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// Exa 13.1 clc; clear all; // Given data // Refer circuit given in Fig no.13.2(b) given on page no.381 Shaft=3; // Shaft stroke in inches Wiper=0.9;// in inches R=5; // Total resistance(R1+R2) in K ohms Vt=5; // Applied voltage in volts // Solution R2=Wiper/Shaft * R ;// in k Ohms // Since Vo/Vt=R2/(R1+R2); // Therefore Vo=R2/(R) *Vt; // Output Voltage(R1+R2) printf(' The output voltage = %.1f V \n',Vo);
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clc Qv=90; //kJ Qp=-95; //kJ W=-18; //kJ U_l=105; //kJ W_lm=0; Q_lm=90; U_m=U_l+90; dU_mn=Qp-W; U_n=U_m+dU_mn; dQ=Qv+Qp; dW=dQ; W_nl=dW-W; disp("W_nl(in kJ)=") disp(W_nl) disp("U_l in kJ =") disp(U_l) disp("U_m in kJ =") disp(U_m) disp("U_n in kJ") disp(U_n)
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9_6.sce
//Centroid of the gusset plate //refer fig. 9.15 //The composite area is divided into algebraic sum and differences of simple geometries //for rectangle A1=160*280 //mm^2 x1=140 //mm y1=80 //mm //for triangle A2=280*40/2 //mm^2 x2=2*280/3 //mm y2=160+40/3 //mm //1st hole A3=(-%pi*21.5^2)/(4) //mm^2 x3=70 //mm y3=50 //mm //second hole A4=-363.05 //mm^2 x4=140 //mm y4=50 //mm //third hole A5=-363.05 //mm^2 x5=210 //mm y5=50 //mm //fourth hole A6=-363.05 //mm^2 x6=70 //mm y6=120 //mm //fifth hole A7=-363.05 //mm^2 x7=140 //mm y7=130 //mm //sixth hole A8=-363.05 //mm^2 x8=210 //mm y8=140 //mm A=A1+A2+A3+A4+A5+A6+A7+A8 //mm^2 sumAixi=A1*x1+A2*x2+A3*x3+A4*x4+A5*x5+A6*x6+A7*x7+A8*x8 //mm^3 xbar=sumAixi/A //mm sumAiyi=A1*y1+A2*y2+A3*y3+A4*y4+A5*y5+A6*y6+A7*y7+A8*y8 ybar=sumAiyi/A //mm printf("\xbar=%.3f mm \nybar=%.3f mm",xbar,ybar)
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P=280//in kN e=50//eccentricity, in mm b=300//width, in mm D=300//depth, in mm sigma_cc=4//in MPa sigma_cbc=5//in MPa m=18.66//modular ratio cover=50//in mm Asc=4*0.785*20^2//four 20 mm dia bars, in sq mm Ag=b*D//in sq mm Ac=Ag-Asc//in sq mm sigma_cc_cal=P*10^3/(Ac+1.5*m*Asc)//in MPa I=b*D^3/12 + (m-1)*Asc*(D/2-cover)^2//in mm^4 z=I/(D/2)//in mm^3 sigma_cbc_cal=P*10^3*e/z//in MPa sigma_max=sigma_cc_cal + sigma_cbc_cal//in MPa sigma_min=sigma_cc_cal - sigma_cbc_cal//in MPa mprintf("Maximum stress = %f MPa (compressive)\nMinimum stress = %f MPa (tensile)", sigma_max,sigma_min)
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tbx_build_macros('OpenPR', get_absolute_file_path('buildmacros.sce')); clear tbx_build_macros;
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clc //Example 18.7 //Calculate the value of turbulent kinematic viscosity K=0.00576//m^2/s^2 eta=0.0196//m^2/s^3 C_mew=0.09//dimentionless v_t=C_mew*(0.00576)^2/(0.0196)//m^2/s printf("the value of turbulent kinematic viscosity is %f m^2/s",v_t);
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/* *rc2poly *Convert reflection coefficient to prediction filter polynomial *Syntax: *a = rc2poly(k) *[a, efinal] = rc2poly(k, r0) * * *Desciption: *a = rc2poly(k) converts the reflection coefficients k corresponding to the lattice structure to the *prediction filter polynomial a, with a(1) = 1. The output a is row vector of length length(k) + 1. * *[a,efinal] = rc2poly(k,r0) returns the final prediction error efinal based on * the zero-lag autocorrelation, r0. * * EXAMPLE: * Consider a lattice IIR filter given by a set of reflection coefficients. * Find its equivalent prediction filter representation. * * * k = [0.3090 0.9800 0.0031 0.0082 -0.0082]; * a = rc2poly(k) * *OUTPUT: *a = 1.0000 0.6148 0.9899 0.0000 0.0032 -0.0082 * * * *AUTHOR: Vrishabh Lakhani *Sources: Kay, Steven M. Modern Spectral Estimation. Englewood Cliffs, NJ: Prentice-Hall, 1988. */ function [a,efinal] = rc2poly( k,varargin) [lhs,rhs]=argn(0) if rhs==1 then a = k(1); //sets the output vector a to the first element of k for i = 2:length(k) //loop through the remaining elements of k a = [ a+conj(a(i-1:-1:1))*k(i) k(i) ]; //levinson's recursion end a = [1 a]; return a elseif rhs>1 then //to find efinal a = k(1); for i = 2:length(k) a = [ a+conj(a(i-1:-1:1))*k(i) k(i) ]; //levinson's recursion end a = [1 a]; return a,a($) //return the prediction polynomial end endfunction
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clear // // // //Variable declaration D=8.92*10**3 //density(kg/m**3) rho=1.73*10**-8 //resistivity(ohm m) W=63.5 //atomic weight Na=6.02*10**26 //avagadro number e=1.6*10**-19 //charge(c) //Calculation n=D*Na/W mew=1/(rho*n*e) //mobility(m**2/Vs) //Result printf("\n mobility is %0.5f m**2/Vs",mew) printf("\n answer given in the book is wrong")
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/* Etideur: Jinshan GUO Objectif: Fonction à resoudre le problème de Ux=y Containtes: U est une matrice carrée triangulaire supérieur y est un vecteur colonne Valeur retour: x */ function [x]=slosup(U,y) nb_lignes = size(U)(1); //Nombre lignes de matrice for i=nb_lignes:-1:1 if abs(U(i,i)) < %eps then error("Matrice U est non inversible"); end sum_temp = 0; for j=i+1:nb_lignes sum_temp = sum_temp + U(i,j)*x(j); end x(i) = 1/U(i,i)*(y(i)-sum_temp); end endfunction
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clear; clc; funcprot(0); //given data Q = 0.1;//in m^3/s N = 1200;//rotational speed in rev/min beta2_ = 50;//in deg D = 0.4;//impeller external diameter in m d = 0.2;//impeller internal diameter in m b2 = 31.7;//axial width in mm eff = 0.515;//diffuser efficiency H = 0.1;//head losses De = 0.15;//diffuser exit diameter A = 0.77; B = 1; g = 9.81; //Calculations U2 = %pi*N*D/60; cr2 = Q/(%pi*D*b2/1000); sigmaB = (A - H*tan(beta2_*%pi/180))/(B - H*tan(beta2_*%pi/180)); ctheta2 = sigmaB*U2*(1-H*tan(beta2_*%pi/180)); Hi = U2*ctheta2/g; c2 = sqrt(cr2^2 + ctheta2^2); c3 = 4*Q/(%pi*De^2); HL = 0.1*Hi + 0.485*((c2^2)-(c3^2))/(2*g) + (c3^2)/(2*g); H = Hi - HL; eff_hyd = H/Hi; //Results printf('The slip factor = %.3f.',sigmaB); printf('\n The manometric head = %.2f m.',H); printf('\n The hydraulic efficiency = %.1f percentage.',eff_hyd*100); //there is a very small error in the answer given in textbook
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//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc., USA,pp 436. //Chapter-4 Ex4.1.a Pg No. 135 //Title:Diffusivity of Chlorine at 573K and 1.5atm //=========================================================================================================== clear clc //INPUT S_g=235;//Total surface per gram (m2/g) V_g=0.29E-6;//Pore volume per gram (cm3/g) rho_p=1.41; D_He=0.0065;//Effective diffusivity of He (cm2/sec) M_He=4;//Molecular weight of He M_Cl2=70.09;//Molecular weight of Cl2 T_ref=293;//Reference temperature T_degC=300; T=T_degC+273;//Reaction temperature(K) //CALCULATION r_bar=2*V_g/S_g;//Mean Pore radius D_Cl2=D_He*((M_He/M_Cl2)*(T/T_ref))^(0.5);//Assuming Knudsen flow at 573K //OUTPUT //Console Output mprintf('The predicted diffusivity of Chlorine is %0.2E cm2/s ',D_Cl2); //File Output fid= mopen('.\Chapter4_Ex1_a_Output.txt','w'); mfprintf(fid,'The predicted diffusivity of Chlorine is %0.2E cm2/s ',D_Cl2); mclose(fid); //============================================END OF PROGRAM=================================================
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clc; //page no 574 //prob no. 15.7.1 // In this problem data regarding the sea water is given conductivity = 4;//measured in S/m rel_permittivity =80; u=4*%pi*10^-7; f1=100;//measured in Hz f2=10^6;//measured in Hz // A) first it is necessary to evaluate the ratio of conductivity/w*rel_permittivity w1=2*%pi*f1; r=conductivity/w1*rel_permittivity; //after the calculation this ratio is much greater than unity. Therefore we have to use following eq to calculate the attenuation coeff as a=sqrt(w1*conductivity*u/2); disp('N/m',a,'The attenuation coeff is'); // By using the conversion factor 1N=8.686 dB a_dB=a*8.686; disp('dB/m',a_dB,'The attenuation coeff in dB/m is'); // B) w2=2*%pi*f2; r=conductivity/w2*rel_permittivity; //after the calculation this ratio is much greater than unity. Therefore we have to use following eq to calculate the attenuation coeff as a=sqrt(w2*conductivity*u/2); disp('N/m',a,'The attenuation coeff is'); // By using the conversion factor 1N=8.686 dB a_dB=a*8.686; disp('dB/m',a_dB,'The attenuation coeff in dB/m is');
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//exapple 3.1 clc; funcprot(0); // Initialization of Variable rho=998; mu=1.002/1000; x=48/100; u=19.6/100; x1=30/100; b=2.6; //calculation //part1 disp("fluid in boundary layer would be entirely in streamline motion "); Re=rho*x*u/mu; printf("reynolds no is %.2e",Re); //part 2 Re1=rho*x1*u/mu; delta=x1*4.64*Re1^-.5; disp(delta*1000,"boundary layer width in (mm):"); //part3 y=0.5*delta;//middle of boundary layer ux=3/2*u*y/delta-.5*u*(y/delta)^3; disp(ux*100,"velocity of water in (cm/s):"); //part4 R=0.323*rho*u^2*Re1^-0.5; disp(R,"shear stress at 30cm in (N/m^2):"); //part5 Rms=0.646*rho*u^2*Re^-0.5; disp(Rms,"mean shear stress experienced over whole plate in (N/m^2)"); //part6 F=Rms*x*b; disp(F,"total force experienced by the plate in (N)")
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//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc.,USA,pp 436. //Chapter-7 Ex7.1.b Pg No.260 //Title:Reaction Volume and Reactor Size //=========================================================================================================== clear clc //INPUT k2=8.5;//Reaction rate constant (L/mol-sec) T=50;//Reaction condition temperature(°C) P=2;//Reaction Pressure (atm) H_O2=8*10^4;// Solubility (atm/mol fraction) F=17000//Feed rate (L/hr) C_B_feed=1.6;//Feed concentration(M) C_B_product=0.8;//Product concentration(M) k_L_a=900;//Liquid film mass transfer coefficient(hr-1) k_g_a=80;//Gas film mass transfer coefficient(mol/hr L atm) Epsilon=0.1;//Porosity Kg_a=0.596;//Refer the overall reaction rate calculated in Ex7.1.a percent_inc=0.2;//Percentage excess required for reactor volume //CALCULATION delta_C_B=C_B_feed-C_B_product; mol_O2_needed=F*delta_C_B/4; N_air=100;//Assuming 100 mole of feed air f_O2=0.209;//Fraction of O2 f_N2=1-f_O2;//Fraction of N2 N_O2_in=N_air*f_O2; N_N2_in=N_air*f_N2; N_O2_out=N_O2_in/2;//Half of O2 fed N_N2_out=N_N2_in; N_air_out=N_N2_out+N_O2_out; P_O2_out=P*(N_O2_out/N_air_out); P_O2_in=P*(N_O2_in/N_air); P_O2_bar=(P_O2_in-P_O2_out)/(log(P_O2_in/P_O2_out));//Log mean Pressure volume=mol_O2_needed/(Kg_a*P_O2_bar); reactor_vol=volume+volume*percent_inc; volume_gal=volume*0.264; reactor_vol_gal=reactor_vol*0.264; //OUTPUT //Console Output mprintf('\n Reaction volume calculated : %0.0f L ',volume ); mprintf('\n Reactor size to be chosen : %0.0f L',reactor_vol); //File Output fid= mopen('.\Chapter7_Ex1_b_Output.txt','w'); mfprintf(fid,'\n Reaction volume calculated : %0.0f L ',volume ); mfprintf(fid,'\n Reactor size to be chosen : %0.0f L',reactor_vol); mclose(fid); //=============================================END OF PROGRAM============================================================ // Disclaimer : The numerically calculated value of reaction volume is 18008 L not 18000 L as mentioned in the textbook
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clc; R_=8314.5; m_=28; R=R_/m_ p1=1.05;//bar p2=4.2;//bar s2=R*log(p1)/1000; s1=R*log(p2)/1000; disp("change of entropy is:"); disp("kJ/kg K",s2-s1); T=15+273; V=0.03; m=p1*V*10^5/(R*T); S1=m*s1; S2=m*s2; Q=T*(S1-S2); disp("heat rejected is:"); disp("kJ/kg",Q); W=-Q; disp("work done is:"); disp("kJ",W)
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// Q-function // // (c)2011 L. Rayzman // Created : 10/18/2011 // Last Modified: 10/18/2011 - Added Eye Measurement Tool //////////////////////////////////////Q-Function//////////////////////////////////// function Qofx = Qfunc(x) // Extracts waveform data from CSDF ASCII files // // Inputs: // x - Self-explanatory // // Outputs: // Qofx - Self-explanatory Qofx = 0.5 * erfc(x/sqrt(2)); endfunction
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clc; clear all; disp("square plate") x=0.4;//m L=0.75;//mm ts=28;// degree C rhol=993.95;//kg/m^3 k=62.53*10^(-2);//W/m.C mu=728.15*10^(-6);// kg/ms hfg=2402*10^3;// J/kg rhov=0.561;//kg/m^3 g=9.81;// m/s tsat=42;// degree C delx=(4*k*mu*(tsat-ts)*x/(g*rhol*(rhol-rhov)*hfg))^0.25; disp("mm",delx*1000,"The film thickness at the bottom of plate =") hx=k/delx; disp("W/m^2.C",hx,"heat transfer coefficient =") delL=(4*k*mu*(tsat-ts)*L/(g*rhol*(rhol-rhov)*hfg))^0.25; disp("mm",delL*1000,"The film thickness at the bottom of plate =") hL=4*k/(3*delL); disp("W/m^2.C",hL,"heat transfer coefficient =") h=1.2*hL; disp("W/m^2.C",h,"The overall heat transfer coefficient =") Q=h*L*L*(tsat-ts); disp("kW",Q/1000,"rate of heat transfer per metre width, Q =") m=Q/hfg;//kg/hr disp("kg/hr",m*3600,"Condensate flow rate =") hinc=h*(sin(%pi*25/180))^0.25; disp("W/m^2.C",hinc,"heat transfer coefficient when the plate is inclined 25 degree with the horizontal") Re=4*m/(mu*L); disp(Re,"Re =")
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// Сохранение графиков function[]=save_graphics(b,z) b_ = 0 for i=2:length(b) b_ = b_ + (i-1)*b(i) end b_ = 1/b_ a = 0.001:0.001:b_-0.001 l = length(a) for i=1:l [N1(i), M1(i), M3(i)] = get_data(a(i),b,z) end properties = gda() // x labels default properties.x_label.text="a"; properties.x_label.font_style = 6; properties.x_label.font_size = 4; properties.x_label.foreground = 5; properties.x_location = "origin"; // y labels default properties.y_label.font_style = 6; properties.y_label.font_size = 4; properties.y_label.foreground = 3; properties.y_location = "origin"; properties.thickness = 2; properties.foreground = 2; // y name properties.y_label.text="N1"; clf() plot2d(a, N1, 3) xs2eps(gcf(),'N1.eps') // y name properties.y_label.text="M1"; clf() plot2d(a, M1, 3) xs2eps(gcf(),'M1.eps') // y name properties.y_label.text="M3"; clf() plot2d(a, M3, 3) xs2eps(gcf(),'M3.eps') endfunction // Сохранение информации в файл *.csv function[]=save_data(a,b,z) b_ = 0 for i=2:length(b) b_ = b_ + (i-1)*b(i) end [N1, M1, M3, N1m, N2, N3, N4, N2m, N3m, M2] = get_data(a,b,z) data = [a, b, M1, M2, M3, N1, N2, N3, N4, N1m, N2m, N3m] write_csv(data, "data.csv", ";") endfunction // Получение значений pv, Pzv, bz, pp, Pzp, p, pcheck, Pz, pm, Pzm, // Pzmcheck, w, wh, wz function[pv, Pzv, bz, pp, Pzp, p, pcheck, .. Pz, pm, Pzm, Pzmcheck, w, wh, wz]=get_stats(a,b,z) n = 100000 b_ = 0 l = length(b) for i=2:l b_ = b_ + (i-1)*b(i) end ro = a * b_ a_ = 1 - a for i=1:l B(i) = 0 for j=i:l B(i) = B(i) + b(j) end end // ~p for i=1:l pv(i) = 0 for j=i:l pv(i) = pv(i) + get_C(j-1,i-1)*a^(i-1)*a_^(j-i)*b(j) end end // ~P(z) Pzv = get_Pzv(z,pv) // b(z) bz = get_bz(z,b) // pp // Pv for i=2:l Pv(i) = 0 for j=i:l Pv(i) = Pv(i) + pv(j) end end // qp for i=2:l qp(i) = 0 for j=2:i-1 qp(i) = qp(i) + qp(j)*Pv(i-j+2) end qp(i) = 1/pv(1) * (Pv(i)+qp(i)) end clear Pv // p+(0) pp(1) = 0 for i=2:l pp(1) = pp(1) + qp(i) end pp(1) = 1 / (1+pp(1)) // p+(i) for i=2:l pp(i) = pp(1)*qp(i) end clear qp // P+(z) Pzp = get_Pzp(z,a,b_,pv) // p p(1) = pp(1) ph(2) = pp(1) + pp(2) for i=3:l ph(i) = pp(i) end for i=2:l tmp1 = 0 for k=1:l-1 tmp2 = 0 for j=max(2,i-k+1):i tmp2 = tmp2 + ph(j)*B(k+1)*get_C(k-1,i-j)*a^(i-j)*a_^(k-i+j-1) end tmp1 = tmp1 + tmp2 end p(i) = a * tmp1 end clear ph // pcheck //pcheck(1) = pp(1) for i=2:l // left part lp = 0 for k=i-1:l-1 lp = lp + B(k+1)*get_C(k-1, i-2)*a^(i-2)*a_^(k-i+1) end lp = pp(1) * lp // right part rp = 0 for j=2:i tmp = 0 for k=i-j+1:l-1 tmp = tmp + B(k+1)*get_C(k-1, i-j)*a^(i-j)*a_^(k-i+j-1) end rp = rp + pp(j) * tmp end pcheck(i) = a * (lp+rp) end // P(z) Pz = get_Pz(z,a,a_,b,b_,pv,pp(1)) // p* pm(1) = 1/a_ * pp(1) for i=2:l // left part lp = 0 for k=i:l-1 lp = lp + B(k+1)*get_C(k-2, i-2)*a^(i-2)*a_^(k-i) end lp = pp(1) * lp // left middle part lmp = 0 for j=2:i tmp = 0 for k=i-j+2:l-1 tmp = tmp + B(k+1)*get_C(k-2, i-j)*a^(i-j)*a_^(k-i+j-2) end lmp = lmp + pp(j) * tmp end // right middle part rmp = 0 for k=i+1:l rmp = rmp + b(k)*get_C(k-2, i-1)*a^(i-1)*a_^(k-i-1) end rmp = pp(1) * rmp // right part rp = 0 for j=2:i+1 tmp = 0 for k=i-j+3:l tmp = tmp + b(k)*get_C(k-2, i-j+1)*a^(i-j+1)*a_^(k-i+j-3) end if (i<l) rp = rp + pp(j) * tmp end end pm(i) = a * (lp+lmp+rmp+rp) end // P*(z) Pzm = get_Pzm(z,pm) // P*check(z) Pzmcheck = get_Pzmcheck(z,a,a_,b(1),pp(1),pp(2),b,b_,pv) // w w(1) = 1 - ro w(2) = a/a_ * w(1) for i=2:l-1 w(i+1) = 0 for j=1:i-2 w(i+1) = w(i+1) + w(j+1)*a*b(i-j) end w(i+1) = (w(i)*(1-a*b(2))-w(1)*a*b(i)-w(i+1)) / a_ end // w^ wh(1) = w(1) + w(2) for i=2:l-1 wh(i) = w(i+1) end // w(z) wz = get_wz(z,a,a_,b,w(1)) endfunction // Получение значений N1, M1, M3, N1m, N2, N3, N4, N2m, N3m, M2 function[N1, M1, M3, N1m, N2, N3, N4, N2m, N3m, M2,l]=get_data(a,b,z) n = 100000 b_ = 0 l = length(b) for i=2:l b_ = b_ + (i-1)*b(i) end ro = a * b_ a_ = 1 - a for i=1:l B(i) = 0 for j=i:l B(i) = B(i) + b(j) end end [pv, Pzv, bz, pp, Pzp, p, pcheck, .. Pz, pm, Pzm, Pzmcheck, w, wh, wz]=get_stats(a,b,z) // N1 N1 = numderivative(list(get_Pzp,a,b_,pv),1) // N2 N2 = 0 for i=1:l N2 = N2 + (i-1)*pp(i) end // N3 N3 = numderivative(list(get_Pz,a,a_,b,b_,pv,pp(1)),1) // N4 N4 = 0 for i=1:l N4 = N4 + (i-1)*p(i) end // N1m N1m = numderivative(list(get_Pzm,pm),1) // N2m N2m = numderivative(list(get_Pzmcheck,a,a_,b(1),pp(1),pp(2),b,b_,pv),1) // N3m N3m = 0 for i=1:l-1 N3m = N3m + (i-1)*pm(i) end // M1 M1 = 0 for i=1:l M1 = M1 + (i-1)*w(i) end // M2 M2 = numderivative(list(get_wz,a,a_,b,w(1)),1) // M3 M3 = 0 for i=1:l-1 M3 = M3 + (i-1)*wh(i) end l= a*(M3+b_) endfunction // C - число сочетаний без повторений function[R]=get_C(n,k) R = factorial(n) / (factorial(k) * factorial(n-k)) endfunction // ~P(z) function[R]=get_Pzv(z,pv) l = length(pv) R = 0 for i=1:l R = R + z^(i-1)*pv(i) end endfunction // b(z) function[R]=get_bz(z,b) l = length(b) R = 0 for i=1:l R = R + z^(i-1)*b(i) end endfunction // P+(z) function[R]=get_Pzp(z,a,b_,pv) up = (1-z) * get_Pzv(z,pv) * (1-a*b_) down = get_Pzv(z,pv) - z R = up/down endfunction // P(z) function[R]=get_Pz(z,a,a_,b,b_,pv,pp0) bbeta = get_bz(a*z+a_,b) Pzp = get_Pzp(z,a,b_,pv) up = (1-bbeta) * (Pzp - pp0 + z*pp0) down = 1 - z R = up/down + pp0 endfunction // P*(z) function[R]=get_Pzm(z,pm) l = length(pm) R = 0 for i=1:l R = R + z^(i-1)*pm(i) end endfunction // P*check(z) function[R]=get_Pzmcheck(z,a,a_,b0,pp0,pp1,b,b_,pv) bbeta1 = get_bz(a*z+a_,b) bbeta2 = get_bz(a_,b) Pzp = get_Pzp(z,a,b_,pv) tmp = a*z + a_ up1 = tmp - bbeta1 down1 = tmp * (1-tmp) tmp2 = bbeta1/tmp - bbeta2/a_ R = pp0/a_ + a*pp0*z*up1/down1 + a*(Pzp-pp0)*up1/down1 + .. a*pp0*tmp2 + a/z*(Pzp-pp0)*tmp2 + a/a_*(Pzp-pp0-pp1*z)*(bbeta2-b0) endfunction // w(z) function[R]=get_wz(z,a,a_,b,w0) bbeta = get_bz(z,b) up = (z-1) * (a_+a*bbeta) down = z - a_ - a*bbeta R = up*w0/down endfunction
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clc // initialization of variables clear // Material properties E=200 //GPa A=100 //mm^2 Y1=500 //M Pa Y2=250 // MPa // calculations E=E*10^9 // Pa A=A*10^-6 //m^2 Y1=Y1*10^6 // Pa Y2=Y2*10^6 //Pa L_FG=1 //m L_CD=2 // m P1=Y2*A e=P1*L_FG/(E*A) e_FG=e e_CD=e P2=E*A*e_FG/L_FG P3=E*A*e_CD/L_CD Py=2*P1+2*P2+P3 //results printf('part (a) \n') printf(' Yield Load Py = %.1f kN and the displacement is %.2f mm',Py/10^3,e*10^3) // part(b) P4=Y1*A e=P4*L_FG/(E*A) P5=E*A*e/L_CD P=2*P1+2*P4+P5 printf('\n part (b) \n') printf(' Yield Load P = %.1f kN and the displacement is %.2f mm',P/10^3,e*10^3) // Fully plastic load P6=Y2*A*2 Pp=2*P1+2*P4+P6 e_CD=P6*L_CD/(E*A) printf('\n Fully Plastic Load Pp = %.1f kN and the displacement is %.2f mm',Pp/10^3,e_CD*10^3)
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clc //initialisation of variables v=1.34//fps s=3.7*10^-3//fps k=0.8//ft r=20//ft k1=0.04//ft v=3.0//fps v1=5.0//fps d=10^-1//ft d1=1.34//ft //CALCULATIONS K=r*k1//ft V=sqrt(r)//times D=d*(v/d1)^2//cm D1=d*(v1/d1)^2//cm //RESULTS printf('the minimum velocity and the gradient at the which coarse quartz=% f cm',D1)
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// chapter 4 , Example4 1 , pg 117 c=3*10^8 //speed of light(in m/sec) h=6.625*10^-34//planck's constant(in J s) lam=1.2*10^-10//wavelength(in m) E=(h*c)/(lam*1.6*10^-19) //energy of photon(in eV) p=h/lam //momentum of photon printf("Energy of photo\n") printf("E=%.1f eV\n",E) printf("momentum of photon(in Kg m/sec)\n") disp(p)
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// Example 2.8 page no-49 clear clc L=1400 E_diff=12400/L //eV del_E=2.15 L2=12400/del_E printf("\nE2-E1=%.2f eV\n1850 A° line is from 6.71 eV to 0 eV\nTherefore, second photon must be from %.2f to 6.71 eV.\nLambda=%d A°.",E_diff,E_diff,L2)
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A = [3 2 1 0 0 0 0 0 2 6 2 1 0 0 0 0 1 2 6 2 1 0 0 0 0 1 2 6 2 1 0 0 0 0 1 2 6 2 1 0 0 0 0 1 2 6 2 1 0 0 0 0 1 2 6 2 0 0 0 0 0 1 2 6] b = [1 1 1 1 1 1 1 1]' x1 =[0 0 0 0 0 0 0 0]' [x,dx] = jacobi(A,b,x1,10^(-3),1000)
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clear; clc; // SCILAB-2.sce // Constantes A = 1; alpha = 0.5; omega = 2; // Funciones function y = f(t) y = A*exp(-alpha*t).*sin(omega*t); endfunction dt = 0.001; tfin = 10; t = 0:dt:tfin; y = f(t); // Gráficas scf(1); clf(1); plot(t,y); xgrid; xlabel('t'); ylabel('y'); // Objetivos yobj = 0.5; indexyobj = find(y>yobj,1); tyobj = t(indexyobj) plot(tyobj,yobj,'b.'); ya = 0.1; yb = 0.2; indexyayb = find(y>ya & y<yb); tyayb = t(indexyayb); yyayb = y(indexyayb); plot(tyayb,yyayb,'b.'); // Máximo y mínimo global [ymax,indexymax] = max(y) tymax = t(indexymax) plot(tymax,ymax,'ro'); [ymin,indexymin] = min(y) tymin = t(indexymin) plot(tymin,ymin,'ro'); // Ceros indexy0 = find(y(1:$-1).*y(2:$)<0) + 1; ty0 = t(indexy0) y0 = y(indexy0) plot(ty0,y0,'bo'); // Extremos dy = diff(y); indexye = find(dy(1:$-1).*dy(2:$)<0) + 1; tye = t(indexye) ye = y(indexye) plot(tye,ye,'rx'); // Puntos de inflexión d2y = diff(y,2); indexyi = find(d2y(1:$-1).*d2y(2:$)<0) + 1; tyi = t(indexyi) yi = y(indexyi) plot(tyi,yi,'gx'); // Integral ta = 0.5; indexta = find(t==ta); tb = 2.5; indextb = find(t==tb); indexI = indexta:indextb; tI = t(indexI); yI = y(indexI); I = inttrap(tI,yI) rectspos = [tI; yI; dt*ones(1,length(tI)); yI]; rectsneg = [tI; zeros(1,length(tI)); dt*ones(1,length(tI)); -yI]; fill = 10*ones(1,length(tI)); xrects(rectspos,fill); xrects(rectsneg,fill); // Derivada t0 = 3; y0 = y(t==t0) plot(t0,y0,'m.') dydt = dy/dt; dydt0 = dydt(t==t0) yt = y0 + dydt0*(t-t0); plot(t,yt,'m--') // Ejes a1 = gca; tlo = 0; tup = tfin; ylo = -1; yup = 1; a1.data_bounds = [tlo,ylo;tup,yup];
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//Solution 6-2 WD=get_absolute_file_path('6_02_solution.sce'); datafile=WD+filesep()+'6_02_example.sci'; clc; exec(datafile) //unit conversions theta = theta * %pi / 180 //from [degrees] to [radians] z_1 = z_1 / 100 //from [cm] to [m] z_2 = z_2 / 100 //from [cm] to [m] A_1 = A_1 * 10**-4 //from [cm^2] to [m^2] A_2 = A_2 * 10**-4 //from [cm^2] to [m^2] //(a) V_1 = mdot / (rho * A_1) //continuity equation at inlet V_2 = mdot / (rho * A_2) //continuity equation at outlet P_1_gauge = rho * g *((V_2**2 - V_1**2)/(2 * g) + z_2 - z_1) //from bernoulli equation printf("The guage pressure at the centre of inlet is %1.2f kPa", P_1_gauge / 1000) //(b) F_Rx = beta1 * mdot * (V_2 * cos(theta) - V_1) - P_1_gauge * A_1 //from momentum equation in X direction F_Rz = beta1 * mdot * V_2 * sin(theta) //from momentum equation in Z direction printf("\nThe anchoring force needed to hold the elbow is given by") printf("\n1.In positive X direction = %1.0f N", F_Rx) printf("\n2.In positive Z direction = %1.0f N", F_Rz)
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clear; clc; //Example11.10[Installing a Heat Exchanger to Save Energy and Money] //Given:- Cp=4.18;//[kJ/kg.degree Celcius] Th_in=80,Tc_in=15;//Inlet temperatures of hot and cold water[degree Celcius] m=15/60;//[kg/s] e=0.75;//Effectiveness t=24*365;//Operating Hours[hours/year] neta=0.8;//Eficiency cost=1.10;//[$/therm] //Solution:- Q_max=m*Cp*(Th_in-Tc_in);//[kJ/kg.degree Celcius] disp("kJ/kg.degree Celcius",Q_max,"Maximun Heat recover is") Q=e*Q_max;//[kJ/s] E_saved=Q*t*3600;//[kJ/year] disp("kJ/year",E_saved,"The energy saved during an entire year will be") F_saved=(E_saved/neta)*(1/105500);//[therms] disp("therms/year",F_saved,"Fuel savings will be") M_saved=F_saved*cost;//[$/year] disp("per year",M_saved,"The amount of money saved is $")
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To install Jest on a Typescript project npm i jest @types/jest ts-jest -D Explanation: Install jest framework (jest) Install the types for jest (@types/jest) Install the TypeScript preprocessor for jest (ts-jest) which allows jest to transpile TypeScript on the fly and have source-map support built in. Save all of these to your dev dependencies (testing is almost always a npm dev-dependency) https://basarat.gitbooks.io/typescript/docs/testing/jest.html To install Karama more info look to http://karma-runner.github.io/4.0/config/configuration-file.html # Install Karma: $ npm install karma --save-dev # Install plugins that your project needs: $ npm install karma-jasmine karma-chrome-launcher karma-firefox-launcher jasmine-core --save-dev This is for Cypress io npm install cypress --save-dev @cypress/webpack-preprocessor typescript ts-loader # If this is from a blank project npm install cypress webpack @cypress/webpack-preprocessor typescript ts-loader
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clc //initialisation of variables n= 0.25 // k mol M= 32 //kg/kmol V= 0.5 //m^3 //CALCULATIONS m= n*M d= m/V v= 1/d v1= V/n //RESULTS printf ('mass of oxygen = %.f kg',m) printf ('\n density of oxygen = %.f kg/m^3',d) printf ('\n specific volume = %.4f kg/m^3',v) printf ('\n molar specific volume = %.f m^3/kmol',v1)
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// problem 5.7 l=0.77 H=0.39 H1=0.6 Dp=H+H1 Cd=0.623 g=9.81 Q=(2*Cd*l*((2*g*H*H*H)^0.5))/3 v=Q/(l*Dp) Ha=(v*v)/(2*g) q=(2*Cd*l*((2*g)^0.5)*(((H+Ha)^1.5)-(Ha^1.5)))/3 disp(q,"discharge in m3/sec")
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clc; //ex3.10 Vlpk=20.5; //volt RL=5100; //ohm Ilpk=Vlpk/RL; //Ampere// from v=r*i Vave=13.1; //volt//from v=r*i Iave=Vave/RL; //Ampere disp('mA',Ilpk*1000,"Ilpk="); //The answers vary due to round off error disp('mA',Iave*1000,"Iave="); //The answers vary due to round off error
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//example1.2 //page 12 clc; funcprot(0); //initialissation of variable delP=10^6;//change in pressure V=1//volume Beta=2.2*10^9; delV=-delP/V/Beta; perV=-delV*100/V;//percent change disp(perV,"the percent change in volume (%);"); clear
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function Guass_Jordan(a,b) [row,col] = size(a) for j = 1:col for i = 1:row if(i ~= j) b(i) = a(j,j)*b(i)/a(i,j) - b(j) a(i , :) = a(j,j)*a(i,:)/a(i,j) - a(j,:) end end end c = [] for i = 1:row c(i) = b(i)/a(i,i) end disp(c) endfunction
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//Section-4,Example-3,Page no.-I.66 //To calculate percentage of light absorbed by the given solution. z_1=40/100 //z_1=(I/I_0) x=2 C_1=20 y=(log10(100/40)/(x*C_1)) //y=e/M C_2=40 z_2=y*C_2*x //z_2=log(I_0/I_t)=log(z_3)where z_3=(I_0/I_t) z_3=10^z_2 I_t=(100/z_3) p_l=(100-I_t) disp (p_l,'Percentage of light absorbed')
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//example 7.1// clc //clears the screen// clear //clears the command window// e=input('Enter the enable i/p level (1or0) :'); //accepting the input of enable// r=input('enter the R i/p level(1or0):'); //accepting the inputs from the user// s=input('enter the S i/p level(1or0):'); //accepting the input S from the user// qn=input('Enter the previous output value (1or0):'); //accepting the old input from the user// flag=0; if e==0 then //calculating the output// op=qn ; elseif(s==0 & r ==0) then op=qn ; elseif ( s ==1& r ==1) then disp('The inputs are illegal') flag=1; else op=s; end if(flag==0) disp('output(Qn+1)=') disp(op) end //displaying the output//
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mode(-1) toolboxname='modbusblocks' pathB=get_absolute_file_path('buildmacros.sce') disp('Building macros in ' +pathB) genlib(toolboxname+'lib',pathB,%t) disp('Building Scicos palette ...') blocks=['MB_INIT_TCP.sci';.. 'MB_INIT_RTU.sci';.. 'MB_READ_COIL_STATUS.sci';.. 'MB_READ_INPUT_STATUS.sci';.. 'MB_READ_HOLDING_REGS.sci';.. 'MB_READ_INPUT_REGS.sci';.. 'MB_FORCE_SINGLE_COIL.sci';.. 'MB_PRESET_SINGLE_REG.sci';.. 'MB_FORCE_MULTIPLE_COILS.sc';.. 'MB_PRESET_MULTIPLE_REGS.sci'] load(SCI+'/macros/scicos/lib') exec(SCI+'/macros/util/create_palette.sci',-1) build_palette(blocks,pathB,'ModbusBlocks') clear pathB genlib toolboxname blocks
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// SerialLink.sci creates a SerialLink robot structure // www.controlsystemslab.com July 2012 // // Parameters // Link(i) Link structure (inherited from L) // gravity direction of gravity [gx gy gz] // base pose of robot's base (4x4 homog xform) // tool robot's tool transform, T6 to tool tip (4x4 homog xform) // name name of robot, used for graphical display // manuf annotation, manufacturer's name // // nj number of joints // config joint configuration string, eg. 'RRRRRR' // mdh kinematic convention boolean (0=DH, 1=MDH) // // Usage: RM = SerialLink(L, options) function rm=seriallink(L,varargin) rm=_Serial_Link(L,varargin); endfunction function rm=SerialLink(L,varargin) rm=_Serial_Link(L,varargin); endfunction function rm=_Serial_Link(L,varargin) varargin = varargin($); varnum=length(varargin); sdhflag = 0; // flag for stdDH mdhflag = 0; // flag for modDH nlinks=size(L,1); // number of links rm.nj = nlinks; // number of joints rm.mdh = 0; // default to stdDH rm.conf = ''; // joint configuration string for i=1:nlinks rm.Link(i)=L(i); if rm.Link(i).mdh then mdhflag = 1; // modified DH detected rm.mdh = 1; // modDH else sdhflag = 1; // standard DH detected end if L(i).sigma then rm.conf=strcat([rm.conf,'P']); else rm.conf=strcat([rm.conf,'R']); end end if (sdhflag & mdhflag) then // mixed DH conventions not allowed rm = []; //return null matrix error('Robot has mixed DH link conventions'); end rm.name = ''; rm.manuf = ''; rm.comment = ''; rm.base = eye(4,4); rm.tool = eye(4,4); rm.gravity = [0; 0; 9.81]; rm.workspace=[]; rm.viewangle=[]; if pmodulo(varnum,2) then // number of arguments is odd. Error! error("Input argument number is odd. You must miss something!"); else for iv =1:2:varnum-1 // select only command at odd position if type(varargin(iv))==10 then // check if string (it should be!) varargin(iv)=convstr(varargin(iv),'l'); // convert to lower else error("Parameter name must be a string (perhaps you forget to put it in quotes)!"); end select varargin(iv), case 'name' then if type(varargin(iv+1))==10 then rm.name = varargin(iv+1); else error("Robot name must be a string"); end case 'manuf' then if type(varargin(iv+1))==10 then rm.manuf = varargin(iv+1); else error("Robot manufacturer must be a string"); end case 'comment' then if type(varargin(iv+1))==10 then rm.comment = varargin(iv+1); else error("Comment must be a string"); end case 'viewangle' then if size(varargin(iv+1))==[1,2] then rm.viewangle = varargin(iv+1); else error("Value for robot viewangle must be 1 x 2 vector"); end case 'base' then if ishomog(varargin(iv+1),'valid') then rm.base = varargin(iv+1); else error("Value for robot base must be 4 x 4 matrix"); end case 'tool' then if ishomog(varargin(iv+1),'valid') then rm.tool = varargin(iv+1); else error("Value for robot tool must be 4 x 4 matrix"); end case 'gravity' then if size(varargin(iv+1))== [3 1] then rm.gravity = varargin(iv+1); else error("Value for robot gravity must be 3 x 1 vector"); end end // select varargin(iv) end // for iv=1:2:varnum-1 end // if pmodulo(varnum,2) endfunction
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function plotly(x,y) //if the file plotly.html already exists, delete it if getos() == 'Windows' then unix('del plotly.html'); else unix('rm -f plotly.html'); end header='<head><script src=""https://cdn.plot.ly/plotly-latest.min.js""></script></head>'; container='<div id=""container"" style=""width:600px;height:400px;""></div>'; // data = '{x: ['+strcat(string(x),",")+'],y: ['+strcat(string(y),",")+'] }'; st = struct("x",x,"y",y); data = toJSON(st); js='<script>CONTAINER = document.getElementById(""container"");Plotly.plot( CONTAINER,['+data+'] );</script>'; write('plotly.html', [header;container;js]) if getos() == 'Windows' then winopen('plotly.html') end endfunction
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// **** Purpose **** // This codes can modify the onsite potential of wannier Hr to mimic // the effects of simple impurities. // **** Variables **** // ==== << PiLab Inputs >> ==== // [imp.HrRead]: 1x1, str, 'wan'/'spl'/'hdr' // <= specify the Hr to read. // [imp.PotState]: 1xn, int // <= states that onsite fields are applied // [imp.PotStreng]: 1xn, real // <= energy shift of each assigned sublattice // ==== << PiLab Outputs >> ==== // [imp.R0_index]: 1x1, int // => index of R=0 unit cell in the loaded uc_index // [imp.pot_orig]: tot_wf x 1, real // => original onsite potential of each WF. // [imp.pot_corr]: tot_wf x 1, real // => onsite potential corrections of each WF. // **** Version **** // 02/24/2016: first built // **** Comment **** function PiLab_imp(project_name) disp('{imp}: starting calculation ...'); c1=clock(); printf('\n'); printf(' => start time: %4d/%02d/%02d %02d:%02d:%02d\n',c1); // loading variables =============================================== disp('{imp}: loading variables ...'); PiLab_loader(project_name,'imp','user','trim'); load(project_name+'_imp.sod'); load(project_name+'_'+imp.HrRead+'.sod'); disp(' => all data loaded') // check variables ================================================ disp('{imp}: checking variables ...') check_var=(imp.HrRead=='wan' | imp.HrRead=='hdr' | imp.HrRead=='spl'); if check_var~=%t then disp('Error: PiLab_imp, imp.HrRead must '... +'be ''wan'', ''hdr'', ''spl'' !'); abort; end check_var=(length(imp.PotState)==length(imp.PotStreng)) if check_var~=%t then disp('Error: PiLab_imp, imp.PotState and imp.PotStreng '... +'must have the same length!'); abort; end disp(' => all variables passed') // core part ======================================================= disp('{imp}: running core part ...'); disp(' => collecting information') select imp.HrRead case 'wan' tot_state=length(wan.state_info(:,1)); imp.R0_index=PIL_row_find(wan.uc_index(:,1:3),[0,0,0]); H0_mat=.. wan.Hr_mat(:,(imp.R0_index-1)*tot_state+1:imp.R0_index*tot_state).. /wan.uc_index(imp.R0_index,4); case 'hdr' tot_state=length(hdr.state_info(:,1)); imp.R0_index=PIL_row_find(hdr.uc_index,[0,0,0]); H0_mat=.. hdr.Hr_mat(:,(imp.R0_index-1)*tot_state+1:imp.R0_index*tot_state); case 'spl' tot_state=length(spl.state_info(:,1)); imp.R0_index=PIL_row_find(spl.uc_index,[0,0,0]) H0_mat=.. spl.Hr_mat(:,(imp.R0_index-1)*tot_state+1:imp.R0_index*tot_state); end H0_mat=full(H0_mat); if max(imp.PotState) > tot_state then disp('Error: PiLab_imp, imp.PotState '... +'has state label that does''t exist !'); abort; end disp(' => modifying onsite potentials') imp.pot_orig=diag(H0_mat); imp.pot_corr=zeros(tot_state,1); imp.pot_corr(imp.PotState)=imp.PotStreng'; // output information ============================================== disp('{imp}: output information ...') fid=mopen(project_name+'_imp.plb','a+'); PIL_print_mat('imp.R0_index, @f:f, R=0 unit cell in the uc index ',.. imp.R0_index,'i',fid(1)); PIL_print_mat('imp.pot_orig, @f:f, original onsite potentials'.. +' of each WFs',imp.pot_orig,'r',fid(1)); PIL_print_mat('imp.pot_corr, @f:f, onsite potential corrections'.. +' of each WFs',imp.pot_corr,'r',fid(1)); mclose(fid(1)) // finishing program =============================================== save(project_name+'_imp.sod','imp'); disp('{imp}: finishing calculation ...'); disp(' => time elapse '+string(etime(clock(),c1))+ ' seconds'); endfunction
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function [a,e]=levdown(a, efinal) ee=a($); a = (a-a($)*flipdim(a,2,1))/(1-a($)^2); a=a(1:$-1) econj=conj(ee); econj=econj'; e = efinal/(1.-(econj.*ee)); endfunction
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//CHAPTER 11 ILLUSRTATION 10 PAGE NO 296 //TITLE:VIBRATIONS //FIGURE 11.18 clc clear //=========================================================================================== //INPUT DATA PI=3.147 g=9.81// ACCELERATION DUE TO GRAVITY IN N /m^2 E=200*10^9// YOUNGS MODUKUS OF SHAFT MATERIAL IN Pascals D=.03// DIAMETER OF SHAFT IN m L=.8// LENGTH OF SHAFT IN m r=40000// DENSITY OF SHAFT MATERIAL IN Kg/m^3 W=10// WEIGHT ACTING AT CENTRE IN N //=========================================================================================== I=PI*D^4/64// MOMENT OF INERTIA OF SHAFT IN m^4 m=PI*D^2/4*r// MASS PER UNIT LENGTH IN Kg/m w=m*g DELTA=W*L^3/(48*E*I)// STATIC DEFLECTION DUE TO W DELTA1=5*w*L^4/(384*E*I)// STATIC DEFLECTION DUE TO WEIGHT OF SHAFT Fn=.4985/(DELTA+DELTA1/1.27)^.5 //========================================================================================== printf('FREQUENCY OF TRANSVERSE VIBRATION = %.3f Hz',Fn)
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// sum 7-6 clc; clear; P=1500; FOS=2; Pd=FOS*P; l=280; E=207*10^3; I=Pd*l^2/(%pi^2*E); D=(64*I/(%pi*(1-0.8^4)))^(1/4); D=8; d=6.4; // printing data in scilab o/p window printf("D is %0.1f mm ",D); printf("\n d is %0.1f mm ",d);
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clc // Given that H_c= 3.3e4 // // Magnetic field in A/m T_c = 7.2 // Critical temperature in kelvin T = 5 // Temperature in kelvin printf("Example 8.2\n") printf("Standard formula used \tH_c = H_c_0*(1-(T/T_c)^2) \n") H_c_0 = H_c*(1-(T/T_c)^2)^(-1) // Calculation of critical field printf("Magnetic Field at %d K is %e A/m\n\n\n",T,H_c_0)
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// Chapter7 // Page.No-296 // Example_7_17_a // Nominal frequency // Given clear;clc; R2=1.5*10^3; R1=10*10^3; R3=10*10^3; C1=0.001*10^-6; V=12; // Supply voltage Vc=R3*V/(R2+R3); // Using voltage divider rule printf("\n Terminal voltage Vc is = %.2f V \n",Vc) // Result fo=2*(V-Vc)/(V*R1*C1); printf("\n Approximate Nominal freq fo is = %.1f Hz \n",fo) // Result
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//Scilab Code for Example 11.3 of Signals and systems by //P.Ramakrishna Rao //Hilbert Transform clc; clear xr n t x1 x2; clear; n=1; for t=-1:0.01:1 xr(n)=exp(%i*2*%pi*t); n=n+1; end //Computing Hilbertb Transform x1=hilbert(real(xr)); x2=hilbert(imag(xr)); x=x1+x2; t=-1:0.01:1; plot(t,xr); title('Given Signal x(t)'); xlabel('time t-->'); figure(1); t=-1:0.01:1; plot(t,imag(x)); title('Hilbert Transform'); xlabel('time t-->');
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//Dynamometer wattmeter power calculation of the load clc; clear; P=250; // Power Recorded by the wattmeter V=200; // Load voltage R=2000; // Resistance of the highly non-inductive pressure coil I=V/R; // Ohm's Law Pcoil=V*I; // Power Absorbed by the pressure coil Pl=P-Pcoil; // Power taken by the load printf('The Power taken by the load = %g watts. \n',Pl)
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// ex3.6 // https://en.wikipedia.org/wiki/Extent_of_reaction // https://www.youtube.com/watch?v=fuk1zTdJifM // 2A <=> B + 3C // Given: // A0 >0 // B0 >0 // C0 >0 // K // calc at eq // A, B, C function eq = model1(x) Xi = x(1) // extent of reaction A = -2*Xi + A0 B = 1*Xi + B0 C = 3*Xi + C0 eq(1) = B*C^3 - K*A^2 endfunction A0 = 2 // mol/L B0 = 1 // mol/L C0 = 0 // mol/L K = 79.734375 guess = [0.5] x = fsolve(guess, model1) Xi = x(1) A = -2*Xi + A0 B = 1*Xi + B0 C = 3*Xi + C0 printf("Xi=%.3f\n", Xi) printf("A=%.3f\n", A) printf("B=%.3f\n", B) printf("C=%.3f\n", C) //----------------------------------------------------- // A + B <=> C + D // Given: // A0 >0 // B0 >0 // C0 >0 // D0 >0 // K // calc at eq // A, B, C, D function eq = model2(x) Xi = x(1) // extent of reaction A = -1*Xi + A0 B = -1*Xi + B0 C = 1*Xi + C0 D = 1*Xi + D0 eq(1) = C*D - K*A*B endfunction // #1 A0 = 1 // mol/L B0 = 1 // mol/L C0 = 0 // mol/L D0 = 0 // mol/L K = 1 guess = [0] x = fsolve(guess, model2) Xi = x(1) A = -1*Xi + A0 B = -1*Xi + B0 C = 1*Xi + C0 D = 1*Xi + D0 printf("\nCase: A0=%.1f mol/L B0=%.1f mol/L A0=%.1f mol/L B0=%.1f mol/L K=%.1f\n", A0,B0,C0,D0,K) printf("Xi=%.3f\n", Xi) printf("A=%.3f\n", A) printf("B=%.3f\n", B) printf("C=%.3f\n", C) printf("D=%.3f\n", D) // #2 A0 = 1 // mol/L B0 = 1 // mol/L C0 = 1 // mol/L D0 = 1 // mol/L // K = 1 guess = [0] x = fsolve(guess, model2) Xi = x(1) A = -1*Xi + A0 B = -1*Xi + B0 C = 1*Xi + C0 D = 1*Xi + D0 printf("\nCase: A0=%.1f mol/L B0=%.1f mol/L A0=%.1f mol/L B0=%.1f mol/L K=%.1f\n", A0,B0,C0,D0,K) printf("Xi=%.3f\n", Xi) printf("A=%.3f\n", A) printf("B=%.3f\n", B) printf("C=%.3f\n", C) printf("D=%.3f\n", D) // #3 A0 = 1 // mol/L B0 = 1 // mol/L C0 = 0.5 // mol/L D0 = 0.5 // mol/L // K = 1 guess = [0] x = fsolve(guess, model2) Xi = x(1) A = -1*Xi + A0 B = -1*Xi + B0 C = 1*Xi + C0 D = 1*Xi + D0 printf("\nCase: A0=%.1f mol/L B0=%.1f mol/L A0=%.1f mol/L B0=%.1f mol/L K=%.1f\n", A0,B0,C0,D0,K) printf("Xi=%.3f\n", Xi) printf("A=%.3f\n", A) printf("B=%.3f\n", B) printf("C=%.3f\n", C) printf("D=%.3f\n", D) // #4 A0 = 0 // mol/L B0 = 0 // mol/L C0 = 1 // mol/L D0 = 1 // mol/L // K = 1 guess = [0] x = fsolve(guess, model2) Xi = x(1) A = -1*Xi + A0 B = -1*Xi + B0 C = 1*Xi + C0 D = 1*Xi + D0 printf("\nCase: A0=%.1f mol/L B0=%.1f mol/L A0=%.1f mol/L B0=%.1f mol/L K=%.1f\n", A0,B0,C0,D0,K) printf("Xi=%.3f\n", Xi) printf("A=%.3f\n", A) printf("B=%.3f\n", B) printf("C=%.3f\n", C) printf("D=%.3f\n", D)
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//Ex 2.9.4 clc;clear;close; format('v',8); //Given : T=27+273;//K V1=0.4;//V V2=0.42;//V I1=10;//mA I2=20;//mA VT=T/11600;//V Eta=1/log(I1/I2)*(V1-V2)/VT disp(Eta,"Value of Eta : "); Io=I1/(exp(V1/Eta/VT)-1)*10^-3;//A disp(Io*10^9,"Current, Io in nA : "); //Ans in the book is not accurate.
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//to point out the reading that can be rejected by chavenets criterion clc; x=[5.3 5.73 6.77 5.26 4.33 5.45 6.09 5.64 5.81 5.75]*10^-3; d=[-.313 .117 1.157 -.353 -1.283 -.163 .477 .027 .197 .137]*10^-3; n=10; X=sum(x)/n; s=sqrt(sum(d^2)/(n-1)); a=abs(d)/s;disp(a); for i=1:10, if a(i)>1.96 then disp(x(i),'rejected value'); end end
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errcatch(-1,"stop");mode(2);//Example 8.8, page no-511 wn=sqrt(3) x=3.2/(2*wn) printf("Damping coefficient = %.3f\nNatural frequency of Oscillation = %.3f",x,wn) exit();
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// Chargement de l'image img_input=readpbm("C:\Users\DimitriXPS\Documents\GitHub\Exolife\Exolife\Images\Mission 5\Gliese 667Cc_surface.pbm"); <<<<<<< HEAD // Do a normalisation on the image display_gray(histogramme(normalisation(img_input))); ======= // Effectuer la fonction normalisation sur l'affichage display_gray(normalisation(img_input)) >>>>>>> origin/Dimitri
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clc //initialisation of variables p1=53//psi p2=54//psi t=638//lb-ft d=275//rpm h1=50.26//sq in h2=49.48//sq in g=(10/12)//lb-ft h=33000//lbf //CALCULATIONS I=(p1*h1+p2*h2)*g*d/(h)//ihp P=2*%pi*d*t/h//bhp M=P/I*100//percent //RESULTS printf('the mechanical efficiency=% f percent',M)
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//Example number 6.9, Page number 120 clc;clear; close; //Variable declaration Ee=10; //electron kinetic energy(eV) Ep=10; //proton kinetic energy(eV) e=1.6*10**-19; //charge(c) me=9.1*10**-31; //mass(kg) mp=1.67*10**-27; //mass(kg) //Calculation cebar=sqrt(2*Ee*e/me); //electron velocity(m/s) cpbar=sqrt(2*Ep*e/mp); //proton velocity(m/s) //Result printf("electron velocity is %.3e m/s",cebar) printf("\n proton velocity is %.3e m/s",cpbar) //answers given in the book are wrong
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// A simple JSON Writer function JSON = JSONWrite(Struct) endfunction
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function r=%b_h_spb(a,b) // perform logical elementwise and a&b where a is a boolean sparse matrix // and b a boolean matrix // Copyright INRIA r=sparse(a)&b
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float displaydata(float * datavalues, int stepval) { float scratchreaddisplay(float * reconstructiondata, float * scratchdata, const char * filename, bool readtile) { fullnumberoflasers in tile class B_DistributionsLoopintern.pgm
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clc //initialisation of variables h1=0.9//percent h2=0.6//percent t=400//ft per sec s=0.8//ft a=20//degree p=500//ft r=p*cosd(a)-t//ft r1=p*sind(a)//ft j=50000//ft w=6700//ft lb e=10.2//ft t1=778//F //CALCULATIONS V=t/s//ft per sec V1=sqrt(r^2+r1^2)//ft lb N=w/(e*t1)*100//percent //RESULTS printf('The nozzle and blade efficiency=% f percent',N)
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//Ex 7.1 page 260 clc; clear; close; N1=1000;// rpm Va1=200;// V alfa=60;// degree Va2=230;// V N2=2*Va2*sqrt(2)*cos(alfa*%pi/180)*N1/Va1/%pi printf('\n Speed of motor = %d rpm',N2) // ans in the textbook is not accurate.
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//Fuels and Combustion// //Example 8.16// C=3;//weight of carbon in 1kg of coal sample in Kilograms// WO2=C*32/12;//weight of oxygen in carbon sample in Kilograms// WA=WO2*100/23;//weight of air in the carbon sample in Kilograms// printf('weight of air required for combustion of carbon=WA=%fKg',WA); MA=WA/28.92;//mol of air in kilograms// VA=MA*22.4;//Volume of air required in m3 air// printf('\nVolume of air required=VA=%fm3',VA);
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errcatch(-1,"stop");mode(2);//Example 2_11 ; ; //To find the slit width d=2 //units in meters lemda=500*10^-9 //units in meters x=5*10^-3 //units in meters a=(d*lemda)/x*10^3 printf("The slit width is %.1f mm",a) exit();
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exec('degree_rad.sci', -1) //Given that Vs = 1482 //in m/s Vw = 343 //in m/s //Sample Problem 18-1 printf("**Sample Probelm 18-1**\n") //deltaT = d/V = D*sin(theta)/V //D*sin(90)/Vs = D*sin(theta)/Vw theta = rtod(asin(Vw/Vs)) printf("The actual angle at which source is present, is %fdegree", theta)
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considerNonPrimitive Expanding for base=2, level=4, reasons+features=primitive Refined variables=a,b,c ReasonFactory: primitive, code="primitive" isNonPrimitive? rmap2=[0+2*a,0+2*b,0+3*c], gcdAdd=2, gcdMul=1 PrimitiveReason.consider( "a²+b²-c²", "a²+b²-c²") = unknown
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function Xi = genererRandUniforme(borneA,borneB, iter) Xi = grand(iter,1,'unf',borneA,borneB); endfunction
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pathname=get_absolute_file_path('3_04.sce') filename=pathname+filesep()+'3_04data.sci' exec(filename) printf("\Answer:\n") printf("\pressur altitude: %f Km\n",Hp) printf("\n\density altitude : %f Km\n\n",Hd)
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// Example 32_7 clc;funcprot(0); //Given data UF=0.5;// Use factor CF=0.4;// Capacity factor //Calculation // Use factor=E/(P_c*t);.... (1) // Capacity factor=(average load/P_c)=(E/(P_c*8760));....(2) // Dividing euations (1) and (2) we get, T=(8760*CF)/(UF);// hours printf('\nThe number of hours of its operation during the year=%0.0f hours',T);
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exec("degree_rad.sci",-1) //Given that m = .20 //in kg F_1 = 4 * [1,0] F_2 = 2 * [-1,0] F_3 = 1 * [cos(dtor(30)),sin(dtor(30))] //Sample Problebb nmkn nm 5-1 printf("**Sample Problem 5-1**\n") acceleration_a = F_1(1)/m acceleration_b = F_2(1)/m acceleration_c = (F_2(1) + F_3(1))/m printf("The acceleration of puck in case a is %d m/s^2\n",acceleration_a) printf("The acceleration of puck in case b is %d m/s^2\n",acceleration_b) printf("The acceleration of puck in case c is %f m/s^2\n",acceleration_c)
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do ddo do1 od2 od if else fi;
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clc T=300 //K k=8.617*10**-5//eV/K e=1.6*10**-19 //C alphaF=0.99 alphaR=0.20 Ic=1//mA IB=0.050//mA Vcesat=k*T*log(((Ic*(1-alphaR)+IB)*alphaF)/((alphaF*IB-(1-alphaF)*Ic)*alphaR)) disp(Vcesat,"VCEsat in V is=")
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clc clear all // constants T = 0.5 L = 1 M = 999 N = 19 delta_t = T/ (M+1) delta_x = L/ (N+1) // initial condition function [f] = initialCondition(x) f = exp(-(x^2))*x*(1-x) endfunction // using the initialCondition function for i = 1: N + 2 u(1, i) = initialCondition(delta_x*(i-1)) end x = (0:N+1)*delta_x plot(x, u(1,:)) //for n = 2 : M + 2 // u(n, 1) = 0 // u(n, N + 2) = 0 //end
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//chapter 2 //example 2.9 //page 48 printf("\n") printf("given") P1=700*10^-3;Vf=.7; //at 25C If=P1/Vf; disp("If") //at 65C D=5*10^-3;T=65-25; P2=P1-D*T If=P2/Vf; printf( "maximum forward current at 65C is %3.3fA\n",If)
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// set len of signal mp mp=500 // set time vector n n=(1:1:mp ) ; // set len of filter hmm and hmp nfilter =20 ; // set noise vector R= .2 // variance Gaussian av =0 // mean Gaussian sd =sqrt(R) // std Gaussian v = grand(1,mp,'nor',av,sd) ;// generate white gaussian hmm = zeros(1,nfilter) ; hmp = zeros(1,nfilter) ; // est vector is dest dest=zeros(1, mp); // create input signal x in theta dtheta =2*%pi/mp ; x=dtheta*n ; // create desired vector d as sin(x) d =sin(x) ; figure(0) ; plot (x ,d) ; // set xmm init vector i=1 ; x1=x; // we are using x as d + noise so we store x as x1 // now create input vector x with noise x= d+v ; deltn =.01 // step size // begin computation for i statement for i=1: mp-nfilter ; i ; xmm = x(1:1, i: (nfilter+i -1) ) ; in= i+1 ; // set next input vector //xmp = x(1:1, in: (nfilter+in -1) ) ; // compute thedhat value from xmm ' *hmm // dhat is set to zero vector first dhat = xmm*hmm' ; // update est vector dest(i) = dhat ; // compute last error elast= d(i) - dhat ; elast ; // update hmm vector hmp= hmm + xmm*elast*deltn ; hmm =hmp ; // next step end ; d ; dest ; figure(1); subplot(221) ; title (' true signal '); plot(x1, d); subplot(222) ; title (' signal + noise '); plot(x1, x); subplot(224) title (' filtered signal '); plot(x1, dest); subplot(223) title (' noise '); plot(x1, v);
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clc T1=350 Te1=450 Te2=250 P1=250 P2=100 R=8.314 Cp=(7*R)/2 me1=(Cp*log(Te1/T1))-(R*log(P2/P1)) me2=(Cp*log(Te2/T1))-(R*log(P2/P1)) mprintf("me1(se1-si)+me2(se2-si)=%fkJ/K",me1+me2)//ans vary due to roundoff error
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 8") disp("Cavitation in Hydraulic Machinery") disp("Just Theory No Solved/Unsolved Examples")
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R1=2; //Assigning values to parameters R2=10; R3=2; R4=5; R5=1; R6=4; I1=28; I2=2; A=[11,-5,-1;5,-17,10;1,10,-13.5]; //Applying KCL at the two nodes B=[280;0;20]; V=inv(A)*B; I1=V(1,1)/R1; I2=(V(1,1)-V(2,1))/R3; I3=(V(1,1)-V(3,1))/R2; I4=(V(2,1)-V(3,1))/R5; I5=V(2,1)/R4; I6=V(3,1)/R6; disp("Amperes",I1,"Current I1") disp("Amperes",I2,"Current I2") disp("Amperes",I3,"Current I3") disp("Amperes",I4,"Current I4") disp("Amperes",I5,"Current I5") disp("Amperes",I6,"Current I6")
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//Electric Drives:concepts and applications by V.subrahmanyam //Publisher:Tata McGraw-Hill //Edition:Second //Ex1_4a clc; clear; V=440;// voltage in V Ia=80;// Current in A Na=1200;//Speed in rpm Na1=125.6;// Speed in rad/sec R1=0.55;// Resistance in ohm R2=110;// Resistance in ohm N0=600;// Speed in rpm N01=62.8;//Speed in rpm Nf=300;// Speed in rpm Nf1=31.4;// Speed in rpm Rsh=1.256;// Resistance in ohm E=V-(Ia*R1); K=E/Na1; E1=K*N01; Tf=K*Ia; E2=E1*(Nf/N0); V2=E2+(Ia*R1); Is=(V2/Rsh)+Ia; Il=Is+(V/R2); Pi=V*Il; Po=Tf*Nf1; Eff=(Po/Pi)*100; disp(Eff,'the effeciency of the motor in % is:')
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// Scilab Code Ex6.3 : Page-6.10 (2004) clc;clear; t = 3e-14; // Mean free time, sec m = 9.1e-31; // Mass of electron, kg e = 1.6e-19; // Charge of electron, C r = 1.85e-10; // Radius of sodium atom, m a = 4*r/sqrt(3); // Sodium has BCC structure n = 2/(a^3); // Number of electron per unit volume rho = m/(n*(e^2)*t); // Electrical resistivity, ohm m printf("\nElectrical resistivity = %3.3e ohm m", rho); // Result // Electrical resistivity = 4.620e-08 ohm m
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//Calculation of Current and power dissipated in resistors connected in series. clc; clear; R1=100; R2=200; R3=300; Rt=R1+R2+R3; V=250; //Ohm's Law V=I*R I=V/Rt; // Power Loss Equation P=(I^2)*R P1=(I^2)*R1; P2=(I^2)*R2; P3=(I^2)*R3; Pt=P1+P2+P3; P=V*I; disp('ohms',Rt,'The total resistance in the circuit =') disp('amperes',I,'The Current in the circuit =') disp('watts',P1,'The power loss in the 100 ohms resistor =') disp('watts',P2,'The power loss in the 200 ohms resistor =') disp('watts',P3,'The power loss in the 300 ohms resistor =') disp('watts',Pt,'The total power loss in the circuit =') disp('watts',P,'The power loss in the circuit (using P=V*I ) =')
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<?xml version="1.0" encoding="utf-8"?> <test> <description>desc P=400</description> <executable>AcousticSolver</executable> <parameters>APE_2DPulseWall_WeakDG_MODIFIED.xml</parameters> <files> <file description="Session File">APE_2DPulseWall_WeakDG_MODIFIED.xml</file> </files> <metrics> <metric type="L2" id="1"> <value variable="p" tolerance="1e-4">6.7577</value> <value variable="u" tolerance="1e-7">0.014607</value> <value variable="v" tolerance="1e-7">0.00571716</value> </metric> <metric type="Linf" id="2"> <value variable="p" tolerance="1e-4">13.659</value> <value variable="u" tolerance="1e-7">0.0280936</value> <value variable="v" tolerance="1e-7">0.0108992</value> </metric> </metrics> </test>
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clc; clear all; A = 2e-4; // Area of steel wire in meter square Y = 2e11 // Young's modulus in Newton per meter square F = A*Y //l = L in this problem hence eliminating and rearranging equation of Y disp('N',F,'The value of force is')
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//Ex9_3 clc; //Given: f=1.0014;// seperation factor s=4;// series p=6;// parallel // Note: The global yield for s stages in series is(f)^s and each parallel stages simply multiplies the yield of the stage, Hence overall yield with p parallel stages (each with s stages in series) will be Y=p*(f)^s //Solution: Y=p*(f)^s; printf("The net yield is = %f",Y)
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// Initialisations ... s = poly(0,'s'); s = syslin('c',s*s/s); // approx(G,ll) returns approximation of G by elts in ll deff('res=approx(G,ll)',... ['res=0'; 'n=length(ll)'; 'for k=1:n,res=res+ll(k);end'; 'res=res+horner(clean(G-res),0)']) // W3dg1(p) returns p(0) (p degree one) deff('res=w3dg1(p)','res=horner(p,0)+0*poly(0,''s'')'); // W3dg2(p) returns p1 with damping(p1) = k damping(p) deff('p1=w3dg2(p,k)',... ['damp=coeff(p,1)'; 'p1=poly([coeff(p,0),k*damp,coeff(p,2)],''s'',''coeff'')';]) Gr=(s+1)*(s-1)*(s+2)*(s^2+0.3*s+1)/((s+0.5)*(s^2*(s^2-0.1*s+2)*(s^2+0.1*s+1))); G=Gr/s; r=size(G); fmin=0.01;fmax=10; frq=calfrq(G,fmin,fmax); W=pfss(G,'c'); W(1)=clean(w(1)); appr=[];yesno=[]; for k=1:size(w); appr=[appr;'G'+string(k-1);];yesno=[yesno;'yes']; end yesno=x_mdialog("Choose elements",appr,yesno) appr=' '; for k=1:size(w)-1; if yesno(k)=='yes' then appr=appr+'W('+string(k)+'),';end end k=size(w); if yesno(k)=='yes' then appr=appr+'W('+string(k)+')';end execstr('bode([G;approx(G,list('+appr+'))],frq)') [lnum,dcgain]=factors(G,'c'); nb=length(lnum); denominators=[]; numerators=[]; for k=1:nb, lnumk=lnum(k); denominators=[denominators;pol2str(lnumk)]; if degree(lnumk)==1 then numerators=[numerators;pol2str(w3dg1(lnumk))];end if degree(lnumk)==2 then numerators=[numerators;pol2str(w3dg2(lnumk,2))];end end Numerators=x_mdialog('Denominators Numerators',Denominators,Numerators); // J(s) Js=1; for k=1:nb, Js=Js*evstr(numerators(k))/evstr(denominators(k)); end sp=poly(0,'s'); Ms=sp+1;Ns=(sp+1); mnns=x_mdialog("Choose Ms and Ns",[pol2str(Ms);'1/'+pol2str(sp+1)],... [pol2str(Ms);'1/'+pol2str(sp+1)]); Ms=evstr(Mnns(1)); Ns=evstr(Mnns(2)); Sys1=sysdiag(1,1,1,1,Ms);Sys2=sysdiag(1,Ns); W5is=[]; for k=1:nb W5is=[W5is;'W5'+string(k)]; end w5=x_mdialog('Choose W5i s',W5is,string(ones(nb,1))); ww5=[]; for k=1:nb;ww5(k)=evstr(w5(k));end Rg=[diag(ww5');ones(ww5')]*[W(1)+W(2);W(2);W(3);W(4)]; U=[0,-1;1,-1]; amin = 0; amax = 2; while (amax -amin)/amax > 1e-2, a = (amin + amax)/2; write(%io(2),a,'(f6.4)') w3=(1/2)*horner((1+s^3),s/a)*w3coeff; P=sysdiag(tf2ss(w3),Rg)*U; Ptmp=Sys1*P*Sys2; [sk,mu]=H_inf(Ptmp,r,0.8,1.2,1); if mu == [] then amin = a; else amax = a; end end w3=(1/ab)*horner((1+s^3),s/amin)*w3coeff; P=sysdiag(tf2ss(w3),Rg)*U; //xbasc(); xset("window",1);gainplot([w3;errmul],.1,1,0.005); Ptmp=Sys1*P*Sys2; [Ktmp,mu]=H_inf(Ptmp,r,0.9,1.1,30); K=ss2tf(Ktmp)/s; ks=trfmod(K); olp=ks*proc; rep2 = repfreq(ks,frq); xbasc(2); xset("window",2);xselect();nyquist(olp,0.03,0.8,0.00015); m_circle(20*log(2.05)/log(10));xset("dashes",0); sensit = rep1 ./(rep3 + rep1.*rep2); xbasc(3); xset("window",3);xselect();gainplot(frq,[sensit;rep1;rep2],['G/(1+KG)';'G';'K']); www=lft(Ptmp,Ktmp); xbasc(5);xset("window",5);xselect(); gainplot(www,0.01,10); www1=lft(ss2tf(P),r,ks); xbasc(6);xset("window",6);xselect(); gainplot(www1,0.01,10,['W3G/(1+KG)';'W50G0/(1+KG)';'W51G1/(1+KG)';'W52G2/(1+KG)']);
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load HackComputer.hdl, output-file LoopStatement.out, compare-to LoopStatement.cmp, output-list RAM64[16]%D1.10.1 RAM64[18]%D1.10.1 RAM64[19]%D1.10.1 RAM64[20]%D1.10.1; ROM32K load LoopStatement.hack, // start = 1, inc = 1, end = 100 set RAM64[16] 1, set RAM64[18] 1, set RAM64[19] 100, // No.of clock cycles must be more than the number of executed instructions in the program repeat 2450 { tick, tock, } output; set reset 1, tick, tock, set reset 0, // start = 1, inc = 2, end = 100 set RAM64[16] 1, set RAM64[18] 2, set RAM64[19] 100, repeat 1300 { tick, tock, } output; set reset 1, tick, tock, set reset 0, // start = 50, inc = 1, end = 100 set RAM64[16] 50, set RAM64[18] 1, set RAM64[19] 100, repeat 1250 { tick, tock, } output; set reset 1, tick, tock, set reset 0, // start = -100, inc = 10, end = 500 set RAM64[16] -100, set RAM64[18] 10, set RAM64[19] 500, repeat 2700 { tick, tock, } output;
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function [ImgO] = OuvertureC(Img) exec('.\DilatationC.sce',-1) exec('.\OuvertureC.sce',-1) ImgO=DilatationC(ErosionC(Img)) endfunction
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 9, Example 5") //A nickel wire of length(L)=0.1m,Diameter(D)=1mm or .001m //Submerged horizontally in water at pressure=1 atm(101kPa) requires current,I=150A at voltage ,E=2.2V to maintain wire at temprature(T1)=110°C L=0.1; T1=110; D=0.001; I=150; E=2.2; //Area(A)=[%pi*D*L] A=%pi*D*L; //The saturation temprature of water at one atmospheric pressure(101kPa) is T2=100°C. T2=100; //We can write from energy balance E*I=h*A*(T1-T2),we can find heat transfer coefficient from it. //h is heat transfer coefficient disp("Heat transfer coefficient in W/m^2 is") h=(E*I)/(A*(T1-T2))
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/////Chapter 10 Properties Of Steam ////Example 10.1 Page No:183 ///Find Dryness fuction of steam ///Input data clc; clear; mw=15; //Water steam ms=185; //Dry steam ///Calculation x=((ms)/(ms+mw))*100; //Dryness fuction of steam in % ///Output printf('Dryness fuction of steam= %f percent \n',x);
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// Exa 2.11 clc; clear; close; format('v',4) // Given data R1 = 4;// in ohm R2 = 3;// in ohm R3 = 2;// in ohm R_L = 5;// in ohm I = 6;// in A V = 15;// in V // V-R1*I1-R3*(I1+I) = 0; I1 = (V-R3*I)/(R1+R3);// in A I = I1 + I;// in A Vth = R3*I;// in V Rth = ((R1*R3)/(R1+R3)) + R2;// in ohm // current in 5 ohm resistance I_L = Vth/(Rth+R_L);// in A disp(I_L,"The current in 5 ohm resistance in A is");
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//o/p when char type is given as i/p a = 'hash'; efinal = 0.2; // Step prediction error r = poly2ac(a,efinal); // Autocorrelation sequence disp(r); //Output //!--error 10000 //Input arguments must be numeric. //at line 31 of function rlevinson called by : //at line 41 of function poly2ac called by : //r = poly2ac(a,efinal); //
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// Example 5.4 // Computation of (a) Amount of torque that must be removed from the motor // shaft to maintain 1760r/min (b) Expected minimum startimg torque for the // lower voltage (c) Percent change in developed torque caused by 10% drop in // system voltage. // Page No. 185 clc; clear; close; // Given data hp=50; // Horsepower n=1760; // Rated speed of machine v1=460; // (a) Amount of torque that must be removed from the motor shaft to maintain // 1760r/min v2=v1*0.90; Trated=hp*5252/n; //Rated torque TD2=Trated*(v2/v1)^2; Treduction=Trated-TD2; // (b) Expected minimum startimg torque for the lower voltage Tlr=1.40*Trated; Tlr2=Tlr*(v2/v1)^2; // (c) Percent change in developed torque caused by 10% drop in system voltage Tchange=(TD2-Trated)/Trated; Tchanger=(Tlr2-Tlr)/Tlr; // Display result on command window printf("\n Amount of torque that must be removed from the motor shaft = %0.1f lb-ft",Treduction); printf("\n Expected minimum starting torque for the lower voltage = %0.1f lb-ft ",Tlr2); printf("\n Percent change in developed torque = %0.0f Percent ",Tchanger*100);
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//Example 6.3 //Calculate the rate of boiling. //Given A=12.5673 B=4234.6 pv=1.813 T1=200 //C, tube wall temp. //For methanol Tc=512.6 //K, critical temp. w=0.556 //acentric factor Zra=0.29056-0.08775*w R=0.08314 //m^3bar/gmol K, universal gas constant Pc=80.9 //bar, critical temp. Mw=32 //g, molecular wt //Calculation //Estimation of liquid and vapour properties //from antoine eq. T=B/(A-log(pv)) //K, boiling point Te=(T1+273)-T //K, excess temp. Tm=((T1+273)+T)/2 //K, mean temp. //Liquid properties //(a) Tr=T/Tc //K, reduced temp. //from Rackett technique Vm=R*Tc*(Zra)^(1+(1-Tr)^(2/7))/Pc //m^3/kg mol, molar volume rhol=Mw/Vm //kg/m^3, density of satorated liquid density //(b) //from Missenard technique T2=348 //K,given data temp. T3=373 //K,given data temp. Cp2=107.5 //j/g mol K specific heat at T2 Cp3=119.4 //j/g mol K specific heat at T3 //By linear interpolation at T=353.7 K Cp=Cp2+(Cp3-Cp2)*((T-T2)/(T3-T2)) //kj/kg mol C, specific heat at T=353.7 K Cp_=Cp*0.03125 //kj/kg C //(c)Surface tension at given temp.(K) T4=313 St4=20.96 T5=333 St5=19.4 //By linear interpolation at T=353.7 K S=17.8 //dyne/cm, surface temp. //(d) liquid viscosity T6=298 MUt6=0.55 //cP, liquid viscosity at temp=298 MU=((MUt6)^-0.2661+((T-T6)/233))^(-1/0.2661) //cP //(e)Prandtl no. a,b,c are constant a=0.3225 b=-4.785*10^-4 c=1.168*10^-7 kl=a+b*T+c*T^2 //W/m C, thermal conductivity Prl=Cp_*1000*MU*10^-3/kl //Prandtl no. //(f)heat of vaporization at 337.5 K Lv=1100 //kj/kg, enthalpy of vaporization //Properties of methanol vapour at Tm //(a) Vm1=R*Tm/pv //m^3/kg mol, molar volume rhov=Mw/Vm1 //kg/m^3, density of vapour //(b) a1,b1,c1,d1 are costants a1=-7.797*10^-3 b1=4.167*10^-5 c1=1.214*10^-7 d1=-5.184*10^-11 //thermal conductivity of vapour kv=a1+b1*Tm+c1*Tm^2+d1*Tm^3 //W/m C //(c)heat capacity of vapour, a2,b2,c2,d2 are costants a2=21.15 b2=7.092*10^-2 c2=2.589*10^-5 d2=-2.852*10^-8 //heat capacity of vapour, in kj/kh mol K Cpv=a2+b2*Tm+c2*Tm^2+d2*Tm^3 //(d)viscosity of vapour T7=67 MUt7=112 T8=127 MUt8=132 //from linear inter polation at Tm MUv=1.364*10^-5 //kg/m s //from Rohsenow's eq. Csf=0.027 //constant n=1.7 //exponent value //from eq. 6.6 g=9.8 //m/s^2, gravitational constant //heat flux //kW/m^2 Q=MU*10^-3*Lv*(g*(rhol-rhov)/S*10^-3)^(1/2)*(Cp_*Te/(Csf*Lv*(Prl)^n))^3 //from eq. 6.11 //from eq 6.11, critical heat flux Qmax=0.131*Lv*(rhov)^(1/2)*(S*10^-3*g*(rhol-rhov))^(1/4) //dimensionless radius r_ r=0.016 r_=r*(g*(rhol-rhov)/(S*10^-3))^(1/2) //peak heat flux Qmax1=Qmax*(0.89+2.27*exp(-3.44*sqrt(r_))) //from eq. 6.12 //heat transfer coefficient hb d=0.032 //m, tube diameter hb=0.62*((kv^3)*rhov*(rhol-rhov)*g*(Lv*10^3+0.4*Cpv*Te)/(d*MUv*Te))^(1/4) Qb=hb*Te //kw/m^2, heat flux BR=Qb*10^-3/Lv //kg/m^2s, boilng rate printf("The boilins rate is %f kg/m^2 h",BR*3600)
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function [x,y,typ]=EXPBLK_f(job,arg1,arg2) // Copyright INRIA x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; graphics=arg1(2);label=graphics(4) model=arg1(3); if size(label,'*')==2 then label=label(2),end while %t do [ok,a,label]=getvalue('Set a^u block parameters',.. 'a (>0)',list('vec',1),label) if ~ok then break,end if or(a<=0) then message('a^u : a must be positive') else graphics(4)=label model(8)=a; x(2)=graphics;x(3)=model break end end x(3)(11)=[] //compatibility case 'define' then in=1 a=%e model=list('expblk',-1,-1,[],[],[],[],%e,[],'c',[],[%t %f],' ',list()) label=[string(in);'%e'] gr_i=['xstringb(orig(1),orig(2),''a^u'',sz(1),sz(2),''fill'');'] x=standard_define([2 2],model,label,gr_i) end
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//Problem 5.09: //initializing the variables: nCO2 = 7.5 nCO = 1.3 nO2 = 8.1 nN2 = 83.1 //calculation: //Determine the amount of oxygen fed for combustion. Since nitrogen does not react (key component), using the ratio of oxygen to nitrogen in air will provide the amount of oxygen fed: O2f = (21/79)*83.1 //A balanced equation for the combustion of the hydrocarbon in terms of N moles of the hydrocarbon and n hydrogen atoms in the hydrocarbon yields //NC3Hn + 22.1O2 ---> 7.5CO2 + 1.3CO + 8.1O2 + N(n/2)H2O //The moles of hydrocarbon, N, is obtained by performing an elemental carbon balance: //3N = 7.5 + 1.3 N = 8.8/3 //Similarly, the moles of water formed is obtained by performing an elemental oxygen balance: //2(22.1) = 2(7.5) + 1.3 + 2(8.1) + N(n/2) //A = N(n/2) A = 44.2 - 15 - 1.3 - 16.2 //The number of hydrogen atoms, n, in the hydrocarbon is then n = 2*A/N //Since n = 8, the hydrocarbon is C3H8, propane. printf("\n\nResult\n\n") printf("\n n= %.0f\n",n) printf("\n the hydrocarbon is C3H8, propane")
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function A = simpson2(a,b,n,y) // Description of name(input) h = (b-a)/n x = a:h:b y = f(x) A = y(1) for i = 2:n if modulo(i,3) == 1 A = A + 2*y(1) else A = A + 3*y(i) end end A = (3*h/8)*(A + y(n+1)) endfunction function y = f(x) // Description of name(input) y = sin(x); endfunction
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V = 3 // m^3 function f = soal_04(v) // Constants Ru = 0.518 // kJ/(kg K) // methane Pc = 4600 // kPa Tc = 191 // Kelvin // a = 0.427 * Ru^2 * Tc^2.5 / Pc b = 0.0866 * Ru * Tc / Pc T = -40 + 273 // K P = 65000 // kPa // denum1 = v - b denum2 = v*(v + b)*sqrt(T) f = Ru*T*denum2 - a*denum1 - P*denum1*denum2 endfunction function P = eval_P(v) // Constants Ru = 0.518 // kJ/(kg K) // methane Pc = 4600 // kPa Tc = 191 // Kelvin // a = 0.427 * Ru^2 * Tc^2.5 / Pc b = 0.0866 * Ru * Tc / Pc T = -40 + 273 // K P = 65000 // kPa // denum1 = v - b denum2 = v*(v + b)*sqrt(T) P = Ru*T/denum1 - a/denum2 endfunction function do_plot() v1 = 0.001 v2 = 0.005 Npoints = 100 v = linspace(v1, v2, Npoints) f = zeros(1,Npoints) for i = 1:Npoints f(i) = soal_04(v(i)) printf("%18.10f %18.10f\n", v(i), f(i)) end clf() plot(v, f) xgrid() xs2pdf( gcf(), "soal_04.pdf" ) endfunction // do_plot() exec("bisection.sce", -1) root = bisection( soal_04, 0.0025, 0.0030 ) printf("At root = %18.10f\n", eval_P(root)) exec("regula_falsi.sce", -1) root = regula_falsi( soal_04, 0.0025, 0.0030 ) printf("At root = %18.10f\n", eval_P(root)) exec("ridder.sce", -1) root = ridder( soal_04, 0.0025, 0.0030 ) printf("At root = %18.10f\n", eval_P(root)) if getscilabmode() ~= "STD" quit() end
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//Example 1.18 //Program to Compute Cross-correlation of given sequences //x(n)=[1 2 1 1], h(n)=[1 1 2 1]; clear; clc ; close ; x=[1 2 1 1]; h=[1 1 2 1]; h1=[1 2 1 1]; y=convol(x,h1); disp(round(y));
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clear; //clc(); d=3; r=0.01; cn=2*(%pi)*8.85*10^(-12)/log([d/r])*1000000000000; printf("\n the capacitance is: %.2f F/km\n ",cn); cl=0.5*cn; printf("\n the line to line capacitance is: %.2f*10^(-9)F/km\n ",cl); bc=2*(%pi)*50*cn; printf("\n the capacitance susceptance is: %.2f*10^(-6) S/km\n ",bc/1000);
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// Prob 1.1 clc; clear; close; format('v',5); // Given data s=36;//no. of slots p=4;//no. of poles ph=3;//no. of phase s1=s/ph;//no. of slots pe phase m=s1/p;//no. of slots per pole per phase alfa=180*p/s;//slot angle in degree Kd=sind(m*alfa/2)/(m*sind(alfa/2));//distribution factor disp(Kd,"Distribution factor for 36 slots : ");
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function [screw] = screw_new(res, mom) screw = [ res; mom ]; endfunction
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// Scilab code Exa6.15: : Page-246 (2011) clc; clear; S = string(rand(2,1)) S(1,1) = 'antiparallel spin' S(2,1) = 'parallel spin' for i = 1:2 if S(i,1) == 'antiparallel spin' then printf("\nFor Fermi types :") printf("\n\n The selection rules for allowed transitions are : \n\tdelta I is zero \n\tdelta pi is plus \nThe emited neutrino and electron have %s",S(i,1)) elseif S(i,1) == 'parallel spin' then printf("\nFor Gamow-Teller types :") printf("\nThe selection rules for allowed transitions are : \n\tdelta I is zero,plus one and minus one\n\tdelta pi is plus\nThe emited neutrino and electron have %s",S(i,1)) end end // Calculation of ratio of transition probability M_F = 1; // Matrix for Fermi particles g_F = 1; // Coupling constant of fermi particles M_GT = 5/3; // Matrix for Gamow Teller g_GT = 1.24; // Coupling constant of Gamow Teller T_prob = g_F^2*M_F/(g_GT^2*M_GT); // Ratio of transition probability // Calculation of Space phase factor e = 1.6e-19; // Charge of an electron, coulomb c = 3e+08; // Velocity of light, metre per sec K = 8.99e+9; // Coulomb constant R_0 = 1.2e-15; // Distance of closest approach, metre A = 57; // Mass number Z = 28; // Atomic number m_n = 1.6749e-27; // Mass of neutron, Kg m_p = 1.6726e-27; // Mass of proton, Kg m_e = 9.1e-31; // Mass of electron. Kg E_1 = 0.76; // First excited state of nickel delta_E = ((3*e^2*K/(5*R_0*A^(1/3))*((Z+1)^2-Z^2))-(m_n-m_p)*c^2)/1.6e-13; // Mass difference, mega electron volts E_0 = delta_E-(2*m_e*c^2)/1.6e-13; // End point energy, mega electron volts P_factor = (E_0-E_1)^5/E_0^5; // Space phase factor printf("\nThe ratio of transition probability = %4.2f\nThe space phase factor = %4.2f", T_prob, P_factor); // Result // The emited neutrino and electron have antiparallel spin // For Gamow-Teller types : // The selection rules for allowed transitions are : // delta I is zero,plus one and minus one // delta pi is plus // The emited neutrino and electron have parallel spin // The ratio of transition probability = 0.39 // The space phase factor = 0.62
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clc; clear all; disp("heat loss per length") r1=10*10^(-3);//m r2=20*10^(-3);//m r3=(20+30)*10^(-3);//m t1=600;// degree C t3=1000;// degree C kB=0.2;// W/(m*C) Ql=2*3.1416*(t1-t3)/((log (r3/r2))/kB); disp("W/m",Ql,"heat transfer per unit length = ")
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/tables/superdarn/hdw/hdw.dat.tst
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hdw.dat.tst
# SD_BEGIN> # This file defines all the hardware parameters for all the radars # the format of the file is: # station_id, year, yr_sec, lat, long, altitude, boresite, bm_sep, # vdir, atten, tdiff, phidiff, interfer_pos[3], rec_rise # # This set of data is for Goose Bay # 0 2999 31556736 +53.32 -60.46 50.0 +5.00 +3.24 +1.0 10.0 +0.4778 +1.0 +1.5 +100.0 +0.0 100.0 2 75 16