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jan.immediate_drawing = "off" delete(Axes(3).children) // Deleta as polylines que estejam no eixo plot(Axes(3),t',Dt') // Plota os deslocamentos nodais Axes(3).data_bounds(2) = T1 select find(radioBut.value) case 2 plot(Axes(3),t',[T' Dt'/lambda]) legendas = [...
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//Chapter 9 Ionic Equilibria and Buffer Action clc; clear; //Initialisation of Variables c= 0.050 //M Kb= 1.8*10**-5 T= 25 //C Kw= 10**-14 //CALCULATIONS C= sqrt(Kw*c/Kb) //RESULTS mprintf("Concentration of hydronium ion = %.2e mol per litre",C)
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 14: TRANSFORMERS // Example 14-21 clear; clc; close; // Clear the work space and console. // Given data(from Ex.14-18) V_sc = 50 ; // Short circuit voltage in volt V_1 = 2300 ; // Rated primary v...
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* LS VERBOSE ALL ON * DV VERBOSE ALL ON # Turn on all traces for APP module on node 1 * APP VERBOSE ALL ON # Advance Time pointer by 15 seconds. Allow the routing protocol to stabilize. TIME 60000 0 APP PING 4 HELLO TIME 200 LINK DOWN 1 6 TIME 50000 0 APP PING 4 HI TIME 200 LINK UP 1 6 TIME 50000 0 APP...
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//Chapter 30 Ex6 clc; clear; close; S={'E','X','T','R','A'}; sizeS=size(S,"c"); n=4; //since there are 3 vowels, they are considered as 1 letter reqLetters=n; //since all the letters are required noLetters=factorial(n)/factorial(n-reqLetters); reqVowels=2; //since vowels are required to be together noWays=...
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//random negative i/p b=blackman(-23); disp(b); //output // //!--error 10000 //N must be a positive integer //at line 35 of function blackman called by : //b=blackman(-23);
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//Variable declaration Rf=5 //forward resistance(ohms) Vo=20 //output voltage(V) Rs=10 //secondary resistance of transformer(ohm) //Calculations //Part a Idc=0.1 //dc current(A) Vm=Vo*(sqrt(2)) //mean voltage(V) Vdc=(2*Vm/(%p...
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//Checking if function works for different values obpts = [ 1 2 -3; 3.3 1.5 .2; 1.1 2.5 2.4; .2 1.5 3.2; 2.3 -1.5 -.5; -1 -3 5.5; -1.5 -.5 3.5]; impts = [282 274; 397 227; 577 276; 462 378; 270 479; 450 523; 566 476]; camera = [ 1 0 0; 0 1 0; 0 0 1] dist = [0 0 0 0]; iterations = 10; reprojectionError ...
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// Example no 5.5 // To calculate mean excess delay, rms delay spread and maximum excess delay // Page no. 202 clc; clear all; // Given data t10dB=5*10^-6; // By definition of maximum excess delay (10dB) t1=0; ...
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PL/SQL Developer Test script 3.0 13 -- Created on 2017/2/17 by ADMINISTRATOR declare -- Local variables here i integer; v_avg number; begin -- Test statements here dbms_output.put_line(my_pack.num1); my_pack.my_procedure(20,v_avg); dbms_output.put_line(v_avg); end; 0 0
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// fonction test du code (exepmle d'évaluation) et paramétres function y=f(x) y=x^2 - 2; endfunction eps=10^-8 a=0 b=3 // Methode de Dichotomie function [x,n]=dicho(f,a,b,eps) if (f(a)*f(b)>0) then disp("Il ne semble pas y avoir de zero dans l''intervalle."); return; end n=0 while ...
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//CHAPTER 8 ILLUSRTATION 3 PAGE NO 223 //TITLE:BALANCING OF ROTATING MASSES pi=3.141 clc clear mA=200// mass of A in kg mB=300// mass of B in kg mC=400// mass of C in kg mD=200// mass of D in kg rA=80// radius of A in mm rB=70// radius of B in mm rC=60// radius of C ...
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//Fluid Systems- By Shiv Kumar //Chapter 7- Performance of Water Turbine //Example 7.8 // To Find Model Runner Speed and Prototype to Model Scale ratio clc clear //Given:- //For Prototype Pp=30; //Power Developed, MW Hp=55; //Head, m Np=100; //Speed, r...
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clc //Initialization of variables QCo2 = 10 // ft^3/min A = 50 // ft^2 h = 6 // ft // Calculations dh_dt = QCo2/A th6 = h/(dh_dt) //results printf(" the time rate of change of depth is %.2f ft/min",dh_dt) printf("\n the time taken to reach 6 feet is %.f min",th6)
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//Chapter 8 //Example 8_4 //Page 173 clear;clc; v2=11; v3=13.1; p1=poly([1 3 1], 'k', 'c'); p2=poly([1 1],'k', 'c'); p=v3*p2-v2*p1; r=roots(p, 'e'); k=r(2); v1=v2/(1+k); printf("V1 = %.2f kV \n\n", v1); v=v1+v2+v3; printf("Voltage between line and earth = %.2f kV \n\n", v); printf("Voltage between bus bars = %.2f ...
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//Example 6.14c clc; syms z n; x1=(1/4)^n; x2=(1/5)^n; X1=symsum(x1*(z^-n),n,0,%inf); X2=symsum(x2*(z^-n),n,-%inf,-1); X=X1+X2; disp(X,'X(z)=');
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*Testcase IEEE LOAD ROUNDED (3), LOAD FP INTEGER (3) DIVIDE (5), DIVIDE TO INTEGER (2) 13 instr total # Divide adjacent pairs of values in the input set (five values means four # quotients). Test data: 1, 2, 4, -2, -2; expected quotients 0.5, 0.5, -2, 1 # Load Floating Point Integer of the above result set. Exp...
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clc;clear; //Example 5.1 //given values W1=4;//wavelength in Angstrom W2=1;//wavelength in Angstrom e=1.6*10^-19;//the charge on electron in C m=9.12*10^-31;//mass of electron in kg //calculation disp("Part (i)"); E=12400/W1; disp(E,'The energy in eV is'); v=sqrt(E*e*2/m); disp(v,'The velocity in m/s is...
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clear all; clc; disp("Ex 2_9") f1_i=0 f1_j=60 f1_k=80 f2_i=50 f2_j=100*(-1) f2_k=100 FR_i=f1_i+f2_i FR_j=f1_j+f2_j FR_k=f1_k+f2_k printf('\n\nIn vector Form, FR = (%.0fi%.0fj+%.0fk) N',FR_i,FR_j,FR_k) FR=sqrt(FR_i^2+FR_j^2+FR_k^2) printf('\n\nThe magnitude of FR = %.0f N',FR) u_i=FR_i/FR u_j=FR_j/FR u_k=FR_k/FR printf(...
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//Calculate the Maximum Electrical work that can be obtained from CH4(g)+2O2(g)=CO2(g)+2H2O(l) //Example 6.3 clc; clear; delrH=-890.3; //change in Enthalp in kJ mol^-1 delrS=-242.8; //Change in Entropy in J K^-1 T=25+273; //Temperature in K delrG=delrH-(T*delrS/1000); //Change in Gibbs energy i...
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K D=1; h=4; P1=100; T1=27+273; P2=125; Cp=14.307; Cv=10.183; V1=(22/7)*(1/4)...
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clc; Vdc=30; RL=1*10**3; y=0.01; C=2890/(y*RL); disp('microF',C*1,"C=");
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clc disp("example 2.13") dlf=0.825; //daily load factor lptmlp=0.87; //average daily peak load to monthly load peak mlptalp=0.78; //average monthly peak load to annual load peak printf("annual load factor =%fx%fx%f=%f.",dlf,lptmlp,mlptalp,dlf*lptmlp*mlptalp)
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// Example 24_22 clc;funcprot(0); //Given data T_1=290;// K p_1=1.01;// bar T_3=650+273;// K p_r=8;// Pressure ratio n_c=0.8;// Isentropic efficiency of compressor n_t1=0.85;// Isentropic efficiency of H.P turbine n_t2=0.83;// Isentropic efficiency of L.P turbine C_pa=1;// kJ/kg.K C_pg=1.15;// kJ/kg.K r_a=...
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clear; clc; //Example3.13[Heat Loss from Buried Steam Pipes] //Given:- T_esurf=10;//Surface temperatur of earth[degree Celcius] T_psurf=80;//Outer surface temperature of pipe[degree Celcius] k_soil=0.9//Thermal Conductivity of soil[W/m.degree Celcius] L=30;//Length of pipe[m] D=0.1;//Diameter of pipe[m] z=0.5;//Depth ...
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clc; //page no 140 //prob no. 4.2 //An FM modulator is given which is modulated by sine wave 3V v=3; kf=30*10^3; //Determination of peak value Em=v*sqrt(2); //Determination of deviation delta delta=kf*Em; disp('kHz',delta/1000,'The value of deviation is ');
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// sum 5-4 clc; clear; p=16; Ri=250; //Yield strength =sigy; sigy=330; v=0.3; FOS=3; Sa=sigy/3; t=Ri*((sqrt(Sa/(Sa-(2*p))))-1); t=50; // printing data in scilab o/p window printf("t is %0.1fmm ",t);
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//Ex:5.24 clc; clear; close; w=30;// line width in nm L=1.5;// length in km d1=6;// in ns/km d2=85;// in ps/km/nm d3=d2/1000;// in ns/km/nm dt=d1*L;// intermodel dispersion in ns dt1=w*d3*L;// intramodel dispersion in ns dT=sqrt(dt^2+dt1^2);// total dispersion in ns printf("The max dispersion =%d ns", dt); ...
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clc C=20 G=18.5 r=0.25 H=21.62 C=25 b= atand(0.5) //from table 15.3 m=1.624 n=1.338 Fs=m-n*r printf(' The value of Fs for D= 1 is %f',Fs)
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//Example number 3.1, Page number 3.32 // importing modules clc;clear;close // Variable declaration V=2265 // m^3 A=92.9 // Coefficient x=2 // The absorption become 2*A of open window // Calculation T=(0.16*V)/A // Sabine's formula T2=(0.16*V)/(x*A) // in s // Result printf("Reverbration time =...
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exec("alaqiltest.start", -1); if UP_get()<>1 then alaqiltesterror(); end if typeof(UP_get())<>"constant" then pause; end if DOWN_get()<>2 then alaqiltesterror(); end if typeof(DOWN_get())<>"constant" then pause; end if LEFT_get()<>3 then alaqiltesterror(); end if typeof(LEFT_get())<>"constant" then pause; end if RI...
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function adc_list = get_adc_list() adc_list = 1:10; endfunction
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clear // // //Initilization of Variables d=25 //mm //diameter of steel d2=18 //mm //Diameter at neck L=200 //mm //length of stee P=80*10**3 //KN //Load P1=160*10**3 //N //Load at Elastic Limit P2=180*10**3 //N //Max Load L1=56 //mm //Total Extension dell_l=0.16 //mm //Extension //Calculations A=%pi*d**2*4**-1 //...
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//Engineering and Chemical Thermodynamics //Example 8.7 //Page no :385 clear ; clc; //Given P = 0.223 ; //[bar] P_a_sat = 0.156 ; // [bar] P_b_sat = 0.124 ; //[bar] R = 8.314 ; T = 50 + 273 ; Xa = 0.554 ; Xb = 1 - Xa ; gama_a = P / P_a_sat ; A1 = R * T * log(gama_a) / (Xb^2) * 10^-3 ; gama_b = P / P_...
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clc; clear; Na=10^15 //doping densities in cm^-3 Nd=10^17 //in cm^-3 V=0.5 //in V e=1.6*10^-19 //in J nn0=10^17 //in cm^-3 ni=1.5*10^10 //in cm^-3 Si_bandgap=1.1 //bandgap of silicon in eV Const=0.0259 //constant value for kT/e in J //Calculation //a) pn0=ni^2/nn0 //in cm^-3 pn=pn0*exp((V)/Const) //b...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 8: AC DYNAMO TORQUE RELATIONS - SYNCHRONOUS MOTORS // Example 8-19 clear; clc; close; // Clear the work space and console. // Given data kVA_load = 500 ; // Load of 500 kVA PF_load = 0.65 ; // Lo...
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//chapter8,Example8_1,pg 180 alpha=0.01 n=10 lam=6000*10^-8 u=1.5 //for dark fringe 2*u*t*cos(alpha)=n*lam //t=xtan(alpha) //2*u*x*sin(alpha)=2*u*x*alpha=n*lam ->alpha is small, sin(alpha)=alpha x=(n*lam)/(2*u*alpha) printf("distance of 10th fringe from edge of wedge\n") printf("x=%.2f cm"...
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clear clc T=[10 132 6.6 .15] M=[5 6.6 .3 .2 ] B=[10 6.6] T(5)= T(3)/T(2) B(3)=B(2)* T(5) B(4)= B(1)*1e6/(sqrt(3)*B(2)*1e3) M(5)=M(4) *B(1)/M(1) M(6)=M(3) *B(1)/M(1) X1=1/((1/M(5))+(1/M(5))+(1/T(4))) IF1=round(100/X1)/100 I1=IF1*B(4) mprintf("\n(a) sub transient fault current=%.0f A", I1) It=round(10...
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//All the quantities are expressed in SI units p =101000; //static pressure T = 320; //static temperature v = 1000; //velocity gam = 1.4; //ratio of specific heats R = 287; //universal gas constant cp = gam*R/(gam-1); //specif...
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The basic test for the set tool. Test Type: auto seperate_output_streams seperate_output_streams
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//Chapter-1, Example 1.4, Page 35 //============================================================================= clc; clear; //INPUT DATA PRF = 1000;//pulse repetitive frequency in Hz Ppeak =10*10^6;//peak power in watts Pav =100*10^3;//average power in watts //Calculations D = Pav/Ppeak;//Duty ...
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//too many i/p args m=[0.3209*%i 0.5183 0.3209 1.0000 0.1677 0.2575;1.0000 0.8927 1.0000 1.0000 0.6196 0.8747]; c=sos2cell(m,2,1); disp(c); //output // !--error 58 //Wrong number of input arguments.at line
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//skipped groundPlane_transform //skipped Manipulator1 //skipped UniversalManip //skipped CubeCompass ///////////////////////////////////////////// // object_Trim_Char_x_1_1__ ///////////////////////////////////////////// #if 0 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1 #endif DX3DMATERIAL_STA...
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// **** Purpose **** // This function geneates the basis transformation matrix based on the // flq.state_info. So PiLab calculattion can be handled easier. // **** Variables **** // [state_info]: structure // <= flq.state_info variable in PiLab // [basis_in]: string, 'c'/'s'/'rc'/'rs' // <= the input basis // [bas...
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A = 10^-4; kT = 0.0259; ni = 1.5*10^10; q = 1.6*10^-19; Na = 10^17; Nd = 10^15; epsilon0 = 8.85*10^-14; epsilon = 11.8; E1 = kT*log(Na/ni); E2 = kT*log(Nd/ni); V0 = E1+E2; V = -4; Cj = sqrt(epsilon*epsilon0)*A*sqrt(q*Nd*Na/(2*(V0-V)*(Na+Nd))); disp(V0,"V0 (in volt)=") disp(Cj,"total depletion constant (in...
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clc // initialization of variables clear Do=22 //mm Di=18 //mm Dm=20 //mm tD=0.1 // t/D //part (a) tau=70 //MPa G=77.5 //GPa //calculations Do=Do*10^-3 Di=Di*10^-3 Dm=Dm*10^-3 tau=tau*10^6 G=G*10^9 A=%pi*Dm^2/4 t=Dm*tD T1=2*A*tau*t th1=tau*%pi*Dm/(2*G*A) J=%pi/32*(Do^4-Di^4) r=Dm/2 T2=tau*J/r th2...
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clc; vl=230; // line voltage f=50; // frequency of supply c=100*10^-6; // value of capacitance in each phase vp=230/sqrt(3); // phase voltage zp=1/(2*%pi*f*c); // phase impedance il=vp/zp; // line current // value of cos(theta) is taken from figB.15 w1=vl*il*cosd(120); w2=vl*il*cosd(60); printf('Reading of wa...
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// Exa 1.21.6 clc; clear; close; // Given data a = 3.65;// in Å h = 1; k = 0; l = 0; d = a/(sqrt( ((h)^2) + ((k)^2) + ((l)^2) ));// in Å n = 1; theta = 60;// in degree //Formula 2*d*sin(theta) = n*lembda; lambda = 2*d*sind(theta);// in Å disp(lambda,"Wavelength of X ray in Å is");
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 4 : Circuit Theorems // Example 4 - 16 clear; clc; close; // // Given data Voc = 12.4000; VL = 12.0000; PL = 2.0000;...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Kovasznay Flow 3D homogeneous 1D, P=5, 6 Fourier modes (FFTW), specHP+homog dealiasing</description> <executable>IncNavierStokesSolver</executable> <parameters>KovaFlow_3DH1D_P5_6modes_FFTW_MixedDeal.xml</parameters> <files> <file descri...
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//example6.27 clc disp("From the fig 6.50 we can write,") disp("V_CC=20V and R_L=12 ohm") disp("i) The maximum ac power that can be delivered to the load is,") p=(20^2)/24 disp(p,"(P_ac)_max[in W]= ") disp("Let new power delivered to load be (P_ac)''.") disp("The corresponding new supply voltage be (V''_cc)") ...
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function [xi,xa,np]=graduate( xmi, xma,n1,n2) // graduate - axis pretty graduations //%Syntax // [xa,xi,np]=graduate( xma, xmi,n1,n2) // [xa,xi,np]=graduate( xma, xmi) //%Parameters // xmi, xma : real scalars // n1 , n2 : integer scalars default values 3,10 // xi , xa : real scalars // np :integer scalar //%D...
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//Integration par la méthode des trapèzes function y=f(x) y=exp(1+x.^2); endfunction; function I=IntTrap(f,a,b,h) I=(f(a)+f(b))/2; //h=(b-a)/n; x=a:h:b; n=length(x); if n>2 then I=I+sum(f(x(2:n-1))); end I=I*h; endfunction disp(IntTrap(f,1,2,1)); disp(IntTrap(f,1...
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прояв N;NOM;SG прояв N;NOM;PL витемс V;PL;3;PST;CAUS витемс V;AC3S;SG;3 витемс V;AC3P;SG;2;PST;PASS витемс V;SG;LGSPEC_AMP;3;PASS витемс V.PTCP;SG;3;PST витемс V;PL;1 витемс V;AC3P;IMP;SG;2;PASS витемс V;AC3P;SG;2;PST витемс V;AC3S;SG;1;CAUS витемс V;AC3P;IMP;SG;2 витемс V;PL;1;PST витемс V;IMP;PL;2 витемс V;AC3S;SG;2 ...
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//Example 7.6 clc clear function [I] = trap (fun,a,b,n) // Integrate the function over the interval using Trapezoidal Formula // trap (fun,a,b,n) // fun - function to be integrated // a - lower limit of integration // b - upper limit of integration // n - No. of times trapezoidal rule needs to be performed...
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function [stk,txt,top]=%i2sci() // //! // Copyright INRIA txt=[] rhs=abs(evstr(op(3)))-2 sto=stk(top);top=top-1 sfrom=stk(top);top=top-1 top=top-rhs+1 s2=stk(top) if rhs==1 then if s2(1)<>':' then if sto(3)=='0'|sto(4)=='0' then txt=sto(1)+'(1,'+s2(1)+') = '+sfrom(1)+';' stk=list(op(2),'-1','?','?',st...
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//EXAMPLE 2-56 PG NO-99-100 V=230+%i*0; R=15+%i*0; L=%i*7.5; Ir=V/R; Z1=-%i*12 disp('i) CURRENT (Ir) is = '+string (Ir) +' A '); IL=V/L; disp('i) INDUCTANCE CURRENT (IL) is = '+string (IL) +' A '); Ic=V/Z1; disp('i) CAPACITOR CURRENT (Ic) is = '+string (Ic) +' A ');...
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//Bolzano method by Rêmullo Costa function y = f(x) y = x^3-5*x+1; endfunction x = 0:0.1:3; y = f(x); plot(x,y); xgrid; a = 0.1; //ponto a avaliado por visualização grafica (point 'a' evaluated by graphical visualization) b = 0.3; // ponto b avaliado por visualização grafica (point 'b' evaluated by graphical vi...
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function bw= enbw (window, fs) // This function estimate Equivalent noise bandwidth. // Calling Sequence // bw=enbw(window) // bw=enbw(window, fs) // // Parameters // window: specify the sample window. // fs: specify the sampling rate of window. // bw: returns th...
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//example 3.23 //calculate irrigation schedule clc; //given Fc=0.18; //field capacity wc=0.07; //wilting cofficient Sg=1.35; //bulk density of soil d=1.2; //root zone depth m=Fc-wc; mo=wc+m/3; dw=100*Sg*d*(Fc-mo); mprintf("Depth of water required=%f cm",dw); ev1=1.1; ...
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clc clear printf('example 1.17 page number 50\n') //to find the specific gravity of plasstic L=1 //length of prototype in m L1=10*L //length of model in m density_prototype=2.65 //gm/cc density_water=1 //gm/cc density_model=(L^3*(density_prototype-density_water))/(L1^3)+1; printf("sp...
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//Chapter 8 //Example 8_16 //Page 185 clear;clc; pc=53; v=106; loss=98; pl=110.9; cv=113; sq=sqrt(loss/pc); vc=(sq*v/sqrt(3)-pl/sqrt(3))/(sq-1); w=(cv/sqrt(3)-vc)^2/(v/sqrt(3)-vc)^2*pc; printf("Critical disruptive voltage = %.2f kV \n\n", vc); printf("Power loss at %.0f kV = %.0f kW \n\n", cv, w);
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function [ac,bc,cc,dc]=reg(sys,k,l,sensors,known,controls) //(returns state spaces of a regulator given state-feedback and estimator gain. // //Calling Sequence //[ac,bc,cc,dc]=reg(sys,k,l) //[ac,bc,cc,dc]=reg(sys,k,l,sensors,controls) // //Parameters //sys:lti model (nx states,nu inputs...
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function droite(X,T,W,b,x1min ,x1max ,x2min ,x2max ,i) //tracer de la droite de séparation [nx ,mx ]= size(X); figure(1) a=get("current_axes");//get the handle of the newly created axes a.data_bounds=[x1min, x1max, x2min, x2max]; set(gca(),"auto_clear","off") //hold on //axis([ x1min x1max x2min x2max ]) for k=1:mx ...
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; @Harness: simplifier ; @Purpose: "Test variants of all instructions" ; @Result: PASS adc r0, r0 add r0, r0 adiw r24, 0 and r0, r0 andi r16, 0 asr r0 bclr 0 bld r0, 0 brbc 0, 0 brbs 0, 0 brcc 0 ...
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function [r] = correlacion(x,y); x = x - mean(x); y = y - mean(y); nx = length(x); ny = length(y); r = []; for l=1:ny-2*nx for m=0:nx-1 sumax = 0; sumay = 0; sigmax = 0; sigmay = 0; suma = 0; for k=1:nx yk = y(l:l+2*nx-1); suma = suma + (x(k)*yk(m+k)...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 1 Introduction to Electronics Pg no. 33 //Solved Problem 3 clear; clc; //Given Data R=120;//resistance in ohms P=1000;//power in watts //Solution I=sqrt(P/R);//current in amperes printf("I=%.2f Amperes.",I);//Displaying upto 2 places of decimal
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//Chapter 3, Example 3.15, page 118 clc //Initialisation d=40 //length in meter Am=2 //area in square meter f=10*10**9 //frequency in hertz //Calculation As=40 ...
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BigVectorArray.parseRecurrence("-(n+5)*(n-4)*a(n) +2*n*(2*n-1)*a(n-1)=0") vname=a_0, k=0, kmax=0, kmin=0, poly=20*a_0 - a_0*n - 2*a_1*n - a_0*n^2 + 4*a_1*n^2 vname=a_1, k=-1, kmax=0, kmin=-1, poly=20*a_0 - a_0*n - 2*a_1*n - a_0*n^2 + 4*a_1*n^2 shift by 0 create bva[3] bva[2]=20 - n - n^2, vector=[20,-1,-1], poly= ...
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//(8.8) Reconsider the turbine and pump of Example 8.2. Determine for each of these components the rate at which exergy is destroyed, in MW. Express each result as a percentage of the exergy entering the plant with the fuel. Let T0 = 22C, p0 = 1 atm //solution T0 = 295 ...
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function y = f(x) y = 3*x^2 endfunction
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//for the jet power executive aircraft(CJ-1): b=16.25;//wingspan(meter) S=29.54;//wingarea(m^2) AR=b^2/S;//aspect ratio Wo=88176.75;//normal gross weight(N) Wf=33211.9;//weight(N)of fuel W1=Wo-Wf//empty weight(N) c=0.6/3600//specific fuel consumption(1/s) D=0.6107;//density at altitude 6705.6 m(Kg/m^3)
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clear ; clc; // Example 3.5 printf('Example 3.5\n\n'); //Page no. 84 // Solution // Basis 100 kg coal ml_r = 9; wt_r = (9*1.008)/(1*12) ;//conversion of mole ratio to wt.ratio m1 = 2 ;//[kg] wt.of sulphur m2 = 1 ;//[kg] wt. of nitrogen m3 = 6 ;//[kg] wt. of oxygen m4 = 11 ;//[kg] wt. of ash m5 = 3 ;//[...
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Hr1 = -249952; // For octane Hp1 = Hr1; // Below values are calculated using value fron table 16.4 T2 = 1000; Hp2 = -1226577 T3 = 1200; Hp3 = 46537; T4 = 1100; Hp4 = -595964; Hp = [Hp2 Hp3 Hp4] T = [T2 T3 T4] T1 = interpln([Hp ; T],Hp1); // Interpolation to find temperature at Hp1 disp("K",T1,"the adeabati...
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clear; clc; // Illustration2.3 // Page: 32 printf('Illustration 2.3 - Page: 32\n\n'); // solution //***Data***// // a = C2H5OH b = air Pt = 101.3*10^(3);//[N/square m] T = 273;//[K] //********// Ma = 46.07;// [kg/kmol] Mb = 29;// [kg/kmol] //For air from Table 2.2 (Pg 33) Eb_by_k = 78.6;// [K] ...
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//[r]=%lssolss(s1,s2) //%lssolss(s1,s2) effectue le test d'egalite de deux systemes d'etat //correspond a l'operation s1==s2 //! for k=2:7,r=and(s1(k)==s2(k));if ~r then return,end,end //end
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clc;clear; //Example 23.7 //calculation of frequency //given values t=5.5*10^-3;//thickness of plate in m Y=8*10^10;//Young's modulus in N/m^2 d=2.65*10^3;//density in kg/m^3 //calculation f=sqrt(Y/d)/(2*t);//in Hz disp(f/10^3,'frequency of fundamental note(in KHz) is');
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//Problem 18.06: Design an inverting amplifier to have a voltage gain of 40 dB, a closed-loop bandwidth of 5 kHz and an input resistance of 10 kohm. //initializing the variables: Vg = 40; // in dB bf = 5000; // in Hz Ri = 10000; // in ohms //calculation: A = 10^(Vg/20) Rf = A*Ri f = A*bf printf("\n\n Re...
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//Chapter 2,Ex2.10,Pg 2.19 clc; disp("Refer to the diagram shown in the figure") A=[7 -1 0 ;-1 6 -3; 0 -3 13] B=[10; 0; -20] I=A\B printf("\n Current through the 2 ohms resistor=%.2f A\n",I(2))
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/////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Date: June 2010 // Description: Mean-Shift Clustering // Reference: Fukunaga, K.; Hostetler, L.; , "The estimation of the gradient // of a density function, with applications in pattern recogniti...
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//Example 13_4 clc;clear; // Given values S_0=0.003;// Bottom slope n_1=0.030; n_2=0.050; // Calculation s=sqrt(3^2+3^2); //Then the flow area, perimeter, and hydraulic radius for each subsection and the entire channel become // Subsection 1: A_c1=21;// m^2 p_1=10.486; // m R_h1=A_c1/p_1;// m // Subsect...
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clear// //Variables dIL = 40.0 //Change in current (in milli-Ampere) VNL = 8.0 //Voltage under no load (in volts) VFL = 7.995 //Voltage under full load (in volts) //Calculation LR = (VNL - VFL)/ dIL //Line regulation (in milli-volt per milli...
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// Example 7.8.2 page 7.39 clc; clear; w=20d-6; //width v=4d4; //velocity t=w/v; //computing drift time BW=(2*%pi*t)^-1; //computing bandwidth rt=1/BW; //computing response time rt=rt*10^9; printf("\nMaximum response time is %.1f ns.",rt); printf("\nNOTE - Calculation error in ...
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TRIANGLE P1(1.416586, 11.0, 2.48) P2(1.416588, 6.01, 2.48) P3(1.416588, 6.01, -2.48) TRIANGLE P1(1.416586, 11.0, 2.48) P2(1.416588, 6.01, -2.48) P3(1.416588, 11.0, -2.48) TRIANGLE P1(-1.060412, 11.0, 2.48) P2(-1.060412, 6.01, 2.48) P3(1.416588, 6.01, 2.48) TRIANGLE P1(-1.060412, 11.0, 2.48) P2(1.416588, 6.01, 2.48) P3(...
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// Example 8.16, page no-220 clear clc d=10500//density avg=6.022*10^26 awt=107.9 n=d*avg/awt//per cubic m h=6.62*10^-34//Js m=9.1*10^-31//Kg e=1.6*10^-19//C ef=((3*n/(8*%pi))^(2/3))*((h^2)/(2*m)) ef=ef/e printf("The Fermi energy for given metal is %.2f eV ",ef)
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function y=f3(r) y = 10 - 20.*(exp((-0.2).*r) - exp((-0.75).*r)) - 5 endfunction axes = get("default_axes"); axes.x_location = "origin"; axes.y_location = "origin"; t = -2:0.05:10 plot(t, f3(t)) secante(f3,6,8,0.00001) // k= 1 x(1)= 0.0000000 |f(x(1))|= 5.0000000 // k= 2 x(2)= 2....
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//<f>=%rss(f1,n2) // %rss(f,m) soustrait la matrice de scalaires m a la matrice de //fractions rationnelles f. //Cette macro correspond a l'operation f-m //! [t,n1,d1]=f1(1:3), [m1,m2]=size(n2) if m1<0 then n2=n2*eye(n1),end [n1,d1]=simp(n1-n2.*d1,d1), f=list(t,n1,d1,f1(4)), //end
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// Example 1.64. resistance clc, clear // given : Rm=10; // in ohm Im=.005; // in A I=1; // in A V=5; Rsh=(Im*Rm)/(I-Im); Rs=(V-(Im*Rm))/Im; disp(Rsh,"shunt resistance,Rsh(ohm) = ") disp(Rs,"series resistance,Rs(ohm) = ")
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clear; clc; //Example2.9[Combined Convection and Radiation Condition] //Given:- T_ball=300;//Temperature of spherical metal ball[degree Celcius] T_ambient=27;//Temperature of ambient air[degree Celcius] k=14.4;//Thermal conductivity of the ball material[W/m.K] h=25;//average convection heat transfer coefficie...
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//ques-16.1 //Calculating rate constant of a reaction clc //t = Time in minutes //c = KMnO4 in mL t1=0; c1=37; t2=5; c2=29.8; t3=15; c3=19.6; t4=25; c4=12.3; t5=45; c5=5; a=c1; k2=(2.303/t2)*log10(a/c2); k3=(2.303/t3)*log10(a/c3); k4=(2.303/t4)*log10(a/c4); k5=(2.303/t5)*log10(a/c5); k=(k2+k3+k4+k5)/4; ...
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clear nums = [1, 1]; ans = 0; while sum(nums) < 4e6 if ~modulo(sum(nums), 2) ans = ans + sum(nums); end nums = [nums(2), sum(nums)]; end printf("%d", ans)
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////given h=6.62*10**-34 //Js c=3*10**8 //m/s lembda=4560.0*10**-10 //m p=1*10**-3 //W a=0.5/100 e=1.6*10**-19 //calculation E=(h*c)/lembda N=p/E //Num...
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// Lecture des données dat = read("/home/Bart/Documents/M2SITN/POO/github/Tests/data1.txt" , -1 , 7) ; // Centrage des données dat_barre = sum(dat,1)/size(dat,1) ; dat = dat - dat_barre(ones(size(dat,1),:),:) ; // cor = dat'*dat/size(dat,1) ; valP = spec(cor) ; //valeur propre disp(valP) ; [Ab,vectP]=bdiag(cor) ; di...
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clc clear // TAREFA 1 // Gabriel de Sousa Araujo - 9299341 // Gustavo Lopes Oliveira - 10335490 // Herval Pereira de Castro Junior - 10335792 // Leonardo Silva Almeida Serra - 1033656 // Lucas Hideki Takeuchi Okamura - 9274315 // Parte 1 fa = 100 // frequência de amostragem t0 = 0 // instante de tempo inicial tf = 4 ...
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clc //Given that theta = %pi/2 // scattering angle of photon h = 6.624e-34 // plank's constant c = 3e8 // speed of light e = 1.6e-19 // charge on electron in coloumb m_e = 9.1e-31 // mass of electron in kg //Sample Problem 6 Page No. 137 printf("\n\n\n # Problem 6 # \n") printf("\n Standard formula Used \n del...
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#it does not match the risto "optimum MMN" paper scenario = "PS3_roving_combination_MMNe_01072015"; #adapted from "nvMMNa5_napls06122009"; #attenuation updated for ER1 insert earphones and X-fi gamer card #Note: this is based on the baldeweg-style of pitch deviance with #the additional constraint that a transition b...
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//Example 8.12, Page Number 398 //The Function fpround(dependency) is used to round a floating point number x to n decimal places clc; n=1.48//Refractive index of fiber n0=1//Refractive index between the fibers in air //From equation 8.39 Rf=(((n-1)/(n+1))**2) //Rf is the fraction of light Rf=fpround(Rf,4) ...