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clc //Given that v = 300 // speed of electron in m/s accuracy = 1e-4 // accuracy in speed h = 6.6e-34 // Plank's constant m_e = 9.1e-31 // mass of electron in Kg //Sample Problem 13 page No. 140 printf("\n\n\n # Problem 13 # \n") printf("\n Standard formula Used \n delta_p * delta_x >= h /(2*pi)") del_p = acc...
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clc clear //Initialization of variables p1=50 //psia pr=0.58 //calculations p=p1*pr s1=1.6585 h1=1174.1 //Btu/lbm sf=0.3680 sfg=1.3313 hfg=945.3 vg=13.746 hf=218.82 x= (s1-sf)/sfg v2=vg*x h2=hf+x*hfg V2rev=223.77*sqrt(h1-h2) m=%pi/4 *1/144 *V2rev/v2 //results printf("mass flow rate = %.3f lbm/sec",m...
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pi=%pi i=%i e=%e // tests // 1 a=1 b=[1 2 3] c=[1 2 3;4 5 6] d=[1 2 3;4 5 6]' d=[1 2 3 4;4 5 6 7;8 9 10 11;12 13 14 15] d=[1 2;3 4] e1=[[1 2] [3 4];[5 6 7 8];[9;10;11;12]'] f([1 3 5],[1 2 3])=[-1 -2 -3;-4 -5 -6;-7 -8 -9] g=[i,2,3;1 i 3;1 2 i] h=[i 1 2 i 3] o=[1 i i 2 3]' b(2)=3 e1(1,3)=1 p='apcdefghijklmnopqrstuv...
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//Example 4.15 clc; syms s; F=(s+3)/(s*((s+1)^2)*(s+2)); f=ilaplace(F); disp(f);
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//clear// //Caption:Program to determine incident and transmitted anlges //Example13.9 //page464 clear; clc; n1 =1.00; //refractive index of air n2 =1.45; //refractive index of glass teta1 = asin(n2/sqrt(n1^2+n2^2)); teta2 = asin(n1/sqrt(n1^2+n2^2)); Brewster_Condition = teta1+teta2; disp(teta1*57.3,'Inciden...
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// Exa 6.17a clc; clear; close; // given data R=10;//in Kohm R1=R;//in Kohm R2=R;//in Kohm R3=R;//in Kohm Rf=5.6;//in Kohm R4=Rf;//in Kohm R5=Rf;//in Kohm RA=2.7;//in Kohm RB=1.5;//in Kohm C=0.01;//in uF C1=C;//in uF C2=C;//in uF alfa=3*RB/(RA+RB); disp("The type of response will be determined by the...
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clc //initialization of varaibles P1=75 //psia P2=15 //psia V1=6 //cu ft g=1.2 m=3 //calculations Q=30 //Btu V2=V1*(P1/P2)^(1/g) U=0.48*(P2*V2-P1*V1) W=Q-U //results printf("Work done = %.1f Btu",W) //The answer given in textbook is wrong. please check using a calculator
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// scilab Code Exa 18.29 Centrifugal compressor with vaned diffuser T01=310; // in Kelvin p01=1.103; // Initial Pressure in bar dh=0.10; // hub diameter in m d2=0.55; // impeller diameter in m c1=100; // Velocity of air at the entry of inducer c3=c1; // Velocity of air at diffuser exit shi=1.035; // power inp...
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// Exa 5.11 format('v',5) clc; clear; close; // Given data k= 0.1;// in mA/V^2 V_T= 1;// in V R2= 87*10^3;// in Ω R1= 110*10^3;// in Ω R_S=2;// in kΩ R_D=2;// in kΩ //R_D=3*10^3;// in Ω V_DD= 6;// in V V_SS= 6;// in V V_G= (V_DD+V_SS)*R2/(R1+R2);// in V // V_S= I_D*R_S-V_SS // V_GS= V_G-V_S= V_G+V_SS-(...
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clc //initialisation of variables w= 62.4 //lb/ft^3 l= 12 //ft b= 6 //ft h= 5.196 //ft a= 60 //degrees a1= 45 //degrees //CALCULATIONS P= w*l*b*h/2 h1= ((l*b^3*(sind(a))^2/12)/(l*b*(h/2)))+(h/2) R= P*(b-(h1/cosd(a/2)))/((b*sind(a1))/2) //RESULTS printf ('Total comression in the promp CD = %.f lb ',R)
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//S.H.M r=0.75 //m T=1.2 //sec omega=((2*%pi)/(1.2)) //rad/sec vxmax=0.75*5.236 //m/sec axmax=0.75*5.236^2 //m/sec^2 printf("\nvx(max)=%.3f m/sec\nax(max)=%.3f m/sec^2",vxmax,axmax)
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clear; clc; disp("--------------Example 4.14---------------") bits= 8; // bits per sample fl=0; // The human voice normally contains frequencies from 0 to 4000 Hz. fh=4000; // Hz sampling_rate = 2*fh; // twice the highest frequency bit_rate=sampling_rate*bits; // formula printf("The sampling rate is %d samples...
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V=250 Ia=200 Ra=0.22 Ea=V-Ia*Ra Pm=Ea*Ia Prl=600 Pmout=Pm-Prl n=1250 wm=2*%pi*n/60 Tl=Pmout/wm disp(Tl) Rf=125 Psh=V*V/Rf Pein=V*Ia+Psh effi=Pmout/Pein disp(effi)
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syms f J K s t T=1/(J*(s^2+(f/J)*s+(K/J))) //Q/I omegaN=sqrt(K/J) Mp=6 //given zeta=0.667 omegaD=omegaN*sqrt(1-zeta^2) Tp=%pi/omegaD disp(Tp," Tp = ") I=laplace('10',t,s) Q=I*T x=limit(s*Q,s,0); disp(10/0.5," K = ") disp(K/omegaN^2," J= ") disp(zeta*(2*sqrt(K*J))," f = ")
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xdel(winsid()); clc; //getd('C:\Users\ab\Desktop\TP S7 eilco\TpImage\TP\cavite'); //// qst 1 //// qst2 //I=imread('code_postale.jpeg'); //figure; //imshow(I); //I_gray=rgb2gray(I); //figure; //imshow(I_gray); ////qst3 //seuil=imgraythresh(I_gray); //I_bw=~im2bw(I_gray,seuil); //figure; //imshow(I_bw); //// qst4 //str...
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function [r] = Baskara(v) // Controla que a sea distinto de 0 if (v(1)<>0) then // Calcula el discriminante disc=v(2).^2-4*v(1)*v(3) // Calcula las raíces x1=(-v(2)+sqrt(disc))/2*v(1); x2=(-v(2)-sqrt(disc))/2*v(1); // Informa el tipo de...
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Time = 0.001 Temperature = 30.02 Energy = 0.000E+00 Time = 0.001 Temperature = 107.10 Energy = -6.849E+02 Time = 0.002 Temperature = 196.30 Energy = -6.841E+02 Time = 0.002 Temperature = ...
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clc //initialisation of variables h1=3221.6 //kj/kg s1=7.399 //kj/kgk sf2=0.521 //kj/kgk sfg2=7.808 //kj/kgk hf2=152 //kj/kg hfg2=2415 //kj/kg t1=653 //temp in k t2=309.2 //temp in k v=0.1006*10^-2 p1=10 //pressure in bar p2=0.06 //pressure in bar h3=152 //kj/kg x=110 y=639.7 z=610 a=2015 //CALCULATIO...
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//Chapter 11_Nonlinear Circuit Application //Caption :Design Peak Detector //Example11.11: Design a positive peak detector using type uA 760 comparator that can respond to a 100 mV(pp),5 MHz sinusoidal input signal.The device has following specifications. Response time=25 ns, propagation time=12 ns, and Input bias cu...
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//How much work must be done by a heat pump when the outdoor temperature is 5 dgree and minus 10 degree //Example 5.3 clc; clear; q2=5000; //Amount of heat deliver by a pump in J T2=295; //Temperature of house in K T1=278; //Outdoor teperature in K q1=abs(q2)*(T1/T2); //Amount of heat in J w...
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clc;clear; //Example 4.4 //given data V1=0.05; P1=200; k=150; A=0.25; //calculations //Part - a V2=2*V1; x2=(V2-V1)/A;//displacement of spring F=k*x2;//compression force P2=P1+F/A;//additional pressure is equivalent the compression of spring disp(P2,'the final pressure inside the cylinder in kPa'); ...
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function [stk,txt,top]=%e2sci() // genere le code relatif a l'extraction d'une sous matrice //! // Copyright INRIA txt=[] rhs=maxi(0,abs(evstr(op(3)))-1) sn=stk(top);top=top-1 s2=stk(top) if rhs==1 then if s2(1)==':' then stk=list(sn(1)+'('+s2(1)+')','0','?','1',sn(5)) elseif sn(3)=='1' then stk=list(sn(1)+...
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//example 15.2 //design an irrigation channel in alluvial soil by Laecy's theory clc;funcprot(0); //given Q=15; //Full supply discharge f=1; //silt factor s=1/2; //side slope of channel //from Laecey regime channel (Fig.15.4(b)) B and D is obtained as; B=15.1; D=1.3...
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//Part B Chapter 4 Example 17 clc; clear; close; l=25;//m d=0.5;//mm n=10;//no. of rounds G=82;//GN/m^2 Ip=%pi/32*d^4*10^-12;//m^4 theta=2*%pi*n;//radian T=G*10^9*Ip*theta/l;//Nm disp("Torque required is "+string(T)+" Nm.");
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exec('trim/trim_f16.sci'); exec('eqm/params_f16.sci'); //[X0, controls, params] = trim_coordinated_turn(800, 1000, 0.3, -3/180*%pi); params = load_f16(); params.xcg = 0.35; params.VT_ftps = 502; params.alt_ft = 0; X0 = [ 502. 0.2391101 0.0005096 1.3665928 0.0500909 0. 0. 0. 0. 0. 0. ...
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clc //initialisation of variables V= 4000 //ft^3 W= 64 //lb w= 62.4 //lbf/ft^3 //CALCULATIONS W1= W*V/2240 V1= W1*2240/w //RESULTS printf (' volume of the dispalcement in fresh water = %.f ft^3',V1)
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//chapter 5 Ex 5 clc; clear; close; //let the value to be found out be x x=sqrt(25/16); mprintf("x=%.2f",x);
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clc clear Na=600; Za=25; Zb=50; Zc=20; Zd=40; Nad=(Zb/Za)*(Zd/Zc); Nd=Na/Nad; printf('Speed of Output Shaft= %2.1f RPM',Nd); printf('\n');
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//Initilization of variables theta1=50.5 //degree //is the angle made between BC & and BE theta2=36.87 //degree //is te angle ade between BA &BE g=9.81 //m/s^2 Wa=15*g //N Wb=40*g //N Wc=20*g //N //Calculations R2=Wc/(sind(theta1)) //N //from F.B.D of cylinder C(sum Fy=0) R4=(Wb+R2*sind(theta1))/sind(theta2) ...
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clc // Given that Ip = 53 // Angle of polarization of light // Sample Problem 9 on page no. 216 printf("\n # PROBLEM 9 # \n") I_r = 90 - Ip // Angle of refraction mu = tan(Ip*%pi/180) // Refractive index of water printf("Standard formula used \n mu=tan(Ip)\n") printf("\nAngle of refraction is %d degree. \n Refractive ...
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// Calculating the square. y = [1.2, 1, 1.9; 4, 2.6, 5; 2.3, 8, 7]; squareres = armaMat("square",y)
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// Grob's Basic Electronics 11e // Chapter No. 03 // Example No. 3_6 clc; clear; // How much current is produced by 60 V across 12 kOhms? // Given data V = 60; // Voltage=60 Volts R = 12*10^3; // Resistance=12k Ohms I = V/R; disp (I,'The Current I in Amps') disp ('i.e 5 mAmps')
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// Pregunta 6 // Aplica f a todos los elementos // de la matriz A function B = matrixfun(f,A) B = A for i = 1 : size(A,'r') for j = 1 : size(A,'c') B(i,j) = f(A(i,j)) end end endfunction // Aplica el metodo compuesto de Simpson // para aproximar la integral definida // de f e...
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 2 disp("CHAPTER 7"); disp("EXAMPLE 2"); //VARIABLE INITIALIZATION v1=400; //primary voltage in Volts v2=200; //secondary voltage in Volts I0=1; //in Amperes pf1=0.4; //power...
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// program to generate & plot a continuous time cosine wave // Exercise 1 clear; clf; clc; // clear previous graph and plots dt = 1/1000; t = -1:dt:1; A =1; f=1; Theta = %pi/4; x = A*cos(2*%pi*f*t + Theta); plot(t,x,'m'); xlabel("t","fontsize",4); ylabel("x","fontsize",4); title("Continuous Time Cosine Wave","fonts...
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//Problem 42.02: A filter section is to have a characteristic impedance at zero frequency of 600 ohm and a cut-off frequency at 5 MHz. Design (a) a low-pass T section filter, and (b) a low-pass pi section filter to meet these requirements. //initializing the variables: R0 = 600; // in ohm fc = 5E6; // in Hz /...
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clc //initialisation of variables A1=0.954*10^-4//ft^2 A2=2.082*10^-4//ft^2 p1=47.9//lb/in^2 T1=180//R Ma1=1 Ma2=2.28//plotting g1=1.4 R=53.3 //CALCULATIONS v1=49*sqrt(T1) k=(g1-1)/2 T2=T1*(k+Ma1)/(1+(k*Ma2*Ma2)) p2=p1/((T1/T2)^(g1/(g1-1))) vs2=49*sqrt(T2) v2=Ma2*vs2 W=144*p1*A1*v1/(R*T1) //RESULT...
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function secanteM(f,xi,tol,imax) //f es la función que se ingresara entre comillas //xi es un punto //tol es la tolerancia //imax es el numero maximo de iteraciones i=1; d=2; printf('+-----------+----------------------+----------------------+\n'); printf('| Iteracion | xi | error |\n...
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funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=round(sd*100)/100 dms=[d m sd] endfunction Long=75.0;//longitude in degrees GST=5+25.0/60+15.0/3600;//GST in hr LMT=5.0+40.0/60;//LMT in hr ...
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clc; clear; s = poly(0, 's'); ratio = 20; //----------------- // Part a g = 1 / (s^2 + 3*s + 2); slope = %pi / log(10); G = syslin('c', g); scf(); evans(G, 1000); x = -10:0.0001:0; y = -slope * x; plot(x, y, 'r-', 'LineWidth', 2); K = 4.437; // constant gain for 10% OS disp("K for 10 % OS = "); disp(K); //-------------...
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K V1=0.1; V3=V1; P1=10; T1=200+273; P2=3; R=0.287; G=1.4; Cv=0.718; m=(P1...
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//Ex4_13 Pg-245 clc V=20 //source voltage in V Vz=12 //zener voltage in V Vs=V-Vz //voltage across resistor in V Rs=330 //series resistance in ohm RL=1.5*10^3 //load resistance in ohm disp("Voltage across resistor ") printf(" = %.0f V \n ",Vr) disp("(1) Current through series resistor Is") Is=Vr/...
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function [newtempmultireactconc]=newtempmultireactconc(nsubsteps, nspecies, concm, n1, n2, n3,t0,t,h,dif,sourcesm,sinksm,inconsts) //cycle over each element of the array //update concentration rconsts=0; nconcm=zeros(n1,n2,n3,nspecies); ddt=dt/nsubsteps; for kk=1:nsubsteps t=t0+ddt; //t0=t0+ddt; for i...
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//chapter 16 //example 16.5 //page 683 printf("\n") printf("given") f=5*10^3;vo=5;I1=1*10^-3;Vf=.7; disp("phase shift oscillator") R1=(vo/29)/I1 R1=150;//use standard value R2=29*R1 R4=(2*Vf)/I1 R4=1.5*10^3;//use 1.5kohm standard value R5=R2-R4 R6=.4*R5 R7=.8*R5 R=R1; C=1/(2*3.14*R*f*sqrt(6))
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//Example 2.14//unknown resistance clc; clear; Z1=50//impedance of first arm(in ohm) Za=80//phase angle of first arm(in degree) Z2=125//impedance of second arm(in ohm) Z3=200//impedane of third arm(in ohm) Zc=30//phase angle of third arm(in degree) Z4=(Z2*Z3)/Z1 disp(Z4,'magnitude of Z4 arm(in ohm)=') Zd=Zc-Za disp(Zd,...
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//Example 1.7 // rating of furnance clc; clear; close; format('v',6) sh=0.1;// specific heat of steel in kcal/Kg/°C lh=26.67;//latent heat in kcal/kg mp=555;//melting point of steel °C t1=35;//initial temperture in °C e=0.8;//overall efficiency ip=5700;//input current in amperes rs=0.008;//resistance of transformer ref...
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function [txt,vnms,vtps,lcount]=cla2sci(clause,vnms,vtps) // traduit une clause (if while for select) //! // Copyright INRIA typ=clause(1) //write(6,'cla2sci '+typ(1)) level;level(1)=level(1)+1 select typ(1) case %if then ncl=size(clause) ncas=(ncl-2)/2 tg=[] level(2)=1 [t1,t2,ilst,vnms,vtps,lcount]=exp2sci(c...
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//find how 2 transformers connected in parallel share the load clc; Z1=complex(.012,.06); Z2=2*complex(.014,.045); Z=Z1+Z2; r=800; //kva rating pf=.8; S_L=r*(complex(pf,-1*sind(acosd(pf)))); S_1=S_L*Z2/Z;disp(S_1,'load by first transformer(kVA)'); S_2=S_L*Z1/Z;disp(S_2,'load by second transformer(kVA)...
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clear clc //At 338 k XA=0.581; t=1;//min //From ex 9.2 at 65 degree celcius XAe=0.89; //For a batch reactor,k1t/XAe=-ln(1-XA/Xae) k1_338=-(XAe/t)*log(1-(XA/XAe)); //At 25 degree celcius XAe1=0.993; T1=338;T2=298; R=8.314; //At 298 k XA1=0.6; t1=10;//min k1_298=-(XAe1/t1)*log(1-(XA1/XAe1)); E1=(R*log(k1...
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clear; //clc(); // Example 8.9 // Page: 189 printf("Example-8.9 Page no.-189\n\n"); //***Data***// // Here we will denote ethanol as species 'a' and water as the species 'b' x_a = 0.1238; x_b = (1-x_a); T = 85.3;//[C] Given boiling temperature // We have // x_a + x_b = 1 and y_a + y_b = 1 // ...
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Gr=0.01 m=acosh(sqrt(10^(0.1*L)-1)/sqrt(10^(0.1*Gr-1)))/acosh(W/Wc) printf("\nm=%.0f\n",m) m=3 E=log(coth(Gr/17.37)) X=sinh(E/2/m) n=3 gp=1 for p=1:1:n ap=sin((2*p-1)*%pi/2/m) bp=X^2+sin(p*%pi/m)^2 printf("\nap=%.4f\nbp=%.4f\n",ap,bp) end gp=0.62425 printf("\ng0=g4=1") printf("\np=1\tgp=0...
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load Computer.hdl, output-file AssignmentStatement.out, compare-to AssignmentStatement.cmp, output-list time%S1.4.1 reset%B2.1.2 ARegister[0]%D1.7.1 DRegister[0]%D1.7.1 pc%D0.4.0 RAM64[19]%D1.7.1 RAM64[16]%D1.7.1 RAM64[17]%D1.7.1 RAM64[18]%D1.7.1; //This program computes a + b - c and where a, b and c are variabl...
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clc// // // //Variable declaration RH=3.66*10^-4; //hall coefficient(m^3/coulomb) e=1.6*10^-19; Pn=8.93*10^-3; //resistivity(ohm m) //Calculation n=1/(RH*e); //density of charge carriers(per m^3) mew_e=RH/Pn; //mobility of charge carriers(m^2/Vs) //Result printf("\n density of charge carri...
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//------------------------------------------------ //■2013.12.14 秋山殿 // 比例到達則+対称化 //------------------------------------------------ //▼2自由度機械システムの定義 L=[1 0; 0 1]; //アクチュエータに加わる力を表す行列(正則行列) //L=[1 3; 0 0]; //アクチュエータに加わる力を表す行列(正則でない正方行列) m1=1; m2=2; //質量 k1=1; k2=2; //ばね定数 d1=1; d2=2; //減衰定数 M=[m1 0; 0 m2]...
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function t=trace(a) // trace - computes the trace of a matrix select type(a) case 1 then [m,n]=size(a) if m<>n then error('the argument of trace must be a square matrix');end t=sum(diag(a)) case 2 then [m,n]=size(a) if m<>n then error('the argument of trace must be a square matrix');end t=sum(diag(a)) //-...
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//reglaTrapecio(fn,a,b). Aplica método del trapecio a una función fn de a hasta b. function y = reglaTrapecio(fn, a, b) h = b-a; y = h/2 * (fn(a) + fn(b)); endfunction //reglaSimpson(fn,a,b). Aplica método del Simpson a una función fn de a hasta b. function y = reglaSimpson(fn, a, b) h = (b-a)/2; med =...
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//Ex4_37 clc; // Given: a=10*10^7;// rate t=15;// h // Soution: A30=a*(1-(0.5)^(2));// dps A45=A30*((0.5)^(3));// dps printf("The residual activity in the sample is %f dps",A45)
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function bitor_demo() a = uint8(12); b = uint8(39); c = bitor(a,b); disp(c); d = uint8([11 10 9;8 7 16;7 5 6]); e = uint8([13 9 10;7 5 3;10 8 3]); f = bitor(d,e); disp(f); aa = uint16(8); bb = uint16(4); cc = bitor(aa,bb); disp(cc); dd = uint16([1 4 6;2 10 8;2 12 16])...
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file1 qwertyuioyuiop qwertyuio some space and some more space .
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//Mission B2 //On récupère l'image. pathname = "C:\Users\Jean-Guillaume P\Documents\Exia\A2\Projets\Imagerie\ExoLife\Images\Mission_B\GD61.pbm"; img_in = readpbm(pathname); //Histogramme de l'image. histogramme = histogrammeFct(img_in); // Normalisation minHisto = debutHistogramme(histogramme); maxHisto = finHi...
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// Example 1.8.sensitivity of gauge clc, clear // given : C=60; // calibration pressure F=(300*%pi)/180; //full scale deflection L=F*90; // length of scale S=L/C; disp(S,"sensitivity,S = (mm/pa)") //answer is calculated in the form of pi in the textbook
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a a l t o n e n ア ー ル ト ネ ン a b b a d i e ア バ デ ィ a b b a g n a n o ア バ ニ ャ ー ノ a b d u r a k h m a n ア ブ ド ゥ ル ア ハ マ ン a b e r t ア ー ベ ル ト a b r a s i m o v ア ブ ラ シ モ フ a c h a r d ア シ ャ ー ル a c h e a m p o n g ア チ ャ ン ポ ン a d a エ イ ダ a d a k ア ダ ッ ク a d a m ア ダ ム a d a m ア ダ ン a d a m ア ー ダ ム a d a m o v i c h ア ダ モ ...
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 1-Properties of Fluid // Problem 1.12 //Given Data Set in the Problem kin_visc=6*10^-4 SG=1.9 dens_water=1000 //Calculations dens_liquid=SG*dens_water visc=dens_liquid*kin_visc //Kinematic viscosity=Dynam...
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//Example 2.25 //one dimensional character array letter=['c','a','l','i','f','o','r','n','i','a']; //size displays the size of array as [start index. end index] [s,e]=size(letter); printf("Element Number Subscript Value Array Element Corresponding data Item"); //in c the subscript start fr...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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// 08.05.30 function Out=PointonCurve(T,PtL) Eps=10^(-4); N=Trunc(T+Eps); S=max(T-N,0); // PtL=Plt; if N==size(PtL,1) Out=PtL(N,:); else Pa=PtL(N,:);; Pb=PtL(N+1,:); Out=(1-S)*Pa+S*Pb; end endfunction
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 2: CONSTANTS OF OVERHEAD TRANSMISSION LINES // EXAMPLE : 2.20 : // Page number 117-118 clear ; clc ; close ; // Clear th...
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clc L=1.25*10^-4 disp("L = "+string(L)+" cm") //initializing value of length of channel. un=600 disp("un = "+string(un)+"cm^2/V-s") //initializing value of mobility of n-channel MOS transistor. Co=6.9*10^-9 disp("Co = "+string(Co)+"F/cm^2") //initializing value of capacitance per unit area . VT=0.60 disp("VT = ...
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//data W=2*%pi*10^8 //rad/s Vp=2.5*10^8 //m/s Vin=75/(50+75)*3*complex(cos(0),sin(0)) //V Iin=3/(50+75)*complex(cos(0),sin(0)) //A //formula and result printf("\nresult:-") b=W/Vp printf("\nB=%.4frad/m",b) printf("\nV=1.8*cos(2*pi*10^8*t-0.8*pi*z)\ni=0.024*cos(2*pi*10^8*t-0.8*pi*z)")
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//example1.18 clc disp("Rearrange the circuit as shown below.") disp("The 3.333ohm and 3.6ohm resistors are in series in fig 1.87(c).") r=3.333+3.6 format(8) disp(r,"Therefore, the equivalent resistance R_yz(in ohm)=")
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x= [60 62 64 65 66 67 68 70 72 74]; y= [63.6 65.2 66 65.5 66.9 67.1 67.4 68.3 70.1 70]; xbar = mean(x); ybar= mean(y); n= 10; SxY = 0; for i= 1:n SxY = SxY + (x(i)*y(i)) - (xbar*ybar); end Sxx = 0; for i=1:n Sxx= Sxx + (x(i)*x(i)) - (xbar*xbar); end SYY = 0; for i=1:n SYY = SYY + (y(i)*y(...
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clc //initialisation of variables v=0.7//percent p=250//psia p1=0.50//percent h=(%pi/4)*(13.1)^2*(16.4/1728)//cu ft g=0.090//ft p2=1.8438//cu ft //CALCULATIONS W=v*h//cu ft V=g+h//cu ft V1=g+p1*h//cu ft H=V1/p2//lb //RESULTS printf('the specific volume of dry =% f lb',H)
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// // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) INRIA // // This file is distributed under the same license as the Scilab package. // // ============================================================================= // Demonstrate animation based on the evolution of a 3D surface /...
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// Exa 5.22 clc; clear; close; format('v',8) // Given data A = 10000; Beta = 0.02; Zi = 1;// in k ohm Zi = Zi * 10^3;// in ohm Zo = 10;// in k ohm Zo = Zo * 10^3;// in ohm // The input impedance Zif = Zi*(1+(A*Beta));// in ohm Zif= Zif*10^-3;// in k ohm disp(Zif,"The input impedance in k ohm is"); // T...
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clc //initialization of new variables clear w=2 //m u=100 //km/h r=1.2 //kg/m^3 mu=1.81*10^-5 //calculations D=w Re=r*u*D/(3.6*mu) St=0.23 //based on Re f=St*u/(3.6*D) l=u/(3.6*f) //results printf('Oscillation frequency is %.2f Hz',f) printf('\n The distance between two cycles is %.2f m',l)
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(set-strategy depth) (unwatch all) ; incrrset.clp test (clear) (open "Results//incrrset.rsl" incrrset "w") (load "compline.clp") (load "incrrset.clp") (progn (dribble-on "Actual//incrrset.out") (testit) (dribble-off)) (printout incrrset "incrrset.clp differences are as follows:" crlf) (compare-files "Expected//incrrset...
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// File name: projects/02/HalfAdder.tst load HalfAdder.hdl, output-file HalfAdder.out, compare-to HalfAdder.cmp, output-list a%B3.1.3 b%B3.1.3 sum%B3.1.3 carry%B3.1.3; set a 0, set b 0, eval, output; set a 0, set b 1, eval, output; set a 1, set b 0, eval, output; set a 1, set b 1, eval, ou...
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//Section-6,Example-2,Page no.-P.42 //To calculate the minimum partial pressure of methane to achieve the following condition. clc; n_M=(21*10^-3)/16 n_B=100/78 x_M=n_M/(n_M+n_B) K_M=4.27*10^5 p_M=x_M*K_M disp(p_M,'Required partial pressure(Torr)')
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clc,clear printf('Example 2.4\n\n') Pole=4 A=Pole //for lap winding V=230,R_a=0.8 //Armature resistance N_0=1000 //no load speed in rpm Z=540 //number of armature conductors phi=25*10^-3 //flux per pole in weber E_b0 = phi*Pole*N_0*Z/(60*A) //induced emf //part(i) printf('(i)Induced e.m.f = %.0f V\n',E_b...
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//Example_a_5_13 page no:214 clc; Vm=15; Im=8.5; omega=200; R=Vm/(Im*sqrt(2)); C=1/(omega*R); disp(R,"the resistance in the circuit is (in ohm)"); disp(C,"the capacitance in the circuit is (in F)");
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// Scilab Code Ex8.8: Page-432 (2011) clc;clear; v = 3700;....// Velocity of ultrasonic beam in copper, m/s t = 1e-006;....// Delay time for ultrasonic beam, s L = v*t; // // Length of a copper wire required for a delay, m printf("\nThe length of a copper wire required for a delay = %6.4f m", L); // Result ...
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function [classe]=classifieur_barycentre(attributs_normalises,img_gris,moyenne,ecart_type,num_classe) C=zeros(1,4); [aire,perimetre,longueur,largeur]=AttributsForme(img_gris); res=[aire,perimetre,longueur,largeur]; for i=1:4 res(i)=(res(i)-moyenne(i))./ecart_type(i); end l=1; f...
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time -g 0 -m 0 -i 50000 boardsize 6 genmove w undo genmove w undo genmove w undo genmove w undo genmove w quit
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// Alberto Oporto Ames 100% // Una función para una función el ejercicio R function [R] = Rmat(u, theta) R = zeros(3,3) ux=u(1) uy=u(2) uz=u(3) R(1,1) = cosd(theta) + ux^2*(1-cosd(theta)) R(1,2) = ux*uy*(1-cosd(theta)) - uz*sind(theta) R(1,3) = ux*uz*(1-cosd(theta)) + uy*sind(thet...
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g1=15 g1 = 15. g2=35 g2 = 35. g3=45 g3 = 45. r1=g1*%pi/180 r1 = 0.2617994 r2=g2*%pi/180 r2 = 0.6108652 r3=g3*%pi/180 r3 = 0.7853982 A=[cos(r1) -sin(r1) 0;sin(r1) cos(r1) 0;0 0 1] A = 0.9659258 -0.258819 0. 0.258819 0.9659258 0. 0. ...
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//Exam:5.7 clc; clear; close; E_f=3.75;//Fermi energy(in eV) e=1.602*10^-19; W_f=e*E_f;//fermi energy in joules t=10^-14;//mean free time between the collisions(in second) m=9.1*10^-31;//mass of electron v_f=(2*W_f/m)^(1/2);//maximum velocity of an electron in a metal(in m/s) mobility=e*t/m;//mobility of elec...
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// Example 2.39.a: Stability factor clc; clear; close; R1=500;//Resistance in killo ohms Rc=500;//Collector resistance in killo ohms R2=5000;//Resistance in killo ohms Vcc=20;// Colector voltage in volts Beta=75; Rc=6.2;// Collector resistance in killo ohms Re=90;// Emitter resistance in ohms Rb=690;// Base ...
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function unhilite_obj(o) // if o(1)=='Block' then graphics=o(2); [orig,sz]=graphics(1:2) thick=xget('thickness') xset('thickness',6*thick); xrect(orig(1),orig(2)+sz(2),sz(1),sz(2)); xset('thickness',thick); elseif o(1)=='Link' then xx=o(2) yy=o(3) thick=xget('thickness') xset('thickness',6*thick) ...
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//subtraction using 2's complement// //Example 22.a// //subtraction using 2's complement// clc //clears the console// clear //clears all exisiting variables// a=bin2dec('11011') b=bin2dec('11001') x=bitcmp(b,5) //complement of the numbers// z=1 u=x+z //1 is added to the complements// w=u+a w=w-bin2dec...
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clc,clear printf('Example 3.8\n\n') V=500 Io=5 //no load current R_a=0.5,R_sh=250//resistance of armature and field circuits I=100 //current at unknown efficiency P_in_NL=V*Io //no load input I_sh=V/R_sh Iao=Io-I_sh arm_cu_loss_no_load=R_a*Iao^2 //No load armature copper loss constant_losses= P_in_NL-...
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//chapter 9 //example9.6 //page 335 fc=1.5*10^3; x=1.414;//damping factor C1=2/x; disp(C1) C2=x/2; disp(C2) R1=1;R2=1; Rf=2; Wc=1; Wc=2*3.14*fc; disp(Wc) R=R1/Wc;//to keep C1 nad C2 unchanged disp(R) Rf=2*R R1=R*10^7;R2=R*10^7;//for maiking filter for practical use disp(R1,R2) C1=C1*10^-7;C2=C2*10^-7...
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//Page Number: 3.14 //Example 3.7 clc; //Given //(a)efficiency=((u^2)/(2+(u^2))) u=0.5; n=((u^2)/(2+(u^2))); np=n*100; disp("%", np, "Efficiney: "); //(b)nmax, //nmax occurs at u=1; u1=1; nmax=((u1^2)/(2+(u1^2))); nmaxp=nmax*100; disp("%", nmaxp, "Efficiney max: "); // test
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clc; clear all; x=input('Enter the 4-Bit sequence: '); d=length(x); N=(2^d)-1; disp('The Period of PN sequence is: '); disp(N); xoring=0; disp(" x1 x2 x3 x4 xoring"); printf(' Initial %d %d %d %d %d \n ',x(1),x(2),x(3),x(4),xoring); for i=1:N printf('Shift %d \n',i); xor...
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clc; clear; function y=f(x) y=x^10 - 1; endfunction x1=0; x2=1.3; xt=1; //using bisection method disp("BISECTION METHOD:") xr=(x1+x2)/2; et=abs(xr-xt)/xt*100;//error disp(1,"Iteration:") disp(x1,"xl:") disp(x2,"xu:") disp(xr,"xr:") disp(et,"et(%):") disp("----------------------------------------"...
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clc,clear printf('Example 1.17\n\n') P=4 //number of poles A=P // because of lap wound N=750 //speed in rpm Z=720 //number of armature conductors phi=30*10^-3 //flux per pole in weber R_sh=200,R_a=0.4,R_L=15, //resistance of shunt winding,armature,series field E=phi*P*N*Z/(60*A) //generated emf //solving ...
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// CALCULA UMA APROXIMACAO x(k), PARA UMA RAIZ DE f NO INTERVALO [a,b] // f: função criada em outro arquivo // [a,b]: intervalo no qual f(a)*f(b) < 0 // eps1: precisão utilizada no critério de parada function bissecao(f,a,b,eps1) if ((f(a).*f(b))>0.0) then printf("\n \n") printf("f( %g )*f( %g )>0 \n \n"...
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clc; clear all; d=2.588*1e-3;//diameter of wire s=300*1e-3//spacing between wires r=d/2;//radius of wire Z0=276*log10(s/r);//characteristic impedence of line disp(Z0,'characteristic impedence of line is');
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//inverse laplace transform n=poly([4],'s','coeff') d=poly([4 8 1],'s','coeff') //w=2,damping ratio=2 G=n/d; disp(G,"G(s)=") pf=pfss(G) disp(pf,"G(s)=") syms s t g1=ilaplace(pf(1),s,t) g2=ilaplace(pf(2),s,t) disp(g1+g2,"g(t)=")
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//To find length of the medium //Example no 1.9 //Page no. 30 clc; clear all; bandwidth=100*10^9; //Bandwidth of optical signal w=2*%pi*bandwidth; //Bandwidth of optical signal in rad/s T=3.14*10^(-12); //Delay between minimum...
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/test/testcases/directed/rred4.tst
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rred4.tst
; rred4.tst ; ; Copyright (c) 1999-2018, Arm Limited. ; SPDX-License-Identifier: MIT func=rred op1=5ee8da6e.555f15d0 result=3ccad12f.2b4c25d3.eaa res2=00000001 errno=0 func=rred op1=5ef7833f.a59d0dfd result=3c919ca2.3f5c493c.c76 res2=00000003 errno=0 func=rred op1=5efb3542.79418f04 result=bca803d2.ba28019c.b3f res2=00...