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clear ; clc; // Example 11.9 printf('Example 11.9\n\n'); printf('Page No. 324\n\n'); //given T1 = 273;// Measured temperature In degree celcius P = 1;// Measured pressure in bar T2 = 290;// initial temperature In degree celcius T3 = 1000;// Final temperature In degree celcius T4 = 1150;// Entering tempeartu...
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; testing loading QF_IDL (set-logic QF_IDL )
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clc p1=1; //bar p2=5; //bar T3=1000; //K cp=1.0425; //kJ/kg K cv=0.7662; //kJ/kg K y=cp/cv; disp("(i)Temperature entropy diagram") s=10:1:50; function T=fb(s) T=s^2 endfunction plot(s,fb,'--') s=10:1:50; function T=fc(s) T=(s+30)^2 endfunction plot(s,fc,'r') s=[12 12]; T=[fb(12) fc(12...
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//Chapter-5, Example 5.42, Page 209 //============================================================================= clc clear //INPUT DATA V1=400;//voltage in volts Z1=(3+((%i)*4));//impedance in ohms //CALCULATIONS //in star connected system,phase voltage=(line voltage) Ep=V1/(sqrt(3));//voltage in volts Ip=...
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// Example 2.5, page no-38 clear clc AP_diff=30000 //difference between apogee and perigee in km AP_sum=62800 //Apogee+perigee E=AP_diff/AP_sum printf("Orbit Eccentricity= %.3f",E)
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c1=3; //number of toys that the youngest child should get c2=2; //number of toys that the third child should get c3=2; //number of toys that the second child should get c4=2; //number of toys that the eldest son should get m=factorial(9)/(factorial(3)*factorial(2)*factorial(2)*factorial(2)); disp(m,'number of...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 7 Example 19") T=(200+273);//temperature of water in K disp("clapeyron equation says,h_fg=T*v_fg*(dp/dT)_sat") disp("from steam tables,vg=0.12736 m^3/kg,vf=0.001...
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// Exa 1.18 clc; clear; close; // Given data miu= 35.2*10^-4;// in m^2/vs n=7.87*10^28; e= 1.6*10^-19;// in C sigma= n*e*miu;// in s/m disp(sigma,"Conductivity in s/m is : ")
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clear; clc; close; Vgg = 2; Idss = 10*10^(-3); Vp = -4; Vdd = 16; Rd = 2*10^(3); Vgs = -Vgg; Id = Idss*(1-(Vgs/Vp))^2; Vds = Vdd - Id*Rd; Vd = Vds; Vg = Vgs; Vs = 0; disp(Vgs,'Vgsq(Volts) = '); disp(Id,'Idq(Amperes) = '); disp(Vds,'Vds(Volts) = '); disp(Vd,'Vd(Volts) = '); disp(Vg,'Vg(Volts) = ');...
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u=75; //mean of a random variable X n=5; //standard deviation of X k=2; //for k=2 l1=u-k*n l2=u+k*n P1=1-(1/k)^2 disp("thus the probability that a value of X lies between 65 and 85 is atleast 0.75 according to Chebyshev inequality") k=3; //for k=3 l1=u-k*n l2=u+k*n P2=1-(1/k)^2 dis...
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clear// //Variables vin = 2.0 * 10**-3 //Input voltage (in volts) gm = 5500.0 * 10**-6 //Transconductance (in Siemen) R1=1.0*10**6;R2=1.0*10**6; RS = 5.0 * 10**3 //Source resistance (in ohm) RL = 2.0 * 10**3 //Load resistanc...
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//Ex1_16 clc; //Given: e=200; //MeV/ atom of U // 1 eV = 1.6*10^-19 J Na=6.023*10^23; M=0.235; // mass in Kg //solution: e1=e*1.6*10^-19*10^6; A=Na/M; e2=A*e1; // energy released in MJ/day e3=e2/(24*3600); printf("\n The rate of energy release in W is %f ",e3)
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clc //given that l = 1e-8 // width of potential well in cm h = 6.63e-34 // Plank constant m = 9.1e-31 // mass of electron in Kg printf("\nExample 2.27") E_1 = (h)^2/(8*m*(l*1e-2)^2) // Calculation of energy of ground state in Joule E_1_eV = E_1/1.6e-19 // Calculation of energy in eV E_2 = (2)^2*h^2/(8*m*(...
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//(Design against Static Load) Example 4.12 //Refer Fig.4.39 //Force acting on the bracket P (kN) P = 5 //Ultimate tensile strength of FG200 material Sut (N/mm2) Sut = 200 //Factor of safety fs fs = 3.5 //Angle made by the line of force with the vertical theta (radian) theta = (60 * (%pi/180)) //Distance be...
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Demand of layer: 0 1 3 6 10 15 21 28 36 45 55 66 78 91 104 117 130 143 156 169 182 195 208 221 234 247 260 Biomass for layer: 0.00 0.01 0.01 0.01 0.01 0.02 0.03 0.04 0.06 0.11 0.18 0.30 0.49 0.79 1.09 1.43 1.76 2.02 2.20 2.32 2.40 2.45 2.48 2.50 2.52 2.52 2.52 Layer on each branch: Phy age 1 0.00 0.00 2....
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//Example 13_1 clc;clear; // given values b=0.4;// Width in m v=0.2;// Flow rate in m^3/s y_1=0.15;// Flow depth in m g=9.81;// m/s^2 // Calculation A_c=y_1*b;// m^2 V=(v/A_c);//The average flow velocity in m/s printf('The average flow velocity,V=%0.2f m/s\n',V); y_c=(v^2/(g*b^2))^(1/3);// The critical dep...
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clc;clear; CB=[0 0.013222222 0.039 0.079 0.101 0.069 0.207 0.265]//acid CF=[.118 .018 .184 .056 .259 .259 .288 .118]//water CD=[0 .312 .924 1.692 1.857 2.919 2.581 2.741]//alc CE=[0 0 0 .021 .034 .042 .093 .144]//ester CG=[0 .013 .040 .092 .127 .1269 .2633 .3387]//lactamide t=[0 10 20 30 40 50 60 70]//time CA=[7...
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EXAMPLE5_31.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 5 //ANGLE MODULATION clear all; clc; printf("EXAMPLE 5.31(PAGENO 257)"); //given f_m1 = 2*10^3//modulating frequency for first case delta_f1= 5*10^3//frequency deviation for first case f_m2 = 1*10^3//modulating frequency for second case del...
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scenario = "trust game"; scenario_type = fMRI_emulation; #scenario_type = fMRI; scan_period = 3000; response_matching = simple_matching; no_logfile = false; sequence_interrupt=false; #default active_buttons = 2; button_codes=0,1; default_font="arial"; default_font_size=30; default_text_color=255,255,255; default_backgr...
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clear;lines(0); deff('j=jdrn(n)','j=zeros(n,n);for k=1:n-1;j(k,k+1)=1;end') A=sysdiag(jdrn(3),jdrn(2),rand(2,2));X=rand(7,7); A=X*A*inv(X); [S,P,D,index]=projspec(A); index //size of J-block trace(P) //sum of dimensions of J-blocks A*S-(eye()-P) norm(D^index,1)
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clear;lines(0); u=file('open',TMPDIR+'/foo','unknown') for k=1:4 a=rand(1,4) write(u,a) end file('rewind',u) x=read(u,2,4) file('close',u) // file('close',file() ) //closes all opened files (C or Fortran type). // [units,typs,nams]=file()
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I(A(int i=0, i < 1*1024, i++, za[i] == 0)); I(A(int i=0, i < 2*1024, i++, za[i] == 0)); I(A(int i=0, i < 4*1024, i++, za[i] == 0)); I(A(int i=0, i < 8*1024, i++, za[i] == 0)); I(A(int i=0, i < 16*1024, i++, za[i] == 0)); I(A(int i=0, i < 32*1024, i++, za[i] == 0)); I(A(int i=0, i < 64*1024, i++, za[i] == 0)); I(A(int i...
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function [T]=TrapEq(n, a, b, f) //trapezoidal rule h = (b - a) / n; x = a; suma = f(x); for i = 1:n-1 x = x+h; suma = suma + 2*f(x); end; suma = suma + f(b); T = (b - a) * suma / (2*n); endfunction;
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clc //to calculate thickness //mass absorption coefficient mum of an absorber is related with linear absorption coefficient mu and density of the material rho is given by //mu=rho*mum=2.7*0.6=1.62 cm^-1 mu=1.62 //if initial intensity Io of the X-ray beam is reduced to I in traversing a distance x in absorber I=Io*...
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// @Harness: verifier // @Purpose: "Test for unresolved operand types" // @Result: "UnresolvedOperandType @ 7:23" architecture unr_type_01 { operand-type AT { sub-operand a: A; } }
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 11: SPECIALIZED DYNAMOS // Example 11-2 clear; clc; close; // Clear the work space and console. // Given data // VR stepper motor n = 3 ; // Number of stacks or phases P_a = 16 ; // Number of ro...
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//pagenumber 111 example 15 clear voltag=375;//volt r1=2000;//ohm induct=20;//henry c1=16*10^-6;//farad r11=100;//ohm r=200;//ohm //(1) voltage and ripple with load disp("voltage and ripple with load"); r=r+r11+400; vdc=((2*sqrt(2)*voltag/3.14))/1.35; ripple=r1/(3*sqrt(2)*(377)*induct*2); disp("vdc = "...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 5 Example 1") p1=5;//initial pressure of air T1=(27+273);//temperature of air in K p2=2;//final pressure of air in K R=0.287;//gas constant in KJ/kg K Cp_air=1...
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E1=100+%i*0; E2=43.30+%i*25 Z1=1+%i*3; Z2=1-%i*3; Z3=2+%i*4; Z4=3-%i*3 Z5=1+%i*5; Z6=2-%i*8; Iab1=E1/((Z1+Z2)+((Z3*Z4)/(Z3+Z4))); I2=E2/((Z5-Z6)+((Z3*Z1+Z2)/(Z3+Z1+Z2))); Iab2=(I2*Z3)/(Z3+Z1+Z2) disp('i) CURRENT (Iab1) is = '+string (Iab1)+'A '); disp('i) CURRENT (I2) is = '+string (I2)+'A '); disp...
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// Exa 7.3 format('v',7);clc;clear;close; // Given data subdivision = 1/5;//sub division in units positivepeak = 2.6;//positive peak in units Vpp = positivepeak + positivepeak;//peak to peak in divisions verticalattenuation = 2;//vertical attenuation in mV/div verticalattenuation = verticalattenuation * 10^-3;//...
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//Exa 6.22 clc; clear; close; // Given data T_A= 700;// in K T_B= 600;// in K T_C= 500;// in K Q_A= 1200;// in kJ // Q_B+Q_C= Q_A-200 (i) // Q_A/T_A = Q_B/T_B+Q_C/T_C (ii) // From eq(i) and (ii) Q_B= (Q_A*(1/T_B-1/T_A)-200/T_B)/(1/T_B-1/T_C);// in kJ Q_C= Q_A-Q_B-200;// in kJ...
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clear // // // //Variable declaration eta=0.7 //quantum efficiency q=1.6*10**-19 //charge(coulomb) lamda=863*10**-9 //lamda(m) P0=0.5*10**-6 //optical power(W) h=6.625*10**-34 //plancks constant(J s) c=3*10**8 //velocity of light(m/s) IT=10*10**-6 //current(A) //Calculation IP=eta*q*lamda*P...
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clc // Conjunto de nodos printf("Conjunto de nodos\n") X = -5:5 disp(X) Y = 2.^X disp(Y) // Valores a interpolar o extrapolar printf("\n Valores a interpolar o extrapolar\n") x1 = 1/2 disp(x1) x2 = 1/3 disp(x2) x3 = 1/4 disp(x3) //Interpolación mediante Lagrange printf("\n Interpolación mediante Lagrang...
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clc;clear; //Example 14.1 //calculation of intensity of laser beam //given values P=10*10^-3;//Power in Watt d=1.3*10^-3;//diametre in m A=%pi*d^2/4;//area in m^2 //calculation I=P/A; disp(I,'intensity (in W/m^2) is');
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clc clear //defining unit step function function y=u(x) y=sign((sign(x)+1)) endfunction deff('[y]=f(x)','y=t.*(u(t)-u(t-2))-2*(t-3).*(u(t-2)-u(t-3))');//finding expression for the given signal t=-1:0.01:4; plot(t,f(t));//plotting the signal h=gca(); h.grid=[1,1]
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Ebinding= 160.647; //binding nergy, MeV Mh= 1.007825; //Mass of H1 atom, u Mn= 1.008665; //Mass of neutron, u Z=10; //number of protons N=10; //number of neutrons Mneon= [(Z*Mh)+(N*Mn)]-[Ebinding/931.49]; //using Eqn 11.7 disp(Mneon,"The atomic mass of Neon 10 isotope, in terms of U, is: ") //Result // The...
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//Example 3.13 clc; syms s; I=2/((s)*(s+1)*(s+2)^(2)); i=ilaplace(I); disp(i);
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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// Calculate the internal resistance of cell and open circuit voltage clc; I=2.2*10^-3; Eo=0.33; Rl=100; Ri=(Eo/I)-100; disp(Ri,'internal resistance of cell (ohm)') Vo=0.33*[log(25)/log(10)]; disp(Vo,'open circuit voltage for a radiant incidence of 25 W/m2 (V)=')
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/* Créateur: Jinshan GUO et Anais Debureaux */ exec(fullpath(pwd() + '\TP6.sci'),-1); disp("===========Exo1==========="); t = [0 1 3 4 5.5 6]; tau_1 = t; A1 = construct(t,tau_1); disp("Resulat_Exo1(c)_A1=", A1); tau_2 = [0.5 2 2.5 3.5 4.5 5.75]; A2 = construct(t,tau_2); disp("Resulat_Exo1(d)_A2=", A2); ...
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a . p . เ อ พ ี a a m o d t อ า ม ั ด ต ์ a b แ อ ๊ บ a b b e แ อ ็ บ บ ี ้ a b b e r l e y แ อ ็ บ เ บ อ ร ์ ล ี ย ์ a b e r c o r n แ อ เ บ อ ร ์ ค อ ร ์ น a b r y เ อ อ บ ร ี ้ a b s a r o k a แ อ บ ซ า โ ร ก า a b s a r o k i t e แ อ บ ซ า โ ร ไ ก ต ์ a c a p u l c o อ า ก า ป ุ ล โ ก a c c e l e r a t o r แ อ ค เ ...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AutoTestC version="2.0.0"> <Title>Test case 2 - polarity dynamic - 8ms</Title> <Organization>Volkswagen</Organization> <Standard>VW 80000 2013</Standard> <Item>6.15 E-15 Reverse polarity</Item> <system> <PowerSystem>3</PowerSystem> ...
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ValueFrame = uicontrol(f, "style", "frame", "position", [15 480 305 80]... ,"tag", "valueFrame", "ForegroundColor", [0/255 0/255 0/255],... "border", createBorder("titled", createBorder("line", "lightGray", 1), ... _("View Panel"), "center", "top", createBorderFont("", 11, "normal"),... "black")); // timeLabel = uicon...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART III : SWITCHGEAR AND PROTECTION // CHAPTER 1: SYMMETRICAL SHORT CIRCUIT CAPACITY CALCULATIONS // EXAMPLE : 1.6 : // Page number 471 clear ; clc ; close ; // Clear the...
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// Exa 4.25 clc; clear; close; // Given data V_CC = 16;// in V V_BE = 0.7;// in V R_B = 470;// in kohm R_B= R_B*10^3;// in ohm bita = 120; R_C = 3.6;// in kohm R_C= R_C*10^3;// in ohm R_E = 0.51;// in kohm R_E= R_E*10^3;// in ohm I_B = (V_CC - V_BE)/(R_B+bita*(R_C+R_E));// in A disp(I_B*10^6,"The base cu...
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clc clear //INPUT v=1.7*10^-4;//viscosity of the air molecule in cgs d=0.00129;//density of the molecule in gm/ml p=76*13.6*981;//pressure of the molecule in gm/cm/sec^2 //CALCULATIONS r=(3*p/d)^(0.5);//rms velocity of the molecule in cm/sec mf=(3*v/(d*r));//mean free path in cm cf=r/mf;//collision frequen...
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basis=100 //lb-mole/h x=0.45 PH2O=31.6 //mm of Hg PSO2=176 //mm of Hg P=760 //mm of Hg y=2 M1=64 M2=18
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//Example 5.6 //Velocity Boundary Layer //Page No. 295 clc;clear;close; U=2; //in m/s L=0.1; //in m x=0.05; //in m y=0.000225; //in m rho=983.1; //kg/m^3 mu=0.4748*10^-6; //m^2/s Re=(U*x)/mu; d1=x*4.64/(Re)^(1/2); n=y/d1; u=U*(3*n-n^3...
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//to calculate the mmf per pole on no load and speed developed clc; ATsefl=2400; ATsenl=(3/25)*ATsefl; ATsh=ATsefl; ATnet=ATsenl+ATsh;disp(ATnet,'mmf/pole(AT)'); Ea=148; //from magnetising curve V=240; vd=3; Eanl=V-vd; n=850; nnl=n*Eanl/Ea; disp(nnl,'speed(rpm)');
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//Variable declaration n=20 // Total Assistants r=3 // Assistants to be chosen //Calculation function ans = fact(n) // returns factorial of number n""" if(n==1 | n==0) then ans = 1 else ans = n*fact(n-1) end endfunction function ans = comb(n,r) // returns number of total...
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clc; //Example 5.3 //Page no. 45 printf("Example 5.3 page no. 45\n\n"); D=0.25//diameter of fixed inner cylinder of viscometer L=0.5//height of fixed inner cylinder of viscometer T=15.3//measured torque printf("Given :\n diameter =%.2f ft\n height =%f ft\n Torque=%f ft.lbf",D,L,T); F=(2*T)/D printf("\n force ...
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// PERFORMING A DEFINITION OF GTE's and OIL's SYSTEMS CHARACTERISTICS tic; xdel(winsid()); clear; stacksize(5e7); warning('off'); printf("*********************\n"); printf("* START application *\n"); printf("*********************\n"); // Additional definitions for start programm execution TRUE = %T; FALSE = %F; ...
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clc; tr=2.5; // ratio of maximum torque to full load torque sm=0.18; // maximum slip r=1; // per phase rotor resistance x2=r/sm; // rotor reactance // using expression for tr we obtain a quadratic equation is s(full load slip) whose terms are t1=1; t2=-tr*2*sm; t3=sm^2; t=[ t1 t2 t3 ]; s=roots(t); x=sqrt((2...
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//Chapter-12, Example 12.8, Page 349 //============================================================================= clc clear //INPUT DATA Rl=100;//resistance of load in ohms f=60;//frequency in hz ripplefactor=0.04; //CALCULATIONS L=Rl/(3*sqrt(2)*(2*%pi*f*ripplefactor));//inductance mprintf("inductance is %...
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//Finding of workdone //Given D1=.6; D=0.3; a=20; b=30; N=1000; g=9.81; Vw=0; rho=1000; //To Find u=(%pi*D*N)/60; u1=(%pi*D1*N)/60; Vf=u*tan(%pi/9); Vw1=(u1*tan(%pi/6)-Vf)/tan(%pi/6); W=(Vw1*u1)/g; disp("Work Done ="+string(W)+" N-m/N");
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//chapter 4 //example 4.15 //page 135 clear all; clc ; //given Vbe=0.7; Vcc=15;//supply voltage V Ic=1;//collector current mA Vcesat=0.2;//saturation voltage Rc=(Vcc-Vcesat)/Ic; printf("\nRc=%.1fkohm,standard value 15kohm",Rc); hfemin=35;//from datasheet of 2N3903 Ibmin=1000*Ic/hfemin; Rb=1000*(Vcc-Vbe)/I...
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d_r = 13640; // Density of mercury in kg/m3 g = 9.79; // Acceleration due to gravity in m/s2 z = 562e-03; // Difference in height in m z0 = 761e-03; // Reading of barometer in m P = (d_r*g*(z+z0))*(0.987/1e05); // Gas Pressure in bar disp("bar",P,"Gas Pressure is ")
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//16.3 clc; pf=(1.8*1000)/(1100*(3^0.5)); Z=1100/100; R=Z*pf; printf("\nResistance of the load=%.2f ohm",R) Xl=(121-108)^0.5; L=Xl/314; printf("\nInductive reactance of the load=%.2f H",L)
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0:00 zwölf 0:15 viertel nach zwölf 0:20 zwanzig nach zwölf 0:45 viertel vor eins 1:00 eins 1:15 viertel nach eins 1:45 viertel vor zwei 2:15 viertel nach zwei 3:15 viertel nach drei 4:29 neunundzwanzig nach vier 5:30 halb sechs 6:31 neunundzwanzig vor sieben 7:45 viertel vor acht 8:50 zehn vor neun 9:00 neun 12:00 zwöl...
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//Example 2.8 v=4;//Velocity (m/s) t=2;//Time (min) t=t*60;//Time (s) x_0=0;//Initial position (m) x=x_0+v*t;//Final position (m) printf('Final position of the jogger = %0.1f m',x) //Final displacement and velocity are along the same direction as they are positive //Openstax - College Physics //Download for fr...
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Example2_11.sce
//Example 2.11 //Program to determine spot size at the operating wavelength using ESI //technique clear; clc ; close ; //Given data lambda=1.30*10^(-6); //metre - OPERATING WAVELENGTH lambda_c=1.08*10^(-6); //metre - CUTOFF WAVELENGTH THEETA_min=12; //degree // The effective ...
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ex11_11.sce
//Example 11.11 clc; //Wein's Bridge //Given values of bridge elements R1=4700; C1=5*10^-9; C3=10*10^-9; R3=10000; //Frequency of the circuit x=sqrt(C1*C3*R1*R3); f=invr(2*%pi*x); printf('\nFrequency of the circuit is %.2f Hz',f)
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17_2.sce
P1 = 0.18e03; // in Kpa R = 0.287; T1 = 310; P0 = 0.1e03; A1 = 0.11; V1 = 267; w = (P1/(R*T1))*A1*V1; g = 1.4; c1 = sqrt(g*R*T1*1000); M1 = V1/c1; A1A_ = 1.0570; // A1/A* A* = A_ P1P01 = 0.68207; T1T01 = 0.89644; F1F_ = 1.0284; A2A1 = 0.44/0.11 ; // A2A1 = A2/A1 A2A_ = A2A1*A1A_; M2 = 0.135; P2P02 = 0.987;...
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//Eg-3.19 //pg-123 clear clc A=[4 2 0;0.5 1 .5;0 3 3]; B=[2.3;1.1;14]; es=10^-7; imax=100; X=[0;0;0]; iter=1; lambda=1; [r,c] = size(A) n = r; errorcheck=1; //Gauss-Seidel Method while errorcheck==1//condition for termination for i=1:n summ=B(i); pivo...
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//16.12 clc; //P_input=W1+W2=15000........(i) pf=0.4 phi=acosd(0.4); a=tand(phi); //tand(phi)=(3^0.5)*(W1-W2)/(W1+W2) //on solving W1-W2=3464.2 ..............(ii) //From (i) and (ii) we can calculate W1=9.232; W2=5.768; printf("\nW1=%.2f kW",W1) printf("\nW2=%.2fkW ",W2)
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// Scilab code Ex12.1: Pg:463 (2008) clc;clear; n1 = 1.5; // Core index of an optical fibre n0 = 1; // Refractive index of air delta = 0.0005; // Intermodal dispersion factor for the fibre // Since delta = (n1-n2)/n1, solving for n2 n2 = n1 - n1*delta; // Refractive index of cladding //As sind(phi_c)...
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function y =t0(x) y = -481 +408 +589.64 * x + (-2349.163 * x^2)/2 endfunction function y=dv0(x) y=589.64 -2349.163*x endfunction x = 0 contador=0 while(1) contador = contador +1 xOld = x; x= abs(x - t0(x)/dv0(x)) Er = abs((x-xOld)/x) if (Er < 10^-3) then break ...
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//Example 5.1 clc rp=2*%pi*10^6*250*300*10^-9 format(7) disp(rp,"R_p(in k-ohm) = omega_0 * L * Q =") rs=(2*%pi*250)/300 format(6) disp(rs,"R_s(in ohm) = omega_0*L / Q =")
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clc; //page 397 F=800;//N Firce in verical direction us=0.35;// Coeffiecient of static friction uk=0.25;//Co=efficient of kinetic friction theta=25;//degree, angle of inclination theta=theta*%pi/180;//rad, Conversion into radian // Force P start block moving up // At static equillibrium Tan(Theta_s)=us theta_s=atan(us...
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//Chapter 7, Problem 8 clc; A=10*10^-4; //cross-sectional area l=0.2; //mean circumference in meter phi=0.3*10^-3; //flux B=phi/A; //flux density H=1000; mmf=H*l; //magnetomotive force disp("From the magnetisa...
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AD12 0001 2030 2003 5910 0100 !OK AT61 1904 3002 3457 3201 !OK AT35 1200 0515 6805 2701 !OK BE68 5390 0754 7034 !OK BE62 5100 0754 7061 !OK CH93 0076 2011 6238 5295 7 !OK CY17 0020 0128 0000 0012 0052 7600 !OK CZ65 0800 0000 1920 0014 5399 !OK DE89 3704 0044 0532 0130 00 !OK DK50 0040 0440 1162 43 !OK EE38 2200 2210 20...
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clear //Given a=10 b=5.0 c=9.0 d=19.0 //Calculation I2=(a-c)/((b*a)-(d*c)) I1=(1-(5*I2))/c I=I1+I2 pd=I*10 //Result printf("\n Current through each cell is %0.2f A",I) printf("\n Potential difference across 10 ohm wire is %0.3f V",pd)
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Ex7_4.sce
clear //Given P1=100.0 //W P=1100.0 //W V=250 //Calculation P2=P-P1 R=V**2/P2 //Result printf("\n The value of unknown resistance is %0.3f ohm", R)
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Euler, Subsonic Cylinder P=3</description> <executable>CompressibleFlowSolver</executable> <parameters>CylinderSubsonic_P3.xml</parameters> <files> <file description="Session File">CylinderSubsonic_P3.xml</file> <file description...
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//Ex3.4.2 //calculation of parameter for half wave rectifier ckt clc; clear; //given Rs=5;//resistance of transformer secondary winding Rf=50;//forward resistance of diode Rl=1000;//load resistance N=1/4;//ratio of no. of turns secondary to primary winding (Ns/Np) V=240;//input ac voltage Vs_rms=N*V;//rms sec...
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4_3.sce
clc; clear; //Example 4.3 L=1; //[m] e=0.8 ; //Emissivity sigma=5.67*10^-8 ; //[m^2.K^4] T1=423; //[K] T2=300; //[K] Do=60; //[mm] Do=Do/1000; //[m] A=%pi*Do*L //[sq m] A=0.189 //Approx in book [m^2] Qr=e*sigma*A*(T1^4-T2^4) //[W/m] printf("\n Net radiaiton rate per 1 metre length of pipe...
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clc; //e.g 22.10 gm=2*10**-3; rd=40*10**3; RD=20*10**3; RG=100*10**6; rL=(RD*rd)/(RD+rd); Av=-gm*rL; disp(Av); Ri=RG; disp('Mohm',Ri*10**-6,"Ri="); Ro=rL; disp('Kohm',Ro*10**-3,"Ro=");
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clear //find the brake thermal efficency of an engine //given w=16.2 t=20. p=126. q=19300. //during 20 minutes period of the test 126 bhp for a period 1/3 hour 126*(1/3.) btu=42.*2544. hi=16.2*19300. bth=(btu/hi)*100. printf("\n \n brake thermal efficency %.2f percent",bth)
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load CS16B032Register8.hdl, output-file CS16B032Register8.out, compare-to CS16B032Register8.cmp, output-list time%S1.4.1 in%D1.6.1 load%B2.1.2 out%D1.6.1; set in 0, set load 0, tick, output; tock, output; set in 0, set load 1, tick, output; tock, output; set in 120, set load 0, tick, output; tock, output; set i...
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//---------------------------// // Compute a cost function over a time horizon // With a free 3d camera // December 11 // Dune // Note : // // On construit un tour d'optimisation // La fonction de cout de ne dépend que de Uc // Uc est le vecteur de commande // Nc (nb commande differentes) n'est pas forcement egal à ...
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//to find no of expected readings clc; x=20; h=0.04; sd=1/(sqrt(2)*h); t=x/sd; P=.3708; disp(ceil(2*P*x),'no of expected readings');
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clc wavelength=0.49; //μm a=5.67*10^(-8); disp("(i) The surface temperature of the sun") T=2898/wavelength; disp(T) disp("K") disp("(ii) The heat flux at the surface of the sun =") E_sun=a*T^4; disp(E_sun) disp("W/m^2")
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// Problem no 12.4,Page No.288 clc;clear; close; L=4 //span of beam w_1=20*10**3 //Nm //u.d.l w_2=30*10**3 //Nm //u.d.l //Calculations //consider a section at a distance x from A and B.M at this section is //M_x=R_b*(3-x)-10*x**2+90*x-195 //Now integrating above equation we get //E*I*dy*(dx)**-1=-R_b(3*x-x**2*2**...
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clear all; clc; disp("From Um=rm*omega") disp("We have rm=30*Um/(N*pi)") rm=30*850/(8000*%pi) printf(" Thus rm= %0.2f ft=12.1 in",rm) disp("rm=(rt^2+rh^2/2)^0.5 or rt^2+rh^2=293.8") disp("Combined with b=rt-rh=4 in,we have rt^2-4rt-138.9=0,thus rt=13.95 in") disp("and rh=9.95 in") disp("To find the numb...
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//Introduction to Fiber Optics by A. Ghatak and K. Thyagarajan, Cambridge, New Delhi, 1999 //Example 21.2 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given nf=1.51;//refractive index of film ns=1.50;//refractive index of substrate nc=1.0;//refractive index of cover d=4e-6;//thickness of film in m...
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clc(); clear; //To determine the charge to mass ratio v=5*10^7; B=0.4; //magnetic field r=0.711*10^-3; //radius of the circle Q=v/(B*r) //Q=q/m printf("The charge to mass ratio is %e",Q);
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toga V;SBJV;PL;2;PST múkki N;GEN;DEF;SG víkja V;SBJV;PL;2;PRS fóður N;NOM;INDF;PL innræting N;NOM;INDF;SG skrokkur N;DAT;INDF;PL dý N;NOM;DEF;SG sveigur N;GEN;INDF;PL sífra V;IMP;SG;2 halastjarna N;ACC;INDF;SG ferill N;GEN;DEF;SG sérhljóði N;GEN;INDF;SG meistari N;ACC;INDF;SG slys N;ACC;INDF;PL fróa V;SBJ...
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//Example_a_8_14 page no:334 clc; fr=120*10^3; BW=50*10^3; Q=2; f1f2=sqrt(fr); f=poly([-14.4*10^9,50000,1],'f1','c'); fre=roots(f); f1=fre(2); f1=f1/1000;//converting to killo Hz f2=BW+f1; f2=f2/1000;//converting to killo Hz disp(f1,"the lower cutoff frequency is (in kHz)"); disp(f2,"the upper cutoff frequ...
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clc clear //Input data l=1;//The thickness of the crystal in cm w=5890d-8;//The wavelength of light used in cm t2=50;//The final temperature of the crystal in degree centigrade t1=20;//The initial temperature of the crystal in degree centigrade p=14;//The number of fringes that crossed the field of view //Ca...
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//Chapter 33 Ex5 clc; clear; close; PW=1100; td=110; bg=(td)^2/PW; bd=td+bg; mprintf("The bankers discount is Rs.%.0f and the bankers gain is Rs.%.0f",bd,bg);
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/01/And.tst load me.hdl, output-file me.out, //compare-to And.cmp, output-list x%B3.16.3 y%B3.16.3 as%B3.1.3 s%B3.16.3 overflow%B3.1.3; set x %B000010000...
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//This Program plots the spectrum of a segment // of a given signal obtained using Rectangular and Hamming Window clc;close;clear; [y,Fs]=wavread('C:\Test_Project\a-team_my_way.wav'); t=(0:length(y)-1)/Fs; subplot(311) plot(t,y) xlabel('Time in Seconds') title('Original Signal') // beg=5200; // Sample at ...
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<?xml version="1.0" ?> <TestCase name="t3" version="5"> <meta> <create version="10.0.0" buildNumber="10.0.0.431" author="admin" date="11/09/2017" host="inbasdpc10722" /> <lastEdited version="10.0.0" buildNumber="10.0.0.431" author="admin" date="11/09/2017" host="inbasdpc10722" /> </meta> <id>E4B8CB2EC52F11E797...
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//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi //chapter 9 //example 9.4 //edition 1 //publisher and place:Nelson Engineering clc; clear; Ra=.5;//armature resistance in ohm KQ=3;//field constant V=277;//source voltage in volt Tup=100;//upward directional load torque in Nm Vm=V*sqr...
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// Scilab Code Ex16.9: Page-604(2014) clc; clear; H0 = 71; // Hubble cinstant, km/s per Mpc tau = 1/H0*1e+006*3.26*9.46e+012/3.16e+007; // The upper limit of the age of the universe, y printf("\nThe upper limit of the age of the universe = %4.2e y", tau); // Result // The upper limit of the age of the uni...
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//EXAMPLE 10.8 //Design of LP FIR filter using Kaiser window clear; clc; wp=0.3*%pi;//rad/sec ws=0.5*%pi;//rad/sec as=40;//dB wc=(wp+ws)/2;//cutoff frequency Bw=ws-wp; disp(Bw,'Normalized transition bandwidth is = ') ds=10^(-as/20); B = (0.5842*(as-21)^0.4) + 0.07886*(as-21); N = ceil((as - 8)/(2.285*Bw)); disp(N,'Or...
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//Steam enters a turbine with a pressure of 30 bar, a temperature of 400C, a velocity of 160 m/s. Steam exits as saturated vapor at 100C with a velocity of 100 m/s. At steady state, the turbine develops work at a rate of 540 kJ per kg of steam flowing through the turbine. Heat transfer between the turbine and its sur...
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clc; printf("Example 1.2\n"); // 1 kW= 103 W = 103 J/s = 10^3 * (1 kg*1 m^2)/1 s^3 // = (10^3 * (1/0.4536) lb x (1/0.3048)^2 ft^2)/1 s^3 lfs=(10^3*(1/0.4536)*(1/.3048)^2); //lfs->lb ft^2/s^3 printf("\n 1 kW = %.0f lb ft^2/s^3",lfs); sfs=lfs/32.2; //sfs->slug ft^2/s^3 printf("\n 1 kW = %.0f slug f...
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//Initilization of variables m=8 //kg n=90 //rpm g=9.8 //m/s^2 r=0.3 //m //calculations w=2*%pi*n/60 //rad/s //Using equations of motion C=(m*g*0.3+m*r*w^2*r)/1.2 //N Bx=C-m*r*w^2 //N By=m*g //N //Result clc printf('The solution is Bx=%f N ,By=%f N and C=%f N',Bx,By,C)
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//**************************** inv_mcab ********************************** if (blk_name.entries(bl) == "inv_mcab") then mputl("#inv_mcab",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) inv_mcab_str= '.subckt inv_mcab'+' in[0]=net'+string(blk(blk_objs(bl),2))+'_'+string(ss)+' out[0]=net'+string(blk(blk_obj...