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//Ex 9.8 clc; clear; close; format('v',6); f0=3;//kHz(Critical frequency) Ap=4;//Pass band gain //For Butterworth filter using sallen key alfa=1.414;klp=1;//constant fH=f0;//kHz f_3dB=f0;//kHz disp("Various design parameters are :-"); C1=0.01;//micro F//Chosen for the design disp(C1,"Capacitance C1(micro F...
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// // direct problem: computation of the reflectitivity spectrum of a FBG and of the errror function // function rhodot=f(z,rho,delta,lamb,zf,dn) // right hand side of the ODE d=splin(zf,dn); // spline interpolation of the apodisation function dnz=in...
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clc clear //Input data t=25;//The temperature of both reactants and products in degree centigrade p=1;//The pressure of both reactants and products in bar //Calculations h=0;//Enthalpy of all elements at given temp and pressure hf1=-103.85;//The enthalpy of the compound C3H8 in the reactants side at given te...
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clc; v=240; // supply voltage n=1000; // speed of motor i=40; // current drawn from supply rf=0.2; // field resistance ra=0.25; // armture resistance rd=0.3; // diverter resistance // torque is constant for different speeds // when diverter is put in parallel with series resistance then some fraction of armatur...
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// Example 7.7 k=1; // Constant N1=2000; // turns of Solenoid N2=500; // turns of Coil mo=4*%pi*10^-7; // Permeability of free Space A=30*10^-4; // Area of aCoil l=0.7; // Length of Solenoid z=k*N1*N2*mo*A; // alph...
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function mdaqDSPStop(arg1) // Check version compatibility [is_supp vers] = mdaq_is_working('mdaqDSPStop'); if is_supp == %F then error('ERROR: ' + vers) return; end if argn(2) == 1 then link_id = arg1; if link_id < 0 then disp("ERROR: Invalid link...
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Bf=1250//width of flange, in mm Df=120//thickness of flange, in mm d=700//effective depth, in mm m=13.33//modular ratio Ast=5500//in sq mm W=60//UDL including self-weight, in kN/m l=8//span, in m M=W*l^2/8*10^6//in N-mm //Assume x>Df. Equating moments of area on compressiona and tension sides about N.A. x=(m*A...
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//Section-14,Example-5,Page no.-PC.114 //To calculate the pH of a solution obtained in the given condition. clc; M_1=0.1 M_2=0.2 V_1=10 V_2=40 V=V_1+V_2 m_eq=(M_1*V_1)+(M_2*V_2*2) //mgm. equivalents of [H3O+] C_1=m_eq/V //[H3O+] pH=-log10(C_1) disp(pH,'pH of the given solution')
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t0 = 0.6*10^-9; tnr = 10^-7; p = 10^22; kT = 26*10^-3; //in eV m0 = 0.91 * 10^-30; //in kg m1 = 0.067*m0; m2 = 0.45*m0; h = 1.05*10^-34; q = 1.6*10^-19; tri = (0.5*p/t0)*(2*%pi*h*h/kT/q/(m1+m2))^1.5; tr1 = 1/tri; disp(tr1,"When the p-type doping is 10^16 cm−3, the hole density is low and the e-h recombination time (in...
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clear; clc; printf("\nEx2.5\n"); //page no.-56 //given h=6.67*10^-27;...............//planck constant in ergs-sec m=9*10^-28;..................//mass of e e=4.8*10^-10;...............//charge in e.s.u. lambda=0.5*10^-8;..........//wavelength in m //we know, lambda=h*sqrt(150/(m*e*V)) V=((h^2*150)/(m*e*lambd...
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//Sample Problem 37-2 printf("**Sample Problem 37-2**\n") I = []; for m = 1:3 theta = (m+.5)*%pi I = [I, (sin(theta)/theta)^2] end printf("The intensities of secondary maximas relative to intensity of CBF is-\n") printf("\tI1/Im = %.4f\n", I(1)) printf("\tI2/Im = %.4f\n", I(2)) printf("\tI3/Im = %.4f...
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//example 8.6 clc; funcprot(0); // Initialization of Variable h2s=272.39; h1=241.35; mdot=0.08; h4=99.56; Wcdot=mdot*(h2s-h1); disp(Wcdot,"work input in kW"); Qindot=mdot*(h1-h4)*60.0/211; disp(Qindot,"refrigration capacity in ton"); Beta=(h1-h4)/(h2s-h1); disp(Beta,"coefficient of performance"); clear()
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function vars=macrovar(macro) // Returns in a list the set of varibles used by a macro // mac : macro // vars : list(in,out,globals,called,locals) // in : input variables // out: output variables // globals: global variables // called : macros called // locals : ...
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//<f>=%rt(f1) // f=f1' //! f=list(f1(1),f1(2)',f1(3)',f1(4)) //end
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copyfile('scilab-base-program-testscript.sce','testscript.sce') //to delete exec('testscript.sce',-1) // no echo except "disp" exec('testscript.sce',0) // echo unless using a ";" // same as option 0 + command prompt exec('testscript.sce',1) // same as option 0 + new line exec('testscript.sce',2) // same as option 1 +...
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clc(); clear; //To determine the diameter of the ninth dark ring n=9; lambda=589*10^-9; //wavelength of light used R=0.95; //radius of curvature of lens mew=1; D=(sqrt((4*n*lambda*R)/mew))*10^2 //diameter of the ninth dark ring printf("The diameter of the ninth da...
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clc //given that l = 2.5e-10 // width of potential well in m h = 6.63e-34 // Plank constant m = 9.1e-31 // mass of electron in Kg printf("Example 2.24") for n = 1:2 E = n^2*h^2/(8*m*l^2) // Calculation of energy in Joule E_eV = E/1.6e-19 // Calculation of energy in eV printf("\n Energy of electron fo...
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clc clear disp('example 12 5') po=5 //mva rating v=10 //voltage in kv n=1500;ns=n/60 //speed f=50 //freaquency pfb=0.8//power factor in b x=0.2*%i //reactance of machine md=0.5 //machanical displacement //no load v=1;e=1; p=4 spu=v*e/abs(x);sp=spu*po*1000;mt=(%pi*p)/(180*2) spm=sp*mt //synchronous power i...
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// Ex 58 Page 401 clc;clear;close; // Given zo=2+%i*3;//ohm zi=0.5+%i*5;//ohm Ri=real(zi) ;//ohm Ro=real(zo) ;//ohm //at standstill s=1;//% at standstill Zo=sqrt(real(zo)**2+imag(zo)**2);//ohm Zi=sqrt(real(zi)**2+imag(zi)**2);//ohm ToBYTi=Ro/Ri*(Zi/Zo)**2;//torque ratio printf("at slip=0, To:Ti = %d:1",ToBYTi) //at ...
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// Exa 7.9 format('v',7);clc;clear;close; // Given data Samplingrate = 200;//Sampling rate in MS/s Samplingrate = Samplingrate * 10^6;// in S/s t_r = 1/Samplingrate;//minimum rise time of pulse in s t_r = t_r * 10^9;// in ns disp(t_r,"The minimum rise time of pulse in ns is");
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// Example 7.4, page no-270 clear clc g1=30 //gain of RF stage in dB t1=20 //Noise temperature in K g2=10 //down converter gain in dB t2=360 //noise temperature in K g3=15 //gain of IF stage in dB t3=1000 //noise temperature in K t=290 //reference temperat...
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mode(-1) //stacksize(40000000) location = 'C:\cygwin\home\Zhan\repository\graph-classifier\dataset\' edgelists = [ 'er-8-8.txt', 'er-9-8.txt', 'er-10-8.txt', 'er-11-8.txt', // 'er-12-8.txt', 'ba-8-8.txt', 'ba-9-8.txt', 'ba-10-8.txt', 'ba-11-8.txt', // 'ba-12-8.txt', 'sw-8-8.txt', 'sw-9-8.txt', ...
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// Fonction niveau de gris function J = niveau_gris(I) if length(size(I))==3 //3 canaux = image couleurs J = mean(I,3); else J = I; end endfunction // Calcule l'homographie qui transforme les 4 points // (cx1(i),cy1(i)) i=1..4 en (cx2(i),cy2(i)) i=1..4, // puis applique cette homographie ...
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# Header section (set default parameters) active_buttons = 1; button_codes = 1; pulse_width = 5; #write_codes = true; response_matching = simple_matching; scenario_type = trials; no_logfile = false; default_background_color = 50, 50, 50; #SDL portion (create objects and trials) begin; bitmap { filename = "red_circle5...
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//Example sec 9.1 //compensation in open loop control system clear;clc; xdel(winsid()); s=%s; disp("G=(60*k)/s*(s+1)*(s+6)") //velocity error constant "Kv" when unit ramp input is applied to G is "5k". //If "k=1",then,steady state error is 0.2. // when "k=35/60" G becomes num=35; den=s*(s+2)*(s+6); G1=s...
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// Example 7.2 clear all; clc; // Given data k_inf = 1.001; // Infinite multiplication factor // From the Example 7.1 l_p = 1e-4; // Prompt neutron lifetime // Calculation T = l_p/(k_inf-1); // Result printf(" \n The response time of the reactor = %2.1f sec \n",T...
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(unwatch all) (clear) (setgen 1) (dribble-on "Actual//dftmpfun.out") (batch "dftmpfun.bat") (dribble-off) (clear) (open "Results//dftmpfun.rsl" dftmpfun "w") (load "compline.clp") (printout dftmpfun "dftmpfun.bat differences are as follows:" crlf) (compare-files "Expected//dftmpfun.out" "Actual//dftmpfun.out" dftmpfun)...
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clear /////////////////////////////////////////////////////// // Integral.sce // // Este programa aproxima la integral con rectangulos // pidiendo los valores de los limites y el numero de // rectangulos // // Nombre1 Apellido1 // Nombre2 Apellido2 // 99 / XXX / 99 version 1.0 ///////////////////////...
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//Variable declaration l = [19.7, 21.5, 22.5, 22.2, 22.6,21.9, 20.5, 19.3, 19.9, 21.7,22.8, 23.2, 21.4, 20.8, 19.4,22.0, 23.0, 21.1, 20.9, 21.3] sum1 = 0.0 //Calculation Mean=sum(l)/length(l) for i = 1:length(l) sum1 = sum1 + l(i)*l(i) end variance = (sum1 - (sum(l)^2.0/length(l)))/(length(l)-1) // varia...
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//Section-10,Example-3,Page no.-CT.9 //To calculate enthalpy of neutralization of acetic acid by sodium hydroxide. clc; dl_H=-57.32 dl_Hionization=1.89 x=dl_H+dl_Hionization disp (x,'Enthalpy of neutralization of acetic acid by sodium hydroxide(kJmol^-1)')
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//Chapter-7, Example 7.10, Page 297 //============================================================================= clc clear //INPUT DATA D=0.015;//Diamter of copper bus bar in m Ta=20;//Temperature of air stream in degree C v=1;//Velocity of air in m/s Ts=80;//Surface temperature in degree C p=0.0175;//Res...
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clear; clc; syms z n ; x=(1/3)^n; X=symsum(x*z^-n,n,0,%inf) disp(X,"X(z)=") Xz=z/(z-1/3); Yz=z/(2*(z-1/2))+z^2/((z-1/3)*(z-1/2)); //y[-1]=1 Y1=z/(z-1/2); Y2=z^2/((z-1/3)*(z-1/2)); FY1=Y1*z^(n-1)*(z-1/2); y1n= limit(FY1,z,1/2); FY21 = Y2*(z^(n-1))*(z-1/2); FY22 = Y2*(z^(n-1))*(z-1/3); y21n = limit(FY21,z,...
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D = 8; N = 160; //viz filter_design_xxx.sce figure; stacksize('max'); coe = read('c:\Users\bernau84\Documents\work\bats\simulace\equi_8bands_160coe_16b.txt', D, N); subplot(5,1,1); plot(coe'); x = wavread('c:\Users\bernau84\Documents\work\bats\simulace\chirp_20_8000_fs44kHz_4s.wav'); f_x = (x + 1.0) * (2^11); //offse...
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[InstantScripts] Node0Directory= [Nodes] F^InstantScripts^welcome.txt F^SetUp R^Issue SYS Grants Required^7.3.3.5, 8.0.4.1, 8.1.5^grants.sql R^Create Required Views and Tables^7.3.3.5, 8.0.4.1, 8.1.5^Crea_tab.sql R^Build a Standard 80 column Report Heading^7.3.3.5, 8.0.4.1, 8.1.5^Title80.sql R^Build a Standard...
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//Chapter 7, Problem 2 clc funcprot(0) // A = p2z(R,Theta) - Convert from polar to rectangular form. // R is a matrix containing the magnitudes // Theta is a matrix containing the phase angles (in degrees). function [A] = p2z(R,Theta) A = R*exp(%i*%pi*Theta/180); endfunction // [R, Theta] = z2p(A) - D...
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echo "### Test Ex7-1" ../bin/carat/Normalizer Ex7_g echo "### Ex7-1 return code $?" echo "### Test Ex7-2" ../bin/carat/Is_finite Ex7_nh echo "### Ex7-2 return code $?" echo "### Test Ex7-3" ../bin/carat/Symbol Ex7_g echo "### Ex7-3 return code $?"
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function [stk,txt,top]=sci_hess() // Copyright INRIA txt=[] if rhs==1 then r=list('hess('+stk(top)(1)+')','0','1','?','?') else r=list('hess('+stk(top-1)(1)+','+stk(top)(1)+')','0','1','?','?') end if lhs==1 then stk=r else r(2)='-1' stk=list(r,r) end
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//Example sec 6.2.2 // location of root locus in between poles and zeros. clear; clc; xdel(winsid()); s=%s; num=((s+1)*(s+2)); den=(s*(s+3)*(s+4)); G=syslin('c',num/den); clf(); evans(G); axes_handle.grid=[1 1] mtlb_axis([-5 5 -5 5]);
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// Scilab Code Ex5.2 : Percentage transmission of polarized light: Page-113 (2010) I0 = 1; // For simplicity, we assume the intensity of light falling on the second Nicol prism to be unity, watt per metre square theta = 30; // Angle through which the crossed Nicol is rotated, degrees I = I0*cosd(90-theta)^2; ...
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// Exa 7.1 clc; clear; // Given data n=2; // Second order Butterworth filter fL=1000; // Higher cut off frequency(Hz) // Solution printf('Let C = 0.1 μF. \n'); C=0.1*10^-6; // Farads // Since fL = 1/(2 * %pi * R*C); // Therefore; R = 1/(2*%pi*fL*C); printf(' The calculated value of R = %....
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load IsZero16.hdl, output-file IsZero16.out, compare-to IsZero16.cmp, output-list in%B1.16.1 out%B1.1.1; set in %B0000000000000000, eval, output; set in %B1111111111111111, eval, output; set in %B1010101010101010, eval, output; set in %B0011110011000011, eval, output; set in %B0000000000000000...
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errcatch(-1,"stop");mode(2); //Initialization of variables h=20 //m c=4187 //N m /(kg K) g=9.81 //calculations dT=g*h/c //results printf("Increase in temperature of water = %.3f K",dT) exit();
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// Example 6.11 format('v',6) clc; clear; close; // given data bita= 150; R1= 10*10^3;// in Ω R2= 2.2*10^3;// in Ω R_C= 3.6*10^3;// in Ω Rs= 1*10^3;// in Ω R_L= 1.5*10^3;// in Ω r_E= 180;// in Ω R_E= 1*10^3;// in Ω V_CC= 10;// in V V_BE= 0.7;// in V Vt= 25*10^-3;// in V Vin= 1*10^-3;// in V V_B= R2*V_...
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//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc. USA,pp 436. //Chapter-2 Ex2.1 Pg No.52 //Title: Effectiveness factor for solid catalyzed reaction //====================================================================================================================== clear clc clf //INPUT...
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clc,clear printf('Example 6.9\n\n') //Line AB for Altermnator 1, and AC for alternator 2.AF is at frequency x measured from A where total load is 3000 kW BO=2000,AO=5//AF=x DC=2000,AD=3,//AF=x //using similarity of triangles AEF and ABO EF_by_AF=(BO/AO)// because (EF/BO)=(AF/AO) //using similarity of triangl...
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3(D)Program to solve Binomial coefficients..sce
function [k]= func1(n,r)// calculating binomial coefficient k= factorial(n)/(factorial(r)*factorial(n-r)); endfunction func1 (8 ,2) func1 (9 ,4) func1 (12 ,5) func1 (10 ,3) func1 (13 ,1) p=factorial(10)/(factorial(10 -7)*factorial(7));// calculating 10C7 q= factorial (10) /( factorial (10 -3) * factorial (3)) ...
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//chapter 37 //example4 clc //given e=1.6*10^-19 //in coul r=5.1*10^-11 //radius of hydrogen atom in meter m=9.1*10^-31// mass of electron in kg epsilon0=8.9*10^-12 //in coul2/nt-m2 B=2 //in wb/m2 delta_p=(e^2*B*r^2)/(4*m) disp(delta_p,"Change in Orbital dipole moment in amp-m2 is + 0r -")
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//Exa4.4 clc; clear; close; //given data T=300;//in Kelvin ND=10^15;//in cm^-3 NA=10^18;//in cm^-3 ni=1.5*10^10;//in cm^-3 VT=T/11600;//in Volts Vbi=VT*log(NA*ND/ni^2);//in Volts disp(Vbi,"Built in potential barrier in volts : ");
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// Example 6.9, Page No-284 clear clc fh=50000 C=0.001*10^-6 R=1/(2*%pi*fh*C) Rkohm=R/1000 printf('R= %.3f kohm', Rkohm) R1=R/1.082 R2=R/0.9241 R3=R/2.613 R4=R/0.3825 printf('\nR1= %.3f kohm', R1/1000) printf('\nR2= %.3f kohm', R2/1000) printf('\nR3= %.3f kohm', R3/1000) printf('\nR4= %.3f kohm', R4/...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 7: PARALLEL OPERATION // Example 7-6 clear; clc; close; // Clear the work space and console. // Given data E = 220 ; // Voltage generated in volt E_1 = E ; // Voltage generated by alternator 1 in...
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// Exa 4.28 clc; clear; close; // Given data V_B = 4;// in V V_BE = 0.7;// in V R_E = 1.2;// in kohm R_E= R_E*10^3;// in ohm V_E = V_B-V_BE;// in V R_C = 2.2;// in kohm R_C= R_C*10^3;// in ohm R_B= 330;// in kohm R_B= R_B*10^3;// in ohm bita = 180; I_B = 7.11 * 10^-6;// in A V_CC = 18;// in V disp("Par...
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// SAMPLE PROBLEM 5/6 clc;funcprot(0); // Given data v_A=0.3;// m/s b=0.2;// m theta=30;// degree // Calculation v_B=-v_A*tand(theta);// m/s a_B=-((v_A^2)/b)*(secd(theta))^3;// m/s^2 omega=(v_A/b)*secd(theta);// rad/s alpha=((v_A^2)/b^2)*(secd(theta))^2*tand(theta);// rad/s^2 printf("\nThe velocity of the ...
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clear //Given M = 50000 //ft-lb , positive bending moment applied N = 9 // number of steel bars n = 15 // The ratio of steel to concrete A_s = 30 //sq.in area of steel in concrete //(10*y)*(y/2) = 30*(20-y) //y**2 + 6*y -120 //solving quadractic equation // a = 1 b = 6 c = -120 // calculate the...
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I1=1 V1=18*I1 V2=6*I1 Z11=V1/I1 Z21=V2/I1 I2=1 V2=9*I2 V1=6*I2 Z12=V1/I2 Z22=V2/I2 A=[Z11,Z12;Z21,Z22] printf("\nA=") disp(A)
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//Electric Power Generation, Transmission and Distribution by S.N.Singh //Publisher:PHI Learning Private Limited //Year: 2012 ; Edition - 2 //Example 15.3 //Scilab Version : 6.0.0 ; OS : Windows clc; clear; V=11; //Supply voltage in kV die_strength=50; ...
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//clear// clear; clc; //Example 28.1 //Given rho_p = 0.002650; //[g/mm^3] a = 2; phi_s = 0.571; //Solution //(a) //For the 4/6-mesh increment, from Table 28.2 x = [0,2.51,12.5,32.07,25.7,15.9,5.38,2.10,1.02,0.77,0.58,0.41,0.31,0.75]'*10^-2; //[mass fraction] Dp = [4.699,3.327,2.362,1.651,1.168,0.833,0.589...
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//// compute_bd // find boundary of mesh, returned bd will be in ccw consective order. For // multiple boundary mesh, return a cell, each cell is a closed boundary. // For single boundary mesh, return an array. // //// Syntax // bd = compute_bd(face) // //// Description // face: double array, nf x 3, connectivit...
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example1.sce
//Chapter-6 example 1 //============================================================================= clc; clear; //input data F = 9*10^9;//Reflex Klystron operating frequency in hz Va = 300;//beam voltage in volts I = 20;//Beam current in mA n = 1;// for 7/4 mode //Calculations //transit tim...
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ex_23_16.sce
//find clc //solution //given m=1800//kg v=1.2//m/s dx=200//m t=365//N/mm^2 C=6 G=80*1000//N/mm2 E=0.5*m*v^2*10^3//N-mm //let W be equivalent load //Es=0.5*W*dx*2=200*W W=E/200//N //let b be suide of square and D be mean Dia\ //D=6b K=(4*C-1)/(4*C-4)+(0.615/C) //t=K*2.4*W*D/b^3=116870/b^2 //b=sqrt(11...
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clc clear //Input data bsfc=0.3;//The brake specific fuel consumption in kg/kWh bp=250;//The brake power in kW N=1500;//Number of cycles per min in rpm CA=15;//Crank angle in degrees pi1=30;//The pressure of air in the cylinder at the beginning of the injection in bar pi2=60;//The pressure of air in the cylinde...
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// Exa 6.25 format('v',7);clc;clear;close; // Given data L2 = 47.8;//inductance in mH R2 = 1.36;//resistance in ohm r1 = 32.7;//resistance in ohm R1 = 1.36;//resistance in ohm //At balance, 100*(r1+J*oemga*L1) = 100*((R2+r2)+(J*omega*L2)); L1 = L2;// in mH (equating imaginary terms) disp(L1,"The inductance of...
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3_12.sce
//Network Theorem 2 //pg no 3.13 //example 3.12 //when 18 V source is acting alone disp("Vx+I1=0");//equation 1 disp("Applying KVL to mesh,"); disp("3Vx-6I1=-18");//equation 2 A=[1 1;3 -6];//solving equation in matrix form B=[0 -18]' X=inv(A)*B; disp(X); disp("I1 = 2 A"); //when the 3 A source is acting alo...
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13_7.sce
clc //initialisation of variables x1= 3 //ft x2= 3 //ft x3= 3 //ft x4= 3 //ft W1= 4 //kips W2= 8 //kips l= x1+x2+x3+x4 //CALCULATIONS b= x2+x3+x4 b1= x4 a= x1 x= l/2 P= (((W1*b*(l/b*(x-a)^3+(l^2-b^2)*x-x^3))/(6*l))+((W2*b1*x*(l^2-x^2-b1^2))/(6*l)))*(48/l^3) R1= 3+2-(P/2) R2= P R3= 1+6-(P/2) //RESULTS ...
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; tanf.tst - Directed test cases for SP tangent ; ; Copyright (C) 2007-2015, ARM Limited, All Rights Reserved ; SPDX-License-Identifier: Apache-2.0 ; ; Licensed under the Apache License, Version 2.0 (the "License"); you may ; not use this file except in compliance with the License. ; You may obtain a copy of the Licens...
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clc; //Given data // Moment arms Fx=-30;//in lb Fy=20;//in lb Fz=20;//in lb //couple Forces x=18;//iN y=12;//iN z=9;//iN Mx=Fx*x;//N.m, Component of Moment along X axis My=Fy*y;//N.m, Component of Moment along Y axis Mz=Fz*z;//N.m, Component of Moment along Z axis //This three moments represent compon...
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clc; clear all; e0=8.854e-12; //permittivity of vacume N=5e28; //no of atoms present per m^3 N xe=2e-40; //polarisability //P=N*xe*Ei and Ei=E+(P/(3*e0)) so.. //Ei=E+(N*xe*Ei/(3*e0)) so... //Ei/E=1/(1-(N*xe/(3*e0))) so..lets take rt=Ei/E m=(N*xe)/(3*e0) rt=1/(1-m);//ratio of internal field to applied field di...
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//chapter 7 printf("\n"); Nmax=10^11; phi=(%pi)/9; fcr=sqrt(81*Nmax); printf("the critical frequency is %gHz",fcr); fmuf=fcr*sec(phi); printf("\nthe maximum usable frequency is %gHz",fmuf);
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errcatch(-1,"stop");mode(2);//Caption:Find the restraining force of the spring //Exa:3.9 ; ; N=500;//no. of turns u_o=4*%pi*10^-7;//Permeablity of air I=4.2;//main winding current(in A) A=2.25*10^-4;//area of air gap(in m^2) x=0.002;//length of air gap(in m) i=I*1.50;//min current needed for activating relay...
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//ques-35.18 //Calculating corresponding energy for a NMR spectra clc f=60;//frequency used (in MHz) E=(6.023*10^23)*(6.625*10^-34)*f*10^6;//energy (in J/mol) E=(E/1000)/4.184;//energy (in kcal/mol) printf("The energy required is %.9f kcal/mol.",E);
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// Updated(18-7-07) // 11.2 C = [1 0.5]; dC = 1; A = [1 -0.6 -0.16]; dA = 2; j = 2; getf recursion.sci [Fj,dFj,Ej,dEj] = recursion(A,dA,C,dC,j)
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// s : 2014.06.22 function Setobjscale(scale) global OBJSCALE; OBJSCALE=scale; endfunction
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Jacksta's 2v1 Simulator.sce
Name=Jacksta's 2v1 Simulator PlayerCharacters=Quaker BotCharacters=Botz Bot.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Quaker AddedBots=Botz Bot.bot;Botz Bot.bot PlayerMaxLives=0 BotMaxLives=0;0 PlayerTeam=1 BotTeams=0;0 MapName=FortniteAimTraining2.1.map MapScale=5.09 BlockProjectilePredictors=true...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 3, Example 23") disp("Inner Diameter,") D2 = 0.45 disp("Outer Diameter,") D1 = 0.9 disp("Radial Discharge") alpha2 = 90 Cr2 = 2.8 ...
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clc clear //Initialization of variables H1=0.059 O1=0.199 C=0.66 S=0.011 //calculations Qh1= 11.52*C+34.56*(H1-O1/8)+4.32*S //results printf("Theoretical air required = %.2f lb of air per lb of coal ",Qh1)
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//Gas Effusion clear; clc; printf("\t Example 5.17\n"); t2=1.5;//diffusion time of compound, min t1=4.73;//diffusion time of Br, min M2=159.8;//mol mass of Br gas, g M=(t2/t1)^2*M2;//molar gas of unknown gas, g(from Graham's Law of Diffusion) printf("\t the molar mass of unknown gas is : %4.1f g/mol\n",...
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clc //Variable declaration a=3.61*10**-7 BC=sqrt(2)/2 AD=(sqrt(6))/2 //Result printf('i.Surface area of the face ABCD =%0.3f*10**-14 mm**2\n",(a**2*10**14)) printf('ii.Surface area of plane (110) =%0.3f*10**13 atoms/mm**2\n",((2/(a*sqrt(2)*a)/10**13))) printf('iii.Surface area of pane(111)=%0.3f*10**13 at...
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clc clear A=[0,1,0,0,0,0;-2,0,2,0,0,0;0,0,0,1,0,0;2,0,-4,-3,2,3;0,0,0,0,0,1;0,0,2,3,-2,-3]; epss=0.01; ksi=epss/(1+epss); DeltaA=[0,0,0,0,0,0;2*ksi,0,-2*ksi,0,0,0;0,0,0,0,0,0;-2*ksi,0,4*ksi,3*ksi,-2*ksi,-3*ksi;0,0,0,0,0,1;0,0,-2*ksi,-3*ksi,2*ksi,3*ksi]; B=[0,1,0,0,0,0;0,0,0,0,0,1]'; DeltaB=[0,-ksi,0,0,0,0;0,0,0,0,0,-ks...
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PL/SQL Developer Test script 3.0 44 -- Created on 11/04/2008 by MKAUL declare -- Local variables here i integer; vTrackID track.id%type; vRankNum INTEGER; begin for x in ( -- Test statements here /* select v.track_id, v.rank_num from ( select x.track_id, ...
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// Calculate maximum velocity of emitted photo electrons clc; E_imparted=(1.24*10^-6)/(0.2537*10^-6); B_energy=E_imparted-4.30; em_ratio=0.176*10^12; v=(2*B_energy*em_ratio)^0.5; disp(v,'maximum velocity of emitted photo electrons (m/s)')
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//Solução de EDO método derivadas //dy/dx=exp(x) ou qualquer função //condição inicial y(0)=1 //h=0.1 //setar as variáveis x=0:0.1:7; y(1)=1; h=0.1; //a função f já é a derivada de y. f(x,y)=y' function z=f(x,y) z=cos(x); endfunction //a função g é a deriv. segunda g(x,y)=y'' function w=g(x,y) w=-sin...
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//Chapter-4, Illustration 17, Page 206 //Title: Steam Nozzles and Steam Turbines //============================================================================= clc clear //INPUT DATA m=2;//Mass flow rate of steam in kg/s W=130;//Turbine power in kW U=175;//Blade velocity in m/s C1=400;//Steam velocity in m/...
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//clear// //Caption: Program to find Excess loss, Splitting loss and total loss //Example10.7 //page 355 clear; clc; close; Power_Lost = 5/100; FT = 1-Power_Lost; //power coupled N = 32; Excess_Loss = -10*log10(FT^log2(N)); Splitting_Loss = -10*log10(1/N); Total_Loss = Excess_Loss+Splitting_Loss; disp(Exce...
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//Initilization of variables P=50 //N Q=100 //N beta=150 //degree // angle between P & the horizontal //Calculations R=sqrt(P^2+Q^2-(2*P*Q*cosd(beta))) // using the Trignometric solution Alpha=asind((sind(beta)*Q)/R)+15 //Result clc printf('The magnitude of resultant is %f Newton (N) \n',R) printf('The direct...
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//EXAMPLE-3.40 PG NO-199 Vry=200; Vbr=200; Vbn=115.47; I1=10; //10-j12 W1=200*I1; X1=173.2; X2=26.66; W2=X1*X2; disp('i)WATTMETERS (W2) = '+string (W2)+' W')
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clc clear //Initialization of variables v1=0.1316 v2=0.2941 x1=0.5 x2=0.2 x3=0.8 d1=14.87 d2=16.34 //calculations and results vm=(1-x2)*v1+x2*v2 phi1=(1-x2)*v1/vm phi2=(x2)*v2/vm Hl2=vm*phi1*phi2*(d1-d2)^2 *10^3 disp("case 2") printf("enthalpy = %.1f kJ/mol",Hl2)
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//EXAMPLE 2.1 //Ensemble averaging clear ; clc ; n = 1:50; clf(); figure(0) a=gca(); a.x_location="origin"; a.y_location="origin"; for i =1:length(n) s(i)=2*n(i)*((0.9)^n(i)); d(i)=(-0.1)^n(i); //arbitrary noise signal. end M=length(n); for i =1:M d(i)=(-0.1)^i; S=sum(d); end Ea...
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//Example 5.18 clc; clear; close; format('v',8); //Given data : D1=40/100;//meter D2=15/100;//meter x=25/100;//meter g=9.81;//gravity constant K=0.98;//Coeff. of meter S=1;//sp. gravity Sm=13.6;//sp. gravity of mercury A1=%pi*D1^2/4;//m^2 A2=%pi*D2^2/4;//m^2 C=A1*A2*sqrt(2*g)/sqrt(A1^2-A2^2);//venturi co...
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function r=%i_j_s(a,n) if or(int(n)<>n)|or(n<0) then r=double(a).^n else if size(a,'*')==1 then r=iconvert(double(a).^n,inttype(a)) else if size(n,'*')<>1 then error(43) else r=a for i=2:n,r=r.*a,end end end end
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function y= fractdiff(x,d) //Compute the fractional differences (1-L)^d x where L denotes the lag-operator and d is greater than -1. //Calling Sequence // fractdiff (X, D) //Description //Compute the fractional differences (1-L)^d x where L denotes the lag-operator and d is greater than -1. if(argn(2)~=2) error("Wron...
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//Specification of Point Coordinates clear; clc; printf("\tExample 3.5\n"); disp("Point coordinates for given positions of BCC cell are"); A=['Point_no','x_axis','y_axis','z_axis','Coordinates'; ' 1','0','0','0','000'; ' 2','1','0','0','100'; ' 3','1','1','0','110'; ' 4','0','1','0','010'; ' 5','...
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r =3; avg = 6; std= 1; var = std^2; expecV2 = var + (avg^2); expecW = 3*expecV2; disp(expecW, "Expectation of W is ") limw=120; limV = sqrt(limw/r); disp(1-cdfnor("PQ", limV, avg, std), "P{W>120} is")
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clc //initialization of variables B=10.34 //cm^-1 c=2.998*10^10 //cm/s h=6.625*10^-27 //erg sec //calculations I=h/(8*%pi^2 *B*c) //results printf("Moment of inertia = %.2e g cm^2",I)
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//Example 2_6_u2 clc(); clear; //To calculate the fermi energy level h=4.14*10^-15 //units in m^2 kg s^-1 n=8.49*10^28 //units in m^-3 m=9.1*10^-31 //units in Kgs Ef=(h^2*(3*n)^0.666)/(8*m*(%pi)^0.666) //units in J Ef=Ef*1.67*10^-19 //units in eV printf("Fermi energy for copper...
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//Calculate the value of resistance //Chapter 2 //Example 2.22 //page 126 clear; clc; disp("Example 2.22") V=440; //primary voltage in volts Ia=50; //armature current in amperes Ra=0.2; //armature resistance in ohms N=600; //speed in rpm E=V-(Ia*R...
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load Abs.asm, output-file Abs.out, compare-to Abs.cmp, output-list RAM[0]%D2.6.2 RAM[1]%D2.6.2; set RAM[0] 0, repeat 15 { ticktock; } output; set PC 0, set RAM[0] 1, repeat 15 { ticktock; } output; set PC 0, set RAM[0] -1, repeat 15 { ticktock; } output; set PC 0, set RAM[0] -1024, ...
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//example 6.20 clear; clc; disp("CaF2(s)<=>CaF2(aq)<=>Ca+2(aq) + 2F-(aq)"); //Given: Ksp=4*10^-11;//Solubility product of sparingly soluble salt CaF2 //To find the value of activity coefficient x=Ksp/4; Cs=x^0.33;//Solubility y=Cs^2; Y=(x/y)^0.33;//activity coefficient printf("The activity coefficie...
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refs/heads/master
2020-04-09T02:43:26.499817
2018-02-03T05:31:52
2018-02-03T05:31:52
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sce
example2_13.sce
clear; clc; //Example2.13[Heat Conduction in the Base Plate of an Iron] //Given:- k=15;//[W/m.degree Celcius] A=300*10^(-4);//Base Area[m^2] L=0.005;//Thickness[m] T_surr=20;//Temp of surrounding[degree Celcius] h=80;//Convection het transfer coefficient[W/m^2.degree Celcius] Q=1200;//[W] //Solution:- q=Q/...