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function [p,err]=approx(f,G,Z,p0) [p,err]=datafit(G,Z,p0) xgrid; xlabel('x'); ylabel('y'); scatter(X,Y); x = -5:0.1:10; plot2d(x,f(x,p),12); endfunction X = [1.28,2.00,2.91,4.07,5.00,6.00,7.01,7.89]; Y = [2.36,3.15,3.55,4.00,4.41,5.08,5.49,6.12]; Z = [X;Y]; scf();clf(); p0=[1;1;1;1;1]; //f...
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function approx = MethodeSecante(f, x_0, x_1, N) xn_1 = x_0; xn = x_1; approx = xn - f(xn)/((f(xn)-f(xn_1))/(xn-xn_1)); n = 1; while n < N xn_1 = xn; xn = approx; approx = xn - f(xn)/((f(xn)-f(xn_1))/(xn-xn_1)); n = n+1; end return; endfunction
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 1 : Basic Concepts // Example 1 - 4 clear; clc; close; // // Given data i = 2.0000; delta_t = 1...
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// For scilab 5.1.1 or lower version users, //use scicos command to open scicos diagrams instead of xcos global fdfh fdt fncr fncw m err_count y p q xk_old p = 40; //prediction horizon q = 4; // control horizon xk_old = zeros(8,1); fncr = 'clientread.sce'; fdt = mopen(fncr); mseek(0); err_count = 0; //initialis...
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q=poly([0 0 6 5 1],'s','coeff'); G=1/q //gain FACTOR=k H=1 y=G*H disp(y) syms s Kp=limit(s*y/s,s,0) //Kp= position error coefficient Kv=limit(s*G*H,s,0) //Kv= velocity error coefficient Ka=limit(s^2*G*H,s,0) //Ka= accelaration error coefficient disp(Ka ,"Ka = ") disp(Kv ,"Kv = ") disp(Kp ,"K...
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//Problem 15.17: Determine the p.d.’s V1 and V2 for the circuit shown in Figure 15.17 if the frequency of the supply is 5 kHz. Draw the phasor diagram and hence determine the supply voltage V and the circuit phase angle. //initializing the variables: R1 = 4; // in ohms C = 1.273E-6; // in Farads L = 286E-6; // in Henr...
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// Exa 2.20 clc; clear; close; // Given data V1 = 10;// in V V2 = 0.7;// in V V3 = V2;// in V V = V1-V2-V3;// in V R1 = 1;// in ohm R2 = 48;// in ohm R3 = 1;// in ohm R = R1+R2+R3;// in ohm I = V/R;// in A I = I * 10^3;// in mA disp(I,"Current in mA is");
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clc //Chapter7 //Ex_2 //Given N=5*10^28 //in m^-3 e=1.6*10^-19 // in coulombs Z=4 me=9.1*10^-31 //in Kg epsilon_o=8.85*10^-12//F/m2 epsilon_r=11.9 //part(a) alpha_e=(3*epsilon_o/N)*((epsilon_r-1)/(epsilon_r+2)) disp(alpha_e,"Electronic polarizability in F/m2") //part(b) //let x=E_loc/E x=(epsilon_r+2)/3 ...
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// reading image PGM RAW (8 bits) (PBM) // usage: img = readpbm('image.pbm'); function image=readpbm(filename) [u,err]=mopen(filename,'rb') if err<>0 then error('Error opening file '+filename), end if mgetl(u,1)~='P5' error('Unrecognized format'), end z=mgetl(u,1), while part(z,1)=='#', z=mgetl(u,1), end n...
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; @Harness: disassembler ; @Result: PASS section .text size=0x00000054 vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x00000088 ;2**0 start .text: label 0x00000000 ".text": 0x0: 0x0f 0x57 subi r16, 0x7F ; 127 0x2: 0x1...
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clear // // // //Variable declaration a=50 n2=1.5 //refractive index of cladding n1=1.53 //refractive index of core lamda0=1 //wavelength(micro m) //Calculation V_number=(2*%pi*a*sqrt(n1**2-n2**2)/lamda0) //V number n=V_number**2/2 //maximum number of modes //Result printf("\n maximum num...
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function [A] = construct (t, tau) exec("place.sci", -1); m = length(tau); n = length(t); A = zeros(m, n); for i = 1 : m j = place(t, tau(i)); // localise t dans la suite de pts T // disp(i); // disp(m); // disp(j); // disp(n); // disp("--"); ...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 13.4 //calculation of the difference in the pressures at A and B point //given data A1=1*10^-4//area(in m^2) at point A of the tube A2=20*10^-6//area(in m^2) at point B of the tube v1=10*10^-2//speed(in m/s) of the i...
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// Convolution of two sequences // 3.2 h = [1 2 3]; u = [4 5 6]; y = convol(u,h)
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errcatch(-1,"stop");mode(2);//Caption: rate of information //Example 9.12 //page no 401 //Find Average rate of information ; ; m=16; pxi=1/16; elements=2*10^6; n=32 HX=0; for(i=1:16) HX=HX+(-(pxi*log2(pxi))); end r=elements*n; R=r*HX printf("Average rate of information\n \n \t R = %d Mbs",R/10^6); exit();
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//ques-19.17 //Calculating mass of a particle clc dx=9.54*10^-10;//uncertainity in position (in m) dv=5.5*10^-20;//uncertainity in velocity (in m/s) h=6.6*10^-34;//(in Js) m=h/(4*%pi*dx*dv); printf("The mass of the particle is %d mg.",m*10^6);
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//Ex:52 clc; clear; close; e=0.5;//orbital eccentricity a_e=14000;//dis b/w center of ellipse to the center of earth in km a=a_e/e;//semi major axis in km r_a=a*(1+e);//apogee in km r_p=a*(1-e);//perigee in km printf("The apogee=%d km",r_a); printf("\n The perigee=%d km",r_p);
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clc; printf("\n Example 4.2\n"); l=30;//Length of the tube d=150e-3;//Diameter of the tube P1=0.4e3;//Initial Pressure P2=0.13e3;//final Pressure //X=e/d, Relative roughness //Y=R/(rho*u^2) = 0.004 X=0.003; Y=0.005; v1=21.15e1; G_A=poly([0],'G_A'); f=(G_A^2*log(P1/P2))+((P2^2-P1^2)/(2*P1*v1))+(4*(Y*l/...
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//Variable declaration Vcc=6 //supply voltage(V) R=1.2 //resistance(k ohms) Vbe=0.7 //base to emitter voltage(V) beeta=100. //current gain //Calculations //Part a Ir=(Vcc-Vbe)/R //current(mA) I=(beeta/(beeta+3))*Ir //current(...
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//Example 8.6, Page Number 380 //Intermodal Dispersion in step index fibers clc; n1=1.48//refractive index n2=1.46//refractive index L=1*(10**3) //Length of Fiber in kilometer c=3*(10**8) //Speed of Light in meters per second //Using equation 8.24 td=((L*n1)/(c*n2))*(n1-n2) //t is the time difference due t...
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//exapple 1.30 clc; funcprot(0); // Initialization of Variable longP=85+20/60;//longitude of place GST=18+30/60;//standard time gst=6+32/60+12/3600;//GST at GMN dot=longP/15;//difference in time GMT=GST-dot-12; i=GMT*9.8565/3600;//error GMT=GMT+i;//SI time LST=GMT+dot+gst;//LST at LMT disp("local standar...
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clc //For the air at 35 0C DBT and 60% R.H. p_vs=0.0563; //bar; Corresponding to 35 0C from stem tables phi=0.6; p_t=1.0132; //bar cp=1.005; t_db=35; //0C h_g=2565.5; //kJ/kg m1=1; //kg m2=2; //kg m=m1+m2; p_v=phi*p_vs; W1=0.622*p_v/(p_t-p_v); //Corresponding to 0.0388 bar, from steam tables t_dp=...
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//Engineering and Chemical Thermodynamics //Example 9.4 //Page no :447 clear ; clc ; //Given del_gf_0_CH2O = -110.0 ; //[kJ/mol],From Appendix A.2 & A.3 del_gf_0_H2 = 0 ; //[kJ/mol],From Appendix A.2 & A.3 del_gf_0_CH4O = -162.0 ; //[kJ/mol],From Appendix A.2 & A.3 del_hf_0_CH2O = -116.0 ; //[kJ/mol],From Ap...
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//find clc //solution //given tL=140000//N ns=4 n=10 L=500//mm dx=80//mm E=200000//N/mm^2 f=600//N/mm^2 W=tL/8//N //let t be thickness and b be th width //f=6WL/(nbt^2) //nbt^2=87.5*1000...eq1 //dx=6WL^3/(nEbt^3) //nbt^3=0.82*10^6....eq2 //from eq1 and eq2 ,we get t=10//mm b1=87.5*1000/(n*t^2) print...
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\shader\cmp.psh \shader\cmp_4x.psh \shader\cmp_pp.psh \shader\frc.psh \shader\frc_4x.psh \shader\lrp.psh \shader\lrp_4x.psh \shader\rcp.psh \shader\rcp_pp.psh \shader\rcp_4x.psh \shader\rsq.psh \shader\rsq_pp.psh \shader\rsq_4x.psh
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//Section-1,Example-3,Page no.-AC.182 //To calculate the percentage of sulphur in the given coal sample. clc; W_BaSO4=0.01 W_coal=0.1 P_S=(W_BaSO4*32*100)/(W_coal*233) disp(P_S,'Percentage of sulphur in the given coal sample')
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//Chapter 16, Problem 11, Fig 16.13(a) clc; f = 50; // in ohm V = 240; // in Volts pf = 0.6 // power factor Im = 50; // in amperes //calculation: phi = acos(pf) phid = phi*180/%pi Ic = Im*sin(phi) I = Im*cos(phi) printf("\n\n (a)T...
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// Example 12.6 //Write a program to append additional items to the file INVENTORY //created in Example 12.3 and print the total contents of the file. funcprot(0); warning('off'); function[item] =append(product,fp) printf("Item name:\n"); product.name=scanf("%s"); printf("Item n...
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function [r]=%r_n_s(l1,l2) // l1<>l2 rational<>constant // Copyright INRIA r=degree(l1('num'))==0&degree(l1('den'))==0 if r then r=coeff(l1('num'))./coeff(l1('den'))==l2,end r=~r
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function [kr, R0]=poly2rc(a, efinal) //poly2rc function convert prediction polynomial to reflection coefficients. // Calling Sequence // kr = poly2rc(a) // [kr, R0] = rc2poly(a, efinal) // Parameters // a: prediction polynomial. // efinal: final prediction error. // kr: Return refelection coefficient. // R0: Re...
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// // // Generates C file and corresponding headers for filters used in // C implementation // clear(); exec('sci_vor_filters.sci'); [filters] = vor_get_filters(); filter_name = [ "BP_VAR" "BP_REF" "LP_DECIM" "LP_VAR" "LP_REF" "LP_FM" ]; f...
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clc(); clear; // to find tempearture difference between inner and outer surface r=1/4; // radius in inches to=300; // outer surface temperature of cylinder in degF q0=10; // i2r heat loss in Btu-in^2/hr k...
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//Exa:3.3 clc; clear; close; //Given: Bw=12;//in KHz Mod_mn=300; Mod_mx=3000; dev=6;//in KHz m1={(Bw-dev)*1000}/Mod_mn; m2={(Bw-dev)*1000}/Mod_mx; printf("\n 1)modulation indexat 300Hz = %f ",m1); printf("\n 2)modulation indexat 3000Hz = %f ",m2);
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clc //initialisation of variables p2=3.24 //pressure in bar p1=1 //pressure in bar v1=16 //volume in m*m*m n=1.35 rp=3.24 //pressure r=10.5 t1=294 //temparature in k t2=294 //temparature in k cp=1.005 //kj/kg rx=0.287 //CALCULATIONS w1=(2*n/(n-1))*p1*v1*100*0.35630 //(3.24)^0.2592-1 w2=(n/(n-1))*p1*v1*10...
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//water// //page 1.10 example 6// clc W1=14.6;//Mg(HCO3)2 in water in mg/L// W2=8.1;//Ca(HCO3)2 in water in mg/L// W3=29.6;//Mg(NO3)2 in water in mg/L// W4=19;//MgCl2 in water in mg/L// W5=24;//MgSO4 in water in mg/L// M1=100/146;//multiplication factor of Mg(HCO3)2// M2=100/162;//multiplication factor of Ca(H...
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clc //ex3.2 C=0.1*10^-6; //symbolic integration cannot be done in scilab t=[0:0.001*10^-3:3*%pi*10^-4]; i=0.5*sin((10^4)*t); //on integrating 'i' w.r.t t q=0.5*10^-4*(1-cos(10^4*t)); C=10^-7; V=q/C; subplot(221) plot(t,q*10^6) xtitle('charge vs time','time in seconds','charge in Mc') //Mc=micro coulomb...
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//Example 22.3 // critical current density clc; clear; //given data : d=1D-3;//diameter of wire in m Ho=6.5D4;//critical field at temperature at 0k Tc=7.18;// critical temperature in kelvin T=4.2;//temperature in kelvin Hc=Ho*(1-(T/Tc)^2);//critical field at T kelvin Jc=4*Hc/d;//formula disp(Jc,"critical curr...
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Vp=120;Angle=60; t0=%pi/2 t1=t0:0.01:(210/360*2*%pi); integrate('2^.5*120*sin(t)','t',t0,t1) Vo=((3*sqrt(6))/(2*%pi))*120*cos(%pi*Angle/180)
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//caption:Find the value of multiplier resistance for the range(a)0-10V(b)0-50V(c)0-100V(d)0-200V //Ex5.8 clc clear close V1=10//maximum voltage range(in V) V2=50//maximum voltage range(in V) V3=100//maximum voltage range(in V) V4=200//maximum voltage range(in V) I=0.002//deflection current(in A) R=100//inter...
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//example 7.2 clc; funcprot(0); c=14.36; Gamma=17.4; H=6; phi=26*%pi/180; Ka=(tan(%pi/4-phi/2))^2; sigma0=Gamma*H*Ka-2*c*sqrt(Ka); Pa=1/2*Gamma*H^2*Ka-2*c*H*sqrt(Ka); disp(Pa,"active force before which tensile crack appeared in kN/m"); zbar=(244.32-323.1)/14.46; disp(zbar,"the line of action on which net for...
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clc; // two transformers are connected in parallel and has following data P1=100; // rated KVA of transformer 1 E11=6600; // rated primary voltage for transformer 1 E21=230; // rated secondary voltage for transformer 1 z1=1.5+4*%i // percentage leakage impedance for transformer 1 P2=200; // rated KVA of transform...
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// chapter 2 // example 2.4 // Find the value of series resistor and average power // page-31 clear; clc; // given // Vg=1.5+8*Ig; // relation between Vg and Ig Vgs=12; // in V t=50; // in us D=0.2; // duty cucle P=5; // in W // calculate // since Vgs=Ig*Rg+Vg=Ig*Rg+1.5+8*Ig or // Vgs=(Rg+8)*Ig+1.5, (i) // since P=Vg*...
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clc //initialisation of variables I= 1.5 //in^4 Da= 0.5 //in E= 30*10^6 l= 60 //in //CALCULATIONS F= 6*Da*E*I/(l^3) //RESULTS printf ('F= %.2f lb',F)
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fs = 44100;//サンプリングレート T = 0.25;//音の生成時間(この値の2倍の長さ) t = [0 : T * fs - 1] / fs;//時間軸の設定 //音の周波数リスト C = 1046.502;//周波数ド(C) D = 1174.659;//周波数レ(D) E = 1318.510;//周波数ミ(E) F = 1396.913;//周波数ファ(F) G = 1567.982;//周波数ソ(G) A = 1760.000;//周波数ラ(A) B = 1975.533;//周波数シ(B) //石焼き芋の歌 c = sin(2 * %pi * C * t); d = sin(2 * %pi * D * t)...
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function t=tanh(x) //Element wise Hyperbolic tangent // Copyright INRIA if type(x)<>1 then error(53),end t1=exp(x);t2=exp(-x); t=(t1-t2)./(t1+t2); k=find(isnan(t)) t(k)=sign(real(x(k)))
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// Example 4.6 clear; clc; // Given data A_U = 238; // Atomic Mass number of Uranium A_O = 16; // Atomic Mass number of Oxygen amt_UO2 = 33000; // Amount of Uranium dioxide (UO2) present in kilogram(kg) x_P = 0.032; // Enrichment of 3.2 w/o uranium product x_T = 0.002; ...
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PL/SQL Developer Test script 3.0 28 DECLARE c utl_tcp.connection; -- TCP/IP connection to the Web server ret_val pls_integer; BEGIN c := utl_tcp.open_connection(remote_host => '192.168.100.2', remote_port => 8084, charset => 'US7ASCII'); -- op...
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//Example 11.4 // current flowing clc; clear; close; //given data : f=50; // frequency in Hz C=100*10^-6;// capacitor in Farad V=210; // voltage in volts pi=22/7; XC=(1/(2*pi*f*C)); Z=XC; I=V/Z; disp(I,"current flowing,I(A) = ")
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//Exa 3.8 clc; clear; close; //given data ND=10^21;//in m^-3 NA=10^22;//in m^-3 De=3.4*10^-3;//in m^2-s^-1 Dh=1.2*10^-3;//in m^2-s^-1 Le=7.1*10^-4;//in meters Lh=3.5*10^-4;//in meters ni=1.6*10^16;//in m^-3 e=1.602*10^-19;//constant IoA=e*ni^2*(Dh/(Lh*ND)+De/(Le*NA)); disp(IoA*10^6,"Reverse saturation cur...
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clc; clear all; disp("heat transferred per meter") ta=15+273;//K air temperature ts=605+273;//K plate temperature U=6.5;// m/s velocity of air x=0.35;//m distance tf=(ts+ta)/2;// mean film temperature rho=0.614;//kg/m^3 cp=1046;//J/kg.K k=0.04593;// W/m.C mu=29.7*10^(-6);//kg/m.s Pr=0.675;, Re=rho*U*x/mu; ...
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// Calculating the demagnetizing and cross magnetizing mmf per pole clc; disp('Example 9.10, Page No. = 9.38') // Given Data P = 500;// Power rating (in kW) rpm = 375;// Speed in r.p.m. p = 8;// Number of poles flux = 0.0885;// Flux per pole (in Wb per meter) // Calculation of the demagnetizing and cross magnet...
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13 8:0.5 13:1.0 32:0.25 81:1.0 222:1.0 1005:1.0 13 8:0.5 37:0.5 130:0.5 624:0.25 13 4:0.3333333333333333 12:0.5 22:0.16666666666666666 29:0.18181818181818182 36:0.1 114:0.14285714285714285 118:1.0 165:1.0 180:0.3333333333333333 198:1.0 279:1.0 582:1.0 963:1.0 1353:1.0 13 8:0.5 12:0.5 32:0.25 153:0.3333333333333333 171:...
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// Scilab Code Ex7.4: Page-252 (2014) clc; clear; n = 3; // Principal quantum number Total = 0; printf("\nn l m_l 2(l + 1)"); printf("\n------------------------------------"); for l = 0:1:n-1 printf("\n%d", n); printf(" %d ", l); if l > 0 then count = 0...
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//Chemical Engineering Thermodynamics //Chapter 1 //Introduction //Example 1.6 clear; clc; //Given n = 1;//n is the Kg mole of ideal gas. P1 = 700*(10^4);//P1 is the initial pressure of the system in N/(m^2) P2 = 638*(10^4);//P2 is the final pressure of the system in N/(m^2) T = 300;//T is temperature of ...
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//Example 1.8 Conversion from decimal number to binary number. clc; x = dec2bin(105); // binary equivalent of decimal number disp('The binary number is = '); disp(x) // answer in binary form
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.18w //calculation of position of image due to refraction at the first surface and position of final image //given data1 //u=infinite object distance (in cm) R=2; //radius of curvature of the spherical convex sur...
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s=poly(0,'s'); F=syslin('c',[(1+0.2*s)*(1+0.025*s)/((1+0.001*s)*s^(3)*(0.005*s+1))]) fmin=0.1; //Min freq in Hz fmax=20; //Max freq in Hz scf(1);clf; bode(F,fmin,fmax); //Plots frequency response of open-loop system in Bode diagram [GainMargin,freqGM]=g_margin(F) //Calculates gain margin [dB] and correspo...
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//Exa 6.34 clc; clear; close; format('v',7); //Given Data : p1=80;//bar Tsup3=350;//degree C pb=712.5/760*1.01325;//bar mdot=2;//Kg/s //mdot=1;//Kg h3=2964;//KJ/Kg(Molliers diagram) h4=2184;//KJ/Kg(Molliers diagram) WT=h3-h4;//KJ/Kg WTdot=mdot*WT;//KW disp(WTdot,"Total turbine work in KW : "); wp=(p1-...
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clc v = 15000 // vertical magnification h = 100 // horizontal magnification l = 0.8 // sampling length in mm a1 = 160 // area above datum line in mm^2 a2 = 90 // area above datum line in mm^2 a3 = 180 // area above datum line in mm^2 a4 = 50 // area above datum line in mm^2 a5 = 95 // area below datum line in m...
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// Exa 3.5 clc; clear; close; // Given data Miu_n = 0.15;// in m^2/v-s K = 1.38*10^-23; T = 300;// in K e = 1.6*10^-19;// in C D_n = Miu_n*((K*T)/e);// in m^2/s Torque_n = 10^-7;// in s L_n = sqrt(D_n*Torque_n);// in m disp(L_n,"The diffusion length in m is"); del_n = 10^20;// in electrons/m^3 J_n = (e*D_...
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lines(10) //to delete plot() // commande graphique Scilab E=gce() // handle de type Compound E.children(1) // 1er des 41 descendants de E
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// Variable Declaration I_f_A = 6000.0 //3-phase fault current of substation A(A) I_f_B = 5000.0 //3-phase fault current of substation B(A) I_f_C = 3000.0 //3-phase fault current of substation C(A) I_f_D = 2000.0 //3-phase fault current of substation D(A) I_L_max = 100.0 //Maximum load cuurent(...
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//check o/p when i/p is a matrix k = [0.3090 0.9801; 0.0031 0.0082; -0.0082 0.54365]; g = rc2lar(k); disp(g); //output // // 0.6388789 4.6001829 // 0.0062000 0.0164004 // - 0.0164004 1.218645 //
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一、数组 常用方法说明 1、copy数组 公式:Arrays.copyOf(original, newLength); 说明:original:源数组,newLength:copy的长度 例: int[] a = new int[]{1, 3, 6, 22, 31, 4}; int[] c = Arrays.copyOf(a, 10); 结果:打印数组c--》[1, 3, 6, 22, 31, 4, 0, 0, 0, 0] 如果源数组a长度不够,则补零; 2、copy数组 公式:Arrays.copyOfRange(original, from, to); 说明:original:源数组,from:从第几位开始,to:到第...
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clc; clear all; disp("heat flow through wire") k=0.12;// W/(m*C) r1=2/2;//mm r2=r1+0.8;//mm ho=35;// W/(m^2*K) rc=1000*k/ho;//mm disp("mm",rc,"critical radius of insulation =") disp("i) heat flow through an insulated wire") Rthcd=(log(r2/r1))/k; Rthcv=1000/(ho*r2); Rth12=Rthcd+Rthcv; //Q12=2*pi*L*(t1-t...
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sd lkjasd l;kajsd lkasd sdg sdf g dsf gs df gs df g df gsdf g sdf g sd fgs df g spp -- test.lua 文件末尾注释-- test.lua 文件末尾注释-- test.lua 文件末尾注释-- test.lua 文件末尾注释
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 7 //Properties of Solutions //Example 10 clear; clc; //Given: K = 4.4*10^4; //Henry's law constant (bar) pp = 0.25; //partial pressure of oxygen in bar M_O2 = 32; //molecular wt of oxygen M_water = 18; //molecular wt of water //To estima...
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clc; //Example 20.7 //page no 276 printf("\n Example 20.7 page no 276\n\n"); //refer to illustrative Example 20.5 //(1) //we have to calculate minimum air ventilation flow rate into the room containing 10 ng/m^3 of a toxic chemical //ng means nanograms rV=250//chemical generated in the laboratory,ng/min c_o=10...
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//Initilization of variables F1=150 //lb F2=80 //lb F3=100 //lb F4=50 //lb theta1=((45*%pi)/180) //radians r=3 //units //Calculations Fh=F1-F3*cos(theta1) //lb Fv=F4-F2-F3*sin(theta1) //lb R=sqrt(Fh^2+Fv^2) //lb //Applying the Varignons Theorem a=(F4*r-F1*r+F2*r-F3*r)/R //units //Result clc printf('The ...
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//Chapter 13, Problem 5, figure 13.16 clc; E1=4; //e.m.f source 1 E2=2; //e.m.f source 2 R=4 //resistor r1=2; //internal resistance 1 r2=1; //internal resistance 2 Rr2=(R*r2)/(R+r2); //equival...
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clc; clear; mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-12.2 Page No.256\n'); //Surface speed Dp=2.5; n=1725; Vm=%pi*Dp*n/12; mprintf('\n Surface speed = %f ft/min.',Vm);
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//The importance of Periodic extension //(a)For M=3 x=[1 2 1]; XDFT=dft(x,-1) w=exp(-%i*2*%pi/3); for i=1:3 for j=1:3 WN(i,j)=w^((i-1)*(j-1)); end end WI=WN'; xn=1/3*WI*XDFT //The result is periodic with M=3 & 1 period equals x[n] //(b)For M=4 y=[1 2 1 0]; YDFT=dft(y,-1) w=exp(-%i*%pi/2)...
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im=0.05; v=5; rm=3; disp("Part a"); rt=v/im; disp("the total resistance (in kΩ) of the meter is"); disp(rt); disp("Part b"); rs=rt-rm; disp("the necessary resistance (in kΩ) of the voltmeter multiplier is"); disp(rs);
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clc; h3=2716.4;//kJ/kg hf2=640; h_fg2=2109; x2=(h3-hf2)/(h_fg2); flow_rate=9; m_w2=(1-x2)*(flow_rate); mass_water=0.5; m_w1=m_w2+mass_water flow_rate_dry=mass_water+flow_rate-m_w1; x1=flow_rate_dry/(mass_water+flow_rate); disp("fraction is:"); disp(x1)
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function bissect(func, a, b, errmargin, maxn) if (sign(func(a)) ~= sign(func(b))) then // If f(a) and f(b) have opposite signs n = 1 x_n = (a + b) / 2 if (func(x_n) == 0) then // If the first X is root disp("found on the first midpoint", string(x_n), "Absolute root of f:") ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 6: MOTORS FOR ELECTRIC TRACTION // EXAMPLE : 6.4 : // Page number 791 clear ; clc ; close ; // Clear the work space and conso...
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// Example 4.3.1 page 4.4 clc; clear; L=10; //fiber length in km Pin=150d-6; //input power Pout=5d-6; //output power len=20; //length of optical link interval=1; //splices after interval of 1 km l=1.2; //loss due to 1 splice attenuation=10*log10(Pin/Pout); alpha=attenu...
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// Initilization of variables P=50 // N // Weight of the car Q=100 // N // Weight of the rectangular block g=9.81 // m/s^2 // acc due to gravity b=25 // cm // width of the rectangular block d=50 // cm // depth of the block // Calculations a=(Q*g)/(4*P+2*Q) // m/s^2 // from eq'n 4 W=(Q*(P+Q))/(4*P+Q) // N // fro...
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// Example 4.1 // To find far field distance for antenna with maximum dimensions and operating frequency // Page No.109 clc; clear all; // Given data D=1; // Maximum dimension in m f=900*10^6; // Operating frequency in Hz C=3*10^8; // Speed of light in m/sec lamb...
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sce
Ex26_3.sce
//Example 26_3 clc(); clear; //To draw the energy level diagram and the find the first line of balmer type series n=1 e1=-54.4/n^2 //units in ev n=2 e2=-54.4/n^2 //units in ev n=3 e3=-54.4/n^2 //units in ev printf("The energy associated with line 1 is E1=%.1f eV\nThe energy associated with line 2 is ...
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Scilab
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453
sce
1.sce
clc d=1.5; // m m=1.2; // kg rate=0.0065; // K/m R=287; // J/(kg.K) T_0=288.15; // K p_0=101*10^3; // Pa g=9.81; // m/s^2 rho=m/(%pi*d^3/6); rho_0=p_0/R/T_0; // log(rho/rho_0)=(g/R*rate - 1)*log((T_0-rate*z)/T_0) z=1/rate*(T_0-T_0*exp(log(rho/rho_0)/(g/R/rate-1))); disp("The height above sea level t...
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2020-04-09T02:43:26.499817
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2018-02-03T05:31:52
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Scilab
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sce
Ex11_4.sce
//example 11.4 clc; funcprot(0); FS=4; Ap=0.1295; Nc=9; cu2=100; Qp=Ap*Nc*cu2; D=[5, 10, 30]; avgD=[2.5, 7.5,20]; sigma=[45, 110.5, 228.5]; cu=[30, 30, 100]; alpha=[0.6 0.9 0.725]; L=[5, 5, 20]; p=%pi*0.406; Qs=0; disp(Qp,"bering capacity in kN"); printf("depth (m)\t avg Depth(m)\t avgVerticalStress(kN/...
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2020-04-09T02:43:26.499817
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Scilab
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695
sce
30_12.sce
clear// //Variables RD = 100.0 * 10**3 //Drain resistance (in ohm) gm = 1.6 * 10**-3 //Transconductance (in Ampere per volt) rd = 44.0 * 10**3 //Resistance (in ohm) Cgs = 3.0 * 10**-12 //Capacitance gate-to-source (i...
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/998/CH29/EX29.66/Ex66.sce
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FOSSEE/Scilab-TBC-Uploads
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2020-04-09T02:43:26.499817
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null
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UTF-8
Scilab
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446
sce
Ex66.sce
//Ex:66 clc; clear; close; r=6378;//radius of earth in km h=35786;// in km r_h=r+h;//height in km E_min=0;// in degree P=cos(E_min*3.14/180); Q=(r/(r_h)*P); a_mx=(asin(Q))*(180/3.14);//the theoretical max coverage angle in degree D=(r^2)+(r_h^2)-2*r*r_h*sin(a_mx*3.14/180); d=sqrt(D);// in km d1=ceil(d);//m...
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/1583/CH4/EX4.6/FSNT_Ex_4_6.sce
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2020-04-09T02:43:26.499817
2018-02-03T05:31:52
2018-02-03T05:31:52
37,975,407
3
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UTF-8
Scilab
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521
sce
FSNT_Ex_4_6.sce
clc //Chapter 4:Frequency selective networks and transformers //example 4.6 paga no 130 //given Rs=10//source resistance L=0.2*10^-6//inductor f=20*10^6//given frequency XL=(2*%pi*f*L)//inductive reactance Rp=50//input impedance Xs=sqrt(Rp*Rs-Rs^2)//series reactance Xcs=5.1//series capacitive reactance CS=(...
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/2417/CH9/EX9.14/Ex9_14.sce
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FOSSEE/Scilab-TBC-Uploads
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2020-04-09T02:43:26.499817
2018-02-03T05:31:52
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sce
Ex9_14.sce
//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 9.14\n\n\n"); // Chapter 9 : Gas Power Cycles // Problem 9.14 (page no. 489) // Solution //A Brayton cycle rc=7; //Compression Ratio Rc=v2/v3 k=1.4; //It is apparent incerease in compression ratio yields an increased cycle efficiency cp=0.24; //Unit...
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2020-04-09T02:43:26.499817
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sce
Example_11_10.sce
clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 11.10 //Caption : Program to Find the Excess Properties for a mixture T0=298.15;//[K] T=323.15;//[K] Cp_E=-2.86;//[J/mol/K] Ho_E=897.9;//[J/mol] Go_E=384...
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2020-04-09T02:43:26.499817
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sce
12_2.sce
//Steel ball shot vertically up //refer fig.12.6 //For upward motion au=18 //m/sec av=0 aa=-9.81 //m/sec^2 //s=h //let t1 be the time required to reach maximum height t1=1.83 //sec h=(18^2)/(2*9.81) //m //total height from the ground ah=25+h //m //Downward motion bu=0 bs=41.51 //m ba=9.81 //m/sec^...
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2020-04-09T02:43:26.499817
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sce
Ex12_6.sce
// Ex12_6 Page:248 (2014) clc; clear; e = 1.6e-019; // Charge on an electron, C n = 5e+028; // Number of atoms per unit volume of Cu, per metre-cube R_H = -1/(n*e); // Hall coefficient, metre-cube/C printf("\nThe Hall coefficient for Cu = %4.2e metre-cube/C", R_H); // Result // The Hall coefficient for Cu = ...
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/source/2.5/macros/m2sci/replace_brackets.sci
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[ "LicenseRef-scancode-public-domain", "LicenseRef-scancode-warranty-disclaimer" ]
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clg55/Scilab-Workbench
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replace_brackets.sci
function txt=replace_brackets(txt) // Copyright INRIA for k=1:size(txt,'r') tk=txt(k) ko=strindex(tk,'{') if ko<>[] then kf=strindex(tk,'}') //create matching pairs kw=[ko,kf] for kk=1:size(ko,'*') pchar=abs(str2code(part(tk,ko(kk)-1))) if pchar<36 then // extraction end end
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/java-src/emulator/assembler/go.tst
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artagesw/FROIDZ
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2016-09-06T13:50:26.181686
2012-05-21T22:59:49
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go.tst
0100 0011 0000 0000 0001 0000 0100 1000 0100 0110 0000 0000 1000 0111 0001 0000 0100 0011 0000 0000 0001 0001 1111 1111 0100 0001 0000 0000 0001 0100 0001 0001 0100 0011 0000 0000 0001 0100 0000 0000 0100 0001 0000 0000 0001 1000 0001 0100 0100 0011 0000 0000 0001 0010 1111 1111 0100 0001 0000 0000 0001 1000 0001 0010 ...
e06b4c88683b85d4b928a097eae185c651b746d7
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/sci2blif/sci2blif_added_blocks/pad_out.sce
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[]
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jhasler/rasp30
9a7c2431d56c879a18b50c2d43e487d413ceccb0
3612de44eaa10babd7298d2e0a7cddf4a4b761f6
refs/heads/master
2023-05-25T08:21:31.003675
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62,917,238
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sce
pad_out.sce
//**************************** IO PAD OUT ****************************** if(blk_name.entries(bl)=='pad_out') then fd_io= mopen (fname+'.pads','a+'); // DEDICATED PADS code for ss=1:scs_m.objs(bl).model.ipar(1) tmp_pad = strsplit(iopad_loc(loc_num,scs_m.objs(blk_objs(bl)).model.rpar(ss)).entries," ") ...
785f1fa8dac0bd4bd6e8c251c9f3caa2527335be
cc3bff70280a1ee19aaf881e852ab1d5a8a1014d
/Experiment No.3 - PDF of different random variable.sce
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imdeepak27/Digital-Communication-Systems
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e35a99437a63bb023e2d6468ecfb92633d6049e5
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2022-06-18T01:07:37.718079
2020-05-13T04:26:12
2020-05-13T04:26:12
263,524,581
0
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null
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UTF-8
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661
sce
Experiment No.3 - PDF of different random variable.sce
clc; clear; u=input(" "); v=input(" "); disp("GAUSSIAN RANDOM VARIABLE"); disp("MEAN = "+string(u)); disp("VARIANCE = "+string(v)); x=-10:0.001:10; N=1/sqrt(2*3.14*v)*exp(-(x-u)^2/(2*v)); figure(1); plot(x,N); xlabel("x"); ylabel("PROBABILITY DENSITY"); title("GAUSSIAN PDF"); a=input(" "); b=input(" ")...
4c1d99a8b1d21ccc61d7b38486f81ce135c3ead5
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/bin/PIL_read_mat.sci
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pipidog/PiLib-Scilab
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2021-01-18T20:30:43.364412
2017-08-17T00:58:50
2017-08-17T00:58:50
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sci
PIL_read_mat.sci
// **** Purpose **** // This is a read function of the standard output format of my library // This format also consistent with my Fortran output format // **** Variables **** // [fid]: 1x1, integer // <= your file ID // [read_range]: 2x2, integer, default: read all data // <= specify the range you want to read,ex:[3,1...
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/projects/02/Ng16.tst
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btesf/nand_to_tetris
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2021-06-19T17:09:22
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tst
Ng16.tst
load Ng16.hdl, output-file Ng16.out, compare-to Ng16.cmp, output-list a%B1.16.1 out%B1.1.1; set a %B0000000000000000, eval, output; set a %B1111111111111111, eval, output; set a %B1010101010101010, eval, output; set a %B0011110011000011, eval, output; set a %B0001001000110100, eval, output;
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/output/KNN/resultadoKNN4.tst
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no_license
joseangeldiazg/probabilistic_keel
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6c5ddf8c98cc7431d523b291e521d1e8607dc662
refs/heads/master
2020-05-21T12:26:41.754863
2017-01-08T10:29:44
2017-01-08T10:29:44
55,733,275
1
0
null
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null
null
UTF-8
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787
tst
resultadoKNN4.tst
@relation ecoli @attribute Mcg real [0.0, 89.0] @attribute Gvh real [1.0, 88.0] @attribute Lip real [1.0, 48.0] @attribute Chg real [1.0, 5.0] @attribute Aac real [0.0, 88.0] @attribute Alm1 real [1.0, 94.0] @attribute Alm2 real [0.0, 99.0] @attribute Site {cp, im, imS, imL, imU, om, omL, pp} @data cp cp cp cp cp cp ...
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/1184/CH2/EX2.13/Ex2_13.sce
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2020-04-09T02:43:26.499817
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sce
Ex2_13.sce
//Example 2-13, Page No - 40 clear clc pout_db =12.3 pout_mW = 0.001*10^(12.3/10) printf('The output power is %.1f mW',pout_mW*10^3)
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/scilab/final/wave_intro/wave1d.sce
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no_license
mikeg2105/matlab-old
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refs/heads/master
2021-05-01T07:58:19.274277
2018-02-11T22:09:18
2018-02-11T22:09:18
121,167,118
1
0
null
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null
null
UTF-8
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false
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509
sce
wave1d.sce
//1d wave //return a 1d vector of wave amplitudes function [wave1d]=wave1d(time, wavetype, maxamplitude, wavenumber, wavefreq,delta, n) wave1d=zeros(n); k=wavenumber; //stationary/standing wave if wavetype == 0 then for i=1:n wave1d(i)=maxamplitude*sin((k*i*delta))*sin(wavefreq*time); ...
0961d1b9d6382c24a88e0fbdf17e4897997820f7
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/Hack Computer/Assembly Language Programs/Program1/Program1.tst
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[]
no_license
saha-nab2001/Hack-ALU-and-Hack-CPU-in-HDL
087c9d59a9032ac4a145b8f899364ee9d6a6d74d
3b1c461aa0f331ce7d7505b6ad9b0eab70f102e3
refs/heads/main
2023-06-15T16:59:24.758610
2021-07-19T15:50:45
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387,511,878
0
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null
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UTF-8
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681
tst
Program1.tst
load HackComputer.hdl, output-file Program1.out, output-list time%S1.4.1 reset%B2.1.2 ARegister[0]%D1.7.1 DRegister[0]%D1.7.1 PC[]%D0.4.0 RAM64[16]%D1.7.1 RAM64[17]%D1.7.1 RAM64[18]%D1.7.1 RAM64[19]%D1.7.1; ROM32K load Program1.hack, output; // First run (at the beginning PC=0) set RAM64[16] 3, set RAM64[17]...
673a192e6e7cdfe1001e57b560a520cd88960be0
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/1962/CH2/EX2.6/example2_6.sce
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no_license
FOSSEE/Scilab-TBC-Uploads
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example2_6.sce
//example 2.6 //page 66 clc; funcprot(0); //initialisation of variable Gamma=9810; ybar=5+0.5; pi=3.14; theta=90/180*pi; Ig=pi*1^4/64;//moment of Inertia A=pi*1^2/4; F=Gamma*A*ybar;//force hbar=ybar+Ig*(sin(theta))^2/A/ybar;//centroid F1=F*(hbar-5); disp(F1,"Force required to open the gate (N)"); clear