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//Example6.17 // determine the closed loop gain clc; clear; close; // the output of the voltage follower is given as //Vo = Aop(V1-Vo); // the closed loop gain of the voltage follower //A = 1/(1+(1/Aop)); // for Aop = 10^4 closed loop gain Aop = 10^4 ; A = 1/(1+(1/Aop)); disp('for Aop = 10^4 closed ...
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function [p,r]=circuit(g) // Copyright INRIA [lhs,rhs]=argn(0) if rhs<>1 then error(39), end // check g check_graph(g) // compute lp, la and ls n=g('node_number') ma=prod(size(g('tail'))) if g('directed')==1 then [lp,la,ls]=m6ta2lpd(g('tail'),g('head'),n+1,n) else error('The graph must be directed') end // compute ...
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-- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -- and may be covered by U.S. and Foreign Patents, patents in process, and are protected by trade -- secret or copyright law. Dissemination of this information or reproduction of this material is -- strictly forbidden unl...
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function r=%spbcb(a,b) // perform [a b] where a is a boolean sparse matrix // and b a boolean matrix r=[a sparse(b)]
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function p=parallel(r1,r2) p=r1*r2/(r1+r2) endfunction //as seen from ab Vth1=30*60/(30+60) Rth1=parallel(30,60) //as seen from cd Vth2=80*40/(40+60) Rth2=parallel(40,60) Vnet=60+Vth1-Vth2 Rnet=Rth1+Rth2 disp(Rnet,Vnet)
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function [x]=gaussseidel(A,b,x0) [nA,mA]=size(A) n=nA [L,U] = lu(A) d = diag(A) a11 = d(1,1) a22 = d(2,1) a33 = d(3,1) D = [a11 0 0;0 a22 0;0 0 a33] H = -inv(L+D)*U C = inv(L+D)*b for m=0:3 x = -inv(D)*(L+U)*x + inv(D)*b m=m+1 disp(x) end endfunction
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clc,clear printf('Example 1.11\n\n') V_t=225 //voltage across winding R_a=0.04 //armature resistance R_sh=90 //shunt resistance R_se=0.02//resistance of series field winding I_L=75 //load current //E -I_a*R_a=V_t+I_L*R_se I_sh=(V_t+I_L*R_se)/R_sh //current through shunt field winding I_a=I_L + I_sh //...
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//Example 3.13(a) clear; clc; C=10*10^(-9);//Assumed C1=C; C2=C; f0=1*10^3; BW=100; R=(2^(1/2))/(2*%pi*f0*C); R1=R; R2=R; R3=R; Q=f0/BW; K=4-((2^(1/2))/Q); RA=10*10^3; RB=(K-1)*RA; RG=K/(4-K); printf("Designed KRC Second Order Band Pass filter"); printf("\nR1=R2=R3=...
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//example 11.5 clc; funcprot(0); D=[6, 12, 20]; fc=[34.34, 54.94, 70.63]; alpha=[0.84, 0.71, 0.63]; dL=[6, 6, 8]; p=4*0.305; Qs=0; printf(" depth(m)\t fc(kN/m^2)\t alpha \t deltaL(m)\t Q(kN)\n"); for i=1:3 Q(i)=alpha(i)*fc(i)*p*dL(i); Qs=Q(i)+Qs; printf("%.2f\t\t %.2f\t %.2f\t %.2f\t\t %....
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// retrieve the Scilab interface language getlanguage() // in French at first // modify Scilab interface language setlanguage('en_US') // change to English setlanguage('fr_FR');//to delete
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// Demo script for PCA getd('../macros') // Data preparation M = csvRead('Datasets/titanic.csv') x = M(:, [2,3,6,7,8,10]); x(or(isnan(x),'c'),:) = [] x = real(x); pca = PCA(x); disp(pca)
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//caption:stability_using_Nyquist_criterion //example 12_23_iii //page 535 disp("for K=10") g=(10*(s+10)*(s+40))/(s*(s+1)*(s+4)); g1=(10*(s1+10)*(s1+40))/(s1*(s1+1)*(s1+4)); GH=syslin('c',g); GH1=syslin('c',g1); nyquist(GH); nyquist(GH1); //mtlb_axis([-1.5 0.2 -0.3 0.3]); xtitle('Nyquist plot of (0.1*(s+10)*(s+40))/(s*...
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T1: T2 T4 T7 T2: T3#ignore me plz T5 T3: T4: T5 T6 T5: T6: T5 T7: T6
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//root finding by Newton-Raphson Algorithm : Linear Equation function eqn=f(x) eqn=(x.^2)-(6*x)+5; // roots=1,5 endfunction x=-7;//root=1 //x=7;//root=5 xR=-10:10; plot(xR,f(xR)); xtitle("plot: f(x)=(x^2)-6x+5","x","f(x)"); xgrid(color("grey")); while(f(x)<>0), plot(x,f(x),'r-o'); dfdx = n...
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Rearth= 1.5*10^(11); //radius of earth, m r= 1.4; //rate of arrival of sunlight, kW/m^2 P= (r*10^3)*4*(%pi)*(Rearth^2); //total power reaching Earth Rsun= 7*10^(8); //radius of Sun, m r2= P/(4*(%pi)*(Rsun^2)); //radiation rate of Sun, W/m^2 emissivity=1; //for blackbody Sig= 5.670*10^(-8); //Stefan's constant,...
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clear; clc; // Illustration 12.8 // Page: 705 printf('Illustration 12.8 - Page: 705\n\n'); // Solution //***Data***// x1 = 8;// [percent moisture] x2 = 0.5;// [percent moisture] Rate_prod = 0.63;// [kg/s] // Drying Gas: xCO2 = 0.025;// [mole fraction] xO2 = 0.147;// [mole fraction] xN2 = 0.760;// ...
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N = input('Donner un entier naturel non nul') S = zeros(1,N) // permettra de calculer les fréquences empiriques for k = 1:10000 i = 1 // i modélise le rang du tirage M = N // M modélise le nombre de boules restant dans l'urne while (________________) i = i+1 M = _______________ ...
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//Page Number: 434 //Example 8.9 clc; //Given e=0.0001; s=330; //Charge transfer effciency n=1-e; //Final charge pulse //x=P/P0 x=(1-(e*s)); disp(x,'Final charge pulse:');
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echo "### Test Ex6-1" ../bin/carat/Bravais_catalog << EOF 1;1;1;1 y stdout a EOF echo "### Ex6-1 return code $?" echo "### Test Ex6-2" ../bin/carat/Bravais_catalog << EOF 4-1 y stdout a EOF echo "### Ex6-2 return code $?" echo "### Test Ex6-3" ../bin/carat/Bravais_inclusions Ex6_B echo "### Ex6-3 return code $?" ec...
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function[x, k] = newtonBDF(f, dfdx, tol, Kmax, x0, h, theta, U, V) if Kmax - floor(Kmax) ~= 0 | Kmax < 0 error('Kmax must be an int'); end if tol < 0 | abs(tol) < %eps error('wrong tol'); end endfunction
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clc clear //Conditions at 7 bat P=7; //in bar Tsat=165+273; //in K Hf=697.2; //in kJ/kg Hfg=2066.3; //in kJ/kg Hg=2763.5; //in kJ/kg Vg=0.273; //in m^3/kg D=0.02; //in m vel=17; //in m/s Cps=4.187; //in kJ/kg K Tw1=...
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; @Harness: disassembler ; @Result: PASS section .text size=0x00000100 vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x00000134 ;2**0 start .text: label 0x00000000 ".text": 0x0: 0xfd 0xf5 brhc .+126 ; 0x80 0x2: 0xf5 0x...
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clc //initialisation of variables w=500//ft p=20//psig h=40//psig h1=1000//in q=1250//ft g=2.308/0.75//ft g1=2.308/1.00//ft s=5200//gpm a=250//gpm //CALCULATIONS H=[h1-(1/2)*(w)]//ft H1=(h-p)*g//percent Q=[q-(1/2)*(w)]//ft Q1=(h-p)*g1//percent S=s/a//gpm //RESULTS printf('the number of standard fire s...
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clc;clear; //Example 16.4 //given data mo=9.1*10^-31;//mass of electron in kg m=1.67*10^-27;//mass of proton in kg c=3*10^8;//speed of light in m/s E=1;//given energy in MeV //calculations Eo=mo*c^2/(1.6*10^-13); mbymo=1+(E/Eo); disp(mbymo,'Ratio for electron'); Eo=m*c^2/(1.6*10^-13); mbymo=1+(E/Eo); d...
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clf(); clc //Chapter3: Modulation //Example3.11, page no 144 //Given deff("[y]=f(x)","y=Ec*(1+ma*(sin(wm*x)))*sin(wc*x)") Ec=10,ma=0.5,wm=10000*%pi,wc=2*%pi*1e7 x=[0:0.01:20]*%pi/10; subplot(2,1,1) fplot2d(x,f) xlabel("t", "fontsize", 3); ylabel("Modulated Wave", "fontsize", 3, "color", "red"); Fc=wc/(2*%pi...
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//Problem 16.10: A coil of inductance 100 mH and resistance 800 ohm is connected in parallel with a variable capacitor across a 12 V, 5 kHz supply. Determine for the condition when the supply current is a minimum: (a) the capacitance of the capacitor, (b) the dynamic resistance, (c) the supply current, and (d) the Q-fa...
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+---a---b---c---d---e---f---g---h---+ | | 8 . . . . . . . . 8 | | 7 . . . . . . . . 7 | | 6 . . . . . . . . 6 | | 5 . . . ...
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// Example 5.7:corner frequency and maximum magnitude asymptote clc; clear; close; Cp=2;//PARALLEL RESISTANCE IN PICO FARAD rs=2;//series resistance in killo ohms rp=10;//PARALLEL resistance in killo ohms tp= ((rs*rp)/(rs+rp)*10^3*Cp*10^-12);//time constant f= (1/(2*%pi*tp))*10^-6;//corner frequency in mega her...
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clc //initialisation of variables p=14.2//psia t=140//F r=6//ratio p1=1300//Btu h1=53.3//ft t1=460//F p2=14.0//ft w=0.1715//ft w1=172.0//ft v=2.64//cu ft per lb v1=15.86//cu ft per lb h2=600//ft x1=517500//ft-lb per lb //CALCULATIONS V=1*h1*(t+t1)/(144*p2)//cu ft per lb P=p2*(r)^1.4//psia P1=(t+t1)*r^...
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//Problem 41.14: An asymmetrical pi-section attenuator is shown in Figure 41.28. Determine for the section (a) the image impedances, and (b) the iterative impedances. //initializing the variables: R1 = 1000; // in ohm R2 = 2000; // in ohm R3 = 3000; // in ohm I1 = 1; // in amperes (lets say) //calculation: /...
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[[-5,0,4],[0,3,0],[-4,0,5]],det=-27 [0,1,1], chain 2 => [4,3,5] => [0,9,9] ?? [36,27,45] [[-5,0,3],[0,4,0],[-3,0,5]],det=-64 [0,1,1], chain 2 => [3,4,5] => [0,16,16] ?? [48,64,80] [[-2,1,2],[-1,2,2],[-2,2,3]],det=-1 [0,1,1], chain 8 => [3,4,5] => [8,15,17] => [33,56,65] [[-2,2,2],[1,2,1],[-1,2,3]],det=-8 [0,1,1], ch...
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Using TensorFlow backend. Obteniendo datos... [AVISO] Usuarios: 5139 [AVISO] Restaurantes: 598 [AVISO] Cargando datos generados previamente... Creando modelo... ################################################## MODELV4 ##################################################...
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//algoritimo de gauss n =3 //a11 x1 +a12 x2 +a13 x3 = b1 //a21 x1 +a22 x2 +a23 x3 = b2 //a31 x1 +a32 x2 +a33 x3 = b3 //eliminação regressiva //iteração 1 e 2; i=1; j=2 && j=3 (j=i+1 até n) //multiplica: a21/a11 a31/a11 => aij/aii //nb = n+1 //matriz aumentada //|a11 a12 a12 b1(a14)| (1) //|a21 a22 a23 b2(a24)| (2) /...
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clear clc function [x, P, A, b] = Gauss(A, b) n = size(A, 1) P = eye(n, n) if( det(A) == 0 ) error("Argiroffo informs: ¡El determinante es cero, nene!") end for i = 1:n mx = A(i, i) idmx = i for j = i+1:n if(abs(A(j, i)) > mx) mx = A(j, i)...
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clc; clf; clear; //question 1 I = exp(1)-1; for n = 1:20; I = exp(1) - n*I end; //question 2 S = 0 for i = 0:20; S = S + 1 / ((i+21)*factorial(i)); end; disp(S)
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//Trapezoidal Rule clc; clear; close(); format('v',10); funcprot(0); disp('Integral 0 to 2 e^x dx'); disp('based on trapezoidal rule '); deff('[y]=f(x)','y=exp(x)'); n = [1 2 4 8]; a = 0; b = 2; h = (ones(:,4)*(b-a))./n; t(1) = h(1)*(f(a)+f(b))/2; disp(t(1),'n=1'); t(2) = h(2)*(f(a)+f(b)+2*f(h(...
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errcatch(-1,"stop");mode(2);//scilab 5.4.1 //Windows 7 operating system //chapter 17 Number Systems,Boolean Algebra,and Digital Circuits s='1111' x=bin2dec(s) disp(,x,"Decimal equivalent of 1111 is ") exit();
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//chemical kinetics and catalysis// //example 3.17// T1=27;//initial temparature in C// T1=T1+273;//in kelvin// Tr=10;//rise in temparature// T2=T1+Tr;//final temparature in kelvin// r=2;//ratio of final to initial rates of chemical reactions(k1/k2)// R=8.314;//value of constant R in J/K.mol// E=log(r)*R*T1*T2/...
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R=2000 C=5E-6 w=1000 Xc=1/(w*C*%i) Y=1/R+1/Xc Z=1/Y Req=real(Z) Ceq=-1/(imag(Z)*w) disp(Ceq*1E6,Req) //////Answer wrong in the book
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// Example 6.30 Deseasonalise the following sales data clc; clear; Sales=[23.7 25.2 21.4 65.4]; SI=[0.78 1.24 0.50 1.48]; DD=Sales./SI; disp(DD,"Deseasonalise Data =",SI,"Seasonal Index",Sales,"Sales in thousand =");
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close; x = 0:0.01:9.42; y = x.*(cos(x)); z = x.*(sin(x)); disp(y); disp(z); plot(y,z); xgrid; title('Curva paramétrica');
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function iddataplot(varargin) [lhs rhs] = argn(0) if rhs <> 1 then error(msprintf(gettext("%s: Wrong number of input arguments."),"iddataplot")) end iddataData = varargin(1) if typeof(iddataData) <> 'iddata' then error(msprintf(gettext("%s:Wrong type for input argument %d: ""iddata...
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load Fill.hack; echo "First, make sure that 'No Animation' is selected. Then, select the Keyboard icon, click on any key and inspect the screen."; repeat { ticktock; }
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10_22.sce
clear; clc; //Example - 10.22 //Page number - 363 printf("Example - 10.22 and Page number - 363\n\n"); //Given T = 50+273.15;//[K] - Temperature P = 25*10^(3);//[Pa] - Pressure y1 = 0.5;//[mol] - mole fraction of equimolar mixture y2 = 0.5; R = 8.314;//[J/mol*K] - Universal gas constant //For component...
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ex25_5.sce
clc; c=12.01; //mass of carbon h=1.008; //mass of hydrogen mass=((2*c)+(4*h))*9.4; //calculating mass disp(mass,"Required mass = "); //displaying result n=6.023*10^23; //avogadro's no ac=(2*9.4)*n; //calculating atoms of c disp(ac,"Atoms of C = "); //displaying result
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////Ex 4.10 clc; clear; close; format('v',5); AOL=2*10^5;//unitless Rio=2;//Mohm Ro=75;//ohm Ri=1;//kohm Rf=10;//kohm ACL=-AOL*Rf/(Rf+Ri+AOL*Ri);//unitless(Exact) disp(ACL,"Exact close loop voltage gain"); ACL=-Rf/Ri;//unitless(Approximate) disp(ACL,"Approximate close loop voltage gain"); Beta=Ri/(Ri+Rf);...
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clear; clc; f=500;Ro=400;f1=50;D1=17; M1=10^(D1/10); D2=4;f2=2500; M2=10^(D2/10); B=sqrt(((f1*f1*(M1-1))-(f2*f2*(M2-1)))/(M2-M1)); A=sqrt((B*B*M2)+(f2*f2*(M2-1))); L11=Ro/(%pi*(A+B)); L12=Ro/(%pi*(A-B)); R11=L11*%pi*(A-B); R12=L12*%pi*(A+B); R21=Ro*Ro/R11; R22=Ro*Ro/R12; C21=L11/(Ro*Ro); C22=L12/(Ro*Ro);...
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// **** Purpose **** // Give four points in the k-space. The first one is origin point and // the other three points span a space in the k-space. This code will // perform k-mesh on this hexahedral. // **** Variables **** // [rec_vec]: 3x3, real, if [], then eye(3,3) // <= reciprocal row vectros. If [], then eye(3,3)...
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//---------Mission A-4----------- //------------------------------------- // Améliorer la qualité de l'image // Utilisation d'un filtre médian pour supprimer le bruit // // funcprot(0) getd("../Fonctions") missPath="./" nomMission="MissionA-4" // PBM--->matrice img = readpbm(missPath+"Jupiter1.pbm") //Traiteme...
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//Reaction at A in overhanging beam //refer fig. 8.9 //Applying virtual work principle //(-2*RA+180-20)*delta(y)=0 //Thus RA=(180-20)/2 //kN printf("\n Reaction is RA=%.2f kN",RA)
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## Test of index, tip, tags, history, paths, expunge and checkout set echo read <simple.fi ~=B index :76 tip tags paths 1..$ expunge theory.txt paths 116 checkout foobar !ls foobar !rm -fr foobar 101,103 diff 101,103 manifest 116 manifest 116 manifest /^reposurgeon/ paths sub foo paths sup :2 setfield comment "The qu...
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// Example 11_12 clc;funcprot(0); // Given data w_1=0.0046;// kg H2O/kg dry air w_2=0.010;// kg H2O/kg dry air // Calculation // (b) dw=w_2-w_1;// The amount of water added in kg H2O/kg dry air printf("\n(b)The amount of water added,w_2-w_1=%0.4f kg H2O/kg dry air",dw);
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//To determine the coil parameters with resistance of 5 ohms clc; clear; //Parameters of the coil R=5; // Resistance I=10; // Current flowing V=200;// Voltage across f=50;// Frequency of operation P=750;//Total Power Dissipated Pc=(I^2)*R; // Copper Loss Pil=P-Pc;// Iron Loss Z=V/I;// Impedance X=sq...
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clear; clc; // RDMP-3a.sce // A => B // No adiabático: camisa a temperatura constante // SISTEMA DE ECUACIONES DIFERENCIALES function dxdt = f(t,x) // Variables diferenciales CA = x(1) T = x(2) // Ecuación de Arrhenius k = k0*exp(-E/(R*T)) // Velocidad de reacción r = k*CA // Calor tr...
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//Exa 1.27 clc; clear; close; format('v',6); //Given Data : m=500;//Kg t1=45;//degree C t0=5;//degree C CP=4.18;//KJ/Kg-degree C Qdot=41.87;//MJ/hr Q=m*CP*(t1-t0);//KJ Q=Q/1000;//MJ Time=Q/Qdot;//hrs disp(Time,"Time required in hours : ");
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.356401D+00 ...
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//Fluid Systems - By Shiv Kumar //Chapter 17- Dimensional and Model Analysis //Example 17.2 //Theoritical Problem to Obtain Expression for Velocity of Propagation of Wave
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deff('d=f(x)','d=(x^3)-x-2'); a=input("Please Enter lower Limit"); b=input("Please Enter Upper Limit"); n=input("Please Enter No. of Iterations"); disp("Checking upto 3 significant digits") c=(b*f(a)-a*f(b))/(f(a)-f(b)); x=a:0.01:b; y=f(x); plot(x,y); disp("Iteration : a : b : c : f(c) ") for i=1:n ...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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// Scilab Code Ex5.6 :: Page-5.27 (2009) clc;clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV A = 235; // Atomic weight of uranium, gm/mol N_A = 6.023e+026; // No. of atoms present in 235 kg of uranium N = N_A/(A*1000); // No. of nuceli of uranium per gram E = N*200; // Energy produced by 1 g of U-...
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// Example 2.2 // Program shows typical declarations,assignments and values stored in various types of variables. //Declarations and Assignments m=int16(54321); n=int32(1234567890); k=uint16(54321); //Assignments x=1.234567890000; //Bydefault type is double in scilab y=9.87654321; //-----...
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clc; e=1.6*10^-19; //charge c=3*10^8; //velocity in m/sec ke=106*10^6; //kinetic energy in eV KE=ke*e; //calculating kinetic energy disp(KE,"Kinetic Energy in Joule = "); //displaying result m=KE/(c*c); //Einstein's equation disp(m,"Mass in kg = "); //displaying re...
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// Return if a given year is a leap year year = input("Give a year: "); if (modulo(year,4)==0 & (modulo(year,400)==0 | modulo(year,100~=0))) printf("Leap year!") else printf("Not a leap year!") end
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//Example 16.8, page 615 clc n=(1/10)/(54*1.66*10^-27) d_ohm=10^-5/(10^-1)**2 d_zigma=(1.3*10^-3)*10^-31//m2/nucleus P=d_zigma*n //disp(P) I=(10^-7)/(1.6*10^-19) //disp(I) dN=I*P printf("\n The number of events detected per sec is s %d",dN) //The answer differnce is because of round off
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pathname=get_absolute_file_path('17_31.sce') filename=pathname+filesep()+'17_31_data.sci' exec(filename) //Heat supplied(in kJ/h) H=Vg*CV*60 //Heat equivalent of bp(in kJ/hr) Hbp=bp*60*60 //Heat lost in jacket cooling water(in kJ/hr) Hc=(Vc*dwc*Cvw)*60 //Mass of gas used(in kg/min) mg=Vg*Pg //Mass of exhaust...
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n=9;m=9; // size of matrices L=([1:n]')*ones(1,m); // row number K=ones(n,1)*[1:m]; // column number R=1+int((K-1)/3)+int((L-1)/3)*3 // region number
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clc clear //At 7 bar and 300 Celcius P=7; //in bars Cps=2.1; Tsup=300+273; //in K Tsat=165+273; //in K Hg=2763.5; //in kJ/kg H1=Hg+(Cps*(Tsup-Tsat)); x2=0.9; //Dryness Fraction Hf=697.2; //in kJ/kg Hfg=2066.3; //in kJ/kg H2=Hf+(x2*Hfg); m=(H1-Hg)/(Hg-H2); printf(...
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FLAGS='--print GB18030' STDIN='' STDOUT='\x84\x31\x95\x33' STDERR='' EXITVAL='0'
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clc // Given that m = 1e-30 // Mass of any object in Kg v = 1e5 // velocity of object in m/s h = 6.625e-34 // Plank constant printf("Example 1.3") lambda = h/(m*v) // calculation of de Broglie wavelength printf("\n de Broglie wavelength of body is %e m.\n\n\n",lambda)
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funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=round(sd*100)/100; if sd==60.0 then sd=0; m=m+1; end dms=[d m sd] endfunction alpha=44+12.0/60+30.0/3600;//angle in...
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//Chapter 10 //Example 10_7 //Page 237 clear;clc; vr=11*1000/sqrt(3); r=1.5; xl=4; pfr=0.8; pd=5000; i=pd*1000/3/vr; vs=vr+i*r*pfr+i*xl*sin(acos(pfr)); reg=(vs-vr)/vr*100; loss=3*i^2*r; op=pd*pfr; ip=op+loss/1000; n=op/ip*100; printf("Recieving end voltage = %.0f V \n\n", vr); printf("Load current = %.2f A \n\n", i...
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// SAMPLE PROBLEM 5/16 clc;funcprot(0); // Given data omega=4;// rad/sec omegadot=10;// rad/sec^2 r=6;// in rdot=5;// in/sec rdotdot=81;// in/sec^2 // Calculation // Velocity v_rel=rdot;// (k) in/sec v_A=[v_rel,(omega*r)];// in/sec printf("\nv_A=%1.0fi+%2.0fj in/sec",v_A(1),v_A(2)); v_A=norm(v_A);// in/s...
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// Chapter 5 additional Example 7 //============================================================================== clc; clear; // input data // given crystal has BCC structure r = 1.2*10^-10; // atomic radius in m // Calculations a = (4*r)/sqrt(3); // lattice constant V = a^3; /...
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//Determine WB //refer fig.8.18 theta=atand(3/4) mu=0.3 WA=200 F=mu*WA*cosd(theta) //N //Let us give virtual displacement of delta(s) up the plane to block A //Applying virtual work principle //(-200*sind(theta)-F+WB/2)*delta(s)=0 WB=2*(200*sind(theta)+F) //N printf("Required value of WB=%.2f N",WB)
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// Problem 5.15,Page no.137 clc;clear; close; B=20 //cm //width of timber D=30 //cm //depth of timber d=25 //cm //depth of steel plate b=1.2 //cm //width of steel plate sigma_s=90 //N/mm**2 //Bending stress in steel sigma_t=6 //N/mm**2 //Bending stress in timber m=20 //Ratio of modulus of elasticity of of steel to ti...
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//Speed of a belt driven shunt generator clc; clear; Pg=100*(10^3);// Power output of the generator Pm=10*(10^3); // Power input of the motor V=220; Ng=300; // Running speed of the generator Ra=0.025; // Armature resistance Rf=60; // Field Resistance Vb=2;// Voltage drop due to brushes Im=Pm/V; // Curr...
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y=image_model(3); printf('Training accuracy of image model: %f%%',(y*100)); y=image_model_test(); printf('Guessed class for this image:') disp(y)
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// Scilab Code Ex19.1: Page-959 (2011) clc; clear; T_c = 6.2; // Critical temperature of lead in superconducting state, K T = 4; // Temperature at which critical field of lead is to be found out, K H_c0 = 0.064; // Critical field for lead at 0 K, MA/m H_cT = H_c0*(1-(T/T_c)^2); // Critical field fo...
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clc // Given that alpha = 10 // Rake angle of tool in Degree v = 200 // Cutting speed in m/min t1 = 0.2 // Uncut thickness in mm w = 2 // Width of cut in mm mu = 0.5 // Avg value of the cofficient of tbe friction T_S = 400 // Shear stress of the work material in N/mm^2 Cm = 70 // Machining constant in Degree // Sample...
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Chapter3_Example11.sce
clc clear //Input data V=25;//Volume of gasoline consumed by an engine in litres/hour cv=6*10^6;//The calorific value of gasoline in calories/litre P=35;//The output of the engine in kilowatts //Calculations h=V*cv;//Total heat produced by gasoline in one hour in calories H=h/3600;//Heat produced per se...
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15_4.sce
//Find Resistivity //Ex:15.4 clc; clear; close; p_cu=0.015*10^-6;//resistivity of copper in ohm-m p_ni=0.012*10^-6;//resistivity of nickel in ohm-m p_ag=0.016*10^-6;//resistivity of silver in ohm-m c1=0.25;//atomic % of nickel c2=0.4;//atomic % of silver p=p_cu+(c1*p_ni)+(c2*p_ag); disp(p,"Resistivity of Cu-...
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//Exa 4.2 clc; clear; close; //Given Data : format('v',7); d=2.8*100;//in cm(spacing) r=0.5*1.5;//in cm ds=0.77888*r;//in cm L=0.2*log(d/ds);//in H/m/phase disp(L*20,"Inductance per phase for a 20 km line (in mH) :");
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//[co,u,g,itv,dtv,cof]=icsuq(u,simu,nap,imp,obs,ytob) // Calcul du controle optimal avec ponderation du controle initial // et ponderation geometrique des poids des observations. // Une mise a l'echelle ramene toutes les composantes du controle // initial a 1.Les composantes initialement nulles le resteront. // Ne...
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// ############################################################################ // Permite obtener la representacion en espacio de estados de un sistema continuo // o discreto. // Sintaxis: // [sys1=]ss(sys) : con sys una FT o cociente de polinomios. // [sys1=]ss(A,B,C,D) : sys1 sera un sistema continuo obteni...
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//symsum// exec ztransfer.sce; sequence=[0 2 0 0 -3 0 0 8] y=ztransfer(sequence); disp(y,"ans=")
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Exa14_1.sce
//Exa 14(i) clc; clear; close; //given data : inINV=50000;//initial investment in Rs. and equal for all projects life=5;//in years salvage=0;//in Rs. TaxRate=55;//in % //depreciation type :Straight line D=inINV/life;//in Rs //cash flows before tax of 1st,2nd,3rd,4th and 5th years CBFT1=10000;//in Rs. CBFT...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/05/CPU.tst load CPU.hdl, output-file CPU.out, compare-to CPU-decoding.cmp, output-list time%S0.4.0 inM%D0.6.0 instruction%B0.16.0 reset%B2.1.2 outM%D1.6.0 writeM%B...
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9.sce
//Variable declaration me=1.676*10**-27; //mass(kg) mn=9.1*10**-31; //mass(kg) h=6.63*10**-34; //planck's constant //Calculation lamda_n=h/sqrt(4*mn*me); //de broglie wavelength(m) //Result printf('de broglie wavelength is %0.3f nm \n',int(lamda_n*10**9))
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europepmc-json_013.tst
Tests the response of the script to a file whose content is not URL-encoded, and the option '--url-encode' is not given. It should return : $0: WARNING, the search term '${SEARCH_TERMS}' contains spaces and will not work $0: WARNING, please URL-encode your search term or use '--url-encode' option $0: WARNING, will skip...
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4_08.sce
//pathname=get_absolute_file_path('4.08.sce') //filename=pathname+filesep()+'4.08-data.sci' //exec(filename) //Maximum temperature(in K): T1=27+273 //Minimum temperature(in K): T2=-8+273 //Leakage(in kJ/s): Q=7.5/60 //Power required(in kW): W=(T1-T2)*Q/T2 printf("\nRESULTS\n") printf("\nPower required = %f ...
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example10_8a.sce
v1=10; v2=20; r1=10^3; r2=2*10^3; r3=3*10^3; r4=4*10^3; r5=5*10^3; i2=(v*(r1+r2)-v1*r2)/((r2+r3+r5)*(r1+r2)-r2^2); vth=v2-i2*r5; rth=(r1*r2/(r1+r2)+r3)*r5/(r1*r2/(r1+r2)+r3+r5); i=vth/(rth+r4); disp("the current (in mA) in R4 is"); disp(i*10^3);
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//To calculate the free volume per unit cell r = 0.1249; //atomic radius, nm a = 4*r/sqrt(3); //lattice constant, nm a_m = a*10^-9; //lattice constant, m V = a_m^3; //volume of unit cell, m^3 PF = 0.68; //packing factor for BCC FV = 1 - PF; //free volume FV1 = FV*V; //free vol...
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PA_Ex_11_4.sce
clc //Chapter 11:Power amplifiers //example 11.4 page no 475 //given Pt=4//max power dissipation in watt Idmax=1.5//max drain current in amp Vcc=48//supply voltage P_t=(4*%pi*Pt)/(Vcc*Idmax)//the normalised max transistor dissipation disp('from figure 11.21 it is found that maximum possible conduction angle is ...
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16_1.sce
clc //initialisation of variables clear v= 1 m= 0.5 //CALCULATIONS m1 = 2*m m2 = 1*m v1 = 2*v v2 = 1*v M = (m1^2*m2)^(1/(v1+v2)) //RESULTS printf ('mean ionic molality = %.1f ',m2) printf ('\n mean ionic molality = %.3f ',M)
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// // bs1=3.150,bs2=3.860,bs3=0.470, is1=2.245,is2=2.125,is3=0.760,is4=1.935,is5=3.225, fs1=1.125,fs2=2.235,fs3=3.890, sbs=bs1+bs2+bs3 sis=is1+is2+is3+is4+is5 sfs=fs1+fs2+fs3 r1=bs1-is1 r2=is1-fs1 r3=bs2-is2 r4=is2-is3 sr=r1+r2+r3+r4 printf("\n r1,r2,r3,r4,sr") f1=fs2-is3 f2=is4-bs3 f3=is5-is4 f4=fs3-is5 sf=f...
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clear all; clc; disp("Scilab Code Ex 6.26 : ") //Given: M = 5; //kNm sigma_y = 500; //MPa r = 16; //mm h = 80; //mm w = 120; //mm r_h = r/h; w_h = w/h; k = 1.45; c = h/(2000); t = 20/1000; //m //Calculations: I = (1/12)*(t)*(h/1000)^3 sigma_max = (k*M*c)/(I*1000); //Display: printf("\n\...
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example3.sce
printf(" Given C(s)/R(s)=10/(s^2+2*s+10)") printf("characterstic equation of the given system is s^2+2*s+10=0"); printf("compare it with the standard second order characterstic equation s^2+2*d*w*s+w^2=0"); w=sqrt(10); d=1/(2*w); mo1=exp((-%pi*d)/sqrt(1-d^2))*100; ts1=4/(d*w); ess1=2*d/w; disp(d,"damping ratio"...