output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
template <typename T>
inline void read(T &x) {
x = 0;
T f = 1;
char c = getchar();
for (; !isdigit(c); c = getchar())
if (c == '-') f = -1;
for (; isdigit(c); c = getchar()) x = (x << 3) + (x << 1) + (c ^ 48);
x *= f;
}
int main() {
int n;
read(n);
for... | ### Prompt
Create a solution in cpp for the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of nu... |
#include <bits/stdc++.h>
int main() {
int t;
scanf("%d", &t);
for (int i = 0; i < t; ++i) {
int x;
scanf("%d", &x);
printf("%d\n", x / 2);
}
return 0;
}
| ### Prompt
Please create a solution in cpp to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
const int INF = 1e9 + 8;
const double pi = 3.14159265359;
template <class T>
T fac(T n) {
T res = 1, i;
for (i = 2; i <= n; i++) res *= i;
return res;
}
template <class T>
T lcm(T a, T b) {
return (a * b) / __gcd(a, b);
}
template <class T>
... | ### Prompt
Generate a cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of numb... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (int i = 0; i < t; ++i) {
int x, ans = 0;
cin >> x;
for (int j = 7; j > 1; --j) {
ans += x / j;
x %= j;
}
if (x) ++ans;
cout << ans << '\n';
}
return 0;
}
| ### Prompt
Please create a solution in Cpp to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int x, c = 0;
cin >> x;
while (x > 0) {
if (8 < x) {
x -= 7;
c++;
} else if (x < 8) {
c++;
cout << c;
return;
} else {
x -= 6;
c++;
}
}
cout << c;
return;
}
int main() {
ios::sync_with_st... | ### Prompt
Create a solution in CPP for the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of nu... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, x;
cin >> t;
while (t--) {
cin >> x;
cout << x / 2 << endl;
}
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 1e5 + 5;
int C[7] = {2, 3, 4, 5, 6, 7};
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int ans = n / 5;
n = n % 5;
if (n) ans++;
cout << ans << endl;
}
}
| ### Prompt
In CPP, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
int main() {
int n, t, x;
scanf("%d", &t);
while (t--) {
scanf("%d", &n);
if (n == 1) {
printf("0\n");
} else {
printf("%d\n", n / 2);
}
}
return 0;
}
| ### Prompt
Construct a CPP code solution to the problem outlined:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
if (n % 2 == 0) {
cout << n / 2 << endl;
} else {
cout << (n - 1) / 2 << endl;
}
}
}
| ### Prompt
Create a solution in cpp for the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of nu... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int x, t = 0, i, j;
cin >> i;
for (j = 0; j < i; j++) {
cin >> x;
if (x % 6 == 0)
x = x / 6;
else if (x / 6 < 1)
x = 1;
else if (x % 6 >= 1 && x / 6 >= 1) {
x = x / 6;
x++;
}
cout << x << "\n";
}
return ... | ### Prompt
Create a solution in CPP for the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of nu... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, a;
cin >> n;
for (i = 0; i < n; i++) {
cin >> a;
if (a % 7 == 0) {
cout << a / 7 << endl;
} else {
cout << a / 7 + 1 << endl;
}
}
}
| ### Prompt
Develop a solution in Cpp to the problem described below:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int n;
int a[101];
int main() {
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> a[i];
if (a[i] % 2 == 0) {
cout << a[i] / 2 << endl;
} else {
cout << (a[i] - 3) / 2 + 1 << endl;
}
}
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
const double pi = 4.0 * atan(1.0);
const double e = exp(1.0);
using namespace std;
map<char, int> p;
int n, m;
int main() {
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
int x;
cin >> x;
int d = x / 7, m = x % 7;
if (m) d++;
cout << d << endl;
}
return 0;
}
| ### Prompt
In cpp, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int q;
std::cin >> q;
while (q--) {
int n;
std::cin >> n;
int ans = 1;
while (!(ans * 2 <= n && n <= ans * 7)) {
ans = 1 + ... | ### Prompt
Please create a solution in cpp to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int counter = 0;
int x;
cin >> x;
while (x != 0) {
counter++;
if (x <= 7) {
x = 0;
break;
}
x -= 7;
}
cout << counter << endl;
}
return 0;
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
cout << (n + 6) / 7 << '\n';
}
return 0;
}
| ### Prompt
In cpp, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
while (n--) {
int t;
cin >> t;
cout << t / 2 << endl;
}
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int ans = 0;
int i = 7;
while (n) {
ans += n / i;
n = n % i;
i--;
}
cout << ans << endl;
}
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just... |
#include <bits/stdc++.h>
using namespace std;
void calc(int k) {
int a[] = {2, 3, 4, 5, 6, 7};
int i = 5;
int cnt = 0;
if ((k > 1) && (k < 8)) {
cnt = 1;
} else {
cnt = 1;
for (; i > -1;) {
int temp = k - a[i];
if (temp > 7) {
cnt++;
k -= a[i];
} else if ((temp > ... | ### Prompt
In Cpp, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (int i = 1; i <= t; i++) {
int x;
cin >> x;
int ans = 0;
while (x > 7) {
if (x - 7 < 2)
x -= 6;
else
x -= 7;
ans++;
}
cout << ans + 1 << endl;
}
return 0;
}
| ### Prompt
Please provide a CPP coded solution to the problem described below:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is ... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 3e5 + 69;
const int INF = 1e9 + 85;
const int MOD = 998244353;
int t, n, ans;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> t;
for (int i = 0; i < t; i++) {
cin >> n;
ans = 0;
if (n % 2 == 1) n -= 3, ans++;
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, x, i;
scanf("%d", &n);
for (i = 0; i < n; ++i) {
scanf("%d", &x);
printf("%d\n", x / 2);
}
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just... |
#include <bits/stdc++.h>
using namespace std;
int const N = 1e5 + 5;
int dx[] = {0, 0, 1, -1, 1, 1, -1, -1};
int dy[] = {1, -1, 0, 0, 1, -1, -1, 1};
int main() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int t;
cin >> t;
while (t--) {
bool done = 0;
int n;
cin >> n;
for (int i = 2; ... | ### Prompt
In Cpp, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
for (int i = 0; i < n; i++) {
int q;
cin >> q;
cout << q / 2 << endl;
}
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int T;
scanf("%d", &T);
while (T--) {
int x;
scanf("%d", &x);
int sum = x / 7;
if (x % 7) sum += 1;
printf("%d\n", sum);
}
return 0;
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int x;
cin >> x;
cout << (int)(ceil(x * 1.0 / 7)) << endl;
}
return 0;
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n;
cin >> t;
for (int i = 1; i <= t; i++) {
cin >> n;
int temp = n;
int div = 7;
for (int j = 0; div > 1; j++) {
if ((temp % div) > 1) {
cout << (temp / div) + 1 << endl;
break;
} else if ((temp % div) ==... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is ... |
#include <bits/stdc++.h>
using namespace std;
int a[400400];
int main() {
ios_base::sync_with_stdio(0);
int a, b;
cin >> a;
for (int i = 0; i < a; i++) {
cin >> b;
cout << b / 2 << endl;
}
}
| ### Prompt
In CPP, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
int main() {
int n;
scanf("%d", &n);
for (int i = 0; i < n; i++) {
int kup, c = 0;
scanf("%d", &kup);
if (kup == 3) {
printf("1\n");
}
if (kup % 2 == 0) {
c = kup / 2;
printf("%d\n", c);
}
if (kup % 2 != 0 && kup != 3) {
c = (kup - 3) / ... | ### Prompt
Please create a solution in Cpp to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int test;
cin >> test;
for (int i = 0; i < test; i++) {
int num;
cin >> num;
int p = floor(num / 7);
int ans = p + 1;
cout << ans << endl;
}
return 0;
}
| ### Prompt
Develop a solution in Cpp to the problem described below:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int main(int argc, char const *argv[]) {
cin.tie(0);
ios_base::sync_with_stdio(false);
int T, N;
cin >> T;
while (T--) {
cin >> N;
int cnt = N / 7;
cnt += (N % 7 > 0);
cout << cnt << '\n';
}
return 0;
}
| ### Prompt
Create a solution in CPP for the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of nu... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int arr[6];
int i, flag = 0;
for (i = 0; i < 6; i++) {
arr[i] = i + 2;
}
if (n > 1 && n < 8) {
cout << "1" << endl;
} else if (n == 1)
cout << "0" << endl;
... | ### Prompt
Please formulate a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
const long long N = 300005;
const long long M = 998244353;
vector<long long> v[N];
long long ans = 1;
vector<long long> colour(N, -1);
long long pow1(long long a, long long b) {
long long res = 1;
for (long long i = 0; i < b; i++) {
res = (res * a) % M;
}
return... | ### Prompt
In cpp, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int T, k, t, j, count = 0;
cin >> T;
while (T--) {
cin >> k;
t = k;
count = 0;
if (t > 7) {
count = t / 7;
}
cout << count + 1 << endl;
}
}
| ### Prompt
In Cpp, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, angka, ans;
int i;
cin >> n;
for (i = 0; i < n; i++) {
cin >> angka;
ans = angka / 2;
cout << ans << endl;
}
}
| ### Prompt
Develop a solution in cpp to the problem described below:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (int i = 0; i < t; i++) {
int x;
cin >> x;
if (x % 7 == 0) {
cout << x / 7 << endl;
} else {
cout << x / 7 + 1 << endl;
}
}
return 0;
}
| ### Prompt
Please create a solution in CPP to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, d;
cin >> n;
for (i = 0; i < n; i++) {
cin >> d;
cout << d / 2 << endl;
}
return 0;
}
| ### Prompt
Please formulate a cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n;
cin >> t;
while (t--) {
cin >> n;
cout << n / 2 << endl;
}
}
| ### Prompt
Construct a CPP code solution to the problem outlined:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of... |
#include <bits/stdc++.h>
using namespace std;
int t, n, ans, dp[101];
int solve(int sum) { return (sum % 7 == 0) ? sum / 7 : sum / 7 + 1; }
int main() {
cin >> t;
while (t--) {
memset(dp, -1, sizeof dp);
cin >> n;
cout << solve(n) << endl;
}
return 0;
}
| ### Prompt
In Cpp, your task is to solve the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of n... |
#include <bits/stdc++.h>
using namespace std;
int n, x, i;
int main() {
cin >> n;
for (i = 1; i <= n; i++) {
cin >> x;
if (x % 7 == 0)
cout << x / 7;
else
cout << x / 7 + 1;
cout << '\n';
}
return 0;
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just... |
#include <bits/stdc++.h>
using namespace std;
long long a, c, d, e, f, g, h, i, j, k, l, m, n, o, p, s;
int main() {
cin >> n;
k = 0;
long long b[n];
for (i = 0; i < n; ++i) {
cin >> m;
cout << m / 2 << endl;
}
return 0;
}
| ### Prompt
Generate a CPP solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of numb... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, m, i, j, k, cnt = 0, sum = 0, mn = INT_MAX, ind, size, lcm,
mx = INT_MIN, diff, num, x, y, z, ee;
int flag = 0, t = 1;
string s, str, s1, s2, s3;
char ch;
ios_base::sync_with_stdio(false);
cin.tie(0);
... | ### Prompt
Construct a cpp code solution to the problem outlined:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of... |
#include <bits/stdc++.h>
using namespace std;
template <class T1, class T2>
istream &operator>>(istream &is, pair<T1, T2> &p) {
return is >> p.first >> p.second;
}
template <class T1, class T2>
ostream &operator<<(ostream &os, pair<T1, T2> &p) {
return os << p.first << " " << p.second;
}
signed main() {
ios_base:... | ### Prompt
Create a solution in cpp for the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of nu... |
#include <bits/stdc++.h>
using namespace std;
inline int two(int n) { return 1 << n; }
inline int test(int n, int b) { return (n >> b) & 1; }
inline void set_bit(int& n, int b) { n |= two(b); }
inline void unset_bit(int& n, int b) { n &= ~two(b); }
inline int last_bit(int n) { return n & (-n); }
inline int ones(int n) ... | ### Prompt
Create a solution in cpp for the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum of nu... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int x;
cin >> x;
cout << x / 2 << "\n";
}
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
cout << (n + 6) / 7 << endl;
}
}
| ### Prompt
Develop a solution in cpp to the problem described below:
Mishka got a six-faced dice. It has integer numbers from 2 to 7 written on its faces (all numbers on faces are different, so this is an almost usual dice).
Mishka wants to get exactly x points by rolling his dice. The number of points is just a sum... |
#include <bits/stdc++.h>
using namespace std;
int ans(vector<vector<int> > &dp, int n, int v, int limit, int x) {
if (dp[n][v] != x) {
return dp[n][v];
}
if (n == 1) {
return dp[n][v] = v;
}
int min_1 = INT_MAX;
if (v + 1 <= limit) {
min_1 = min(min_1, 0 + ans(dp, n - 1, v + 1, limit, x));
}
... | ### Prompt
In cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int ans = 0;
ans += min(n - 1, v);
for (int i = 2; i <= n - v; i++) {
ans += i;
}
cout << ans;
return 0;
}
| ### Prompt
In CPP, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, c;
cin >> n >> v;
int cost = 0, fuel = 0;
c = min(n - 1 - fuel, v);
cost += c;
fuel += c;
for (int i = 2; i <= n; i++) {
fuel--;
if (fuel < n - i) {
c = min(n - i - fuel, v - fuel);
fuel += c;
cost += c * i;
... | ### Prompt
Please create a solution in Cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int n, u, ans, i;
int main() {
cin >> n >> u;
if (n - 1 <= u)
cout << n - 1;
else {
ans = u;
for (i = 2; i <= n - u; i++) ans += i;
cout << ans;
}
return 0;
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n;
cin >> n;
int v;
cin >> v;
int res = v;
int vol = 0;
if (v >= n) {
cout << n - 1;
return 0;
}
if (n == v + 1) {
cout << v;
return 0;
}
for (int i = 2; i <=... | ### Prompt
Generate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n <= v)
cout << n - 1 << "\n";
else {
n -= v;
int res = v + ((n * (n + 1)) / 2) - 1;
cout << res << "\n";
}
return 0;
}
| ### Prompt
Construct a Cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int n, v;
int main() {
cin >> n >> v;
int sum = min(v, n - 1), have = min(v, n - 1);
for (int i = 2; i < n; i++) {
have--;
int need;
if (v + i >= n)
need = n - i;
else
need = v;
if (have < need) {
sum += (need - have) * i;
h... | ### Prompt
Generate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v >= n - 1)
cout << n - 1;
else
cout << (n - v) * (n - v + 1) / 2 + v - 1;
return 0;
}
| ### Prompt
Please create a solution in Cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a, b;
cin >> a >> b;
int c;
c = a - b - 1;
if (c < 1)
cout << (a - 1) << endl;
else {
long long int d;
c++;
d = b + (c * (c + 1) / 2) - 1;
cout << d << endl;
}
return 0;
}
| ### Prompt
Please formulate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, i, k;
int money;
cin >> n >> v;
if (n > v) {
i = 2;
money = money + v;
k = n - v - 1;
while (k--) {
money = money + i;
i++;
}
} else {
money = n - 1;
}
cout << money;
}
| ### Prompt
Please formulate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, c = 0, d;
cin >> n >> v;
if (n - 1 == v) {
cout << v;
return 0;
} else if (v >= n) {
cout << n - 1;
return 0;
}
for (int i = 1; i < n; i++) {
if (i == 1) {
c += i * v;
} else {
d = i;
c += i;
... | ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int now = 1, you = 0;
int qian = 0;
for (int i = 1; i <= n; i++) {
if (you < n - i) {
qian += min((n - i - you), v - you) * i;
you += min((n - i - you), v - you);
}
you--;
}
cout << qian << endl;
}
| ### Prompt
Your challenge is to write a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int n, v;
int main() {
scanf("%d %d", &n, &v);
int ans = v, i = 2, t = n - 1;
if (v >= n - 1) return printf("%d\n", n - 1), 0;
while (t > 0) {
if (t <= v) {
t--;
continue;
}
ans += i;
t--;
i++;
}
printf("%d\n", ans);
}
| ### Prompt
Please create a solution in Cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
const int inf = 1e9 + 5;
const long long mo = 1e9 + 7;
long long sx, sy, ex, ey, dx[6] = {0, 1, 0, -1, 0, 0},
dy[6] = {1, 0, -1, 0, 0, 0}, m, n, k,
dz[6]{0, 0, 0, 0, -1, 1}, sg, re;
long long p, no, v, ans, w;
long long pa... | ### Prompt
Please formulate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n - 1 <= v) {
cout << n - 1 << endl;
return 0;
}
int result = v - 1;
for (int i = 1; i <= n - v; ++i) {
result += i;
}
cout << result << endl;
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, v;
cin >> n >> v;
if (v >= n)
cout << n - 1;
else {
long long ans = 0;
for (int i = 2; i < n - v + 1; i++) ans += i;
cout << v + ans;
}
return 0;
}
| ### Prompt
Generate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n, v, i, sum;
cin >> n >> v;
if (n - 1 <= v)
cout << n - 1;
else {
sum = v;
for (i = 1; i < n - v; i++) sum += i + 1;
cout << sum;
}
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
template <typename... Args>
void dbg(Args... args) {
((cout << args), ...);
}
void f_dbg(int x) { dbg(x); }
void f_dbg(unsigned int x) { dbg(x); }
void f_dbg(long long x) { dbg(x); }
void f_dbg(unsigned long long x) { dbg(x); }
void f_dbg(double x) { dbg(x); }
void f_dbg(... | ### Prompt
In cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, i;
cin >> n >> v;
int s = v;
if (v >= (n - 1)) {
cout << n - 1;
} else {
for (i = 2; i <= (n - v); i++) {
s = s + i;
}
cout << s;
}
return 0;
}
| ### Prompt
Construct a CPP code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
scanf("%d%d", &n, &v);
if (n - v <= 1) {
printf("%d", n - 1);
} else {
printf("%d", (n - v + 1) * (n - v) / 2 + v - 1);
}
return 0;
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, v;
cin >> n >> v;
if (v >= (n - 1))
cout << n - 1;
else {
long long x = n - v;
cout << v - 1 + (x * (x + 1)) / 2;
}
cout << "\n";
return 0;
}
| ### Prompt
Generate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
const long long INF = 1e18;
const int MX = 100001;
const long double PI = 4 * atan((long double)1);
int n, v, result;
void solve() {
cin >> n >> v;
if (n - 1 < v)
cout << n - 1 << "\n";
else {
result = v;
for (int i = 2; i <= n - v... | ### Prompt
Your task is to create a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int act = 0, sol = 0;
for (int i = 1; i <= n; i++) {
while (act < n - i && act < v) {
act++;
sol += i;
}
act--;
}
cout << sol << endl;
ios_base::sync_with_stdio(false);
return 0;
}
| ### Prompt
Generate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n <= v)
cout << n - 1 << "\n";
else {
int scr = v + 1;
int rem = n - scr;
int tt = 2;
while (rem--) {
scr += (tt);
tt++;
}
cout << scr - 1 << "\n";
}
return 0;
}
| ### Prompt
Create a solution in cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, count = 0;
cin >> n >> v;
if (n - 1 == v) {
cout << v;
} else if (n - 1 < v) {
cout << n - 1;
} else {
count += v;
for (int i = 2; i <= n - v; i++) {
count += i;
}
cout << count;
}
return 0;
}
| ### Prompt
Develop a solution in Cpp to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1000000007;
bool isPrime(long long n) {
for (long long i = 2; i * i <= n; ++i) {
if (n % i == 0) {
return false;
}
}
return true;
}
long long factorial(long long n) {
return (n == 1 || n == 0) ? 1 : n * factorial(n - 1);
}
long lo... | ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
long long n, v, sum, res, ans;
int main() {
cin >> n >> v;
long long i = 1;
--n;
long long res = min(n, v - 1);
ans += res;
while (n > 0) {
if (res >= n) break;
n--;
ans += i;
i++;
}
cout << ans << endl;
return 0;
}
| ### Prompt
Generate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, v, ans, i;
cin >> n >> v;
if (v >= n - 1)
cout << n - 1;
else {
ans = v;
for (i = 2;; i++) {
if (v == n - 1)
break;
else {
ans = ans + i;
n = n - 1;
}
}
cout << ans;
}
re... | ### Prompt
Construct a CPP code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
const long long int N = 1e6, N2 = 5e3 + 10, mod = 1e9 + 7, inf = 1e10;
const long double PI = 3.141592653589793;
long long int a[N], dp[N];
char c[N];
int main() {
ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);
long long int n, v, cnt = 0, ans = 0;
cin >> n >> ... | ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
int n, v;
cin >> n >> v;
if (v >= n - 1) {
cout << n - 1 << endl;
} else {
int diff = n - v;
int cost = v;
for (int i = 2; i <= diff; i++) {
cost += i;
}
cout << cost << endl;
}
return 0;
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int ROW[] = {+1, -1, +0, +0};
int COL[] = {+0, +0, +1, -1};
int X[] = {+0, +0, +1, -1, -1, +1, -1, +1};
int Y[] = {-1, +1, +0, +0, +1, +1, -1, -1};
int KX[] = {-2, -2, -1, -1, 1, 1, 2, 2};
int KY[] = {-1, 1, -2, 2, -2, 2, -1, 1};
int GCD(int a, int b) { return b == 0 ? a : ... | ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
long long n, v;
cin >> n >> v;
long long cur = 0;
long long ans = 0;
for (int i = 1; i < n; i++, cur--) {
if (cur < n - i) {
ans += i * (min((v - cur), (n - i)));
cur = v;
}
}
cout << ans << endl;
}
int main() {
ios::sync_w... | ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int curr = v, req = n - 1, cost = v;
if (curr == req) {
cout << cost << endl;
} else if (curr > req) {
cout << req << endl;
} else {
int i = 2;
while (curr < req) {
req--;
cost += i;
i++;
... | ### Prompt
Construct a CPP code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
vector<vector<int> > mat(n + 1, vector<int>(v + 1, INT_MAX));
for (int i = 1, j = 0; j <= v; j++) {
mat[i][j] = j;
}
for (int i = 2; i <= n; i++) {
for (int j = 0; j <= v; j++) {
if (j < v) {
mat[i][j] ... | ### Prompt
Generate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
template <typename... Args>
void dbg(Args... args) {
((cout << args), ...);
}
void f_dbg(int x) { dbg(x); }
void f_dbg(unsigned int x) { dbg(x); }
void f_dbg(long long x) { dbg(x); }
void f_dbg(unsigned long long x) { dbg(x); }
void f_dbg(double x) { dbg(x); }
void f_dbg(... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main(int argc, char const *argv[]) {
int n, v;
std::cin >> n >> v;
int city = 1;
int fuel = 0;
int cost = 0;
fuel = min(n - city, v);
cost = min(n - city, v);
fuel--;
city++;
while (city != n) {
if (fuel < n - city) {
fuel++;
cost += ... | ### Prompt
Construct a cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, ans = 0, tank = 0;
cin >> n >> v;
int need = n - 1;
if (need <= v) {
cout << need;
return 0;
}
ans += v;
need -= v;
need++;
ans += need * (need + 1) / 2;
ans--;
cout << ans;
}
| ### Prompt
Please provide a CPP coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
template <typename T1, typename T2>
inline void chmin(T1 &a, T2 b) {
if (a > b) a = b;
}
template <typename T1, typename T2>
inline void chmax(T1 &a, T2 b) {
if (a < b) a = b;
}
using namespace std;
class Solve {
public:
void input() {}
void solve() {
input();
int n, v;
cin... | ### Prompt
Construct a cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n, v;
cin >> n >> v;
if (v >= n) return cout << n - 1, 0;
cout << v - 1 + 1ll * (n - v) * (n - v + 1) / 2;
}
| ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, wy, prc, i = 2;
cin >> n >> v;
wy = n - 1;
if (v > wy) {
cout << wy << endl;
return 0;
}
wy = wy - v;
prc = v;
while (wy) {
wy--;
prc = prc + i;
i++;
}
cout << prc << endl;
return 0;
}
| ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n, v;
cin >> n >> v;
int cost = 0;
cost = min(n - 1, v);
int i = 2;
int count = 1;
while (count <= n - 1 - v) {
cost += i;
i++;
count++;
}
cout << cost << e... | ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
const int mod = 1e9 + 7;
long long qpow(long long a, long long b) {
long long ans = 1;
a %= mod;
assert(b >= 0);
for (; b; b >>= 1) {
if (b & 1) ans = ans * a % mod;
a = a * a % mod;
}
return ans;
}
long long gcd(long long a, lo... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v < n) {
int s = v;
int h = n - v;
cout << ((h + 1) * h / 2 + v - 1);
} else
cout << n - 1;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long n, v;
cin >> n >> v;
long long cur, ans;
if (n - 1 < v) {
cur = n - 1;
ans = n - 1;
} else {
cur = v;
ans = v;
}
cur--;
for (long long i = 2; i < n; i++) {... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
while (~scanf("%d %d", &n, &v)) {
int cost;
--n;
if (v >= n)
printf("%d\n", n);
else {
cost = v;
for (int i = 2; i <= n - v + 1; i++) cost += i;
printf("%d\n", cost);
}
}
return 0;
}
| ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int ans = 0;
ans = min(v, n - 1);
for (int i = 2; i <= n - v; ++i) ans += i;
cout << ans;
return 0;
}
| ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int ans = 0;
if (n < v) {
cout << n - 1 << endl;
return 0;
}
ans += v;
int k = n - 1;
if (ans + 1 == k)
ans += 2;
else if (ans != k) {
int kkk = (((k - ans) + 2 + 1) * (k - ans) / 2);
ans += kkk;
... | ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int curr, cost = 0, n, v;
cin >> n >> v;
cost = v;
curr = v;
if (n - 1 <= v) {
cout << n - 1 << endl;
} else {
for (int i = 2; i < n; i++) {
curr--;
if (curr >= n - i) {
cout << cost;
return 0;
} else {
... | ### Prompt
Please formulate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int num, l = 0, i, res = 0;
scanf("%i %i", &num, &l);
res = min(num - 1, l);
l = res;
for (i = 1; i < num; i++) {
if (num - i > l) {
res = res + i + 1;
l = l + 1;
}
l = l - 1;
}
printf("%i\n", res);
}
| ### Prompt
In cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long int n, v;
cin >> n >> v;
n--;
if (n <= v) {
cout << n << endl;
} else {
long long int cnt = v;
for (long long int i = 2; i <= n; i++) {
cnt += i;
... | ### Prompt
Construct a CPP code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using std::map;
using std::queue;
using std::set;
using std::string;
using std::vector;
const int kMax = 1000;
const int kInf = INT32_MAX;
const double kEps = 10e-8;
template <typename T>
T read() {
T var;
std::cin >> var;
return var;
}
int main() {
const int n = read<int>();
const in... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, m;
scanf("%lld%lld", &n, &m);
if (n <= m) {
cout << n - 1 << endl;
return 0;
}
long long int joss = n - m;
joss = (joss * (joss + 1) / 2) - 1;
cout << joss + m << endl;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, l, i;
long long s;
cin >> n >> v;
if (v >= n - 1) {
cout << n - 1;
return 0;
}
s = v;
l = v;
for (i = 2; i < n; i++) {
l--;
if (n - i >= v) {
s += (v - l) * i;
l++;
}
}
cout << s;
return 0;
}
| ### Prompt
Construct a Cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int a[100010];
int main() {
int n, v;
cin >> n >> v;
if (n - 1 <= v)
cout << n - 1 << endl;
else {
int t = n - 1 - v;
int ans = 0;
for (int i = 2; i <= t + 1; i++) {
ans += i;
}
cout << ans + v << endl;
}
}
| ### Prompt
Your challenge is to write a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
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