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clc; //page no 23 //pro no 1.7 //Given:refer fig.1.12 of page no.23;R1=100ohm,300K;R2=200ohm,400k;B=100kHz;Rl=300ohm R1=100;T1=300;R2=200;T2=400;B=100*10^3;Rl=300;k=1.38*10^-23; //open-ckt noise voltage is given by //Vn1 =sqrt(Vr1^2 + Vr2^2) // =sqrt[sqrt(4kTBR1)^2 + sqrt(4kTBR2)^2] //by solving this we get ...
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//example3.22 clc disp("%eta_FL = 96%, cos(phi)=0.8, %eta_HL =97.2%, cos(phi)=1") disp("%eta_FL=(VA *cos(phi))/(VA *cos(phi)+P_i+P_cu(FL))*100 i.e. 0.96=((259*10^3)*0.8)/((250*10^3)*0.8+P_i+P_cu(FL))") disp("Therefore, P_i+P_cu(FL)=8333.333 ...(1)") disp("%eta_HL=(n*VA*cos(phi))/(n*VA*cos(phi)+P_i+(n^2)*P...
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function sierpinski(n,a,b,c,d) if n<1 plot([a(1),b(1)],[a(2),b(2)]); plot([b(1),c(1)],[b(2),c(2)]); plot([c(1),d(1)],[c(2),d(2)]); plot([d(1),a(1)],[d(2),a(2)]); e=gce() set(gca(),"isoview","on") else //calcul des coordonnees des points e=[(b(1)-a(...
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@relation vehicle @attribute COMPACTNESS integer[73,119] @attribute CIRCULARITY integer[33,59] @attribute DISTANCECIRCULARITY integer[40,112] @attribute RADIUSRATIO integer[104,333] @attribute PRAXISASPECTRATIO integer[47,138] @attribute MAXLENGTHASPECTRATIO integer[2,55] @attribute SCATTERRATIO integer[112,265] @attri...
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clear; clc; //Example14.9[Measuring Diffusion Coefficient by the Stefan tube] //Given:- D=0.03;//Diameter of tube[m] P=83.5;//Atmospheric Pressure at an elevation of 1600m[kPa] T=20+273;//Ambient temperature[K] R=8.314;//Universal Gas Constant[kPa.m^3/kmol.K] P_vapor0=2.34;//The saturation pressure of water a...
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// Exa 1.2 clc; clear; close; // Given data V_CC = 50;// in V V_BE2 = 0.7;// in V R = 50;// in k ohm R = 50 * 10^3;// in ohm I_C1 = 10;// in µA I_C1 =I_C1 * 10^-6;// in A V_T = 26;// in mV V_T = V_T * 10^-3;// in V I_C2 = (V_CC - V_BE2)/R;// in A R_E = (V_T*log(I_C2/I_C1))/I_C1;// in ohm R_E = R_E * 10^-...
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//Image Processing and Computer Vision Toolbox for Scilab (IPCV)が必要 //コスミカット法のアルゴリズム //加算合成 //比較明合成 //加算-比較明 //結果/(枚数-1) //ファイルの準備 //Scilab カレントディレクトリ/alignd_num/0.tif, 1.tif, 2.tif, ..., n-1.tif (Light Frame) //キャッシュクリア clear(); xdel(winsid()); //Light Frameの枚数 num_of_img = 10; img_index = num_of_img - 1; //0から始まる...
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data=[...];//ici les donnees t=data(:,1); y=data(:,2); function return=constrA(t,y,d) n=length(t); A=ones(n,d+1); for i=1:d A(:,i+1)=t.^i; end return=A; endfunction function [theta,reg,erreur]=reglin(t,y,p) A=constrA(t,y,p); theta=A\y; erreur=norm(A*theta-y)^2; reg=A*theta; endfunction function y=evalpoly(th...
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clear close clc valor = 3 x = [1; 2; 3; 4; 5] y = [15; 28.4; 45.3; 58.6; 77.4] X = [size(x,1) sum(x); sum(x) sum(x^2)] Y = [sum(y); sum(x.*y)] A = X\Y resultado = A(1,1)+A(2,1)*valor disp (resultado, "Resultado: ") disp (A, "A: ") disp ("f(x) = a+b/x")
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clc;funcprot(0);//Example 9.7 //Initilisation of Variables T=5800;....//Temparature of sun in K L1=0.35*10^-6;....//First Visible range of Wavelength in Mew m L2=3.0*10^-6;....//Last Visible range of Wavelength in Mew m R=5.67*10^-8;.....//Stefens boltsman constant Tr=0.93;....//Glass Transmissivity of incident r...
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 6 : DIRECT CURRENT POWER TRANSMISSION // EXAMPLE : 6.1 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA K_1 = 2.5 ; // Factor K_2 = 1.7 ; // Factor ...
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// Scilab Code Ex3.4: Page-98 (2013) clc; clear T = 1600 + 273; // Temperature of the furnace, K b = 2.898e-003; // Wein's constant, m-K lambda_max = ceil(b/(T*1e-009)); // Maximum wavelength from Wein's Displacement Law, nm printf("\nThe maximum wavelength emitted from the heated furnace = %4d nm", lambd...
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clc; t=-12:0.01:12 x=sin(2*t)+cos(t)+0.5*(sin(3*t)-sin(t)) h=-sin(2*t)+cos(t)-0.5*(sin(3*t)-sin(t)) e=cos(t)//(x+h)/2 o=(x-h)/2//sin(t)+0.5*(sin(3*t)-sin(t)) subplot(3,1,1) plot(t,e) xtitle('even signal') subplot(3,1,2) plot(t,o) xtitle('odd signal')
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ATWM1_Working_Memory_MEG_Nonsalient_Uncued_Run2.sce
# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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s=%s; syms k; num=s+1; den=(s^2)*(s^2+5*s+6); t=syslin('c',num,den); clf; evans(t)
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DECLARE results grp.results_tt; indx PLS_INTEGER; minrow PLS_INTEGER; maxrow PLS_INTEGER; BEGIN results := grp.countby ('employee', 'department_id'); indx := results.FIRST; LOOP EXIT WHEN indx IS NULL; IF minrow IS NULL OR minrow > results(indx).countby THEN ...
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// Scilab code Ex2.15: Pg.96-97 (2008) clc; clear; // For electron // For simplicity let velocity of light be unity c = 1; // Velocity of light, m/s E_k = 10; // Kinetic energy of electron, MeV E_r = 0.511; // Rest energy of the electron, MeV gama_e = 1 + (E_k/E_r); // Simplification factor E = E_k ...
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//Find the equivalent current source clear; clc; //soltion //given Vs=2;//Volts //dc voltage source Rs=1;//ohm //internal resistance Rl=1;//ohm //load resistance Ise=Vs/Rs;//ampere //equivalent current source // In accordance to figure 1.23a Il1=Ise*(Rs/(Rs+Rl))...
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//To find velocity and accelerations clc //Given: omegaAO1=100 //rad/s O1A=100/1000,AC=700/1000,BC=200/1000,BD=150/1000,O2D=200/1000,O2E=400/1000,O3C=200/1000 //m //Solution: //Refer Fig. 8.19 //Calculating the linear velocity of A with respect to O1 vAO1=omegaAO1/O1A //m/s vA=vAO1 //By measurement from the v...
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clc //initialisation of variables Q= 450 //gal/min w= 6.24 //lb/ft^3 f= 0.005 l1= 1000 //ft l2= 2000 //ft r1= 1.6 r2= 4.4 r3= 0.8 r4 = 12.85 h1= 59.1 //ft h2= 40.19 //ft v= 1.2 //ft/sec f= 0.0056 l= 10 //ft //CALCULATIONS Q1= Q/(w*60) Q2= (r1+sqrt(r1^2+4*r2))/2 Q3= Q2-Q1 Q4= (-r3+sqrt(r3^2+4*r4))...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex8_8.sce. clc; clear; R=200; P=100e3; V=500; E=525; printf("\n (a)") Il=P/V; If=V/R; Ia=Il+If; Ra=(E-V)/Ia; printf("\n The armature resistance=%1.4f ohm \...
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r=2; t=linspace(0,2*%pi,102); x=r*cos(t); y=r*sin(t); //plot2d(x,y,2) comet(x,y)
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A11 = [0]; A12 = [1]; S2 = eye(1); // 配置したい極を指定 p = [-5]; // 超平面の設計 F = ppol(A11,A12,p) S = S2*[F S2] //切換超平面Sの値をコンソールに出力 disp("切換超平面:S=") disp(S)
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// Calculate BJT parameters using beta gain // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 5-1 in page 235 clear; clc; close; // Part 1 // Given Data beta_bjt=100; // Beta Gain of BJT Vcc=10; // DC voltage across Collector in V Rb=100000; //...
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clc //initialisation of variables P=100 //lbf/in^2 T=600 //F A=20000//lbm/hr P1=0.545 //lbf/in^2 P2=54.5 //lbf/in^2 S=1.7581 //Btu/lbm-R h0=1329.1 //Btu/lbm T1=460//F h=1264.0 //Btu/lbm V=w1*sqrt(h0-h)//ft/sec v1=9.961 //lbf/in^2 PE=20 //lbf/in^2 sE=1.7581 //Btu/lbm-R hE=1174.9 //Btu/lbm vE=21.28 //lb...
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clc clear //Input data n=2 //Number of jets D=0.25 //Diameter of turbojet in m P=3000 //Net power at turbojet in W mf_kWh=0.42 //Fuel consumption in kg/kWh CV=49000 //Calorific value in kJ/kg u=300 //Flight velocity in m/s d=0.168 //Density in kg/m^3 AFR=53 //Air fuel ratio //Calculatioon mf=mf_kWh*P/...
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// Example 3.1 // Computation for mobility of the free electrons in aluminium// // Page no.61 clc; clear; close; //Given data ; d=2.70*10^3//2.70*10^3 kg/m3 v=3;//3 electrons/atom A=26.98; M=1.660*10^-27;//1.660*10^-27 kg/atom e=1.60*10^-19; R=3.44*10^-8;//R=resistivity //...................................(B).........
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clc //initialisation n=5 h=2 p=1/6 //CALCULATIONS t=1-p a=((factorial(n))/(factorial(h)*factorial(n-h)))*(p^h)*(t^(n-h)) //results printf(' \n probability of apperance of 4 in two dices= % 1f ',a)
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//Example No. 6.10.2 clc; clear; close; format('v',6); D=20;//dB(Directivity) //d=lambda/4;(spacing) dBYlambda=1/4;//(spacing/wavelength) D=10^(D/10);//unitless(Directivity) n=D/4/dBYlambda;//no. of elements disp(n,"(i) No. of elements : "); LBYlambda=(n-1)*dBYlambda;//(length/wavelength) disp("(ii) Length ...
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function f2=objfun1(x) f2(1) = 100*(x(2)-x(1)^2)^2 + (1-x(1))^2; f2(2)= x(2)-x(1)*5+x(2)*x(2) endfunction x0 = [-1,2]; A = [1,2]; b = [3]; goal=[5,-6]; weight=abs(goal); [z,gval,attainfactor,exitflag,output,lambda]=fgoalattain(objfun1,x0,goal,weight,A,b)
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clc //Chapter7 //Example7.6 //Given mue=25// tube parameters rp=10e3// tube parameters gm=2.5e-3// transconductance Req=2.5/gm// equivalent resistance Rs=1000 Rg=1e5 F1=1+(((Req*((Rs+Rg)^2))+Rg*Rs^2)/(Rs*(Rg^2)))//noise figure of the first stage Rg2=9.1e3 Rs2=10e3 Es=1// assuming Es=1 for ease of calculati...
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//Chapter-9,Example9_27,pg 9_81 V=250 FLo=16*10^3//full scale output n=80 I=FLo*100/n//input Il=I/V Il=Il Ia=1.5*Il //at start Ra=V/Ia Rac=0.18//Ra actual Ras=Ra-Rac//Ra starter Ia=Il//Ia drops as motor starts Eb=V-Ia*(Ra) printf("back e.m.f\n") printf("Eb=%.2f V",Eb)
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I = imread('../images/color2.jpeg'); c1 = [200 250 300 250 200 150 200] r1 = [ 170 170 135 100 100 135 154] BW = roiPoly(I,c1,r1); imshow(BW)
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T1=1*5*10*1; T2=1*10*1; L1=10*(-1); L2=1*(-2); L3=5*10*1*(-1); L4=10*1*(-1) delta=1-(L1+L2+L3+L4)+(L1*L4) del1=1; del2=1-L1; TF=(T1*del1 + T2*del2)/delta ; disp(TF,"C/R = ")
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// 1d servo of a position x to zero // when the PG disturbs the control with an additional sin // comparison of 2 methods // 1) cancelling the effect of the sin in the control // 2) compensate for the sin clear // --- Control variable sat = 2; // control saturation k = 0.7; // gain...
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clc A=[1 2 3;3 4 4;7 10 12] disp('rank of A is') p=rank(A) if p==3 then disp('equations have only a trivial solution:x=y=z=0') else disp('equations have infinite no. of solutions.') end
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//Function to standardise the given bolt-size function[v] = standard(w) v = ceil(w) rem = pmodulo(v,10) if (rem ~= 0) then v = v + (10 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution7_4.sce') //Obtain path of data file datapath = path + fi...
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% Test SCOPE Package. % NOTE: The SCOPE, GHORNER, GSTRUCTR and GENTRAN packages must be loaded % to run these tests. on priall$ optimize z:=a^2*b^2+10*a^2*m^6+a^2*m^2+2*a*b*m^4+2*b^2*m^6+b^2*m^2 iname s; off priall$ on primat,acinfo$ optimize ghorner <<z:=a^2*b^2+10*a^2*m^6+a^2*m^2+2*a*b*m^4+2*b^2*m^...
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// Exa 4.25 clc; clear; close; // Given data R_F = 5;// in k ohm R_G = 1;// in k ohm R1 = 10;// in k ohm R2 = 20;// in k ohm A = (1 + ((2*R_F)/R_G))*(R2/R1); disp(A,"The gain of instrumentaion amplifier is");
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v=120; i=3; t=12; e=v*i*t; disp("energy supplied by the source (in J) is"); disp(e);
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z=1+2*%i // a complex number conj(z) // complex conjugate real(z) // real part imag(z) // imaginary part [r,a]=polar(z) // polar representation r*exp(%i*a) // =z sqrt(-1) // principal sqrt of -1
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//page 155 clear; close; clc; b=[1;2;3]; disp(b,'b='); a=[1;1;1]; disp(a,'a=') x=(a'*b)/(a'*a) disp(x*a,'Projection p of b onto the line through a is x^*a='); disp((a'*b)/(sqrt(a'*a)*sqrt(b'*b)),'cos(thetha)='); //end
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//Example 7.13: maximum power and total distance clc; clear; close; format('v',5) //given data : w=250;//in tonnes we=(1+(10/100))*w;//efective weight in tonnes r=5*9.81;//in N/tonne G=1;// t1=30;//in sec t2=70;// in sec alpha=2;//kmphps V1=alpha*(t1);// in km/h ft=(277.8*we*alpha)+(98.1*G*w)+(w*r);//in newtons po=((ft...
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clear; clc; r1=0,r2=1,z1=-2,z2=2,q1=0,q2=2*%pi; Q=integrate('p^2','p',r1,r2)*integrate('(cos(Q)^2)','Q',q1,q2)*integrate('1','z',z1,z2); disp(Q,'Total charge is =');
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clear // //eqns derived from figure //6v1-4v2=2-->1 //-4v1+7v2=-3-->2 //eqn 1 and 2 are written in matrix form and solved using cramers rule printf("\n v1=0.0769 V") printf("\n v2=-0.3846V") printf("\n current in 0.5ohm resistance is 0.154A,0.25ohm resistance is 1.846,0.66ohm resistor is -1.154A")
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//caption:stability_using_Routh-hurwitz_criterion //example 7.5.7.(a) //page 207 s=%s; syms T K P=s*(s*(s+10)+T); CH=sym('s^3+10*s^2+T*s+K'); disp('=0',CH,"characterstics_eq,CH=") c0=coeffs(CH,'s',0); c1=coeffs(CH,'s',1); c2=coeffs(CH,'s',2); c3=coeffs(CH,'s',3); b=[c0 c1 c2 c3] n=4; routh=[b([4,2]);b([3,...
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//Script to model influence of uniform e and b field //on charged particle motion clear(); exec('lorentz.sce'); m=1.6*(10^(-27)); q=1.6*(10^(-19)); dt=5.0*(10^(-9)); it=1:1:1000; r=zeros(3,1); v=zeros(3,1); v(2,1)=1.0*(10^6); b=zeros(3,1); e=zeros(3,1); //bfield in z direction b(3,1)=0.1; //efield in y direction...
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function [tolmax,argmax,envs,ccode] = tolsolvty(infA,supA,infb,supb,varargin) // // Вычисление максимума распознающего функционала допускового множества // решений для интервальной системы линейных алгебраических уравнений // // TOLSOLVTY(infA, supA, infb, supb) выдаёт значение максимума распознающего // функц...
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clc C = 1000 // cost of fixture Co = 700 // cost of old fixture Cs = 250 // scrap value a = 10 //saving per piece in paisa a = a/100 b = 30 // overhead applied on direct labour saved b = b/100 I = 8 // interest rate I = I/100 M = 3 // allowance for maintenance M = M/100 T = 12 // allowance for tax T = T/10...
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clear; clc; //Example - 7.11 //Page number - 246 printf("Example - 7.11 and Page number - 246\n\n"); //This problem involves proving a relation in which no numerical components are involved. //For prove refer to this example 7.11 on page number 246 of the book. printf(" This problem involves proving a relati...
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spliTTER IG {} fILtEr RRv { } FilTER Y {nOt P Or nj } V -> YC GROUper k {MoDUlE MmGzI{ } MoDULE Y{ fAv < UAKXT DEltA 56 YT < R RdelTA 5 } aggRegATE UX } UngRoupEr N { } GrouPFiLteR aFaw {} meRGeR n { MoDule T { braNches vIs } MODUle Q { BrAncHEs n } MoDule x { bRaNCheS c, z, mQ } ExpOrT Fpr }
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//example 4.6 clc; funcprot(0); Gamma=16.8; B=1.5; //from table Nyq=120; qu=1/2*Gamma*B*Nyq; disp(qu," shear stress in kN/m^2");
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errcatch(-1,"stop");mode(2); A=[-1 2 -2;1 2 1;-1 -1 0] disp("R is matrix of transformation and D is a diagonal matrix ") [R D]=spec(A) exit();
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//Tested on Windows 7 Ultimate 32-bit //Chapter 7 Field Effect Transistors Pg no. 251 clear; clc; //Given Data IDSS=15D-3;//drain saturation current in amperes VGS0=-6;//gate to source cutoff voltage in volts VGS_1=-2;//gate to source voltage in volts VGS_2=2;//gate to source voltage in volts //Solution ...
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//Finding of Force Exerted //Given rho=1000; d=0.07; V=25; theta=20; theta2=15; //To Find A=(%pi/4)*d^2 Fx=rho*A*V^2*(sin(%pi/9)+cos(%pi/12)); Fy=rho*A*V^2*(sin(%pi/9)-sin(%pi/12)); disp("Fx ="+string(Fx)+" Newtons"); disp("Fy ="+string(Fy)+" Newtons");
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//Ex 5.5 page 186 clc; clear; close; Vs=220;//V Vo=660;// V Toff=100;// micro s //Vo=Vs/(1-alfa) alfa=1-Vs/Vo;// duty cycle //alfa=Ton/(Ton+Toff) Ton=alfa*Toff/(1-alfa);// micro s T=Ton+Toff;//micro s printf('Pulse width of output voltage, Ton = %d micro s & T = %d micro s',Ton,T) //(ii) reduce pulse width by 50% To...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Euler Isentropic Vortex P=3</description> <executable>CompressibleFlowSolver</executable> <parameters>IsentropicVortex16_P3.xml</parameters> <files> <file description="Session File">IsentropicVortex16_P3.xml</file> </files> <metr...
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clear ; clc; // Example 11.7 printf('Example 11.7\n\n'); printf('Page No. 320\n\n'); //given T1 = 40;// in degree T2 = 0;// in degree celcius //As from carnot cycle, C.O.P = (T1/(T1 - T2)), where temperature are in degree celcius C_O_P1 = ((T1+273)/((T1+273) - (T2+273))); printf('C.O.P. is %.1f \n',C_O_P1)...
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function []=hist3d(f,labels,view) // hist3d() ---> example defaults=list(['x','y','z'],[0,%pi/4,%pi/3,xget('white'),2,0.25]) smod=0;first=1-smod; //gestion de la liste d'appel [lhs,rhs]=argn(0), if rhs<=0, write(%io(2),'hist3d(rand(10,10));'); hist3d(rand(10,10)); return;end; enable_r=0 select rhs case 1 then,[la...
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clc; printf("\n Example 4.3\n"); Q=50; //volumetric flow rate of methane P=101.3e3;//Given Pressure T1=288;//Given Temperature d=0.6;//Diameter of pipeline l=3e3;//length of the pipe line R_R=0.0001;//Relative roughness P2=170e3;//Pressure at which methane is to be discharged T2=297;//Temperature at which ...
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//Caption: 2D DFT of 4x4 grayscale image //Example4.5 //page 171 clc; F = [16,0,0,0;0,0,0,0;0,0,0,0;0,0,0,0]; N =4; //4-point DFT kernel = dft_mtx(N); f = (kernel*(F*kernel'))/(N^2); f = real(f); disp(f,'Inverse 2D DFT of the transformed image f =') //Result //Inverse 2D DFT of the transformed image f = ...
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clear; clc; V_s=230; C=50*10^-6; L=20*10^-6; I_cp=V_s*sqrt(C/L); I_o=200; x=I_cp/I_o; t_c=(%pi-2*asin(1/x))*sqrt(C*L); printf("turn off time of main thyristor=%.2f us",t_c*10^6); th1=asind(1/x); t=(5*%pi/2-th1*%pi/180)*sqrt(L*C)+C*V_s*(1-cosd(th1))/I_o; printf("\ntotal commutation interval=%.3f us",t*10...
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ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.266132D+00 2 -0.438931D-02 0.228397D-02 3 -0.110970D+00 0.29250...
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y=[5 -2 6 1;0 3 7 -4;0 0 4 5;0 0 0 2]; c=[1 -2 28 8]; x=[0 0 0 0]; for i=4:-1:1 soma=0; for j=i+1:4 soma=soma+(y(i,j)*x(j)); end x(i)=(c(i)-soma)/y(i,i); end disp(x);
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//pagenumber 290 example 10 clear re=1*10^3;//ohm hie=100;//ohm hfe=100; //voltage gain volgai=1/((1+(hie/(2*(1+hfe)*re)))); //ri ri=(hie/2)+(1+hfe)*re; disp("voltage gain = "+string((volgai))); disp("input resistance = "+string((ri))+"ohm");
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#### Benedikt Kretzmeyer - current version: 11.11.2019 #### Decision-Making and how it as affected by Cognitive Workload in a Lane Merging Task. #### A fMRI driving simulator study ### Script is supposed to: ### - calibrate and control eyetracker ### - play video ### - play nback soundfile ### - record button presse...
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// Example 3.17 //Computation of conversion efficiency // Page no 484 clc; clear; //Given data i=10*10^-6; // Device current p=5; // Electrical power op=50 *10^-6; // Optical power ip=5*10*10^-3; // Input power //Conversion efficiency c=op/ip*100; ...
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//Variable declaration lamda=1.54; //wavelength(angstrom) h=1; k=1; l=1; n=1; theta=19.2; //angle(degrees) //Calculation theta=theta*%pi/180; //angle(radian) d=n*lamda/(2*sin(theta)); a=d*sqrt(h**2+k**2+l**2); //cube edge of unit cell(angstrom) //Result printf('cube edge of unit cel...
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// problem 11.5 H=50 Q=1.2 u1=18 y=160 y2=180-y Cv=0.94 g=9.81 V1=Cv*((2*g*H)^0.5) Vw1=V1 Vr1=V1-u1 Vr2=Vr1 Vw2=Vr2*(cosd(y2))-u1 w=9810 P=(w*Q*(Vw1+Vw2)*u1)/(g*1000) n=P*1000/(w*Q*H) disp(n*100,P,"power developed in Kw and efficiency of the wheel")
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//Exa 1.1 clc; clear; close; //Given data I=40;//in mA V=0.25;//in Volt T=20;//in degree C T=T+273;//in Kelvin ETA=1;//For Ge e=1.6*10^-19;//in Coulamb(electronic charge) k=1.38*10^-23;//in J/K(Boltzman Constant) //Formula : I=Io*(exp(%e*V/(ETA*k*T))-1) y=(e*V/(ETA*k*T));//Assumed y=round(y); Io=I*10^-3/...
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clc; hfe=50; hfb=-hfe/(1+hfe); disp(hfb); hfc=-(1+hfe); disp(hfc);
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function z = f(t,y) //f(t,z) represents the sysmte of ODEs: // -the first argument should always be the independe variable // -the second argument should always be the dependent variables // -it may have more than two arguments // -y is a vector 2x1: y(1) = theta, y(2) = theta' // ...
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Doolittle_Factorisation LU.sci
/* Etideur: Jinshan GUO Objecitf: Fonction à réaliser l'algorithme de Doolittle pour le calcul direct en factorisation LU Principe A = LU => Ax = b => LUx = b => Ly = b,Ux = y Containtes: A est une matrice carré inversible L est une matrice triangulaire inférieure dont les termes diagonaux...
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//Caption:to_find_various_signal_flow_graph_parameter // example 4.4.3 //page 66 syms a b c d e f g h ij // forward path denoted by P1,P2 and so on and loop by L1,L2 and so on //path factor by D1,D2 and so on and graph determinant by D //six independent path P1=a*b*d P2=e*f*h P3=a*j*h P4=e*i*d P5=-e*i*c*j*h...
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//example 5.20 ////calculate //yield from well clc; //given h1=2.5; //initial pumping depression h=1.8; //heigth after recuperation t=80; //time h2=h1-h; KbyA=2.303*60*log10(h1/h2)/t; d=4; //diameter of well H=3; //depression head ...
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//Page Number: 9.20 //Example 9.13 clc; //Given Mf1=0.003; //for f<=1.5D+3 Hz f1=1.5D+3; //Hz Mf2=0.001; //for 1.5D+3 <=f<=3D+3 Hz f2=3D+3; //Hz Mf3=0; //for f>3D+3 Hz //(a) Ac that power transmitted is 100mW St=100D-3; //W //As St=2*[{f1*(Mf1*Ac/2)^2}+{f1*(Mf2*Ac/2)^2}+{f2*(Mf3*Ac/2)^2}] //Negle...
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-->Ab = [1 -2 1]; dAb = 2; zBb = [0 1 1]; dzBb = 2; -->phi = [1 -1.2 0.52]; dphi = 2; -->[S1,dS1,R1,dR1] = xdync(zBb,dzBb,Ab,dAb,phi,dphi) dR1 = 1. R1 = 1. 0.32 dS1 = 1. S1 = 0.48 - 0.32 -->diary off
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//example 3.1 //page 119 clc; funcprot(0); // Initialization of Variable rho=997.1; pi=3.14; v=15;//velocity A=pi*0.3^2/4; Q=v*A; disp(Q,"discharge in (m^3/s)"); m=rho*Q; disp(m,"mass flow rate(kg/s)="); clear
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# ATWM1 MRI Experiment scenario = "ATWM1_Working_Memory_MRI_nonsalient_cued_run1"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds =...
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//Exa 7.8 clc; clear; close; //Given data : format('v',5) L=0.3;//in mm L=L*10^-3;//in meter n=3.6;//Refractive Index(unitless) c=3*10^8;//speed of light in m/s lambda=0.82;//in um lambda=lambda*10^-6;//in meter deltaNEU=c/(2*n*L);//in Hz disp(deltaNEU*10^-9,"Frequency spread between longitudinal modes in ...
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//To find speed of road wheel clc //Given: TA=10, TB=60 NA=1000, NQ=210, ND=NQ //rpm //Solution: //Refer Fig. 13.24 and Table 13.20 //Calculating the speed of crown gear B NB=NA*(TA/TB) //rpm //Calculating the values of x and y y=200 x=y-210 //Calculating the speed of road wheel attached to axle P NC=x+y /...
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clc //initialisation of variables clear w= 62.4 //lbf/ft^3 g= 32.2 //ft/sec^2 v= 86.5 //ft/sec d2= 3 //in d1= 6 //in dp= 50 //lbf/in^2 //CALCULATIONS Fb= -((%pi*(w/g)*v^2*(1/d1)^2*(1-(d2/d1)^2)*0.25)-dp*144*(%pi/4)*(1/d2)^2) //RESULTS printf ('Load on the bolts = %.f lbf',Fb)
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//clear// clc clear k=0.1 cao=8; z0=0; z = 0:1:200; function w=f(z,x) w =zeros(1,1); lam=200-z; ca=cao*(1-x) E1=4.44658e-10*(lam^4)-1.1802e-7*(lam^3)+1.35358e-5*(lam^2)-.00086 5652*lam+.028004; E2=-2.64e-9*(lam^3)+1.3618e-6*(lam^2)-.00024069*lam+.015011 F1=4.44658e-10/5*(lam^5)-1.1802e-7/4*lam^4+1.35358e-5/3*lam^3...
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clc(); clear; //Given : lambda = 1.25; // wavelength in mu_m n1 = 1.462; // refractive index of core n2 = 1.457; // refractive index of cladding // Single mode propogation : (2*pi*a*sqrt(n1^2 - n2^2))/lambda < 2.405 a = (2.405*lambda)/(2*%pi*sqrt(n1^2 - n2^2)); // radius in mu_m d = a*2; // diameter in mu_m p...
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//i/p arg x contains only negative elements x=[-12 -3 -4 -5 -6 -7 -8 -9]; a=5; y=polyscale(x,a); disp(y); //output // column 1 to 5 // // - 12. - 15. - 100. - 625. - 3750. // // column 6 to 8 // // - 21875. - 125000. - 703125. //>>
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5 (5 ()()) ~~~~~~~~~~~~~~~~~~~~~~~~ yes
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//Trabalho de Simulação //Disciplina: Sistemas de Comunicação II //Dupla: Stéphanie Braga e Hugaleno //Questão 3 - Equalizador ZF. clc; close; clear; //****SINAL****// b=rand(1,10); //Gera matriz com valores aleatórios entre 0 e 1. s=round(b); //arredonda os valores para 0 ou 1. ns=size(s,2); //retorna o número...
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// Example 1.18 clc; clear; close; // Given data format('v',5); VEE= 10;// in V VBE= 0.715;// in V beta_ac= 100; beta_dc= 100; R= 5.6;// in kΩ I_REF= (VEE-VBE)/R;// in mA IC1= I_REF*beta_ac/(2+beta_ac);// in mA // IC1= IC2= IC3 (by symmetry) IC2= IC1;// in mA IC3= IC2;// in mA I_RC= IC1+IC2+IC3;// curr...
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clc; clear all; disp("Local HT coefficient") U=5;//m/s velocity of air rho=0.815;//kg/m^3 density of air k=0.0364;// W/(m.C) mu=24.5*10^(-6);//Ns/m^2 viscosity of air Pr=0.7;// Prandlt number Ts=200;// degree C Ta=120;// degree C x=0.5;//m width of plate v=mu/rho; Rex=U*x/v;// Reynold's number Rex delt...
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clc //initialisation of variables s= 3.61*10^-8 //cm v= 4.44*10^4 //cm/sec n= 2.46*10^19 //molecules N= 6.02*10^23 //molecules Z1= 13.6*10^16 //collisions cm^-3 sec^-1 N= 6*10^23 //molecules //CALCULATIONS Z= sqrt(2)*%pi*s^2*v*n^2*10^3/(2*N) Z2= Z1*10^3/N //RESULTS printf ('Z= %.2e moles of collisons litre...
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clear // Note that it is convenient to take axis in such a way that the centroids of all simple figures are having positive coordinates. If coordinate of any simple figure comes out to be negative, one should be careful in assigning the sign of moment of area //variable declaration A1=2.0*6.0*1.0/2.0 //...
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//Chapter 6 //Example 6.4 //Page 147 //leakagereactance clear;clc; //Given V_lt = 110; V_ht = 440; P = 2.5e3; x_lt = 0.06; //Calculations disp('Viewed from low-tension side') lt_base_impedance = (V_lt)^2 / P; printf("\n Leakage reactance from low-tension side = %.2f ohm",x_lt) printf("\n Low-tension base impedance = ...
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// Test # 13 : Valid input test case #2 exec('./allpassshiftc.sci',-1); [n,d]=allpassshiftc(0.861,0.546); disp(d); disp(n); // //Scilab Output //d=1. 0. //n= 0 0.5490228 - 0.8358074i // //Matlab Output //d = 1 0 //n = 0.0000 + 0.0000i 0.5490 - 0.8358i
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tpyrun $p/bin/util/markdown_test
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funcprot(0); clear all; ////////////////////////////////////////////////////////////////////// // parameters ////////////////////////////////////////////////////////////////////// sampleNum = 1024; // sample number sampleFreq = 44100; // sampling frequency waveFreq = 440; // wave frequency /////////////////////...
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// Example 3.3 // Computation of (a) Buck boost transformer parameters // (b) Repeating the same assuming utilization voltage as 246V // Page No. 102 clc; clear; close; // Given data S=10000; // Supply voltage VLS=212; // Voltage at the low side VHSNEW=246; // New volt...
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//signals and systems //time domain analysis of discreet time systems //total response with initial conditions clear; close; clc; n=(-2:10)'; y=[25/4;0;zeros(length(n)-2,1)]; x=[0;0;4^-n(3:length(n))]; for k=1:length(n)-2 y(k+2)=0.6*y(k+1)+0.16*y(k)+5*x(k+2); end; clf; a=gca(); plot2d3(n,y); y1=[2...
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clc //to calculate smallest angle between two stars lambda=5*10^-5 //wavelength in cm a=100*2.54 //diameter in cm theta=1.22*lambda/a disp("the smallest angle between two stars is thita="+string(theta)+"radians")
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8q2.sce
clc //initialisation of variables Nd= 6 H1= 5.6 //m H2= 2.2 //m k= 5e-5 //cm/sec dL= 4.1 //m //calculations H= (H1-H2)/Nd h1= 5.61-H h2= 5.61-5*H q= 2.38*(H1-H2)*k/Nd i= H/dL //results printf ('at point a,water will rise to height of = % 3f m ',h1) printf ('at point b,water will rise to height of = % 3f ...