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//Ex 5.1 clc; clear; close; format('v',5); V1=2;V2=3;V3=4;V4=5;//V R1=10;R2=15;R3=22;R4=50;//kohm Rf=10;//kohm Vout=-Rf/R1*V1-Rf/R2*V2-Rf/R3*V3-Rf/R4*V4;//V disp(Vout,"Output voltage of the circuit(V)");;
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//Caption:calculate the generated emf //Exam:2.5 clc; clear; close; S_1=80;//Number of armature slots S_2=6;//Number of conductor per slot Z=S_1*S_2;//Number of armature conductors F=50;//Flux per pole(in mWb) F_1=F*10^-3;//(in Wb) P=6;//Number of poles A=P;//Number of parallel paths N=1200;//armature spee...
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function s=%sslss(d1,s2) //s=d1-s2 [a2,b2,c2,d2,x2,dom2]=s2(2:7), s=list('lss',a2,-b2,c2,d1-d2,x2,dom2),
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clc clear //INPUT DATA p0=1;//suction pressure in bar p1=1;//pressure in bar p2=6;//delivery pressure in bar v0=5;//volume in m^3/min t0=288;//suction temperature in K t1=300;//initial temperature in K k=0.05;//Clearance n=1.3;//index of compression N=150;//speed in rpm //CALCULATIONS va=(p0/p1)*(t1/t0)*...
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errcatch(-1,"stop");mode(2);//Ex19_12 Pg-962 oct='257'; //binary input dec=oct2dec(oct) //decimal output disp("The decimal equivalent of 257 is") disp(dec) exit();
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//Chapter-13, Example 13.18, Page 393 //============================================================================= clc clear //INPUT DATA Ib=15*10^-3;//base current in A b=150;//common-emitter DC current gain //CALCULATIONS Ic=b*Ib;//collector current in A Ie=Ic+Ib;//emitter current in A a=b/(1+b);//common...
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//Example13.3 // to calculate the frequency of a wein bridge oscillator clc; clear; close; C = 2400*10^-12 ; // F R = 10*10^3 ; // ohm // the oscillator frequency of practical RC phase shift oscillator f f = 1/(2*%pi*R*C); disp('the oscillator frequency of practical RC phase shift oscillator f is = '+strin...
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//Ex:4.40 clc; clear; close; f=6000;// frequency in MHz y=300/f;// wavelength in m A=%pi*100*0.54;// aperture area in m^2 G=(4*%pi*A)/y^2;// gain of the reflector antenna G1=10*log(G)/log(10);// gain of the reflector antenna in dB printf("The gain of the reflector antenna = %f dB", G1);
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// Scilab code: Ex3.17 : Mean energy per electron at 0K:Pg: 86 (2008) m = 9.1e-031; // Mass of an electron, kg a = 50e-010; // Length of molecule, m h = 6.624e-034; // Plancks constant, joule second E = h^2/(8*m*a^2); // Energy per electron, joule printf("\nThe mean energy per electron at 0K = %3.1e eV...
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//problem 6 pagenumber 2.90 //given format(6); r1=2e3;//ohm rf1=8e3;//ohm A=45;//open loop gain a=1+(rf1/r1);//Nonverting gain gain=A/(1+A/a); disp( 'Gain = '+string(gain));//no unit
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//Exa 4.16 format('v',7) clc; clear; close; //Given data I_CEo = 21;// in µA I_CBO = 1.1;// in µA // Value of beta_dc beta_dc = round((I_CEo/I_CBO) - 1); disp(beta_dc,"Value of beta_dc is"); // The value of alpha_dc alpha_dc = beta_dc/(1 + beta_dc); disp(alpha_dc,"The value of alpha_dc is");
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clc,clear printf('Example 2.3\n\n') Pole=4 A=Pole //for lap winding Z=480//number of armature conductors phi=20*10^-3 //flux per pole in weber I_a=50 //Armature current T_a = 0.159*phi*I_a*Pole*Z/A //Gross torque developed by armature printf('Gross torque developed by armature is %.3f N-m',T_a)
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//Fluid Systems - By - Shiv Kumar //Chapter 4 - Pelton Turbine (Impulse Turbine) //Example 4.16 clc clear //Given Data:- P=4900; //Shaft Power, kW P_mr=100; //Power absorbed in mechanical resistance, kW eta_H=92/100; //Hydraulic Efficiency P_n=415; ...
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv //Biegler & Tjoa, 1993 //“A parallel implementation for parameter estimation with implicit models” //Annals of Operations Research, V42, Issue 1, pp 1-...
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//Network Theorem 2 //pg no 3.25 //example 3.22 disp("removing the 10 Ohm resistor from the network"); disp("Applying KVL to mesh 1"); disp("4*I1-I2=-25");....//equation 1 disp("Applying KVL to mesh 2"); disp("-I1+4*I2=10");....//equation 2 A=[4 -1;-1 4];//solving the equations in matrix form B=[-25 10]' X=i...
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close; N =100; b = rand(1,N,'n'); // criando vetor de número aleatórios b = sign(b); // transforma em -1 e 1 b = 0.5 * (b +1); // transformar em 0 e 1 p = ones(1,10); v = []; var = 0.2; // determina o ruido for k=1:N v = [v,p*b(k)], end; n = sqrt(var)*rand(v,'n' ); vn = (v+n); figure; subplot(2,2,1); plot (v*1.01 ...
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//example a=realp('a',5,-14,15,10) //non zero free values considered as 1(true) disp(a) b=realp('b',10) disp(b) b.value=50 disp(b)
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// Exa 2.3 clc; clear; close; // Given data Am= 25.34;// in watt del_A= -0.11;// in watt A= Am-del_A; disp(A,"True value in watt")
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//chapter 5 //example 5.15 //page 214 printf("\n") printf("given") Vce=9;Ve=4;Ic=4*10^-3;Vcc=18; Ie=Ic; R4=Ve/Ie Vb=Ve+Vbe I2=Ic/10 R2=Vb/I2 disp(" with R2=12Kohm standard") R2=12*10^3; I2=Vb/R2 R1=(Vce+Ve-Vb)/I2 disp(" with R1=22kohm standard") R1=22*10^3; Vr3=Vcc-Vce-Ve R3=Vr3/(Ic+I2)
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scenario = "DFG_fMRI"; scenario_type = fMRI; scan_period = 2500; pulse_code = 20; pulses_per_scan = 1; no_logfile = false; default_font_size = 36; default_background_color = 128,128,128; active_buttons = 5; button_codes = 1,2,33,44,55; response_logging = log_active; # code 1 = left button # code 2 = right button # cod...
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//Rodríguez Montiel Moises Ulises //2MN51 function X = jacobi(A, B, fx) [m,n] = size(A) iter = 0 if (m <> n) then error("La matriz no es cuadrada.") end e = 5*10^-fx X = zeros(n, 1); y=[]; fin=%F; while fin==%F fin=%T; for i=1:1:n y(i)=B(i); ...
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Xijold = [220 251 226 246 260; 244 235 232 242 225; 252 272 250 238 256]; Xij = Xijold - 220; m=3; n=5; Xidot = zeros(3,1); for i=1:m for j=1:n Xidot(i)=Xidot(i) + Xij(i,j); end end Xidot = Xidot/n; Xdotdot = sum(Xidot)/m; SSb=0; for i=1:m SSb = SSb + (Xidot(i)-Xdotdot)^2; end SSb = ...
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// Scilab Code Ex 10.9 Electrical Conductivity of Cu: Page-345 (2010) e = 1.6D-19; // Electronic charge, C N = 6.023D+23; // Avogardro's number d = 8920; // Density of Copper, kg per metre cube A = 63.5; // Atomic weight of copper, g/mole I = 10; // Current through uniform copper wir, ...
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clc // Given that mu1 = 1.6 // refractive index for core mu2 = 1.5 // refractive index for cladding // Sample Problem 2 on page no. 5.16 printf("\n # PROBLEM 2 # \n") NA = sqrt(mu1^2 - mu2^2)//calculation for numerical aperture theta_0 = asin(NA) * (180 / %pi)//calculation for maximum incidence angle printf("Standard ...
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clear; clc; //Example 3.5 b=100; Vbe=0.7;//(V) Vce=0.2;//(V) Vbb=8;//(v) Rb=220;//(KOhm) Ib=(Vbb-Vbe)/Rb printf('\nbase current=%f mA\n',Ib) //transistor in active region Ic=b*Ib; printf('\ncollector current=%.3f mA\n',Ic) Vcc=10;//(V) Rc=4;//(KOhm) Vce=Vcc-Ic*Rc; printf('\ncollector emitter voltage=%.2...
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//example 13.1 clc; funcprot(0); Sw=1; Z=2; deltaSf=0.0033*Z*Sw*1000; disp(deltaSf,"free surface swell in mm");
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clear; clc; //Example - 7.36 //Page number - 270 printf("Example - 7.36 and Page number - 270\n\n"); //Given T_1 = 100 + 273.15;//[K] P_1 = 1.01325;//[bar] T_2 = 98 + 273.15;//[K] P_2 = 0.943;//[bar] V_vap = 1.789;//[m^(3)] - Volume in vapour phase vessel_vol = 1.673;//[m^(3)] - Volume of the vessel R =...
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//skipped groundPlane_transform //skipped Manipulator1 //skipped UniversalManip //skipped CubeCompass ///////////////////////////////////////////// // object_Trim_Char_x_1_1__ ///////////////////////////////////////////// #if 0 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1 #endif DX3DMATERIAL_STA...
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//example-3.43 pg no-200-201 Ip=11<36.87; PL=5808; QL=4356; Pm=6000; Qm=8000; P=PL+Pm; Q=Qm-QL; S=((P*P)+(Q*Q))^0.5; X=P/S; //POWER FACTOR disp('i)ACTIVE POWER (P) = '+string (P)+' W') disp('i)REACTIVE POWER (Q) = '+string (Q)+' vars(inductive)') disp('i)APPARENT POWER (S) = '+string (S)+' ...
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clear; clc; printf("\t Example 5.4\n"); //part(i) pa=13.3; //pressure in kpa pa2=20.6; //vapour pressure at 60 degree pt=106.6 //total pressure in kpa y=pa/(pt-pa); //absolute molal humidity y_bar=y*(18/28.84); //relative humi...
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//water chemistry// //example 7.7// W1=160;//Ca2+ in water in mg/l or ppm// W2=72;//Mg2+ in water in mg/l or ppm// W3=732;//HCO3- in water in mg/l or ppm// W4=44;//CO2 in water in mg/l or ppm// W5=16.4;//NaAlO2 in water in mg/l or ppm// W6=30;//(CO3)2- in water in mg/l or ppm// W7=17;//OH- in water in mg/l or p...
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//Solving by LU decomposition method clc clear function[x]=crout(A,b) [n,m]=size(A) L=zeros(A) U=zeros(A) for i=1:n L(i,1)=A(i,1) U(i,i)=1 end; for j=2:n for k=2:n //This loop is for checking pivoting if L(1,1)==0 temp=L(1,:) L(1,:)=L(...
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clear; n = 6; // # of cells in a row m = 200; // # of steps cp = 1; cr = -1; con_coef = 1; pos_coef = 1; x = linspace(0,9,n);// initial values y = linspace(0,9,n);// initial values if 1==2 then for i=1:n for j=1:n p(i,j)=n-i//abs(cos(j)); r(i,j)=1//abs(sin(i)*cos(j)); end end end...
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clear clc disp("example 3.5") ic=120 //installed capacity ccppkw=40000 ///capital cost of plant iand=0.15 //interest and depreciation fco=0.64 //fuel consumption fc=1.5//fuel cost oc=50*10^6 //operating cost pl=100//peak load lf=0.6 //load factor al=lf*pl//avarrage load printf(" average load %dMW",al) eg=a...
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//clc() x = [3,4.5,7,9]; fx = [2.5,1,2.5,0.5]; //we get the following equations for cubic splines //8*f"(4.5) + 2.5*f"(7) = 9.6 //2.5*f"(4.5) + 9*f"(7) = -9.6 //above two equations give m = 1.67909;//(m = f"(4.5)) n = -1.53308;//(n = f"(7)) //this values can be used to yield the final equation //f1(x) = 0.18...
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//chapter10,Example10_2,pg 271 R=0.35 n=1.38*10^7 m=1.67*10^-27 q=1.6*10^-19 B=(2*%pi*n*m)/q E=((B^2)*(q^2)*(R^2))/(2*m) E=E/q printf("magnetic field induction\n") printf("B=%.2f wb/m2",B) printf("\nmaximum energy of proton\n") printf("E=%.2f ev",E)
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clear; clc; //Example4.8[Cooling of a Short Brass Cylinder] //Given:- Ti=120;//Initial Temperature[degree Celcius] T_ambient=25;//Temperature of atmospheric air[degree Celcius] h=60;//convetcion heat transfer coefficient[W/m^2.degree Celcius] r=0.05;//radius of cylinder[m] L=0.06;//thickness[m] a=3.39*(10^(-...
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//ques-4.3 //Calculating COD of effluent sample clc V=25;//volume of effluent (in mL) v=8.3;//volume of dichromate (in mL) M=0.001;//molarity of dichromate //1000mL of 0.001M dichromate = 6x8x0.001g of oxygen O=(6*8*M*v)/1000;//oxygen in 25mL sample (in g) O=O*(1000/25);//oxygen in 1L sample (in g) printf("COD...
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// Function Name: rcond // Return the 1-norm estimate of the reciprocal of the condition number of square matrix A // Values close to 1 suggest that A is well-conditioned // Values close to 0 suggest that A is badly conditioned // Calculating the rcond inputMat = [ 1, 2, 3; 4, 5, 6; 7, 8, 1;] result = armaMat...
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// Computation of concentration of all the species in solution of Oxalic acid clear; clc; printf("\t Example 15.11\n"); InitC2H2O4=0.1;//Initial concentration of C2H2O4 solution, M //Let 'x1' be the equilibrium concentration of the [H+] and [C2HO4-] ions, M //First stage of ionisation Kw=10^-14;//ion...
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// Example6.9 // determine Vo when 1) VI1 = 2 V VI2 = -2 V and 2) VI1 = 2 V VI2 = 2 V // and common mode rejection ratio CMRR clc; clear; close; R1 = 10*10^3 ; // ohm R2 = 20*10^3 ; // ohm R3 = 10*10^3 ; // ohm R4 = 22*10^3 ; // ohm // the output of the difference ampl...
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// Example 8_2 clc;funcprot(0); // Given data D=2;// The diameter of the pipe in inch h_in=10;// Elevation in m Q=425;// The volumetric flow rate in gal/min g=9.807;// The acceleration due to gravity in m/s^2 // Calculation D=D*2.54*10^-2;// m Q=(Q*3.785*10^-3)/60;// The volumetric flow rate in m^3/s V=(4*Q...
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clear all; clc; disp("Ex 2_8") f=100 b1=60//given angle theta in degrees b=b1*%pi/180 g1=45//given angle theta in degrees g=g1*%pi/180 p=sqrt(1-(cos(b)^2)-(cos(g)^2)) p1=p*(-1) printf('\n\ncos(alpha) = + or - %.1f',p) l1=acos(p) lf=l1*180/%pi l2=acos(p1) lf1=l2*180/%pi printf('\n\n alpha = %.0f degrees or %.0f degrees'...
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//EXAMPLE 1-11 PG NO-21 R55=58; //resistance R15=50; //Resistance T1=55; //Temperature T2=15; //Temperature A15=[(R55/R15)-1]/(T1-T2); //alpha 15 disp('i) ALPHA (A15) = '+string (A15)+' ')...
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clear /** * Se diz pra extrapolar/interpolar em menos pontos, * só meter menos pontos nnos vetores abaixo */ x=[-1 0 1 2]' y=[1 2 3 2]' n=length(x) plot(x,y,'ro-'),xgrid // Monta matriz de Vandermonde for i=1:n for j=1:n V(i,j)=x(i)^(j-1) end end a=inv(V)*y X=0.01 // x para interpolar // Caso dese...
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clc // Process a-b Qab = 0 // Heat transfer along the path ab in kJ/ min Wab = 2170 // Work transfer along the path ab in kJ/min Eab = Qab-Wab // Change in internal energy along the path ab in kJ/min // Process b-c Qbc = 21000 // Heat transfer along the path bc in kJ/ min Wbc = 0 // Work transfer along the path ...
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//Example 1.15.2 // to find maximum core diameter for single mode.. clc; clear; n1= 1.5; //RI of core.. del= 0.01; //Relative RI difference... lamda= 1.3; //Wavelength of operation... V= 2.4*sqrt(2); // Maximum value of V for GRIN... a= V*lamda/(2*%pi*n1*sqrt(2*del)); //radius of core.. printf('The...
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prueba.sce
//************** Ejecucion metodo busqueda incremental ************** clear all; clc; function fx = funcion(x) fx = sin(10*x)+cos(3*x); endfunction // Realice pruebas con ndivs = 50 y ndivs = 100 y encuentre las diferencias xl = 3, xu = 6, ndivs = 50 [x, fx, xraices, fxraices] = busquedaincremental(funci...
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//------------------------------------------------------------------------------ // Détermination d'un critère de stabilité du processus par méthode graphique //------------------------------------------------------------------------------ // Paramètres lambdaMin = 0.4 lambdaMax = 0.5 step = 0.02 mu = 0.5 tmax = 4000 ...
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i1=4*10^(-3); i2=6*10^(-3); v=12; r1=2*10^3; r2=4*10^3; r4=10^3; rl=3*10^3; v1=i1*r1; v2=i2*r2; i=(v2-v1-v)/(r1+r2+r4+rl); disp("the load current (in mA) is"); disp(i*10^3);
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clc; clear all; //page no 158 //prob no. 5.7 fLO=40; //MHz //function for ascending pulse function V=pulse_a() V=[] for i=1:.005:2 V=[V i] end endfunction //function for descending pulse function V=pulse_d() V=[] for i=2:-.005:1 V=[V i] end endfunction /...
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//example 1.9 //page 27 clc; funcprot(0); //initialisation of variable mu=0.44; N=300; t=0.00025;//thickness R1=0.15;//radius R2=0.1;//radius pi=3.14; T=pi^2*mu*N/60/t*(R1^4-R2^4); P=T*2*pi*N/60 disp(P,"power lost in (watts)"); clear
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//to find the raise time of the displayed waveform // example 9-7 in page 262 clc; //Data given Rs=3.3e+3; Ci=15D-12;//source resistance in ohm and input capacitance in farad tri=[109e-9 327e-9];//input raise times in seconds for which trd is to be determined //calculations tuo=2.2*Rs*Ci;//tuo is the rise time i...
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// mathematical constants a=cos(%pi) b=log(%e) // complex numbers %i^2 // =-1 (1+%i)^2 // =2i c=exp(%i*%pi) // =-1 (within rounding error!) ans // contains the result of 2*%i // NaN, infinity and machine epsilon typeof(%eps) // machine epsilon x=10^155,x^2 // >10^309 yields infinity %inf-...
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//each solution to the equation can be viewed as a combination of objects r=18; //number of objects M=3; //kinds of object m=factorial(r+(M-1))/(factorial(r+(M-1)-(M-1))*factorial(M-1)); disp(m,'number of non negative integer solutions of the given equation x+y+z=18')
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// Solving Using Shooting Method // u''-(1-x/5)uu'=x, u(1)=2, u(3)=-1) function ydot=f(t, y), ydot=[y(2); t+y(1)*y(2)*(1-t/5);] endfunction y0=[2,-1.5]';t0=1;t=1:0.2:3; y=ode(['rkf'],y0,t0,t,f) y1=[2,-3]' U=ode(['rkf'],y1,t0,t,f) y2=[2,-2.2137]' V=ode(['rkf'],y2,t0,t,f) y11=[2,-1.9460]' U1...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/04/mult/Mult.tst load Division.asm, output-file Division.out, compare-to Division.cmp, output-list RAM[13]%D2.8.2 RAM[14]%D2.8.2 RAM[15]%D2.8.2; set RAM[13] 4, ...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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inf = float('inf') plant_pvt_init_data = None initial_set = [[-1, -1], [1, 1]] error_set = [[5, 5], [6, 6]] # x\in[5,6], y\in[5,6] grid_eps = [0.1, 0.1] num_samples = 1 delta_t = 0.2 T = 3.0 plant_description = 'python' plant_path = 'const2.py' ci = [[], []] pi = [[],[]] ##########################################...
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//Example 5_35 clc; clear; close; format('v',4); //given data : Ez=2*10^7;///V/m //Vz=epsilon*Ez^2/(2*e*NA) //e*NA=sigp/mu_p; as sigp=NA*e*mu_p epsilon=16/(36*%pi*10^9);//F/m mu_p=1800;//cm^2/V-s sigp=poly(0,'sigp');//Notation : sigp=sigma_p Vz=epsilon*Ez^2/2*mu_p*10^-6/sigp;//V disp(Vz,"(a) Breakdown Vol...
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clear; clc; //Example 6.2 Vgsq=2.12; Vdd=5; Rd=2.5; Vtn=1; Kn=0.8; //let lambda=y y=0.02;//V^-1 Idq=Kn*(Vgsq-Vtn)^2; printf('\ndrain current=%.3f mA\n',Idq) Vdsq=Vdd-Idq*Rd; printf('\ndrain to source voltage=%.3f V\n',Vdsq) Vgs=1.82; Vgs-Vtn //since Vdsq>Vgs-Vtn transistor is biased in saturation g_m=2...
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errcatch(-1,"stop");mode(2);//Example 1_25 ; ; //To find the value of the slit width lemda=6500 //units in angstroam theta=30 //units in degrees a=lemda/sin(theta*%pi/180) printf("The value of the slit is %.0f angstroam",a) exit();
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clc; clear; h=6.63*10^-34 //plancks constant in J-s c=3*10^8 //velocity of light in m/s lambda=180*10^-9 //wavelength in m W=2*1.6*10^-19 //work function in Joule m=9.1*10^-31 //mass in kg e=1.6*10^-19 //charge in C B=5*10^-5 //magnetic flux density in Tesla //calculation E=((h*c)/lambda)-W //kinetic energ...
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//Example 2.4 //Solving Simultaneous Linear Equation //Page 36 clc;close;clear; //eq1= 5x-331y=3.5 //eq2= 6x-397y=5.2 A=[5,-331;6,-397]; B=[3.5;5.2]; C=inv(A)*B; //finding value by multiplying inverse with values disp(C(1,1),'Value of x='); disp(C(2,1),'Value of y=');
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global bcd_file_name folder_name; function dir_callback() disp(" "); endfunction function bcd_folder_name_callback() global folder_name; folder_name_obj = findobj('tag','bcd_folder_name'); folder_name = folder_name_obj.string; endfunction function bcd_file_name_callback() global bcd_file_name; ...
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clc; clear; v1=100;//mi/hr ht=10000;//ft //from standard table for static pressure at an altitude p1=1456//lb/ft^2(abs) P1=1456*0.006947;//psi d=0.001756;//slugs/ft^3 //1 mi/hr = 1.467 ft/s p2=p1+(d*(v1*1.467)^2/2);//lb/ft^3 //in terms of gage pressure p2g p2g=p2-p1;//lb/ft^2 //1lb/ft^2 = 0.006947 psi P2=...
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//pathname=get_absolute_file_path('8.24.sce') //filename=pathname+filesep()+'8.24-data.sci' //exec(filename) //Turbine efficiency: nt=0.80 //Mechanical efficiency: nm=0.90 //Power delivered by turbine(in kW): p=720 //From steam tables: h1=3045.8 //kJ/kg s1=7.0317 //kJ/kg.K s4=s1 x4=0.841 h4=2192.24 //kJ/k...
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> storage_init ciyam > session_variable @attached_file_path . > pe guest 20120102 100 105100 "-v=@async=false,@message=Removing All Packages..." guest_model =1.0 -105450 Removing All Packages... > pd guest 20120102 100 105100 guest_model >
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2 14:0.1111111111111111 21:1.0 41:0.2 81:0.3333333333333333 110:0.3333333333333333 141:0.5 269:0.5 289:1.0 343:1.0 544:1.0 912:1.0 1237:1.0 1276:1.0 1319:1.0 2 6:1.0 141:0.5 424:1.0 2 6:3.0 9:1.0 14:0.3333333333333333 16:0.014925373134328358 21:1.0 27:0.25 50:0.3333333333333333 52:0.6666666666666666 81:0.33333333333333...
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clear; clc; // Illustration 2.5 // Page: 37 printf('Illustration 2.5 - Page: 37\n\n'); // solution //***Data****// // a = mannitol b = H2O T = 293; // [K] //*****// Mb = 18.02;// [kg/kmol] // From Table 2.3 (Pg 33) Va = (0.0148*6)+(0.0037*14)+(0.0074*6); // [cubic m/kmol] viscosity = 0.001005; //...
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713812398="polish" 255027957="Polish" 1345666108="apples" 2021641141="null" 2062818015="DONUTS!" 1401642950="Tintin" 452378790="Babar" 1233559284="Bread" 225953796="abc" 908862969="null" 615516935="Babar" 449902312="Dollar" 266711480="asterix"
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PL/SQL Developer Test script 3.0 5 begin -- Call the procedure personas_por_bebedor(pbebedor => :pbebedor, p_recordset => :p_recordset); end; 2 pbebedor 1 Semanalmente 5 p_recordset 1 <Cursor> 116 0
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// sero.bas : demo de icse // calcul coefficients optimaux du modele simplifie 5ht-plaquette // ************************************************************** // // les doubles slash introduisent des commentaires // // contexte : tue les variables de nom reserve // Copyright INRIA exec('icse.contexte')...
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clc; T1=703;//K p1=6.8;//bar p2=1.013;//bar gama=1.4; T2=T1/[(p1/p2)^([gama-1]/gama)]; //from graph: T2s=423;//K cp=1.005; inc_ent=cp*log(T2/T2s); disp("increasi in entropy is:"); disp("kJ/kg K",-inc_ent)
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//Chapter 5: Point Source and Their Arrays //Example 5-6.2 clc; clear; //Variable Initialization Um=1 //Maximum radiation intensity (unitless) deff('z=f(x,y)','z=cos(x)*sin(x)')//Integrand(Unitless) X=[0 0;%pi/2 %pi/2;%pi/2 0]; Y=[0 0;2*%pi 2*%pi;0 2*%pi]; [I,err]=int2d(X,Y,f)//Total power radiated (relative to Um) D...
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clear clc //Given //Concentrations in mol/litre CAo=0.1;CBo=0.01;Cco=0;CAf=0.02;CBf=0.03;Ccf=0.04; //Volume in litre V=1; //Volumetric flow rate(l/min) v=1; //For mixed flow reactor CA=CAf;CB=CBf;Cc=Ccf; //Rate of reaction(mol/litre.min) rA=(CAo-CA)/(V/v); rB=(CBo-CB)/(V/v); rc=(Cco-Cc)/(V/v); printf("\n...
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//EXAMPLE 5-37 PG NO-330-331 R=8; R1=12.67; R2=4; R3=10; R4=3.077; R5=13.077; R50=9.9; //RESISTANCE AT 50 V BATTERY V=50; //VOLTAGE I1=V/R50; //CURRENT I=I1*[R/(R+R1)]; disp(' Current is (I1) = '+stri...
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clc //Example 11.4 //Calculate the Average power absorbed and average power supplied by source //From figure 11.6 //By applying mesh analysis I1mag=11.18;I1ang=-63.43;I2mag=7.071;I2ang=-45;R=2;Vleft=20;Vright=10; //Current through 2 ohm resistor printf("I1-I2=%d(%d ang) A \n",5,-90) //Average power absorbed by ...
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clc B=5*10^(-5); // /K K=8.6*10^(-12); // m^2/N v=0.114*10^(-3); //m^3/kg p2=800*10^5; //Pa p1=20*10^5; //Pa T=288; //K disp("(i) Work done on the copper = ") W=-v*K/2*(p2^2-p1^2); disp(W) disp("J/kg") disp("(ii) Change in entropy =") ds=-v*B*(p2-p1); disp(ds) disp("J/kg K") disp("(iii) The heat tran...
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// Grob's Basic Electronics 11e // Chapter No. 16 // Example No. 16_4 clc; clear; // The voltage across the charged capacitor is 20 V. Calculate C. //Given data V = 20; // Voltage=20 Volts Q = 40*10^-6; // Charge=40 uColumb C = Q/V disp (C,'The Capacitance in Farad') disp ('i.e 2 uF')
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//EXAMPLE 2-77 PG NO-114 R=sqrt(2.5^2-1.724^2)-0.69; disp('i) Resistance (R) is = '+string (R) +' ohm '); R1=sqrt(2.5^2-1.92^2)-0.384; disp('ii) Resistance (R1) is = '+string (R1) +' ohm '); r=5; PF=(0.69+R)/2.5; disp('iii) Power Factor (PF) is = '+string (PF) +' ...
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errcatch(-1,"stop");mode(2);// Exa 8.6 ; ; // Given data R_f = 0;// in V R1 = 2;// in kohm R1 = R1 * 10^3;// in ohm A_vmin = (1+(R_f/R1)); disp(A_vmin,"The minimum d loop voltage gain is"); R_f1 = 100;// in kohm R_f1 = R_f1 * 10^3;// in ohm A_vmax = (1+(R_f1/R1)); disp(A_vmax,"The maximum d loop voltage g...
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//Chapter 11 : Free Electron Theory Of Metals clear; //Variable declaration fE=0.01 //probability delE=8*10**-20 //ev to J //Calculations T=5797/log(99) //Result disp('K',T,"Temperature=")
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clear; clc; disp("--------------Example 3.9--------------") fl=0; // 0kHz fh=4; // 4kHz // example explanation printf("Figure shows a nonperiodic composite signal. It can be the signal created by a microphone or a telephone set when a word or two\nis pronounced. In this case, the composite signal cannot be period...
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//Reciprocal Exchange Mutation //Sorteia duas cidades e as troca de lugar function mutatedChromosome = ExchangeMutation(chromosome) if rand() <= mutationRate then cities = grand(1, 2, "uin", 1, citiesNumber); chromosome(cities) = chromosome([cities(1) cities(2)]); end mutatedChromosome = c...
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n=input('Enter the number'); nof=0; for i=1:n if(modulo(n,i)==0) nof=nof+1; end end if(nof==2) disp('Prime'); else disp('Composite'); end
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// Given:- P1 = 3.5 // pressure of refrigerant entering the compressor in bars T1 = 268.0 // temperature of refrigerant entering the compressor in kelvin P2 = 14.0 // pressure of refrigerant entering ...
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// Scilab Code Ex2.6 Maximum velocity of emitted electrons: Pg:46 (2008) h = 6.624e-034; // Planck's constant, Js c = 3e+08; // Speed of light, m/s m = 9.1e-031; // Mass of an electron, kg e = 1.6e-019; // Energy equivalent of 1 eV, joule/eV L = 4300e-010; // Wavelength of incident light, m phi = 5...
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## Test =I and transcode read <<EOF # This stream dump contains a Latin-1 character blob mark :398168 data 16 Blob at :398168 blob mark :398169 data 16 Blob at :398169 reset refs/heads/master^0 commit refs/heads/master mark :398170 author Johan Bockgärd <bojohan@gnu.org> 1383515485 +0100 committer Johan Bockgärd <boj...
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pathname=get_absolute_file_path('8_3.sce') filename=pathname+filesep()+'8_3_data.sci' exec(filename) //Actual volume of air sucked in per second(in m^3/s) V=nv*Vcyl*(N/2)*(1/60) //Volume flow at atmospheric conditions(in m^3/s) V1=V/2 //Mass flow at atmospheric conditions(in kg/s) ma=(pa/(R*Ta))*(V1) //Pressur...
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// Exa 4.16.11 clc; clear; close; // Given data I_o = 10;// in nA // I = I_o * ((e^(v/(Eta * V_T))) - 1) // e^(v/(Eta * V_T)<< 1, so neglecting it I = I_o * (-1);// in nA disp(I,"The Diode current in nA is ");
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clc clear disp("example 17 3") //given n=4 //number of generating station f=0.05 //F.O.R a=1-f p=50 //generation station power mp=150 //maximum alowable power lf=50 //load factor in persentage function [y]=comb(m,r) y=factorial(m)/(factorial(m-r)*factorial(r)) endfunction for i=0:n pg(i+1)=comb(n,i)...
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-- Created on 04/02/2020 by ALUGA.COM --declare -- Local variables here MySum number; --MyCount number; MyPoint number; MyAcordo number; MyReturn number; MyIpLog varchar2(100); MyParam varchar2(500); ErrOracle varchar2(3700); /* Consulta atualizada pelo e-mail Marcia Nepomuceno do...
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//Example 6.11 //Program to Plot Magnitude Responce of given L.P.F. with specifications: //wp=20rad/sec, ws=30rad/sec, wsf=100rad/sec //as=44.0dB, ap=0.1dB //Using Kaiser Window clear; clc ; close ; wsf=100//rad/sec ws=30;//rad/sec wp=20;//rad/sec as=44.0//dB ap=0.1//dB B=ws-wp; wc=0.5*(ws+wp); wc1=wc*2*...
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//Chapter-9,Example9_20,pg 9_70 V=250 Ra=0.15 Rsh=166.67 No=1280 Il1=67 Ish=V/Rsh Ia1=Il1-Ish Eb1=V-Ia1*Ra //on no load Ilo=6.5 Ish=1.5 Iao=Ilo-Ish Ebo=V-Iao*Ra N1=Eb1*No/Ebo Sr=(No-N1)*100/No//speed regulation SL=Ebo*Iao Po=Eb1*Ia1-SL//full load shaft output hp=Po/746//horse power rating Pi=V*Il1 n...
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errcatch(-1,"stop");mode(2);//Chapter 9 //page no 337 //given ; all; Alpha=2; a=25; //in micrometer y=2; //in micrometer Cgim=2/%pi*(y/a)*(Alpha+2)/(Alpha+1); //lateral coupling coefficient printf("\n Csim= %0.3f\n",Cgim); Lgim=-10*log10(1-Cgim); //insertion loss printf("\n In...