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//clear// clear; clc; //Example 21.4 //Given Nre = 20000; T = 40; //[C] D = 2; //[in.] Dv1 = 0.288; //[cm^2/s], for water-air Dv2 = 0.145; //[cm^2/s], for ethanol-air //Solution //For air at 40 C rho = 29/22410*273.16/313.16; //[g/cm^3] mu = 0.0186; //[cP], from Appendix 8 mubyrho = mu*10^-2/rho; //[cm...
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function [S, P]=FloydSPR(AdjMax) // *INPUT:* // AdjMax: Adjacent matrix that represents a weighted, directed graph // // *OUTPUT:* // S: distance to destination node // P: next hop node // // *DESCRIPTION* // Given a input adjacent matrix (AdjMax) that represents a weighted, directed graph. // The function finds the ...
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//Exa 4.1 clc; clear; close; L=poly(0,'L') //Defining L as lambda l=10*L N=20 // number of elements d=l/N // formula : BW=(2*(L/d)*1/N) BW1=(horner((2*L/(N*d)),1)) disp(BW1,"Null-to-null BW of broadside array in radians when l=10*L,N=20:") l=50*L N=100 // number of elements d=l/N // formula : BW=(2*(L/...
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//Example 7.4 //page 436 //Control Systems: Principles and Design //M Gopal, Second Edition, Tata McGraw-Hill //Chapter:Compensator Design Using Root Locus xdel(winsid())//close all graphics Windows clear; clc; //transfer function s=%s; P=1/((s)*(s+3)*(s^2+2*s+2)); //Root locus plot using evans root loc...
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clc; //Example 17.2 //page no 201 printf("Example 17.2 page no 201\n\n"); rpm=1694//speed of fan q=12200//flow rate of q_a rpm_n=2100//new speed of fan q_n=q*(rpm_n/rpm)//new flow rate printf("\nnew flow rate q_n=%f acfm",q_n); //applyingeq 17.5 P=5//pressure ,in P_n=P*(rpm_n^2/rpm^2)//new pressure printf...
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clear; clc; clf; // enter cut-off frequencies and input length wc1 = input("Enter the starting cut-off frequency") wc2 = input("Enter the ending cut-off frequency") M = input("Enter the input length") Tuo = (M-1)/2 // center value // if the cut off frequencies are equal if wc1 == wc2 then wc = wc1*%pi for n ...
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//Example18.3 delta_Vac=42//in volt R_eq=14//in ohm I=delta_Vac/R_eq disp("solution b") disp(I,"Current in amps=")
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//Марчук Л.Б. 5307 подгруппа 3 //Данный модуль принимает на вход корни характеристического многочлена; //возвращает практическую длительность переходного процесса. function result = PTime(p1, p2) result = 3/min(abs(real(p1)), abs(real(p2))); endfunction
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clc; clear; function Rxx = autocor(N,L) // Generates a random signal x = rand(1,N*L,"normal"); // Fill a matrix (NxN) with zeros Rxx = zeros(N,N); // Main loop for l = 0 : L-1 /* Creates L different vectors of segmented parts from the original random signal */ ...
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// Exa 6.8 format('v',7);clc;clear;close; // Given data R1 = 1.2;// in k ohm R1 = R1 * 10^3;// in ohm R2 = 4.7;// in k ohm R2 = R2 * 10^3;// in ohm C1 = 1;// in µF C1 = C1 * 10^-6;// in F C3 = 1;// in µF C3 = C3 * 10^-6;// in F Rx = (R2*C1)/C3;// unknown resistance in ohm Rx = Rx * 10^-3;// in k ohm Cx = (...
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// Scilab Code Ex9.4 Page:280 (2006) clc;clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV E_g = 3.4e-04; // Energy gap of aluminium, eV v_F = 2.02e+08; // Fermi velocity of aluminium, cm/sec h_bar = 1.05e-034; // Planck's constant L = h_bar*v_F/(2*E_g*e); // Coherence Length of aluminium, cm ...
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// Exa 1.22 clc; clear; close; // Given data vo= -10;// in V i_f= 1;// in mA i_f= i_f*10^-3;//in A // Formula vo= -i_f*Rf Rf= -vo/i_f;// in Ω // The output voltage, vo= -(v1+5*v2) (i) // vo= -Rf/R1*v1 - Rf/R2*v2; (ii) // Comparing equations (i) and (2) R1= Rf/1;// in Ω R2= Rf/5;//...
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clear //variable declaration //summation of all horizontal forces is zero & vertical forces is zero. //Let the left support C be at a distance x metres from A. P1=(30) //vertical down load at A,KN Pu=(6) //uniform distributed load over whole span,KN/m,(20m of span) P...
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//Example No. 6.6 clc; clear; close; format('v',6); //Given Data : V=400;//volt P=8;//pole f=50;//Hz r1=1.2;//ohm r2dash=1.2;//ohm x1=2.5;//ohm x2dash=2.5;//ohm N=720;//rpm Ns=120*f/P;//rpm S=(Ns-N)/Ns;//full load slip S2=2-S;//Slip during plugging V1=V/sqrt(3);//V I2dash=V1/sqrt((r1+r2dash/S2)^2+(...
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clear; clc; // A Textbook on HEAT TRANSFER by S P SUKHATME // Chapter 2 // Heat Conduction in Solids // Example 2.16 // Page 75 printf("Example 2.16, Page 75 \n\n") //Theoretical Problem printf('\n\n This is a Theoretical Problem, does not involve any mathematical computation.'); //END
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clear;lines(0); xset("use color",1) champ1(-5:5,-5:5,rand(11,11),rand(11,11),2,[-10,-10,10,10],"021")
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//Compression ratio r=8; //Compression and expansion process follow the law pv^1.3=const n=1.3; //Pressure at beginning of compression(in bar) p1=1; //Temperature at beginning of compression(in K) T1=300; //Specific heat at constant pressure(in kJ/kgK) Cp=1.004; //Specific heat at constant volume(in kJ/kgK) ...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.270712D+00 ...
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//Caption: efficiency //Example 9.44 //page no 436 //Find efficiency of the code clear; clc; px1=1/2; px2=1/4; px3=1/8; px4=1/8; n1=1 n2=2; n3=3; n4=3; //information content of each symbol Ix1=-log2(px1); Ix2=-log2(px2); Ix3=-log2(px3); Ix4=-log2(px4); HX=px1*log2(1/px1)+px2*log2(1/px2)+px3*lo...
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// Define positive a quaternion // // This function ensures that the scalar part is positive. // This function is typically used to ensure sign of vectorial part // when considering the product of two quaternions with a small angles // approximation. // // INTPUT // - qIn: input quaternion // // OUTPUT // - qOut: quat...
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//Chapter2, Ex2.6,Pg 2.11 function [R] = deltatostar(R1,R2,R3,n) Rtotal=R1+R2+R3 if(n==1) R=R1*R2/Rtotal elseif(n==2) R=R2*R3/Rtotal else R=R1*R3/Rtotal end endfunction clc; disp("Refer to the diagram shown in the figure") r1=deltatostar(20,5,15,1) //Converting delta...
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//Example 8_2<b> //determine the nyquist rate of x(t)=sinc2(200*pi*t) //sinc(400t)=0.5cos(400t)/400t clc; clear all; wp=400; F1=wp/2; Fs=2*F1; disp('Nyquist Rate='); disp(Fs);
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-5,Example 19,Page 186 //Title: Power consumed by the compressor //================================================================================================================ clear clc //INPUT Ti=25;//te...
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% OUTER_HULL Compute the "outer hull" of a potentially non-manifold mesh (V,F) % whose intersections have been "resolved" (e.g. using `cork` or % `igl::selfintersect`). The outer hull is defined to be all facets (regardless % of orientation) for which there exists some path from infinity to the face % without intersect...
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h=6.625*10^-27;//plank's constant// g=10^3;//particle mass in grams// l1=1;//length of one dimensional box in cm// n1=1; n2=2; dE1=((n2^2-n1^2)*h^2)/(8*g*l1^2);//Energy difference between two energy levels of particle in eV// printf('Energy difference between two energy levels of particle=dE1=1*10^-44eV'); l2=2*...
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polys[0]=0 polys[1]=-4 polys[2]=-4 polys[3]=2,1 order=2 initialize: mN=-1, mRElen=3, mNPlen=1, mOrder=2, mLinit=2 exp: multiply ring=[0,0,*0] by mN=0 exp: multiply ring=[0,0,*0] by mN=0 exp: multiply ring=[0,0,*0] by mN=0 setRE(0,1): [*0,0,0] -> [*1,0,0] result=1, RE=[*1,0,0] 0 1 exp: multiply r...
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//Linear convolution clc clear close x = input("sequence x(n): ") h = input("sequence h(n): ") y = conv(x,h) disp("Linear Convolution: ",y) //plots x_n = 0:length(x)-1; h_n = 0:length(h)-1; y_n = 0:length(y)-1; figure(0) subplot(311) plot2d3(x_n,x) plot(x_n,x,"red.") title("x(n)") xlabel("---> samples (n)") ylabel(...
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I = imread('C:\Users\loujoseftan\Dropbox\SciNotes\Act 7\ROI.jpg'); I = double(I); //I is the image of the region of interest imshow(I); R = I(:,:,1); G = I(:,:,2); B = I(:,:,3); Int = R+G+B; Int(find(Int==0))=100000; r = R./ Int; g = G./Int; BINS = 32; rint = round(r*(BINS-1) + 1); gint = round(g*(BINS-1) + 1)...
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clc disp("Example 2.4") printf("\n") printf("Given") disp("Current through diode is 30mA") //From the table the nearest value is at v=0.74V V=0.74;I=28.7*10^-3; R=V/I; delV=0.75-0.73 delI=42.7*10^-3-19.2*10^-3 r=delV/delI p=(V*I)*10^3 printf("\n \n Static resistance is %3.2fohm\n",R) printf("Dynamic resist...
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//Chapter-2, Illustration 1, Page 55 //Title: Gas Power Cycles //============================================================================= clc clear //INPUT DATA P1=0.1;//Pressure of air supplied in MPa T1=308;//Temperature of air supplied in K rv=8;//Compression ratio q1=2100;//Heat supplied in kJ/kg C...
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clear; clc; disp("--------------Example 4.5---------------") data_rate=1; // 1 Mbps frac= 0.25 // 4B/5B coding adds 25% to the baud rate add=data_rate*frac; N = (data_rate+add)*10^6; // Hz NRZI_B= N/2; // minimum bandwidth using NRZ-I Manchester_B = data_rate; // minimum bandwidth using Manchester scheme // d...
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timelimit 5 boardsize 10 play w C3 play w D3 play w F3 play b A2 play w B2 play w C2 play w D2 play w E2 gogui-rules_board genmove b # b's move can be any (random because loss) gogui-rules_board genmove w #?[F2|E3] gogui-rules_board genmove b # b's move can be any (random because loss) gogui-rules_board # Should comp...
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clear// //Variables V = 10.0 //Voltage (in volts) R1 = 10**6 //Resistance (in ohm) R2 = 10 * 10**3 //Resistance (in ohm) //Case (a): //Calculation RT = R1 + R2 //Total Resistance (in ohm) I = V / RT //Current (in Ampere) //Result p...
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clc clear //Input data P=100//Power in MW T=550//temperature in degree C p=0.1//Pressure in bar m=500000//Mass flow rate in kg/h at rated load mo=25000//Mass flow rate in kg/h at zero load x=[1/4,1/2,3/4,1]//Fraction of load //Calculations b=(m-mo)/(P*10^3)//Steam rate in kg/kWh y1=(x(1)*(P*10^3))//For on...
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//Example 15.10. clc format(6) disp("(i) To find capacitance, C:") disp(" Frequency of oscillation is") disp(" fo = 1 / 2*pi*fo*R*C*sqrt(6+4K)") disp(" C = 1 / 2*pi*fo*R*C*sqrt(6+4(Rc/R))") fo=1/(2*%pi*(10*10^3)*(7.1*10^3)*sqrt(6+((4*40*10^3)/(7.1*10^3)))) // in Farady x1=fo*10^9 // in nF disp(x1," C(nF)...
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//Exa 5.13.9 clc; clear; close; //Given data bita = 100; V_CE = 0.2;//in V V_BE = 0.8;// in V R_C= 500;// in Ω R_B= 44*10^3;// in Ω R_E= 1*10^3;// in Ω V_CC= 15;// in V V_GE= -15;// in V // Applying KVL to collector circuit // V_CC-V_GE - I_Csat*R_C-V_CE-I_E*R_E=0, but I_Csat= bita*I_Bmin and I_E= 1+bita ...
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//chapter-6,Example6_4,pg 493 d=1*10^-3//separation between plates fe=300//acceleration of electron e=1.6*10^-19//charge of 1 electron me=9.1*10^-31//mass of 1 electron Vp=((me*fe*d)/e)//voltage apllied between plates printf("voltage applied between plates\n") printf("Vp=%.14f Kgm^2/s^2C",Vp)
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//Book - Power system: Analysisi & Design 5th Edition //Authors - J. Duncan Glover, Mulukutla S. Sarma, and Thomas J.Overbye //Chapter-9 ;Example 9.6 //Scilab Version - 6.0.0; OS - Windows clc; clear; Vf=1.05 //Prefault voltage in per unit Z0=%i*0.250 ...
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//clear// //Caption:Transform the vector of Rectangular coordinates into spherical coordinates //Example1.4 //page 22 clc; y = sym('y'); x = sym('x'); z = sym('z'); ax = sym('ax'); ay = sym('ay'); az = sym('az'); ar = sym('ar'); aTh = sym('aTh'); aphi = sym('aphi'); G = (x*z/y)*ax; disp(G,'Given vector i...
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Ex6_6.sce
clear; clc; funcprot(0); //page no. 188 p1 = 14.7;// psia v1 = 1732;// fps a1 = 862;// fps beta = 40;// degrees M1 = v1/a1; T1 = a1^2 /(1.4*32.2*53.3); p2 = p1*(1 + 2*(1.4/2.4)*(M1^2 *(sin(beta*%pi/180))^2 -1)); theta = beta - (180/%pi)*atan(tan(beta*%pi/180) * (0.4*(M1*sin(beta*%pi/180))^2 +2)/(2.4*...
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Figure6_4.sce
//clear// //Caption:Power Spectra of different binary data formats //Figure 6.4: Power Spectal Densities of //Different Line Coding Techniques //[1].NRZ Polar Format [2].NRZ Bipolar format //[3].NRZ Unipolar format [4]. Manchester format //Page 241 close; clc; //[1]. NRZ Polar format a = input('Enter the Amp...
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clc; clear; r=30000e3; v1=11e3; v2=110e3; zb1=v1^2/r; zb2=v2^2/r; zp1=80/zb2; zp2=.1*%i*30000/35000; zp3=.2*%i*30000/10000; zp3r=real(zp3); zp2r=real(zp2); zp3i=imag(zp3); zp2i=imag(zp2); zb2=round(zb2*10)/10; zp1=round(zp1*1000)/1000; zp2i=round(zp2i*10000)/10000; zp3i=round(zp3i*10)/10; mprintf("the...
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newRKAlgorithm.sce
function ydot = f(t, y) ydot = 6 * t^4 + 5 * t^3 + 4 * exp(t); endfunction h = 0.01; y(1) = 0; t(1) = 0; for i=1:50 k1 = f(t(i), y(i)); k2 = f(t(i) + h/2, y(i) + h * k1 / 2); k3 = f(t(i) + 3*h/4, y(i) + 3*h*k2/4); k4 = f(t(i) + h, y(i) + 2*h*k1/9 + h*k2/3 + 4*h*k3/9); y(...
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sphere_harmonics1.sce
//Spherical harmonics //solution for perturbed pressure for a spherical hydrodynamical system //Using scilab //http://www.scilab.org/ //Scilab is free and open source software for numerical computation providing a powerful computing environment //for engineering and scientific applications. //http://solarwavetheory...
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sce
31_18.sce
clear// //Variables fo = 2.0 * 10**3 //Frequency (in Hertz) hie = 2.0 * 10**3 //hie (in ohm) R1 = 20.0 * 10**3 //Resistance (in ohm) R2 = 80.0 * 10**3 //Resistance (in ohm) RC = 10.0 * 10**...
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//Example 3.25 //Program to Compute the 8-point Circular Convolution of the Sequences //x1[n]=[1,1,1,1,0,0,0,0] //x2[n]=sin(3*pi*n/8) clear; clc ; close ; x1=[1,1,1,1,0,0,0,0]; n=0:1:7; pi=22/7; x2=sin(3*pi*n/8); //DFT Computation X1=fft (x1,-1); X2=fft (x2,-1); //Circular Convolution using DFT Y=X1.*X2...
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hacker.tst
TITLE: THE HACKER TEST - Version 1.0 (LONG) Preface: 06.16.89 This test was conceived and written by Felix Lee, John Hayes and Angela Thomas at the end of the spring semester, 1989. It has gone through many revisions prior to this initial release, and will undoubtedly go through many more. (Herewith a compe...
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//Calculate the Specific conductance //Example 8.1 clc; clear; C=0.689; //Cunductance of the cell in ohm^-1 c=0.255; //Cell constant in cm^-1 (c=l/A) k=C*c; //Specific conductance in ohm^-1 cm^-1 printf("Specific conductance = %.3f ohm^-1 cm^-1",k);
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//ques10(i) clc disp('To find the the given integral find the laplace of tsin(t) and put s=2 '); syms t s m f=sin(t)*t; l=laplace(f,t,s) s=2 disp(eval(l));
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//Ex 5.2 page 185 clc; clear; close; R=5;// ohm Vs=300;// V f=1*1000;// Hz Ton=20;// ms Toff=10;// ms k= Ton/(Ton+Toff);// duty ratio f=1000/(Ton+Toff);//Hz Voav=Vs*k;// V Ioav=Voav/R;// A printf('\n duty ratio = %.3f',k) printf('\n chopping frequency = %.2f Hz',f) printf('\n Average load voltage = %.2f V', Voav) pr...
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0014.tst
spLitteR S {} FiLtEr CiVR { } fIltER l {B or noT S OR VI or Mkb } Y -> Okt -> F -> rr -> Ec groUpEr q {moDUle e{ f > VkU dElta 5720 } aggrEgate yjE } UNGrOUper d { } gRouPFiLTEr wFN {biTOR () oR 3.228.153.228 NOT in izVPV or bf:3D:cD:FE:Ab:6D IN 6 } merGER aK { modUle S { bRanchEs U, uv not zK ( ) } moD...
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// Updated(18-7-07) // 8.1 sys = tf(10,[5 1]); sysd = ss2tf(dscr(sys,0.5));
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clc; VEE=10; RE=10*10**3; RB=100*10**3; B=50; VBE=0.7; IE=(VEE-VBE)/(RE+(RB/B)); re=25/IE*10**-3; Ri=B*(RE+re); disp('Kohm',Ri*10**-3,"Ri="); Ris=(RB*Ri)/(RB+Ri); Rs=0; Ro=re+((RB*Rs)/(RB+Rs))/B; disp('ohm',Ro,"Ro="); Av=RE/(re+RE); disp(Av);
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clc //Initialization of variables disp("from steam tables,") h1=1416.4 //B/lbm s1=1.6842 //B/lbm R //calculations s2=s1 P2=50 //psia T2=317.5 //F h2=1193.7 W=h2-h1 //results printf("Work calculated = %.1f B/lbm",W)
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Arrowdata.sci
// 08.05.08 function Out=Arrowdata(varargin) global YaSize YaAngle YaPosition YaThick YaStyle; Nargs=length(varargin); P=varargin(1); Q=varargin(2); R=Q; Futosa=YaThick; Ookisa=YaSize; Thickness=1; Hiraki=YaAngle; Yapos=YaPosition; Position=1; Str=YaStyle; Flg=0; for I=3:Nargs Tmp=varar...
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//Exa 13.3 clc; clear; close; //given data : SP=500;//in Rs. VC=300;//in Rs. FC=400000;//in RS. BEP=FC/(SP-VC);//in units disp(BEP,"BEP in units : "); disp("Since the demand(1500units) is less than the break even quantity, the company should buy the cabinets for its TV production.")
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// Example : 4.58 v1=233.73-%i*8.934; vs=240+%i*0; r1=0.6+%i*0.8; i1=(vs-v1)/r1; disp('the value of I1 is = '+string(i1)+' Amp'); r2=0.5+%i*0.866; vs1=239.5-%i*14.359; i2=(vs1-v1)/r2; disp('the value of I1 is = '+string(i2)+' Amp'); r3=16+%i*12; il=i1/r3; disp('the value of I1 is = '+string(il)+' Amp...
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//Example 1_24 clc; clear; close; format('v',6); //given data : V1=6;//V V2=15;//V R1=6;//ohm R2=3;//ohm R3=4;//ohm R4=6;//ohm //writing KVL equation for the loop I=poly(0,'I'); eqn=V2-R2*I-R1*I-V1;//KVL equation I=roots(eqn);//A VCD=V2-R2*I;//V //Potential of point A with respect to B VAB=VCD;//V VO...
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clc // Given that w = 2 // work function of sodium in eV h = 6.62e-34 // Planck constant in J-sec c = 3e8 // speed of light in m/sec e = 1.6e-19 // charge on an electron in C // Sample Problem 19 on page no. 14.27 printf("\n # PROBLEM 19 # \n") printf("Standard formula used \n ") printf(" E = (h * c)/ lambda \n") lamb...
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//Example:15.43 //eigen values of matrix A clear;clc; xdel(winsid()); A=[0 6 -5;1 0 2;3 2 4]; spec(A)
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clear;lines(0); timer();A=rand(100,100);timer()
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function [n]=vonNeumannNextRand(n) l=ceil(log10(n)); sn=""; for i=floor(l/2)+1:floor(3*l/2), j=part(string(n^2),i); sn=sn+j; end; n=evstr(sn); endfunction function [result]=MS_gen(N,seed) result=[]; n=seed; for i=[1:N], n=vonNeumannNextRand(n); result($+1,1)=n/9999; end endfunction ...
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//clear// //Example 10.36:To find output response of an LTI System syms n z; H = z/(z+3) X = z/(z-1) Y = X*H F1 = Y*(z^(n-1))*(z-1); y1 = limit(F1,z,1); F2 = Y*(z^(n-1))*(z+3); y2 = limit(F2,z,-3); disp(y1*"u(n)"+y2*"u(n)",'y[n]=') //Result //y[n] = u(n)/4-(-3)^(n+1)*u(n)/4 //Equivalent to = (1/4).u[n]-...
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SPLItter N {} fiLter cq { } fILtER y {YsK rC or nOt D oR nOt Q E Not i Or E or M } r brAnCh f grOUPEr Tj {moduLe g{ } mOduLe k{ } aGGReGate kWQ ,tbTXt ,suM(Q.D) aS u } uNGrOuPEr AHds { } gROUPFIlteR dMM {noT O ( 157.58.123.161, ::C2Ee:c:EDb:cE2:bB4:cEd:6, ) BITANd ( D, ) } MergEr l { export Rw }
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//fiber optic communications by joseph c. palais //example 3.2 //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given SW=1//spectral width of laser in nm lambda1=0.82e-6//wave length in m d=10//path length in km lambda2=1.5e-6//wave length in m M1=110//Material dispersion ps/(nmxKm) for lambda1 M2...
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//Chapter-2 example 2.9 //============================================================================= clc; clear; Pt=500000;//peal power in watts F=10*10^9;//operating frequency in hz MRP=0.1*10^-12;//minimum receivable power in pico watts Ac=5;//capture area of antenna in m^2; RCS=20;//radar cross sectional ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 2: CONSTANTS OF OVERHEAD TRANSMISSION LINES // EXAMPLE : 2.11 : // Page number 109 clear ; clc ; close ; // Clear the wo...
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//example 6.2 clc; funcprot(0); // Initialization of Variable Qcdot=8000; Wcycledot=3200.0; Tc=268.0; Th=295.0; Beta=Qcdot/Wcycledot; disp(Beta,"coeff. of performance"); Betamax=Tc/(Th-Tc); disp(Betamax,"maximum coeff. of performance"); clear()
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bref=[];bnorm=[];income-mean=[];rents=[]; bref(1)=5000; bnorm(1)=10000; income-mean(1)=10000; rents(1,1)=36.529802855125276; rents(1,2)=36.52980285512526; rents(1,3)=36.529802855125254; rents(1,4)=36.52980285512521; rents(1,5)=36.529802855125226; rents(1,6)=36.52980285512523; rents(1,7)=36.52980285512532; rents(1,8)=36...
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system("--allow-net", 1); system("--min-time", "0.001"); system("--ticks-per-sec", 1000); LIB"../LIB/f5ex2.lib"; sprintf("Example: Katsura-10"); katsuran(10); bigint mem2 = memory(2); int tr = timer; ideal g = f5e(i); timer-tr; memory(2)-mem2; nvars(basering); size(i); size(g); $
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//To find total load clc //Given: P=120*1000 //W d=250/1000, r=d/2 //m N=650 //rpm phi=20 //degrees //Solution: //Calculating the angular speed of the gear omega=2*%pi*N/60 //rad/s //Calculating the torque transmitted T=P/omega //N-m //Calculating the tangential load on the pinion FT=T/r //N //Calculating...
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// Exa 6.10 // To calculate the data link protocol efficiency with //(1) Stop and Wait protocol — full duplex, //(2) SRP with window size W=8, and //(3) Go-Back-N protocol with window size W=8. clc; clear all; Tprop=4; //maximum propogation delay in sec R=10; // data rate in Mbps PackLen=400; //data pack...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 5.36\n\n\n"); // Chapter 5 : Properties Of Liquids And Gases // Problem 5.36 (page no. 219) // Solution //Because the tank volume is 10 ft^3,the final specific volume of the steam is 10 ft^3/lbm.Interpolations in Table A.2 yield a final pressure of 42 p...
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clc; disp("Example 3.13") density=1000 // in kg/m^3 b= 0.005 // gap between plates in m mew=0.1 // viscosity in kg/ms q=1/60 // in m^3/s/m U= q/b // here the pressure gradient is delP= 12*mew*U/b*b delP= (12*mew*U)/(b*b) Re= b*U*density/mew disp(" Reynolds number is ") disp(Re)
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errcatch(-1,"stop");mode(2);// Example 4.11, page no-213 //(a) v_obj=2/1000 wt=1.5 dx=wt/v_obj sg=dx/1000 printf("(a)\nSpecific Gravity = %.2f",sg) //(b) sgl=0.8 dens=800 W1=dens*v_obj-wt printf("\n(b)\nW1 = %.1f kg",W1) //(c) sg2=1.2 dens2=1200 W2=dens2*v_obj-wt printf("\n(c)\nW2 = %.1f kg",W...
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function buf=hrtSerialRead(h,n) if ~exists("n","local") then N=serialstatus(h); n=N(1); end TCL_EvalStr("binary scan [read "+h+" "+string(n)+"] cu* ttybuf") buf=part(msprintf(" %02s",dec2hex(evstr(TCL_GetVar("ttybuf")))'),2:$); endfunction
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// Scilab Code Ex5.30: Page-300 (2008) clc; clear; e = 1.602e-019; // Energy equivalent of 1 eV, J E1 = 3.2e-018/e; // Minimum energy possible for a particle entrapped in a one dimensional box, eV n = [1 2 3 4]; // Principal quantum number for K, L, M and N states printf("\nThe next three energies which t...
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//2.52 clc; Kq=40*10^-3; Cp=1000*10^-12; K=Kq/Cp; printf(" Sensitivity of the transducer=%.2f V/m",K) Cc=300*10^-12; Ca=50*10^-12; C=Cp+Cc+Ca; Hf=Kq/C; printf("\n High frequency sensitivity =%.2f V/m",Hf) R=1*10^6; tc=R*C; M=0.95; w=(1/tc)*[(M^2)/(1-M^2)]^0.5; f=w/(2*%pi); printf("\n Minimum frequency=%...
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errcatch(-1,"stop");mode(2);// Example 19.3, page no-542 H=10^4 //A/m sus=-0.8*10^-5 mu=4*%pi*10^-7 M=sus*H B=mu*(M+H) printf("The flux density in the material is %.2f * 10^-2 Wb.m^-2",B*10^2) exit();
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// RLC circuit problems on resonace clc; clear; R=6.28; L=20*(10^-3); f=5*(10^3); w=2*%pi*f; C=1/(L*(w^2)); Xc=1/(w*C); Xl=L*w; Vc=5; Z=Xc+R+Xl; I=Vc/Xc // Total current V=I*R; // frequency is inversely proportional to square root of capacitance // So if C is halved; f will increase s...
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clc; mH2O=3*18; q=2441.8; h0=-3301397+(mH2O*q) disp(h0,"Δh0 for H2O in the vapour phase:")
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clc; // page no 842 // prob no 22.1 PR = -100;//In dBm // The mobile transmitted power is PT_dBm =-76-PR;//this is in dBm disp('or','dBm',PT_dBm,'The mobile transmitted power in dBm is'); PT_mW =10^(PT_dBm/10); disp('mW',PT_mW,'The mobile transmitted power is');
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//Chapter 2 //Example 2-2 //ProbOnPWM //Page 34 clear;clc; //Given f=50;//in Hz Vtemp=4; //input signal in volts Ecm=10; //maximum peak voltage of sawtooth carrier wave in volts //Example 2-2(a) T=1/f; Th=(Vtemp*T)/Ecm;//High time in seconds printf("\n\n High Time = %.4f s \n\n",Th) //Example 2-2(b) d=(Th/T)*100;//...
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//example6.11 clc disp("I_m=15 mA, R_m=1.5 ohm at 15 degree celcius, R=3.5 ohm") r=1.5+3.5 disp(r,"Therefore, R_mT(in ohm)= Total meter resistance = 1.5+3.5 = ") disp("i) I=20A") r=(15*5*10^-3)/(20-(15*10^-3)) format(10) disp(r,"Therefore, R_sh(in ohm)=[(I_m)*(R_mT)]/[I-(I_m)]=") disp("ii) V=250 V") r=(100/(1...
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// generujemy punkty X1 = 2 * rand(1, 20); X2 = 2 + 2 * rand(1, 20); Y1 = 2 * rand(1, 20); Y2 = 2 + 2 * rand(1, 20); X = [X1 X2]; Y = [Y1 Y2]; Z = (-1) * ones(1, 40); // macierz punktow P = [X; Y; Z]; D = [ones(1,20) zeros(1,20)]; plot(X1, Y1, 'go'); plot(X2, Y2, 'rx'); function y=perceptron(x, w) net = x * w';...
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clc; funcprot(0); //Example 9.1 Lift due to Circulation // Initialisation of variables D = 4; L = 12; V = 40*1.467; rho = 0.002378; W = 100/60; // Revolution per second // Calculations R =D/2; Vt = 2*%pi*R*W; T = 2*%pi*R*Vt; Lift = rho*T*V; L_total = Lift*L //Results disp(L_total,"Total lif...
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clc; // answer is calculated for torque=30 but it is asked for torque=40 i.e why answer varies p=4; // number of dc series motor f=4*10^-3; // ratio of flux per pole to armature current T=40; // torque of fan n=1000; // speed of motor a=2; // number of parallel path for waave winding z=480; // number of conducto...
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//Example 11.1: Total Length clc; clear; close; //given data : l=20;// in m w=0.5;// weight per meter in kg T=500;// Tension applied in kg del=(w*l^2)/(2*T); two_S=2*(l+(2/3)*(del^2/l)); disp(two_S,"Total Length(m) = ")
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// Test # 8 : Input Argument #1 or #2 length test exec('./allpasslp2bp.sci',-1); [n,d]=allpasslp2bp([0.3,0.2],[0.6,0.8]); //!--error 10000 //Wo must be real ,numeric and scalar //at line 36 of function allpasslp2bp called by : //[n,d]=allpasslp2bp([0.3,0.2],[0.6,0.8]);
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//mdl_cylindrical.sce cylindrical robot // This file creates a cylindrical (RPP) robot // www.controlsystemslab.com October 2012 clear L; // length and offset parameters d1 = 1; d2 = 2; // maximum stretch for variable d2, d3 d3 = 1; L(1)=Link([0 d1 0 0]); L(2)=Link([0 d2 0 -pi/2],'P'); // prismatic j...
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//Ex 3.11 page 125 clc; clear; close; Vs=230;// V Io=5;// A alpha = 45;// degree printf('part(i)') Vo=2*sqrt(2)*Vs/%pi*cos(alpha*%pi/180);// V printf('\n dc output voltage = %.1f V',Vo) Pi=Vo*Io;// W printf('\n Active power = %.1f W',Pi) Qi=2*sqrt(2)*Vs/%pi*sin(alpha*%pi/180)*Io;// VAR printf('\n Reactive power = %.1...
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//Example 2.5 clc funcprot(0); sum = 10+ 20; printf("%d\n", sum);
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clc; clear; //Y is a Gaussian Random Variable syms y; x=5; m=-3*(x)+5; //mean disp(m,"mean"); var=4*7; //variance disp(var,"variance"); Y=exp(-{(y+10)^2}/56)/sqrt(56*%pi); disp("Y is an N{-10,28} random variable"); disp(Y,"density function f(y)= ");
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// Example 11_3 clc;funcprot(0); // Given data p=1.00;// MPa // Solution // From Table C.2b at p = 1.00 MPa, we find that, h_fg=2015.3;// kJ/kg T_sat=179.90;// °C s_fg=h_fg/(T_sat+273.15);// kJ/kg .K printf("\nThe phase change entropy for water,s_fg=%1.4f kJ/kg.K",s_fg);
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clc; clear all; m = 9.1e-31; // Mass of electron in kg h = 6.62e-34; // Planck's constant in J.s c = 3e8; // Velocity of light in vaccum lambda = 1.8e18; // Frequency of the incident rays theta = 180;//angle in degree lambda = c/lambda; delta = (h*(1-cosd(theta)))/(m*c); Nlambda = lambda+delta;//'Wavelength of...
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//Determine the value of base resistance clear; clc; //soltion //given B=100; //dc beta Rc=200;//ohm //resistor connected to collector Re=500;//ohm //resistor connected to emitter Vcc=9;//V //Voltage supply across the collector as it is PNP so taking positive Vce=4.5;//V //...
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int sum(int x, int y) begin return x + y; end main begin int s; int x; int y; int z; x = 1; y = 2; z = 3; s = sum(x, y, z); return s; end
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// chapter 14 // example 14.9 // Determine motor torque, motor current and supply power factor // page-878-879 clear; clc; // given P=20; // in HP (power rating of motor) E0=650; // in V (voltgae rating of motor) N=1000; // in rpm Ra=0.25; // in ohm (armature resistance) K_af=0.03; // in NmA^2 K_res=0.075; // in Vs/rad...
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3_12.sce
clear; clc; printf("\t\t\tExample Number 3.12\n\n\n"); // Three-dimensional numerical formulation // Example 3.12 (page no.-110-113) // solution Tinf = 10;// [degree celsius] environment temperature h = 500;// [W/square meter degree celsius] Ts = 100;// [degree celsius] four side temperature k = 2;// [W/m de...
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//program to solve differential equation using runge-kutta method function []=rungekutta(x0,y0,xn,h) deff('y1=f(x,y)','y1=x+y') while x0<xn k1=h*f(x0,y0) k2=h*f(x0+h/2, y0+k1/2) k3=h*f(x0+h/2, y0+k2/2) k4=h*f(x0+h,y0+k3) k=(k1+2*k2+2*k3+k4)/6 x0=x0+h ...