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clc,clear printf('Example 5.6\n\n') phi=acos(0.8) VA=1000*10^3 V_L=1905 V_ph=V_L/sqrt(3) R_a=0.2//Armature reactance per phase //Part(i) //Ampere-turn method I_L=VA/(sqrt(3)*V_L) I_aph=I_L V_dash=V_ph+I_aph*R_a*cos(phi)//V_dash is a dummy quantity and has no significance..it's used only for mapping corre...
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errcatch(-1,"stop");mode(2);// Example 2.30 page no-95 B=0.1 //Wb/m^2 Vh=50 //mV I=10 //mA rho=2*10^5 //Ohm-cm w=3*10^-3 //m x=B*I*10^-3/(Vh*10^-2*w) printf("\n1/RH=%.3f",x) y=1/(rho*10^-2) printf("\nConductivity = %f mhos/meter\nmu=%.0f cm^2/V-sec",y,(y/x)*10^6) exit();
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// Copyright (C) INRIA 1999-2005 // // This program is free software; you can redistribute it and/or modify it // under the terms of the GNU General Public License version 2 as published // by the Free Software Foundation. // // This program is distributed in the hope that it will be useful, but // WITHOUT ANY WARRAN...
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clc //Chapter3: Modulation //Example3.28, page no 177 //Given R=1//Antenna Resistance assumed to be 1 ohm for ease of calculation Ic=10.8// current with no modulation Pc=Ic^2*R//power with no modulation It=12.15//modulated current Pt=It^2*R// modulated power ma=(sqrt(2*(((It/Ic)^2)-1)))//modulation depth) m...
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clc; F=300 // N , given force AB=sqrt(8^2+6^2);// m Length of AB cos_alpha=8/AB; sin_alpha=-6/AB; Fx=F*cos_alpha;//N, Horizontal component Fy=F*sin_alpha;// N, Vertical Component printf("Horizontal component of F is %.2f N\n",Fx); printf("Vertial component of F is %.2f N\n",Fy); printf("We may write F as \n ...
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// export class ODataContext { public static MetadataPath = '$metadataPath$'; public static ODataRootPath = '$odataRootPath$'; public static CreationDate = '$CreationDate$'; public static ODataVersion = '$ODataVersion$'; }
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//Ex 1.15 clc;clear;close; format('v',6); E1=10;//V V2=6;//V V3=8;//V //E1=V1+V2;//KCL for left loop V1=E1-V2;//V //-E2=-V2-V3;//KCL for right loop E2=V2+V3;//V disp(V1,"Voltage V1(V)"); disp(E2,"Voltage E2(V)");
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; tests declare-fun (set-logic QF_UF) (declare-sort A 0) (declare-fun x () A) (declare-fun y (A A) A)
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map1104" Width="13" Height="9" CellSize="40" BackgroundSize="1" Background="7plus.png"> <Cell Name="丛林图腾2" X="1" Y="1" /> <Cell Name="篱笆2" X="2" Y="1" /> <Cell Name="篱笆2" X="3" Y="1" /> <Cell Name="篱笆2" X="4" Y="1" /> <Cell Name="篱笆2" X="5" Y="1" /> <Ce...
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//Force P for impending motion //Refer fig. 5.12 //consider equilibrium of block A //NA*cosd(30)+FA*sind(30)-1500-500=0 //Law of friction gives NA=2000 //N FA=NA*tand(15) //N C=NA*sind(30)-FA*cosd(30) //N //consider equilibrium of block B NB=2000*cosd(60)+535.90*cosd(30) //N FB=NB*tand(15) //N P=(392.3...
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performing tests... <opt/a> [<opt/a>] {<opt/a>} <opt/abcd> <opt/a><opt/b> <opt/a>|<opt/b> [<opt/a>]<opt/b> <opt/a>{<opt/b>} <opt/a>[<opt/b>] [<opt/a><opt/b>] {<opt/a><opt/b>} <pat/[0-9]*abc/> [<opt/a>|<opt/b>] {<opt/a>}|<opt/b> [<opt/a>][<opt/b>] [<opt/a>{<opt/b>}] {[<opt/a>]<opt/b>} [<opt/a>]{<opt/b>} <opt/a><opt/b><...
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/* Escola Politécnica da USP Disciplina - PME3200 - Mecânica Geral II (2018) Exercício de Simulação Numérica Atividade 1 - Estudo do movimento de um pêndulo com massa fixa acoplada Casos: - Pêndulo sem amortecimento - Pêndulo com amortecimento viscoso - Pêndulo com amortecimento viscoso e momento oscilatór...
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function [] = log_plot(rh,tit) [m,n] = size(rh); iter = [1:n]; scf(5); clf(5); plot2d("nl",iter,rh,style=2); // "nl" --> normal x, logarítmica y; style: color de la linea p = get("hdl"); p.children.mark_mode = "on"; p.children.mark_style = 9; // tipo de punto p.children.t...
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// Exa 14.2 // To determine the upper bound of the throughput and the throughput with retransmissions due to errors. clc; clear all; RTT=0.1; //Round trip-time in sec MSS=536*8; //Maximum segment size in bits p=0.01;// packet loss probability for the path RTO=5*RTT; //Retransmission time out(from eqn 14.2 on...
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d = 0.03 ; // diameter of the shaft in meter T2 = 450 ; // Torque in N-m T1 = 275 ; // T3 = 175 ; // Lbc = 0.5 ; // Length of shaft in meter Lcd = 0.4 ; // Length of shaft in meter G = 80e09 ; // Modulus of elasticity Tcd = T2-T1 ; // torque in segment CD Tbc = -T1 ; // torque in segment BC tcd = (16*Tcd)/(%pi...
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// Exa 4.19 format('v',6) clc; clear; close; // Given data h_FE = 100; R = 50;// in k ohm R = R * 10^3;// in ohm R1 = 3;// in k ohm R1 = R1 * 10^3;// in ohm V1 = 10;// in V V2 = 5;// in V V_BE = 0.8;// in V V_CE = 0.2;// in V //Applying KVL in input side, V2 - (R*I_B)-V_BE = 0; I_B = (V2-V_BE)/R;// in A...
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//Chapter 18 //Example 18_6 //Page 431 clear;clc; i=12; printf("Zero sequence current is equal to 1/3rd the current in nuetral wire.\n"); printf("Zero sequence current in each phase = %d A \n\n", i/3);
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//example-10.2 //page no-303 //given //initial length of the specimen h0=24.02*10^-3 //m //initial gauge diameter of the specimen d0=18.74*10^-3 //m //final length of specimen hf=18.70*10^-3 //m //final diameter df=21.54*10^-3 //m //initial an final cross sectional areas are A_i=3.14/4*d0^2 //m^2 A...
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clc clear disp('Ex-4.10'); printf(' Group velocity is found out from Eq. 4.18.\n Since k=2*pi/w ; Vphase= w/k \n w/k = sqrt(g/k) /n w=sqrt(g*k)'); printf('\ndifferetiating on both sides\n'); printf('dw=1/2 * sqrt(g) * k^-1/2 * dk\n dw= 1/2 * sqrt(g/k)\n Hence Vgroup= Vphase/2');
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%%-*- mode: erlang -*- %%-*- coding: utf-8 -*- % Test control options [{tests, []}]. %% %% TESTS %% "CLOSE name_cursor_1". "DECLARE name_cursor_1 CURSOR FOR SELECT * FROM name_table_1". "FETCH name_cursor_1 INTO name_column_1". "OPEN name_cursor_1". "DELETE FROM table_name WHERE CURRENT OF name_cursor". "UPDATE nam...
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chdir('C:\Users\matve\Desktop\Code These\'); exec('ResilienceMEY2\donnees.sce'); exec('ResilienceMEY2\test_mey.sce'); //Pour RCP 2.6 aij=data_param(2:2+N_species-1,2:2+N_species-1); Y=20; PopGuyTr=PopGuyTrim; /////////////////////////////////////////////////////////////////////////////// [p_opt,Nb_iter]=Calib_MAT_2(ite...
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x-y straight line graph.sce
x=[0:0.1:5]; y=[1:0.1:6]; xlabel("x axis"); ylabel("y axis"); title("X vs Y graph"); plot(x,y,".r"); //r is for red color, . is for displaying in dots
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @output...
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//let the depth of neutral axis be x b=150//width, in mm d=400//effective depth, in mm Ast=804//area of steel, in sq mm m=18.66//modular ratio //b(x^2)/2=mAst(d-x)-->this becomes a quadratic equation of form px^2+qx+r=0 p=b/2 q=m*Ast r=-m*Ast*d //solving the quadratic equation x=(-q+sqrt(q^2-4*p*r))/(2*p)//in...
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clc pathname=get_absolute_file_path('7_6_3.sce') filename=pathname+filesep()+'763.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") disp("Mass balance on Water,") disp("m3+m1=m2") disp("Energy balance,") disp("m3*H3+m1*H1=m...
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//example2.23 clc disp("The generator is shown in the fig 2.64") disp("The current through R_se is I_L=80 A as the generator is short shunt.") disp("The drop across R_sh is the sum of the drop across R_se and V_t") disp("[(I_sh)*(R_sh)]=(V_t)+[(I_L)*(R_se)]") disp("i.e 100(I_sh)=250+(80*0.03)") p=2.5+(0.8*0.03...
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Ex8_1.sce
//===================================================================================================================================== // chapter 8 example 1 clc; clear; // Variable declaration Ephoton = 1.5; // energy of photon in eV Eg = 1.4; // energy gap in eV m = 9.1*10^-31...
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//Exa 6.5 clc; clear; close; //Given Data: f=10;//in GHz f=f*10^9;//in Hz BWFN=10;//in degree c=3*10^8;//Speed of light in m/s lambda=c/f;//in meter //Part (a): d=140*lambda/BWFN;//in meter disp(d,"Diameter of a parabolic Antenna in meter : "); //Part (b): HPBW=58*lambda/d;//in degree disp(HPBW,"3-dB Bea...
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9_07.sce
//Time required// pathname=get_absolute_file_path('9.07.sce') filename=pathname+filesep()+'9.07-data.sci' exec(filename) //Time required to decelerate to 100 mph(in seconds): t=(s1-s2)*2*w/(s1*s2)/Cd/d/A/g*3600/5280 printf("\n\nRESULTS\n\n") printf("\n\nTime required to decelerate to 100 mph: %.3f seconds\n\n",t...
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//Chapter-1, Example 1.17, Page 27 //============================================================================= clc; clear; //INPUT DATA R1=0.031;//resistance of wire in ohm d1=11.7;//diameter of wire in mm in case 1 r1=d1/2;//radius of wire in mm in case 1 d2=5;//diameter of wire in mm in case 2 r2=d2/2;//...
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clc; //e.g 28.6 L1=2*10**-3; L2=20*10**-6; fo=950*10**3; C=1/(4*%pi^2*(L1+L2)*fo^2); disp('pF',C*10**12,"C="); fo=2050*10**3; C=1/(4*%pi^2*(L1+L2)*fo^2); disp('pF',C*10**12,"C=");
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fatoracaoLU.sce
//Eliminação Gaussiana: //Implementação destinada à resolução de um sistema linear Ax=b. //Entrada: A (matriz mxn), b (vetor mx1) clear //limpa a memoria do scilab clc //limpa a tela do console //A = [1 0 -1; 0 3 7; 5 -2 1]; //linhas espaçadas por ponto e vírgula //A = [0 0 -2; 2 4 -10; 2 5 1]; //A = [0 3 1; 2 -2 1; ...
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//Optical Fiber communication by A selvarajan //example 6.3 //OS=Windows XP sp3 //Scilab version 5.5.1 clc; clear all; //given lamda=1.3;//wavelength in um nf=1.51;//Film refractive index t=1.5;//Film thickness in um ns=1.5//Waveguide refractive index na=1//refractive index of air V=(2*%pi*t/lamda)*sqrt(nf...
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function img_out = seuilMissionA1(img, seuil) size_X = size(img, 1); //On récupère la longueur de l'image à modifier. size_Y = size(img, 2); //On récupère la largeur de l'image à modifier. img_out = zeros(size_X, size_Y); //On crée une matrice nulle qui va contenir l'image modifiée (ici une matrice lig...
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test_numeric_1_b.tst
> set 111111111.11111111100000000000 111111111.111111111 > add 1000000000 error: overflow occurred > mul 10000000000 error: overflow occurred > div .0000000001 error: underflow occurred > div 10 11111111.1111111111 > div 10 1111111.11111111111 > div 10 111111.111111111111 > div 10 11111.1111111111111 > div 10 ...
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clc //Example 8.5 //Calculate the pressure and density at a pt where temperature ratio is 1.8 and initial pressure and density are given ratio_T=1.8//dimentionless P1=2//bar k=1.4//dimentionless P2=P1/ratio_T^(k/(k-1))//bar printf("The pressure where temperature ratio is 1.8 and initial pressure is 2 bar is %f b...
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute...
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// Variable Declaration V_r = 220000.0 //Voltage(V) P = 100.0 //Power(MW) r = 0.08 //Series resistance(ohm) x = 0.8 //Series reactance(ohm) s = 6.0*10**(-6) //Shunt susceptance(mho) pf = 0.8 //Power factor lagging l_1 = 60.0 //Transmission length(km) for case(i) l_2 = 200.0 ...
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//clear// //Caption:Convolutional Encoding - Time domain approach //Example8.7:Convolutional Code Generation //Time Domain Approach close; clc; g1 = input('Enter the input Top Adder Sequence:=') g2 = input('Enter the input Bottom Adder Sequence:=') m = input('Enter the message sequence:=') x1 = round(convol(g1...
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clc; p=6; // number of poles c=240; // number of coils t=2; // number of turns per coil rt=0.03; // resistance of one turn l=0.5; // length of armature d=0.4; // diameter of armature B=0.6; // air gap flux density a=p; // number of parallel paths is same as number of poles foe lap winding an=40; // mechanical ...
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//Caption:Run Test for Randomness //Example9.11 //Page326 //run test of randomness of large samples //Ho: The occurrence of the runs of the given stream of symbols (W,L) is random //H1: The occurrence of the runs of the given stream of symbols (W,L) is not random clc; n1 = 24; //Frequency of occurrence of lett...
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************************************************************************** //output-> shows the error on console //-> means that output is correct and no modification needs to be done ************************************************************************** I1 = imread("box.png"); a = [0 0 0; 0 1 0; 0 0 0]; //convol...
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function [u,v]=simulerUV(p) u=0 // nombre de Pile obtenu v=0 // nombre de Face obtenu while(___) if rand()<p // si on tombe sur pile u=___ else v=___ end end end p=.5 N=10^1 // taille de l'échantillon echantillonU=[] echantillonV=[] for k=1:N [u,v]=simulerUV(p) echantillonU=[echanti...
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//clear// clc clear exec("2.2data.sci"); CA0=(yA0*P0)/(R*T0); FA0 = CA0*v0; V = FA0*X*(1/-rA) disp("FA0 =") disp(FA0) disp("mol/s") disp("V =") disp(V) disp ("dm^3")
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//Given that n = 1 //in mol Vi = 1 //(say) Vf = 2*Vi R = 8.31 //in J/mol.K T = 1 //(say) //Sample Problem 21-1 printf("**Sample Problem 21-1**\n") Q = n*R*T*log(Vf/Vi) deltaS = Q/T printf("The change in entropy for the irreversible process is equal to %fJ/K", deltaS)
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//variable initialization h=1.054*10^-34; //planck's constant (joule-second) e=1.6*10^-19; //charge of electron (coulomb) m=9.1*10^-31; ...
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// scilab Code Exa 3.3 ideal reheat cycle gas turbine T1=300; // Minimum cycle Temperature in Kelvin r=25; // pressure ratio of the turbine and compressor gamma=1.4; T3=1500; // Maximum cycle Temperature in Kelvin cp=1.005; // Specific Heat at Constant Pressure in kJ/(kgK) beeta=T3/T1; n=(gamma-1)/gamma; t=(...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 3 Example 8") T1=(627+273);//initial temperature of air in nozzle in K T2=(27+273);//temperature at which air leaves nozzle in K Cp=1.005*10^3;//specific heat at...
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//For p1, the 5-A current is out of the positive terminal (or into the negative terminal hence, // power(p) in watts is given by p=V*I // v voltage in volts and i current in Amperes p1=20*-5; disp("p1=") disp(p1) units='Watts W' p1=[string(p1) units]; disp(p1) // in watts // power in p1 is -10...
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// Exa 6.14 format('v',4); clc; clear; close; // Given data L1= 2;// in mH L1= L1*10^-3;// in H L2= 1.5;// in mH L2= L2*10^-3;// in H // Formula f= 1/(2*%pi*sqrt((L1+L2)*C) // For f= 1000 kHz, C will be maximum f=1000;// in kHz f=f*10^3;// in Hz Cmax= 1/((2*%pi*f)^2*(L1+L2));// in F // For f= 2000 kHz, C...
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@relation unknow @attribute mcg real[0.11,1.0] @attribute gvh real[0.13,1.0] @attribute alm real[0.21,1.0] @attribute mit real[0.0,1.0] @attribute erl real[0.5,1.0] @attribute pox real[0.0,0.83] @attribute vac real[0.0,0.73] @attribute nuc real[0.0,1.0] @attribute class{MIT,NUC,CYT,ME1,ME2,ME3,EXC,VAC,POX,ERL} @inputs...
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// Scilab Code Ex7.8: Page-257 (2014) clc; clear; m = 1.67e-027; // Mass of the proton, kg k = 1.38e-023; // Boltzmann constant, J/K T = 663; // Temperature of the discharge tube, K v_x = sqrt(3*k*T/m); // Average speed of the hydrogen atom mu_z = 9.27e-024; // Bohr's magneton, J/T B_grad = 1240; ...
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//Starter Test stimulus file for AddSub10 load AddSub10.hdl, output-file AddSub10.out, compare-to AddSub10.cmp, output-list a%B1.10.1 b%B1.10.1 sub%B1.1.1 out%B1.10.1 carry%B3.1.3; // 2 set a %B0000000000, set b %B0000000000, set sub 0, eval, output; // 3 set a %B0000000001, set b %B...
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//skipped groundPlane_transform //skipped Manipulator1 //skipped UniversalManip //skipped CubeCompass ///////////////////////////////////////////// // object_Trim_Char_x_1_1__ ///////////////////////////////////////////// #if 0 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1 #endif DX3DMATERIAL_STA...
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// Exa 5.9 clc; clear; close; format('v',6) // Given data V_CC = 12;// in V V_EE = V_CC;// in V I = 1;// in mA I = I * 10^-3;// in A R_B = 120;// in k ohm R_B = R_B * 10^3;// in ohm R_C = 10;// in k ohm R_C = R_C * 10^3;// in ohm Rsig = 5;// in k ohm Rsig = Rsig * 10^3;// in ohm R_L = 5;// in k ohm R_...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 14 Operational Amplifiers Pg no. 435 and 436 clear; clc; //Given //Figure 14.21 R=12D3;//resistances R1,R2,R3 in RC network in ohms C=0.001D-6;//capacitances C1,C2,C3 in RC network in ohms A=29;//gain for oscillator operation //Solution fr=1/(2*%pi*R*C*s...
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// Exa 5.10 clc; clear; close; // Given data R_L = 10;// in kohm R_L= R_L*10^3;// in ohm R_C = 3.6;// in kohm R_C= R_C*10^3;// in ohm r_e_desh = 22.73;// in ohm R_L_desh = R_L/2;// in ohm A_v = ( (R_C*R_L_desh)/(R_C+R_L_desh))/r_e_desh; disp(A_v,"The voltage gain is");
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.264489D+00 ...
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clc,clear printf('Example 6.5\n\n') //note that a new function p2z has been defined below for direct representation of complex numbers in polar form function [FUN] = p2z(RRRR,Theeeta) FUN = RRRR.*exp(%i*%pi*Theeeta/180.); endfunction V_L=6.6*10^3 V_ph=V_L/sqrt(3) VA=3*10^6 I_FL=VA/(V_L*sqrt(3)) //full load ...
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//chapter 4 //example 4.6 //find wavelength and energy //page 77 clear; clc; //given h=1,k=1,l=1; // miller indices a=5.63; // in Angstrom (lattice constant) theta=27.5; // in degree (Glancing angle) n=1; //order H=6.625E-34; // in J-s (Plank's constant) c=3E8; // in m/s (velocity of light) e=1.6E-19;// c...
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m1=1;m2=1;r1=1;r2=1; g=9.8; t0=0; t=0:.1:1.5; z0=[%pi/2;%pi/2;0;0]; getf('dpend.sci'); z=ode(z0,t0,t,dpend); pp(z);
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//contains imaginary element m=[0.3209*%i 0.5183 0.3209 1.0000 0.1677 0.2575;1.0000 0.8927 1.0000 1.0000 0.6196 0.8747]; c=sos2cell(m,2); disp(c); //output // column 1 to 4 // //![2,1] [%i*0.3209, 0.5183, 0.3209] [ 1, 0.1677, 0.2575] [ 1, 0.8927, 1] ! // // column 5 // //!...
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clc //initialization of variables P1=30 //lb/in^2 T1=300+460 //R T2=60 +460 //R cp=0.25 //B/lbm F R=53.3 //ft-lb/lbm R //calculations Q=cp*(T2-T1) du=(cp-R/778)*(T2-T1) W=778*(Q-du) function [ds]=c(T) ds=cp/T endfunction S=intg(T1,T2,c) //results printf("Change in entropy = %.3f B/lbm R",S)
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clc //initialisation of variables d1= 4//ft d2= 2 //in l= 300 //ft P= 5 //lb/in^2 h1= 3 //ft h2= 6 //ft f= 0.01 //CALCULATIONS X= P*2.31*10*(d2/12)^5/(f*l) A= %pi*d1^2/4 function [y]=fun(h) y=A*sqrt((P*2.31*10*(d2/12)^5/(f*l))-(10*(d2/12)^5*h/(f*l)))/(10*(d2/12)^5/(f*l))/7 endfunction vec2=intg(h1,h2...
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function Hk = filtro_passa_faixa(f_max,f_c_min,f_c_max,num) res_f = 2*f_max/num Hk1 = [zeros(1,f_c_min/res_f) ones(1,(f_c_max-f_c_min)/res_f) zeros(1,(f_max-f_c_max)/res_f)] Hk = [Hk1 Hk1(length(Hk1):-1:1)]; odd=1; while length(Hk)<num if odd==1 Hk(length(Hk)+1) = 0 ...
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disp('chapter 5 ex5.1') disp('given') disp('maximum signal voltage Vs=.5volt') disp('voltage gain Av=10') disp('IBmax=1.5*10^(-6)A and I1=100*IBmax') Vs=.5 Av=10 IBmax=1.5*10^(-6) I1=100*IBmax disp('amperes',I1) disp('R1=Vs/I1') R1=Vs/I1 disp('ohms',R1) disp('R2=Av*R1') R2=Av*R1 disp('ohms',R2) disp('R3...
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//Obtain path of solution file path = get_absolute_file_path('solution4_13.sce') //Obtain path of data file datapath = path + filesep() + 'data4_13.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the yield strength in shear Ssy (N/mm2) Ssy = (50/100)*Syt //Calculate the permissible s...
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// chapter 1 //example 1.14 // page 46, figure1.54 Bac=100;Bdc=100; Vbe=.715;Vd1=.715; Vz=6.2;Vee=-10;Vcc=10;Vt=26*10^-3;// at room temprature Re=2700;Rin=10000;Rc=4700;//assuming Rin= 10k Izt=41*10^-3; Vin=0;// for dc analysis //calculation of the value of Ie,Icq1 and Icq2 Vb3=Vee+Vz+Vd1 Ve3=Vb3-Vbe Ie=(Ve3-Vee)/Re; d...
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//Example 7.3, page no-438 clear clc //(b) R=0.5 L=5 p_diff=800 V=10 mu=(3.14*R^4)*p_diff/(8*V*L) printf("(b)\nmu=%.4f poise =%.2f centipoise",mu,mu*100)
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//Chapter 22, Problem 23 clc; n1=24; //rotating speed due to Ia = 15A phi2=2; //flux V=240; //supply voltage Ia=15; //armature current I2=30; //current Ra=0.2; //ar...
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clear ; close; clc; t=0:0.01:50; x1=cos(4*t); x2=sin(6*t); w1=4; w2=6; w=int32([w1,w2]); w0=gcd(w); x=x1+x2; for k=-5:5 cc(k+6,:)=exp(-%i*k.*t*2); ck(k+6)=x*cc(k+6,:)'/length(t); if abs(ck(k+6))<0.1 then ck(k+6)=0; end end
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function [Chi]= Chi_test(Alpha,Test) if Alpha ==0.05 then if (Test==1 |Test==2) then Chi = 19.675 else Chi = [4.575,19.675] end elseif Alpha ==0.01 Chi = 1.239; end endfunction
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// Problem no 2.4,Page no.33 clc;clear; close; D=10 //cm //diameter of circle b=4 //cm //width of rectangle d=4 //cm //breadth of rectangle Y=1 //cm //Distance of centroid of rectangle 1 to C.G a=16 //cm**2 //area of rectangle //Calculations I_x_x_1=%pi*64**-1*(D**4) //cm**4 //moment of inertia of circle about x-...
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// Pregunta 5 // Aproxima la funcion que pasa por los puntos // x con imagen y // por el metodo de los minimos cuadrados // a partir de los 2 polinomios: // x // x^2 // retorna los coeficientes correspondientes function a = minimosCuadrados(x, y) [_, n] = size(x) A = zeros(n, 2) for i = 1:n ...
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%% TypoScript // 1. // 2. // 3. %% Lexer
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clc,clear printf('Example 7.1\n\n') V_l=400 R_a=0.2,X_s=2 //armature resistance and synchronous reactance I_L=25 I_aph=I_L V_ph=V_l/sqrt(3) Z_s=complex(R_a,X_s) //synchronous impedance theta=(%pi/180)*phasemag(Z_s) //Phasemag returns the angle in degrees not radians E_Rph=I_aph*abs(Z_s) //case 1 phi=acos(0.8) //lagg...
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//MEXER SÓ NOS VALORES COM //ALTERAR clear x=[1 2 3 4 5]' //ALTERAR // 4 pontos -> curva com 4-1 pontos (tinha 4 pontos, botei 2 do meio pq pediu) y=[0 2 3 2 1]' //ALTERAR n=length(x); // size(x,1) //plot(x,y,'ro-'),xgrid // Faz grafico dos pontos // Monta a matriz de Vandermonde for i=1:n for j=1:n V(i,j)=...
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clc; clear; mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-13.4 Page No.288\n'); //Pitch diameter Ng=60; Pd=6; Dp=Ng/Pd; mprintf('\n Pitch diameter = %f in.',Dp); //Circular pitch Pc=%pi*Dp/Ng; mprintf('\n Circular pitch = %f in.',Pc); L=Pc; //Lead angle D=2; LA=atan(L/(%pi*D)); LA=LA*180/%pi; m...
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// Builder gateway function for Sequence Deinterleaver function builder_gw_cpp() WITHOUT_AUTO_PUTLHSVAR = %t; tbx_build_gateway("skeleton_cpp", .. ["seq_deinterleaver","itpp_seq_deinterleaver"], .. ["itpp_seq_deinterleaver.cpp"], .. get_absolute_file_path("builder_gateway_cpp.sce"), [], "-litpp"); ...
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// Tutorial para a geologia mode(7) format("v",10); // Numeros inteiros e reais. // a. atribuicao: usamos o = para fazr atribuicao de variaveis u=2.8 v=1.75 a=2 // b. operacoes com numeros u+v // soma u*v // multiplicacao u/a // divisao u^3 // potenciacao u ao cubo sqrt(a) // raiz quadrada // c. funcoes booleanas u>=v...
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//Electric Drives:concepts and applications by V.subrahmanyam //Publisher:Tata McGraw-Hill //Edition:Second //Ex3_7 clc; clear; Id=50;//Current in A Vs=220;//Supply voltage in V Vdio=257.4;// voltage in V f=50;//Frequency in Hz L=0.0015;//Inductance in mH pf=0.866;//Powerfactor Xc=2*%pi*f*L; Vdia=1.17*V...
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//Obtain path of solution file path = get_absolute_file_path('solution7_8.sce') //Obtain path of data file datapath = path + filesep() + 'data7_8.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate the direct tensile force Dtensile (N) Dtensile = (P * 1000)/N //Calculate the tensile forc...
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//Chapter-1,Example1_10,pg 1_41 rd=200*10^3 gm=0.004 Rs=40*10^3 Rm=1000 V1=1 rdf=rd/(1+gm*rd)//actual rd Rth=(2*Rs*rdf/(Rs+rdf)) Vo=(gm*rdf*Rs)*V1/(rdf+Rs) Im=50*10^-6 Rcal=(Vo/Im)-Rth-Rm//caliberation resistance printf("caliberation resistance\n") printf("Rcal=%.2f ohm",Rcal)
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clc clear //INPUT mf=28.5*10^-6;//mean free path in cm d=0.000178;//density of helium in gm/ml m=6*10^-24;//mass of the helium atom in gm a=(2^(0.5))*3.14;//constant //CALCULATIONS d=(m/(a*d*mf))^(0.5);//diameter of the size in cm //OUTPUT mprintf('the size of the helium atom is %3.10f cm',d)
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//scilab 5.4.1 //windows 7 operating system //chapter 5:Semiconductor Junction Diodes clc clear //given e=1.6*10^-19//e=charge of an electron in C V1=0.06//V1=applied forward bias in V V2=(-0.06)//V2 =applied reverse bias in V kB=1.38*10^(-23)//kB=Boltzmann's constant in J/K T=300//T=Temperature in Kelvin /...
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clc clear //input m=140//mass v=8//speed r=5//radius g=9.8//acceleration due to gravity //calculation t=((m*v^2/5)^2)+(140*9.8)^2 //applying parallelogram of vectors t1=sqrt(t) //output printf("the tension in arm is %3.3f N",t1)
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clc;clear; //Example 25.1 //calculation of sum of two binary numbers //given values X='0011';//first binary number Y='0101';//second binary number //calculation x=bin2dec(X);//decimal equivalent y=bin2dec(Y);//decimal equivalent z=x+y; Z=dec2bin(z); disp(Z,'Sum of the given binary numbers is ')
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//pagenumber 288 example 6 beta1=100; r1=1.5*10^3;//ohm vcc=10;//volt r=100*10^3;//ohm vb=((vcc)/(r+10*10^3))*10*10^3; ie=0.3/100; ib=ie/beta1; disp("collector current = "+string((ie))+"ampere"); disp("emitter current = "+string((ie))+"ampere"); disp("base current = "+string((ib))+"ampere");
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//Example 2_8 clc(); clear; //To calculate the wavelength k=2 theta1=10 //units in degrees dtheta=3 //units in degrees dlamda=5*10^-9 //units in cm lamda=(sin((theta1*%pi)/180)*dlamda*60*60)/(cos((theta1*%pi)/180)*dtheta*(%pi/180)) //units in cm printf("Wavelength of the lines is...
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//CAPTION:location_Determination_of_voltage_maximum_and_minimum_from_load //chapter_no.-3, page_no.-104 //Example_no.3-5-1 clc; Zl=1+ %i*1;//Given normalise load impedance disp('1. Enter Zl=1+(1*i) on the chart'); disp('read .162lamda on the distance scale by drawing a dashed straight line from the centre of...
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t = 1:200; y = [ 0. -0.0022203 0.0150156 0.3234877 -0.5142454 -0.1275302 0.3038018 -0.0552285 -0.265671 0.2409936 0.8815557 -0.0823882 0.0021477 -1.3310292 -0.449962 -0.1049736 -0.4385235 0.2309155 0.2433727 0.0492592 0.8748562 -0.0628307 ...
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clf; clear; clc; load('C:\Users\tangu\OneDrive\Documents\GitHub\Modelisation\TD4\NetworkData.sod') // Extraction des temps de service index_bool = ( data(:, 3) == 1 ) tabS1 = data(index_bool, :) t_s1 = tabS1(1:$,4); deciles=perctl(t_s1,10:10:90); for i=2:10 ClassesDeciles(i)=deciles(i-1) end ClassesDeciles(1)=min...
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sce
Example4_2.sce
//Chapter-4,Example4_2,pg 4-24 E1rms=10 E2rms=15 E1m=E1rms*sqrt(2) E2m=E2rms*sqrt(2) //voltage across AB is proportional to E1+E2 in positive half cycle Ep=(1/(2*%pi))*(2*E1m+E2m)//output in positive half cycle //voltage across AB is proportional to E1-E2 in negative half cycle En=(1/(2*%pi))*(2*E1m-E2m)//outpu...