output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 7;
const long long mod = 1e9 + 7;
int n, m;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n >> m;
int nw = 0;
int cst = 0;
for (int i = (1); i <= (n); ++i) {
if (nw < n - i) {
int num = min(m - nw, n - i);
cs... | ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
#pragma GCC optimize "trapv"
using namespace std;
void solveEachTest(long long int T35TC453N = 1) {
long long int n, v;
cin >> n >> v;
if (n <= v) {
cout << n - 1ll;
} else {
n -= v - 1;
long long int ans = v - 1ll + (n * (n - 1)) / 2;
cout << ans;
}
cout << "\n";
... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1e9 + 7;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n, v, cost = 0;
cin >> n >> v;
n--;
cost = v;
if (v == n)
cout << cost;
else if (v > n)
cout << n;
else {
for (int i = 0; i < n -... | ### Prompt
Generate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, j, k;
int n, v;
int cost;
scanf("%d %d", &n, &v);
if (v >= (n - 1)) {
printf("%d", n - 1);
return 0;
}
cost = v;
for (i = 2; i < n; i++) {
if (v == (n - 1)) break;
cost += i;
v++;
}
printf("%d", cost);
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
long long next() {
long long x;
cin >> x;
return x;
}
const long long inf = 1e18, eps = 1e9 + 7, nmax = 2 * 1e5 + 4;
int main() {
long long n = next(), v = next(), i = 1, ans = 0;
if (v > n) v = n;
ans = (n + 1 - v) * (n - v) / 2;
ans += v - 1;
cout << ans;
... | ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n, v;
cin >> n >> v;
int neededoil = n - 1;
if (neededoil <= v) {
cout << neededoil << endl;
return 0;
} else {
int cost = v;
int oil = v;
for (int i = 2;; i++) {
oil +... | ### Prompt
Construct a CPP code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int numcity, maxtank, dollar = 0;
cin >> numcity >> maxtank;
int lt = numcity - 1;
if (maxtank >= lt) {
cout << lt;
} else {
for (int i = 1; i <= numcity; i++) {
if (i == 1) {
dollar = dollar + maxtank;
lt = lt - maxtank;... | ### Prompt
Generate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i = 2, j, k = 1, v, c = 0;
cin >> n >> v;
c = (v <= n - 1) ? v : n - 1;
j = c;
while (j < n - 1) {
j++;
c += i;
i++;
}
cout << c;
return 0;
}
| ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
int main() {
int n, v;
int cost;
scanf("%d %d", &n, &v);
if (v >= n - 1)
printf("%d\n", n - 1);
else {
cost = v;
for (int i = 2; i + v <= n; i++) {
cost = cost + i;
}
printf("%d", cost);
}
}
| ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
vector<long long> a;
long long n, v;
cin >> n >> v;
if (v >= n - 1) {
cout << n - 1 << endl;
} else {
long long money = 0;
long long m = n - 1;
money += v;
long long k = 0;
k += v;
long long i = 2;
while (k < m) {
... | ### Prompt
In cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
ios_base::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL);
int64_t n, v;
cin >> n >> v;
if (v >= n) {
cout << (n - 1);
return 0;
}
int64_t x = (n - v);
int64_t sum = (x * (x + 1)) / 2 - 1;
cout << sum + v;
return 0;
}
| ### Prompt
Your challenge is to write a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
long long n, v;
cin >> n >> v;
if (n >= v) {
long long t = (n - v) * (n - v + 1);
t /= 2;
t += v - 1;
cout << t;
} else {
cout << n - 1;
}
}
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long t;
t... | ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int n, v, ans, k;
int main() {
cin >> n >> v;
for (int i = 1; i <= n; i++) {
if (k < n - i) {
int x = min(v, n - i);
ans += (x - k) * i;
k = v;
}
k--;
}
cout << ans;
}
| ### Prompt
Develop a solution in cpp to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n - 1 <= v) {
cout << n - 1 << endl;
return 0;
}
int result = v;
int ex = 2;
for (int i = 1; i <= n - 1 - v; i++) {
result += ex;
ex++;
}
cout << result << endl;
}
| ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, x;
cin >> n >> v;
if (n <= v) {
cout << n - 1;
} else {
x = n - v;
int p = (x * (x + 1) / 2) + v - 1;
cout << p;
}
return 0;
}
| ### Prompt
In cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
const long long int LL_MAX = 1e18 + 5;
const int MX = INT_MAX;
const long long int mod = 1000000007;
const int maxx = 2e5;
const int d4i[4] = {-1, 0, 1, 0};
const int d4j[4] = {0, 1, 0, -1};
const int d8i[8] = {-1, -1, 0, 1, 1, 1, 0, -1};
const int d8j[8] = {0, 1, 1, 1, 0, ... | ### Prompt
Create a solution in cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int n, v, f[105][105];
int solve(int n1, int v1) {
if (n1 > n) return 0;
if (v1 < 0) return 1000000007;
if (f[n1][v1] != -1) return f[n1][v1];
int res = 1000000007;
for (int i = 0; i <= v - v1; ++i) {
res = min(res, solve(n1 + 1, v1 - 1 + i) + n1 * i);
}
r... | ### Prompt
Generate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
queue<int> q;
int main() {
int i, j, k, l, m, n, cnt = 0, v, sum = 0;
scanf("%d%d", &n, &v);
while (cnt < v) {
q.push(1);
sum += 1;
cnt++;
}
for (int i = 2; i <= n; i++) {
cnt--;
q.pop();
while (cnt < v) {
q.push(i);
sum += i;
... | ### Prompt
Develop a solution in cpp to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n, v;
cin >> n >> v;
int ans = 0;
int tank = 0;
for (int i = 1; i < n; i++) {
if (tank == 0) {
ans += min(v, n - 1) * i;
tank += min(v, n - 1) - 1;
} else {
... | ### Prompt
Create a solution in CPP for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int n, v;
int ans = 0;
int f = 0;
int main() {
cin >> n >> v;
if (v >= n)
ans = n - 1;
else {
ans = v + (2 + 2 + (n - v - 1) - 1) * (n - v - 1) / 2;
}
cout << ans;
return 0;
}
| ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int n, v;
int main() {
cin >> n >> v;
int ans = 0;
int p = 1;
int cur = 0;
for (int i = n - 1; i >= 0; i--, p++) {
if (cur >= i) continue;
ans += p * (min(i, v - cur));
cur = cur + min(i, v - cur) - 1;
}
cout << ans << endl;
return 0;
}
| ### Prompt
Develop a solution in cpp to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n, v;
cin >> n >> v;
int dis = n - 1;
if (dis <= v) {
cout << dis << endl;
return;
}
int lagbe = dis - v;
int j = 2;
int sum = v;
for (int i = 0; i < lagbe; i++) {
sum += j;
j++;
}
cout << sum << endl;
return;
}
int... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
using namespace std::chrono;
template <typename T, size_t N>
int SIZE(const T (&t)[N]) {
return N;
}
template <typename T>
int SIZE(const T &t) {
return t.size();
}
string to_string(const string s, int x1 = 0, int x2 = 1e9) {
return '"' + ((x1 < s.size()) ? s.substr(x... | ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
bool isPrime(int n) {
if (n <= 1) return false;
for (int i = 2; i < n; i++)
if (n % i == 0) return false;
return true;
}
const int N = 1e5 + 7;
long long l, tr, n, m, sum, mini, maxi, a, b, c, x, y, z;
long long t[N];
set<int> vis;
vector<int> v;
int main() {
io... | ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, sum = 0, t;
cin >> n >> v;
t = n - v - 1;
if (t > 0) {
for (int i = 2; i <= t + 1; i++) sum = sum + i;
sum = sum + v;
cout << sum;
} else if (n <= v) {
cout << n - 1;
} else {
cout << v;
return 0;
}
return 0;
}
| ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v >= n - 1)
cout << n - 1;
else
cout << (n - v) * (n - v + 1) / 2 - 1 + v;
return 0;
}
| ### Prompt
Generate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int n, v;
int main() {
cin >> n >> v;
if (v >= n - 1) {
cout << n - 1 << endl;
} else {
cout << v + (n - v + 2) * (n - v - 1) / 2 << endl;
}
return 0;
}
| ### Prompt
Please provide a cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
const long long int inf = 1000000000;
const long long int mod = 1000000000 + 7;
inline void IO() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
inline int dcmp(long double x) { return x < -1e-12 ? -1 : (x > 1e-12); }
template <class T>
inline int CHECK(T M... | ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int c = v, i = 1;
while (i != n) {
i++;
if (n - i >= v) {
c += i;
}
}
if (n <= v) {
c = n - 1;
}
cout << c;
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
int main() {
std::ios::sync_with_stdio(0);
std::cin.tie(0);
std::cout.tie(0);
int n, v;
std::cin >> n >> v;
int cost = std::min(n - 1, v);
int cur = v + 1;
int i = 2;
while (cur < n) {
cost += i;
i++;
cur++;
}
std::cout << cost;
return 0;
}
| ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
inline void filee() {
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
}
int main() {
int a, b;
cin >> a >> b;
int c = b;
if (a == b)
cout << a - 1 << endl;
else if (a < b)
cout << a - 1 << endl;
else {
for (int i = 2; i <= a... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int ans = 0;
if (n - 1 > v)
ans += v;
else
ans += n - 1;
for (int i = 2; i <= n; i++) {
if (n - i + 1 > v) {
ans += i;
}
}
cout << ans;
}
| ### Prompt
Construct a Cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int N, M;
cin >> N >> M;
int ans = M;
if (M >= N - 1) {
cout << N - 1;
return 0;
}
for (int i = 2; i <= N - M; i++) {
ans += i;
}
cout << ans;
return 0;
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
scanf("%d%d", &n, &v);
if (v >= n)
printf("%d\n", n - 1);
else {
int sum = v;
int i = 1;
while (i + v < n) {
i++;
sum += i;
}
printf("%d\n", sum);
}
return 0;
}
| ### Prompt
In cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1000000007;
long long pm(long long x, long long n) {
long long result = 1;
while (n > 0) {
if (n % 2 == 1) result = ((result % mod) * (x % mod)) % mod;
x = ((x % mod) * (x % mod)) % mod;
n /= 2;
}
return result;
}
long long p(long l... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int n, v, m;
void nhap() { cin >> n >> v; }
void xuat() { cout << m; }
void xuli() {
if (v >= n - 1)
m = n - 1;
else if (v < n - 1) {
m = v;
for (int i = 2; i <= n - v; i++) m += i;
}
}
int main() {
nhap();
xuli();
xuat();
}
| ### Prompt
Please create a solution in Cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
const long long Inf = 1e9 + 7;
void solve() {
int64_t n, c;
cin >> n >> c;
if (c > (n - 1)) {
c = n - 1;
}
int64_t co = c;
for (int64_t i = 2; i <= n - c; i++) {
co += i;
}
cout << co << "\n";
}
int32_t main() {
ios_base::sync_with_stdio(false);
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n, v;
cin >> n >> v;
int req = n - 1, cost = v, pos = 2, left = v - 1;
if (v >= n - 1)
cost = n - 1;
else {
while (left < n - pos) {
cost += pos;
left = v - 1;
... | ### Prompt
In CPP, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, j, k, l, m, n, v;
while (cin >> n >> v) {
k = v;
if (n <= v) {
printf("%d\n", n - 1);
continue;
}
for (j = 2; j <= n - v; j++) {
k += j;
}
printf("%d\n", k);
}
}
| ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int N, V;
cin >> N >> V;
vector<int> A(N);
int rem = N - 1;
int fuel = 0;
int cost = 0;
for (int n = 1; n <= N; n++) {
if (rem > 0) {
int buy = min(rem, V - fuel);
fuel += buy;
rem... | ### Prompt
Generate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
long long n, v;
void solve() {
cin >> n >> v;
long long ans = 0, c = 0, x = 1;
while (x < n) {
if (c < n - x) {
ans += x * min(v - c, n - x - c);
c += min(v - c, n - x - c);
}
c--;
x++;
}
cout << ans << endl;
}
void prep() {}
int main()... | ### Prompt
Create a solution in cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
long long n, v;
long long a[1000];
long long f[1000];
void INP() { cin >> n >> v; }
void solve() {
if (v >= n - 1)
cout << n - 1;
else
cout << v - 1 + (n - v) * (n - v + 1) / 2;
}
int main() {
INP();
solve();
return 0;
}
| ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
;
long long n, v, cost = 0;
cin >> n >> v;
if (v >= (n - 1)) {
cout << (n - 1) << "\n";
} else {
cost = v;
for (long long i = 2; i <= n - v; i++) {
cost += i;
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
int main() {
int n, v, s = 0, i, j;
scanf("%d%d", &n, &v);
if (n - 1 - v <= 0) {
s = n - 1;
} else {
i = 2;
for (j = 0; j < n - 1 - v; i++, j++) {
s = s + i;
}
s = s + v;
}
printf("%d\n", s);
return 0;
}
| ### Prompt
Construct a Cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, m, v, i, sum = 0;
scanf("%d %d", &n, &v);
if (n - 1 <= v) {
printf("%d", n - 1);
return 0;
}
sum += v;
for (i = 2; i <= n - v; i++) {
sum += i;
}
printf("%d", sum);
return 0;
}
| ### Prompt
Please provide a cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
const int Inf = 2e9;
long long LINF = (long long)4e18;
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n, u;
cin >> n >> u;
int cur = u;
int need = n - 1;
int now = 1;
int ans = min(n - 1, u);
need -= ans;
while (now < n) {
n... | ### Prompt
Please formulate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int n, v, ans1, w, ans2, kfjdsaljfalk;
string skldgflakdjdlsa;
int main() {
cin >> n >> v;
for (int i = 1; i <= 5; i++) kfjdsaljfalk++;
for (int i = 1; i <= 5; i++) kfjdsaljfalk++;
for (int i = 1; i <= 5; i++) kfjdsaljfalk++;
for (int i = 1; i <= 5; i++) kfjdsaljf... | ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
n--;
if (n <= v)
cout << n << "\n";
else {
n -= v - 1;
cout << v + n * (n + 1) / 2 - 1 << "\n";
}
return 0;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
long long maxLL(long long a, long long b) { return (a > b ? a : b); }
long long minLL(long long a, long long b) { return (a < b ? a : b); }
void solve() {
int n, v;
cin >> n >> v;
if (v >= n) {
cout << n - 1 << "\n";
} else {
int cost = v;
for (int i = 2... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, v;
cin >> n >> v;
long long c = 0;
c = v;
if (v >= n)
cout << n - 1;
else {
for (int i = 0; i < (n - v - 1); ++i) c += (i + 2);
cout << c;
}
return 0;
}
| ### Prompt
Please formulate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
int cant = 1;
int res = 0;
cin >> n >> v;
int i = 1;
int llena;
while (n - (--cant) > 0) {
if (v - cant < n - i - cant)
llena = v - cant;
else
llena = n - i - cant;
if (llena == 0) break;
cant += llena;
re... | ### Prompt
Create a solution in cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n - v <= 1) {
cout << n - 1 << endl;
return 0;
} else {
int ans = v;
for (int i = 2; i <= n - v; i++) ans += i;
cout << ans << endl;
}
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n > v + 1) {
cout << v - 1 + ((n - v) * (n - v + 1)) / 2;
} else {
cout << n - 1;
}
return 0;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int k = 1, sum = 0;
if (v >= n) {
cout << n - 1 << endl;
return 0;
}
for (int i = 1; i <= (n - v); i++) {
k -= 1;
if (k < v) {
sum += (v - k) * i;
k = v;
}
}
cout << sum << endl;
return ... | ### Prompt
In cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
long long power(long long n, long long p) {
if (p == 0) return 1;
if (p % 2 == 0) {
long long c = power(n, p / 2);
return ((c % 1000000007) * (c % 1000000007)) % 1000000007;
}
return ((n % 1000000007) * (power(n, p - 1) % 1000000007)) % 1000000007;
}
int n, ... | ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1000000007;
bool isPrime(long long n) {
for (long long i = 2; i * i <= n; ++i) {
if (n % i == 0) {
return false;
}
}
return true;
}
long long factorial(long long n) {
return (n == 1 || n == 0) ? 1 : n * factorial(n - 1);
}
long lo... | ### Prompt
Develop a solution in cpp to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, cap;
cin >> n >> cap;
int city = n - cap;
int ans = min(n - 1, cap);
if (city >= 2) {
ans += (city * (city + 1)) / 2 - 1;
}
cout << ans << endl;
}
| ### Prompt
Generate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int t = 1;
int sum = 0;
int i = 1;
while (n - i + 1 > t) {
t--;
int r = min(v - t, n - i);
sum += r * i;
t += r;
i++;
}
cout << sum << endl;
}
| ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr), cout.tie(nullptr);
int n, v;
cin >> n >> v;
if (n - 1 <= v) {
cout << n - 1 << endl;
return 0;
}
int result = v - 1;
for (int i = 1; i <= n - v; ++i) {
result += i;
}
cout <... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, u;
cin >> n >> u;
int cnt = 0;
if (u >= n - 1) {
cnt = n - 1;
} else {
cnt = u;
for (int i = u + 1; i < n; ++i) {
cnt += 1 + i - u;
}
}
cout << cnt;
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int dp[110][110];
int main() {
int n, v;
cin >> n >> v;
for (int i = 1; i <= v; i++) dp[1][i] = i;
for (int i = 2; i <= n; i++) {
for (int j = 0; j < v; j++) {
dp[i][j] = min(dp[i - 1][j + 1], dp[i - 1][j] + i);
}
dp[i][v] = dp[i - 1][v] + i;
}
... | ### Prompt
Generate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long l, v;
cin >> l >> v;
long pr = l - 1;
if (pr > v) {
long ans = v;
pr = pr - v;
long x = 2;
while (pr) {
pr = pr - 1;
ans = ans + x;
x++;
}
cout << ans << endl;
} else {
cout << pr << endl;
}
retur... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
;
long long n, l, ans;
cin >> n >> l;
ans = min(n - 1, l);
for (long long i = 1; i < n; i++) {
if ((n - i) - l <= 0) break;
ans += i + 1;
}
cout << ans << "\n";
return 0;
}
| ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
inline void filee() {
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
}
int main() {
int a, b;
cin >> a >> b;
int c = b;
if (a <= b)
cout << a - 1 << endl;
else {
for (int i = 2; i <= a - c; i++) {
b += i;
}
cout << ... | ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, i, cost = 0;
cin >> n >> v;
if (n > v) {
for (i = 1; i <= n - v; i++)
if (i == 1)
cost += v;
else
cost += i;
cout << cost;
return 0;
}
cout << n - 1;
return 0;
}
| ### Prompt
Your task is to create a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int now = min(n - 1, v);
int ans = now;
for (int i = 2; i <= n; i++) {
int rem = n - i;
if (now > rem) break;
ans += i;
}
cout << ans << endl;
return 0;
}
| ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, m;
cin >> n >> m;
int x = n - 1;
int sum = 0;
for (int i = 1; i <= n - 1; i++) {
if (m < x && i == 1) {
sum += m * i;
x -= m;
} else if (x <= m && i == 1) {
sum += x * i;
break;
} else if (i > 1 && x > 0) {
... | ### Prompt
Your task is to create a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, a;
cin >> n >> v;
if (v < n - 1)
a = (v - 1) + ((n - v) * (n - v + 1)) / 2;
else
a = n - 1;
cout << a;
return 0;
}
| ### Prompt
Please formulate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
const long long MOD = 1e9 + 9;
const long long INF = 1e18;
const int MAXN = 1e6 + 10;
const int MAXM = 1e4 + 500;
const int N = 2000 + 15;
const double EPS = 1e-9;
int dx[] = {1, 0, 0, -1};
int dy[] = {0, 1, -1, 0};
double len(complex<long long> a) {
return sqrt(a.real() ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (n - 1 <= k) {
cout << n - 1;
} else {
int c = k, cost = k, i = 2;
while (c != n - 1) {
cost += i;
c++;
i++;
}
cout << cost;
}
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distanc... |
#include <bits/stdc++.h>
int n, v, ans;
int main() {
scanf("%d%d", &n, &v);
n--;
if (v > n) v = n;
ans = v;
n -= v;
for (int i = 2; i; i++) {
if (!n) break;
n--;
ans += i;
}
printf("%d\n", ans);
return 0;
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
int rupee = 0;
if (v >= n)
rupee = n - 1;
else {
rupee += v;
int remain = n - v;
int sum = ((n - v) * (n - v + 1)) / 2;
sum--;
rupee += sum;
}
cout << rupee;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100005;
const int INF = 0x3f3f3f3f;
const int MOD = 998244353;
int i, j, n, v, now = 0, ans = 0, cnt = 0;
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin >> n >> v;
if (v >= n - 1) cout << n - 1 << endl, exit(0);
cnt... | ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
inline void pisz(int n) { printf("%d\n", n); }
const int fx[4][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}};
const int fxx[8][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0},
{1, 1}, {1, -1}, {-1, 1}, {-1, -1}};
template <typename T, typename TT>
ostream& operator... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long n, v, cost, i;
cin >> n >> v;
if (v >= (n - 1))
cout << n - 1;
else {
cost = v;
for (i = 2; i <= n; i++) {
v--;
if ((n - i) <= v) {
cout << cost;
brea... | ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, v;
cin >> n >> v;
long long int cost = 0, tank = 0;
if (v >= n - 1) {
cout << (n - 1);
return 0;
}
for (long long int i = 1; i < n; i++) {
cost += (v - tank) * i;
tank = v;
if (tank >= n - i) break;
tank--;
... | ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
cin.tie(0);
cout.tie(0);
ios_base::sync_with_stdio(0);
int n, v;
cin >> n >> v;
v = min(v, n - 1);
int ret = v;
for (int i = 2; i <= n - v; i++) ret += i;
cout << ret << endl;
return 0;
}
| ### Prompt
Construct a CPP code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if ((n - 1) <= v) {
cout << n - 1 << endl;
return 0;
}
int cost = v;
for (int i = 2; i + v <= n; i++) {
cost += i;
}
cout << cost << endl;
return 0;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
const long long int m = 1e9 + 7;
long int dp[3000][3000] = {0};
int main() {
int n, v;
cin >> n >> v;
n--;
if (v > n) {
cout << n;
} else {
int fill = n - v;
int count = v;
int i = 2;
while (fill > 0) {
count += i;
i++;
fill--... | ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, sum = 0, cnt = 0;
scanf("%d", &n), scanf("%d", &v);
for (int i = 1; i < n; ++i) {
if (i == 1) {
sum += min(v, n - 1);
cnt += min(v, n - 1);
} else {
sum += i;
cnt += 1;
}
if (cnt == n - 1) break;
}
pri... | ### Prompt
Please formulate a cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
string s;
bool solve(int l, int r) {
stack<char> st;
for (int i = l; i <= r; i++) {
if (s[i] == '(')
st.push(s[i]);
else if (s[i] == ')') {
if (st.empty())
return false;
else {
if (st.top() == '(')
st.pop();
el... | ### Prompt
Generate a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
void FIO() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
}
ll gcd(ll a, ll b) {
if (b == 0)
return a;
else {
return gcd(b, a % b);
}
}
void tmt(void) {
int n, v;
cin >> n >> v;
int cost =... | ### Prompt
Please create a solution in cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n, v;
cin >> n >> v;
if (v >= n - 1) {
cout << (n - 1) << endl;
;
return 0;
}
int ans = v;
for (int i = 2; i <= n - v; i++) {
ans += i;
}
cout << (ans) << endl;
;
retur... | ### Prompt
Please create a solution in Cpp to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
#pragma GCC target("avx2")
#pragma GCC optimization("O3")
#pragma GCC optimization("unroll-loops")
const int INF = 1e9 + 1;
const int maxN = 1e6 + 2;
typedef int Array[maxN];
typedef long long LLArray[maxN];
long long n, k, ans = 0, cur;
LLArray c;
deque<long long> cur_max;... | ### Prompt
In cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
int n, v;
cin >> n >> v;
if (n - 1 <= v) {
cout << n - 1;
} else {
int cost = v;
for (int i = 2; i <= n - v; i++) {
cost += i;
}
cout << cost;
}
}
| ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
using iii = tuple<int, int, int>;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int n, v, x = 0, r = 0;
cin >> n >> v;
for (int i = 0; i < n; i++) {
while (x < n - i - 1 && x < v) x++, r += i... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v, s;
cin >> n >> v;
if (n - 1 <= v)
s = n - 1;
else {
s = v - 1;
n -= v;
s += (n * (n + 1)) / 2;
}
cout << s;
return 0;
}
| ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main(int argc, char const *argv[]) {
int n, k;
cin >> n >> k;
int cnt = min(n - 1, k);
int a = n - cnt;
cnt += (a * (a + 1)) / 2 - 1;
cout << cnt << endl;
return 0;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
while (scanf("%d%d", &n, &v) != EOF) {
if (v >= n - 1)
printf("%d\n", n - 1);
else {
int cost = v;
for (int i = 0, j = 2; i < n - 1 - v; i++, j++) cost += j;
printf("%d\n", cost);
}
}
return 0;
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
long long read(long long x = 0, long long fr = 1, char c = getchar()) {
while (c < '0' || c > '9') fr *= (c == '-') ? -1 : 1, c = getchar();
while (c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar();
return x * fr;
}
int n, v;
int main() {
n = read(), v = rea... | ### Prompt
Create a solution in Cpp for the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between an... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (v + 1 >= n) {
cout << n - 1;
return 0;
}
cout << v + ((n - v + 2) * (n - v - 1)) / 2;
}
| ### Prompt
Develop a solution in CPP to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, v;
cin >> n >> v;
if (n - 1 < v) {
cout << n - 1;
return 0;
}
int x = 1;
int b = 0;
int ans = 0;
while (x < n) {
if (x + b == n) {
cout << ans;
return 0;
}
ans += (v - b) * x;
b = v;
x++;
b--;
... | ### Prompt
In CPP, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long int t = 1;
while (t--) {
long long int n, v, ans = 0;
cin >> n >> v;
if (v >= n - 1) {
cout << n - 1 << "\n";
return 0;
}
if (v == 1) {
n-... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a, b, c;
cin >> a >> b;
if (a - 1 <= b) {
cout << a - 1 << endl;
return 0;
}
c = b - 1;
for (int i = 1; i <= a - b; ++i) {
c += i;
}
cout << c << endl;
}
| ### Prompt
In Cpp, your task is to solve the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between a... |
#include <bits/stdc++.h>
using namespace std;
int n, v, ans;
int main() {
cin >> n >> v;
ans = min(n - 1, v);
for (int i = 2; i <= n - v; i++) ans += i;
cout << ans;
}
| ### Prompt
Generate a CPP solution to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between any ... |
#include <bits/stdc++.h>
using namespace std;
void Solution() {
int n, v, m = 0;
cin >> n >> v;
if (n - 1 < v)
cout << n - 1;
else {
int result = v - 1;
for (int i = 1; i <= n - v; ++i) {
result += i;
}
cout << result;
}
}
int main() { Solution(); }
| ### Prompt
Construct a Cpp code solution to the problem outlined:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance between... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100005;
const int INF = 0x3f3f3f3f;
const int MOD = 998244353;
int i, j, n, v, now = 0, ans = 0, cnt = 0;
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin >> n >> v;
now = n - 1;
if (n <= v) cout << n - 1 << endl, exi... | ### Prompt
Develop a solution in cpp to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int flag = 1;
int n, v;
scanf("%d%d", &n, &v);
if (n - 1 <= v) {
printf("%d\n", n - 1);
return 0;
}
int sum = 0;
n--;
n -= v;
sum += v;
while (n--) {
flag++;
sum += flag;
}
printf("%d\n", sum);
return 0;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, n, v, y, sum = 0;
cin >> n >> v;
n--;
if (v >= n) {
cout << n << endl;
return 0;
} else {
sum += v;
for (int i = 1; i <= n - v; i++) sum += (i + 1);
cout << sum << endl;
}
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The dis... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 100005;
const int N = 26;
int main() {
int n, v;
scanf("%d %d", &n, &v);
if (v + 1 >= n) {
v = min(v, n - 1);
printf("%d\n", v);
return 0;
}
int pos = 1;
int ans = v;
while (pos + 1 != n) {
if (v >= n - pos) {
break;
... | ### Prompt
Please create a solution in CPP to the following problem:
Sasha is a very happy guy, that's why he is always on the move. There are n cities in the country where Sasha lives. They are all located on one straight line, and for convenience, they are numbered from 1 to n in increasing order. The distance betw... |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.