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trainLRClassifier.sci
// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt // Author: Siddhant Narang // Organization: FOSSEE, IIT Bombay // Email: toolbox@scilab.in function classifier = trainLRClassifier(imgSets, bag, classifierName, varargin) // This function is used to train an image classifier using the LR algorithm. // // Calling Sequence // classifier = trainLRClassifier(imgSets, bag, classifierName) // classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate) // classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate, iteration) // classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate, iteration, regularization) // classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate, iteration, regularization, trainMethod) // classifier = trainLRClassifier(imgSets, bag, classifierName, learningRate, iteration, regularization, trainMethod, minibatch) // // Parameters // classifier: Image category classifier // imgSets: Input imageSet to train the classifier on // bag: The bagOfFeatures of the imageSet provided // learningRate: Defines the rate at which the classifier will learn. // iteration: Number of iterations the training function will perform. // regularization: Controls the kind of regularization to be applied. The types are<itemizedlist><listitem>REG_DISABLE- Regularization disabled, flag value = -1.</listitem><listitem>REG_L1- L1 norm, flag value = 0.</listitem><listitem>REG_L2- L2 norm, flag value = 1.</listitem></itemizedlist> // // trainMethod: Controls the kind of training method to be applied. The types are<itemizedlist><listitem>BATCH- flag value = 1.</listitem><listitem>MINI_BATCH- flag value = 0.</listitem></itemizedlist> // // minibatch: Specifies the number of training samples taken in each step of Mini-Batch Gradient Descent. // Will only be used if trainMethod flag value is set to 0 training algorithm. // It has to take values less than the total number of training samples. // // // Description // This function trains a LR classifier which can be used to predict classes of images given to it as // input using the predictLR() function. // // Examples // imgSet = imageSet('images/trainset_2/','recursive'); // [trainingSet testSet] = partition(imgSet,[0.8]); // bag = bagOfFeatures(trainingSet); // lrclassi = trainLRClassifier(im, bag, "lrclassi", 1, 150, 0, 1, 5); // // Examples // imgSet = imageSet('images/trainset_3/','recursive'); // [trainingSet testSet] = partition(imgSet,[0.8]); // bag = bagOfFeatures(trainingSet); // lrclassi = trainLRClassifier(im, bag, "lrclassi", 1, 150, 0); // save("var.dat", "lrclassi"); // // See also // imageSet // partition // bagOfFeatures // mlPredict // save // // Authors // Siddhant Narang bag_list = bagStructToList(bag); imgSets_list = imageSetToList(imgSets); // Handling variable arguments. [lhs rhs] = argn(0) if lhs > 1 error(msprintf("Too many output arguments")); elseif rhs < 3 error(msprintf("Not enough input arguments")); elseif rhs > 8 error(msprintf("Too many input arguments")); end if rhs == 3 temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName); elseif rhs == 4 temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1)); elseif rhs == 5 temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1), varargin(2)); elseif rhs == 6 temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1), varargin(2), varargin(3)); msprintf("6 arguments"); elseif rhs == 7 temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1), varargin(2), varargin(3), varargin(4)); elseif rhs == 8 temp = raw_trainLRClassifier(imgSets_list, bag_list, classifierName, varargin(1), varargin(2), varargin(3), varargin(4), varargin(5)); end classifier = struct("ClassifierType", temp(1), "ClassifierLocation", temp(2), "BagofFeaturesLocation", temp(3), "Description", temp(4)) endfunction
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ex_1_21_1.sce
//Example 1.21.1: L and C clc; clear; close; //given data : V=100;// in volts Irm=40;// in A tq=40;// in micro-sec Del_t=(50/100)*tq;// in micro-sec C=(Irm*(tq+Del_t))/V; disp(C,"capacitance,C(micro-farad) = ") L_min=(V/Irm)^2*C; disp(L_min,"minimum inductance,L_min(micro-Henry) = ") T=2.5;// assume one cycle period in ms L_max=((0.01*(T*10^-3)^2)/(%pi^2*C*10^-6))*10^6; disp(L_max,"Maximum inductance,L_max(micro-Henry) = ")
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Example9_3.sce
//chapter-9,Example9_3,pg 502 N=64//data units //implimentation steps for DFT=64^2 //for FFT r=(log2(N)/N)//implimentation ratio printf("implimentation ratio\n") printf("r=%.4for(3/32)",r)
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clc clear printf("Example 12.2 | Page number 416 \n\n"); //Find the stoichiometric air for combustion of (a)Carbon (b)Hydrogen (c)Sulphur //Given data //Molar masses of O2,H2,N2,C and S respectively MO2 = 32 //g/mol MH2 = 2 //g/mol MN2 = 28 //g/mol MC = 12 //g/mol MS = 32 //g/mol //Part(a) printf("Part(a)\n") printf("Stoichiometric air(Carbon) = %.2f kg/kg carbon\n\n",(MO2 + 3.76*MN2)/MC) //Part(b) printf("Part(b)\n") printf("Stoichiometric air(Hydrogen) = %.2f kg/kg hydrogen\n\n",0.5*(MO2 + 3.76*MN2)/MH2) //Part(c) printf("Part(c)\n") printf("Stoichiometric air(Sulphur) = %.2f kg/kg sulphur\n",(MO2 + 3.76*MN2)/MS)
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example8_4.sce
clear; clc; //Example8.4[Pressure Drop in a Water tube] Tw=15;//temp of water while entering[degree Celcius] rho=999.1;//[kg/m^3] mu=1.138*10^(-3);//Viscosity[kg/m.s] id=0.05;//Internal diameter[m] V=5.5*10^(-3);//Flow rate[m^3/s] l=60;//length of tube[m] e=0.002*10^(-3);//[m] //Solution:- v=V/(%pi*(id^2)*(1/4));//Mean Velocity[m/s] Re=rho*v*id/mu; disp(Re,"Reynolds Number is") //Flow is turbulent r=e/id;//Relative roughness of the tube function[Func]=fric(fac) Func(1)=(1/(fac(1)^(1/2)))+(2*log((0.00004/3.7)+(2.51/(122900*fac(1)^(1/2))))); deff('[Func]=fric(fac)',['fric_1=(1/(fac(1)^(1/2)))+(2*log((0.00004/3.7)+(2.51/(122900*fac(1)^(1/2)))))']) endfunction xa = 3.99*10^-3; xs = fric(xa);) disp(xs,"Friction Factor is") del_P=xs*l*rho*(v^2)/(2*id);//[kPa] disp("Pa",del_P,"The pressure drop is") W_pump=V*del_P;//[W] disp("W",W_pump,"The required poer input tp overcome the frictional losses in the tube is")
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ex4_20.sce
// Example 4.20 page no-241 clear clc vdd=30 //v rl=4.7 //k-ohm vd=20 //v id=(vdd-vd)/rl printf("\nId = %.1f mA",id) printf("\nfor vd to be constant, it should be within ±1V") del_id=1/rl printf("\nDelta_Id = ± %.1f mA\nId(min) = %f mA\nId(max) = %f mA" ,del_id,id-del_id,id+del_id) delv=vdd-vd deli=2.5 //mA rs=delv/(deli) printf("\nRs = %d K-Ohm",rs)
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ex1_13.sce
// Example 1.13 page no-34 clear clc l=1.27 //cm D=19.4 //cm s=0.475 //cm Va=400 //volts Se=l*D*10^-2/(2*s*Va) Se=ceil(Se*10^5) printf("\nS_E=%.2f mm/v",Se/100) v=30 //volt e=1.6*10^-19 //C m=9.1*10^-31 //kg x=sqrt(m/e) B=(x*0.65*30*sqrt(2*Va))/(l*D) printf("\nB=%.2f*10^-5 wb/m^2",B*10^5)//answer not matches with given answer
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// Script question 5, fonction de remonté calculant la solution X du système trans(L)X = Z clc; function X = remonte(Ldiag, Linf, Z) indiceMax = size(Ldiag, "c") //Calcul des coefficients, X est un vecteur ligne for i=indiceMax:-1:1 if i==indiceMax then X(1,i)=Z(i)/Ldiag(i) else X(1,i)=(Z(i)-X(1,i+1)*Linf(i))/Ldiag(i) end end endfunction
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3_17.sce
clear; clc; Y1=500^-1; Y2=1000^-1; Z=100; A= 1+Y2 * Z; B=Z; C=Y1+Y2+(Y1*Y2*Z); D=1+Y1 * Z mprintf("A= %.1f ; B= %.1f ohm ; C=%.1f *1e-3seimens; D= %.1f", A, B, C*1e3, D);
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Ex1_7.sce
clc //initialization of new variables clear T=300 //K gama=1.4 R=286.6 //calculation // for air a=sqrt(gama*R*T) //result printf('The speed of sound in air is %.1f m/s ',a) // for sea water E=2.34*10^9 // N/m^2 rho=1000 //kg/cm^2 a=sqrt(E/rho) //result printf(' \n The speed of sound in sea waer is %d m/s ',a)
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//Example 2.8.3://ARITHEMATIC MEAN ,median value ,standard deviation clc; clear; format('v',6) q=[29.2,29.5,29.6,30.0,30.5,31.4,31.7,32.4,33.0,33.3,39.4,28.9];// AM= mean(q);//arithematic mean in mm for i= 1:12 qb(i)= q(i)-AM; end Q= [qb(1),qb(2),qb(3),qb(4),qb(5),qb(6),qb(7),qb(8),qb(9),qb(10),qb(11),qb(12)];// AV=(-qb(1)-qb(2)+qb(3)+qb(4)-qb(5))/12;// SD=stdev(Q);//standard deviation V=SD^2;//variance mv=q(5);// disp(AM,"arithematic mean is ") disp(mv,"median value is") disp((SD),"standard deviation is")
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Example2_3.sce
close(); clear; clc; R1 = 12; //ohm R2 = 4; //ohm R3 = 5; //ohm R4 = 5; //ohm R5 = 15; //ohm //voltage across R1 'V1' V1 = 132; //V I = V1/R1; R = R1 + R2 + (R4+R5)*R3/(R3+R4+R5); //source voltage 'V' V = I*R; mprintf("The voltage source, V = %d V",round(V));
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Ex9_20.sce
//Example 9_20 page no:380 clc; Zr=4+(%i*8); Zrmag=8.944; Zrang=63.4; Zy=3+(%i*4); Zymag=5; Zyang=53.1; Zb=15+(%i*20); Zbmag=25; Zbang=53.1; I2ang=136.58; //calculating Zry,Zyb,Zbr ZrZymag=(Zrmag*Zymag); ZrZyang=(Zrang+Zyang); ZrZyreal=(ZrZymag)*cosd(ZrZyang); ZrZyimg=(ZrZymag)*sind(ZrZyang); ZyZbmag=(Zymag*Zbmag); ZyZbang=(Zyang+Zbang); ZyZbreal=(ZyZbmag)*cosd(ZyZbang); ZyZbimg=(ZyZbmag)*sind(ZyZbang); ZbZrmag=(Zbmag*Zrmag); ZbZrang=(Zbang+Zrang); ZbZrreal=(ZbZrmag)*cosd(ZbZrang); ZbZrimg=(ZbZrmag)*sind(ZbZrang); Zrybreal=ZrZyreal+ZyZbreal+ZbZrreal; Zrybimg=ZrZyimg+ZyZbimg+ZbZrimg; Zrybmag=sqrt(Zrybreal^2+Zrybimg^2); Zrybang=atand(Zrybimg/Zrybreal); Zrymag=(Zrybmag)/Zbmag; Zryang=(Zrybang-Zbang); Zybmag=(Zrybmag)/Zrmag; Zybang=(Zrybang-Zrang); Zbrmag=(Zrybmag)/Zymag; Zbrang=(Zrybang-Zyang); //taking Vry as reference Vry=400<0; Vrymag=400; Vryang=0; Vybmag=400; Vybang=-120; Vbrmag=400; Vbrang=-240; //calculating the phase currents Irmag=Vrymag/Zrymag; Irang=Vryang-Zryang; Iymag=Vybmag/Zybmag; Iyang=Vybang-Zybang; Ibmag=Vbrmag/Zbrmag; Ibang=Vbrang-Zbrang; //calculating the line currents Irreal=Irmag*cosd(Irang); Irimg=Irmag*sind(Irang); Iyreal=Iymag*cosd(Iyang); Iyimg=Iymag*sind(Iyang); Ibreal=Ibmag*cosd(Ibang); Ibimg=Ibmag*sind(Ibang); I1real=Irreal-Ibreal; I1img=Irimg-Ibimg; I2real=Iyreal-Irreal; I2img=Iyimg-Irimg; I3real=Ibreal-Iyreal; I3img=Ibimg-Iyimg; I1mag=sqrt(I1real^2+I1img^2); I1ang=atand(I1img/I1real); I2mag=sqrt(I2real^2+I2img^2); I3mag=sqrt(I3real^2+I3img^2); I3ang=atand(I3img/I3real); disp(I1mag,"the magnitude of I1 current is (in A)"); disp(I1ang,"the angle of I1 current is (in degree)"); disp(I2mag,"the magnitude of I2 current is (in A)"); disp(I2ang,"the angle of I2 current is (in degree)"); disp(I3mag,"the magnitude of I3 current is (in A)"); disp(I3ang,"the angle of I3 current is (in degree)"); //calculating the voltage across each phase Vrmag=I1mag*Zrmag; Vrang=I1ang+Zrang; disp(Vrmag,"the magnitude of V across R phase is (in V)");//in text book the values are rounded off but here values stored in variables are not altered disp(Vrang,"the angle of V across R phase is (in V)"); Vymag=I2mag*Zymag; Vyang=I2ang+Zyang; disp(Vymag,"the magnitude of V across R phase is (in V)"); disp(Vyang,"the angle of V across R phase is (in V)"); Vbmag=I3mag*Zbmag; Vbang=I3ang+Zbang; disp(Vbmag,"the magnitude of V across R phase is (in V)");//in text book the values are rounded off but here values stored in variables are not altered disp(Vbang,"the angle of V across R phase is (in V)"); //in text book values of current and impedence are rounded off hence values vary slightly
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EXAMPLE8_6.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 7 //WAVEFORM CODING TECHNIQUES clear all; clc; printf("EXAMPLE 8.6(PAGENO 389)"); //given v = 7//bits of encoder r = 50*10^6//bit rate of the system //calculations f_m = r/(2*v)//maximum message bandwidth which is less than or equal to obtained value SbyN_dB = 1.8 + 6*v//signal to noise ratio in dB //results printf("\n\ni.Maximum message bandwidth = %.2f Hz",f_m); printf("\n\nii.Signal to noise ratio when modulating frquency is 1MHz applied = %.2f dB",SbyN_dB)
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clear clc //function y = funcao(x) // y=(x(1) - 2).^4 + (x(1)-2*x(2)).^2; //endfunction function grad_x = gradiente(x) n = length (x); h = 1e-5; gg = []; for i = 1 : n x_adv = x x_adv(i) = x(i) + h; dev = (f(x_adv)- f(x))/h; gg = [gg; dev]; end grad_x = gg; endfunction function linha = derivada1(x,yj,dj) h = 1e-5; linha = (func_teta(x + h,yj,dj)- func_teta(x - h,yj,dj))/ (2*h); endfunction function duas_linha = derivada2 (x,yj,dj) h = 1e-5; duas_linha = (func_teta(x + h,yj,dj) - (2*func_teta(x,yj,dj)) + func_teta(x - h,yj,dj))/h.^2; endfunction function valor_teta=func_teta(x,yj,dj) valor_teta=f(yj+x*dj); endfunction function lambda = newton (lambda,yj,dj) //lambda = 10; tolerance = 10^-3; erro = 10; while (erro > tolerance) lambda_novo = lambda - (derivada1(lambda,yj,dj)/derivada2(lambda,yj,dj)); erro = abs (lambda_novo - lambda); lambda = lambda_novo; end lambda = lambda_novo; endfunction function otimo = steepest_descent(xk) erro = 1; tol = 1e-4; while erro > tol dk = -gradiente (xk); lambdak = newton (0.1,xk,dk); xk_new = xk + lambdak*dk erro = norm (gradiente(xk_new) - gradiente(xk)); xk = xk_new; end otimo = xk endfunction
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//Example 9.5.a clc;clear;close; z=poly(0,'z'); s=poly(0,'s'); Hz=3*(2*z^2+5*z+4)/(2*z+1)/(z+2); H=pfss(Hz/z); for k=1:length(H) H(k)=clean(H(k)); H1(k)=z*horner(H(k),z); disp(H1(k),'System Function for parallel realisation Hk(z)='); end disp(Hz,'System Function H(z)=');
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//Exa 3.6 clc; clear; close; //Given data : Tr=0.2;//in us l=20;//in Km //part (a) B=1/(2*Tr*10^-6);//in Hz B=B/10^6;//in MHz disp(B,"Maximum possible assuming no intersymbol interference in MHz : "); //Part (b) Dispersion=Tr*10^-6/l;//in sec/Km disp(Dispersion*10^9,"Dispersion in ns/Km : "); //part (c) BDP=B*l;//in MHz-Km disp(BDP,"Band =width Distance product for the fibre in MHz-Km : ");
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-- CE3002C.TST -- Grant of Unlimited Rights -- -- Under contracts F33600-87-D-0337, F33600-84-D-0280, MDA903-79-C-0687, -- F08630-91-C-0015, and DCA100-97-D-0025, the U.S. Government obtained -- unlimited rights in the software and documentation contained herein. -- Unlimited rights are defined in DFAR 252.227-7013(a)(19). By making -- this public release, the Government intends to confer upon all -- recipients unlimited rights equal to those held by the Government. -- These rights include rights to use, duplicate, release or disclose the -- released technical data and computer software in whole or in part, in -- any manner and for any purpose whatsoever, and to have or permit others -- to do so. -- -- DISCLAIMER -- -- ALL MATERIALS OR INFORMATION HEREIN RELEASED, MADE AVAILABLE OR -- DISCLOSED ARE AS IS. THE GOVERNMENT MAKES NO EXPRESS OR IMPLIED -- WARRANTY AS TO ANY MATTER WHATSOEVER, INCLUDING THE CONDITIONS OF THE -- SOFTWARE, DOCUMENTATION OR OTHER INFORMATION RELEASED, MADE AVAILABLE -- OR DISCLOSED, OR THE OWNERSHIP, MERCHANTABILITY, OR FITNESS FOR A -- PARTICULAR PURPOSE OF SAID MATERIAL. --* -- OBJECTIVE: -- CHECK THAT FIELD IS A SUBTYPE OF INTEGER, FIELD'FIRST = 0, AND -- FIELD'LAST HAS A SPECIFIED IMPLEMENTATION-DEPENDENT VALUE. -- HISTORY: -- SPS 09/30/82 -- SPS 11/09/82 -- JBG 03/16/83 -- JLH 08/07/87 REVISED VALUES USED IN INTEGER AND FIELD TO THE -- INTEGER VALUE 1. WITH REPORT; USE REPORT; WITH TEXT_IO; USE TEXT_IO; PROCEDURE CE3002C IS BEGIN TEST ("CE3002C", "CHECK THAT FIELD IS A SUBTYPE OF INTEGER AND " & "FIELD'FIRST = 0"); DECLARE A : INTEGER; B : FIELD; BEGIN IF FIELD'FIRST /= IDENT_INT (0) THEN FAILED ("FIELD'FIRST NOT 0; IS" & FIELD'IMAGE(FIELD'FIRST)); END IF; IF FIELD'LAST /= $FIELD_LAST THEN FAILED ("FIELD'LAST NOT $FIELD_LAST; IS" & FIELD'IMAGE(FIELD'LAST)); END IF; A := IDENT_INT (1); B := A; B := IDENT_INT (1); A := B; END; RESULT; END CE3002C;
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//Chapter 2,Ex2.16,Pg2.24 clc; disp("Refer to the diagram shown in the figure") a=[15 -10 -5;0 1 -1;-15 12 6] b=[50;2;0] i=a\b printf("\n I1 = %.0f A\n",i(1)) printf("\n I2 = %.2f A\n",i(2)) printf("\ I3=%.2f A\n",i(3)) printf("\n Current through 5 ohms resistor = %.1f A\n",i(1)-i(3))
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// Example 4.11, Page No-213 clear clc fa=200 fmax=fa C1=0.1*10^-6 Rf=1/(2*%pi*fa*C1) Rf=Rf/1000 printf("Rf= %.3f kohm", Rf) fb=10*fa R1=1/(2*%pi*fb*C1) R1=R1/1000 printf("\nR1= %.3f kohm", R1) Cf=R1*C1/Rf Cf=Cf*10^6 printf("\nCf= %.2f uF", Cf)
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5_5.sce
clc,clear printf('Example 5.5\n\n') V_OC_line=230,I_asc=12.5 // when I_f=0.38 V_OC_ph=V_OC_line/sqrt(3) Z_s=V_OC_ph/I_asc R_a=1.8/2 //1.8 is between terminals..0.9 is per phase X_s=sqrt(Z_s^2-R_a^2) I_a=10// when regulation is needed V_L=230 V_ph=V_L/sqrt(3) //Part(i) phi1=acos(0.8) //and lagging E_ph1=sqrt((V_ph*cos(phi1)+I_a*R_a)^2+(V_ph*sin(phi1)+I_a*X_s)^2) regulation1=100*(E_ph1-V_ph)/V_ph printf('Regulation for 10 A at 0.8 lagging pf is %.2f percent\n',regulation1) //Part(ii) phi2=acos(0.8) //and leading E_ph2=sqrt((V_ph*cos(phi2)+I_a*R_a)^2+(V_ph*sin(phi2)-I_a*X_s)^2) regulation2=100*(E_ph2-V_ph)/V_ph printf('Regulation for 10 A at 0.8 leading pf is %.2f percent\n',regulation2)
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rf = 0.25; span = 4; sps = 3; h= rcosdesign(rf,span,sps,'normal'); h_expeceted=[-1.83515589323958e-17 -0.0839769617250925 -0.111533834697389 2.20296105783395e-17 0.241477835573582 0.492495595150919 0.599407402858453 0.492495595150919 0.241477835573582 2.20296105783395e-17 -0.111533834697389 -0.0839769617250925 -1.83515589323958e-17]; r=assert_checkalmostequal(h,h_expected); disp(r); //output //!--error 10000 //assert_checkalmostequal: Assertion failed: expected = [0.0307603 ...] while computed = [-2.287D-17 ...] //at line 22 of function assert_generror called by : //at line 103 of function assert_checkalmostequal called by : //r=assert_checkalmostequal(h,h_expected);
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//chapter-5,Example5_8,pg 493 Nx=64//2^6, 6 bit counteer register Vref=2.2//ref. voltage N=32//SAR output Vi=(N/(Nx+1)*Vref)//input voltage printf("input voltage\n") printf("Vi=%.2f V",Vi)
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//chapter-9 page 412 example 9.8 //============================================================================== clc; clear; //For a Gunn Diode L=20*10^(-4);//Active Length in cm Vd=2*10^7;//Drift Velocity of Electrons in cm/sec Ec=3.3*10^3;//Criticl Field for GaAs in V/cm //CALCULATION fn=(Vd/L)/10^9;//Natural(Rational) Frequency in GHz Vc=L*Ec;//Critical Voltage of the diode in volts //OUTPUT mprintf('\nNatural(Rational) Frequency is fn=%2.0f GHz \nCritical Voltage of the diode is Vc=%1.1f volts',fn,Vc); //=========================END OF PROGRAM===============================
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//Exa 7.7 clc; clear; close; // given : D_a=6 // Diameter of paraboloid reflector in m c=3*10^8 // speed of light in m/s f=4 // frequency in GHz f=4*10^9 // frequency in Hz lambda=c/f // wavelength in m r=2*D_a^2/lambda // required minimum distance between two antennae in m disp(r,"required minimum distance between two antennae in m:")
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clc m=5; //kg T1=550; //K p1=4*10^5; //Pa T2=290; //K T0=T2; p2=1*10^5; //Pa p0=p2; cp=1.005; //kJ/kg K cv=0.718; //kJ/kg K R=0.287; //kJ/kg K disp("(i) Availability of the system :") ds=cp*log(T1/T0) - R*log(p1/p0); Availability=m*[cv*(T1-T0) - T0*ds]; disp("Availability of the system =") disp(Availability) disp("kJ") disp("(ii) Available energy and Effectiveness") Q=m*cp*(T1-T0); dS=m*cp*log(T1/T0); E=T0*dS; //Unavailable energy AE=Q-E; disp("Available Energy = ") disp(AE) disp("kJ") disp("Effectiveness=") Effectiveness=AE/Availability; disp(Effectiveness)
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a=imread('milkeway.jpg'); b=double(a); [m,n]=size(b); for i=1:m for j=1:n c(i,j)=10*log(1+b(i,j)); end end imshow(c);
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timeMat = fscanfMat('Linear_Regression/TimeMatrix') numlines = length(timeMat(:,1)) for i = 1:numlines end
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//Example 9.34 clc disp("Resolution = V_0FS / 2^n - 1") disp("Therefore, 20 = V_0FS / 2^n - 1") disp("Therefore, V_0FS = 5.1 V") disp(" D = Equivalent of 10000000 = 128") disp("Therefore, V0 = Resolution * D = 20 * 128 = 2.56 V")
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style.fontSize=12; style.displayedLabel="<table> <tr> <td><b>In</b></td> <td>nmirror<br>w_bias</td></tr></table>"; pal5 = xcosPalAddBlock(pal5,"nmirror_w_bias",[],style);
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//Chapter 7: Solid State //Problem: 6 clc; //Declaration of Variables l = 2 * 10 ** - 10 //in m t = 30 //in degrees // Solution mprintf("For first-order reflection\n") d = l / (2 * sin(t)) dist = 2 * d mprintf(" Hence, distance between planes is : %.0e m ",abs(dist))
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// Scilab code Ex1.7: Pg:20 (2008) clc;clear; m = 9.1e-031; // Mass of an electron, kgm h = 6.6e-034; // Planck's constant, joule-sec c = 3e+08; // Velocity of light, m/s // Energy of one quantum of radiation is given by E = h*nu and // furhter, E = m*c^2 where nu = c/Lambda, the frequency of radiation // On compairing the energies and solving for Lambda Lambda = h/(m*c); // de Broglie wavelength of an electron, m printf("\nThe wavelength of quantum of radiant energy = %6.4f angstrom", Lambda/1e-010); // Result // The wavelength of quantum of radiant energy = 0.0242 angstrom
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ft=3.67; m=ft*0.3048; disp("the given length (in m) is"); disp(m);
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clc //initialization of the problems clear s=1.6 //m s1=4 //m pi=28 //degrees w=16 //kg/m^2 p=100 //kg/m^2 pl=20 //cm pb=10 //cm r=500 //kg/m^3 Zx=54.8 //cm^3 Zy=3.9 //cm^3 // calculations pi=pi*%pi/180 //radians W=w*s+8.1 P=p*s L=P+W*cos(pi) Mx=L*s1^2*100/8 sigma_1=Mx/Zx My=W*sin(pi)*s1^2*100/8 sigma_2=My/Zy sigma=sigma_1+sigma_2 // results printf('Maximum stresses are %d kg/cm^2, tension or compression',sigma)
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clear // Variable declaration T_ra=21// The temperature of the returning air H=50// % saturation T_d=28// The dry bulb temperature in °C T_w=20// The wet bulb temperature in °C m_a=20// The mass flow rate of returning air in kg/s m_b=3// The mass flow rate of outside air in kg/s x_ra=0.0079// The moisture content in kg/kg x_oa=0.0111// The moisture content in kg/kg h_a=41.8// The enthalpy in kJ/kg h_b=56.6// The enthalpy in kJ/kg // Calculation // Method (b) t_c=((T_ra*m_a)+(T_d*m_b))/(m_a+m_b)// °C g_c=((x_ra*m_a)+(x_oa*m_b))/(m_a+m_b)// kg/kg h_c=((h_a*m_a)+(h_a*m_b))/(m_a+m_b)// kJ/kg dry air printf("\n \nThe condition of the mixture,t_c=%2.1f°C",t_c) printf("\n \n g_c=%0.4f kg/kg",g_c) printf("\n \n h_c=%2.1f kJ/kg dry air",h_c)
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//chapter 3 // exmaple 3.6 //page 124 , figure 3.17 R1=1*10^3;R2=R1;R3=R1;//given Rf=1*10^3;//given Vin1=2;Vin2=1;Vin3=4;//given Vout=-((Rf/R1)*Vin1+(Rf/R2)*Vin2+(Rf/R3)*Vin3); disp(Vout)
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# Heat exchanger test units SI $thermo = VirtualMaterials.Peng-Robinson / -> $thermo thermo + PROPANE ISOBUTANE n-BUTANE n-PENTANE # lets have some streams for this test hotInlet = Stream.Stream_Material() coldInlet = Stream.Stream_Material() hotOutlet = Stream.Stream_Material() coldOutlet = Stream.Stream_Material() cd hotInlet.In Fraction = .25 .25 .25 .25 T = 375 K P = 500 MoleFlow = 800 cd /coldInlet.In Fraction Fraction = .95 0 .05 0 VapFrac = 0 P = 300 T MoleFlow = 1000 cd / exch = Heater.HeatExchanger() exch cd exch DeltaPC = 10 DeltaPH = 50 DeltaTHO = 5 K cd / coldInlet.Out -> exch.InC exch.OutC -> coldOutlet.In hotInlet.Out -> exch.InH exch.OutH.T exch.OutH -> hotOutlet.In # results coldInlet coldInlet.Out coldOutlet.Out hotInlet.Out hotOutlet.Out exch.ColdSide.InQ cd / copy /exch /hotInlet /coldInlet /hotOutlet /coldOutlet sub = Flowsheet.SubFlowsheet() paste /sub cd /sub coldInlet coldInlet.Out coldOutlet.Out hotInlet.Out hotOutlet.Out exch.ColdSide.InQ
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//Section-1,Example-3,Page no.-AC.205 //To calculate the percentage of excess air used for combustion. clc; C=0.54 H=0.065 O=0.03 N=0.018 M_W=(((32/12)*C)+((16/2)*H)-O)*(100/23)//Minimum weight of air required for combustion W_CO2=(C*(44/12)) W_N2=N+(M_W*(77/100)) T_W=(W_CO2+W_N2) //Total weight of dry products of combustion B_W=(21.5-T_W) //Balance weight P_EA=(B_W/M_W)*100 disp(P_EA,' percentage of excess air used for combustion')
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; @Harness: simulator ; @Format: atmel ; @Arch: avr ; @Purpose: "Test the ASR (arithmetic shift right) instruction" ; @Result: "r16 = 1, flags.c = 0, flags.s = 0" start: ldi r16, 0b10 asr r16 end: break
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// Example 2_15 clc;funcprot(0); //Given data w=[1 2 3 4 5 6 7 8 9 10 11 12];// Week b=[6000 4000 5400 2000 1500 1000 1200 4500 8000 4000 3000 2000];// Weekly flow in m^3/sec //Calculation for(i=1:12) c(i)=b(i)*7; end Cv(1)=c(1);// day-sec-metres Cv(2)=Cv(1)+c(2);// day-sec-metres Cv(3)=Cv(2)+c(3);// day-sec-metres Cv(4)=Cv(3)+c(4);// day-sec-metres Cv(5)=Cv(4)+c(5);// day-sec-metres Cv(6)=Cv(5)+c(6);// day-sec-metres Cv(7)=Cv(6)+c(7);// day-sec-metres Cv(8)=Cv(7)+c(8);// day-sec-metres Cv(9)=Cv(8)+c(9);// day-sec-metres Cv(10)=Cv(9)+c(10);// day-sec-metres Cv(11)=Cv(10)+c(11);// day-sec-metres Cv(12)=Cv(11)+c(12);// day-sec-metres w=[0 1 2 3 4 5 6 7 8 9 10 11 12];// Week for plot CV=[0 Cv(1) Cv(2) Cv(3) Cv(4) Cv(5) Cv(6) Cv(7) Cv(8) Cv(9) Cv(10) Cv(11) Cv(12)];// Cumulative volume in day-sec-metres for plot ylabel('Flow in thousands & day-sec-meter'); plot(w,CV/1000) // The total flow in the week,Q=7*day-sec-metres. // From fig.prob.2.15 C=42*10^3;// The capacity of the reservoir in day-sec-metre bc=5.7*20*10^3;// day-sec-metre ac=5.5;// day Q=bc/(ac*7);// Flow rate available in m^3/sec printf('\n The capacity of the reservoir=%0.1e day-sec-metre \nFlow rate available=%0.0f m^3/sec',C,Q); // The answer vary due to round off error
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//Chapter 3 : Systems of Linear Equations //Example 3.26 //Scilab 6.0.1 //Windows 10 clear; clc; A=[1 2 -1 -2; -1 -1 1 1; 0 1 2 1]; disp(A,'A=') I1=eye(4,4) I2=eye(3,3) A=[A I2] disp(I1) disp(A) A(2,:)=A(2,:)+A(1,:) disp(I1) disp(A) A(3,:)=A(3,:)-A(2,:) disp(I1) disp(A) A(3,:)=A(3,:)/2 disp(I1) disp(A) I1(1,:)=2*I1(1,:)-A(1,1:4) disp(I1) disp(A) A(1,1:4)=I1(1,:)+A(1,1:4) A(1,1:4)=A(1,1:4)/2 disp(I1) disp(A) I1(2,:)=I1(2,:)+I1(4,:) A(2,1:4)=A(2,1:4)+I1(2,:) A(2,1:4)=A(2,1:4)/2 I1(1,:)=I1(1,:)-2*I1(4,:) disp(I1) disp(A) I1(1,:)=I1(1,:)-I1(4,:) I1(3,:)=I1(3,:)-I1(4,:) A(3,1:4)=A(3,1:4)-I1(4,:) disp(I1) disp(A) N=[] N(1,:)=A(1,1:4) N(2,:)=A(2,1:4) N(3,:)=A(3,1:4) disp(N,'N=') P=[] P(1,:)=A(1,5:7) P(2,:)=A(2,5:7) P(3,:)=A(3,5:7) disp(P,'P=') disp(I1,'Q=')
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exec("degree_rad.sci",-1) //Given that gr_height = 3 //in m theta = dtor(53) g = -9.8 //in m/s^2 v0 = 26.5 //in m/s tower_height = 18 //in m //Sample Problem 4-8a printf("**Sample Problem 4-8a**\n") x = poly(0,'x') y = x * tan(theta) + g * x * x /(2* v0^2) * sec(theta)^2 y_tower1 = horner(y,23) if y_tower1<0 then printf("No, It does not clear the first Ferris wheel\n") else printf("Yes, It clears the first Ferris wheel\n") end //Sample Proble, 4-8b printf("\n**Sample Problem 4-8b**\n") y_max = horner(y,34.5) printf("The balls clearance above middle tower is %f m\n", y_max + gr_height - tower_height) //Sample Problem 4-8c printf("\n**Sample Problem 4-8c**\n") Range = -v0^2 * sin(2*theta)/g printf("The centre of the net should be placed at a diastance of %f m form the cannon", Range)
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// Exa 8.4 clc; clear; close; // Given data l=2.5;// in cm l=l*10^-2;// in meter d=1;// in cm d=d*10^-2;// in meter Va= 1000;// in volts theta= 1;// in degree // Formula tand(theta) = l*Vd/(2*d*Va) Vd= 2*d*Va/l*tand(theta);// in volts disp(Vd,"Voltage required across the deflection plates in volts")
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//[]=finit() // Initialisation de parametres relatif au probleme // de l'alunissage //k : acceleration de poussee de la fusee //gamma : acceleration de la pesanteur sur la lune //umax : debit maximum d'ejection des gaz //mcap : masse de la capsule //cpen : penalisation dans la fonction cout de l'etat final //! k=100 gamma=1 umax = 1 mcap = 10 cpen =100; [k,gamma,umax,mcap,cpen]=resume(k,gamma,umax,mcap,cpen) //end //[ukp1]=fuseegrad(niter,ukp1,pasg) //[ukp1]=fuseegrad(niter,ukp1,pasg) // niter : nombre d'iteration de gradient a faire a partir // de ukp1 solution initiale de taille 135 // pasg : le pas de gradient choisit // la valeur renvoyee est la derniere loi de commande obtenue. // l'optimum s'obtient avec ubang(135,50) // (optimum du pb non penalise) //! // fenetres graphiques xset("window",0);xclear(); xset("window",1); if xget("window")=0 , xinit('unix:0.0'),xset("window",1),end xclear(); xset("window",2); if xget("window")=0 , xinit('unix:0.0'),xset("window",2),end xclear(); // on s'arrete a tf=135 tf=135 [n1,n2]=size(ukp1) if n2 <>135, print(%io(2),"uk doit etre un vecteur (1,135)") return,end // Calculs de gradient et dessins for i=1:niter, [c,xk,pk,ukp1]=fcout(tf,ukp1,pasg), write(%io(2),c,'(''Cout : '',f20.2)'); write(%io(2),xk(3,135),'(''Masse de la fusee : '',f20.2)'); xset("window",0); tt=1:tf; plot2d(tt',xk(1,:)',[-1],"111","Trajectoire",[1,0,tf,5200]); xset("window",1); plot2d(tt',xk(3,:)',[-1],"111","Evolution de la masse",[1,10,tf,100]); xset("window",2); plot2d(tt',ukp1',[-1],"111","Commande",[1,-1,tf,2]); end //end //[c,xk,pk,ukp1]=fcout(tf,uk,pasg) //[c,xk,pk,ukp1]=fcout(tf,uk,pasg) // pour une loi de commande uk // Calcule la fonction cout que l'on cherche a minimiser // c = -m(tf) + C*( h(tf)**2 + v(tf)**2) // (on veut minimiser la consommation et atteindre la // cible h=0 avec une vitess nulle obtenue par penalisation) // la trajectoire associee // Calcule aussi une nouvelle loi de commande par une methode // de gradient //! [xk,pk]=equad(tf,uk); c= - xk(3,tf) +cpen*(xk(1,tf)**2 +xk(2,tf)**2); grad = k*pk(2,:)./xk(3,:) -pk(3,:); //gradient projete su [0,umax] ukp1=maxi(mini(uk- pasg*grad,umax*ones(1,tf)),0*ones(1,tf)); //end //[xdot]=fusee(t,x) //[xdot]=fusee(t,x) // dynamique de la fusee //! xd= x(2); if x(3)<= 10, md=0 yd= -gamma; ,else md= -pousse(t), yd= k*pousse(t)/x(3)-gamma; end; xdot=[xd;yd;md]; //end //[pdot]=fuseep(t,p) //[pdot]=fuseep(t,p) //equation adjointe //! xp=0 yp=-p(1); zp= p(2)*k*pousse(t)/(traj(t)**2); pdot=[xp;yp;zp] //end //[ut]=pousse(t) //[ut]=pousse(t) // la loi de commande u(t) constante par morceaux // construite sur la loi de comande discrete uk //! [n1,n2]=size(uk); ut=uk(mini(maxi(ent(t),1),n2)); //end //[uk]=ubang(tf,tcom) //[uk]=ubang(tf,tcom) // genere une loi bang-bang qui vaut 0 de 0 a tcom // et 1 de tcom a tf //! uk=0*ones(1,tf) uk(tcom:tf)=1*ones(1,tf-tcom+1); //end //[]=sfusee(tau,h0,v0,m0,Tf) //[]=sfusee(tau,h0,v0,m0,Tf) // // calcule la trajectoire de la fusee soumise a // une commande bang-bang // tau est la date de commutation // h0 : la hauteur initiale // v0 : la vitesse initiale ( negative si chute) // m0 : la masse initiale ( carburant + capsule) // Tf : l'horizon d'integration //! // Premiere phase : chute libre n=20; ind=1:n; t= ind*tau/n; m(ind)= m0*ones(1,n); v(ind)=-gamma*(t)+v0*ones(1,n); h(ind)= - gamma*(t.*t)/2 + v0*(t) + h0*ones(1,n); m = [ m0,m] v= [ v0,v] h= [h0,h] t= [ 0 t] // Deuxieme phase : frein plein gaz n1=40; ind=1:n1; ind1=0:(n1-1) t1= ind1*Tf/(n1-1) +tau* ((n1-1)*ones(1,n1)-ind1)/(n1-1); m1(ind)= ( m0+umax*tau)*ones(1,n1) -umax*(t1); mcapsul=mcap*ones(1,n1); m1=maxi(m1,mcapsul); v1(ind)= - gamma*(t1)+ v0*ones(1,n1) -k *log( m1(ind)/m0); h1(ind)= - gamma*(t1.*t1)/2 + v0*(t1) + (h0-k*tau)*ones(1,n1)... +(k/umax)*m1(ind).*log(m1(ind)/m0)+k*t1; m=[m,m1]; v=[v,v1]; h=[h,h1]; t=[t,t1]; // a revoir [m1,m2]=maxi(h,0*h); m2=2*ones(m2)-m2; [n1,n2]=size(m2); ialu=1; for i=1:n2,if m2(i)=0,ialu=[ialu,i],end,end ialu=ialu(2); write(%io(2),t(ialu),'('' Date alunissage'',f7.2)') write(%io(2),m(ialu),'('' Masse alunissage'',f7.2)') write(%io(2),v(ialu),'('' Vitesse alunissage'',f7.2)') xset("window",0) xclear(); // Dessin [q1,q2]=size(h) h1=0*ones(h); //h1(ialu:q2)=maxi(h)*ones(1,q2-ialu+1); // plot2d([t]',[h]',[-1;1],"111","distance par rapport au sol",... [0,0,tf,maxi(h)]) xset("window",1) if xget("window")=0 , xinit('unix:0.0'),xset("window",1),end xclear(); plot2d([t;t]',[v;0*v]',[-1;-1],"121",... "vitesse de la fusee (si + v ascent.)@0"); //recherche de la date d'arrivee au sol //end //[xk,pk]=equad(tf,uk) //[xk,pk]=equad(tf,uk) // pour une loi de commande u(t) stockee dans uk, calcule // la trajectoire xk associee et l'etat adjoint pk //! xk=ode([5220;-5;100],1,1:tf,0.01,0.01,fusee); deff('[y]=gg(t,x)','y=-fuseep('+string(tf)+'-t,x)'); // condition finales pour l'equation adjointe // en fait on minimise -m(tf)**2+... pk=ode([2*cpen*xk(1,tf);2*cpen*xk(2,tf);-xk(3,tf)],0.01,0.01:tf,... 1,1,gg); pk(1,:)=pk(1,tf:-1:1); pk(2,:)=pk(2,tf:-1:1); pk(3,:)=pk(3,tf:-1:1); //end //[xt]=traj(t) //[xt]=traj(t) // approximation constante par morceaux de l'evolution de la masse // construite sur xk : trajectoire discrete. //! xt=xk(3,maxi(ent(t),1)); // //end
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errcatch(-1,"stop");mode(2);//scilab 5.4.1 //Windows 7 operating system //chapter 23 Lasers,Fibre Optics,and Holography V=500//V=bandwidth of a He-Ne laser in Hz t=1/V//t=coherence time disp("ms",(t*(10^3)),"The coherence time is =") c=3*10^8//c=velocity of light in m/s Lc=c/V//Lc=longitudinal coherence length disp("km",(Lc/1000),"The longitudinal coherence length is=") exit();
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//water chemistry// //example 7.13// W1=160;//amount of Ca2+ in ppm// W2=88;//amount of Mg2+ in ppm// W3=72;//amount of CO2 in ppm// W4=488;//amount of (HCO3)- in ppm// W5=139;//amount of (FeSO4).7H2O in ppm// M1=100/40;//multiplication factor of Ca2+// M2=100/24;//multiplication factor of Mg2+// M3=100/44;//multiplication factor of CO2// M4=100/(61*2);//multiplication factor of (HCO3)-// M5=100/278;//multiplication factor of (FeSO4).7H2O// P1=W1*M1;//in terms of CaCO3// P2=W2*M2;//in terms of CaCO3// P3=W3*M3;//in terms of CaCO3// P4=W4*M4;//in terms of CaCO3// P5=W5*M5;//in terms of CaCO3// V=100000;//volume of water in litres// L=0.74*(P2+P3+P4+P5)*V;//lime required in mg// L=L/10^6; printf("Lime required is %fkg",L); S=1.06*(P1+P2+P5-P4)*V;//soda required in mg// S=S/10^6; printf("\nSoda required is %fkg",S);
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//Example 7.10 m=65;//Mass of player (kg) v_i=6;//Initial velocity (m/s) f=450;//Force of friction (N) theta=5;//Angle of incline (deg) d=(1/2*m*v_i^2)/(f+m*g*sind(theta));//Distance slid (m) printf('Distance slid = %0.2f m',d) //Openstax - College Physics //Download for free at http://cnx.org/content/col11406/latest
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close(); clear; clc; //line voltage 'Vl', resistance 'R', reactance 'X' Vl = 207.8; R = 36; X = 48; //inpedance Z = sqrt(R^2 + X^2); //(a)phase current 'Ip' Ip = Vl/Z; //A mprintf("Phase current, Ip = %0.2f A\n\n",Ip); //(b)line current 'Il' Il = sqrt(3)*Ip; //A mprintf("Line current, Il = %d A\n\n",round(Il)); //(c)power factor 'pf' pf = R/Z; mprintf("Power factor, pf = %0.1f lagging\n\n",pf); //(d)total power 'P' P = sqrt(3)*Vl*Il*pf; //W mprintf("Total power, P = %d W",round(P));
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//pathname=get_absolute_file_path('12.01.sce') //filename=pathname+filesep()+'12.01-data.sci' //exec(filename) //Pressure at which steam is supplied(in MPa): p1=0.2 //Temperature of steam(in C): T=250 //Pressure upto which steam is expanded(in bar): p2=0.3 //Pressure at which it is finally released(in bar): p3=0.05 //From steam tables: h1=2971 //kJ/kg s1=7.7086 //kJ/kg.K s2=s1 h2=2601.97 //kJ/kg v2=5.1767 //m^3/kg hf=137.82 //kJ/kg Tmax=393.23 //K Tmin=305.88 //K //Work output from engine cycle per kg of steam(in kJ/kg): W=h1-h2+v2*(p2-p3)*10^2 //Heat input per kg of steam(in kJ/kg): Q=h1-hf //Efficiency of modified Rankine cycle: n=W/Q*100 //Carnot efficiency: nc=(1-Tmin/Tmax)*100 printf("\n RESULT \n") printf("\nModified Rankine cycle efficiency = %f percent",n) printf("\nCarnot efficiency = %f percent",nc)
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clc disp("Example 5.45") printf("\n") disp("calculate the value of R & c for RC phase shift oscillator") printf("Given\n") //oscillating frequency f=2000 //select Capacitor value C=0.1*10^-6 //resistance value R=1/(2*%pi*f*C*sqrt(6)) printf("Resistance value \n%f ohm\n",R)
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//CAPTION: Conductivity_of_an_n-Type_GaAs_Gunn_Diode //chapter_no.-7, page_no.-294 //Example_no.7-2-1 clc; //Calculate_the_conductivity_of_the_diode e=1.6*(10^-19); nl=(10^10)*(10^6);//electron_density_at_lower_valley nu=(10^8)*(10^6);//electron_density_at_upper_valley ul=8000*(10^-4);//electron_mobility_at_lower_valley uu=180*(10^-4);//electron_mobility_at_upper_valley o=e*((nl*ul)+(nu*uu)); o=o*1000; disp(o,'the_conductivity_of_the_diode(in mmhos)is =');
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localdir="./*.wav" listoffiles = listfiles(localdir) //disp(listoffiles(:)) [numfiles, y] = size(listoffiles) //disp(numfiles) //disp(y) listoffiles = ["_Inambari-Tambopata__Antwren_0.wav" "Papa-formiga-barrado_7.wav"] data = read(listoffiles(1,1) + ".dat", -1,240000) listoffiles = ["_Inambari-Tambopata__Antwren_0.wav" "Papa-formiga-barrado_7.wav"] for i = 1:2 filename = listoffiles(1,i) disp(filename) [x,y] = loadwave(filename) [linhas, colunas] = size(x) // disp(x) disp(y) disp(linhas) disp(colunas) end disp ("Fim...")
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//Section-6,Example-1,Page no.-P.40 //To find by how much is the chemical potential of benzene reduced for the given conditions. clc; x_B=0.10 x_A=1.0-0.10 R=8.314 T=298 mu=R*T*log(x_A) //mu=mu_A-mu_Abar disp(mu,'Required chemical potential(Jmol^-1)')
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// Example 11.4 // Computation of resistance using linear approximation and values are // compared with results obtained in example 11.1 // Page No. 456 clc; clear; close; // Given data HP=40; // hp rating of the device %ratedload=0.902; // Percentage rated load VT=240; // Voltage value of motor RF=99.5; // Resistance of shunt motor Nf=1231; // Turns per pole of the shunt motor Ra=0.0680; // Armature resistance RIP=0.0198; // Interpole winding resistance Rs=0.00911; // Resistance of series field winding Bp1=0.70; // Flux density for a net mmf n1=1150; // Speed of shunt motor n2=1.25*n1; IT=137.84; // Computation of resistance using linear approximation and values are // compared with results obtained in example 11.1 IF=VT/RF; // Field current Ia1=IT-IF; // Armature current Fnet1=Nf*IF; // Net mmf Racir=Ra+RIP+Rs; // Armature circuit resistance Fnet2=Fnet1*(n1/n2)*((VT-Ia1*Racir*1.15)/(VT-Ia1*Racir)); IF1=Fnet2/Nf; // Field current Rx=(VT/IF1)-RF; // External resistance required // Display result on command window printf("\n The resistance rating of an external resistance = %0.2f Ohm ",Rx);
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errcatch(-1,"stop");mode(2);//Caption:Find the speed of machine //Exa:2.22 ; ; V=250;//in volts P_i=50*10^3;//in watts I_L1=P_i/V;//in amperes R_a=0.02;//in ohms R_f=50;//in ohms I_f=V/R_f;//in amperes I_a1=I_L1+I_f;//in amperes I_L2=P_i/V;//in amperes I_a2=I_L2-I_f;//in amperes N_1=400;//in rpm E_2=V-(I_a2*R_a)-(2*1);//in volts E_1=V+(I_a1*R_a)+(2*1);//in volts N_2=int(N_1*(E_2/E_1));//in rpm disp(N_2,'speed of motor (in rpm)=') exit();
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//Exa 2.48 clc; clear; close; format('v',7); //Given Data : V1=1.5;//m^3 V2=0;//m^3 p=1.02;//bar W=p*10^5*integrate('1','V',V1,V2);//J disp(W/1000,"Work done by the air in KJ : ");
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// Scilab Code Ex7.14: Page-382 (2008) clc; clear; e = 1.6e-019; // The energy equivalent of 1 eV, J c = 3e+008; // Speed of light in vacuum, m/s n = 1; // Order of diffraction d = 2.82e-010; // Interplanar spacing, m V = 9.1e+003; // Operating voltage of X rays theta = 14; // Bragg's angle, degree lambda = 2*d*sind(theta)/n; // Wavelength of X rays, m nu = c/lambda; // Frequency of X rays, Hz h = e*V/nu; // Planck's constant, Js printf("\nThe value of Planck constant, h = %4.2e Js", h); // Result // The value of Planck constant, h = 6.62e-034 Js
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clc,clear printf('Example 7.13\n\n') CE_Ag=107.98; CE_Al=27/3; //chemical equivalents //Electrochemical equivalents ECE_Ag=0.00111*10^-3 //in kg/C ECE_Al=ECE_Ag * (CE_Al/CE_Ag) current_efficiency=92/100 I=3000 //average current in A t=24*3600 //duration of flow of current in seconds m_al=ECE_Al*I*t*current_efficiency printf('Mass of aluminium produced = %.3f kg',m_al)
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//*************** HH neuron b debug ********************** if (blk_name.entries(bl) =='hh_neuron_b_debug') then mputl("# HH neuron b debug",fd_w); hh_neuron_b_debug_str= ".subckt hh_neuron_b_debug" for ss=1:scs_m.objs(bl).model.ipar(1) hh_neuron_b_debug_str=hh_neuron_b_debug_str+" in[0]=net"+string(blk(blk_objs(bl),2))+"_"+string(ss)+" in[1]=net"+string(blk(blk_objs(bl),3))+"_1"+" in[2]=net"+string(blk(blk_objs(bl),4))+"_1"+" in[3]=net"+string(blk(blk_objs(bl),5))+"_1"+" out[0]=net"+string(blk(blk_objs(bl),2+numofip))+"_"+string(ss)+" out[1]=net"+string(blk(blk_objs(bl),3+numofip))+"_1"+" out[2]=net"+string(blk(blk_objs(bl),4+numofip))+"_1"+" #hh_neuron_b_local[0] =0&hh_neuron_b_bias_1[0] ="+string(sprintf('%1.2e',scs_m.objs(bl).model.rpar(1)))+"&hh_neuron_b_bias_2[0] ="+string(sprintf('%1.2e',scs_m.objs(bl).model.rpar(2)))+"&hh_neuron_b_bias_3[0] ="+string(sprintf('%1.2e',scs_m.objs(bl).model.rpar(3)))+"&hh_neuron_b_bias_4[0] =2.0e-06"; end mputl(hh_neuron_b_debug_str,fd_w); mputl(" ",fd_w); if scs_m.objs(bl).model.ipar(2) == 1 then plcvpr = %t; plcloc=[plcloc;'net'+string(blk(blk_objs(bl),2+numofip))+'_1',' '+string(scs_m.objs(bl).model.ipar(3))+' '+string(scs_m.objs(bl).model.ipar(4))+' 0']; end string(sprintf('%1.2e',scs_m.objs(blk_objs(bl)).model.rpar(ss*3))) end
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//ques41 clc disp('tanu=dQ/dr*r'); syms Q a; r=2*a/(1-cos(Q)); u=atan(r/diff(r2,Q,1)); u=eval(u); p=r*sin(u); syms r; Q=acos(1-2*a/r); //cos(Q)=1-2*a/r; p=eval(p); disp(p);
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART III : SWITCHGEAR AND PROTECTION // CHAPTER 1: SYMMETRICAL SHORT CIRCUIT CAPACITY CALCULATIONS // EXAMPLE : 1.1 : // Page number 466-467 clear ; clc ; close ; // Clear the work space and console // Given data V = 500.0 // Generator voltage(V) rating = 10.0 // Rating of the generator(kVA) n_up = 1.0/2 // Turns ratio of step-up transformer Z_line = complex(1.0,2.0) // Transmission line impedance(ohm) n_down = 10.0/1 // Turns ratio of step-down transformer load = complex(2.0,4.0) // Load(ohm) // Calculations V_base_gen = V // Base voltage(V) kVA_base_gen = rating // Base rating(kVA) I_base_gen = kVA_base_gen*1000/V_base_gen // Base current(A) Z_base_gen = V_base_gen/I_base_gen // Base impedance(ohm) V_base_line = V_base_gen/n_up // Voltage base of the transmission line(V) kVA_base_line = rating // Base rating of transmission line(kVA) I_base_line = kVA_base_line*1000/V_base_line // Base current of transmission line(A) Z_base_line = V_base_line/I_base_line // Base impedance of transmission line(ohm) Z_line_1 = Z_line/Z_base_line // Impedance of transmission line(p.u) V_base_load = V_base_line/n_down // Base voltage at the load(V) kVA_base_load = rating // Base rating of load(kVA) I_base_load = kVA_base_load*1000/V_base_load // Base current of load(A) Z_base_load = V_base_load/I_base_load // Base impedance of load(ohm) Z_load = load/Z_base_load // Load impedance(p.u) Z_total = Z_line_1+Z_load // Total impedance(p.u) I = 1.0/Z_total // Current(p.u) // Results disp("PART III - EXAMPLE : 1.1 : SOLUTION :-") printf("\nCurrent, I = %.3f∠%.2f° p.u", abs(I),phasemag(I))
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<!DOCTYPE html> <html> <head> <meta charset="utf-8"/> <title>JavaScript File Encryption App</title> <meta name="viewport" content="width=device-width, initial-scale=1" /> <link href="http://fonts.googleapis.com/css?family=Raleway:400,700" rel="stylesheet" /> <link href="assets/css/style.css" rel="stylesheet" /> </head> <body> <a class="back"></a> <div id="stage"> <div id="step1"> <div class="content"> <a class="button encrypt green">Encrypt a file</a> <a class="button decrypt magenta">Decrypt a file</a> </div> </div> <div id="step2"> <div class="content if-encrypt"> <h1>Choose which file to encrypt</h1> <a class="button browse blue">Browse</a> <input type="file" id="encrypt-input" /> </div> <div class="content if-decrypt"> <h1>Choose which file to decrypt</h1> <a class="button browse blue">Browse</a> <input type="file" id="decrypt-input" /> </div> </div> <div id="step3"> <div class="content if-encrypt"> <h1>Enter a pass phrase</h1> <input type="password" /> <a class="button process red">Encrypt!</a> </div> <div class="content if-decrypt"> <h1>Enter the pass phrase</h1> <input type="password" /> <a class="button process red">Decrypt!</a> </div> </div> <div id="step4"> <div class="content"> <h1>Your file is ready!</h1> <a class="button download green">Download</a> </div> </div> </div> </body> <!-- Include the AES algorithm of the crypto library --> <script src="https://rawgithub.com/bitwiseshiftleft/sjcl/master/sjcl.js"></script> <script src="http://cdnjs.cloudflare.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script> <script src="assets/js/script.js"></script> </html>
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Example9_28.sce
//Chapter-9,Example9_28,pg 9_82 Po=20*735.5//(in W) V=230 N=1150 P=4 A=P Z=882 Ia=73 Ish=1.6 T=60*Po/(2*%pi*N) phi=T*A/(0.159*Ia*P*Z)//flux per pole Il=Ia+Ish Pin=V*Il n=Po*100/Pin printf("electromagnetic torque\n") printf("T=%.3f Nm\n",T) printf("flux per pole\n") printf("phi=%.3f Wb\n",phi) printf("efficiency of motor\n") printf("n=%.3f",n)
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Exercise 22a.sce
//============================================= // Exercise 22: Exchange flow through a strait //============================================= // Animation of surface and bottom distributions of Eulerian concentrations & flow fields // Author: Jochen Kaempf, March 2015 (update) f = gcf(); f.color_map = jetcolormap(64); f.figure_size = [600,600]; scf(0); // manipulate color map to make the extreme red a bit lighter map = jetcolormap(64); ic = 57; for i = ic+1:64; map(i,1:3) = map(ic,1:3); end; f.color_map = map; // read input data C1=read("cS.dat",-1,100); u1=read("uS.dat",-1,100); v1=read("vS.dat",-1,100); C2=read("cB.dat",-1,100); u2=read("uB.dat",-1,100); v2=read("vB.dat",-1,100); [ntot nx] = size(C1); x = (1:2:199)'; y = (1:2:99)'; ntot = int(ntot/50); for n = 1:ntot // animation loop time = (n-1)*6; // time in hours nn = n-1; // grab data blocks itop = (n-1)*50+1; ibot = itop+49; cS = C1(itop:ibot,1:100)'; uS = u1(itop:ibot,1:100); vS = v1(itop:ibot,1:100); cB = C2(itop:ibot,1:100)'; uB = u2(itop:ibot,1:100); vB = v2(itop:ibot,1:100); // subplot 1: surface distribution // interpolate velocity components onto scalar grid point um = uS; vm = vS; for j = 1:50; for k = 2:100; um(j,k) = 0.5*(uS(j,k)+uS(j,k-1)); end; end; for j = 1:50; um(j,1) = um(j,2); end; for j = 2:50; for k = 1:100; vm(j,k) = 0.5*(vS(j,k)+vS(j-1,k)); end; end; for k = 1:100; vm(1,k) = vm(2,k);end; // elimination of grid points of too low speeds for j = 1:50; for k = 1:100; speed(j,k) = sqrt(um(j,k)*um(j,k)+vm(j,k)*vm(j,k)); if speed(j,k) < 0.01; um(j,k) = 0.0; vm(j,k) = 0.0; end; end; end; ua = um(1:2:50,1:2:100); va = vm(1:2:50,1:2:100); drawlater; clf(); subplot(211); // 2d color plot of surface concentration field Sgrayplot(x,y,1-cS,,zminmax=[0,1]); // overlay contour plot xset("fpf"," "); col(1:11) = 80; contour2d(x,y,cS,11,col); //overlay flow arrows champ(x(1:2:100),y(1:2:50),ua',va',1); // specify graph & axis properties a = gca(); a.font_size = 3; a.data_bounds = [0,0;200,100]; a.auto_ticks = ["off","off","on"]; a.sub_ticks = [1,1]; a.x_ticks = tlist(["ticks", "locations","labels"],.. [0 40 80 120 160 200], ["0" "40" "80" "120" "160" "200"]); a.y_ticks = tlist(["ticks", "locations","labels"],.. [0 20 40 60 80 100], ["0" "20" "40" "60" "80" "100"]); xset("color",-1) xfrect(80,30,40,29); xfrect(80,100,40,30); xset("color",-1); xstring(83, 90,"SURFACE"); txt=gce(); txt.font_size = 3; txt.font_foreground = -1; title("Time = "+string(0.01*int(100*time/24))+" days","fontsize",3,'position',[100 100]); // add title xstring(90,2,"x (m)"); // add x label txt=gce(); txt.font_size = 3; txt.font_foreground = -1; xstring(2,47,"y (cm)"); // add z label txt=gce(); txt.font_size = 3; txt.font_foreground = -2; // subplot 2: bottom distribution // interpolate velocity components onto scalar grid point um = uB; vm = vB; for j = 1:50; for k = 2:100; um(j,k) = 0.5*(uB(j,k)+uB(j,k-1)); end; end; for j = 1:50; um(j,1) = um(j,2); end; for j = 2:50; for k = 1:100; vm(j,k) = 0.5*(vB(j,k)+vB(j-1,k)); end; end; for k = 1:100; vm(1,k) = vm(2,k);end; // elimination of grid points of too low speeds for j = 1:50; for k = 1:100; speed(j,k) = sqrt(um(j,k)*um(j,k)+vm(j,k)*vm(j,k)); if speed(j,k) < 0.01; um(j,k) = 0.0; vm(j,k) = 0.0; end; end; end; ua = um(1:2:50,1:2:100); va = um(1:2:50,1:2:100); subplot(212); // 2d color plot of bottom concentration field Sgrayplot(x,y,1-cB,,zminmax=[0,1]); // overlay contour plot xset("fpf"," "); col(1:11) = 80; contour2d(x,y,cB,11,col); //overlay flow arrows champ(x(1:2:100),y(1:2:50),ua',va',1); // specify graph & axis properties a = gca(); a.font_size = 3; a.data_bounds = [0,0;200,100]; a.auto_ticks = ["off","off","on"]; a.sub_ticks = [1,1]; a.x_ticks = tlist(["ticks", "locations","labels"],.. [0 40 80 120 160 200], ["0" "40" "80" "120" "160" "200"]); a.y_ticks = tlist(["ticks", "locations","labels"],.. [0 20 40 60 80 100], ["0" "20" "40" "60" "80" "100"]); xset("color",-1) xfrect(80,30,40,29); xfrect(80,100,40,30); xset("color",-1); xstring(83, 90,"BOTTOM"); txt=gce(); txt.font_size = 3; txt.font_foreground = -1; title("Time = "+string(0.01*int(100*time/24))+" days","fontsize",3,'position',[100 100]); // add title xstring(90,2,"x (m)"); // add x label txt=gce(); txt.font_size = 3; txt.font_foreground = -1; xstring(2,47,"y (cm)"); // add z label txt=gce(); txt.font_size = 3; txt.font_foreground = -2; drawnow; // save frames as sequential GIF files (optional) //if nn < 10 then // xs2gif(0,'ex100'+string(nn)+'.gif') //else // if nn < 100 then // xs2gif(0,'ex10'+string(nn)+'.gif') //else // xs2gif(0,'ex1'+string(nn)+'.gif') // end //end end // end reference for animation loop
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Ex4_18.sce
clear //In this problem, it is required to find out the moment of inertia of the section about an axis AB. So there is no need to find out the position of the centroid. //The given section is split up into simple rectangles //Moment of inertia about AB = Sum of moments of inertia of the rectangle about AB //variable declaration A1=400*20.0 A2=100*10 A3=10*380.0 A4=100*10.0 IAB=(400.0*(20**3)/12)+(A1*(10**2))+((100*(10**3)/12)+(A2*(25**2)))*2+((10*(380**3)/12)+(A3*(220**2)))*2+((100*(10**3)/12)+(A4*(415**2)))*2 printf("\n IAB= %0.0f mm^4",IAB)
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/Scilab/SpuleLadekurve.sce
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SpuleLadekurve.sce
U = 5 R = 2 L = 50 * 10^(-3) tau = L/R t = [0:tau/10:10*tau] yu = U + (t*0.001) yul = U * (%e^(-(t/tau))) yi = (U/R) * (1 - %e^(-(t/tau))) xset("thickness",3) plot2d(t,yu, style=3); plot2d(t,yul, style=2); plot2d(t,yi, style=5); ylabel("U, Ul, Il", "fontsize", 6); xlabel("t/s", "fontsize", 6) //xtitle('Kondensator Ladekurve','t/s','Uc, Ic',"fontsize". 5) legends(['Il in A','U in V','Ul in V'],[5 3 2],4, font_size=5) xgrid(1, 1, 1)
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d78e219ed4a41604a772b97289d20254865863fd
458def2f7b4bd44cdf75f29a4c0cabed2e6ca516
/GradesSDL.sce
0e1b66b53a193a111b28e8f92ad0cd83f12d5b4a
[]
no_license
SoanKim/Presentation_Software
1a03bfc9e22bd2a874c5787ca89faa0947c09e67
382c84878496fce1e790386a4ff6c03741eb4974
refs/heads/master
2022-12-09T03:50:22.916992
2020-09-10T10:55:45
2020-09-10T10:55:45
294,382,441
0
0
null
null
null
null
UTF-8
Scilab
false
false
159
sce
GradesSDL.sce
#SDL: scenario = "Grades"; pcl_file = "GradesPCL.pcl"; begin; picture { text { caption = "grades on screen";} t_Grades; x= 0; y = 0; }p_Grades;
7e461701eb190bbe67f5d41b1e44476dfed54502
d24d7ba8468707f00bf7adaaf2eb6f9cf024419b
/projects/05/stof.tst
613ee83b0b66f581be40f92fe63ecfb5cfcdf115
[]
no_license
linbug/nand2tetris
f22b01e400234e726131260e7fe9ccc4a7b6686d
0156e5eb1144b37173223e9d000cf3f94178216c
refs/heads/master
2021-01-19T00:17:27.599132
2017-04-02T21:03:32
2017-04-02T21:03:32
72,981,675
0
0
null
null
null
null
UTF-8
Scilab
false
false
178
tst
stof.tst
load stof.hdl, output-file stof.out, compare-to stof.cmp, output-list in%B1.16.1 out%B1.15.1; set in %B1110000000000001, eval, output; set in %B0000000000000001, eval, output;
7665a3daf9f314350e69cc9cdbbc7a98c9adab6b
089894a36ef33cb3d0f697541716c9b6cd8dcc43
/NLP_Project/test/tweet/bow/bow.20_19.tst
9d5661b3c4358216059609b6788d24dbefb5aefb
[]
no_license
mandar15/NLP_Project
3142cda82d49ba0ea30b580c46bdd0e0348fe3ec
1dcb70a199a0f7ab8c72825bfd5b8146e75b7ec2
refs/heads/master
2020-05-20T13:36:05.842840
2013-07-31T06:53:59
2013-07-31T06:53:59
6,534,406
0
1
null
null
null
null
UTF-8
Scilab
false
false
25,896
tst
bow.20_19.tst
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/Functions.sce
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neighborBoy0/ProjetFinDeEtude
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2023-04-10T14:56:39.636998
2021-04-12T19:05:53
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Scilab
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sce
Functions.sce
m = mode(); mode(-1); // the position error between the current and final positions for the end effector // // CPosition: Cartesian coordinates of the current position. // FPosition: Cartesian coordinates of the end point. function result = F1(CPosition, FPosition) try positions = [CPosition; FPosition]; result = nan_pdist(positions, 'euclidean'); // calcule euclidean distance between CPosition and FPosition catch [error_message,error_number]=lasterror(%t) disp("There is an error in function F1, error message:" + error_message); end endfunction // The purpose of this term is to keep the control points (the center of the joints in this case) away from the various obstacles // // M is the number of obstacles // N is the total number of control points // obstacle is the position of obstacles function result = F2(M, N, obstacle) try f2 = 0 // calcule sum of the euclidean distance between each joint and each obstacles for i=1:N for j=1:M positions = [robot.links(i).r; obstacle(j, :)]; // Suppose there is only one obstacle at 0.5, 0.5, 0.5 f2 = f2 + nan_pdist(positions, 'euclidean'); end end result = f2; catch [error_message,error_number]=lasterror(%t) disp("There is an error in function F2, error message:" + error_message); end endfunction // The purpose of this term is to maximize the manipulability of the robot // // Q: Each joint angle. function result = F3(Q) // Q = [] // loop = size(robot.links); // the number of joints // for i=1:loop // T = r2t(robot.links(6).I); // Qtemp = tr2q(T1) // Q = [Q, Qtemp(2)] // end J = jacob0(robot, Q, 'rot') // it was jacobn result = sqrt(det(J * J')); endfunction // To minimize the variation of joint variables, in order to obtain small movements // // Q: Each joint angle. // N: The number of joints // joints_origin: The angle of each joint in the previous position. function result = F4(Q, N, joints_origin) temp = 0; for i=1:N temp=temp+(Q(i) - joints_origin(i))^2; end result = temp / 2; endfunction
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/1955/CH4/EX4.13/example13.sce
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clc clear //input data b2=10//Rotor blade air angle at exit in degree Dt=0.6//The tip diameter in m Dh=0.3//The hub diameter in m N=960//The speed of the fan in rpm P=1//Power required by the fan in kW pi=0.245//The flow coefficient P1=1.02//The inlet pressure in bar T1=316//The inlet temperature in K R=287//The universal gas constant in J/kg.K Cp=1.005//The specific heat of air at constant pressure in kJ/kg.K r=1.4//The ratio of specific heats of air g=9.81//Acceleration due to gravity in m/s^2 //calculations A=(3.141/4)*((Dt^2)-(Dh^2))//Area of the fan at inlet in m^2 Dm=(Dt+Dh)/2//The mean rotor diameter in m U=(3.141*Dm*N)/60//The mean blade speed in m/s Ca=pi*U//The axial velocity in m/s Q=A*Ca//The flow rate of air in m^3/s d=(P1*10^5)/(R*T1)//Density of air in kg/m^3 dPst=((d*(U^2)*(1-((pi*tand(b2))^2)))/2)*((10^5)/(g*(10^3)))*10^-5//Static pressure across the stage in m W.G Wm=U*(U-(Ca*tand(b2)))//Work done per unit mass in J/kg m=d*Q//Mass flow rate in kg/s W=m*Wm//Work done in W no=W/(P*10^3)//Overall efficiency //output printf('(a)THe flow rate is %3.3f m^3/s\n(b)Static pressure rise across the stage is %3.3f m W.G\n(c)The overall efficiency is %3.4f',Q,dPst,no)
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Example_11_14.sci
clear; clc; xdo = 0.98; //per cent of ortho top product xwo = 0.125; //per cent of ortho bottom product function[f]=product(x) f(1) = 100 - x(1) - x(2); //x(1) is D and x(2) is W f(2) = 60 - x(1)*xdo - x(2)*xwo; funcprot(0); endfunction x = [0,0]; y = fsolve(x,product) printf("\n D = %.2f kmol & W = %.2f kmol",y(1),y(2)); printf("\n Let us assume that the distillate contains 0.6 mole per cent meta and 1.4 mole per cent para"); printf("\n Component Feed Distillate Bottoms "); printf("\n (kmol) (mole per cent) (kmol) (mole per cent) (kmol) (mole per cent) "); printf("\n Ortho %.3f %.2f %.2f %.2f %.2f %.2f ",60,60,y(1)*0.98,98,y(2)*0.125,12.5); printf("\n Meta %.3f %.2f %.2f %.2f %.2f %.2f ",4,4,y(1)*0.006,0.6,y(2)*0.083,8.3); printf("\n Para %.3f %.2f %.2f %.2f %.2f %.2f ",36,36,y(1)*0.014,1.4,y(2)*0.792,79.2); ao = 1.7; //relative volatility of ortho relative to para am = 1.16; //relative volatility of meta relative to para ap =1; //relative volatility of para w.r.t. to itself xso = 0.125; xsm = 0.083; xsp = 0.792; xwo = 0.125; xwp = 0.083; xwm = 0.792; yso = ao*xso/(ao*xso+ap*xsp+am*xsm); ysm = am*xsm/(ao*xso+ap*xsp+am*xsm); ysp = ap*xsp/(ao*xso+ap*xsp+am*xsm); //Equations of operating lines //Above the feed point Ln = 5*y(1); //Liquid downflow Vn = 6*y(1); //Vapour up //Assuming the feed is liquid at its boiling point F = 100; //feed Lm = Ln+F; //liquid downflow Vm = Lm-y(2); //Vapour up x1o = poly([0],'x1o'); x11 = roots(yso - (Lm/Vm)*x1o + (y(2)/Vm)*xwo); x1p = poly([0],'x1p'); x12 = roots(ysp - (Lm/Vm)*x1p + (y(2)/Vm)*xwp); x1m = poly([0],'x1m'); x13 = roots(ysm - (Lm/Vm)*x1m + (y(2)/Vm)*xwm); x1 = [x11 x13 x12]; ax1 = [ao*x11 am*x13 ap*x12]; y1 = [ax1(1)/(ax1(1)+ax1(2)+ax1(3)) ax1(2)/(ax1(1)+ax1(2)+ax1(3)) ax1(3)/(ax1(1)+ax1(2)+ax1(3))]; x2o = poly([0],'x2o'); x21 = roots(y1(1) - (Lm/Vm)*x2o + (y(2)/Vm)*xwo); x2p = poly([0],'x2p'); x22 = roots(y1(3) - (Lm/Vm)*x2p + (y(2)/Vm)*xwp); x2m = poly([0],'x2m'); x23 = roots(y1(2) - (Lm/Vm)*x2m + (y(2)/Vm)*xwm); x2 = [x21 x23 x22]; printf("\n plate compositions below the feed plate"); printf("\n Component xs axs ys x1 ax1 y1 x2"); printf("\n o %.3f %.3f %.3f %.3f %.3f %.3f %.3f",xso,ao*xso,yso,x1(1),ax1(1),y1(1),x2(1)); printf("\n m %.3f %.3f %.3f %.3f %.3f %.3f %.3f",xsm,am*xsm,ysm,x1(2),ax1(2),y1(2),x2(2)); printf("\n p %.3f %.3f %.3f %.3f %.3f %.3f %.3f",xsp,ap*xsp,ysp,x1(3),ax1(3),y1(3),x2(3)); printf("\n %.3f %.3f %.3f %.3f %.3f %.3f %.3f",xso+xsm+xsp,ao*xso+am*xsm+ap*xsp,yso+ysm+ysp,x1(1)+x1(2)+x1(3),ax1(1)+ax1(2)+ax1(3),y1(1)+y1(2)+y1(3),x2(1)+x2(2)+x2(3)); ax2 = [ao*x2(1) am*x2(2) ap*x2(3)]; y2 = [ax2(1)/(ax2(1)+ax2(2)+ax2(3)) ax2(2)/(ax2(1)+ax2(2)+ax2(3)) ax2(3)/(ax2(1)+ax2(2)+ax2(3))]; x3o = poly([0],'x3o'); x31 = roots(yso - (Lm/Vm)*x3o + (y(2)/Vm)*xwo); x3p = poly([0],'x3p'); x32 = roots(ysp - (Lm/Vm)*x3p + (y(2)/Vm)*xwp); x3m = poly([0],'x3m'); x33 = roots(ysm - (Lm/Vm)*x3m + (y(2)/Vm)*xwm); x3 = [x31 x33 x32]; ax3 = [ao*x3(1) am*x3(2) ap*x3(3)]; y3 = [ax3(1)/(ax3(1)+ax3(2)+ax3(3)) ax3(2)/(ax3(1)+ax3(2)+ax3(3)) ax3(3)/(ax3(1)+ax3(2)+ax3(3))]; x4o = poly([0],'x4o'); x41 = roots(yso - (Lm/Vm)*x4o + (y(2)/Vm)*xwo); x4p = poly([0],'x4p'); x42 = roots(ysp - (Lm/Vm)*x4p + (y(2)/Vm)*xwp); x4m = poly([0],'x4m'); x43 = roots(ysm - (Lm/Vm)*x4m + (y(2)/Vm)*xwm); x4 = [x41 x43 x42]; ax4 = [ao*x4(1) am*x4(2) ap*x4(3)]; y4 = [ax4(1)/(ax4(1)+ax4(2)+ax4(3)) ax4(2)/(ax4(1)+ax4(2)+ax4(3)) ax4(3)/(ax4(1)+ax4(2)+ax4(3))]; x5o = poly([0],'x5o'); x51 = roots(yso - (Lm/Vm)*x5o + (y(2)/Vm)*xwo); x5p = poly([0],'x5p'); x52 = roots(ysp - (Lm/Vm)*x5p + (y(2)/Vm)*xwp); x5m = poly([0],'x5m'); x53 = roots(ysm - (Lm/Vm)*x5m + (y(2)/Vm)*xwm); x5 = [x51 x53 x52]; ax5 = [ao*x5(1) am*x5(2) ap*x5(3)]; y5 = [ax5(1)/(ax5(1)+ax5(2)+ax5(3)) ax5(2)/(ax5(1)+ax5(2)+ax5(3)) ax5(3)/(ax5(1)+ax5(2)+ax5(3))]; x6o = poly([0],'x6o'); x61 = roots(yso - (Lm/Vm)*x6o + (y(2)/Vm)*xwo); x6p = poly([0],'x6p'); x62 = roots(ysp - (Lm/Vm)*x6p + (y(2)/Vm)*xwp); x6m = poly([0],'x6m'); x63 = roots(ysm - (Lm/Vm)*x6m + (y(2)/Vm)*xwm); x6 = [x61 x63 x62]; ax6 = [ao*x6(1) am*x6(2) ap*x6(3)]; y6 = [ax6(1)/(ax6(1)+ax6(2)+ax6(3)) ax6(2)/(ax6(1)+ax6(2)+ax6(3)) ax6(3)/(ax6(1)+ax6(2)+ax6(3))]; x7o = poly([0],'x7o'); x71 = roots(yso - (Lm/Vm)*x7o + (y(2)/Vm)*xwo); x7p = poly([0],'x7p'); x72 = roots(ysp - (Lm/Vm)*x7p + (y(2)/Vm)*xwp); x7m = poly([0],'x7m'); x73 = roots(ysm - (Lm/Vm)*x7m + (y(2)/Vm)*xwm); x7 = [x71 x73 x72]; printf("\n Component ax2 y2 x3 ax3 y3 x4 ax4"); printf("\n o %.3f %.3f %.3f %.3f %.3f %.3f %.3f",ax2(1),y2(1),x3(1),ax3(1),y3(1),x4(1),ax4(1)); printf("\n m %.3f %.3f %.3f %.3f %.3f %.3f %.3f",xsm,am*xsm,ysm,x1(2),ax1(2),y1(2),x2(2)); printf("\n p %.3f %.3f %.3f %.3f %.3f %.3f %.3f",xsp,ap*xsp,ysp,x1(3),ax1(3),y1(3),x2(3)); printf("\n Component y4 x5 ax5 y5 x6 ax6 y6"); printf("\n o %.3f %.3f %.3f %.3f %.3f %.3f %.3f",y4(1),x5(1),ax5(1),y5(1),x6(1),ax6(1),y6(1)); printf("\n m %.3f %.3f %.3f %.3f %.3f %.3f %.3f",y4(2),x5(2),ax5(2),y5(2),x6(2),ax6(2),y6(2)); printf("\n p %.3f %.3f %.3f %.3f %.3f %.3f %.3f",y4(3),x5(3),ax5(3),y5(3),x6(3),ax6(3),y6(3)); ax7 = [ao*x7(1) am*x7(2) ap*x7(3)]; y7 = [ax7(1)/(ax7(1)+ax7(2)+ax7(3)) ax7(2)/(ax7(1)+ax7(2)+ax7(3)) ax7(3)/(ax7(1)+ax7(2)+ax7(3))]; x8o = poly([0],'x8o'); x81 = roots(yso - (Ln/Vn)*x8o + (y(2)/Vn)*xwo); x8p = poly([0],'x8p'); x82 = roots(ysp - (Ln/Vn)*x8p + (y(2)/Vn)*xwp); x8m = poly([0],'x8m'); x83 = roots(ysm - (Ln/Vn)*x8m + (y(2)/Vn)*xwm); x8 = [x81 x83 x82]; ax8 = [ao*x8(1) am*x8(2) ap*x8(3)]; y8 = [ax8(1)/(ax8(1)+ax8(2)+ax8(3)) ax8(2)/(ax8(1)+ax8(2)+ax8(3)) ax8(3)/(ax8(1)+ax8(2)+ax8(3))]; x9o = poly([0],'x9o'); x91 = roots(yso - (Ln/Vn)*x9o + (y(2)/Vn)*xwo); x9p = poly([0],'x9p'); x92 = roots(ysp - (Ln/Vn)*x9p + (y(2)/Vn)*xwp); x9m = poly([0],'x9m'); x93 = roots(ysm - (Ln/Vn)*x9m + (y(2)/Vn)*xwm); x9 = [x91 x93 x92]; printf("\n Component x7 ax7 y7 x8 ax8 y8 x9"); printf("\n o %.3f %.3f %.3f %.3f %.3f %.3f %.3f",x7(1),ax7(1),y7(1),x8(1),ax8(1),y8(1),x9(1)); printf("\n m %.3f %.3f %.3f %.3f %.3f %.3f %.3f",x7(2),ax7(2),y7(2),x8(2),ax8(2),y8(2),x9(2)); printf("\n p %.3f %.3f %.3f %.3f %.3f %.3f %.3f",x7(3),ax7(3),y7(3),x8(3),ax8(3),y8(3),x9(3)); printf("\n Component x7 ax7 y7 x8 ax8 y8 x9"); printf("\n o %.3f %.3f %.3f %.3f %.3f %.3f %.3f",y4(1),x5(1),ax5(1),y5(1),x6(1),ax6(1),y6(1)); printf("\n m %.3f %.3f %.3f %.3f %.3f %.3f %.3f",y4(2),x5(2),ax5(2),y5(2),x6(2),ax6(2),y6(2)); printf("\n p %.3f %.3f %.3f %.3f %.3f %.3f %.3f",y4(3),x5(3),ax5(3),y5(3),x6(3),ax6(3),y6(3));
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//Velocity calculation clc //initialisation of variables t=20//ft t1=30//ft v=1320//ft/s p=25//sec q=15//ft/s v1=v/t//ft/s v2=v/t1//ft/s T=(v2-v1)/p//ft/s^2 V=v2-q*-T//ft/s V1=-V^2/(2*T)//ft/s //RESULTS printf('the velocity time is=% f ft/s',V1)
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Ex23_1.sce
//Example 23.1 N=1;//Number of loops r=6*10^-2;//Radius of coil (m) A=%pi*r^2;//Area of loop (m^2) delta_BcosTheta=0.250-0.05;//Change in value of magnetic field strength perpendicular to area (T) delta_phi=A*delta_BcosTheta;//Change in magnetic flux (T.m^2) delta_t=0.1;//Time (s) Emf=N*delta_phi/delta_t;//Induced emf (V) printf('Induced emf = %0.1f mV',Emf*1000) //Openstax - College Physics //Download for free at http://cnx.org/content/col11406/latest
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17_1.sce
clc //initialisation of variables l=1000//mm L=l/2//mm y=2.6//g/cu y1=7.85//g/cu a=375//mm //CALCULATIONS D=y1/y//mm C=L/2+a//mm //RESULTS printf('the centre of gravity of the shaft=% f mm',C)
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// Grob's Basic Electronics 11e // Chapter No. 30 // Example No. 30_7 clc; clear; // Calculate Av, Vo & Zo. // Given Data Rs = 240; // Source Resistor=240 Ohms Rl = 1.8*10^3; // Load Resistor=1.8 kOhms Vgsoff = -8; // Voltage Gate-Source(off)=-8 Volts Vgs = -2; // Voltage Gate-Source=-2 Volts Idss = 15*10^-3 // Idss=15 mAmps. Vin = 1; // Input Voltage=1 Volts(p-p) rl = ((Rs*Rl)/(Rs+Rl)); gmo = 2*Idss/-Vgsoff; gm = gmo*(1-(Vgs/Vgsoff)); Av = gm*rl/(1+gm*rl); disp (Av,'The Voltage Gain Av is') Vo = Av*Vin; disp (Vo,'The Output Voltage Vo in Volts(p-p)') A = (1/gm); Zo = ((Rs*A)/(Rs+A)); disp (Zo,'The Output Impedence Zo in Ohms') disp ('Appox 143.5 Ohms')
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CH09Exa11.sce
// Scilab code Exa9.11 : : Page-394 (2011) clc; clear; R_0 = 1.2e-015; // Distance of closest approach, metre // Mass number of the nuclei are allocated below : N = rand(4,1) N(1,1) = 17; // for oxygen N(2,1) = 33; // for sulphur N(3,1) = 63; // for copper N(4,1) = 209; // for bismuth for i = 1:4 if N(i,1) == 17 then printf("\n For Oxygen : ") I = 5/2; // Total angular momentum l = 2; // Orbital angular momentum mu = -1.91; // for odd neutron and I = l+1/2 Q = -3/5*(2*I-1)/(2*I+2)*(R_0*N(i,1)^(1/3))^2*10^28; // Quadrupole moment of oxygen, barn printf("\n The value of magnetic moment is : %4.2f \n The value of quadrupole moment is : %6.4f barn", mu, Q); elseif N(i,1) == 33 then printf("\n\n For Sulphur : ") I = 3/2; // Total angular momentum l = 2; // Orbital angular momentum mu = 1.91*I/(I+1); // for odd neutron and I = l-1/2 Q = -3/5*(2*I-1)/(2*I+2)*(R_0*N(i,1)^(1/3))^2*10^28; // Quadrupole moment of sulphur, barn printf("\n The value of magnetic moment is : %5.3f \n The value of quadrupole moment is : %6.4f barn", mu, Q); elseif N(i,1) == 63 then printf("\n\n For Copper : ") I = 3/2; // Total angular momentum l = 1; // Orbital angular momentum mu = I+2.29; // for odd protons and I = l+1/2 Q = -3/5*(2*I-1)/(2*I+2)*(R_0*N(i,1)^(1/3))^2*10^28; // Quadrupole momentum of copper, barn printf("\n The value of magnetic moment is : %4.2f \n The value of quadrupole moment is : %6.4f barn", mu, Q); elseif N(i,1) == 209 then printf("\n\n For Bismuth : ") I = 9/2; // Total angular momentum l = 5; // Orbital angular momentum mu = I-2.29*I/(I+1); // for odd protons and I = l-1/2 Q = -3/5*(2*I-1)/(2*I+2)*(R_0*N(i,1)^(1/3))^2*10^28; // Quadrupole momentum of bismuth, barn printf("\n The value of magnetic moment is : %4.2f \n The value of quadrupole moment is : %5.3f barn", mu, Q); end end // Result // For Oxygen : // The value of magnetic moment is : -1.91 // The value of quadrupole moment is : -0.0326 barn // For Sulphur : // The value of magnetic moment is : 1.146 // The value of quadrupole moment is : -0.0356 barn // For Copper : // The value of magnetic moment is : 3.79 // The value of quadrupole moment is : -0.0547 barn // For Bismuth : // The value of magnetic moment is : 2.63 // The value of quadrupole moment is : -0.221 barn
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Chap3_Ex14_R1.sce
// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-3,Example 14,Page 75 //Title:Volume using generalized form of the Redlich-Kwong equation of state //================================================================================================================ clear clc //INPUT T=427.85;//temperature of n-octane vapour in K P=0.215;//pressure of n-ocatne vapour in MPa Tc=569.4;//critical temperature of n-octane in K Pc=2.497;//critical pressure of n-octane in MPa R=8.314;//universal gas constant in (Pa m^3)/(mol K) //CALCULATION Tr=T/Tc;//calculation of reduced temperature (no unit) Pr=P/Pc;//calculation of reduced pressure (no unit) z_init=1;//taking a guess value of z (compressibilty factor) to get a value of h for solving the system h=(0.08664*Pr)/(z_init*Tr);//calculation of h using Eq.(3.68) tolerance=1e-6;//Framing the tolerance limit for the convergence of the equation function[fn]=solver_func(zi) fn=zi-((1/(1-h))-((h/(1+h))*(4.93398/(Tr^(3/2)))));//Function defined for solving the system using Eq.(3.67) endfunction [z]=fsolve(h,solver_func,tolerance)//using inbuilt function fsolve for solving the system of equations V=(z*R*T)/(P*10^6);//calculation of volume in m^3/mol using Eq.(3.59) //OUTPUT mprintf('\n The volume occupied by n-octane vapour obtained by the generalized form of Redlich-Kwong equation of state= %f m^3/mol\n',V); //===============================================END OF PROGRAM===================================================
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//(Design against Static Load) Example 4.18 //Refer Fig.4.57 on page 126 //Tensile yield strength of FeE250 Syt (N/mm2) Syt = 250 //Factor of safety fs fs = 5 //Diameter of bars to be sheared D (mm) D = 6.25 //Ultimate shear strength of the material Sus (N/mm2) Sus = 350 //Permissible bearing pressure on the pins p (N/mm2) p = 10 //Pin length to diameter ratio r1 r1 = 1.25 //Link cross-section width to thickness ratio r2 r2 = 2 //Distance between pinA and pinB l1 (mm) l4 = 400 //Distance between bar to be sheared and pinA & force application point and pinC l2 (mm) l2 = 100 //Distance between the force applied and pinD l3 (mm) l3 = 1000 //Thickness of gunmetal bush over pin C t (mm) t = 2.5
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clc; clear all; close; x1=[1,3,7,-2,5]; x2=[2,-1,0,3]; z=xcorr(x1,x2); disp(z,"This is the required correlation"); l=length(z); t=0:l-1; plot2d3(t,z); xlabel("n"); ylabel("Amplitude"); title("Correlation: y(n)=x1(n)*x2(-n)"); figure;
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clc //initialisation of variables W= -10 //KN/m r= 5 //m //CALCULATIONS Rav= -W*2*r/2 Rbv= Rav function[y]=conv(x) y=125*(sin(x))^2*5*(sin(x))*5 endfunction v=intg(0,%pi,conv) function[y]=conk(x) y=25*(sin(x))^2*5 endfunction k=intg(0,%pi,conk) Rbh= v/k Rah= Rbh //RESULTS printf ('Rav= %.2f KN',Rav) printf (' \n Rbv=%.2f KN',Rbv) printf (' \n Rah=%.2f KN',Rah) printf (' \n Rbh=%.2f KN',Rbh)
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function status = generateTFProc(name, forward_coefficients, feedback_coefficients, parameters) fd = parameters.fd mfprintf(fd, '#include <string.h>\n') mfprintf(fd, 'static __inline__ _NUMBER_TYPE %s(_NUMBER_TYPE e1)\n{\n', name) mfprintf(fd, '%sstatic _NUMBER_TYPE x[] = {', parameters.indent) for i = 1:length(feedback_coefficients)-1 mfprintf(fd, '0.0, ') end mfprintf(fd, '0.0};\n') mfprintf(fd, '%s_NUMBER_TYPE x0 = %f *e1;\n', ... parameters.indent, feedback_coefficients(1)) mfprintf(fd, '%s_NUMBER_TYPE e2;\n', ... parameters.indent) for i = 2:length(feedback_coefficients) mfprintf(fd, '%sx0 += %f * x[%d];\n', ... parameters.indent, feedback_coefficients(i), i-1) end mfprintf(fd, '%se2 = %f * x0;\n', ... parameters.indent, forward_coefficients(1)) for i = 2:length(forward_coefficients) mfprintf(fd, '%se2 += %f * x[%d];\n', ... parameters.indent, forward_coefficients(i), i-1) end mfprintf(fd, '\n%sx[0]=x0; memmove(&x[1], &x[0], sizeof(x)-sizeof(x[0]));\n', ... parameters.indent) mfprintf(fd, '\n%sreturn e2;\n}\n', parameters.indent) status = %t endfunction
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//Page Number: 5.41 //Example 5.34 clc; //Given, fs=8000; //Hz m=24; n=8; //(a) Duration of each bit t1=1/fs; t2=(m*n)+1; // Extra bit for synchronization Tb=t1/t2; disp('seconds',Tb,'Duration of each bit'); //(b) Transmission Rate Rb=1/Tb; disp('b/s',Rb,'Transmission Rate'); //(c)Minimum transmission bandwidth fT1=1/(2*Tb); disp('Hz',fT1,'Minimum transmission bandwidth');
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//example 4.25 //calculate average depth of hourly rainfall excess clc;funcprot(0); //given r=[2.0 2.5 7.6 3.8 10.6 5.0 7.0 10.0 6.4 3.8 1.4 1.4]; //rainfall depths A1=20; A2=40; A3=60; A=A1+A2+A3; fi1=7.6; fi2=3.8; fi3=1.0; for i=1:12 R1(i)=r(i)-fi1; //rainfall excess R2(i)=r(i)-fi2; R3(i)=r(i)-fi3; if (R1(i)<0) then R1(i)=0; end if (R2(i)<0) then R2(i)=0; end if (R3(i)<0) then R3(i)=0; end end mprintf("average depth of hourly rainfall excess(cm/hr)"); for i=1:12 a1(i)=R1(i)*A1/A; //average rainfall excess a2(i)=R2(i)*A2/A; a3(i)=R3(i)*A3/A; T(i)=a1(i)+a2(i)+a3(i); //total hourly rainfall excess T(i)=round(T(i)*100)/100; mprintf("\n%f",T(i)); end
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clear data7; exec('data02.dat'); getf('label.sci'); T = data7(:,1); fan = data7(:,3); //T is time, fan is fan speed u = data7(:,2); y = data7(:,4)-data7(1,4); // u is current, y is temperature ord = [u y]; x = [T T]; // u and y are plotted vs. time and time xbasc(); plot2d(x,ord); xgrid(); title = 'Ramp change in current and the resulting temperature' label(title,4,'time (s)','Current, Temperature (C)',4);
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//ques11 disp('To find the inverse laplace transform of the function'); syms s t f=(s^2-3*s+4)/s^3; il=ilaplace(f,s,t); disp(il);
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// chapter 2 // example 2.8 // Fig. E2.8 // Calculate the resistance, gate power dissipation and maximum triggering frequency // page-32-33 clear; clc; // given Ig_min=500; // in mA (minimum gate current) gradient=16; // in V/A Egs=15; // in V (gate source voltage) T_on=4; // in us (minimum turn on time) Pg_av=0.3; // in W (average gate power dissipation) // calculate Ig_min=Ig_min*1E-3; // changing unit from mA to A Vg=gradient*Ig_min; // calculation of gate voltage Rs=(Egs-Vg)/Ig_min; // calculation of resistance printf("\nThe resistance to be connected in series with SCR gate is \tRs= %.f ohm",Rs); Pg=Vg*Ig_min; // calculation of power dissipation printf("\n\nThe gate power dissipation is \t\t\t\t\tPg= %.f W",Pg); // Since Pg=Pg_av/(f*T_on), therefore T_on=T_on*1E-6; // changing unit from us to sec f=Pg_av/(Pg*T_on); // calculation of maximum triggering frequency f=f*1E-3; // changing unit from Hz to khz printf("\n\nThe maximum triggering frequency is \tf= %.2f kHz \t or \tF= %.f kHz",f,f);
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%r_clean.sci
function a=%r_clean(a,epsa,epsr) //Syntax: a=%r_ clean(a,epsa,epsr) // Given a, matrix of rationals , this function // eliminates all the coefficients of a with absolute value < epsa // and realtive value < epsr (relative means realive wrt norm 1 of // the coefficients) // Default values : epsa=1.d-10; epsr=1.d-10; //! // Copyright INRIA [lhs,rhs]=argn(0) if rhs == 1 then epsa=1.d-10; epsr=1.d-10; elseif rhs==2 then epsr=1.d-10; end tdom=a(4) a=simp(clean(a(2),epsa,epsr)./clean(a(3),epsa,epsr));a(4)=tdom
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clc p1=75.882; //cm of Hg T1=286; //K V1=0.08; //m^3 p2=76; //cm of Hg T2=288; //K V2=p1*V1*T2/p2/T1; m=28; //kg c=4.18; t2=23.5; //0C t1=10; //0C Q_received=m*c*(t2-t1); HCV=Q_received/V2; disp("Higher calorific value =") disp(HCV) disp("kJ/m^3") amt=0.06/0.08; //Amount of vapour formed per m^3 of gas burnt LCV=HCV-2465*amt; disp("Lower calorific value =") disp(LCV) disp("kJ/kg")
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//Chapter-6, Example 6.9, Page 258 //============================================================================= clc clear //INPUT DATA L=100;//Length of rectangular duct in m A=[0.02,0.025];//Area of duct in m^2 Tw=40;//Temperature of water in degree C v=0.5;//Velocity of flow in m/s k=(0.66*10^-6);//kinematic viscosity in m^2/s p=995;//Density of water in kg/m^3 //CALCULATIONS P=2*(A(1)+A(2));//Perimeter of the duct in m Dh=(4*(A(1)*A(2)))/P//Hydraulic diameter of the duct in m Re=(v*Dh)/k;//Reynolds number f=0.316*Re^(-0.25);//Friction factor hL=(f*L*v^2)/(2*Dh*9.81);//Head loss in m P=(hL*9.81*p)/10^4;//Pressure drop in smooth rectangular duct in 10^4 N/m^2 //OUTPUT mprintf('Pressure drop in smooth rectangular duct is %3.4f*10^4 N/m^2',P) //=================================END OF PROGRAM==============================
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clear; clc; close; Rl = 1000; R = 120; Vdc = 60; Vdc_dash = (Rl/(R+Rl))*Vdc; disp(Vdc_dash,'Dc voltage across 1k-ohm load = ');
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//Tested on Windows 7 Ultimate 32-bit //Chapter 9 Frequency Response of Amplifier Pg no. 307 and 308 clear; clc; //Given VCC=15;//collector supply voltage in volts RC=2.2D3;//collector resistance in ohms RE=470;//emitter resistance in ohms R1=33D3;//divider network resistance R1 in ohms R2=10D3;//divider network resistance R2 in ohms VBE=0.7;//forward voltage drop of emitter diode in volts B=150;//DC CE current gain beta Rs=600;//source internal impedance in ohms RL=4.7D3;//load resistance in ohms C1=0.1D-6;//input coupling capacitance in farads C2=50D-6;//emitter bypass capacitance in farads C3=0.1D-6;//output coupling capacitance in farads re=4;//a.c. emitter resistance in ohms //Solution Rth=1/(1/R1+1/R2+1/Rs);//thevenin resistance at base in ohms Rin_emitter=re+Rth/B;//resistance looking into the emitter in ohms R=1/(1/Rin_emitter+1/RE);//resistance of the equivalent RC network in ohms fc=1/(2*%pi*R*C2);//critical frequency of the bypass network in hertz printf("critical frequency of the bypass network fc = %d Hz",fc);
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s=%s;//given Kv=1000sec^-1 Kv =1000; g =Kv/( s*(0.1*s +1)* (1+.001*s)) G= syslin ('c',g) fmin =0.01; fmax =100; bode (G,fmin , fmax ) show_margins (G) xtitle (" uncompensated system") [gm , freqGM ]= g_margin (G) [pm , freqPM ]= p_margin (G) disp (gm ," g a i n ma r g i n=") disp (( freqGM *2* %pi)," =gain margin frequency"); disp (pm ," phas e margin=") disp (( freqPM *2* %pi)," phase margin frequency="); printf (" sine the phase margin is less than the desired pahse margin so we need pahse lead compensator ") gc =(1+0.016* s) /(1+0.00214* s) Gc= syslin ('c',gc) disp (Gc ," transfer function of lead compensator="); G1=G*Gc disp (G1 ," overall transfer function="); fmin =0.01; fmax =100; bode (G1 ,fmin , fmax ); show_margins (G1) xtitle (" compensated system") [gm , freqGM ]= g_margin (G1); [pm , freqPM ]= p_margin (G1); disp (pm ," phase margin of compensated system=") disp (( freqPM *2* %pi)," gain crossover frequency=")
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//pathname=get_absolute_file_path('5.10.sce') //filename=pathname+filesep()+'5.10-data.sci' //exec(filename) //Initial pressure(in kPa): p1=3000 //Initial volume(in m^3): v1=0.05 //Final volume(in m^3): v2=0.3 //Value of n: n=1.4 //Final pressure(in MPa): p2=p1*((v1/v2)^n) //Entropy change: dS=0 //Change in enthalpy(in kJ): dH=((p1*(v1^n))^(1/n))*(p1^((n-1)/n)-p2^((n-1)/n))/((n-1)/n) printf("\nRESULT\n") printf("\nEnthalpy change = %f kJ",dH) printf("\nEntropy change = %d",dS)
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//Load scripts from folder funcprot(0) getd("../scripts"); //Global variables imgPos = "../images/"; //The position of the source images renderPos = "render/"; //The folder where the render images will be saved //Load image imgin = readpbm(imgPos+"Formes.pbm"); imgout = median(imgin,0) //Show the coordinates of the brightest color of the image loaded writepbm(imgout,renderPos+"MissionC2.pbm");
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PL/SQL Developer Test script 3.0 5 begin -- Call the procedure personas_por_quiere_mascota(pqmascotas => :pqmascotas, p_recordset => :p_recordset); end; 2 pqmascotas 1 1 5 p_recordset 1 <Cursor> 116 0
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lab4_task2.sci
clc; clear all; close; //----------------------------------------------------------------------------- b = chdir('C:\Users\work\OneDrive\Documents\SciLab\lab_v4') //read data [irc_my, Fs_irc, h_bits] = wavread("C:\Users\work\OneDrive\Documents\SciLab\lab_v4\1a_marble_hall.wav") [signal, Fs_s, s_bits] = wavread("C:\Users\work\OneDrive\Documents\SciLab\lab_v4\7cef8230.wav") irc_my = irc_my(1,:) signal = signal(1,:) // as it presented in doc with some mofification finding inverse filter steps: filter_my_irc = conj(fft(irc_my))./abs(fft(irc_my))^2 // inverse filter len = length(filter_my_irc) filter_not_shifted = real(filter_my_irc) frequencies = (0:len-1)/len * Fs_irc; filter_my_irc = ifft(filter_my_irc) len = length(filter_my_irc) filter_not_shifted = real(filter_my_irc) frequencies = (0:len-1)/len * Fs_irc; //plot filter figure(0) plot(filter_my_irc) xlabel("Time", 'fontsize', 2) ylabel("Amplitude", 'fontsize', 2) title("IRC inverse filter") //shifting impulse response filter_shifted = cshift(filter_not_shifted, [0 (len - modulo(len, 2)) / 2]) reslut_filter = filter_shifted .* window('kr', length(filter_shifted), 8) figure(1) plot(reslut_filter) xlabel("Time", 'fontsize', 2) ylabel("Amplitude", 'fontsize', 2) title("IRC inverse filter Impulse response") // applying filter figure(2) signal_with_effect = convol(irc_my, signal) filtered = convol(signal_with_effect, reslut_filter) subplot(2, 1, 1) plot(signal_with_effect) xlabel("Time") ylabel("Amplitude") title("Before filtering") subplot(2, 1, 2) plot(filtered) xlabel("Time") ylabel("Amplitude") title("After filtering") savewave("C:\Users\work\OneDrive\Documents\SciLab\lab_v4\without_effect_with_irc", filtered, Fs_s)
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Ex9_8.sce
//chapter9 //example9.8 //page148 V=15 // V R=0.5 // kilo ohm V_D=0.7 // V // both diodes are forward biased I1=(V-V_D)/R I_D1=I1/2 I_D2=I_D1 printf("current through diode D1 = %.3f mA and diode D2 = %.3f mA \n",I_D1,I_D2)
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Example_9_5.sce
//clear// clear; clc; //Example 9.5 //Given Dt = 6; //[ft] H = 8; //[ft] T = 70; //[F] sp_gr = 3.18; w_fr = 0.25; Da = 2; //[ft] h = 1.5; //[ft] gc = 32.17; //[ft-lb/lbf-s^2] // (a) //Using data of Buurman et al. in Fig.(9.19) //change in nc delta_nc = (104/200)^0.2*(2.18/1.59)^0.45*(33.3/11.1)^0.13; //change in P dalta_P = delta_nc^3; //Using Fig. 9.19 V = %pi/4*Dt^2*H*7.48 ; //[gal] P = 3.3*V/1000 //[hp] //(b) //From Table 9.3, for a cour blade turbine, KT = 1.27; Np = KT; //slurry density rho_m = 1/((w_fr/sp_gr)+(1-w_fr))*62; // [lb/ft^3] nc = (P*gc*550/(Np*rho_m*Da^5))^(1/3) // [r/s]