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// Example 2_4 clc;clear;funcprot(0); // Given values l=0.0015; // Gap between two cylinders in m T=1.8; // Torque in N.m L=.4; // Length in m R=.06; // Outer radius of inner cylinder in m n=300/60; // Number of revolutions per unit time (seconds) //Calculation mu=(T*l/(4*%pi^2*R^3*n*L)); // Viscosity of t...
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disp('chapter 9 ex9.2') disp('given') disp('for circuit designed in ex 9.1 estimate minimum op-amp slew rate to give a reasonably undistorted output') disp('Vcc=12volt,Vee=12volt and Vosat=1volt') disp('t=500*10^(-6)s') disp('R1=120kohm and C1=0.015*10^(-6)F') Vcc=12 Vee=-12 Vosat=1 t=500*10^(-6) R1=120000 C...
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// Crank-Nicolson // Para ecuaciones del tipo // u_t - a(x)u_xx + b(x)u_x +c(x)u = f // Ejemplo // Ecuación de calor 1D // u_t = u_xx // 0<x<l // 0<t<T // u(0,t) = u(l,t) = constante 0 < t < T cond de frontera // u(x,0) = g(x) 0 <=x <= l // Datos de entrada // extremo l // tiempo máximo T // la constante alpha // ...
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clc //variable Initialization Vm=230//Input Voltage In Volts Ra=0.5 //Armature Resistance In Ohm Rf=190 //Field resistace in Ohm N=1400 //Speed Of Motor In RPM Ka=0.8 //Motor voltage constant in V/A-rad/sec T=50 //Load Torque In N-m //Solution W=(2*%pi*N)/60 //Angular Speed In rad/Sec. //Since the maximum f...
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//find max value of torque clc //solution //given d=50//mm M=2000*10^6//N-mm fs=200//N/mm^2 //let T be torque pi=3.14 Z=(pi/32)*d^3//mm^3 //acc to max principal stress theory f1=M/Z//N/mm^2//bending stress //t=16*T/(pi*d^3)//shear stress due to torque/ //ft1=(f1/2)+(0.5*sqrt((f1^2)+4*t^2)//N/mm^2 //ft2=(...
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(unwatch all) (clear) (set-strategy depth) (open "strngfnx.rsl" strngfnx "w") (dribble-on "strngfnx.out") (batch "strngfnx.bat") (dribble-off) (load "compline.clp") (printout strngfnx "strngfnx.bat differences are as follows:" crlf) (compare-files strngfnx.exp strngfnx.out strngfnx) ; close result file (close strngfnx)...
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// read the image object+people.jpg I = imread("object+people.jpg"); bboxes = peopleDetector(I) // output: // bboxes: // no output
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polinomio de lagrange.sce
s = %s; H = [446 485 441] ti = [0.0970 0.263 0.598] h = H(1) + ((H(2)-H(1))/(ti(2)-ti(1)))*(s-ti(1)) + ((H(3)-H(2))/(ti(3)-ti(2)) - ((H(2)-H(1))/(ti(2)-ti(1))))/(ti(3)-ti(1)).*((s-ti(1)).*(s-ti(2)))
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 12 : CONSTRUCTION OF OVERHEAD LINES // EXAMPLE : 12.4 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA T1 = 3000 ; // Bending moments in lb T2 = 2500 ;...
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# ATWM1 MRI Experiment scenario = "ATWM1_Working_Memory_MRI_nonsalient_uncued_run1"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds...
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executeFxnsForEnvironment.sce
exec('AllStagesNoteEnergies.sci', -1) exec('LoadAudioSample.sci', -1) exec('CalcNoteFiltersEnergies.sci', -1) exec('Calc3NoteToSignalRatios.sci', -1) exec('CoeffsToHz.sci', -1) exec('Convert2DIndexTo1D.sci', -1) exec('PrepAudioForProcessing.sci', -1) exec('CreateChord.sci', -1) exec('StageFilter.sci', -1) exec...
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4_20data.sci
Me=2; //mach no in test section at standard sea level condition //following are the standard sea level conditions desired at the exit of nozzle: Pe=1.01*10^5;//static pressure,N/m^2 Te=288.16; //static temperature in Kelvin y=1.4; //specific heat ratio for air A=1+(y-1)*Me^2/2
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// Scilab code Ex7.14: Pg:309 (2008) clc;clear; amu = 931.5; // Energy equivalent of 1 amu, MeV M_He = 4.00260; // Mass of helium, amu m_e = 0.00055; // Mass of electron, amu M_C = 12.000; // Mass of carbon, amu m_He = M_He - 2*m_e; // Mass of helium nucleus, amu m_C = M_C - 6*m_e; // Mass of c...
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// PG (307) deff('[y]=f(x)','y=sqrt(-log(x))') funcprot(0) a=0; b=1; // True value I = integrate('sqrt(-log(x))','x',a,b)
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//NETWORK PROJECT //IMPLEMENT NETWOK TOPOLOGY WITH DATA TRANSFER INCLUDING SECURITY STANDARDS // BY SHREYA SOMKUWAR name='TOPOLOGY';// graph name n=7;//graph parameters tail=[1 1 1 2 2 3 3 4 4 4 5 6]; head=[2 3 4 4 5 4 6 5 6 7 7 7]; node_x=[100 275 275 500 750 750 900]; node_y=[500 200 800 500 200 800 500]; [g]=...
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clc; //e.g 28.8 fo=100*10**3; L=0.5*10**-3; C=2/(4*%pi^2*L*fo^2); disp('microF',C*10**6,"C=");
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//CHAPTER 6 ILLUSRTATION 1 PAGE NO 175 //TITLE:Turning Moment Diagram and Flywheel clc clear k=1// radius of gyration of flywheel in m m=2000// mass of the flywheel in kg T=1000// torque of the engine in Nm w1=0// speedin the begining t=10// time duration //====================...
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SpLiTTeR q {} fIltEr yV { 252.7.32.206/71 >> C not ::8.90.202.244/1 >> -275e6 Or nOt 255.104.53.233 < 167.180.250.238 ae:Fd:Bb:De:Dd:01 in cF:bBd:4E::254.253.184.9 oR BITaND ( BITAND ( ), EF:a9:bA:ce:Dd:B4 , 4, 131.214.251.252, w, Dl, u, ) OR NOT d <= 69 } FilTer A {lLo not tvF OR C } Q branch B GRoupER...
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//Chapter-6, Illustration 9, Page 316 //Title: Refrigeration cycles //============================================================================= clc clear //INPUT DATA T2=40;//Temperature at point 2 in oC T1=-5;//Temperature at point 1 in oC h2=367.155;//Enthalpy at point 2 from F-12 tables in kJ/kg sg=1....
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clc // Given that mu_0 = 1 // refractive index of air mu1 = 1.5 // refractive index for core mu2 = 1.48 // refractive index for cladding // Sample Problem 3 on page no. 5.16 printf("\n # PROBLEM 3 # \n") theta_c = asin(mu2 / mu1) * (180 / %pi) delta_mu = (mu1 - mu2) / mu1 NA = sqrt(mu1^2 - mu2^2) theta_0 = asin(NA) * ...
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function I = simpson_compuesto_puntos(x, y) n = length(x) if modulo(n, 2) <> 0 then h = (x(n)-x(1))/(n-1) ypar = y(2:2:n-1) yimpar = y(3:2:n-2) I = (h/3)*(y(1)+4*sum(ypar)+2*sum(yimpar)+y(n)) else disp('n debe ser impar') I = 0 end endfunction
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//All the quantities are in SI units v_inf = 240; //freestream velocity l = 1; //wavelength of the wall h = 0.01; //amplitude of the wall M_inf = 0.7; //freestream mach number b = sqrt(1-(M_inf^2)); x = l/4; y = l; function temp = u(x,y) temp = v_inf*(1 + (h/b*2*%pi/l*cos(2*%pi*x/l)*exp(-2*%pi*b*y/l...
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clc;funcprot(0);//EXAMPLE 12.1 // Initialisation of Variables r1=0.111;......//Rate of copper in min^-1 at 135 degree celsius r2=0.004;.......//Rate of copper in min^-1 at 88 degree celsius T1=408;.......//Temperature in K T2=361;.......//Temperature in K R=1.987;......//Gas constant Q=20693;.......//Change in R...
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clc; us=0.25;// Coeffiecient of static friction //Applying equillibrium equation we get relation in x printf("Apply equillibrium equations. It is theoritical part. \n"); x=12-(.75*2)+1.5//in, Distance at which the applied load can be supported printf("Minimum distance at which the applied load can be supported is ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART I : GENERATION // CHAPTER 7: TARIFFS AND ECONOMIC ASPECTS IN POWER GENERATION // EXAMPLE : 7.24 : // Page number 84 clear ; clc ; close ; // Clear the work space and ...
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## !!! DO NOT EDIT !!! ## THIS IS AN AUTOMATICALLY GENERATED FILE ## modify build-bc-overload-tests.sh to generate the tests you need. %!shared ex %! ex.double = 1; %! ex.single = single (1); %! ex.logical = true; %! ex.char = 'char'; %! ex.int8 = int8 (1); %! ex.int16 = int16 (1); %! ex.int32 = int32 (1); %! ex.int6...
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function drawTriangle() xpoly([0.0,1.0,0.5,0.0],[0.0,0.0,sqrt(3.0)/2.0,0.0]); endfunction
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//example-8.7 //page no-250 //given //the eutectoidal mixture of pearlite consists of two phases viz. alpha (ferrite) and Fe3C (cementite). the eutectoid composition contains 0.83% carbon. the lever rule is applied in which the lever arm has ferrite (=0% carbon) at one end and cementite (6.67% carbon) at the other ...
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PL/SQL Developer Test script 3.0 13 -- 测试包头和包体调用 declare -- Local variables here v_avg number; begin dbms_output.put_line(my_pack.num1); my_pack.num2 :=30; dbms_output.put_line(my_pack.num2); my_pack.p_test_sal(20,v_avg); dbms_output.put_line(v_avg); end; 0 0
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/* Questionaire created by optica toolkit Date: Wed Mar 05 11:29:09 1997 */ question(1, 'item 1-1', 'Het lampje staat 4 centimeter boven de hoofdas. Als we het 2 centimeter naar onder bewegen, wat kun je dan zeggen over de plaats waar de lichtstraal de hoofdas raakt?', [ 'Niets, want het ligt aan het soort l...
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function r = inscribedCircleRadius(p1,p2,p3) //Computes the inscribed circle radius n12 = norm(p2-p1); n23 = norm(p3-p2); n31 = norm(p1-p3); sumn = (n12+n23+n31)/2; r=sqrt(sumn-n12)*(sumn-n31)*(sumn-n23)/sumn; endfunction
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function xdot = sir_eqn(t,x) // Parameter values bet=0.1; mu=0.05; // Define variables s = x(1); y = x(2); r = x(3); // Define ODEs ds=-bet*s*y; dy=bet*s*y-mu*y; dr=mu*y; // Return gradients xdot = [ds,dy,dr]; endfunction; // SIR model // Define t t = linspace(0, ...
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clear; clc; S=250; V=3330; r=.25; x=3.5; pf=0.8; i=(S*1000)/(sqrt(3)*V); Il=i; Vp=(V/sqrt(3)); z=complex(r,x); Ia=complex(34.99,-26.24); E=Vp+(Ia*z); Vv=sqrt((real(E)^2)+(imag(E)^2)); reg=((Vv-Vp)/Vp)*100; mprintf("regulation=%f percent",reg);
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// Example 4-3, page 97 clear;clc; close; // Given data Vrms=120;// in volts // 10:1 step down transformer // Calculations Vp1=Vrms/0.707;// peak primary voltage in volts Vp2=Vp1/10;// peak secondary voltage in volts // the full wave rectifier acts like 2 back-to-back half-wave rectifiers.because of the center tap...
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clc clear //Input data C=85//Composition of C in percent H2=15//Composition of H2 in percent CV=10600//Calorific value in kcal/kg eO2=60//Percentage of air in excess bhp=240//Brake horse power in h.p nth=30//Thermal efficiency in percent O2=23//Percentage of oxygen contained in air by weight wC=12//Molecular ...
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//Chapter 5:Dc Motor Drives //Example 17 clc; //Variable Initialization //Ratings of the separately excited motor V=220 // rated voltage in V N=1500 // rated speed in rpm Ia=50 // rated current in A Ra=0.5 // armature resistance in ohms Vl=440 // line voltage inV with 3-phase ac supply f=50 //frequen...
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// Chapter 8_Metal Semiconductor and Semiconductor heterojunctions //Caption_Shottky barrier diode //Ex_1//page 308 eps=13.1*8.85*10^-14; e = 1.6*10^-19; T=300 //temperature in kelvin Nd=10^16 //donor impurity phi_m=4.55 //metal work function for tungsten xi=4.01 //electron affinity for silicon phi_bo=phi...
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// Exa 5.3 clc; clear; // Given fs = 10000; // frequency of modulated signal(Hz) fm = 200*10^3; // modulation frequency(Hz) Ri = 10; // Input resistance(ohms) e2_by_e1 = 1.3; // limit for lowest frequency(in %) // Solution F_lower = fm - fs ; printf(' For a double-section filter, \n e2/e1 = 1/s...
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// Example 2.4: Calculate base current and collector current Beta=100;//Common Emitter D.C. Current gain Ie=10;// Emitter current in mili ampere alfa= (Beta/(Beta+1));//Common Base D.C. Current gain Ic= alfa*Ie;// Collector current in milli ampere Ib=Ie-Ic;// Base Current in milli ampere disp(Ic,"Collector curren...
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clc //Chapter7 //Example7.9 //Given g01=round(10^(25/10))//low noise amplifier gain Te1=4//low noise amplifier noise temp g02=round(10^(1.7))//preamplifier gain F2=round(10^0.6)//preamplifier noise figure F3=round(10^1.2)//preamplifier noise figure T=290// room temp Te2=round((F2-1)*T) Te3=round((F3-1)*T) T...
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//include the configuration file here, so we can actually access the values. //Read in the values as a two dimensional array so we can keep everything //as organized as we can. exec ('C:\Documents and Settings\Administrator\My Documents\CSCI\Thesis\ThesisProjectSource\BodyConfig.sci'); exec ('C:\Documents and Se...
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clear; clc; // Example: 6.4 // Page: 206 printf("Example: 6.4 - Page: 206\n\n"); // Solution // *****Data******// T1 = -40 + 273;// [K] T2 = -45 + 273;// [K] P1 = 51.25;// [kPa] R = 0.0815;// [kJ/kg K] Hv = 225.86;// [kJ/kg] //****************// // From Eqn. 6.61: P2 = P1*exp((Hv/R)*((1/T1) - (1...
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//********************************************************************************************************** //*************** Algoritmo para calcular la frecuencia fundamental de una señal de audio ****************** //**************************** se prueban la correlacion y demas funciones utiles ********************...
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//Chapter-3,Example3_17_11,pg 3-39 phi=5.9*10^-3 //magnetic flux ur=900 //relative permeability of material n=700 //number of turns u0=4*%pi*10^-7 //permeability of free space A=60*10^-4 ...
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// Chargement des données agri=[100,60,76,74,90,93,102,98,103,110,117,118,112,115,116,121,134,130] indu=[100,50,84,99,113,122,128,143,145,146,159,172,188,204,213,220,242,254] disp("Le nuage et son centre de gravite"); for i=1:18,plot2d(agri(i),indu(i),-4),end; xbarre=sum(agri)/18; ybarre=sum(indu)/18; plot2d(xbarre, y...
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l=2.5+1.5//span, in m R=0.15//rise, in m t=0.25//tread in m sigma_cbc=7//in MPa sigma_st=275//in MPa //assuming 50 mm per 1 m of span D=50*l//in mm W1=D/10^3*25*1.5*sqrt(R^2+t^2)/t//slab load on plan, in kN/m W2=1/2*R*t*1.5*25/t//load of step per metre, in kN/m W3=1.5*5//live load, in kN/m W=W1+W2+W3//in kN/m...
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P=15E3 a=3000/250 /////OC Parameters Poc=105 Ioc=0.62 Voc=250 /////SC Parameters Psc=360 Isc=5.2 Vsc=157 Y0=Ioc/Voc Gi=Poc/Voc/Voc Bm=sqrt(Y0*Y0-Gi*Gi) Z=Vsc/Isc R=Psc/Isc/Isc X=sqrt(Z*Z-R*R) ///////////Referred to HV side GiHV=Gi/a/a disp(GiHV) BmHV=Bm/a/a disp(BmHV) disp(R) disp(X) ...
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// ==================================================================== // Allan CORNET // DIGITEO 2008 - 2010 // ==================================================================== // <-- CLI SHELL MODE --> // ==================================================================== r = xls_NewExcel(); assert_checktrue(...
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//Example 9.32 clc disp("For the given DAC,") disp(" n = Number of bits = 8") disp("(i) Resolution = 2^n = 2^8 = 256") disp("i.e. the output voltage can have 256 different values including zero.") disp("(ii) V_0FS = Full scale output voltage") disp(" = 2.55 V") disp("Therefore, Resolution = V_0FS ...
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//Chapter1,Example1.15,Pg1.19 clc; disp("Refer to the figure shown in the problem") R1=4*4/(4+4) //Equivalent resistance of the upper triangular network R2=3*3/(3+3) //Equivalent resistance of the triangular network on right R3=2*(R1+R2)/(2+R1+R2) R=2*(R3+1)/(2+R3+1) printf("\n Equivalent resistance =%.2f ohms \...
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function [] = kiks_setdiod(id,dnr,status) // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- g...
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// DFE emulation function for application to Pulse Responses // // (c)2009 L. Rayzman // Created : 08/09/2008 // Last Modified: 08/09/2008 - Initial //////////////////////////////////////DFE emulation//////////////////////////////////// function [t, D, opt_coeff, err] = DFE_pr(tpulse, Dpulse, coeffs, tU...
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//EXAMPLE 26.4 //LONG SHUNT COMPOUND GENERATOR clc; funcprot(0); //Variable Initialisation I=50;.............//Load current in Amperes V=500;.............//Terminal voltage in Volts Rsh=250;............//Resistance of shunt field in Ohms Ra=0.05;...........//Resistance of armature in Ohms Rse=0.03;...........
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@relation flare @attribute LargestSpotSize{A,R,S,X,K,H} @attribute SpotDistribution{X,O,I,C} @attribute Activity{1,2} @attribute Evolution{1,2,3} @attribute Prev24Hour{1,2,3} @attribute HistComplex{1,2} @attribute BecomeHist{1,2} @attribute Area{1,2} @attribute C-class{0,1,2,3,4,5,6,7,8} @attribute M-class{0,1,2,3,4,5...
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clear //Given M=4.001509 //a.m.u N=1.008666 N1=1.007277 a=1.66*10**-27 c=3*10**8 e=1.6*10**-19 n=4.0 //Calculation A=2*N1+2*N M1=A-M Eb=M1*a*c**2/e B=Eb/n //Result printf("\n (i) Mass defect is %0.3f a.m.u",M1) printf("\n (ii) Binding energy is %0.1f Mev",Eb*10**-6) printf("\n Binding energy pe...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>LocProject_Diff2D Tri Mod. Basis P=6, Q=7</description> <executable>LocProject</executable> <parameters>-s triangle -b Modified_A Modified_B -o 6 6 -p 7 7 -c 0.0 0.0 1.0 1.0 0.5 1.0 -d</parameters> <metrics> <metric type="L2" id="1"> ...
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clear;lines(0); // Simple one dimension ODE // dy/dt=y^2-y sin(t)+cos(t), y(0)=0 deff('[ydot]=f(t,y)','ydot=y^2-y*sin(t)+cos(t)') y0=0;t0=0;t=0:0.1:%pi; y=ode(y0,t0,t,f) plot(t,y) // Simulation of dx/dt = A x(t) + B u(t) with u(t)=sin(omega*t), // x0=[1;0] ; // solution x(t) desired at t=0.1, 0.2, 0.5 ,1. // A and u f...
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clc //initialisation of variables P= 100 //psia n= 0.97 hf= 298.4 //Btu/lb hfg= 888.8 //Btu/lb hg= 1187.2 //Btu/lb //CALCULATIONS hx= hf+n*hfg hx1= hg-(1-n)*hfg //RESULTS printf ('Enthalpy= %.f Btu/lb',hx) printf (' \n Precise Enthalpy= %.1f Btu/lb',hx1)
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clc pathname=get_absolute_file_path('9_5_6.sce') filename=pathname+filesep()+'956.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") disp("Using S balance, ") m2=basis*x*MS*MSalt/(MAcid*MS) printf(" \n m2=%f g Na2SO4",m2) di...
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clc //initialisation of variables r=14 g=1.4 x=1.78 //x=v3/v2 //CALCULATIONS oef=1-(1/14)^(g-1) def=1-((1/(14)^(g)*1.4))*((x^(g) -1)/(x-1)) printf('otto efficiency is %2f',oef)
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//(7.2) Refrigerant 134a, initially a saturated vapor at -28C, is contained in a rigid, insulated vessel. The vessel is fitted with a paddle wheel connected to a pulley from which a mass is suspended. As the mass descends a certain distance, the refrigerant is stirred until it attains a state where the pressure is ...
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// Exa 4.7 format('v',7);clc;clear;close; // Given data n = 3;// number of bit R = 1/(10^n); V = 1;// in V // For 1V range, Resolution = V*R;// in V disp(Resolution,"For 1 V range, the resolution in V is"); // For 50 V range, V = 50;// in V Resolution = V*R;// in V disp(Resolution,"For 50 V range, the resol...
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// s: 2014.09.07 function Out=Objjoin(varargin) global OBJJOIN if length(varargin)>0 OBJJOIN=abs(sign(varargin(1))) end; Out=OBJJOIN endfunction
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// Scilab Code Ex8.9: Page-174 (2010) c = 1; // For simplicity assume speed of light to be unity, m/s m0 = 1; // For simplicity assume rest mass to be unity, kg m = (20/100+1)*m0; // Mass in motion, kg // As m = m0/sqrt(1-(u/c)^2), solving for u u = sqrt(1-(m0/m)^2)*c; // Speed of moving mass, m/s pr...
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clc pathname=get_absolute_file_path('9_1_2.sce') filename=pathname+filesep()+'912.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") disp("From reaction, only gaseous are counted") left=1+2 right=1+1 deltaUr=deltaHr-R*T*(rig...
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(X (X a) (X (X Lorillard) (X (X spokewoman) (X (X said) (X (X ,) (X (X ``) (X (X This) (X (X is) (X (X an) (X (X old) (X (X story) (X .)))))))))))) (X (X there) (X (X is) (X (X no) (X (X asbestos) (X (X in) (X (X our) (X (X products) (X (X now) (X (X .) (X '')))))))))) (X (X it) (X (X has) (X (X no) (X (X bearing) (X (...
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@relation yeast-1 @attribute Mcg real [0.11, 1.0] @attribute Gvh real [0.13, 1.0] @attribute Alm real [0.21, 1.0] @attribute Mit real [0.0, 1.0] @attribute Erl real [0.5, 1.0] @attribute Pox real [0.0, 0.83] @attribute Vac real [0.0, 0.73] @attribute Nuc real [0.0, 1.0] @attribute Class {MIT, NUC, CYT, ME1, ME2, ME3, E...
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//EXAMPLE 2-68 PG NO-109-110 V=100; Y1=0.16+%i*0.12; Y2=-%i*0.15; I1=V*Y1; disp('i) CURRENT (I1) is in polar form = '+string (I1) +' A '); I2=V*Y2; disp('ii) CURRENT (I2) is in polar form = '+string (I2) +' A '); P=(V*I1*0.8)+(V*I2*0); disp('iii) Power (P) is in p...
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clc //initialisation of variables P= 0.0060 //atm Vl= 0.0181 //l H= -10730 //cal V2= 22.4 //l //CALCULATIONS W= (V2-P*Vl)*(1.987/.08205) E= H+W //RESULTS printf (' increase in energy= %.f cal ',E+4)
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clc clear //Input data D=0.07;//Diameter of the steel tube in m L=3;//Length of the steel tube t1=227;//Temperature of the steel tube in m t2=27;//Temperature of the room in degree centigrade s=20.52*10^-8;//Stefan Boltzmann constant in kJ/hr m^2 T^4 pi=3.1428;//Constant value of pi //Calculations A=2*pi*D...
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clear; clc; disp(' Example 14.4'); // aim : To determine // (a) the final pressure and temperature // (b) the energy required to drive the compressor // given values rv = 5;// pressure compression ratio m_dot = 10;// air flow rate, [kg/s] P1 = 100;// initial pressure, [kN/m^2] T1 = 273+20;// initial temp...
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(grid (margins (vertical 20) (horizontal 20)) (rows (proportional-height 1) (fixed-height 50) (proportional-height 2)) (columns (proportional-width 1) (proportional-width 1)) (row-gap 20) (column-gap 10) (items (label (caption "Padded Label"...
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// Example 4.8;resistance,reactances and impedances and copper losses clc; close; clear; //given r1=3.45;//ohms r2=0.009;//ohms x1=5.2;//ohms x2=0.015;//ohms kva=100;//kVA e1=8800;//volts e2=440;//volts i1=(kva*10^3)/e1;//in amperes i2=(kva*10^3)/e2;//in amperes k=e2/e1;//transformation ratio ro1=r1+(r2/k^2);//ohms xo1...
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load Drinks.hdl, output-file Drinks.out, output-list wine%B3.1.3 water%B3.1.3 juice%B3.1.3 cond1%B3.1.3 cond2%B3.1.3 cond3%B3.1.3 ; set wine 0, set water 0, set juice 0, eval, output; set wine 1, set water 0, set juice 0, eval, output; set wine 0, set water 1, set juice 0, eval, output; set wine 1, set water 1, set ...
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clear; //clc(); v=275*1000; vrp=v/sqrt(3); p=250*10^(6); cosq=0.9; ir1=p/(sqrt(3)*v*cosq); ir=ir1*(cosd(25.84) + (%i)*sind(-25.84)); A=0.9855138 + 0.0027367*(%i); D=0.9855138 + 0.0027367*(%i); C=- 0.0000004 + 0.0004379*(%i); B=12.37926 + 65.692432*(%i); is=C*vrp + D*ir; printf('the sending end current ...
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FLAGS='--detect foo bar' STDIN='' STDOUT='' STDERR='!USAGE!' EXITVAL='1'
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// Element-wise comparision of three vectors (less then) function vless3(V1, V2, V3) R = double(V1 < V2) < V3; // Required conversion from boolean to double endfunction
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function W=treina() //entrada x=[ 1 0 0 1 0 0 1 1 1 1 0 0 1 0 0 0 0 1 0 0 1 ; 1 0 0 1 0 0 0 1 1 1 0 0 1 0 0 1 0 1 0 0 1 ; 0 0 1 0 0 1 1 1 1 0 0 1 0 0 0 1 0 0 1 0 0 ; 1 0 0 1 0 0 1 1 1 1 0 0 1 0 0 0 0 1 0 0 1 ; 1 0 0 1 0 0 1 1 1 1 0 0 1 0 0 1 0 1 0 0 1 ; 1 0 0 1 0 0 0 1 1 1 0 0 1 0 0 1 0 1 0 0 1 ; 1 0 0 1 0 0 0 1 1...
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errcatch(-1,"stop");mode(2);//caption:find value of frequency of the bridge arm resistance of arm AD //Ex4.13 R1=1000//resistance of arm AB(in ohm) C1=0.159*10^-6//capacitance of arm AB(in F) R2=1000//resistance of arm BC(in ohm) C3=0.636*10^-6//capacitance of arm BC(in F) R4=500//resistance of arm BC(in oh...
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clear //Sistema mecanico, massa-mola-amortecedor em PID T_sim = 10; //tempo de simulaçao //valores das variaveis de massa, força viscosa e Kmola Massa = 0.1; Fviscosa = 0.2; Kmola = 1.6; //calcula eta e wn Wn = sqrt(Kmola/Massa); eta = (Fviscosa/Massa)/(2*Wn); disp('Wn e eta', [Wn eta]); //funçao poly cria polinom...
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clc //Chapter3: Modulation //Example3.3 //Given M1=0.2//depth of modulation for first tone M2=0.4//depth of modulation for second tone Pc=1200//Tx Power Pmod=Pc*(1+M1^2/2+M2^2/2)//total power radiated after modulation by both the tones mprintf('The total power radiated is %d watts',Pmod)
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// This code helps you generate k-point for band struncture calculation. // << Variables >> // [lat_const]: 1x1, real // => lattice constant. primitive vectors will all multipile this constant. // [pri_vect]: 3x3, real // => primitive vectors in row form // [red_path]: nx3, real // => k-path divided points in reduced k...
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//CHAPTER 4_ Motion and Dimensional Measurement //Caption : Resistance strain gage // Example 1// Page 163 disp("Rg=120") disp("E=200 *10^9") disp("dL=3 ") disp("dp=0.3") disp("v=0.3 ") Rg=120 //('enter the resistance of strain gage=:') E=200 *10^9 // given dL=3 //('enter the percent change in the leng...
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clc // at 15 degree Celsius Psat1 = 0.01705 // Saturation pressure in bar hg1 = 2528.9 // Enthalpy in kJ/kg // At 35 degree Celsius Psat2 = 0.05628 // Saturation pressure in bar hg2 = 2565.3 // Enthalpy in kJ/kg fi1 = 0.55// Humidity ratio at state 1 Pw1 = fi1*Psat1 // water vapor pressure at state 1 fi2 = 1 ...
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//example 14.28 //design a regime channel using Laecy's theory clc;funcprot(0); //given Q=35; //discharge f=0.9; //silt factor s=1/2; //side slope V=(Q*f/140)^(1/6); A=Q/V; P=4.75*Q^0.5; D=(P-(P^2-6.944*A)^0.5)/3.472; B=P-2.236*D; R=5*V^2/(2*f); S=f^(5/3)/(3340*Q^(1/6));...
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<!DOCTYPE html> <html> <head> <meta charset="utf-8" /> <title>leaflet</title> <script>(function() { // If window.HTMLWidgets is already defined, then use it; otherwise create a // new object. This allows preceding code to set options that affect the // initialization process (though none currently exist). windo...
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h=50;//in mm t=1.5;//in mm b=25;//in mm
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//Chapter-3,Example3_8,pg 3_38 n=3 R=1/(10^n) //for 10V range R=R*10 err1=R//1-digit error //reading is 5V err=(0.5/100)*5//error due to reading errt=err1+err//total error printf("error when reading is 5V\n") printf("errt=%.4f V\n",errt) //reading is 0.1V err=(0.5/100)*0.1//error due to reading errt=err+...
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// Exa 1.23 clc; clear; close; // given : rho=5 // magnitude of the complex number A phi=45 // phase of a complex number A in Degrees x=rho*cosd(phi) // real part of complex number A y=rho*sind(phi) // imaginary part of complex number A A=x+y*(%i) // complex number A disp(x,"real part of complex number A:") ...
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// evaluate over a grid x=[-1:0.2:1];y=x;[X,Y]=meshgrid(x,y); Z=X.^2-Y.^2; // compute a color (0,1,...,10) for each facet C=round(5*(1+X)); // display the surface clf; subplot(221) surf(Z) xtitle('surf(z)') subplot(222) surf(Z,C) xtitle('surf(z,C)') subplot(223) surf(x,y,Z,C) xtitle('surf(x,y,z,C)') subplot(224) mesh(...
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clear ; clc; // Example 1.2 printf('Example 1.2\n\n'); //Page no. 17 // Solution // (a) // Converting all terms to same unit ml = 1.61;//[km] km = (2*1)/(ml);//[miles] printf('(a) 2 kilometers is equal to %.2f miles.\n',km); //(b) in = 2.54;//[cm] dy = 24*60;//[min] nw_unit = (400*(in)^3*1)/(1*dy);/...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 2 : AC Circuits // Chapter 14 : Frequency Response // Example 14 - 18 clear; clc; close; // // Given data f0 = 770.0000; ...
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scenario = "Mutual Advantage game player 2"; scenario_type = fMRI_emulation; #scenario_type = fMRI; scan_period = 3000; response_matching = simple_matching; no_logfile = false; sequence_interrupt=false; #default #active_buttons = 2; #button_codes=0,1; default_font="arial"; default_font_size=30; default_text_color=255,2...
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kissinamukun kitta wẻ kissinamukỏkepun V;IPFV;SBJV+POT+OPT kissinamukun ā kẻ kissinamukủkepun V;PFV;SBJV kissinamukun ā kissinamukủkepunā V;IPFV;ADM kissinamukun kẻ kissinamukunotookwā V;PRF;COND+IND kissinamukun kitta kẻ kissinamukunookopun V;PFV;COND+POT kissinamukun kitta kẻ wẻ kissinamukunookopun V;PFV;COND+POT+OPT...
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//Solution 6-1 WD=get_absolute_file_path('6_01_solution.sce'); datafile=WD+filesep()+'6_01_example.sci'; clc; exec(datafile) beta1 = -4*integrate('y**2','y',1,0) //integrating to obtain beta printf("Momentum-Flux Correction Factor for Laminar pipe flow is %1.2f",beta1)
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//check o/p when 1 i/p arg is passed to the function y=uencode([1 2 3 4 5 5]); disp(y); //output //!--error 10000 //Incorrect number of input arguments. //at line 42 of function uencode called by : //y=uencode([1 2 3 4 5 5]);
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clear //Given F=14.4*10**-4 //N d=0.05 //m F1=1.6*10**-4 //Calculation // u=4*%pi*10**-7 m=sqrt((F*4*%pi*d**2)/u) d1=1/(sqrt((F1*4*%pi)/(u*m**2))) //Result printf("\n Distance is %0.3f m",d1)
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// Scilab Code Ex5.36: Page:314 (2011) clc;clear; theta = 26.4;....// Optical rotation of sugar solution, degrees l = 20;....// Length of the tube, cm c = 0.20;....// Concentration of the solution, g/cc S = 10*theta/(l*c); // The specific rotation of the sugar solution, degree per dm per (g/cc) printf("\nThe ...