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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Example 1.21.1: L and C clc; clear; close; //given data : V=100;// in volts Irm=40;// in A tq=40;// in micro-sec Del_t=(50/100)*tq;// in micro-sec C=(Irm*(tq+Del_t))/V; disp(C,"capacitance,C(micro-farad) = ") L_min=(V/Irm)^2*C; disp(L_min,"minimum inductance,L_min(micro-Henry) = ") T=2.5;// assume one cycle period in...
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//chapter-9,Example9_3,pg 502 N=64//data units //implimentation steps for DFT=64^2 //for FFT r=(log2(N)/N)//implimentation ratio printf("implimentation ratio\n") printf("r=%.4for(3/32)",r)
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clc clear printf("Example 12.2 | Page number 416 \n\n"); //Find the stoichiometric air for combustion of (a)Carbon (b)Hydrogen (c)Sulphur //Given data //Molar masses of O2,H2,N2,C and S respectively MO2 = 32 //g/mol MH2 = 2 //g/mol MN2 = 28 //g/mol MC = 12 //g/mol MS = 32 //g/mol //Part(a) printf("Part(a)\n...
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clear; clc; //Example8.4[Pressure Drop in a Water tube] Tw=15;//temp of water while entering[degree Celcius] rho=999.1;//[kg/m^3] mu=1.138*10^(-3);//Viscosity[kg/m.s] id=0.05;//Internal diameter[m] V=5.5*10^(-3);//Flow rate[m^3/s] l=60;//length of tube[m] e=0.002*10^(-3);//[m] ...
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// Example 4.20 page no-241 clear clc vdd=30 //v rl=4.7 //k-ohm vd=20 //v id=(vdd-vd)/rl printf("\nId = %.1f mA",id) printf("\nfor vd to be constant, it should be within ±1V") del_id=1/rl printf("\nDelta_Id = ± %.1f mA\nId(min) = %f mA\nId(max) = %f mA" ,del_id,id-del_id,id+del_id) delv=vdd-vd deli=2.5...
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// Example 1.13 page no-34 clear clc l=1.27 //cm D=19.4 //cm s=0.475 //cm Va=400 //volts Se=l*D*10^-2/(2*s*Va) Se=ceil(Se*10^5) printf("\nS_E=%.2f mm/v",Se/100) v=30 //volt e=1.6*10^-19 //C m=9.1*10^-31 //kg x=sqrt(m/e) B=(x*0.65*30*sqrt(2*Va))/(l*D) printf("\nB=%.2f*10^-5 wb/m^2",B*10^5)//answer ...
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// Script question 5, fonction de remonté calculant la solution X du système trans(L)X = Z clc; function X = remonte(Ldiag, Linf, Z) indiceMax = size(Ldiag, "c") //Calcul des coefficients, X est un vecteur ligne for i=indiceMax:-1:1 if i==indiceMax then X(1,i)=Z(i)/Ldiag(i) ...
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clear; clc; Y1=500^-1; Y2=1000^-1; Z=100; A= 1+Y2 * Z; B=Z; C=Y1+Y2+(Y1*Y2*Z); D=1+Y1 * Z mprintf("A= %.1f ; B= %.1f ohm ; C=%.1f *1e-3seimens; D= %.1f", A, B, C*1e3, D);
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clc //initialization of new variables clear T=300 //K gama=1.4 R=286.6 //calculation // for air a=sqrt(gama*R*T) //result printf('The speed of sound in air is %.1f m/s ',a) // for sea water E=2.34*10^9 // N/m^2 rho=1000 //kg/cm^2 a=sqrt(E/rho) //result printf(' \n The speed of sound in sea waer is %d m/...
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//Example 2.8.3://ARITHEMATIC MEAN ,median value ,standard deviation clc; clear; format('v',6) q=[29.2,29.5,29.6,30.0,30.5,31.4,31.7,32.4,33.0,33.3,39.4,28.9];// AM= mean(q);//arithematic mean in mm for i= 1:12 qb(i)= q(i)-AM; end Q= [qb(1),qb(2),qb(3),qb(4),qb(5),qb(6),qb(7),qb(8),qb(9),qb(10),qb(11),qb(12)];// A...
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close(); clear; clc; R1 = 12; //ohm R2 = 4; //ohm R3 = 5; //ohm R4 = 5; //ohm R5 = 15; //ohm //voltage across R1 'V1' V1 = 132; //V I = V1/R1; R = R1 + R2 + (R4+R5)*R3/(R3+R4+R5); //source voltage 'V' V = I*R; mprintf("The voltage source, V = %d V",round(V));
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//Example 9_20 page no:380 clc; Zr=4+(%i*8); Zrmag=8.944; Zrang=63.4; Zy=3+(%i*4); Zymag=5; Zyang=53.1; Zb=15+(%i*20); Zbmag=25; Zbang=53.1; I2ang=136.58; //calculating Zry,Zyb,Zbr ZrZymag=(Zrmag*Zymag); ZrZyang=(Zrang+Zyang); ZrZyreal=(ZrZymag)*cosd(ZrZyang); ZrZyimg=(ZrZymag)*sind(ZrZyang); ZyZbmag=(...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 7 //WAVEFORM CODING TECHNIQUES clear all; clc; printf("EXAMPLE 8.6(PAGENO 389)"); //given v = 7//bits of encoder r = 50*10^6//bit rate of the system //calculations f_m = r/(2*v)//maximum message bandwidth which is less than or equal to o...
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clear clc //function y = funcao(x) // y=(x(1) - 2).^4 + (x(1)-2*x(2)).^2; //endfunction function grad_x = gradiente(x) n = length (x); h = 1e-5; gg = []; for i = 1 : n x_adv = x x_adv(i) = x(i) + h; dev = (f(x_adv)- f(x))/h; gg = [gg; dev]; ...
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//Example 9.5.a clc;clear;close; z=poly(0,'z'); s=poly(0,'s'); Hz=3*(2*z^2+5*z+4)/(2*z+1)/(z+2); H=pfss(Hz/z); for k=1:length(H) H(k)=clean(H(k)); H1(k)=z*horner(H(k),z); disp(H1(k),'System Function for parallel realisation Hk(z)='); end disp(Hz,'System Function H(z)=');
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//Exa 3.6 clc; clear; close; //Given data : Tr=0.2;//in us l=20;//in Km //part (a) B=1/(2*Tr*10^-6);//in Hz B=B/10^6;//in MHz disp(B,"Maximum possible assuming no intersymbol interference in MHz : "); //Part (b) Dispersion=Tr*10^-6/l;//in sec/Km disp(Dispersion*10^9,"Dispersion in ns/Km : "); //part (c) ...
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-- CE3002C.TST -- Grant of Unlimited Rights -- -- Under contracts F33600-87-D-0337, F33600-84-D-0280, MDA903-79-C-0687, -- F08630-91-C-0015, and DCA100-97-D-0025, the U.S. Government obtained -- unlimited rights in the software and documentation contained herein. -- Unlimit...
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//Chapter 2,Ex2.16,Pg2.24 clc; disp("Refer to the diagram shown in the figure") a=[15 -10 -5;0 1 -1;-15 12 6] b=[50;2;0] i=a\b printf("\n I1 = %.0f A\n",i(1)) printf("\n I2 = %.2f A\n",i(2)) printf("\ I3=%.2f A\n",i(3)) printf("\n Current through 5 ohms resistor = %.1f A\n",i(1)-i(3))
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// Example 4.11, Page No-213 clear clc fa=200 fmax=fa C1=0.1*10^-6 Rf=1/(2*%pi*fa*C1) Rf=Rf/1000 printf("Rf= %.3f kohm", Rf) fb=10*fa R1=1/(2*%pi*fb*C1) R1=R1/1000 printf("\nR1= %.3f kohm", R1) Cf=R1*C1/Rf Cf=Cf*10^6 printf("\nCf= %.2f uF", Cf)
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clc,clear printf('Example 5.5\n\n') V_OC_line=230,I_asc=12.5 // when I_f=0.38 V_OC_ph=V_OC_line/sqrt(3) Z_s=V_OC_ph/I_asc R_a=1.8/2 //1.8 is between terminals..0.9 is per phase X_s=sqrt(Z_s^2-R_a^2) I_a=10// when regulation is needed V_L=230 V_ph=V_L/sqrt(3) //Part(i) phi1=acos(0.8) //and lagging ...
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rf = 0.25; span = 4; sps = 3; h= rcosdesign(rf,span,sps,'normal'); h_expeceted=[-1.83515589323958e-17 -0.0839769617250925 -0.111533834697389 2.20296105783395e-17 0.241477835573582 0.492495595150919 0.599407402858453 0.492495595150919 0.241477835573582 2.20296105783395e-17 -0.111533834697389 -0.0839769617250925 -1.83515...
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//chapter-5,Example5_8,pg 493 Nx=64//2^6, 6 bit counteer register Vref=2.2//ref. voltage N=32//SAR output Vi=(N/(Nx+1)*Vref)//input voltage printf("input voltage\n") printf("Vi=%.2f V",Vi)
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//chapter-9 page 412 example 9.8 //============================================================================== clc; clear; //For a Gunn Diode L=20*10^(-4);//Active Length in cm Vd=2*10^7;//Drift Velocity of Electrons in cm/sec Ec=3.3*10^3;//Criticl Field for GaAs in V/cm //CALCULATION fn=(Vd/L)/10^9;//N...
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//Exa 7.7 clc; clear; close; // given : D_a=6 // Diameter of paraboloid reflector in m c=3*10^8 // speed of light in m/s f=4 // frequency in GHz f=4*10^9 // frequency in Hz lambda=c/f // wavelength in m r=2*D_a^2/lambda // required minimum distance between two antennae in m disp(r,"required minimum distance ...
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clc m=5; //kg T1=550; //K p1=4*10^5; //Pa T2=290; //K T0=T2; p2=1*10^5; //Pa p0=p2; cp=1.005; //kJ/kg K cv=0.718; //kJ/kg K R=0.287; //kJ/kg K disp("(i) Availability of the system :") ds=cp*log(T1/T0) - R*log(p1/p0); Availability=m*[cv*(T1-T0) - T0*ds]; disp("Availability of the system =") disp(Availab...
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a=imread('milkeway.jpg'); b=double(a); [m,n]=size(b); for i=1:m for j=1:n c(i,j)=10*log(1+b(i,j)); end end imshow(c);
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timeMat = fscanfMat('Linear_Regression/TimeMatrix') numlines = length(timeMat(:,1)) for i = 1:numlines end
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//Example 9.34 clc disp("Resolution = V_0FS / 2^n - 1") disp("Therefore, 20 = V_0FS / 2^n - 1") disp("Therefore, V_0FS = 5.1 V") disp(" D = Equivalent of 10000000 = 128") disp("Therefore, V0 = Resolution * D = 20 * 128 = 2.56 V")
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style.fontSize=12; style.displayedLabel="<table> <tr> <td><b>In</b></td> <td>nmirror<br>w_bias</td></tr></table>"; pal5 = xcosPalAddBlock(pal5,"nmirror_w_bias",[],style);
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//Chapter 7: Solid State //Problem: 6 clc; //Declaration of Variables l = 2 * 10 ** - 10 //in m t = 30 //in degrees // Solution mprintf("For first-order reflection\n") d = l / (2 * sin(t)) dist = 2 * d mprintf(" Hence, distance between planes is : %.0e m ",abs(dist))
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// Scilab code Ex1.7: Pg:20 (2008) clc;clear; m = 9.1e-031; // Mass of an electron, kgm h = 6.6e-034; // Planck's constant, joule-sec c = 3e+08; // Velocity of light, m/s // Energy of one quantum of radiation is given by E = h*nu and // furhter, E = m*c^2 where nu = c/Lambda, the frequency of radiation...
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ft=3.67; m=ft*0.3048; disp("the given length (in m) is"); disp(m);
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clc //initialization of the problems clear s=1.6 //m s1=4 //m pi=28 //degrees w=16 //kg/m^2 p=100 //kg/m^2 pl=20 //cm pb=10 //cm r=500 //kg/m^3 Zx=54.8 //cm^3 Zy=3.9 //cm^3 // calculations pi=pi*%pi/180 //radians W=w*s+8.1 P=p*s L=P+W*cos(pi) Mx=L*s1^2*100/8 sigma_1=Mx/Zx My=W*sin(pi)*s1^2*100/8 si...
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clear // Variable declaration T_ra=21// The temperature of the returning air H=50// % saturation T_d=28// The dry bulb temperature in °C T_w=20// The wet bulb temperature in °C m_a=20// The mass flow rate of returning air in kg/s m_b=3// The mass flow rate of outside air in kg/s x_ra=0.0079// The moisture content in k...
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//chapter 3 // exmaple 3.6 //page 124 , figure 3.17 R1=1*10^3;R2=R1;R3=R1;//given Rf=1*10^3;//given Vin1=2;Vin2=1;Vin3=4;//given Vout=-((Rf/R1)*Vin1+(Rf/R2)*Vin2+(Rf/R3)*Vin3); disp(Vout)
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# Heat exchanger test units SI $thermo = VirtualMaterials.Peng-Robinson / -> $thermo thermo + PROPANE ISOBUTANE n-BUTANE n-PENTANE # lets have some streams for this test hotInlet = Stream.Stream_Material() coldInlet = Stream.Stream_Material() hotOutlet = Stream.Stream_Material() coldOutlet = Stream.Stream_Ma...
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//Section-1,Example-3,Page no.-AC.205 //To calculate the percentage of excess air used for combustion. clc; C=0.54 H=0.065 O=0.03 N=0.018 M_W=(((32/12)*C)+((16/2)*H)-O)*(100/23)//Minimum weight of air required for combustion W_CO2=(C*(44/12)) W_N2=N+(M_W*(77/100)) T_W=(W_CO2+W_N2) //Total weight of dry products of ...
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; @Harness: simulator ; @Format: atmel ; @Arch: avr ; @Purpose: "Test the ASR (arithmetic shift right) instruction" ; @Result: "r16 = 1, flags.c = 0, flags.s = 0" start: ldi r16, 0b10 asr r16 end: break
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// Example 2_15 clc;funcprot(0); //Given data w=[1 2 3 4 5 6 7 8 9 10 11 12];// Week b=[6000 4000 5400 2000 1500 1000 1200 4500 8000 4000 3000 2000];// Weekly flow in m^3/sec //Calculation for(i=1:12) c(i)=b(i)*7; end Cv(1)=c(1);// day-sec-metres Cv(2)=Cv(1)+c(2);// day-sec-metres Cv(3)=Cv(2)+c(3);// d...
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//Chapter 3 : Systems of Linear Equations //Example 3.26 //Scilab 6.0.1 //Windows 10 clear; clc; A=[1 2 -1 -2; -1 -1 1 1; 0 1 2 1]; disp(A,'A=') I1=eye(4,4) I2=eye(3,3) A=[A I2] disp(I1) disp(A) A(2,:)=A(2,:)+A(1,:) disp(I1) disp(A) A(3,:)=A(3,:)-A(2,:) disp(I1) disp(A) A(3,:)=A(3,:)/2 di...
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exec("degree_rad.sci",-1) //Given that gr_height = 3 //in m theta = dtor(53) g = -9.8 //in m/s^2 v0 = 26.5 //in m/s tower_height = 18 //in m //Sample Problem 4-8a printf("**Sample Problem 4-8a**\n") x = poly(0,'x') y = x * tan(theta) + g * x * x /(2* v0^2) * sec(theta)^2 y_tower1 = horner(y,23) ...
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// Exa 8.4 clc; clear; close; // Given data l=2.5;// in cm l=l*10^-2;// in meter d=1;// in cm d=d*10^-2;// in meter Va= 1000;// in volts theta= 1;// in degree // Formula tand(theta) = l*Vd/(2*d*Va) Vd= 2*d*Va/l*tand(theta);// in volts disp(Vd,"Voltage required across the deflection plates in volts")
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//[]=finit() // Initialisation de parametres relatif au probleme // de l'alunissage //k : acceleration de poussee de la fusee //gamma : acceleration de la pesanteur sur la lune //umax : debit maximum d'ejection des gaz //mcap : masse de la capsule //cpen : penalisation dans la fonction cout de l'etat final //! k...
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errcatch(-1,"stop");mode(2);//scilab 5.4.1 //Windows 7 operating system //chapter 23 Lasers,Fibre Optics,and Holography V=500//V=bandwidth of a He-Ne laser in Hz t=1/V//t=coherence time disp("ms",(t*(10^3)),"The coherence time is =") c=3*10^8//c=velocity of light in m/s Lc=c/V//Lc=longitudinal coherence leng...
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//water chemistry// //example 7.13// W1=160;//amount of Ca2+ in ppm// W2=88;//amount of Mg2+ in ppm// W3=72;//amount of CO2 in ppm// W4=488;//amount of (HCO3)- in ppm// W5=139;//amount of (FeSO4).7H2O in ppm// M1=100/40;//multiplication factor of Ca2+// M2=100/24;//multiplication factor of Mg2+// M3=100/44;//m...
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//Example 7.10 m=65;//Mass of player (kg) v_i=6;//Initial velocity (m/s) f=450;//Force of friction (N) theta=5;//Angle of incline (deg) d=(1/2*m*v_i^2)/(f+m*g*sind(theta));//Distance slid (m) printf('Distance slid = %0.2f m',d) //Openstax - College Physics //Download for free at http://cnx.org/content/col11406/...
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close(); clear; clc; //line voltage 'Vl', resistance 'R', reactance 'X' Vl = 207.8; R = 36; X = 48; //inpedance Z = sqrt(R^2 + X^2); //(a)phase current 'Ip' Ip = Vl/Z; //A mprintf("Phase current, Ip = %0.2f A\n\n",Ip); //(b)line current 'Il' Il = sqrt(3)*Ip; //A mprintf("Line current, Il = %d A\n\n",ro...
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//pathname=get_absolute_file_path('12.01.sce') //filename=pathname+filesep()+'12.01-data.sci' //exec(filename) //Pressure at which steam is supplied(in MPa): p1=0.2 //Temperature of steam(in C): T=250 //Pressure upto which steam is expanded(in bar): p2=0.3 //Pressure at which it is finally released(in bar): p...
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clc disp("Example 5.45") printf("\n") disp("calculate the value of R & c for RC phase shift oscillator") printf("Given\n") //oscillating frequency f=2000 //select Capacitor value C=0.1*10^-6 //resistance value R=1/(2*%pi*f*C*sqrt(6)) printf("Resistance value \n%f ohm\n",R)
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//CAPTION: Conductivity_of_an_n-Type_GaAs_Gunn_Diode //chapter_no.-7, page_no.-294 //Example_no.7-2-1 clc; //Calculate_the_conductivity_of_the_diode e=1.6*(10^-19); nl=(10^10)*(10^6);//electron_density_at_lower_valley nu=(10^8)*(10^6);//electron_density_at_upper_valley ul=8000*(10^-4);//electron_mobility_a...
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localdir="./*.wav" listoffiles = listfiles(localdir) //disp(listoffiles(:)) [numfiles, y] = size(listoffiles) //disp(numfiles) //disp(y) listoffiles = ["_Inambari-Tambopata__Antwren_0.wav" "Papa-formiga-barrado_7.wav"] data = read(listoffiles(1,1) + ".dat", -1,240000) listoffiles = ["_Inambari-Tambopata...
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//Section-6,Example-1,Page no.-P.40 //To find by how much is the chemical potential of benzene reduced for the given conditions. clc; x_B=0.10 x_A=1.0-0.10 R=8.314 T=298 mu=R*T*log(x_A) //mu=mu_A-mu_Abar disp(mu,'Required chemical potential(Jmol^-1)')
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// Example 11.4 // Computation of resistance using linear approximation and values are // compared with results obtained in example 11.1 // Page No. 456 clc; clear; close; // Given data HP=40; // hp rating of the device %ratedload=0.902; // Percentage rated load VT=240; ...
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errcatch(-1,"stop");mode(2);//Caption:Find the speed of machine //Exa:2.22 ; ; V=250;//in volts P_i=50*10^3;//in watts I_L1=P_i/V;//in amperes R_a=0.02;//in ohms R_f=50;//in ohms I_f=V/R_f;//in amperes I_a1=I_L1+I_f;//in amperes I_L2=P_i/V;//in amperes I_a2=I_L2-I_f;//in amperes N_1=400;//in rpm E_2=V-(...
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//Exa 2.48 clc; clear; close; format('v',7); //Given Data : V1=1.5;//m^3 V2=0;//m^3 p=1.02;//bar W=p*10^5*integrate('1','V',V1,V2);//J disp(W/1000,"Work done by the air in KJ : ");
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// Scilab Code Ex7.14: Page-382 (2008) clc; clear; e = 1.6e-019; // The energy equivalent of 1 eV, J c = 3e+008; // Speed of light in vacuum, m/s n = 1; // Order of diffraction d = 2.82e-010; // Interplanar spacing, m V = 9.1e+003; // Operating voltage of X rays theta = 14; // Bragg's angle, de...
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clc,clear printf('Example 7.13\n\n') CE_Ag=107.98; CE_Al=27/3; //chemical equivalents //Electrochemical equivalents ECE_Ag=0.00111*10^-3 //in kg/C ECE_Al=ECE_Ag * (CE_Al/CE_Ag) current_efficiency=92/100 I=3000 //average current in A t=24*3600 //duration of flow of current in seconds m_al=ECE_Al*I*t*curre...
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//*************** HH neuron b debug ********************** if (blk_name.entries(bl) =='hh_neuron_b_debug') then mputl("# HH neuron b debug",fd_w); hh_neuron_b_debug_str= ".subckt hh_neuron_b_debug" for ss=1:scs_m.objs(bl).model.ipar(1) hh_neuron_b_debug_str=hh_neuron_b_debug_str+" in[0]=net"+string(...
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//ques41 clc disp('tanu=dQ/dr*r'); syms Q a; r=2*a/(1-cos(Q)); u=atan(r/diff(r2,Q,1)); u=eval(u); p=r*sin(u); syms r; Q=acos(1-2*a/r); //cos(Q)=1-2*a/r; p=eval(p); disp(p);
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART III : SWITCHGEAR AND PROTECTION // CHAPTER 1: SYMMETRICAL SHORT CIRCUIT CAPACITY CALCULATIONS // EXAMPLE : 1.1 : // Page number 466-467 clear ; clc ; close ; // Clear...
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<!DOCTYPE html> <html> <head> <meta charset="utf-8"/> <title>JavaScript File Encryption App</title> <meta name="viewport" content="width=device-width, initial-scale=1" /> <link href="http://fonts.googleapis.com/css?family=Raleway:400,700" rel="stylesheet" /> <link href="assets/css/style.css" rel="styleshe...
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//Chapter-9,Example9_28,pg 9_82 Po=20*735.5//(in W) V=230 N=1150 P=4 A=P Z=882 Ia=73 Ish=1.6 T=60*Po/(2*%pi*N) phi=T*A/(0.159*Ia*P*Z)//flux per pole Il=Ia+Ish Pin=V*Il n=Po*100/Pin printf("electromagnetic torque\n") printf("T=%.3f Nm\n",T) printf("flux per pole\n") printf("phi=%.3f Wb\n",phi) printf("...
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//============================================= // Exercise 22: Exchange flow through a strait //============================================= // Animation of surface and bottom distributions of Eulerian concentrations & flow fields // Author: Jochen Kaempf, March 2015 (update) f = gcf(); f.color_map = jetcolorm...
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clear //In this problem, it is required to find out the moment of inertia of the section about an axis AB. So there is no need to find out the position of the centroid. //The given section is split up into simple rectangles //Moment of inertia about AB = Sum of moments of inertia of the rectangle about AB //variable ...
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U = 5 R = 2 L = 50 * 10^(-3) tau = L/R t = [0:tau/10:10*tau] yu = U + (t*0.001) yul = U * (%e^(-(t/tau))) yi = (U/R) * (1 - %e^(-(t/tau))) xset("thickness",3) plot2d(t,yu, style=3); plot2d(t,yul, style=2); plot2d(t,yi, style=5); ylabel("U, Ul, Il", "fontsize", 6); xlabel("t/s", "fontsize", 6) //xtitle('Kondensat...
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#SDL: scenario = "Grades"; pcl_file = "GradesPCL.pcl"; begin; picture { text { caption = "grades on screen";} t_Grades; x= 0; y = 0; }p_Grades;
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load stof.hdl, output-file stof.out, compare-to stof.cmp, output-list in%B1.16.1 out%B1.15.1; set in %B1110000000000001, eval, output; set in %B0000000000000001, eval, output;
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m = mode(); mode(-1); // the position error between the current and final positions for the end effector // // CPosition: Cartesian coordinates of the current position. // FPosition: Cartesian coordinates of the end point. function result = F1(CPosition, FPosition) try positions = [CPosition; FPosition];...
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example13.sce
clc clear //input data b2=10//Rotor blade air angle at exit in degree Dt=0.6//The tip diameter in m Dh=0.3//The hub diameter in m N=960//The speed of the fan in rpm P=1//Power required by the fan in kW pi=0.245//The flow coefficient P1=1.02//The inlet pressure in bar T1=316//The inlet temperature in K R=287/...
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Example_11_14.sci
clear; clc; xdo = 0.98; //per cent of ortho top product xwo = 0.125; //per cent of ortho bottom product function[f]=product(x) f(1) = 100 - x(1) - x(2); //x(1) is D and x(2) is W f(2) = 60 - x(1)*xdo - x(2)*xwo; funcprot(0); endfunction x = [0,0]; y = fsolve(x,pro...
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Ex1_1.sce
//Velocity calculation clc //initialisation of variables t=20//ft t1=30//ft v=1320//ft/s p=25//sec q=15//ft/s v1=v/t//ft/s v2=v/t1//ft/s T=(v2-v1)/p//ft/s^2 V=v2-q*-T//ft/s V1=-V^2/(2*T)//ft/s //RESULTS printf('the velocity time is=% f ft/s',V1)
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//Example 23.1 N=1;//Number of loops r=6*10^-2;//Radius of coil (m) A=%pi*r^2;//Area of loop (m^2) delta_BcosTheta=0.250-0.05;//Change in value of magnetic field strength perpendicular to area (T) delta_phi=A*delta_BcosTheta;//Change in magnetic flux (T.m^2) delta_t=0.1;//Time (s) Emf=N*delta_phi/delta_t;//Induc...
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17_1.sce
clc //initialisation of variables l=1000//mm L=l/2//mm y=2.6//g/cu y1=7.85//g/cu a=375//mm //CALCULATIONS D=y1/y//mm C=L/2+a//mm //RESULTS printf('the centre of gravity of the shaft=% f mm',C)
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// Grob's Basic Electronics 11e // Chapter No. 30 // Example No. 30_7 clc; clear; // Calculate Av, Vo & Zo. // Given Data Rs = 240; // Source Resistor=240 Ohms Rl = 1.8*10^3; // Load Resistor=1.8 kOhms Vgsoff = -8; // Voltage Gate-Source(off)=-8 Volts Vgs = -2; // Voltage Ga...
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// Scilab code Exa9.11 : : Page-394 (2011) clc; clear; R_0 = 1.2e-015; // Distance of closest approach, metre // Mass number of the nuclei are allocated below : N = rand(4,1) N(1,1) = 17; // for oxygen N(2,1) = 33; // for sulphur N(3,1) = 63; // for copper N(4,1) = 209; // for...
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Chap3_Ex14_R1.sce
// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-3,Example 14,Page 75 //Title:Volume using generalized form of the Redlich-Kwong equation of state //================================================================================================================ ...
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//(Design against Static Load) Example 4.18 //Refer Fig.4.57 on page 126 //Tensile yield strength of FeE250 Syt (N/mm2) Syt = 250 //Factor of safety fs fs = 5 //Diameter of bars to be sheared D (mm) D = 6.25 //Ultimate shear strength of the material Sus (N/mm2) Sus = 350 //Permissible bearing pressure on th...
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clc; clear all; close; x1=[1,3,7,-2,5]; x2=[2,-1,0,3]; z=xcorr(x1,x2); disp(z,"This is the required correlation"); l=length(z); t=0:l-1; plot2d3(t,z); xlabel("n"); ylabel("Amplitude"); title("Correlation: y(n)=x1(n)*x2(-n)"); figure;
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clc //initialisation of variables W= -10 //KN/m r= 5 //m //CALCULATIONS Rav= -W*2*r/2 Rbv= Rav function[y]=conv(x) y=125*(sin(x))^2*5*(sin(x))*5 endfunction v=intg(0,%pi,conv) function[y]=conk(x) y=25*(sin(x))^2*5 endfunction k=intg(0,%pi,conk) Rbh= v/k Rah= Rbh //RESULTS printf ('Rav= %.2f KN...
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function status = generateTFProc(name, forward_coefficients, feedback_coefficients, parameters) fd = parameters.fd mfprintf(fd, '#include <string.h>\n') mfprintf(fd, 'static __inline__ _NUMBER_TYPE %s(_NUMBER_TYPE e1)\n{\n', name) mfprintf(fd, '%sstatic _NUMBER_TYPE x[] = {', parameters.inde...
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//Page Number: 5.41 //Example 5.34 clc; //Given, fs=8000; //Hz m=24; n=8; //(a) Duration of each bit t1=1/fs; t2=(m*n)+1; // Extra bit for synchronization Tb=t1/t2; disp('seconds',Tb,'Duration of each bit'); //(b) Transmission Rate Rb=1/Tb; disp('b/s',Rb,'Transmission Rate'); //(c)Minimum transmissio...
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//example 4.25 //calculate average depth of hourly rainfall excess clc;funcprot(0); //given r=[2.0 2.5 7.6 3.8 10.6 5.0 7.0 10.0 6.4 3.8 1.4 1.4]; //rainfall depths A1=20; A2=40; A3=60; A=A1+A2+A3; fi1=7.6; fi2=3.8; fi3=1.0; for i=1:12 R1(i)=r(i)-fi1; //rainfall excess R2(i)=r(...
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clear data7; exec('data02.dat'); getf('label.sci'); T = data7(:,1); fan = data7(:,3); //T is time, fan is fan speed u = data7(:,2); y = data7(:,4)-data7(1,4); // u is current, y is temperature ord = [u y]; x = [T T]; // u and y are plotted vs. time and time xbasc(); plot2d(x,ord); xgrid(); title = 'Ramp change in ...
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//ques11 disp('To find the inverse laplace transform of the function'); syms s t f=(s^2-3*s+4)/s^3; il=ilaplace(f,s,t); disp(il);
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// chapter 2 // example 2.8 // Fig. E2.8 // Calculate the resistance, gate power dissipation and maximum triggering frequency // page-32-33 clear; clc; // given Ig_min=500; // in mA (minimum gate current) gradient=16; // in V/A Egs=15; // in V (gate source voltage) T_on=4; // in us (minimum turn on time) Pg_av=0.3; // ...
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function a=%r_clean(a,epsa,epsr) //Syntax: a=%r_ clean(a,epsa,epsr) // Given a, matrix of rationals , this function // eliminates all the coefficients of a with absolute value < epsa // and realtive value < epsr (relative means realive wrt norm 1 of // the coefficients) // Default values : epsa=1.d-10; epsr=1.d-10...
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clc p1=75.882; //cm of Hg T1=286; //K V1=0.08; //m^3 p2=76; //cm of Hg T2=288; //K V2=p1*V1*T2/p2/T1; m=28; //kg c=4.18; t2=23.5; //0C t1=10; //0C Q_received=m*c*(t2-t1); HCV=Q_received/V2; disp("Higher calorific value =") disp(HCV) disp("kJ/m^3") amt=0.06/0.08; //Amount of vapour formed per m...
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//Chapter-6, Example 6.9, Page 258 //============================================================================= clc clear //INPUT DATA L=100;//Length of rectangular duct in m A=[0.02,0.025];//Area of duct in m^2 Tw=40;//Temperature of water in degree C v=0.5;//Velocity of flow in m/s k=(0.66*10^-6);//kine...
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clear; clc; close; Rl = 1000; R = 120; Vdc = 60; Vdc_dash = (Rl/(R+Rl))*Vdc; disp(Vdc_dash,'Dc voltage across 1k-ohm load = ');
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//Tested on Windows 7 Ultimate 32-bit //Chapter 9 Frequency Response of Amplifier Pg no. 307 and 308 clear; clc; //Given VCC=15;//collector supply voltage in volts RC=2.2D3;//collector resistance in ohms RE=470;//emitter resistance in ohms R1=33D3;//divider network resistance R1 in ohms R2=10D3;//divider n...
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s=%s;//given Kv=1000sec^-1 Kv =1000; g =Kv/( s*(0.1*s +1)* (1+.001*s)) G= syslin ('c',g) fmin =0.01; fmax =100; bode (G,fmin , fmax ) show_margins (G) xtitle (" uncompensated system") [gm , freqGM ]= g_margin (G) [pm , freqPM ]= p_margin (G) disp (gm ," g a i n ma r g i n=") disp (( freqGM *2* %pi)," =gain ...
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//pathname=get_absolute_file_path('5.10.sce') //filename=pathname+filesep()+'5.10-data.sci' //exec(filename) //Initial pressure(in kPa): p1=3000 //Initial volume(in m^3): v1=0.05 //Final volume(in m^3): v2=0.3 //Value of n: n=1.4 //Final pressure(in MPa): p2=p1*((v1/v2)^n) //Entropy change: dS=0 //Change...
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//Load scripts from folder funcprot(0) getd("../scripts"); //Global variables imgPos = "../images/"; //The position of the source images renderPos = "render/"; //The folder where the render images will be saved //Load image imgin = readpbm(imgPos+"Formes.pbm"); imgout = median(imgin,0) //Show the coordinates of t...
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PL/SQL Developer Test script 3.0 5 begin -- Call the procedure personas_por_quiere_mascota(pqmascotas => :pqmascotas, p_recordset => :p_recordset); end; 2 pqmascotas 1 1 5 p_recordset 1 <Cursor> 116 0
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clc; clear all; close; //----------------------------------------------------------------------------- b = chdir('C:\Users\work\OneDrive\Documents\SciLab\lab_v4') //read data [irc_my, Fs_irc, h_bits] = wavread("C:\Users\work\OneDrive\Documents\SciLab\lab_v4\1a_marble_hall.wav") [signal, Fs_s, s_bits] = wavread("C:\User...
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//chapter9 //example9.8 //page148 V=15 // V R=0.5 // kilo ohm V_D=0.7 // V // both diodes are forward biased I1=(V-V_D)/R I_D1=I1/2 I_D2=I_D1 printf("current through diode D1 = %.3f mA and diode D2 = %.3f mA \n",I_D1,I_D2)
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sce
Example_9_5.sce
//clear// clear; clc; //Example 9.5 //Given Dt = 6; //[ft] H = 8; //[ft] T = 70; //[F] sp_gr = 3.18; w_fr = 0.25; Da = 2; //[ft] h = 1.5; //[ft] gc = 32.17; //[ft-lb/lbf-s^2] // (a) //Using data of Buurman et al. in Fig.(9.19) //change in nc delta_nc = (104/200)^0.2*(2.18/1.59)^0.45*(33.3/11.1)^0.13;...