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example2_14.sce
clear; clc; // Stoichiometry // Chapter 2 // Basic Chemical Calculations // Example 2.14 // Page 24 printf("Example 2.14, Page 24 \n \n"); // solution m = 100 //[kg] Lye (basis) m1 = 73 //[kg] NaOH M1 = 40 // NaOH M2 = 62 // Na2O p = (M2*m1)/(2*M1) printf("percentage of Na2O in the solution is "...
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//Calculations on four stroke petrol engine clc,clear //Given: bp=35 //Brake power in kW eta_m=80 //Mechanical efficiency in percent bsfc=0.4 //Brake specific fuel consumption in kg/kWh A_F=14/1 //Air-fuel ratio CV=43000 //Calorific value in kJ/kg //Solution: //(a) ip=bp*100/eta_m //Indicated power in kW //(...
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// Exo 4: plotting and projecting confidence regions // Gen data et gen modèle // Our model is m2 (with 3 parameters), our Cm is inv(G2'*G2) exec('/Users/sebh/Desktop/MasterII/repos_master2/ProbInverses/TP1/01genTestDistribs.sce',-1); exec('/Users/sebh/Desktop/MasterII/repos_master2/ProbInverses/TP1/02leastsquares.sce...
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clear //Given e=1.6*10**-19 f=6.8*10**15 r=0.51*10**-10 u=4*3.14*10**-7 //T/A m //Calculation // I=e*f B=(u*I)/(2*r) M=1*I*%pi*r**2 //Result printf("\n The effective dipole moment is %0.0f *10**-24 Am**2",M*10**24)
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//Exa 2.11 clc; clear; close; //Given data IES=10^-14;//in A alfaF=1;//unitless alfaR=0.1;//unitless //Formula : alfaF*IES=alfaR*ICS ICS=(alfaF/alfaR)*IES;//in Ampere disp(ICS,"Collector base junction saturation current in Ampere : "); RelativeSize=ICS/IES;//unitless disp("Collector is "+string(RelativeSize...
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// Given:- Wnetdot = 45.00 // in MW T1 = 300.00 // in kelvin p1 = 100.00 // in kpa etac = 0.84 ...
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clear clc clf(1); clf(2); clf(3); clf(4) format('v', 10) csvDefault("eol", "windows") csvDefault("blank", "on") [ok, sPartNumber] = getvalue("Input Part Number", "PN", list("str", 1), ["16010-4002-001"]); if ~ok then abort end [ok, sSerialNumber] = getvalue("Input Serial Number", "SN", list("str", 1), ["default"]...
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//(13.6) A mixture of 1 kmol of gaseous methane and 2 kmol of oxygen initially at 25C and 1 atm burns completely in a closed, rigid container. Heat transfer occurs until the products are cooled to 900 K. If the reactants and products each form ideal gas mixtures, determine (a) the amount of heat transfer, in kJ, and...
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//Problem 22.05: A 3-phase, 60 Hz induction motor has 2 poles. If the slip is 2% at a certain load, determine (a) the synchronous speed, (b) the speed of the rotor and (c) the frequency of the induced e.m.f.’s in the rotor. //initializing the variables: p = 2/2; // number of pairs of poles f = 60; // in Hz s = 0....
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//All the quantities are expressed in SI units alpha1 = 4; alpha2 = -1.1; alpha3 = -4; cl_1 = 0.55; //cl at alpha1 cl_2 = 0; //cl at alpha2 c_m_qc1 = -0.005; //c_m_qc at alpha1 c_m_qc3 = -0.0125; //c_m_qc at alpha3 //the lift slope is given by a0 = (cl_1 ...
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function [x,y,typ]=MFCLCK_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) graphics=arg1(2); [orig,sz]=graphics(1:2) xstringb(orig(1),orig(2),['M. freq';'clock'],sz(1),sz(2),'fill') case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standar...
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// Ex 24 Page 366 clc;clear;close; // Given b=3;//cm a=4.5;//cm f=9*10**9;//Hz v=3*10**10;//cm/s lamda=v/f;//cm printf("\n For TE10 mode:") m=1;// for TE10 mode lamda_c = 2*a/m;//cm rho=sqrt(1-(lamda/lamda_c)**2) lamda_g=lamda/rho;//cm vg=rho*v;//cm/s vp=v/rho;//cm/s ZTE=120*%pi/rho;//ohm printf("\n cutoff wavelengt...
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// calculation of hysterisis and eddy current losses clc; P1=1500; f1=50; P2=3000; f2=75; A=[1 50;1 75]; //P/f=A+B*f B=[30;40]; v=A\B; disp('at 50Hz'); P_h=v(1)*f1;disp(P_h,'hysterisis loss(W)'); P_e=v(2)*f1^2;disp(P_e,'eddy current loss(W)'); disp('at 75Hz'); P_h=v(1)*f2;disp(P_h,'hysteri...
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funcprot(0) function [polar] = rect2polar(x,y) //Function to convert rectangular coordinates to polar coordinates polar=ones(1,2) polar(1)=sqrt((x^2)+(y^2)) polar(2)=atan(y/x) polar(2)=(polar(2)*180)/%pi endfunction clc Po=200*10^3 //Output Power f=50 //frequency in hertz Vl=440 n=91 //effic...
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clc clear //INPUT DATA x=6.40*10^7//electrical conductivity in mho m^-1 t=300//temperature of copper in k L=2.44*10^-8//Lorentz number in W ohm K^-2 //CALCULATION K=x*t*L//thermal conductivity of copper in W m^-1 K^-1 //OUTPUT printf('The thermal conductivity of copper is %3.2f W.m^-1.K^-1',K)
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Chapter14_example7.sce
clc clear //Input data M=2300//Magnetization in A/m B=0.00314//Flux density in Wb/m^2 uo=(4*3.14)*10^-7//Permeability of free space in H/m //Calculations H=(B/uo)-M//Magnetizing force in A/m ur=(M/H)+1//Relative permeability //Output printf('The magnetizing force is %3.0f A/m \n The relative permeability ...
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clc //initialisation of variables g= 32.2 //ft/sec^2 d= 12 //in h= 0.1 //m w= 240 //r.p.m W= 62.4 //lbft/sec^2 //CALCULATIONS P= (%pi*(d/24)^4*W*(2*%pi*4)^2)/(4*g) Pt= P+%pi*(d/24)^2*W*(h/12) //RESULTS printf (' Total pressure on bottom of cylinder = %.3f Lb ',Pt)
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//Chapter-2,Example2_3,pg 2_12 n=4 Vofs=15 Res=Vofs/((2^n)-1) D=bin2dec('0110')//decimal equivalent Vo=Res*D printf("output voltage\n") printf("Vo=%.2f V",Vo)
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clc clear //Input data C=83.7;//The amount of carbon present in the fuel oil according to ultimate analysis of a fuel oil in % H=12.7;//The amount of hydrogen present in the fuel oil according to ultimate analysis of a fuel oil in % O=1.2;//The amount of oxygen present in the fuel oil according to ultimate analys...
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//Page Number: 4.17 //Example 4.15 clc; //Given //x(t)=10cos(wct+3sinwmt) //Comparing with standard equation B=3; fm=1D+3; //hz fb=2*(B+1)*fm; //(a)fm is doubled fma=2*fm; fba=2*(B+1)*fma; disp(fba,"fb with 2fm: "); //(b)fm is one halved fmb=fm/2; fbb=2*(B+1)*fmb; disp(fbb,"fb with 0.5fm: "); ...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 4 : DIRECT CURRENT MACHINES // EXAMPLE : 4.16 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA Out_hp = 20; // Output of the Motor in HP eta...
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clc; x = [1 2 3 4 5 6 7 8 9 10 ]; y = [5 0 5 0 5 0 5 0 5 0 ]; plot2d2(x,y) xlabel('VALUES OF x'); ylabel('VALUES OF y'); title('SQUARE WAVE FUNCTION');
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// Exa 7.4 clc; clear; // Given data n=2; // Second order Butterworth filter fH=1000; // Lower cut off frequency(Hz) // Solution printf('Let C = 0.1 μF. \n'); C=0.1*10^-6; // Farads // Since fH = 1/(2 * %pi * R*C); // Therefore; R = 1/(2*%pi*fH*C); printf(' The calculated value of R = %.1...
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clear() clc disp('Example 1 : Display the current working shell ') disp('***************************************************************************') disp('Answer : ') printf('The current Working Shell is ') if (getos()=='Linux') then unix_w("echo $SHELL") el...
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a=4;//major axis,in mm b=3;//minor axis of bar,in mm T=100000;//applied torque,in N.mm G=76923;//shear modulus,in N/mm^2
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//Example 5_4 clc(); clear; //To calculate the inter planar distance a=0.82 //units in nm b=0.94 //units in nm c=0.75 //units in nm h=1 k=2 l=3 d=1/sqrt((((h/a)^2)+((k/b)^2)+((l/c)^2))) //units in nm printf("The Distance between (1,2,3) planes and (2,4,6) planes is d123=%.2fnm and d24...
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errcatch(-1,"stop");mode(2);//Example 3.16 : volume ; ; format('v',7) //given data : a=0.2665; // in mm c=0.4947;// in mm V=(3*sqrt(3)*a^2*c)/2; disp(V,"volume,V(mm^3) = ") exit();
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// Scilab code Ex3.2: Pg.125 (2008) clc; clear; T = 5800; // Temperature of sun, K b = 2.898e-003; // Wein's constant, m-K lamda_m = b/T; // Peak wavelength of solar spectrum, m printf("\nPeak wavelength of solar spectrum = %5.1f nm", lamda_m/1e-009); // Result // Peak wavelength of solar spectrum = 499....
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<?xml version="1.0" encoding="utf-8"?> <test> <description>3D homogeneous 1D Channel Flow, SEM parallelisation (2 proc)</description> <executable>IncNavierStokesSolver</executable> <parameters>ChanFlow_3DH1D_Parallel_mode1.xml</parameters> <processes>2</processes> <files> <file description="...
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//Example 2-8, Page No- 38 clear clc gain_dB = 40 pout_W= 100 pin_W = pout_W/10^4 printf('The input power is %.2f watt',pin_W);
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 2, Example 8") //D2 is siameter in meter, N is rpm, Cr2 in m/s and Cw2=U2 in m/s , V velocity of flow in m/s D2 = 0.6; N = 550; Cr2 =...
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a^4*m11^2 - 2*a^2*b^2*m11^2 + b^4*m11^2 + 4*a^3*b*m11*m12 - 4*a*b^3*m11*m12 + 4*a^2*b^2*m12^2 + 2*a^4*m11*m13 - 2*b^4*m11*m13 + 4*a^3*b*m12*m13 + 4*a*b^3*m12*m13 + a^4*m13^2 + 2*a^2*b^2*m13^2 + b^4*m13^2 + a^4*m21^2 - 2*a^2*b^2*m21^2 + b^4*m21^2 + 4*a^3*b*m21*m22 - 4*a*b^3*m21*m22 + 4*a^2*b^2*m22^2 + 2*a^4*m21*m23 - 2*...
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// Exa 3.8 clc; clear; close; // Given data V_BE= 0.7;// in V V_CE= 3;// in V I_C= 1;// in mA I_C=I_C*10^-3;// in A bita= 100; I_B= I_C/bita;// in A // V_CE= V_BE+V_CB and V_CB= I_B*R_B R_B= (V_CE-V_BE)/I_B;// in Ω disp(R_B*10^-3,"The value of R_B in kΩ is : ")
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//Exa_2.10 // TO find ABS/BH(average busy season per busy hour) calling rates, design cell capacity for the switch and design Erlangs. clc; clear all; Rlines=15000;//Residential lines Blines=80000;//Business lines PWElines=5000;//PBX, WATS, and Foreign Exchange (FX) lines CR_R=2;//Call rates for Rlines CR_...
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clear // //variable declaration P1=20.0 P2=30.0 P3=20.0 theta3=60.0*%pi/180.0 //Taking horizontal direction towards left as x axis and the vertical downward direction as y axis. ////sum of vertical Fy & sum of horizontal forces Fx is zero //Assume direction of Fx is right //Assume direction of Fy is up Fx=20.0*cos...
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A = 0.5; Na = 10^17; p0 = Na; ni = 1.5*10^10; dp = 5*10^16; x = 10^-5; up = 500; Tp = 10^-10; kT = 0.0259; q0 = 1; q = 1.6*10^-19; Dp = kT*up/q0; Lp = sqrt(Dp*Tp); p = p0 + dp*exp(-x/Lp); E = kT*log(p/ni); E0 = 1.1/2 + E; Ip = q*A*Dp*dp*exp(-x/Lp)/Lp; Qp = q*A*dp*Lp; Qp0 = Qp*10^6; disp(E0,"steady st...
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clc // Given that P_in = 100 // power of input signal in mW P_out = 50 // power of output signal in mW // Sample Problem 12 on page no. 280 printf("\n # PROBLEM 12 # \n") alpha = (10 * log10(P_in / P_out))//calculation for absorption coefficient printf("\n Standard formula used \n alpha=10/L*log(Pi/Po).\n") printf("\n...
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clc clear close deff('y2dot=f(ydot,y)','y2dot=-4*y-0.8*ydot'); y(1)=5e-3; ydot(1)=0; y2dot(1)=f(ydot(1),y(1)); dt=.05; t=0:dt:10; for i=2:length(t) ydot(i)=ydot(i-1)+dt*y2dot(i-1); y(i)=y(i-1)+dt*ydot(i-1); y2dot(i)=f(ydot(i),y(i)); end Y=[y ydot y2dot]; // [azul,verde,vermelho] X=[t' t' t']; plot(X,Y) ...
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clc clear //Initialization of variables dH=-2369859 //Btu r=1.986 //Gas constant dn=5.5 //Change in number of moles T=536.7 //R //calculations dQ=dH+dn*r*T //results printf("Higher heating value = %d Btu",dQ)
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syms R1 R2 R3 C1 C2 C3 L1 L2 s; T1=1/(R3*(R1+s*L1)*(R2+s*L2)*C1*C2*C3*s^3) L1=-1/(s*(R1+s*L1)*C1); L2=-1/(s*(R2+s*L2)*C1); L3=1/(-(s*L2+R2)*s*C2); L4=1/(-s*R3*C2) L5=-1/(s*R3*C3) delta=1-(L1+L2+L3+L4+L5)+(L1*L3 + L1*L4 + L1*L5 + L2*L4 + L2*L5 + L3*L5)-(L1*L3*L5) del1=1; TF=(T1*del1)/delta ; disp(TF,"V...
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clear; clc; printf("\t Example 5.11\n"); Q=14; //steady heat transfer,W D=0.06; //diameter of heat source,m l=0.3;; // length of source below surface ,m T=308; //temperature of heat source,K T1=294; //temperature of surface,K k=(Q/(T-T1))*(1-(D/2)/(D*10))/(4*3.14*D/2)+0.025; // thermal conductivity of s...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 13.11w //calculation of the velocity of the water coming out of the opening //given data AA=.5//area(in m^2) of the tank AB=1*10^-4//area(in m^2) of the cross section at the bottom m=20//mass(in kg) of the load h=5...
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// Scilab Code Ex2.7 Bond formation Energy for K+ and Cl- ion pair: Page-70 (2010) eps_0 = 8.854D-12; // Absolute electrical permittivity of free space, coulomb sqaure per newton per metre square e = 1.6D-19; // Electronic charge, C IP_K = 4.1; // Ionization potential of potassium, electron-volt EA_Cl = 3.6; // El...
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// Exa 3.12 clc; clear; close; // Given data N_A = 2*10^16;// in /cm^3 N_D = 10^16;// in /cm^3 C = N_A-N_D;// in /cm^3 disp(C,"Carrier concentration in holes/cm^3 is");
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//example no. 3.12 //solve system by decomposition method A=[1 1 -1;2 2 5;3 2 -3] b=[2;-3;6] // hence we can observe that LU decomposition method fails to solve this system since the pivot L(2,2)=0; //we note that the coefficient matrix is not a positive definite matrix an...
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clc; Vt=230;//Supply voltage P=4;//No of poles A=2;//No of parallel paths for armature conductors Z=500;//No of armature conductors Ra=0.2;//armature circuit resistance in ohm Rs=0.1;//field resistance in ohm Il=40;//line current N=1000;//rated speed in rpm Ia1=40;//armature current for dc series motor at 40 A...
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clc //initialisation of variables d= 1.6 //lb/ft^3 vk= 6.2*10^-6 //ft^2/sec R= 1.8 //lbf v= 100 //ft/sec d1= 64 //lb/ft^3 vk1= 1.7*10^-5 //ft62/sec l= 10 //ft //CALCULATIONS u= v*vk1/(vk*l) u1= v*vk1/(vk*l*1.98) r= d1*l^2*(u/100)^2/d F= r*R //RESULTS printf (' resistance= %.f lbf ',F)
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clf; c=3.986e+5; function[y]=f16(x,u) y(1)=u(2); y(2)=-c*u(1)/((u(1)^2+u(3)^2)^(3/2)); y(3)=u(4); y(4)=-c*u(3)/((u(1)^2+u(3)^2)^(3/2)); endfunction T=2*24*60*60; //Q1 teta=linspace(0,2*%pi,1001); r=6400; plot2d(r*cos(teta),r*sin(teta),2); y0=[6400+35786;0;0;3.07]; t=linspace(0,T,5001); y=ode(y0,0,t,f16...
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## Test the split command set echo set interactive set quiet read <mergeinfo.svn :6 split at 2 prefer git inspect
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//Example 2.2, page 49 clc h=6.63*10^-34//Joule-sec vo=5.6*10^14 w=h*vo printf("\npower is %e per sec",w) ev=(1/(1.6*10^-19)) wo=w*ev printf("\nEnergy is %f ev",wo)
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errcatch(-1,"stop");mode(2);//Caption:In a dc machine calculate speed at which the induced emf will be 250 Volts and also calculate the increase in main flux of field in percentage for induced emf of 250 Volts and speed 700 rpm //Exam:2.37 ; ; E_1=220;//Primary emf(in Volts) N_1=750;//Speed of the machine at 220...
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//chapter 5 //example 5.14 //page 443 clear; clc; disp("example 5.14"); disp("star connected alternator") printf("\n"); KVA=1500; //rating ph=3; //3-phase V_l=6600; //voltage Ra=0.4 //armature resistance Xs=6; //reactance Ia=(KVA*1000)/(sqrt(3)*V_l); printf("Full-l...
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dgn=figure('figure_position',[300,300],'figure_size',[300,300],'auto_resize','on','background',[27],'figure_name','Design Metrics'); delmenu(dgn.figure_id,gettext('File')) delmenu(dgn.figure_id,gettext('?')) delmenu(dgn.figure_id,gettext('Tools')) delmenu(dgn.figure_id,gettext('Edit')) toolbar(dgn.figure_id,'off') dgn...
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//Example 3.9 // resistance and current clc; clear; close; //given data : V=240; // voltage in volts r1=2; // resistance in ohm r2=3; // resistance in ohm r3=8.8; // resistance in ohm r4=10; // resistance in ohm r5=3; // resistance in ohm R1=(r1*r2)/(r1+r2); // equivalent resistance of parallel branch R2=R1+r3; // e...
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//Ques 1 //To determine the efficiency of Rankine cycle clc clear //1-Inlet state of pump //2-Exit state of pump P2=2000;//Exit pressure in kPa P1=10;//Inlet pressure in kPa v=0.00101;//specific weight of water in m^3/kg wp=v*(P2-P1);//work done in pipe in kJ/kg h1=191.8;//Enthalpy in kJ/kg from table h2=h1+...
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clc clear V1=5; P1=1; P2=5; n=1.25; Em=0.9; IP=[n/(n-1)]*[P1*100*V1/60]*[((P2/P1)^((n-1)/n))-1]; SP=IP/Em; printf('Shaft Power: %3.1f kW',SP); printf('\n'); IsoP=P1*100*V1*(log(P2/P1))*(1/60); Eo=IsoP/SP; printf('Overall Efficiency: %3.0f Percent',Eo*100); printf('\n');
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clc clear //input data u=2800 //rocket speed in m/s Cj=1400 //effective exhaust velocity in m/s mp=5 //propellent flow rate in kg/s q=6500 //heat of propellent per kg of propellant mixture in kJ/kg //calculation s=u/Cj //effective jet speed ratio np=(2*s)/(1+s^2) //propulsive efficiency F=Cj*mp*10^-3 //th...
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// Exa 2.22 clc; clear; close; format('v',7) // Given data V_L = 25;// in V I_L = 200;// in mA I_L = I_L * 10^-3;// in A R_L = V_L/I_L;// in ohm Gamma = 3/100; //Gamma = 1/(6*sqrt(2)*(omega^2)*L*C); f = 50;// in Hz omega = 2*%pi*f;// in rad/sec //LC = 1/( 6*sqrt(2)*(omega^2)*Gamma ) L = R_L/(3*omega);// ...
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clc; clear; format('v',6); V1=60; V2=20; r1=2; //in cm r2=6; //in cm r=4; //in cm disp("where A and B are constants.","V=A*ln(r)+B","The potential V as a function of coordinates is "); disp("B=85.2","A=-36.4","using the given data,we get"); V=-36.4*log(r)+85.2; disp(V,"The pot...
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// Topografia IV // Allan Turini Speroto 78233 // Fernando Martins Pimenta 80018 // Gabriel Batista Freitas 82718 // Matheus Lopes Vieira 80020 // Funções para o processamento da interseção linear function [Lb, Xa, sigma_d_xy] = getParams(Xp, Yp) /* Retorna os vetores Lb, Xa e sigma_d...
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clear; clc; disp("--------------Example 3.15---------------") printf("Another example of a nonperiodic composite signal is the signal received by an old-fashioned analog black-and-white TV.\n"); s=30; // screen is scanned 30 times per second //screen resolution = 525 x 700 vl=525; hl=700; pixels=vl*hl; // tota...
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//Example 13.5 //Stirlings Central Difference Derivatives //Page no. 426 clc;close;clear; printf(' x\t\t y\t\t d\t\t d2\t\t d3\n') printf('---------------------------------------------------------------------------') h=0.01;s=0.5; deff('y=f1(x,s)','y=((z(x,3)+z(x-1,3))/2+s*z(x-1,4)+(z(x-1,5)+z(x-2,...
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//Example6.13 // Determine the time constant of the integrator clc; clear; close; Vo = 20 ; t = 1*10^-3 ; VI = -1 ; // at t =0 ; // The output voltage of an integrator is define as RC = t/10 ; disp(' The time constant of the given filter is RC = '+string(RC)+ ' sec '); R = 1*10^3 ; // we assume C = R...
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// Function dlyapchol //lyapunov equation a =[-0.25 0.25; 0.6 -0.4]; b=[1.5442;0]; r=dlyapchol(a,b) //generalized lyapunov equation a =[-0.25 0.25; 0.6 -0.4]; b=[1.5442;0]; e=[11 22 ;33 44]; r1=dlyapchol(a,b,e)
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// Example No. 2.16 // To find the length of DCF so that the pulse width (FWHM) at the output of the DCF is twice the pulse width at the input of the TF // Page No. 84 clc; clear; // Given data beta2TF=-21*(10^(-12))^2; // Dispersion coefficient of transmission fiber in s^2/...
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// Calculate the range of readings clc; fsd=1000; TP=100; Efsd=(1/100)*1000; disp(Efsd,'magnitude of Error when specified in terms of full scale deflection (w)=') disp('Thus the meter will read between 90W and 110W') Etv=(1/100)*100; disp(Etv,'magnitude of Error when specified in terms of true value (w)=') dis...
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//example2.3 clc disp("Consider shunt generator as shown in the fig 2.29") disp("I_a=(I_L)+(I_sh)") disp("I_sh=(V_t)/(R_sh)") disp("Now, V_t=250 V") disp("and, R_sh=100 ohm") i=250/100 disp(i,"Therefore, I_sh(in A)=") disp("Load power=5 kW") disp("Therefore, P=(V_t)*(I_L)") i=(5*10^3)/250 disp(i,"I_...
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//Example No. 4_03 //Pg No. 64 clear ; close ; clc ; a = 0.1 b = 0.4 for i = 1:8 afrac(i) = floor(a*2) a = a*2 - floor(a*2) bfrac(i) = floor(b*2) b = b*2 - floor(b*2) end afrac_s = '0' + '.' + strcat(string(afrac)) //string form binary equivalent of a i.e 0.1 bfrac_s = '0' + '.' + strcat(s...
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clc VLB=2400 //line to base voltage in volts Ix=2005 //current in amperes xda=VLB/(sqrt(3)*Ix) mprintf("xda=%fΩ\n",xda)//ans may vary due to roundoff error Ifv=116 //current in amperes ma1=VLB/(sqrt(3)*Ifv)//equal to ma` in textbook mprintf("má=V1B/Ifv=%fΩ\n",ma1)//ans may vary due to roundoff error //from ex 2_7 V1=V...
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//Example_a_9_6 page no:406 clc; Vl=400; Vrnmag=400/sqrt(3); Vrnang=0; Vynmag=400/sqrt(3); Vrnang=-120; Vbnmag=400/sqrt(3); Vrnang=-240; R=10; omega=314; L=1; C=100*10^-6; Yph=(1/R)+(1/(%i*omega*L))+(%i*omega*C); Iph=Vrnmag*Yph;//multiplication of Vrnmag and Yph is rounded off in text book so output line ...
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// Variable Declaration TMS = 0.5 //Time multiplier setting I_f = 5000.0 //Fault current(A) CT = 500.0/5 //CT ratio set_plug = 1.0 //Relay plug set I_relay = 5.0 //Rated relay current(A) // Calculation Section PSM = I_f/(CT*set_plug*I_relay) //Plug setting multiplier T1 = 1.0 ...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>3D channel flow, Hexahedral elements, P=3, Successive RHS(5), par(2)</description> <executable>IncNavierStokesSolver</executable> <parameters>--use-scotch Hex_channel_m3_srhs.xml</parameters> <processes>2</processes> <files> <file de...
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// Example 4.15, page no-156 clear clc p=10000 //power fed to the antenna in W ag=60 //Antenna gain loss=2 //Power lossin feed system adb=10*log10(p) EIRP=adb+ag-loss printf("Earth station EIRP = %ddB",EIRP)
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clc //initialisation of variables r= 82.4 //ohms k= 0.002768 //ohm^-1 R1= 326 //ohm //CALCULATIONS K= r*k K1= (K/R1) //RESULTS printf ('cell constant= %.4f cm^-1',K) printf ('\n specific conductance= %.3e ohm^-1 cm^-1',K1)
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function [txt]=indentsci(txt) // //! // Copyright INRIA bl=' ' txt=bl(ones(prod(size(txt)),1))+txt
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errcatch(-1,"stop");mode(2);//Initilization of variables W=32.2 //lb T=120 //lb m=1 //slug r=6/12 //ft //Calculations w=sqrt((T*(3/5)*4)/(m*r*3)) //rad/s //Result printf('The angular speed permissible is %f rad/s',w) exit();
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errcatch(-1,"stop");mode(2);//Chapter 12 //page no 432 //given ; all; Pt1=-18; //in dBm for 50/125 micron fiber Pt2=-10; //in dBm for 100/125 micron fiber Pd=Pt1-Pt2; printf("\n Additional Power = %0.0f dBm",Pd); exit();
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function out=S2(x,p) somme=0; for i=0:p somme=somme+cos((2*i+1)*x)/(2*i+1)^2; end out=%pi/2-somme*4/%pi; endfunction //pas de discontinuite, donc pas d'effet Gibbs clf; x=linspace(-%pi,%pi,10000); n=100; plot(x,S2(x,n)); title("n=100");
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# vio_chsize.tst # # (virtual IO: operations that change file size) # read 0 5716 1.tmp expect 0 5716 0 compare_file 1.tmp data1.dat # shrink file set_size 0x1500 expect 0 read 0x1400 0x100 1.tmp expect 0 0x100 0 compare_file 1.tmp result13.dat read 0x1400 0x100 1p.tmp portion expect 0 0x100 0...
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function lagrangre() endfunction
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//Example 4.10.a//total load of lights and fans clc; clear; close; lp=50;//no. of light points lw=60;//wattage of light points fp=20;//no. of fan points fw=100;//wattage of fan points wpp=10;//no. of wall plug points wppw=60;//wattage of wall plug points bp=5;//no. of bell points bpw=40;//wattage of bell points ppp=8;...
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//Force P required to raise the load eta=0.70 W=2500 //N //refer fig. 6.17 //For third order pulley //VR=2^2-1 //For whole system VR=3+3 P=W/(eta*VR) //N printf("Required force p=%.2f N",P)
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//exapple 1.25 clc; funcprot(0); // Initialization of Variable time=4+20/60+30/3600; accn=time*9.8565/3600;//acceleration stime=time+accn;//sideral time disp("local mean time in past midnight observed:"); a=modulo(stime*3600,60); printf("seconds %.3f",a); b=modulo(stime*3600-a,3600)/60; printf(" minutes ...
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####### INITIATION ####### # Initiation of the scenario and the main PCL-file scenario = "CSpeech"; scenario_type = fMRI_emulation;# set to fMRI at the scanner! pcl_file = "CSpeech_Session1_MAIN.pcl"; pulse_code = 255; pulses_per_scan = 1; scan_period = 2000; write_codes = true; default_output_port = 1; # !!!!!!!!!!!...
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main function fibo(n); array[10] f; var i; { let f[0] <- 0; let f[1] <- 1; let i <- 2; while i < 10 do let f[i] <- f[i - 1] + f[i - 2]; let i <- i + 1 od; return f[n] }; { call outputnum(call fibo(9)) }.
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remove BADPATH create /test 123 remove /test remove /test remove /foo create /test abc create /test/b def remove /test
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//<>=errbar(x,y,em,ep) //<>=errbar(x,y,em,ep) // Rajoute des barres d'erreur sur un graphique 2D // x et y decrivent les courbes (voir plot2d) // em et ep sont deux matrices la barre d'erreur au point // <x(i,j),y(i,j)> va de <x(i,j),y(i,j)-em(i,j)> a <x(i,j),y(i,j)+em(i,j)> // x,y,em et ep sont donc des matrices (p,q)...
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//////////////////////////////////////////////////////////////////////////////// //// Неделя 8. //// Формирующий фильтр. //// Моделирование динамики матрицы ковариаций в байесовском подходе. //// Рекуррентный метод. Векторный случай //////////////////////////////////////////////////////////////////////////////// clear...
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Tint 255 0 0 0 Label Here1 TintAlphaChange 100 0.5 Linear Wait 0.5 TintAlphaChange 0 0.5 Linear Wait 0.5 Goto Here1
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clear// //Variables RC = 250.0 * 10**-12 //Time constance (in seconds) Vomax = 50.0 //Maximum output voltage (in volts) tau = 0.05 * 10**-6 //time (in seconds) //Calculation alpha = Vomax / RC //alp...
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clc clear clf() t=[0:%pi/20:2*%pi]'; z=sin(t)*cos(t'); plot3d(t,t,z)
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// Example 2.30 page no-95 clear clc B=0.1 //Wb/m^2 Vh=50 //mV I=10 //mA rho=2*10^5 //Ohm-cm w=3*10^-3 //m x=B*I*10^-3/(Vh*10^-2*w) printf("\n1/RH=%.3f",x) y=1/(rho*10^-2) printf("\nConductivity = %f mhos/meter\nmu=%.0f cm^2/V-sec",y,(y/x)*10^6)
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att1 att2 att3 att4 att5 att6 class 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 1 1 1 1 1 2 2 1 1 1 1 1 3 1 1 1 1 1 1 3 2 1 1 1 1 1 4 1 1 1 1 1 1 4 2 1 1 1 1 2 1 1 1 1 1 1 2 1 2 1 1 1 1 2 2 1 1 1 1 1 2 2 2 1 1 1 1 2 3 1 1 1 1 1 2 3 2 1 1 1 1 2 4 1 1 1 1 1 2 4 2 1 1 1 1 3 1 1 1 1 1 1 3 1 2 1 1 1 1 3 2 1 1 1 1 1 3 2 2 1 1 1 ...
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//to calculate syncronising power/elec deg,pu sync torque/mech deg clc; j=sqrt(-1); Xd=.8; Xq=.5; Vt=1; pf=.8; phi=acosd(pf); Ia=1*complex(cosd(phi),sind(phi)); Ef=Vt-j*Ia*Xq; Eff=abs(Ef); dl=atand(imag(Ef)/real(Ef)); w=-dl+phi; Id=abs(Ia)*sind(w); Ef=Eff+Id*(Xd-Xq); Psyn=abs(Ef)*Vt*cosd(dl)/Xd+Vt^...
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clc; clear all; u0=4*%pi*1e-7; b=9.27*1e-24; H=1e3;//homogeneous field k=1.38*1e-23;//boltzmann constant T=303;//temp in kelvin T1 = T - 273; // Temp In Degree x=u0*b*H/(k*T);//avg magnetic moment disp('bohr magneton/spin',x,'avg magnetic moment is=');
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function a=f2t(S,fs) N=length(S); T=1/fs*N; t=[-(T/2):1/fs:(T/2-1/fs)]; temp1=fft(S)/T; temp2=N*ifft(S)/T; a(1:N/2)=temp1(N/2+1:-1:2); a(N/2+1:N)=temp2(1:N/2); a=a.*exp((-%i*%pi)*fs*t); endfunction
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//Example 9.5 m_ub=55.0;//Mass of upper body (kg) m_box=30.0;//Mass of box (kg) r_ub=35*10^-2;//Distance of CG of upper body from pivot (m) r_box=50*10^-2;//Distance of CG of box from pivot (m) r_B=8*10^-2;//Distance of force F_B from pivot (m) g=9.80;//Acceleration due to gravity (m/s) F_B=((r_ub*m_ub*g)+(r_box...