output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
long n = 0;
long a = 0;
long b = 0;
int u = 0;
int oil = 0;
int cash = 0;
cin >> n >> u;
if (n <= u) {
cash = n - 1;
oil = n;
} else
cash = oil = u;
for... | ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v >= n - 1) {
cout << n - 1 << '\n';
exit(0);
}
int ans = v;
for (int i = 2; i <= n - v; ++i) ans += i;
cout << ans << '\n';
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
scanf("%d %d", &n, &v);
int dist = 1, money = 0;
for (int i = 1; i < n; i++) {
if (dist < n) {
if (i == 1) {
int spend = min(v, n - 1);
dist += spend;
money += spend;
} else {
dist++;
mon... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
const int nmax = 112345;
int n, v, res;
int main() {
scanf("%d %d", &n, &v);
--n;
if (n <= v) {
res = n;
} else {
res += v;
n -= v;
int i = 2;
while (n > 0) {
res += i;
--n;
++i;
}
}
printf("%d", res);
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
;
int n, v, i, j, s = 1, t, c = 0;
cin >> n >> v;
t = v;
if (v > n || v == n) {
cout << n - 1 << "\n";
return 0;
}
if (v == (n - 1)) {
cout << v << "\n";
return 0;
}
c += v;
... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v >= n - 1) {
cout << n - 1 << endl;
return 0;
}
int num = 0;
num += v;
for (int i = 2; i <= n - v; i++) {
num += i;
}
cout << num << endl;
}
| ### Prompt
Please provide a CPP coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
using ull = unsigned long long int;
using ld = long double;
using ll = signed long long int;
const int MX = 200;
int n, v, t, res;
int main() {
ios_base::sync_with_stdio(false);
cout.tie(nullptr);
cin.tie(nullptr);
cout << fixed;
cout.precision(12);
cin >> n >> ... | ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int ans(vector<vector<int> > &dp, int n, int f, int limit, int x) {
if (dp[n][f] != x) {
return dp[n][f];
}
if (n == 1) {
return dp[n][f] = f;
}
int min_1 = INT_MAX;
if (f + 1 <= limit) {
min_1 = min(min_1, 0 + ans(dp, n - 1, f + 1, limit, x));
}
... | ### Prompt
Construct a cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, d = 0, c, g = 0;
cin >> n >> v;
c = n - 1;
for (int i = 1; i < n; i++) {
if (g < c) {
while (g < v) {
g++;
d += i;
if (g >= c) {
break;
}
}
}
if (g >= c) {
break;
}
... | ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int f = 0;
int ans = 0;
if (v >= n - 1) {
cout << n - 1;
return 0;
}
f += v;
f--;
ans += v;
for (int i = 2; i < n; i++) {
if (f < n - i) {
f++;
ans += i;
} else {
cout << ans;
... | ### Prompt
Construct a CPP code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n <= v) {
cout << n - 1 << endl;
return 0;
} else {
int ans = v;
int coun = (n - 1) - v;
int j = 2;
for (int i = 1; i <= coun; i++) {
ans += j;
j++;
}
cout << ans << endl;
}
re... | ### Prompt
Please create a solution in Cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, res;
cin >> n >> v;
if ((v + 1) >= n)
cout << n - 1 << endl;
else {
res = v;
for (int i = v + 1, j = 2; i < n; i++, j++) {
res += j;
}
cout << res << endl;
}
return 0;
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
mt19937 rnd;
int gcd(int a, int b) {
while (b) {
a %= b;
swap(a, b);
}
return a;
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int n, v;
cin >> n >> v;
if (n < v + 1) {
cout << n - 1;
return 0;
}
int ans = v;
for (int i = 2; ... | ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int cont = 0;
cont += min(v, n - 1);
int custo = min(v, n - 1);
for (int i = 2; i < n; i++) {
if (cont == n - 1) break;
cont++;
custo += i;
}
cout << custo << "\n";
}
| ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int n, v, c;
cin >> n >> v;
if (v >= n - 1)
c = n - 1;
else
c = (v - 1) + (n - v) * (n - v + 1) / 2;
cout << c << "\n";
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n, v;
int cur = 0, cost = 0;
cin >> n >> v;
for (int i = 0; i < (n - 1); i++) {
if (cur < (n - i - 1)) {
if ((n - i - 1 - cur) >= (v - cur)) {
cost += ((i + 1) * (v -... | ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (k == n - 1)
cout << k;
else if (k >= n)
cout << n - 1;
else {
int x = (n - k);
x = ((x * (x + 1)) / 2) + (k - 1);
cout << x;
}
return 0;
}
| ### Prompt
Create a solution in cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, x, ans;
cin >> n >> v;
x = n - v;
if (v <= n - 1) {
ans = (x * (x + 1)) / 2;
cout << ans - 1 + v;
} else
cout << n - 1;
}
| ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n, v, cost = 0;
cin >> n >> v;
if (n > v)
cost += v;
else
cost += n - 1;
for (int i = 2; i <= n - v; i++) {
cost += i;
}
cout << cost << endl;
return 0;
}
| ### Prompt
Your task is to create a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
long long n, k, d[110][110];
long long depe(long long pos, long long sisa) {
if (sisa < 0) return 1e18;
if (pos == n) return 0;
long long ret = d[pos][sisa];
if (ret == -1) {
ret = 1e18;
if (sisa < k) ret = min(ret, depe(pos, sisa + 1) + pos);
ret = min(... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n - 1 <= v) {
cout << n - 1;
return 0;
}
int result = v - 1;
for (int i = 1; i <= n - v; ++i) {
result += i;
}
cout << result;
}
| ### Prompt
Generate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n <= v + 1) cout << n - 1;
if (n > v + 1) cout << v + (2 + n - v) * (n - v - 1) / 2;
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v >= n)
cout << n - 1 << endl;
else {
int ans = v;
for (int i = 2; i <= n - v; i++) {
ans += i;
}
cout << ans << endl;
}
}
| ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, cost = 0;
cin >> n >> v;
int d = n - 1;
if (d <= v) {
cout << d << endl;
} else {
cost = cost + v;
for (int i = 2; i <= n; i++) {
if (i + v == n) {
cost = cost + i * 1;
break;
} else {
cost = c... | ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int city_point, capcity;
cin >> city_point >> capcity;
if (city_point - 1 <= capcity)
cout << city_point - 1;
else {
cout << capcity - 1 +
(1 + city_point - capcity) * (city_point - capcity) / 2;
}
return 0;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
while (cin >> n >> v) {
if (n - 1 - v <= 0) {
cout << n - 1 << endl;
continue;
} else {
cout << v + (2 + n - v) * (n - 1 - v) / 2 << endl;
continue;
}
}
}
| ### Prompt
Your task is to create a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n, v;
cin >> n >> v;
if (v >= (n - 1))
cout << n - 1;
else {
int ans = 0, i = 1;
ans += (v);
int x = (n - 1 - v);
for (int i = 2; i <= (1 + x); i++) {
ans += (i);... | ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
void boost() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
const int N = 1e6;
const int inf = 1e9 + 7;
int n, v;
int main() {
boost();
cin >> n >> v;
if (v >= n - 1) {
cout << n - 1;
return 0;
}
int i = 2, ans = v;
while (v < n - 1) {
... | ### Prompt
Develop a solution in cpp to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int ans = 0, a = 0;
for (int i = 1; i <= n - 1; i++) {
if (a < n - i) {
ans += i * min(v - a, n - i - a);
a += min(v - a, n - i - a);
}
a--;
}
cout << ans;
}
| ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v >= n)
cout << n - 1 << "\n";
else if (v < n) {
if ((n - v) == 1)
cout << v << "\n";
else {
int count = v;
for (int i = 2; i <= n; i++) {
if (n - i >= v)
count += i;
e... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a, b;
cin >> a >> b;
if (a <= b) {
cout << a - 1 << endl;
} else {
int ans = 0;
ans += b;
for (int i = 2; i <= a - b; i++) {
ans += i;
}
cout << ans << endl;
}
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n - 1 <= v)
cout << n - 1 << endl;
else {
int counter = v;
for (int i = 2; i < n - v + 1; i++) {
counter += i;
}
cout << counter << endl;
}
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
scanf("%d%d", &n, &v);
printf("%d\n", v >= n - 1 ? n - 1 : (1 + n - v) * (n - v) / 2 + v - 1);
return 0;
}
| ### Prompt
Generate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
const int N = 2e5 + 9, INF = 1e9;
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v >= n) {
cout << n - 1;
} else {
int p = n - v;
cout << (v - 1) + (((1 + p) * p) / 2);
}
return 0;
}
| ### Prompt
Generate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
long long totalCost = 0, currentTank = 0;
for (int i = 1; i <= n; ++i) {
if (n - i > currentTank) {
int toAdd = min(v, n - i) - currentTank;
currentTank += toAdd;
totalCost += i * toAdd;
}
--current... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int n, v, ans;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> v;
int f = 0;
int x = n - 1;
for (int i = 1; i <= n; i++) {
ans += i * min(x, v - f);
x -= min(x, v - f);
f = v - 1;
}
cout << ans << '\n';
return ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
long long n, k;
cin >> n >> k;
if (k >= n - 1) {
cout << n - 1 << endl;
} else {
cout << k + (2 + n - k) * (n - 1 - k) / 2 << endl;
}
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
unsigned long long ar[101];
bool f;
void fun() {
f = true;
ar[1] = 1;
for (int i = 2; i < 101; i++) {
ar[i] = 4 * (i - 1) + ar[i - 1];
}
}
int main() {
int n, v;
cin >> n >> v;
if (v >= n) {
cout << n - 1;
return 0;
}
int c = v;
int k = 1;
... | ### Prompt
Please formulate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int tank, money;
int main() {
int n, v;
cin >> n >> v;
for (int i = 1; i <= n; i++) {
int fillup = min(v, n - i) - tank;
money += fillup * i;
tank += fillup - 1;
}
cout << money << endl;
}
| ### Prompt
Develop a solution in cpp to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int fx[4] = {1, -1, 0, 0};
int fy[4] = {0, 0, 1, -1};
const double PI = acos(-1.0);
const double EPS = 1e-6;
const int MOD = (int)1e9 + 7;
const int maxn = (int)2e5 + 5;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
int n, v;
cin >> n >... | ### Prompt
Your task is to create a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
multiset<long long> ms;
int a[500000];
int main() {
int n, v;
cin >> n >> v;
int pos = 1;
int money = min(v, n - 1);
while (pos < n) {
v--;
pos++;
if (n - pos > v) {
money += pos;
v++;
}
}
cout << money;
}
| ### Prompt
Please formulate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int testCase;
string s;
int iinf = 1e9 + 1;
long long inf = 1e16 + 1;
void solve() {
long long n;
cin >> n;
long long k;
cin >> k;
if (k >= n) {
cout << n - 1;
return;
}
long long extra = n - k;
cout << (extra * (extra + 1)) / 2 + k - 1;
}
int main()... | ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int ans = 0;
if (v < n) {
ans += v;
for (int i = 2; i <= n - v; i++) ans += i;
} else
ans = n - 1;
cout << ans << endl;
return 0;
}
| ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
void getIn(stack<int> &left, stack<int> &right,
vector<pair<int, int>> &result) {
while (!left.empty() && !right.empty()) {
int lidx = left.top();
left.pop();
int ridx = right.top();
right.pop();
result.push_back({lidx, ridx});
}
}
int mai... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
int n;
cin >> n;
string l;
cin >> l;
string r;
cin >> r;
vector<vector<int>> left(26);
vector<vector<int>> right(26);
vector<int> wl;
vector<int> wr;
int i, j;
for (... | ### Prompt
In cpp, your task is to solve the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot... |
#include <bits/stdc++.h>
using namespace std;
int n;
map<char, vector<int>> l;
map<char, vector<int>> r;
vector<pair<int, int>> ans;
int main() {
scanf("%d", &n);
getchar();
for (int i = 0; i < n; i++) {
char ch = getchar();
l[ch].push_back(i);
}
getchar();
for (int i = 0; i < n; i++) {
char ch ... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-t... |
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
using namespace std;
long long n;
queue<long long> q[2][30];
queue<long long> cnt1;
queue<long long> cnt2;
string l;
string r;
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
;
cin >> n;
vector<pair... | ### Prompt
Generate a Cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot an... |
#include <bits/stdc++.h>
using namespace std;
const int A = 26;
int main() {
int n;
cin >> n;
string l;
cin >> l;
vector<vector<int> > left(A);
vector<int> wl;
for (int i = 0; i < int(n); i++)
if (l[i] != '?')
left[l[i] - 'a'].push_back(i);
else
wl.push_back(i);
string r;
cin >> r;... | ### Prompt
Your task is to create a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
;
long long n;
cin >> n;
string a, b;
cin >> a >> b;
vector<vector<long long> > aa(27), bb(27);
vector<vector<bool> > ad(27), bd(27);
for (long long i = 0; i < n; i++) {
if (a[i] != '?... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
vector<int> cr1[27];
vector<int> cr2[27];
int s1[27];
int s2[27];
struct node {
int x;
int y;
};
int main() {
int n;
cin >> n;
char c;
for (int i = 0; i < n; i++) {
cin >> c;
if (c == '?') {
s1[26]++;
cr1[26].push_back(i);
} else {
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
const long long N = 15e4 + 5, mod = 998244353;
long long n, o, e, bit;
vector<long long> v[30], z, x, a, b;
vector<pair<long long, long long>> ans;
string s, t;
bool mk[N];
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> s >> t;
for (lon... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-t... |
#include <bits/stdc++.h>
using namespace std;
long long n, x, y, m, s, t, k, a, b, u;
const int mod = 1e9 + 7;
const int mxn = 2e5 + 5;
long long mx = 0, mn = 1e18;
long long arr[2000000], wan[2000000];
string str, str2;
string str4 = "abcdefghijklmnopqrstuvwxyz";
map<char, set<long long>> mp;
map<char, set<long long>>... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
const int MX = 1500010;
vector<vector<int> > vec(MX);
bool V1[MX], V2[MX];
int main() {
int n, cnt = 0;
cin >> n;
string s1, s2;
cin >> s1 >> s2;
vector<int> q1, q2;
for (int i = 0; i < n; i++) {
if (s1[i] == '?') {
q1.push_back(i);
} else {
... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 15e4;
bool visa[maxn + 10], visb[maxn + 10];
int n, cnta[30], cntb[30], posa[30][maxn + 10], posb[30][maxn + 10];
char a[maxn + 10], b[maxn + 10];
int main() {
scanf("%d%s%s", &n, a, b);
for (int i = 0; i < n; ++i) {
if (a[i] == '?')
posa[0][+... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
scanf("%d", &n);
vector<int> left[27], right[27];
vector<pair<int, int> > ans;
string l, r;
cin >> l >> r;
for (int i = 0; i < n; i++) {
char c = l[i];
if (c == '?')
left[26].push_back(i + 1);
else
left[c - 'a'].push... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
vector<long long> l[200];
vector<long long> r[200];
vector<pair<long long, long long> > ans;
signed main() {
long long n, l_q = 1, r_q = 1;
char c;
cin >> n;
for (long long i = 0; i < n; i++) {
cin >> c;
l[(long long)c].push_back(i);
}
for (long long i =... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 7;
const int mod = 1e9 + 7;
void Smax(int &a, int b) {
if (a < b) a = b;
}
void Smin(int &a, int b) {
if (a > b) a = b;
}
long long read() {
long long c = getchar(), Nig = 1, x = 0;
while (!isdigit(c) && c != '-') c = getchar();
if (c == '-'... | ### Prompt
In cpp, your task is to solve the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot... |
#include <bits/stdc++.h>
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
inline long long int rand(long long int x, long long int y) {
++y;
return (rng() % (y - x)) + x;
}
long long int n;
vector<long long int> co[26], v;
string A, S;
vector<pair<long long int, long long in... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
const int MAX = 150009;
vector<int> l[29];
vector<int> r[29];
int ans[MAX][2];
int main() {
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
char now;
cin >> now;
if (now == '?')
l[26].push_back(i);
else
l[now - 'a'].push_back(i);
}
for ... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
long long int mo = 1000000007;
bool greed(const pair<int, int> a, const pair<int, int> b) {
return (a.first - a.second) > (b.first - b.second);
}
queue<int> a[28], b[28];
int main() {
int n;
cin >> n;
string l, r;
cin >> l >> r;
for (int i = 0; i < n; i++) {
... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long n;
cin >> n;
string a, b;
cin >> a >> b;
long long aa[27] = {0}, bb[27] = {0};
queue<long long> q[27], v[27];
for (int i = 0; i < a.size(); i++) {
if (a[i] == '?') {
aa[26]++... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int test, i, j, n, count, flag = 0, o1 = 0, o2 = 0, b1, x, y, m, l,
z, max1, x1, y1, x2, y2, z1, k, sum, f, r,
ans1;
cin >> n;
vector<long long int> mk1[27];
vector<lo... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long int n;
cin >> n;
string a, b;
cin >> a >> b;
vector<queue<int> > x(26), y(26);
vector<pair<int, int> > pos;
int count1 = 0, count2 = 0, ans = 0, count3 = 0, count4 = 0;
q... | ### Prompt
Create a solution in cpp for the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
const int Mod = 1000000007;
const int INF = 0x3f3f3f3f;
const long long LL_INF = 0x3f3f3f3f3f3f3f3f;
const double e = exp(1);
const double PI = acos(-1);
const double ERR = 1e-10;
char a[maxn], b[maxn];
vector<int> lia[30], lib[30];
vector<pair<int... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
int fv[2][26], unk[2], bruh[2];
vector<int> nch[26][2];
int szch[26][2];
vector<int> nun[2];
int szun[2];
vector<pair<int, int> > ans;
int main() {
int n;
cin >> n;
bruh[0] = bruh[1] = n;
string s;
int i, j, z;
for (i = 0; i < 2; i++) {
cin >> s;
for (j ... | ### Prompt
Please create a solution in cpp to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
int main() {
std::ios_base::sync_with_stdio(false);
std::cin.tie(0);
std::cout.tie(0);
int n;
std::cin >> n;
std::vector<std::stack<int>> left(27);
std::vector<std::stack<int>> right(27);
std::string ls;
std::cin >> ls;
for (int i = 0; i < n; i++) {
if (ls[i] == '?') {
... | ### Prompt
Generate a Cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot an... |
#include <bits/stdc++.h>
using namespace std;
struct Boot {
int _pos;
char _char;
};
struct PairBoots {
Boot _left;
Boot _right;
};
int main() {
int n;
string leftBoots;
string rightBoots;
vector<vector<Boot>> leftBootsBucket(27);
vector<vector<Boot>> rightBootsBucket(27);
vector<PairBoots> ans;
c... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, letter1[270], letter2[270], q1 = 0, q2 = 0;
cin >> n;
char s1[150005], s2[150005];
cin >> s1 >> s2;
int ar[150005];
memset(ar, 0, sizeof(ar));
vector<int> v1[150005];
vector<int> v2[150005];
queue<int> qq1;
queue<int> qq2;
memset(le... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
int n;
char s[150005], t[150005];
queue<int> p[27], q[27];
vector<pair<int, int> > ans;
int main() {
while (~scanf("%d", &n)) {
for (int i = 0; i < 27; i++) {
while (q[i].size()) q[i].pop();
while (p[i].size()) p[i].pop();
}
ans.clear();
scanf(... | ### Prompt
Generate a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int len;
cin >> len;
vector<int> v1[26], v2[26];
vector<int> leftqmark, rightqmark;
vector<int> till1(26, 0), till2(26, 0);
vector<pair<int, int>> ans;
string s1, s2;
cin >> s1 >> s2;
for (int i = 0; i < s1.length(); i++) {
if (s1[i] == '?... | ### Prompt
Create a solution in Cpp for the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot ... |
#include <bits/stdc++.h>
using namespace std;
string alpha = "abcdefghijklmnopqrstuvwxyz?";
string _alpha = "abcdefghijklmnopqrstuvwxyz";
const long long mod = 1e9 + 7;
const long long inf = 1e18 + 5;
const long long nax = 2010;
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long lon... | ### Prompt
Your task is to create a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-t... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
template <class T>
using V = vector<T>;
template <class T, class U>
using P = pair<T, U>;
using vll = V<ll>;
using vvll = V<vll>;
template <class T>
inline bool chmax(T& a, T b) {
if (a < b) {
a = b;
return true;
}
return false;
}
templat... | ### Prompt
Generate a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot an... |
#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
vector<pair<int, int>> match(const string& s1, const string& s2, int n) {
unordered_map<char, unordered_set<int>> a, b;
for (int i = 0; i < n; i++) a[s1[i]].insert(i + 1), b[s2[i]].insert(i + 1);
vector<pair<int, int>> res;
for (c... | ### Prompt
Please create a solution in cpp to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
double sqr(double x) { return x * x; }
int const N = (int)2e6 + 1, INF = (int)1e9 + 1, MOD = (int)1e9 + 7;
long long mypow(long long a, long long b, long long mod) {
long long rv = 1;
while (b) {
if (b % 2) rv = rv * a % mod;
a = a * a % mod;
b /= 2;
}
r... | ### Prompt
Create a solution in Cpp for the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio;
cin.tie(0);
cout.tie(0);
int n;
cin >> n;
string a, b;
cin >> a >> b;
set<int> qmarka;
set<int> qmarkb;
vector<pair<int, int>> vec;
set<int> s[26];
for (int i = 0; i < n; i++) {
if (a[i] == '?')
qmark... | ### Prompt
Please create a solution in CPP to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const ll inf = 1e18;
const int N = 2 * 1e5 + 10;
std::vector<ll> v[30], vv[30];
std::vector<ll> x, xx;
std::vector<pair<ll, ll>> vvv;
ll res;
void solve() {
ll n;
cin >> n;
string s, ss;
cin >> s >> ss;
for (int i = 0; i < n; ++i) {
if (s... | ### Prompt
In cpp, your task is to solve the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot... |
#include <bits/stdc++.h>
using namespace std;
char a[150050];
char b[150050];
int c[150050][2];
int n;
int cnt1[28], cnt2[28], cnt3[28];
int pick1[28][150000], pick2[28][150000];
int main() {
scanf("%d %s %s", &n, a, b);
for (int i = 0; i < n; i++) {
if (a[i] == '?') {
pick1[0][cnt1[0]] = i;
cnt1[0]... | ### Prompt
Generate a cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot an... |
#include <bits/stdc++.h>
long long dx[4] = {-1, 0, 1, 0};
long long dy[4] = {0, -1, 0, 1};
long long mod = 1e9 + 7;
long long inf = 5e17;
using namespace std;
void _print(long long t) { cerr << t; }
void _print(int t) { cerr << t; }
void _print(string t) { cerr << t; }
void _print(char t) { cerr << t; }
template <class... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
struct save {
vector<int> l;
vector<int> r;
};
int main() {
int n;
cin >> n;
string s1, s2;
cin >> s1 >> s2;
vector<save> check(26);
vector<pair<int, int>> ans;
save qm;
for (int i = 0; i < n; i++) {
if (s2[i] == '?') {
qm.r.push_back(i);
}... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 200 * 1000 + 100;
vector<pair<int, int> > res;
vector<int> l[30];
vector<int> r[30];
int main() {
int n;
cin >> n;
string s, t;
cin >> s >> t;
for (int i = 0; i < n; i++) {
if (s[i] == '?')
l[26].push_back(i);
else
l[s[i] - 'a'... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
vector<int> A[27], B[27];
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n;
string a, b;
cin >> n >> a >> b;
for (int i = 0; i < n; i++) {
if (a[i] == '?')
A[26].push_back(i + 1);
else {
A[a[i] - 'a'].push... | ### Prompt
Please create a solution in CPP to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
int n;
string a, b;
set<int> A, B;
queue<int> qA, qB;
map<char, queue<int> > q;
vector<pair<int, int> > resp;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> a >> b;
for (int i = 0; i < n; ++i) {
if (a[i] == '?')
qA.push(i);
e... | ### Prompt
Generate a Cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot an... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios::sync_with_stdio(0);
cin.tie(0);
long long freq1[26] = {0};
long long freq2[26] = {0};
map<char, stack<long long>> mp1, mp2;
long long mark1 = 0, mark2 = 0;
long long n;
cin >> n;
string s1, s2;
cin >> s1 >> s2;
for (long long i = ... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-t... |
#include <bits/stdc++.h>
using namespace std;
const double EPS = 1e-8;
const double pi = acos(-1);
long long dcmp(double a, double b) {
return fabs(a - b) <= EPS ? 0 : a < b ? -1 : 1;
}
void debug() {}
int const N = 200000 + 9, M = 100 + 9, OO = 1e9;
vector<vector<int>> vec1(130);
vector<vector<int>> vec2(130);
vecto... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-t... |
#include <bits/stdc++.h>
using namespace std;
char s1[1000007], s2[1000007];
vector<int> v1, v2;
vector<int> vv[37];
vector<pair<int, int> > vp;
int vis[1000007];
int main() {
int n;
scanf("%d", &n);
scanf("%s%s", s1 + 1, s2 + 1);
for (int i = 1; i <= n; i++)
if (s1[i] >= 'a' && s1[i] <= 'z')
vv[s1[i]... | ### Prompt
Create a solution in CPP for the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 150007;
int n;
char a[maxn], b[maxn];
stack<int> a1[30], b1[30];
vector<pair<int, int> > ans;
int main() {
scanf("%d", &n);
scanf("%s", a);
scanf("%s", b);
for (int i = 0; i < n; i++) {
if (a[i] == '?') a1[27].push(i + 1);
if (b[i] == '?') b... | ### Prompt
Please create a solution in cpp to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 150007;
int n;
char a[maxn], b[maxn];
int main() {
while (cin >> n) {
stack<int> a1[30], b1[30];
vector<pair<int, int> > ans;
scanf("%s", a);
scanf("%s", b);
for (int i = 0; i < n; i++) {
if (a[i] == '?') a1[27].push(i + 1);
... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
vector<long long> righ[200];
vector<long long> e1;
vector<long long> e2;
vector<pair<long long, long long> > p;
int main() {
ios::sync_with_stdio(0);
long long n;
string r, l;
cin >> n >> r >> l;
for (int i = 0; i < n; i++) {
if (r[i] == '?')
e1.push_bac... | ### Prompt
Your task is to create a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-t... |
#include <bits/stdc++.h>
using namespace std;
int ara1[26], ara2[26], ara[26];
int sig1[150001], sig2[150001];
int par[150000][2];
vector<vector<int>> pos1, pos2;
vector<int> qpos1, qpos2;
int main() {
int i, j, k;
int n;
int max_pair = 0;
int q1 = 0, q2 = 0, q;
char str1[150001], str2[150001];
scanf("%d", ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ull = unsigned long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using vi = vector<int>;
using vll = vector<ll>;
const ll MOD = 1000000007ll;
const ll INF = 0x3f3f3f3f3f3f3f3f;
inline ll SUB(ll a, ll b) { return a - b >= 0ll ? a - ... | ### Prompt
In cpp, your task is to solve the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot... |
#include <bits/stdc++.h>
using namespace std;
char a[150010];
char b[150010];
vector<vector<int> > v(300);
vector<int> sp;
int ans[150010][2];
int cnt = 0;
bool find(int s, int x) {
if (v[s].empty()) return 0;
ans[cnt][0] = v[s].back();
ans[cnt][1] = x;
cnt++;
v[s].pop_back();
return 1;
}
int main() {
int... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
long long n;
string a, b;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long ttttt = 1;
while (ttttt--) {
cin >> n >> a >> b;
vector<long long> x, y;
vector<vector<long long>> v(26), w(26);
vector<pair<long long, long lon... | ### Prompt
In cpp, your task is to solve the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
const int Mod = 1000000007;
const int INF = 0x3f3f3f3f;
const long long LL_INF = 0x3f3f3f3f3f3f3f3f;
const double e = exp(1);
const double PI = acos(-1);
const double ERR = 1e-10;
int sum[2][27];
char str1[maxn], str2[maxn];
vector<int> tt[2][27];
... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot... |
#include <bits/stdc++.h>
using namespace std;
const long long base = 7;
const long long maxn = 1e6 + 9;
const long long inf = 1e9 + 7;
queue<long long> l[30], r[30], l1, r1, lf, rf;
vector<pair<long long, long long> > res;
long long n, i;
string a, b;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cou... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, ans = 0;
cin >> n;
string s, t;
cin >> s >> t;
queue<int> v1[27], v2[27], left, right;
vector<pair<int, int> > p;
for (int i = 0; i < n; i++) {
if (s[i] != '?') {
v1[s[i] - 97].push(i);
} else
left.push(i);
}
for (in... | ### Prompt
Generate a CPP solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left boot an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n;
cin >> n;
string left;
string right;
cin >> left >> right;
vector<int> v1[27];
vector<int> v2[27];
for (int i = 0; i < n; i++) {
if (left[i] == '?')
v1[26].push_back(i + 1);
... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-t... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 150007;
int n;
char a[maxn], b[maxn];
stack<int> a1[30], b1[30];
vector<pair<int, int> > ans;
int main() {
scanf("%d", &n);
scanf("%s", a);
scanf("%s", b);
for (int i = 0; i < n; i++) {
if (a[i] == '?') a1[27].push(i + 1);
if (b[i] == '?') b... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 150005;
const int INF = 0x3f3f3f3f;
char l[MAXN], r[MAXN];
int top = 0;
stack<int> lc[100], rc[100];
struct Ans {
int l, r;
} ans[MAXN];
int main() {
int n;
scanf("%d", &n);
scanf("%s%s", l, r);
for (int i = 0; l[i] != '\0'; i++) {
if (l[i] ==... | ### Prompt
Please create a solution in cpp to the following problem:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
int n;
char s[150050];
queue<int> a[30], b[30], pos_qa, pos_qb;
vector<pair<int, int> > res;
int main() {
scanf("%d", &n);
scanf("%s", s + 1);
for (int i = 1; i <= n; i++)
if (s[i] != '?')
a[s[i] - 'a'].push(i);
else
pos_qa.push(i);
scanf("%s", s... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ifstream fin("input.txt");
long long n, m;
cin >> n;
{
string l, r;
unordered_map<char, vector<int>> mp1;
unordered_map<char, vector<int>> mp2;
vector<pair<int, int>> out;
bool state1[150001], state2[150001];
for (int i = 0; i < ... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n left boots and n right boots. Each boot has a color which is denoted as a lowercase Latin letter or a question mark ('?'). Thus, you are given two strings l and r, both of length n. The character l_i stands for the color of the i-th left bo... |
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