(:, 3) == 3 ) tabS3 = data(index_bool, :) t_s3 = tabS3(1:$,4); deciles=perctl(t_s3,10:10:90); for i=2:10 ClassesDeciles(i)=deciles(i-1) end ClassesDeciles(1)=min...
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clc // Given that d = 12e-6 // diameter in m d_ = 90e-9 // diameter of nanoparticle in m // Sample Problem 1 on page no. 22.13 printf("\n # PROBLEM 1 # \n") r = d / 2 r_ = d_ / 2 k = r / 3 k_ = r_ / 3 R = k_ / k printf("\n The ratio of the value of Nb/Ns of spherical particle and nanoparticle = %e .",R)
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disp('chapter 12 ex12.4') disp('given') disp("output =10V to 15V") Vomax=15 disp("max load current=4000mA") Il=.4 disp("Vsmin=Vomax+3 V") Vsmin=Vomax+3 disp('volts',Vsmin) disp("allowing Vrs=3V(p to p)") Vrs=3 disp("Vs=Vsmin+Vrs/2") Vs=Vsmin+Vrs/2 disp('volts',Vs) disp("ZENER CIRCUIT") disp("let Vz=Vo/2") Vz=Vomax/2 d...
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scenario = "Unattended Rivalry"; response_matching = simple_matching; active_buttons = 2; button_codes = 1,2; default_font = "Calibri"; default_font_size = 18; default_text_color = 100,100,100; default_clear_active_stimuli = false; response_logging = log_all; write_codes = true; pulse_width = 6; response_po...
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7_3.sce
//To Calculate the Voltage Drop and Verify The Cable Selected //Page 329 clc; clear; pf=0.9; //Power Factor Vb=120; //Base Voltage //From The Tables r=0.334; //Resistance per thousand feet x=0.0299; //Reactance per thousand feet K1=0.02613; //Voltage Drop //Assumed Cable I=100; //Secodary line Current Ls=...
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//Example 1.5 (c) //To Determine Whether Given Signal is Periodic or not clear; clc ; close ; t=0:0.01:10; x1=cos(2*%pi*t/3); subplot(1,2,1); plot(t,x1); xlabel('t'); ylabel('x(t)'); title('CONTINUOUS TIME PLOT'); n=0:0.2:10; x2=cos(2*%pi*n/3); subplot(1,2,2); plot2d3(n,x2); xlabel('n'); ylabel('x(n)')...
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//example 5.9 //calculate input h.p of pump clc; //given A=20; //area of field H=129; //level to the highest land h1=120.2; //water level in well during discharge Du=800; //duty for rise; eita=0.6; //efficiency of the pump Q=A/Du; w=Q*1000; lift=H-h1; //design...
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clear; //clc(); // Example 11.8 // Page: 287 printf("Example-11.8 Page no.-287\n\n"); //***Data***// T_i = 50;//[F] Initial temperature of the system T_f = 20;//[F] Final temperature of the system M_gas = 115;//[g/mol] Molecular weight of gasoline at room temperature M_water = 18;//[g/mol] Molecular we...
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clear; clc; vf=1; r=1250e3; V=600; x1=.5; x2=.5; x3=.02; ia2=vf/(x1+x2+x3); ia=3*ia2; ia1=ia2; ia0=ia1; iab=r/(sqrt(3)*V); iab=round(iab/10)*10; ia=round(ia*100)/100; If=ia*iab;//the difference in result is due to erroneous calculation in textbook. printf("fault current If=%fA",If); disp("the differenc...
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PL/SQL Developer Test script 3.0 21 -- Created on 08.09.2014 by ZHURAVOV_VB declare -- Local variables here a anydata; o xxdoo_cntr_contractor_typ; c xxdoo_cntr_contractors_typ; -- procedure show(a anydata) is l_type_code pls_integer; l_type anytype; begin l_type_code := a.GetType(l_...
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//Exa 8.2 clc; clear; close; //given data t_hi=160;// in degree C t_ci=25;// in degree C t_ho=60;// in degree C Mh=2;// in kg/s Mc=2;// in kg/s Cph=2.035; // in kJ/kg degree C Cpc=4.187;// in kJ/kg degree C U=250;// in W/m^2 K d=0.5;// in m // Energy balance Mh*Cph*(t_hi-t_ho) = Mc*Cpc*(t_co-t_ci) t_co=...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 4, Example 5") disp("Impeller tip speed is given by") D = 0.914; N = 9000; U2 = %pi*D*N/60 disp("Since the exit is radial and no sli...
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// Caption: Finding per unit system clear; close; clc; Z_baseH=2400/20.8; Z_baseX=240/208; I_x=5.41/208;//per unit at low voltage side Z_eqH=(1.42+%i*1.82)/115.2;//per unit disp(Z_eqH,'equivalent impedence referred to high voltage side')
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// sum 12-5 clc; clear; h=10; t=10/sqrt(2); Ta=80; x=((50*25)+(50*0))/(50+50); y=x; ra=sqrt(x^2+37.5^2); Ixx=(7.07*50^3/12)+(50*7.07*(12.5^2))+(50*7.07*12.5^2); IG=2*Ixx; e=100+(50-12.5); Tr=16.09*10^-3; P=Ta/Tr; P=P*10^-3; // printing data in scilab o/p window printf("P is %0.3f KN ",P);
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clc; t=1/2; //ratio of continuous rating to one hour rating p=2; // ratio of new KVA rating to old KVA rating al=2*(p*t); printf('Ratio of core loss to ohmic loss is %f ',al);
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clc;close;clear; function [A]=Eigen(A) lam = poly(0,'lam') lam = lam charMat = A-lam*eye(3,3) disp(charMat,'The characteristic matrix is') charPoly = poly(A,'lam') disp(charPoly,'the characteristic polynomial is') lam = spec(A) disp(lam,'the eigen values of A are') function...
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// Example 2.38.a:S clc; clear; close; Beta=180;//Common emitter D.C. Current gain Re=1;// Collector resistance in killo ohms R1=5.76;// resistance in killo ohms R2=34.67;// resistance in killo ohms S=1+Beta; disp(S,"Stability factor in fixed bias case is")
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//Continuous Time Fourier Series Coefficients of //a periodic signal x(t) = sin(2*Wot) clear; close; clc; t = 0:0.01:1; T = 1; Wo = 2*%pi/T; xt = sin(2*Wo*t); for k =0:4 C(k+1,:) = exp(-sqrt(-1)*Wo*t.*k); a(k+1) = xt*C(k+1,:)'/length(t); if(abs(a(k+1))<=0.01) a(k+1)=0; end end a ...
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//ex_2.3.a even and odd signals of x(t) clear; clc; close; t = 0:0.01:5; x=exp(t) figure a=gca(); xtitle('x(t)') plot2d(t,x) figure a=gca(); xtitle('even signal') plot2d(t,x/2) t1=-5:1/100:0; plot2d(t1,x($:-1:1)/2) a.y_location='origin' figure a=gca(); xtitle('odd signal') plot2d(t,x/2) t1=-5:1/100...
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syms t s w; y=laplace('sin(w*t)',t,s); disp(y,"ans=")
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aaltonen abano abra achille adina adjani adnet agate agnello agneta agostini agustin ahrweiler ahuja ajit alberdi albertini albo albornoz alcaide alem alesana alessio alia alina alken allegri alvear alvina amaral amati amendola ananta anda anderer andrada andros anis anja anka ansari anselmo ansgar antes antin antje ap...
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//Chapter 10 //Example 10.2 //Page 256 //loadedfault clear;clc; //Given Pgm = 30e6; Vgm = 13.2e3; Xgm = 0.20; Xl = 0.10; Pm = 20e6;pfm = 0.8;Vt_m = 12.8e3; Pbase = Pgm; Vbase = Vgm; Vf = Vt_m / Vbase; Ibase = Pbase / (sqrt(3) * Vbase); I_L = (Pm / (pfm * sqrt(3) * Vt_m)) * (cos(36.9 * %pi/180) + %i * sin(36.9 * %pi / 1...
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//Example 1_3_u2 clc(); clear; //To calculate the uncertenity in momentum h=6.63e-34 deltax=2*%pi*10^-9 deltap=h/(2*deltax) //units in Kg ms^-1 printf("The uncertenity in momentum is delta p=") disp(deltap) printf("Kg ms^-1") //In text book the answer is printed wrong as 0.53*10^-15 Kg ms^-1 the corr...
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function [out]=stack(n,varargin) //build model (cell)array by stacking models along array dimensions // //Calling Seqence //out=stack(n,sys1,sys2.....) // //Parameters //sys : siso or mimo lti system or system array(cell). //n : arraydimension //out:(cell)array of input syst...
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//Example 12.17 //Program to calculate: //(a)The optimium receiver bandwidth //(b)The peak to peak signal power to rms noise ratio clear; clc ; close ; //Given data Tr=12*10^(-9); //s - SYSTEM RISE TIME fo=20*10^6; //Hz - NOMINAL PULSE RATE fd=5*10^6; //Hz - P...
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// Demo script for linear regression getd('../') data_url = 'https://raw.githubusercontent.com/franklinwillemen/Machine_Learning/master/Regression/Simple_Linear_Regression/Salary_Data.csv' machineLearnURLDownload(data_url) machineLearnCustomURL('custom', 'preprocessing.py');
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// EJERCICIO 1 Determine gráficamente valores aproximados de las primeras tres raíces positivas de f(x)=cos(x)cosh(x)+1 deff ('y = f(x)', 'y = cos(x).* cosh(x)+1'); x=0:.01:15; // el 15 sale de ir probando a ver donde estan las raíces. a=gca(); ...
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//Problem 20.24: An a.c. source of 24 V and internal resistance 15 kohm is matched to a load by a 25:1 ideal transformer. Determine (a) the value of the load resistance and (b) the power dissipated in the load. //initializing the variables: tr = 25; // teurn ratio V = 24; // in Volts R1 = 15000; // in Ohms Rin ...
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// Example 5.5 page no-287 clear clc b=50 //Beta vcc=10 //V rc= 250 //ohm ib=0.4 //mA ic=21 //mA vce=vcc-((ic+ib)*rc/1000) vce=floor(vce*10)/10//aproximated to printf("\nVce = %.1fV",vce) vbe=0.6 rb=(vce-vbe)/ib s=(b+1)/(1+(b*rc/(rc+rb*1000))) printf("\nRb = %.0f K-Ohm\nS = %d",rb,ceil(s))
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sistemas lineares - jacobi.sce
clear; clc; // Implementação resolução pelo método de Jacobi function [x, Er]= jacobi(A,b,x0,n) [l,c]=size(A) erro = 1; cont = 1; x = x0; while (cont <= n) xa = x for i = 1:l soma=0; for j = 1:l if(j~=i) then ...
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5_06_solution.sce
//Solution 5-06 WD=get_absolute_file_path('5_06_solution.sce'); datafile=WD+filesep()+'5_06_example.sci'; clc; exec(datafile) V_2 = sqrt(2 * g * z_1); //Toricelli equation printf("Water leaves the tank with initial velocity of %1.2f m/s", V_2);
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clc //initialisation of variables d= 0.275 //in p= 15 p1= 20 p3= 8 //CALCULATIONS Fs= (d*p/100)+(d*p1/100)-(d*p3/100) Fs1= Fs*100/d //RESULTS printf ('final available squeeze = %.2f percent',Fs1)
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//scilab 5.4.1 //Windows 7 operating system //chapter 14 Integrated Circuits and Operational Amplifiers clc clear R1=1*1000//R1=input resistance in ohms in the inverting amplifier circuit Rf=50*1000//Rf=feedback resistance in ohms A=-(Rf/R1)//AV=voltage gain of the inverting amplifier circuit disp(A,"The voltag...
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exa13_6.sce
// Example 13.6 // Inversion with complex Poles s=%s; t=0:0.001:10 num=15*s^2-16*s-7; den=(s+2)*(s^2+6*s+25); F_s=num/den; pfe=pfss(F_s); // partial fraction of the transfer function // from pfe(1) we get B=10; C=-66; alpha=3;// from pfe(1) beta=sqrt(25-9);//Comparing the denominator of pfe(1) with standard...
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clc //Example 16.4 disp('Given') disp('R1=2 ohm R2=3 ohm L=1H C=125mF') R1=2;R2=3 ; L=1;C=125*10^-3; w0=sqrt(1/(L*C)-(R1/L)^2) printf("w0=%d rad/s \n",w0) //Input admittance is 1/R2+i*w*C+1/(R+I*w*L) Y=1/3+%i/4+1/(2+%i*2) printf("Y= %3.4f S \n",Y) //Now input impedance at resonance Z=1/Y printf("Z= %3.4f o...
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//exapple 1.31 clc; funcprot(0); // Initialization of Variable longP=112+20/60+15/3600;//longitude of place GST=8+10/60+28/3600;//GST at GMM lst=18+28/60+12/3600;//local sidereal time dot=longP/15;//difference in time gmm=lst+dot-GST;//SI at GMM i=gmm*9.8565/3600;//error gmm=gmm-i;//LST at L.M.N LMT=gmm...
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clc // Given that V = 30e3 // voltage in V lambda_min = 0.414e-10 // shortest wavelength in m e = 1.6e-19 // charge on an electron in C c = 3e8 // speed of light in m/sec // Sample Problem 2 on page no. 20.7 printf("\n # PROBLEM 2 # \n") printf("Standard formula used \n ") printf("h*c/lambda = eV \n") h = (e * V * lam...
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loadmatfile("matriz.txt") //Funcao que calcula a linha com maior numero de zeros nlin = 0 cont2 = 0 for i = 1:4 cont = 0 for j = 1:4 if matriz(i,j) == 0 then cont = cont + 1 end end if cont > cont2 then nlin = i cont2 = cont for j = 1:4...
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// Scilab code Ex7.3: Pg.292 (2008) clc; clear; l_1 = 2; // Orbital quantum number l_2 = 3; // Orbital quantum number printf("\nThe possible values of l are:"); for l = (l_2-l_1):1:(l_1 + l_2) printf(" %d ", l); end; // Result // The possible values of l are: 1 2 3 4 5
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//Section-14,Example-1,Page no.-PC.7 //To find the temperature at which pressure of gas will reach the bursting value. clc; //PV=nRT P=10 V=(10^-3)*(1/10^-3) n=((5*10^-3)/30) R=0.0821 T=((P*V)/(n*R)) disp(T,'Required temperature(K)')
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clc; clear all; disp("heat lost by man") d=0.35;// m h=1.65;//m ts=28;// degree C ta=12;// degree C U=30*1000/3600;// m/s tf=(ts+ta)/2; // film temperature k=2.59*10^(-2);// W/m.C v=15*10^(-6);// m^2/s Pr=0.707; Re=U*d/v; disp("Nu=C*Re^n*Pr^(1/3)") C=0.027; n=0.805; Nu=C*Re^n*Pr^(1/3); hs=Nu*k/d Q=hs...
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2_1.sce
clc; x=0.9; vg=0.1104; v=x*vg; disp("specific volume is:"); disp("m^3/kg",v) hf=885; h_fg=1912; h=hf+x*h_fg; disp("specific enthalpy is:"); disp("kJ/kg",h); uf=883; ug=2598; u=(1-x)*uf+x*ug; disp("specific internal energy is:"); disp("kJ/kg",u);
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Example_7_14.sce
// Example 7.14 Apply the geometric mean to find general index from the following clc; clear; I=[118 120 97 107 111 93]; W=[4 1 2 6 5 2]; IN=sum(log(I).*W)/sum(W); GI=exp(IN) disp(GI,"General Index",IN,"Log General Index number =")
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//Fx(xn+0.8h) = [C1Fn-1 + C2Fn + C3Fn+1] / H // ESSE AQUI A GENTE USA PRA DERIVADA PRIMEIRA HEEEIN x =[0 1/9 2] // corresponde a n+0,n + 1/9 e n + 2 xc= 0 // onde é calculada a derivada. (xn+0), ficaria = 0 b(1)=0 b(2)=1 b(3)=2*xc //tem que usar aqui xc for i=1:3 M(1,i)=1 M(2,i)=x(i) M(3,i)=x(i)^...
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example_14_3.sce
//Chapter 14 //Example 14.3 //page 538 //To estimate the values of the random variables x1 and x2 using WLSE clear;clc; i=0; x=1;y=8.5 printf('---------------------------------------\n'); printf('iteration\t\tx(l)\n'); printf('---------------------------------------\n'); printf('\t%d\t\t%0.3f\n',i,x); for i=1:1:10 ...
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clear all; clc; //This numerical is Ex 2_1S,page 29. Q1=18.2 N1=1000 N2=1500 delta_p1=10.3 P_s1=6 Q2=Q1*N2/N1 printf("\n The value of Q2 is equal to %g m^3/h",Q2) delta_p2=delta_p1*((N2/N1)^2) printf("\n The value of delta_p2 is equal to %0.1f bars",delta_p2) P_s2=P_s1*(N2/N1)^3 printf("\n The value o...
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//Example 2.34 clc disp("The name of the oscillator is Pierce oscillator") disp("C1 = 1000 pF, C2 = 100 pF, f_s = 1 MHz") ceq=(1000*100*10^-12)/1100 format(11) disp(ceq,"C_eq(in F) = C1*C2 / C1+C2 =") disp("At resonance, X_L = X_Ceq i.e. 2*pi*f*L = 1 / 2*pi*f*C_eq") l=(1/(((2*%pi*10^6)^2)*(90.909*10^-12)))...
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//Scilab Code for Example 2.10 of Signals and systems by //P.Ramakrishna Rao //The value of X(s) is found by solving the differential equation clear; clc; syms t s; s= %s; X=pfss((s^2+8*s+6)/((s+2)*(s+3)*s)); X(1)=1/s; f1=ilaplace(X(1)) f2=ilaplace(X(2)) f3=ilaplace(X(3)) fz=f1+f2+f3; disp(fz*'u(t)',"c) x(...
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ex3_22.sce
// Exa 3.22 clc; clear; close; // Given data h = 6.64*10^-34;// in J-s q=1.6*10^-19;// in C h= h/q;// in eV c = 3*10^8;// in m/s lembda = 0.87*10^-6;// in m E_g = (h*c)/lembda;// in eV disp(E_g,"The band gap in eV is");