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//Chapter 8, Example 8.6 clc //Initialisation f1=1000 //frequency in hertz f2=10 //frequency in hertz f3=100 //frequency in hertz f4=20 //frequency in hertz f5=10**6 //frequency in hertz f6=50 ...
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function F2D=fracF2D(f2D,ac,ar) [M,N] = size(f2D); F2D = zeros(M,N); if ac == 0 F2D = f2D; else for k = 1:N F2D(:,k) = fracF(f2D(:,k),ac); end; end; F2D = conj(F2D'); if ar ~= 0 for k = 1:M F2D(:,k) = fracF(F2D(:,k),ar); end; end; F2D = conj(F2D'); endfunction
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//Chapter 4 //Example 4_2 //Page 74 clear;clc; p=200000; s=10000; n=20; r=0.08; q=(p-s)*r/((1+r)^n-1); printf("Annual payment for sinking fund = Rs. %.0f \n\n", q);
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//================================================================================== // chapter 4 example 13 clc; clear; //input data Er = 1.000074; //dielectric constant for a gas at 0°C //calculation sighe = Er-1; //result mprintf('dielectric susceptibility=%3.6f\n',...
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// Scilab code Ex4.1: Pg.150 (2008) clc; clear; R_H = 1.096776e+07; // Rydberg constant for Hydrogen, per metre // For Lymann series m = 1; // Integer value n = 2; // Integer value lamda = 1/(R_H*(1/m^2 - 1/n^2)); // Wavelength of Lymann series, m printf("\nThe wavelength of first line of Lymann ser...
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// Scilab code Exa11.9 : : Page-538 (2011) clc; clear; q = 1.6023e-19; // Charge of an electron, C B_0 = 1.5; // Magnetic field at the centre, tesla m_d = 2.014102*1.66e-27; // Mass of the deutron, Kg f_max = B_0*q/(2*%pi*m_d*10^6); // Maximum frequency of the dee voltage, mega cycles pe...
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// Scilab code Exa15.1 : : Page-652 (2011) clc; clear; N_0_235 = 1; // Number of uranium atom N_0_c = 10^5; // Number of graphite atoms per uranium atom sigma_a_235 = 698; // Absorption cross section for uranium, barns sigma_a_c = 0.003; // Absorption cross section for graphite, barns f = N_0_23...
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//check o/p when i/p is a char vector x=['a']; [d]=dutycycle(x); //output //!--error 10000 //Input arguments must be double. //at line 56 of function dutycycle called by : //[d]=dutycycle(x); //at line 3 of exec file called by : //cycle16.sce', -1
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.302521D+00 ...
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//Example 1.30 // velocity of light in medium clc; clear; //given data : d1=.3;// diameter of ring in cm d2=.25;//diameter of ring(in cm) after placing in medium c=3D8;//speed of light in m/s u=(d2/d1)^2;// refractive index of medium v=u*c;// velocity of light in fluid disp(v,"velocity of light in liquid in m/...
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//Finding of Vane Angle ,Head ,Velocity ,Efficiency //Given u=12; D=0.8; D1=1; Vw1=0; Hout=1; Vw=12; Vf=3; g=9.81; //To Find a=atand(Vf/Vw); V=sqrt(Vw^2+Vf^2); u1=(D1/D)*u; V1=u1*tan(%pi/9); H=((V1^2/(2*g))+1)+((Vw*u)/g); E=((Vw*u)/(g*H))*100; disp("Absolute Velocity ="+string(V)+" m/sec"); disp("Vane...
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/////////////////////////////////////// //   適応フィルタ(再帰最小二乗法)       //   Adaptive Filter //   Recursive least squares //             //            M.Tsutsui /////////////////////////////////////// clear; funcprot(0); function[y_opt_buf]=RLS(arufa,lambda,update);//arufa:α ,lambda:忘却係数 ,update:更新回数 ...
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//chapter22 //example22.7 //page496 I_DSS=5d-3 // A V_DD=20 // V V_DS=10 // V V_P=-2 // V V_G=0 // V I_D=1.5d-3 // A V_GS=V_P*(1-((I_D/I_DSS)^0.5)) // I_D=I_DSS*(1-V_GS/V_P)^2 V_S=V_G-V_GS R_S=V_S/I_D // by Kirchoff's law we get V_DD=I_D*R_D+V_DS+I_D*R_S so making R_D as subject we get R_D=(V_DD-V_DS...
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clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.9 // Page 220 printf("Example 5.9, Page 220 \n \n"); // solution // (a) T = 305.15 //K Pv1 = 10^(4.0026-(1171.530/(305.15-48.784))) // bar // (b) T = 395.15 Pv2 = 10^(3.559-(643.748/(395.15-198.043))) // bar printf(" ...
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clear; clc; printf("\n Example 16.2"); E = [1 0.64 0.49 0.38 0.295 0.22 0.14]; J = [0 0.1 0.2 0.3 0.5 0.6 0.7]; plot(J,E,rect=[0,1,0,1]); xtitle("Plot for drying data","J = kt/L^2","E"); //For the 10 mm strips mi = (0.28 - 0.07); //Initial free moisture content in kg/kg mf = (0.13-0.07); //Fi...
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// A program to find the form of an interpolating polynomial using the Newton’s forward interpolation. // Input // x and y = A set of data points // Output // yp = A polynomial of the form a0+a1 x+a2 x^2+ ...+an x^n function [yp]=ak_Newton_Fwd_Int_poly(x, y) n=length(x); // Prepare forwa...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 3 : TRANSFORMERS // EXAMPLE : 3.16 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA S = 20 * 10 ^ 3; // Rating of the Step-down Transformer i...
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// To determine percentage of specimens //page no 22 clear clc; m=118.5;// volts mean sd=1.2;// volts psi p1=0.0188;//The probability from tables p1=p1*100; x=116; z=x-(m/sd); p2=0.8944;//The probability from tables p2=p2*100; p=p2-p1; mprintf("Therefore the percentage of specimen falling between 116 and 1...
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// Example 4.3: Design of given circuit to obtain I_D=80uA // FET is operating in saturation region I_D=80*10^-6; // (A) V_t=0.6; // (V) uC_n=200*10^-6; // (A/V^2) L=0.8*10^-6; // (m) W=4*10^-6; // (m) V_DD=3; // (V) V_OV=sqrt(2*I_D/(uC_n*(W/L))); V_GS=V_t+V_OV; V_DS=V_GS; V_D=V_DS; disp(V_D,"V_D (V)") R=(...
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clc #defina a matriz A = [4 3 8 1; 12 10 30 8; 24 25 93 49; 20 19 85 90] [nl,nc]=size(A) for i= 1:nl pivo=A(i,i) for j= i+1:nc A(j,:)=A(j,:)-(A(j,i)/pivo).*A(i,:) end end
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function _make_figures(plot_dir, plot_format) ids_array=winsid(); for i=1:length(ids_array) id=ids_array(i); outfile = sprintf('%s/__ipy_sci_fig_%03d', plot_dir, i); if plot_format == 'jpg' then xs2jpg(id, outfile + '.jpg'); elseif plot_format == 'jpeg' then xs2jp...
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////Ex 10.2 clc; clear; close; format('v',9); Vsat=7;//V R1=68;//kohm R2=82;//kohm VUTP=R2*Vsat/(R1+R2);//V VLTP=R2*-Vsat/(R1+R2);//V disp(VUTP,"Upper trip point(V)"); disp(VLTP,"Lower trip point(V)");
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clear; clc; printf("\t Example 3.7\n"); D=.1; l=3; // l is length of bubble in cm a=3.14*D*l; // area in cm^2 Ca_o=0.0001; //pure conc. of gas in g*mol/cc*atm Ca=0; NA=.482*10^-5; // molar rate of absorption in g*moles/s //Pa_o and Ca_o indicates pure pressure and conc. kl=NA/(...
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// This file is adapted from part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. load Mux8.hdl, output-file Mux8.out, compare-to Mux8.cmp, output-list a%B1.8.1 b%B1.8.1 sel%D2.1.2 out%B1.8.1; set a 0, set b 0, set sel 0, eval, output; set sel 1, eval, ...
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mode(0) function [stop] = imc_virtual(setpoint,fan,alpha) global temp heat C0 u_old u_new e_old e_new fdfh fdt fncr fncw m err_count stop q heatdisp fandisp tempdisp setpointdisp limits m x sampling_time e_old_old e_new = setpoint - temp; b=((1-alpha)/0.01163); u_new = u_old + b*(e_new - (0.9723*e_old));...
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### Datenschutzerklärung für die Nutzung von Disqus Die Kommentarfunktion dieser Website wird von [Disqus, Inc., Law Enforcement Requests, 301 Howard St., Suite 300, San Francisco, CA 94105, USA][3] realisiert. Beachten Sie daher auch die [Disqus Privacy Policy][4]. ### Datenschutzerklärung für die Nutzung von Google...
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void main(void) { int x, y; x=x; x=x+1; x++; --y; return 0; }
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// This file is released under the 3-clause BSD license. See COPYING-BSD. // Generated by builder.sce : Please, do not edit this file // ---------------------------------------------------------------------------- // if ~win64() then warning(_("This module requires a Windows x64 platform.")); return end // libmex_p...
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clc clear //INPUT DATA AW=63.5//atomic weight of copper in u M=63.5*1.66*10^-27//mass of one copper atom in Kg d=8.94*10^3//density of sodium in Kg/m^3 m=9.11*10^-31//mass of electon in Kg h=6.625*10^-34//plank's constant in m^2 Kg/sec e=1.6*10^-19//charge of electro in C //CALCULATION nc=(d)/M//number of e...
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//laplace// syms t s; y= laplace('%e^(-t)+5*t+6*%e^(-3*t)',t,s); disp(y,"ans=")
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clc clear k=0; while 1, k=k+1; if k > 100 then break //interrupt loop end; end disp(k)
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R1=0.2; R2=0.3; R3=0.1; V1=120; V2=110; A=[5,-2;1,-4]; //Applying KCL at the two nodes B=[358.2;-324]; V=inv(A)*B; I1=(120-V(1,1))/R1; I2=(V(1,1)-V(2,1))/R2; I3=(110-V(2,1))/R3; disp("Amperes",I1,"Current I1") disp("Amperes",I2,"Current I2") disp("Amperes",I3,"Current I3")
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// // // steepest descent method with backtracking line search applied to the rastrigin function // // function y=rastrigin(x) // the function to optimize n=max(size(x)); y=n+sum(x.^2-cos(2*%pi*x)); endfunction //----------------------------------------------------- function y=rastr...
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a=1*10^-8; pi=3.14; disp("∆E*∆t=h*∆v*∆t >= h/(4*pi)"); b=1/(4*pi*a); printf('\n So, ∆v >= %f Hz',b); disp("E=p^2/(2*m0)+(-e^2/(4*pi*Є0*r))"); printf('\n'); disp("The minimum value of E occurs at r=5.3*10^-11 m"); m0=9.31; e=1.6; h=1.054; d=8.85; //say d=Є0 c=((-m0)*(e^4)*4*((pi)^2))/(2*(h^2)*(4*pi*d)^2); ...
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//pagenumber 517 example 5 clear induct=500*10^-6;//henry induc1=5000*10^-6;//henry mutuin=300*10^-6;//henry c1=150*10^-12;//farad //(a) frequency indcto=induct+induc1+2*mutuin; freque=1/((2)*3.14*sqrt(indcto*c1)); //(b) condition r=10*10^3;//ohm conduc=8*10^-3;//ampere per volt r1=50*10^3;//ohm r`=r*r1/(r...
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clc(); clear; //(a) //Given: lambda = 5890;// Wavelength in A l = 5.89; //thickness of the film in mu m mu = 1.35; //refractive index delta = mu*l;// optical path in the medium in m //(b) (i)Number of waves in the medium //1 angstrom = 1.0*10^-10 m and 1 mu m = 1*10^-6 m N= (l*10^-6)/(lambda*10^-10/mu); /...
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clc //initialisation of variables clear psif= 10.2 //lbf/in^2 usit= 3.8*10^-7 //lbf sec/ft^2 usif= 3.52*10^-7 //lbf sec/ft^2 Tsit= 530 //R Tsif= 480 //R wf= 15000 //rev/min //CALCULATIONS Psit= psif*usit*sqrt(Tsit/Tsif)/usif wt= wf*sqrt(Tsit/Tsif) //RESULTS printf ('Pressure in the test cell = %.1f lbf/in^...
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// Estimates Discrete time estpoly model // y(t) = [B(q)/F(q)]u(t) + [C(q)/D(q)]e(t) // Current version uses random initial guess // Need to get appropriate guess from OE and noise models // Authors: Ashutosh,Harpreet,Inderpreet // Updated(12-6-16) //function [theta_estpoly,opt_err,resid] = estpoly(varargin) functio...
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clear; clc; // Stoichiometry // Chapter 3 // Material Balances Without Chemical Reaction // Example 3.9 // Page 65 printf("Example 3.9, Page 65 \n \n"); // solution l = 1 //[litre] water (basis) Cl = 475.6 //[mg] m1 = (58.5/35.5)*Cl //[mg] NaCl present in water SO4 = 102.9 //[mg] // SO4 m3 = (142...
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//Exa 4.1 clc; clear; close; //Given Data : format('v',9); r=1.213/2;//in cm f=60;//in Hz ds=0.77888*r;//in cm spacing=1.25;//in meter L=4*10^-7*log(spacing*100/ds);//in H/m disp(L*1000,"Inductance(in H/km) :"); XL=2*%pi*f*L;//in ohm/m disp(XL*1000*60,"Inductive reactance for 60 km line(in ohm) :");
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testSave.tst
(export JS_STORE_PATH="./AppTests/testStore.json"; export JS_DATE="2019-12-01T14:33:49.427Z"; node beverage.js --save --empId 1234 --beverage Orange --qty 2; rm ./AppTests/testStore.json) Transaction Recorded: Employee ID,Beverage,Quantity,Date 1234,Orange,2,2019-12-01T14:33:49.427Z
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consulta_por_color_ojos.tst
PL/SQL Developer Test script 3.0 5 begin -- Call the procedure personas_por_color_ojos(pcolor_ojos => :pcolor_ojos, p_recordset => :p_recordset); end; 2 pcolor_ojos 1 Verde 5 p_recordset 1 <Cursor> 116 0
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clc // Intialization of variables d = 1.23 //Kg/m3 V = 50 // m/s D = 0.004 //m U = 1.79*(10^-5) // N.s/M^2 f1 = 0.00467 l = 0.1 //m f2 = 0.028 // Calculations Re = d*V*D/U Dp = f1*l*d*(V^2)/(D*2) Dp1 = 32*U*l*V/(D^2) Dp2 = f2*l*d*(V^2)/(D*2) // results printf("the pressure drop at 0.1 section of the tub...
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script3.sce
//19/12/18 //TP note de méthode numérique, exo3 //Anandou Candassamy A = [-6, -2, 2,; 0, -2, -4; 3, 1, -1]; t1 = 0.1; t2 = 3.0; rslt1 = matexp2(A, t1); rslt2 = matexp2(A, t2); disp(rslt1, "Résultat de la fonction pour t = 0.1"); disp(expm(A*t1), "Résultat donnée par scilab pour t=0.1"); disp(rslt2, "Ré...
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ex_2_27.sce
//Example 2.27 // distributed capacitance clc; clear; close; //given data : C1=410; // in pico-farad C2=50; // inpico-farad f1=2; // in MHz f2=5; // in MHz F=f2/f1; Cd=(C1-F^2*C2)/5.25; disp(Cd,"the self capacitance,Cd(pico-farad) = ")
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ex30_10.sce
clc; A=107.87; //atomic mass in gm F=96500; //in Coloumb v=1; //valency z=A/(F*v); //calculating ECE using Faraday's Law disp(z,"(a)Electrochemical Eqvivalent = "); //displaying result A1=16; //atomic mass in gm v1=2; //valency z1=A1/(F*v1); //Faraday's L...
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//page 385 clc primary_alpha=((0.77-.5)/(0.77-0.0218))*100 pearlite=((0.5-0.0218)/(0.77-0.0218))*100 disp(primary_alpha,"primary alpha in percentage =") disp(pearlite,"pearlite in percentage =") //Answer difference is due to roundoff
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example5.sce
function y=_f(x) y=0 for i =1:6 y=y+sin(x(i)); end endfunction x1 = [-2, -2, -2, -2, -2, -2]; x2 = [2, 2, 2, 2, 2, 2]; //exec builder.sce //exec loader.sce options=list("MaxIter",[1500],"CpuTime", [100],"TolX",[1e-6]) [xopt,fopt,exitflag,output,zl,zu] = fminbnd(_f,x1,x2,options)
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clc; funcprot(0); //Example 22.3. //Initializing the variables Ma = 0.6; Cl = 0.6; tByC = 0.035; // Thickness to chord ratio cByC = 0.015; // Camber to chord ratio x = 3; // Angle of incidence //Calculations lamda = 1/sqrt(1-Ma^2); Cl# = lamda*Cl; tByC1 = tByC*lamda; cByC1 = cByC*lamda; Cl1 = Cl*lamda^...
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//problem 22 pagenumber 2.105 //given rc1=1;format(3);clf(); vi=5;//volt c=1e-6;//farad r=1e6;//ohm x0=0;x1=1:1:5; //determine output voltage v0=integrate('5','t',x0,x1); disp('Output voltage = -'+string(v0(5))+" V"); subplot(1,2,1); x=linspace(1,5,5); y=5* ones(length(x),1); plot(x,y); xtitle('input waveform problem E...
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Gload.sce
// for the GLoad feature // Copyright INRIA if strindex(gl_name,'.')<>[] then select part(gl_name,k($)+1:length(gl_name)); case "sci" then getf(gl_name), case "sce" then exec(gl_name), case "scg" then xload(gl_name), case "bin" then load(gl_name), case "cos" then scicos(gl_name) case "cosf" then scico...
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//poly2ac a = [1.0000 0.4288 0.76 0.0404 -0.02]; efinal = 0.2; // Step prediction error r = poly2ac(a,efinal); // Autocorrelation sequence disp(r); //Output // !--error 10000 //Input polynomial has to be a 1-dimensional array //at line 35 of function poly2ac called by : //r = poly2ac(a,efin...
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clf(); a=gca();a.isoview='on'; drawTriangle(); drawAxis(1,0.2:0.2:0.9,"%4.2f",fontSty=2,fontSiz=4.0); drawAxis(2,0.2:0.2:0.9,"%4.2f",fontSty=2,fontSiz=4.0); drawAxis(3,0.2:0.2:0.9,"%4.2f",fontSty=2,fontSiz=4.0); vertexLabel(1,"A",fontSty=8,fontSiz=4.0); vertexLabel(2,"B",fontSty=8,fontSiz=4.0); vertexLabel(3,"C",fon...
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clc //Chapter 5:High Frequency Amplifiers and Automatic Gain Control //example 5.5 page no 159 //given s=poly(0,"s") Vo=-(0.4-s*4*10^-12)*(966*10^3) Vth=s^2*(79.6*10^-18)+s*(190.2*10^-9)+1 disp(Vo/Vth,'the transfer function is ') wz=10^11//transfer function zero w1=-5.5*10^6//pole due to input circuit w2=-2.4...
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//CAPTION:Characteristic_Impedance_of_a_Coplanar_Stripline //chapter_no.-11, page_no.-507 //Example_no.11-3-1 clc; Pavg=250*(10^-3);//average_power_flowing_in_the_positive_z_direction Io=100*(10^-3);//total_peak_current Z0=(2*Pavg)/(Io^2); disp(Z0,'the_characteristic_impedance_of_the_coplanar_strip_line(in ...
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Rencana TA -Algoritma *SPK *Pencarian ^PDF -IOT -Studi Kasus ^Disdukcapil ^Mitsubishi -Big Data
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//Variable declaration: T1 = 138.0 //Temperature of oil entering the cooler (°F) T2 = 103.0 //Temperature of oil leaving the cooler (°F) t1 = 88.0 //Temperature of coolant entering the cooler (°F) t2 = 98.0 //Temperature of coolant leaving the cooler...
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//chapter 4 //example 4.8 //page 113 clear all; clc ; //given hfe1=50;//minimum value hfe2=150;//maximum value Vbe=0.7; Vcc=15;//supply voltage V R1=18.6;R2=11.4;//kohm VT=(Vcc*R2)/(R1+R2); RT=(R1*R2)/(R1+R2); Rc=1;//kohm Re=1.0; //for hfe=50 Ic1=(VT-Vbe)/(RT/hfe1+Re*(1/hfe1+1));Ic1=4.31; Vce1=Vcc-...
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exec ex1.sci exec ex3.sci exec ltisol.sci exec step_feuler.sci exec feuler.sci exec jacobiant.sci exec step_beuler.sci exec beuler.sci exec mixed_euler.sci exec cicled_euler.sci exec alpha_mixed_euler.sci exec global_error.sci
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exec('C:/home/juan/Escritorio/Scilab/Simpson.sci',-1); deff('[y]= f(x)', 'y= (3*(x^3)+(%e^x))'); x=[0:0.1:0.8]; [s] = Simpson(x,f); disp(s);
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clc clear //Input data T=300;//The given temperature in K R=8.3*10^7;//The Universal gas constant in ergs/g mol-K //Calculations E=((3/2)*(R*T))/10^7;//The total random kinetic energy per gram -molecule of oxygen in joules //Output printf('The total random kinetic energy of one gm-molecule of oxygen a...
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clear y //to delete function y=foo(x) disp('dans ''foo'' x='+string(x)) y=1+x^2 disp('dans ''foo'' y='+string(y)) endfunction x=2 z=foo(1) // inside "foo" x is 1 x // x is still equal to 2 y // y doesn't exist here
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compile(skip:1 ; skip:2, C) :: C = [noop:1, noop:2]. phrase(stmt(S), [var(x), =, 5, +, 7]), add_control_points(S, Sp), compile(Sp, C) :: C = [push(7), push(5), add, store(x):_, eop:_]. phrase(stmt(S), [var(x), =, 5, *, 3, -, 2]), add_control_points(S, Sp), compile(Sp, C) :: C = [push(2), push(3), push(5), mult, su...
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//Desenvolver um programa em Matlab que leia 20 //valores correspondentes as notas de //PCI. As notas variam de 0 a 10, somente valores //inteiros. Calcular e escrever a //Frequência Absoluta e a Frequência Relativa //das notas lidas. //Obs: //a)Frequência Absoluta é a quantidade de vezes que uma nota ocorreu no ...
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//output power of cable //given clc alpha=0.28//db/m//attenuation alpha_50m=0.28*50//db//attenutaion of 50 m cable pi=0.4//watt//input power//ERROR po=pi/(10^((alpha_50m)/10))//watt//output power disp(po*1000,'the output power of 50m in mW ')//mW //ERROR in calculation of the book as pi=0.04
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clear;lines(0); pwd
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// Chapter 6_The pn junction //Caption_Junction capacitance //Ex_5//page 230 Na=10^16 //acceptor ion concentration T=300 //temperature in kelvin Nd=10^15 ni=1.5*(10^10) //intrinsic ion concentration Vr=5 //Reverse applied voltage Vbi=0.635 V=Vr+Vbi C=(e*eps*Na*Nd/(2*(V)*(Na+Nd)))^0.5 A=10^-4 //Are...
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//This script demonstrates the use of ODE solver and computing the //solution at different times. The output is in the form of a plot //of time versus computed solution clear clc //Definition the function. function ydot = func(t,y) ydot = t^2*exp(-2*t) + y endfunction //Initial condition y0 = -1; //Start time t...
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clear // W=500.0 //weight of block F1=200.0 //force up the inclined plane when block is moving down F2=300.0 //force up the inclined plane when block is at rest //When block starts moving down the plane //sum of all forces perpendicular to the plane = 0 //N =Wcoso //sum of all forces parallel to the plane = ...
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fir_lpf_impulse_response.sci
// this file gives the impulse response of an ideal LPF function [h_n]=impulse_response_ideal_lpf(w_p, n_max) // passpand till w_p n = -n_max:n_max; h_n = (w_p/%pi)*sinc(w_p*n); endfunction //n_max = 500; //wp2 = 1.767; //wp1 = 1.386; //h1 = impulse_response_ideal_lpf(wp2,n_max); //n_axis = -n_...
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2d Program to solve algebraic and transcendental equation by Newton Raphson.sce
deff('y=f(x)','y=sin(x)-x/2'); deff('y1=f1(x)','y1=cos(x)-1/2'); x0=2, d=0.0001; c=0;n=1; printf('successive iterations \tx0 \tf(x0) \tf1(x0) \n'); while n==1 x2=x0; x1=x0-(f(x0)/f1(x0)); x0=x1; printf('\t%f \t%f \t%f \n',x2,f(x1),f(x1)); c=c+1; if abs (f(x0))<d break; end end pr...
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//chapter 20 //example 20.2 //page 905 printf("\n") printf("given") Vs=30;Vd1=.7;Vg=.8;Ig=200*10^-6; Vspk=1.414*Vs disp(" at 5 degree") es=Vspk*.087// sin5=.087 disp(" at 90 degree") es=Vspk Vt=Vd1+Vg disp(" to trigger at es=3.7V the R2 moving contact is at the top") es=3.7; Vr1=es-Vt I1=1*10^-3; R1=Vr...
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// Given:- // When expressed on a per mole of fuel basis, the balanced chemical equation obtained in the solution to Example 13.2 takes the form // CH4 + 2.265O2 + 8.515N2 ----- .951CO2 + .049CO + .289O2 + 8.515N2 + 2H2O cpbar = 38.00 // specific hea...
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numbers.sce
randomize_trials=true; write_codes = true; pulse_width = 100; begin; text { caption="0"; font_color = 255,255,255; font_size = 400; } tx0; text { caption="1"; font_color = 255,255,255; font_size = 400; } tx1; text { caption="2"; font_color = 255,255,255; font_size = 400; } tx2; text { caption="3"; font_color = 255,...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clc;clear; //Example 25.7 //calculation of product of two binary numbers //given values X='10101';//first binary number with last two digits in fractional part Y='101';//second binary number with last two digits in fractional part //calculation x=bin2dec(X);//decimal equivalent y=bin2dec(Y);//decimal equiva...
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ok_LRA.tst
; checks that all symbols in LRA are defined and that various ; expressions in the language are permitted (set-logic LRA) (declare-fun a () Real) (declare-fun b () Real) (assert (= a (+ a b))) (assert (= a (+ b 1))) (assert (= a (+ b 1.0))) (assert (= a (+ 1 b))) (assert (= a (+ 1.0 b))) (assert (= a (- a b))) (assert...
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//Finding efficiency //Example 15.35(pg. 416) clc clear m=2//quantity of aluminium to be melted in kg t1=15,t2=660//temp in degreeC S=0.212//specific heat of aluminium L=78.8//latent heat of aluminium in kcal/kg H=(m*S*(t2-t1))+(m*L)//total heat required to melt Al in kcal i=5//input to furnace in kW E=i*(100...
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// Example 7.10: [45/0/90/-45]_S, truncated max. strain mode(0); funcprot(0); clc; clear; exec('C:\Users\EJB\OneDrive\Scilab\CLT.sci');// see Appendix CLT.sci E1 = 126E3; E2 = 11E3; G12 = 6.6E3; //MPa, AS4/3501-6 v12 = 0.28; tt = 0.8; tk = 0.125; //mm F1t = 1950; F1c = 1480; F2t = 48; F2c = 200; F6 = 79;//MPa or...
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//example 11.12 clc; funcprot(0); z1=21/2; Lg=9; Bg=6; Qg=500*1000; Cc1=0.3; Cc2=0.2; Cc3=0.25; H2=12; H3=6; H1=21; e1=0.82; e2=0.7; e3=0.75; s1=Qg/(Lg+z1)/(Bg+z1); //sigma1 s2=500*1000/(9+27)/(6+27);//sigma2 s3=500*1000/(9+36)/(6+36);//sigma3 ss1=6*105+(27+21/2)*(115-62.4);//sigmadash1 ss2=6*105+(27...
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scenario = "frame"; scenario_type = fMRI_emulation; #scenario_type = fMRI; scan_period = 3000; response_matching = simple_matching; no_logfile = false; sequence_interrupt=false; #default active_buttons = 2; button_codes=0,1; default_font="arial"; default_font_size=30; default_text_color=255,255,255; default_background_...
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m=[0 1 0 1 0 0 1 0 0] e1=1 e2=3 fsk=[] n=0:0.001:1 for i=1:length(m) if m(i)==0 then fsk=[fsk 1*sin(2*%pi*e1*n)] else fsk=[fsk 1*sin(2*%pi*e2*n)] end end plot(fsk); xgrid(4)
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//example 11.11 clc; funcprot(0); Lg=9.92; Bg=7; n1=3; Nc=8.75; n2=4/1000; Ap=14^2/12^2; cup=1775; a1=0.4;//alpha1 p=4*14/12; cu1=1050; L1=15; a2=0.54;//alpha2 cu2=1775; L2=45; FS=4; Qu=n1*n2*(9*Ap*cup+a1*p*cu1*L1+a2*p*cu2*L2); Qu2=Lg*Bg*cup*Nc+2*(Lg+Bg)*(cu1*L1+cu2*L2); disp(Qu2/1000,"load in kip") ...
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//ques-18.25 //Calculating pressure at which water must be heated to produce superheated steam clc Hv=540;//latent heat of vapourization (in cal/g) T1=273+100; T2=273+150;//temperature (in K) P1=1;//in atm R=1.987;//cal/mol/K //On solving, log(P2/P1) = (Hv*(T2-T1))/(2.303*R*T1*T2) P2=P1*4.709 printf("The requi...
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//Example 1.17<i> //Determine the power and the rms value of the signal clc; t=0:0.001:10; y=5*cos(50*t+%pi/3); P=(integrate('5^2*(cos(50*t))^2','t',0,2*%pi))/(2*%pi); rmsvalue=sqrt(P); disp(P,'The power of the given signal is:'); disp(rmsvalue,'the rms value is:'); //Example 1.17<ii> //Determine the power am...
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//Chemical Engineering Thermodynamics //Chapter 15 //Fuel Cells //Example 15.1 clear; clc; //Given del_F = -56.29;//Standard free energy change in Kcal/Kgmole del_H = -68.317;//Standard heat of reaction in Kcal/kgmole F = 23.06;//Electro-chemical equivalent in Kcal/volt J = 2;//Valance for H2 //To Calc...
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//problem 1.9 s1=1.6 s2=0.8 s3=13.6 p1=98100 p2=176580 w=9810 h1=p1/w h2=p2/w h=(h2-h1+1.6*s2-4.1*s1)/(s3-s2) disp(h.*100 ,"difference in mercury level(cm)")
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//chapter-4,Example4_12,pg 491 printf("normal count would be 2^3=8, while 5-modulo counter would limit it to 5, so that illegitimate states are 8-5=3")
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<?xml version="1.0" ?> <TestCase name="testing1" version="5"> <meta> <create version="10.0.0" buildNumber="10.0.0.431" author="admin" date="03/22/2018" host="inbasdpc10722" /> <lastEdited version="10.0.0" buildNumber="10.0.0.431" author="admin" date="03/22/2018" host="inbasdpc10722" /> </meta> <id>A7E1B70E2C0B...
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3_14.sce
//example 3.14 //lagrange's interpolation formula //page 105 clc;clear;close; y=[4 12 19]; x=[1 3 4]; y_x=7; Y_X=0; poly(0,'y'); for i=1:3 p=x(i); for j=1:3 if i~=j then p=p*((y_x-y(j) )/( y(i)-y(j))) end end Y_X=Y_X+p; end disp(Y_X,'Y_X=');
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clc // initialization of variables // The reaction equation for theoritical air is //C3H8 + 5(O2 + 3.76N2) ---> 3CO2 + 4H2O + 18.8N2 // for 250% theoritical air reaction becomes //C3H8 + 12.5(O2 + 3.76N2) ---> 3CO2 + 4H2O + 47N2 + 7.5O2 // All the enthalpy of formation values are taken from Table B.5 with ...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex8_7.sce. clc; clear; P=300e3; V=500; a=8; p=4; Z=786; theta=5; I=P/V; armature_AT=(1/2)*(I/a)*(Z/(2*p)); //Total AT per pole demagnetizing_AT...
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//caption:Find magnitude of limiting error fot R1 and R2 //Ex2.5 clc clear close R1=36//resistance(in ohm) R2=75//resistance(in ohm) er=0.005//limiting error(in ohm) dR1=R1*er disp(dR1,'magnitude of limiting error for R1(in ohm)=') dR2=R2*er disp(dR2,'magnitude of limiting error for R2(in ohm)=')
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clear; //clc(); x2d=(%i)*0.3; xl1=(%i)*0.08; xline=(%i)*0.55; xl2=(%i)*0.08; ig=0.75; z2t=x2d +xl1 +xline + xl2; er=1; eint=er+ig*z2t; e2int=sqrt(real(eint)^2 + imag(eint)^2); x2gf=imag(x2d + xl1); i2d=e2int/x2gf; x2bf=imag(xl1 +xline); i2df=er/x2bf; tot_i2d=i2d +i2df; printf("The total subtransie...
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//=========================================== // Exercise 21: Eddy formation in a Strait //=========================================== // Animation of Eulerian concentration & surface flow fields // Author: Jochen Kaempf, March 2015 (update) f = gcf(); f.color_map = jetcolormap(64); f.figure_size = [1000,500]; s...
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//check o/p when i/p arg sps is of type char beta=0.3; span=3; sps='a'; h=rcosdesign(beta,span,sps); //output // !--error 10000 //input variable should be of type double //at line 10 of function checkIpValidity called by : //at line 34 of function rcosdesign called by : //h=rcosdesign(beta,span,sps); //...
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clear clc disp('probability of problem not getting solved=1/2*2/3*3/4=') 1/2*2/3*3/4 disp('probability of problem getting solved=1-(1/2*2/3*3/4)=') 1-(1/2*2/3*3/4)
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clear clc //to find average velocity for interval AD and DF //to find slope of position curve at the points B and F and compare it with the value in velocity curve //to find average acceleration in the interval AD and AF //to find slope of velocity curve at the points D and compare it with the value in accelera...
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// Initilization of variables W1=2000 //N (or 2 kN)// load at joint D of the truss W2=4000 //N (or 4 kN)// load at joint E of the truss Lac=6 //m // length of the tie Lab=3 //m Lbc=3 //m theta=60 //degree // interior angles of the truss // Calculations // Here A is simply supported & B is roller support. Now t...
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//Example 4.10 clear; clc; //Given R=8.314;// gas constant in J K^-1 mol^-1 Cp=2.5*R; //specific heat capacity at constant pressure of the gas in J K^-1 mol^-1 V1=10;//volume of gas in m^3 T1=300; //initial temperature in K T2=400;//final temperature in K P=101000;//pressure in N m^-2 //to calculate the e...