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//Exa Misc 8.2 clc; clear; close; //given data format('v',6); fo=10;//in KHz R1=25;//in kohm R2=60;//in kohm Rc=40;//in kohm R=7.1;//in kohm hie=1.8;//in kohm C=1/(2*%pi*fo*10^3*R*10^3*sqrt(6+4*Rc/R));//in F disp(C*10^9,"Value of Capacitor(in nF) :"); hfe=23+29*R/Rc+4*Rc/R;//unitless disp("Value of hfe i...
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function [nsize,nodes]=max_clique(g,ind) // Copyright INRIA [lhs,rhs]=argn(0) if rhs>2|rhs<1 then error(39) elseif rhs==1 then ind=0 end; // check g check_graph(g) // check ind if (ind<>0&ind<>1) then error('The second argument must be 0 or 1') end m=prod(size(g('tail'))) n=g('node_number') head=g('head'); tail=...
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7_1.sce
clear; clc; c=3*(10^8); f=3000*(10^8); lo=c/f; l=lo*(10^4); m=1;n=0;a=7.62; lc=2*a; printf("-Critical wavelength = %f cm\n",lc); lg=sqrt((l*l*lc*lc)/((lc*lc)-(l*l))); printf("-Guide wavelength = %f cm",round(lg*10)/10);
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//Chemical Engineering Thermodynamics //Chapter 14 //Thermodynamics of Chemical Reactions //Example 14.6 clear; clc; //Given //SO2 + (1/2)O2 - SO3 //Basis: 1 Kgmole of SO2 n_SO2 = 1;// SO2 fed in Kgmole //From table 14.1 (page no 301) //alpha values for the following components are given as a_SO2 = 7.116; a_O2 = 6.14...
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errcatch(-1,"stop");mode(2);//Exa4.12 ; ; //given data Vz=5;//in volts to=25;//in degree centigrade t=100;//in degree centigrade Vdrop=4.8;//in Volts delVz=Vdrop-Vz;//in Volts delt=t-to;//in degree centigrade TempCoeff=delVz*100/(Vz*delt); disp(TempCoeff,"Temperature coefficient f zener diode in % : "); e...
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clc clear //Initialization of variables n1=8 n2=9 n3=1 n4=12.5 U11=3852 U12=115 U21=3009 U22=101 U31=24773 U32=640 U41=2539 U42=83 H=-2203389 //calculations dU1=n1*(U11-U12)+n2*(U21-U22) dU2=n3*(U31-U32)+n4*(U41-U42) Q=H+dU1-dU2 //results printf("Heat of reaction = %d Btu",Q)
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// This file was created by Evyatar. load EQ2.asm, output-file EQ2.out, compare-to EQ2.cmp, output-list RAM[0]%D2.6.2 RAM[256]%D2.6.2; set RAM[0] 256, // initializes the stack pointer repeat 200 { // enough cycles to complete the execution ticktock; } output; // the stack pointer and the stack ba...
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clear clc w1=1;//amount of glucose C6H12O6 in gm w2=1;//amount of sucrose C12H12022 in gm n=(w1/180)+(w2/342);//amount of solute R=8.314;//in J/Kmol T=25;//in C V=1000;//volume of water in gm P=(n*R*(T+273))/(V*10^-6);//osmotic pressure of solution printf('P=%.3f *10^4 N/m^2',P/10^4) w=(w1+w2);//weight of so...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 3 : TRANSFORMERS // EXAMPLE : 3.10 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA V1 = 440; // HV Side Voltage Rating o...
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//Exa 2.6 clc; clear; close; //given data ni=1.4*10^18;//in atoms/m^3 Nd=1.4*10^24;//in atoms/m^3 n=Nd;//in atoms/m^3 p=ni^2/n;//in atoms/m^3 ratio=n/p;//unitless disp(p,"Concentration of holes in per m^3 : "); disp(ratio,"Ratio of electron to hole concentration : ");
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// Example 22_15 clc;funcprot(0); //Given data T_1=400;// °C p_1=40;// bar p_2=2;// bar p_3=0.5;// bar p_4=0.05;// bar n_t1=75/100;// The isentropic efficiency of the first stage of the turbine n_t2=80/100;// The isentropic efficiency of the second stage of the turbine n_t3=85/100;// The isentropic efficiency...
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//EXAMPLE 2-108 PG NO-146 I1=(100/1.414)^2; I2=(10/1.414)^2; R.M.S=(I1+I2)^0.5; disp('R.M.S VALUE is = '+string(R.M.S)+' A');
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smooth.sci
function [pt]=smooth(ptd,pas) // [lhs,rhs]=argn(0) [m,n]=size(ptd) d=splin(ptd(1,:),ptd(2,:)) if rhs=1 then l=abs(ptd(1,n)-ptd(1,1));pas=l/100;end pt=[ptd(1,1)+pas:pas:ptd(1,n)] pt=[ptd(:,1) [pt;interp(pt,ptd(1,:),ptd(2,:),d)] ptd(:,n)]
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//Chapter-5,Example 5_14,Page 5-31 clc() //Given Values: m=1.676*10^-27 //mass of neutron h=6.625*10^-34 //Planck's constant lam=1*10^-10 //wavelength of neutron //Calculations: C=3*10^8 //Velocity of light Ep1=h*C/lam //Energy of photon in joules E1=...
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clc// // // //Variable declaration V=20*15*5; //volume(m^3) T=3.5; //time(s) A=950; //surface area(m^2) //Calculation sigma_as=0.165*V/T; //total absorption in the hall(OWU) ac=sigma_as/A; //average absorption coefficient //Result printf("\n total absorption in the hall is %0.3f...
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9_06.sce
clear clc FAo=1000;//mol/min //Drawing trial operating lines with a slope of 1/72 and for each evaluating integral dXA/-rA //From graph Area=1.72; V=FAo*Area; printf("\n The volume of adiabatic plug flow reactor is %f",V) printf("litres")
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// to find load voltage and load current using ideal diode // Example 3-3, page 65 clear;clc; close; // Given data // diode is forward biased, equivalent to a closed switch. // Calculations V=10;// load voltage in volts R=1000;// load resistance in ohms I=V/R;// all the source voltage appears across the load resist...
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//Caption:Design a square wave generator using 7555 CMOS //Ex8.4 clc; clear; close; V=5//Supply voltage(in volts) f1=1//Frequency(in khz) f2=3//Frequency(in khz) C=0.01//Capacitance(in micro farad) Ra=47//Choosed resistor(in kilo ohm) t1=1/(2*f1) t2=1/(2*f2) R=t1/(0.693*C) Rb=R-Ra disp(C,Rb,Ra,'Components...
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Ex20_6.sce
//chapter20 //example20.6 //page441 Vin_min=22 // V Vout=15 // V Il_max=0.1 // A // for maximum series resistance, we consider the case when input voltage is minimum and load current is maximum because then zener current drops to minimum.Thus, Rs_max=(Vin_min-Vout)/Il_max printf("required series resistanc...
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example25.sce
//Example 2.5 clc; Max_Limit=10; h=ones(1,Max_Limit); N2=0:length(h)-1; a=0.5;//constant a>0 for t=1:Max_Limit x(t)=exp(-a*(t-1)); end N1=0:length(x)-1; y=convol(x,h)-1; N=0:length(x)+length(h)-2; figure a=gca(); plot2d(N2,h) xtitle('Impulse Response','t','h(t)'); a.thickness=2; figure a=gca(); plot2d(N1,x) xtitle('Inp...
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17_5.sce
clc //initialisation of variables M1= 18.02 //gms m1= 0.965 //gms m2= 0.035 //gms M2= 58.5 //gms R= 8.314 //J/mol K M= 18.02 //kg T= 20 //C vf= 0.001002 //m^3 x21= 0.021856 //m^3 //CALCULATIONS n1= m1/M1 n2= m2/M2 x1= n1/(n1+n2) x2= n2/(n2+n1) P= R*(273.15+T)*x2/(M*vf) P1= R*(273.15+T)*x21/(M*vf) //R...
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2_19.sce
clc,clear printf('Example 2.19\n\n') V=110 P=4 R_a = 0.1,R=0.01 //A resistance of 0.01 ohms R_se=R+R //case(i) I_1=50, I_a1=I_1 N_1=700 E_b1 = V -I_a1*(R_a + R_se) //T (prop.) phi*I_a from torque equation (1) //phi_1 (prop.) I_a1 ...
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CH18Exa15.sce
// Scilab code Exa18.15 : : Page-768 (2011) clc; clear; I_1 = 3/2; // Isospin for delta(1232) I_2 = 1/2; // Isospin for delta 0 delta_ratio = sqrt((2/3)^2)/sqrt((1/3)^2); // Branching ratio printf("\nThe branching ratio for a resonance with I = 1/2 is %d", delta_ratio); // Result // The branchin...
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Ch3_3_54.sce
clc disp("Example 3.54") printf("\n") disp(" Draw a DC load line for the base bias circuit neglecting Vbe") printf("Given\n") //given betadc=100 Rc=5*10^3 Rb=1.5*10^6 Vc=30 //to find Ib Ib=Vc/Rb //from ciruit //Ic value Icq=betadc*Ib //Vce value Vceq=Vc-(Icq*Rc) //to draw DC load line Ic1=Vc/Rc Vce1=...
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Ex_9_2.sce
// Example 9.2;//photocurrent clc; clear; close; R=0.85;//responsivity in ampere per watt Po=1;//output power in milli watt Ip= R*Po;//photocurrent in milli ampere disp(Ip,"photocurrent in milli ampere is ")
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7_10.sce
clc; b=0.228; a=1-b; c=[1+(2*0.455)-b-2*a]/2 n2=a+b+c+1.709; p1=8.28; T2=555; n1=1+0.455+1.709; T1=2968; p2=p1*(n2/n1)*(T1/T2); p=1; K=a/b*[n2*p/(c*p2)]^0.5; disp(log(K),"log(K) is:"); disp("2968","from tables it is proved that temperatur is:")
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Ex8_12.sce
// Variable declaration val = 0 data1 = [27,23,64,44,30,75,26,124,54,30,14] data2 = [15,13,22,29,31,64,30,64,56,20,21] y = [1,1,1,1,1,1,1,1,1,1.1,1] d = [] alpha = 0.05 // level of significance for i = 1:11 d(i) = data1(i)-data2(i) end n = length(d) Mean = sum(d)/(length(d)) // Calcula...
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r_lineal.sce
clear /////////////////////////////////////////////////////// // r_lineal.sce // // Este programa obtiene los coefientes de una ecuacion // lineal por medio de sus fórmulas de regresión, dado // un conjunto de pares coordenados. // // José Elías Garza Vázquez // 22 / 01 / 20 version 1.0 //////////////...
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19.sce
clc clear //INPUT DATA n=2//no.of atoms in BCC structure d=7.86*10^6//density of iron of FCC structure in kg/m^3 AW=55.85//atomic weight of Fe N=6.023*10^23//Avogadro's Number per Kg mol //CALCULATION a=(((n*AW)/(d*N))^(1/3))/10^-10//The lattice constant in m r=((a*sqrt(3))/4)//The atomic radius of Fe which ...
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clc //Variable Initialisation Ea=230//Input Voltage of motor in volts Ia=50//Armature Current in Ampere N1=800//Rated Speed of Motor in rpm Ra=0.4//Armature resistance in ohm d1=0.3//Duty ratio for Motoring Operation d2=0.6//Duty ratio for Motoring Operation d3=0.7//Duty ratio for Braking Operation d4=0.4//Dut...
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12_3.sce
//chapter 12 //example 12.3 //page 371 clear all; clc ; //given Vcc=20;//supply voltage Rl=500;//load resistance Av=75;//closed loop voltage gain f1=30;// i/p signal frquency Hz hfe=80; hie=1.4; Ve=5;Vce=3; VR2=5.7; Vbe=5; VR3=Vcc-Vce-Ve; R3=Rl/10; Ic=VR3/R3*10^3; printf("\ncollector current = %d micr...
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// Theory and Problems of Thermodynamics // Chapter 4 // Energy Analysis of Process // Example 10 clear ;clc; //Given data V = 2 // volume in m^3 gam = 1.67 // gamma ideal gas coefficient P0 = 0.1 // Initial Pressure in MPa T0 = 300 // Initia...
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variants.sce
k=1; cp=zeros(1,991); c=zeros(1,991); noe=zeros(1,991); for n=10:1000 noe(k)=n; a=round(rand(1,n)*100); [cmp_h,ab] = quick(a,1,n,0); [cmp_r,ar] = sorttest_quick(a,1,n,0); cp(k) = cmp_r; c(k) = cmp_h; k=k+1; end plot(noe,cp,"m"); plot(noe,c); xlabel("ARRAY SIZE"); ylabel("NUMBER OF CO...
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example5_5.sce
disp('chapter 5 ex5.5') disp('given') disp('709 op-amp is used to design an noninverting amplifier') disp('voltage gain Av=50') Av=50 disp('voltage gain Av=50=34dB') disp('compensation components are listed for Av=20dB and for Av=40dB') disp('for over compensation use components for Av=20dB') disp('C1=500pF R1=...
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try type(cdo_factor); delmenu('CDO'); catch // exec builder.sce; exec loader.sce; end; addmenu('CDO',['Product';'Model';'Computation';'Last computation';'Numdef';'Losses']); CDO=['exec(''product.sci'',-1)';'exec(''model.sci'',-1)';'exec(''computation.sci'',-1)';'exec(''last_computation.sci'',-1)';'exec...
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//problem 16 pagenumber 2.99 //given f1=500;//hz f2=2.2e3;//hz a=5; c=0.1e-6;//farad rf1=10e3;//ohm //determine r1 r2 R1=1/(2*3.14*f1*c); R2=1/(2*3.14*f2*c); Ri=2e3;//ohm assuming Rf=(a-1)*Ri;format(6); disp('R = '+string(R1/10^3)+' Kohm'); disp('R2 = '+string(R2/10^3)+' Kohm');//error in book disp('R1 = ...
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clc; clear; funcprot(0); function V0 = UpOutPut_BS_MC_Richardson (S0, r, sigma, T, K, B, M, m) delta_t = T/(2*m); // Fine mash // generate a Matrix of mxM normaly distributed r.v. with mean = 0 and ... // sd = sqrt(delta_t) delta_W1 = grand(m, M, "nor", 0, sqrt(delta_t)); delta_W2 = grand(m,...
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Ex1_3.sce
//Example 1-3, Page No - 15 clear clc wavelength_feet=75 wavelength_meter= 75/3.28 c=300000000 frequency=c/wavelength_meter printf('The signal frequncy is %.3f Megahertz',frequency/1000000)
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex8_4.sce clc; clear; p=4; s=21; Cs_per_slot=4; Cs=Cs_per_slot*s; printf("\n Number of coil sides=%d \n",Cs) C=Cs/2; printf("\n Number of coils=%d \n",C) Yc1=(C...
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clear clc t = [0:0.001:4] //tempo l1 = 1 //tamanho do braco 1 l2 = .5 theta1 = %pi*t/8 //theta1 em funcao do tempo theta2 = %pi*(t.^2)/16 // theta2 em funcao do tempo dtheta1 = %pi/8 dtheta2 = -%pi*t/8 ddtheta1 = 0 ddtheta2 = -%pi/8 //Movimento x = l1*cos(theta1) + l2*cos(theta1+theta2) y = l1*sin(theta1) + l2*si...
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//Example6.22 // To determine the output voltage clc; clear; close; Vin = 2 ; R2 = 20*10^3 ; R1 = 2*10^3 ; // the output voltage of follower Vo1 is Vo1 = Vin ; disp('the output voltage of follower Vo1 is = '+string(Vo1)+ ' V'); // the output voltage of an inverting amplifier Vo = -(R2/R1)*Vo1 ; disp('Th...
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clear all; clc; disp("From figure 8.14c we have Pl=620hp at N=18400rpm. Pick a point on the curve of N/(T01^0.5)=18400/(530^0.5)=800") disp("In figure 8.14a,say p02/p01=5") disp("So we have") disp("m(T01^0.5)/p01 ETAc p02(psia) m(lbm/s) p03(psia) p03/p04") disp(" 5.7 0.85 73.5 ...
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//Fuels and Combustion// //Example 8.18// C=624;//weight of carbon in 1kg of coal sample in grams// O=69;//weight of oxygen in 1kg of coal sample in grams// S=8;//weight of Sulphur in 1kg of coal sample in grams// N=12;//weight of nytrogen in 1kg of coal sample in grams// H=41;//weight of hydrogen in 1kg of coal ...
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//Example 15.11 //Midpoint Method //Page no. 518 clc;clear;close; deff('y=f(x,y)','y=y+x') y=1; h=0.2; printf('i\txi\tyi\tslope1\tslope2\ty(i+1)\n-----------------------------------------------\n') for i=1:3 x=(i-1)*h s1=f(x,y); s2=f(x+h/2,y+s1*h/2); printf(' %i\t%g\t%g\t%g\t%g',i-1,x,y,s1,s...
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clc printf("\n") //let //S=displacement of car from rest with uniform acceleration a, the engine torque T assumed to remain ocnstant //v=final speed ofcar //G=gear ratio //r=effective radius //n=efficiency of transmission //M=mass of the car //Ia and Ib=moments of inertia of road whels and engine //formula...
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FLAGS='--detect --list' STDIN='' STDOUT='' STDERR='!USAGE!' EXITVAL='1'
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 4: OVERHEAD LINE INSULATORS // EXAMPLE : 4.1 : // Page number 183 clear ; clc ; close ; // Clear the work space and cons...
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exec("mnprobln.sci",2); function ok=test_mnprobln() mu=[1;-1]; Sigma=[5 6;6 9]; n1=51; y1=linspace(-10,10,n1); n2=51; y2=linspace(-10,10,n2); y=zeros(2,n1*n2); for i1=1:n1 b=(i1-1)*n2; y(1,b+1:b+n2)=y1(i1); y(2,b+1:b+n2)=y2; end dy=((y1(n1)-y1(1))/(n1-1))*((y2(n2)-y2(1))/(n2-1)); p=...
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//Initilization of variables theta=45 //degrees l=0.5 //m w=10 //rad/s //Calculations //PART a //Here the theta derivative with respect to time is angular speed w Vp1=l*(secd(theta)^2)*w //m/s //Part b //Radial Component r=l*secd(theta)*tand(theta)*w //m/s //Transverse Component t=l*secd(theta)*w //m/s //T...
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//ex_23 product of discrete signal and unit step function clear; clc; close; t=-3:3; x=[3 2 1 0 1 2 3]; //u[1-n] for i=1:length(t); if t(i)<=1 then u1(i)=1; else u1(i)=0; end end y=x.*u1'; figure a=gca(); plot2d3(t,y) plot(t,y,'r.') xtitle('y[n]','n') a.y_location='origin...
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// Example 3.2: calculate the input impedence, output impedence, voltage gain and current gain clc, clear; Hie=3.2; // the h-parameters of the transistor in kilo-ohm Hfe=100; // the h-parameters of the transistor R1=40; // resistance in kilo-ohm R2=4.7; // resistance in kilo-ohm; Rc=4; // resistance in kilo-ohm...
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// chapter 2 // example 2.9 // Fig. 2.17 // Calculate the value of commutating capacitance // page-54 clear; clc; // given Edc=120; // in V (source voltage) I=20; // in A (current) t_off=60; // in us (turn-off time of both SCR) // calculate R1=Edc/I; // calculation of R1 R2=R1; // calculation of R2 C=1.44*t_off/R1; // ...
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clear; clc; ld=100; //load in KW v=500;............// voltage in volts res=1.75*(.000001);...........//restivity in milli ohm per cm sq nos_cores=2;.......//number of feeder core l=0.8;.............//length of tx line in km area=1;...........//area in cm sq cost_of_energy=0.12;..//cost in Rs per un...
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clc //Initialization of variables T1=400+460 //R P1=100 //lb/in^2 P2=20 //lb/in^2 T2=140+460 //R Cp=50 //calculations Pratio=P1/P2 Tratio=T1/T2 C=log(Tratio) /log(Pratio) n=1/(1-C) v1=Cp*T1/(144*P1) v2=Cp*T2/(144*P2) w=144*P1*v1^n function[p]=fun(v) p=w/v^n endfunction Work=intg(v1,v2,fun) //results printf("Work done ...
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function a=%sp_sum(a,flag) // Copyright INRIA [m,n]=size(a); if flag==2|flag=='c' then a=sparse(a*ones(n,1)) end if flag==1|flag=='r' then a=sparse(ones(1,m)*a); end
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//Example 20_3 clc(); clear; //To find the current through the inductor f=60 //Units in Hz l=15*10^-3 //Units in H xl=2*%pi*f*l //Units in Ohms v=40 //Units in V i=v/xl //Units in A printf("The current in the inductor when frequency=60 Hz is I=%.2f A",i) f=6*10^5 ...
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function total = hitung(atas) jum = 0; i=1; while i < atas if i modulo 5 = 0 then jum = jum + i; end i=i+1; end total = jum; endfunction
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rewrite ^(.+)$ /index.html last;
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//calculate the current I1.I2 I=12 R1=6 R2=8 I1=I*R2/(R1+R2) I2=I*R1/(R1+R2) disp('I1='+string(I1)+'amps' , 'I2 ='+string(I2)+'amps')
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clc //initialisation of variables Ksp= 2*10^-12 M= 8.84*10^-5 //molar n= 2 //CALCULATIONS r= (Ksp/(n^2*M^3))^(1/3) //RESULTS printf ('mean ionic activity coefficient = %.1f ',r)
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clc; k=[1 1 0 1; 0 1 1 1]; karmap3(k);
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//To find angle and maximum velocity clc //Given: phi=20 //degrees t=20, G=2 m=5 //mm v=1.2 //m/s addendum=1*m //mm //Solution: //Angle turned through by pinion when one pair of teeth is in mesh: //Calculating the pitch circle radius of pinion r=m*t/2 //mm //Calculating the pitch circle radius of wheel R=m...
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## Test of the unite feature read <bzr.fi read <testrepo.fi unite bzr testrepo write -
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clc //initialisation of variables R= 0.08205 //l-atm deg^-1 mole^-1 T= 25 //K n= 1 //mole V= 0.5 //lit b= 0.04267 //lit mole^-1 a= 3.592 //lit^2 atm mol^-2 //CALCULATIONS P= R*(273.15+T)/V P1= (R*(273.15+T)/(V-b))-(a/V^2) //RESULTS printf ('pressure calculated using ideal gas law= %.1f atm',P) printf ('\n...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.392222D+00 ...
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clc //initialisation of variables p= 800 //atm P= 10000 //psi x= 14.696 //psi/atm //CALCULATIONS P1= p*x //RESULTS if (P1>P) then disp("Salesman is honest")
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FLAGS='--list --print NONE' STDIN='' STDOUT='' STDERR='!USAGE!' EXITVAL='1'
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clear; clc; v=400; Xl=.30; Xc=3.75*10^(-6); l=300; L=Xl/(2*%pi*50); C=Xc/(2*%pi*50); Zc=sqrt(L/C); mprintf(" surge impedence is %.3f ohm\n",Zc); phase=2*%pi*50*sqrt(L*C); pconstant=%i*phase; mprintf("propagation constant is %.4f\n",imag(pconstant)); A=cos(phase*l); D=A; B=%i*Zc*sin(phase*l); C=(%i*sin(p...
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x = 0:5:35; y = [0 20 43 59 89 124 154 200]; h = 5; x = 25/h + 1 velocityAt25seconds = (y(x + 1) - y(x - 1)) /(2* h) ; accelerationAt25seconds = (y(x + 1) - (2 * y(x)) + y(x - 1))/(h^2) x = 1; velocityAt0seconds = (y(x + 1) - y(x)) /(h) ;
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//Mass flow// pathname=get_absolute_file_path('12.02.sce') filename=pathname+filesep()+'12.02-data.sci' exec(filename) //Checking for chocking: c=pb/p0; if(c<=0.528) //choked else //Not choked //Therefore pressure at exit = back pressure pe=pb; //Mach number at exit: Me=(((p0/pe)^((k-1)/k)-1)*(...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.303401D+00 ...
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clear; clf; dt = 1/10000; //Generating a sine wave and then passing it through a quadratic function t = -0.01:dt:0.01; x = sin(200.*(%pi).*t); a = 3; b = 5; y = a.*x + b.*x.*x; subplot(2,1,1); plot(t,x); xgrid(1); xlabel("T", "fontsize", 3); ylabel("X", "fontsize", 3); title("Sine wave: x", "fontsize", 3); subplot...
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function f = soal_06(z) epsilon0 = 0.885e-12 F = 0.3 Q = 9.4e-6 q = 2.4e-5 R = 0.1 c = 1 - z/sqrt(z^2 + R^2) f = Q*q*c/(2*epsilon0) - F endfunction function F = eval_F(z) epsilon0 = 0.885e-12 Q = 9.4e-6 q = 2.4e-5 R = 0.1 c = 1 - z/sqrt(z^2 + R^2) F = Q*q*c/(2*epsilon0) endfunction function ...
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//Ex 3.4 clc; clear; close; format('v',5); SR=0.5;//V/micro second Vm=10;//V f=100;//kHz fm=(SR/10^-6)/(2*%pi*Vm);//Hz disp(fm/1000,"Maximum frequency, fm is(kHz)");
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clc; close(); clear(); //page no 379 //prob no. 11.8 B=400*64; //Mb/s mprintf('Memory bus bandwidth = %i Mb/s or %i MB/s',B,B/8);
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// Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clear// //Variables VCC = -18.0 //Source voltage (in volts) RC = 4.3 //Collector resistance (in kilo-ohm) RE = 1.0 //Emitter resistance (in kilo-ohm) beta = 200.0 //Common emitter current gain VBE = -0...
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//example 12.9 clc; funcprot(0); // Initialization of Variable k1=0.88;//p2/poy; k2=0.628;//poy/pox pox=100;//pressure R=1545; T2=494; k=1.4; M2=0.24; A=2.4; V2=M2*sqroot(k*R/28.97*T2*32.2); mdot=95.9*A*V2/T2/R*28.97; disp(mdot,"mass flow rate in lb/s"); p2=k1*k2*pox; disp(p2,"pressure in lbf/in^2") cle...
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// Exa 1.22 clc; clear; close; // Given data miu_p= 0.05;// in m^2/v-sec rho=5*10^28/10^8;// in /m^3 q= 1.6*10^-19;// in C sigma= q*rho*miu_p;// in (Ωm)^-1 disp(sigma,"The conductivity of silicon material in (Ωm)^-1 is : ")
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clc; //Example 10.3 //Page No 400 disp("Given: For figure, Analog sample voltage of +1.07 V. ;"); //solution a=1.07/1 disp(round(a)); disp("The quantization error is the difference between the original sample voltage and the quantized level, or"); q=1.07-1; disp(q,"Qe = "); disp("From Table 10-2, the PCM code...
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a=1 theta=0:%pi/64:2*%pi; r=a*(1-cos(theta)) polarplot(theta,r) r=a*sin(theta) polarplot(theta,r)
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// here is an example use of the while statement // which is used for finding the root of a polynomial // which is known to lie within a certain interval. // a is the lower value of the range // b is the upper value of the range a= 0; fa = -%inf; b =3 ; fb = %inf ; while abs(b-a) > %eps*b x = ( a + b ) ...
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//Ex 6.4 clc;clear;close; format('v',5); Range=0:10;//range //(i)2-bit DAC n=2;//no. of bits step=max(Range)/2^n;//V reading='10';//input in binary Vo=step*bin2dec(reading);//V disp(Vo,"(i) Output Voltage(V)"); //(ii)4-bit DAC n=4;//no. of bits step=max(Range)/2^n;//V reading='0110';//input in binary Vo=s...
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EX20_39.sce
clc;funcprot(0);//EXAMPLE 20.39 // Initialisation of Variables N=10000;.................//Compressor rpm v=660;............//Volume of air delivered in m^3/min p1=1;.................//Inlet pressure in bar t1=293;.............//Inlet temperature in K rp=4;.............//Pressure ratio etaisen=0.82;........//Isen...
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errcatch(-1,"stop");mode(2);//Example 1_52 ; ; //To find diameter of 25th ring dm=0.62 //units in cm ds=0.3 //units in cm d25=2*(dm^2-ds^2)+ds^2 //units in cm^2 d25=sqrt(d25) //units in cm printf("Diameter of 25th ring is %.3f cm",d25) exit();
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//Variable Declaration x = [0.1 0.4 0.1 ; 0.2 0.2 0] //Calculation p1 = x(2,1)/sum(x(2,1:3)) // for x1=0 & x2=1 p2 = x(2,2)/sum(x(2,1:3)) // for x1=1 & x2=1 p3 = x(2,3)/sum(x(2,1:3)) // for x1=2 & x2=1 // Result printf ( "P(0|1): %.2f , P(1|1): %.2f , P(2|1) : %.2f",p1,p2,p3) printf ( "As P(0|1) is not equal...
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Ex10_11.sce
clear // // // //Variable declaration epsilon0=8.854*10^-12; //relative permeability(F/m) alphae=10^-40; //dielectric polarizability(Fm^2) N=3*10^28; //number of atoms //Calculations epsilonr=1+(N*alphae/epsilon0); //dielectric constant //Result printf("\n dielectric constant is...
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Thalf1= 2.5*(10^5); //half-life of U-234, y AtomicRatio= 1.8*(10^4); //atomic ratio of u-238 and U-234 in the sample Thalf2= AtomicRatio*Thalf1; //using Eqn12.9 disp(Thalf2,"The half-life of Uranium-238, in years, is: ") //Result // The half-life of Uranium-238, in years, is: // 4.500D+09
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clear all; clc; disp("Ex 5_16") disp("Free body diagram is as shown in fig 5-30b") //Initilization of variables F=[0,0,-200] //matrix notation //Calculations //Applying summation of forces along all axes and equating them to zero //Applying moment about point X,Y,Z and equating it to zero //We get six equations an...
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10_7.sce
//chapter 10 //example 10.7 //page 303 clear all; clc ; //given R1=1 ; R2=3.9;//in Mohm Rl=56; Rs=2.2; Rd=6.8;//in kohm gm=4.5;//mA/V rd=100;//kohm vi=50;//mV rs=200;//ohm Rp=1/gm;//in kohm Zi=1000*(Rs*Rp)/(Rs+Rp); Zo=Rd*rd/(Rd+rd); Av=gm*(Rd*Rl)/(Rd+Rl); vo=Av*vi*Zi/(rs+Zi); printf('\nInput Impe...
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// This file is part of the materials accompanying the book // "The Elements of Computing Systems" by Nisan and Schocken, // MIT Press. Book site: www.nand2tetris.org // File name: projects/00/And.tst load And.hdl, output-file And.out, compare-to And.cmp, output-list a%B3.1.3 b%B3.1.3 out%B3.1.3; set a 0,...
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//Force P required to hold the system //Refer to fig. 2.28 (a),(b)&(c) //Applying Lami's Theorem at A we get C=4000*sind(180-60)/sind(60+90-15) //N //Applying equilibrium conditions B P=(-2000*cosd(45)+C*cosd(60))/cosd(15) //N printf("P=%.1f N is required to hold the system in given position.",P) ...
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//pathname=get_absolute_file_path('4.15.sce') //filename=pathname+filesep()+'4.15-data.sci' //exec(filename) //Maximum temperature(in K): T1=500+273 //Minimum temperature(in K): T2=200+273 //Temperature of the body(in K): T3=450+273 //Efficiency: n=1-T2/T1 //Ratio of W to Q1: r1=n //COP of pump: COP=T3/(T...
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// File name: projects/07/MemoryAccess/BasicTest/BasicTestVME.tst load BasicTest.vm, output-file BasicTest.out, compare-to BasicTest.cmp, output-list RAM[256]%D1.6.1 RAM[300]%D1.6.1 RAM[401]%D1.6.1 RAM[402]%D1.6.1 RAM[3006]%D1.6.1 RAM[3012]%D1.6.1 RAM[3015]%D1.6.1 RAM[11]%D1.6.1; set ...
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clear // //applying kcl to circuit at node b i3+i4=6-4=2 vb=8 vba=2 //voltage drop across nodes b and a va=6 //potential of node a w.r.t note c i2=3 //applying kcl to node a isa=1 vs=va+2*isa printf("\n vse= %0.1f V",vs)
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//Example 12.1 //Program to Calculate the Gain of a Negative Feedback Amplifier with //Given Specifications clear; clc ; close ; //Given Circuit Data A=100; //Internal Gain B=1/10; //Feedback Factor //Calculation Af=A/(1+A*B); //Displaying The Results in Command Window printf("\n\t The Value of the Gain of ...
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//example 3.5 //calculate Field Capacity clc; //Given d=2; //root zone depth Wc=0.05; //existing water content gammad=15; //dry density of soil gammaw=9.81; //unit weigth of water Vw=500 //water applied to the soil Wl=0.1; //water loss A=1000; //area of p...